text stringlengths 198 433k | conversation_id int64 0 109k |
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in the right places.
The robber girl was angry at first, but then she decided to arrange the animals herself. She repeatedly names numbers l and r such that r - l + 1 is even. After that animals that occupy positions between l and r inclusively are rearranged as follows: the animal at position l swaps places with the animal at position l + 1, the animal l + 2 swaps with the animal l + 3, ..., finally, the animal at position r - 1 swaps with the animal r.
Help the robber girl to arrange the animals in the order of non-decreasing height. You should name at most 20 000 segments, since otherwise the robber girl will become bored and will start scaring the animals again.
Input
The first line contains a single integer n (1 β€ n β€ 100) β number of animals in the robber girl's zoo.
The second line contains n space-separated integers a1, a2, ..., an (1 β€ ai β€ 109), where ai is the height of the animal occupying the i-th place.
Output
Print the sequence of operations that will rearrange the animals by non-decreasing height.
The output should contain several lines, i-th of the lines should contain two space-separated integers li and ri (1 β€ li < ri β€ n) β descriptions of segments the robber girl should name. The segments should be described in the order the operations are performed.
The number of operations should not exceed 20 000.
If the animals are arranged correctly from the start, you are allowed to output nothing.
Examples
Input
4
2 1 4 3
Output
1 4
Input
7
36 28 57 39 66 69 68
Output
1 4
6 7
Input
5
1 2 1 2 1
Output
2 5
3 4
1 4
1 4
Note
Note that you don't have to minimize the number of operations. Any solution that performs at most 20 000 operations is allowed.
Submitted Solution:
```
import copy
n = int(input())
arr = [int(x) for x in input().split(' ')]
carr = copy.deepcopy(arr)
carr.sort()
while True:
for i in range(n-1):
if arr[i] <= arr[i+1]: continue
j = i
while arr[j] > arr[j+1]:
arr[j], arr[j+1] = arr[j+1], arr[j]
print(j+1,j+2)
j += 1
if j == n-1: break
if carr == arr: exit()
```
Yes
| 2,100 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in the right places.
The robber girl was angry at first, but then she decided to arrange the animals herself. She repeatedly names numbers l and r such that r - l + 1 is even. After that animals that occupy positions between l and r inclusively are rearranged as follows: the animal at position l swaps places with the animal at position l + 1, the animal l + 2 swaps with the animal l + 3, ..., finally, the animal at position r - 1 swaps with the animal r.
Help the robber girl to arrange the animals in the order of non-decreasing height. You should name at most 20 000 segments, since otherwise the robber girl will become bored and will start scaring the animals again.
Input
The first line contains a single integer n (1 β€ n β€ 100) β number of animals in the robber girl's zoo.
The second line contains n space-separated integers a1, a2, ..., an (1 β€ ai β€ 109), where ai is the height of the animal occupying the i-th place.
Output
Print the sequence of operations that will rearrange the animals by non-decreasing height.
The output should contain several lines, i-th of the lines should contain two space-separated integers li and ri (1 β€ li < ri β€ n) β descriptions of segments the robber girl should name. The segments should be described in the order the operations are performed.
The number of operations should not exceed 20 000.
If the animals are arranged correctly from the start, you are allowed to output nothing.
Examples
Input
4
2 1 4 3
Output
1 4
Input
7
36 28 57 39 66 69 68
Output
1 4
6 7
Input
5
1 2 1 2 1
Output
2 5
3 4
1 4
1 4
Note
Note that you don't have to minimize the number of operations. Any solution that performs at most 20 000 operations is allowed.
Submitted Solution:
```
#686B
n = int(input())
a = list(map(int, input().split()))
for i in range(n-1,0,-1):
for j in range(i):
if a[j] > a[j+1]:
a[j],a[j+1] = a[j+1],a[j]
print(j+1, j+2)
# print(*a)
```
Yes
| 2,101 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in the right places.
The robber girl was angry at first, but then she decided to arrange the animals herself. She repeatedly names numbers l and r such that r - l + 1 is even. After that animals that occupy positions between l and r inclusively are rearranged as follows: the animal at position l swaps places with the animal at position l + 1, the animal l + 2 swaps with the animal l + 3, ..., finally, the animal at position r - 1 swaps with the animal r.
Help the robber girl to arrange the animals in the order of non-decreasing height. You should name at most 20 000 segments, since otherwise the robber girl will become bored and will start scaring the animals again.
Input
The first line contains a single integer n (1 β€ n β€ 100) β number of animals in the robber girl's zoo.
The second line contains n space-separated integers a1, a2, ..., an (1 β€ ai β€ 109), where ai is the height of the animal occupying the i-th place.
Output
Print the sequence of operations that will rearrange the animals by non-decreasing height.
The output should contain several lines, i-th of the lines should contain two space-separated integers li and ri (1 β€ li < ri β€ n) β descriptions of segments the robber girl should name. The segments should be described in the order the operations are performed.
The number of operations should not exceed 20 000.
If the animals are arranged correctly from the start, you are allowed to output nothing.
Examples
Input
4
2 1 4 3
Output
1 4
Input
7
36 28 57 39 66 69 68
Output
1 4
6 7
Input
5
1 2 1 2 1
Output
2 5
3 4
1 4
1 4
Note
Note that you don't have to minimize the number of operations. Any solution that performs at most 20 000 operations is allowed.
Submitted Solution:
```
#!/usr/bin/python3
n = int( input() )
a = [ 0 ] + list( map( int , input().split() ) )
def negs():
i = 1
while i < n :
if a[ i ] > a[ i + 1 ]:
yield ( i , i + 1 )
i += 1
i += 1
sorted = False
while not sorted:
sorted = True
for pair in negs():
sorted = False
i , j = pair[ 0 ] , pair[ 1 ]
print( i , j )
a[ i ] , a[ j ] = a[ j ] , a[ i ]
```
Yes
| 2,102 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in the right places.
The robber girl was angry at first, but then she decided to arrange the animals herself. She repeatedly names numbers l and r such that r - l + 1 is even. After that animals that occupy positions between l and r inclusively are rearranged as follows: the animal at position l swaps places with the animal at position l + 1, the animal l + 2 swaps with the animal l + 3, ..., finally, the animal at position r - 1 swaps with the animal r.
Help the robber girl to arrange the animals in the order of non-decreasing height. You should name at most 20 000 segments, since otherwise the robber girl will become bored and will start scaring the animals again.
Input
The first line contains a single integer n (1 β€ n β€ 100) β number of animals in the robber girl's zoo.
The second line contains n space-separated integers a1, a2, ..., an (1 β€ ai β€ 109), where ai is the height of the animal occupying the i-th place.
Output
Print the sequence of operations that will rearrange the animals by non-decreasing height.
The output should contain several lines, i-th of the lines should contain two space-separated integers li and ri (1 β€ li < ri β€ n) β descriptions of segments the robber girl should name. The segments should be described in the order the operations are performed.
The number of operations should not exceed 20 000.
If the animals are arranged correctly from the start, you are allowed to output nothing.
Examples
Input
4
2 1 4 3
Output
1 4
Input
7
36 28 57 39 66 69 68
Output
1 4
6 7
Input
5
1 2 1 2 1
Output
2 5
3 4
1 4
1 4
Note
Note that you don't have to minimize the number of operations. Any solution that performs at most 20 000 operations is allowed.
Submitted Solution:
```
#!/usr/bin/env python3
import math
import random
def main():
n = int(input())
a = [int(x) for x in input().split()]
for i in range(n - 1):
for j in range(i + 1, n):
if a[i] > a[j]:
print(i + 1, j + 1)
a[i], a[j] = a[j], a[i]
if __name__ == '__main__':
main()
```
No
| 2,103 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in the right places.
The robber girl was angry at first, but then she decided to arrange the animals herself. She repeatedly names numbers l and r such that r - l + 1 is even. After that animals that occupy positions between l and r inclusively are rearranged as follows: the animal at position l swaps places with the animal at position l + 1, the animal l + 2 swaps with the animal l + 3, ..., finally, the animal at position r - 1 swaps with the animal r.
Help the robber girl to arrange the animals in the order of non-decreasing height. You should name at most 20 000 segments, since otherwise the robber girl will become bored and will start scaring the animals again.
Input
The first line contains a single integer n (1 β€ n β€ 100) β number of animals in the robber girl's zoo.
The second line contains n space-separated integers a1, a2, ..., an (1 β€ ai β€ 109), where ai is the height of the animal occupying the i-th place.
Output
Print the sequence of operations that will rearrange the animals by non-decreasing height.
The output should contain several lines, i-th of the lines should contain two space-separated integers li and ri (1 β€ li < ri β€ n) β descriptions of segments the robber girl should name. The segments should be described in the order the operations are performed.
The number of operations should not exceed 20 000.
If the animals are arranged correctly from the start, you are allowed to output nothing.
Examples
Input
4
2 1 4 3
Output
1 4
Input
7
36 28 57 39 66 69 68
Output
1 4
6 7
Input
5
1 2 1 2 1
Output
2 5
3 4
1 4
1 4
Note
Note that you don't have to minimize the number of operations. Any solution that performs at most 20 000 operations is allowed.
Submitted Solution:
```
# little robber girl zoo solution
# the swapping is similar to bubblesort, but it is impossible to
# fully bubble anything because every other value is swapped with
# the value right above it, so there is no bubbling. bubbling can
# only be performed with consecutive swaps over range i and i + 1
# we need the animals in ascending order of height
if (__name__ == "__main__"):
# read number of animals
n = int(input())
# make permanent for outer loop
nn = n
# get array of animals
a = list(map(int, input().split()))
# perform a selection sort
i = 0
while (i < nn):
j = 0
# find the index of largest element
mi = 0
while (j < n):
if (a[j] >= a[mi]):
mi = j
j += 1
# bubble the element to the end, printing ranges as we go
while (mi < n - 1):
print("{} {}".format(mi, mi + 1))
temp = a[mi]
a[mi] = a[mi + 1]
a[mi + 1] = temp
mi += 1
# decrement n
n -= 1
# increment i
i += 1
```
No
| 2,104 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in the right places.
The robber girl was angry at first, but then she decided to arrange the animals herself. She repeatedly names numbers l and r such that r - l + 1 is even. After that animals that occupy positions between l and r inclusively are rearranged as follows: the animal at position l swaps places with the animal at position l + 1, the animal l + 2 swaps with the animal l + 3, ..., finally, the animal at position r - 1 swaps with the animal r.
Help the robber girl to arrange the animals in the order of non-decreasing height. You should name at most 20 000 segments, since otherwise the robber girl will become bored and will start scaring the animals again.
Input
The first line contains a single integer n (1 β€ n β€ 100) β number of animals in the robber girl's zoo.
The second line contains n space-separated integers a1, a2, ..., an (1 β€ ai β€ 109), where ai is the height of the animal occupying the i-th place.
Output
Print the sequence of operations that will rearrange the animals by non-decreasing height.
The output should contain several lines, i-th of the lines should contain two space-separated integers li and ri (1 β€ li < ri β€ n) β descriptions of segments the robber girl should name. The segments should be described in the order the operations are performed.
The number of operations should not exceed 20 000.
If the animals are arranged correctly from the start, you are allowed to output nothing.
Examples
Input
4
2 1 4 3
Output
1 4
Input
7
36 28 57 39 66 69 68
Output
1 4
6 7
Input
5
1 2 1 2 1
Output
2 5
3 4
1 4
1 4
Note
Note that you don't have to minimize the number of operations. Any solution that performs at most 20 000 operations is allowed.
Submitted Solution:
```
input()
heights = list(map(int, input().split()))
sortedHeights = sorted(heights)
for i,item in enumerate(sortedHeights):
index = heights[i:].index(item) + i
if index > i:
for current in range(index - i):
c = index - current - 1
heights[c+ 1],heights[c] = heights[c],heights[c+1]
print(c, c + 1)
```
No
| 2,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Robber Girl likes to scare animals in her zoo for fun. She decided to arrange the animals in a row in the order of non-decreasing height. However, the animals were so scared that they couldn't stay in the right places.
