message stringlengths 2 22.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 145 109k | cluster float64 9 9 | __index_level_0__ int64 290 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643 | instruction | 0 | 99,314 | 9 | 198,628 |
"Correct Solution:
```
Time = [int(input()) for X in range(0,5)]
Loss = [(10-X%10)%10 for X in Time]
print(sum(Time)+sum(sorted(Loss)[:4]))
``` | output | 1 | 99,314 | 9 | 198,629 |
Provide a correct Python 3 solution for this coding contest problem.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643 | instruction | 0 | 99,315 | 9 | 198,630 |
"Correct Solution:
```
lis = [int(input()) for _ in range(5)]
times = [(l + 9) // 10 * 10 for l in lis]
loss = [(10 - l % 10) % 10 for l in lis]
print(sum(times) - max(loss))
``` | output | 1 | 99,315 | 9 | 198,631 |
Provide a correct Python 3 solution for this coding contest problem.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643 | instruction | 0 | 99,316 | 9 | 198,632 |
"Correct Solution:
```
a=[int(input()) for _ in range(5)]
import math
b=[math.ceil(i/10)*10-i for i in a]
print(sum(a)+sum(b)-max(b))
``` | output | 1 | 99,316 | 9 | 198,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643
Submitted Solution:
```
x = [int(input()) for i in range(5)]
ans = 0
gap = []
for i in x:
y = -i//10 * -10
ans += y
gap.append(y-i)
ans = ans - max(gap)
print(ans)
``` | instruction | 0 | 99,317 | 9 | 198,634 |
Yes | output | 1 | 99,317 | 9 | 198,635 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643
Submitted Solution:
```
e,*a=sorted(eval('int(input()),'*5),key=lambda x:~-x%10);print(e-sum(-i//10*10for i in a))
``` | instruction | 0 | 99,318 | 9 | 198,636 |
Yes | output | 1 | 99,318 | 9 | 198,637 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643
Submitted Solution:
```
time=[]
ans=0
for i in range(5):
A=int(input())
a=10-A%10
ans+=A+a%10
time.append(a%10)
time.sort()
ans-=time[-1]
print(ans)
``` | instruction | 0 | 99,319 | 9 | 198,638 |
Yes | output | 1 | 99,319 | 9 | 198,639 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643
Submitted Solution:
```
time = list(int(input()) for i in range(5))
def f(x):
return (10-x%10)%10
b = list(map(f, time))
ans = sum(time) + sum(b) - max(b)
print(ans)
``` | instruction | 0 | 99,320 | 9 | 198,640 |
Yes | output | 1 | 99,320 | 9 | 198,641 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643
Submitted Solution:
```
import numpy as np
A = int(input())
B = int(input())
C = int(input())
D = int(input())
E = int(input())
a = A % 10
b = B % 10
c = C % 10
d = D % 10
e = E % 10
aa = A // 10
bb = B // 10
cc = C // 10
dd = D // 10
ee = E // 10
r = np.array([a, b, c, d, e])
k = (r > 0).sum()
l = r[r != 0].min()
print((aa + bb + cc + dd + ee) * 10 + 10*(k-1) + l)
``` | instruction | 0 | 99,321 | 9 | 198,642 |
No | output | 1 | 99,321 | 9 | 198,643 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643
Submitted Solution:
```
d=[int(input()) for i in range(5)]
d2=[j+(10-j%10) for j in d]
d_mod=[10-k%10 for k in d]
ans=sum(d2)-max(d_mod)
print(ans)
``` | instruction | 0 | 99,322 | 9 | 198,644 |
No | output | 1 | 99,322 | 9 | 198,645 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643
Submitted Solution:
```
order_time = [0, 0, 0, 0, 0]
order = len(order_time)
time = 0
last_order = 9
count_change = 0
for i in range(0, order):
order_time[i] = int(input())
if (order_time[i] % 10 != 0) and (order_time[i] % 10 <= last_order % 10):
last_order = order_time[i]
count_change += 1
if count_change == 0:
last_order = order_time[i]
for i in range(0, order):
if order_time[i] % 10 != 0:
time += order_time[i] // 10 * 10 + 10
else:
time += order_time[i]
time -= last_order // 10 * 10 + 10
time += last_order
print(time)
order_time = [0, 0, 0, 0, 0]
order = len(order_time)
time = 0
last_order = 9
count_change = 0
for i in range(0, order):
order_time[i] = int(input())
if (order_time[i] % 10 != 0) and (order_time[i] % 10 <= last_order % 10):
last_order = order_time[i]
count_change += 1
for i in range(0, order):
if order_time[i] % 10 != 0:
time += order_time[i] // 10 * 10 + 10
else:
time += order_time[i]
if count_change == 0:
last_order = order_time[i]
else:
time -= last_order // 10 * 10 + 10
time += last_order
print(time)
``` | instruction | 0 | 99,323 | 9 | 198,646 |
No | output | 1 | 99,323 | 9 | 198,647 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The restaurant AtCoder serves the following five dishes:
* ABC Don (rice bowl): takes A minutes to serve.
* ARC Curry: takes B minutes to serve.
* AGC Pasta: takes C minutes to serve.
