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If the smooth surface \( S \) is contained in the domain \( D \subset {\mathbb{R}}^{n} \) in which a form \( \omega \) is defined, then, since the inclusion \( T{S}_{x} \subset T{D}_{x} \) holds at each point \( x \in S \) , one can consider the restriction of \( \omega \left( x\right) \) to \( T{S}_{x} \) . In this wa...
As we know, a surface can be defined parametrically, either locally or globally. Let \( \varphi : U \rightarrow S = \varphi \left( U\right) \subset D \) be a parametrized smooth surface in the domain \( D \) and \( \omega \) a form on \( D \) . Then we can transfer the form \( \omega \) to the domain \( U \) of paramet...
Yes
Example 16 Let \( {\omega }_{\mathbf{V}}^{2} \) be the flux form considered in Example 8, generated by the velocity field \( \mathbf{V} \) of a flow in the domain \( D \) of the oriented Euclidean space \( {\mathbb{R}}^{3} \) . If \( S \) is a smooth oriented surface in \( D \), one may consider the restriction \( {\om...
If \( \varphi : I \rightarrow S \) is a local chart of the surface \( S \), then, making the change of variable \( x = \varphi \left( t\right) \) in the coordinate expression (12.22) for the form \( {\omega }_{\mathbf{V}}^{2} \), we obtain the coordinate expression for the form \( {\varphi }^{ * }{\omega }_{\mathbf{V}}...
Yes
Consider the force field \( \mathbf{F} = \left( {-\frac{y}{{x}^{2} + {y}^{2}},\frac{x}{{x}^{2} + {y}^{2}}}\right) \) defined at all points of the plane \( {\mathbb{R}}^{2} \) except the origin. Let us compute the work of this field along the curve \( {\gamma }_{1} \) defined as \( x = \cos t, y = \sin t,0 \leq t \leq {...
According to formulas (13.1),(13.2), and \( \left( {13.2}^{\prime }\right) \), we find\n\n\[ \n{\int }_{{\gamma }_{1}}{\omega }_{\mathbf{F}}^{1} = {\int }_{{\gamma }_{1}} - \frac{y}{{x}^{2} + {y}^{2}}\mathrm{\;d}x + \frac{x}{{x}^{2} + {y}^{2}}\mathrm{\;d}y = \n\]\n\n\[ \n= {\int }_{0}^{2\pi }\left( {-\frac{\sin t \cdot...
Yes
Let \( \mathbf{r} \) be the radius vector of a point \( \left( {x, y, z}\right) \in {\mathbb{R}}^{3} \) and \( r = \left| \mathbf{r}\right| \) . Suppose a force field \( \mathbf{F} = f\left( r\right) \mathbf{r} \) is defined everywhere in \( {\mathbb{R}}^{3} \) except at the origin. This is a so-called central force fi...
Using (13.2), we find\n\n\[ \n{\int }_{\gamma }f\left( r\right) \left( {x\mathrm{\;d}x + y\mathrm{\;d}y + z\mathrm{\;d}z}\right) = \frac{1}{2}{\int }_{\gamma }f\left( r\right) \mathrm{d}\left( {{x}^{2} + {y}^{2} + {z}^{2}}\right) = \n\]\n\n\[ \n= \frac{1}{2}{\int }_{0}^{1}f\left( {r\left( t\right) }\right) \mathrm{d}{r...
Yes
Example 3 Suppose a medium is advancing with constant velocity \( \mathbf{V} = \left( {1,0,0}\right) \) . If we take any closed surface in the domain of the flow, then, since the density of the medium does not change, the amount of matter in the volume bounded by this surface must remain constant. Hence the total flux ...
In this case, let us check formula (13.6) by taking \( S \) to be the sphere \( {x}^{2} + {y}^{2} + {z}^{2} = {R}^{2} \) . Up to a set of area zero, which is therefore negligible, this sphere can be defined parametrically \[ x = R\cos \psi \cos \varphi \] \[ y = R\cos \psi \sin \varphi \] \[ z = R\sin \psi \] where \( ...
Yes
Suppose the velocity field of a medium moving in \( {\mathbb{R}}^{3} \) is defined in Cartesian coordinates \( x, y, z \) by the equality \( \mathbf{V}\left( {x, y, z}\right) = \left( {{V}^{1},{V}^{2},{V}^{3}}\right) \left( {x, y, z}\right) = \left( {x, y, z}\right) \). Let us find the flux through the sphere \( {x}^{2...
Taking the parametrization of the sphere given in the last example, and carrying out the substitution in the right-hand side of (13.6), we find that\n\n\[ \n{\int }_{0}^{2\pi }\mathrm{d}\varphi {\int }_{-\pi /2}^{\pi /2}\left| \begin{matrix} R\cos \psi \cos \varphi & R\cos \psi \sin \varphi & R\sin \psi \\ - R\cos \psi...
Yes
The integral \( \left( {13.2}^{\prime }\right) \) of Sect. 13.1, which expresses the work on the path \( \gamma : \left\lbrack {a, b}\right\rbrack \rightarrow {\mathbb{R}}^{n} \), can be written as the integral of first kind
\[ {\int }_{\gamma }\langle \mathbf{F},\mathbf{e}\rangle \mathrm{d}s \] (13.23) where \( s \) is arc length on \( \gamma ,\mathrm{d}s \) is the element of length (a 1 -form), and \( \mathbf{e} \) is a unit velocity vector containing all the information about the orientation of \( \gamma \) . From the point of view of t...
Yes
The flux (13.3) of Sect. 13.1 of the velocity field \( \mathbf{V} \) across a surface \( S \subset {\mathbb{R}}^{n} \) oriented by unit normals \( \mathbf{n}\left( x\right) \) can be written as the surface integral of first kind
\[ {\int }_{S}\langle \mathbf{V},\mathbf{n}\rangle \mathrm{d}\sigma \]
Yes
Example 3 Faraday’s law \( {}^{4} \) asserts that the electromotive force arising in a closed conductor \( \Gamma \) in a variable magnetic field \( \mathbf{B} \) is proportional to the rate of variation of the flux of the magnetic field across a surface \( S \) bounded by \( \Gamma \) . Let \( \mathbf{E} \) be the ele...
\[ {\oint }_{\Gamma }\mathbf{E} \cdot \mathrm{d}\mathbf{s} = - \frac{\partial }{\partial t}{\int }_{S}\mathbf{B} \cdot \mathrm{d}\mathbf{\sigma } \]
Yes
Let us set \( P = - y, Q = x \) in (13.25). We then obtain\n\n\[ \n{\int }_{\partial D} - y\mathrm{\;d}x + x\mathrm{\;d}y = {\int }_{D}2\mathrm{\;d}x\mathrm{\;d}y = {2\sigma }\left( D\right) ,\n\]\n\nwhere \( \sigma \left( D\right) \) is the area of \( D \) .
