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Theorem 3.7.1. Let \( {F}^{\prime }/{K}^{\prime } \) be a Galois extension of \( F/K \) and \( {P}_{1},{P}_{2} \in {\mathbb{P}}_{{F}^{\prime }} \) be extensions of \( P \in {\mathbb{P}}_{F} \) . Then \( {P}_{2} = \sigma \left( {P}_{1}\right) \) for some \( \sigma \in \operatorname{Gal}\left( {{F}^{\prime }/F}\right) \)...
Proof. Assume that the assertion is false; i.e., \( \sigma \left( {P}_{1}\right) \neq {P}_{2} \) for all \( \sigma \in G \mathrel{\text{:=}} \) \( \operatorname{Gal}\left( {{F}^{\prime }/F}\right) \) . By the Approximation Theorem there is an element \( z \in {F}^{\prime } \) such that \( {v}_{{P}_{2}}\left( z\right) >...
Yes
Corollary 3.7.2. Notation as in Theorem 3.7.1 (in particular \( {F}^{\prime }/F \) is a Galois extension). Let \( {P}_{1},\ldots ,{P}_{r} \) be all the places of \( {F}^{\prime } \) lying over \( P \) . Then we have:\n\n(a) \( e\left( {{P}_{i} \mid P}\right) = e\left( {{P}_{j} \mid P}\right) \) and \( f\left( {{P}_{i} ...
Proof. (a) is obvious by Theorem 3.7.1 and Lemma 3.5.2, and (b) is an immediate consequence of (a) and Theorem 3.1.11. As to (c), we have to consider the integral closure\n\n\[ {\mathcal{O}}_{P}^{\prime } = \mathop{\bigcap }\limits_{{i = 1}}^{r}{\mathcal{O}}_{{P}_{i}} \]\n\nof \( {\mathcal{O}}_{P} \) in \( {F}^{\prime ...
Yes
Proposition 3.7.3 (Kummer Extensions). Let \( F/K \) be an algebraic function field where \( K \) contains a primitive \( n \) -th root of unity (with \( n > 1 \) and \( n \) relatively prime to the characteristic of \( K \) ). Suppose that \( u \in F \) is an element satisfying\n\n\[ u \neq {w}^{d}\;\text{ for all }w ...
We note that every cyclic field extension \( {F}^{\prime }/F \) of degree \( n \) is a Kummer extension, provided that \( n \) is relatively prime to the characteristic of \( F \) and \( F \) contains all \( n \) -th roots of unity. This fact is well-known from Galois theory, cf. Appendix A.
No
Assume char \( K \neq 2 \) . Let \( F = K\left( {x, y}\right) \) with\n\n\[ \n{y}^{2} = f\left( x\right) = {p}_{1}\left( x\right) \cdot \ldots \cdot {p}_{s}\left( x\right) \in K\left\lbrack x\right\rbrack ,\n\]\n\nwhere \( {p}_{1}\left( x\right) ,\ldots ,{p}_{s}\left( x\right) \) are distinct irreducible monic polynomi...
Proof. We have \( F = {F}_{0}\left( y\right) \) where \( {F}_{0} = K\left( x\right) \) is the rational function field. Let \( {P}_{i} \in {\mathbb{P}}_{K\left( x\right) } \) denote the zero of \( {p}_{i}\left( x\right) \) and \( {P}_{\infty } \) the pole of \( x \) in \( K\left( x\right) \) . Then \( {v}_{{P}_{i}}\left...
Yes
Proposition 3.7.8 (Artin-Schreier Extensions). Let \( F/K \) be an algebraic function field of characteristic \( p > 0 \). Suppose that \( u \in F \) is an element which satisfies the following condition:\n\n\[ u \neq {w}^{p} - w\;\text{ for all }w \in F. \]\n\nLet\n\n\[ {F}^{\prime } = F\left( y\right) \;\text{ with }...
Proof. (a) This is well-known from Galois theory, see Appendix A.\n\n(b) and (c) First we consider the case \( {m}_{P} = - 1 \) ; i.e., \( {v}_{P}\left( {u - \left( {{z}^{p} - z}\right) }\right) \geq 0 \) for some \( z \in F \). Let \( {y}_{1} = y - z \) and \( {u}_{1} = u - \left( {{z}^{p} - z}\right) \) ; then \( {F}...
Yes
Theorem 3.8.2. With notation as above the following hold:\n\n(a) The decomposition group \( {G}_{Z}\left( {{P}^{\prime } \mid P}\right) \) has order \( e\left( {{P}^{\prime } \mid P}\right) \cdot f\left( {{P}^{\prime } \mid P}\right) \) .
Proof. (a) By Theorem 3.7.1 \( G \) acts transitively on the set of extensions of \( P \) in \( {F}^{\prime } \) . So we can choose \( {\sigma }_{1},\ldots ,{\sigma }_{r} \in G \) such that \( {\sigma }_{1}\left( {P}^{\prime }\right) ,\ldots ,{\sigma }_{r}\left( {P}^{\prime }\right) \) are all places of \( {F}^{\prime ...
Yes
Theorem 3.8.3. Consider a Galois extension \( {F}^{\prime }/F \) of algebraic function fields, a place \( P \in {\mathbb{P}}_{F} \) and an extension \( {P}^{\prime } \) of \( F \) in \( {F}^{\prime } \) . For an intermediate field \( F \subseteq M \subseteq {F}^{\prime } \) let \( {P}_{M} \mathrel{\text{:=}} {P}^{\prim...
Proof. By Theorem 3.8.2(d) all implications \( \Rightarrow \) are obvious. Before proving the converse, we remark that the decomposition group of \( {P}^{\prime } \) over \( {P}_{M} \) is contained in \( {G}_{Z}\left( {{P}^{\prime } \mid P}\right) \), and the inertia group of \( {P}^{\prime } \) over \( {P}_{M} \) is c...
Yes
Proposition 3.8.5. With the above notations we have:\n\n(a) \( {G}_{-1} = {G}_{Z}\left( {{P}^{\prime } \mid P}\right) \) and \( {G}_{0} = {G}_{T}\left( {{P}^{\prime } \mid P}\right) \) . In particular, \( \operatorname{ord}{G}_{0} = e\left( {{P}^{\prime } \mid P}\right) \) .\n\n(b) \( {G}_{-1} \supseteq {G}_{0} \supset...
Proof. (a) and (b) are obvious.\n\n(c) Consider the inertia field \( T \) of \( {P}^{\prime } \) over \( P \), the restriction \( {P}_{T} = {P}^{\prime } \cap T \) and the corresponding valuation ring \( {\mathcal{O}}_{{P}_{T}} = {\mathcal{O}}_{{P}^{\prime }} \cap T \) . The elements \( 1, t,\ldots ,{t}^{e - 1} \) (whe...
Yes
Theorem 3.8.7 (Hilbert's Different Formula). Consider a Galois extension \( {F}^{\prime }/F \) of algebraic function fields, a place \( P \in {\mathbb{P}}_{F} \) and a place \( {P}^{\prime } \in {\mathbb{P}}_{{F}^{\prime }} \) lying over \( P \) . Then the different exponent \( d\left( {{P}^{\prime } \mid P}\right) \) ...
Proof. First we assume that \( {P}^{\prime } \mid P \) is totally ramified; i.e., \( G \mathrel{\text{:=}} \operatorname{Gal}\left( {{F}^{\prime }/F}\right) = \) \( {G}_{0}\left( {{P}^{\prime } \mid P}\right) \) . Set \( {e}_{i} \mathrel{\text{:=}} \operatorname{ord}{G}_{i}\left( {{P}^{\prime } \mid P}\right) \) (for \...
Yes
Lemma 3.9.2. Let \( G \) be a finite group and \( U \subseteq G \) be a normal subgroup such that \( \operatorname{ord}U = {p}^{n} \) (with either \( p = 1 \) or else, \( p \) a prime number) and \( G/U \) is cyclic of order relatively prime to p. Suppose that \( {H}_{1} \) is a subgroup of \( G \) with \( {p}^{n} \mid...
Proof of the Lemma. Clearly the order of \( {H}_{1} \cap {H}_{2} \) divides the orders of \( {H}_{1} \) and of \( {H}_{2} \), thus\n\n\[ \operatorname{ord}\left( {{H}_{1} \cap {H}_{2}}\right) \mid \gcd \left( {\operatorname{ord}{H}_{1},\operatorname{ord}{H}_{2}}\right) . \]\n\nWe set ord \( {H}_{1} = {a}_{1}{p}^{n} \) ...
Yes
Corollary 3.9.3. Let \( {F}^{\prime }/F \) be a finite separable extension of function fields and let \( P \) be a place of \( F \). (a) Suppose that \( {F}^{\prime } = {F}_{1}{F}_{2} \) is the compositum of two intermediate fields \( F \subseteq {F}_{1},{F}_{2} \subseteq {F}^{\prime } \). If \( P \) is unramified in \...
Proof. (a) This is just a special case of Theorem 3.9.1.\n\n(b) The Galois closure \( {F}^{\prime } \) of \( {F}_{0}/F \) is the compositum of the fields \( \sigma \left( {F}_{0}\right) \), where \( \sigma \) runs through all embeddings \( \sigma : {F}_{0} \rightarrow \bar{F} \) over \( F \) (where \( \bar{F} \supseteq...
Yes
Lemma 3.9.5. Let \( {F}_{0}/F \) be a finite separable extension of function fields and let \( {F}^{\prime } \supseteq {F}_{0} \) be the Galois closure of \( {F}_{0}/F \) . Assume that a place \( P \in {\mathbb{P}}_{F} \) is completely splitting in \( {F}_{0}/F \) . Then \( P \) splits completely in \( {F}^{\prime }/F ...
Proof. Let \( {P}^{\prime } \) be a place of \( {F}^{\prime } \) lying above \( P \) and consider the decomposition field \( Z \mathrel{\text{:=}} Z\left( {{P}^{\prime } \mid P}\right) \subseteq {F}^{\prime } \) (see Definition 3.8.1). Set \( {P}_{0} \mathrel{\text{:=}} {P}^{\prime } \cap {F}_{0} \) . Since \( P \) spl...