* APC Ramen: takes D minutes to serve.
* ATC Hanbagu (hamburger patty): takes E minutes to serve.
Here, the time to serve a dish is the time between when an order is placed and when the dish is delivered.
This restaurant has the following rules on orders:
* An order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).
* Only one dish can be ordered at a time.
* No new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.
E869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.
Here, he can order the dishes in any order he likes, and he can place an order already at time 0.
Constraints
* A, B, C, D and E are integers between 1 and 123 (inclusive).
Input
Input is given from Standard Input in the following format:
A
B
C
D
E
Output
Print the earliest possible time for the last dish to be delivered, as an integer.
Examples
Input
29
20
7
35
120
Output
215
Input
101
86
119
108
57
Output
481
Input
123
123
123
123
123
Output
643
Submitted Solution:
```
# ABC123
# Five Dishes
#B=A R=B G=C P=D T=E
Ryori = [input() for _ in range(5)]
O = []
t = 0
for i in Ryori:
print(i)
if int(i[-1]) == 0:
x = Ryori.pop(Ryori.index(i))
O.append(x)
Ryori = sorted(Ryori,key=lambda x: x[-1], reverse=True)
for i in range(len(Ryori)-1):
for j in range(10):
if (int(Ryori[i]) + j) % 10 == 0:
t += int(Ryori[i]) + j
t += int(Ryori[-1])
for i in O:
t += int(i)
print(t)
``` | instruction | 0 | 99,324 | 9 | 198,648 |
No | output | 1 | 99,324 | 9 | 198,649 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image> | instruction | 0 | 100,477 | 9 | 200,954 |
Tags: constructive algorithms, math
Correct Solution:
```
import sys
input = sys.stdin.readline
x = int(input())
for _ in range(x):
a, b, c, d = map(int, input().split())
print(b, c, c)
``` | output | 1 | 100,477 | 9 | 200,955 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image> | instruction | 0 | 100,478 | 9 | 200,956 |
Tags: constructive algorithms, math
Correct Solution:
```
for i in range(int(input())):
a,b,c,d = map(int,input().split()) #100 3 4
print(b,c,c)
``` | output | 1 | 100,478 | 9 | 200,957 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image> | instruction | 0 | 100,479 | 9 | 200,958 |
Tags: constructive algorithms, math
Correct Solution:
```
z=input
mod = 10**9 + 7
from collections import *
from queue import *
from sys import *
from collections import *
from math import *
from heapq import *
from itertools import *
from bisect import *
from collections import Counter as cc
from math import factorial as f
def lcd(xnum1,xnum2):
return (xnum1*xnum2//gcd(xnum1,xnum2))
################################################################################
"""
n=int(z())
for _ in range(int(z())):
x=int(z())
l=list(map(int,z().split()))
n=int(z())
l=sorted(list(map(int,z().split())))[::-1]
a,b=map(int,z().split())
l=set(map(int,z().split()))
led=(6,2,5,5,4,5,6,3,7,6)
vowel={'a':0,'e':0,'i':0,'o':0,'u':0}
color-4=["G", "GB", "YGB", "YGBI", "OYGBI" ,"OYGBIV",'ROYGBIV' ]
"""
###########################---START-CODING---###############################################
for _ in range(int(z())):
a,b,c,d=map(int,input().split())
print(b,c,c)
``` | output | 1 | 100,479 | 9 | 200,959 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image> | instruction | 0 | 100,480 | 9 | 200,960 |
Tags: constructive algorithms, math
Correct Solution:
```
# https://codeforces.com/problemset/problem/1337/A
tests = int(input())
while tests > 0:
a, b, c, d = [int(i) for i in input().split(" ")]
print(f'{b} {c} {c}')
tests = tests - 1
``` | output | 1 | 100,480 | 9 | 200,961 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image> | instruction | 0 | 100,481 | 9 | 200,962 |
Tags: constructive algorithms, math
Correct Solution:
```
def solve():
s = input().split()
for i in range(len(s)):
s[i] = int(s[i])
print (s[1], s[2], s[2])
t = int(input())
for i in range(t):
solve()
``` | output | 1 | 100,481 | 9 | 200,963 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image> | instruction | 0 | 100,482 | 9 | 200,964 |
Tags: constructive algorithms, math
Correct Solution:
```
from sys import stdin,stdout
from collections import defaultdict as df
t=int(input())
for i in range(t):
a,b,c,d=list(map(int,input().split()))
ans=[]
ans.append(b)
if c>b:
ans.append(c)
else:
ans.append(b)
ans.append(c)
print(*ans)
``` | output | 1 | 100,482 | 9 | 200,965 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image> | instruction | 0 | 100,483 | 9 | 200,966 |
Tags: constructive algorithms, math
Correct Solution:
```
for ii in range(int(input())):
n = [int(i) for i in input().split()]
a = n[0]
b = n[1]
c= n[2]
d = n[3]
x= b
y = c
if b+c <= d :
z = b+c-1
else :
z = d
print(x,y,z)
``` | output | 1 | 100,483 | 9 | 200,967 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image> | instruction | 0 | 100,484 | 9 | 200,968 |
Tags: constructive algorithms, math
Correct Solution:
```
t = int(input())
