message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a pot and N ingredients. Each ingredient has a real number parameter called value, and the value of the i-th ingredient (1 \leq i \leq N) is v_i.
When you put two ingredients in the pot, they will vanish and result in the formation of a new ingredient. The value of the new ingredient will be (x + y) / 2 where x and y are the values of the ingredients consumed, and you can put this ingredient again in the pot.
After you compose ingredients in this way N-1 times, you will end up with one ingredient. Find the maximum possible value of this ingredient.
Constraints
* 2 \leq N \leq 50
* 1 \leq v_i \leq 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
v_1 v_2 \ldots v_N
Output
Print a decimal number (or an integer) representing the maximum possible value of the last ingredient remaining.
Your output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.
Examples
Input
2
3 4
Output
3.5
Input
3
500 300 200
Output
375
Input
5
138 138 138 138 138
Output
138
Submitted Solution:
```
N = int(input())
v = list(map(int,input().split()))
nabe = 0
for i in range(0,N,2):
v.sort()
v.append((v[0]+v[1])/2)
del v[:2]
print(v[0])
``` | instruction | 0 | 45,989 | 9 | 91,978 |
No | output | 1 | 45,989 | 9 | 91,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a pot and N ingredients. Each ingredient has a real number parameter called value, and the value of the i-th ingredient (1 \leq i \leq N) is v_i.
When you put two ingredients in the pot, they will vanish and result in the formation of a new ingredient. The value of the new ingredient will be (x + y) / 2 where x and y are the values of the ingredients consumed, and you can put this ingredient again in the pot.
After you compose ingredients in this way N-1 times, you will end up with one ingredient. Find the maximum possible value of this ingredient.
Constraints
* 2 \leq N \leq 50
* 1 \leq v_i \leq 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
v_1 v_2 \ldots v_N
Output
Print a decimal number (or an integer) representing the maximum possible value of the last ingredient remaining.
Your output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.
Examples
Input
2
3 4
Output
3.5
Input
3
500 300 200
Output
375
Input
5
138 138 138 138 138
Output
138
Submitted Solution:
```
N = float(input())
v = list(map(float, input().split()))
v.sort()
ans = float(0)
ans = v[0]+v[1]/2
if N>3:
for i in v[2::]:
ans = (ans+i)/2
print(ans)
``` | instruction | 0 | 45,990 | 9 | 91,980 |
No | output | 1 | 45,990 | 9 | 91,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a pot and N ingredients. Each ingredient has a real number parameter called value, and the value of the i-th ingredient (1 \leq i \leq N) is v_i.
When you put two ingredients in the pot, they will vanish and result in the formation of a new ingredient. The value of the new ingredient will be (x + y) / 2 where x and y are the values of the ingredients consumed, and you can put this ingredient again in the pot.
After you compose ingredients in this way N-1 times, you will end up with one ingredient. Find the maximum possible value of this ingredient.
Constraints
* 2 \leq N \leq 50
* 1 \leq v_i \leq 1000
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
v_1 v_2 \ldots v_N
Output
Print a decimal number (or an integer) representing the maximum possible value of the last ingredient remaining.
Your output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.
Examples
Input
2
3 4
Output
3.5
Input
3
500 300 200
Output
375
Input
5
138 138 138 138 138
Output
138
Submitted Solution:
```
try:
N = int(input())
if N>1 and N<51:
S = input()
A = S.split()
A = list(map(float, A))
if all(len(A)==N and i > 0 and i < 1001 for i in A):
sum = [0]*(N)
sum = A.copy()
for k in range(0, N):
for i in range(0, N-1):
if((k+i)>=(N-1)):
j = i+k+1-N
else:
j=i+k+1
sum[k] = (sum[k]+A[j])/2
print(max(sum))
except:
print("Error")
``` | instruction | 0 | 45,991 | 9 | 91,982 |
No | output | 1 | 45,991 | 9 | 91,983 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2 | instruction | 0 | 46,105 | 9 | 92,210 |
"Correct Solution:
```
def getid(node, m, n):
if node == 'H':
return 0
elif node == 'D':
return m + n + 1
elif node[0] == 'C':
return int(node[1:])
else:
return m + int(node[1:])
import heapq
#??±???????±?????????±???????????????????????????
def ex_dijkstra(graph, m, size, start=0):
distance = [float('inf')] * size
distance[start] = 0
que = []
heapq.heappush(que, (0, start))
while len(que):
_, u = heapq.heappop(que)
for length, vi in graph[u]:
if distance[vi] > distance[u] + length:
distance[vi] = distance[u] + length
if 1 <= vi <= m:
continue
heapq.heappush(que, (distance[vi], vi))
return distance
import sys
f = sys.stdin
from collections import defaultdict
from itertools import permutations
from itertools import chain
while True:
m,n,k,d = map(int, f.readline().split())
if m == 0:
break
cake = [0] + list(map(int, f.readline().split()))
graph = defaultdict(list)
for a, b, dist in [f.readline().split() for _ in range(d)]:
a, b, dist = getid(a,m,n), getid(b,m,n), int(dist) * k
graph[a].append((dist,b))
graph[b].append((dist,a))
compressed_graph = [ex_dijkstra(graph, m, m + n + 2, i) for i in range(m + 1)]
calorie = []
for combination in chain(*[permutations(range(1,m + 1), i) for i in range(m + 1)]):
combination = (0,) + combination + (m + n + 1,)
temp = -sum(cake[i] for i in combination[:-1])
for s, e in zip(combination,combination[1:]):
temp += compressed_graph[s][e]
calorie.append(temp)
print(min(calorie))
``` | output | 1 | 46,105 | 9 | 92,211 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2 | instruction | 0 | 46,106 | 9 | 92,212 |
"Correct Solution:
```
from itertools import combinations
from heapq import heappop, heappush
import sys
sys.setrecursionlimit(1000000)
INF = 10 ** 20
def convert(s, m, n):
if s == "H":
return 0
if s == "D":
return 1
if s[0] == "C":
return int(s[1:]) + 1
if s[0] == "L":
return int(s[1:]) + m + 1
def get_cost(start, m, n, edges):
cost = [INF] * (m + n + 2)
cost[start] = 0
que = []
heappush(que, (0, start))
while que:
total, node = heappop(que)
for dist, to in edges[node]:
if cost[to] > total + dist:
cost[to] = total + dist
if not (2 <= to <= m + 1):