Yes
Proposition 3.9.6. Let \( {F}^{\prime }/F \) be a finite separable extension of function fields and let \( {F}_{1},{F}_{2} \) be intermediate fields of \( {F}^{\prime }/F \) such that \( {F}^{\prime } = {F}_{1}{F}_{2} \) is their compositum.\n\n(a) Suppose that \( P \) is a place of \( F \) which splits completely in t...
Proof. (a) Let \( E/F \) be the Galois closure of \( {F}_{1}/F \) ; then \( P \) splits completely in the extension \( E/F \) by Lemma 3.9.5. We consider the compositum \( {E}^{\prime } \mathrel{\text{:=}} E{F}_{2} \) . By Galois theory we know that the extension \( {E}^{\prime }/{F}_{2} \) is Galois, and the Galois gr...
Yes
Corollary 3.9.7. Let \( F/K \) be a function field whose full constant field is \( K \) . (a) Suppose that \( {F}^{\prime } = {F}_{1}{F}_{2} \) is the compositum of two finite separable extensions \( {F}_{1}/F \) and \( {F}_{2}/F \) . Assume that there exists a place \( P \in {\mathbb{P}}_{F} \) of degree one which spl...
Proof. (a) We only have to show that \( K \) is the full constant field of \( {F}^{\prime } = {F}_{1}{F}_{2} \) ; the remaining assertions follow immediately from Proposition 3.9.6. We choose a place \( {P}^{\prime } \) of \( {F}^{\prime } \) lying above \( P \), then \( f\left( {{P}^{\prime } \mid P}\right) = 1 \) and...
Yes
Lemma 3.10.1. Suppose \( {F}^{\prime }/F \) is a purely inseparable field extension of degree \( p \) . Then \( K \) is the constant field of \( {F}^{\prime } \) as well. Every place \( P \in {\mathbb{P}}_{F} \) has only one extension \( {P}^{\prime } \in {\mathbb{P}}_{{F}^{\prime }} \), namely\n\n\[ \n{P}^{\prime } = ...
Proof. Let \( a \in {F}^{\prime } \) be algebraic over \( K \) . Since \( {F}^{\prime }/F \) is purely inseparable of degree \( p \), we have \( {a}^{p} \in F \) and \( {a}^{p} \) is algebraic over \( K \) . As \( K \) is the constant field of \( F \) this shows that \( {a}^{p} \in K \) . But \( K \) is perfect, so \( ...
Yes
Proposition 3.10.2. (a) Assume \( z \in F \) satisfies \( {v}_{P}\left( z\right) ≢ 0{\;\operatorname{mod}\;p} \) for some \( P \in {\mathbb{P}}_{F} \) . Then \( z \) is a separating element for \( F/K \) . In particular \( F/K \) is separably generated.
Proof. (a) Suppose that \( z \) is not separating. The extension \( F/K\left( z\right) \) is of finite degree since \( z \notin K \), hence there is an intermediate field \( K\left( z\right) \subseteq {F}_{s} \subseteq F \) such that \( F/{F}_{s} \) is purely inseparable of degree \( p \) . Let \( {P}_{s} \mathrel{\tex...
Yes
Proposition 3.11.1. Let \( {F}_{1}/K \) be a subfield of \( F/K \) and \( \left\lbrack {F : {F}_{1}}\right\rbrack = n \) . Assume that \( \left\{ {{z}_{1},\ldots ,{z}_{n}}\right\} \) is a basis of \( F/{F}_{1} \) such that all \( {z}_{i} \in \mathcal{L}\left( C\right) \) for some divisor \( C \in \operatorname{Div}\lef...
Proof. Let \( {A}_{1} \) be a divisor of \( {F}_{1}/K \) of sufficiently large degree such that\n\n\[ \ell \left( {A}_{1}\right) = : t = \deg {A}_{1} + 1 - {g}_{1}. \]\n\nChoose a basis \( \left\{ {{x}_{1},\ldots ,{x}_{t}}\right\} \subseteq {F}_{1} \) of \( \mathcal{L}\left( {A}_{1}\right) \) . Set \( A \mathrel{\text{...
Yes
Lemma 3.11.2. Assume that \( K \) is algebraically closed, and consider a subfield \( {F}_{1}/K \) of \( F/K \) such that \( F/{F}_{1} \) is separable of degree \( \left\lbrack {F : {F}_{1}}\right\rbrack = n > 1 \) . Let \( y \in F \) be an element with \( F = {F}_{1}\left( y\right) \) . Then almost all \( P \in {\math...
Proof. Let \( \varphi \left( T\right) = {T}^{n} + {z}_{n - 1}{T}^{n - 1} + \cdots + {z}_{0} \in {F}_{1}\left\lbrack T\right\rbrack \) be the minimal polynomial of \( y \) over \( {F}_{1} \) . For almost all \( P \in {\mathbb{P}}_{{F}_{1}} \) the following hold:\n\n\[ \left\{ {1, y,\ldots ,{y}^{n - 1}}\right\} \text{is ...
Yes
Proposition 3.11.5. Consider an algebraic function field \( F = K\left( {x, y}\right) \) over \( K \), where the irreducible equation of \( y \) over \( K\left( x\right) \) has the form\n\n\[ \n{y}^{n} + {f}_{1}\left( x\right) {y}^{n - 1} + \ldots + {f}_{n - 1}\left( x\right) y + {f}_{n}\left( x\right) = 0 \n\]\n\n(3.1...
Proof. The proof is similar to that of Proposition 3.11.1. Let \( A \mathrel{\text{:=}} {\left( x\right) }_{\infty } \) denote the pole divisor of \( x \) in \( F \) . It is a positive divisor of degree \( n \) . We claim that\n\n\[ \n{v}_{P}\left( y\right) \geq - {v}_{P}\left( A\right) \text{ for all }P \in {\mathbb{P...
Yes
Lemma 4.1.2. Let \( \delta : F \rightarrow M \) be a derivation of \( F/K \) into \( M \) . Then we have:\n\n(a) \( \delta \left( a\right) = 0 \) for each \( a \in K \) .\n\n(b) \( \delta \left( {z}^{n}\right) = n{z}^{n - 1} \cdot \delta \left( z\right) \) for \( z \in F \) and \( n \geq 0 \) .\n\n(c) If \( \operatorna...
The simple proof of this lemma can be omitted.
No
Lemma 4.1.3. Suppose that \( x \) is a separating element of \( F/K \) and that \( {\delta }_{1},{\delta }_{2} \) : \( F \rightarrow M \) are derivations of \( F/K \) with \( {\delta }_{1}\left( x\right) = {\delta }_{2}\left( x\right) \) . Then \( {\delta }_{1} = {\delta }_{2} \) .
Proof. Lemma 4.1.2(b) implies for a polynomial \( f\left( x\right) = \sum {a}_{i}{x}^{i} \in K\left\lbrack x\right\rbrack \) that \( {\delta }_{j}\left( {f\left( x\right) }\right) = \left( {\sum i{a}_{i}{x}^{i - 1}}\right) \cdot {\delta }_{j}\left( x\right) \) for \( j = 1,2 \), hence \( {\delta }_{1}\left( {f\left( x\...
Yes
Lemma 4.1.6. Let \( x \) be a separating element of \( F/K \) . Then the following hold:\n\n(a) For each derivation \( \eta \in {\operatorname{Der}}_{F} \) we have \( \eta = \eta \left( x\right) \cdot {\delta }_{x} \) . In particular, \( {\operatorname{Der}}_{F} \) is a one-dimensional \( F \) -module.\n\n(b) (Chain ru...
Proof. (a) Consider the two derivations \( \eta \) and \( \eta \left( x\right) \cdot {\delta }_{x} \) of \( F/K \) into \( F \) . Since \( \left( {\eta \left( x\right) \cdot {\delta }_{x}}\right) \left( x\right) = \eta \left( x\right) \cdot {\delta }_{x}\left( x\right) = \eta \left( x\right) \) and \( x \) is separatin...
Yes
Proposition 4.1.8. (a) Let \( z \in F \) be separating. Then \( {dz} \neq 0 \), and every differential \( \omega \in {\Delta }_{F} \) can uniquely be written in the form \( \omega = {udz} \) with \( u \in F \) . Hence \( {\Delta }_{F} \) is a one-dimensional \( F \) -module.
Proof. (a) The differential \( 0 = {0dz} \) is the zero element of \( {\Delta }_{F} \) . By (4.6) we see immediately that \( \left( {0, z}\right) \) is not equivalent to \( \left( {1, z}\right) \), hence \( {dz} \neq 0 \) .\n\nConsider now an arbitrary differential \( \omega \in {\Delta }_{F} \), say \( \omega = {vdy} ...
Yes
Lemma 4.2.4. Let \( {\left( {z}_{n}\right) }_{n \geq 0} \) be a sequence in a complete valued field \( \left( {T, v}\right) \) . Then we have: The infinite series \( \mathop{\sum }\limits_{{i = 0}}^{\infty }{z}_{i} \) is convergent if and only if the sequence \( {\left( {z}_{n}\right) }_{n \geq 0} \) converges to 0 .
Proof. Suppose that \( {\left( {z}_{n}\right) }_{n \geq 0} \) converges to 0 . Consider the \( m \) -th partial sum \( {s}_{m} \mathrel{\text{:=}} \mathop{\sum }\limits_{{i = 0}}^{m}{z}_{i} \) . For \( n > m \) we have\n\n\[ v\left( {{s}_{n} - {s}_{m}}\right) = v\left( {\mathop{\sum }\limits_{{i = m + 1}}^{n}{z}_{i}}\r...
Yes
Proposition 4.2.7. Let \( P \) be a place of \( F/K \) of degree one and let \( t \in F \) be a P-prime element. If \( z \in F \) has the P-adic expansion \( z = \mathop{\sum }\limits_{{i = n}}^{\infty }{a}_{i}{t}^{i} \) with coefficients \( {a}_{i} \in K \), then\n\n\[ \frac{dz}{dt} = \mathop{\sum }\limits_{{i = n}}^{...
