text stringlengths 198 433k | conversation_id int64 0 109k |
|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
"Correct Solution:
```
import sys
input()
d=dict.fromkeys('AC WA TLE RE'.split(),0)
for ln in sys.stdin:
d[ln.strip()]+=1
for k,v in d.items():
print(k,'x',v)
```
| 86,300 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
"Correct Solution:
```
N = int(input())
D = {"AC":0, "WA":0, "TLE":0, "RE":0}
for _ in range(N):
S = input()
D[S] += 1
for i, x in D.items():
print(i+" x "+str(x))
```
| 86,301 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
"Correct Solution:
```
n,*s=open(0).read().split()
for t in['AC','WA','TLE','RE']:print(f'{t} x {s.count(t)}')
```
| 86,302 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
"Correct Solution:
```
n = int(input())
s = [input() for i in range(n)]
a = ["AC","WA","TLE","RE"]
for i in a:
print(i,'x',s.count(i))
```
| 86,303 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
"Correct Solution:
```
n=int(input())
c={}
for _ in range(n):
s=input()
c[s]=c.get(s,0)+1
for j in ('AC','WA','TLE','RE'):
print(j,'x',c.get(j,0))
```
| 86,304 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
Submitted Solution:
```
from collections import Counter
ans = Counter(input() for _ in range(int(input())))
for i in ['AC', 'WA', 'TLE', 'RE']:
print(f'{i} x {ans[i]}')
```
Yes
| 86,305 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
Submitted Solution:
```
n = int(input())
C = {"AC": 0, "WA": 0, "TLE": 0, "RE": 0}
for i in range(n):
C[input()] += 1
for s in C:
print(f'{s} x {C[s]}')
```
Yes
| 86,306 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
Submitted Solution:
```
n = int(input())
di = {'AC':0, 'WA':0, 'TLE':0, 'RE':0}
for _ in range(n):
di[input()] += 1
for i, j in di.items():
print(i, 'x', j)
```
Yes
| 86,307 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
Submitted Solution:
```
dict={"AC":0,"WA":0,"TLE":0,"RE":0}
n,*s=map(str,open(0).read().split())
for i in s:
dict[i]+=1
for k, v in dict.items():
print(k+" x "+str(v))
```
Yes
| 86,308 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
Submitted Solution:
```
n = int(input())
judge = list(input() for _ in range(n))
ac, wa, tle, re = 0
for i in judge:
if i == 'AC':
ac = ac + 1
elif i == 'WA':
wa = wa + 1
elif i == 'TLE':
tle = tle + 1
elif i == 'RE':
re = re + 1
print('AC x ' + str(ac))
print('WA x ' + str(wa))
print('TLE x ' + str(tle))
print('RE x ' + str(re))
```
No
| 86,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
Submitted Solution:
```
n = int(input())
c0, c1, c2, c3 = 0
for _ in range(n):
if _ == "AC":
c0 += 1
if _ == "WA":
c1 += 1
if _ == "TLE":
c2 += 1
if _ == "RE":
c3 += 1
print("AC x", c0)
print("WA x", c1)
print("TLE x", c2)
print("RE x", c3)
```
No
| 86,310 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
Submitted Solution:
```
from sys import stdin, stdout
import heapq
import cProfile
from collections import Counter, defaultdict, deque
from functools import reduce
import math
from bisect import bisect,bisect_right,bisect_left
def get_int():
return int(stdin.readline().strip())
def get_tuple():
return map(int, stdin.readline().split())
def get_list():
return list(map(int, stdin.readline().split()))
n = get_int()
dic = defaultdict(int)
for _ in range(n):
st = input()
dic[st] += 1
for val in ['AC','WA','TLE','RE']:
print(val+" * "+str(dic[val]))
```
No
| 86,311 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.
The problem has N test cases.
For each test case i (1\leq i \leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively.
See the Output section for the output format.
Constraints
* 1 \leq N \leq 10^5
* S_i is `AC`, `WA`, `TLE`, or `RE`.
Input
Input is given from Standard Input in the following format:
N
S_1
\vdots
S_N
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Output
Let C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is `AC`, `WA`, `TLE`, and `RE`, respectively. Print the following:
AC x C_0
WA x C_1
TLE x C_2
RE x C_3
Examples
Input
6
AC
TLE
AC
AC
WA
TLE
Output
AC x 3
WA x 1
TLE x 2
RE x 0
Input
10
AC
AC
AC
AC
AC
AC
AC
AC
AC
AC
Output
AC x 10
WA x 0
TLE x 0
RE x 0
Submitted Solution:
```
n = int(input())
j = list()
for _ in range(n):
string = input()
j.append(string)
ac = j.count("AC")
wa = j.count("WA")
tel = j.count("TEL")
re = j.count("RE")
print(f"AC x {ac}")
print(f"WA x {wa}")
print(f"TEL x {tel}")
print(f"RE x {re}")
```
No
| 86,312 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
"Correct Solution:
```
N = int(input())
def standard(n, cur):
if n == 0:
print(''.join(cur))
else:
newC = chr(ord(sorted(cur)[-1]) + 1)
for c in sorted(set(cur + [newC])):
standard(n - 1, cur + [c])
standard(N - 1, ['a'])
```
| 86,313 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
"Correct Solution:
```
N = int(input())
def calc(n, L, ma):
if n == 0:
print("".join([chr(a+97) for a in L]))
return L
for i in range(ma+2):
l = calc(n-1, L + [i], max(ma, i))
calc(N, [], -1)
```
| 86,314 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
"Correct Solution:
```
def dfs(a='', b=chr(ord('a'))):
if len(a) == N:
print(a)
else:
i = chr(ord('a'))
while i < b:
dfs(a + i, b)
i = chr(ord(i) + 1)
dfs(a + b, chr(ord(b) + 1))
N = int(input())
dfs()
```
| 86,315 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
"Correct Solution:
```
N = int(input())
def dfs(s, mx):
if len(s) == N:
print(s)
return
for c in 'abcdefghij'[:(ord(mx)-ord('a'))+1]:
dfs(s+c, chr(ord(mx)+1)) if c == mx else dfs(s+c, mx)
dfs('', 'a')
```
| 86,316 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
"Correct Solution:
```
n = int(input())
def dfs(s, mx):
if len(s) == n:
print(''.join([chr(ord('a') + i) for i in s]))
else:
for i in range(mx+1):
dfs(s + [i], mx if i != mx else mx + 1)
dfs([], 0)
```
| 86,317 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
"Correct Solution:
```
n = int(input())
a = ord('a')
def dfs(s, m):
# print("dfs", s, chr(m))
if len(s) == n:
print(s)
else:
for i in range(m + 1 - a):
dfs(s + chr(a + i), m + 1 if i == m - a else m)
dfs("", a)
```
| 86,318 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
"Correct Solution:
```
n=int(input())
l=[["a"]]+[[] for i in range(9)]
for i in range(9):
for j in l[i]:
k=len(set(list(j)))
for h in range(k+1):
l[i+1].append(j+chr(97+h))
for i in l[n-1]:print(i)
```
| 86,319 |
Provide a correct Python 3 solution for this coding contest problem.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
"Correct Solution:
```
n = int(input())
def dfs(s, mx):
if len(s) == n:
print(s)
return
for c in range(ord("a"), mx+2):
dfs(s+chr(c), max(mx, c))
dfs("", ord("a")-1)
```
| 86,320 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
Submitted Solution:
```
str = 'abcdefghijklmnop'
def bt(n,m,s):
if n == 0:
print(s)
return
for c in range(m):
bt(n-1,m,s+str[c])
#introduce another character
bt(n-1,m+1,s+str[m])
n = int(input())
bt(n,0,'')
```
Yes
| 86,321 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
Submitted Solution:
```
n = int(input())
A= 'a'
# 文字数を増やして, その各々の元に対して文字を追加する.
for _ in range(n - 1):