def fn(a,b,c,d):
for x in [a,b]:
for y in [b,c]:
for z in [c,d]:
if x + y > z and y + z > x and x + z > y:
print(x,y,z)
return
for _ in range(t):
a,b,c,d = map(int, input().split())
fn(a,b,c,d)
``` | output | 1 | 100,484 | 9 | 200,969 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image>
Submitted Solution:
```
t = int(input())
for tt in range(0,t):
a,b,c,d = map(int,input().split())
print(b,c,c)
``` | instruction | 0 | 100,485 | 9 | 200,970 |
Yes | output | 1 | 100,485 | 9 | 200,971 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image>
Submitted Solution:
```
t = int(input())
for q in range(t):
a, b, c, d = map(int, input().split())
x = a
y = b
z = c
if c == max(a, b, c):
h = c - a - b + 1
if h > 0:
i = min(h, b - a)
h -= i
x += i
if h > 0:
y += h
elif b == max(a, b, c):
h = b - a - c + 1
if h > 0:
i = min(h, b - a)
h -= i
x += i
if h > 0:
z += h
else:
h = a - b - c + 1
if h > 0:
i = min(h, c - b)
h -= i
y += i
if h > 0:
z += h
print(x, y, z)
``` | instruction | 0 | 100,486 | 9 | 200,972 |
Yes | output | 1 | 100,486 | 9 | 200,973 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image>
Submitted Solution:
```
tc = int(input())
cases = []
for _ in range(tc):
cases.append(list(map(int, input().split())))
for case in cases:
print(case[1], case[2], case[2])
``` | instruction | 0 | 100,487 | 9 | 200,974 |
Yes | output | 1 | 100,487 | 9 | 200,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image>
Submitted Solution:
```
def solve(a,b,c,d):
x = a
y = c
min_z = max(c-a+1, c)
max_z = min(d, c+a-1)
z = max(min_z, max_z)
print("{} {} {}".format(x, y, z))
def main():
t = int(input())
for _ in range(t):
a,b,c,d = [int(x) for x in input().split()]
solve(a,b,c,d)
main()
``` | instruction | 0 | 100,488 | 9 | 200,976 |
Yes | output | 1 | 100,488 | 9 | 200,977 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image>
Submitted Solution:
```
for _ in range(int(input())):
a, b, c, d = map(int, input().split(" "))
print(a, b, c)
``` | instruction | 0 | 100,489 | 9 | 200,978 |
No | output | 1 | 100,489 | 9 | 200,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image>
Submitted Solution:
```
def myfun(a,b,c,d):
if (a+b>=c) and (b+c>=a) and (c+a>=b):
print(a,b,c)
return
if (b+c>=d) and (c+d>=b) and(d+b>=c):
print(b,c,d)
return
for i in range(a,b+1):
for j in range(b,c+1):
for k in range(c,d+1):
if (i + j <= k) or (i + k <= j) or (j + k <= i):
pass
else:
print(i ,j ,k)
return
for n in range(int(input())):
a,b,c,d = list(map(int , input().split()))
myfun(a,b,c,d)
``` | instruction | 0 | 100,490 | 9 | 200,980 |
No | output | 1 | 100,490 | 9 | 200,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image>
Submitted Solution:
```
test = int(input())
def solve():
arr = list(map(int, input().split()))
print(*arr[1:])
for x in range(test):
solve()
``` | instruction | 0 | 100,491 | 9 | 200,982 |
No | output | 1 | 100,491 | 9 | 200,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ichihime is the current priestess of the Mahjong Soul Temple. She claims to be human, despite her cat ears.
These days the temple is holding a math contest. Usually, Ichihime lacks interest in these things, but this time the prize for the winner is her favorite β cookies. Ichihime decides to attend the contest. Now she is solving the following problem.
<image>
You are given four positive integers a, b, c, d, such that a β€ b β€ c β€ d.
Your task is to find three integers x, y, z, satisfying the following conditions:
* a β€ x β€ b.
* b β€ y β€ c.
* c β€ z β€ d.
* There exists a triangle with a positive non-zero area and the lengths of its three sides are x, y, and z.
Ichihime desires to get the cookie, but the problem seems too hard for her. Can you help her?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The next t lines describe test cases. Each test case is given as four space-separated integers a, b, c, d (1 β€ a β€ b β€ c β€ d β€ 10^9).
Output
For each test case, print three integers x, y, z β the integers you found satisfying the conditions given in the statement.
It is guaranteed that the answer always exists. If there are multiple answers, print any.
Example
Input
4
1 3 5 7
1 5 5 7
100000 200000 300000 400000
1 1 977539810 977539810
Output
3 4 5
5 5 5
182690 214748 300999
1 977539810 977539810
Note
One of the possible solutions to the first test case:
<image>
One of the possible solutions to the second test case:
<image>
Submitted Solution:
```
t = int(input())
while (t):
line = input().split()
a,b,c,d = int(line[0]),int(line[1]),int(line[2]),int(line[3])
print(b,c,c+1)
t -= 1
``` | instruction | 0 | 100,492 | 9 | 200,984 |
No | output | 1 | 100,492 | 9 | 200,985 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a nuts and lots of boxes. The boxes have a wonderful feature: if you put x (x β₯ 0) divisors (the spacial bars that can divide a box) to it, you get a box, divided into x + 1 sections.