Proof. We define a mapping \( \delta : {\widehat{F}}_{P} \rightarrow {\widehat{F}}_{P} \) by\n\n\[ \delta \left( {\mathop{\sum }\limits_{{i = m}}^{\infty }{c}_{i}{t}^{i}}\right) \mathrel{\text{:=}} \mathop{\sum }\limits_{{i = m}}^{\infty }i{c}_{i}{t}^{i - 1}. \]\n\nThis mapping is obviously \( K \) -linear and satisfie...
Yes
Proposition 4.2.9. Let \( s, t \in F \) be \( P \) -prime elements (where \( P \) is a place of degree one). Then\n\n\[ \n{\operatorname{res}}_{P, s}\left( z\right) = {\operatorname{res}}_{P, t}\left( {z \cdot \frac{ds}{dt}}\right)\n\]\n\nfor all \( z \in F \) .
Proof. The power series expansion of \( s \) with respect to \( t \) has the following form (see Theorem 4.2.6):\n\n\[ \ns = \mathop{\sum }\limits_{{i = 1}}^{\infty }{c}_{i}{t}^{i}\;\text{ with }\;{c}_{1} \neq 0.\n\]\n\nProposition 4.2.7 yields\n\n\[ \n\frac{ds}{dt} = {c}_{1} + \mathop{\sum }\limits_{{i = 2}}^{\infty }...
Yes
Corollary 4.3.3 (Residue Theorem). Let \( F/K \) be an algebraic function field over an algebraically closed field, and let \( \omega \in {\Delta }_{F} \) be a differential of \( F/K \) . Then \( {\operatorname{res}}_{P}\left( \omega \right) = 0 \) for almost all places \( P \in {\mathbb{P}}_{F} \), and\n\n\[ \mathop{\...
Proof of the Corollary. Write \( \omega = {zdx} \) with \( z \in F \) and a separating element \( x \in F \) . By Theorem 4.3.2(d) we have \( {\operatorname{res}}_{P}\left( \omega \right) = {\left( z \cdot \delta \left( x\right) \right) }_{P}\left( 1\right) \) . Now Proposition 1.7.2 yields the desired result.
Yes
Lemma 4.3.5. Let \( F \) be an algebraic function field over an algebraically closed field \( K \) . Suppose that \( x \) is a separating element of \( F/K \) and \( {P}_{0} \in {\mathbb{P}}_{K\left( x\right) } \) satisfies the following conditions:\n\n(1) \( {P}_{0} \) is unramified in \( F/K\left( x\right) \) .\n\n(2...
Proof. By (1) and (2) there exists an element \( a \in K \) such that \( t \mathrel{\text{:=}} x - a \) is a \( P \) - prime element. As always, \( {P}_{\infty } \) denotes the pole of \( x \) in \( K\left( x\right) \) . Consider the Weil differential \( \eta \in {\Omega }_{K\left( x\right) } \) which is given by (4.22...
Yes
(c) As an important special case of Theorem 3.4.6 we obtain the following formula for the divisor of a differential \( \omega = {zdx} \neq 0 \) :
\[ \left( {zdx}\right) = \left( z\right) + \left( {dx}\right) = \left( z\right) - 2{\left( x\right) }_{\infty } + \operatorname{Diff}\left( {F/K\left( x\right) }\right) . \]
Yes
Lemma 5.1.1. For every \( n \geq 0 \) there exist only finitely many positive divisors of degree \( n \) .
Proof. A positive divisor is a sum of prime divisors. Hence it is sufficient to prove that the set \( S \mathrel{\text{:=}} \left\{ {P \in {\mathbb{P}}_{F} \mid \deg P \leq n}\right\} \) is finite. We choose an element \( x \in F \smallsetminus {\mathbb{F}}_{q} \) and consider the set \( {S}_{0} \mathrel{\text{:=}} \le...
Yes
Proposition 5.1.3. \( {\mathrm{{Cl}}}^{0}\left( F\right) \) is a finite group. Its order \( h = {h}_{F} \) is called the class number of \( F/{\mathbb{F}}_{q} \) ; i.e., \[ h \mathrel{\text{:=}} {h}_{F} \mathrel{\text{:=}} \operatorname{ord}{\operatorname{Cl}}^{0}\left( F\right) . \]
Proof. Choose a divisor \( B \in \operatorname{Div}\left( F\right) \) of degree \( \geq g \), say \( n \mathrel{\text{:=}} \deg B \), and consider the set of divisor classes \[ {\mathrm{{Cl}}}^{n}\left( F\right) \mathrel{\text{:=}} \{ \left\lbrack C\right\rbrack \in \mathrm{{Cl}}\left( F\right) \mid \deg \left\lbrack C...
Yes
Lemma 5.1.4. (a) \( {A}_{n} = 0 \) if \( \partial \nmid n \) .
Proof. (a) is trivial.
No
Proposition 5.1.6. The power series \( Z\left( t\right) = \mathop{\sum }\limits_{{n = 0}}^{\infty }{A}_{n}{t}^{n} \) is convergent for \( \left| t\right| < {q}^{-1} \) . More precisely, we have for \( \left| t\right| < {q}^{-1} \) : (a) If \( F/{\mathbb{F}}_{q} \) has genus \( g = 0 \) then\n\n\[ Z\left( t\right) = \fr...
Proof. (a) \( g = 0 \) . To begin with, we show that a function field of genus zero has class number \( h = 1 \) ; i.e., every divisor \( A \) of degree 0 is principal. This fact follows easily from the Riemann-Roch Theorem: as \( 0 > {2g} - 2 \), we have \( \ell \left( A\right) = \deg A + 1 - g = 1 \), and we can ther...
Yes
Corollary 5.1.7. \( Z\\left( t\\right) \) can be extended to a rational function on \( \\mathbb{C} \) ; it has a simple pole at \( t = 1 \) .
Proof. Obvious, since \( 1/\\left( {1 - {t}^{\\partial }}\\right) \) has a simple pole at \( t = 1 \) .
Yes
Proposition 5.1.8 (Euler Product). For \( \left| t\right| < {q}^{-1} \) the Zeta function can be represented as an absolutely convergent product\n\n\[ Z\left( t\right) = \mathop{\prod }\limits_{{P \in {\mathbb{P}}_{F}}}{\left( 1 - {t}^{\deg P}\right) }^{-1}. \]
Proof. The right hand side of (5.5) converges absolutely for \( \left| t\right| < {q}^{-1} \), since \( \mathop{\sum }\limits_{{P \in {\mathbb{P}}_{F}}}{\left| t\right| }^{\deg P} \leq \mathop{\sum }\limits_{{n = 0}}^{\infty }{A}_{n}{\left| t\right| }^{n} < \infty \) by Proposition 5.1.6. Each factor of (5.5) can be wr...
Yes
Lemma 5.1.9. (a) \( {F}_{r}/F \) is a cyclic extension of degree \( r \) (i.e., \( {F}_{r}/F \) is Galois with a cyclic Galois group of order \( r \) ). The Galois group \( \operatorname{Gal}\left( {{F}_{r}/F}\right) \) is generated by the Frobenius automorphism \( \sigma \) which acts on \( {\mathbb{F}}_{{q}^{r}} \) b...
Proof. (a) It is well-known that \( {\mathbb{F}}_{{q}^{r}}/{\mathbb{F}}_{q} \) is cyclic of degree \( r \), and its Galois group is generated by the Frobenius map \( \alpha \mapsto {\alpha }^{q} \) . Since \( \left\lbrack {{F}_{r} : F}\right\rbrack = \left\lbrack {{\mathbb{F}}_{{q}^{r}} : {\mathbb{F}}_{q}}\right\rbrack...
Yes
Proposition 5.1.10. Let \( Z\left( t\right) \) (resp. \( {Z}_{r}\left( t\right) \) ) denote the Zeta function of \( F \) (resp. of \( {F}_{r} = F{\mathbb{F}}_{{q}^{r}} \) ). Then\n\n\[ \n{Z}_{r}\left( {t}^{r}\right) = \mathop{\prod }\limits_{{{\zeta }^{r} = 1}}Z\left( {\zeta t}\right) \n\]\n\n(5.8)\n\nfor all \( t \in ...
Proof. It is sufficient to prove (5.8) for \( \left| t\right| < {q}^{-1} \) . In this region the Euler product representation yields\n\n\[ \n{Z}_{r}\left( {t}^{r}\right) = \mathop{\prod }\limits_{{P \in {\mathbb{P}}_{F}}}\mathop{\prod }\limits_{{{P}^{\prime } \mid P}}{\left( 1 - {t}^{r \cdot \deg {P}^{\prime }}\right) ...
Yes
Corollary 5.1.11 (F.K. Schmidt). \( \partial = 1 \) .
Proof. For \( {\zeta }^{\partial } = 1 \) we have\n\n\[ Z\left( {\zeta t}\right) = \mathop{\prod }\limits_{{P \in {\mathbb{P}}_{F}}}{\left( 1 - {\left( \zeta t\right) }^{\deg P}\right) }^{-1} = \mathop{\prod }\limits_{{P \in {\mathbb{P}}_{F}}}{\left( 1 - {t}^{\deg P}\right) }^{-1} = Z\left( t\right) ,\]\n\nsince \( \pa...
Yes
Corollary 5.1.12. (a) Every function field \( F/{\mathbb{F}}_{q} \) of genus 0 is rational, and its Zeta function is\n\n\[ Z\left( t\right) = \frac{1}{\left( {1 - t}\right) \left( {1 - {qt}}\right) }.\n\]
Proof. A function field of genus 0 having a divisor of degree 1 is rational, cf. Proposition 1.6.3. The remaining assertions follow from Proposition 5.1.6 and \( \partial = 1 \) .