The robber girl was angry at first, but then she decided to arrange the animals herself. She repeatedly names numbers l and r such that r - l + 1 is even. After that animals that occupy positions between l and r inclusively are rearranged as follows: the animal at position l swaps places with the animal at position l + 1, the animal l + 2 swaps with the animal l + 3, ..., finally, the animal at position r - 1 swaps with the animal r.
Help the robber girl to arrange the animals in the order of non-decreasing height. You should name at most 20 000 segments, since otherwise the robber girl will become bored and will start scaring the animals again.
Input
The first line contains a single integer n (1 β€ n β€ 100) β number of animals in the robber girl's zoo.
The second line contains n space-separated integers a1, a2, ..., an (1 β€ ai β€ 109), where ai is the height of the animal occupying the i-th place.
Output
Print the sequence of operations that will rearrange the animals by non-decreasing height.
The output should contain several lines, i-th of the lines should contain two space-separated integers li and ri (1 β€ li < ri β€ n) β descriptions of segments the robber girl should name. The segments should be described in the order the operations are performed.
The number of operations should not exceed 20 000.
If the animals are arranged correctly from the start, you are allowed to output nothing.
Examples
Input
4
2 1 4 3
Output
1 4
Input
7
36 28 57 39 66 69 68
Output
1 4
6 7
Input
5
1 2 1 2 1
Output
2 5
3 4
1 4
1 4
Note
Note that you don't have to minimize the number of operations. Any solution that performs at most 20 000 operations is allowed.
Submitted Solution:
```
##############--->>>>> Deepcoder Amit Kumar Bhuyan <<<<<---##############
"""
Perfection is achieved not when there is nothing more to add, but rather when there is nothing more to take away.
"""
from __future__ import division, print_function
import os,sys
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
from __builtin__ import xrange as range
from future_builtins import ascii, filter, hex, map, oct, zip
def ii(): return int(input())
def si(): return input()
def mi(): return map(int,input().strip().split(" "))
def msi(): return map(str,input().strip().split(" "))
def li(): return list(mi())
def dmain():
sys.setrecursionlimit(1000000)
threading.stack_size(1024000)
thread = threading.Thread(target=main)
thread.start()
#from collections import deque, Counter, OrderedDict,defaultdict
#from heapq import nsmallest, nlargest, heapify,heappop ,heappush, heapreplace
#from math import log,sqrt,factorial,cos,tan,sin,radians
#from bisect import bisect,bisect_left,bisect_right,insort,insort_left,insort_right
#from decimal import *
#import threading
#from itertools import permutations
#Copy 2D list m = [x[:] for x in mark] .. Avoid Using Deepcopy
import sys
input = sys.stdin.readline
scanner = lambda: int(input())
string = lambda: input().rstrip()
get_list = lambda: list(read())
read = lambda: map(int, input().split())
get_float = lambda: map(float, input().split())
# from bisect import bisect_left as lower_bound;
# from bisect import bisect_right as upper_bound;
# from math import ceil, factorial;
def ceil(x):
if x != int(x):
x = int(x) + 1
return x
def factorial(x, m):
val = 1
while x>0:
val = (val * x) % m
x -= 1
return val
def fact(x):
val = 1
while x > 0:
val *= x
x -= 1
return val
# swap_array function
def swaparr(arr, a,b):
temp = arr[a];
arr[a] = arr[b];
arr[b] = temp;
## gcd function
def gcd(a,b):
if b == 0:
return a;
return gcd(b, a % b);
## lcm function
def lcm(a, b):
return (a * b) // math.gcd(a, b)
def is_integer(n):
return math.ceil(n) == math.floor(n)
## nCr function efficient using Binomial Cofficient
def nCr(n, k):
if k > n:
return 0
if(k > n - k):
k = n - k
res = 1
for i in range(k):
res = res * (n - i)
res = res / (i + 1)
return int(res)
## upper bound function code -- such that e in a[:i] e < x;
## prime factorization
def primefs(n):
## if n == 1 ## calculating primes
primes = {}
while(n%2 == 0 and n > 0):
primes[2] = primes.get(2, 0) + 1
n = n//2
for i in range(3, int(n**0.5)+2, 2):
while(n%i == 0 and n > 0):
primes[i] = primes.get(i, 0) + 1
n = n//i
if n > 2:
primes[n] = primes.get(n, 0) + 1
## prime factoriazation of n is stored in dictionary
## primes and can be accesed. O(sqrt n)
return primes
## MODULAR EXPONENTIATION FUNCTION
def power(x, y, p):
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1
x = (x * x) % p
return res
## DISJOINT SET UNINON FUNCTIONS
def swap(a,b):
temp = a
a = b
b = temp
return a,b;
# find function with path compression included (recursive)
# def find(x, link):
# if link[x] == x:
# return x
# link[x] = find(link[x], link);
# return link[x];
# find function with path compression (ITERATIVE)
def find(x, link):
p = x;
while( p != link[p]):
p = link[p];
while( x != p):
nex = link[x];
link[x] = p;
x = nex;
return p;
# the union function which makes union(x,y)
# of two nodes x and y
def union(x, y, link, size):
x = find(x, link)
y = find(y, link)
if size[x] < size[y]:
x,y = swap(x,y)
if x != y:
size[x] += size[y]
link[y] = x
## returns an array of boolean if primes or not USING SIEVE OF ERATOSTHANES
def sieve(n):
prime = [True for i in range(n+1)]
prime[0], prime[1] = False, False
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
# Euler's Toitent Function phi
def phi(n) :
result = n
p = 2
while(p * p<= n) :
if (n % p == 0) :
while (n % p == 0) :
n = n // p
result = result * (1.0 - (1.0 / (float) (p)))
p = p + 1
if (n > 1) :
result = result * (1.0 - (1.0 / (float)(n)))
return (int)(result)
def is_prime(n):
if n == 0:
return False
if n == 1:
return True
for i in range(2, int(n ** (1 / 2)) + 1):
if not n % i:
return False
return True
def next_prime(n, primes):
while primes[n] != True:
n += 1
return n
#### PRIME FACTORIZATION IN O(log n) using Sieve ####
MAXN = int(1e5 + 5)
def spf_sieve():
spf[1] = 1;
for i in range(2, MAXN):
spf[i] = i;
for i in range(4, MAXN, 2):
spf[i] = 2;
for i in range(3, ceil(MAXN ** 0.5), 2):
if spf[i] == i:
for j in range(i*i, MAXN, i):
if spf[j] == j:
spf[j] = i;
## function for storing smallest prime factors (spf) in the array
################## un-comment below 2 lines when using factorization #################
spf = [0 for i in range(MAXN)]
# spf_sieve();
def factoriazation(x):
res = []
for i in range(2, int(x ** 0.5) + 1):
while x % i == 0:
res.append(i)
x //= i
if x != 1:
res.append(x)
return res
## this function is useful for multiple queries only, o/w use
## primefs function above. complexity O(log n)
def factors(n):
res = []
for i in range(1, int(n ** 0.5) + 1):
if n % i == 0:
res.append(i)
res.append(n // i)
return list(set(res))
## taking integer array input
def int_array():
return list(map(int, input().strip().split()));
def float_array():
return list(map(float, input().strip().split()));
## taking string array input
def str_array():
return input().strip().split();
def binary_search(low, high, w, h, n):
while low < high:
mid = low + (high - low) // 2
# print(low, mid, high)
if check(mid, w, h, n):
low = mid + 1
else:
high = mid
return low
## for checking any conditions
def check(moves, n):
val = (moves + 1) // 2
rem = moves - val
sol = (val + 1) * (rem + 1)
return sol < n
## for sorting according to second position
def sortSecond(val):
return val[1]
#defining a couple constants
MOD = int(1e9)+7;
CMOD = 998244353;
INF = float('inf'); NINF = -float('inf');
alphs = "abcdefghijklmnopqrstuvwxyz"
################### ---------------- TEMPLATE ENDS HERE ---------------- ###################
from itertools import permutations
import math
import bisect as bis
import random
import sys
import collections as collect
import functools as fnt
from decimal import Decimal
# from sys import stdout
# import numpy as np
"""
_______________
rough work here
_______________
36 28 57 39 66 69 68
28 36 39 57 66 68 69
5 4 3 2 1
5 4 3 1 2
5 4 1 3 2
5 4 1 2 3
5 1 4 2 3
1 5 4 2 3
1 5 2 4 3
1
"""
def solve():
n = scanner()
a = get_list()
for i in range(n - 1):
for j in range(i + 1, n):
if a[j] < a[j - 1]:
a[j], a[j - 1] = a[j - 1], a[j]
print(j, j + 1)
# print(*a)
# region fastio
# template taken from https://github.com/cheran-senthil/PyRival/blob/master/templates/template.py
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
"""Prints the values to a stream, or to sys.stdout by default."""
sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
if sys.version_info[0] < 3:
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
#read()
# sys.stdin = open("input.txt", "r")
# sys.stdout = open("output.txt", "w")
t = 1
for i in range(t):
solve()
#dmain()
# Comment Read()
# fin_time = datetime.now()
# print("Execution time (for loop): ", (fin_time-init_time))
```
No
| 2,106 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Tags: implementation
Correct Solution:
```
n, b, k = map(int,input().split())
array = list(map(int,input().split()))
now = 0
count = 0
for num in array:
if num <= b:
now += num
if now > k:
now = 0
count += 1
print(count)
```
| 2,107 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Tags: implementation
Correct Solution:
```
n, b, d = input().split()
n = int(n)
b = int(b)
d = int(d)
oranges = input().split()
waste = 0
ret = 0
for i in range(n):
x = int(oranges[i])
if x>b:
continue
waste += x
if waste>d:
waste = 0
ret = ret + 1
print (ret)
```
| 2,108 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Tags: implementation
Correct Solution:
```
n,b,d=[int(g) for g in input().split()]
a=[int(f) for f in input().split()]
x=0
f=0
for i in a:
if i<=b:
x+=i
if x>d:
f+=1
x=0
print(f)
```
| 2,109 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Tags: implementation
Correct Solution:
```
n,b,d = map(int,input().split())
a = list(map(int, input().split()))
sm = 0
ans = 0
for i in a :
if i <= b:
sm += i
if sm > d:
ans += 1
sm = 0
print(ans)
```
| 2,110 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Tags: implementation
Correct Solution:
```
n,b,d=map(int,input().split(" "))
list1=list(map(int,input().split(" ")))
sum1=0
ct=0
for j in list1:
if j<=b:
sum1+=j
if sum1>d:
sum1=0
ct+=1
print(ct)
```
| 2,111 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Tags: implementation
Correct Solution:
```
n,b,d=map(int,input().split())
a=list(map(int,input().split()))
c=0
e=0
for i in range(n):
if a[i]<=b:
c+=a[i]
if c>d:
c=0
e+=1
print(e)
```
| 2,112 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Tags: implementation
Correct Solution:
```
#n = int(input())
n, k, m = map(int, input().split())
#s = input()
c = list(map(int, input().split()))
l = 0
t = 0
for i in range(n):
if c[i] <= k:
t += c[i]
if t > m:
t = 0
l += 1
print(l)
```
| 2,113 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Tags: implementation
Correct Solution:
```
import sys
c=0
m=0
i=0
n,b,d=input().split()
x=list(int(num) for num in input().split())
while i<int(n):
if x[i]<=int(b):
c=c+x[i]
if c>int(d):
m+=1
c=0
i+=1
print(m)
```
| 2,114 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Submitted Solution:
```
a, b, c = map(int, input().split())
li = list(map(int, input().split()))
countt = 0
jus_wast = 0
for i in li:
if i <= b:
jus_wast += i
if jus_wast <= c:
pass
else:
jus_wast = 0
countt += 1
print(countt)
```
Yes
| 2,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Submitted Solution:
```
n, b, d = [int(i) for i in input().split()]
a = [int(i) for i in input().split()]
c = 0
w = 0
for i in range(n):
if a[i] <= b:
c += a[i]
if c > d:
c = 0
w += 1
print(w)
```
Yes
| 2,116 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Submitted Solution:
```
n, b, d = map(int, input().split())
daf = list(map(int, input().split()))
jum = 0
was = 0
for j in daf:
if j > b:
continue
was += j
if was > d:
jum += 1
was = 0
print(jum)
```
Yes
| 2,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Submitted Solution:
```
inp1 = list(map(int, input().rstrip().split()))
inp2 = list(map(int, input().rstrip().split()))
s = 0
c = 0
for i in inp2:
if i > inp1[1]: continue
else:
s += i
if s > inp1[2]:
s = 0
c += 1
print(c)
```
Yes
| 2,118 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Submitted Solution:
```
_, b, d = map(int, input().split())
a = list(map(int, input().split()))
total_waste = sum([i for i in a if i < b])
print(total_waste // (d + 1))
```
No
| 2,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Submitted Solution:
```
n, b, d = map(int, input().split())
o = list(map(int, input().split()))
waste, times = 0, 0
for i in range(n):
if o[i] < b:
waste += i
if waste > d:
times += 1
waste = 0
print(times)
```
No
| 2,120 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Submitted Solution:
```
n,b,d = [int(x) for x in input("").split()]
a = [int(x) for x in input("").split()]
currJuice = 0
ans = 0
for i in a:
if i < b:
currJuice += i
if currJuice > d:
ans+=1
currJuice = 0
print(ans)
```
No
| 2,121 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Kolya is going to make fresh orange juice. He has n oranges of sizes a1, a2, ..., an. Kolya will put them in the juicer in the fixed order, starting with orange of size a1, then orange of size a2 and so on. To be put in the juicer the orange must have size not exceeding b, so if Kolya sees an orange that is strictly greater he throws it away and continues with the next one.
