message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.
She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:
If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then
* if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie.
* if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie.
After that:
* If there is at least one cookie of the selected type, the guest eats one.
* Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home.
Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.
For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).
Output
For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".
You can print each letter in any case (upper or lower).
Example
Input
6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000
Output
Yes
No
No
Yes
No
Yes
Note
In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:
* The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1 chocolate cookie.
* The second guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 0 chocolate cookies.
* The last guest selects a chocolate cookie, but there are no chocolate cookies. So, the guest gets angry.
So, this order can't be chosen by Anna.
Let's consider the order \{2, 2, 1\} of types of guests. Then:
* The first guest eats a vanilla cookie. After that, there is 1 vanilla cookie and 2 chocolate cookies.
* The second guest eats a vanilla cookie. After that, there are 0 vanilla cookies and 2 chocolate cookies.
* The last guest eats a chocolate cookie. After that, there are 0 vanilla cookies and 1 chocolate cookie.
So, the answer to this test case is "Yes".
In the fifth test case, it is illustrated, that the number of cookies (a + b) can be equal to zero, but the number of guests (n + m) can't be equal to zero.
In the sixth test case, be careful about the overflow of 32-bit integer type.
Submitted Solution:
```
for i in range(int(input())):
a,b,n,m=map(int,input().split())
if m<=min(a,b) and a+b>=m+n:
print("Yes")
else:
print("No")
``` | instruction | 0 | 61,643 | 9 | 123,286 |
Yes | output | 1 | 61,643 | 9 | 123,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.
She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:
If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then
* if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie.
* if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie.
After that:
* If there is at least one cookie of the selected type, the guest eats one.
* Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home.
Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.
For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).
Output
For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".
You can print each letter in any case (upper or lower).
Example
Input
6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000
Output
Yes
No
No
Yes
No
Yes
Note
In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:
* The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1 chocolate cookie.
* The second guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 0 chocolate cookies.
* The last guest selects a chocolate cookie, but there are no chocolate cookies. So, the guest gets angry.
So, this order can't be chosen by Anna.
Let's consider the order \{2, 2, 1\} of types of guests. Then:
* The first guest eats a vanilla cookie. After that, there is 1 vanilla cookie and 2 chocolate cookies.
* The second guest eats a vanilla cookie. After that, there are 0 vanilla cookies and 2 chocolate cookies.
* The last guest eats a chocolate cookie. After that, there are 0 vanilla cookies and 1 chocolate cookie.
So, the answer to this test case is "Yes".
In the fifth test case, it is illustrated, that the number of cookies (a + b) can be equal to zero, but the number of guests (n + m) can't be equal to zero.
In the sixth test case, be careful about the overflow of 32-bit integer type.
Submitted Solution:
```
for w in range(int(input())):
a,b,n,m=map(int,input().strip().split())
if m<=min(a,b) and n+m<=a+b:
print("YES")
else:
print("NO")
``` | instruction | 0 | 61,644 | 9 | 123,288 |
Yes | output | 1 | 61,644 | 9 | 123,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.
She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:
If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then
* if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie.
* if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie.
After that:
* If there is at least one cookie of the selected type, the guest eats one.
* Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home.
Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.
For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).
Output
For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".
You can print each letter in any case (upper or lower).
Example
Input
6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000
Output
Yes
No
No
Yes
No
Yes
Note
In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:
* The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1 chocolate cookie.
* The second guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 0 chocolate cookies.
* The last guest selects a chocolate cookie, but there are no chocolate cookies. So, the guest gets angry.
So, this order can't be chosen by Anna.
Let's consider the order \{2, 2, 1\} of types of guests. Then:
* The first guest eats a vanilla cookie. After that, there is 1 vanilla cookie and 2 chocolate cookies.
* The second guest eats a vanilla cookie. After that, there are 0 vanilla cookies and 2 chocolate cookies.
* The last guest eats a chocolate cookie. After that, there are 0 vanilla cookies and 1 chocolate cookie.
So, the answer to this test case is "Yes".
In the fifth test case, it is illustrated, that the number of cookies (a + b) can be equal to zero, but the number of guests (n + m) can't be equal to zero.
In the sixth test case, be careful about the overflow of 32-bit integer type.
Submitted Solution:
```
t=int(input())
for j in range(t):
a,b,n,m=map(int,input().split())
if(n+m<=a+b and m<=min(a,b)):
print("YES")
else:
print("NO")
``` | instruction | 0 | 61,645 | 9 | 123,290 |
Yes | output | 1 | 61,645 | 9 | 123,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.
She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:
If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then
* if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie.
* if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie.
After that:
* If there is at least one cookie of the selected type, the guest eats one.
* Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home.
Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.
For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).
Output
For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".
You can print each letter in any case (upper or lower).
Example
Input
6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000
Output
Yes
No
No
Yes
No
Yes
Note
In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:
* The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1 chocolate cookie.
* The second guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 0 chocolate cookies.
* The last guest selects a chocolate cookie, but there are no chocolate cookies. So, the guest gets angry.
So, this order can't be chosen by Anna.
Let's consider the order \{2, 2, 1\} of types of guests. Then:
* The first guest eats a vanilla cookie. After that, there is 1 vanilla cookie and 2 chocolate cookies.
* The second guest eats a vanilla cookie. After that, there are 0 vanilla cookies and 2 chocolate cookies.
* The last guest eats a chocolate cookie. After that, there are 0 vanilla cookies and 1 chocolate cookie.
So, the answer to this test case is "Yes".
In the fifth test case, it is illustrated, that the number of cookies (a + b) can be equal to zero, but the number of guests (n + m) can't be equal to zero.
In the sixth test case, be careful about the overflow of 32-bit integer type.
Submitted Solution:
```
for _ in range(int(input())):
a,b,n,m = map(int,input().split())
k = 0
if a+b<n+m:
k = 0
else:
k = 1
if k==1:
if min(a,b)>=m:
k = 1
else:
k = 0
if k==1:
print("Yes")
else:
print("No")
``` | instruction | 0 | 61,646 | 9 | 123,292 |
Yes | output | 1 | 61,646 | 9 | 123,293 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.
She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:
If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then
* if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie.
* if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie.
After that:
* If there is at least one cookie of the selected type, the guest eats one.
* Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home.
Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.
For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).
Output
For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".
You can print each letter in any case (upper or lower).
Example
Input
6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000
Output
Yes
No
No
Yes
No
Yes
Note
In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:
* The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1 chocolate cookie.
* The second guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 0 chocolate cookies.
* The last guest selects a chocolate cookie, but there are no chocolate cookies. So, the guest gets angry.
So, this order can't be chosen by Anna.
Let's consider the order \{2, 2, 1\} of types of guests. Then:
* The first guest eats a vanilla cookie. After that, there is 1 vanilla cookie and 2 chocolate cookies.
* The second guest eats a vanilla cookie. After that, there are 0 vanilla cookies and 2 chocolate cookies.
* The last guest eats a chocolate cookie. After that, there are 0 vanilla cookies and 1 chocolate cookie.
So, the answer to this test case is "Yes".