Using Green’s formula one can thus obtain the following expression for the area of a domain on the plane in terms of line integrals over the oriented boundary of the domain:\n\n\[ \n\sigma \left( D\right) = \frac{1}{2}{\int }_{\partial D} - y\mathrm{\;d}x + x\mathrm{\;d}y = - {\int }_{\partial D}y\mathrm{\;d}x = {\int ...
Yes
Proposition 2 Let \( {\mathbb{R}}^{3} \) be three-dimensional space with a fixed coordinate system \( x, y, z \) and \( \bar{D} \) a compact domain in \( {\mathbb{R}}^{3} \) bounded by piecewise-smooth surfaces. Let \( P, Q \), and \( R \) be smooth functions in the closed domain \( \bar{D} \) . Then the following rela...
The Gauss-Ostrogradskii formula (13.30) can be derived by repeating the derivation of Green's formula step by step with obvious modifications. So as not to do a verbatim repetition, let us begin by considering not a cube in \( {\mathbb{R}}^{3} \), but the domain \( {D}_{x} \) shown in Fig. 13.7, which is bounded by a l...
Yes
Let us compute the buoyant force of a homogeneous liquid on a body \( D \) immersed in it. We choose the Cartesian coordinates \( x, y, z \) in \( {\mathbb{R}}^{3} \) so that the \( {xy} \) -plane is the surface of the liquid and the \( z \) -axis is directed out of the liquid. A force \( {\rho gz}\mathbf{n}\mathrm{d}\...
\[ \mathbf{F} = {\iint }_{S}{\rho gz}\mathbf{n}\mathrm{d}\sigma \] If \( \mathbf{n} = {\mathbf{e}}_{x}\cos {\alpha }_{x} + {\mathbf{e}}_{y}\cos {\alpha }_{y} + {\mathbf{e}}_{z}\cos {\alpha }_{z} \), then \( \mathbf{n}\mathrm{d}\sigma = {\mathbf{e}}_{x}\mathrm{\;d}y \land \mathrm{d}z + {\mathbf{e}}_{y}\mathrm{\;d}z \lan...
Yes
Using the Gauss-Ostrogradskii formula (13.30), one can give the following formulas for the volume \( V\left( D\right) \) of a body \( D \) bounded by a surface \( \partial D \) .
\[ V\left( D\right) = \frac{1}{3}{\iint }_{\partial D}x\mathrm{\;d}y \land \mathrm{d}z + y\mathrm{\;d}z \land \mathrm{d}x + z\mathrm{\;d}x \land \mathrm{d}y = \] \[ = {\iint }_{\partial D}x\mathrm{\;d}y \land \mathrm{d}z = {\iint }_{\partial D}y\mathrm{\;d}z \land \mathrm{d}x = {\iint }_{\partial D}z\mathrm{\;d}x \land...
Yes
Proposition 3 Let \( S \) be an oriented piecewise-smooth compact two-dimensional surface with boundary \( \partial S \) embedded in a domain \( G \subset {\mathbb{R}}^{3} \), in which a smooth 1- form \( \omega = P\mathrm{\;d}x + Q\mathrm{\;d}y + R\mathrm{\;d}z \) is defined. Then the following relation holds:\n\n\[ \...
Proof If \( C \) is a standard parametrized surface \( \varphi : I \rightarrow C \) in \( {\mathbb{R}}^{3} \), where \( I \) is a square in \( {\mathbb{R}}^{2} \), relation (13.34) follows from Eqs. (13.28) taking account of what has been proved for the square and Green's formula.\n\nIf the orientable surface \( S \) c...
Yes
Example 5 Let us show that every smooth mapping \( f : \bar{B} \rightarrow \bar{B} \) of a closed ball \( \bar{B} \subset {\mathbb{R}}^{m} \) into itself has at least one fixed point.
Proof If the mapping \( f \) had no fixed points, then, as in Example 2, one could construct a smooth mapping \( \varphi : \bar{B} \rightarrow \partial \bar{B} \) that is the identity on the sphere \( \partial \bar{B} \) . In the domain \( {\mathbb{R}}^{m} \smallsetminus 0 \), we consider the vector field \( \frac{\mat...
Yes
Proposition 1 To a linear combination of forms of the same degree there corresponds a linear combination of the vector and scalar fields corresponding to them.
Proof Proposition 1 is of course obvious. However, let us write out the full proof, as an example, for 1 -forms:\n\n\[ \n{\alpha }_{1}{\omega }_{{\mathbf{A}}_{1}}^{1} + {\alpha }_{2}{\omega }_{{\mathbf{A}}_{2}}^{1} = {\alpha }_{1}\left\langle {{\mathbf{A}}_{1}, \cdot }\right\rangle + \alpha \left\langle {{\mathbf{A}}_{...
Yes
Proposition 2 If \( \mathbf{A},\mathbf{B},{\mathbf{A}}_{1} \), and \( {\mathbf{B}}_{1} \) are vector fields in the oriented Euclidean space \( {\mathbb{R}}^{3} \), then\n\n\[ \n{\omega }_{{\mathbf{A}}_{1}}^{1} \land {\omega }_{{\mathbf{A}}_{2}}^{1} = {\omega }_{{\mathbf{A}}_{1} \times {\mathbf{A}}_{2}}^{2} \n\]\n\n(14....
Proof To prove these assertions, fix an orthonormal basis in \( {\mathbb{R}}^{3} \) and the Cartesian coordinates \( {x}^{1},{x}^{2},{x}^{3} \) corresponding to it.\n\nIn Cartesian coordinates\n\n\[ \n{\omega }_{\mathbf{A}}^{1}\left( x\right) \left( \mathbf{\xi }\right) = \mathbf{A}\left( x\right) \cdot \mathbf{\xi } =...
