message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Bubble Cup hypothesis stood unsolved for 130 years. Who ever proves the hypothesis will be regarded as one of the greatest mathematicians of our time! A famous mathematician Jerry Mao managed to reduce the hypothesis to this problem:
Given a number m, how many polynomials P with coefficients in set {\{0,1,2,3,4,5,6,7\}} have: P(2)=m?
Help Jerry Mao solve the long standing problem!
Input
The first line contains a single integer t (1 ≤ t ≤ 5⋅ 10^5) - number of test cases.
On next line there are t numbers, m_i (1 ≤ m_i ≤ 10^{18}) - meaning that in case i you should solve for number m_i.
Output
For each test case i, print the answer on separate lines: number of polynomials P as described in statement such that P(2)=m_i, modulo 10^9 + 7.
Example
Input
2
2 4
Output
2
4
Note
In first case, for m=2, polynomials that satisfy the constraint are x and 2.
In second case, for m=4, polynomials that satisfy the constraint are x^2, x + 2, 2x and 4.
Submitted Solution:
```
t = int(input())
a = list(map(int, input().split()))
out = []
for n in a:
ans = (n//2 + 2)
ans = ans*ans
ans //= 4
out.append(ans)
print(' '.join(str(x) for x in out))
``` | instruction | 0 | 50,692 | 9 | 101,384 |
No | output | 1 | 50,692 | 9 | 101,385 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Bubble Cup hypothesis stood unsolved for 130 years. Who ever proves the hypothesis will be regarded as one of the greatest mathematicians of our time! A famous mathematician Jerry Mao managed to reduce the hypothesis to this problem:
Given a number m, how many polynomials P with coefficients in set {\{0,1,2,3,4,5,6,7\}} have: P(2)=m?
Help Jerry Mao solve the long standing problem!
Input
The first line contains a single integer t (1 ≤ t ≤ 5⋅ 10^5) - number of test cases.
On next line there are t numbers, m_i (1 ≤ m_i ≤ 10^{18}) - meaning that in case i you should solve for number m_i.
Output
For each test case i, print the answer on separate lines: number of polynomials P as described in statement such that P(2)=m_i, modulo 10^9 + 7.
Example
Input
2
2 4
Output
2
4
Note
In first case, for m=2, polynomials that satisfy the constraint are x and 2.
In second case, for m=4, polynomials that satisfy the constraint are x^2, x + 2, 2x and 4.
Submitted Solution:
```
# ===============================================================================================
# importing some useful libraries.
from __future__ import division, print_function
from fractions import Fraction
import sys
import os
from io import BytesIO, IOBase
from itertools import *
import bisect
from heapq import *
from math import ceil, floor
from copy import *
from collections import deque, defaultdict
from collections import Counter as counter # Counter(list) return a dict with {key: count}
from itertools import combinations # if a = [1,2,3] then print(list(comb(a,2))) -----> [(1, 2), (1, 3), (2, 3)]
from itertools import permutations as permutate
from bisect import bisect_left as bl
from operator import *
# If the element is already present in the list,
# the left most position where element has to be inserted is returned.
from bisect import bisect_right as br
from bisect import bisect
# If the element is already present in the list,
# the right most position where element has to be inserted is returned
# ==============================================================================================
# fast I/O region
BUFSIZE = 8192
from sys import stderr
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
"""Prints the values to a stream, or to sys.stdout by default."""
sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
if sys.version_info[0] < 3:
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
# inp = lambda: sys.stdin.readline().rstrip("\r\n")
# ===============================================================================================
### START ITERATE RECURSION ###
from types import GeneratorType
def iterative(f, stack=[]):
def wrapped_func(*args, **kwargs):
if stack: return f(*args, **kwargs)
to = f(*args, **kwargs)
while True:
if type(to) is GeneratorType:
stack.append(to)
to = next(to)
continue
stack.pop()
if not stack: break
to = stack[-1].send(to)
return to
return wrapped_func
#### END ITERATE RECURSION ####
# ===============================================================================================
# some shortcuts
mod = 1000000007
def inp(): return sys.stdin.readline().rstrip("\r\n") # for fast input
def out(var): sys.stdout.write(str(var)) # for fast output, always take string
def lis(): return list(map(int, inp().split()))
def stringlis(): return list(map(str, inp().split()))
def sep(): return map(int, inp().split())
def strsep(): return map(str, inp().split())
def fsep(): return map(float, inp().split())
def nextline(): out("\n") # as stdout.write always print sring.
def testcase(t):
for p in range(t):
solve()
def pow(x, y, p):
res = 1 # Initialize result
x = x % p # Update x if it is more , than or equal to p
if (x == 0):
return 0
while (y > 0):
if ((y & 1) == 1): # If y is odd, multiply, x with result
res = (res * x) % p
y = y >> 1 # y = y/2
x = (x * x) % p
return res
from functools import reduce
def factors(n):
return set(reduce(list.__add__,
([i, n // i] for i in range(1, int(n ** 0.5) + 1) if n % i == 0)))
def gcd(a, b):
if a == b: return a
while b > 0: a, b = b, a % b
return a
# discrete binary search
# minimise:
# def search():
# l = 0
# r = 10 ** 15
#
# for i in range(200):
# if isvalid(l):
# return l
# if l == r:
# return l
# m = (l + r) // 2
# if isvalid(m) and not isvalid(m - 1):
# return m
# if isvalid(m):
# r = m + 1
# else:
# l = m
# return m
# maximise:
# def search():
# l = 0
# r = 10 ** 15
#
# for i in range(200):
# # print(l,r)
# if isvalid(r):
# return r
# if l == r:
# return l
# m = (l + r) // 2
# if isvalid(m) and not isvalid(m + 1):
# return m
# if isvalid(m):
# l = m
# else:
# r = m - 1
# return m
##to find factorial and ncr
# N=100000
# mod = 10**9 +7
# fac = [1, 1]
# finv = [1, 1]
# inv = [0, 1]
#
# for i in range(2, N + 1):
# fac.append((fac[-1] * i) % mod)
# inv.append(mod - (inv[mod % i] * (mod // i) % mod))
# finv.append(finv[-1] * inv[-1] % mod)
#
#
# def comb(n, r):
# if n < r:
# return 0
# else:
# return fac[n] * (finv[r] * finv[n - r] % mod) % mod
##############Find sum of product of subsets of size k in a array
# ar=[0,1,2,3]
# k=3
# n=len(ar)-1
# dp=[0]*(n+1)
# dp[0]=1
# for pos in range(1,n+1):
# dp[pos]=0
# l=max(1,k+pos-n-1)
# for j in range(min(pos,k),l-1,-1):
# dp[j]=dp[j]+ar[pos]*dp[j-1]
# print(dp[k])
def prefix_sum(ar): # [1,2,3,4]->[1,3,6,10]
return list(accumulate(ar))
def suffix_sum(ar): # [1,2,3,4]->[10,9,7,4]
return list(accumulate(ar[::-1]))[::-1]
def N():
return int(inp())
# =========================================================================================
from collections import defaultdict
def numberOfSetBits(i):
i = i - ((i >> 1) & 0x55555555)
i = (i & 0x33333333) + ((i >> 2) & 0x33333333)
return (((i + (i >> 4) & 0xF0F0F0F) * 0x1010101) & 0xffffffff) >> 24
def solve():
n=N()
ar=lis()
for i in range(len(ar)):
m=ar[i]
t=m//4
ans=(t+1)*(m//2) - t*(t+1) + m//2
print(ans%mod)
solve()
#testcase(int(inp()))
``` | instruction | 0 | 50,693 | 9 | 101,386 |
No | output | 1 | 50,693 | 9 | 101,387 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3 | instruction | 0 | 50,695 | 9 | 101,390 |
Tags: binary search, greedy, sortings
Correct Solution:
```
def delivery_dilemma(x, y, z):
delivery, pick = zip(*sorted(list(zip(x, y))))
s = sum(pick)
for j in range(len(pick)):
if delivery[j] >= s:
z.append(s)
break
s -= pick[j]
if delivery[j] >= s:
z.append(delivery[j])
break
t = int(input())
d = []
p = []
lt = []
for i in range(t):
n = int(input())
d.append(list(map(int, input().split())))
p.append(list(map(int, input().split())))
for k in range(t):
delivery_dilemma(d[k], p[k], lt)
for ans in lt:
print(ans)
``` | output | 1 | 50,695 | 9 | 101,391 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3 | instruction | 0 | 50,696 | 9 | 101,392 |
Tags: binary search, greedy, sortings
Correct Solution:
```
#state [i][0,1,2] = 0 - do nothing, 1, add bomb, 2,explode
for tt in range(int(input())):
n = int(input())
a = [[0] * 2 for i in range(n)]
b = list(map(int,input().split()))
c = list(map(int,input().split()))
for i in range(n):
a[i] = [b[i],c[i]]
suff = 0
ans = float("inf")
a.sort()
for i in range(n-1,-1,-1):
ans = min(ans,a[i][0] + max(0,suff - a[i][0]))
suff += a[i][1]
print(min(ans,suff))