heappush(que, (total + dist, to))
return cost
def shortest_path(start, goal, rest, cakes_dist, dic):
if not rest:
return cakes_dist[start][goal]
if (start, rest) in dic:
return dic[(start, rest)]
ret = INF
for to in rest:
ret = min(ret, shortest_path(to, goal, tuple((i for i in rest if i != to)), cakes_dist, dic) + cakes_dist[start][to])
dic[(start, rest)] = ret
return ret
while True:
m, n, k, d = map(int, input().split())
if m == 0:
break
clst = list(map(int, input().split()))
"""
Home ... 0
D ... 1
Cake ... 2, 3, ... m + 1
Land ... m + 2, m + 3, ... m + n + 1
"""
edges = [[] for _ in range(m + n + 2)]
for _ in range(d):
s, t, e = input().split()
e = int(e)
s = convert(s, m, n)
t = convert(t, m, n)
edges[s].append((e, t))
edges[t].append((e, s))
cakes_dist = [[INF] * (m + 2) for _ in range(m + 2)]
for start in range(m + 2):
cost = get_cost(start, m, n, edges)
for to in range(m + 2):
if to != start:
cakes_dist[start][to] = cost[to]
"""
now ... 現在いる点
rest ... 残りのめぐる点
dic[(now, rest)] ... 現在いる点、残りの点をまわる時の最小距離
dic[(now, rest)] = min(cakes_dist[now][to] + dic[(to, rest - to)] for to in rest)
"""
dic = {}
ans = INF
cakes = [i for i in range(2, m + 2)]
for num in range(m + 1):
for rest in combinations(cakes, num):
cal = sum([clst[i - 2] for i in rest])
ans = min(ans, shortest_path(0, 1, rest, cakes_dist, dic) * k - cal)
print(ans)
``` | output | 1 | 46,106 | 9 | 92,213 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2 | instruction | 0 | 46,107 | 9 | 92,214 |
"Correct Solution:
```
# ref: http://lethe2211.hatenablog.com/entry/2014/12/30/011030
# ref: http://d.hatena.ne.jp/simezi_tan/20101019/1287462266
from heapq import heappop,heappush
if __name__ == '__main__':
def id(s):
# edges = [C1 C2 C3...Cm L1 L2 L3...Ln H D]
# len(edges) = m+n+1+1
if s[0]=="H": return ne-2
if s[0]=="D": return ne-1
num = int(s[1:])
if s[0]=="C": return num-1
return num-1+m
while(True):
m,n,k,d = map(int, input().split())
if not m: break
ne = m+n+2
cs = list(map(int, input().split()))
edges = [[] for _ in range(ne) ]
for i in range(d):
s1,s2,di = input().split()
t1,t2,ca = id(s1),id(s2),int(di)*k
edges[t1].append([t2,ca])
edges[t2].append([t1,ca])
que = []
cost = [float('inf')]*(ne<<m)
cost[(ne-2)<<m] = 0
ans = float('inf')
heappush(que,[0,(ne-2)<<m])
while(que):
cc,state = heappop(que)
vis_cak = state&(2**m-1)
cur_pos = state>>m
if cur_pos == ne-1: ans = min(ans,cc)
if cost[state]>cc: continue
for ss,dd in edges[cur_pos]:
nxt_cost = cc+dd
nxt_pos = ss
nxt_bit = vis_cak
# calc cakeshop (visit one time only)
if 0<=nxt_pos and nxt_pos<m:
if 1<<nxt_pos & vis_cak: continue
nxt_cost -= cs[nxt_pos]
nxt_bit ^= 1 << nxt_pos
# combine next_position and visited_cakeshop
new_state = (nxt_pos<<m) + nxt_bit
if cost[new_state] > nxt_cost:
heappush(que,[nxt_cost,new_state])
cost[new_state] = nxt_cost
print(ans)
``` | output | 1 | 46,107 | 9 | 92,215 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2 | instruction | 0 | 46,108 | 9 | 92,216 |
"Correct Solution:
```
from itertools import combinations
from heapq import heappop, heappush
INF = 10 ** 20
def convert(s, m, n):
if s == "H":
return 0
if s == "D":
return 1
if s[0] == "C":
return int(s[1:]) + 1
if s[0] == "L":
return int(s[1:]) + m + 1
def get_cost(start, m, n, edges):
cost = [INF] * (m + n + 2)
cost[start] = 0
que = []
heappush(que, (0, start))
while que:
total, node = heappop(que)
for dist, to in edges[node]:
if cost[to] > total + dist:
cost[to] = total + dist
if not (2 <= to <= m + 1):
heappush(que, (total + dist, to))
return cost
def shortest_path(start, goal, rest, cakes_dist, dic):
if not rest:
return cakes_dist[start][goal]
#if (start, rest) in dic:
# return dic[(start, rest)]
ret = INF
for to in rest:
ret = min(ret, shortest_path(to, goal, tuple((i for i in rest if i != to)), cakes_dist, dic) + cakes_dist[start][to])
dic[(start, rest)] = ret
return ret
while True:
m, n, k, d = map(int, input().split())
if m == 0:
break
clst = list(map(int, input().split()))
"""
Home ... 0
D ... 1
Cake ... 2, 3, ... m + 1
Land ... m + 2, m + 3, ... m + n + 1
"""
edges = [[] for _ in range(m + n + 2)]
for _ in range(d):
s, t, e = input().split()
e = int(e)
s = convert(s, m, n)
t = convert(t, m, n)
edges[s].append((e, t))
edges[t].append((e, s))
cakes_dist = [[INF] * (m + 2) for _ in range(m + 2)]
for start in range(m + 2):
cost = get_cost(start, m, n, edges)
for to in range(m + 2):
if to != start:
cakes_dist[start][to] = cost[to]
"""
now ... 現在いる点
rest ... 残りのめぐる点
dic[(now, rest)] ... 現在いる点、残りの点をまわる時の最小距離
dic[(now, rest)] = min(cakes_dist[now][to] + dic[(to, rest - to)] for to in rest)
"""
dic = {}
ans = INF
cakes = [i for i in range(2, m + 2)]
for num in range(m + 1):
for rest in combinations(cakes, num):
cal = sum([clst[i - 2] for i in rest])
ans = min(ans, shortest_path(0, 1, rest, cakes_dist, dic) * k - cal)
print(ans)
``` | output | 1 | 46,108 | 9 | 92,217 |
Provide a correct Python 3 solution for this coding contest problem.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2 | instruction | 0 | 46,109 | 9 | 92,218 |
"Correct Solution:
```
from heapq import heappush, heappop
INF = 10**18
while 1:
M, N, K, D = map(int, input().split())
if M == N == K == D == 0:
break
*C, = map(int, input().split())
def convert(s):
if s == 'H':
return 0
if s[0] == 'C':
return int(s[1:])
if s[0] == 'L':
return M+int(s[1:])
return 1+N+M
G = [[] for i in range(N+M+2)]
H = [-1]*(N+M+2)
for i in range(M):
H[i+1] = i
for i in range(D):
s, t, e = input().split()
s = convert(s); t = convert(t)
e = int(e)
G[s].append((t, e))
G[t].append((s, e))
dist = [[INF]*(1 << 6) for i in range(N+M+2)]
que = [(0, 0, 0)]
while que:
cost, state, v = heappop(que)
if dist[v][state] < cost:
continue
for w, e in G[v]:
d = cost + e*K; n_state = state
if H[w] != -1:
if state & (1 << H[w]):
continue
n_state |= (1 << H[w])
d -= C[H[w]]
if d < dist[w][n_state]:
dist[w][n_state] = d
heappush(que, (d, n_state, w))
print(min(dist[N+M+1]))
``` | output | 1 | 46,109 | 9 | 92,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2
Submitted Solution:
```
from itertools import combinations
from heapq import heappop, heappush
import sys
sys.setrecursionlimit(1000000)
INF = 10 ** 20
def convert(s, m, n):
if s == "H":
return 0
if s == "D":
return 1
if s[0] == "C":