Yes
\[ \operatorname{div}\left( {\mathbf{A} \times \mathbf{B}}\right) = \mathbf{B} \cdot \operatorname{curl}\mathbf{A} - \mathbf{A} \cdot \operatorname{curl}\mathbf{B}. \]
Proof We shall verify this last equality:\n\n\[ {\omega }_{\mathrm{{div}}\mathbf{A} \times \mathbf{B}}^{3} = \mathrm{d}{\omega }_{\mathbf{A} \times \mathbf{B}}^{2} = \mathrm{d}\left( {{\omega }_{\mathbf{A}}^{1} \land {\omega }_{\mathbf{B}}^{1}}\right) = \mathrm{d}{\omega }_{\mathbf{A}}^{1} \land {\omega }_{\mathbf{B}}^...
Yes
In the case when polar coordinates \( \left( {r,\varphi }\right) \) are defined in the same plane \( {\mathbb{R}}^{2} \), at each point \( x \in {\mathbb{R}}^{2} \smallsetminus 0 \) one can also attach unit vectors \( {\mathbf{e}}_{1}\left( x\right) = {\mathbf{e}}_{r}\left( x\right) \) , \( {\mathbf{e}}_{2} = {\mathbf{...
Thus, if \( \left( {{A}^{1},{A}^{2}}\right) \left( x\right) \equiv \left( {1,0}\right) \), this is a field of unit vectors in \( {\mathbb{R}}^{2} \) pointing radially away from the center 0 . The field \( \left( {{A}^{1},{A}^{2}}\right) \left( x\right) \equiv \left( {0,1}\right) \) can be obtained from the preceding fi...
Yes
Example 5 In Cartesian coordinates \( \left( {x, y, z}\right) \), cylindrical coordinates \( \left( {r,\varphi, z}\right) \), and spherical coordinates \( \left( {R,\varphi ,\theta }\right) \) on Euclidean space \( {\mathbb{R}}^{3} \) the quadratic form (14.25) has the respective forms
\[ \mathrm{d}{s}^{2} = \mathrm{d}{x}^{2} + \mathrm{d}{y}^{2} + \mathrm{d}{z}^{2} = \] \[ = \mathrm{d}{r}^{2} + {r}^{2}\mathrm{\;d}{\varphi }^{2} + \mathrm{d}{z}^{2} = \] \[ = \mathrm{d}{R}^{2} + {R}^{2}{\cos }^{2}\theta \mathrm{d}{\varphi }^{2} + {R}^{2}\mathrm{\;d}{\theta }^{2}. \] Thus, each of these coordinate syste...
Yes
Example 6 It follows from formulas (14.27) and the results of Example 5 that for Cartesian, cylindrical, and spherical coordinates, the triples of unit vectors along the coordinate directions have respectively the following forms:
\[ {\mathbf{e}}_{x} = \left( {1,0,0}\right) ,\;{\mathbf{e}}_{y} = \left( {0,1,0}\right) ,\;{\mathbf{e}}_{z} = \left( {0,0,1}\right) ; \] \( \left( {14.27}^{\prime }\right) \) \[ {\mathbf{e}}_{r} = \left( {1,0,0}\right) ,\;{\mathbf{e}}_{\varphi } = \left( {0,\frac{1}{r},0}\right) ,\;{\mathbf{e}}_{z} = \left( {0,0,1}\rig...
Yes
Using the notation introduced in Example 8 and formulas \( \left( {14.26}^{\prime }\right) \) , \( \left( {14.26}^{\prime \prime }\right) \) and \( \left( {14.26}^{\prime \prime \prime }\right) \), we obtain in Cartesian, cylindrical, and spherical coordinates respectively\n\n\[ \n{\omega }_{\mathbf{B}}^{2} = {B}_{x}\m...
\[ \n= {B}_{r}r\mathrm{\;d}\varphi \land \mathrm{d}z + {B}_{\varphi }\mathrm{d}z \land \mathrm{d}r + {B}_{z}r\mathrm{\;d}r \land \mathrm{d}\varphi = \n\]\n\n(14.32″)\n\n\[ \n= {B}_{R}{R}^{2}\cos \theta \mathrm{d}\varphi \land \mathrm{d}\theta + {B}_{\varphi }R\mathrm{\;d}\theta \land \mathrm{d}R + {B}_{\theta }R\cos \t...
Yes
Example 10 In particular, for Cartesian, cylindrical, and spherical coordinates respectively, formula (14.33) has the following forms:
\[ {\omega }_{\rho }^{3} = \rho \mathrm{d}x \land \mathrm{d}y \land \mathrm{d}z = \] \( \left( {14.33}^{\prime }\right) \) \[ = {\rho r}\mathrm{\;d}r \land \mathrm{d}\varphi \land \mathrm{d}z = \] \( \left( {14.33}^{\prime \prime }\right) \) \[ = \rho {R}^{2}\cos \theta \mathrm{d}R \land \mathrm{d}\varphi \land \mathrm...
Yes
In Cartesian, cylindrical, and spherical coordinates respectively, \[ \operatorname{grad}f = \frac{\partial f}{\partial x}{\mathbf{e}}_{x} + \frac{\partial f}{\partial y}{\mathbf{e}}_{y} + \frac{\partial f}{\partial z}{\mathbf{e}}_{z} = \]
\[ = \frac{\partial f}{\partial r}{\mathbf{e}}_{r} + \frac{1}{r}\frac{\partial f}{\partial \varphi }{\mathbf{e}}_{\varphi } + \frac{\partial f}{\partial z}{\mathbf{e}}_{z} = \] \[ = \frac{\partial f}{\partial R}{\mathbf{e}}_{R} + \frac{1}{R\cos \theta }\frac{\partial f}{\partial \varphi }{\mathbf{e}}_{\varphi } + \frac...
Yes
Example 12 In Cartesian, cylindrical, and spherical coordinates respectively\n\n\\[ \n\\operatorname{curl}\\mathbf{A} = \\left( {\\frac{\\partial {A}_{z}}{\\partial y} - \\frac{\\partial {A}_{y}}{\\partial z}}\\right) {\\mathbf{e}}_{x} + \\left( {\\frac{\\partial {A}_{x}}{\\partial z} - \\frac{\\partial {A}_{z}}{\\part...
\\[ \n= \\frac{1}{r}\\left( {\\frac{\\partial {A}_{z}}{\\partial \\varphi } - \\frac{\\partial r{A}_{\\varphi }}{\\partial z}}\\right) {\\mathbf{e}}_{r} + \\left( {\\frac{\\partial {A}_{r}}{\\partial z} - \\frac{\\partial {A}_{z}}{\\partial r}}\\right) {\\mathbf{e}}_{\\varphi } + \\frac{1}{r}\\left( {\\frac{\\partial r...