``` | output | 1 | 50,696 | 9 | 101,393 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3 | instruction | 0 | 50,697 | 9 | 101,394 |
Tags: binary search, greedy, sortings
Correct Solution:
```
for _ in range(int(input())):
n = int(input())
a = list(map(int, input().split()))
#c.sort(reversed = True)
b = list(map(int, input().split()))
c = []
for i in range(n):
c.append((a[i], b[i]))
c.sort(reverse = True)
#print(c)
s = 0
f = False
for x, y in c:
if s>=x:
print(s)
f = True
break
if y>=x:
print(x)
f = True
break
else:
s += y
if s>=x:
print(x)
f = True
break
if f==False:
print(s)
``` | output | 1 | 50,697 | 9 | 101,395 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3 | instruction | 0 | 50,698 | 9 | 101,396 |
Tags: binary search, greedy, sortings
Correct Solution:
```
for ct in range(int(input())):
n = int(input())
a = [int(i) for i in input().split()]
b = [int(i) for i in input().split()]
d = list(zip(a, b))
d.sort(reverse=True)
d.append((0, 0))
# print(d)
soma = 0
for i in range(n):
if soma + d[i][1] > d[i][0]:
print(max(soma, d[i][0]))
break
else:
soma += d[i][1]
else:
print(soma)
``` | output | 1 | 50,698 | 9 | 101,397 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3 | instruction | 0 | 50,699 | 9 | 101,398 |
Tags: binary search, greedy, sortings
Correct Solution:
```
from sys import stdin
input = stdin.readline
for _ in range(int(input())):
n = int(input())
a = [*map(int, input().split())]
b = [*map(int, input().split())]
l,r = 0, max(a)
while l < r:
mid = (l + r) // 2
if sum(j if i > mid else 0 for i,j in zip(a,b)) <= mid:
r = mid
else:
l = mid + 1
print(l)
``` | output | 1 | 50,699 | 9 | 101,399 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3 | instruction | 0 | 50,700 | 9 | 101,400 |
Tags: binary search, greedy, sortings
Correct Solution:
```
for _ in range(int(input())):
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
dp = []
c = sorted(a)
summ = 0
for i in range(n):
dp.append([a[i],i])
summ+=(b[i])
dp.sort()
k = n-1
ans = max(a)
count = 0
for i in dp[-1::-1]:
k-=1
count+=(b[i[1]])
ans = min(ans,max(count,c[k]))
print(min(ans,summ))
``` | output | 1 | 50,700 | 9 | 101,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3 | instruction | 0 | 50,701 | 9 | 101,402 |
Tags: binary search, greedy, sortings
Correct Solution:
```
t = int(input())
for i in range(t):
n = int(input())
lst1 = list(map(int,input().split()))
lst2 = list(map(int,input().split()))
lst3 = []
for i in range(n):
lst3.append([lst1[i],lst2[i]])
lst3 = sorted(lst3)
for i in range(n):
lst1[i] = lst3[i][0]
lst2[i] = lst3[i][1]
sum1 = sum(lst2)
sumprev = 0
ans = sum1
for i in range(n):
sumprev += lst2[i]
ans = min(ans, max(lst1[i],sum1-sumprev))
print(ans)
``` | output | 1 | 50,701 | 9 | 101,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3 | instruction | 0 | 50,702 | 9 | 101,404 |
Tags: binary search, greedy, sortings
Correct Solution:
```
R=lambda:map(int,input().split())
t,=R()
for _ in[0]*t:
R();a=[];b=[0];s=0
for x,y in sorted(zip(R(),R()))[::-1]:a+=x,;s+=y;b+=s,
print(min(map(max,zip(a+[0],b))))
``` | output | 1 | 50,702 | 9 | 101,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3
Submitted Solution:
```
import itertools
for _ in range(int(input())):
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
time = sorted(zip(a, b), key=lambda x: x[0])
a = [a for a, _ in time]
b = [b for _, b in time]
acc = list(itertools.accumulate(b[::-1]))[::-1] + [0]
ans = acc[0]
for i in range(len(a)):
ans = min(ans, max(a[i], acc[i + 1]))
print(ans)
``` | instruction | 0 | 50,703 | 9 | 101,406 |
Yes | output | 1 | 50,703 | 9 | 101,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3
Submitted Solution:
```
T = int(input())
to_print = []
while T:
T -= 1
n = int(input())
a = [int(x) for x in input().split()]
b = [int(x) for x in input().split()]
if n==1:
#print(min(a[0], b[0]))
to_print.append( min(a[0], b[0]) )
continue
ab = list(zip(a,b))
ab.sort( key = lambda x: (-x[0], x[1]))
for i in range(1, n):
ab[i] = ab[i][0], (ab[i][1]+ab[i-1][1])
#print(ab)
#print( max ( map(min, ab) ) )
to_print.append( max ( map(min, ab) ) )
else:
print('\n'.join(map(str, to_print)))
``` | instruction | 0 | 50,704 | 9 | 101,408 |
Yes | output | 1 | 50,704 | 9 | 101,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3
Submitted Solution:
```
# Problem: C. The Delivery Dilemma
# Contest: Codeforces - Codeforces Round #681 (Div. 2, based on VK Cup 2019-2020 - Final)
# URL: https://codeforces.com/contest/1443/problem/C
# Memory Limit: 256 MB
# Time Limit: 2000 ms
# Powered by CP Editor (https://github.com/cpeditor/cpeditor)
from collections import defaultdict
from functools import reduce
from bisect import bisect_right
from bisect import bisect_left
import copy
def main():
for _ in range(int(input())):
n=int(input())
d=defaultdict(list)
a=list(map(int,input().split()))
b=list(map(int,input().split()))
for i in range(n):
d[i].append(a[i])
d[i].append(b[i])
delivery=[]
takeaway=[]
for key, value in sorted(d.items(), key=lambda e: e[1][0]):
delivery.append(value[0])
takeaway.append(value[1])
for i in range(n-2,-1,-1):
takeaway[i]+=takeaway[i+1]
mini=min(delivery[n-1],takeaway[0])
for i in range(n-1):
mini=min(mini,max(delivery[i],takeaway[i+1]))
print(mini)
if __name__ == '__main__':
main()
``` | instruction | 0 | 50,705 | 9 | 101,410 |
Yes | output | 1 | 50,705 | 9 | 101,411 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3
Submitted Solution:
```
import sys
t = int(sys.stdin.readline())
ans = []
for _ in range(t):
n = int(sys.stdin.readline())
a = list(map(int, sys.stdin.readline().split()))
b = list(map(int, sys.stdin.readline().split()))
c = sorted(list(zip(a, b)), reverse=True)
b_time = 0
for i in range(n):
b_time += c[i][1]
if b_time >= c[i][0]:
b_time = max(c[i][0], b_time - c[i][1])
break
ans.append(b_time)
sys.stdout.write('\n'.join(map(str, ans)))
``` | instruction | 0 | 50,706 | 9 | 101,412 |
Yes | output | 1 | 50,706 | 9 | 101,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3
Submitted Solution:
```
import sys
reader = (s.rstrip() for s in sys.stdin)
input = reader.__next__
def gift():
for _ in range(t):
n = int(input())
an = list(map(int,input().split()))
bn = list(map(int,input().split()))
left = []
maxTime = 0
timeSpend = 0
for i in range(n):
if an[i]<=bn[i]:
maxTime = max(an[i],maxTime)
else:
left.append([an[i],bn[i]])
fleft = []
for ele in left:
if ele[0]>maxTime:
fleft.append(ele)
fleft.sort(key=lambda x:(-x[1],-x[0]))
for ele in fleft:
ani,bni = ele
if bni+timeSpend<ani:
timeSpend+=bni
maxTime=max(maxTime,timeSpend)
else:
maxTime=ani
yield maxTime
if __name__ == '__main__':
t= int(input())
ans = gift()
print(*ans,sep='\n')
#"{} {} {}".format(maxele,minele,minele)
# 5
# 18 14 12 10 8
``` | instruction | 0 | 50,707 | 9 | 101,414 |
No | output | 1 | 50,707 | 9 | 101,415 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3
Submitted Solution:
```
def mySolver(n, a, b):
ans = []
dt = b[0]
cost = 0
for i in range(n):
if a[i] <= dt:
ans.append(a[i])
dt = b[i]
else:
cost += b[i]
# print("this is cost: ", cost)
dt = cost
if ans:
return max(cost, max(ans))
else:
return cost
def main():
# Read test case num
case = int(input())
myAns = []
for i in range(0,case):
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
myAns.append(mySolver(n, a, b))
for j in myAns:
print(j)
main()
``` | instruction | 0 | 50,708 | 9 | 101,416 |
No | output | 1 | 50,708 | 9 | 101,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3
Submitted Solution:
```
for _ in range(int(input())):
n = int(input())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
p = []
for i in range(n):
p.append((a[i], b[i]))
p.sort(key = lambda tup: tup[1])
time = 0
r = 0
for a, b in p:
if r + b <= a:
time = max(time, r + b)
r = r + b
else:
time = max(time, a)
print(time)
``` | instruction | 0 | 50,709 | 9 | 101,418 |
No | output | 1 | 50,709 | 9 | 101,419 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya is preparing for his birthday. He decided that there would be n different dishes on the dinner table, numbered from 1 to n. Since Petya doesn't like to cook, he wants to order these dishes in restaurants.
Unfortunately, all dishes are prepared in different restaurants and therefore Petya needs to pick up his orders from n different places. To speed up this process, he wants to order courier delivery at some restaurants. Thus, for each dish, there are two options for Petya how he can get it:
* the dish will be delivered by a courier from the restaurant i, in this case the courier will arrive in a_i minutes,
* Petya goes to the restaurant i on his own and picks up the dish, he will spend b_i minutes on this.
