Q
stringlengths
4
3.96k
A
stringlengths
1
3k
Result
stringclasses
4 values
Corollary 14.5. Suppose that the search directions satisfy (14.5). If the step size is chosen by the exact minimization rule or limited minimization rule, then any limit \( {x}^{ * } \) of the sequence \( {\left\{ {x}_{k}\right\} }_{0}^{\infty } \) is a critical point of \( f \), that is, \( \nabla f\left( {x}^{ * }\ri...
Proof. Suppose that \( \mathop{\lim }\limits_{{i \rightarrow \infty }}{x}_{{k}_{i}} = {x}^{ * } \), but \( \nabla f\left( {x}^{ * }\right) \neq 0 \) . Let \( {\widehat{x}}_{{k}_{i}} = {x}_{{k}_{i}} + {\widehat{\alpha }}_{{k}_{i}}{d}_{{k}_{i}} \) be the point that would be chosen using an Armijo-type rule. Then\n\n\[ f\...
Yes
Lemma 14.6. (Zoutendijk) Let \( f \) be a function bounded from below on the sublevel set \( M \mathrel{\text{:=}} \left\{ {x : f\left( x\right) \leq f\left( {x}_{0}\right) }\right\} \), with a Lipschitz continuous gradient there, that is, for some \( L > 0 \), \[ \parallel \nabla f\left( y\right) - \nabla f\left( x\ri...
Proof. Recalling \( \begin{Vmatrix}{d}_{k}\end{Vmatrix} = 1 \), we have \[ \left( {{c}_{2} - 1}\right) \left\langle {\nabla f\left( {x}_{k}\right) ,{d}_{k}}\right\rangle \leq \left\langle {\nabla f\left( {x}_{k + 1}\right) - \nabla f\left( {x}_{k}\right) ,{d}_{k}}\right\rangle \leq {t}_{k}L \] where the inequalities fo...
Yes
Lemma 14.8. (Kantorovich’s inequality) If \( Q \) is a symmetric positive definite \( n \times n \) matrix with eigenvalues \( {\left\{ {\lambda }_{i}\right\} }_{1}^{n} \) in the interval \( \left\lbrack {m, M}\right\rbrack \), then\n\n\[ \frac{\langle {Qx}, x\rangle \cdot \langle {Q}^{-1}x, x\rangle }{\parallel x{\par...
Proof. Since the above inequality remains unchanged if we replace each \( Q \) with \( {\tau Q} \), where \( \tau \) is any positive constant, we assume that \( {mM} = 1 \) . Let \( Q = {U}^{T}{\Lambda U} \) be the spectral decomposition of \( Q \), where \( \Lambda = \operatorname{diag}\left( {{\lambda }_{1},\ldots ,{...
Yes
Theorem 14.9. In the steepest-descent method for minimizing a strongly convex quadratic function \( q\left( x\right) \) in (14.9), the optimality gap \( E\left( x\right) = q\left( x\right) - \mathop{\min }\limits_{{\mathbb{R}}^{n}}q \) decreases at a geometric rate,\n\n\[ E\left( {x}_{k + 1}\right) \leq {\left( \frac{\...
Proof. Since \( {x}_{k + 1} - {x}_{k} = - {\alpha }_{k}{r}_{k} \), we have\n\n\[ E\left( {x}_{k + 1}\right) = E\left( {x}_{k}\right) - {\alpha }_{k}{\begin{Vmatrix}{r}_{k}\end{Vmatrix}}^{2} + \frac{{\alpha }_{k}^{2}}{2}\left\langle {Q{r}_{k},{r}_{k}}\right\rangle = E\left( {x}_{k}\right) - \frac{1}{2}\frac{{\begin{Vmat...
Yes
In the steepest-descent method for minimizing a strongly convex quadratic function \( q \) on \( {\mathbb{R}}^{n} \), the optimality gap \( E\left( x\right) = q\left( x\right) - \mathop{\min }\limits_{{\mathbb{R}}^{n}}q \) is halved in every \( O\left( \kappa \right) \) iterations, where \( \kappa = {\lambda }_{\max }/...
Proof. Let \( m \) be the smallest integer satisfying the condition \( {\left( 1 - 2/\left( \kappa + 1\right) \right) }^{m} \leq \) \( 1/2 \) . We have \( \frac{E\left( {x}_{m}\right) }{E\left( {x}_{0}\right) } \leq \frac{1}{2} \), and if \( \kappa \) is large, then\n\n\[ \n- \ln 2 \approx m\ln \left( {1 - \frac{2}{\ka...
Yes
If \( f \) is a convex function with a Lipschitz continuous derivative satisfying\n\n\[ \parallel \nabla f\left( x\right) - \nabla f\left( y\right) \parallel \leq L\parallel x - y\parallel \;\text{ for all }\;x, y \in {\mathbb{R}}^{n}, \]\n\nthen\n\n\[ f\left( y\right) \leq f\left( x\right) + \langle \nabla f\left( x\r...
Proof. Define the function \( g\left( t\right) \mathrel{\text{:=}} f\left( {x + t\left( {y - x}\right) }\right) \), and note that\n\n\[ g\left( 1\right) - g\left( 0\right) = {\int }_{0}^{1}{g}^{\prime }\left( t\right) {dt} = {g}^{\prime }\left( 0\right) + {\int }_{0}^{1}\left( {{g}^{\prime }\left( t\right) - {g}^{\prim...
Yes
Lemma 14.12. Let \( f : C \rightarrow \mathbb{R} \) be a differentiable convex function on the convex set \( C \) . The following conditions are equivalent:\n\n\[ \parallel \nabla f\left( y\right) - \nabla f\left( x\right) \parallel \leq L\parallel y - x\parallel \;\text{ for all }\;x, y \in C. \]\n\n(14.10)\n\n\[ \fra...
Proof. \( \left( {14.10}\right) \Rightarrow \left( {14.11}\right) \) : Notice that Lemma 14.11 gives the second inequality in (14.11); to prove the first inequality, define the function\n\n\[ g\left( y\right) \mathrel{\text{:=}} f\left( y\right) - \langle \nabla f\left( x\right), y\rangle \]\n\nwith the gradient \( \na...
Yes
Lemma 14.15. Let \( C \subseteq {\mathbb{R}}^{n} \) be a closed convex set, and \( f : C \rightarrow \mathbb{R} \) a differentiable function. Let \( s > 0 \). A point \( {x}^{ * } \in C \) satisfies the variational inequality\n\n\[ \left\langle {\nabla f\left( {x}^{ * }\right), x - {x}^{ * }}\right\rangle \geq 0\text{ ...
Proof. By Theorem 6.1, \( {\Pi }_{C}\left( {{x}^{ * } - s\nabla f\left( {x}^{ * }\right) }\right) = {x}^{ * } \) if and only if\n\n\[ \left\langle {\left( {{x}^{ * } - s\nabla f\left( {x}^{ * }\right) }\right) - {x}^{ * }, x - {x}^{ * }}\right\rangle \leq 0\;\text{ for all }\;x \in C, \]\n\nwhich is clearly equivalent ...
Yes
Lemma 14.19. If \( f \) and \( {x}^{ * } \) are as in the above theorem, then\n\n\[ f\left( x\right) = {\int }_{0}^{1}{Df}\left( {{x}^{ * } + t\left( {x - {x}^{ * }}\right) }\right) \left( {x - {x}^{ * }}\right) {dt}. \]
Proof. For the coordinate function \( {f}_{i} \), define \( \alpha \left( t\right) = {f}_{i}\left( {{x}^{ * } + t\left( {x - {x}^{ * }}\right) }\right) \) . We have \( {\alpha }^{\prime }\left( t\right) = \left\langle {\nabla {f}_{i}\left( {{x}^{ * } + t\left( {x - {x}^{ * }}\right) }\right), x - {x}^{ * }}\right\rangl...
Yes
Lemma 14.23. A set \( {\left\{ {d}_{i}\right\} }_{i = 1}^{k} \) of \( Q \) -conjugate directions is linearly independent.
Proof. If \( {\alpha }_{1}{d}_{1} + \cdots + {\alpha }_{k}{d}_{k} = 0 \), then\n\n\[ 0 = \left\langle {\mathop{\sum }\limits_{{i = 1}}^{k}{\alpha }_{i}{d}_{i}, Q{d}_{j}}\right\rangle = \mathop{\sum }\limits_{{i = 1}}^{k}{\alpha }_{i}\left\langle {{d}_{i}, Q{d}_{j}}\right\rangle = {\alpha }_{j}\left\langle {{d}_{j}, Q{d...
Yes
Theorem 14.24. Let \( {\left\{ {d}_{i}\right\} }_{i = 0}^{n - 1} \) be a set of \( Q \) -conjugate directions in \( {\mathbb{R}}^{n} \), and \( {\left\{ {x}_{i}\right\} }_{i = 0}^{n - 1} \) the points generated by the conjugate-direction method using these directions. Then \( {x}_{k} \) is the global minimizer of \( q ...
Proof. Let \( \bar{x} = {x}_{0} + {\gamma }_{0}{d}_{0} + \cdots + {\gamma }_{k - 1}{d}_{k - 1} \) be the minimizer of \( q \) on \( {M}_{k} \). We will show that \( {\gamma }_{i} = {\alpha }_{i}, i = 0,\ldots, k - 1 \), which will imply the first statement of the theorem. By (14.42), we have \[ {\gamma }_{i} = - \frac{...