A = {a + s for a in A for s in a + chr(ord(max(a)) + 1)}
# print(A)
# 最後にsortして調整する.
#print(*A, sep = '\n')
print(*sorted(A), sep='\n')
```
Yes
| 86,322 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
Submitted Solution:
```
n = int(input())
s = "abcdefghij"
def func(a):
if len(a) == n:
print(a)
else:
for i in range(len(set(a))+1):
func(a+s[i])
func("a")
```
Yes
| 86,323 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
Submitted Solution:
```
N = int(input())
strlist = 'abcdefghij'
def dfs(s, i):
if len(s) == N:
print(s)
else:
for j in range(i+1):
t = s + strlist[j]
if j == i:
dfs(t, i+1)
else:
dfs(t, i)
dfs('', 0)
```
Yes
| 86,324 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
Submitted Solution:
```
from collections import deque
import sys
N = int(input())
if N == 1:
print('a')
sys.exit()
else:
ans = []
def solve(s):
if len(s) == N:
ans.append(s)
return
cp = s[-1]
o = ord(cp)
for n in range(97, o+2):
solve(s + chr(n))
solve('a')
for a in ans:
print(a)
```
No
| 86,325 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
Submitted Solution:
```
n = int(input())
tmp_list = list('a' * n)
num_list = [97] * n
target = n - 1
tmp_target=n-1
max_num=97
while tmp_target>0:
print("".join(list(map(chr, num_list))))
if max(num_list[0:target:]) >= num_list[target]:
num_list[target] += 1
else:
num_list[target]=97
tmp_target=target-1
while tmp_target>0:
if max(num_list[0:tmp_target:]) >=num_list[tmp_target]:
num_list[tmp_target]+=1
break
else:
num_list[tmp_target]=97
tmp_target-=1
```
No
| 86,326 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
Submitted Solution:
```
import string
import itertools
alphabets = string.ascii_lowercase
N = int(input())
def bfs(s, d):
if d == N - 1:
print(s)
return s
res = []
for i in range(ord(s[-1]) - ord("a") + 2):
res.append(bfs(s + alphabets[i], d + 1))
# return res
bfs("a", 0)
# print(list(bfs("a", 0)))
```
No
| 86,327 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In this problem, we only consider strings consisting of lowercase English letters.
Strings s and t are said to be isomorphic when the following conditions are satisfied:
* |s| = |t| holds.
* For every pair i, j, one of the following holds:
* s_i = s_j and t_i = t_j.
* s_i \neq s_j and t_i \neq t_j.
For example, `abcac` and `zyxzx` are isomorphic, while `abcac` and `ppppp` are not.
A string s is said to be in normal form when the following condition is satisfied:
* For every string t that is isomorphic to s, s \leq t holds. Here \leq denotes lexicographic comparison.
For example, `abcac` is in normal form, but `zyxzx` is not since it is isomorphic to `abcac`, which is lexicographically smaller than `zyxzx`.
You are given an integer N. Print all strings of length N that are in normal form, in lexicographically ascending order.
Constraints
* 1 \leq N \leq 10
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Output
Assume that there are K strings of length N that are in normal form: w_1, \ldots, w_K in lexicographical order. Output should be in the following format:
w_1
:
w_K
Examples
Input
1
Output
a
Input
2
Output
aa
ab
Submitted Solution:
```
n = int(input())
a = [ [] for _ in range(11) ]
a[0].append("a")
alp = "abcdefghijklmn"
for i in range(1, 10):
for aa in a[i-1]:
for c in alp[:i+1]:
if ord(aa[-1])+1 < ord(c): break
a[i].append(aa+c)
for ans in a[n-1]:
print(ans)
```
No
| 86,328 |
Provide a correct Python 3 solution for this coding contest problem.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
"Correct Solution:
```
a,b=map(int,input().split())
print(a*b if a<10 and b<10 else "-1")
```
| 86,329 |
Provide a correct Python 3 solution for this coding contest problem.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
"Correct Solution:
```
a,b=map(int,input().split());print(-1 if a>9 or b>9 else a*b)
```
| 86,330 |
Provide a correct Python 3 solution for this coding contest problem.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
"Correct Solution:
```
a,b=map(int, input().split())
print(a*b if a<=9 and b<=9 else "-1")
```
| 86,331 |
Provide a correct Python 3 solution for this coding contest problem.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
"Correct Solution:
```
x,y=map(int,input().split())
if x>9 or y>9:
print(-1)
else:
print(x*y)
```
| 86,332 |
Provide a correct Python 3 solution for this coding contest problem.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
"Correct Solution:
```
A,B=map(int,input().split())
ans = A*B if A <= 9 and B <= 9 else -1
print(ans)
```
| 86,333 |
Provide a correct Python 3 solution for this coding contest problem.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
"Correct Solution:
```
a,b=map(int,input().split())
if max(a,b)>=10:
print(-1)
else:
print(a*b)
```
| 86,334 |
Provide a correct Python 3 solution for this coding contest problem.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
"Correct Solution:
```
a,b=map(int,input().split())
print(-1 if a >= 10 or b >= 10 else a*b)
```
| 86,335 |
Provide a correct Python 3 solution for this coding contest problem.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
"Correct Solution:
```
#144_A
a, b = map(int, input().split())
print(a*b if a<10 and b<10 else -1)
```
| 86,336 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
a,b=map(int,input().split())
if 10<=a or 10<=b:
print(-1)
else:
print(a*b)
```
Yes
| 86,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
a,b=map(int, input().split())
if (a<=9 and b<=9):
print(a*b)
else:
print("-1")
```
Yes
| 86,338 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
a,b = map(int, input().split())
print(a*b if (a<=9)&(b<=9) else -1)
```
Yes
| 86,339 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
A,B=map(int,input().split())
print(-1) if A>=10 or B>=10 else print(A*B)
```
Yes
| 86,340 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
n,m=map(int,input().split())
if n<10 && m<10 :
print(n*m)
else :
print(-1)
```
No
| 86,341 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
import bisect,collections,copy,heapq,itertools,math,string
import numpy as np
import sys
sys.setrecursionlimit(10**7)
def _S(): return sys.stdin.readline().rstrip()
def I(): return int(sys.stdin.readline().rstrip())
def LI(): return list(map(int,sys.stdin.readline().rstrip().split()))
def LS(): return list(sys.stdin.readline().rstrip().split())
# 最短距離
# 素因数分解
N = I()
def make_divisors(n):
divisors = []
for i in range(1, int(n**0.5)+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n//i)