Each restaurant has its own couriers and they start delivering the order at the moment Petya leaves the house. In other words, all couriers work in parallel. Petya must visit all restaurants in which he has not chosen delivery, he does this consistently.
For example, if Petya wants to order n = 4 dishes and a = [3, 7, 4, 5], and b = [2, 1, 2, 4], then he can order delivery from the first and the fourth restaurant, and go to the second and third on your own. Then the courier of the first restaurant will bring the order in 3 minutes, the courier of the fourth restaurant will bring the order in 5 minutes, and Petya will pick up the remaining dishes in 1 + 2 = 3 minutes. Thus, in 5 minutes all the dishes will be at Petya's house.
Find the minimum time after which all the dishes can be at Petya's home.
Input
The first line contains one positive integer t (1 ≤ t ≤ 2 ⋅ 10^5) — the number of test cases. Then t test cases follow.
Each test case begins with a line containing one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of dishes that Petya wants to order.
The second line of each test case contains n integers a_1 … a_n (1 ≤ a_i ≤ 10^9) — the time of courier delivery of the dish with the number i.
The third line of each test case contains n integers b_1 … b_n (1 ≤ b_i ≤ 10^9) — the time during which Petya will pick up the dish with the number i.
The sum of n over all test cases does not exceed 2 ⋅ 10^5.
Output
For each test case output one integer — the minimum time after which all dishes can be at Petya's home.
Example
Input
4
4
3 7 4 5
2 1 2 4
4
1 2 3 4
3 3 3 3
2
1 2
10 10
2
10 10
1 2
Output
5
3
2
3
Submitted Solution:
```
def solve():
n=int(input())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
# a=[3,7,4,5]
# b=[2,1,2,4]
# a=[1,2,3,4]
# b=[3,3,3,3]
# a=[1,2]
# b=[10,10]
# a=[10,10]
# b=[1,2]
temp_b=0
temp=[]
for i in range(len(a)):
temp_ans=min(a[i],temp_b+b[i])
temp.append(temp_ans)
if a[i]>temp_b+b[i]:
temp_b=temp_b+b[i]
# print(temp_ans)
# print(temp)
print(max(temp))
t=int(input())
while t:
solve()
t-=1
``` | instruction | 0 | 50,710 | 9 | 101,420 |
No | output | 1 | 50,710 | 9 | 101,421 |
Provide a correct Python 3 solution for this coding contest problem.
In Takahashi's mind, there is always an integer sequence of length 2 \times 10^9 + 1: A = (A_{-10^9}, A_{-10^9 + 1}, ..., A_{10^9 - 1}, A_{10^9}) and an integer P.
Initially, all the elements in the sequence A in Takahashi's mind are 0, and the value of the integer P is 0.
When Takahashi eats symbols `+`, `-`, `>` and `<`, the sequence A and the integer P will change as follows:
* When he eats `+`, the value of A_P increases by 1;
* When he eats `-`, the value of A_P decreases by 1;
* When he eats `>`, the value of P increases by 1;
* When he eats `<`, the value of P decreases by 1.
Takahashi has a string S of length N. Each character in S is one of the symbols `+`, `-`, `>` and `<`. He chose a pair of integers (i, j) such that 1 \leq i \leq j \leq N and ate the symbols that are the i-th, (i+1)-th, ..., j-th characters in S, in this order. We heard that, after he finished eating, the sequence A became the same as if he had eaten all the symbols in S from first to last. How many such possible pairs (i, j) are there?
Constraints
* 1 \leq N \leq 250000
* |S| = N
* Each character in S is `+`, `-`, `>` or `<`.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the answer.
Examples
Input
5
+>+<-
Output
3
Input
5
+>+-<
Output
5
Input
48
-+><<><><><>>>+-<<>->>><<><<-+<>><+<<>+><-+->><<
Output
475 | instruction | 0 | 51,139 | 9 | 102,278 |
"Correct Solution:
```
import random
from collections import defaultdict
def solve(n, s, xs, m):
ans = [10 ** 9] * (n + 1)
for x in xs:
p = 0
h = 0
y = 1
r = pow(x, m - 2, m)
pos = [0] * (n + 1)
hashes = [0] * (n + 1)
for i, c in enumerate(s, start=1):
if c == '>':
p += 1
y = y * x % m
elif c == '<':
p -= 1
y = y * r % m
elif c == '+':
h = (h + y) % m
else:
h = (h - y) % m
pos[i] = p
hashes[i] = h
pow_x = [1]
for _ in range(max(pos)):
pow_x.append(pow_x[-1] * x % m)
mp = min(pos)
if mp < 0:
pow_x.append(pow(r, -mp, m))
for _ in range(-mp - 1):
pow_x.append(pow_x[-1] * x % m)
ideal = hashes[-1]
required = defaultdict(lambda: 0)
for i, (p, h) in enumerate(zip(pos, hashes)):
ans[i] = min(ans[i], required[h])
req = (ideal * pow_x[p] + h) % m
required[req] += 1
return sum(ans)
n = int(input())
s = input()
xs = random.sample(range(10 ** 9, 10 ** 10), 3)
m = 2305843009213693951
print(solve(n, s, xs, m))
``` | output | 1 | 51,139 | 9 | 102,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Takahashi's mind, there is always an integer sequence of length 2 \times 10^9 + 1: A = (A_{-10^9}, A_{-10^9 + 1}, ..., A_{10^9 - 1}, A_{10^9}) and an integer P.
Initially, all the elements in the sequence A in Takahashi's mind are 0, and the value of the integer P is 0.
When Takahashi eats symbols `+`, `-`, `>` and `<`, the sequence A and the integer P will change as follows:
* When he eats `+`, the value of A_P increases by 1;
* When he eats `-`, the value of A_P decreases by 1;
* When he eats `>`, the value of P increases by 1;
* When he eats `<`, the value of P decreases by 1.
Takahashi has a string S of length N. Each character in S is one of the symbols `+`, `-`, `>` and `<`. He chose a pair of integers (i, j) such that 1 \leq i \leq j \leq N and ate the symbols that are the i-th, (i+1)-th, ..., j-th characters in S, in this order. We heard that, after he finished eating, the sequence A became the same as if he had eaten all the symbols in S from first to last. How many such possible pairs (i, j) are there?
Constraints
* 1 \leq N \leq 250000
* |S| = N
* Each character in S is `+`, `-`, `>` or `<`.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the answer.
Examples
Input
5
+>+<-
Output
3
Input
5
+>+-<
Output
5
Input
48
-+><<><><><>>>+-<<>->>><<><<-+<>><+<<>+><-+->><<
Output
475
Submitted Solution:
```
import random
from collections import defaultdict
def solve(n, s, x, m):
p = 0
h = 0
y = 1
r = pow(x, m - 2, m)
pos = [0] * (n + 1)
hashes = [0] * (n + 1)
for i, c in enumerate(s, start=1):
if c == '>':
p += 1
y = y * x % m
elif c == '<':
p -= 1
y = y * r % m
elif c == '+':
h = (h + y) % m
else:
h = (h - y) % m
pos[i] = p
hashes[i] = h
pow_x = [1]
for _ in range(max(pos)):
pow_x.append(pow_x[-1] * x % m)
mp = min(pos)
if mp < 0:
pow_x.append(pow(r, -mp, m))
for _ in range(-mp + 1):
pow_x.append(pow_x[-1] * x % m)
ans = 0
ideal = hashes[-1]
required = defaultdict(lambda: 0)
for p, h in zip(pos, hashes):
ans += required[h]
req = (ideal * pow_x[p] + h) % m
required[req] += 1
return ans
n = int(input())
s = input()
xs = random.sample(range(10 ** 9, 10 ** 10), 5)
m = 2305843009213693951
ans = min(solve(n, s, x, m) for x in xs)
print(ans)
``` | instruction | 0 | 51,140 | 9 | 102,280 |
No | output | 1 | 51,140 | 9 | 102,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Takahashi's mind, there is always an integer sequence of length 2 \times 10^9 + 1: A = (A_{-10^9}, A_{-10^9 + 1}, ..., A_{10^9 - 1}, A_{10^9}) and an integer P.
Initially, all the elements in the sequence A in Takahashi's mind are 0, and the value of the integer P is 0.
When Takahashi eats symbols `+`, `-`, `>` and `<`, the sequence A and the integer P will change as follows:
* When he eats `+`, the value of A_P increases by 1;
* When he eats `-`, the value of A_P decreases by 1;
* When he eats `>`, the value of P increases by 1;
* When he eats `<`, the value of P decreases by 1.
Takahashi has a string S of length N. Each character in S is one of the symbols `+`, `-`, `>` and `<`. He chose a pair of integers (i, j) such that 1 \leq i \leq j \leq N and ate the symbols that are the i-th, (i+1)-th, ..., j-th characters in S, in this order. We heard that, after he finished eating, the sequence A became the same as if he had eaten all the symbols in S from first to last. How many such possible pairs (i, j) are there?
Constraints
* 1 \leq N \leq 250000
* |S| = N
* Each character in S is `+`, `-`, `>` or `<`.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the answer.
