text stringlengths 198 433k | conversation_id int64 0 109k |
|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two kittens, Max and Min, play with a pair of non-negative integers x and y. As you can guess from their names, kitten Max loves to maximize and kitten Min loves to minimize. As part of this game Min wants to make sure that both numbers, x and y became negative at the same time, and kitten Max tries to prevent him from doing so.
Each kitten has a set of pairs of integers available to it. Kitten Max has n pairs of non-negative integers (ai, bi) (1 β€ i β€ n), and kitten Min has m pairs of non-negative integers (cj, dj) (1 β€ j β€ m). As kitten Max makes a move, it can take any available pair (ai, bi) and add ai to x and bi to y, and kitten Min can take any available pair (cj, dj) and subtract cj from x and dj from y. Each kitten can use each pair multiple times during distinct moves.
Max moves first. Kitten Min is winning if at some moment both numbers a, b are negative simultaneously. Otherwise, the winner of the game is kitten Max. Determine which kitten wins if both of them play optimally.
Input
The first line contains two integers, n and m (1 β€ n, m β€ 100 000) β the number of pairs of numbers available to Max and Min, correspondingly.
The second line contains two integers x, y (1 β€ x, y β€ 109) β the initial values of numbers with which the kittens are playing.
Next n lines contain the pairs of numbers ai, bi (1 β€ ai, bi β€ 109) β the pairs available to Max.
The last m lines contain pairs of numbers cj, dj (1 β€ cj, dj β€ 109) β the pairs available to Min.
Output
Print Β«MaxΒ» (without the quotes), if kitten Max wins, or "Min" (without the quotes), if kitten Min wins.
Examples
Input
2 2
42 43
2 3
3 2
3 10
10 3
Output
Min
Input
1 1
1 1
3 4
1 1
Output
Max
Note
In the first test from the statement Min can respond to move (2, 3) by move (3, 10), and to move (3, 2) by move (10, 3). Thus, for each pair of Max and Min's moves the values of both numbers x and y will strictly decrease, ergo, Min will win sooner or later.
In the second sample test after each pair of Max and Min's moves both numbers x and y only increase, thus none of them will become negative.
Submitted Solution:
```
import sys
import math
input = sys.stdin.readline
n, m = map(int, input().split())
p, q = map(int, input().split())
first = []
for i in range(n):
x, y = map(int, input().split())
first.append((x, y))
maxX, maxY, maxSum = 0, 0, 0
for i in range(m):
x, y = map(int, input().split())
maxX = max(maxX, x)
maxY = max(maxY, y)
maxSum = max(maxSum, x + y)
for i in first:
if i[0] >= maxX or i[1] >= maxY or i[0] + i[1] >= maxSum:
print('Max')
exit(0)
print('Min')
```
No
| 4,600 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two kittens, Max and Min, play with a pair of non-negative integers x and y. As you can guess from their names, kitten Max loves to maximize and kitten Min loves to minimize. As part of this game Min wants to make sure that both numbers, x and y became negative at the same time, and kitten Max tries to prevent him from doing so.
Each kitten has a set of pairs of integers available to it. Kitten Max has n pairs of non-negative integers (ai, bi) (1 β€ i β€ n), and kitten Min has m pairs of non-negative integers (cj, dj) (1 β€ j β€ m). As kitten Max makes a move, it can take any available pair (ai, bi) and add ai to x and bi to y, and kitten Min can take any available pair (cj, dj) and subtract cj from x and dj from y. Each kitten can use each pair multiple times during distinct moves.
Max moves first. Kitten Min is winning if at some moment both numbers a, b are negative simultaneously. Otherwise, the winner of the game is kitten Max. Determine which kitten wins if both of them play optimally.
Input
The first line contains two integers, n and m (1 β€ n, m β€ 100 000) β the number of pairs of numbers available to Max and Min, correspondingly.
The second line contains two integers x, y (1 β€ x, y β€ 109) β the initial values of numbers with which the kittens are playing.
Next n lines contain the pairs of numbers ai, bi (1 β€ ai, bi β€ 109) β the pairs available to Max.
The last m lines contain pairs of numbers cj, dj (1 β€ cj, dj β€ 109) β the pairs available to Min.
Output
Print Β«MaxΒ» (without the quotes), if kitten Max wins, or "Min" (without the quotes), if kitten Min wins.
Examples
Input
2 2
42 43
2 3
3 2
3 10
10 3
Output
Min
Input
1 1
1 1
3 4
1 1
Output
Max
Note
In the first test from the statement Min can respond to move (2, 3) by move (3, 10), and to move (3, 2) by move (10, 3). Thus, for each pair of Max and Min's moves the values of both numbers x and y will strictly decrease, ergo, Min will win sooner or later.
In the second sample test after each pair of Max and Min's moves both numbers x and y only increase, thus none of them will become negative.
Submitted Solution:
```
n,m=map(int,input().split())
x,y=map(int,input().split())
ma=mi=0
for i in range(n): ma=max(ma,max(map(int,input().split())))
for i in range(m): mi=max(mi,max(map(int,input().split())))
print('Min' if mi>ma else 'Max')
```
No
| 4,601 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two kittens, Max and Min, play with a pair of non-negative integers x and y. As you can guess from their names, kitten Max loves to maximize and kitten Min loves to minimize. As part of this game Min wants to make sure that both numbers, x and y became negative at the same time, and kitten Max tries to prevent him from doing so.
Each kitten has a set of pairs of integers available to it. Kitten Max has n pairs of non-negative integers (ai, bi) (1 β€ i β€ n), and kitten Min has m pairs of non-negative integers (cj, dj) (1 β€ j β€ m). As kitten Max makes a move, it can take any available pair (ai, bi) and add ai to x and bi to y, and kitten Min can take any available pair (cj, dj) and subtract cj from x and dj from y. Each kitten can use each pair multiple times during distinct moves.
Max moves first. Kitten Min is winning if at some moment both numbers a, b are negative simultaneously. Otherwise, the winner of the game is kitten Max. Determine which kitten wins if both of them play optimally.
Input
The first line contains two integers, n and m (1 β€ n, m β€ 100 000) β the number of pairs of numbers available to Max and Min, correspondingly.
The second line contains two integers x, y (1 β€ x, y β€ 109) β the initial values of numbers with which the kittens are playing.
Next n lines contain the pairs of numbers ai, bi (1 β€ ai, bi β€ 109) β the pairs available to Max.
The last m lines contain pairs of numbers cj, dj (1 β€ cj, dj β€ 109) β the pairs available to Min.
Output
Print Β«MaxΒ» (without the quotes), if kitten Max wins, or "Min" (without the quotes), if kitten Min wins.
Examples
Input
2 2
42 43
2 3
3 2
3 10
10 3
Output
Min
Input
1 1
1 1
3 4
1 1
Output
Max
Note
In the first test from the statement Min can respond to move (2, 3) by move (3, 10), and to move (3, 2) by move (10, 3). Thus, for each pair of Max and Min's moves the values of both numbers x and y will strictly decrease, ergo, Min will win sooner or later.
In the second sample test after each pair of Max and Min's moves both numbers x and y only increase, thus none of them will become negative.