The juicer has a special section to collect waste. It overflows if Kolya squeezes oranges of the total size strictly greater than d. When it happens Kolya empties the waste section (even if there are no more oranges) and continues to squeeze the juice. How many times will he have to empty the waste section?
Input
The first line of the input contains three integers n, b and d (1 β€ n β€ 100 000, 1 β€ b β€ d β€ 1 000 000) β the number of oranges, the maximum size of the orange that fits in the juicer and the value d, which determines the condition when the waste section should be emptied.
The second line contains n integers a1, a2, ..., an (1 β€ ai β€ 1 000 000) β sizes of the oranges listed in the order Kolya is going to try to put them in the juicer.
Output
Print one integer β the number of times Kolya will have to empty the waste section.
Examples
Input
2 7 10
5 6
Output
1
Input
1 5 10
7
Output
0
Input
3 10 10
5 7 7
Output
1
Input
1 1 1
1
Output
0
Note
In the first sample, Kolya will squeeze the juice from two oranges and empty the waste section afterwards.
In the second sample, the orange won't fit in the juicer so Kolya will have no juice at all.
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Sat Jan 12 22:39:41 2019
@author: Noussa
"""
n,b,d = map(int,input().split())
a = list(map(int,input().split()))
w = 0
for e in a:
if e >= b:
continue
w += e
print(w // d)
```
No
| 2,122 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new trade empire is rising in Berland. Bulmart, an emerging trade giant, decided to dominate the market of ... shovels! And now almost every city in Berland has a Bulmart store, and some cities even have several of them! The only problem is, at the moment sales are ... let's say a little below estimates. Some people even say that shovels retail market is too small for such a big company to make a profit. But the company management believes in the future of that market and seeks new ways to increase income.
There are n cities in Berland connected with m bi-directional roads. All roads have equal lengths. It can happen that it is impossible to reach a city from another city using only roads. There is no road which connects a city to itself. Any pair of cities can be connected by at most one road.
There are w Bulmart stores in Berland. Each of them is described by three numbers:
* ci β the number of city where the i-th store is located (a city can have no stores at all or have several of them),
* ki β the number of shovels in the i-th store,
* pi β the price of a single shovel in the i-th store (in burles).
The latest idea of the Bulmart management is to create a program which will help customers get shovels as fast as possible for affordable budget. Formally, the program has to find the minimum amount of time needed to deliver rj shovels to the customer in the city gj for the total cost of no more than aj burles. The delivery time between any two adjacent cities is equal to 1. If shovels are delivered from several cities, the delivery time is equal to the arrival time of the last package. The delivery itself is free of charge.
The program needs to find answers to q such queries. Each query has to be processed independently from others, i.e. a query does not change number of shovels in stores for the next queries.
Input
The first line contains two integers n, m (1 β€ n β€ 5000, 0 β€ m β€ min(5000, nΒ·(n - 1) / 2)). Each of the next m lines contains two integers xe and ye, meaning that the e-th road connects cities xe and ye (1 β€ xe, ye β€ n).
The next line contains a single integer w (1 β€ w β€ 5000) β the total number of Bulmart stores in Berland. Each of the next w lines contains three integers describing the i-th store: ci, ki, pi (1 β€ ci β€ n, 1 β€ ki, pi β€ 2Β·105).
The next line contains a single integer q (1 β€ q β€ 1000) β the number of queries. Each of the next q lines contains three integers describing the j-th query: gj, rj and aj (1 β€ gj β€ n, 1 β€ rj, aj β€ 109)
Output
Output q lines. On the j-th line, print an answer for the j-th query β the minimum amount of time needed to deliver rj shovels to the customer in city gj spending no more than aj burles. Print -1 if there is no solution for the j-th query.
Example
Input
6 4
4 2
5 4
1 2
3 2
2
4 1 2
3 2 3
6
1 2 6
2 3 7
3 1 2
4 3 8
5 2 5
6 1 10
Output
2
-1
2
2
3
-1
Submitted Solution:
```
def add_edge(u,v):
global edge_to,edge_next,cnt,head
edge_to[cnt] = v; edge_next[cnt] = head[u]; head[u] = cnt; cnt += 1;
def _check(time,need,cost):
global W,dist,w
tot = 0
for i in range(w):
if (dist[W[i][2]] > time): continue;
if (need-W[i][1] >= 0):
if (tot+W[i][1]*W[i][0] > cost): return -1;
tot += (W[i][1]*W[i][0])
need -= W[i][1]
else :
if (tot+W[i][0]*need > cost): return -1;
return tot+W[i][0]*need;
if (need > 0): return -1;
return 1;
def bfs(city,need,cost):
global n,edge_to,edge_next,head,dist
dist[city] = 0
check = [True for i in range(n+1)];
bfs_ = []; bfs_.append(city);
while (len(bfs_) > 0):
fr = bfs_[0]; check[fr] = False
i = head[fr]
while (i > 0):
to = edge_to[i]; i = edge_next[i];
if (check[to] == False): continue;
check[to] = False
bfs_.append(to)
if (dist[to] > dist[fr]+1): dist[to] = dist[fr]+1;
del bfs_[0]
l = 0; r = n;
while (l <= r):
mid = int((l+r)/2)
if (_check(mid,need,cost) >= 0): r = mid-1;
else : l = mid+1;
if (_check(mid,need,cost) >= 0): return mid;
elif (mid == n) : return -1;
else : return mid+1
n,m = list(map(int,input().split()))
head = [0 for i in range(n+1)]
edge_to = [0 for i in range(int((n*n)/2))]
edge_next = [0 for i in range(int((n*n)/2))]
cnt = 1
for i in range(m): x,y = list(map(int,input().split())); add_edge(x,y); add_edge(y,x);
w = int(input())
W = [[0]*3 for i in range(m+1)]
for i in range(w):
x,y,z = list(map(int,input().split()));
W[i][2],W[i][1],W[i][0] = x,y,z;
q = int(input())
while (q > 0):
q -= 1;
g,r,a = list(map(int,input().split()))
dist =[10**10 for i in range(n+1)];
print(bfs(g,r,a))
```
No
| 2,123 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Tags: dp, greedy, math
Correct Solution:
```
n=int(input())
k=1
spis=[]
j=0
if n == 3:
spis=spis+["1","2"]
j=2
else:
while True:
j=j+1
if n-k >= 3 and str(n-k) not in spis and n-k != k :
n=n-k
spis=spis+[str(k)]
else:
spis=spis+[str(n)]
break
k=k+1
print(j)
print(" ".join(spis))
```
| 2,124 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Tags: dp, greedy, math
Correct Solution:
```
n = int(input())
ans = []
i = 0
while i < n:
i += 1
ans.append(i)
n -= i
ans[-1] += n
print(len(ans))
print(*ans)
```
| 2,125 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Tags: dp, greedy, math
Correct Solution:
```
n = int(input())
x = n
i = 1
while n >= i:
n -= i
i += 1
print(i-1)
for j in range(1,i):
if j == i-1:
print(x)
break
else:
print(j,end= ' ')
x -= j
```
| 2,126 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Tags: dp, greedy, math
Correct Solution:
```
def sol():
n=int(input())
dp=[]
s=0
i=1
while(s+i+i+1<=n):
s+=i
dp.append(i)
i+=1
dp.append(n-sum(dp))
print(len(dp))
print(*dp,sep=" ")
if(__name__=='__main__'):
sol()
```
| 2,127 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Tags: dp, greedy, math
Correct Solution:
```
n=int(input())
a=[]
while n>len(a):
a+=[len(a)+1]
n-=a[-1]
a[-1]+=n
print(len(a))
print(*a)
```
| 2,128 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Tags: dp, greedy, math
Correct Solution:
```
import sys
def CalcAnswer(n):
at = 1
remainder = n
list = []
while at+at+1 <= remainder:
list.append(at)
remainder-=at
at+=1
list.append(remainder)
return list
def PrintAnswer(list_of_candies):
print(len(list_of_candies))
print(" ".join(str(x) for x in list_of_candies))
PrintAnswer(CalcAnswer(int(sys.stdin.readline().strip())))
```
| 2,129 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Tags: dp, greedy, math
Correct Solution:
```
n = int(input())
num = 1
sum1 = 0
diff = 0
lst = list()
while True:
lst.append(num)
sum1 += num
diff = n - sum1
if diff < num + 1:
print(num)
lst[-1] += diff
print(*lst)
break
num += 1
```
| 2,130 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Tags: dp, greedy, math
Correct Solution:
```
n = int(input())
s = 0
ans = []
for i in range(1,2*(n+1)):
s += i
if s <= n:
ans.append(i)
else:
s -= i
ans[-1] = ans[-1] + n-s
break
print(len(ans))
print(*ans)
```
| 2,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Submitted Solution:
```
num = int(input())
a = [i for i in range(45)]
s = 1
idx = 1
while True:
idx += 1
if (s + idx > num):
n = idx-1
break
s += idx
left = num - s
a[n] += left
print(n)
for i in range(1, n+1):
print(a[i], end=" ")
print()
```
Yes
| 2,132 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Submitted Solution:
```
# CF 753/A
# 1100
def f(n):
s = 0
count = 0
for i in range(1, n + 1):
s += i
count += 1
if s >= n:
break
return [j for j in range(1, count + 1) if j != (s - n)]
assert f(2) == [2]
assert f(5) == [2, 3]
n = int(input().strip())
ans = f(n)
print(len(ans))
print(" ".join(map(str, ans)))
```
Yes
| 2,133 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Submitted Solution:
```
n = int(input())
l = []
def foo():
global l
global n
for i in range(1, n + 1):
if i in l:
continue
l.append(i)
n = n - i
foo()
if n == 0:
return
elif len(l) > 0:
n = n + l[len(l) - 1]
del(l[len(l) - 1])
foo()
print(len(l))
for i in l:
print(i, end=" ")
```
Yes
| 2,134 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Submitted Solution:
```
n = int(input()); ans = 0; i = 1
ans1 = []
while ans + i <= n:
ans += i
ans1.append(i)
i += 1
ans1[-1] = ans1[-1]+(n-sum(ans1))
print(len(ans1))
print(*ans1)
```
Yes
| 2,135 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Submitted Solution:
```
x=int(input())
if x==1:
print(1)
print(1)
else:
c=0
i=1
while(c+i<x):
c+=i
i+=1
print(i-1)
for y in range(i-2):
print(y+1,end=" ")
print(i+(x-c-1))
#in clasa riyazi mohandesi :)
```
No
| 2,136 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Submitted Solution:
```
n = int(input())
def max(n):
k=0
while n-k>k:
n-=k
k+=1
print (k)
for i in range(1, k+1):
if i == n-k-1:
print ((n-k+n-k-1),'',end="")
elif i == n-k:
continue
else: print (i,'',end="")
print (k)
return
if n == 2:
print(1)
print(2)
else:
max(n)
```
No
| 2,137 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Submitted Solution:
```
import sys
n = int(sys.stdin.readline())
i=1
t = 1
l = []
while(t < n):
l.append(i)
t+=i
i+=1
leng = len(l)
if t > n:
leng += -1
i+=-1
t+=-i
l.pop(leng)
l[leng-1] += n-sum(l)
print(leng)
strang = ""
for item in l:
strang+=str(item)+" "
print( strang)
```
No
| 2,138 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus has n candies, he dreams to give them as gifts to children.