Examples
Input
5
+>+<-
Output
3
Input
5
+>+-<
Output
5
Input
48
-+><<><><><>>>+-<<>->>><<><<-+<>><+<<>+><-+->><<
Output
475
Submitted Solution:
```
N = int(input())
S = str(input())
all_eaten = [0] * (2 * N + 1)
p = N
for i in S:
if i == ">":
p += 1
elif i == "<":
p -= 1
elif i == "+":
all_eaten[p] += 1
elif i == "-":
all_eaten[p] -= 1
counter = 0
for i in range(1, N+1):
for j in range(i, N+1):
part_eaten = [0] * (2 * N + 1)
p = N
s = S[i-1:j]
for k in s:
if k == ">":
p += 1
elif k == "<":
p -= 1
elif k == "+":
part_eaten[p] += 1
elif k == "-":
part_eaten[p] -= 1
if part_eaten == all_eaten:
counter += 1
print(counter)
``` | instruction | 0 | 51,141 | 9 | 102,282 |
No | output | 1 | 51,141 | 9 | 102,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Takahashi's mind, there is always an integer sequence of length 2 \times 10^9 + 1: A = (A_{-10^9}, A_{-10^9 + 1}, ..., A_{10^9 - 1}, A_{10^9}) and an integer P.
Initially, all the elements in the sequence A in Takahashi's mind are 0, and the value of the integer P is 0.
When Takahashi eats symbols `+`, `-`, `>` and `<`, the sequence A and the integer P will change as follows:
* When he eats `+`, the value of A_P increases by 1;
* When he eats `-`, the value of A_P decreases by 1;
* When he eats `>`, the value of P increases by 1;
* When he eats `<`, the value of P decreases by 1.
Takahashi has a string S of length N. Each character in S is one of the symbols `+`, `-`, `>` and `<`. He chose a pair of integers (i, j) such that 1 \leq i \leq j \leq N and ate the symbols that are the i-th, (i+1)-th, ..., j-th characters in S, in this order. We heard that, after he finished eating, the sequence A became the same as if he had eaten all the symbols in S from first to last. How many such possible pairs (i, j) are there?
Constraints
* 1 \leq N \leq 250000
* |S| = N
* Each character in S is `+`, `-`, `>` or `<`.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the answer.
Examples
Input
5
+>+<-
Output
3
Input
5
+>+-<
Output
5
Input
48
-+><<><><><>>>+-<<>->>><<><<-+<>><+<<>+><-+->><<
Output
475
Submitted Solution:
```
from collections import defaultdict
def takahashi(s):
a = defaultdict(lambda: 0)
P = 0
for c in s:
if c == '+':
a[P] += 1
elif c == '-':
a[P] -= 1
elif c == '>':
P += 1
else:
P -= 1
keys = a.keys()
return {k:v for k, v in a.items() if v != 0}
def main():
N = int(input())
s = input()
ans = takahashi(s)
# print(ans)
n = 0
for i in range(N):
for j in range(i+1, N+1):
# print(s[i:j], takahashi(s[i:j]) == ans)
if takahashi(s[i:j]) == ans:
n += 1
print(n)
main()
``` | instruction | 0 | 51,142 | 9 | 102,284 |
No | output | 1 | 51,142 | 9 | 102,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Takahashi's mind, there is always an integer sequence of length 2 \times 10^9 + 1: A = (A_{-10^9}, A_{-10^9 + 1}, ..., A_{10^9 - 1}, A_{10^9}) and an integer P.
Initially, all the elements in the sequence A in Takahashi's mind are 0, and the value of the integer P is 0.
When Takahashi eats symbols `+`, `-`, `>` and `<`, the sequence A and the integer P will change as follows:
* When he eats `+`, the value of A_P increases by 1;
* When he eats `-`, the value of A_P decreases by 1;
* When he eats `>`, the value of P increases by 1;
* When he eats `<`, the value of P decreases by 1.
Takahashi has a string S of length N. Each character in S is one of the symbols `+`, `-`, `>` and `<`. He chose a pair of integers (i, j) such that 1 \leq i \leq j \leq N and ate the symbols that are the i-th, (i+1)-th, ..., j-th characters in S, in this order. We heard that, after he finished eating, the sequence A became the same as if he had eaten all the symbols in S from first to last. How many such possible pairs (i, j) are there?
Constraints
* 1 \leq N \leq 250000
* |S| = N
* Each character in S is `+`, `-`, `>` or `<`.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the answer.
Examples
Input
5
+>+<-
Output
3
Input
5
+>+-<
Output
5
Input
48
-+><<><><><>>>+-<<>->>><<><<-+<>><+<<>+><-+->><<
Output
475
Submitted Solution:
```
from collections import defaultdict
def takahashi(s):
a = defaultdict(lambda: 0)
P = 0
for c in s:
if c == '+':
a[P] += 1
elif c == '-':
a[P] -= 1
elif c == '>':
P += 1
else:
P -= 1
keys = a.keys()
return {k:v for k, v in a.items() if v != 0}
def main():
N = int(input())
s = input()
ans = takahashi(s)
# print(ans)
n = 0
for i in range(N):
for j in range(i+1, N+1):
# print(s[i:j], takahashi(s[i:j]) == ans)
if takahashi(s[i:j]) == ans:
n += 1
print(n)
``` | instruction | 0 | 51,143 | 9 | 102,286 |
No | output | 1 | 51,143 | 9 | 102,287 |
Provide a correct Python 3 solution for this coding contest problem.
Carving the cake 2 (Cake 2)
JOI-kun and IOI-chan are twin brothers and sisters. JOI has been enthusiastic about making sweets lately, and JOI tried to bake a cake and eat it today, but when it was baked, IOI who smelled it came, so we decided to divide the cake. became.
The cake is round. We made radial cuts from a point, cut the cake into N pieces, and numbered the pieces counterclockwise from 1 to N. That is, for 1 ≤ i ≤ N, the i-th piece is adjacent to the i − 1st and i + 1st pieces (though the 0th is considered to be the Nth and the N + 1st is considered to be the 1st). The size of the i-th piece was Ai, but I was so bad at cutting that all Ai had different values.
<image>
Figure 1: Cake example (N = 5, A1 = 2, A2 = 8, A3 = 1, A4 = 10, A5 = 9)
I decided to divide these N pieces by JOI-kun and IOI-chan. I decided to divide it as follows:
1. First, JOI chooses and takes one of N.
2. After that, starting with IOI-chan, IOI-chan and JOI-kun alternately take the remaining pieces one by one. However, if you can only take a piece that has already been taken at least one of the pieces on both sides, and there are multiple pieces that can be taken, IOI will choose the largest one and JOI will take it. You can choose what you like.
JOI wants to maximize the total size of the pieces he will finally take.
Task
Given the number N of cake pieces and the size information of N pieces, create a program to find the maximum value of the total size of pieces that JOI can take.
input
Read the following input from standard input.
* The integer N is written on the first line, which means that the cake is cut into N pieces.
* The integer Ai is written on the i-th line (1 ≤ i ≤ N) of the following N lines, which indicates that the size of the i-th piece is Ai.
output
Output an integer representing the maximum value of the total size of pieces that JOI can take to the standard output on one line.
Limits
All input data satisfy the following conditions.
* 1 ≤ N ≤ 20000.
* 1 ≤ Ai ≤ 1 000 000 000.
* Ai are all different.
Input / output example
Input example 1
Five
2
8
1
Ten
9
Output example 1
18
JOI is best to take the pieces as follows.
1. JOI takes the second piece. The size of this piece is 8.
2. IOI takes the first piece. The size of this piece is 2.
3. JOI takes the 5th piece. The size of this piece is 9.
4. IOI takes the 4th piece. The size of this piece is 10.
5. JOI takes the third piece. The size of this piece is 1.
Finally, the total size of the pieces taken by JOI is 8 + 9 + 1 = 18.
Input example 2
8
1
Ten
Four
Five
6
2
9
3
Output example 2
26
Input example 3
15
182243672
10074562
977552215
122668426
685444213
3784162
463324752
560071245
134465220
21447865
654556327
183481051
20041805
405079805
564327789
Output example 3
3600242976
The question text and the data used for the automatic referee are the question text and the test data for scoring, which are created and published by the Japan Committee for Information Olympics.
Example
Input
5
2
8
1
10
9
Output
18 | instruction | 0 | 51,239 | 9 | 102,478 |
"Correct Solution:
```
import sys
sys.setrecursionlimit(10000)
n = int(input())
A = [int(input()) for i in range(n)] * 3
dp = [[-1 for i in range(n * 2)] for j in range(n * 2)]
def dfs(i,j):
#if (j - i > n - 1):undefined
if dp[i][j] != -1:
pass
elif (j - i == n - 1):
dp[i][j] = 0
elif (j - i) % 2 == 0:
if A[i - 1] > A[j + 1]:
dp[i][j] = dfs(i - 1, j)
else:
dp[i][j] = dfs(i, j + 1)
else:
dp[i][j] = max(dfs(i - 1, j) + A[i - 1], dfs(i, j + 1) + A[j + 1])
return dp[i][j]
ans = 0
for i in range(n):
ans = max(ans, dfs(i,i) + A[i])
print(ans)
``` | output | 1 | 51,239 | 9 | 102,479 |
Provide a correct Python 3 solution for this coding contest problem.
Carving the cake 2 (Cake 2)
JOI-kun and IOI-chan are twin brothers and sisters. JOI has been enthusiastic about making sweets lately, and JOI tried to bake a cake and eat it today, but when it was baked, IOI who smelled it came, so we decided to divide the cake. became.
The cake is round. We made radial cuts from a point, cut the cake into N pieces, and numbered the pieces counterclockwise from 1 to N. That is, for 1 ≤ i ≤ N, the i-th piece is adjacent to the i − 1st and i + 1st pieces (though the 0th is considered to be the Nth and the N + 1st is considered to be the 1st). The size of the i-th piece was Ai, but I was so bad at cutting that all Ai had different values.