Yes
Theorem 14.25. Let the gradient vectors \( {\left\{ {r}_{i}\right\} }_{i = 0}^{k} \) be all nonzero. Then \( {\left\{ {r}_{i}\right\} }_{i = 0}^{k} \) are mutually orthogonal, that is,\n\n\[ \n\left\langle {{r}_{i},{r}_{j}}\right\rangle = 0\text{ for all }i \neq j.\n\]\n\nMoreover,\n\n\[ \n{d}_{k} = - {r}_{k} + {\beta ...
Proof. Note that the vectors \( {\left\{ {d}_{i}\right\} }_{0}^{k - 1} \) are generated from the vectors \( {\left\{ {r}_{i}\right\} }_{0}^{k - 1} \) by the Gram-Schmidt process, so that\n\n\[ \n\operatorname{span}\left\{ {{d}_{0},\ldots ,{d}_{k - 1}}\right\} = \operatorname{span}\left\{ {{r}_{0},\ldots ,{r}_{k - 1}}\r...
Yes
Corollary 14.27. Let \( {\left\{ {x}_{i}\right\} }_{i = 0}^{k},{\left\{ {r}_{i}\right\} }_{i = 0}^{k} \), and \( {\left\{ {d}_{i}\right\} }_{i = 0}^{k} \) be the iterates, gradients, and conjugate direction vectors, respectively, generated by a conjugate-gradient method.\n\nIf all the gradient vectors \( {r}_{i} \) are...
Proof. The first equality was already proved in Corollary 14.26; to prove the second, we use induction on \( k \) . The equality is trivially true for \( k = 0 \) ; assuming that it is true for \( k - 1 \), let us prove its truth for \( k \) . Let \( {\left\{ {r}_{i}\right\} }_{i = 0}^{k} \) all be nonzero vectors. It ...
Yes
Theorem 14.29. (Expanding subspace theorem)The point \( {x}_{k} \) generated by the conjugate-gradient method has the variational characterization\n\n\[ E\left( {x}_{k}\right) = \frac{1}{2}\min \left\{ {{\begin{Vmatrix}p\left( Q\right) \left( {x}_{0} - {x}^{ * }\right) \end{Vmatrix}}_{Q}^{2} : p \in {\mathcal{P}}_{k}, ...
Proof. It follows from Theorem 14.24 and Corollary 14.27 that \( {x}_{k} \) is the minimizer \( q \) on the affine subspace \( {M}_{k - 1} = {x}_{0} + \mathcal{K}\left( {Q,{r}_{0}, k - 1}\right) \) . If \( x \in {M}_{k - 1} \) , write\n\n\[ x = {x}_{0} + {\gamma }_{0}{r}_{0} + {\gamma }_{1}Q{r}_{0} + \cdots + {\gamma }...
Yes
Theorem 14.30. Let \( {x}_{k + 1} \) be the \( \left( {k + 1}\right) \) th point generated by the conjugate-gradient method. If \( {\left\{ {\lambda }_{i}\right\} }_{i = 1}^{n} \) are the eigenvalues of the matrix \( Q \), then\n\n\[ \frac{E\left( {x}_{k + 1}\right) }{E\left( {x}_{0}\right) } \leq \mathop{\min }\limits...
Proof. Let \( Q = {U\Lambda }{U}^{T} \) be the spectral decomposition of \( Q \), where \( \Lambda = \) \( \operatorname{diag}\left( {{\lambda }_{1},\ldots ,{\lambda }_{n}}\right) \), and write \( {x}_{0} - {x}^{ * } = {U\delta } \).\n\nIf \( p \in {\mathcal{P}}_{k} \) is such that \( 1 + {tp}\left( t\right) \) is the ...
Yes
Corollary 14.31. Let \( {x}_{k} \) be the \( k \) th point generated by the conjugate-gradient method. Let \( \kappa = {\lambda }_{\max }/{\lambda }_{\min } \) be the condition number of \( Q \), where \( {\lambda }_{\max } \) and \( {\lambda }_{\min } \) are the largest and smallest eigenvalues of \( Q \), respectivel...
Proof. Write \( m = {\lambda }_{\min } \) and \( M = {\lambda }_{\max } \) . Theorem 14.30 implies\n\n\[ \frac{E\left( {x}_{k}\right) }{E\left( {x}_{0}\right) } \leq \mathop{\min }\limits_{p}\mathop{\max }\limits_{i}p{\left( {\lambda }_{i}\right) }^{2} \leq \mathop{\min }\limits_{p}\mathop{\max }\limits_{{x \in \left\l...
Yes
Corollary 14.32. The optimality gap \( E\left( x\right) = q\left( x\right) - q\left( {x}^{ * }\right) \) is halved in every \( O\left( \sqrt{\kappa }\right) \) iterations of the conjugate-gradient method.
Proof. See the proof of Corollary 14.10.
No
Write \( \mathbb{T} \) for the quotient group \( \mathbb{R}/\mathbb{Z} = \{ x + \mathbb{Z} \mid x \in \mathbb{R}\} \), which can be identified with a circle (as a topological space, this can also be obtained as a quotient space of \( \left\lbrack {0,1}\right\rbrack \) by identifying 0 with 1); there is a natural biject...
To see this, assume first that \( x = \frac{p}{q} \) is rational. In this case the orbit of \( x \) is some subset of \( \left\{ {0,\frac{1}{q},\ldots ,\frac{q - 1}{q}}\right\} \) . Conversely, if the orbit is finite then there must be integers \( m, n \) with \( 1 \leq n < m \) for which \( {T}^{m}\left( x\right) = {T...
Yes
We show later that the circle rotation \( {R}_{\alpha } : \mathbb{T} \rightarrow \mathbb{T} \) defined by \( {R}_{\alpha }\left( t\right) = t + \alpha \left( {\;\operatorname{mod}\;1}\right) \) is uniquely ergodic if \( \alpha \) is irrational (see Definition 4.9 and Example 4.11). A consequence of this is that for any...
\[ \frac{1}{N}\mathop{\sum }\limits_{{n = 0}}^{{N - 1}}{\chi }_{\lbrack a, b)}\left( {{R}_{\alpha }^{n}\left( t\right) }\right) \rightarrow b - a \] as \( N \rightarrow \infty \) for every \( t \in \mathbb{T} \) (see Theorem 4.10 and Lemma 4.17).
No
For any \( \alpha \in \mathbb{R} \), define the circle rotation by \( \alpha \) to be the map \[ {R}_{\alpha } : \mathbb{T} \rightarrow \mathbb{T},{R}_{\alpha }\left( t\right) = t + \alpha \;\left( {\;\operatorname{mod}\;1}\right) . \] We claim that \( {R}_{\alpha } \) preserves the Lebesgue measure \( {m}_{\mathbb{T}}...
By Theorem A.8, it is enough to prove it for intervals, where it is clear. Alternatively, we may note that Lebesgue measure is a Haar measure on the compact group \( \mathbb{T} \), which is invariant under any translation by construction (see Sects. 8.3 and C.2).
Yes
The circle-doubling map is \( {T}_{2} : \mathbb{T} \rightarrow \mathbb{T},{T}_{2}\left( t\right) = {2t}\left( {\;\operatorname{mod}\;1}\right) \). We claim that \( {T}_{2} \) preserves the Lebesgue measure \( {m}_{\mathbb{T}} \) on the circle.
By Theorem A.8, it is sufficient to check this on intervals, so let \( B = \lbrack a, b) \subseteq \lbrack 0,1) \) be any interval. Then it is easy to check that\n\n\[ {T}_{2}^{-1}\left( B\right) = \left\lbrack {\frac{a}{2},\frac{b}{2}}\right) \cup \left\lbrack {\frac{a}{2} + \frac{1}{2},\frac{b}{2} + \frac{1}{2}}\righ...
Yes
Generalizing Example 2.4, let \( X \) be a compact abelian group and let \( T : X \rightarrow X \) be a surjective endomorphism. Then \( T \) preserves the Haar measure \( {m}_{X} \) on \( X \) by the following argument.
Define a measure \( \mu \) on \( X \) by \( \mu \left( A\right) = {m}_{X}\left( {{T}^{-1}A}\right) \). Then, given any \( x \in X \) pick \( y \) with \( T\left( y\right) = x \) and notice that\n\n\[ \mu \left( {A + x}\right) = {m}_{X}\left( {{T}^{-1}\left( {A + x}\right) }\right) = {m}_{X}\left( {{T}^{-1}A + y}\right)...
Yes
Lemma 2.6. A measure \( \mu \) on \( X \) is \( T \) -invariant if and only if\n\n\[ \int f\mathrm{\;d}\mu = \int f \circ T\mathrm{\;d}\mu \] \n\n(2.1) \n\nfor all \( f \in {\mathcal{L}}^{\infty } \) . Moreover, if \( \mu \) is \( T \) -invariant, then (2.1) holds for \( f \in {L}_{\mu }^{1} \) .
Proof. If (2.1) holds, then for any measurable set \( B \) we may take \( f = {\chi }_{B} \) to see that\n\n\[ \mu \left( B\right) = \int {\chi }_{B}\mathrm{\;d}\mu = \int {\chi }_{B} \circ T\mathrm{\;d}\mu = \int {\chi }_{{T}^{-1}B}\mathrm{\;d}\mu = \mu \left( {{T}^{-1}B}\right) , \] \n\nso \( T \) preserves \( \mu \)...
Yes
The shift map in Example 2.8 is an example of a one-sided Bernoulli shift. A more general \( {}^{\left( {13}\right) } \) and natural two-sided definition is the following. Consider an infinitely repeated throw of a loaded \( n \) -sided die. The possible outcomes of each throw are \( \{ 1,2,\ldots, n\} \), and these ap...
\[ X = \{ 1,2,\ldots, n{\} }^{\mathbb{Z}} = \left\{ {x = \left( {\ldots ,{x}_{-1},{x}_{0},{x}_{1},\ldots }\right) \mid {x}_{i} \in \{ 1,2,\ldots, n\} \text{ for all }i \in \mathbb{Z}}\right\} . \] The measure on \( X \) is the infinite product measure \( \mu = \mathop{\prod }\limits_{\mathbb{Z}}{\mu }_{\mathbf{p}} \), ...