return int(s[1]) + 1
if s[0] == "L":
return int(s[1]) + m + 1
def get_cost(start, m, n, edges):
cost = [INF] * (m + n + 2)
cost[start] = 0
que = []
heappush(que, (0, start))
while que:
total, node = heappop(que)
for dist, to in edges[node]:
if cost[to] > total + dist:
cost[to] = total + dist
if not (2 <= to <= m + 1):
heappush(que, (total + dist, to))
return cost
def shortest_path(start, goal, rest, cakes_dist, dic):
if not rest:
return cakes_dist[start][goal]
if (start, rest) in dic:
return dic[(now, rest)]
ret = INF
for to in rest:
ret = min(ret, shortest_path(to, goal, tuple((i for i in rest if i != to)), cakes_dist, dic) + cakes_dist[start][to])
dic[(start, rest)] = ret
return ret
print(0)
while True:
m, n, k, d = map(int, input().split())
if m == 0:
break
clst = list(map(int, input().split()))
"""
Home ... 0
D ... 1
Cake ... 2, 3, ... m + 1
Land ... m + 2, m + 3, ... m + n + 1
"""
edges = [[] for _ in range(m + n + 2)]
for _ in range(d):
s, t, e = input().split()
e = int(e)
s = convert(s, m, n)
t = convert(t, m, n)
edges[s].append((e, t))
edges[t].append((e, s))
cakes_dist = [[INF] * (m + 2) for _ in range(m + 2)]
for start in range(m + 2):
cost = get_cost(start, m, n, edges)
for to in range(m + 2):
if to != start:
cakes_dist[start][to] = cost[to]
print(cakes_dist)
dic = {}
"""
now ... 現在いる点
rest ... 残りのめぐる点
dic[(now, rest)] ... 現在いる点、残りの点をまわる時の最小距離
dic[(now, rest)] = min(cakes_dist[now][to] + dic[(to, rest - to)] for to in rest)
"""
ans = INF
cakes = [i for i in range(2, m + 2)]
for num in range(m + 1):
for rest in combinations(cakes, num):
cal = sum([clst[i - 2] for i in rest])
ans = min(ans, shortest_path(0, 1, rest, cakes_dist, dic) * k - cal)
print(ans)
``` | instruction | 0 | 46,110 | 9 | 92,220 |
No | output | 1 | 46,110 | 9 | 92,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2
Submitted Solution:
```
def getid(node, m, n):
if node == 'H':
return 0
elif node == 'D':
return m + n + 1
elif node[0] == 'C':
return int(node[1:])
else:
return m + int(node[1:])
import heapq
def dijkstra(graph, size, start=0):
distance = [float('inf')] * size
distance[start] = 0
que = []
heapq.heappush(que, (0, start))
while len(que):
_, u = heapq.heappop(que)
for length, vi in graph[u]:
if distance[vi] > distance[u] + length:
distance[vi] = distance[u] + length
heapq.heappush(que, (distance[vi], vi))
return distance
import sys
f = sys.stdin
from collections import defaultdict
from itertools import permutations
from itertools import chain
while True:
m,n,k,d = map(int, f.readline().split())
if m == n == k == d == 0:
break
cake = [0] + list(map(int, f.readline().split()))
graph = defaultdict(list)
for a, b, dist in [f.readline().split() for _ in range(d)]:
a, b, dist = getid(a,m,n), getid(b,m,n), int(dist) * k
graph[a].append((dist,b))
graph[b].append((dist,a))
compressed_graph = [dijkstra(graph, m + n + 2, i) for i in range(m + 1)]
calorie = []
for combination in chain(*[permutations(range(1,m + 1), i) for i in range(m + 1)]):
combination = (0,) + combination + (m + n + 1,)
temp = -sum(cake[i] for i in combination[:-1])
for s, e in zip(combination,combination[1:]):
temp += compressed_graph[s][e]
calorie.append(temp)
print(min(calorie))
``` | instruction | 0 | 46,111 | 9 | 92,222 |
No | output | 1 | 46,111 | 9 | 92,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2
Submitted Solution:
```
from itertools import combinations
from heapq import heappop, heappush
import sys
sys.setrecursionlimit(1000000)
INF = 10 ** 20
def convert(s, m, n):
if s == "H":
return 0
if s == "D":
return 1
if s[0] == "C":
return int(s[1]) + 1
if s[0] == "L":
return int(s[1]) + m + 1
def get_cost(start, m, n, edges):
cost = [INF] * (m + n + 2)
cost[start] = 0
que = []
heappush(que, (0, start))
while que:
total, node = heappop(que)
for dist, to in edges[node]:
if cost[to] > total + dist:
cost[to] = total + dist
if not (2 <= to <= m + 1):
heappush(que, (total + dist, to))
return cost
def shortest_path(start, goal, rest, cakes_dist, dic):
if not rest:
return cakes_dist[start][goal]
if (start, rest) in dic:
return dic[(now, rest)]
ret = INF
for to in rest:
ret = min(ret, shortest_path(to, goal, tuple((i for i in rest if i != to)), cakes_dist, dic) + cakes_dist[start][to])
dic[(start, rest)] = ret
return ret
while True:
m, n, k, d = map(int, input().split())
if m == 0:
break
clst = list(map(int, input().split()))
"""
Home ... 0
D ... 1
Cake ... 2, 3, ... m + 1
Land ... m + 2, m + 3, ... m + n + 1
"""
edges = [[] for _ in range(m + n + 2)]
for _ in range(d):
s, t, e = input().split()
e = int(e)
s = convert(s, m, n)
t = convert(t, m, n)
edges[s].append((e, t))
edges[t].append((e, s))
``` | instruction | 0 | 46,112 | 9 | 92,224 |
No | output | 1 | 46,112 | 9 | 92,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr. A loves sweets, but recently his wife has told him to go on a diet. One day, when Mr. A went out from his home to the city hall, his wife recommended that he go by bicycle. There, Mr. A reluctantly went out on a bicycle, but Mr. A, who likes sweets, came up with the idea of stopping by a cake shop on the way to eat cake.
If you ride a bicycle, calories are consumed according to the mileage, but if you eat cake, you will consume that much calories. The net calories burned is the calories burned on the bike minus the calories burned by eating the cake. Therefore, the net calories burned may be less than zero.
If you buy a cake at a cake shop, Mr. A will eat all the cake on the spot. Mr. A does not stop at all cake shops, but when he passes through the point where the cake shop exists, he always stops and buys and eats one cake. However, it's really tempting to pass in front of the same cake shop many times, so each cake shop should only be visited once. In addition, you may stop by the cake shop after passing the destination city hall, and then return to the city hall to finish your work, and you may visit as many times as you like except the cake shop.
Enter the map information from Mr. A's home to the city hall, a list of calories of cakes that can be eaten at the cake shop on the way, and the calories burned by traveling a unit distance, from leaving home to entering the city hall. Create a program that outputs the minimum net calories burned.