Submitted Solution:
```
n,m=map(int,input().split())
x,y=map(int,input().split())
ma1=ma2=mi1=mi2=0
for i in range(n):
a,b=map(int,input().split())
ma1=max(ma1,a)
ma2=max(ma2,b)
for i in range(m):
a,b=map(int,input().split())
mi1=max(mi1,a)
mi2=max(mi2,b)
print('Min' if mi1>ma1 or mi2>ma2 else 'Max')
```
No
| 4,602 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Tags: math
Correct Solution:
```
from math import ceil
n = int(input())
n1 = n
p = 1
mas = set()
for i in range(2, ceil(n**.5) + 1):
cnt = 0
while n % i == 0:
n = n//i
mas.add(i)
p *= i
mas.add(n1 // p)
p = 1
for i in mas:
p *= i
print(p)
```
| 4,603 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Tags: math
Correct Solution:
```
from math import *
n = int(input())
for i in range(2,10**6):
while n%(i*i)==0 :
n//=(i)
print(n)
```
| 4,604 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Tags: math
Correct Solution:
```
import math
n = int(input())
m = n
m = math.sqrt(m)
m = math.floor(m)
i = 2
x = 1
while i<=m:
if (n % i*i)==0:
while (n % i)==0:
n = n//i
n = n*i
m = n
m = math.sqrt(m)
m = math.floor(m)
i = i+1
print(n)
```
| 4,605 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Tags: math
Correct Solution:
```
import math
n = int(input())
def factors(n):
return set(x for tup in ([i, n//i] for i in range(1, int(n**0.5)+1) if n % i == 0) for x in tup)
for factor in sorted(factors(n), reverse=True):
failed = False
for f in factors(factor):
if f != 1 and f == int(math.sqrt(f))**2:
failed = True
break
if not failed:
print(factor)
break
```
| 4,606 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Tags: math
Correct Solution:
```
from copy import copy
n = int(input())
factors = set()
new = copy(n)
for i in range(2, int(n**(1/2))+1):
#print(i)
while new % i == 0:
factors.add(i)
new //= i
if new != 1:
factors.add(new)
ans = 1
for i in factors:
ans *= i
print(ans)
```
| 4,607 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Tags: math
Correct Solution:
```
import sys
#sys.stdin = open("input.txt")
#sys.stdout = open("output.txt", "w")
n = int(input())
di = [1]
i = 2
while n > 1:
if i*i > n:
break
if n % i == 0:
di += [i]
while n % i == 0 and n > 1:
n //= i
i += 1
if n != 1:
di += [n]
ans = 1
for item in di:
ans *= item
print(ans)
```
| 4,608 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Tags: math
Correct Solution:
```
import math
n=int(input())
y=0
if n==1:
print(1)
exit(0)
while (n**(0.5))%1==0:
n=int(n**(0.5))
#print(n)
for i in range(2,10**6+1):
x=math.log(n,i)
#print(x)
if n%i==0 :
j=int(x)+1
while(j>=2):
if n%(i**j)==0:
y+=1
#print(y)
j-=1
n/=(i**(y))
y=0
print(int(n))
```
| 4,609 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Tags: math
Correct Solution:
```
# Python program to print prime factors
import math
from collections import Counter
# A function to print all prime factors of
# a given number n
def primeFactors(n):
primes = Counter()
# Print the number of two's that divide n
while n % 2 == 0:
primes[2] += 1
n = n / 2
# n must be odd at this point
# so a skip of 2 ( i = i + 2) can be used
for i in range(3,int(math.sqrt(n))+1,2):
# while i divides n , print i ad divide n
while n % i== 0:
primes[i] += 1
n = n / i
# Condition if n is a prime
# number greater than 2
if n > 2:
primes[int(n)] += 1
return primes
# Driver Program to test above function
n = int(input())
c = primeFactors(n)
total = 1
for n in c.keys():
total *= n
print(total)
# This code is contributed by Harshit Agrawal
```
| 4,610 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Submitted Solution:
```
n = int(input())
i=2
while i*i <= n:
while n%(i*i)==0:
n=n//i
i+=1
print(n)
```
Yes
| 4,611 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Submitted Solution:
```
import math
n=int(input())
squareFreePart=1
while(n>1):
nothingFound=True
for p in range(2,int(math.sqrt(n))+1):
if(n%p==0):
nothingFound=False
while(n%p==0):
n=n//p
squareFreePart*=p
break
if (nothingFound):
squareFreePart*=n
break
print(squareFreePart)
```
Yes
| 4,612 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Submitted Solution:
```
n = int(input())
i = 2
resposta = 1
while i * i <= n:
if n % i == 0:
resposta *= i
while n % i == 0:
n //= i
i += 1
if n > 1:
resposta *= n
print(resposta)
```
Yes
| 4,613 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Submitted Solution:
```
n = int(input())
ans = 1
i = 2
while i * i <= n:
if n % i == 0:
while n % i == 0:
n //= i
ans *= i
i += 1
if n > 1:
ans *= n
print(ans)
```
Yes
| 4,614 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Submitted Solution:
```
import math
n=int(input())
y=0
if n==1:
print(1)
exit(0)
while (n**(0.5))%1==0:
n=int(n**(0.5))
#print(n)
for i in range(2,int(n**0.5)+1):
x=math.log(n,i)
if n%i==0 :
for j in range(2,int(x+1)):
if n%(i**j)==0:
y+=1
#print(y)
n/=(i**(y))
y=0
print(int(n))
```
No
| 4,615 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Submitted Solution:
```
n = int(input())
d = n
s = 2
result=True
while d!=1:
if n%d==0:
result = True
s=2
while s**2<d:
if (d%(s**2)==0):
result=False
break
else:
s += 1
#if s**2>d:
#result=True
if result:
break
d -= 1
print(d)
```
No
| 4,616 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Submitted Solution:
```
from math import sqrt
n = int(input())
for i in range(2, int(sqrt(n))+1):
if n%(i**2)==0:
print(int(n/(i**2)))
exit()
print(n)
```
No
| 4,617 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Duff is in love with lovely numbers! A positive integer x is called lovely if and only if there is no such positive integer a > 1 such that a2 is a divisor of x.
<image>
Malek has a number store! In his store, he has only divisors of positive integer n (and he has all of them). As a birthday present, Malek wants to give her a lovely number from his store. He wants this number to be as big as possible.
Malek always had issues in math, so he asked for your help. Please tell him what is the biggest lovely number in his store.
Input
The first and only line of input contains one integer, n (1 β€ n β€ 1012).
Output
Print the answer in one line.
Examples
Input
10
Output
10
Input
12
Output
6
Note
In first sample case, there are numbers 1, 2, 5 and 10 in the shop. 10 isn't divisible by any perfect square, so 10 is lovely.
In second sample case, there are numbers 1, 2, 3, 4, 6 and 12 in the shop. 12 is divisible by 4 = 22, so 12 is not lovely, while 6 is indeed lovely.
Submitted Solution:
```
def getDivisors(number):
div = set()
for i in range(1, (number // 2) + 1):
if(number % i == 0):
div.add(i)
div.add(number // i)
div = list(div)
div.sort(reverse = True)
return div
def isLovely(number):
divisors = getDivisors(number)
for i in range(len(divisors)):
j = 2
while(pow(j, 2) <= number):
if((pow(j,2)) in divisors):
return False
j += 1
return True
number = int(input())
divisors = getDivisors(number)
for i in range(len(divisors)):
divisor = divisors[i]
if(isLovely(divisor)):
print(divisor)
break
```
No
| 4,618 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Tags: combinatorics, math
Correct Solution:
```
n=int(input())
print(6*(4**(n-3) * 4) + (n-3)*9*4**(n-3))
```
| 4,619 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Tags: combinatorics, math
Correct Solution:
```
a=int(input())
print(4**(a-3)*3*(3*a-1))
```
| 4,620 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Tags: combinatorics, math
Correct Solution:
```
n = int(input())
N = 2*n-2
ans = 0;
for i in range(n):
l_cnt = i
r_cnt = N - i - n
if r_cnt < 0: break
m = 4
p = int(l_cnt > 0) + int(r_cnt > 0)
m *= 3 ** p
l_cnt = max(0, l_cnt - 1)
r_cnt = max(0, r_cnt - 1)
p = l_cnt + r_cnt;
m *= 4 ** p;
ans += m
print(ans)
```
| 4,621 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Tags: combinatorics, math
Correct Solution:
```
# ΠΡΠΈΠ½ΠΈΠΌΠ°Π΅ΠΌ Π²Ρ
ΠΎΠ΄Π½ΡΠ΅ Π΄Π°Π½Π½ΡΠ΅
n = int(input())
# ΠΡΡΠΈΡΠ»ΡΠ΅ΠΌ ΠΎΡΠ²Π΅Ρ
ways_count = max(((n - 3) * 36 * 4**(n - 4)), (n - 3) * 36) # ΠΠΎΠ³Π΄Π° ΠΌΠ°ΡΠΈΠ½Ρ ΡΡΠΎΡΡ Π½Π΅ ΠΏΠΎ ΠΊΡΠ°ΡΠΌ
ways_count += 2 * (3 * 4**(n-3)) * 4 # ΠΠΎΠ³Π΄Π° ΠΌΠ°ΡΠΈΠ½Ρ ΡΡΠΎΡΡ ΠΏΠΎ ΠΊΡΠ°ΡΠΌ
# ΠΡΠ²ΠΎΠ΄ΠΈΠΌ ΡΠ΅Π·ΡΠ»ΡΡΠ°Ρ
print(int(ways_count))
```
| 4,622 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Tags: combinatorics, math
Correct Solution:
```
n = int(input())
print(int(4*(n-3)*9*4**(n-4) + 2*4*3*4**(n-3)))
```
| 4,623 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Tags: combinatorics, math
Correct Solution:
```
n = int(input())
print(6 * 4**(n-2) + 9 * (n-3) * 4**(n-3))
```
| 4,624 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Tags: combinatorics, math
Correct Solution:
```
n = int(input())
res = 0
res += 8 * (3 * pow(4, n - 3))
res += ((n - 3) * 4 * 9 * int(pow(4, n - 4)))
print(res)
```
| 4,625 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Tags: combinatorics, math
Correct Solution:
```
import sys,math
inputs = iter(sys.stdin.readlines())
n = int(next(inputs))
print(int(2*4*3*pow(4,n-3) + (n-3)*4*3**2*pow(4,n-4)))
```
| 4,626 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Submitted Solution:
```
ans = 0
n = int(input())
for i in range(1,n):
p = 2*n-2-i-n+1
q = i-1
if p >= 1:
p = 3 * (4**(p-1))
else:
p = 1
if q >= 1:
q = 3 * (4**(q-1))
else:
q = 1
ans += 4*p*q
print(ans)
```
Yes
| 4,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Submitted Solution:
```
n=int(input());print(int(2*4*3*pow(4,n-3)+(n-3)*4*3*3*pow(4,n-4)))
```
Yes
| 4,628 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Submitted Solution:
```
n=int(input())
n=n-3
print(3*4**n*(8+3*n))
```
Yes
| 4,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Submitted Solution:
```
n=int(input())
if n == 3:
print(24)
else:
print((2*3*4**(n-3)*4) + ((n-3)*9*4**(n-4)*4))
```
Yes
| 4,630 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Submitted Solution:
```
n = int(input())
print((n - 3) * (2 * n - 3) ** 2 * (2 * n - 2) ** (n - 3) + 2 * (2 * n - 3) * (2 * n - 2) ** (n - 2))
```
No
| 4,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Submitted Solution:
```
#with recursion
def binpow(a,n,m):
if n==0:
return(1)
x = binpow(a,n//2,m)
x=(x*x)%m
if (n%2==1):
x = (x*a)%m
return(x)
#without recursion
def binpow1(a,n,m):
r = 1
while(n>0):
if (n&1):
r = (r*a)%m
a = (a*a)%m
n=n>>1
return(r)
n = int(input())
ans = 0
if n>3:
ans += 36*pow(4,n-4)
ans += 24*pow(4,n-3)
print(ans)
```
No
| 4,632 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Submitted Solution:
```
n=int(input())
print(3*(3*(n-1))*pow(2,2*n-6))
```
No
| 4,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
To quickly hire highly skilled specialists one of the new IT City companies made an unprecedented move. Every employee was granted a car, and an employee can choose one of four different car makes.
The parking lot before the office consists of one line of (2n - 2) parking spaces. Unfortunately the total number of cars is greater than the parking lot capacity. Furthermore even amount of cars of each make is greater than the amount of parking spaces! That's why there are no free spaces on the parking lot ever.
Looking on the straight line of cars the company CEO thought that parking lot would be more beautiful if it contained exactly n successive cars of the same make. Help the CEO determine the number of ways to fill the parking lot this way.
Input
The only line of the input contains one integer n (3 β€ n β€ 30) β the amount of successive cars of the same make.
Output
Output one integer β the number of ways to fill the parking lot by cars of four makes using the described way.