What is the maximal number of children for whose he can give candies if Santa Claus want each kid should get distinct positive integer number of candies. Santa Class wants to give all n candies he has.
Input
The only line contains positive integer number n (1 β€ n β€ 1000) β number of candies Santa Claus has.
Output
Print to the first line integer number k β maximal number of kids which can get candies.
Print to the second line k distinct integer numbers: number of candies for each of k kid. The sum of k printed numbers should be exactly n.
If there are many solutions, print any of them.
Examples
Input
5
Output
2
2 3
Input
9
Output
3
3 5 1
Input
2
Output
1
2
Submitted Solution:
```
n=int(input())
count=0
total_so_far=0
l=[]
for i in range(1,n+1):
if total_so_far+i>n:
l[-1]+=n-total_so_far
else:
count+=1
l.append(i)
print(count)
print(*l,sep=' ')
```
No
| 2,139 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Arkadiy has lots square photos with size a Γ a. He wants to put some of them on a rectangular wall with size h Γ w.
The photos which Arkadiy will put on the wall must form a rectangular grid and the distances between neighboring vertically and horizontally photos and also the distances between outside rows and columns of photos to the nearest bound of the wall must be equal to x, where x is some non-negative real number. Look on the picture below for better understanding of the statement.
<image>
Arkadiy haven't chosen yet how many photos he would put on the wall, however, he want to put at least one photo. Your task is to determine the minimum value of x which can be obtained after putting photos, or report that there is no way to put positive number of photos and satisfy all the constraints. Suppose that Arkadiy has enough photos to make any valid arrangement according to the constraints.
Note that Arkadiy wants to put at least one photo on the wall. The photos should not overlap, should completely lie inside the wall bounds and should have sides parallel to the wall sides.
Input
The first line contains three integers a, h and w (1 β€ a, h, w β€ 109) β the size of photos and the height and the width of the wall.
Output
Print one non-negative real number β the minimum value of x which can be obtained after putting the photos on the wall. The absolute or the relative error of the answer must not exceed 10 - 6.
Print -1 if there is no way to put positive number of photos and satisfy the constraints.
Examples
Input
2 18 13
Output
0.5
Input
4 4 4
Output
0
Input
3 4 3
Output
-1
Note
In the first example Arkadiy can put 7 rows of photos with 5 photos in each row, so the minimum value of x equals to 0.5.
In the second example Arkadiy can put only 1 photo which will take the whole wall, so the minimum value of x equals to 0.
In the third example there is no way to put positive number of photos and satisfy the constraints described in the statement, so the answer is -1.
Tags: *special, number theory
Correct Solution:
```
def gcd(x,y):
if y==0:return x
else:return gcd(y,x%y)
A,H,W=map(int,input().split())
G=gcd(A+H,A+W)
S=(A+W)//G
T=((W//A+1)//S)*S-1
if T<=0:print(-1)
else:print("%.10lf"%((W-T*A)/(T+1)))
```
| 2,140 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Arkadiy has lots square photos with size a Γ a. He wants to put some of them on a rectangular wall with size h Γ w.
The photos which Arkadiy will put on the wall must form a rectangular grid and the distances between neighboring vertically and horizontally photos and also the distances between outside rows and columns of photos to the nearest bound of the wall must be equal to x, where x is some non-negative real number. Look on the picture below for better understanding of the statement.
<image>
Arkadiy haven't chosen yet how many photos he would put on the wall, however, he want to put at least one photo. Your task is to determine the minimum value of x which can be obtained after putting photos, or report that there is no way to put positive number of photos and satisfy all the constraints. Suppose that Arkadiy has enough photos to make any valid arrangement according to the constraints.
Note that Arkadiy wants to put at least one photo on the wall. The photos should not overlap, should completely lie inside the wall bounds and should have sides parallel to the wall sides.
Input
The first line contains three integers a, h and w (1 β€ a, h, w β€ 109) β the size of photos and the height and the width of the wall.
Output
Print one non-negative real number β the minimum value of x which can be obtained after putting the photos on the wall. The absolute or the relative error of the answer must not exceed 10 - 6.
Print -1 if there is no way to put positive number of photos and satisfy the constraints.
Examples
Input
2 18 13
Output
0.5
Input
4 4 4
Output
0
Input
3 4 3
Output
-1
Note
In the first example Arkadiy can put 7 rows of photos with 5 photos in each row, so the minimum value of x equals to 0.5.
In the second example Arkadiy can put only 1 photo which will take the whole wall, so the minimum value of x equals to 0.
In the third example there is no way to put positive number of photos and satisfy the constraints described in the statement, so the answer is -1.
Tags: *special, number theory
Correct Solution:
```
def gcd(x,y):
if (x%y==0): return y
return gcd(y,x%y)
a,h,w=input().split()
a=int(a)
h=int(h)
w=int(w)
g=gcd(h+a,w+a)
if (g<a or h<a or w<a):
print("-1")
else:
print(g/(g//a)-a)
```
| 2,141 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Arkadiy has lots square photos with size a Γ a. He wants to put some of them on a rectangular wall with size h Γ w.
The photos which Arkadiy will put on the wall must form a rectangular grid and the distances between neighboring vertically and horizontally photos and also the distances between outside rows and columns of photos to the nearest bound of the wall must be equal to x, where x is some non-negative real number. Look on the picture below for better understanding of the statement.
<image>
Arkadiy haven't chosen yet how many photos he would put on the wall, however, he want to put at least one photo. Your task is to determine the minimum value of x which can be obtained after putting photos, or report that there is no way to put positive number of photos and satisfy all the constraints. Suppose that Arkadiy has enough photos to make any valid arrangement according to the constraints.
Note that Arkadiy wants to put at least one photo on the wall. The photos should not overlap, should completely lie inside the wall bounds and should have sides parallel to the wall sides.
Input
The first line contains three integers a, h and w (1 β€ a, h, w β€ 109) β the size of photos and the height and the width of the wall.
Output
Print one non-negative real number β the minimum value of x which can be obtained after putting the photos on the wall. The absolute or the relative error of the answer must not exceed 10 - 6.
Print -1 if there is no way to put positive number of photos and satisfy the constraints.
Examples
Input
2 18 13
Output
0.5
Input
4 4 4
Output
0
Input
3 4 3
Output
-1
Note
In the first example Arkadiy can put 7 rows of photos with 5 photos in each row, so the minimum value of x equals to 0.5.
In the second example Arkadiy can put only 1 photo which will take the whole wall, so the minimum value of x equals to 0.
In the third example there is no way to put positive number of photos and satisfy the constraints described in the statement, so the answer is -1.
Tags: *special, number theory
Correct Solution:
```
a,h,w=(int(x) for x in input().split())
if h==w:
if a<h:
n=w//a
x=(w-a*n)/(n+1)
print(x)
elif a==h:
print(0)
else:
print(-1)
else:
for i in range(100):
if h>w:
w,h=h,w
if w>h+a*2:
w=w-h-a
if h>w:
w,h=h,w
m=h//a
s=(w-h)//a
r=0
if m<s or s==0:
for i in range(m,0,-1):
x=(h-a*i)/(i+1)
w1=w-x
a1=a+x
q=w1%a1
if q<0.00000001 or a1-q<0.0000001:
r=1
break
if r==0:
print(-1)
else:
print(x)
else:
for i in range(s,0,-1):
x=(w-h-i*a)/i
w1=w-x
a1=a+x
q=w1%a1
if q<0.00000001:
r=1
break
if r==0:
print(-1)
else:
print(x)
```
| 2,142 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Arkadiy has lots square photos with size a Γ a. He wants to put some of them on a rectangular wall with size h Γ w.
The photos which Arkadiy will put on the wall must form a rectangular grid and the distances between neighboring vertically and horizontally photos and also the distances between outside rows and columns of photos to the nearest bound of the wall must be equal to x, where x is some non-negative real number. Look on the picture below for better understanding of the statement.
<image>
Arkadiy haven't chosen yet how many photos he would put on the wall, however, he want to put at least one photo. Your task is to determine the minimum value of x which can be obtained after putting photos, or report that there is no way to put positive number of photos and satisfy all the constraints. Suppose that Arkadiy has enough photos to make any valid arrangement according to the constraints.
Note that Arkadiy wants to put at least one photo on the wall. The photos should not overlap, should completely lie inside the wall bounds and should have sides parallel to the wall sides.
Input
The first line contains three integers a, h and w (1 β€ a, h, w β€ 109) β the size of photos and the height and the width of the wall.
Output
Print one non-negative real number β the minimum value of x which can be obtained after putting the photos on the wall. The absolute or the relative error of the answer must not exceed 10 - 6.
Print -1 if there is no way to put positive number of photos and satisfy the constraints.
Examples
Input
2 18 13
Output
0.5
Input
4 4 4
Output
0
Input
3 4 3
Output
-1
Note
In the first example Arkadiy can put 7 rows of photos with 5 photos in each row, so the minimum value of x equals to 0.5.
In the second example Arkadiy can put only 1 photo which will take the whole wall, so the minimum value of x equals to 0.
In the third example there is no way to put positive number of photos and satisfy the constraints described in the statement, so the answer is -1.
Tags: *special, number theory
Correct Solution:
```
def gcd(a,b):
if(b==0):return a;
else: return gcd(b,a%b);
def main():
a,h,w=map(int,input().split());
x=gcd(a+h,a+w);
y=(a+w)//x;
z=((w//a+1)//y)*y-1;
if(z<=0): print("-1");
else: print("%.10lf"%((1.00*w-z*a)/(z+1)));
main();
```
| 2,143 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Arkadiy has lots square photos with size a Γ a. He wants to put some of them on a rectangular wall with size h Γ w.
The photos which Arkadiy will put on the wall must form a rectangular grid and the distances between neighboring vertically and horizontally photos and also the distances between outside rows and columns of photos to the nearest bound of the wall must be equal to x, where x is some non-negative real number. Look on the picture below for better understanding of the statement.
<image>
Arkadiy haven't chosen yet how many photos he would put on the wall, however, he want to put at least one photo. Your task is to determine the minimum value of x which can be obtained after putting photos, or report that there is no way to put positive number of photos and satisfy all the constraints. Suppose that Arkadiy has enough photos to make any valid arrangement according to the constraints.
Note that Arkadiy wants to put at least one photo on the wall. The photos should not overlap, should completely lie inside the wall bounds and should have sides parallel to the wall sides.
Input
The first line contains three integers a, h and w (1 β€ a, h, w β€ 109) β the size of photos and the height and the width of the wall.
Output
Print one non-negative real number β the minimum value of x which can be obtained after putting the photos on the wall. The absolute or the relative error of the answer must not exceed 10 - 6.
Print -1 if there is no way to put positive number of photos and satisfy the constraints.
Examples
Input
2 18 13
Output
0.5
Input
4 4 4
Output
0
Input
3 4 3
Output
-1
Note
In the first example Arkadiy can put 7 rows of photos with 5 photos in each row, so the minimum value of x equals to 0.5.