Yes
Consider the 2-to-1 map \( T : \mathbb{R} \rightarrow \mathbb{R} \) defined by\n\n\[ T\left( x\right) = \frac{1}{2}\left( {x - \frac{1}{x}}\right) \]\n\nfor \( x \neq 0 \), and \( T\left( 0\right) = 0 \). For any \( {L}^{1} \) function \( f \), the substitution \( y = T\left( x\right) \) shows that
\[ {\int }_{-\infty }^{\infty }f\left( {T\left( x\right) }\right) \frac{\mathrm{d}x}{\pi \left( {1 + {x}^{2}}\right) } = {\int }_{-\infty }^{\infty }f\left( y\right) \frac{\mathrm{d}y}{\pi \left( {1 + {y}^{2}}\right) } \]\n\n(in this calculation, note that \( T \) is only injective when restricted to \( \left( {0,\inft...
Yes
Theorem 2.11 (Poincaré Recurrence). Let \( T : X \rightarrow X \) be a measure-preserving transformation on a probability space \( \left( {X,\mathcal{B},\mu }\right) \), and let \( E \subseteq X \) be a measurable set. Then almost every point \( x \in E \) returns to \( E \) infinitely often. That is, there exists a me...
Proof. Let \( B = \left\{ {x \in E \mid {T}^{n}x \notin E}\right. \) for any \( \left. {n \geq 1}\right\} \) . Then\n\n\[ B = E \cap {T}^{-1}\left( {X \smallsetminus E}\right) \cap {T}^{-2}\left( {X \smallsetminus E}\right) \cap \cdots ,\]\n\nso \( B \) is measurable. Now, for any \( n \geq 1 \),\n\n\[ {T}^{-n}B = {T}^...
Yes
Example 2.12. The map \( T : \mathbb{R} \rightarrow \mathbb{R} \) defined by \( T\left( x\right) = x + 1 \) preserves the Lebesgue measure \( {m}_{\mathbb{R}} \) on \( \mathbb{R} \) . Just as in Definition 2.1, this means that\n\n\[ \n{m}_{\mathbb{R}}\left( {{T}^{-1}A}\right) = {m}_{\mathbb{R}}\left( A\right) \n\] \n\n...
For any bounded set \( E \subseteq \mathbb{R} \) and any \( x \in E \) , the set \n\n\[ \n\left\{ {n \geq 1 \mid {T}^{n}x \in E}\right\} \n\] \n\nis finite. Thus the map \( T \) exhibits no recurrence.
No
Proposition 2.14. The following are equivalent properties for a measure-preserving transformation \( T \) of \( \left( {X,\mathcal{B},\mu }\right) \) .\n\n(1) \( T \) is ergodic.\n\n(2) For any \( B \in \mathcal{B},\mu \left( {{T}^{-1}B\bigtriangleup B}\right) = 0 \) implies that \( \mu \left( B\right) = 0 \) or \( \mu...
Proof of Proposition 2.14. (1) \( \Rightarrow \) (2): Assume that \( T \) is ergodic, so the implication (2.2) holds, and let \( B \) be an almost invariant measurable set-that is, a measurable set \( B \) with \( \mu \left( {{T}^{-1}B\bigtriangleup B}\right) = 0 \) . We wish to construct an invariant set from \( B \),...
Yes
Proposition 2.16. The circle rotation \( {R}_{\alpha } : \mathbb{T} \rightarrow \mathbb{T} \) is ergodic with respect to the Lebesgue measure \( {m}_{\mathbb{T}} \) if and only if \( \alpha \) is irrational.
Proof. If \( \alpha \in \mathbb{Q} \), then we may write \( \alpha = \frac{p}{q} \) in lowest terms, so \( {R}_{\alpha }^{q} = {I}_{\mathbb{T}} \) is the identity map. Pick any measurable set \( A \subseteq \mathbb{T} \) with \( 0 < {m}_{\mathbb{T}}\left( A\right) < \frac{1}{q} \) . Then\n\n\[ B = A \cup {R}_{\alpha }A...
Yes
Proposition 2.17. The circle-doubling map \( {T}_{2} : \mathbb{T} \rightarrow \mathbb{T} \) from Example 2.4 is ergodic (with respect to Lebesgue measure).
Proof. By Example 2.8, \( {T}_{2} \) and the Bernoulli shift \( \sigma \) on \( X = \{ 0,1{\} }^{\mathbb{N}} \) together with the fair coin-toss measure are measurably isomorphic. By Proposition 2.15 the latter is ergodic, and it is clear that measurably isomorphic systems are either both ergodic or both not ergodic.
Yes
Lemma 2.18. A measure-preserving transformation \( T \) is ergodic if and only if 1 is a simple eigenvalue of the associated operator \( {U}_{T} \) . Hence ergodicity is a unitary property.
Proof. This follows from the proof of the equivalence of (2) and (5) in Proposition 2.14 or via Exercise 2.3.5 applied with \( p = 2 \) : an eigenfunction for the eigenvalue 1 is a \( T \) -invariant function, and ergodicity is characterized by the property that the only \( T \) -invariant functions are the constants.
No
Theorem 2.19. Let \( T : X \rightarrow X \) be a continuous surjective homomorphism of a compact abelian group \( X \) . Then \( T \) is ergodic with respect to the Haar measure \( {m}_{X} \) if and only if the identity \( \chi \left( {{T}^{n}x}\right) = \chi \left( x\right) \) for some \( n > 0 \) and character \( \ch...
Proof. First assume that there is a non-trivial character \( \chi \) with\n\n\[ \chi \left( {{T}^{n}x}\right) = \chi \left( x\right) \]\n\nfor some \( n > 0 \), chosen to be minimal with this property. Then the function\n\n\[ f\left( x\right) = \chi \left( x\right) + \chi \left( {Tx}\right) + \cdots + \chi \left( {{T}^...
Yes
Corollary 2.22. \( {}^{\left( {19}\right) } \) Let \( \left( {X,\mathcal{B},\mu, T}\right) \) be a measure-preserving system. Then for any function \( f \in {L}_{\mu }^{1} \) the ergodic averages \( {\mathrm{A}}_{N}^{f} \) converge in \( {L}_{\mu }^{1} \) to a \( T \) - invariant function \( {f}^{\prime } \in {L}_{\mu ...
Proof. By the mean ergodic theorem (Theorem 2.21) we know that for any \( g \in {L}_{\mu }^{\infty } \subseteq {L}_{\mu }^{2} \), the ergodic averages \( {\mathrm{A}}_{N}^{g} \) converge in \( {L}_{\mu }^{2} \) to some \( {g}^{\prime } \in {L}_{\mu }^{2} \) . We claim that \( {g}^{\prime } \in {L}_{\mu }^{\infty } \) ....
Yes
Let \( \left( {X,{\mathcal{B}}_{X},\mu, T}\right) \) be a measure-preserving system, and fix a small measurable set \( B \in {\mathcal{B}}_{X} \) with \( \mu \left( B\right) = \varepsilon > 0 \) . Consider the ergodic average\n\n\[ \n{\mathrm{A}}_{N}^{{\chi }_{B}} = \frac{1}{N}\mathop{\sum }\limits_{{n = 0}}^{{N - 1}}{...
Since \( T \) preserves \( \mu ,{\int }_{X}{\chi }_{B} \circ {T}^{n}\mathrm{\;d}\mu = \mu \left( B\right) \) for any \( n \geq 0 \), so\n\n\[ \n{\int }_{X}{\mathrm{\;A}}_{N}^{{\chi }_{B}}\mathrm{\;d}\mu = {\int }_{X}{\chi }_{B}\mathrm{\;d}\mu = \mu \left( B\right) = \varepsilon .\n\]\n\nNotice that\n\n\[ \n\sqrt{\varep...
Yes
Proposition 2.26 (Maximal Inequality). Let \( U : {L}_{\mu }^{1} \rightarrow {L}_{\mu }^{1} \) be a positive linear operator with \( \parallel U\parallel \leq 1 \) . For \( f \in {L}_{\mu }^{1} \) a real-valued function, define inductively the functions\n\n\[ \n{f}_{0} = 0 \n\] \n\n\[ \n{f}_{1} = f \n\] \n\n\[ \n{f}_{2...
Proof. For each \( N \), it is clear that \( {F}_{N} \in {L}_{\mu }^{1} \) . Since \( U \) is positive and linear, and since \n\n\[ \n{F}_{N} \geq {f}_{n} \n\] \n\nfor \( 0 \leq n \leq N \), we have \n\n\[ \nU{F}_{N} + f \geq U{f}_{n} + f = {f}_{n + 1}. \n\] \n\nHence \n\n\[ \nU{F}_{N} + f \geq \mathop{\max }\limits_{{...
Yes
Lemma 2.27 (Finite Vitali covering lemma). Let \( {B}_{{r}_{1}}\left( {a}_{1}\right) ,\ldots ,{B}_{{r}_{K}}\left( {a}_{K}\right) \) be any collection of balls in a metric space. Then there exists a subcollection \( {B}_{{r}_{j\left( 1\right) }}\left( {a}_{j\left( 1\right) }\right) ,\ldots ,{B}_{{r}_{j\left( k\right) }}...