Examples
Input
3
Output
24
Note
Let's denote car makes in the following way: A β Aston Martin, B β Bentley, M β Mercedes-Maybach, Z β Zaporozhets. For n = 3 there are the following appropriate ways to fill the parking lot: AAAB AAAM AAAZ ABBB AMMM AZZZ BBBA BBBM BBBZ BAAA BMMM BZZZ MMMA MMMB MMMZ MAAA MBBB MZZZ ZZZA ZZZB ZZZM ZAAA ZBBB ZMMM
Originally it was planned to grant sport cars of Ferrari, Lamborghini, Maserati and Bugatti makes but this idea was renounced because it is impossible to drive these cars having small road clearance on the worn-down roads of IT City.
Submitted Solution:
```
n = int(input().strip())
r = 24 * 4 ** (n - 3)
if r > 3:
r += (n - 3) * 36 * 4 ** (n - 4)
print(r)
```
No
| 4,634 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Tags: implementation, math
Correct Solution:
```
s = input()
c = s.split(" ")
n = int(c[0])
r = int(c[1])
s = int(c[2])
print((r-1+s) % n + 1)
```
| 4,635 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Tags: implementation, math
Correct Solution:
```
# -*- coding: utf-8 -*-
import math
import collections
import bisect
import heapq
import time
import random
import itertools
import sys
"""
created by shhuan at 2017/11/24 13:57
"""
n, a, b = map(int, input().split())
ans = (a + b - 1 + n * abs(b)) % n + 1
print(ans)
```
| 4,636 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Tags: implementation, math
Correct Solution:
```
n,a,r=list(map(int,input().split()))
if r>0:
for x in range(5555555):
if r!=0:
if a!=n:
a+=1
r-=1
else:
a=1
r-=1
else:
break
print(a)
else:
for x in range(5555555):
if r!=0:
if a!=1:
a-=1
r+=1
else:
a=n
r+=1
else:
break
print(a)
```
| 4,637 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Tags: implementation, math
Correct Solution:
```
n,a,b = map(int,input().split())
print(n if (a+b)%n==0 else (a+b)%n)
```
| 4,638 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Tags: implementation, math
Correct Solution:
```
n,x,y=map(int,input().split(' '))
if((x+y)%n ==0 ):
print(n)
else:
print ((x+y)%n)
```
| 4,639 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Tags: implementation, math
Correct Solution:
```
n,a,b=map(int,input().split())
if b>=0:
x=a+b
else:
x=n+(a+b)
print(n if x%n==0 else x%n)
```
| 4,640 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Tags: implementation, math
Correct Solution:
```
num_entrances, start, movement = map(int, input().split())
end = (start + movement) % num_entrances
if end < 1:
end = num_entrances - end
print(end)
```
| 4,641 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Tags: implementation, math
Correct Solution:
```
# Description of the problem can be found at http://codeforces.com/problemset/problem/659/A
n, a, b = map(int, input().split())
b %= n
print(((a + b) % n) if (a + b) % n != 0 else n)
```
| 4,642 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Submitted Solution:
```
a, b, c = map(int, input().split(' '))
print((((b - 1 + c) % a) + a) % a + 1)
```
Yes
| 4,643 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Submitted Solution:
```
n,a,b=map(int,input().split())
print(((a+b)%n+n-1)%n+1)
```
Yes
| 4,644 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Submitted Solution:
```
n,a,b=(int(z) for z in input().split())
if b>=0:
for i in range(b):
a+=1
a%=n
if b<0:
for i in range(-b):
a-=1
a%=n
if a==0:
a=n
print(a)
```
Yes
| 4,645 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Submitted Solution:
```
n,a,b=list(map(int,input().split()))
print((a+b)%n if (a+b)%n !=0 else n)
```
Yes
| 4,646 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Submitted Solution:
```
n,a,b = map(int,input().split())
if b < 0:
if (abs(a-b))%n == 0:
print(n)
else:print((abs(a+b))%n)
else:
if (a+b)%n == 0:
print(n)
else:print((a+b)%n)
```
No
| 4,647 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Submitted Solution:
```
n,a,b=map(int,input().split())
aa=abs(a+(abs(b)%n)*[1,-1][b<0])
print([aa,n][aa==0])
```
No
| 4,648 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Submitted Solution:
```
n, a, b = [int(x) for x in input().strip().split(" ")]
if a == n:
print(a)
elif b==0:
print(a)
elif b<0:
n_ = abs(b)+a
if n_ > n:
n_-=n
print(a+n_)
elif b>0:
while b>n:
b-=n
print(a+b)
```
No
| 4,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to n. Entrance n and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance a and he decided that during his walk he will move around the house b entrances in the direction of increasing numbers (in this order entrance n should be followed by entrance 1). The negative value of b corresponds to moving |b| entrances in the order of decreasing numbers (in this order entrance 1 is followed by entrance n). If b = 0, then Vasya prefers to walk beside his entrance.
<image> Illustration for n = 6, a = 2, b = - 5.
Help Vasya to determine the number of the entrance, near which he will be at the end of his walk.
Input
The single line of the input contains three space-separated integers n, a and b (1 β€ n β€ 100, 1 β€ a β€ n, - 100 β€ b β€ 100) β the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively.
Output
Print a single integer k (1 β€ k β€ n) β the number of the entrance where Vasya will be at the end of his walk.
Examples
Input
6 2 -5
Output
3
Input
5 1 3
Output
4
Input
3 2 7
Output
3
Note
The first example is illustrated by the picture in the statements.
Submitted Solution:
```
def solved(n,a,b):
if b < 0:
return a + n + b
elif b > 0:
if n > b:
return a + b
elif n < b:
return a + (b%n)
else:
return a
if __name__ == '__main__':
n,a,b = map(int,input().split())
print(solved(n,a,b))
```
No
| 4,650 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Tags: constructive algorithms, data structures, greedy
Correct Solution:
```
from heapq import heappush, heappop
from sys import stdin
heap = []
L = []
n, *l = stdin.read().splitlines()
for string in l:
array = string.split()
if array[0] == 'insert':
heappush(heap, int(array[1]))
elif array[0] == 'getMin':
key = int(array[1])
while heap and heap[0] < key:
heappop(heap)
L.append('removeMin')
if not heap or heap[0] > key:
heappush(heap, key)
L.append('insert ' + str(key))
else:
if heap:
heappop(heap)
else:
L.append('insert 0')
L.append(string)
print(len(L))
print('\n'.join(L))
```
| 4,651 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Tags: constructive algorithms, data structures, greedy
Correct Solution:
```
from heapq import *
numLines = int(input())
heap = []
output_ops = []
for _ in range(numLines):
opString = input()
operation = opString.split()
if operation[0] == "insert":
heappush(heap, int(operation[1]))
if operation[0] == "removeMin":
if not heap:
heappush(heap, 1)
output_ops.append("insert 1")
heappop(heap)
elif operation[0] == "getMin":
currMin = int(operation[1])
while heap and heap[0] < currMin:
heappop(heap)
output_ops.append("removeMin")
if not heap or heap[0] > currMin:
heappush(heap, currMin)
output_ops.append("insert " + str(currMin))
output_ops.append(opString)
print(len(output_ops))
for op in output_ops:
print(op)
```
| 4,652 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Tags: constructive algorithms, data structures, greedy
Correct Solution:
```
import heapq
n = int(input())
m = n
operations = []
heap = []
for i in range(n):
s = input()
a = s.split()
if a[0] == 'insert':
heapq.heappush(heap, int(a[1]))
elif a[0] == 'removeMin':
if heap:
heapq.heappop(heap)
else:
m += 1
operations.append('insert 1')
elif a[0] == 'getMin':
b = int(a[1])
while heap:
if heap[0] < b:
operations.append('removeMin')
m += 1
heapq.heappop(heap)
else:
break
else:
operations.append('insert {}'.format(b))
m += 1
heapq.heappush(heap, b)
if heap[0] > b:
operations.append('insert {}'.format(b))
m += 1
heapq.heappush(heap, b)
operations.append(s)
print(m)
print('\n'.join(operations))
```
| 4,653 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Tags: constructive algorithms, data structures, greedy
Correct Solution:
```
import heapq
m = int(input())
heap = []
ans = []
for i in range(m):
a = input()
if a == 'removeMin':
if heap == []:
heapq.heappush(heap, 1)
heapq.heappop(heap)
ans.append('insert 1')
ans.append('removeMin')
else:
heapq.heappop(heap)
ans.append('removeMin')
else:
a, x = a.split()
x = int(x)
if a == 'insert':
heapq.heappush(heap, x)
ans.append('insert ' + str(x))
else:
while len(heap) > 0 and heap[0] < x:
heapq.heappop(heap)
ans.append('removeMin')
if len(heap) > 0 and heap[0] == x:
ans.append('getMin ' + str(x))
else:
heapq.heappush(heap, x)
ans.append('insert ' + str(x))
ans.append('getMin ' + str(x))
print(len(ans))
print('\n'.join(ans))
```
| 4,654 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Tags: constructive algorithms, data structures, greedy
Correct Solution:
```
import heapq
n = int(input())
commands = []
arr = []
for i in range(n):
s = input()
tmp = s.split(' ')
if tmp[0] == "insert":
heapq.heappush(arr, int(tmp[1]))
elif tmp[0] == "removeMin":
if not len(arr):
commands.append("insert 1")
else:
heapq.heappop(arr)
else:
x = int(tmp[1])
while len(arr) and arr[0] < x:
commands.append("removeMin")
heapq.heappop(arr)
if not len(arr) or arr[0] != x:
commands.append("insert " + tmp[1])
heapq.heappush(arr, x)
commands.append(s)
print(len(commands))
print('\n'.join(commands))
```
| 4,655 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Tags: constructive algorithms, data structures, greedy
Correct Solution:
```
from sys import stdin
from bisect import bisect_left
n = int(stdin.readline())
heap = []
res = []
for i in range(n):
string = stdin.readline()
oper = string.split()
if oper[0][0] == 'i':
key = int(oper[1])
pos = bisect_left(heap, key)
heap[pos:pos] = [key]
elif oper[0][0] == 'g':
key = int(oper[1])
num = bisect_left(heap, key)
heap[:num] = []
res.extend(['removeMin\n'] * num)
if not heap or heap[0] != key:
heap[0:0] = [key]
res.append('insert ' + oper[1] + '\n')
else:
if heap:
heap[:1] = []
else:
res.append('insert 0\n')
res.append(string)
print(len(res))
print(''.join(res), end='')
```
| 4,656 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Tags: constructive algorithms, data structures, greedy
Correct Solution:
```
import heapq
def inp(n):
L = []
for i in range(n):
s = str(input())
s1 = s.split()
if len(s1) == 2:
L.append([s1[0],int(s1[1])])
else:
L.append(s1)
return L
n = int(input())
L = inp(n)
S = []
H = []
heapq.heapify(H)
for j in L:
if j[0] == 'insert':
heapq.heappush(H,j[1])
S.append('insert' +' '+ str(j[1]))
elif j[0] == 'removeMin':
if len(H) == 0:
S.append('insert' +' '+ str(0))
S.append('removeMin')
else:
heapq.heappop(H)
S.append('removeMin')
else:
k = j[1]
if len(H) == 0:
heapq.heappush(H,k)
S.append('insert' +' '+ str(k))
S.append('getMin' +' '+ str(k))
elif k == H[0]:
S.append('getMin' +' '+ str(H[0]))
else:
if k<H[0]:
heapq.heappush(H,k)
S.append('insert' +' '+ str(k))
S.append('getMin' +' '+ str(k))
else:
while len(H) != 0 and k>H[0]:
heapq.heappop(H)
S.append('removeMin')
if len(H) == 0 or H[0] != k:
heapq.heappush(H,k)
S.append('insert' +' '+ str(k))
S.append('getMin' +' '+ str(k))
else:
S.append('getMin' +' '+ str(H[0]))
print(str(len(S)))
for i in S:
print(i)
```
| 4,657 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Tags: constructive algorithms, data structures, greedy
Correct Solution:
```
from __future__ import division, print_function
import heapq
import math
import sys
import os
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
"""Prints the values to a stream, or to sys.stdout by default."""
sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
if sys.version_info[0] < 3:
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
n=inp()
l=[]
a=[]
heapq.heapify(l)
count_ex=0
for i in range(n):
x=input()
cm=x.split()
if cm[0]=='insert':
v=int(cm[1])
heapq.heappush(l,v)
elif cm[0]=='removeMin':
if len(l)==0:
a.append('insert 0')
else:
heapq.heappop(l)
else:
v=int(cm[1])
while(len(l)>0 and l[0]!=v):
if l[0]<v:
a.append('removeMin')
heapq.heappop(l)
else:
a.append('insert {}'.format(v))
heapq.heappush(l,v)
if len(l)==0:
a.append('insert {}'.format(v))
heapq.heappush(l,v)
a.append(x)
print(len(a))
for each in a:
print(each.strip())
```
| 4,658 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Submitted Solution:
```
import heapq
ot = []
n = int(input())
a = []
heapq.heapify(a)
for i in range(n):
k1 = input()
k = k1.split()
if k[0] == "insert":
heapq.heappush(a, int(k[1]))
elif k[0] == "removeMin":
if len(a) == 0:
ot.append("insert 3")
else:
heapq.heappop(a)
else:
while len(a) != 0 and a[0] < int(k[1]):
ot.append("removeMin")
heapq.heappop(a)
if len(a) == 0:
ot.append("insert" + " " + k[1])
heapq.heappush(a, int(k[1]))
elif a[0] > int(k[1]):
ot.append("insert" + " " + k[1])
heapq.heappush(a, int(k[1]))
ot.append(k1)
print(len(ot))
for x in ot:
print(x)
```
Yes
| 4,659 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Submitted Solution:
```
import math,heapq
import sys
input = sys.stdin.readline
n = int(input())
flag = 0
ans = []
l = []
heapq.heapify(l)
for i in range(n):
s = input()
if s[0] == "i":
heapq.heappush(l,int(s[7:len(s)-1]))
ans.append(s[0:len(s)-1])
continue
if s[0] == "r":
if len(l) == 0:
ans.append("insert 1")
ans.append(s[0:len(s)-1])
else:
ans.append(s[0:len(s)-1])
heapq.heappop(l)
continue
val = int(s[7:len(s)-1])
f = 0
# print(l)
while len(l) > 0 and f == 0:
if val == l[0]:
f = 1
break
if val > l[0]:
heapq.heappop(l)
ans.append("removeMin")
continue
heapq.heappush(l,val)
ans.append("insert "+str(val))
f = 1
break
if f == 0:
heapq.heappush(l, val)
ans.append("insert " + str(val))
ans.append(s[0:len(s)-1])
# print(ans)
print(len(ans))
for i in ans:
print(i)
```
Yes
| 4,660 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Submitted Solution:
```
from heapq import heappush, heappop
n = int(input())
heap = []
res = []
for i in range(n):
string = input()
oper = string.split()
if oper[0][0] == 'i':
heappush(heap, int(oper[1]))
elif oper[0][0] == 'g':
key = int(oper[1])
while heap and heap[0] < key:
heappop(heap)
res.append('removeMin')
if not heap or heap[0] != key:
heappush(heap, key)
res.append('insert ' + oper[1])
else:
if heap:
heappop(heap)
else:
res.append('insert 0')
res.append(string)
print(len(res))
print('\n'.join(res))
```
Yes
| 4,661 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Submitted Solution:
```
from heapq import heappop, heappush
from sys import stdin
n, *l = stdin.read().splitlines()
heap, res = [], []
for s in l:
array = s.split()
if array[0] == 'insert':
heappush(heap, int(array[1]))
elif array[0] == 'getMin':
key = int(array[1])
while heap and heap[0] < key:
heappop(heap)
res.append('removeMin')
if not heap or heap[0] != key:
heappush(heap, key)
res.append('insert ' + array[1])
else:
if heap:
heappop(heap)
else:
res.append('insert 0')
res.append(s)
print(len(res))
print('\n'.join(res))
```
Yes
| 4,662 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Submitted Solution:
```
from queue import PriorityQueue
res = []
l = 0
q = PriorityQueue()
for _ in range(int(input())):
a = input()
if a[:6] == "insert":
q.put(int(a.split()[1]))
elif a[:6] == "getMin":
mn = int(a.split()[1])
while not q.empty() and q.get() != mn:
res.append("removeMin")
l += 1
if q.empty():
res.append("insert "+str(mn))
l += 1
else:
print(q.empty())
if q.empty():
q.put(0)
res.append("insert 0")
l += 1
q.get()
res.append(a)
l += 1
print(l)
for each in res:
print(each)
```
No
| 4,663 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Submitted Solution:
```
def left(idx):
return (idx << 1) + 1
def right(idx):
return (idx << 1) + 2
def parent(idx):
return ((idx + 1) >> 1) - 1
class Heap:
def __init__(self, capacity):
self.data = [0] * capacity
self.L = 0
def restore_heap(self, idx, up=True):
best = idx
l, r = left(idx), right(idx)
if l < self.L and self.data[l] < self.data[best]:
self.data[l], self.data[idx] = self.data[idx], self.data[l]
best = l
if r < self.L and self.data[r] < self.data[best]:
self.data[r], self.data[best] = self.data[best], self.data[r]
best = r
if best == idx:
return
if up:
self.restore_heap(parent(idx), True)
else:
self.restore_heap(best, False)
def add(self, val):
self.data[self.L] = val
self.L += 1
self.restore_heap(parent(self.L - 1))
def removeMin(self):
if self.L == 0: return None
self.L -= 1
self.data[0] = self.data[self.L]
self.restore_heap(0, False)
if self.L == 0: return None
return self.data[0]
def getMin(self):
if self.L == 0: return None
return self.data[0]
n = int(input())
h = Heap(100000)
answer = []
for i in range(n):
q = input()
if q[0] == 'i':
v = int(q.split()[1])
h.add(v)
elif q[0] == 'g':
v = int(q.split()[1])
m = h.getMin()
while m is not None and m < v:
answer.append("removeMin")
m = h.removeMin()
if m is None or m > v:
answer.append("insert " + str(v))
h.add(v)
elif h.removeMin() is None:
answer.append("insert 0")
answer.append(q)
def print_answer():
print(len(answer))
print("\n".join(answer))
print_answer()
```
No
| 4,664 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Submitted Solution:
```
import heapq
def inp(n):
L = []
for i in range(n):
s = str(input())
s1 = s.split()
L.append([s1[0],int(s1[1])])
return L
n = int(input())
L = inp(n)
S = []
H = []
heapq.heapify(H)
for j in L:
if j[0] == 'insert':
heapq.heappush(H,j[1])
S.append('insert' +' '+ str(j[1]))
elif j[0] == 'removeMin':
if len(H) == 0:
S.append('insert' +' '+ str(0))
S.append('removeMin')
else:
heapq.heappop(H)
S.append('removeMin')
else:
k = j[1]
if len(H) == 0:
heapq.heappush(H,k)
S.append('insert' +' '+ str(k))
S.append('getMin' +' '+ str(k))
elif k == H[0]:
S.append('getMin' +' '+ str(H[0]))
else:
if k<H[0]:
heapq.heappush(H,k)
S.append('insert' +' '+ str(k))
S.append('getMin' +' '+ str(k))
else:
while len(H) != 0 and k>H[0]:
heapq.heappop(H)
S.append('removeMin')
if len(H) == 0 or H[0] != k:
heapq.heappush(H,k)
S.append('insert' +' '+ str(k))
S.append('getMin' +' '+ str(k))
else:
S.append('getMin' +' '+ str(H[0]))
for i in S:
print(i)
```
No
| 4,665 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya has recently learned data structure named "Binary heap".
The heap he is now operating with allows the following operations:
* put the given number into the heap;
* get the value of the minimum element in the heap;
* extract the minimum element from the heap;
Thus, at any moment of time the heap contains several integers (possibly none), some of them might be equal.