divisors.sort()
return divisors
# c = sympy.divisors(N)
c = make_divisors(N)
lenc = len(c)
if (lenc % 2)==0:
a = c[lenc // 2 - 1]
b = c[lenc // 2]
else:
a = c[lenc // 2]
b = a
print(a + b -2)
#H,N = LI()
#AB = [LI() for _ in range(N)]
#A,B = zip(*AB)
#Ap = np.array(A)
#C = np.zeros(N + 1)
# if ans:
# print('Yes')
# else:
# print('No')
```
No
| 86,342 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
a,b=map(int, input().split())
if (9-a)*(9-b)<0:
print(-1)
else:
print(a*b)
```
No
| 86,343 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
s = input().split()
if A > 10 or B > 10:
print(1)
else:
print(a * b)
```
No
| 86,344 |
Provide a correct Python 3 solution for this coding contest problem.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
"Correct Solution:
```
N, M = map(int, input().split())
List = [int(input()) for _ in range(M)]
P = 10**9+7
dp = [1]*(N+1)
for i in List:
dp[i]=0
for j in range(1, N):
if dp[j+1]!=0:
dp[j+1] = dp[j]+dp[j-1]
print(dp[N]%P)
```
| 86,345 |
Provide a correct Python 3 solution for this coding contest problem.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
"Correct Solution:
```
import sys
N,M=map(int,input().split())
S=set(map(int,sys.stdin))
a,b=0,1
for i in range(1,N+1):
if i in S:
a,b=b,0
else:
a,b=b,a+b
print(b%(10**9+7))
```
| 86,346 |
Provide a correct Python 3 solution for this coding contest problem.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
"Correct Solution:
```
n,b,*a=map(int,open(0).read().split())
a=set(a)
d=i=0
c=1
while i<n:i+=1;b=(c+d)%(10**9+7)*(not i in a);c,d=b,c
print(b)
```
| 86,347 |
Provide a correct Python 3 solution for this coding contest problem.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
"Correct Solution:
```
n,m=map(int,input().split())
a=set(int(input()) for i in range(m))
mod=10**9+7
dp=[0]*(n+1)
dp[0]=1
if 1 not in a:
dp[1]=1
for i in range(2,n+1):
if i not in a:
dp[i]+=(dp[i-2]+dp[i-1])%mod
print(dp[-1])
```
| 86,348 |
Provide a correct Python 3 solution for this coding contest problem.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
"Correct Solution:
```
n,m=map(int,input().split())
a=set(int(input()) for _ in range(m))
dp=[0]*(n+2)
dp[0]=1
for i in range(n):
if i in a:
continue
dp[i+1]+=dp[i]
dp[i+2]+=dp[i]
print(dp[n]%1000000007)
```
| 86,349 |
Provide a correct Python 3 solution for this coding contest problem.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
"Correct Solution:
```
N,M=map(int,input().split())
a=[int(input()) for _ in range(M)]+[10**6]
A=[0]*(N+2)
A[0:2]=[0,1]
j=0
for i in range(N):
if i+1 != a[j]:
A[i+2]=(A[i]+A[i+1])%(10**9+7)
else:
j+=1
print(A[N+1])
```
| 86,350 |
Provide a correct Python 3 solution for this coding contest problem.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
"Correct Solution:
```
MOD=10**9+7
N,M=map(int,input().split())
dp=[1]*(N+1)
for i in range(M):
dp[int(input())]=0
for n in range(2,N+1):
if dp[n]!=0:
dp[n]=(dp[n-1]+dp[n-2])
print(dp[N]%MOD)
```
| 86,351 |
Provide a correct Python 3 solution for this coding contest problem.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
"Correct Solution:
```
N, M = map(int,input().split())
a = [1] * (N+1)
for i in range(M):
a[int(input())] = 0
mod = 1000000007
ans = [0] * (N+1)
ans[0] = 1
for i in range(1,N+1):
ans[i] = (ans[i-2]*a[i-2] + ans[i-1]*a[i-1]) % mod
print(ans[N])
```
| 86,352 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
Submitted Solution:
```
n, m = map(int, input().split())
mod = 1_000_000_007
A = [1] * (n+1)
for i in range(m):
A[int(input())] = 0
for i in range(2, n+1):
if A[i]!=0:
A[i] = (A[i-1] + A[i-2])%mod
print(A[-1])
```
Yes
| 86,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
Submitted Solution:
```
N, M=map(int, input().split())
A = [int(input()) for _ in range(M)]
mod = 10**9 + 7
step = [1]*(N+1)
for a in A:
step[a]=0
for i in range(2, N+1):
step[i]=(step[i-1]+step[i-2])%mod*step[i]
print(step[-1])
```
Yes
| 86,354 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
Submitted Solution:
```
n,m=map(int,input().split())
a={int(input()) for i in range(m)}
mod=10**9+7
x=1 if 1 not in a else 0
dp=[1,x]+[0]*(n-1)
for i in range(2,n+1):
if i in a:
continue
dp[i]=(dp[i-1]+dp[i-2])
print(dp[-1]%mod)
```
Yes
| 86,355 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
Submitted Solution:
```
n,m=map(int,input().split())
a=[int(input()) for i in range(m)]
b=set(a)
dp=[0]*(n+2)
dp[0]=0
dp[1]=1
for j in range(n):
if j+1 not in b:
dp[j+2]=(dp[j]+dp[j+1])%(10**9+7)
else:
dp[j+2]=0
print(dp[j+2]%(10**9+7))
```
Yes
| 86,356 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
Submitted Solution:
```
N, M = [int(i) for i in input().split()]
a=[]
for i in range(M):
a +=[int(input())]
ways=[]
for i in range(N+1):
if i in a:
a=a[1:]
ways+=[0]
elif i==0:
ways +=[1]
elif i==1:
ways +=[1]
else:
ways+=[(ways[i-2]+ways[i-1])%1000000007]
print(ways[-1])
```
No
| 86,357 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
Submitted Solution:
```
import sys
input = sys.stdin.readline
MOD = 10 ** 9 + 7
def main():
N, M = map(int, input().split())
memo = [0] * (N + 1)
a = [0] * M
memo[0] = 0
memo[1] = 1
memo[2] = 2
for i in range(3, N+1):
memo[i] = memo[i-1] + memo[i-2]
# print(memo)
ans = 1
for i in range(M):
a[i] = int(input())
if i != 0 and abs(a[i] - a[i-1]) == 1:
print(0)
return
if a[i] == 1:
ans *= 1
elif i == 0:
ans *= memo[a[i] - 1]
ans %= MOD
# print(a[i], ans, a[i] - 1)
else:
ans *= memo[a[i] - a[i-1] - 2]
ans %= MOD
# print(a[i], ans, a[i] - a[i-1] - 2)
ans *= memo[N - a[M-1] - 1]
ans %= MOD
# print(ans, N - a[M-1] - 1)
print(ans)
if __name__ == '__main__':
main()
```
No
| 86,358 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
Submitted Solution:
```
def fib_memo(n):
"""メモ化フィボナッチ"""
memo = [0]*(n+1)
def _fib(n):
if n <= 1:
return n
if memo[n] != 0:
return memo[n]
memo[n] = _fib(n-1) + _fib(n-2)
return memo[n]
return _fib(n)
N, M = map(int, input().split())
A = [int(input()) for _ in range(M)]
B = [0]*(M-1)
for i in range(M):
diff = 0
if i == 0:
diff = A[i] - 1
B[0] = fib_memo(diff + 1)
else if i == (M - 1):
diff = N - A[M-1] -1
B[M-1] = fib_memo(diff + 1)
else:
diff = A[i] - A[i-1]
B[i] = fib_memo(diff + 1)
Ans = reduce(lambda a, b: a*b, B)
print(Ans % 1000000007)
```
No
| 86,359 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step. He can climb up one or two steps at a time.
However, the treads of the a_1-th, a_2-th, a_3-th, \ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.