<image>
Figure 1: Cake example (N = 5, A1 = 2, A2 = 8, A3 = 1, A4 = 10, A5 = 9)
I decided to divide these N pieces by JOI-kun and IOI-chan. I decided to divide it as follows:
1. First, JOI chooses and takes one of N.
2. After that, starting with IOI-chan, IOI-chan and JOI-kun alternately take the remaining pieces one by one. However, if you can only take a piece that has already been taken at least one of the pieces on both sides, and there are multiple pieces that can be taken, IOI will choose the largest one and JOI will take it. You can choose what you like.
JOI wants to maximize the total size of the pieces he will finally take.
Task
Given the number N of cake pieces and the size information of N pieces, create a program to find the maximum value of the total size of pieces that JOI can take.
input
Read the following input from standard input.
* The integer N is written on the first line, which means that the cake is cut into N pieces.
* The integer Ai is written on the i-th line (1 ≤ i ≤ N) of the following N lines, which indicates that the size of the i-th piece is Ai.
output
Output an integer representing the maximum value of the total size of pieces that JOI can take to the standard output on one line.
Limits
All input data satisfy the following conditions.
* 1 ≤ N ≤ 20000.
* 1 ≤ Ai ≤ 1 000 000 000.
* Ai are all different.
Input / output example
Input example 1
Five
2
8
1
Ten
9
Output example 1
18
JOI is best to take the pieces as follows.
1. JOI takes the second piece. The size of this piece is 8.
2. IOI takes the first piece. The size of this piece is 2.
3. JOI takes the 5th piece. The size of this piece is 9.
4. IOI takes the 4th piece. The size of this piece is 10.
5. JOI takes the third piece. The size of this piece is 1.
Finally, the total size of the pieces taken by JOI is 8 + 9 + 1 = 18.
Input example 2
8
1
Ten
Four
Five
6
2
9
3
Output example 2
26
Input example 3
15
182243672
10074562
977552215
122668426
685444213
3784162
463324752
560071245
134465220
21447865
654556327
183481051
20041805
405079805
564327789
Output example 3
3600242976
The question text and the data used for the automatic referee are the question text and the test data for scoring, which are created and published by the Japan Committee for Information Olympics.
Example
Input
5
2
8
1
10
9
Output
18 | instruction | 0 | 51,240 | 9 | 102,480 |
"Correct Solution:
```
import sys
sys.setrecursionlimit(100000)
N, *A = map(int, open(0).read().split())
memo = [[-1]*N for i in range(N)]
for i in range(N):
memo[i][i] = A[i] if N % 2 else 0
def dfs(p, q, t):
if memo[p][q] != -1:
return memo[p][q]
if t:
memo[p][q] = r = max(A[p] + dfs((p+1)%N, q, 0), A[q] + dfs(p, (q-1)%N, 0))
else:
if A[p] < A[q]:
memo[p][q] = r = dfs(p, (q-1)%N, 1)
else:
memo[p][q] = r = dfs((p+1)%N, q, 1)
return r
ans = 0
for i in range(N):
ans = max(ans, A[i] + dfs((i+1)%N, (i-1)%N, 0))
print(ans)
``` | output | 1 | 51,240 | 9 | 102,481 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Carving the cake 2 (Cake 2)
JOI-kun and IOI-chan are twin brothers and sisters. JOI has been enthusiastic about making sweets lately, and JOI tried to bake a cake and eat it today, but when it was baked, IOI who smelled it came, so we decided to divide the cake. became.
The cake is round. We made radial cuts from a point, cut the cake into N pieces, and numbered the pieces counterclockwise from 1 to N. That is, for 1 ≤ i ≤ N, the i-th piece is adjacent to the i − 1st and i + 1st pieces (though the 0th is considered to be the Nth and the N + 1st is considered to be the 1st). The size of the i-th piece was Ai, but I was so bad at cutting that all Ai had different values.
<image>
Figure 1: Cake example (N = 5, A1 = 2, A2 = 8, A3 = 1, A4 = 10, A5 = 9)
I decided to divide these N pieces by JOI-kun and IOI-chan. I decided to divide it as follows:
1. First, JOI chooses and takes one of N.
2. After that, starting with IOI-chan, IOI-chan and JOI-kun alternately take the remaining pieces one by one. However, if you can only take a piece that has already been taken at least one of the pieces on both sides, and there are multiple pieces that can be taken, IOI will choose the largest one and JOI will take it. You can choose what you like.
JOI wants to maximize the total size of the pieces he will finally take.
Task
Given the number N of cake pieces and the size information of N pieces, create a program to find the maximum value of the total size of pieces that JOI can take.
input
Read the following input from standard input.
* The integer N is written on the first line, which means that the cake is cut into N pieces.
* The integer Ai is written on the i-th line (1 ≤ i ≤ N) of the following N lines, which indicates that the size of the i-th piece is Ai.
output
Output an integer representing the maximum value of the total size of pieces that JOI can take to the standard output on one line.
Limits
All input data satisfy the following conditions.
* 1 ≤ N ≤ 20000.
* 1 ≤ Ai ≤ 1 000 000 000.
* Ai are all different.
Input / output example
Input example 1
Five
2
8
1
Ten
9
Output example 1
18
JOI is best to take the pieces as follows.
1. JOI takes the second piece. The size of this piece is 8.
2. IOI takes the first piece. The size of this piece is 2.
3. JOI takes the 5th piece. The size of this piece is 9.
4. IOI takes the 4th piece. The size of this piece is 10.
5. JOI takes the third piece. The size of this piece is 1.
Finally, the total size of the pieces taken by JOI is 8 + 9 + 1 = 18.
Input example 2
8
1
Ten
Four
Five
6
2
9
3
Output example 2
26
Input example 3
15
182243672
10074562
977552215
122668426
685444213
3784162
463324752
560071245
134465220
21447865
654556327
183481051
20041805
405079805
564327789
Output example 3
3600242976
The question text and the data used for the automatic referee are the question text and the test data for scoring, which are created and published by the Japan Committee for Information Olympics.
Example
Input
5
2
8
1
10
9
Output
18
Submitted Solution:
```
n = int(input())
A = [int(input()) for i in range(n)] * 3
dp = [[-1 for i in range(n * 2)] for j in range(n * 2)]
def dfs(i,j):
#if (j - i > n - 1):undefined
if dp[i][j] != -1:
pass
elif (j - i == n - 1):
dp[i][j] = 0
elif (j - i) % 2 == 0:
if A[i - 1] > A[j + 1]:
dp[i][j] = dfs(i - 1, j)
else:
dp[i][j] = dfs(i, j + 1)
else:
dp[i][j] = max(dfs(i - 1, j) + A[i - 1], dfs(i, j + 1) + A[j + 1])
return dp[i][j]
ans = 0
for i in range(n):
ans = max(ans, dfs(i,i) + A[i])
print(ans)
``` | instruction | 0 | 51,241 | 9 | 102,482 |
No | output | 1 | 51,241 | 9 | 102,483 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Carving the cake 2 (Cake 2)
JOI-kun and IOI-chan are twin brothers and sisters. JOI has been enthusiastic about making sweets lately, and JOI tried to bake a cake and eat it today, but when it was baked, IOI who smelled it came, so we decided to divide the cake. became.
The cake is round. We made radial cuts from a point, cut the cake into N pieces, and numbered the pieces counterclockwise from 1 to N. That is, for 1 ≤ i ≤ N, the i-th piece is adjacent to the i − 1st and i + 1st pieces (though the 0th is considered to be the Nth and the N + 1st is considered to be the 1st). The size of the i-th piece was Ai, but I was so bad at cutting that all Ai had different values.
<image>
Figure 1: Cake example (N = 5, A1 = 2, A2 = 8, A3 = 1, A4 = 10, A5 = 9)
I decided to divide these N pieces by JOI-kun and IOI-chan. I decided to divide it as follows:
1. First, JOI chooses and takes one of N.
2. After that, starting with IOI-chan, IOI-chan and JOI-kun alternately take the remaining pieces one by one. However, if you can only take a piece that has already been taken at least one of the pieces on both sides, and there are multiple pieces that can be taken, IOI will choose the largest one and JOI will take it. You can choose what you like.
JOI wants to maximize the total size of the pieces he will finally take.
Task
Given the number N of cake pieces and the size information of N pieces, create a program to find the maximum value of the total size of pieces that JOI can take.
input
Read the following input from standard input.
* The integer N is written on the first line, which means that the cake is cut into N pieces.
* The integer Ai is written on the i-th line (1 ≤ i ≤ N) of the following N lines, which indicates that the size of the i-th piece is Ai.
output
Output an integer representing the maximum value of the total size of pieces that JOI can take to the standard output on one line.
Limits
All input data satisfy the following conditions.
* 1 ≤ N ≤ 20000.
* 1 ≤ Ai ≤ 1 000 000 000.
* Ai are all different.
Input / output example
Input example 1
Five
2
8
1
Ten
9
Output example 1
18
JOI is best to take the pieces as follows.
1. JOI takes the second piece. The size of this piece is 8.
2. IOI takes the first piece. The size of this piece is 2.
3. JOI takes the 5th piece. The size of this piece is 9.
4. IOI takes the 4th piece. The size of this piece is 10.
5. JOI takes the third piece. The size of this piece is 1.
Finally, the total size of the pieces taken by JOI is 8 + 9 + 1 = 18.