In the second example Arkadiy can put only 1 photo which will take the whole wall, so the minimum value of x equals to 0.
In the third example there is no way to put positive number of photos and satisfy the constraints described in the statement, so the answer is -1.
Tags: *special, number theory
Correct Solution:
```
def gcd(n,m):
if m==0:return n
else:return gcd(m,n%m)
a,h,w=map(int,input().split())
g=gcd(a+h,a+w)
s=(a+w)//g
t=((w//a+1)//s)*s-1
if t<=0:print(-1)
else:print("%.10lf"%((w-t*a)/(t+1)))
```
| 2,144 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Arkadiy has lots square photos with size a Γ a. He wants to put some of them on a rectangular wall with size h Γ w.
The photos which Arkadiy will put on the wall must form a rectangular grid and the distances between neighboring vertically and horizontally photos and also the distances between outside rows and columns of photos to the nearest bound of the wall must be equal to x, where x is some non-negative real number. Look on the picture below for better understanding of the statement.
<image>
Arkadiy haven't chosen yet how many photos he would put on the wall, however, he want to put at least one photo. Your task is to determine the minimum value of x which can be obtained after putting photos, or report that there is no way to put positive number of photos and satisfy all the constraints. Suppose that Arkadiy has enough photos to make any valid arrangement according to the constraints.
Note that Arkadiy wants to put at least one photo on the wall. The photos should not overlap, should completely lie inside the wall bounds and should have sides parallel to the wall sides.
Input
The first line contains three integers a, h and w (1 β€ a, h, w β€ 109) β the size of photos and the height and the width of the wall.
Output
Print one non-negative real number β the minimum value of x which can be obtained after putting the photos on the wall. The absolute or the relative error of the answer must not exceed 10 - 6.
Print -1 if there is no way to put positive number of photos and satisfy the constraints.
Examples
Input
2 18 13
Output
0.5
Input
4 4 4
Output
0
Input
3 4 3
Output
-1
Note
In the first example Arkadiy can put 7 rows of photos with 5 photos in each row, so the minimum value of x equals to 0.5.
In the second example Arkadiy can put only 1 photo which will take the whole wall, so the minimum value of x equals to 0.
In the third example there is no way to put positive number of photos and satisfy the constraints described in the statement, so the answer is -1.
Tags: *special, number theory
Correct Solution:
```
def gcd(a,b):
if b==0:return a
else:return gcd(b,a%b)
a,h,w=map(int,input().split())
g=gcd(a+h,a+w)
t=(a+w)//g
q=((w//a+1)//t)*t-1
if q<=0:print(-1)
else:print("%.9lf"%((w-q*a)/(q+1)))
```
| 2,145 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Arkadiy has lots square photos with size a Γ a. He wants to put some of them on a rectangular wall with size h Γ w.
The photos which Arkadiy will put on the wall must form a rectangular grid and the distances between neighboring vertically and horizontally photos and also the distances between outside rows and columns of photos to the nearest bound of the wall must be equal to x, where x is some non-negative real number. Look on the picture below for better understanding of the statement.
<image>
Arkadiy haven't chosen yet how many photos he would put on the wall, however, he want to put at least one photo. Your task is to determine the minimum value of x which can be obtained after putting photos, or report that there is no way to put positive number of photos and satisfy all the constraints. Suppose that Arkadiy has enough photos to make any valid arrangement according to the constraints.
Note that Arkadiy wants to put at least one photo on the wall. The photos should not overlap, should completely lie inside the wall bounds and should have sides parallel to the wall sides.
Input
The first line contains three integers a, h and w (1 β€ a, h, w β€ 109) β the size of photos and the height and the width of the wall.
Output
Print one non-negative real number β the minimum value of x which can be obtained after putting the photos on the wall. The absolute or the relative error of the answer must not exceed 10 - 6.
Print -1 if there is no way to put positive number of photos and satisfy the constraints.
Examples
Input
2 18 13
Output
0.5
Input
4 4 4
Output
0
Input
3 4 3
Output
-1
Note
In the first example Arkadiy can put 7 rows of photos with 5 photos in each row, so the minimum value of x equals to 0.5.
In the second example Arkadiy can put only 1 photo which will take the whole wall, so the minimum value of x equals to 0.
In the third example there is no way to put positive number of photos and satisfy the constraints described in the statement, so the answer is -1.
Submitted Solution:
```
a,h,w=(int(x) for x in input().split())
for i in range(100):
if h>w:
w,h=h,w
if w>h+a*2:
w=w-h-a
if h>w:
w,h=h,w
m=h//a
s=(w-h)//a
r=0
if m<s or s==0:
for i in range(m,0,-1):
x=(h-a*i)/(i+1)
w1=w-x
a1=a+x
q=w1%a1
if q<0.00000001 or a1-q<0.0000001:
r=1
break
if r==0:
print(-1)
else:
print(x)
else:
for i in range(s,0,-1):
x=(w-h-i*a)/i
w1=w-x
a1=a+x
q=w1%a1
if q<0.00000001:
r=1
break
if r==0:
print(-1)
else:
print(x)
```
No
| 2,146 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Arkadiy has lots square photos with size a Γ a. He wants to put some of them on a rectangular wall with size h Γ w.
The photos which Arkadiy will put on the wall must form a rectangular grid and the distances between neighboring vertically and horizontally photos and also the distances between outside rows and columns of photos to the nearest bound of the wall must be equal to x, where x is some non-negative real number. Look on the picture below for better understanding of the statement.
<image>
Arkadiy haven't chosen yet how many photos he would put on the wall, however, he want to put at least one photo. Your task is to determine the minimum value of x which can be obtained after putting photos, or report that there is no way to put positive number of photos and satisfy all the constraints. Suppose that Arkadiy has enough photos to make any valid arrangement according to the constraints.
Note that Arkadiy wants to put at least one photo on the wall. The photos should not overlap, should completely lie inside the wall bounds and should have sides parallel to the wall sides.
Input
The first line contains three integers a, h and w (1 β€ a, h, w β€ 109) β the size of photos and the height and the width of the wall.
Output
Print one non-negative real number β the minimum value of x which can be obtained after putting the photos on the wall. The absolute or the relative error of the answer must not exceed 10 - 6.
Print -1 if there is no way to put positive number of photos and satisfy the constraints.
Examples
Input
2 18 13
Output
0.5
Input
4 4 4
Output
0
Input
3 4 3
Output
-1
Note
In the first example Arkadiy can put 7 rows of photos with 5 photos in each row, so the minimum value of x equals to 0.5.
In the second example Arkadiy can put only 1 photo which will take the whole wall, so the minimum value of x equals to 0.
In the third example there is no way to put positive number of photos and satisfy the constraints described in the statement, so the answer is -1.
Submitted Solution:
```
a,h,w=(int(x) for x in input().split())
for i in range(100):
if h>w:
w,h=h,w
if w>h+a*2:
w=w-h-a
if h>w:
w,h=h,w
m=h//a
s=(w-h)//a
r=0
if m<s or s==0:
for i in range(m,0,-1):
x=(h-a*i)/(i+1)
w1=w-x
a1=a+x
q=w1%a1
if q<0.00000001:
r=1
break
if r==0:
print(-1)
else:
print(x)
else:
for i in range(s,0,-1):
x=(w-h-i*a)/i
w1=w-x
a1=a+x
q=w1%a1
if q<0.00000001:
r=1
break
if r==0:
print(-1)
else:
print(x)
```
No
| 2,147 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Arkady reached the n-th level in Township game, so Masha decided to bake a pie for him! Of course, the pie has a shape of convex n-gon, i.e. a polygon with n vertices.
Arkady decided to cut the pie in two equal in area parts by cutting it by a straight line, so that he can eat one of them and give the other to Masha. There is a difficulty because Arkady has already put a knife at some point of the pie, so he now has to cut the pie by a straight line passing trough this point.
Help Arkady: find a line that passes through the point Arkady has put a knife into and cuts the pie into two parts of equal area, or determine that it's impossible. Your program has to quickly answer many queries with the same pie, but different points in which Arkady puts a knife.
Input
The first line contains two integers n and q (3 β€ n β€ 104, 1 β€ q β€ 105) β the number of vertices in the pie and the number of queries.
n line follow describing the polygon vertices in clockwise order. The i-th of these line contains two integers xi and yi ( - 106 β€ xi, yi β€ 106) β the coordinates of the i-th vertex. It is guaranteed that the polygon is strictly convex, in particular, no three vertices line on the same line.
An empty line follows.
q lines follow describing the query points. The i-th of these lines contain two integers xi and yi ( - 106 β€ xi, yi β€ 106) β the coordinates of the point in which Arkady puts the knife in the i-th query. In is guaranteed that in each query the given point is strictly inside the polygon, in particular, is not on its edges.
Output
For each query print single integer β the polar angle of the line that is the answer for the corresponding query, in radians. The angle should be in the segment [0;Ο], the angles are measured from the direction of OX axis in counter-clockwise order. For example, the polar angle of the OY axis is <image>. If there is no answer in that query, print -1.
If there are several answers, print any of them. Your answer is considered correct if the difference between the areas of the parts divided by the total area of the polygon doesn't exceed 10 - 4 by absolute value. In other words, if a and b are the areas of the parts after the cut, then your answer is correct if and only of <image>.
Examples
Input
3 1
0 0
0 3
3 0
1 1
Output
2.67794504460098710000
Input
5 3
6 5
6 3
5 0
0 0
0 5
5 4
3 3
5 2
Output
0.60228734612690049000
1.27933953226473580000
2.85805511179015910000
Submitted Solution:
```
str1=input()
lst=[]
for i in range(len(str1)):
if i%2 == 0:
lst.append(str1[i])
lst.sort()
print(lst[0],end='')
for i in range(1,len(lst)):
print("+",end='')
print(lst[i],end='')
```
No
| 2,148 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Tags: implementation, strings
Correct Solution:
```
ans = input()
while " ," in ans:
ans = ans.replace(" ,", ",")
ans = ans.replace("...", " ...").replace(",", ", ")
for ps, pv in [(" ", " ")]:
while ps in ans: ans = ans.replace(ps, pv)
for d in "0123456789":
ans = ans.replace(". "+d, "."+d)
print(ans.strip(), end="")
```
| 2,149 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Tags: implementation, strings
Correct Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
from collections import defaultdict
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#-------------------game starts now-----------------------------------------------------
s=input()
l=list()
for i in range(len(s)):
if s[i]==' ':
if s[i-1]!=' ':
l.append(' ')
else:
l.append(s[i])
a=list()
#print(*l,sep='')
num=0
for i in range (len(l)):
if l[i]!=' ':
a.append(l[i])
else:
if l[i-1]!='.' and l[i+1]!='.' and l[i-1]!=',' and l[i+1]!=',':
a.append(' ')
n=len(a)
b=list()
#print(*a,sep='')
b.append(' ')
curr=0
for i in range(n):
if a[i]=='.':
curr+=1
else:
curr=0
if curr==4:
curr=1
if a[i]==',':
b.append(',')
b.append(' ')
elif a[i]=='.':
if curr==1 and b[-1]!=' ':
b.append(' ')
b.append('.')
else:
b.append('.')
else:
b.append(a[i])
j=len(b)
if b[-1]==' ':
j-=1
print(*b[1:j],sep='')
```
| 2,150 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Tags: implementation, strings
Correct Solution:
```
import sys
from itertools import *
from math import *
def solve():
s = input()
# s = input().split(',')
res = ""
i = 0
numberfound = False
spacefound = False
while i < len(s):
if s[i] == ' ':
i+=1
continue
if s[i] == '.':
if len(res) > 0 and res[-1] != ' ': res += ' ...'
else: res += '...'