How many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps? Find the count modulo 1\ 000\ 000\ 007.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq M \leq N-1
* 1 \leq a_1 < a_2 < ... < a_M \leq N-1
Input
Input is given from Standard Input in the following format:
N M
a_1
a_2
.
.
.
a_M
Output
Print the number of ways to climb up the stairs under the condition, modulo 1\ 000\ 000\ 007.
Examples
Input
6 1
3
Output
4
Input
10 2
4
5
Output
0
Input
100 5
1
23
45
67
89
Output
608200469
Submitted Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
from functools import lru_cache
@lru_cache(maxsize=None)
def fib(n):
if n == 0:
return 1
elif n == 1:
return 1
else:
return fib(n-1) + fib(n-2)
PRIME = 10 ** 9 + 7
N, M = list(map(int, input().split()))
broken_stairs = []
for _ in range(M):
broken_stairs.append(int(input()))
prev_broken = -1
cannot = False
ans = 1
for a in broken_stairs:
if a - prev_broken == 1:
cannot = True
break
ans *= fib(a - prev_broken - 2)
ans %= PRIME
prev_broken = a
ans *= fib(N - prev_broken - 1)
ans %= PRIME
if cannot:
print(0)
else:
print(ans)
```
No
| 86,360 |
Provide a correct Python 3 solution for this coding contest problem.
There are N cities in Republic of AtCoder. The size of the i-th city is A_{i}. Takahashi would like to build N-1 bidirectional roads connecting two cities so that any city can be reached from any other city by using these roads.
Assume that the cost of building a road connecting the i-th city and the j-th city is |i-j| \times D + A_{i} + A_{j}. For Takahashi, find the minimum possible total cost to achieve the objective.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq D \leq 10^9
* 1 \leq A_{i} \leq 10^9
* A_{i} and D are integers.
Input
Input is given from Standard Input in the following format:
N D
A_1 A_2 ... A_N
Output
Print the minimum possible total cost.
Examples
Input
3 1
1 100 1
Output
106
Input
3 1000
1 100 1
Output
2202
Input
6 14
25 171 7 1 17 162
Output
497
Input
12 5
43 94 27 3 69 99 56 25 8 15 46 8
Output
658
"Correct Solution:
```
from operator import itemgetter
import itertools
def inpl(): return list(map(int, input().split()))
def cost(x, y):
if x == y:
return float('inf')
return D * abs(x - y) + A[x] + A[y]
N, D = inpl()
A = inpl()
Right = [(v - i*D, i) for i, v in enumerate(A)]
Left = [(v + i*D, i) for i, v in enumerate(A)][::-1]
Right = list(map(itemgetter(1), itertools.accumulate(Right, min)))
Left = list(map(itemgetter(1), itertools.accumulate(Left, min)))[::-1]
ans = 0
hub = []
for i, (l, r) in enumerate(zip(Left, Right)) :
if i == l == r:
hub.append(i)
else:
ans += min(cost(i, r), cost(i, l))
print(ans + sum([cost(i, j) for i, j in zip(hub, hub[1:])]))
```
| 86,361 |
Provide a correct Python 3 solution for this coding contest problem.
There are N cities in Republic of AtCoder. The size of the i-th city is A_{i}. Takahashi would like to build N-1 bidirectional roads connecting two cities so that any city can be reached from any other city by using these roads.
Assume that the cost of building a road connecting the i-th city and the j-th city is |i-j| \times D + A_{i} + A_{j}. For Takahashi, find the minimum possible total cost to achieve the objective.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq D \leq 10^9
* 1 \leq A_{i} \leq 10^9
* A_{i} and D are integers.
Input
Input is given from Standard Input in the following format:
N D
A_1 A_2 ... A_N
Output
Print the minimum possible total cost.
Examples
Input
3 1
1 100 1
Output
106
Input
3 1000
1 100 1
Output
2202
Input
6 14
25 171 7 1 17 162
Output
497
Input
12 5
43 94 27 3 69 99 56 25 8 15 46 8
Output
658
"Correct Solution:
```
# E
N, D = map(int, input().split())
A_list = list(map(int, input().split()))
# minimum spanning tree
res = 0
# Prim based
B_list = [0]*N
for i in range(N):
B_list[i] = A_list[i] + D*i
C_list = [0]*N
for i in range(N):
C_list[i] = A_list[i] + D*(N-i)
# cummin seen from left
B_cummmin = [0]*N
R = B_list[N-1]
BA = N-1
for i in range(N-1, -1, -1):
if B_list[i] <= R:
R = B_list[i]
BA = i
B_cummmin[i] = BA
# cummin seen from right
C_cummmin = [0]*N
R = C_list[0]
CA = 0
for i in range(N):
if C_list[i] <= R:
R = C_list[i]
CA = i
C_cummmin[i] = CA
# start from 0
start = 0
while start < N-1:
end = B_cummmin[start+1]
target = C_cummmin[start]
res += D*(end - target) + A_list[target] + A_list[end]
for i in range(start+1, end):
ds = D*(i - target) + A_list[target] + A_list[i]
de = D*(end - i) + A_list[end] + A_list[i]
res += min(ds, de)
start = end
print(res)
```
| 86,362 |
Provide a correct Python 3 solution for this coding contest problem.
There are N cities in Republic of AtCoder. The size of the i-th city is A_{i}. Takahashi would like to build N-1 bidirectional roads connecting two cities so that any city can be reached from any other city by using these roads.
Assume that the cost of building a road connecting the i-th city and the j-th city is |i-j| \times D + A_{i} + A_{j}. For Takahashi, find the minimum possible total cost to achieve the objective.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq D \leq 10^9
* 1 \leq A_{i} \leq 10^9
* A_{i} and D are integers.
Input
Input is given from Standard Input in the following format:
N D
A_1 A_2 ... A_N
Output
Print the minimum possible total cost.
Examples
Input
3 1
1 100 1
Output
106
Input
3 1000
1 100 1
Output
2202
Input
6 14
25 171 7 1 17 162
Output
497
Input
12 5
43 94 27 3 69 99 56 25 8 15 46 8
Output
658
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
from heapq import heappush, heappop, heapify
from collections import defaultdict
"""
・最小値のある場所を調べる。左右にまたがる辺は結ばない。
・最小値の両隣は必ず最小値と結ぶ。
・結んだあと1点に縮約していく。
"""
N,D,*A = map(int,read().split())
A = [0] + A + [0] # 番兵
# (value<<32) + (index)
mask = (1<<32)-1
q = [(x<<32)+i for i,x in enumerate(A[1:-1],1)]
heapify(q)
removed = defaultdict(int)
cost = []
while q:
while q:
x = q[0]
if not removed[x]:
break
heappop(q); removed[x] -= 1
if not q:
break
x = heappop(q)
val,ind = x>>32, x&mask
L = A[ind-1]; R = A[ind+1]
if L:
cost.append(L+val+D)
# Lの値を書き換える
newL = val+D
if L > newL:
A[ind-1] = newL
removed[(L<<32)+(ind-1)] += 1
heappush(q,(newL<<32)+(ind-1))
if R:
cost.append(R+val+D)
# Lの値を書き換える
newR = val+D
if R > newR:
A[ind+1] = newR
removed[(R<<32)+(ind+1)] += 1
heappush(q,(newR<<32)+(ind+1))
A[ind] = 0
answer = sum(cost)
print(answer)
```
| 86,363 |
Provide a correct Python 3 solution for this coding contest problem.