In order to better learn this data structure Petya took an empty heap and applied some operations above to it. Also, he carefully wrote down all the operations and their results to his event log, following the format:
* insert x β put the element with value x in the heap;
* getMin x β the value of the minimum element contained in the heap was equal to x;
* removeMin β the minimum element was extracted from the heap (only one instance, if there were many).
All the operations were correct, i.e. there was at least one element in the heap each time getMin or removeMin operations were applied.
While Petya was away for a lunch, his little brother Vova came to the room, took away some of the pages from Petya's log and used them to make paper boats.
Now Vova is worried, if he made Petya's sequence of operations inconsistent. For example, if one apply operations one-by-one in the order they are written in the event log, results of getMin operations might differ from the results recorded by Petya, and some of getMin or removeMin operations may be incorrect, as the heap is empty at the moment they are applied.
Now Vova wants to add some new operation records to the event log in order to make the resulting sequence of operations correct. That is, the result of each getMin operation is equal to the result in the record, and the heap is non-empty when getMin ad removeMin are applied. Vova wants to complete this as fast as possible, as the Petya may get back at any moment. He asks you to add the least possible number of operation records to the current log. Note that arbitrary number of operations may be added at the beginning, between any two other operations, or at the end of the log.
Input
The first line of the input contains the only integer n (1 β€ n β€ 100 000) β the number of the records left in Petya's journal.
Each of the following n lines describe the records in the current log in the order they are applied. Format described in the statement is used. All numbers in the input are integers not exceeding 109 by their absolute value.
Output
The first line of the output should contain a single integer m β the minimum possible number of records in the modified sequence of operations.
Next m lines should contain the corrected sequence of records following the format of the input (described in the statement), one per line and in the order they are applied. All the numbers in the output should be integers not exceeding 109 by their absolute value.
Note that the input sequence of operations must be the subsequence of the output sequence.
It's guaranteed that there exists the correct answer consisting of no more than 1 000 000 operations.
Examples
Input
2
insert 3
getMin 4
Output
4
insert 3
removeMin
insert 4
getMin 4
Input
4
insert 1
insert 1
removeMin
getMin 2
Output
6
insert 1
insert 1
removeMin
removeMin
insert 2
getMin 2
Note
In the first sample, after number 3 is inserted into the heap, the minimum number is 3. To make the result of the first getMin equal to 4 one should firstly remove number 3 from the heap and then add number 4 into the heap.
In the second sample case number 1 is inserted two times, so should be similarly removed twice.
Submitted Solution:
```
from heapq import heapify,heappop,heappush
n = int(input())
a = []
fi = []
heapify(a)
for _ in range(0,n):
s = input().split(' ')
if s[0] == "insert":
heappush(a,int(s[1]))
fi.append(' '.join(s))
elif s[0] == "getMin":
while len(a)>0 and a[0]<int(s[1]):
fi.append("removeMin")
heappop(a)
if len(a) == 0:
fi.append("insert "+s[1])
fi.append(' '.join(s))
else:
fi.append(' '.join(s))
else:
if len(a) == 0:
fi.append("insert 1")
fi.append(' '.join(s))
else:
fi.append(' '.join(s))
heappop(a)
print(len(fi))
for i in fi:
print(i)
```
No
| 4,666 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Tags: implementation, math
Correct Solution:
```
n, m, k = map(int, input().split())
L = int(k/(m+m))
if k%(m+m)!=0:L = L + 1
D = (L-1)*(m+m) + 1
if k%2==0:D = D + 1
D = int((k-D)/2) + 1
st = "L"
if k%2==0:st = "R"
print(L, D, st)
```
| 4,667 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Tags: implementation, math
Correct Solution:
```
import math
n,m,k=map(int,input().split())
l=math.ceil(k/(2*m))
se=math.ceil((k-((l-1)*2*m))/2)
print(l,se,end=' ')
if k%2==0:print('R')
else:print('L')
```
| 4,668 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Tags: implementation, math
Correct Solution:
```
n,m,k = map(int,input().split())
a = []
p = 1
for i in range(m): a += [[p,p+1]]; p += 2
p -= 1
x = -(-k//p)
if k % 2 == 0: z = "R"
else: z = "L"
if k % p == 0: y = m
else:
for i in range(m):
if k%p in a[i]: y = i+1; break
print(x,y,z)
```
| 4,669 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Tags: implementation, math
Correct Solution:
```
# Santa Claus and a Place in a Class
def santa(n, m, k):
direction = 'R'
if k & 1 == 1:
direction = 'L'
lane = 2
while True:
if k <= (m * lane):
prev = (m * (lane - 2)) + 1
desk = 1
while True:
if k == prev or k == prev + 1:
break
desk += 1
prev += 2
break
lane += 2
lane //= 2
print(lane, desk, direction)
n, m, k = list(map(int, input().split()))
santa(n, m, k)
```
| 4,670 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Tags: implementation, math
Correct Solution:
```
n,m,k=map(int,input().split())
a=k%2
x={1:"L",0:"R"}
r=k//(2*m)
if(k%(2*m)!=0):
r+=1
d=(k-(m*(r-1)*2))
if(d%2!=0):
d+=1
d=d//2
print(r,d,x[a])
```
| 4,671 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Tags: implementation, math
Correct Solution:
```
n, m, k = map(int, input().split())
z = (k + 2 * m - 1) // (2 * m)
q = k % (2 * m)
if q == 0:
q = 2 * m
q = (q + 1) // 2
w = q % 2
if k % 2:
w = 'L'
else:
w = 'R'
print(z, q, w)
```
| 4,672 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Tags: implementation, math
Correct Solution:
```
from math import ceil
def solve(n, m, k):
t = ceil(k / 2)
x = m if t % m == 0 else t % m
y = ceil(t / m)
p = 'L' if k % 2 == 1 else 'R'
return f'{y} {x} {p}'
def main():
n, m, k = list(map(int, input().split()))
print(solve(n, m, k))
main()
```
| 4,673 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Tags: implementation, math
Correct Solution:
```
# A. Santa Claus and a Place in a Class
n, m, k = map(int, input().split())
r = k // (2 * m)
if k % (2 * m) != 0:
r += 1
d = (k - (r - 1) * 2 * m) // 2
if (k - (r - 1) * 2 * m) % 2 != 0:
d += 1
s = "L" if k % 2 != 0 else "R"
print(r, d, s)
```
| 4,674 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Submitted Solution:
```
n, m , k = map(int, input().split())
if k%2 == 0:
print(((k-1)//2)//m+1, ((k-1)//2)%m+1, 'R')
else:
print(((k-1)//2)//m+1, ((k-1)//2)%m+1, 'L')
```
Yes
| 4,675 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Submitted Solution:
```
s = input().split()
n = int(s[0])
m = int(s[1])
k = int(s[2])
if k % 2 == 0:
k = int(k / 2)
a = int(k / m)
b = k % m
if b != 0:
print(a+1, b, 'R')
else:
print(a, m, 'R')
else:
k = int((k +1) / 2)
a = int(k / m)
b = k % m
if b != 0:
print(a+1, b, 'L')
else:
print(a, m, 'L')
```
Yes
| 4,676 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Submitted Solution:
```
n,m,k=list(map(int, input().split()))
if(k//(m*2)!=k/(m*2)):
r=k//(m*2)+1
else:
r=k//(m*2)
p=(k%(m*2))
place=p%2
if(p//2!=p/2):
p=p//2+1
else:
p=p//2
if(p==0):
p=m
if(place):
place='L'
else:
place='R'
print(r,p, place)
```
Yes
| 4,677 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Submitted Solution:
```
n, m, k = map(int, input().split())
r = (k + 2 * m -1)// (2 * m)
z = (k % (m * 2))
if z != 0:
d = (k % (m * 2) + 1) // 2
s = (k % (m * 2) + 1) % 2
else:
d = m
s = 'R'
if s == 0:
s = 'L'
else:
s = 'R'
print(r, d, s)
```
Yes
| 4,678 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Submitted Solution:
```
'''input
2 4 4
'''
n, m, k = map(int, input().split())
if k % (2*m) == 0:
l = k // (2*m)
else:
l = k // (2*m) + 1
print(l, end = " ")
if (k+1)//2 % m == 0:
print(m, end = " ")
else:
print((k+1)//2, end = " ")
print("L" if k % 2 == 1 else "R")
```
No
| 4,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Submitted Solution:
```
n,m,k=map(int,input().split())
o=k
fg=''
d=(2*m*n)//(2*m)
k=(2*m*n)-((d-1)*(2*m))
f=(k//2)
if k%2!=0:
k=k+1
if o% 2 != 0:
fg="L"
else:
fg="R"
print(abs(d),abs(f),fg)
```
No
| 4,680 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Submitted Solution:
```
def solution(l1):
n,m=l1[0],l1[1]
k=l1[2]
#print(2*m)
ans1=int(k/(2*m))+1
ans2=int((k%(2*m))/2)+1
if k%2:
side="L"
else:
side="R"
return str(ans1)+" "+str(ans2)+" "+side
def answer():
l1 = [int(x) for x in input().split()]
print(solution(l1))
answer()
```
No
| 4,681 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Santa Claus is the first who came to the Christmas Olympiad, and he is going to be the first to take his place at a desk! In the classroom there are n lanes of m desks each, and there are two working places at each of the desks. The lanes are numbered from 1 to n from the left to the right, the desks in a lane are numbered from 1 to m starting from the blackboard. Note that the lanes go perpendicularly to the blackboard, not along it (see picture).
The organizers numbered all the working places from 1 to 2nm. The places are numbered by lanes (i. e. all the places of the first lane go first, then all the places of the second lane, and so on), in a lane the places are numbered starting from the nearest to the blackboard (i. e. from the first desk in the lane), at each desk, the place on the left is numbered before the place on the right.
<image> The picture illustrates the first and the second samples.
Santa Clause knows that his place has number k. Help him to determine at which lane at which desk he should sit, and whether his place is on the left or on the right!