Input example 2
8
1
Ten
Four
Five
6
2
9
3
Output example 2
26
Input example 3
15
182243672
10074562
977552215
122668426
685444213
3784162
463324752
560071245
134465220
21447865
654556327
183481051
20041805
405079805
564327789
Output example 3
3600242976
The question text and the data used for the automatic referee are the question text and the test data for scoring, which are created and published by the Japan Committee for Information Olympics.
Example
Input
5
2
8
1
10
9
Output
18
Submitted Solution:
```
n = int(input())
A = [int(input()) for i in range(n)] * 2
dp = [[-1 for i in range(n * 2)] for j in range(n * 2)]
def dfs(i,j):
#if (j - i > n - 1):undefined
if dp[i][j] != -1:
pass
elif (j - i == n - 1):
dp[i][j] = 0
elif (j - i) % 2 == 0:
if A[i - 1] > A[j + 1]:
dp[i][j] = dfs(i - 1, j)
else:
dp[i][j] = dfs(i, j + 1)
else:
dp[i][j] = max(dfs(i - 1, j) + A[i - 1], dfs(i, j + 1) + A[j + 1])
return dp[i][j]
ans = 0
for i in range(n):
for j in range(i,2 * n):
ans = max(ans, dfs(i,i) + A[i])
print(ans)
``` | instruction | 0 | 51,242 | 9 | 102,484 |
No | output | 1 | 51,242 | 9 | 102,485 |
Provide a correct Python 3 solution for this coding contest problem.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3 | instruction | 0 | 51,980 | 9 | 103,960 |
"Correct Solution:
```
n,m=map(int,input().split())
k,*a = input().split()
sa = set(a)
for i in range(n-1):
k,*a = input().split()
sa &= set(a)
print(len(sa))
``` | output | 1 | 51,980 | 9 | 103,961 |
Provide a correct Python 3 solution for this coding contest problem.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3 | instruction | 0 | 51,981 | 9 | 103,962 |
"Correct Solution:
```
n,m = map(int, input().split())
like = set(range(1,m+1))
for i in range(n):
k,*a = map(int, input().split())
like&=set(a)
print(len(like))
``` | output | 1 | 51,981 | 9 | 103,963 |
Provide a correct Python 3 solution for this coding contest problem.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3 | instruction | 0 | 51,982 | 9 | 103,964 |
"Correct Solution:
```
n, m = map(int, input().split())
k = set(range(1, m + 1))
for i in range(n):
k &= set(map(int, input().split()[1:]))
print(len(k))
``` | output | 1 | 51,982 | 9 | 103,965 |
Provide a correct Python 3 solution for this coding contest problem.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3 | instruction | 0 | 51,983 | 9 | 103,966 |
"Correct Solution:
```
(n, m) = map(int, input().split())
l = [set(list(map(int, input().split()))[1:]) for _ in range(n)]
print(len(l[0].intersection(*l[1:])))
``` | output | 1 | 51,983 | 9 | 103,967 |
Provide a correct Python 3 solution for this coding contest problem.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3 | instruction | 0 | 51,984 | 9 | 103,968 |
"Correct Solution:
```
(n,m), *ka = [list(map(int, s.split())) for s in open(0)]
c = [0]*(m+1)
for k, *a in ka:
for elm in a:
c[elm] += 1
print(c.count(n))
``` | output | 1 | 51,984 | 9 | 103,969 |
Provide a correct Python 3 solution for this coding contest problem.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3 | instruction | 0 | 51,985 | 9 | 103,970 |
"Correct Solution:
```
N,M=map(int, input().split())
A=[0]*M
for _ in range(N):
_,*T=map(int,input().split())
for t in T:
A[t-1]+=1
print(A.count(N))
``` | output | 1 | 51,985 | 9 | 103,971 |
Provide a correct Python 3 solution for this coding contest problem.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3 | instruction | 0 | 51,986 | 9 | 103,972 |
"Correct Solution:
```
n,m=map(int,input().split())
s={}
for _ in range(n):
*b,=map(int,input().split())
b=b[1:]
a=set(b)
if not s:
s=a
else:
s=s&a
print(len(s))
``` | output | 1 | 51,986 | 9 | 103,973 |
Provide a correct Python 3 solution for this coding contest problem.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3 | instruction | 0 | 51,987 | 9 | 103,974 |
"Correct Solution:
```
n, m = map(int, input().split())
S = set(range(1, m + 1))
for i in range(n):
K, *a = map(int, input().split())
S = S & set(a)
print(len(S))
``` | output | 1 | 51,987 | 9 | 103,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3
Submitted Solution:
```
n,m = map(int,input().split())
count = [0]*m
for i in range(n):
k,*l = map(int,input().split())
for c in l:
count[c-1] += 1
print(count.count(n))
``` | instruction | 0 | 51,988 | 9 | 103,976 |
Yes | output | 1 | 51,988 | 9 | 103,977 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3
Submitted Solution:
```
I = lambda: map(int, input().split())
n, m = I()
F = [n]*(m+1)
for _ in range(n):
k, *A = I()
for a in A:
F[a] -= 1
print(F.count(0))
``` | instruction | 0 | 51,989 | 9 | 103,978 |
Yes | output | 1 | 51,989 | 9 | 103,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3
Submitted Solution:
```
N,M = map(int, input().split())
A = [set(list(map(int,input().split()))[1:]) for i in range(N)]
for i in range(1,N):
A[0] &= A[i]
print(len(A[0]))
``` | instruction | 0 | 51,990 | 9 | 103,980 |
Yes | output | 1 | 51,990 | 9 | 103,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3
Submitted Solution:
```
n, m = map(int, input().split())
s = set(range(1, m+1))
for i in range(n):
c, *a = map(int, input().split())
s &= set(a)
print(len(s))
``` | instruction | 0 | 51,991 | 9 | 103,982 |
Yes | output | 1 | 51,991 | 9 | 103,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3
Submitted Solution:
```
import sys
(sn, sm) = sys.stdin.readline().split()
n = int(sn)
m = int(sm)
flg = [0 for j in range(m)]
for i in range(n):
sa = sys.stdin.readline().split()
for saj in sa[1:]
aj = int(saj)
flg[aj - 1] += 1
suma = 0
for sumaj in flg:
if sumaj == n:
suma += 1
print(suma)
``` | instruction | 0 | 51,992 | 9 | 103,984 |
No | output | 1 | 51,992 | 9 | 103,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3
Submitted Solution:
```
n, m = map(int, input().split())
lst = list(range(1, m+1)):
for _ in range(n):
for i in lst:
if i not in list(map(int, input().split()))[1:]:
lst.pop(lst.index(i))
print(len(lst))
``` | instruction | 0 | 51,993 | 9 | 103,986 |
No | output | 1 | 51,993 | 9 | 103,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3
Submitted Solution:
```
n , m = map(int, input().split())
ans = set(list(i for i in range(m)))
for i in range(n):
ans = ans & set(list(map(int, input().split()))[1:])
print(len(ans))
``` | instruction | 0 | 51,994 | 9 | 103,988 |
No | output | 1 | 51,994 | 9 | 103,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Katsusando loves omelette rice.
Besides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.
To prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.
The i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.
Find the number of the foods liked by all the N people.
Constraints
* All values in input are integers.
* 1 \leq N, M \leq 30
* 1 \leq K_i \leq M
* 1 \leq A_{ij} \leq M
* For each i (1 \leq i \leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.
Constraints
Input is given from Standard Input in the following format:
N M
K_1 A_{11} A_{12} ... A_{1K_1}
K_2 A_{21} A_{22} ... A_{2K_2}
:
K_N A_{N1} A_{N2} ... A_{NK_N}
Output
Print the number of the foods liked by all the N people.
Examples
Input
3 4
2 1 3
3 1 2 3
2 3 2
Output
1
Input
5 5
4 2 3 4 5
4 1 3 4 5
4 1 2 4 5
4 1 2 3 5
4 1 2 3 4
Output
0
Input
1 30
3 5 10 30
Output
3
Submitted Solution:
```
a,b= map(int,input().split())
arr = [0]*a
for x in range(a):
te = list(map(int,input().split()))
K = te[0]
if a != 1:
for p in range(K):
arr[te[p+1]-1] += 1
else:
arr = list(set(te[1:len(te)]))
h = max(arr)
if h == a:
print(arr.count(h))
elif a == 1:
print(len(arr))
else:
print(0)
``` | instruction | 0 | 51,995 | 9 | 103,990 |
No | output | 1 | 51,995 | 9 | 103,991 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A mouse encountered a nice big cake and decided to take a walk across it, eating the berries on top of the cake on its way. The cake is rectangular, neatly divided into squares; some of the squares have a berry in them, and some don't.
The mouse is in a bit of a hurry, though, so once she enters the cake from its northwest corner (the top left cell in the input data), she will only go east (right) or south (down), until she reaches the southeast corner (the bottom right cell). She will eat every berry in the squares she passes through, but not in the other squares.
The mouse tries to choose her path so as to maximize the number of berries consumed. However, her haste and hunger might be clouding her judgement, leading her to suboptimal decisions...
Input
The first line of input contains two integers H and W (1 ≤ H, W ≤ 5), separated by a space, — the height and the width of the cake.
The next H lines contain a string of W characters each, representing the squares of the cake in that row: '.' represents an empty square, and '*' represents a square with a berry.
Output
Output the number of berries the mouse will eat following her strategy.
Examples
Input
4 3
*..