The map shows Mr. A's home and city hall, a cake shop and a landmark building. The input data representing the map contains a line consisting of a symbol representing the two points and the distance between them, when there is a road connecting Mr. A's home, city hall, cake shop and each point of the landmark. For example, if the distance between the 5th cake shop and the 3rd landmark is 10, the input data will contain a line similar to the following:
C5 L3 10
In this way, cake shops are represented by C, and landmarks are represented by L in front of the number. Also, Mr. A's home is represented by H and the city hall is represented by D. If the input data is given two points and the distance between them, advance between the two points in either direction. For example, in the example above, you can go from a cake shop to a landmark and vice versa. In addition, you must be able to reach the city hall from your home. Other input data given are the number of cake shops m, the number of landmarks n, the calories burned per unit distance k, and the cakes that can be bought at each of the first cake shop to the mth cake shop. The total number of m data representing calories and distance data d.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by four 0 lines. Each dataset is given in the following format:
m n k d
c1 c2 ... cm
s1 t1 e1
s2 t2 e2
::
sd td ed
Number of cake shops m (1 ≤ m ≤ 6), number of landmarks n (1 ≤ n ≤ 100), calories burned per unit distance k (1 ≤ k ≤ 5), distance data on the first line The total number d (5 ≤ d ≤ 256) is given.
The second line gives the calories ci (1 ≤ ci ≤ 100) of the cake you buy at each cake shop.
The following d line is given the distance data si, ti, ei (1 ≤ ei ≤ 20) between the i-th two points.
The number of datasets does not exceed 100.
Output
Outputs the minimum total calories burned on one line for each input dataset.
Example
Input
1 1 2 5
35
H L1 5
C1 D 6
C1 H 12
L1 D 10
C1 L1 20
2 1 4 6
100 70
H L1 5
C1 L1 12
C1 D 11
C2 L1 7
C2 D 15
L1 D 8
0 0 0 0
Output
1
-2
Submitted Solution:
```
from itertools import combinations
from heapq import heappop, heappush
import sys
sys.setrecursionlimit(1000000)
INF = 10 ** 20
def convert(s, m, n):
if s == "H":
return 0
if s == "D":
return 1
if s[0] == "C":
return int(s[1]) + 1
if s[0] == "L":
return int(s[1]) + m + 1
def get_cost(start, m, n, edges):
cost = [INF] * (m + n + 2)
cost[start] = 0
que = []
heappush(que, (0, start))
while que:
total, node = heappop(que)
for dist, to in edges[node]:
if cost[to] > total + dist:
cost[to] = total + dist
#if not (2 <= to <= m + 1):
heappush(que, (total + dist, to))
return cost
def shortest_path(start, goal, rest, cakes_dist, dic):
if not rest:
return cakes_dist[start][goal]
if (start, rest) in dic:
return dic[(start, rest)]
ret = INF
for to in rest:
ret = min(ret, shortest_path(to, goal, tuple((i for i in rest if i != to)), cakes_dist, dic) + cakes_dist[start][to])
dic[(start, rest)] = ret
return ret
while True:
m, n, k, d = map(int, input().split())
if m == 0:
break
clst = list(map(int, input().split()))
"""
Home ... 0
D ... 1
Cake ... 2, 3, ... m + 1
Land ... m + 2, m + 3, ... m + n + 1
"""
edges = [[] for _ in range(m + n + 2)]
for _ in range(d):
s, t, e = input().split()
e = int(e)
s = convert(s, m, n)
t = convert(t, m, n)
edges[s].append((e, t))
edges[t].append((e, s))
cakes_dist = [[INF] * (m + 2) for _ in range(m + 2)]
for start in range(m + 2):
cost = get_cost(start, m, n, edges)
for to in range(m + 2):
if to != start:
cakes_dist[start][to] = cost[to]
"""
now ... 現在いる点
rest ... 残りのめぐる点
dic[(now, rest)] ... 現在いる点、残りの点をまわる時の最小距離
dic[(now, rest)] = min(cakes_dist[now][to] + dic[(to, rest - to)] for to in rest)
"""
dic = {}
ans = INF
cakes = [i for i in range(2, m + 2)]
for num in range(m + 1):
for rest in combinations(cakes, num):
cal = sum([clst[i - 2] for i in rest])
ans = min(ans, shortest_path(0, 1, rest, cakes_dist, dic) * k - cal)
print(ans)
``` | instruction | 0 | 46,113 | 9 | 92,226 |
No | output | 1 | 46,113 | 9 | 92,227 |
Provide a correct Python 3 solution for this coding contest problem.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four | instruction | 0 | 46,908 | 9 | 93,816 |
"Correct Solution:
```
input()
print("Four") if 'Y' in input() else print("Three")
``` | output | 1 | 46,908 | 9 | 93,817 |
Provide a correct Python 3 solution for this coding contest problem.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four | instruction | 0 | 46,909 | 9 | 93,818 |
"Correct Solution:
```
input()
print("Three" if len(set(input().split()))==3 else "Four")
``` | output | 1 | 46,909 | 9 | 93,819 |
Provide a correct Python 3 solution for this coding contest problem.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four | instruction | 0 | 46,910 | 9 | 93,820 |
"Correct Solution:
```
input();print("TFhoruere"["Y" in input()::2])
``` | output | 1 | 46,910 | 9 | 93,821 |
Provide a correct Python 3 solution for this coding contest problem.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four | instruction | 0 | 46,911 | 9 | 93,822 |
"Correct Solution:
```
input()
print(["Three","Four"]["Y" in input()])
``` | output | 1 | 46,911 | 9 | 93,823 |
Provide a correct Python 3 solution for this coding contest problem.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four | instruction | 0 | 46,912 | 9 | 93,824 |
"Correct Solution:
```
_ = input()
s = input().split()
print('Four' if 'Y' in s else 'Three')
``` | output | 1 | 46,912 | 9 | 93,825 |
Provide a correct Python 3 solution for this coding contest problem.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four | instruction | 0 | 46,913 | 9 | 93,826 |
"Correct Solution:
```
input();print('TFhoruere'['Y'in input()::2])
``` | output | 1 | 46,913 | 9 | 93,827 |
Provide a correct Python 3 solution for this coding contest problem.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four | instruction | 0 | 46,914 | 9 | 93,828 |
"Correct Solution:
```
_ = input()
s = set(input().split())
print("TFhoruere"[len(s)==4::2])
``` | output | 1 | 46,914 | 9 | 93,829 |
Provide a correct Python 3 solution for this coding contest problem.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four | instruction | 0 | 46,915 | 9 | 93,830 |
"Correct Solution:
```
n = int(input())
s = input().split()
print("Four" if "Y" in s else "Three")
``` | output | 1 | 46,915 | 9 | 93,831 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four
Submitted Solution:
```
n,a=open(0);print("TFhoruere"["Y"in a::2])
``` | instruction | 0 | 46,916 | 9 | 93,832 |
Yes | output | 1 | 46,916 | 9 | 93,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four
Submitted Solution:
```
input()
a = set(input().split())
print('Four' if len(a) == 4 else 'Three')
``` | instruction | 0 | 46,917 | 9 | 93,834 |
Yes | output | 1 | 46,917 | 9 | 93,835 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four
Submitted Solution:
```
n=input()
if "Y" in input():
print("Four")
else:
print("Three")
``` | instruction | 0 | 46,918 | 9 | 93,836 |
Yes | output | 1 | 46,918 | 9 | 93,837 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four
Submitted Solution:
```
n = input()
w = set(input().split())
print ('Three' if len(w)==3 else 'Four')
``` | instruction | 0 | 46,919 | 9 | 93,838 |
Yes | output | 1 | 46,919 | 9 | 93,839 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Japan, people make offerings called hina arare, colorful crackers, on March 3.