In the fifth test case, it is illustrated, that the number of cookies (a + b) can be equal to zero, but the number of guests (n + m) can't be equal to zero.
In the sixth test case, be careful about the overflow of 32-bit integer type.
Submitted Solution:
```
def solu(a,b,n,m):
v = max(a,b)
c = min(a,b)
if(v+c<n+m):
return False
if(m>min(v,c)):
return False
return True
nt = int(input())
for i in range(nt):
arr = input().split(" ")
if(nt==1000 and i == 15):
print(arr)
if(solu(arr[0],arr[1],arr[2],arr[3])):
print("Yes")
else:
print("No")
``` | instruction | 0 | 61,647 | 9 | 123,294 |
No | output | 1 | 61,647 | 9 | 123,295 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.
She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:
If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then
* if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie.
* if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie.
After that:
* If there is at least one cookie of the selected type, the guest eats one.
* Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home.
Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.
For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).
Output
For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".
You can print each letter in any case (upper or lower).
Example
Input
6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000
Output
Yes
No
No
Yes
No
Yes
Note
In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:
* The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1 chocolate cookie.
* The second guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 0 chocolate cookies.
* The last guest selects a chocolate cookie, but there are no chocolate cookies. So, the guest gets angry.
So, this order can't be chosen by Anna.
Let's consider the order \{2, 2, 1\} of types of guests. Then:
* The first guest eats a vanilla cookie. After that, there is 1 vanilla cookie and 2 chocolate cookies.
* The second guest eats a vanilla cookie. After that, there are 0 vanilla cookies and 2 chocolate cookies.
* The last guest eats a chocolate cookie. After that, there are 0 vanilla cookies and 1 chocolate cookie.
So, the answer to this test case is "Yes".
In the fifth test case, it is illustrated, that the number of cookies (a + b) can be equal to zero, but the number of guests (n + m) can't be equal to zero.
In the sixth test case, be careful about the overflow of 32-bit integer type.
Submitted Solution:
```
for gg in range(int(input())):
a,b,n,m=map(int,input().split())
if(a+b<n+m):
print("NO")
continue
else:
if(m>=min(a,b)):
print("NO")
else:
print("YES")
``` | instruction | 0 | 61,648 | 9 | 123,296 |
No | output | 1 | 61,648 | 9 | 123,297 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.
She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:
If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then
* if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie.
* if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie.
After that:
* If there is at least one cookie of the selected type, the guest eats one.
* Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home.
Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.
For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).
Output
For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".
You can print each letter in any case (upper or lower).
Example
Input
6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000
Output
Yes
No
No
Yes
No
Yes
Note
In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:
* The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1 chocolate cookie.
* The second guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 0 chocolate cookies.
* The last guest selects a chocolate cookie, but there are no chocolate cookies. So, the guest gets angry.
So, this order can't be chosen by Anna.
Let's consider the order \{2, 2, 1\} of types of guests. Then:
* The first guest eats a vanilla cookie. After that, there is 1 vanilla cookie and 2 chocolate cookies.
* The second guest eats a vanilla cookie. After that, there are 0 vanilla cookies and 2 chocolate cookies.
* The last guest eats a chocolate cookie. After that, there are 0 vanilla cookies and 1 chocolate cookie.
So, the answer to this test case is "Yes".
In the fifth test case, it is illustrated, that the number of cookies (a + b) can be equal to zero, but the number of guests (n + m) can't be equal to zero.
In the sixth test case, be careful about the overflow of 32-bit integer type.
Submitted Solution:
```
for _ in range(int(input())):
a,b,n,m=map(int,input().split())
if(a+b<n+m):
print("No")
continue
elif (a==0 or b==0) and n<=m:
print("No")
continue
print("Yes")
``` | instruction | 0 | 61,649 | 9 | 123,298 |
No | output | 1 | 61,649 | 9 | 123,299 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anna is a girl so brave that she is loved by everyone in the city and citizens love her cookies. She is planning to hold a party with cookies. Now she has a vanilla cookies and b chocolate cookies for the party.
She invited n guests of the first type and m guests of the second type to the party. They will come to the party in some order. After coming to the party, each guest will choose the type of cookie (vanilla or chocolate) to eat. There is a difference in the way how they choose that type:
If there are v vanilla cookies and c chocolate cookies at the moment, when the guest comes, then
* if the guest of the first type: if v>c the guest selects a vanilla cookie. Otherwise, the guest selects a chocolate cookie.
* if the guest of the second type: if v>c the guest selects a chocolate cookie. Otherwise, the guest selects a vanilla cookie.
After that:
* If there is at least one cookie of the selected type, the guest eats one.
* Otherwise (there are no cookies of the selected type), the guest gets angry and returns to home.
Anna wants to know if there exists some order of guests, such that no one guest gets angry. Your task is to answer her question.
Input
The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Next t lines contain descriptions of test cases.
For each test case, the only line contains four integers a, b, n, m (0 ≤ a,b,n,m ≤ 10^{18}, n+m ≠ 0).
Output
For each test case, print the answer in one line. If there exists at least one valid order, print "Yes". Otherwise, print "No".
You can print each letter in any case (upper or lower).
Example
Input
6
2 2 1 2
0 100 0 1
12 13 25 1
27 83 14 25
0 0 1 0
1000000000000000000 1000000000000000000 1000000000000000000 1000000000000000000
Output
Yes
No
No
Yes
No
Yes
Note
In the first test case, let's consider the order \{1, 2, 2\} of types of guests. Then:
* The first guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 1 chocolate cookie.
* The second guest eats a chocolate cookie. After that, there are 2 vanilla cookies and 0 chocolate cookies.
* The last guest selects a chocolate cookie, but there are no chocolate cookies. So, the guest gets angry.
So, this order can't be chosen by Anna.
Let's consider the order \{2, 2, 1\} of types of guests. Then:
* The first guest eats a vanilla cookie. After that, there is 1 vanilla cookie and 2 chocolate cookies.
* The second guest eats a vanilla cookie. After that, there are 0 vanilla cookies and 2 chocolate cookies.
* The last guest eats a chocolate cookie. After that, there are 0 vanilla cookies and 1 chocolate cookie.
So, the answer to this test case is "Yes".
In the fifth test case, it is illustrated, that the number of cookies (a + b) can be equal to zero, but the number of guests (n + m) can't be equal to zero.
In the sixth test case, be careful about the overflow of 32-bit integer type.
Submitted Solution:
```
t=int(input())
for _ in range(t):
a,b,n,m=map(int,input().split())
if m+n>a+b:
print("No")
elif min(a,b)>m:
print("Yes")
else:
print("No")
``` | instruction | 0 | 61,650 | 9 | 123,300 |
No | output | 1 | 61,650 | 9 | 123,301 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a random day, Neko found n treasure chests and m keys. The i-th chest has an integer a_i written on it and the j-th key has an integer b_j on it. Neko knows those chests contain the powerful mysterious green Grapes, thus Neko wants to open as many treasure chests as possible.
The j-th key can be used to unlock the i-th chest if and only if the sum of the key number and the chest number is an odd number. Formally, a_i + b_j ≡ 1 \pmod{2}. One key can be used to open at most one chest, and one chest can be opened at most once.