No
Proposition 5.1.13 (Functional Equation of the Zeta Function). The Zeta function of \( F/{\mathbb{F}}_{q} \) satisfies the functional equation\n\n\[ Z\left( t\right) = {q}^{g - 1}{t}^{{2g} - 2}Z\left( \frac{1}{qt}\right) . \]
Proof. For \( g = 0 \) this is obvious from Corollary 5.1.12(a). For \( g \geq 1 \) we write \( Z\left( t\right) = F\left( t\right) + G\left( t\right) \) as in Corollary 5.1.12(b). Let \( W \) be a canonical divisor of \( F \) ; then\n\n\[ \left( {q - 1}\right) F\left( t\right) = \mathop{\sum }\limits_{{0 \leq \deg \le...
Yes
Theorem 5.1.15. (a) \( L\left( t\right) \in \mathbb{Z}\left\lbrack t\right\rbrack \) and \( \deg L\left( t\right) = {2g} \) .
All assertions are trivial for \( g = 0 \), hence we can assume from now on that \( g \geq 1 \) . (a) We have already remarked that \( L\left( t\right) \) is a polynomial of degree \( \leq {2g} \) . In (d) we shall prove that its leading coefficient is \( {q}^{g} \), so \( \deg L\left( t\right) = {2g} \) . The assertio...
No
Corollary 5.1.16. For all \( r \geq 1 \) ,\n\n\[ \n{N}_{r} = {q}^{r} + 1 - \mathop{\sum }\limits_{{i = 1}}^{{2g}}{\alpha }_{i}^{r} \n\]\n\nwhere \( {\alpha }_{1},\ldots ,{\alpha }_{2g} \in \mathbb{C} \) are the reciprocals of the roots of \( L\left( t\right) \) . In particular, since \( {N}_{1} = N\left( F\right) \), w...
Proof. By Theorem 5.1.15(d), \( {N}_{r} - \left( {{q}^{r} + 1}\right) \) is the coefficient of \( t \) in the \( L \) - polynomial \( {L}_{r}\left( t\right) \) . On the other hand, since \( {L}_{r}\left( t\right) = \mathop{\prod }\limits_{{i = 1}}^{{2g}}\left( {1 - {\alpha }_{i}^{r}t}\right) \), this coefficient is \( ...
Yes
Corollary 5.1.17. Let \( L\left( t\right) = \mathop{\sum }\limits_{{i = 0}}^{{2g}}{a}_{i}{t}^{i} \) be the L-polynomial of \( F/{\mathbb{F}}_{q} \), and \( {S}_{r} \mathrel{\text{:=}} {N}_{r} - \left( {{q}^{r} + 1}\right) \) . Then we have:\n\n(a) \( {L}^{\prime }\left( t\right) /L\left( t\right) = \mathop{\sum }\limit...
Proof. (a) Write \( L\left( t\right) = \mathop{\prod }\limits_{{i = 1}}^{{2g}}\left( {1 - {\alpha }_{i}t}\right) \) as in (5.13). Then\n\n\[ {L}^{\prime }\left( t\right) /L\left( t\right) = \mathop{\sum }\limits_{{i = 1}}^{{2g}}\frac{-{\alpha }_{i}}{\left( 1 - {\alpha }_{i}t\right) } = \mathop{\sum }\limits_{{i = 1}}^{...
Yes
Theorem 5.2.3 (Hasse-Weil Bound). The number \( N = N\left( F\right) \) of places of \( F/{\mathbb{F}}_{q} \) of degree one satisfies the inequality\n\n\[ \left| {N - \left( {q + 1}\right) }\right| \leq {2g}{q}^{1/2} \]
Proof. Corollary 5.1.16 yields\n\n\[ N - \left( {q + 1}\right) = - \mathop{\sum }\limits_{{i = 1}}^{{2g}}{\alpha }_{i} \]\n\nHence the Hasse-Weil Bound is an immediate consequence of the Hasse-Weil Theorem.
No
Lemma 5.2.4. Let \( m \geq 1 \) . Then the Hasse-Weil Theorem holds for \( F/{\mathbb{F}}_{q} \) if and only if it holds for the constant field extension \( {F}_{m}/{\mathbb{F}}_{{q}^{m}} \) .
Proof. The reciprocals of the roots of \( {L}_{F}\left( t\right) \) are \( {\alpha }_{1},\ldots ,{\alpha }_{2g} \) . By Theorem 5.1.15(f), the reciprocals of the roots of \( {L}_{m}\left( t\right) \) are \( {\alpha }_{1}^{m},\ldots ,{\alpha }_{2g}^{m} \) (as in Theorem 5.1.15, we denote by \( {L}_{m}\left( t\right) \) ...
Yes
Lemma 5.2.5. Assume there is a constant \( c \in \mathbb{R} \) such that for all \( r \geq 1 \) ,\n\n\[ \left| {{N}_{r} - \left( {{q}^{r} + 1}\right) }\right| \leq c{q}^{r/2} \]\n\nThen the Hasse-Weil Theorem holds for \( F/{\mathbb{F}}_{q} \) .
Proof. Corollary 5.1.16 states that \( {N}_{r} - \left( {{q}^{r} + 1}\right) = - \mathop{\sum }\limits_{{i = 1}}^{{2g}}{\alpha }_{i}^{r} \), hence (5. yields\n\n\[ \left| {\mathop{\sum }\limits_{{i = 1}}^{{2g}}{\alpha }_{i}^{r}}\right| \leq c{q}^{r/2} \]\n\n(5.21)\n\nfor all \( r \geq 1 \) . Consider the meromorphic fu...
Yes
Proposition 5.2.6. Suppose that \( F/{\mathbb{F}}_{q} \) satisfies the following assumptions:\n\n\[ \text{(1)}q\text{is a square, and (2)}q > {\left( g + 1\right) }^{4}\text{.} \]\n\nThen the number \( N = N\left( F\right) \) of places of \( F/{\mathbb{F}}_{q} \) of degree one can be estimated \( {by} \)\n\n\[ N < \lef...
Proof. We can assume that there exists a place \( Q \in {\mathbb{P}}_{F} \) of degree one (otherwise \( N = 0 \), and the proposition is trivial). Set\n\n\[ {q}_{0} \mathrel{\text{:=}} {q}^{1/2}, m \mathrel{\text{:=}} {q}_{0} - 1\;\text{ and }\;n \mathrel{\text{:=}} {2g} + {q}_{0}. \]\n\nOne checks easily that\n\n\[ r ...
Yes
Lemma 5.2.7. Let \( {G}^{\prime } \) be a group which is the direct product\n\n\[ \n{G}^{\prime } = \langle \sigma \rangle \times G \n\]\n\n(5.31)\n\nof a cyclic subgroup \( \langle \sigma \rangle \) and a subgroup \( G \subseteq {G}^{\prime } \) such that \( \operatorname{ord}G = m,\operatorname{ord}\left( \sigma \rig...
Proof. For \( \tau \in G \) we consider the cyclic subgroup \( \langle {\sigma \tau }\rangle \subseteq {G}^{\prime } \) . Since \( {\sigma \tau } = {\tau \sigma } \) (by (5.31)), ord \( \left( \sigma \right) = n \) and \( \operatorname{ord}\left( \tau \right) \mid m \) we conclude that \( \operatorname{ord}\left( {\sig...
Yes
Corollary 5.2.10. (a) The estimate\n\n\[ \n\\left| {{B}_{r} - \\frac{{q}^{r}}{r}}\\right| \\leq \\left( {\\frac{q}{q - 1} + {2g}\\frac{{q}^{1/2}}{{q}^{1/2} - 1}}\\right) \\cdot \\frac{{q}^{r/2} - 1}{r} < \\left( {2 + {7g}}\\right) \\cdot \\frac{{q}^{r/2}}{r} \n\]\n\nholds for all \( r \\geq 1 \) .
Proof. (a) For \( r = 1 \) we have \( {B}_{1} = N \), and the assertion follows easily from the Hasse-Weil Bound. For \( r \\geq 2 \) Proposition 5.2.9 yields\n\n\[ \n{B}_{r} - \\frac{{q}^{r}}{r} = \\frac{1}{r}\\mathop{\\sum }\\limits_{{d \\mid r, d < r}}\\mu \\left( \\frac{r}{d}\\right) {q}^{d} + \\frac{1}{r}\\mathop{...
Yes
Proposition 5.3.3 (Ihara). Suppose that \( F/{\mathbb{F}}_{q} \) is a maximal function field. Then \( g \leq \left( {q - {q}^{1/2}}\right) /2 \) .
Proof. Let \( {\alpha }_{1},\ldots ,{\alpha }_{2g} \) be the reciprocals of the roots of \( L\left( t\right) \) . Since\n\n\[ N = q + 1 - \mathop{\sum }\limits_{{i = 1}}^{{2g}}{\alpha }_{i}\;\text{ and }\;\left| {\alpha }_{i}\right| = {q}^{1/2} \]\n\n(by Corollary 5.1.16 and Theorem 5.2.1), the assumption \( N = q + 1 ...
Yes
Proposition 5.3.4 (Serre’s Explicit Formulas). Suppose that \( {c}_{1},\ldots ,{c}_{m} \in \) \( \mathbb{R} \) satisfy the following conditions:\n\n(1) \( {c}_{r} \geq 0 \) for \( r = 1,\ldots, m \), and not all \( {c}_{r} = 0 \).\n\n(2) \( {f}_{m}\left( t\right) \geq 0 \) for all \( t \in \mathbb{C} \) with \( \left| ...
Proof. We have \( N = {N}_{1} \leq {N}_{r} \) for all \( r \geq 1 \) . So (5.54) and the assumptions (1) and (2) imply\n\n\[ N \cdot {\lambda }_{m}\left( {q}^{-1/2}\right) \leq {\lambda }_{m}\left( {q}^{1/2}\right) + {\lambda }_{m}\left( {q}^{-1/2}\right) + g. \]\n\nDividing this inequality by \( {\lambda }_{m}\left( {...