Proof. By reordering the balls if necessary, we may assume that \[ {r}_{1} \geq {r}_{2} \geq \cdots \geq {r}_{K} \] Let \( j\left( 1\right) = 1 \) . We choose the remaining disjoint balls by induction as follows. Assume that we have chosen \( j\left( 1\right) ,\ldots, j\left( n\right) \) from the indices \( \{ 1,\ldots...
Yes
For any \( \phi \in {\ell }^{1}\left( \mathbb{Z}\right) \) and \( \alpha > 0 \), define\n\n\[ \n{\phi }^{ * }\left( a\right) = \mathop{\sup }\limits_{{n \geq 1}}\frac{1}{n}\mathop{\sum }\limits_{{i = 0}}^{{n - 1}}\phi \left( {a + i}\right)\n\]\n\nand\n\n\[ \n{E}_{\alpha }^{\phi } = \left\{ {a \in \mathbb{Z} \mid {\phi ...
Proof of Lemma 2.29. Let \( {a}_{1},\ldots ,{a}_{K} \) be different elements of \( {E}_{\alpha }^{\phi } \), and let \( \ell \left( j\right) \) for \( j = 1,\ldots, K \) be chosen so that\n\n\[ \n\frac{1}{\ell \left( j\right) }\mathop{\sum }\limits_{{i = 0}}^{{\ell \left( j\right) - 1}}\phi \left( {{a}_{j} + i}\right) ...
Yes
In Example 1.2 we explained that almost every real number has the property that any block of length \( k \) of digits base 10 appears with asymptotic frequency \( \frac{1}{{10}^{k}} \), thus almost every number is normal base 10 . We now have all the material needed to justify this result: By Corollary 2.20, the map \(...
FIRST Proof of THEOREM 2.30. Recall that \( \left( {X,\mathcal{B},\mu, T}\right) \) is a measure-preserving system, \( \mu \left( X\right) = 1 \), and \( f \in {\mathcal{L}}_{\mu }^{1} \) . It is sufficient to prove the result for a real-valued function \( f \) . Define, for any \( x \in X \) ,\n\n\[ \n{f}^{ * }\left( ...
Yes
A circle rotation \( {R}_{\alpha } : \mathbb{T} \rightarrow \mathbb{T} \) is not mixing.
There is a sequence \( {n}_{j} \rightarrow \infty \) for which \( {n}_{j}\alpha \left( {\;\operatorname{mod}\;1}\right) \rightarrow 0 \) (if \( \alpha \) is rational we may choose to have \( {n}_{j}\alpha \left( {\;\operatorname{mod}\;1}\right) = 0 \) ). If \( A = B = \left\lbrack {0,\frac{1}{2}}\right\rbrack \) then \...
Yes
Lemma 2.43. The induced transformation \( {T}_{A} \) is a measure-preserving transformation on the space \( \left( {A,{\left. \mathcal{B}\right| }_{A},{\mu }_{A} = {\left. \frac{1}{\mu \left( A\right) }\mu \right| }_{A},{T}_{A}}\right) \) . If \( T \) is ergodic with respect to \( \mu \) then \( {T}_{A} \) is ergodic w...
Proof of Lemma 2.43. If \( B \subseteq A \) is measurable, then \( B = \mathop{\bigsqcup }\limits_{{n \geq 1}}B \cap {A}_{n} \) is a disjoint union so\n\n\[ \n{\mu }_{A}\left( B\right) = \frac{1}{\mu \left( A\right) }\mathop{\sum }\limits_{{n \geq 1}}\mu \left( {B \cap {A}_{n}}\right) \n\]\n\n(2.37)\n\nNow\n\n\[ \n{T}_...
Yes
Theorem 2.44 (Kac). Let \( \left( {X,\mathcal{B},\mu, T}\right) \) be an ergodic measure-preserving system and let \( A \in \mathcal{B} \) have \( \mu \left( A\right) > 0 \) . Then the expected return time to \( A \) is \( \frac{1}{\mu \left( A\right) } \) ; equivalently\n\n\[{\int }_{A}{r}_{A}\mathrm{\;d}\mu = 1\]
\( {\text{Proof}}^{\left( {35}\right) } \) . Referring to Fig. 2.2, each column\n\n\[{A}_{n} \sqcup T\left( {A}_{n}\right) \sqcup \cdots \sqcup {T}^{n - 1}\left( {A}_{n}\right)\]\n\ncomprises \( n \) disjoint sets each of measure \( \mu \left( {A}_{n}\right) \), and the entire skyscraper contains almost all of \( X \) ...
Yes
Lemma 2.45 (Kakutani-Rokhlin). Let \( \\left( {X,\\mathcal{B},\\mu, T}\\right) \) be an invertible ergodic measure-preserving system and assume that \( \\mu \) is non-atomic (that is, \( \\mu \\left( {\\{ x\\} }\\right) = 0 \) for all \( x \\in X \) ). Then for any \( n \\geq 1 \) and \( \\varepsilon > 0 \) there is a ...
Proof of Lemma 2.45. Let \( A \) be a measurable set with \( 0 < \\mu \\left( A\\right) < \\varepsilon /n \) (such a set exists by the assumption that \( \\mu \) is non-atomic) and form the Kakutani skyscraper over \( A \) . Then \( X \) decomposes into a union of disjoint columns of the form\n\n\[ {A}_{k} \\sqcup T\\l...
Yes
Fix a sequence \( {\left( {a}_{n}\right) }_{n \geq 0} \) with \( {a}_{0} \in {\mathbb{N}}_{0} \) and \( {a}_{n} \in \mathbb{N} \) for \( n \geq 1 \) . Then the rational numbers\n\n\[ \frac{{p}_{n}}{{q}_{n}} = \left\lbrack {{a}_{0};{a}_{1},{a}_{2},\ldots ,{a}_{n}}\right\rbrack \]\n\nfor \( n \geq 0 \) with coprime numer...
Proof. Notice first that the sequence \( {\left( {a}_{n}\right) }_{n \geq 0} \) defines the sequences \( {\left( {p}_{n}\right) }_{n \geq - 1} \) and \( {\left( {q}_{n}\right) }_{n \geq - 1} \) . The claim of the lemma is proved by induction on \( n \) . Assume that (3.3) holds for \( 0 \leq n \leq k - 1 \) and \( {p}_...
Yes
Lemma 3.2. Let \( {a}_{n} \in \mathbb{N} \) for all \( n \geq 0 \) . Then the limit in (3.10) is irrational.
Proof. Suppose that \( u = \frac{a}{b} \in \mathbb{Q} \) . Then, by (3.14), \[ \left| {{q}_{n}a - b{p}_{n}}\right| < \frac{b}{{a}_{n + 1}{q}_{n}} \leq \frac{b}{{q}_{n}}. \] Since \( {q}_{n} \rightarrow \infty \) by the inequality (3.6) and \( {q}_{n}a - b{p}_{n} \in \mathbb{Z} \) we see that \[ {q}_{n}a - b{p}_{n} = 0 ...
Yes
Lemma 3.4. The map that sends the sequence\n\n\\[ \n\\left( {{a}_{0},{a}_{1},\\ldots }\\right) \\in {\\mathbb{N}}_{0} \\times {\\mathbb{N}}^{\\mathbb{N}}\n\\]\n\nto the limit in (3.10) is injective.
Proof. Let \\( u = \\left( {{a}_{0},{a}_{1},\\ldots }\\right) \\in {\\mathbb{N}}_{0} \\times {\\mathbb{N}}^{\\mathbb{N}} \\) be given. Then it is clear that\n\n\\[ \nu = \\left\\lbrack {{a}_{0};{a}_{1},\\ldots }\\right\\rbrack \\]\n\nis positive. Applying this to \\( \\left( {{a}_{1},{a}_{2},\\ldots }\\right) \\) and t...
Yes
Lemma 3.5. The continued fraction map \( T\left( x\right) = \left\{ \frac{1}{x}\right\} \) on \( \left( {0,1}\right) \) preserves the Gauss measure \( \mu \) given by\n\n\[ \mu \left( A\right) = \frac{1}{\log 2}{\int }_{A}\frac{1}{1 + x}\mathrm{\;d}x \] \n\nfor any Borel measurable set \( A \subseteq \left\lbrack {0,1}...
Proof of Lemma 3.5. It is sufficient to show that \( \mu \left( {{T}^{-1}\left\lbrack {0, s}\right\rbrack }\right) = \mu \left( \left\lbrack {0, s}\right\rbrack \right) \) for every \( s > 0 \) . Clearly\n\n\[ {T}^{-1}\left\lbrack {0, s}\right\rbrack = \{ x \mid 0 \leq T\left( x\right) \leq s\} = \mathop{\bigsqcup }\li...
Yes
For any irrational \( x \in \left\lbrack {0,1}\right\rbrack \smallsetminus \mathbb{Q} \) the sequence \( \left( {{a}_{n}\left( x\right) }\right) \) defined in (3.18) gives the digits of the continued fraction expansion to \( x \) . That is,\n\n\[ x = \left\lbrack {{a}_{1}\left( x\right) ,{a}_{2}\left( x\right) ,\ldots ...
Proof. Define \( {a}_{n} = {a}_{n}\left( x\right) \) and let \( u = \left\lbrack {{a}_{1},{a}_{2},\ldots }\right\rbrack \) be the limit as in (3.10) with \( {a}_{0} = 0 \) . By (3.11) we have\n\n\[ \frac{{p}_{2n}}{{q}_{2n}} < u < \frac{{p}_{{2n} + 1}}{{q}_{{2n} + 1}} \]\n\nand by (3.8) and the inequality (3.6) we have\...
Yes
Theorem 3.7. The continued fraction map \( T\left( x\right) = \left\{ \frac{1}{x}\right\} \) on \( \left( {0,1}\right) \) is ergodic with respect to the Gauss measure \( \mu \) .