We have a bag that contains N hina arare. (From here, we call them arare.)
It is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.
We have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: `P`, white: `W`, green: `G`, yellow: `Y`.
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Constraints
* 1 \leq N \leq 100
* S_i is `P`, `W`, `G` or `Y`.
* There always exist i, j and k such that S_i=`P`, S_j=`W` and S_k=`G`.
Input
Input is given from Standard Input in the following format:
N
S_1 S_2 ... S_N
Output
If the number of colors of the arare in the bag was three, print `Three`; if the number of colors was four, print `Four`.
Examples
Input
6
G W Y P Y W
Output
Four
Input
9
G W W G P W P G G
Output
Three
Input
8
P Y W G Y W Y Y
Output
Four
Submitted Solution:
```
N = int(input())
ans = False
for i in range(N):
s = input()
if(s == "Y"):
ans = True
if(ans):
print("Four")
else:
print("Three")
``` | instruction | 0 | 46,920 | 9 | 93,840 |
No | output | 1 | 46,920 | 9 | 93,841 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being Santa Claus is very difficult. Sometimes you have to deal with difficult situations.
Today Santa Claus came to the holiday and there were m children lined up in front of him. Let's number them from 1 to m. Grandfather Frost knows n spells. The i-th spell gives a candy to every child whose place is in the [L_i, R_i] range. Each spell can be used at most once. It is also known that if all spells are used, each child will receive at most k candies.
It is not good for children to eat a lot of sweets, so each child can eat no more than one candy, while the remaining candies will be equally divided between his (or her) Mom and Dad. So it turns out that if a child would be given an even amount of candies (possibly zero), then he (or she) will be unable to eat any candies and will go sad. However, the rest of the children (who received an odd number of candies) will be happy.
Help Santa Claus to know the maximum number of children he can make happy by casting some of his spells.
Input
The first line contains three integers of n, m, and k (1 ≤ n ≤ 100 000, 1 ≤ m ≤ 10^9, 1 ≤ k ≤ 8) — the number of spells, the number of children and the upper limit on the number of candy a child can get if all spells are used, respectively.
This is followed by n lines, each containing integers L_i and R_i (1 ≤ L_i ≤ R_i ≤ m) — the parameters of the i spell.
Output
Print a single integer — the maximum number of children that Santa can make happy.
Example
Input
3 5 3
1 3
2 4
3 5
Output
4
Note
In the first example, Santa should apply the first and third spell. In this case all children will be happy except the third.
Submitted Solution:
```
n,m,k=map(int,input().split())
li=[0]*(m+1)
odd=[0]*(m+1)
while(n>0):
l,r=map(int,input().split())
prev_odd=sum(odd[l-1:r])
prev_even=(r-l)-prev_odd+1
for i in range(l-1,r):
if prev_even>=prev_odd:
maximum=max(odd[l-1:r])
if maximum+1<=k:
li[i]=li[i]+1
if li[i]%2==0 and odd[i]>=0:
odd[i]=odd[i]-1
else:
odd[i]=odd[i]+1
else:
break
else:
break
n=n-1
print(sum(odd))
``` | instruction | 0 | 47,137 | 9 | 94,274 |
No | output | 1 | 47,137 | 9 | 94,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being Santa Claus is very difficult. Sometimes you have to deal with difficult situations.
Today Santa Claus came to the holiday and there were m children lined up in front of him. Let's number them from 1 to m. Grandfather Frost knows n spells. The i-th spell gives a candy to every child whose place is in the [L_i, R_i] range. Each spell can be used at most once. It is also known that if all spells are used, each child will receive at most k candies.
It is not good for children to eat a lot of sweets, so each child can eat no more than one candy, while the remaining candies will be equally divided between his (or her) Mom and Dad. So it turns out that if a child would be given an even amount of candies (possibly zero), then he (or she) will be unable to eat any candies and will go sad. However, the rest of the children (who received an odd number of candies) will be happy.
Help Santa Claus to know the maximum number of children he can make happy by casting some of his spells.
Input
The first line contains three integers of n, m, and k (1 ≤ n ≤ 100 000, 1 ≤ m ≤ 10^9, 1 ≤ k ≤ 8) — the number of spells, the number of children and the upper limit on the number of candy a child can get if all spells are used, respectively.
This is followed by n lines, each containing integers L_i and R_i (1 ≤ L_i ≤ R_i ≤ m) — the parameters of the i spell.
Output
Print a single integer — the maximum number of children that Santa can make happy.
Example
Input
3 5 3
1 3
2 4
3 5
Output
4
Note
In the first example, Santa should apply the first and third spell. In this case all children will be happy except the third.
Submitted Solution:
```
def number_of_bits(a):
res=0
for i in bin(a):
if(i=='1'):
res+=1
return res
def process():
spells,students,choclates=list(map(int,input().split()))
s=0
for i in range(spells):
l,r=list(map(int,input().split()))
bits_l=(2**(students-l+1))-1
bits_r=(2**(students-r))-1
temp=bits_l^bits_r
s1=s^temp
if(number_of_bits(s1)>number_of_bits(s)):
s=s1
if(choclates%2==0):
print(0)
return
print(number_of_bits(s))
process()
``` | instruction | 0 | 47,138 | 9 | 94,276 |
No | output | 1 | 47,138 | 9 | 94,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being Santa Claus is very difficult. Sometimes you have to deal with difficult situations.
Today Santa Claus came to the holiday and there were m children lined up in front of him. Let's number them from 1 to m. Grandfather Frost knows n spells. The i-th spell gives a candy to every child whose place is in the [L_i, R_i] range. Each spell can be used at most once. It is also known that if all spells are used, each child will receive at most k candies.
It is not good for children to eat a lot of sweets, so each child can eat no more than one candy, while the remaining candies will be equally divided between his (or her) Mom and Dad. So it turns out that if a child would be given an even amount of candies (possibly zero), then he (or she) will be unable to eat any candies and will go sad. However, the rest of the children (who received an odd number of candies) will be happy.
Help Santa Claus to know the maximum number of children he can make happy by casting some of his spells.
Input
The first line contains three integers of n, m, and k (1 ≤ n ≤ 100 000, 1 ≤ m ≤ 10^9, 1 ≤ k ≤ 8) — the number of spells, the number of children and the upper limit on the number of candy a child can get if all spells are used, respectively.
This is followed by n lines, each containing integers L_i and R_i (1 ≤ L_i ≤ R_i ≤ m) — the parameters of the i spell.
Output
Print a single integer — the maximum number of children that Santa can make happy.
Example
Input
3 5 3
1 3
2 4
3 5
Output
4
Note
In the first example, Santa should apply the first and third spell. In this case all children will be happy except the third.