Yes
If, in particular, \( \operatorname{div}\mathbf{B} \equiv 0 \), that is, there are no sources, then the flux across the boundary of the region must be zero: the amount flowing in equals the amount flowing out.
And, as formula \( \left( {14.42}^{\prime }\right) \) shows, this is indeed the case.
No
A point electric charge of magnitude \( q \) creates an electric field in space. Suppose the charge is located at the origin. By Coulomb’s law \( {}^{6} \) the intensity \( \mathbf{E} = \) \( E\left( x\right) \) of the field at the point \( x \in {\mathbb{R}}^{3} \) (that is, the force acting on a unit test charge at t...
The field \( \mathbf{E} \) is defined at all points different from the origin. In spherical coordinates \( \mathbf{E} = \frac{q}{{4\pi }{\varepsilon }_{0}}\frac{1}{{R}^{2}}{\mathbf{e}}_{R} \), so that by formula \( \left( {{14.36}'''}\right) \) of the preceding section, one can see immediately that \( \operatorname{div...
Yes
Suppose the entire space, regarded as a rigid body, is rotating with constant angular speed \( \omega \) about a fixed axis (let it be the \( x \) -axis). Let us find the curl of the field \( \mathbf{v} \) of linear velocities of the points of space. (The field is being studied at any fixed instant of time.)
In cylindrical coordinates \( \left( {r,\varphi, z}\right) \) we have the simple expression \( \mathbf{v}\left( {r,\varphi, z}\right) = \) \( {\omega r}{\mathbf{e}}_{\varphi } \) . Then by formula \( \left( {14.35}^{\prime \prime }\right) \) of Sect. 14.1, we find immediately that \( \operatorname{curl}\mathbf{v} = \) ...
Yes
At a point of space having radius-vector \( \mathbf{r} \) the intensity \( \mathbf{F} \) of the gravitational field due to a point mass \( M \) located at the origin can be computed from Newton's law as\n\n\[ \mathbf{F} = - {GM}\frac{\mathbf{r}}{{r}^{3}} \]\n\n(14.55)\n\nwhere \( r = \left| \mathbf{r}\right| \) .
This is the force with which the field acts on a unit mass at this point of space. The gravitational field (14.55) is a potential field. Its potential in the sense of Definition 1 is the function\n\n\[ U = {GM}\frac{1}{r} \]\n\n(14.56)
Yes
In the language of differential forms the equality \( \mathbf{A} = \operatorname{grad}U \) means that \( {\omega }_{\mathbf{A}}^{1} = \) \( \mathrm{d}{\omega }_{U}^{0} = \mathrm{d}U \), from which it follows that
\[ \mathrm{d}{\omega }_{\mathbf{A}}^{1} = 0 \] (14.57) since \( {\mathrm{d}}^{2}{\omega }_{U}^{0} = 0 \) . This is a necessary condition for the field \( \mathbf{A} \) to be a potential field.\n\nIn Cartesian coordinates this condition can be expressed very simply. If \( \mathbf{A} = \) \( \left( {{A}^{1},\ldots ,{A}^{...
Yes
Example 3 The field \( \mathbf{A} = \left( {x,{xy},{xyz}}\right) \) in Cartesian coordinates in \( {\mathbb{R}}^{3} \) cannot be a potential field, since, for example, \( \frac{\partial {xy}}{\partial x} \neq \frac{\partial x}{\partial y} \) .
since, for example, \( \frac{\partial {xy}}{\partial x} \neq \frac{\partial x}{\partial y} \)
Yes
A continuous vector field \( \mathbf{A} \) in a domain \( D \subset {\mathbb{R}}^{n} \) is a potential field in \( D \) if and only if its circulation (work) around every closed curve \( \gamma \) contained in \( D \) is zero:
Proof Necessity. Suppose \( \mathbf{A} = \operatorname{grad}U \) . Then by the Newton-Leibniz formula (Formula \( \left( {14.40}^{\prime }\right) \) of Sect. 14.2),\n\n\[{\oint }_{\gamma }\mathbf{A} \cdot \mathrm{d}\mathbf{s} = U\left( {\gamma \left( b\right) }\right) - U\left( {\gamma \left( a\right) }\right)\]\n\nwhe...
Yes
Proposition 2 If the necessary condition for a field to be a potential field holds in a ball, then the field has a potential in that ball.
Proof For the sake of intuitiveness we first carry out the proof in the case of a disk \( D = \left\{ {\left( {x, y}\right) \in {\mathbb{R}}^{2} \mid {x}^{2} + {y}^{2} < r}\right\} \) in the plane \( {\mathbb{R}}^{2} \) . One can arrive at the point \( \left( {x, y}\right) \) of the disk from the origin along two diffe...
Yes
Proposition 3 If the 1 -form \( {\omega }_{\mathbf{A}}^{1} \) in the domain \( D \) is such that \( \mathrm{d}{\omega }_{\mathbf{A}}^{1} = 0 \), and the closed paths \( {\gamma }_{0} \) and \( {\gamma }_{1} \) are homotopic in \( D \), then\n\n\[{\int }_{{\gamma }_{0}}{\omega }_{\mathbf{A}}^{1} = {\int }_{{\gamma }_{1}...
Proof Let \( \Gamma : {I}^{2} \rightarrow D \) be a homotopy from \( {\gamma }_{0} \) to \( {\gamma }_{1} \) (see Fig. 14.4). If \( {I}_{0} \) and \( {I}_{1} \) are the bases of the square \( {I}^{2} \) and \( {J}_{0} \) and \( {J}_{1} \) its vertical sides, then by definition of a homotopy of closed paths, the restric...
Yes
Proposition 4 If a field \( \mathbf{A} \) defined in a simply connected domain \( D \) satisfies the necessary condition (14.57) or \( \left( {14.57}^{\prime }\right) \) to be a potential field, then it is a potential field in \( D \) .
Proof By Proposition 1 and Remark 1 it suffices to verify that Eq. (14.59) holds for every smooth path \( \gamma \) in \( D \) . The path \( \gamma \) is by hypothesis homotopic to a constant path whose support consists of a single point. The integral over such a one-point path is obviously zero. But by Proposition 3 t...