You are minimalist. Therefore, on the one hand, you are against dividing some box into more than k sections. On the other hand, you are against putting more than v nuts into some section of the box. What is the minimum number of boxes you have to use if you want to put all the nuts in boxes, and you have b divisors?
Please note that you need to minimize the number of used boxes, not sections. You do not have to minimize the number of used divisors.
Input
The first line contains four space-separated integers k, a, b, v (2 β€ k β€ 1000; 1 β€ a, b, v β€ 1000) β the maximum number of sections in the box, the number of nuts, the number of divisors and the capacity of each section of the box.
Output
Print a single integer β the answer to the problem.
Examples
Input
3 10 3 3
Output
2
Input
3 10 1 3
Output
3
Input
100 100 1 1000
Output
1
Note
In the first sample you can act like this:
* Put two divisors to the first box. Now the first box has three sections and we can put three nuts into each section. Overall, the first box will have nine nuts.
* Do not put any divisors into the second box. Thus, the second box has one section for the last nut.
In the end we've put all the ten nuts into boxes.
The second sample is different as we have exactly one divisor and we put it to the first box. The next two boxes will have one section each. | instruction | 0 | 100,668 | 9 | 201,336 |
Tags: greedy, math
Correct Solution:
```
k,a,b,v=map(int,input().split())
for i in range(1,2000):
t=min(k,b+1)
a-=t*v
b-=t-1
if a<=0:
print(i)
break
``` | output | 1 | 100,668 | 9 | 201,337 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a nuts and lots of boxes. The boxes have a wonderful feature: if you put x (x β₯ 0) divisors (the spacial bars that can divide a box) to it, you get a box, divided into x + 1 sections.
You are minimalist. Therefore, on the one hand, you are against dividing some box into more than k sections. On the other hand, you are against putting more than v nuts into some section of the box. What is the minimum number of boxes you have to use if you want to put all the nuts in boxes, and you have b divisors?
Please note that you need to minimize the number of used boxes, not sections. You do not have to minimize the number of used divisors.
Input
The first line contains four space-separated integers k, a, b, v (2 β€ k β€ 1000; 1 β€ a, b, v β€ 1000) β the maximum number of sections in the box, the number of nuts, the number of divisors and the capacity of each section of the box.
Output
Print a single integer β the answer to the problem.
Examples
Input
3 10 3 3
Output
2
Input
3 10 1 3
Output
3
Input
100 100 1 1000
Output
1
Note
In the first sample you can act like this:
* Put two divisors to the first box. Now the first box has three sections and we can put three nuts into each section. Overall, the first box will have nine nuts.
* Do not put any divisors into the second box. Thus, the second box has one section for the last nut.
In the end we've put all the ten nuts into boxes.
The second sample is different as we have exactly one divisor and we put it to the first box. The next two boxes will have one section each. | instruction | 0 | 100,669 | 9 | 201,338 |
Tags: greedy, math
Correct Solution:
```
k, a, b, v = map(int, input().split(' '))
c, i = 1, 1
while a - v > 0:
a -= v
if i < k and b > 0:
i += 1
b -= 1
else:
i = 1
c += 1
print(c)
``` | output | 1 | 100,669 | 9 | 201,339 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a nuts and lots of boxes. The boxes have a wonderful feature: if you put x (x β₯ 0) divisors (the spacial bars that can divide a box) to it, you get a box, divided into x + 1 sections.
You are minimalist. Therefore, on the one hand, you are against dividing some box into more than k sections. On the other hand, you are against putting more than v nuts into some section of the box. What is the minimum number of boxes you have to use if you want to put all the nuts in boxes, and you have b divisors?
Please note that you need to minimize the number of used boxes, not sections. You do not have to minimize the number of used divisors.
Input
The first line contains four space-separated integers k, a, b, v (2 β€ k β€ 1000; 1 β€ a, b, v β€ 1000) β the maximum number of sections in the box, the number of nuts, the number of divisors and the capacity of each section of the box.
Output
Print a single integer β the answer to the problem.
Examples
Input
3 10 3 3
Output
2
Input
3 10 1 3
Output
3
Input
100 100 1 1000
Output
1
Note
In the first sample you can act like this:
* Put two divisors to the first box. Now the first box has three sections and we can put three nuts into each section. Overall, the first box will have nine nuts.
* Do not put any divisors into the second box. Thus, the second box has one section for the last nut.
In the end we've put all the ten nuts into boxes.
The second sample is different as we have exactly one divisor and we put it to the first box. The next two boxes will have one section each. | instruction | 0 | 100,671 | 9 | 201,342 |
Tags: greedy, math
Correct Solution:
```
def f(l):
k,a,b,v = l
ns = (a+v-1)//v
return max(ns-b,(ns+k-1)//k)
l = list(map(int,input().split()))
print(f(l))
``` | output | 1 | 100,671 | 9 | 201,343 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have a nuts and lots of boxes. The boxes have a wonderful feature: if you put x (x β₯ 0) divisors (the spacial bars that can divide a box) to it, you get a box, divided into x + 1 sections.