Submitted Solution:
```
n,m,k=map(int,input().split())
child=[0 for i in range(m)]
for i in range(0,k):
l,r=map(int,input().split())
while(l<=r):
child[l-1]+=1
l+=1
child=[i-1 for i in child]
count=0
for i in child:
if i==0 or i%2!=0:
count+=1
print(count)
``` | instruction | 0 | 47,139 | 9 | 94,278 |
No | output | 1 | 47,139 | 9 | 94,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being Santa Claus is very difficult. Sometimes you have to deal with difficult situations.
Today Santa Claus came to the holiday and there were m children lined up in front of him. Let's number them from 1 to m. Grandfather Frost knows n spells. The i-th spell gives a candy to every child whose place is in the [L_i, R_i] range. Each spell can be used at most once. It is also known that if all spells are used, each child will receive at most k candies.
It is not good for children to eat a lot of sweets, so each child can eat no more than one candy, while the remaining candies will be equally divided between his (or her) Mom and Dad. So it turns out that if a child would be given an even amount of candies (possibly zero), then he (or she) will be unable to eat any candies and will go sad. However, the rest of the children (who received an odd number of candies) will be happy.
Help Santa Claus to know the maximum number of children he can make happy by casting some of his spells.
Input
The first line contains three integers of n, m, and k (1 ≤ n ≤ 100 000, 1 ≤ m ≤ 10^9, 1 ≤ k ≤ 8) — the number of spells, the number of children and the upper limit on the number of candy a child can get if all spells are used, respectively.
This is followed by n lines, each containing integers L_i and R_i (1 ≤ L_i ≤ R_i ≤ m) — the parameters of the i spell.
Output
Print a single integer — the maximum number of children that Santa can make happy.
Example
Input
3 5 3
1 3
2 4
3 5
Output
4
Note
In the first example, Santa should apply the first and third spell. In this case all children will be happy except the third.
Submitted Solution:
```
n,m,k=map(int, input().split())
l=[False for i in range(m+1)]
maxx=0
for i in range(n):
L,R=map(int ,input().split())
count=l[:L].count(False)
for i in range(L,R+1):
if l[i]:
l[i]=False
else:
l[i]=True
count+=1
maxx=max(maxx,count)
print(count)
``` | instruction | 0 | 47,140 | 9 | 94,280 |
No | output | 1 | 47,140 | 9 | 94,281 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01 | instruction | 0 | 47,486 | 9 | 94,972 |
Tags: combinatorics
Correct Solution:
```
_=input()
pos_1=[]
for i,e in enumerate(input().split()):
if e=='1':
pos_1.append(i)
if not pos_1:
print(0)
elif len(pos_1)==1:
print(1)
else:
tot=1
for i in range(1,len(pos_1)):
tot*=pos_1[i]-pos_1[i-1]
print(tot)
``` | output | 1 | 47,486 | 9 | 94,973 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01 | instruction | 0 | 47,487 | 9 | 94,974 |
Tags: combinatorics
Correct Solution:
```
n = int(input())
chocolate = list(map(int, input().split()))
prev = 0
parts = 1
start = False
count = 0
nut = False
for c in chocolate:
if c == 0:
if start:
count += 1
prev = 0
else:
start = True
nut = True
if prev != 1:
parts *= (count+1)
count = 0
prev = 1
if nut:
print(parts)
else:
print(0)
``` | output | 1 | 47,487 | 9 | 94,975 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01 | instruction | 0 | 47,488 | 9 | 94,976 |
Tags: combinatorics
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
if len(a) == a.count(0):
print(0)
else:
r = 1
t = []
for i, b in enumerate(a):
if b == 1:
t += [i]
for i in range(len(t)-1):
r *= t[i+1]-t[i]
print(r)
``` | output | 1 | 47,488 | 9 | 94,977 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01 | instruction | 0 | 47,489 | 9 | 94,978 |
Tags: combinatorics
Correct Solution:
```
n=int(input())
a=[int(i) for i in input().split()]
ans=1
prev=-1
i=0
while(i<n):
if(a[i]==1):
prev=i
i+=1
break
i+=1
#print(i,ans)
while(i<n):
if(a[i]==1):
ans*=(i-prev)
prev=i
i+=1
if(prev==-1):
print(0)
else:
print(ans)
``` | output | 1 | 47,489 | 9 | 94,979 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01 | instruction | 0 | 47,490 | 9 | 94,980 |
Tags: combinatorics
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
result = 1
flag = False
res = 1
for i in a:
if i == 1 and flag:
result *= res
res = 1
if i == 1:
flag = True
if i == 0 and flag:
res += 1
if not flag:
print(0)
else:
print(result)
``` | output | 1 | 47,490 | 9 | 94,981 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01 | instruction | 0 | 47,491 | 9 | 94,982 |
Tags: combinatorics
Correct Solution:
```
#!/usr/bin/python3
n = int(input())
a = list(tuple(map(int, input().split())))
while len(a) > 0 and a[0] == 0:
a.pop(0)
while len(a) > 0 and a[-1] == 0:
a.pop()
if len(a) == 0:
print("0")
else:
res = 1
num = 1
for i in a:
if i == 0:
num += 1
if i == 1:
res *= num
num = 1
print(str(res))
``` | output | 1 | 47,491 | 9 | 94,983 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01 | instruction | 0 | 47,492 | 9 | 94,984 |
Tags: combinatorics
Correct Solution:
```
n = int(input())
l = list(map(int,input().split()))
ans = 1
p = -1
for i in range(len(l)):
if l[i] == 1:
if p == -1:
p = i
continue
if i-p:
ans *= i-p
p = i
if p != -1:
print(ans)
else:
print(0)
``` | output | 1 | 47,492 | 9 | 94,985 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01 | instruction | 0 | 47,493 | 9 | 94,986 |
Tags: combinatorics
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
# from math import *
from collections import *
# from fractions import *
# from heapq import*
from bisect import *
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
ALPHA='abcdefghijklmnopqrstuvwxyz/'
M=1000000007
EPS=1e-6
def Ceil(a,b): return a//b+int(a%b>0)
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
# vsInput()
n=Int()
a=array()
i=0
while(i<n and not a[i]): i+=1
a=a[i:]
a=a[::-1]
i=0
while(i<len(a) and not a[i]): i+=1
a=a[i:]
# print(a)
ans=0
if(len(a)): ans=1
last=0
for i in range(1,len(a)):
if(a[i]):
ans*=(i-last)
last=i
print(ans)
``` | output | 1 | 47,493 | 9 | 94,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01
Submitted Solution:
```
def ways(s):
if len(s)==1:
return 1
count=1
i=1
while True:
if s[i]=='0':
count+=1
else:
break
i+=1
return count*ways(s[i::])
n=int(input())
s=input()
s=s.replace(" ","")
if "1" in s:
s=s[s.index('1'):s.rindex('1')+1:]
print(ways(s))
else:
print('0')
``` | instruction | 0 | 47,494 | 9 | 94,988 |
Yes | output | 1 | 47,494 | 9 | 94,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01
Submitted Solution:
```
n=int(input())
s=list(map(int,input().split()))
if s.count(1)==0:
print("0")
else:
ans=1
sp=0
f=True
for i in s:
if i==0:
sp+=1
elif f:
f=False
sp=1
else:
ans*=sp
sp=1
print(ans)
``` | instruction | 0 | 47,495 | 9 | 94,990 |
Yes | output | 1 | 47,495 | 9 | 94,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01
Submitted Solution:
```
n = int(input())
L = input().split()
Flag = False
indl = -1
indr = -1
ans = 1
t = 0
for i in range(len(L)):
if L[i] == '1' and Flag != True :