Proof of Theorem 3.7. The description of the continued fraction map as a shift on the space \( {\mathbb{N}}^{\mathbb{N}} \) described above suggests the method of proof: the measure \( \mu \) corresponds to a rather complicated measure on the shift space, but if we can control the measure of cylinder sets (and their in...
Yes
For almost every real number \( x = \left\lbrack {{a}_{1},{a}_{2},\ldots }\right\rbrack \in \left( {0,1}\right) \), the digit \( j \) appears in the continued fraction with density
Proof. The digit \( j \) appears in the first \( N \) digits with frequency\n\n\[ \frac{1}{N}\left| \left\{ {i \mid i \leq N,{a}_{i} = j}\right\} \right| = \frac{1}{N}\left| \left\{ {i \mid i \leq N,{T}^{i}x \in \left( {\frac{1}{j + 1},\frac{1}{j}}\right) }\right\} \right| \]\n\n\[ \rightarrow \frac{1}{\log 2}{\int }_{...
Yes
Proposition 3.10. A number \( u \in \left( {0,1}\right) \) is badly approximable if and only if there exists some \( \varepsilon > 0 \) with the property that\n\n\[ \left| {u - \frac{p}{q}}\right| \geq \frac{\varepsilon }{{q}^{2}} \]\n\nfor all rational numbers \( \frac{p}{q} \) .
Proof. If \( u \) is badly approximable, then (3.4) shows that\n\n\[ {q}_{n + 1} \leq \left( {M + 1}\right) {q}_{n} \]\n\nfor all \( n \geq 0 \) . For any \( q \) there is some \( n \) with \( q \in \left( {{q}_{n - 1},{q}_{n}}\right\rbrack \), and by Proposition 3.3 and (3.15) we therefore have\n\n\[ \left| {\frac{p}{...
Yes
Notice that \( \frac{2}{\sqrt{5} - 1} = \frac{\sqrt{5} + 1}{2} \in \left( {1,2}\right) \) and \( \frac{\sqrt{5} + 1}{2} - 1 = \frac{\sqrt{5} - 1}{2} \). It follows that if \[ \frac{\sqrt{5} - 1}{2} = \left\lbrack {{a}_{1},{a}_{2},\ldots }\right\rbrack \] then \( {a}_{1} + \left\lbrack {{a}_{2},{a}_{3},\ldots }\right\rb...
Indeed, the specific number in Example 3.11 is, in a precise sense, the most badly approximable real number in \( \left( {0,1}\right) \) . In the next section we generalize this example to show that all quadratic irrationals are badly approximable.
Yes
Theorem 3.13 (Lagrange). Let \( u \) be an irrational positive real number. Then the continued fraction expansion of \( u \) is eventually periodic if and only if \( u \) is a quadratic irrational.
Proof. Assume first that \( u = \left\lbrack \overline{{a}_{0};{a}_{1},\ldots ,{a}_{k}}\right\rbrack \) has a strictly periodic continued fraction expansion, so that \( {u}_{k + 1} = {u}_{0} = u \) . Thus\n\n\[ u = \frac{u{p}_{k} + {p}_{k - 1}}{u{q}_{k} + {q}_{k - 1}} \]\n\nby \( \left( {3.20}\right) \), so\n\n\[ {u}^{...
Yes
Corollary 3.14. Any quadratic irrational is badly approximable.
Proof. This is an immediate consequence of Theorem 3.13 and Definition 3.9.
No
Corollary 4.2 (Kryloff-Bogoliouboff). Under the hypotheses of Theorem 4.1, \( {\mathcal{M}}^{T}\left( X\right) \) is non-empty.
Proof. Since \( \mathcal{M}\left( X\right) \) is weak*-compact, the sequence \( \left( {\mu }_{n}\right) \) must have a limit point.
No
Define the 'North-South' map \( T : X \rightarrow X \) on the circle \( X = \{ z \in \mathbb{C}\left| \right| z - \mathrm{i} \mid = 1\} \) using the stereographic projection \( \pi \) and show its properties.
The 'North-South' map \( T : X \rightarrow X \) is defined by \[ T\left( z\right) = \left\{ \begin{array}{ll} 2\mathrm{i} & \text{ if }z = 2\mathrm{i} \\ {\pi }^{-1}\left( {\pi \left( z\right) /2}\right) & \text{ if }z \neq 2\mathrm{i} \end{array}\right. \] as shown in Fig. 4.1. Using Poincaré recurrence (Theorem 2.11)...
No
Lemma 4.6. If \( {\mu }_{1},{\mu }_{2} \in {\mathcal{E}}^{T}\left( X\right) \) and \( {\mu }_{1} \neq {\mu }_{2} \) then \( {\mu }_{1} \) and \( {\mu }_{2} \) are mutually singular.
Proof. Let \( f \in C\left( X\right) \) be chosen with \( \int f\mathrm{\;d}{\mu }_{1} \neq \int f\mathrm{\;d}{\mu }_{2} \) (such a function exists by Theorem B.11). Then by the ergodic theorem (Theorem 2.30)\n\n\[{\mathrm{A}}_{n}^{f}\left( x\right) \rightarrow \int f\mathrm{\;d}{\mu }_{1}\]\n\n(4.3)\n\nfor \( {\mu }_{...
Yes
Theorem 4.8 (Ergodic decomposition). Let \( X \) be a compact metric space and \( T : X \rightarrow X \) a continuous map. Then for any \( \mu \in {\mathcal{M}}^{T}\left( X\right) \) there is a unique probability measure \( \lambda \) defined on the Borel subsets of the compact metric space \( {\mathcal{M}}^{T}\left( X...
Proof. This follows from Choquet's theorem [55] (see also the notes of Phelps [283]). A different proof will be given later (cf. p. 154), and a nontrivial example may be seen in Example 4.13.
No
The circle rotation \( {R}_{\alpha } : \mathbb{T} \rightarrow \mathbb{T} \) is uniquely ergodic if and only if \( \alpha \) is irrational. The unique invariant measure in this case is the Lebesgue measure \( {m}_{\mathbb{T}} \).
This may be proved using property (5) of Theorem 4.10 (or using property (1); see Theorem 4.14). Assume first that \( \alpha \) is irrational, so \( {\mathrm{e}}^{{2\pi }\mathrm{i}{k\alpha }} = 1 \) only if \( k = 0 \) . If \( f\left( t\right) = {\mathrm{e}}^{{2\pi }\mathrm{i}{kt}} \) for some \( k \in \mathbb{Z} \), t...
Yes
Let \( X = \{ z \in \mathbb{C}\left| \right| z \mid = 1 \) or \( 2\} \), let \( \alpha \) be an irrational number, and define a continuous map \( T : X \rightarrow X \) by \( T\left( z\right) = {\mathrm{e}}^{{2\pi }\mathrm{i}\alpha }z \). By unique ergodicity on each circle, any invariant measure \( \mu \) takes the fo...
\[ \mu = s{m}_{1} + \left( {1 - s}\right) {m}_{2} \] where \( {m}_{1} \) and \( {m}_{2} \) denote Lebesgue measures on the two circles comprising \( X \) . Thus \( {\mathcal{M}}^{T}\left( X\right) = \left\{ {s{m}_{1} + \left( {1 - s}\right) {m}_{2} \mid s \in \left\lbrack {0,1}\right\rbrack }\right\} \), with the two e...
Yes
A more sophisticated version of Example 4.12 is a rotation on the disk. Let \( \mathbb{D} = \{ z \in \mathbb{C}\left| \right| z \mid \leq 1\} \), let \( \alpha \) be an irrational number, and define a continuous map \( T : \mathbb{D} \rightarrow \mathbb{D} \) by \( T\left( z\right) = {\mathrm{e}}^{{2\pi }\mathrm{i}\alp...
\[ \mu \left( A\right) = {\int }_{{\mathcal{M}}^{T}\left( X\right) }{m}_{r}\left( A\right) \mathrm{d}\nu \left( {m}_{r}\right) \]
Yes
Theorem 4.14. Let \( X \) be a compact metrizable group and \( {R}_{g}\left( x\right) = {gx} \) the rotation by a fixed element \( g \in X \) . Then the following are equivalent.\n\n(1) \( {R}_{g} \) is uniquely ergodic (with the unique invariant measure being \( {m}_{X} \), the Haar measure on \( X \) ).\n\n(2) \( {R}...
Proof. (1) \( \Rightarrow \) (2): This is clear.\n\n(2) \( \Rightarrow \) (3): Let \( Y \) denote the closure of the subgroup generated by \( g \) . If \( Y \neq X \) then there is a continuous non-constant function on \( X \) that is constant on each coset of \( Y \) : in fact if \( \mathrm{d} \) is a bi-invariant met...
Yes
Corollary 4.15. Let \( X = {\mathbb{T}}^{\ell } \), and let \( g = \left( {{\alpha }_{1},{\alpha }_{2},\ldots ,{\alpha }_{\ell }}\right) \in {\mathbb{R}}^{\ell } \) . Then the toral rotation \( {R}_{g} : {\mathbb{T}}^{\ell } \rightarrow {\mathbb{T}}^{\ell } \) given by \( {R}_{g}\left( x\right) = x + g \) is uniquely e...
Exercise 4.3.5. Prove Corollary 4.15\n\n(a) using Theorem 4.14;\n\n(b) using Theorem 4.10(5).
No
A consequence of Theorem 4.10 and Example 4.11 is that for any irrational number \( \alpha \), and any initial point \( x \in \mathbb{T} \), the orbit \( x,{R}_{\alpha }x,{R}_{\alpha }^{2}x,\ldots \) under the circle rotation is an equidistributed sequence.