You are minimalist. Therefore, on the one hand, you are against dividing some box into more than k sections. On the other hand, you are against putting more than v nuts into some section of the box. What is the minimum number of boxes you have to use if you want to put all the nuts in boxes, and you have b divisors?
Please note that you need to minimize the number of used boxes, not sections. You do not have to minimize the number of used divisors.
Input
The first line contains four space-separated integers k, a, b, v (2 β€ k β€ 1000; 1 β€ a, b, v β€ 1000) β the maximum number of sections in the box, the number of nuts, the number of divisors and the capacity of each section of the box.
Output
Print a single integer β the answer to the problem.
Examples
Input
3 10 3 3
Output
2
Input
3 10 1 3
Output
3
Input
100 100 1 1000
Output
1
Note
In the first sample you can act like this:
* Put two divisors to the first box. Now the first box has three sections and we can put three nuts into each section. Overall, the first box will have nine nuts.
* Do not put any divisors into the second box. Thus, the second box has one section for the last nut.
In the end we've put all the ten nuts into boxes.
The second sample is different as we have exactly one divisor and we put it to the first box. The next two boxes will have one section each. | instruction | 0 | 100,675 | 9 | 201,350 |
Tags: greedy, math
Correct Solution:
```
def main():
k, a, b, v = map(int, input().split())
res = (b + k - 2) // (k - 1)
o = b + res
if o * v < a:
res += (a + v - 1) // v - o
else:
res = (a + k * v - 1) // (k * v)
print(res)
if __name__ == '__main__':
main()
``` | output | 1 | 100,675 | 9 | 201,351 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR). | instruction | 0 | 100,697 | 9 | 201,394 |
Tags: dp
Correct Solution:
```
import math,sys,bisect,heapq
from collections import defaultdict,Counter,deque
from itertools import groupby,accumulate
#sys.setrecursionlimit(200000000)
int1 = lambda x: int(x) - 1
input = iter(sys.stdin.buffer.read().decode().splitlines()).__next__
ilele = lambda: map(int,input().split())
alele = lambda: list(map(int, input().split()))
ilelec = lambda: map(int1,input().split())
alelec = lambda: list(map(int1, input().split()))
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
MOD = 1000000000 + 7
def Y(c): print(["NO","YES"][c])
def y(c): print(["no","yes"][c])
def Yy(c): print(["No","Yes"][c])
t,k = ilele()
dp = [0]*100001
for i in range(1,100001):
dp[i] += dp[i-1] + 1
if i-k>=0: dp[i] += dp[i-k] + 1
dp[i] %= MOD
for i in range(t):
a,b = ilele()
print((dp[b] - dp[a-1])%MOD)
``` | output | 1 | 100,697 | 9 | 201,395 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR). | instruction | 0 | 100,698 | 9 | 201,396 |
Tags: dp
Correct Solution:
```
import sys
import array
def solve():
MOD = 1000000007
size = 100003
t, groupsize = read()
mem = array.array('i',(0 for i in range(0,size)))
summ = array.array('i',(0 for i in range(0,size)))
mem[0] = 1
for i in range(1, groupsize):
mem[i] = (mem[i-1]) % MOD
for i in range(groupsize, len(mem)):
mem[i] = (mem[i - 1] + mem[i - groupsize]) % MOD
summ[0] = mem[0]
for i in range(1, len(summ)):
summ[i] = (mem[i] + summ[i - 1]) % MOD
res = list()
for i in range(t):
a, b = read()
res.append((summ[b]-summ[a-1]+MOD)%MOD)
return res
def read(mode=2):
inputs = input().strip()
if mode == 0: return inputs # String
if mode == 1: return inputs.split() # List of strings
if mode == 2: return list(map(int, inputs.split())) # List of integers
def write(s="\n"):
if s is None: s = ""
if isinstance(s, list): s = "\n".join(map(str, s))
if isinstance(s, tuple): s = " ".join(map(str, s))
s = str(s)
print(s, end="")
def run():
#if sys.hexversion == 50594544 : sys.stdin = open("test.txt")
res = solve()
write(res)
run()
``` | output | 1 | 100,698 | 9 | 201,397 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR). | instruction | 0 | 100,699 | 9 | 201,398 |
Tags: dp
Correct Solution:
```
import sys
input=sys.stdin.readline
t,k=map(int,input().split())
nmax=int(1e5+1)
mod=int(1e9+7)
dp=[0 for i in range(nmax)]
dp[0]=1
for i in range(1,nmax):
if i>=k:
dp[i]=(dp[i-1]+dp[i-k])%mod
else :
dp[i]=1
for i in range(1,nmax):
dp[i]+=dp[i-1]
dp[i]%=mod
for _ in range(t):
a,b=map(int,input().split())
print((dp[b]-dp[a-1]+mod)%mod)
``` | output | 1 | 100,699 | 9 | 201,399 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR). | instruction | 0 | 100,700 | 9 | 201,400 |