indl = i
Flag = True
if L[i] == '1' :
indr = i
if indl == -1 and indr == -1:
print("0")
else:
for i in range(indl+1,indr+1):
if L[i] == '0':
t += 1
else:
ans = ans * (t + 1)
t = 0
print(ans)
``` | instruction | 0 | 47,496 | 9 | 94,992 |
Yes | output | 1 | 47,496 | 9 | 94,993 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01
Submitted Solution:
```
n=int(input())
l=list(map(int,input().split()))
if not 1 in l:
print(0)
else:
j=l.index(1)
s=1
for i in range(j+1,n):
if l[i]==1:
s*=i-j
j=i
print(s)
``` | instruction | 0 | 47,497 | 9 | 94,994 |
Yes | output | 1 | 47,497 | 9 | 94,995 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01
Submitted Solution:
```
n = int(input())
string = input()
count = 0
total=1
arr=[]
for i in string:
if(count==0):
if(i=="1"):count=1
else:
if(i=="1"):
total*=count
count=1
else:
count+=1
print(total)
``` | instruction | 0 | 47,498 | 9 | 94,996 |
No | output | 1 | 47,498 | 9 | 94,997 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01
Submitted Solution:
```
n = int(input())
a = [int(i) for i in input().split()]
f = False
c = []
k = 1
for v in a:
if v == 0:
k += 1
else:
if f:
c += [k]
k = 1
f = True
p = 1
for v in c:
p *= v
print(p)
``` | instruction | 0 | 47,499 | 9 | 94,998 |
No | output | 1 | 47,499 | 9 | 94,999 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01
Submitted Solution:
```
n=int(input())
arr=list(map(int,input().split()))
cut=sum(arr)
if cut==1 or cut==0:
print(0)
else:
li=[]
for i in range(n):
if arr[i]&1:
li.append(i)
ans=1
for i in range(1,len(li)):
ans*=(li[i]-li[i-1])
print(ans)
``` | instruction | 0 | 47,500 | 9 | 95,000 |
No | output | 1 | 47,500 | 9 | 95,001 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob loves everything sweet. His favorite chocolate bar consists of pieces, each piece may contain a nut. Bob wants to break the bar of chocolate into multiple pieces so that each part would contain exactly one nut and any break line goes between two adjacent pieces.
You are asked to calculate the number of ways he can do it. Two ways to break chocolate are considered distinct if one of them contains a break between some two adjacent pieces and the other one doesn't.
Please note, that if Bob doesn't make any breaks, all the bar will form one piece and it still has to have exactly one nut.
Input
The first line of the input contains integer n (1 ≤ n ≤ 100) — the number of pieces in the chocolate bar.
The second line contains n integers ai (0 ≤ ai ≤ 1), where 0 represents a piece without the nut and 1 stands for a piece with the nut.
Output
Print the number of ways to break the chocolate into multiple parts so that each part would contain exactly one nut.
Examples
Input
3
0 1 0
Output
1
Input
5
1 0 1 0 1
Output
4
Note
In the first sample there is exactly one nut, so the number of ways equals 1 — Bob shouldn't make any breaks.
In the second sample you can break the bar in four ways:
10|10|1
1|010|1
10|1|01
1|01|01
Submitted Solution:
```
n= int(input())
s=[int(i) for i in input().split()]
l=[]
for i in range(n):
if s[i]==1:
l.append(i)
k=1
for i in range(len(l)-1):
k= k*(l[i+1]-l[i])
print(k)
``` | instruction | 0 | 47,501 | 9 | 95,002 |
No | output | 1 | 47,501 | 9 | 95,003 |
Provide a correct Python 3 solution for this coding contest problem.
At the pancake shop you work for, pancake dough is lined up in a row on an elongated iron plate and baked. Pancakes can be completed by turning them over with a spatula several times. How many times you turn it over to complete it depends on the pancake.
Since the spatula is large, two adjacent pancakes will be turned over at the same time. At this time, the positions of these two sheets do not switch. However, not only can you flip both ends together with the pancake next to you, but you can also flip just one. After turning over all the pancakes more than the required number of times, remove them all at once from the iron plate and you're done.
I don't want to flip the pancakes too much, as turning them over more than necessary will make them harder. So you wanted to find a way to minimize the total number of times each pancake was flipped over by the time it was all finished.
When each pancake is given the number of pancakes on the iron plate and how many times it must be turned over before it is completed, the number of times each pancake is turned over before it is completed (manipulate the spatula). Create a program that calculates the minimum sum of (not the number of times).
Input
The input is given in the following format.
N
p1 p2 ... pN
The number of pancakes N (3 ≤ N ≤ 5000) is given on the first line. The second line gives the number of flips pi (0 ≤ pi ≤ 3) required to complete each pancake.
Output
Output the minimum value of the total number of times each pancake is turned inside out on one line until all are completed.
Examples
Input
3
1 2 1
Output
4
Input
3
0 3 0
Output
6 | instruction | 0 | 47,866 | 9 | 95,732 |
"Correct Solution:
```
import sys
sys.setrecursionlimit(10**6)
n = int(input())
*P, = map(int, input().split())
memo = {(n-1, i): i for i in range(P[-1]+1)}
def dfs(pos, t):
if (pos, t) in memo:
return memo[pos, t]
res = memo[pos, t] = dfs(pos+1, max(0, P[pos+1]-t)) + t*2
return res
print(min(dfs(0, P[0]-i)+i for i in range(P[0]+1)))
``` | output | 1 | 47,866 | 9 | 95,733 |
Provide a correct Python 3 solution for this coding contest problem.
At the pancake shop you work for, pancake dough is lined up in a row on an elongated iron plate and baked. Pancakes can be completed by turning them over with a spatula several times. How many times you turn it over to complete it depends on the pancake.
Since the spatula is large, two adjacent pancakes will be turned over at the same time. At this time, the positions of these two sheets do not switch. However, not only can you flip both ends together with the pancake next to you, but you can also flip just one. After turning over all the pancakes more than the required number of times, remove them all at once from the iron plate and you're done.
I don't want to flip the pancakes too much, as turning them over more than necessary will make them harder. So you wanted to find a way to minimize the total number of times each pancake was flipped over by the time it was all finished.
When each pancake is given the number of pancakes on the iron plate and how many times it must be turned over before it is completed, the number of times each pancake is turned over before it is completed (manipulate the spatula). Create a program that calculates the minimum sum of (not the number of times).
Input
The input is given in the following format.
N
p1 p2 ... pN
The number of pancakes N (3 ≤ N ≤ 5000) is given on the first line. The second line gives the number of flips pi (0 ≤ pi ≤ 3) required to complete each pancake.
Output
Output the minimum value of the total number of times each pancake is turned inside out on one line until all are completed.