There are N cities in Republic of AtCoder. The size of the i-th city is A_{i}. Takahashi would like to build N-1 bidirectional roads connecting two cities so that any city can be reached from any other city by using these roads.
Assume that the cost of building a road connecting the i-th city and the j-th city is |i-j| \times D + A_{i} + A_{j}. For Takahashi, find the minimum possible total cost to achieve the objective.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq D \leq 10^9
* 1 \leq A_{i} \leq 10^9
* A_{i} and D are integers.
Input
Input is given from Standard Input in the following format:
N D
A_1 A_2 ... A_N
Output
Print the minimum possible total cost.
Examples
Input
3 1
1 100 1
Output
106
Input
3 1000
1 100 1
Output
2202
Input
6 14
25 171 7 1 17 162
Output
497
Input
12 5
43 94 27 3 69 99 56 25 8 15 46 8
Output
658
"Correct Solution:
```
from itertools import accumulate
from operator import itemgetter
n, d = map(int, input().split())
aaa = list(map(int, input().split()))
costs_l = [(-i * d + a, i) for i, a in enumerate(aaa)]
costs_r = [(i * d + a, i) for i, a in enumerate(aaa)]
costs_l = list(accumulate(costs_l, min))
costs_r = list(accumulate(reversed(costs_r), min))
costs_r.reverse()
hubs = set(map(itemgetter(1), costs_l))
hubs.intersection_update(map(itemgetter(1), costs_r))
hubs.add(0)
hubs.add(n - 1)
hubs = sorted(hubs)
ans = sum(aaa) - aaa[-1]
s = hubs[0]
for t in hubs[1:]:
cls = costs_l[s][0]
crt = costs_r[t][0]
ans += crt - s * d
ans += sum(min(cls + i * d, crt - i * d) for i in range(s + 1, t))
s = t
print(ans)
```
| 86,364 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cities in Republic of AtCoder. The size of the i-th city is A_{i}. Takahashi would like to build N-1 bidirectional roads connecting two cities so that any city can be reached from any other city by using these roads.
Assume that the cost of building a road connecting the i-th city and the j-th city is |i-j| \times D + A_{i} + A_{j}. For Takahashi, find the minimum possible total cost to achieve the objective.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq D \leq 10^9
* 1 \leq A_{i} \leq 10^9
* A_{i} and D are integers.
Input
Input is given from Standard Input in the following format:
N D
A_1 A_2 ... A_N
Output
Print the minimum possible total cost.
Examples
Input
3 1
1 100 1
Output
106
Input
3 1000
1 100 1
Output
2202
Input
6 14
25 171 7 1 17 162
Output
497
Input
12 5
43 94 27 3 69 99 56 25 8 15 46 8
Output
658
Submitted Solution:
```
class Unionfindtree:
def __init__(self, number):
self.par = [i for i in range(number)]
self.rank = [0] * (number)
def find(self, x): # 親を探す
if self.par[x] == x:
return x
else:
self.par[x] = self.find(self.par[x])
return self.par[x]
def union(self, x, y): # x,yを繋げる
px = self.find(x)
py = self.find(y)
if px == py:
return
if self.rank[px] < self.rank[py]:
self.par[px] = py
else:
self.par[py] = px
if self.rank[px] == self.rank[py]:
self.rank[px] += 1
def connect(self, x, y): # 親が同じかみる
return self.find(x) == self.find(y)
class BIT():
def __init__(self, number):
self.n = number
self.list = [10**22] * (number + 1)
def add(self, i, x): # ith added x 1indexed
while i <= self.n:
self.list[i] = min(x,self.list[i])
i += i & -i
def search(self, i): # 1-i min
s = 10**22
while i > 0:
s = min(s,self.list[i])
i -= i & -i
return s
N,D=map(int,input().split())
A=[int(i) for i in input().split()]
lefttree = BIT(N)
dd={}
table=[]
for i in range(N):
lefttree.add(i+1,A[i]+(N-1-i)*D)
dd[A[i]+(N-1-i)*D]=i
if i>0:
s=lefttree.search(i)
y=dd[s]
table.append((A[i]+A[y]+D*abs(i-y),i,y))
#print(table)
righttree = BIT(N)
dr={}
for i in range(N-1,-1,-1):
righttree.add(N-i,A[i]+i*D)
dr[A[i]+i*D]=i
if i<N-1:
s=righttree.search(N-1-i)
#print(i, dr,s)
y=dr[s]
table.append((A[i]+A[y]+D*abs(i-y),i,y))
#print(table)
#print(table)
#print(dr)
table.sort()
uniontrees=Unionfindtree(N)
ans=0
for cost,s,t in table:
if not uniontrees.connect(s,t):
ans+=cost
uniontrees.union(s,t)
print(ans)
```
No
| 86,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cities in Republic of AtCoder. The size of the i-th city is A_{i}. Takahashi would like to build N-1 bidirectional roads connecting two cities so that any city can be reached from any other city by using these roads.
Assume that the cost of building a road connecting the i-th city and the j-th city is |i-j| \times D + A_{i} + A_{j}. For Takahashi, find the minimum possible total cost to achieve the objective.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq D \leq 10^9
* 1 \leq A_{i} \leq 10^9
* A_{i} and D are integers.
Input
Input is given from Standard Input in the following format:
N D
A_1 A_2 ... A_N
Output
Print the minimum possible total cost.
Examples
Input
3 1
1 100 1
Output
106
Input
3 1000
1 100 1
Output
2202
Input
6 14
25 171 7 1 17 162
Output
497
Input
12 5
43 94 27 3 69 99 56 25 8 15 46 8
Output
658
Submitted Solution:
```
def judT(x, y):
xR = x
xC = 0
while T[xR] != xR:
xC += 1
xR = T[xR]
yR = y
yC = 0
while T[yR] != yR:
yC += 1
yR = T[yR]
if xR != yR:
if xC < yC:
T[xR] = yR
else:
T[yR] = xR
return xR != yR
N, D = tuple(map(int,input().split()))
A = tuple(map(int, input().split()))
rt = A[N - 1]
Ll = [N - 1]
k = N - 1
for i in range(N - 2, 0, -1):
t = A[i]
if rt > t - (k - i) * D :
Ll.append(i)
k = i
rt = t
rt = A[0]
Lr = [0]
k = 0
for i in range(1, N - 1):
t = A[i]
if rt > t + (k - i) * D:
Lr.append(i)
k = i
rt = t
Lr.append(N-1)
Ll = tuple(Ll)
Lr = tuple(Lr)
L = []
lC = -1
rC = 1
lCmax = -len(Ll) - 1
for i in range(N-1):
if i >= Ll[lC]:
lC -= 1
for j in range(lC, lCmax, -1):
t = Ll[j]
if A[i] >= A[t]:
L.append((A[i] + A[t] + (t - i) * D, i, t))
break
k = i + 1
if k > Lr[rC]:
rC += 1
for j in range(rC - 1, -1, -1):
t = Lr[j]
if A[k] > A[t]:
L.append((A[k] + A[t] + (k - t) * D, t, k))
break
L.sort()
T = [i for i in range(N)]
C = 0
A = 0
for i in L:
if judT(i[1], i[2]):
C += 1
A += i[0]
#print(i)
if C == N-1:
break
print(A)
```
No
| 86,366 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cities in Republic of AtCoder. The size of the i-th city is A_{i}. Takahashi would like to build N-1 bidirectional roads connecting two cities so that any city can be reached from any other city by using these roads.