Input
The only line contains three integers n, m and k (1 β€ n, m β€ 10 000, 1 β€ k β€ 2nm) β the number of lanes, the number of desks in each lane and the number of Santa Claus' place.
Output
Print two integers: the number of lane r, the number of desk d, and a character s, which stands for the side of the desk Santa Claus. The character s should be "L", if Santa Clause should sit on the left, and "R" if his place is on the right.
Examples
Input
4 3 9
Output
2 2 L
Input
4 3 24
Output
4 3 R
Input
2 4 4
Output
1 2 R
Note
The first and the second samples are shown on the picture. The green place corresponds to Santa Claus' place in the first example, the blue place corresponds to Santa Claus' place in the second example.
In the third sample there are two lanes with four desks in each, and Santa Claus has the fourth place. Thus, his place is in the first lane at the second desk on the right.
Submitted Solution:
```
import math
n_row, n_desk, n_sant = list(map(lambda x: int(x), str(input()).split(' ')))
desk = math.ceil(n_sant / (n_desk * 2))
seat = ''
if n_sant % 2 == 0:
seat = 'R'
else:
seat = 'L'
row = math.ceil((n_sant - (n_desk * 2 * (desk - 1))) / n_desk) + 1
if n_sant == 1 or n_sant == 2:
row = 1
print(desk, row, seat)
```
No
| 4,682 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Tags: *special, implementation
Correct Solution:
```
""" Created by Henrikh Kantuni and Shahen Kosyan on 3/12/17 """
from itertools import groupby
n = int(input())
seq = list(input())
answer = []
stack = []
depth = -1
for i in range(len(seq)):
if seq[i] == '[':
stack.append('[')
depth += 2
answer.append(depth)
else:
stack.pop()
answer.append(depth)
depth -= 2
if len(stack) == 0:
answer.append('*')
# break down answer into nested lists using * separator
answer = [list(group) for k, group in groupby(answer, lambda x: x != "*") if k]
max_depth = 0
for i in range(len(answer)):
if max_depth < max(answer[i]):
max_depth = max(answer[i])
for i in range(len(answer)):
answer[i] = [(max_depth + 1 - a) for a in answer[i]]
# flatten
answer = [s for sub in answer for s in sub]
out = ""
stack = []
for i in range(len(answer)):
line = ""
if seq[i] == "[" and len(stack) == 0:
line += " " * ((max_depth - answer[i]) // 2)
line += "+"
line += "|" * answer[i]
line += "+"
line += " " * ((max_depth - answer[i]) // 2)
if seq[i + 1] == "]":
line += " " * ((max_depth - answer[i]) // 2)
line += "-"
line += " " * answer[i]
line += "-"
line += " " * ((max_depth - answer[i]) // 2)
stack.append(answer[i])
elif seq[i] == "[" and len(stack) > 0:
if seq[i - 1] == "[":
line += " " * ((max_depth - answer[i] - 2) // 2)
line += "-"
else:
line += " " * ((max_depth - answer[i]) // 2)
line += "+"
line += "|" * answer[i]
line += "+"
if seq[i - 1] == "[":
line += "-"
line += " " * ((max_depth - answer[i] - 2) // 2)
else:
line += " " * ((max_depth - answer[i]) // 2)
if seq[i + 1] == "]":
line += " " * ((max_depth - answer[i]) // 2)
line += "-"
line += " " * answer[i]
line += "-"
line += " " * ((max_depth - answer[i]) // 2)
stack.append(answer[i])
elif seq[i] == "]":
if seq[i - 1] == "[":
line += " " * ((max_depth - answer[i]) // 2)
line += "-"
line += " " * answer[i]
line += "-"
line += " " * ((max_depth - answer[i]) // 2)
if i < len(answer) - 1 and seq[i + 1] == "]":
line += " " * ((max_depth - answer[i] - 2) // 2)
line += "-"
line += "+"
line += "|" * answer[i]
line += "+"
line += "-"
line += " " * ((max_depth - answer[i] - 2) // 2)
else:
line += " " * ((max_depth - answer[i]) // 2)
line += "+"
line += "|" * answer[i]
line += "+"
line += " " * ((max_depth - answer[i]) // 2)
stack.pop()
out += line
# divide into chunks of size = max_depth + 2
out = [out[i:i + max_depth + 2] for i in range(0, len(out), max_depth + 2)]
# add a new line between - - and - -
i = 0
while i < len(out):
if out[i].replace(" ", "") == "--" and out[i + 1].replace(" ", "") == "--":
out.insert(i + 1, " " * len(out[i]))
i += 1
vertical = [list(r) for r in out]
# horizontal printing
final = ""
for i in range(len(vertical[0])):
for j in range(len(vertical)):
final += vertical[j][i]
final += "\n"
# remove the trailing space
final = final[:-1]
print(final)
```
| 4,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Tags: *special, implementation
Correct Solution:
```
n = int(input())
s = input()
def parse(s, i=0):
ss = i
start = i
h = 0
while i < len(s) and s[i] == '[':
i, nh = parse(s, i+1)
h = max(h, nh+2)
#print(s[start:i], h)
start = i
#print("parse {}:{} {}".format(start, i+1, h))
if i == ss:
h = 1
return i+1, h
_, h = parse(s)
l = 4 * n
mid = (h-1) // 2
buf = [[' ' for i in range(l)] for i in range(h)]
def draw(s, h, i=0, p=0):
if i >= len(s):
return
if s[i] == '[':
r = (h-1)//2
for j in range(r):
buf[mid+j][p] = '|'
buf[mid-j][p] = '|'
buf[mid+r][p] = '+'
buf[mid-r][p] = '+'
buf[mid+r][p+1] = '-'
buf[mid-r][p+1] = '-'
draw(s, h-2, i+1, p+1)
else:
h += 2
if s[i-1] == '[':
p += 3
r = (h-1)//2
for j in range(r):
buf[mid+j][p] = '|'
buf[mid-j][p] = '|'
buf[mid+r][p] = '+'
buf[mid-r][p] = '+'
buf[mid+r][p-1] = '-'
buf[mid-r][p-1] = '-'
draw(s, h, i+1, p+1)
draw(s, h)
for i in range(h):
l = -1
for j in range(len(buf[i])):
if buf[i][j] != ' ':
l = j+1
buf[i] = buf[i][:l]
for i in buf:
print(''.join(i))
```
| 4,684 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Tags: *special, implementation
Correct Solution:
```
from itertools import groupby
n = int(input())
seq = list(input())
answer = []
stack = []
depth = -1
for i in range(len(seq)):
if seq[i] == '[':
stack.append('[')
depth += 2
answer.append(depth)
else:
stack.pop()
answer.append(depth)
depth -= 2
if len(stack) == 0:
answer.append('*')
# break down answer into nested lists using * separator
answer = [list(group) for k, group in groupby(answer, lambda x: x != "*") if k]
max_depth = 0
for i in range(len(answer)):
if max_depth < max(answer[i]):
max_depth = max(answer[i])
for i in range(len(answer)):
answer[i] = [(max_depth + 1 - a) for a in answer[i]]
# flatten
answer = [s for sub in answer for s in sub]
out = ""
stack = []
for i in range(len(answer)):
line = ""
if seq[i] == "[" and len(stack) == 0:
line += " " * ((max_depth - answer[i]) // 2)
line += "+"
line += "|" * answer[i]
line += "+"
line += " " * ((max_depth - answer[i]) // 2)
if seq[i + 1] == "]":
line += " " * ((max_depth - answer[i]) // 2)
line += "-"
line += " " * answer[i]
line += "-"
line += " " * ((max_depth - answer[i]) // 2)
stack.append(answer[i])
elif seq[i] == "[" and len(stack) > 0:
if seq[i - 1] == "[":
line += " " * ((max_depth - answer[i] - 2) // 2)
line += "-"
else:
line += " " * ((max_depth - answer[i]) // 2)
line += "+"
line += "|" * answer[i]
line += "+"
if seq[i - 1] == "[":
line += "-"
line += " " * ((max_depth - answer[i] - 2) // 2)
else:
line += " " * ((max_depth - answer[i]) // 2)
if seq[i + 1] == "]":
line += " " * ((max_depth - answer[i]) // 2)
line += "-"
line += " " * answer[i]
line += "-"
line += " " * ((max_depth - answer[i]) // 2)
stack.append(answer[i])
elif seq[i] == "]":
if seq[i - 1] == "[":
line += " " * ((max_depth - answer[i]) // 2)
line += "-"
line += " " * answer[i]
line += "-"
line += " " * ((max_depth - answer[i]) // 2)
if i < len(answer) - 1 and seq[i + 1] == "]":
line += " " * ((max_depth - answer[i] - 2) // 2)
line += "-"
line += "+"
line += "|" * answer[i]
line += "+"
line += "-"
line += " " * ((max_depth - answer[i] - 2) // 2)
else:
line += " " * ((max_depth - answer[i]) // 2)
line += "+"
line += "|" * answer[i]
line += "+"
line += " " * ((max_depth - answer[i]) // 2)
stack.pop()
out += line
# divide into chunks of size = max_depth + 2
out = [out[i:i + max_depth + 2] for i in range(0, len(out), max_depth + 2)]
# add a new line between - - and - -
i = 0
while i < len(out):
if out[i].replace(" ", "") == "--" and out[i + 1].replace(" ", "") == "--":
out.insert(i + 1, " " * len(out[i]))
i += 1
vertical = [list(r) for r in out]
# horizontal printing
final = ""
for i in range(len(vertical[0])):
for j in range(len(vertical)):
final += vertical[j][i]
final += "\n"
# remove the trailing space
final = final[:-1]
print(final)
```
| 4,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Tags: *special, implementation
Correct Solution:
```
input()
a = input()
field = [[" " for j in range(500)] for i in range(500)]
mxb = -1
b = 0
for i in range(len(a)):
if a[i] == "[":
b += 1
else:
b -= 1
mxb = max(mxb, b)
m = (mxb * 2 + 1) // 2
def opn(curpos, curb):
up = mxb - curb + 1
for i in range(up):
field[m + i][curpos] = "|"
for i in range(up):
field[m - i][curpos] = "|"
field[m + up][curpos] = "+"
field[m - up][curpos] = "+"
field[m + up][curpos + 1] = "-"
field[m - up][curpos + 1] = "-"
def clos(curpos,curb):
up = mxb - curb + 1
for i in range(up):
field[m + i][curpos] = "|"
for i in range(up):
field[m - i][curpos] = "|"
field[m + up][curpos] = "+"
field[m - up][curpos] = "+"
field[m + up][curpos - 1] = "-"
field[m - up][curpos - 1] = "-"
curb = 0
pos = 0
for i in range(len(a)):
if a[i] == "[":
curb += 1
opn(pos,curb)
pos += 1
else:
if a[i - 1] == "[":
pos += 3
clos(pos,curb)
curb -= 1
pos += 1
ans = []
for i in range(len(field)):
lst = -1
for j in range(len(field[0])):
if field[i][j] != " ":
lst = j
ans.append(lst + 1)
for i in range(len(field)):
for j in range(ans[i]):
print(field[i][j],end="")
if ans[i]:
print()
```
| 4,686 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Tags: *special, implementation
Correct Solution:
```
n = int(input())
s = input()
bal = 0
m = 0
v = [0] * n
for i in range(n):
if s[i] == '[':
bal += 1
v[i] = bal
m = max(m, bal)
else:
v[i] = -bal
bal -= 1
for j in range(1, 2 * m + 2):
for i in range(0, n):
if abs(v[i]) == j or abs(v[i]) == 2 * (m + 1) - j:
if v[i] > 0:
print('+-', end = '')
else:
print('-+', end = '')
elif abs(v[i]) < j and abs(v[i]) < 2 * (m + 1) - j:
print('|', end = '')
if i + 1 < n and v[i + 1] < 0 and v[i] == -v[i + 1]:
print(' ', end = '')
else:
print(' ', end = '')
if i > 0 and abs(v[i - 1]) >= abs(v[i]) and i + 1 < n and abs(v[i + 1]) >= abs(v[i]):
print(' ', end = '')
if i + 1 < n and v[i + 1] < 0 and v[i] == -v[i + 1]:
print(' ', end = '')
print()
```
| 4,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Tags: *special, implementation
Correct Solution:
```
#This code is dedicated to Olya S.