Note that this is proved in Example 4.11 by using property (2) of Lemma 4.17.
No
Corollary 4.20. Let \( X \) be a compact metric space, let \( T : X \rightarrow X \) be a continuous map, and let \( \mu \) be a \( T \) -invariant ergodic probability measure. Then \( \mu \) - almost every point in \( X \) is generic with respect to \( T \) and \( \mu \) .
Proof. Recall that \( C\left( X\right) \) is a separable metric space with respect to the uniform norm\n\n\[ \parallel f{\parallel }_{\infty } = \sup \{ \left| {f\left( x\right) }\right| \mid x \in X\} \]\n\nby Lemma B.8. Let \( {\left( {f}_{n}\right) }_{n \geq 1} \) be a dense sequence in \( C\left( X\right) \) . By a...
Yes
Theorem 4.21 (Furstenberg). Let \( T : X \rightarrow X \) be a uniquely ergodic homeomorphism of a compact metric space with unique invariant measure \( \mu \) . Let \( G \) be a compact group* with Haar measure \( {m}_{G} \), and let \( c : X \rightarrow G \) be a continuous map. Define the skew-product map \( S \) on...
Proof. To see that \( S \) preserves \( \mu \times {m}_{G} \), let \( f \in C\left( Y\right) \) . Then, by Fubini’s theorem, \[ {\int }_{Y}f \circ S\mathrm{\;d}\left( {\mu \times {m}_{G}}\right) = {\int }_{X}{\int }_{G}f\left( {{Tx}, c\left( x\right) g}\right) \mathrm{d}{m}_{G}\left( g\right) \mathrm{d}\mu \left( x\rig...
Yes
Corollary 4.22. Let \( \alpha \) be an irrational number. Then the map \( S : {\mathbb{T}}^{k} \rightarrow {\mathbb{T}}^{k} \) defined by\n\n\[ S : \left( \begin{matrix} {x}_{1} \\ {x}_{2} \\ \vdots \\ {x}_{k} \end{matrix}\right) \mapsto \left( \begin{matrix} {x}_{1} + \alpha \\ {x}_{2} + {x}_{1} \\ \vdots \\ {x}_{k} +...
Proof. Notice that the transformation \( S \) is built up from the irrational circle map by taking \( \left( {k - 1}\right) \) skew-product extensions as in Theorem 4.21. By Theorem 4.21, it is sufficient to prove that \( S \) is ergodic with respect to\n\nLebesgue measure on \( {\mathbb{T}}^{k} \) . Let \( f \in {L}^{...
Yes
If \( \mathcal{A} = \sigma \left( \xi \right) \) is the finite \( \sigma \) -algebra generated by a finite partition \( \xi = \left\{ {{A}_{1},\ldots ,{A}_{n}}\right\} \) of \( X \), then
\[ E\left( {f \mid \mathcal{A}}\right) \left( x\right) = \frac{1}{\mu \left( {A}_{i}\right) }{\int }_{{A}_{i}}f\mathrm{\;d}\mu \] if \( x \in {A}_{i} \) . The \( \sigma \) -algebra being conditioned on is illustrated in Fig. 5.1 for a partition into \( n = 8 \) sets; \( E\left( {f \mid \mathcal{A}}\right) \) is then a ...
Yes
Lemma 5.6 (Doob’s inequality). Let \( f \in {L}^{1}\left( {X,\mathcal{B},\mu }\right) \), let
Proof. Assume that \( f \geq 0 \) (if necessary replacing \( f \) by \( \left| f\right| \), which makes \( \mu \left( E\right) \) no smaller). Let
No
Theorem 5.8 (Decreasing martingale theorem). Let \( \left( {X,\mathcal{B},\mu }\right) \) be a probability space. If \( {\mathcal{A}}_{n} \searrow {\mathcal{A}}_{\infty } \) is a decreasing sequence of sub- \( \sigma \) -algebras of \( \mathcal{B} \) then\n\n\[ E\left( {f \mid {\mathcal{A}}_{n}}\right) \rightarrow E\le...
FIRST PART OF PROOF OF THEOREM 5.8, USING \( {L}^{2} \) . Recall from the proof of Theorem 5.1 that in \( {L}^{2}\left( {X,\mathcal{B},\mu }\right) \) the conditional expectation with respect to \( {\mathcal{A}}_{n} \) (or \( {\mathcal{A}}_{\infty } \) ) is precisely the orthogonal projection to \( {L}^{2}\left( {X,{\m...
Yes
Let \( \xi \) be a countable partition of \( \left( {X,\mathcal{B},\mu }\right) \), with \( \mathcal{A} = \sigma \left( \xi \right) \) the smallest \( \sigma \) -algebra containing \( \xi \) . Then
\[ {\mu }_{x}^{\mathcal{A}} = {\left. \frac{1}{\mu \left( P\right) }\mu \right| }_{P} \] for \( x \in P \in \mathcal{A} \) defines such a measure for almost every \( x \) ; if \( \mu \left( P\right) = 0 \) then \( {\mu }_{x}^{\mathcal{A}} \) is not defined for \( x \in P \) .
No
Let \( \mathcal{A} = {\mathcal{B}}_{\left\lbrack 0,1\right\rbrack } \times \{ \varnothing ,\left\lbrack {0,1}\right\rbrack \} \subseteq {\mathcal{B}}_{{\left\lbrack 0,1\right\rbrack }^{2}} \). Then
\[ {\mu }_{\left( {x}_{1},{x}_{2}\right) }^{\mathcal{A}} = {\delta }_{{x}_{1}} \times {m}_{\left\lbrack 0,1\right\rbrack } \] where as usual \( m \) denotes Lebesgue (or Haar) measure (see Fig. 5.2).
No
Let \( X = \{ 0,1{\} }^{\mathbb{R}} \), with the product topology and the \( \sigma \) -algebra of Borel sets. The product measure \( \mu \) of the \( \left( {\frac{1}{2},\frac{1}{2}}\right) \) measure on each of the sets \( \{ 0,1\} \) makes \( X \) into a probability space with the property that there is an uncountab...
\[ \mu \left( {{A}_{{s}_{1}} \cap \cdots \cap {A}_{{s}_{n}}}\right) = \frac{1}{{2}^{n}} \] for any \( n \) distinct reals \( {s}_{1},\ldots ,{s}_{n} \).
Yes
Lemma 5.17. If \( \left( {X,\mathcal{B},\mu }\right) \) is a Borel probability space and \( \mathcal{A} \subseteq \mathcal{B} \) is a \( \sigma \) - algebra then there is a countably-generated \( \sigma \) -algebra \( \mathcal{A} \) with \( \mathcal{A} = \mathcal{A} \) .
Proof. Recall that \( C\left( \bar{X}\right) \) is separable for any compact metric space \( \bar{X} \) (see Lemma B.8). Since \( C\left( \bar{X}\right) \) is mapped continuously to a dense subspace of \( {L}^{1}\left( {X,\mathcal{B},\mu }\right) \), the same holds for \( {L}^{1}\left( {X,\mathcal{B},\mu }\right) \) . ...
Yes
Lemma 5.18. Let \( \left( {X,\mathcal{B},\mu }\right) \) be a Borel probability space and let \( \mathcal{A} \subseteq \mathcal{B} \) be a countably-generated \( \sigma \) -algebra. If \( f \in {\mathcal{L}}^{\infty }\left( {X,\mathcal{B}}\right) \) is constant on atoms of \( \mathcal{A} \) , then \( {\left. f\right| }...
Proof of Lemma 5.18. By Theorem 5.14(2), on \( {X}^{\prime } \) we have\n\n\[ \int f\mathrm{\;d}{\mu }_{x}^{\mathcal{A}} = f\left( x\right) \]\n\nsince \( {\mu }_{x}^{\mathcal{A}}\left( {\left\lbrack x\right\rbrack }_{\mathcal{A}}\right) = 1 \) and, by assumption, \( f \) is constant (and equal to \( f\left( x\right) \...
Yes
Corollary 5.22. Let \( \left( {X,\mathcal{B},\mu }\right) \) be a Borel probability space, and let \( \mathcal{A} \subseteq \mathcal{B} \) be a countably-generated \( \sigma \) -algebra. Then there is a conull set \( {X}^{\prime } = X \smallsetminus N \) in \( \mathcal{A} \), a compact metric space together with its Bo...
This will be proved later; the conclusion described in Corollary 5.22 is depicted in Fig. 5.3.
No
If \( \bar{X} \) is a compact metric space, and \( f \in {\mathcal{L}}^{\infty }\left( \bar{X}\right) \), then the map\n\n\[ \mathcal{M}\left( X\right) \ni \nu \mapsto \int f\mathrm{\;d}\nu \]\n\nis Borel measurable. In particular, for a Borel subset \( X \) of \( \bar{X} \), we have that \( \mathcal{M}\left( X\right) ...
Proof. Starting with continuous functions, we know that \( \int f\mathrm{\;d}\nu \) depends continuously on \( \nu \) (by definition of the weak*-topology on \( \mathcal{M}\left( X\right) \) ). Arguing just as we did on p. 139, this can be extended to show that \( \int f\mathrm{\;d}\nu \) depends measurably on \( \nu \...
Yes
Corollary 5.24. Let \( \phi : \left( {X,{\mathcal{B}}_{X},\mu }\right) \rightarrow \left( {Y,{\mathcal{B}}_{Y},\nu }\right) \) be a measure-preserving map between Borel probability spaces, and let \( \mathcal{A} \subseteq {\mathcal{B}}_{Y} \) be a sub-σ-algebra. Then\n\n\[ \n{\phi }_{ * }{\mu }_{x}^{{\phi }^{-1}\mathca...