Tags: dp
Correct Solution:
```
mod=10**9+7
def main():
t,k=map(int,input().split())
dp=[0]*(10**5+1)
for i in range(k):
dp[i]=1
for i in range(k,10**5+1):
dp[i]=(dp[i-1]+dp[i-k])%mod
for i in range(1,10**5+1):
dp[i]=(dp[i]+dp[i-1])%mod
for _ in range(t):
a,b=map(int,input().split())
print((dp[b]-dp[a-1])%mod)
main()
``` | output | 1 | 100,700 | 9 | 201,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR). | instruction | 0 | 100,701 | 9 | 201,402 |
Tags: dp
Correct Solution:
```
t, k = map(int, input().split())
MOD = int(1e9) + 7
def madd(a, b):
if a + b >= MOD:
return a + b - MOD
return a + b
def msub(a, b):
if a >= b:
return a - b
return a - b + MOD
dp = [0] * 100001
dp[0] = 1
prefix = [0] * 100001
for i in range(1, 100001):
dp[i] = dp[i - 1]
if i >= k:
dp[i] = madd(dp[i], dp[i - k])
prefix[i] = madd(prefix[i - 1], dp[i])
for _ in range(t):
a, b = map(int, input().split())
print(msub(prefix[b], prefix[a - 1]))
``` | output | 1 | 100,701 | 9 | 201,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR). | instruction | 0 | 100,702 | 9 | 201,404 |
Tags: dp
Correct Solution:
```
t, k = [int(x) for x in input().split(' ')]
d = [1]
c = [1]
l = 1
for i in range(1, 10**5+1):
v = d[i-1] + (d[i-k] if i-k >= 0 else 0)
v %= (10**9+7)
d.append(v)
c.append((v + l) % (10**9+7))
l = (v + l) % (10**9+7)
# print(d[:5], c[:5])
for _ in range(t):
a, b = [int(x) for x in input().split(' ')]
s = c[b] - c[a-1]
print(str(s) if s >= 0 else str(10**9+7+s))
``` | output | 1 | 100,702 | 9 | 201,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR). | instruction | 0 | 100,703 | 9 | 201,406 |
Tags: dp
Correct Solution:
```
import sys
def solve():
MOD = 1000000007
size = 100003
t, groupsize = read()
mem = [0]*size
summ = [0]*size
mem[0] = 1
for i in range(1, len(mem)):
mem[i] = (mem[i - 1] + mem[i - groupsize] if i >= groupsize else mem[i-1]) % MOD
summ[0] = mem[0]
for i in range(1, len(summ)):
summ[i] = (mem[i] + summ[i - 1]) % MOD
res = list()
for i in range(t):
a, b = read()
res.append((summ[b]-summ[a-1]+MOD)%MOD)
return res
def read(mode=2):
inputs = input().strip()
if mode == 0: return inputs # String
if mode == 1: return inputs.split() # List of strings
if mode == 2: return list(map(int, inputs.split())) # List of integers
def write(s="\n"):
if s is None: s = ""
if isinstance(s, list): s = "\n".join(map(str, s))
if isinstance(s, tuple): s = " ".join(map(str, s))
s = str(s)
print(s, end="")
def run():
if sys.hexversion == 50594544 : sys.stdin = open("test.txt")
res = solve()
write(res)
run()
``` | output | 1 | 100,703 | 9 | 201,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR). | instruction | 0 | 100,704 | 9 | 201,408 |
Tags: dp
Correct Solution:
```
#!/usr/bin/python3
from sys import stdin, stdout
t , k = map(int,stdin.readline().split())
a = [0] * 100001
s = [0] * 100001
MOD = 1000000007
for i in range(0,100001):
if i < k:
a[i] = 1
else:
a[i] = (a[i - 1] + a[i - k])%MOD
s[i] = (s[i - 1] + a[i])%MOD
for i in range(0 , t):
l , r = map(int,stdin.readline().split())
stdout.write( str( (s[r]-s[l-1]+MOD )%MOD ) + "\n" )
``` | output | 1 | 100,704 | 9 | 201,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR).
Submitted Solution:
```
t,k=map(int,input().split())
A=[0]
B=[0]
bmax=0
m=1000000007
for _ in range(t):
a,b=map(int,input().split())
A+=[a]
B+=[b]
bmax=max(B)
arr=[0]*(bmax+1)
for i in range(bmax+1):
if i<k:
arr[i]=1
else:
arr[i]=(arr[i-1]%m+arr[i-k]%m)%m
for i in range(bmax+1):
if i!=0:
arr[i]=(arr[i-1]%m+arr[i]%m)%m
for i in range(1,t+1):
print((arr[B[i]]%m-arr[A[i]-1]%m)%m)
``` | instruction | 0 | 100,705 | 9 | 201,410 |
Yes | output | 1 | 100,705 | 9 | 201,411 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR).
Submitted Solution:
```
#a, b, c, d = [int(x) for x in stdin.readline().split()]
#a, b, c, d = map( int, stdin.readline().split() )
from sys import stdin, stdout
modconst=1000000007
n,k=map(int, stdin.readline().split())
f=[0]*100001
ss=[0]*100001
f[0]=0
for i in range(1,k):
f[i]=1
f[k]=2
for i in range(k+1,100001):
f[i]=(f[i-1]+f[i-k])%modconst
ss[0]=0;
for i in range(1,100001):
ss[i]=(ss[i-1]+f[i])%modconst
for i in range(n):
a,b=map(int, stdin.readline().split())
stdout.write( str( (ss[b]-ss[a-1]+modconst )%modconst ) + "\n" )
``` | instruction | 0 | 100,706 | 9 | 201,412 |
Yes | output | 1 | 100,706 | 9 | 201,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR).