Yes
Proposition 6.1.3. (a) \( \operatorname{char}K \neq 2 \) . Suppose that \( F = K\left( {x, y}\right) \) with\n\n\[ \n{y}^{2} = f\left( x\right) \in K\left\lbrack x\right\rbrack \n\]\n\nwhere \( f\left( x\right) \) is a square-free polynomial of degree 3 . Consider the decomposition \( f\left( x\right) = c\mathop{\prod ...
Proof. In case char \( K \neq 2 \), all assertions follow easily from Proposition 3.7.3 (see also Corollary 3.7.4 and Example 3.7.6).
Yes
We would like to investigate some elliptic function fields \( F \) over the field \( {\mathbb{F}}_{2} \). Let \( N \) denote the number of places of \( F/{\mathbb{F}}_{2} \) of degree one. The Serre Bound states that\n\n\[ N \leq 2 + 1 + g \cdot \left\lbrack {2\sqrt{2}}\right\rbrack = 5. \]
Let us show that (up to isomorphism) there exists exactly one elliptic function field \( F/{\mathbb{F}}_{2} \) with \( N = 5 \). By Proposition 6.1.2(b) we can write \( F = {\mathbb{F}}_{2}\left( {x, y}\right) \n\nwith\n\[ {y}^{2} + y = x + \frac{1}{x + b},\;b \in {\mathbb{F}}_{2} \]\n\n(6.8)\n\nor\n\n\[ {y}^{2} + y = ...
Yes
Proposition 6.1.6. Let \( F/K \) be an elliptic function field. Define\n\n\[ \n{\mathbb{P}}_{F}^{\left( 1\right) } \mathrel{\text{:=}} \left\{ {P \in {\mathbb{P}}_{F} \mid \deg P = 1}\right\} \n\] \n\nThen the following hold:\n\n(a) For each divisor \( A \in \operatorname{Div}\left( F\right) \) with \( \deg A = 1 \) th...
Proof. (a) Let \( A \in \operatorname{Div}\left( F\right) \) and \( \deg A = 1 \) . We show the existence of a place \( P \in {\mathbb{P}}_{F}^{\left( 1\right) } \) with \( A \sim P \) as in the proof of Proposition 6.1.2; since \( \ell \left( A\right) = \) \( \deg A + 1 - g > 0 \), there is a divisor \( {A}_{1} \sim A...
Yes
Proposition 6.1.7. Let \( F/K \) be an elliptic function field. Then:\n\n(a) \( {\mathbb{P}}_{F}^{\left( 1\right) } \) is an abelian group with respect to the operation \( \oplus \) as defined in (6.14).\n\n(b) The place \( {P}_{0} \) is the zero element of the group \( {\mathbb{P}}_{F}^{\left( 1\right) } \) .\n\n(c) F...
Proof. (a), (b) and (d) are obvious.\n\n(c) By (6.14) we have the following equivalences:\n\n\[ P \oplus Q = R \Leftrightarrow \Phi \left( R\right) = \Phi \left( P\right) + \Phi \left( Q\right) \]\n\n\[ \Leftrightarrow R - {P}_{0} \sim \left( {P - {P}_{0}}\right) + \left( {Q - {P}_{0}}\right) \]\n\n\[ \Leftrightarrow P...
Yes
Lemma 6.2.2. (a) A function field \( F/K \) of genus \( g \geq 2 \) is hyperelliptic if and only if there exists a divisor \( A \in \operatorname{Div}\left( F\right) \) with \( \deg A = 2 \) and \( \ell \left( A\right) \geq 2 \) .
Proof. (a) Suppose that \( F/K \) is hyperelliptic. Choose an element \( x \in F \) such that \( \left\lbrack {F : K\left( x\right) }\right\rbrack = 2 \), and consider the divisor \( A \mathrel{\text{:=}} {\left( x\right) }_{\infty } \) . Then \( \deg A = 2 \) and the elements \( 1, x \in \mathcal{L}\left( A\right) \) ...
Yes
Proposition 6.2.3. Assume that \( \operatorname{char}K \neq 2 \) .\n\n(a) Let \( F/K \) be a hyperelliptic function field of genus \( g \) . Then there exist \( x, y \in F \) such that \( F = K\left( {x, y}\right) \) and\n\n\[ {y}^{2} = f\left( x\right) \in K\left\lbrack x\right\rbrack \]\n\nwith a square-free polynomi...
Proof. (a) As \( F/K\left( x\right) \) is cyclic of degree 2 and \( \operatorname{char}K \neq 2 \), there exists an element \( z \in F \) such that \( F = K\left( {x, z}\right) \) and \( {z}^{2} = u\left( x\right) \in K\left( x\right) \) . Write\n\n\[ u\left( x\right) = c \cdot \prod {p}_{i}{\left( x\right) }^{{r}_{i}}...
Yes
Proposition 6.2.4. Consider a hyperelliptic function field \( F/K \) of genus \( g \) and a rational subfield \( K\left( x\right) \subseteq F \) with \( \left\lbrack {F : K\left( x\right) }\right\rbrack = 2 \) . Then the following hold:\n\n(a) All rational subfields \( K\left( z\right) \subseteq F \) with \( \left\lbra...
Proof. (a) Suppose that \( \left\lbrack {F : K\left( z\right) }\right\rbrack \leq g \) but \( z \notin K\left( x\right) \) . Then \( F = K\left( {x, z}\right) \) , and Riemann's Inequality (Theorem 3.11.4) yields the contradiction\n\n\[ g \leq \left( {\left\lbrack {F : K\left( x\right) }\right\rbrack - 1}\right) \cdot ...
Yes
Proposition 6.3.1. Suppose that \( F = K\left( {x, y}\right) \) is defined by (6.18) and (6.19). Then we have:\n\n(a) \( K \) is the full constant field of \( F \), and \( \left\lbrack {F : K\left( x\right) }\right\rbrack = n \) . If \( K \) contains a primitive \( n \) -th root of unity, \( F/K\left( x\right) \) is a ...
Proof. All assertions follow immediately from Proposition 3.7.3, Corollary 3.7.4 and Remark 3.7.5.
No
The special case \( H \mathrel{\text{:=}} {\mathbb{F}}_{{q}^{2}}\left( {x, y}\right) \) with\n\n\[ \n{x}^{q + 1} + {y}^{q + 1} = 1 \n\]\n\nis called the Hermitian function field over \( {\mathbb{F}}_{{q}^{2}} \) .
It is a maximal function field by (6.23), so it provides an example of a maximal function field of genus \( g = q\left( {q - 1}\right) /2 \) and shows that Proposition 5.3.3 cannot be improved. The number of places of degree one is \( N = 1 + {q}^{3} \) .
No
We consider the function field \( F = K\left( {y, z}\right) \) defined by\n\n\[ \n{z}^{3} + {y}^{3}z + y = 0.\n\]\n\n\( F \) is called the function field of the Klein Quartic. The polynomial \( {T}^{3} + {y}^{3}T + y \in K\left( y\right) \left\lbrack T\right\rbrack \) is absolutely irreducible (by Proposition 3.1.15), ...
It is convenient to choose other generators of \( F/K \). We multiply (6.29) by \( {y}^{6} \), set \( x \mathrel{\text{:=}} - {y}^{2}z \) and obtain \( F = K\left( {x, y}\right) \) with\n\n\[ \n{y}^{7} = {x}^{3}/\left( {1 - x}\right)\n\]\n\nIf char \( K = 7, F/K\left( x\right) \) is purely inseparable; therefore \( F/K...
Yes
Proposition 6.4.1. Consider a function field \( F = K\left( {x, y}\right) \) with\n\n\[ \n{y}^{q} + {\mu y} = f\left( x\right) \in K\left\lbrack x\right\rbrack \n\]\n\n(6.32)\n\nwhere \( q = {p}^{s} > 1 \) is a power of \( p \) and \( 0 \neq \mu \in K \) . Assume that \( \deg f = : m > 0 \) is prime to \( p \), and tha...
Proof. Equation (6.32) is a special case of the situation which was considered in Proposition 3.7.10, so (a) - (e) hold.\n\n(g) \( {\left( x\right) }_{\infty } = q{Q}_{\infty } \) follows from (c). The elements \( x \) and \( y \) have the same poles, hence \( {Q}_{\infty } \) is the only pole of \( y \) as well. Since...
Yes
We consider a special case of the previous proposition, namely\n\n\\[ F = {\\mathbb{F}}_{{q}^{2}}\\left( {x, y}\\right) \\;\\text{ with }\\;{y}^{q} + y = {x}^{m}\\;\\text{ and }\\;m \\mid \\left( {q + 1}\\right) .\n\\]\n\nThe genus of \\( F \\) is \\( g = \\left( {q - 1}\\right) \\left( {m - 1}\\right) /2 \\) . We clai...
The pole \\( {Q}_{\\infty } \\) of \\( x \\) is one of them. The other places of degree one are extensions of some place \\( {P}_{\\alpha } \\in {\\mathbb{P}}_{K\\left( x\\right) } \\) . Hence, by Proposition 6.4.1(i), we have to count the elements \\( \\alpha \\in {\\mathbb{F}}_{{q}^{2}} \\) such that the equation\n\n...
Yes
The Hermitian function field \( H \) which was studied in Example 6.3.6 is given by \[ H = {\mathbb{F}}_{{q}^{2}}\left( {u, v}\right) \;\text{ with }\;{u}^{q + 1} + {v}^{q + 1} = 1. \]
We choose \( a, b, c \in {\mathbb{F}}_{{q}^{2}} \) such that \[ {a}^{q + 1} = - 1,\;{b}^{q} + b = 1\;\text{ and }\;c = - a{b}^{q}; \] then it follows that \[ a{b}^{q} + c = 0, \] \[ {a}^{q}b + {c}^{q} = {\left( a{b}^{q} + c\right) }^{q} = 0, \] \[ a{c}^{q} + {a}^{q}c = a\left( {-{a}^{q}b}\right) + {a}^{q}\left( {-a{b}^...
Yes
Lemma 7.2.3. Let \( \mathcal{F} = \left( {{F}_{0},{F}_{1},{F}_{2},\ldots }\right) \) be a tower over \( {\mathbb{F}}_{q} \) . Then the following hold:\n\n(a) The sequence of rational numbers \( {\left( N\left( {F}_{i}\right) /\left\lbrack {F}_{i} : {F}_{0}\right\rbrack \right) }_{i \geq 0} \) is monotonically decreasin...