i += 2
if s[i] == ',':
res += ', '
if s[i].isdigit():
if len(res) > 0 and res[-1].isdigit() and i > 0 and s[i-1] == ' ': res+=' '
if not (spacefound and numberfound): res += s[i]
numberfound = True
i += 1
if res[-1] == ' ': res = res[:len(res) - 1]
print(res)
# for term in s:
if sys.hexversion == 50594544 : sys.stdin = open("test.txt")
solve()
```
| 2,151 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Tags: implementation, strings
Correct Solution:
```
s=input()
while(' ' in s):
s=s.replace(' ',' ')
while(' ,' in s):
s=s.replace(' ,',',')
while('. ' in s):
s=s.replace('. ','.')
s=s.replace(',',', ')
s=s.replace('...',' ...')
if(s[0]==' '):
s=s[1:]
if(s[-1]==' '):
s=s[:len(s)-1]
while(' ' in s):
s=s.replace(' ',' ')
print(s)
```
| 2,152 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Tags: implementation, strings
Correct Solution:
```
import re
s = input().strip()
s = re.sub('(\d)\s+(?=\d)', r'\1x', s)
s = re.sub('\s', '', s)
s = re.sub(',', ', ', s)
s = re.sub('\.\.\.', ' ...', s)
s = re.sub('^\s|\s$', '', s)
s = re.sub('\s\s', ' ', s)
s = re.sub('x', ' ', s)
print(s)
```
| 2,153 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Tags: implementation, strings
Correct Solution:
```
ans = input()
while " ," in ans:
ans = ans.replace(" ,", ",")
ans = ans.replace("...", " ...").replace(",", ", ")
while " " in ans:
ans = ans.replace(" ", " ")
for d in "0123456789": ans = ans.replace(". " + d, "." + d)
print(ans.strip(), end="")
```
| 2,154 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Tags: implementation, strings
Correct Solution:
```
from sys import stdin,stdout
from math import gcd, ceil, sqrt
ii1 = lambda: int(stdin.readline().strip())
is1 = lambda: stdin.readline().strip()
iia = lambda: list(map(int, stdin.readline().strip().split()))
isa = lambda: stdin.readline().strip().split()
mod = 1000000007
s = is1()
res = ""
for j,i in enumerate(s):
if i == ',':
res += ", "
elif i.isdigit():
if s[j - 1] == " " and res[-1].isdigit():
res+=" "
res += i
elif i == ".":
if len(res)>0 and res[-1] != " " and res[-1] != ".":
res += " "
if len(res) >= 3 and res[-1] == "." and res[-2] == '.' and res[-3] == '.':
res+=" "
res += "."
elif i == " ":
if len(res)>0 and res[-1] not in "0123456789 .":
res += " "
print(res.strip())
```
| 2,155 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Tags: implementation, strings
Correct Solution:
```
s=input()
ans=' '.join(s.split())
ans=ans.replace(', ',',')
ans=ans.replace(' ,',',')
ans=ans.replace(',',', ')
ans=ans.replace('... ','...')
ans=ans.replace(' ...','...')
ans=ans.replace('...',' ...')
if ans[0]==' ':
ans=ans[:0]+ans[1:]
if ans[-1]==' ':
ans=ans[:-1]
print(ans)
```
| 2,156 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Submitted Solution:
```
a=input()
b=''
c=0
n=len(a)
d=0
e=0
for i in range(n):
if a[i]=='.':
if c%3==0 and i!=0 and (e==0 or b[-1]!=' '):
b+=' '
e+=1
b+=a[i]
e+=1
c+=1
d=0
elif a[i]==',':
b+=a[i]
e+=1
if i!=n-1:
b+=' '
e+=1
d=0
elif a[i]!=' ':
if d==2:
b+=' '
e+=1
b+=a[i]
e+=1
d=1
else:
if d==1:
d=2
print(b)
```
Yes
| 2,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Submitted Solution:
```
s = input()
res = ''
i = 0
while i < len(s):
if s[i] == ',':
res += ','
if i != len(s)-1:
res += ' '
elif s[i] == '.':
if len(res) != 0:
if res[-1] != ' ':
res += ' '
res += '...'
i += 2
elif s[i].isdigit():
if len(res) != 0:
if s[i-1] == ' ' and res[-1].isdigit():
res += ' '
res += s[i]
i += 1
print(res)
```
Yes
| 2,158 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Submitted Solution:
```
s=input()
u=' '.join(s.split())
u=u.replace(', ',',')
u=u.replace(' ,',',')
u=u.replace(',',', ')
u=u.replace('... ','...')
u=u.replace(' ...','...')
u=u.replace('...',' ...')
if u[0]==' ':
u=u[:0]+u[1:]
if u[-1]==' ':
u=u[:-1]
print(u)
```
Yes
| 2,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Submitted Solution:
```
s = input()
for i in range(255):
s = s.replace(', ', ',')
s = s.replace(' ,', ',')
s = s.replace(' ...', '...')
s = s.replace('... ', '...')
s = s.replace(' ', ' ')
s = s.replace(',.', ', .')
for i in range(255):
s = s.replace(',,', ', ,')
s = s.replace('......', '... ...')
for i in range(10):
s = s.replace(',' + str(i), ', ' + str(i))
s = s.replace(str(i) + '...', str(i) + ' ...')
print(s.strip())
```
Yes
| 2,160 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Submitted Solution:
```
s = input()
s = s.split(" ")
s = [ i for i in s if len(i)]
s = " ".join(s)
s = s.strip()
s = s.split(",")
s = [i.strip() for i in s]
s = ", ".join(s).strip()
s = s.split("...")
s = " ...".join(s)
print(s.strip())
```
No
| 2,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Submitted Solution:
```
s = input()
while ' ' in s:
s = s.replace(' ', ' ')
print(s.replace('...', ' ...').replace(' ,', ',')
.replace(', ', ',').replace(',', ', ').strip())
```
No
| 2,162 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Submitted Solution:
```
v = input()
while " " in v: v = v.replace(" ", " ")
i = -1
ln = len(v)
acc = ""
def next():
global i
i += 1
if i >= ln:
return None
return v[i]
while True:
c = next()
if c == None: break
if c in "0123456789":
if len(acc) > 0 and acc[-1] == ",":
acc += " "
acc += c
if c == " ":
if len(acc) > 0 and acc[-1] != " ":
acc += c
if c == ".":
if len(acc) > 0 and acc[-1] != " ":
acc += " "
next(); next();
acc += "..."
if c == ",":
if len(acc) > 1 and acc[-1] == " " and acc[-2] != ",":
acc = acc[:-1] + ","
else:
if len(acc) > 0 and acc[-1] == ",":
acc += " "
acc += ","
print(acc.strip())
```
No
| 2,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp is very careful. He even types numeric sequences carefully, unlike his classmates. If he sees a sequence without a space after the comma, with two spaces in a row, or when something else does not look neat, he rushes to correct it. For example, number sequence written like "1,2 ,3,..., 10" will be corrected to "1, 2, 3, ..., 10".
In this task you are given a string s, which is composed by a concatination of terms, each of which may be:
* a positive integer of an arbitrary length (leading zeroes are not allowed),
* a "comma" symbol (","),
* a "space" symbol (" "),
* "three dots" ("...", that is, exactly three points written one after another, also known as suspension points).
Polycarp wants to add and remove spaces in the string s to ensure the following:
* each comma is followed by exactly one space (if the comma is the last character in the string, this rule does not apply to it),
* each "three dots" term is preceded by exactly one space (if the dots are at the beginning of the string, this rule does not apply to the term),
* if two consecutive numbers were separated by spaces only (one or more), then exactly one of them should be left,
* there should not be other spaces.
Automate Polycarp's work and write a program that will process the given string s.
Input
The input data contains a single string s. Its length is from 1 to 255 characters. The string s does not begin and end with a space. Its content matches the description given above.
Output
Print the string s after it is processed. Your program's output should be exactly the same as the expected answer. It is permissible to end output line with a line-break character, and without it.
Examples
Input
1,2 ,3,..., 10
Output
1, 2, 3, ..., 10
Input
1,,,4...5......6
Output
1, , , 4 ...5 ... ...6
Input
...,1,2,3,...
Output
..., 1, 2, 3, ...
Submitted Solution:
```
t, s, i, a, v = ' ', input() + ' ', 0, [], ' '
while i < len(s):
if s[i] == ',':
a.append(',')
elif s[i] == '.':
a.append('...')
i += 2
elif s[i].isdigit():
j = i
while s[j].isdigit():
j += 1
a.append(s[i:j])
i = j - 1
i += 1
a.append(' ')
i = 0
while i < len(a):
if a[i] == ',':
v += ', '
elif a[i] == '...':
v += (' ' if v[-1] != ' ' else '') + '...'
elif a[i].isdigit():
if a[i + 1].isdigit():
a.pop(i + 1)
v += (' ' if v[-1].isdigit() else '') + a[i]
i += 1
print(v.strip())
```
No
| 2,164 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The capital of Berland looks like a rectangle of size n Γ m of the square blocks of same size.
Fire!
It is known that k + 1 blocks got caught on fire (k + 1 β€ nΒ·m). Those blocks are centers of ignition. Moreover positions of k of these centers are known and one of these stays unknown. All k + 1 positions are distinct.
The fire goes the following way: during the zero minute of fire only these k + 1 centers of ignition are burning. Every next minute the fire goes to all neighbouring blocks to the one which is burning. You can consider blocks to burn for so long that this time exceeds the time taken in the problem. The neighbouring blocks are those that touch the current block by a side or by a corner.
Berland Fire Deparment wants to estimate the minimal time it takes the fire to lighten up the whole city. Remember that the positions of k blocks (centers of ignition) are known and (k + 1)-th can be positioned in any other block.
Help Berland Fire Department to estimate the minimal time it takes the fire to lighten up the whole city.
Input
The first line contains three integers n, m and k (1 β€ n, m β€ 109, 1 β€ k β€ 500).
Each of the next k lines contain two integers xi and yi (1 β€ xi β€ n, 1 β€ yi β€ m) β coordinates of the i-th center of ignition. It is guaranteed that the locations of all centers of ignition are distinct.
Output
Print the minimal time it takes the fire to lighten up the whole city (in minutes).
Examples
Input
7 7 3
1 2
2 1
5 5
Output
3
Input
10 5 1
3 3
Output
2
Note
In the first example the last block can have coordinates (4, 4).
In the second example the last block can have coordinates (8, 3).
Tags: binary search, data structures
Correct Solution:
```
import sys
from collections import Counter
from operator import itemgetter
from heapq import heappop, heappush
n, m, k = map(int, input().split())
points = [list(map(int, line.split())) for line in sys.stdin]
pts_sorted_x = sorted(points)
pts_sorted_y = sorted(points, key=itemgetter(1, 0))
inf = 10**9+1
OK = (inf, inf)
def solve2(imos, t):
acc, cur = 0, 0
for k in sorted(imos.keys()):
if t < k:
break
if acc <= 0 and cur+1 < k or acc + imos[k] <= 0:
acc = 0
break
acc += imos[k]
return acc <= 0
def add_imos(imos, x, y):
imos[x] += y
if imos[x] == 0:
del imos[x]
def solve(t, px=-1, py=-1):
set_x = {1, n}
set_y = {1, m}
for x, y in points:
set_x.update((max(1, x-t), max(1, x-t-1), min(n, x+t), min(n, x+t+1)))
set_y.update((max(1, y-t), max(1, y-t-1), min(m, y+t), min(m, y+t+1)))
ans_x = ans_y = inf
pi, imos, hq = 0, Counter(), []
if px != -1:
imos[py] += 1
imos[py+t*2+1] -= 1
for cx in sorted(set_x):
while hq and hq[0][0] < cx:
add_imos(imos, hq[0][1], -1)
add_imos(imos, hq[0][2], +1)
heappop(hq)
while pi < k and pts_sorted_x[pi][0]-t <= cx <= pts_sorted_x[pi][0]+t:
x, y = pts_sorted_x[pi]
add_imos(imos, max(1, y-t), 1)
add_imos(imos, y+t+1, -1)
heappush(hq, (x+t, max(1, y-t), y+t+1))
pi += 1
if solve2(imos, m):
ans_x = cx
break
pi = 0
imos.clear()
hq.clear()
if px != -1:
imos[px] += 1
imos[px+t*2+1] -= 1
for cy in sorted(set_y):
while hq and hq[0][0] < cy:
add_imos(imos, hq[0][1], -1)
add_imos(imos, hq[0][2], +1)
heappop(hq)
while pi < k and pts_sorted_y[pi][1]-t <= cy <= pts_sorted_y[pi][1]+t:
x, y = pts_sorted_y[pi]
add_imos(imos, max(1, x-t), 1)
add_imos(imos, x+t+1, -1)
heappush(hq, (y+t, max(1, x-t), x+t+1))
pi += 1
if solve2(imos, n):
ans_y = cy
break
return ans_x, ans_y
ok, ng = 10**9+1, -1
while abs(ok - ng) > 1:
mid = (ok + ng) >> 1
p = solve(mid)
if p == OK:
ok = mid
continue
if solve(mid, p[0], p[1]) == OK:
ok = mid
else:
ng = mid
print(ok)
```
| 2,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The capital of Berland looks like a rectangle of size n Γ m of the square blocks of same size.