Find the maximum number of chests Neko can open.
Input
The first line contains integers n and m (1 ≤ n, m ≤ 10^5) — the number of chests and the number of keys.
The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the numbers written on the treasure chests.
The third line contains m integers b_1, b_2, …, b_m (1 ≤ b_i ≤ 10^9) — the numbers written on the keys.
Output
Print the maximum number of chests you can open.
Examples
Input
5 4
9 14 6 2 11
8 4 7 20
Output
3
Input
5 1
2 4 6 8 10
5
Output
1
Input
1 4
10
20 30 40 50
Output
0
Note
In the first example, one possible way to unlock 3 chests is as follows:
* Use first key to unlock the fifth chest,
* Use third key to unlock the second chest,
* Use fourth key to unlock the first chest.
In the second example, you can use the only key to unlock any single chest (note that one key can't be used twice).
In the third example, no key can unlock the given chest. | instruction | 0 | 62,339 | 9 | 124,678 |
Tags: greedy, implementation, math
Correct Solution:
```
import collections
def solve():
N,M = map(int,input().split())
A = list(map(int,input().split()))
B = list(map(int,input().split()))
A = [a%2 for a in A]
B = [b%2 for b in B]
cntA = collections.Counter(A)
cntB = collections.Counter(B)
return min(cntA[0], cntB[1]) + min(cntA[1], cntB[0])
print(solve())
``` | output | 1 | 62,339 | 9 | 124,679 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a random day, Neko found n treasure chests and m keys. The i-th chest has an integer a_i written on it and the j-th key has an integer b_j on it. Neko knows those chests contain the powerful mysterious green Grapes, thus Neko wants to open as many treasure chests as possible.
The j-th key can be used to unlock the i-th chest if and only if the sum of the key number and the chest number is an odd number. Formally, a_i + b_j ≡ 1 \pmod{2}. One key can be used to open at most one chest, and one chest can be opened at most once.
Find the maximum number of chests Neko can open.
Input
The first line contains integers n and m (1 ≤ n, m ≤ 10^5) — the number of chests and the number of keys.
The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the numbers written on the treasure chests.
The third line contains m integers b_1, b_2, …, b_m (1 ≤ b_i ≤ 10^9) — the numbers written on the keys.
Output
Print the maximum number of chests you can open.
Examples
Input
5 4
9 14 6 2 11
8 4 7 20
Output
3
Input
5 1
2 4 6 8 10
5
Output
1
Input
1 4
10
20 30 40 50
Output
0
Note
In the first example, one possible way to unlock 3 chests is as follows:
* Use first key to unlock the fifth chest,
* Use third key to unlock the second chest,
* Use fourth key to unlock the first chest.
In the second example, you can use the only key to unlock any single chest (note that one key can't be used twice).
In the third example, no key can unlock the given chest. | instruction | 0 | 62,340 | 9 | 124,680 |
Tags: greedy, implementation, math
Correct Solution:
```
n,m = map(int,input().split())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
odd,oddn = 0,0
even,eve =0,0
for i in range(m):
if b[i]%2:odd = odd + 1
else:even = even + 1
for j in range(n):
if a[j]%2:oddn = oddn + 1
else:eve = eve + 1
mo = min(odd,eve)
me = min(even,oddn)
print(mo+me)
``` | output | 1 | 62,340 | 9 | 124,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a random day, Neko found n treasure chests and m keys. The i-th chest has an integer a_i written on it and the j-th key has an integer b_j on it. Neko knows those chests contain the powerful mysterious green Grapes, thus Neko wants to open as many treasure chests as possible.
The j-th key can be used to unlock the i-th chest if and only if the sum of the key number and the chest number is an odd number. Formally, a_i + b_j ≡ 1 \pmod{2}. One key can be used to open at most one chest, and one chest can be opened at most once.
Find the maximum number of chests Neko can open.
Input
The first line contains integers n and m (1 ≤ n, m ≤ 10^5) — the number of chests and the number of keys.
The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the numbers written on the treasure chests.
The third line contains m integers b_1, b_2, …, b_m (1 ≤ b_i ≤ 10^9) — the numbers written on the keys.
Output
Print the maximum number of chests you can open.
Examples
Input
5 4
9 14 6 2 11
8 4 7 20
Output
3
Input
5 1
2 4 6 8 10
5
Output
1
Input
1 4
10
20 30 40 50
Output
0
Note
In the first example, one possible way to unlock 3 chests is as follows:
* Use first key to unlock the fifth chest,
* Use third key to unlock the second chest,
* Use fourth key to unlock the first chest.
In the second example, you can use the only key to unlock any single chest (note that one key can't be used twice).
In the third example, no key can unlock the given chest. | instruction | 0 | 62,341 | 9 | 124,682 |
Tags: greedy, implementation, math
Correct Solution:
```
n, m = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
a = b = c = d = 0
for i in range(n):
if A[i] % 2 == 0:
a += 1
else:
b += 1
for i in range(m):
if B[i] % 2 == 0:
c += 1
else:
d += 1
print (min(a, d) + min (b, c))
``` | output | 1 | 62,341 | 9 | 124,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a random day, Neko found n treasure chests and m keys. The i-th chest has an integer a_i written on it and the j-th key has an integer b_j on it. Neko knows those chests contain the powerful mysterious green Grapes, thus Neko wants to open as many treasure chests as possible.
The j-th key can be used to unlock the i-th chest if and only if the sum of the key number and the chest number is an odd number. Formally, a_i + b_j ≡ 1 \pmod{2}. One key can be used to open at most one chest, and one chest can be opened at most once.
Find the maximum number of chests Neko can open.
Input
The first line contains integers n and m (1 ≤ n, m ≤ 10^5) — the number of chests and the number of keys.
The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the numbers written on the treasure chests.
The third line contains m integers b_1, b_2, …, b_m (1 ≤ b_i ≤ 10^9) — the numbers written on the keys.
Output
Print the maximum number of chests you can open.
Examples
Input
5 4
9 14 6 2 11
8 4 7 20
Output
3
Input
5 1
2 4 6 8 10
5
Output
1
Input
1 4
10
20 30 40 50
Output
0
Note
In the first example, one possible way to unlock 3 chests is as follows:
* Use first key to unlock the fifth chest,
* Use third key to unlock the second chest,
* Use fourth key to unlock the first chest.
In the second example, you can use the only key to unlock any single chest (note that one key can't be used twice).
In the third example, no key can unlock the given chest. | instruction | 0 | 62,343 | 9 | 124,686 |
Tags: greedy, implementation, math
Correct Solution:
```
n, m = list(map(lambda x: int(x), input().split()))
Ai = list(map(lambda x: int(x), input().split()))
Bi = list(map(lambda x: int(x), input().split()))
Astats = [0, 0] #[odd, even]
Bstats = [0, 0]
for i in Ai:
if i%2 == 0: Astats[1] += 1
else: Astats[0] += 1
for i in Bi:
if i%2 == 0: Bstats[1] += 1
else: Bstats[0] += 1
print(min(Astats[1], Bstats[0]) + min(Astats[0], Bstats[1]))
``` | output | 1 | 62,343 | 9 | 124,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a random day, Neko found n treasure chests and m keys. The i-th chest has an integer a_i written on it and the j-th key has an integer b_j on it. Neko knows those chests contain the powerful mysterious green Grapes, thus Neko wants to open as many treasure chests as possible.