Proof. (a) If \( Q \) is a rational place of \( {F}_{i + 1} \), then the restriction \( P \mathrel{\text{:=}} Q \cap {F}_{i} \) of \( Q \) to \( {F}_{i} \) is a rational place of \( {F}_{i} \) . Conversely, at most \( \left\lbrack {{F}_{i + 1} : {F}_{i}}\right\rbrack \) rational places of \( {F}_{i + 1} \) lie above a ...
Yes
Proposition 7.2.8. Let \( \mathcal{E} \) be a subtower of \( \mathcal{F} \) . Then \( \lambda \left( \mathcal{E}\right) \geq \lambda \left( \mathcal{F}\right) \) . In particular one has:\n\n(a) If \( \mathcal{F} \) is asymptotically good then \( \mathcal{E} \) is also asymptotically good.\n\n(b) If \( \mathcal{E} \) is...
Proof. Let \( {\varphi }_{i} : {E}_{i} \rightarrow {F}_{j\left( i\right) } \) be an embedding of \( {E}_{i} \) into \( {F}_{j\left( i\right) } \) . Let \( {H}_{i} \) be the subfield of \( {F}_{j\left( i\right) } \) which is uniquely determined by the following properties:\n\n- \( {\varphi }_{i}\left( {E}_{i}\right) \su...
Yes
Theorem 7.2.10. Let \( \mathcal{F} = \left( {{F}_{0},{F}_{1},{F}_{2},\ldots }\right) \) be a tower over \( {\mathbb{F}}_{q} \) . (a) Let \( s \mathrel{\text{:=}} \left| {\operatorname{Split}\left( {\mathcal{F}/{F}_{0}}\right) }\right| \) . Then the splitting rate \( \nu \left( {\mathcal{F}/{F}_{0}}\right) \) satisfies ...
Proof. (a) Above each place \( P \in \operatorname{Split}\left( {\mathcal{F}/{F}_{0}}\right) \) there are exactly \( \left\lbrack {{F}_{n} : {F}_{0}}\right\rbrack \) places of \( {F}_{n} \), and they are all rational. Hence \( N\left( {F}_{n}\right) \geq \left\lbrack {{F}_{n} : {F}_{0}}\right\rbrack \cdot \left| {\oper...
Yes
Corollary 7.2.11. Let \( \mathcal{F} = \left( {{F}_{0},{F}_{1},{F}_{2},\ldots }\right) \) be a tame tower. Assume that the splitting locus \( \operatorname{Split}\left( {\mathcal{F}/{F}_{0}}\right) \) is non-empty and that the ramification locus \( \operatorname{Ram}\left( {\mathcal{F}/{F}_{0}}\right) \) is finite. The...
Proof. For a tamely ramified place \( Q \mid P \) we have \( d\left( {Q \mid P}\right) = e\left( {Q \mid P}\right) - 1 \leq \) \( e\left( {Q \mid P}\right) \), by Dedekind’s Different Theorem. Therefore we can choose \( {a}_{P} \mathrel{\text{:=}} 1 \) in (7.7), and Theorem 7.2.10(c) gives the desired result.
Yes
Proposition 7.2.15. Consider a sequence of fields \( {F}_{0} \subseteq {F}_{1} \subseteq {F}_{2} \subseteq \ldots \) where \( {F}_{0} \) is a function field with the exact constant field \( {\mathbb{F}}_{q} \) and \( \left\lbrack {{F}_{n + 1} : {F}_{n}}\right\rbrack \) \( < \infty \) for all \( n \geq 0 \) . Suppose th...
Proof. By the Fundamental Equality we have \( \left\lbrack {{F}_{n + 1} : {F}_{n}}\right\rbrack \geq e\left( {{Q}_{n} \mid {P}_{n}}\right) \) and therefore \( {F}_{n} \subsetneqq {F}_{n + 1} \) . If we assume the equality \( e\left( {{Q}_{n} \mid {P}_{n}}\right) = \left\lbrack {{F}_{n + 1} : {F}_{n}}\right\rbrack \), t...
Yes
Proposition 7.2.20. Let \( \mathcal{F} = \left( {{F}_{0},{F}_{1},{F}_{2},\ldots }\right) \) be a tower over \( {\mathbb{F}}_{q} \) which is recursively defined by the equation \( f\left( Y\right) = h\left( X\right) \), and let \( F = {\mathbb{F}}_{q}\left( {x, y}\right) \) be the corresponding basic function field with...
Proof. Let \( \alpha \in \sum \) . We show by induction that the place \( \left( {{x}_{0} = \alpha }\right) \) splits completely in \( {F}_{n}/{F}_{0} \) for all \( n \geq 0 \) . This is trivial for \( n = 0 \), and we assume now that the assertion holds for some \( n \) . We have to show that every place \( Q \in {\ma...
Yes
Corollary 7.2.21. Let \( \mathcal{F} = \left( {{F}_{0},{F}_{1},{F}_{2},\ldots }\right) \) be a tower over \( {\mathbb{F}}_{q} \) which is recursively defined by the equation \( f\left( Y\right) = h\left( X\right) \) . Let \( m \mathrel{\text{:=}} \deg f\left( Y\right) \) . Assume that \( \sum \subseteq {\mathbb{F}}_{q}...
Proof. Consider the basic function field \( F = {\mathbb{F}}_{q}\left( {x, y}\right) \) with defining equation \( f\left( y\right) = h\left( x\right) \) . Let \( P = \left( {x = \alpha }\right) \) with \( \alpha \in \sum \) be the place of \( {\mathbb{F}}_{q}\left( x\right) \) which is the zero of \( x - \alpha \), and...
Yes
We return to the tower \( \mathcal{F} \) in Example 7.2.16; i.e., \( \mathcal{F} \) is recursively given by the equation \( f\left( Y\right) = h\left( X\right) \) with \( f\left( Y\right) = {Y}^{2} \) and \( h\left( X\right) = \left( {{X}^{2} + 1}\right) /{2X} \) over a field \( {\mathbb{F}}_{q} \) of odd characteristi...
The field \( {\mathbb{F}}_{9} \) can be represented as \( {\mathbb{F}}_{9} = {\mathbb{F}}_{3}\left( \delta \right) \) with \( {\delta }^{2} = - 1 \), so we have \( {\mathbb{F}}_{9} = \{ 0, \pm 1, \pm \delta , \pm \left( {\delta + 1}\right) , \pm \left( {\delta - 1}\right) \} \). We claim that the set \( \sum \mathrel{\...
Yes
Proposition 7.2.23. Let \( \mathcal{F} = \left( {{F}_{0},{F}_{1},{F}_{2},\ldots }\right) \) be a recursive tower over \( {\mathbb{F}}_{q} \) , defined by the equation \( f\left( Y\right) = h\left( X\right) \), and let \( {\mathcal{F}}^{\prime } = \mathcal{F}L = \left( {{F}_{0}^{\prime },{F}_{1}^{\prime },{F}_{2}^{\prim...
Proof. By definition, the field \( {F}_{0}^{\prime } \) is the rational function field \( {F}_{0}^{\prime } = L\left( {x}_{0}\right) \) over \( L \) . Let \( P \in \operatorname{Ram}\left( {{\mathcal{F}}^{\prime }/{F}_{0}^{\prime }}\right) \) . There is some \( n \geq 0 \) and some place \( Q \) of \( {F}_{n}^{\prime }...
Yes
We claim that \( \Lambda \) satisfies Condition (2) of Proposition 7.2.23. So we have to show that for all \( \beta \in \Lambda \), all solutions \( \alpha \in {\widetilde{\mathbb{F}}}_{q} \cup \{ \infty \} \) of the equation \( \left( {{\alpha }^{2} + 1}\right) /{2\alpha } = {\beta }^{2} \) are in \( \Lambda \) .
This is easily checked as follows:\n\n\[ \text{if}\beta = \infty \;\text{then}\alpha = 0\text{or}\alpha = \infty \text{;}\]\n\n\[ \text{if}\beta = 0\;\text{then}\alpha = \pm \delta \text{;}\]\n\n\[ \text{if}\beta = \pm 1\text{then}\alpha = 1\text{;}\]\n\n\[ \text{if}\beta = \pm \delta \text{then}\alpha = - 1\text{.} \]
Yes
Theorem 7.3.1. Let \( m \geq 2 \) be an integer with \( q \equiv 1{\;\operatorname{mod}\;m} \) . Assume that the polynomial \( h\left( X\right) \in {\mathbb{F}}_{q}\left\lbrack X\right\rbrack \) has the following properties:\n\n(1) \( \deg h\left( X\right) = m \), and the leading coefficient of \( h\left( X\right) \) i...
Proof. We consider the sequence \( \mathcal{F} = \left( {{F}_{0},{F}_{1},{F}_{2},\ldots }\right) \), where \( {F}_{0} = {\mathbb{F}}_{q}\left( {x}_{0}\right) \) is a rational function field and for all \( n \geq 0 \) ,\n\n\[ \n{F}_{n + 1} = {F}_{n}\left( {x}_{n + 1}\right) \text{ with }{x}_{n + 1}^{m} = h\left( {x}_{n}...
Yes
Proposition 7.3.2. Let \( q = {\ell }^{2} \) be a square, \( \ell > 2 \) . Then the equation\n\n\[ \n{Y}^{\ell - 1} = 1 - {\left( X + 1\right) }^{\ell - 1}\n\]\n\ndefines an asymptotically good tower \( \mathcal{F} \) over \( {\mathbb{F}}_{q} \) with limit\n\n\[ \n\lambda \left( \mathcal{F}\right) \geq 2/\left( {\ell -...