Assume that the cost of building a road connecting the i-th city and the j-th city is |i-j| \times D + A_{i} + A_{j}. For Takahashi, find the minimum possible total cost to achieve the objective.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq D \leq 10^9
* 1 \leq A_{i} \leq 10^9
* A_{i} and D are integers.
Input
Input is given from Standard Input in the following format:
N D
A_1 A_2 ... A_N
Output
Print the minimum possible total cost.
Examples
Input
3 1
1 100 1
Output
106
Input
3 1000
1 100 1
Output
2202
Input
6 14
25 171 7 1 17 162
Output
497
Input
12 5
43 94 27 3 69 99 56 25 8 15 46 8
Output
658
Submitted Solution:
```
# from typing import Callable
def connecting_cities(N: int, D: int, A: list) -> int:
edges = select_edges(N, D, A)
edges = sorted(edges, key=lambda x: x[2], reverse=True)
uft = UnionFindTree(N)
count = 0
while not len(edges) == 0:
u, v, d = edges.pop()
if not uft.same(u, v):
uft.summarize(u, v)
count += d
return count
def select_edges(N: int, D: int, A: list) -> list:
INF = 1 << 32
st_l = SegmentTree(N, lambda x, y: x if x[0] < y[0] else y, (INF, -1))
st_r = SegmentTree(N, lambda x, y: x if x[0] < y[0] else y, (INF, -1))
indexes_A = sorted([i for i in range(N)], key=lambda x: A[x])
edges = []
for i in indexes_A:
la, li = st_l.range(0, i)
if la < INF and li != -1:
edges.append((li, i, abs(i - li) * D + A[i] + A[li]))
ra, ri = st_r.range(i, N)
if ra < INF and ri != -1:
edges.append((ri, i, abs(i - ri) * D + A[i] + A[ri]))
st_l.update(i, (A[i] + (N - i) * D, i))
st_r.update(i, (A[i] + i * D, i))
# return [(i, j, abs(i - j) * D + A[i] + A[j])
# for i in range(N) for j in range(i + 1, N)]
return edges
class SegmentTree:
# def __init__(self, size: int, op: Callable[[any, any], any], init: any = 0):
def __init__(self, size, op, init):
"""initialize SegmentTree
:param size: Size of tree. This must be natural number.
:param op: Operator which compares two numbers. This function return the
representative value of two arguments.
:param init: The initial value of element of tree.
"""
if size < 1:
raise Exception('size must be greater than 0 (actual = %d)' % size)
self.__treesize = 1
self.__init = init
# tree size is the minimum number which is greater than or equal to
# designed `size` and is power of 2.
while self.__treesize < size:
self.__treesize *= 2
self.__size = self.__treesize
self.__treesize = self.__treesize * 2 - 1
self.__comp = op
# initialize tree
self.__tree = [init for _ in range(self.__treesize)]
def range(self, l: int, r: int) -> int:
"""Returns the representative value in range [l, r)
:param l: left value(include)
:param r: right value(not include)
:return: the representative value in range[l, r)
"""
return self.__range(l, r, 0, 0, self.__size)
def __range(self, l: int, r: int, k: int, kl: int, kr: int) -> int:
"""
:param l: left value (include)
:param r: right value (not include)
:param k: node index
:param kl: left value of node
:param kr: right value of node
"""
if kr <= l or r <= kl:
# no crossing
return self.__init
if l <= kl and kr <= r:
# including whole k's range
return self.__tree[k]
vl = self.__range(l, r, 2 * k + 1, kl, (kl + kr) // 2)
vr = self.__range(l, r, 2 * k + 2, (kl + kr) // 2, kr)
if vl is None:
return vr
if vr is None:
return vl
return self.__comp(vl, vr)
def update(self, index: int, val: int):
"""update value at self.__tree[index]'s value
"""
index += self.__size - 1
self.__tree[index] = val
while index > 0:
index = (index - 1) // 2
self.__tree[index] = self.__comp(
self.__tree[2*index + 1], self.__tree[2*index + 2])
def print(self):
"""for debug
"""
print(self.__tree)
class UnionFindTree:
def __init__(self, size: int):
"""UnionFindTreeを初期化します
:param size: サイズ
:return: UnionFindTree
"""
if size < 0:
raise Exception('size must be greater than 0.')
self.__parent = [-1] * size
def summarize(self, a: int, b: int):
"""aを含む木とbを含む木をまとめます
:param a: 木a
:param b: 木b
"""
a = self.__root(a)
b = self.__root(b)
if a != b:
self.__parent[b] = a
def __root(self, a: int) -> int:
"""aの根を求めます
:param a: 木の要素
:return: 根
"""
if self.__parent[a] == -1:
return a
else:
return self.__root(self.__parent[a])
def same(self, a: int, b: int) -> bool:
"""a と b が同じ木に属するかを判断します
:param a: 木
:param b: 木
:return: a と b が同じ木なら True。そうでないなら False。
"""
return self.__root(a) == self.__root(b)
if __name__ == "__main__":
N, D = [int(s) for s in input().split()]
A = [int(s) for s in input().split()]
ans = connecting_cities(N, D, A)
print(ans)
```
No
| 86,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N cities in Republic of AtCoder. The size of the i-th city is A_{i}. Takahashi would like to build N-1 bidirectional roads connecting two cities so that any city can be reached from any other city by using these roads.
Assume that the cost of building a road connecting the i-th city and the j-th city is |i-j| \times D + A_{i} + A_{j}. For Takahashi, find the minimum possible total cost to achieve the objective.
Constraints
* 1 \leq N \leq 2 \times 10^5
* 1 \leq D \leq 10^9
* 1 \leq A_{i} \leq 10^9
* A_{i} and D are integers.
Input
Input is given from Standard Input in the following format:
N D
A_1 A_2 ... A_N
Output
Print the minimum possible total cost.