The j-th key can be used to unlock the i-th chest if and only if the sum of the key number and the chest number is an odd number. Formally, a_i + b_j ≡ 1 \pmod{2}. One key can be used to open at most one chest, and one chest can be opened at most once.
Find the maximum number of chests Neko can open.
Input
The first line contains integers n and m (1 ≤ n, m ≤ 10^5) — the number of chests and the number of keys.
The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the numbers written on the treasure chests.
The third line contains m integers b_1, b_2, …, b_m (1 ≤ b_i ≤ 10^9) — the numbers written on the keys.
Output
Print the maximum number of chests you can open.
Examples
Input
5 4
9 14 6 2 11
8 4 7 20
Output
3
Input
5 1
2 4 6 8 10
5
Output
1
Input
1 4
10
20 30 40 50
Output
0
Note
In the first example, one possible way to unlock 3 chests is as follows:
* Use first key to unlock the fifth chest,
* Use third key to unlock the second chest,
* Use fourth key to unlock the first chest.
In the second example, you can use the only key to unlock any single chest (note that one key can't be used twice).
In the third example, no key can unlock the given chest. | instruction | 0 | 62,344 | 9 | 124,688 |
Tags: greedy, implementation, math
Correct Solution:
```
n = input()
lc = [int(i) for i in input().split()]
lk = [int(i) for i in input().split()]
co = 0
ce = 0
for i in lc:
if(i%2 == 0):
ce +=1
else:
co+=1
ko = 0
ke = 0
for i in lk:
if(i%2 == 0):
ke+=1
else:
ko+=1
print(min(co,ke)+min(ce,ko))
``` | output | 1 | 62,344 | 9 | 124,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a random day, Neko found n treasure chests and m keys. The i-th chest has an integer a_i written on it and the j-th key has an integer b_j on it. Neko knows those chests contain the powerful mysterious green Grapes, thus Neko wants to open as many treasure chests as possible.
The j-th key can be used to unlock the i-th chest if and only if the sum of the key number and the chest number is an odd number. Formally, a_i + b_j ≡ 1 \pmod{2}. One key can be used to open at most one chest, and one chest can be opened at most once.
Find the maximum number of chests Neko can open.
Input
The first line contains integers n and m (1 ≤ n, m ≤ 10^5) — the number of chests and the number of keys.
The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the numbers written on the treasure chests.
The third line contains m integers b_1, b_2, …, b_m (1 ≤ b_i ≤ 10^9) — the numbers written on the keys.
Output
Print the maximum number of chests you can open.
Examples
Input
5 4
9 14 6 2 11
8 4 7 20
Output
3
Input
5 1
2 4 6 8 10
5
Output
1
Input
1 4
10
20 30 40 50
Output
0
Note
In the first example, one possible way to unlock 3 chests is as follows:
* Use first key to unlock the fifth chest,
* Use third key to unlock the second chest,
* Use fourth key to unlock the first chest.
In the second example, you can use the only key to unlock any single chest (note that one key can't be used twice).
In the third example, no key can unlock the given chest. | instruction | 0 | 62,345 | 9 | 124,690 |
Tags: greedy, implementation, math
Correct Solution:
```
n,m=list(map(int,input().strip().split()))
a=list(map(int,input().strip().split()))
b=list(map(int,input().strip().split()))
c=0
d=0
e=0
f=0
for i in range(n):
if a[i]%2==0:
c=c+1
else:
d=d+1
for j in range(m):
if b[j]%2==0:
e=e+1
else:
f=f+1
print(min(c,f)+min(d,e))
``` | output | 1 | 62,345 | 9 | 124,691 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On a random day, Neko found n treasure chests and m keys. The i-th chest has an integer a_i written on it and the j-th key has an integer b_j on it. Neko knows those chests contain the powerful mysterious green Grapes, thus Neko wants to open as many treasure chests as possible.
The j-th key can be used to unlock the i-th chest if and only if the sum of the key number and the chest number is an odd number. Formally, a_i + b_j ≡ 1 \pmod{2}. One key can be used to open at most one chest, and one chest can be opened at most once.
Find the maximum number of chests Neko can open.
Input
The first line contains integers n and m (1 ≤ n, m ≤ 10^5) — the number of chests and the number of keys.
The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^9) — the numbers written on the treasure chests.
The third line contains m integers b_1, b_2, …, b_m (1 ≤ b_i ≤ 10^9) — the numbers written on the keys.
Output
Print the maximum number of chests you can open.
Examples
Input
5 4
9 14 6 2 11
8 4 7 20
Output
3
Input
5 1
2 4 6 8 10
5
Output
1
Input
1 4
10
20 30 40 50
Output
0
Note
In the first example, one possible way to unlock 3 chests is as follows:
* Use first key to unlock the fifth chest,
* Use third key to unlock the second chest,
* Use fourth key to unlock the first chest.
In the second example, you can use the only key to unlock any single chest (note that one key can't be used twice).
In the third example, no key can unlock the given chest. | instruction | 0 | 62,346 | 9 | 124,692 |
Tags: greedy, implementation, math
Correct Solution:
```
n,m = map(int, input().split())
A = list(map(int, input().split()))
B = list(map(int, input().split()))
n = len(A)
m = len(B)
AA = [0,0];
BB = [0,0];
for i in A:
AA[i%2] +=1
for i in B:
BB[i%2] +=1
print( min(AA[0], BB[1]) + min(AA[1], BB[0]))
``` | output | 1 | 62,346 | 9 | 124,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As we all know, Winnie-the-Pooh just adores honey. Ones he and the Piglet found out that the Rabbit has recently gotten hold of an impressive amount of this sweet and healthy snack. As you may guess, Winnie and the Piglet asked to come at the Rabbit's place. Thus, there are n jars of honey lined up in front of Winnie-the-Pooh, jar number i contains ai kilos of honey. Winnie-the-Pooh eats the honey like that: each time he chooses a jar containing most honey. If the jar has less that k kilos of honey or if Winnie-the-Pooh has already eaten from it three times, he gives the jar to Piglet. Otherwise he eats exactly k kilos of honey from the jar and puts it back. Winnie does so until he gives all jars to the Piglet. Count how much honey Piglet will overall get after Winnie satisfies his hunger.
Input
The first line contains two integers n and k (1 ≤ n ≤ 100, 1 ≤ k ≤ 100). The second line contains n integers a1, a2, ..., an, separated by spaces (1 ≤ ai ≤ 100).
Output
Print a single number — how many kilos of honey gets Piglet.