Submitted Solution:
```
import sys
input = sys.stdin.readline
MOD = 1000000007
MOD2 = 998244353
ii = lambda: int(input())
si = lambda: input()
dgl = lambda: list(map(int, input()))
f = lambda: map(int, input().split())
il = lambda: list(map(int, input().split()))
ls = lambda: list(input().strip('\n'))
let = 'abcdefghijklmnopqrstuvwxyz'
N=10**5+1
t,k=f()
dp=[1]*N
dpsm=[0]*N
dpsm[0]=1
for i in range(k,N):
dp[i]=(dp[i-1]+dp[i-k])%MOD
for i in range(1,N):
dpsm[i]=(dpsm[i-1]+dp[i])%MOD
for _ in range(t):
a,b=f()
print((dpsm[b]-dpsm[a-1])%MOD)
``` | instruction | 0 | 100,707 | 9 | 201,414 |
Yes | output | 1 | 100,707 | 9 | 201,415 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR).
Submitted Solution:
```
# https://codeforces.com/problemset/problem/474/D
MOD = 1000000007
SIZE = 100010
dp = [-1 for i in range(SIZE)]
def flowers(n, k):
if n == 0:
return 1
if dp[n] != -1:
return dp[n]
temp = 0
if n >= k:
temp = (flowers(n-k, k) % MOD)
temp += (flowers(n-1, k) % MOD)
temp %= MOD
dp[n] = temp
return dp[n]
def flowers_runner():
dp[0] = 0
line = input()
sn, sk = line.split(' ')
n = int(sn)
k = int(sk)
for i in range(SIZE-1):
flowers(i+1, k)
for i in range(SIZE-1):
dp[i+1] += dp[i]
dp[i+1] %= MOD
while n != 0:
line = input()
sa, sb = line.split(' ')
a = int(sa)
b = int(sb)
print((MOD + dp[b] - dp[a-1]) % MOD)
n -= 1
flowers_runner()
``` | instruction | 0 | 100,708 | 9 | 201,416 |
Yes | output | 1 | 100,708 | 9 | 201,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR).
Submitted Solution:
```
n,k=map(int,input().split())
s=[]
m=0
for i in range(n):
t=list(map(int,input().split()))
s+=t
m=max([m]+t)
r=[[0,0] for i in range(m)]
for i in range(min(k-1,m)):
r[i]=[1,0]
if k<=m:
r[k-1]=[1,1]
for i in range(k,m):
r[i][0]=sum(r[i-1])
r[i][1]=sum(r[i-k])
r=list(map(sum,r))
for i in range(0,len(s),2):
a,b=s[i],s[i+1]
print(sum(r[a-1:b]))
``` | instruction | 0 | 100,709 | 9 | 201,418 |
No | output | 1 | 100,709 | 9 | 201,419 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR).
Submitted Solution:
```
def cases(i):
if i==0:
return 1
elif i<k:
return 1
else:
if arr[i]!=0:
return arr[i]
else:
arr[i]=cases(i-1)+cases(i-k)
return arr[i]
t,k=map(int,input().split())
A=[]
B=[]
for _ in range(t):
a,b=map(int,input().split())
A+=[a]
B+=[b]
bmax=max(B)
arr=[0]*(bmax+1)
prefixsum=[0]*(bmax+1)
for i in range(bmax+1):
if i!=0:
prefixsum[i]+=prefixsum[i-1]+cases(i)
#print(prefixsum)
for i in range(t):
print(prefixsum[B[i]]-prefixsum[A[i]-1])
``` | instruction | 0 | 100,710 | 9 | 201,420 |
No | output | 1 | 100,710 | 9 | 201,421 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR).
Submitted Solution:
```
t,k=map(int,input().split())
m=10**9+7
power=[1]
for i in range(100001):
power.append((power[-1]*2)%m)
dp=[0 for i in range(100001)]
for i in range(1,100001):
if(i<k):
dp[i]=(dp[i-1]+1)%m
else:
dp[i]=(dp[i-1]+1+power[i-k])%m
while t:
a,b=map(int,input().split())
print(dp[b]-dp[a-1])
t-=1
``` | instruction | 0 | 100,711 | 9 | 201,422 |
No | output | 1 | 100,711 | 9 | 201,423 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We saw the little game Marmot made for Mole's lunch. Now it's Marmot's dinner time and, as we all know, Marmot eats flowers. At every dinner he eats some red and white flowers. Therefore a dinner can be represented as a sequence of several flowers, some of them white and some of them red.
But, for a dinner to be tasty, there is a rule: Marmot wants to eat white flowers only in groups of size k.
Now Marmot wonders in how many ways he can eat between a and b flowers. As the number of ways could be very large, print it modulo 1000000007 (109 + 7).