Fire!
It is known that k + 1 blocks got caught on fire (k + 1 β€ nΒ·m). Those blocks are centers of ignition. Moreover positions of k of these centers are known and one of these stays unknown. All k + 1 positions are distinct.
The fire goes the following way: during the zero minute of fire only these k + 1 centers of ignition are burning. Every next minute the fire goes to all neighbouring blocks to the one which is burning. You can consider blocks to burn for so long that this time exceeds the time taken in the problem. The neighbouring blocks are those that touch the current block by a side or by a corner.
Berland Fire Deparment wants to estimate the minimal time it takes the fire to lighten up the whole city. Remember that the positions of k blocks (centers of ignition) are known and (k + 1)-th can be positioned in any other block.
Help Berland Fire Department to estimate the minimal time it takes the fire to lighten up the whole city.
Input
The first line contains three integers n, m and k (1 β€ n, m β€ 109, 1 β€ k β€ 500).
Each of the next k lines contain two integers xi and yi (1 β€ xi β€ n, 1 β€ yi β€ m) β coordinates of the i-th center of ignition. It is guaranteed that the locations of all centers of ignition are distinct.
Output
Print the minimal time it takes the fire to lighten up the whole city (in minutes).
Examples
Input
7 7 3
1 2
2 1
5 5
Output
3
Input
10 5 1
3 3
Output
2
Note
In the first example the last block can have coordinates (4, 4).
In the second example the last block can have coordinates (8, 3).
Submitted Solution:
```
import sys
from collections import Counter
n, m, k = map(int, input().split())
pts_x, pts_y = map(
list, zip(*[list(map(int, line.split())) for line in sys.stdin]))
inf = 10**9+1
OK = (inf, inf)
def solve2(set_p, a1, a2, n, m, t):
res = inf
for cpos in set_p:
imos = Counter()
for pos1, pos2 in zip(a1, a2):
if pos1-t <= cpos <= pos1+t:
imos[max(1, pos2-t)] += 1
if pos2+t+1 <= m:
imos[pos2+t+1] -= 1
cur, acc = 0, 0
for k in sorted(imos.keys()):
if acc <= 0 and cur+1 < k or acc + imos[k] <= 0:
acc = 0
break
acc += imos[k]
if acc <= 0:
res = min(res, cpos)
return res
def solve(t):
set_x = set()
set_y = set()
for x, y in zip(pts_x, pts_y):
set_x.update((max(1, x-t), max(1, x-t-1), min(n, x+t), min(n, x+t+1)))
set_y.update((max(1, y-t), max(1, y-t-1), min(m, y+t), min(m, y+t+1)))
ans_x = solve2(set_x, pts_x, pts_y, n, m, t)
ans_y = solve2(set_y, pts_y, pts_x, m, n, t)
return ans_x, ans_y
ok, ng = 10**9+1, -1
while abs(ok - ng) > 1:
mid = (ok + ng) >> 1
p = solve(mid)
if p == OK:
ok = mid
continue
pts_x.append(min(n, p[0]+mid))
pts_y.append(min(m, p[1]+mid))
if solve(mid) == OK:
ok = mid
else:
ng = mid
pts_x.pop()
pts_y.pop()
print(ok)
```
No
| 2,166 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Tags: greedy, implementation, two pointers
Correct Solution:
```
n = int(input())
l = [int(x) for x in input().split()]
max_claw = 0
alive_count = 1
for i in range(n-1, -1, -1):
max_claw = max(max_claw, l[i])
if max_claw == 0 and i > 0:
alive_count += 1
else:
max_claw -= 1
print(alive_count)
```
| 2,167 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Tags: greedy, implementation, two pointers
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
kill = 0
minus = 0
s = []
for i in range(n - 1, -1, -1):
if kill > 0:
kill -= 1;
minus += 1;
kill = max(kill, a[i])
print(n - minus)
```
| 2,168 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Tags: greedy, implementation, two pointers
Correct Solution:
```
if __name__ == "__main__":
n = int(input())
t = list(map(int, input().split()))
a = [0] * n
for i in range(n):
a[max(0, i - t[i])] += 1
a[i] -= 1
res = 0
for i in range(n):
if i > 0:
a[i] += a[i - 1]
if a[i] == 0:
res += 1
print(res)
```
| 2,169 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Tags: greedy, implementation, two pointers
Correct Solution:
```
q=int(input())
a=list(map(int,input().split()))
ans=0
t=q
for i in range(q-1,-1,-1):
if t>i:
ans+=1
t=min(t,i-a[i])
print(ans)
```
| 2,170 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Tags: greedy, implementation, two pointers
Correct Solution:
```
n = int(input())
claws = list(map(int, input().split()))
c = 0
r = n
for claw in reversed(claws):
if c > 0:
r -= 1
c = max(c - 1, claw)
print(r)
```
| 2,171 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Tags: greedy, implementation, two pointers
Correct Solution:
```
#10
#1 1 3 0 0 0 2 1 0 3
n = int(input())
lv = list(map(int,input().strip().split(' ')))
ans = 0
safe = n
i = n
while i > 0:
if i <= safe:
ans += 1
safe = min(safe,i - lv[i-1] - 1)
if safe < 0:
break
i -= 1
print(ans)
```
| 2,172 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Tags: greedy, implementation, two pointers
Correct Solution:
```
#Wrath
n = int(input())
l = list(map(int, input().split()))
i = n - 1
j = n - 1
count = 0
while j >= 0 and i >= 0:
if j >= i:
count += 1
j = i - l[i] - 1
if i - l[i] <= j:
j = i - l[i] - 1
i -= 1
print(count)
```
| 2,173 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Tags: greedy, implementation, two pointers
Correct Solution:
```
n = int(input())
l = list(map(int, input().split()))
left = n - 1
right = n - 1
ans = 0
for i in range(n-1, -1, -1):
right = i
if left == right:
ans += 1
left = min(left, right - l[i] - 1)
print(ans)
```
| 2,174 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Submitted Solution:
```
n = int(input())
l = list(map(int,input().split()))
s = set()
i = len(l)-1
j = len(l)-2
while(i > -1):
while(j > -1 and i > j):
if (j+1) >= ((i+1)-l[i]):
#print(i,j)
s.add(j)
j = j-1
else:
break
if i == j:
j = j-1
else:
i = i-1
print(len(l)-len(s))
```
Yes
| 2,175 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Submitted Solution:
```
def solve(n,seq) :
alive = n
pointer = n-1
alivePointer = n-2
while pointer > 0 and alivePointer >= 0 :
value = (pointer+1) - seq[pointer]
if value <= 0 :
value = 1
value -= 1
if alivePointer == pointer :
alivePointer -= 1
if alivePointer >= value :
diff = alivePointer - value + 1
alivePointer = value - 1
alive -= diff
pointer -= 1
return alive
n = int(input())
seq = list(map(int,input().split()))
print (solve(n,seq))
```
Yes
| 2,176 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Submitted Solution:
```
n = int(input())
L = [int(i) for i in input().split()]
pomoika = 0
l = n
for i in range(n - 1, 0, -1):
nl = max(i - L[i], 0)
if l > nl:
if i < l:
pomoika += i - nl
else:
pomoika += l - nl
l = nl
if l <= 0:
break
print(n - pomoika)
```
Yes
| 2,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Submitted Solution:
```
n = int(input())
a = [i - int(x) + 1 for i, x in enumerate(input().split())]
a.insert(0, 0)
min_a = a[-1]
res = n
for i in range(n - 1, 0, -1):
if i >= min_a:
res -= 1
min_a = min(min_a, a[i])
print(res)
```
Yes
| 2,178 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Submitted Solution:
```
n=int(input())
l=input().split()
count=1
var=0
j=1
while j<n:
if l[n-j]=='0':
count+=1
j+=1
else:
j=j+int(l[n-j])
print(count)
```
No
| 2,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Submitted Solution:
```
n=int(input())
m=list(map(int,input().split()))
c=set()
x=1
for i in range(len(m)):
x-=1
for j in range(1,min(i,m[i]-x)+1):
c.add(i-j)
x=max(x,m[i],1)
print(n-len(c))
```
No
| 2,180 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Submitted Solution:
```
size = int(input())
array = [int(i) for i in input().split()]
check = [0]*size
total = 0
for i in range(size-1,0,-1):
if array[i]:
val = i - array[i] if 0 < i - array[i] else 0
check[val] = 1
pos = size -1
for i in range(size-1,-1,-1):
if check[i]:
total += pos - i
for j in range(i,-1,-1):
if array[j]:
pos = j
break
print(size-total)
```
No
| 2,181 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Hands that shed innocent blood!
There are n guilty people in a line, the i-th of them holds a claw with length Li. The bell rings and every person kills some of people in front of him. All people kill others at the same time. Namely, the i-th person kills the j-th person if and only if j < i and j β₯ i - Li.
You are given lengths of the claws. You need to find the total number of alive people after the bell rings.
Input
The first line contains one integer n (1 β€ n β€ 106) β the number of guilty people.
Second line contains n space-separated integers L1, L2, ..., Ln (0 β€ Li β€ 109), where Li is the length of the i-th person's claw.
Output
Print one integer β the total number of alive people after the bell rings.
Examples
Input
4
0 1 0 10
Output
1
Input
2
0 0
Output
2
Input
10
1 1 3 0 0 0 2 1 0 3
Output
3
Note
In first sample the last person kills everyone in front of him.