Examples
Input
3 3
15 8 10
Output
9
Submitted Solution:
```
import sys
import math
f = open('input.txt', 'r')
n, k = [int(x) for x in (f.readline()).split()]
an = list(map(int, (f.readline()).split()))
f.close()
res = 0
for i in an:
if(i < k):
res += i
else:
res += i - min(int(i / k), k) * k
fr = open('output.txt', 'w')
fr.write(str(res))
fr.close()
``` | instruction | 0 | 62,371 | 9 | 124,742 |
No | output | 1 | 62,371 | 9 | 124,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As we all know, Winnie-the-Pooh just adores honey. Ones he and the Piglet found out that the Rabbit has recently gotten hold of an impressive amount of this sweet and healthy snack. As you may guess, Winnie and the Piglet asked to come at the Rabbit's place. Thus, there are n jars of honey lined up in front of Winnie-the-Pooh, jar number i contains ai kilos of honey. Winnie-the-Pooh eats the honey like that: each time he chooses a jar containing most honey. If the jar has less that k kilos of honey or if Winnie-the-Pooh has already eaten from it three times, he gives the jar to Piglet. Otherwise he eats exactly k kilos of honey from the jar and puts it back. Winnie does so until he gives all jars to the Piglet. Count how much honey Piglet will overall get after Winnie satisfies his hunger.
Input
The first line contains two integers n and k (1 ≤ n ≤ 100, 1 ≤ k ≤ 100). The second line contains n integers a1, a2, ..., an, separated by spaces (1 ≤ ai ≤ 100).
Output
Print a single number — how many kilos of honey gets Piglet.
Examples
Input
3 3
15 8 10
Output
9
Submitted Solution:
```
f = open('input.txt', 'r')
g = open('output.txt', 'w')
n, k = map(int, f.readline().split())
a = list(map(int, f.readline().split()))
s, result = sum(a), 0
for elem in a:
result += int(k * min(elem // k, 3))
print(result, file=g)
``` | instruction | 0 | 62,372 | 9 | 124,744 |
No | output | 1 | 62,372 | 9 | 124,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As we all know, Winnie-the-Pooh just adores honey. Ones he and the Piglet found out that the Rabbit has recently gotten hold of an impressive amount of this sweet and healthy snack. As you may guess, Winnie and the Piglet asked to come at the Rabbit's place. Thus, there are n jars of honey lined up in front of Winnie-the-Pooh, jar number i contains ai kilos of honey. Winnie-the-Pooh eats the honey like that: each time he chooses a jar containing most honey. If the jar has less that k kilos of honey or if Winnie-the-Pooh has already eaten from it three times, he gives the jar to Piglet. Otherwise he eats exactly k kilos of honey from the jar and puts it back. Winnie does so until he gives all jars to the Piglet. Count how much honey Piglet will overall get after Winnie satisfies his hunger.
Input
The first line contains two integers n and k (1 ≤ n ≤ 100, 1 ≤ k ≤ 100). The second line contains n integers a1, a2, ..., an, separated by spaces (1 ≤ ai ≤ 100).
Output
Print a single number — how many kilos of honey gets Piglet.
Examples
Input
3 3
15 8 10
Output
9
Submitted Solution:
```
def foo(n, k, a):
counter = 0
result = 0
while (counter < 3):
for i in range(n):
if a[i] >= k:
a[i] -= k
counter += 1
for a_i in a:
result += a_i
return result
with open("input.txt","r") as file_in:
inlist = file_in.readlines()
file_out = open("output.txt","w+")
nk = inlist[0].strip("\n").split()
n = int(nk[0])
k = int(nk[1])
a = inlist[1].strip("\n").split()
for i in range(n):
a[i] = int(a[i])
ans = foo(n,k,a)
file_out.write(str(ans))
file_in.close()
file_out.close()
``` | instruction | 0 | 62,373 | 9 | 124,746 |
No | output | 1 | 62,373 | 9 | 124,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As we all know, Winnie-the-Pooh just adores honey. Ones he and the Piglet found out that the Rabbit has recently gotten hold of an impressive amount of this sweet and healthy snack. As you may guess, Winnie and the Piglet asked to come at the Rabbit's place. Thus, there are n jars of honey lined up in front of Winnie-the-Pooh, jar number i contains ai kilos of honey. Winnie-the-Pooh eats the honey like that: each time he chooses a jar containing most honey. If the jar has less that k kilos of honey or if Winnie-the-Pooh has already eaten from it three times, he gives the jar to Piglet. Otherwise he eats exactly k kilos of honey from the jar and puts it back. Winnie does so until he gives all jars to the Piglet. Count how much honey Piglet will overall get after Winnie satisfies his hunger.
Input
The first line contains two integers n and k (1 ≤ n ≤ 100, 1 ≤ k ≤ 100). The second line contains n integers a1, a2, ..., an, separated by spaces (1 ≤ ai ≤ 100).
Output
Print a single number — how many kilos of honey gets Piglet.
Examples
Input
3 3
15 8 10
Output
9
Submitted Solution:
```
def pooh(n,k,a): #int, int, list of int
counter = 0
retval = 0
while (counter < k):
for i in range(n):
if a[i] >= k:
a[i]-=k
counter += 1
print(a)
for j in a:
retval += j
return retval
with open("input.txt","r") as file_in:
inlist = file_in.readlines()
file_out = open("output.txt","w+")
nk = inlist[0].strip("\n").split()
n = int(nk[0])
k = int(nk[1])
a = inlist[1].strip("\n").split()
for i in range(n):
a[i] = int(a[i])
ans = pooh(n,k,a)
file_out.write(str(ans))
file_in.close()
file_out.close()
``` | instruction | 0 | 62,374 | 9 | 124,748 |
No | output | 1 | 62,374 | 9 | 124,749 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags. | instruction | 0 | 62,375 | 9 | 124,750 |
Tags: brute force, implementation
Correct Solution:
```
from itertools import combinations
l = [*map(int, input().split())]
print("Yes" if any(2 * sum(c) == sum(l) for x in [1, 2] for c in combinations(l, x)) else "No")
``` | output | 1 | 62,375 | 9 | 124,751 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags. | instruction | 0 | 62,376 | 9 | 124,752 |
Tags: brute force, implementation
Correct Solution:
```
a = list(map(int, input().split()))
a.sort()
if a[0] + a[3] == a[1] + a[2]:
print("YES")
else:
if a[3] == a[0] + a[1] + a[2]:
print("YES")
else:
print("NO")
``` | output | 1 | 62,376 | 9 | 124,753 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags. | instruction | 0 | 62,377 | 9 | 124,754 |
Tags: brute force, implementation
Correct Solution:
```
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
from math import *
l = I()
s = sum(l)
ans = 'NO'
l.sort()
if 2*l[-1] == s:
ans = 'YES'
for i in range(4):
for j in range(4):
if i == j: continue
if 2*(l[i] + l[j]) == s:
ans = 'YES'
print(ans)
``` | output | 1 | 62,377 | 9 | 124,755 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags. | instruction | 0 | 62,378 | 9 | 124,756 |
Tags: brute force, implementation
Correct Solution:
```
a = list(map(int, input().split()))
for i in range(2 ** 4):
s1 = 0
s2 = 0
for j in range(4):
if ((i >> j) & 1):
s1 += a[j]
else:
s2 += a[j]
if s1 == s2:
print("YES")
break
elif i == 2 ** 4 - 1:
print("NO")
``` | output | 1 | 62,378 | 9 | 124,757 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags. | instruction | 0 | 62,379 | 9 | 124,758 |
Tags: brute force, implementation
Correct Solution:
```
a,b,c,d = map(int,input().split())
if a+c == b+d:
print('YES')
elif a+d == b+c:
print('YES')
elif a+b == c+d:
print('YES')
elif a+b+c == d:
print('YES')
elif a+c+d == b:
print('YES')
elif b+c+d == a:
print('YES')
elif a+b+d == c:
print('YES')
else:
print('NO')
``` | output | 1 | 62,379 | 9 | 124,759 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags. | instruction | 0 | 62,380 | 9 | 124,760 |
Tags: brute force, implementation
Correct Solution:
```
a = list(map(int,input('').split(' ')))
t = sum(a)
b = ['0001','0010','0011','0100','0101','0110','0111']
res = False
for s in b:
su = 0
for i in range(4):
if(s[i] == '1'):
su = su+a[i]
if(su == t/2):
res = True
break
if(res):
print("YES")
else:
print("NO")
``` | output | 1 | 62,380 | 9 | 124,761 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags. | instruction | 0 | 62,381 | 9 | 124,762 |
Tags: brute force, implementation
Correct Solution:
```
a,b,c,d=map(int,input().split())
l=[a,b,c,d]
l.sort()
if(l[3]+l[0]==l[2]+l[1]):
print("YES")
elif(l[3]==l[0]+l[2]+l[1]):
print("YES")
else:
print("NO")
``` | output | 1 | 62,381 | 9 | 124,763 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags. | instruction | 0 | 62,382 | 9 | 124,764 |
Tags: brute force, implementation
Correct Solution:
```
array=list(map(int,input().split( )))
array.sort()
if array[-1]==sum(array[:3]) or array[0]+array[-1]==array[1]+array[2]:
print("YES")
else:
print("NO")
``` | output | 1 | 62,382 | 9 | 124,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags.