.*.
..*
...
Output
3
Input
4 4
.*..
*...
...*
..*.
Output
2
Input
3 4
..**
*...
....
Output
1
Input
5 5
..*..
.....
**...
**...
**...
Output
1 | instruction | 0 | 52,455 | 9 | 104,910 |
Tags: *special, greedy, implementation, shortest paths
Correct Solution:
```
n,m=map(int,input().split())
a=[]
for i in range(n):
a.append(input())
x=y=0
ans=0
dir=0
if a[0][0]=='*': ans+=1
while x<n and y<m:
xx,yy=n-1,m-1
dis=int(1e18)
for i in range(x,n):
for j in range(y,m):
if i==x and y==j:
continue
if a[i][j]=='*':
if (i-x)+(j-y)<dis:
dis=(i-x)+(j-y)
xx=i
yy=j
elif (i-x)+(j-y)==dis and j>yy:
dis=(i-x)+(j-y)
xx=i
yy=j
if xx==n-1 and yy==m-1:
ans+=(a[n-1][m-1]=="*")
break
x,y=xx,yy
ans+=1
#while x<n and y<m:
# if a[x][y]=='*':
# ans+=1
# if dir:
# y+=1
#dir=0
# else:
#x+=1
#dir=1
#
#while x<n:
# ans+= (a[x][m-1]=='*')
# x+=1
#
#while y<m:
# ans+= (a[n-1][y]=='*')
# y+=1
print(ans)
``` | output | 1 | 52,455 | 9 | 104,911 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A mouse encountered a nice big cake and decided to take a walk across it, eating the berries on top of the cake on its way. The cake is rectangular, neatly divided into squares; some of the squares have a berry in them, and some don't.
The mouse is in a bit of a hurry, though, so once she enters the cake from its northwest corner (the top left cell in the input data), she will only go east (right) or south (down), until she reaches the southeast corner (the bottom right cell). She will eat every berry in the squares she passes through, but not in the other squares.
The mouse tries to choose her path so as to maximize the number of berries consumed. However, her haste and hunger might be clouding her judgement, leading her to suboptimal decisions...
Input
The first line of input contains two integers H and W (1 ≤ H, W ≤ 5), separated by a space, — the height and the width of the cake.
The next H lines contain a string of W characters each, representing the squares of the cake in that row: '.' represents an empty square, and '*' represents a square with a berry.
Output
Output the number of berries the mouse will eat following her strategy.
Examples
Input
4 3
*..
.*.
..*
...
Output
3
Input
4 4
.*..
*...
...*
..*.
Output
2
Input
3 4
..**
*...
....
Output
1
Input
5 5
..*..
.....
**...
**...
**...
Output
1 | instruction | 0 | 52,456 | 9 | 104,912 |
Tags: *special, greedy, implementation, shortest paths
Correct Solution:
```
import collections
import string
import math
import copy
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
def input(): return sys.stdin.readline().rstrip("\r\n")
# n = 0
# m = 0
# n = int(input())
# li = [int(i) for i in input().split()]
# s = sorted(li)
"""
from dataclasses import dataclass
@dataclass
class point:
x: float
y: float
@dataclass
class line:
A: float
B: float
C: float
def gety(self, x):
return (self.A*x+self.C)/-self.B
def getx(self, y):
return (self.B*y+self.C)/-self.A
def k(self):
return -self.A/self.B
def b(self):
return -self.C/self.B
def dist(self, p: point):
return abs((self.A*p.x+self.B*p.y+self.C)/(self.A**2+self.B**2)**0.5)
def calc_line(u: point, v: point):
return line(A=u.y-v.y, B=v.x-u.x, C=u.y*(u.x-v.x)-u.x*(u.y-v.y))
def is_parallel(u: line, v: line) -> bool:
f1 = False
f2 = False
try:
k1 = u.k()
except:
f1 = True
try:
k2 = v.k()
except:
f2 = True
if f1 != f2:
return False
return f1 or k1 == k2
def seg_len(_from: point, _to: point):
return ((_from.x - _to.x)**2 + (_from.y - _to.y)**2) ** 0.5
def in_range(_from: point, _to: point, _point: point) -> bool:
if _from.x < _to.x:
if _from.y < _to.y:
return _from.x <= _point.x <= _to.x and _from.y <= _point.y <= _to.y
else:
return _from.x <= _point.x <= _to.x and _from.y >= _point.y >= _to.y
else:
if _from.y < _to.y:
return _from.x >= _point.x >= _to.x and _from.y <= _point.y <= _to.y
else:
return _from.x >= _point.x >= _to.x and _from.y >= _point.y >= _to.y
def intersect(u: line, v: line) -> point:
tx = (u.B*v.C-v.B*u.C)/(v.B*u.A-u.B*v.A)
if u.B!=0.0:
ty = -u.A*tx/u.B - u.C/u.B
else:
ty = -v.A*tx/v.B - v.C/v.B
return point(x=tx, y=ty)
def in_direction(_from: point, _to: point, _point: point) -> bool:
if _from.x < _to.x:
if _from.y < _to.y:
return _to.x < _point.x and _to.y < _point.y
else:
return _to.x < _point.x and _point.y <= _to.y
else:
if _from.y < _to.y:
return _to.x >= _point.x and _to.y < _point.y
else:
return _to.x >= _point.x and _point.y <= _to.y
"""
mo = int(1e9+7)
def exgcd(a, b):
if not b:
return 1, 0
y, x = exgcd(b, a % b)
y -= a//b * x
return x, y
def getinv(a, m):
x, y = exgcd(a, m)
return -1 if x == 1 else x % m
def comb(n, b):
res = 1
b = min(b, n-b)
for i in range(b):
res = res*(n-i)*getinv(i+1, mo) % mo
# res %= mo
return res % mo
def quickpower(a, n):
res = 1
while n:
if n & 1:
res = res * a % mo
n >>= 1
a = a*a % mo
return res
def dis(a, b):
return abs(a[0]-b[0]) + abs(a[1]-b[1])
def getpref(x):
if x > 1:
return (x)*(x-1) >> 1
else:
return 0
def orafli(upp):
primes = []
marked = [False for i in range(upp+3)]
prvs = [i for i in range(upp+3)]
for i in range(2, upp):
if not marked[i]:
primes.append(i)
for j in primes:
if i*j >= upp:
break
marked[i*j] = True
prvs[i*j] = j
if i % j == 0:
break
return primes, prvs
def lower_ord(c: str) -> int:
return ord(c)-97
def upper_ord(c: str) -> int:
return ord(c) - 65
def read_list():
return [int(i) for i in input().split()]
def read_int():
s = input().split()
if len(s) == 1:
return int(s[0])
else:
return map(int, s)
def ask(s):
print(f"? {s}", flush=True)
def answer(s):
print(f"{s}", flush=True)
mo = int(1e9+7)
#;-
d = {
(1,0,0,1,0):'a',
(2,0,0,1,1):'c',
(2,1,0,1,2):'d',
(1,1,0,1,1):'e',
(2,1,0,2,1):'f',
(1,1,1,2,1):'o',
(1,2,1,3,1):'r',
(1,1,2,2,2):'z'
}
pss = []
# for i in range(3):
# for ii in range(3):
# for iii in range(3):
# for iiii in range(4):
# for iiiii in range(4):
# if i+ii+iii == iiii+iiiii:
# print(i,ii,iii,iiii,iiiii)
# pss.append((i,ii,iii,iiii,iiiii))
# print(pss)
def solve():
n,m = read_int()
a = []
for i in range(n):
a.append(input())
x = 0
y = 0
ans = 0
d = 0
if a[0][0] == '*':
ans += 1
while True:
xx,yy=n-1,m-1
ds = int(114514191981093111)
for i in range(x,n):
for j in range(y,m):
if i==x and y==j:
continue
if a[i][j]=='*':
if i-x+j-y < ds:
ds = i-x+j-y
xx = i
yy = j
elif i-x+j-y == ds and j > yy:
ds = i-x+j-y
xx = i
yy = j
if xx==n-1 and yy == m-1:
ans+=a[n-1][m-1]=="*"
break
x,y = xx,yy
ans+=1
print(ans)
# n,m = read_int()
# s1 = {23,4,13,14,11,8,19,7}
# s2 = {7,8,15,14,3,17,14,12,4}
# # print(n%26)
# # print(m%26)
# if n%26 in s1 or m%26 in s2:
# print('YES')
# else:
# print("NO")
# fi = open('C:\\cppHeaders\\CF2020.12.17\\test.data', 'r')
# def input(): return fi.readline().rstrip("\r\n")
# primes, prv = orafli(10001)
solve()
# t = int(input())
# for ti in range(t):
# print(f"Case #{ti+1}: ", end='')
# solve()
``` | output | 1 | 52,456 | 9 | 104,913 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A mouse encountered a nice big cake and decided to take a walk across it, eating the berries on top of the cake on its way. The cake is rectangular, neatly divided into squares; some of the squares have a berry in them, and some don't.
The mouse is in a bit of a hurry, though, so once she enters the cake from its northwest corner (the top left cell in the input data), she will only go east (right) or south (down), until she reaches the southeast corner (the bottom right cell). She will eat every berry in the squares she passes through, but not in the other squares.
The mouse tries to choose her path so as to maximize the number of berries consumed. However, her haste and hunger might be clouding her judgement, leading her to suboptimal decisions...
Input
The first line of input contains two integers H and W (1 ≤ H, W ≤ 5), separated by a space, — the height and the width of the cake.