Yes
A differential form \( {\omega }^{p} \) is exact in a domain \( D \) if there exists a form \( {\omega }^{p - 1} \) in \( D \) such that \( {\omega }^{p} = \mathrm{d}{\omega }^{p - 1} \) .
If the form \( {\omega }^{p} \) is exact in \( D \), then \( \mathrm{d}{\omega }^{p} = {\mathrm{d}}^{2}{\omega }^{p - 1} = 0 \) . Thus the condition\n\n\[ \mathrm{d}\omega = 0 \]\n\n(14.62)\n\nis a necessary condition for the form \( \omega \) to be exact.
No
Consider the plane \( {\mathbb{R}}^{2} \) with two points \( {p}_{1} \) and \( {p}_{2} \) removed (Fig. 14.5), and the paths \( {\gamma }_{0},{\gamma }_{1} \), and \( {\gamma }_{2} \) whose supports are shown in the figure. The path \( {\gamma }_{2} \) can be contracted to a point inside \( D \), and therefore if a clo...
The integral over \( {\gamma }_{1} \) obviously reduces to the integral over one cycle enclosing the point \( {p}_{1} \) clockwise and the double of the integral over a cycle enclosing \( {p}_{2} \) counterclockwise. If \( {T}_{1} \) and \( {T}_{2} \) are the integrals of the form \( \omega \) over small circles enclos...
Yes
Example 1 Let \( {X}^{ * } \) be the dual space to \( X \) (consisting of the linear functionals on \( X \) ) and \( {e}^{1},\ldots ,{e}^{n} \) the basis of \( {X}^{ * } \) dual to the basis \( {e}_{1},\ldots ,{e}_{n} \) in \( X \), that is, \( {e}^{i}\left( {e}_{j}\right) = {\delta }_{j}^{i} \).
Since \( {e}^{i}\left( x\right) = {e}^{i}\left( {{x}^{j}{e}_{j}}\right) = {x}^{j}{e}^{i}\left( {e}_{j}\right) = {x}^{j}{\delta }_{j}^{i} = {x}^{i} \), taking account of (15.1) and (15.9), we can write any \( k \) -form \( {F}^{k} : {X}^{k} \rightarrow \mathbb{R} \) as\n\n\[ \n{F}^{k} = {a}_{{i}_{1}\ldots {i}_{k}}{e}^{{...
Yes
Taking account of relations (15.12) and (15.13), we find by (15.10) that\n\n\[ A{F}^{k} = {a}_{{i}_{1}\ldots {i}_{k}}A\left( {{e}^{{i}_{1}} \otimes \cdots \otimes {e}^{{i}_{k}}}\right) ,\n\]\n\nso that it is of interest to find \( A\left( {{e}^{{i}_{1}} \otimes \cdots \otimes {e}^{{i}_{k}}}\right) \) .
From Definition (15.11), taking account of the relation \( {e}^{i}\left( x\right) = {x}^{i} \), we find\n\n\[ A\left( {{e}^{{j}_{1}} \otimes \cdots \otimes {e}^{{j}_{k}}}\right) \left( {{x}_{1},\ldots ,{x}_{k}}\right) =\n\]\n\n\[ = \frac{1}{k!}{e}^{{j}_{1}}\left( {x}_{{i}_{1}}\right) \cdot \ldots \cdot {e}^{{j}_{k}}\le...
Yes
Example 3 Based on the result (15.14) of Example 2, we find by Definition (15.15) that\n\n\[ \n{e}^{{i}_{1}} \land {e}^{{i}_{2}}\left( {{x}_{1},{x}_{2}}\right) = \frac{2!}{1!1!}A\left( {{e}^{{i}_{1}} \otimes {e}^{{i}_{2}}}\right) \left( {{x}_{1},{x}_{2}}\right) = \n\]
\[ \n= \left| \begin{array}{ll} {e}^{{i}_{1}}\left( {x}_{1}\right) & {e}^{{i}_{2}}\left( {x}_{1}\right) \\ {e}^{{i}_{1}}\left( {x}_{2}\right) & {e}^{{i}_{2}}\left( {x}_{2}\right) \end{array}\right| = \left| \begin{array}{ll} {x}_{1}^{{i}_{1}} & {x}_{1}^{{i}_{2}} \\ {x}_{2}^{{i}_{1}} & {x}_{2}^{{i}_{2}} \end{array}\righ...
Yes
Example 6 Let \( {e}^{1},\ldots ,{e}^{m} \) and \( {\widetilde{e}}^{1},\ldots ,{\widetilde{e}}^{n} \) be the bases of the conjugate spaces \( {X}^{ * } \) and \( {Y}^{ * } \) dual to the bases in Example 5. Under the hypotheses of Example 5 we obtain
\[ \left( {{l}^{ * }{\widetilde{e}}^{j}}\right) \left( x\right) = \left( {{l}^{ * }{\widetilde{e}}^{j}}\right) \left( {{x}^{i}{e}_{i}}\right) = {\widetilde{e}}^{j}\left( {{x}^{i}l{e}_{i}}\right) = {x}^{i}{\widetilde{c}}^{j}\left( {{c}_{i}^{k}{\widetilde{e}}_{k}}\right) = \] \[ = {x}^{i}{c}_{i}^{k}{\widetilde{e}}^{j}\le...
Yes
Example 7 Retaining the notation of Example 6 and taking account of relations (15.22) and (15.29), we now obtain
\[ {l}^{ * }\left( {{\widetilde{e}}^{{j}_{1}} \land \cdots \land {\widetilde{e}}^{{j}_{k}}}\right) = {l}^{ * }{\widetilde{e}}^{{j}_{1}} \land \cdots \land {\widetilde{l}}^{ * }{e}^{{j}_{k}} = \] \[ = \left( {{c}_{{i}_{1}}^{{j}_{1}}{e}^{{i}_{1}}}\right) \land \cdots \land \left( {{c}_{{i}_{k}}^{{j}_{k}}{e}^{{i}_{k}}}\ri...
Yes
The sphere \( {S}^{2} = \left\{ {x \in {\mathbb{R}}^{3}\left| \right| x \mid = 1}\right\} \) is a two-dimensional manifold.
If we interpret \( {S}^{2} \) as the surface of the Earth, then an atlas of geographical maps will be an atlas of the manifold \( {S}^{2} \).
No
Proposition 1 The boundary \( \partial M \) of an \( n \) -dimensional manifold with boundary \( M \) is an \( \left( {n - 1}\right) \) -dimensional manifold without boundary.