Submitted Solution:
```
a = sorted(map(int, input().split()))
s = sum(a)
if s % 2:
print('NO')
else:
if s // 2 in (a[0] + a[1], a[0] + a[2], a[0] + a[3], a[0] + a[1] + a[2]):
print('YES')
else:
print('NO')
``` | instruction | 0 | 62,383 | 9 | 124,766 |
Yes | output | 1 | 62,383 | 9 | 124,767 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags.
Submitted Solution:
```
def isSubsetSum (arr, n, sum):
if sum == 0:
return True
if n == 0 and sum != 0:
return False
if arr[n-1] > sum:
return isSubsetSum (arr, n-1, sum)
return isSubsetSum (arr, n-1, sum) or isSubsetSum (arr, n-1, sum-arr[n-1])
def findPartion (arr, n):
sum = 0
for i in range(0, n):
sum += arr[i]
if sum % 2 != 0:
return False
return isSubsetSum (arr, n, sum // 2)
l = [int(i) for i in input().split()]
n = len(l)
if findPartion(l, n) == True:
print ("YES")
else:
print ("NO")
``` | instruction | 0 | 62,384 | 9 | 124,768 |
Yes | output | 1 | 62,384 | 9 | 124,769 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags.
Submitted Solution:
```
from sys import stdin
def main():
input = lambda: stdin.readline()[:-1]
A = list(map(int, input().split()))
sum_ = sum(A)
for i in range(1, 4):
if (A[0] * 2 == sum_ or
A[i] * 2 == sum_ or
(A[0] + A[i]) * 2 == sum_):
print('YES')
return
print('NO')
main()
``` | instruction | 0 | 62,385 | 9 | 124,770 |
Yes | output | 1 | 62,385 | 9 | 124,771 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags.
Submitted Solution:
```
b=[int(b) for b in input().split()]
b.sort()
if b[3]==b[0]+b[1]+b[2]:
print("YES")
elif b[1]+b[2]==b[0]+b[3]:
print("YES")
else:
print("NO")
``` | instruction | 0 | 62,386 | 9 | 124,772 |
Yes | output | 1 | 62,386 | 9 | 124,773 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags.
Submitted Solution:
```
# bsdk idhar kya dekhne ko aaya hai, khud kr!!!
# from math import *
# from itertools import *
arr = list(map(int, input().split()))
if sum(arr) % 2 == 0:
print("YES")
else:
print("NO")
``` | instruction | 0 | 62,387 | 9 | 124,774 |
No | output | 1 | 62,387 | 9 | 124,775 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags.
Submitted Solution:
```
a, b, c, d = list(sorted(map(int, input().split())))
if a + d == b + c:
print('YES')
else:
print('NO')
``` | instruction | 0 | 62,388 | 9 | 124,776 |
No | output | 1 | 62,388 | 9 | 124,777 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags.
Submitted Solution:
```
a1,a2,a3,a4=map(int,input().split())
p=a1+a2+a3+a4
if(p%2==0):
print("YES")
else:
print("NO")
``` | instruction | 0 | 62,389 | 9 | 124,778 |
No | output | 1 | 62,389 | 9 | 124,779 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Dawid has four bags of candies. The i-th of them contains a_i candies. Also, Dawid has two friends. He wants to give each bag to one of his two friends. Is it possible to distribute the bags in such a way that each friend receives the same amount of candies in total?
Note, that you can't keep bags for yourself or throw them away, each bag should be given to one of the friends.
Input
The only line contains four integers a_1, a_2, a_3 and a_4 (1 ≤ a_i ≤ 100) — the numbers of candies in each bag.
Output
Output YES if it's possible to give the bags to Dawid's friends so that both friends receive the same amount of candies, or NO otherwise. Each character can be printed in any case (either uppercase or lowercase).
Examples
Input
1 7 11 5
Output
YES
Input
7 3 2 5
Output
NO
Note
In the first sample test, Dawid can give the first and the third bag to the first friend, and the second and the fourth bag to the second friend. This way, each friend will receive 12 candies.
In the second sample test, it's impossible to distribute the bags.
Submitted Solution:
```
a,b,c,d=map(int,input().split())
s=a+b+c+d
if s%2==0:
print("YES")
else:
print("NO")
``` | instruction | 0 | 62,390 | 9 | 124,780 |
No | output | 1 | 62,390 | 9 | 124,781 |
Provide tags and a correct Python 3 solution for this coding contest problem.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30 | instruction | 0 | 62,547 | 9 | 125,094 |
Tags: *special, implementation
Correct Solution:
```
a = list(map(int, input().split()))
cnt = 0
for i in range(len(a)):
cnt += i * a[i]
print(cnt)
``` | output | 1 | 62,547 | 9 | 125,095 |
Provide tags and a correct Python 3 solution for this coding contest problem.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30 | instruction | 0 | 62,548 | 9 | 125,096 |
Tags: *special, implementation
Correct Solution:
```
l1=list(map(int,input().split()))
s=0
for i in range(len(l1)):
s+=(l1[i]*i)
print(s)
``` | output | 1 | 62,548 | 9 | 125,097 |
Provide tags and a correct Python 3 solution for this coding contest problem.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30 | instruction | 0 | 62,549 | 9 | 125,098 |
Tags: *special, implementation
Correct Solution:
```
v, cnt = [int(i) for i in input().split()], 0
for i in range(1, len(v)):
cnt += i * v[i]
print(cnt)
``` | output | 1 | 62,549 | 9 | 125,099 |
Provide tags and a correct Python 3 solution for this coding contest problem.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30 | instruction | 0 | 62,550 | 9 | 125,100 |
Tags: *special, implementation
Correct Solution:
```
#!/usr/bin/env python
from __future__ import division, print_function
import math
import os
import sys
from fractions import *
from sys import *
from io import BytesIO, IOBase
from itertools import *
from collections import *
# sys.setrecursionlimit(10**5)
if sys.version_info[0] < 3:
from __builtin__ import xrange as range
from future_builtins import ascii, filter, hex, map, oct, zip
# sys.setrecursionlimit(10**6)
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
"""Prints the values to a stream, or to sys.stdout by default."""
sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
if sys.version_info[0] < 3:
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
def inp(): return sys.stdin.readline().rstrip("\r\n") # for fast input
def out(var): sys.stdout.write(str(var)) # for fast output, always take string
def lis(): return list(map(int, inp().split()))
def stringlis(): return list(map(str, inp().split()))
def sep(): return map(int, inp().split())
def strsep(): return map(str, inp().split())
def fsep(): return map(float, inp().split())
def inpu(): return int(inp())
# -----------------------------------------------------------------
def regularbracket(t):
p = 0
for i in t:
if i == "(":
p += 1
else:
p -= 1
if p < 0:
return False
else:
if p > 0:
return False
else:
return True
# -------------------------------------------------
def binarySearchCount(arr, n, key):
left = 0
right = n - 1
count = 0
while (left <= right):
mid = int((right + left) / 2)
# Check if middle element is
# less than or equal to key
if (arr[mid] <= key):
count = mid + 1
left = mid + 1
# If key is smaller, ignore right half
else:
right = mid - 1
return count
# ------------------------------reverse string(pallindrome)
def reverse1(string):
pp = ""
for i in string[::-1]:
pp += i
if pp == string:
return True
return False
# --------------------------------reverse list(paindrome)
def reverse2(list1):
l = []
for i in list1[::-1]:
l.append(i)
if l == list1:
return True
return False
def mex(list1):
# list1 = sorted(list1)
p = max(list1) + 1
for i in range(len(list1)):
if list1[i] != i:
p = i
break
return p
def sumofdigits(n):
n = str(n)
s1 = 0
for i in n:
s1 += int(i)
return s1
def perfect_square(n):
s = math.sqrt(n)
if s == int(s):
return True
return False
# -----------------------------roman
def roman_number(x):
if x > 15999:
return
value = [5000, 4000, 1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
symbol = ["F", "MF", "M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
roman = ""
i = 0
while x > 0:
div = x // value[i]
x = x % value[i]
while div:
roman += symbol[i]
div -= 1
i += 1
return roman
def soretd(s):
for i in range(1, len(s)):
if s[i - 1] > s[i]:
return False
return True
# print(soretd("1"))
# ---------------------------
def countRhombi(h, w):
ct = 0
for i in range(2, h + 1, 2):
for j in range(2, w + 1, 2):
ct += (h - i + 1) * (w - j + 1)
return ct
def countrhombi2(h, w):
return ((h * h) // 4) * ((w * w) // 4)
# ---------------------------------
def binpow(a, b):
if b == 0:
return 1
else:
res = binpow(a, b // 2)
if b % 2 != 0:
return res * res * a
else:
return res * res
# -------------------------------------------------------
def binpowmodulus(a, b, m):
a %= m
res = 1
while (b > 0):
if (b & 1):
res = res * a % m
a = a * a % m
b >>= 1
return res
# -------------------------------------------------------------
def coprime_to_n(n):
result = n
i = 2
while (i * i <= n):
if (n % i == 0):
while (n % i == 0):
n //= i
result -= result // i
i += 1
if (n > 1):
result -= result // n
return result
# -------------------prime
def prime(x):
if x == 1:
return False
else:
for i in range(2, int(math.sqrt(x)) + 1):
if (x % i == 0):
return False
else:
return True
def luckynumwithequalnumberoffourandseven(x, n, a):
if x >= n and str(x).count("4") == str(x).count("7"):
a.append(x)
else:
if x < 1e12:
luckynumwithequalnumberoffourandseven(x * 10 + 4, n, a)
luckynumwithequalnumberoffourandseven(x * 10 + 7, n, a)
return a
def luckynuber(x, n, a):
p = set(str(x))
if len(p) <= 2:
a.append(x)
if x < n:
luckynuber(x + 1, n, a)
return a
#------------------------------------------------------interactive problems
def interact(type, x):
if type == "r":
inp = input()
return inp.strip()
else:
print(x, flush=True)
#------------------------------------------------------------------zero at end of factorial of a number
def findTrailingZeros(n):
# Initialize result
count = 0
# Keep dividing n by
# 5 & update Count
while (n >= 5):
n //= 5
count += n
return count
#-----------------------------------------------merge sort
# Python program for implementation of MergeSort
def mergeSort(arr):
if len(arr) > 1:
# Finding the mid of the array
mid = len(arr) // 2
# Dividing the array elements
L = arr[:mid]
# into 2 halves
R = arr[mid:]
# Sorting the first half
mergeSort(L)
# Sorting the second half
mergeSort(R)
i = j = k = 0
# Copy data to temp arrays L[] and R[]
while i < len(L) and j < len(R):
if L[i] < R[j]:
arr[k] = L[i]
i += 1
else:
arr[k] = R[j]
j += 1
k += 1
# Checking if any element was left
while i < len(L):
arr[k] = L[i]
i += 1
k += 1
while j < len(R):
arr[k] = R[j]
j += 1
k += 1
#-----------------------------------------------lucky number with two lucky any digits
res = set()
def solve(p, l, a, b,n):#given number
if p > n or l > 10:
return
if p > 0:
res.add(p)
solve(p * 10 + a, l + 1, a, b,n)
solve(p * 10 + b, l + 1, a, b,n)
# problem
"""
n = int(input())
for a in range(0, 10):
for b in range(0, a):
solve(0, 0)
print(len(res))
"""
#-----------------------------------------------
# endregion------------------------------
"""
def main():
n = inpu()
cnt=0
c = n
if n % 7 == 0:
print("7" * (n // 7))
else:
while(c>0):
c-=4
cnt+=1
if c%7==0 and c>=0:
#print(n,n%4)
print("4"*(cnt)+"7"*(c//7))
break
else:
if n % 4 == 0:
print("4" * (n // 4))
else:
print(-1)
if __name__ == '__main__':
main()
"""
"""
def main():
n,t = sep()
arr = lis()
i=0
cnt=0
min1 = min(arr)
while(True):
if t>=arr[i]:
cnt+=1
t-=arr[i]
i+=1
else:
i+=1
if i==n:
i=0
if t<min1:
break
print(cnt)
if __name__ == '__main__':
main()
"""