Proof. We set \( h\left( X\right) = 1 - {\left( X + 1\right) }^{\ell - 1} \) and \( \Lambda = {\mathbb{F}}_{\ell } \) . We need to check that the assumptions of Theorem 7.3.1 are satisfied:\n\n(1) The leading coefficient of \( h\left( X\right) \) is -1, which is a square in \( {\mathbb{F}}_{q} \) since \( q = {\ell }^{...
Yes
Proposition 7.3.3. Let \( q = {\ell }^{e} \) with \( e \geq 2 \) . Then the equation\n\n\[ \n{Y}^{m} = 1 - {\left( X + 1\right) }^{m} \n\]\n\nwith \( m \mathrel{\text{:=}} \left( {q - 1}\right) /\left( {\ell - 1}\right) \) defines an asymptotically good tower \( \mathcal{F} \) over \( {\mathbb{F}}_{q} \) with limit\n\n...
Proof. In this case we have \( h\left( X\right) = 1 - {\left( X + 1\right) }^{m} \) and we set \( \Lambda \mathrel{\text{:=}} {\mathbb{F}}_{q} \) . Observe that the map \( \gamma \mapsto {\gamma }^{m} \) is the norm map from \( {\mathbb{F}}_{q} \) to \( {\mathbb{F}}_{\ell } \) and hence is surjective. Moreover, every e...
Yes
Lemma 7.4.3. Equation (7.14) defines a recursive tower \( \mathcal{G} = \left( {{G}_{0},{G}_{1},{G}_{2},\ldots }\right) \) over \( {\mathbb{F}}_{q} \) . All extensions \( {G}_{i + 1}/{G}_{i} \) are Galois of degree \( \left\lbrack {{G}_{i + 1} : {G}_{i}}\right\rbrack = \ell \), and the place \( \left( {{x}_{0} = \infty...
Proof. It is clear that the equation \( {Y}^{\ell } - Y = {X}^{\ell }/\left( {1 - {X}^{\ell - 1}}\right) \) is separable and hence all extensions \( {G}_{i + 1}/{G}_{i} \) are separable of degree \( \left\lbrack {{G}_{i + 1} : {G}_{i}}\right\rbrack \leq \ell \) . Let \( {P}_{0} \mathrel{\text{:=}} \left( {{x}_{0} = \in...
Yes
Lemma 7.4.4. Let \( \mathcal{G} \) be the tower over \( {\mathbb{F}}_{q} \) (with \( q = {\ell }^{2} \) ), which is recursively defined by Equation (7.14). Then the splitting locus of \( \mathcal{G}/{G}_{0} \) satisfies\n\n\[ \operatorname{Split}\left( {\mathcal{G}/{G}_{0}}\right) \supseteq \left\{ {\left( {{x}_{0} = \...
Proof. We want to show that the set \( \sum \mathrel{\text{:=}} {\mathbb{F}}_{q} \smallsetminus {\mathbb{F}}_{\ell } \) satisfies the condition of Corollary 7.2.21. So let \( \alpha \in \sum \) ; then\n\n\[ \frac{{\alpha }^{\ell }}{1 - {\alpha }^{\ell - 1}} \in {\mathbb{F}}_{q}\;\text{ since }{\alpha }^{\ell - 1} \neq ...
Yes
Lemma 7.4.5. The tower \( \mathcal{G} \) over \( {\mathbb{F}}_{q} \) (with \( q = {\ell }^{2} \) ) which is recursively defined by Equation (7.14) has a finite ramification locus. More precisely one has \[ \operatorname{Ram}\left( {\mathcal{G}/{G}_{0}}\right) \subseteq \left\{ {\left( {{x}_{0} = \beta }\right) \mid \be...
It is easy to show that the tower \( \mathcal{G} \) is a wild tower. As we have seen in Lemma 7.4.3, in each step \( {G}_{i + 1}/{G}_{i} \) there are places which are totally (and hence wildly) ramified. So we do not have the estimate \( d\left( {Q \mid P}\right) \leq e\left( {Q \mid P}\right) \) for all \( P \in \oper...
No
Proposition 7.4.13. Let \( E/F \) be a finite extension of function fields and let \( M, N \) be intermediate fields of \( E \supseteq F \) such that \( E = {MN} \) is the compositum of \( M \) and \( N \) . Assume that both extensions \( M/F \) and \( N/F \) are weakly ramified. Then \( E/F \) is weakly ramified.
Proof. The special case \( \left\lbrack {M : F}\right\rbrack = \left\lbrack {N : F}\right\rbrack = p \) has been considered in Proposition 3.9.4. The idea of proof here is to reduce the general case to this special case. There is a sequence of intermediate fields\n\n\[ F = {M}_{0} \subseteq {M}_{1} \subseteq \ldots \su...
Yes
Lemma 7.4.14. Let \( K\left( x\right) \) be the rational function field over a field \( K \supseteq {\mathbb{F}}_{\ell } \) . Consider the subfields \( K\left( u\right) \subseteq K\left( t\right) \subseteq K\left( x\right) \) with\n\n\[ t \mathrel{\text{:=}} {x}^{\ell } - x\text{ and }u \mathrel{\text{:=}} {\left( {x}^...
Proof. (a) We consider the two subgroups \( {U}_{0},{U}_{1} \) of the automorphism group of \( K\left( x\right) /K \) which are defined by\n\n\[ {U}_{0} \mathrel{\text{:=}} \left\{ {\sigma : x \mapsto {ax} + b \mid a \in {\mathbb{F}}_{\ell }^{ \times }, b \in {\mathbb{F}}_{\ell }}\right\} ,\]\n\n\[ {U}_{1} \mathrel{\te...
No
Theorem 7.4.15. Let \( q = {\ell }^{2} \) be a square. With the above notation, the following hold:\n\n(a) \( {\mathbb{F}}_{q} \) is the full constant field of \( {G}_{i}^{ * } \) for all \( i \geq 0 \) . Therefore the sequence\n\n\[ \n{\mathcal{G}}^{ * } \mathrel{\text{:=}} \left( {{G}_{0}^{ * },{G}_{1}^{ * },{G}_{2}^...
Proof. We consider the field extensions\n\n\[ \n{\mathbb{F}}_{q}\left( {u}_{0}\right) \subseteq {\mathbb{F}}_{q}\left( {t}_{0}\right) \subseteq {\mathbb{F}}_{q}\left( {x}_{0}\right) = {G}_{0} \subseteq {G}_{1} \subseteq {G}_{2} \subseteq \ldots\n\]\n\n(7.28)\n\nThe first step \( {\mathbb{F}}_{q}\left( {t}_{0}\right) /{...
Yes
Corollary 7.4.16. With the notations of Theorem 7.4.15, we set\n\n\[ \n{n}_{i} \mathrel{\text{:=}} \left\lbrack {{G}_{i}^{ * } : {\mathbb{F}}_{q}\left( {u}_{0}\right) }\right\rbrack = \left( {\ell - 1}\right) \cdot {m}_{i} \]\n\n(7.30)\n\nfor every \( i \geq 0 \), so \( {m}_{i} = \left\lbrack {{G}_{i}^{ * } : {\mathbb{...
Proof. The places \( \left( {{t}_{0} = 0}\right) \) and \( \left( {{t}_{0} = \infty }\right) \) are the only places of \( {\mathbb{F}}_{q}\left( {t}_{0}\right) \) which ramify in the extension \( {G}_{i}^{ * }/{\mathbb{F}}_{q}\left( {t}_{0}\right) \) . Since they are weakly ramified (Theorem 7.4.15(c),(d)), the differe...
Yes
Lemma 7.4.19. Assume that \( {\mathbb{F}}_{\ell } \subseteq K \) . With the above notation we have:\n\n(a) The extensions \( K\left( x\right) /K\left( u\right), K\left( y\right) /K\left( u\right), K\left( y\right) /K\left( v\right) \) and \( K\left( z\right) /K\left( v\right) \) are Galois of degree \( \ell \left( {\el...
Proof. (a) By Lemma 7.4.14(a), the extension \( K\left( y\right) /K\left( u\right) \) is Galois of degree \( \left\lbrack {K\left( y\right) : K\left( u\right) }\right\rbrack = \ell \left( {\ell - 1}\right) \), since \( u = {\left( {y}^{\ell } - y\right) }^{\ell - 1} + 1 \) . Now we observe that the equation \( u = - {x...
Yes
Lemma 7.4.20. We maintain the notation of Equations (7.36), (7.37) and Figures 7.3,7.4, and also assume that \( {\mathbb{F}}_{{\ell }^{2}} \subseteq K \) . Let \( R \) be a place of \( H \) which is ramified in the extension \( H/K\left( u\right) \) . Then the restriction \( {P}^{ * } = R \cap K\left( u\right) \) of \(...
Proof. Since \( R \\mid {P}^{ * } \) is ramified, at least one of the places \( P \\mid {P}^{ * } \) or \( {R}^{ * } \\mid {P}^{ * } \) is ramified, see Figure 7.4. We distinguish several cases:\n\n(i) Assume that \( P \\mid {P}^{ * } \) is ramified. Since \( K\\left( x\\right) = K\\left( {1/x}\\right) \) and\n\n\[ {\\...
Yes
Proposition 7.4.22. Let \( K \) be a field with \( {\mathbb{F}}_{\ell } \subseteq K \), and consider the sequence \( \mathcal{H} = \left( {{H}_{0},{H}_{1},{H}_{2},\ldots }\right) \) where \( {H}_{0} = K\left( {y}_{0}\right) \) is a rational function field, and \( {H}_{i + 1} = {H}_{i}\left( {y}_{i + 1}\right) \) with\n...
Proof. The field \( {H}_{2} = K\left( {{y}_{0},{y}_{1},{y}_{2}}\right) \) is isomorphic to the function field \( H = \) \( K\left( {x, y, z}\right) \) that we studied in Lemmas 7.4.19 and 7.4.20. Therefore we know already that \( {H}_{1}/{H}_{0} \) is Galois of degree \( \ell \left( {\ell - 1}\right) \), the extension ...