Proof. First notice that for any \( f \in {L}^{1}\left( {Y,{\mathcal{B}}_{Y},\nu }\right) ,{E}_{\nu }\left( {f \mid \mathcal{A}}\right) \circ \phi \) is \( {\phi }^{-1}\mathcal{A} \) - measurable and\n\n\[ \n{\int }_{{\phi }^{-1}A}{E}_{\nu }\left( {f \mid \mathcal{A}}\right) \circ \phi \mathrm{d}\mu = {\int }_{A}{E}_{\...
Yes
Lemma 5.25. Let \( X, Y, Z \) be Borel subsets of compact metric spaces \( \bar{X},\bar{Y} \) and \( \bar{Z} \) respectively, and let \( {\phi }_{Z} : X \rightarrow Z \) and \( {\phi }_{Y} : X \rightarrow Y \) be measurable maps. Suppose that \( {\phi }_{Z} \) is \( {\phi }_{Y}^{-1}\left( {\mathcal{B}}_{Y}\right) \) -m...
Proof of Lemma 5.25. Define \( \mathcal{A} = {\phi }_{Y}^{-1}\left( {\mathcal{B}}_{Y}\right) \), which is countably-generated since \( {\mathcal{B}}_{Y} \) is. Since the Borel \( \sigma \) -algebra \( {\mathcal{B}}_{Y} \) of \( Y \) separates points,\n\n\[{\left\lbrack x\right\rbrack }_{\mathcal{A}} = {\phi }_{Y}^{-1}\...
Yes
Theorem 6.1. Let \( \\left( {X,\\mathcal{B},\\mu, T}\\right) \) be a measure-preserving system and \( f \\in {L}_{\\mu }^{1} \) . Then\n\n\[ \n\\frac{1}{M}\\mathop{\\sum }\\limits_{{n = 0}}^{{M - 1}}f \\circ {T}^{n} \\rightarrow E\\left( {f \\mid \\mathcal{E}}\\right)\n\]\n\nalmost everywhere and in \( {L}^{1} \), wher...
Proof of Theorem 6.1. By Theorem 2.30 the sequence converges to some \( {f}^{ * } \\in {L}^{1} \) both pointwise and in \( {L}^{1} \). Now \( {f}^{ * } \) is \( \\mathcal{E} \) -measurable since \( {f}^{ * } \) is \( T \) -invariant. Moreover, for any set \( A \\in \\mathcal{E} \) with positive measure, we may apply Th...
Yes
Lemma 6.3. Let \( \left( {X,{\mathcal{B}}_{X},\nu, T}\right) \) be a measure-preserving system on a Borel probability space, and let \( \left\{ {{f}_{1},{f}_{2},\ldots }\right\} \) be dense in \( C\left( \bar{X}\right) \) . Then \( \nu \) is ergodic if and only if\n\n\[ \n\frac{1}{M}\mathop{\sum }\limits_{{n = 0}}^{{M ...
Proof. Ergodicity clearly implies the stated property. For the converse, recall that \n\n\[ \n\frac{1}{M}\mathop{\sum }\limits_{{n = 0}}^{{M - 1}}f \circ {T}^{n}\underset{{L}_{\nu }^{2}}{ \rightarrow }{P}_{T}f \n\] \n\nwhere \( {P}_{T} \) denotes the projection operator onto the space of \( {U}_{T} \) -invariant functi...
Yes
Theorem 6.5. Let \( \\left( {X,{\\mathcal{B}}_{X},\\mu }\\right) \) be a Borel probability space, and let \( T \) be a measure-preserving transformation on \( X \) . Assume furthermore that there is a T-invariant sub-\\sigma-algebra \( \\mathcal{A} \\subseteq {\\mathcal{B}}_{X} \) . Then there is a measure-preserving s...
Proof. We are going to apply Corollary 5.22 with the choice \( Y = \\mathcal{M}\\left( X\\right) \) appearing in the proof. Let \( S : Y \\rightarrow Y \) be the map defined by \( {S\\nu } = {T}_{ * }\\nu \) for any \( \\nu \\in Y \) . By Lemma 5.23, \( S \) is measurable. Define a map \( \\phi : X \\rightarrow Y \) by...
Yes
Lemma 6.8. Let \( \mathrm{X} \) and \( \mathrm{Y} \) be ergodic systems with \( \rho \in J\left( {\mathrm{X},\mathrm{Y}}\right) \) . Then almost every ergodic component of \( \rho \) is an ergodic joining of \( \mathrm{X} \) and \( \mathrm{Y} \) .
Proof of Lemma 6.8. Suppose that\n\n\[ \rho = {\int }_{Z}{\rho }_{z}\mathrm{\;d}\tau \left( z\right) \]\n\nis the ergodic decomposition of \( \rho \) from Theorem 6.2, for some probability space \( \left( {Z,{\mathcal{B}}_{Z},\tau }\right) \) . Recall that \( {\pi }_{X} : X \times Y \rightarrow X \) denotes the project...
Yes
Lemma 6.9. If \( \left( {X,\mathcal{B},\mu, T}\right) \) is ergodic then every eigenvalue of \( {U}_{T} \) is simple, and the set of all eigenvalues of \( {U}_{T} \) is a subgroup of \( {\mathbb{S}}^{1} \) .
Proof. If \( {U}_{T}f = {\lambda f} \) then\n\n\[ \langle f, f\rangle = \left\langle {{U}_{T}f,{U}_{T}f}\right\rangle = \lambda \bar{\lambda }\langle f, f\rangle \]\n\nso \( \lambda \bar{\lambda } = 1 \) . If \( f \) is an eigenfunction corresponding to the eigenvalue \( \lambda \), then\n\n\[ {U}_{T}\left| f\right| = ...
Yes
Theorem 6.10 (Kronecker factors). Let \( \left( {X,\mathcal{B},\mu, T}\right) \) be an invertible ergodic measure-preserving system on a Borel probability space, and let \( \mathcal{A} \) be the smallest \( \sigma \) -algebra with respect to which all \( {L}_{\mu }^{2} \) eigenfunctions of \( {U}_{T} \) are measurable....
Proof of Theorem 6.10. Let \( \left\{ {{\chi }_{i} \mid i \in \mathbb{N}}\right\} \subseteq {L}_{\mu }^{2} \) be an enumeration* of the eigenfunctions of \( {U}_{T} \) normalized so that \( \left| {\chi }_{i}\right| = 1 \) almost everywhere, and let \( {U}_{T}{\chi }_{i} = {\lambda }_{i}{\chi }_{i} \) . Define a map \(...
Yes
Lemma 6.12. Given any countable subgroup \( K \leq {\mathbb{S}}^{1} \) there is an ergodic measure-preserving system \( \left( {X,{\mathcal{B}}_{X},\mu, T}\right) \) on a Borel probability space with the property that \( K \) is the group of eigenvalues of \( {U}_{T} \) .
Proof. Give \( K \) the discrete topology, so that the dual group \( X = \widehat{K} \) is a compact metric abelian group; write \( \mu = {m}_{X} \) for the normalized Haar measure on \( X \) . The map \( \theta : K \rightarrow {\mathbb{S}}^{1} \) defined by \( \theta \left( \kappa \right) = \kappa \) is a character on...
Yes
Proposition 6.16. Let \( \rho \) be the relatively independent joining of the invertible systems \( \mathrm{X} \) and \( \mathrm{Y} \) over a common factor \( \mathrm{Z} \) as above. Then the following properties hold.\n\n(1) The relatively independent joining is concentrated on the measurable set\n\n\[ \Phi = \left\{ ...
Proof of Proposition 6.16. Property (1) follows easily by substitution:\n\n\[ \rho \left( \Phi \right) = \int {\mu }_{z} \times {\nu }_{z}\left( \Phi \right) \mathrm{d}\lambda \left( z\right) = 1 \]\n\nsince \( {\mu }_{z}\left( {{\left( {\phi }_{X}\right) }^{-1}\left( z\right) }\right) = {\nu }_{z}\left( {{\left( {\phi...
Yes
Theorem 7.1. Given \( \ell, r \geq 1 \) there is some \( N\left( {\ell, r}\right) \) with the property that if \( N \geq N\left( {\ell, r}\right) \) and\n\n\[ \{ 1,2,\ldots, N\} = {C}_{1} \sqcup \cdots \sqcup {C}_{r} \]\n\nthen for some \( j \) the set \( {C}_{j} \) contains an arithmetic progression of length \( \ell ...
In the proof, it will be convenient to write \( \{ a, a + 1,\ldots, b\} \) as \( \left\lbrack {a, b}\right\rbrack \) and to define a coloring of a set \( \left\lbrack {1, N}\right\rbrack \) into \( r \) colors as a map \( C : \left\lbrack {1, N}\right\rbrack \rightarrow \{ 1,\ldots, r\} \) .\n\nWe define two integer ve...
Yes
Lemma 7.3. \( \mathbf{V}\left( {\ell, m}\right) \) for all \( m \geq 1 \) implies \( \mathbf{V}\left( {\ell + 1,1}\right) \) .
Proof. Fix \( r \), and let\n\n\[ C : \left\lbrack {1,{2N}\left( {\ell, r, r}\right) }\right\rbrack \rightarrow \{ 1,\ldots, r\} \]\n\nbe given, where \( N\left( {\ell, r, r}\right) \) is as in \( \mathbf{V}\left( {\ell, r}\right) \) . Then there exist \( a,{d}_{1},\ldots ,{d}_{r} > 0 \) such that\n\n\[ a + \mathop{\su...