Examples
Input
3 1
1 100 1
Output
106
Input
3 1000
1 100 1
Output
2202
Input
6 14
25 171 7 1 17 162
Output
497
Input
12 5
43 94 27 3 69 99 56 25 8 15 46 8
Output
658
Submitted Solution:
```
import numpy as np
InputData1 = input()
InputData2 = input()
Lines = [data.split(" ") for data in [InputData1, InputData2]]
InputNumbers = [int(numbers) for line in Lines for numbers in line]
N = InputNumbers[0]
D = InputNumbers[1]
A = InputNumbers[2:]
# print(N, D, A)
def NetworkMatrix(Num, vector):
matrix = np.empty((Num, Num))
for i in range(Num):
ai = np.empty(Num)
for j in range(Num):
if i < j:
aij = (j-i)*D + vector[i] + vector[j]
else:
aij = 0
ai[j] = aij
matrix[i] = ai
return matrix
def Explore(Num, matrix):
ResultMatrix = matrix
for i in range(Num):
# ResultVector[i] = min(matrix.T[i])
for j in range(Num):
for k in range(Num):
if i < j and j < k and min([matrix[i,j], matrix[j,k], matrix[i,k]]) != 0:
if matrix[i,j] >= matrix[j,k] and matrix[i,j] >= matrix[i,k]:
ResultMatrix[i,j] = 0
elif matrix[j,k] > matrix[i,j] and matrix[j,k] >= matrix[i,k]:
ResultMatrix[j,k] = 0
elif matrix[i,k] > matrix[i,j] and matrix[i,k] > matrix[j,k]:
ResultMatrix[i,k] = 0
if np.sum(ResultMatrix != matrix) != 0:
ResultMatrix = Explore(Num, matrix)
return ResultMatrix
Matrix = NetworkMatrix(N, A)
# print(Matrix)
# Raveled = Matrix.ravel()
# Answer = sum(sorted(Raveled)[:N-1])
AnswerMatrix=Explore(N, Matrix)
# print(AnswerMatrix)
print(int(np.sum(AnswerMatrix)))
```
No
| 86,368 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
"Correct Solution:
```
from fractions import*;exec("a,b,c,d=map(int,input().split());g=gcd(b,d);print('YNeos'[b>min(a,d)or b-g+a%g>c::2]);"*int(input()))
```
| 86,369 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
"Correct Solution:
```
T=int(input())
ABCD=[list(map(int,input().split())) for i in range(T)]
from fractions import gcd
def f(a):
print(['No','Yes'][a])
for a,b,c,d in ABCD:
if a<b:f(0)
elif d<b:f(0)
elif b<=c:f(1)
else:
g=gcd(b,d)
h=a%b
f(max(((b-h)//g*g+h)%b,b-g)<=c)
```
| 86,370 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
"Correct Solution:
```
def main():
import math
def gcd(a, b):
while b:
a, b = b, a % b
return a
N = int(input())
ABCD = [list(map(int, input().split())) for i in range(N)]
for A,B,C,D in ABCD:
# 在庫が買う本数以下 or 在庫追加が買う本数以下
if A < B or D < B:
print("No")
continue
A %= B
# 在庫が買う本数以下になり、補給出来ない
if C < A:
print("No")
continue
if B == D:
print("Yes")
continue
flag = True
#print((B-A-1)%(D-B) ,">", (B-1)-(C+1))
if (B-A-1)%(gcd(D,B)) <= (B-1)-(C+1):
flag = False
print("Yes" if flag else "No")
if __name__ == '__main__':
main()
```
| 86,371 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
"Correct Solution:
```
def gcd(a,b):
if b== 0:
return a
else:
return gcd(b,a%b)
t = int(input())
abcd = []
ans = "No"
for i in range(0,t):
ABCD = list(map(int,input().split()))
abcd.append(ABCD)
for a,b,c,d in abcd:
if a >= b and b==d and b <= c:
ans = "Yes"
if a >= b and d >= b and b > c and b - gcd(d,b) + a%gcd(d,b) <= c:
ans = "Yes"
if a >= b and d >= b and b <= c:
ans = "Yes"
print(ans)
ans = "No"
```
| 86,372 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
"Correct Solution:
```
printn = lambda x: print(x,end='')
inn = lambda : int(input())
inl = lambda: list(map(int, input().split()))
inm = lambda: map(int, input().split())
ins = lambda : input().strip()
DBG = True # and False
BIG = 10**18
R = 10**9 + 7
def ddprint(x):
if DBG:
print(x)
import fractions
t = inn()
for i in range(t):
a,b,c,d = inm()
if a<b or d<b:
print('No')
else:
g = fractions.gcd(b,d)
r = a%g
q = c%g
p = c-q+r
if p<=c:
p += g
#ddprint(f"a {a} b {b} c {c} d {d} g {g} r {r} q {q} p {p}")
if p>=b:
print('Yes')
else:
print('No')
```
| 86,373 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
"Correct Solution:
```
# coding: utf-8
# Your code here!
import fractions
def isok(a,b,c,d):
if a < b or b > d:
print('No')
return
g= fractions.gcd(d, b)
r=((c-a%g)//g)*g+a%g
# print(r)
if r+g-b < 0:
print('No')
else:
print('Yes')
T=int(input())
for _ in range(T):
a,b,c,d = list(map(int,input().split()))
isok(a,b,c,d)
```
| 86,374 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
"Correct Solution:
```
import sys
input = sys.stdin.readline
sys.setrecursionlimit(10 ** 7)
def gcd(a, b):
if b == 0:
return a
else:
return gcd(b, a % b)
import math
import decimal
ctx = decimal.Context(prec=3, rounding=decimal.ROUND_CEILING)
for i in range(int(input())):
a, b, c, d = map(int, input().split())
if a < b:
print('No')
continue
if b > d:
print('No')
continue
if c >= b:
print('Yes')
continue
g = gcd(b, d)
r = a % g
# FYI: https://stackoverflow.com/questions/2795946/getting-ceil-of-decimal-in-python
_max = (int(((decimal.Decimal(b, context=ctx) - decimal.Decimal(r, context=ctx)) / decimal.Decimal(g, context=ctx)).to_integral_exact(context=ctx)) * g) + r - g
# math.ceilは精度不足でエラーになる: https://cocoinit23.com/math-floor-ceil-error/
#_max = ((math.ceil((b - r) / g)) * g) + r - g
# OK: (a + b - 1) // b: https://nariagari-igakusei.com/cpp-division-round-up/
#_max = ((b - r + g - 1)//g) * g + r - g
if c < _max:
print('No')
else:
print('Yes')
```
| 86,375 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
"Correct Solution:
```
T = int(input())
def gcd(a, b):
if a < b:
a, b = b, a
if b == 0:
return 0
while a % b:
a, b = b, a % b
return b
while T:
T -= 1
A, B, C, D = map(int, input().split())
if B > A or B > D:
print("No")
else:
p = A - (A - C + B - 1) // B * B
r = D % B
g = gcd(r, B - r)
if p < 0:
print("No")
elif r == 0 or (C - r - p + g) // g * g + p - B + r >= 0:
print("Yes")
else:
print("No")
```
| 86,376 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Submitted Solution:
```
import sys
input = sys.stdin.readline
from fractions import gcd
def f(a,b,c,d):
if a<b:
return 0
if b>d:
return 0
if b-1<=c:
return 1
x=a%b
#print(3)
if b==d:
if c<x:
return 0
elif c>=x:
return 1
#print(4)
if c<x:
return 0
e=(d-b)%b
d1=gcd(e,b)
q=(c+1-x)//d1
q1=(b-1-x)//d1
#print(d1,q,q1,x,(c+1-x)%d1)
if q<q1:
return 0
if (c+1-x)%d1==0:
return 0
return 1
T=int(input())
X=[[int(i) for i in input().split()] for i in range(T)]
for a,b,c,d in X:
s=f(a,b,c,d)
if s:
print('Yes')
else:
print('No')
```
Yes
| 86,377 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Submitted Solution:
```
def gcd(a, b):
return a if b == 0 else gcd(b, a % b)
def solve(a, b, c, d):
if a < b or d < b:
return False
if b < c:
return True
g = gcd(b, d)
return (b + a % g - g) <= c
T, *L = map(int, open(0).read().split())
for t in zip(*[iter(L)] * 4):
print("Yes" if solve(*t) else "No")
```
Yes
| 86,378 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Submitted Solution:
```
def gcd(a, b):
while b:
a, b = b, a % b
return(a)
T = int(input())
for i in range(T):
A,B,C,D = map(int,input().split())
if B > D:
print('No')
elif A < B:
print('No')