Proof Indeed, \( \partial {H}^{n} = {\mathbb{R}}^{n - 1} \), and the restriction to \( \partial {H}^{n} \) of a chart of the form \( {\varphi }_{i} \) : \( {H}^{n} \rightarrow {U}_{i} \) belonging to an atlas of \( M \) generates an atlas of \( \partial M \) .
Yes
Example 4 Consider the planar double pendulum (Fig. 15.2) with arm a shorter than \( \operatorname{arm}b \), both being free to oscillate, except that the oscillations of \( b \) are limited in range by barriers. The configuration of such a system is characterized at each instant of time by the two angles \( \alpha \) ...
Under these constraints, the configuration space of the double pendulum is parametrized by the points of the cylinder \( {S}_{\alpha }^{1} \times {I}_{\beta }^{1} \), where \( {S}_{\alpha }^{1} \) is the circle, corresponding to all possible positions of the arm \( a \), and \( {I}_{\beta }^{1} = \{ \beta \in \mathbb{R...
Yes
Proposition 2 If a manifold \( M \) is connected, it is path connected.
Proof After fixing a point \( {x}_{0} \in M \), consider the set \( {E}_{{x}_{0}} \) of points of \( M \) that can be joined to \( {x}_{0} \) by a path in \( M \) . The set \( {E}_{{x}_{0}} \), as one can easily verify from the definition of a manifold, is both open and closed in \( M \) . But that means that \( {E}_{{...
Yes
If to each real \( n \times n \) matrix we assign the point of \( {\mathbb{R}}^{{n}^{2}} \) whose coordinates are obtained by writing out the elements of the matrix in some fixed order, then the group \( {GL}\left( {n,\mathbb{R}}\right) \) of nonsingular \( n \times n \) matrices becomes a manifold of dimension \( {n}^...
This manifold is noncompact (the elements of the matrices are not bounded) and nonconnected. This last fact follows from the fact that \( {GL}\left( {n,\mathbb{R}}\right) \) contains matrices with both positive and negative determinants. The points of \( {GL}\left( {n,\mathbb{R}}\right) \) corresponding to two such mat...
Yes
Example 8 Let \( \mathbf{a} \) be a vector in \( {\mathbb{R}}^{2} \) and \( {T}_{\mathbf{a}} \) the group of rigid motions of the plane generated by \( \mathbf{a} \) . The elements of \( {T}_{\mathbf{a}} \) are translations by vectors of the form \( n\mathbf{a} \), where \( n \in \mathbb{Z} \) . Under the action of the...
In the present case we can take as a fundamental domain a strip of width \( \left| \mathbf{a}\right| \) bounded by two parallel lines orthogonal to \( \mathbf{a} \) . We need only take into account that these lines themselves are obtained from each other through translations by \( \mathbf{a} \) and -a respectively. Ins...
Yes
Now let \( \mathbf{a} \) and \( \mathbf{b} \) be a pair of orthogonal vectors of the plane \( {\mathbb{R}}^{2} \) and \( {T}_{\mathbf{a},\mathbf{b}} \) the group of translations generated by these vectors. In this case a fundamental domain is the rectangle with sides \( \mathbf{a} \) and \( \mathbf{b} \) . Inside this ...
After gluing the sides of this fundamental rectangle together, we verify that the resulting manifold \( {\mathbb{R}}^{2}/{T}_{\mathbf{a},\mathbf{b}} \) is homeomorphic to the two-dimensional torus.
Yes
Now consider the group \( {G}_{a, b} \) of rigid motions of the plane \( {\mathbb{R}}^{2} \) generated by the transformations \( a\left( {x, y}\right) = \left( {x + 1,1 - y}\right) \) and \( b\left( {x, y}\right) = \left( {x, y + 1}\right) \) .
A fundamental domain for the group \( {G}_{a, b} \) is the unit square whose horizontal sides are identified at points lying on the same vertical line, but whose vertical sides are identified at points symmetric about the center. Thus the resulting manifold \( {\mathbb{R}}^{2}/{G}_{a, b} \) turns out to be homeomorphic...
No
Example 11 An atlas consisting of a single chart can be regarded as having any desired smoothness. Consider in this connection the atlas on the line \( {\mathbb{R}}^{1} \) generated by the identity mapping \( {\mathbb{R}}^{1} \ni x \mapsto \varphi \left( x\right) = x \in {\mathbb{R}}^{1} \), and a second atlas - genera...
In particular, if \( \widetilde{\varphi }\left( x\right) = {x}^{3} \), then the atlas consisting of the two charts \( \left\{ {x,{x}^{3}}\right\} \) is not smooth, since \( {\widetilde{\varphi }}^{-1}\left( x\right) = {x}^{1/3} \) . Using what has just been said, we can construct infinitely smooth atlases in \( {\mathb...
Yes
The one-dimensional manifold \( {\mathbb{{RP}}}^{1} \) called the real projective line, is the pencil of lines in \( {\mathbb{R}}^{2} \) passing through the origin, with the natural notion of distance between two lines (measured, for example, by the magnitude of the smaller angle between them). Each line of the pencil ...
It is useful to keep in mind the following interpretation of the manifold \( {\mathbb{{RP}}}^{1} \). Each line of the original pencil of lines is completely determined by its intersection with the unit circle. But there are exactly two such points, diametrically opposite to each other. Lines are near if and only if the...
Yes
If we now consider the pencil of lines passing through the origin in \( {\mathbb{R}}^{3} \) , or, what is the same, the set of equivalence classes of ordered triples of points \( \left( {{x}^{1},{x}^{2},{x}^{3}}\right) \) of real numbers that are not all three zero, we obtain the real projective plane \( {\mathbb{{RP}}...
In the regions \( {U}_{1},{U}_{2} \), and \( {U}_{3} \) where \( {x}^{1} \neq 0,{x}^{2} \neq 0,{x}^{3} \neq \) 0 respectively, we introduce local coordinate systems \( \left( {1,\frac{{x}^{2}}{{x}^{1}},\frac{{x}^{3}}{{x}^{1}}}\right) = \left( {1,{t}_{1}^{2},{t}_{1}^{3}}\right) \sim \) \( \left( {{t}_{1}^{2},{t}_{1}^{3}...