Yes
Theorem 7.4 (Furstenberg). For any system \( \left( {X,\mathcal{B},\mu, T}\right) \) and set \( A \in \mathcal{B} \) with \( \mu \left( A\right) > 0 \), and for any \( k \in \mathbb{N} \) ,\n\n\[ \mathop{\liminf }\limits_{{N \rightarrow \infty }}\frac{1}{N}\mathop{\sum }\limits_{{n = 1}}^{N}\mu \left( {A \cap {T}^{-n}A...
In fact Furstenberg proved that\n\n\[ \mathop{\liminf }\limits_{{N - M \rightarrow \infty }}\frac{1}{N - M}\mathop{\sum }\limits_{{n = M}}^{{N - 1}}\mu \left( {A \cap {T}^{-n}A \cap {T}^{-{2n}}A \cap \cdots \cap {T}^{-{kn}}A}\right) > 0, \]\n\nbut the inequality (7.2) is sufficient for Szemerédi's theorem.
Yes
If \( T = {R}_{\alpha } \) is an ergodic rotation, then the inequality (7.3) is clear: If \( 0,{n\alpha },{2n\alpha },\ldots ,{kn\alpha }\left( {\;\operatorname{mod}\;1}\right) \) are all very close together (which may be arranged for \( \alpha \notin \mathbb{Q} \) and any \( k \geq 1 \) by choice of \( n \) ), then th...
\[ {\chi }_{A},{\chi }_{A - {n\alpha }},\ldots ,{\chi }_{A - {kn\alpha }} \] will be close together in \( {L}_{{m}_{\mathbb{T}}}^{2} \) for any interval (indeed, for any Borel set) \( A \) , so the intersection \[ A \cap {R}_{\alpha }^{-n}A \cap \cdots \cap {R}_{\alpha }^{-{kn}}A \] will have measure close to that of \...
No
Proposition 7.13. Let \( \left( {X,\mathcal{B},\mu, T}\right) \) be a weak-mixing system. Then for any functions \( {f}_{1},\ldots ,{f}_{k} \in {L}_{\mu }^{\infty } \) ,
Proof of Proposition 7.13. Since \( T \) is weak-mixing it is certainly ergodic, so (7.18) holds for \( k = 1 \) by the mean ergodic theorem (Theorem 2.21). We proceed by induction on \( k \) .
No
Theorem 7.14. Let \( \left( {X,\mathcal{B},\mu, T}\right) \) be a measure-preserving system. Then, for any functions \( {f}_{1},{f}_{2} \in {L}^{\infty }\left( {X,\mathcal{B},\mu }\right) \), \[ \frac{1}{N}\mathop{\sum }\limits_{{n = 1}}^{N}{U}_{T}^{n}{f}_{1}{U}_{T}^{2n}{f}_{2} \] (7.19) converges in \( {L}^{2}\left( {...
Just as in the proof from Sect. 7.4, we will prove this by decomposing the system (more precisely, by decomposing the space of \( {L}^{2} \) -functions on the space) into an orderly and a chaotic part. We will see below that for this result the appropriate splitting will be given by the Kronecker factor.
No
Proposition 7.15. Let \( T \) be an invertible ergodic measure-preserving transformation on a Borel probability space \( \\left( {X,\\mathcal{B},\\mu, T}\\right) \) . Let \( \\mathcal{K} \) be the \( \\sigma \) -algebra corresponding to the Kronecker factor of \( T \), and let \( {f}_{1},{f}_{2} \\in {L}_{\\mu }^{\\inf...
Proof of Theorem 7.14 assuming Propositions 7.12 and 7.15. By Proposition 7.15, the sequence\n\n\[ \n\\frac{1}{N}\\mathop{\\sum }\\limits_{{n = 1}}^{N}{U}_{T}^{n}{f}_{1}{U}_{T}^{2n}{f}_{2}\n\]\n\nconverges to the same limit as\n\n\[ \n\\frac{1}{N}\\mathop{\\sum }\\limits_{{n = 1}}^{N}{U}_{T}^{n}E\\left( {{f}_{1} \\mid ...
No
Lemma 7.16. Let \( \left( {X,\mathcal{B},\mu, T}\right) \) be any measure-preserving system on a Borel probability space. Suppose that \( K : {L}_{\mu }^{2} \rightarrow {L}_{\mu }^{2} \) is a compact self-adjoint operator commuting with \( {U}_{T} \) . Then all eigenspaces of \( K \) with non-zero eigenvalue are finite...
Recall that any kernel in \( {L}_{\mu \times \mu }^{2} \) defines a compact operator on \( {L}_{\mu }^{2} \), hence\n\n\[ \n{K}_{H} : g \mapsto \int {F}_{H}\left( {x, y}\right) g\left( y\right) \mathrm{d}\mu \left( y\right) \n\]\n\nand\n\n\[ \nK : g \mapsto \int F\left( {x, y}\right) g\left( y\right) \mathrm{d}\mu \lef...
Yes
Let \( X = {\mathbb{T}}^{2} \) and define \( {}^{\left( {69}\right) } \) a map \( T : X \rightarrow X \) by\n\n\[ T : x = \left( \begin{array}{l} y \\ z \end{array}\right) \mapsto \left( \begin{array}{l} y + \alpha \\ z + y \end{array}\right) \]\n\nThe iterates of the map \( T \) take the form\n\n\[ {T}^{n} : \left( \b...
For example, the function\n\n\[ f : {\mathbb{T}}^{2} \rightarrow \mathbb{C} \]\n\ndefined by\n\n\[ f\left( \begin{array}{l} y \\ z \end{array}\right) = {\mathrm{e}}^{{2\pi }\mathrm{i}z} \]\n\nhas\n\n\[ {U}_{T}^{n}f\left( \begin{array}{l} y \\ z \end{array}\right) = {\mathrm{e}}^{{2\pi }\mathrm{i}c\left( {n,\alpha }\rig...
Yes
Example 7.19. The map \( T : {\mathbb{T}}^{2} \rightarrow {\mathbb{T}}^{2} \) constructed in Example 7.17 is a compact extension of the circle rotation \( {R}_{\alpha } : \mathbb{T} \rightarrow \mathbb{T} \) . The character
\[ \left( \begin{array}{l} y \\ z \end{array}\right) \mapsto {\mathrm{e}}^{{2\pi }\mathrm{i}z} \] is mapped to the function \[ \left( \begin{array}{l} y \\ z \end{array}\right) \mapsto \underset{\text{modulus }1}{\underbrace{C\left( {n,\alpha, y}\right) }}{\mathrm{e}}^{{2\pi }\mathrm{i}z} \] in \( {L}_{{\mu }_{y}}^{2} ...
No
Theorem 7.21. Let \( \left( {X,\mathcal{B},\mu, T}\right) \) be an ergodic measure-preserving system on a Borel probability space and suppose that ![8dbccc5c-1b75-4e41-a357-96decb48997c_221_0.jpg](images/8dbccc5c-1b75-4e41-a357-96decb48997c_221_0.jpg)\n\nis an extension of measure-preserving systems. Then one of the fo...
Proof of Theorem 7.21. Let\n\n\[ \widetilde{\mathrm{X}} = \left( {\widetilde{X} = X \times X,\mathcal{B} \otimes \mathcal{B},\widetilde{\mu } = \mu { \times }_{\mathrm{Y}}\mu ,\widetilde{T} = T \times T}\right) \]\n\nand assume that \( \mathrm{X} \rightarrow \mathrm{Y} \) is not relatively weak-mixing. Then there is a ...
Yes
Lemma 7.22. There is a function \( \phi \in {L}^{\infty }\left( X\right) \) such that \( H * \phi \notin {L}^{2}\left( Y\right) \) .
Proof. Suppose there is no such function, and choose a sequence \( \left( {\mathcal{P}}_{n}\right) \) of finite partitions of \( X \) with the property that\n\n\[ \sigma \left( {\mathop{\bigcup }\limits_{{n \geq 1}}\sigma \left( {\mathcal{P}}_{n}\right) }\right) = \mathcal{B} \]\n\nThen for \( {x}_{2} \in P \in {\mathc...
Yes
For any \( y \in \mathop{\bigcap }\limits_{{\ell = 0}}^{k}{T}^{-\ell n}\widetilde{A} \), the set\n\n\[ B = \left\{ {\left( {f,{U}_{T}^{n + m}f,\ldots ,{U}_{T}^{k\left( {n + m}\right) }f}\right) \mid m \in F}\right\} \]\n\nis an \( \varepsilon \) -separated subset of \( {\mathcal{L}}^{ * }\left( y\right) \) .
Proof. Since \( {T}^{\ell \left( {n + m}\right) }y \in A \) for \( \ell = 0,\ldots, k \) and \( m \in F \), the set \( B \) is in \( {\mathcal{L}}^{ * }\left( y\right) \) . Take \( m,{m}^{\prime } \in F, m \neq {m}^{\prime } \) . Since \( y \in \widetilde{A} \) belongs to the set in (7.35), there exists \( \ell \leq k ...
Yes
Corollary 7.28. If \( \\left( {X,\\mathcal{B},\\mu, T}\\right) \) is a weak-mixing measure-preserving system, then for \( {B}_{0},\\ldots ,{B}_{k} \\in \\mathcal{B} \) ,
\[ \\mathop{\\lim }\\limits_{{N \\rightarrow \\infty }}\\frac{1}{N}\\mathop{\\sum }\\limits_{{n = 1}}^{N}\\left\\lbrack {\\mu \\left( {{B}_{0} \\cap {T}^{-n}{B}_{1} \\cap \\cdots \\cap {T}^{-{kn}}{B}_{k}}\\right) }\\right.\n\n\[ {\\left. -\\mu \\left( {B}_{0}\\right) \\mu \\left( {B}_{1}\\right) \\cdots \\mu \\left( {B...
Yes