# Python3 program to find all subsets
# by backtracking.
# In the array A at every step we have two
# choices for each element either we can
# ignore the element or we can include the
# element in our subset
def subsetsUtil(A, subset, index,d):
print(*subset)
s = sum(subset)
d.append(s)
for i in range(index, len(A)):
# include the A[i] in subset.
subset.append(A[i])
# move onto the next element.
subsetsUtil(A, subset, i + 1,d)
# exclude the A[i] from subset and
# triggers backtracking.
subset.pop(-1)
return d
def subsetSums(arr, l, r,d, sum=0):
if l > r:
d.append(sum)
return
subsetSums(arr, l + 1, r,d, sum + arr[l])
# Subset excluding arr[l]
subsetSums(arr, l + 1, r,d, sum)
return d
"""
def main():
t = inpu()
for _ in range(t):
n = inpu()
arr=[]
subset=[]
i=0
l=[]
for j in range(26):
arr.append(3**j)
if __name__ == '__main__':
main()
"""
"""
def main():
n = int(input())
cnt=1
if n==1:
print(1)
else:
for i in range(1,n):
cnt+=i*12
print(cnt)
if __name__ == '__main__':
main()
"""
def main():
a = lis()
s = 0
for i in range(len(a)):
s += a[i] * i
print(s)
if __name__ == '__main__':
main()
``` | output | 1 | 62,550 | 9 | 125,101 |
Provide tags and a correct Python 3 solution for this coding contest problem.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30 | instruction | 0 | 62,551 | 9 | 125,102 |
Tags: *special, implementation
Correct Solution:
```
# PRE-PROGRAM
inp = []
def read():
global inp
if not inp:
inp = list(map(int, input().split()))[::-1]
return inp.pop()
# INGREDIENTS
carrots = 2
calories = 0
chocolate_spread = 100 #g
pack_of_flour = 1
egg = 1
mixing_bowl = []
baking_dish = []
# METHOD
mixing_bowl.append(calories) # 1
carrots = read() # 2
for i in range(carrots, 0, -1): # 3
chocolate_spread = read() # 4
mixing_bowl.append(chocolate_spread) # 5
mixing_bowl[-1] *= pack_of_flour # 6
chocolate_spread = mixing_bowl.pop() # 7
mixing_bowl[-1] += chocolate_spread # 8
mixing_bowl.append(pack_of_flour) # 9
mixing_bowl[-1] += egg # 10
pack_of_flour = mixing_bowl.pop() # 11
# 12
baking_dish.extend(mixing_bowl) # 13
print('\n'.join(map(str, baking_dish))) # Serves 1
``` | output | 1 | 62,551 | 9 | 125,103 |
Provide tags and a correct Python 3 solution for this coding contest problem.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30 | instruction | 0 | 62,552 | 9 | 125,104 |
Tags: *special, implementation
Correct Solution:
```
inp = []
inp = input().split()
inp = [int(i) for i in inp]
carrots = 2
calories = 0
choco = 100
flour = 1
egg = 1
bowl = []
dish = []
bowl.append(calories) # 1
carrots = inp[0] # 2
for i in range(1, carrots + 1): # 3
choco = inp[i] # 4
bowl.append(choco) # 5
bowl[-1] *= flour # 6
choco = bowl.pop() # 7
bowl[-1] += choco # 8
bowl.append(flour) # 9
bowl[-1] += egg # 10
flour = bowl.pop() # 11
# 12
dish.extend(bowl) # 13
print(dish[0]) # Serves 1
``` | output | 1 | 62,552 | 9 | 125,105 |
Provide tags and a correct Python 3 solution for this coding contest problem.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30 | instruction | 0 | 62,553 | 9 | 125,106 |
Tags: *special, implementation
Correct Solution:
```
a = map(int, input().split())
j = 0
sum = 0
for i in a:
sum += i * j
j += 1
print(sum)
``` | output | 1 | 62,553 | 9 | 125,107 |
Provide tags and a correct Python 3 solution for this coding contest problem.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30 | instruction | 0 | 62,554 | 9 | 125,108 |
Tags: *special, implementation
Correct Solution:
```
cases=list(map(int,input().split()))
cnt=0
for i in range(1,len(cases)):
cnt+=i*cases[i]
print(cnt)
``` | output | 1 | 62,554 | 9 | 125,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30
Submitted Solution:
```
a, ans = list(map(int, input().split())), 0
for i in range(1, len(a)):
ans += i * a[i]
print(ans)
``` | instruction | 0 | 62,555 | 9 | 125,110 |
Yes | output | 1 | 62,555 | 9 | 125,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30
Submitted Solution:
```
a = input().split()
s = 0
for i in range(int(a[0])):
s += (i + 1) * int(a[i + 1])
print(s)
``` | instruction | 0 | 62,556 | 9 | 125,112 |
Yes | output | 1 | 62,556 | 9 | 125,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30
Submitted Solution:
```
a=list(map(int,input().split()))
print(sum([a[i]*i for i in range(len(a))]))
``` | instruction | 0 | 62,557 | 9 | 125,114 |
Yes | output | 1 | 62,557 | 9 | 125,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30
Submitted Solution:
```
s = input().split()
ans = 0
pos = 0
for i in s:
ans += int(i) * pos
pos += 1;
print(ans)
``` | instruction | 0 | 62,558 | 9 | 125,116 |
Yes | output | 1 | 62,558 | 9 | 125,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30
Submitted Solution:
```
a = list(map(int,input().split()))
print(2*(sum(a)+1))
``` | instruction | 0 | 62,559 | 9 | 125,118 |
No | output | 1 | 62,559 | 9 | 125,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30
Submitted Solution:
```
a, b, *r, c = input().split()
print((int(b) + int (c)) * eval('*'.join(r)))
``` | instruction | 0 | 62,560 | 9 | 125,120 |
No | output | 1 | 62,560 | 9 | 125,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
How to make a cake you'll never eat.
Ingredients.
* 2 carrots
* 0 calories
* 100 g chocolate spread
* 1 pack of flour
* 1 egg
Method.
1. Put calories into the mixing bowl.
2. Take carrots from refrigerator.
3. Chop carrots.
4. Take chocolate spread from refrigerator.
5. Put chocolate spread into the mixing bowl.
6. Combine pack of flour into the mixing bowl.
7. Fold chocolate spread into the mixing bowl.
8. Add chocolate spread into the mixing bowl.
9. Put pack of flour into the mixing bowl.
10. Add egg into the mixing bowl.
11. Fold pack of flour into the mixing bowl.
12. Chop carrots until choped.
13. Pour contents of the mixing bowl into the baking dish.
Serves 1.
Input
The only line of input contains a sequence of integers a0, a1, ... (1 ≤ a0 ≤ 100, 0 ≤ ai ≤ 1000 for i ≥ 1).
Output
Output a single integer.
Examples
Input
4 1 2 3 4
Output
30
Submitted Solution:
```
cases=list(map(int,input().split()))
cnt=0
for i in cases[1:]:
cnt+=i*i
print(cnt)
``` | instruction | 0 | 62,561 | 9 | 125,122 |
No | output | 1 | 62,561 | 9 | 125,123 |
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