Yes
The set of lines in the plane \( {\mathbb{R}}^{2} \) can be partitioned into two sets: \( U \), the nonvertical lines, and \( V \), the nonhorizontal lines. Each line in \( U \) has an equation of the form \( y = {u}_{1}x + {u}_{2} \), and hence is characterized by the coordinates \( \left( {{u}_{1},{u}_{2}}\right) \),...
Every line in the plane has an equation \( {ax} + {by} + c = 0 \) and is characterized by a triple of numbers \( \left( {a, b, c}\right) \), proportional triples defining the same line. For that reason, it might appear that we are again dealing with the projective plane \( {\mathbb{{RP}}}^{2} \) considered in Example 1...
Yes
Proposition 5 The boundary of an orientable smooth \( n \) -dimensional manifold is an orientable \( \left( {n - 1}\right) \) -dimensional manifold admitting a structure of the same smoothness as the original manifold.
Proof The proof of Proposition 5 is a verbatim repetition of the proof of the analogous Proposition 2 of Sect. 12.3.2 for surfaces embedded in \( {\mathbb{R}}^{n} \) .
No
Corollary 1 If \( M \) is a compact manifold and \( A \) a \( {C}^{\left( k\right) } \) atlas on \( M \), then there exists a finite partition of unity \( \left\{ {{e}_{1},\ldots ,{e}_{l}}\right\} \) on \( M \) subordinate to a covering of the manifold by the ranges of the charts of \( A \) .
Proof Since \( M \) is compact, the atlas \( A \) can be regarded as finite. We now have the hypotheses of Proposition 6, if we set \( K = M \) in it.
No
Corollary 2 For every compact set \( K \) contained in a manifold \( M \) and every open set \( G \subset M \) containing \( K \), there exists a function \( f : M \rightarrow \mathbb{R} \) with smoothness equal to that of the manifold and such that \( f\left( x\right) \equiv 1 \) on \( K \) and \( \operatorname{supp}f...
Proof Cover each point \( x \in K \) by a neighborhood \( U\left( x\right) \) contained in \( G \) and inside the range of some chart of the manifold \( M \) . From the open covering \( \{ U\left( x\right), x \in K\} \) of the compact set \( K \) extract a finite covering, and construct a partition of unity \( \left\{ ...
Yes
Theorem 1 (Poincaré) Every closed \( \left( {p + 1}\right) \) -form \( \left( {p \geq 0}\right) \) on a manifold that is contractible to a point is exact.
The nontrivial part of the proof consists of the following \
No
Let \( A, B \), and \( C \) be smooth real-valued functions of the variables \( x, y, z \in {\mathbb{R}}^{3} \). We ask how to solve the following system of equations for \( P, Q \), and \( R \): \n\n\[ \n\left\{ \begin{array}{l} \frac{\partial R}{\partial y} - \frac{\partial Q}{\partial z} = A, \\ \frac{\partial P}{\p...
An obvious necessary condition for the consistency of the system (15.54) is that the functions \( A, B \), and \( C \) satisfy the relation \n\n\[ \n\frac{\partial A}{\partial x} + \frac{\partial B}{\partial y} + \frac{\partial C}{\partial z} = 0 \n\] \n\nwhich is equivalent to saying that the form \n\n\[ \n\omega = A\...
Yes
Example 4 Consider the sequence \( {f}_{n}\left( x\right) = 2\left( {n + 1}\right) x{\left( 1 - {x}^{2}\right) }^{n} \) on the closed interval \( I = \left\lbrack {0,1}\right\rbrack \) .
Since \( n{q}^{n} \rightarrow 0 \) for \( \left| q\right| < 1 \), this sequence tends to zero on the entire closed interval \( I \) .
Yes
Let \( m, n \in \mathbb{N} \), and let \( {f}_{m}\left( x\right) \mathrel{\text{:=}} \mathop{\lim }\limits_{{n \rightarrow \infty }}{\left( \cos m!\pi x\right) }^{2n} \) . If \( m!x \) is an integer, then \( {f}_{m}\left( x\right) = 1 \), and if \( m!x \notin \mathbb{Z} \), obviously \( {f}_{m}\left( x\right) = 0 \) .
We shall now consider the sequence \( \left\{ {{f}_{m};m \in \mathbb{N}}\right\} \) and show that it converges on the entire real line to the Dirichlet function\n\n\[ \mathcal{D}\left( x\right) = \left\{ \begin{array}{ll} 0, & \text{ if }x \notin \mathbb{Q}, \\ 1, & \text{ if }x \in \mathbb{Q}. \end{array}\right. \]\n\...
Yes
Example 6 We know that for any \( x \in \mathbb{R} \)\n\n\[ \sin x = x - \frac{1}{3!}{x}^{3} + \frac{1}{5!}{x}^{5} - \cdots + \frac{{\left( -1\right) }^{m}}{\left( {{2m} + 1}\right) !}{x}^{{2m} + 1} + \cdots ,\]\n\n(16.1)\n\nbut after the examples we have just considered, we understand that the relations\n\n\[ {\sin }^...
Indeed, if the equality\n\n\[ S\left( x\right) = {a}_{1}\left( x\right) + {a}_{2}\left( x\right) + \cdots + {a}_{m}\left( x\right) + \cdots \]\n\nis understood in the sense that \( S\left( x\right) = \mathop{\lim }\limits_{{n \rightarrow \infty }}{S}_{n}\left( x\right) \), where \( {S}_{n}\left( x\right) = \mathop{\sum...
Yes
Example 8 Let us consider the family of functions \( {f}_{t} : I \rightarrow \mathbb{R} \) defined on the closed interval \( I = \{ x \in \mathbb{R} \mid 0 \leq x \leq 1\} \) and depending on the parameter \( t \in \rbrack 0,1\rbrack \) . The graph of the functions \( y = {f}_{t}\left( x\right) \) is shown in Fig. 16.1...
In such cases we shall say for convenience that the family converges nonuniformly to the limit function.
Yes
The sequence of functions \( {f}_{n}\left( x\right) = {x}^{n} - {x}^{2n} \) defined on the closed interval \( 0 \leq x \leq 1 \), as one can see, converges to zero at each point as \( n \rightarrow \infty \). To determine whether this convergence is uniform, we find the quantity \( {\Delta }_{n} = \) \( \mathop{\max }\...