l=int(input())
n=input()
def offset(ml,x):
return (ml-x)//2
def getstate(g,line,ml):
off=offset(ml,g[0])
if line<off or line>=g[0]+off:
return 0
elif line==off or line == g[0]+off-1:
return 1
else:
return 2
#Find max bracket#
ml=1
cl=1
for b in n:
if b=='[':
cl+=2
if ml<cl:
ml=cl
else:
cl-=2
######MAP######
sc=[]
for b in n:
if b=='[':
sc.append([ml,True])
ml-=2
else:
ml+=2
sc.append([ml,False])
#####################
for i in range(ml):
for j in range(l):
g=sc[j]
state=getstate(g,i,ml)
if state==1:
if g[1]:
print('+-',end='')
else:
print('-+',end='')
elif state==0:
if sc[j-1][0]-sc[j][0]!=2:
print(' ',end='')
else:
print('|',end='')
if sc[j][1] and not sc[j+1][1]:
if state==2:
print(' ',end='')
else:
print(' ',end='')
print()
```
| 4,688 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Tags: *special, implementation
Correct Solution:
```
n = int(input())
x = input()
d = [0] * n
cd = 0
xp = []
for i in range(n):
if x[i] == '[':
d[i] = cd
cd = cd + 1
else:
cd = cd - 1
d[i] = cd
for i in range(n-1):
xp.append((x[i], d[i]))
if x[i] == '[' and x[i+1] == ']':
xp.extend([(' ', d[i]), (' ', d[i]), (' ', d[i])])
xp.append((x[n-1], d[n-1]))
md = max(d)
h = md * 2 + 3
res = []
for i in range(h):
l = [' ' for j in xp]
res.append(l)
for i in range(len(xp)):
for j in range(h):
if xp[i][0] == '[' and j > xp[i][1] and j < h - xp[i][1] - 1:
res[j][i] = '|'
elif xp[i][0] == ']' and j > xp[i][1] and j < h - xp[i][1] - 1:
res[j][i] = '|'
elif xp[i][0] == '[' and (j == xp[i][1] or j == h - xp[i][1] - 1):
res[j][i] = '+'
res[j][i+1] = '-'
elif xp[i][0] == ']' and (j == xp[i][1] or j == h - xp[i][1] - 1):
res[j][i] = '+'
res[j][i-1] = '-'
for i in range(h):
print(''.join(res[i]))
```
| 4,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Tags: *special, implementation
Correct Solution:
```
import base64
code = "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"
eval(compile(base64.b64decode(code),'<string>','exec'))
```
| 4,690 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Submitted Solution:
```
n = int(input())
s = input()
t = set()
a = [0]*len(s)
q = 0
m = 0
ans = []
for i in range(len(s)):
if(s[i]=='['):
q+=1
a[i]=q
m=max(m,q)
else:
a[i]=q
q-=1
m = max(m,q)
if(s[i-1]=='['):
t.add(i-1)
for i in range(m+1):
e=''
for j in range(len(s)):
if(a[j]-1==i):
if(s[j]=='['):
e+='+-'
if(j in t):
e+=' '
else:
e+='-+'
elif(a[j]-1<i):
if(s[j]=='['):
e+='|'
if(j in t):
e+=' '
elif(s[j]==']'):
if(j-1 in t):
e+=' '
e+='|'
else:
if(s[j]=='['):
if(j>0 and s[j-1]==']' and a[j-1]==a[j]):
e+=' '
e+=' '
if(j in t):
e+=' '
else:
if(j!=len(s)-1 and s[j+1]!=']'):
e+=' '
e+=' '
ans+=[e]
for i in range(len(ans)):
print(ans[i])
for i in range(len(ans)-2,-1,-1):
print(ans[i])
```
Yes
| 4,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Submitted Solution:
```
d = dict()
d['['] = 1
d[']'] = -1
n = int(input())
s = input()
bal = 0
best = -1
for elem in s:
bal += d[elem]
best = max(best, bal)
size = 2 * best + 1
ans = [[' '] * (3 * n) for i in range(size)]
last_type = 'close'
last_size = size
curr_state = 0
for elem in s:
if last_type == 'close' and elem == '[':
curr_state += 1
up = best - last_size // 2
down = best + last_size // 2
ans[up][curr_state] = '+'
ans[down][curr_state] = '+'
for i in range(up + 1, down):
ans[i][curr_state] = '|'
ans[up][curr_state + 1] = '-'
ans[down][curr_state + 1] = '-'
last_type = 'open'
elif last_type == 'close' and elem == ']':
curr_state += 1
up = best - last_size // 2 - 1
down = best + last_size // 2 + 1
ans[up][curr_state] = '+'
ans[down][curr_state] = '+'
for i in range(up + 1, down):
ans[i][curr_state] = '|'
ans[up][curr_state - 1] = '-'
ans[down][curr_state - 1] = '-'
last_size += 2
elif last_type == 'open' and elem == '[':
curr_state += 1
up = best - last_size // 2 + 1
down = best + last_size // 2 - 1
ans[up][curr_state] = '+'
ans[down][curr_state] = '+'
for i in range(up + 1, down):
ans[i][curr_state] = '|'
ans[up][curr_state + 1] = '-'
ans[down][curr_state + 1] = '-'
last_size -= 2
else:
curr_state += 4
up = best - last_size // 2
down = best + last_size // 2
ans[up][curr_state] = '+'
ans[down][curr_state] = '+'
for i in range(up + 1, down):
ans[i][curr_state] = '|'
ans[up][curr_state - 1] = '-'
ans[down][curr_state - 1] = '-'
last_type = 'close'
for i in range(size):
for j in range(1, curr_state + 1):
print(ans[i][j], end = '')
print()
```
Yes
| 4,692 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Submitted Solution:
```
n = input()
s = input()
b = 0
maxb = 0
for c in s:
if c == '[':
b += 1
else:
b -= 1
if b > maxb:
maxb = b
res = [""] * (maxb * 2 + 1)
b = maxb
pred = ""
for k in range(len(s)):
c = s[k]
if c == '[':
if k != len(s) - 1:
if s[k+1] == ']':
sep = '| '
else:
sep = '|'
else:
sep = '|'
i = maxb - b
for j in range(i):
res[j] += ' '
res[i] += '+-'
for j in range(i + 1, len(res) - i - 1):
res[j] += sep
res[len(res) - i - 1] += '+-'
for j in range(len(res) - i, len(res)):
res[j] += ' '
pred = '['
b -= 1
elif c == ']':
if k != len(s) - 1:
if s[k+1] == '[':
space = ' '
else:
space = ' '
else:
space = ' '
b += 1
if pred == '[':
sep = ' |'
for j in range(len(res)):
res[j] += ' '
else:
sep = '|'
i = maxb - b
for j in range(i):
res[j] += space
res[i] += '-+'
for j in range(i + 1, len(res) - i - 1):
res[j] += sep
res[len(res) - i - 1] += '-+'
for j in range(len(res) - i, len(res)):
res[j] += space
pred = ']'
for i in res:
print(i)
```
Yes
| 4,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Submitted Solution:
```
class Screen:
def __init__(self, n_rows):
self.rows = [[] for _ in range(n_rows)]
self.height = n_rows
def draw(self, x, y, c):
row = self.rows[y]
while x > len(row) - 1:
row.append(' ')
row[x] = c
def draw_open(self, x, height):
middle = self.height // 2
self.draw(x, middle, '|')
for dy in range(1, height + 1):
self.draw(x, middle + dy, '|')
self.draw(x, middle - dy, '|')
self.draw(x, middle + height + 1, '+')
self.draw(x + 1, middle + height + 1, '-')
self.draw(x, middle - height - 1, '+')
self.draw(x + 1, middle - height - 1, '-')
def draw_close(self, x, height):
middle = self.height // 2
self.draw(x, middle, '|')
for dy in range(1, height + 1):
self.draw(x, middle + dy, '|')
self.draw(x, middle - dy, '|')
self.draw(x, middle + height + 1, '+')
self.draw(x - 1, middle + height + 1, '-')
self.draw(x, middle - height - 1, '+')
self.draw(x - 1, middle - height - 1, '-')
def strings(self):
return [''.join(row) for row in self.rows]
def to_heights(seq):
depths = []
cur_depth = 0
for par in seq:
if par == '[':
depths.append(cur_depth)
cur_depth += 1
else:
cur_depth -= 1
depths.append(cur_depth)
max_depth = max(depths)
heights = [max_depth - depth for depth in depths]
return heights
def to_strings(seq, heights):
n_rows = 2 * (max(heights) + 1) + 1
screen = Screen(n_rows)
cur_x = 0
prev_par = None
for par, height in zip(seq, heights):
if par == '[':
screen.draw_open(cur_x, height)
cur_x += 1
if par == ']':
if prev_par == '[':
cur_x += 3
screen.draw_close(cur_x, height)
cur_x += 1
prev_par = par
return screen.strings()
n = int(input())
seq = input()
heights = to_heights(seq)
strings = to_strings(seq, heights)
for string in strings:
print(string)
```
Yes
| 4,694 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Submitted Solution:
```
s = input()
t = set()
a = [0]*len(s)
q = 0
m = 0
ans = []
for i in range(len(s)):
if(s[i]=='['):
q+=1
a[i]=q
m=max(m,q)
else:
a[i]=q
q-=1
m = max(m,q)