Yes
Lemma 7.4.24. Assume that \( {\mathbb{F}}_{{\ell }^{2}} \subseteq K \) . Then the ramification locus of \( \mathcal{H} \) over \( {H}_{0} \) satisfies\n\n\[ \operatorname{Ram}\left( {\mathcal{H}/{H}_{0}}\right) \subseteq \left\{ {\left( {{y}_{0} = \beta }\right) \mid \beta \in {\mathbb{F}}_{{\ell }^{2}}\cup \{ \infty \...
Proof of Lemma 7.4.24. We want to apply Proposition 7.2.23. We set\n\n\[ {\Lambda }_{0} \mathrel{\text{:=}} \left\{ {{y}_{0}\left( P\right) \mid P \in {\mathbb{P}}_{{H}_{0}}\text{ is ramified in }{H}_{1}/{H}_{0}}\right\} . \]\n\nThen \( {\Lambda }_{0} = {\mathbb{F}}_{{\ell }^{2}}^{ \times } \cup \{ \infty \} \) by Lemm...
Yes
Corollary 7.4.25. The genus \( \gamma \left( {\mathcal{H}/{H}_{0}}\right) \) of the tower \( \mathcal{H} \) is finite; it is bounded \( {by} \)\n\n\[ \gamma \left( {\mathcal{H}/{H}_{0}}\right) \leq \frac{{\ell }^{2} + 2\ell }{2}. \]
Proof. Recall that both extensions \( {H}_{2}/K\left( {{y}_{0},{y}_{1}}\right) \) and \( {H}_{2}/K\left( {{y}_{1},{y}_{2}}\right) \) are weakly ramified Galois extensions of degree \( \ell \) by Corollary 7.4.21. For all \( n \geq 2 \) we consider the field \( {H}_{n} \) as the compositum of the fields \( {H}_{n - 1} \...
Yes
Proposition 8.1.1.\n\n\[ \n{C}_{\Omega }\left( {D, G}\right) = \left\{ {\left( {{\operatorname{res}}_{{P}_{1}}\left( \omega \right) ,\ldots ,{\operatorname{res}}_{{P}_{n}}\left( \omega \right) }\right) \mid \omega \in {\Omega }_{F}\left( {G - D}\right) }\right\} .\n\]
It is this representation that is most commonly used in the literature to define the code \( {C}_{\Omega }\left( {D, G}\right) \) .\n\nH. Stichtenoth, Algebraic Function Fields and Codes,\n\n289\n\nGraduate Texts in Mathematics 254,\n\n(C) Springer-Verlag Berlin Heidelberg 2009\n\nBy Proposition 2.2.10 the code \( {C}_...
No
Proposition 8.1.2. Let \( t \) be an element of \( F \) such that \( {v}_{{P}_{i}}\left( t\right) = 1 \) for \( i = 1,\ldots, n \) . Then the following hold:\n\n(a) The differential \( \eta \mathrel{\text{:=}} {dt}/t \) satisfies \( {v}_{{P}_{i}}\left( \eta \right) = - 1 \) and \( {\operatorname{res}}_{{P}_{i}}\left( \...
Proof. (a) Since \( t \) is a prime element of \( P \mathrel{\text{:=}} {P}_{i} \), the \( P \) -adic power series of \( \eta = {dt}/t \) with respect to \( t \) is\n\n\[ \eta = \frac{1}{t}{dt} \]\n\nHence \( {v}_{P}\left( \eta \right) = - 1 \) and \( {\operatorname{res}}_{P}\left( \eta \right) = 1 \) .\n\n(b) Follows ...
Yes
Corollary 8.1.3. Suppose that \( t \in F \) is a prime element for all places \( {P}_{1},\ldots ,{P}_{n} \)\n\n(a) If \( {2G} - D \leq \left( {{dt}/t}\right) \) then the code \( {C}_{\mathcal{L}}\left( {D, G}\right) \) is self-orthogonal; i.e.,\n\n\[ {C}_{\mathcal{L}}\left( {D, G}\right) \subseteq {C}_{\mathcal{L}}{\le...
Proof. This is an immediate consequence of Corollary 2.2.11.
No
Proposition 8.2.3. (a) \( {\operatorname{Aut}}_{D, G}\left( {F/{\mathbb{F}}_{q}}\right) \) acts on the code \( {C}_{\mathcal{L}}\left( {D, G}\right) \) by\n\n\[ \sigma \left( \left( {x\left( {P}_{1}\right) ,\ldots, x\left( {P}_{n}\right) }\right) \right) \mathrel{\text{:=}} \left( {x\left( {\sigma \left( {P}_{1}\right)...
Proof. (a) We begin with the following assertion: given a place \( P \) of degree one and an element \( y \in F \) with \( {v}_{P}\left( y\right) \geq 0 \), we have\n\n\[ \sigma \left( y\right) \left( {\sigma \left( P\right) }\right) = y\left( P\right) \]\n\n(8.3)\n\nIn fact, setting \( a \mathrel{\text{:=}} y\left( P\...
Yes
Example 8.2.4. As an example we consider a BCH code \( C \) of length \( n \) over \( {\mathbb{F}}_{q} \) . As shown in Section 2.3, \( C \) can be realized as a subfield subcode of a rational AG code as follows: let \( n \mid \left( {{q}^{m} - 1}\right) \) and let \( \beta \in {\mathbb{F}}_{{q}^{m}} \) be a primitive ...
\[ C = {\left. {C}_{\mathcal{L}}\left( {D}_{\beta }, r{P}_{0} + s{P}_{\infty }\right) \right| }_{{\mathbb{F}}_{q}} \] with \( r, s \in \mathbb{Z} \) (see Proposition 2.3.9). The automorphism \( \sigma \in \operatorname{Aut}\left( {F/{\mathbb{F}}_{{q}^{m}}}\right) \) given by \( \sigma \left( z\right) = {\beta }^{-1}z \...
Yes
Proposition 8.3.2. The dual code of \( {C}_{r} \) is\n\n\[ \n{C}_{r}^{ \bot } = {C}_{{q}^{3} + {q}^{2} - q - 2 - r}.\n\]\n\nHence \( {C}_{r} \) is self-orthogonal if \( {2r} \leq {q}^{3} + {q}^{2} - q - 2 \), and \( {C}_{r} \) is self-dual for \( r = \left( {{q}^{3} + {q}^{2} - q - 2}\right) /2 \) .
Proof. Consider the element\n\n\[ \nt \mathrel{\text{:=}} \mathop{\prod }\limits_{{\alpha \in {\mathbb{F}}_{{q}^{2}}}}\left( {x - \alpha }\right) = {x}^{{q}^{2}} - x.\n\]\n\n\( t \) is a prime element for all places \( {P}_{\alpha ,\beta } \leq D \), and its principal divisor is \( \left( t\right) = D - {q}^{3}{Q}_{\in...
Yes
Proposition 8.3.3. Suppose that \( 0 \leq r \leq {q}^{3} + {q}^{2} - q - 2 \) . Then the following hold:\n\n(a) The dimension of \( {C}_{r} \) is given by\n\n\[ \dim {C}_{r} = \left\{ \begin{matrix} \left| {I\left( r\right) }\right| & \text{ for }0 \leq r < {q}^{3}, \\ {q}^{3} - \left| {I\left( s\right) }\right| & \tex...
Proof. (a) For \( 0 \leq r < {q}^{3} \) Corollary 2.2.3 gives\n\n\[ \dim {C}_{r} = \dim \mathcal{L}\left( {r{Q}_{\infty }}\right) = \left| {I\left( r\right) }\right| . \]\n\nFor \( {q}^{3} \leq r \leq {q}^{3} + {q}^{2} - q - 2 \) we set \( s \mathrel{\text{:=}} {q}^{3} + {q}^{2} - q - 2 - r \) . Then \( 0 \leq s \leq \...
Yes
Corollary 8.3.4. Suppose that \( 0 \leq r < {q}^{3} \) . Let \( 0 = {s}_{1} < {s}_{2} < \ldots < {s}_{k} \leq r \) be all pole numbers \( \leq r \) of \( {Q}_{\infty } \) . Then the \( k \times {q}^{3} \) matrix \( {M}_{r} \) whose rows are \( {u}_{{s}_{1}},\ldots ,{u}_{{s}_{k}} \), is a generator matrix of \( {C}_{r} ...
Proof. Corollary 2.2.3.
No
Proposition 8.4.2. There is a continuous function \( {\alpha }_{q} : \left\lbrack {0,1}\right\rbrack \rightarrow \left\lbrack {0,1}\right\rbrack \) such that\n\n\[ \n{U}_{q} = \left\{ {\left( {\delta, R}\right) \mid 0 \leq \delta \leq 1\text{ and }0 \leq R \leq {\alpha }_{q}\left( \delta \right) }\right\} .\n\]\n\nMore...
The proof of this proposition requires only elementary techniques of coding theory; we refer to [29].
No
Proposition 8.4.4 (Gilbert-Varshamov Bound). For \( 0 \leq \delta \leq 1 - {q}^{-1} \) , \[ {\alpha }_{q}\left( \delta \right) \geq 1 - {H}_{q}\left( \delta \right) \]
The Gilbert-Varshamov bound is the best lower bound for \( {\alpha }_{q}\left( \delta \right) \) which is known from elementary coding theory. However, its proof is not constructive (i.e., it does not provide a simple algebraic algorithm for the construction of good long codes).
No
Lemma 8.4.5. Suppose that \( {P}_{1},\ldots ,{P}_{n} \) are distinct places of \( F/{\mathbb{F}}_{q} \) of degree one. Then there exists, for each \( r \geq 0 \), a divisor \( G \) such that \( \deg G = r \) and \( {P}_{i} \notin \operatorname{supp}G \) (for \( i = 1,\ldots, n \) ).
Proof. The lemma is trivial if there is another place \( Q \) of degree one, different from \( {P}_{1},\ldots ,{P}_{n} \) . In this case we set \( G \mathrel{\text{:=}} {rQ} \) . If \( {P}_{1},\ldots ,{P}_{n} \) are all the places of \( F/{\mathbb{F}}_{q} \) of degree one, we choose a divisor \( G \sim r{P}_{1} \) (i.e...
Yes