Input
Input contains several test cases.
The first line contains two integers t and k (1 β€ t, k β€ 105), where t represents the number of test cases.
The next t lines contain two integers ai and bi (1 β€ ai β€ bi β€ 105), describing the i-th test.
Output
Print t lines to the standard output. The i-th line should contain the number of ways in which Marmot can eat between ai and bi flowers at dinner modulo 1000000007 (109 + 7).
Examples
Input
3 2
1 3
2 3
4 4
Output
6
5
5
Note
* For K = 2 and length 1 Marmot can eat (R).
* For K = 2 and length 2 Marmot can eat (RR) and (WW).
* For K = 2 and length 3 Marmot can eat (RRR), (RWW) and (WWR).
* For K = 2 and length 4 Marmot can eat, for example, (WWWW) or (RWWR), but for example he can't eat (WWWR).
Submitted Solution:
```
t, k = map(int, input().split())
a_b_values = []
max_b = 0
mod = 10 ** 9 + 7
for i in range(t):
a, b = map(int, input().split())
a_b_values.append((a, b))
max_b = max(b, max_b)
ways = [None] * (max_b + 1)
sum_ways = [None] * (max_b + 1)
for i in range(k):
ways[i] = 1
if i == 0:
sum_ways[i] = 0
else:
sum_ways[i] = sum_ways[i - 1] + 1
for i in range(k, max_b + 1):
ways[i] = (ways[i - 1] + ways[i - k])
sum_ways[i] = (ways[i] + sum_ways[i - 1])
for a,b in a_b_values:
total = sum_ways[b] - sum_ways[a - 1]
print(total)
``` | instruction | 0 | 100,712 | 9 | 201,424 |
No | output | 1 | 100,712 | 9 | 201,425 |
Provide a correct Python 3 solution for this coding contest problem.
Way to go! Heidi now knows how many brains there must be for her to get one. But throwing herself in the midst of a clutch of hungry zombies is quite a risky endeavor. Hence Heidi wonders: what is the smallest number of brains that must be in the chest for her to get out at all (possibly empty-handed, but alive)?
The brain dinner night will evolve just as in the previous subtask: the same crowd is present, the N - 1 zombies have the exact same mindset as before and Heidi is to make the first proposal, which must be accepted by at least half of the attendees for her to survive.
Input
The only line of input contains one integer: N, the number of attendees (1 β€ N β€ 109).
Output
Output one integer: the smallest number of brains in the chest which allows Heidi to merely survive.
Examples
Input
1
Output
0
Input
3
Output
1
Input
99
Output
49 | instruction | 0 | 100,785 | 9 | 201,570 |
"Correct Solution:
```
n = int(input())
if (n % 2 == 1):
print(n // 2)
exit(0)
i = 1
while (i <= n):
i *= 2
i //= 2
n -= i
print(n // 2)
``` | output | 1 | 100,785 | 9 | 201,571 |
Provide a correct Python 3 solution for this coding contest problem.
Way to go! Heidi now knows how many brains there must be for her to get one. But throwing herself in the midst of a clutch of hungry zombies is quite a risky endeavor. Hence Heidi wonders: what is the smallest number of brains that must be in the chest for her to get out at all (possibly empty-handed, but alive)?
The brain dinner night will evolve just as in the previous subtask: the same crowd is present, the N - 1 zombies have the exact same mindset as before and Heidi is to make the first proposal, which must be accepted by at least half of the attendees for her to survive.
Input
The only line of input contains one integer: N, the number of attendees (1 β€ N β€ 109).
Output
Output one integer: the smallest number of brains in the chest which allows Heidi to merely survive.
Examples
Input
1
Output
0
Input
3
Output
1
Input
99
Output
49 | instruction | 0 | 100,786 | 9 | 201,572 |
"Correct Solution:
```
n = int(input())
if (n % 2 == 1):
print(n // 2)
else:
x = 1
while (x <= n):
x *= 2
print((n - x // 2) // 2)
``` | output | 1 | 100,786 | 9 | 201,573 |
Provide a correct Python 3 solution for this coding contest problem.
Way to go! Heidi now knows how many brains there must be for her to get one. But throwing herself in the midst of a clutch of hungry zombies is quite a risky endeavor. Hence Heidi wonders: what is the smallest number of brains that must be in the chest for her to get out at all (possibly empty-handed, but alive)?
The brain dinner night will evolve just as in the previous subtask: the same crowd is present, the N - 1 zombies have the exact same mindset as before and Heidi is to make the first proposal, which must be accepted by at least half of the attendees for her to survive.
Input
The only line of input contains one integer: N, the number of attendees (1 β€ N β€ 109).
Output
Output one integer: the smallest number of brains in the chest which allows Heidi to merely survive.
Examples
Input
1
Output
0
Input
3
Output
1
Input
99
Output
49 | instruction | 0 | 100,787 | 9 | 201,574 |
"Correct Solution:
```
from math import log2, floor
N = int(input())
if N % 2 == 0:
N //= 2
ans = N - 2 ** floor(log2(N))
else:
ans = (N+1) // 2 - 1
print(ans)
``` | output | 1 | 100,787 | 9 | 201,575 |
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