if(s[i-1]=='['):
t.add(i-1)
for i in range(m+1):
e=''
for j in range(len(s)):
if(a[j]-1==i):
if(s[j]=='['):
e+='+-'
if(j in t):
e+=' '
else:
e+='-+'
elif(a[j]-1<i):
if(s[j]=='['):
e+='|'
if(j in t):
e+=' '
elif(s[j]==']'):
if(j-1 in t):
e+=' '
e+='|'
else:
if(s[j]=='['):
if(j>0 and s[j-1]==']' and a[j-1]==a[j]):
e+=' '
e+=' '
if(j in t):
e+=' '
else:
if(j!=len(s)-1 and s[j+1]!=']'):
e+=' '
e+=' '
ans+=[e]
for i in range(len(ans)):
print(ans[i])
for i in range(len(ans)-2,-1,-1):
print(ans[i])
```
No
| 4,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Submitted Solution:
```
import fileinput
s = fileinput.input().readline()[:-1]
ln = len(s)
l = [0] * ln
c = 0
for i, x in enumerate(s):
if x == '[':
c += 1
l[i] = c
if x == ']':
c -= 1
enc = max(l)
h_max = enc * 2 + 1
for h_ in range(h_max):
h = min(h_, 2*enc - h_)
for i in range(ln):
if h+1 == l[i]:
if s[i] == '[':
print('+', end='')
elif s[i] == ']':
print('+', end='')
elif h+2 == l[i] and (s[i] == s[i-1] == '[' or s[i] == s[i+1] == ']'):
print('-', end='')
elif h >= l[i]:
print('|', end='')
else:
print(' ', end='')
if s[i] == '[' and s[i+1] ==']':
if h+1 == l[i]:
print('- -', end='')
else:
print(' ', end='')
print()
```
No
| 4,696 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Submitted Solution:
```
def depths(S):
current_max = 1
n = len(S)
for i in range(n):
if S[i] == '[':
yield current_max, 'L'
current_max += 2
elif S[i] == ']':
yield current_max - 2, 'R'
current_max -= 2
n = input()
s = input()
full_rev_l = list(depths(s))
rev_l = [i[0] for i in full_rev_l]
set_rev_l = list(set(rev_l))
l = [(set_rev_l[set_rev_l.index(val) * -1 - 1], full_rev_l[ind][1]) for ind, val in enumerate(rev_l)]
m = max(set_rev_l) + 2
paint = [[' ' for x in range(len(l)*3)] for y in range(m)]
i = 0
pre = ''
for br, side in l:
start = int((m - br) / 2 - 1)
end = int(m - (m - br) / 2)
if side == 'L':
# paint head
paint[start][i] = '+'
paint[start][i + 1] = '-'
# paint body
for j in range(start + 1, end):
paint[j][i] = '|'
# paint foot
paint[end][i] = '+'
paint[end][i + 1] = '-'
# i ++
else:
if pre == 'L': i += 3
# paint head
paint[start][i] = '+'
paint[start][i - 1] = '-'
# paint body
for j in range(start + 1, end):
paint[j][i] = '|'
# paint foot
paint[end][i] = '+'
paint[end][i - 1] = '-'
i += 1
pre = side
for s in paint:
print(''.join(s).strip())
```
No
| 4,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A sequence of square brackets is regular if by inserting symbols "+" and "1" into it, you can get a regular mathematical expression from it. For example, sequences "[[]][]", "[]" and "[[][[]]]" β are regular, at the same time "][", "[[]" and "[[]]][" β are irregular.
Draw the given sequence using a minimalistic pseudographics in the strip of the lowest possible height β use symbols '+', '-' and '|'. For example, the sequence "[[][]][]" should be represented as:
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Each bracket should be represented with the hepl of one or more symbols '|' (the vertical part) and symbols '+' and '-' as on the example which is given above.
Brackets should be drawn without spaces one by one, only dividing pairs of consecutive pairwise brackets with a single-space bar (so that the two brackets do not visually merge into one symbol). The image should have the minimum possible height.
The enclosed bracket is always smaller than the surrounding bracket, but each bracket separately strives to maximize the height of the image. So the pair of final brackets in the example above occupies the entire height of the image.
Study carefully the examples below, they adequately explain the condition of the problem. Pay attention that in this problem the answer (the image) is unique.
Input
The first line contains an even integer n (2 β€ n β€ 100) β the length of the sequence of brackets.
The second line contains the sequence of brackets β these are n symbols "[" and "]". It is guaranteed that the given sequence of brackets is regular.
Output
Print the drawn bracket sequence in the format which is given in the condition. Don't print extra (unnecessary) spaces.
Examples
Input
8
[[][]][]
Output
+- -++- -+
|+- -++- -+|| |
|| || ||| |
|+- -++- -+|| |
+- -++- -+
Input
6
[[[]]]
Output
+- -+
|+- -+|
||+- -+||
||| |||
||+- -+||
|+- -+|
+- -+
Input
6
[[][]]
Output
+- -+
|+- -++- -+|
|| || ||
|+- -++- -+|
+- -+
Input
2
[]
Output
+- -+
| |
+- -+
Input
4
[][]
Output
+- -++- -+
| || |
+- -++- -+
Submitted Solution:
```
def draw(ind, type, size):
global ans, mid
ans[mid][ind] = '|'
for i in range(size // 2):
ans[mid + i][ind] = '|'
ans[mid - i][ind] = '|'
ans[mid + size // 2][ind] = '+'
ans[mid - size // 2][ind] = '+'
if type == "left":
ans[mid + size // 2][ind - 1] = '-'
ans[mid - size // 2][ind - 1] = '-'
else:
ans[mid + size // 2][ind + 1] = '-'
ans[mid - size // 2][ind + 1] = '-'
n = int(input())
s = input()
mx = 0
cs = 0
for i in range(n):
if s[i] == "[":
cs += 1
else:
cs -= 1
mx = max(mx, cs)
mx -= 1
a = [mx]
for i in range(1, n):
if (s[i] == "[" and s[i - 1] == "]") or (s[i - 1] == "[" and s[i] == "]"):
a.append(a[-1])
elif s[i] == "[":
a.append(a[-1] - 1)
else:
a.append(a[-1] + 1)
ans = [[' ' for i in range(n * 3)] for j in range(3 + mx * 2)]
mid = mx + 1
draw(0, "right", mx * 2 + 3)
li = 0
for i in range(1, n):
if s[i] == "[" and s[i - 1] == "]":
li += 1
draw(li, "right", a[i] * 2 + 3)
elif s[i - 1] == "[" and s[i] == "]":
li += 4
draw(li, "left", a[i] * 2 + 3)
elif s[i] == "[":
li += 1
draw(li, "right", a[i] * 2 + 3)
else:
li += 1
draw(li, "left", a[i] * 2 + 3)
for i in ans:
for j in i:
print(j, end="")
print()
```
No
| 4,698 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Karen is getting ready for a new school day!
<image>
It is currently hh:mm, given in a 24-hour format. As you know, Karen loves palindromes, and she believes that it is good luck to wake up when the time is a palindrome.
What is the minimum number of minutes she should sleep, such that, when she wakes up, the time is a palindrome?
Remember that a palindrome is a string that reads the same forwards and backwards. For instance, 05:39 is not a palindrome, because 05:39 backwards is 93:50. On the other hand, 05:50 is a palindrome, because 05:50 backwards is 05:50.
Input
The first and only line of input contains a single string in the format hh:mm (00 β€ hh β€ 23, 00 β€ mm β€ 59).
Output
Output a single integer on a line by itself, the minimum number of minutes she should sleep, such that, when she wakes up, the time is a palindrome.
Examples
Input
05:39
Output
11
Input
13:31
Output
0
Input
23:59
Output
1
Note
In the first test case, the minimum number of minutes Karen should sleep for is 11. She can wake up at 05:50, when the time is a palindrome.
In the second test case, Karen can wake up immediately, as the current time, 13:31, is already a palindrome.
In the third test case, the minimum number of minutes Karen should sleep for is 1 minute. She can wake up at 00:00, when the time is a palindrome.
Tags: brute force, implementation
Correct Solution:
```
hh, mm = [str(x) for x in input().split(':')]
ih = int(hh)
im = int(mm)
cnt = 0
while True:
sh = str(ih)
sm = str(im)
if len(sh) == 1:
sh = '0'+sh
if len(sm) == 1:
sm = '0'+sm
if sh == sm[::-1]:
print(cnt)
break
im += 1
if im >= 60:
ih += 1
im = 0
if ih >= 24:
ih = 0
cnt += 1
```
| 4,699 |
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