elif C + 1 >= B:
print('Yes')
else:
q = gcd(B,D)
r = (A-C)%q
if r == 0:
r = q
if C + r >= B:
print('Yes')
else:
print('No')
```
Yes
| 86,379 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Submitted Solution:
```
# -*- coding: utf-8 -*-
import sys
from fractions import gcd
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
sys.setrecursionlimit(10 ** 9)
INF = 10 ** 19
MOD = 10 ** 9 + 7
def bisearch_min(mn, mx, func):
""" 条件を満たす最小値を見つける二分探索 """
ok = mx
ng = mn
while ng+1 < ok:
mid = (ok+ng) // 2
if func(mid):
# 下を探しに行く
ok = mid
else:
# 上を探しに行く
ng = mid
return ok
def bisearch_max(mn, mx, func):
""" 条件を満たす最大値を見つける二分探索 """
ok = mn
ng = mx
while ok+1 < ng:
mid = (ok+ng) // 2
if func(mid):
# 上を探しに行く
ok = mid
else:
# 下を探しに行く
ng = mid
return ok
for _ in range(INT()):
a, b, c, d = MAP()
# そもそも無理
if a < b or d < b:
No()
continue
# b個減ってd個増える繰り返しなので、このgより細かく値が動くことはない
g = gcd(b, d)
# cより大きくてb未満が存在するかどうか
mn = bisearch_min(-INF, INF, lambda m: a%g + g*m > c)
mx = bisearch_max(-INF, INF, lambda m: a%g + g*m < b)
if mn > mx:
Yes()
else:
No()
```
Yes
| 86,380 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Submitted Solution:
```
import math
T = int(input())
for i in range(T) :
A,B,C,D = map(int,input().split())
a1 = A-B
d = D-B
P = (C+d-a1)/d
Q = (B+d-a1)/d
PP = math.floor(P)
QQ = math.floor((Q))
if P != PP :
if PP != QQ :
print("No")
else :
print("Yes")
```
No
| 86,381 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Submitted Solution:
```
t = int(input())
for i in range(t):
a, b, c, d = map(int, input().split())
if a>=b and c >=b-1 and d>=b:
print("Yes")
else:
print("No")
```
No
| 86,382 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Submitted Solution:
```
#coding:utf-8
T = int(input())
for i in range(T):
a,b,c,d = map(int,input().split())
if b > d:
print("No")
elif a < b:
print("No")
else:
sur = a % b
while sur != a:
a += d
if c < a % b:
print("No")
break
a %= b
else:
print("Yes")
```
No
| 86,383 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo Mart, a convenience store, sells apple juice.
On the opening day of Ringo Mart, there were A cans of juice in stock in the morning. Snuke buys B cans of juice here every day in the daytime. Then, the manager checks the number of cans of juice remaining in stock every night. If there are C or less cans, D new cans will be added to the stock by the next morning.
Determine if Snuke can buy juice indefinitely, that is, there is always B or more cans of juice in stock when he attempts to buy them. Nobody besides Snuke buy juice at this store.
Note that each test case in this problem consists of T queries.
Constraints
* 1 \leq T \leq 300
* 1 \leq A, B, C, D \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
T
A_1 B_1 C_1 D_1
A_2 B_2 C_2 D_2
:
A_T B_T C_T D_T
In the i-th query, A = A_i, B = B_i, C = C_i, D = D_i.
Output
Print T lines. The i-th line should contain `Yes` if Snuke can buy apple juice indefinitely in the i-th query; `No` otherwise.
Examples
Input
14
9 7 5 9
9 7 6 9
14 10 7 12
14 10 8 12
14 10 9 12
14 10 7 11
14 10 8 11
14 10 9 11
9 10 5 10
10 10 5 10
11 10 5 10
16 10 5 10
1000000000000000000 17 14 999999999999999985
1000000000000000000 17 15 999999999999999985
Output
No
Yes
No
Yes
Yes
No
No
Yes
No
Yes
Yes
No
No
Yes
Input
24
1 2 3 4
1 2 4 3
1 3 2 4
1 3 4 2
1 4 2 3
1 4 3 2
2 1 3 4
2 1 4 3
2 3 1 4
2 3 4 1
2 4 1 3
2 4 3 1
3 1 2 4
3 1 4 2
3 2 1 4
3 2 4 1
3 4 1 2
3 4 2 1
4 1 2 3
4 1 3 2
4 2 1 3
4 2 3 1
4 3 1 2
4 3 2 1
Output
No
No
No
No
No
No
Yes
Yes
No
No
No
No
Yes
Yes
Yes
No
No
No
Yes
Yes
Yes
No
No
No
Submitted Solution:
```
t = int(input())
abcd = [[int(i) for i in input().split()] for i in range(t)]
counter = 0
for qu in abcd:
if qu[0] < qu[1]:
print("No")
elif qu[1]-1<=qu[2]:
if qu[3] < qu[1]:
print("No")
else:
print("Yes")
else:
amod = qu[0]%qu[1]
dmod = qu[3]%qu[1]
deadzone = range(qu[2]+1,qu[1])
cycle = []
flag = True
while(flag):
if amod in deadzone:
print("No")
flag = False
elif amod in cycle:
print("Yes")
flag = False
else:
cycle.append(amod)
amod = (amod + dmod) % qu[1]
```
No
| 86,384 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
"Correct Solution:
```
print("EOvdedn"[eval(input().replace(" ","*"))%2::2])
```
| 86,385 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
"Correct Solution:
```
a, b = map(int, input().split()); print('Even') if a*b%2 == 0 else print('Odd')
```
| 86,386 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
"Correct Solution:
```
print('EOvdedn'[eval(input().replace(' ','*')+'%2')::2])
```
| 86,387 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
"Correct Solution:
```
print('EOvdedn'[sum(s in'04'for s in input())<1::2])
```
| 86,388 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
"Correct Solution:
```
a,b=[int(x) for x in input().split()]
print("Odd" if a*b%2==1 else "Even")
```
| 86,389 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
"Correct Solution:
```
a, b = map(int,input().split())
print('Even' if (a*b%2 == 0) else 'Odd')
```
| 86,390 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
"Correct Solution:
```
a, b = map(int, input().split())
print('Odd' if a*b%2 != 0 else 'Even')
```
| 86,391 |
Provide a correct Python 3 solution for this coding contest problem.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
"Correct Solution:
```
a,b = map(int, input().split())
print('EOvdedn'[a*b%2==1::2])
```
| 86,392 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, input().split())
if a * b % 2: print('Odd')
else: print('Even')
```
Yes
| 86,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, input().split())
print(a*b % 2 and 'Odd' or 'Even')
```
Yes
| 86,394 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, input().split())
print(["Even", "Odd"][a * b % 2])
```
Yes
| 86,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, (input().split()))
print("Even" if a * b % 2 == 0 else "Odd")
```
Yes
| 86,396 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a = int(input())
b = int(input())
if a*b % 2 == 0:
print("Even")
else:
print("Odd")
```
No
| 86,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = map(int, input().split())
if (a*b) % 2:
print(‘Odd’)
else:
print(‘Even’)
```
No
| 86,398 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
AtCoDeer the deer found two positive integers, a and b. Determine whether the product of a and b is even or odd.
Constraints
* 1 ≤ a,b ≤ 10000
* a and b are integers.
Input
Input is given from Standard Input in the following format:
a b
Output
If the product is odd, print `Odd`; if it is even, print `Even`.
Examples
Input
3 4
Output
Even
Input
1 21
Output
Odd
Submitted Solution:
```
a, b = tuple(int(num) for input().split())
ab = a * b
if ab % 2:
print('Odd')
else:
print('Even')
```
No
| 86,399 |
Subsets and Splits
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