Examples
Input
3
1 2 1
Output
4
Input
3
0 3 0
Output
6 | instruction | 0 | 47,867 | 9 | 95,734 |
"Correct Solution:
```
n = int(input())
pancake = list(map(int, input().split()))
ans = 10**9
for i in range(4):
cnt = [0] * n
cnt[0] += i
for j in range(n-1):
diff = pancake[j] - cnt[j]
if diff > 0:
cnt[j] += diff
cnt[j+1] += diff
diff = pancake[n-1] - cnt[n-1]
if diff > 0:
cnt[n-1] += diff
if ans > sum(cnt):
ans = sum(cnt)
print(ans)
``` | output | 1 | 47,867 | 9 | 95,735 |
Provide a correct Python 3 solution for this coding contest problem.
At the pancake shop you work for, pancake dough is lined up in a row on an elongated iron plate and baked. Pancakes can be completed by turning them over with a spatula several times. How many times you turn it over to complete it depends on the pancake.
Since the spatula is large, two adjacent pancakes will be turned over at the same time. At this time, the positions of these two sheets do not switch. However, not only can you flip both ends together with the pancake next to you, but you can also flip just one. After turning over all the pancakes more than the required number of times, remove them all at once from the iron plate and you're done.
I don't want to flip the pancakes too much, as turning them over more than necessary will make them harder. So you wanted to find a way to minimize the total number of times each pancake was flipped over by the time it was all finished.
When each pancake is given the number of pancakes on the iron plate and how many times it must be turned over before it is completed, the number of times each pancake is turned over before it is completed (manipulate the spatula). Create a program that calculates the minimum sum of (not the number of times).
Input
The input is given in the following format.
N
p1 p2 ... pN
The number of pancakes N (3 ≤ N ≤ 5000) is given on the first line. The second line gives the number of flips pi (0 ≤ pi ≤ 3) required to complete each pancake.
Output
Output the minimum value of the total number of times each pancake is turned inside out on one line until all are completed.
Examples
Input
3
1 2 1
Output
4
Input
3
0 3 0
Output
6 | instruction | 0 | 47,868 | 9 | 95,736 |
"Correct Solution:
```
def solve():
from sys import stdin
f_i = stdin
N = int(f_i.readline())
P = list(map(int, f_i.readline().split()))
left = P[0]
ans = N * 6
for i in range(left + 1):
tP = P[:]
tP[0] -= i
t_ans = i
for j in range(N - 1):
tpj = tP[j]
if tpj > 0:
tP[j + 1] -= tpj
t_ans += 2 * tpj
if tP[-1] > 0:
t_ans += tP[-1]
if t_ans < ans:
ans = t_ans
print(ans)
solve()
``` | output | 1 | 47,868 | 9 | 95,737 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
At the pancake shop you work for, pancake dough is lined up in a row on an elongated iron plate and baked. Pancakes can be completed by turning them over with a spatula several times. How many times you turn it over to complete it depends on the pancake.
Since the spatula is large, two adjacent pancakes will be turned over at the same time. At this time, the positions of these two sheets do not switch. However, not only can you flip both ends together with the pancake next to you, but you can also flip just one. After turning over all the pancakes more than the required number of times, remove them all at once from the iron plate and you're done.
I don't want to flip the pancakes too much, as turning them over more than necessary will make them harder. So you wanted to find a way to minimize the total number of times each pancake was flipped over by the time it was all finished.
When each pancake is given the number of pancakes on the iron plate and how many times it must be turned over before it is completed, the number of times each pancake is turned over before it is completed (manipulate the spatula). Create a program that calculates the minimum sum of (not the number of times).
Input
The input is given in the following format.
N
p1 p2 ... pN
The number of pancakes N (3 ≤ N ≤ 5000) is given on the first line. The second line gives the number of flips pi (0 ≤ pi ≤ 3) required to complete each pancake.
Output
Output the minimum value of the total number of times each pancake is turned inside out on one line until all are completed.
Examples
Input
3
1 2 1
Output
4
Input
3
0 3 0
Output
6
Submitted Solution:
```
'''aizu 0340
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0340
'''
# encoding: 'utf-8'
def main():
input()
hill = [int(x) for x in input().split()]
count = 0
while any([x > 0 for x in hill]):
hill, c = step(hill)
count += c
# print(count, hill)
print(count)
def step(hill):
c = 0
highest = max(hill)
for (i, _) in ((i, x) for (i, x) in enumerate(hill) if x == highest):
if 0 < i < len(hill)-1:
if hill[i] % 2 == hill[i-1] % 2:
hill[i-1] -= 1
elif hill[i] % 2 == hill[i+1] % 2:
hill[i+1] -= 1
else:
if hill[i-1] > hill[i+1]:
hill[i-1] -= 1
else:
hill[i+1] -= 1
hill[i] -= 1
c += 2
elif i == 0:
if hill[1] > 0:
hill[1] -= 1
c += 1
hill[0] -= 1
c += 1
elif i == len(hill) - 1:
if hill[-2] > 0:
hill[-2] -= 1
c += 1
hill[-1] -= 1
c += 1
else:
raise Exception("unreachable")
return (hill, c)
if __name__ == '__main__':
main()
``` | instruction | 0 | 47,869 | 9 | 95,738 |
No | output | 1 | 47,869 | 9 | 95,739 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
At the pancake shop you work for, pancake dough is lined up in a row on an elongated iron plate and baked. Pancakes can be completed by turning them over with a spatula several times. How many times you turn it over to complete it depends on the pancake.
Since the spatula is large, two adjacent pancakes will be turned over at the same time. At this time, the positions of these two sheets do not switch. However, not only can you flip both ends together with the pancake next to you, but you can also flip just one. After turning over all the pancakes more than the required number of times, remove them all at once from the iron plate and you're done.
I don't want to flip the pancakes too much, as turning them over more than necessary will make them harder. So you wanted to find a way to minimize the total number of times each pancake was flipped over by the time it was all finished.
When each pancake is given the number of pancakes on the iron plate and how many times it must be turned over before it is completed, the number of times each pancake is turned over before it is completed (manipulate the spatula). Create a program that calculates the minimum sum of (not the number of times).
Input
The input is given in the following format.
N
p1 p2 ... pN
The number of pancakes N (3 ≤ N ≤ 5000) is given on the first line. The second line gives the number of flips pi (0 ≤ pi ≤ 3) required to complete each pancake.
Output
Output the minimum value of the total number of times each pancake is turned inside out on one line until all are completed.
Examples
Input
3
1 2 1
Output
4
Input
3
0 3 0
Output
6
Submitted Solution:
```
'''aizu 0340
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0340
'''
# encoding: 'utf-8'
def main():
input()
hill = [int(x) for x in input().split()]
_hill = [0] * len(hill)
count = 0
while hill != _hill:
print(count, hill)
_hill = hill
hill, c = step(hill)
count += c
count += finalize(hill)
print(count)
def step(hill):
c = 0
for i in range(len(hill)-1):
if hill[i] > 0 and hill[i+1] >0:
scraped = min(hill[i], hill[i+1])
hill[i] -= scraped
hill[i+1] -= scraped
c += 2
return (hill, c)
def finalize(hill):
c = hill[0] + hill[-1] + sum(hill[1:-1])*2
return c
if __name__ == '__main__':
main()
``` | instruction | 0 | 47,870 | 9 | 95,740 |
No | output | 1 | 47,870 | 9 | 95,741 |
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