Submitted Solution:
```
n=int(input())
claw=[int(x) for x in input().split()]
kill=[0]*n
for i in range(n-2,-1,-1):
kill[i]=claw[i+1]+max(kill[i+1]-1,0)
alive=0
for i in range(n):
if kill[i]<2:
alive+=1
print(alive)
```
No
| 2,182 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Tags: games, greedy, implementation
Correct Solution:
```
from collections import Counter
n = int(input())
c = Counter([int(x) for x in input().split()])
flag = 0
for key in c.keys():
if c[key] % 2 != 0:
flag = 1
break
print("Conan" if flag else "Agasa")
```
| 2,183 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Tags: games, greedy, implementation
Correct Solution:
```
n = int(input())
a = list(map(int,input().split()))
d = dict()
for i in a:
if i in d:
d[i] += 1
else:
d[i] = 1
import collections
nd = collections.OrderedDict(sorted(d.items(), key = lambda t : t[0], reverse = True))
for i in nd:
if nd[i] % 2 == 1:
print('Conan')
break
else:
print('Agasa')
```
| 2,184 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Tags: games, greedy, implementation
Correct Solution:
```
n = int(input())
nums = [int(x) for x in input().split()]
nums.sort()
nums.reverse()
last_num = nums[0]
count = 0
for num in nums:
if num == last_num:
count += 1
else:
if count % 2 == 1:
print('Conan')
break;
else:
last_num = num
count = 1
else:
if count % 2 == 1:
print('Conan')
else:
print('Agasa')
```
| 2,185 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Tags: games, greedy, implementation
Correct Solution:
```
def read():
return list(map(int,input().split()))
n=int(input())
a=read()
b={}
for i in a:
if i in b:
b[i]+=1
else:
b[i]=1
for i in b:
if b[i]%2==1:
print('Conan')
exit()
print('Agasa')
```
| 2,186 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Tags: games, greedy, implementation
Correct Solution:
```
from collections import Counter
n = int(input())
cards = Counter(map(int, input().split()))
for card, amt in cards.items():
if amt % 2:
print('Conan')
break
else:
print('Agasa')
```
| 2,187 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Tags: games, greedy, implementation
Correct Solution:
```
n=int(input())
a=input().split()
for i in range(n):
a[i]=int(a[i])
a.sort()
#print(a)
k=0
h=a[0]
for i in a:
if(i==h):
if(k==1):
k=0
else:
k=1
else:
if(k==1):
p=1
break
k=1
h=i
if(k==1):
print("Conan")
else:
print("Agasa")
```
| 2,188 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Tags: games, greedy, implementation
Correct Solution:
```
from collections import Counter
n = int(input())
print(('Agasa', 'Conan')[1 in [i % 2 for i in Counter(list(map(int, input().split()))).values()]])
```
| 2,189 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Tags: games, greedy, implementation
Correct Solution:
```
from collections import Counter
n = int(input())
a = [int(i) for i in input().strip().split()]
c = Counter(a)
conan = False
a.sort(reverse=True)
for i in set(a):
if c[i] % 2 == 1:
conan = True
break
print("Conan" if conan else "Agasa")
```
| 2,190 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Submitted Solution:
```
n = int(input())
a = sorted(list(map(int, input().split())))
last = a[0]
cnt = 1
x = []
for i in range(1, n):
if a[i] != last:
x.append(cnt)
last = a[i]
cnt = 0
cnt += 1
x.append(cnt)
x = x[::-1]
for i in x:
if i%2==1:
print('Conan')
exit(0)
print('Agasa')
```
Yes
| 2,191 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Submitted Solution:
```
n=int(input())
b=[0]*100001
a=list(map(int,input().split()))
for i in a:
b[i]+=1
for i in b:
if i%2==1:
print('Conan')
exit()
print('Agasa')
```
Yes
| 2,192 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Submitted Solution:
```
n = int(input())
a = [int(i) for i in input().split()]
m = [0] * (10 ** 5 + 2)
for i in a:
m[i] += 1
for i in range(10 ** 5 + 2):
if m[i] % 2 != 0:
print("Conan")
exit()
print("Agasa")
```
Yes
| 2,193 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Submitted Solution:
```
input()
from collections import Counter as c
print('Conan' if [i for i in c(map(int , input().split())).values() if i % 2 ] else 'Agasa')
```
Yes
| 2,194 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Submitted Solution:
```
#import math
#t=int(input())
#for i in range(t):
n=int(input())
#n,k = map(int, input().strip().split(' '))
lst = list(map(int, input().strip().split(' ')))
c=lst.count(max(lst))
if c%2==0:
print('Agasa')
else:
print('Conan')
```
No
| 2,195 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Submitted Solution:
```
n=int(input())
a=input().split()
for i in range(n):
a[i]=int(a[i])
a.sort()
print(a)
k=0
h=a[0]
for i in a:
if(i==h):
if(k==1):
k=0
else:
k=1
else:
if(k==1):
p=1
break
k=1
h=i
if(k==1):
print("Conan")
else:
print("Agasa")
```
No
| 2,196 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Submitted Solution:
```
import sys
import string
from collections import Counter, defaultdict
from math import fsum, sqrt, gcd, ceil, factorial
from operator import add
inf = float('inf')
# input = sys.stdin.readline
flush = lambda : sys.stdout.flush
comb = lambda x , y : (factorial(x) // factorial(y)) // factorial(x - y)
#inputs
# ip = lambda : input().rstrip()
ip = lambda : input()
ii = lambda : int(input())
r = lambda : map(int, input().split())
rr = lambda : list(r())
n = ii()
arr = rr()
m = max(arr)
if arr.count(m) == n:
print(["Conan" , "Agasa"][n%2==0])
else:
print(["Conan" , "Agasa"][arr.count(m)%2==0])
```
No
| 2,197 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Edogawa Conan got tired of solving cases, and invited his friend, Professor Agasa, over. They decided to play a game of cards. Conan has n cards, and the i-th card has a number ai written on it.
They take turns playing, starting with Conan. In each turn, the player chooses a card and removes it. Also, he removes all cards having a number strictly lesser than the number on the chosen card. Formally, if the player chooses the i-th card, he removes that card and removes the j-th card for all j such that aj < ai.
A player loses if he cannot make a move on his turn, that is, he loses if there are no cards left. Predict the outcome of the game, assuming both players play optimally.
Input
The first line contains an integer n (1 β€ n β€ 105) β the number of cards Conan has.
The next line contains n integers a1, a2, ..., an (1 β€ ai β€ 105), where ai is the number on the i-th card.
Output
If Conan wins, print "Conan" (without quotes), otherwise print "Agasa" (without quotes).
Examples
Input
3
4 5 7
Output
Conan
Input
2
1 1
Output
Agasa
Note
In the first example, Conan can just choose the card having number 7 on it and hence remove all the cards. After that, there are no cards left on Agasa's turn.
In the second example, no matter which card Conan chooses, there will be one one card left, which Agasa can choose. After that, there are no cards left when it becomes Conan's turn again.
Submitted Solution:
```
yolo=int(input())
pren=[int(z) for z in input().split()]
max=-99999999999999
k=0
for i in range(yolo):
if max<pren[i]:
max=pren[i]
k=1
elif max==pren[i]:
k+=1
if k%2==1:
print("Conan")
else:
print("Agasa")
```
No
| 2,198 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vitya loves programming and problem solving, but sometimes, to distract himself a little, he plays computer games. Once he found a new interesting game about tanks, and he liked it so much that he went through almost all levels in one day. Remained only the last level, which was too tricky. Then Vitya remembered that he is a programmer, and wrote a program that helped him to pass this difficult level. Try do the same.
The game is organized as follows. There is a long road, two cells wide and n cells long. Some cells have obstacles. You control a tank that occupies one cell. Initially, the tank is located before the start of the road, in a cell with coordinates (0, 1). Your task is to move the tank to the end of the road, to the cell (n + 1, 1) or (n + 1, 2).
<image>
Every second the tank moves one cell to the right: the coordinate x is increased by one. When you press the up or down arrow keys, the tank instantly changes the lane, that is, the y coordinate. When you press the spacebar, the tank shoots, and the nearest obstacle along the lane in which the tank rides is instantly destroyed. In order to load a gun, the tank needs t seconds. Initially, the gun is not loaded, that means, the first shot can be made only after t seconds after the tank starts to move.
If at some point the tank is in the same cell with an obstacle not yet destroyed, it burns out. If you press the arrow exactly at the moment when the tank moves forward, the tank will first move forward, and then change the lane, so it will not be possible to move diagonally.
Your task is to find out whether it is possible to pass the level, and if possible, to find the order of actions the player need to make.
Input
The first line contains four integers n, m1, m2 and t, the length of the field, the number of obstacles in the first lane, the number of obstacles in the second lane and the number of tank steps before reloading, respectively (1 β€ n β€ 109; 0 β€ m1, m2 β€ n; 0 β€ m1 + m2 β€ 106; 1 β€ t β€ n).
The next two lines contain a description of the obstacles. The first of these lines contains m1 numbers xi β the obstacle coordinates in the first lane (1 β€ xi β€ n; xi < xi + 1). The y coordinate for all these obstacles will be 1.
The second line contains m2 numbers describing the obstacles of the second lane in the same format. The y coordinate of all these obstacles will be 2.
Output
In the first line print Β«YesΒ», if it is possible to pass the level, or Β«NoΒ», otherwise.
If it is possible, then in the second line print the number of times the tank moves from one lane to another, and in the next line print the coordinates of the transitions, one number per transition: the coordinate x (0 β€ x β€ n + 1). All transition coordinates coordinates must be distinct and should be output in strictly increasing order.The number of transitions should not exceed 2Β·106. If the tank can pass the level, then it can do it using no more than 2Β·106 transitions.
In the fourth line print the number of shots that the tank makes during the movement, in the following lines print two numbers, x and y coordinates of the point (1 β€ x β€ n, 1 β€ y β€ 2), from which the tank fired a shot, the number of shots must not exceed m1 + m2. Shots must be output in the order in which they are fired.
If there are several solutions, output any one.
Examples
Input
6 2 3 2
2 6
3 5 6
Output
Yes
2
0 3
2
2 2
4 1
Input
1 1 1 1
1
1
Output
No
Input
9 5 2 5
1 2 7 8 9
4 6
Output
Yes
4
0 3 5 10
1
5 2
Note
Picture for the first sample test.
<image>
Submitted Solution:
```
#!/usr/bin/env python
# -*- coding:utf-8 -*-
block1 = []
block2 = []
n, m1, m2, t = map(int, input().split())
block1 = input().split()
block2 = input().split()
for i in range(len(block2)):
block2[i] = int(block2[i])
for i in range(len(block1)):
block1[i] = int(block1[i])
# print(n, m1, m2, t, block1, block2)
# ε»Ίη«εζεΊ
vision = [[],[]]
# setup
for i in range(n):
if i+1 in block2:
vision[1].append(1)
else:
vision[1].append(0)
if i+1 in block1:
vision[0].append(1)
else:
vision[0].append(0)
# print(vision)
fire_ready=False
y=1
x=0
expect=[y,x]
transition=[]
shoots=[]
fire_spot=[]
last_shot=0
failed=False
vision_boundary=t+1
while x!=n:
if vision[y-1][x]==0:
expect=[y,x+1]
x=x+1
elif y==1:
if vision[1][x-1]==0 and vision[1][x]==0:
expect = [y+1 , x]
transition.append(str(x))
y = y + 1
elif vision[1][x-1]==0 and vision[1][x]==1:
if vision[0][x+1]==0 or (vision[0][x+1]==1 and vision[1][x+1]==1):
if x - last_shot >= t:
fire_spot = [y, x]
expect = [y, x + 1]
x = x + 1
shoots.append([y, x - 1])
last_shot = x
else:
failed = True
break
elif vision[0][x+1]==1 and vision[1][x+1]==0:
expect = [y + 1, x]
transition.append(str(x))
y = y + 1
elif vision[y][x-1]==1:
if x-last_shot>=t:
fire_spot = [y, x ]
expect=[y,x+1]
x=x+1
shoots.append([y,x-1])
last_shot=x
else:
failed=True
break
elif y==2:
if vision[0][x-1]==0 and vision[0][x]==0:
expect = [y-1 , x]
transition.append(str(x))
y = y - 1
elif vision[0][x-1]==0 and vision[0][x]==1:
if vision[1][x+1]==0 or (vision[0][x+1]==1 and vision[1][x+1]==1):
if x - last_shot >= t:
fire_spot = [y, x]
expect = [y, x + 1]
x = x + 1
shoots.append([y, x - 1])
last_shot = x
else:
failed = True
break
elif vision[1][x+1]==1 and vision[0][x+1]==0:
expect = [y - 1, x]
transition.append(str(x))
y = y - 1
elif vision[0][x-1]==1:
if x-last_shot>=t:
fire_spot = [y, x ]
expect=[y,x+1]
x=x+1
shoots.append([y,x-1])
last_shot=x
else:
failed=True
break
# while x!=n:
# if y==2:
# if vision[1][x]==1:
# if vision[0][x-1]==0:
# expect=[y-1,x]
# transition.append(x)
# y=y-1
# elif vision[0][x-1]==1:
# if x - last_shot >= t:
# fire_spot = [y, x]
# expect = [y, x + 1]
# x = x + 1
# shoots.append([y, x])
# last_shot = x
# else:
# failed = True
# break
if failed==True:
print("No")
else:
print("Yes")
print(len(transition))
print(" ".join(transition))
print(len(shoots))
for i in shoots:
print(i[1],i[0])
```
No
| 2,199 |
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