The next H lines contain a string of W characters each, representing the squares of the cake in that row: '.' represents an empty square, and '*' represents a square with a berry.
Output
Output the number of berries the mouse will eat following her strategy.
Examples
Input
4 3
*..
.*.
..*
...
Output
3
Input
4 4
.*..
*...
...*
..*.
Output
2
Input
3 4
..**
*...
....
Output
1
Input
5 5
..*..
.....
**...
**...
**...
Output
1 | instruction | 0 | 52,458 | 9 | 104,916 |
Tags: *special, greedy, implementation, shortest paths
Correct Solution:
```
from sys import stdin, gettrace
if gettrace():
def inputi():
return input()
else:
def input():
return next(stdin)[:-1]
def inputi():
return stdin.buffer.readline()
def main():
h,w = map(int, input().split())
cake = [input() for _ in range(h)]
mx = 0
my = 0
res = 0
if cake[0][0] == '*':
res += 1
while mx < w:
for i in range(1, w-mx+h-my):
for j in range(0, i+1):
x = mx + i - j
y = my + j
if x < w and y < h and cake[y][x] == '*':
res += 1
mx = x
my = y
break
else:
continue
break
else:
mx = w
print(res)
if __name__ == "__main__":
main()
``` | output | 1 | 52,458 | 9 | 104,917 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A mouse encountered a nice big cake and decided to take a walk across it, eating the berries on top of the cake on its way. The cake is rectangular, neatly divided into squares; some of the squares have a berry in them, and some don't.
The mouse is in a bit of a hurry, though, so once she enters the cake from its northwest corner (the top left cell in the input data), she will only go east (right) or south (down), until she reaches the southeast corner (the bottom right cell). She will eat every berry in the squares she passes through, but not in the other squares.
The mouse tries to choose her path so as to maximize the number of berries consumed. However, her haste and hunger might be clouding her judgement, leading her to suboptimal decisions...
Input
The first line of input contains two integers H and W (1 ≤ H, W ≤ 5), separated by a space, — the height and the width of the cake.
The next H lines contain a string of W characters each, representing the squares of the cake in that row: '.' represents an empty square, and '*' represents a square with a berry.
Output
Output the number of berries the mouse will eat following her strategy.
Examples
Input
4 3
*..
.*.
..*
...
Output
3
Input
4 4
.*..
*...
...*
..*.
Output
2
Input
3 4
..**
*...
....
Output
1
Input
5 5
..*..
.....
**...
**...
**...
Output
1 | instruction | 0 | 52,459 | 9 | 104,918 |
Tags: *special, greedy, implementation, shortest paths
Correct Solution:
```
h, w = [int(i) for i in input().split()]
a, b = 1, 1
cherry = []
r = 0
for i in range(h):
line = input()
for j in range(w):
if line[j] == '*':
cherry.append((i+1,j+1))
def remov(point):
global a, b
_p1, _p2 = point
if _p1 < a or _p2 < b:
return False
else:
return True
def distance(point):
global a, b
_p1, _p2 = point
return abs(a-_p1) + abs(b-_p2)
def srt(point):
_p1, _p2 = point
return (distance(point), _p1, _p2)
while True:
if a==h and b==w:
break
cherry = list(filter(remov, cherry))
cherry.sort(key=srt)
#print(cherry)
if not cherry:
break
a, b = cherry.pop(0)
r += 1
print(r)
``` | output | 1 | 52,459 | 9 | 104,919 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A mouse encountered a nice big cake and decided to take a walk across it, eating the berries on top of the cake on its way. The cake is rectangular, neatly divided into squares; some of the squares have a berry in them, and some don't.
The mouse is in a bit of a hurry, though, so once she enters the cake from its northwest corner (the top left cell in the input data), she will only go east (right) or south (down), until she reaches the southeast corner (the bottom right cell). She will eat every berry in the squares she passes through, but not in the other squares.
The mouse tries to choose her path so as to maximize the number of berries consumed. However, her haste and hunger might be clouding her judgement, leading her to suboptimal decisions...
Input
The first line of input contains two integers H and W (1 ≤ H, W ≤ 5), separated by a space, — the height and the width of the cake.
The next H lines contain a string of W characters each, representing the squares of the cake in that row: '.' represents an empty square, and '*' represents a square with a berry.
Output
Output the number of berries the mouse will eat following her strategy.
Examples
Input
4 3
*..
.*.
..*
...
Output
3
Input
4 4
.*..
*...
...*
..*.
Output
2
Input
3 4
..**
*...
....
Output
1
Input
5 5
..*..
.....
**...
**...
**...
Output
1 | instruction | 0 | 52,460 | 9 | 104,920 |
Tags: *special, greedy, implementation, shortest paths
Correct Solution:
```
# greedy, prefer right?
from collections import defaultdict as dd, deque
n,m = [int(x) for x in input().split()]
S = [[c == '*' for c in input()] for _ in range(n)]
def next_move(sx, sy):
Q = deque()
Q.append((sx,sy, 0))
res = []
while Q:
x, y, d = Q.popleft()
if x != -1 and S[y][x] and d > 0:
res.append((d, y, x))
if x != m-1:
Q.append((x+1, y, d+1))
if x != -1 and y != n-1:
Q.append((x, y+1, d+1))
res.sort()
if res:
d,y,x = res[0]
return x,y
return None
x,y = -1,0
r = 0
while True:
nxt = next_move(x, y)
if not nxt:
break
x,y = nxt
r += 1
print(r)
``` | output | 1 | 52,460 | 9 | 104,921 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A mouse encountered a nice big cake and decided to take a walk across it, eating the berries on top of the cake on its way. The cake is rectangular, neatly divided into squares; some of the squares have a berry in them, and some don't.
The mouse is in a bit of a hurry, though, so once she enters the cake from its northwest corner (the top left cell in the input data), she will only go east (right) or south (down), until she reaches the southeast corner (the bottom right cell). She will eat every berry in the squares she passes through, but not in the other squares.
The mouse tries to choose her path so as to maximize the number of berries consumed. However, her haste and hunger might be clouding her judgement, leading her to suboptimal decisions...
Input
The first line of input contains two integers H and W (1 ≤ H, W ≤ 5), separated by a space, — the height and the width of the cake.
The next H lines contain a string of W characters each, representing the squares of the cake in that row: '.' represents an empty square, and '*' represents a square with a berry.
Output
Output the number of berries the mouse will eat following her strategy.
Examples
Input
4 3
*..
.*.
..*
...
Output
3
Input
4 4
.*..
*...
...*
..*.
Output
2
Input
3 4
..**
*...
....
Output
1
Input
5 5
..*..
.....
**...
**...
**...
Output
1 | instruction | 0 | 52,461 | 9 | 104,922 |
Tags: *special, greedy, implementation, shortest paths
Correct Solution:
```
import sys
import math
from collections import deque, defaultdict
#print = sys.stdout.write
from string import ascii_letters
letters = ascii_letters[:26]
ONLINE_JUDGE = 0
if any(['--local' in i for i in sys.argv]) and not ONLINE_JUDGE:
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
n, m = map(int, input().split())
pos = [0, 0]
ans = 0
arr = [list(input()) for i in range(n)]
while True:
ind = (-1, -1)
v = 9999999
for i in range(n):
for g in range(m):
if i < pos[0] or g < pos[1]:
continue
if arr[i][g] != '*':
continue
d = abs(i - pos[0]) + abs(g - pos[1])
if d < v:
v = d
ind = (i, g)
if ind[0] == -1:
break
arr[ind[0]][ind[1]] = '.'
pos = (ind[0], ind[1])
ans += 1
print(ans)
``` | output | 1 | 52,461 | 9 | 104,923 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A mouse encountered a nice big cake and decided to take a walk across it, eating the berries on top of the cake on its way. The cake is rectangular, neatly divided into squares; some of the squares have a berry in them, and some don't.
The mouse is in a bit of a hurry, though, so once she enters the cake from its northwest corner (the top left cell in the input data), she will only go east (right) or south (down), until she reaches the southeast corner (the bottom right cell). She will eat every berry in the squares she passes through, but not in the other squares.
The mouse tries to choose her path so as to maximize the number of berries consumed. However, her haste and hunger might be clouding her judgement, leading her to suboptimal decisions...
Input
The first line of input contains two integers H and W (1 ≤ H, W ≤ 5), separated by a space, — the height and the width of the cake.
The next H lines contain a string of W characters each, representing the squares of the cake in that row: '.' represents an empty square, and '*' represents a square with a berry.
Output
Output the number of berries the mouse will eat following her strategy.
Examples
Input
4 3
*..
.*.
..*
...
Output
3
Input
4 4
.*..
*...
...*
..*.
Output
2
Input
3 4
..**
*...
....
Output
1
Input
5 5
..*..
.....
**...
**...
**...
Output
1 | instruction | 0 | 52,462 | 9 | 104,924 |
Tags: *special, greedy, implementation, shortest paths
Correct Solution:
```
n, m = map(int, input().split())
ar = [input() for i in range(n)]
x = 0
y = 0
res = 0
while True:
res += 1 if ar[x][y] == '*' else 0
if x == n - 1 and y == m - 1:
break
elif x == n - 1:
y += 1
elif y == m - 1:
x += 1
elif ar[x][y + 1] == '*':
y += 1
elif ar[x + 1][y] == '*':
x += 1
else:
y += 1
print(res)
``` | output | 1 | 52,462 | 9 | 104,925 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.