Since \( {f}_{n}^{\prime }\left( x\right) = n{x}^{n - 1}\left( {1 - 2{x}^{n}}\right) = 0 \) for \( x = 0 \) and \( x = {2}^{-1/n} \) , it is clear that \( {\Delta }_{n} = {f}_{n}\left( {2}^{-1/n}\right) = 1/4 \) . Thus \( {\Delta }_{n} \nrightarrow 0 \) as \( n \rightarrow \infty \) and our sequence converges to the li...
Yes
The sequence of functions \( {f}_{n} = {x}^{n} \) on the interval \( 0 \leq x \leq 1 \) converges to the function\n\n\[ f\left( x\right) = \left\{ \begin{array}{ll} 0, & \text{ if }0 \leq x < 1 \\ 1, & \text{ if }x = 1 \end{array}\right. \]
nonuniformly, since for each \( n \in \mathbb{N} \)\n\n\[ {\Delta }_{n} = \mathop{\sup }\limits_{{0 \leq x \leq 1}}\left| {f\left( x\right) - {f}_{n}\left( x\right) }\right| = \mathop{\sup }\limits_{{0 \leq x < 1}}\left| {f\left( x\right) - {f}_{n}\left( x\right) }\right| =\n\n= \mathop{\sup }\limits_{{0 \leq x < 1}}\l...
Yes
The sequence of functions \( {f}_{n}\left( x\right) = \frac{\sin {n}^{2}x}{n} \) studied in Example 2 converges to zero uniformly on the entire set \( \mathbb{R} \) as \( n \rightarrow \infty \)
since in this case\n\n\[\n\left| {f\left( x\right) - {f}_{n}\left( x\right) }\right| = \left| {{f}_{n}\left( x\right) }\right| = \left| \frac{\sin {n}^{2}x}{n}\right| \leq \frac{1}{n},\n\]\n\nthat is, \( {\Delta }_{n} \leq 1/n \), and hence \( {\Delta }_{n} \rightarrow 0 \) as \( n \rightarrow \infty \) .
Yes
Earlier we defined the function exp : \( \mathbb{C} \rightarrow \mathbb{C} \) by the relation\n\n\[ \exp z \mathrel{\text{:=}} \mathop{\sum }\limits_{{n = 0}}^{\infty }\frac{1}{n!}{z}^{n} \]\n\n(16.4)\n\nafter first verifying that the series on the right converges for every value \( z \in \mathbb{C} \) .
In the language of Definitions 1-3 one can now say that the series (16.4) of functions \( {a}_{n}\left( z\right) = \frac{1}{n!}{z}^{n} \) converges on the entire complex plane, and the function \( \exp z \) is its sum.\n\nBy Definitions 1 and 2 just adopted a two-way connection is established between series and their s...
No
Theorem 1 (Cauchy criterion for uniform convergence of a series) The series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{a}_{n}\left( x\right) \) converges uniformly on a set \( E \) if and only if for every \( \varepsilon > 0 \) there exists \( N \in \mathbb{N} \) such that\n\n\[ \left| {{a}_{n}\left( x\right) + \cdot...
Proof Indeed, setting \( {n}_{1} = m,{n}_{2} = n - 1 \) in (16.5) and assuming that \( {s}_{n}\left( x\right) \) is the partial sum of the series, we obtain inequality (16.6), from which relation (16.5) in turn follows with the same notation and hypotheses of the theorem.
No
Corollary 1 (Necessary condition for uniform convergence of a series) A necessary condition for the series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{a}_{n}\left( x\right) \) to converge uniformly on a set \( E \) is that \( {a}_{n} \rightrightarrows 0 \) on \( E \) as \( n \rightarrow \infty \) .
Proof This follows from the definition of uniform convergence of a sequence to zero and inequality (16.6) if we set \( m = n \) in it.
No
The series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }\frac{{z}^{n}}{n} \), as we know, converges in the unit disk \( K = \{ z \in \) \( \mathbb{C}\left. {\left| \right| z \mid < 1}\right\} \) . Since \( \left| \frac{{z}^{n}}{n}\right| < \frac{1}{n} \) for \( z \in K \), we have \( \frac{{z}^{n}}{n} \Rightarrow 0 \) o...
In fact, for any fixed \( n \in \mathbb{N} \), by the continuity of the terms of the series, if \( z \) is sufficiently close to 1, we can get the inequalities\n\n\[ \left| {\frac{{z}^{n}}{n} + \cdots + \frac{{z}^{2n}}{2n}}\right| > \frac{1}{2}\left| {\frac{1}{n} + \cdots + \frac{1}{2n}}\right| > \frac{1}{4}. \]\n\nFro...
Yes
Proposition 1 If the series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{a}_{n}\left( x\right) \) and \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{b}_{n}\left( x\right) \) are such that \( \left| {{a}_{n}\left( x\right) }\right| \leq \) \( {b}_{n}\left( x\right) \) for every \( x \in E \) and for all sufficiently large...
Proof Under these assumptions for all sufficiently large indices \( n \) and \( m \) (let \( n \leq m \) ) at each point \( x \in E \) we have\n\n\[ \left| {{a}_{n}\left( x\right) + \cdots + {a}_{m}\left( x\right) }\right| \leq \left| {{a}_{n}\left( x\right) }\right| + \cdots + \left| {{a}_{m}\left( x\right) }\right| \...
Yes
Corollary 2 (Weierstrass’ \( M \) -test for uniform convergence of a series) If for the series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{a}_{n}\left( x\right) \) one can exhibit a convergent numerical series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{M}_{n} \) such that \( \mathop{\sup }\limits_{{x \in E}}\left| {...
Proof The convergent numerical series can be regarded as a series of constant functions on the set \( E \), which by the Cauchy criterion converges uniformly on \( E \) . Hence the Weierstrass test follows from Proposition 1 if we set \( {b}_{n}\left( x\right) = {M}_{n} \) in it.
Yes
Proposition 2 If a power series \( \mathop{\sum }\limits_{{n = 0}}^{\infty }{c}_{n}{\left( z - {z}_{0}\right) }^{n} \) converges at a point \( \zeta \neq {z}_{0} \) , then it converges absolutely and uniformly in any disk \( {K}_{q} = \left\{ {z \in \mathbb{C}\left| \right| z - {z}_{0} \mid < }\right. \) \( \left. {q\l...
Proof By the necessary condition for convergence of a numerical series it follows from the convergence of the series \( \mathop{\sum }\limits_{{n = 0}}^{\infty }{c}_{n}{\left( \zeta - {z}_{0}\right) }^{n} \) that \( {c}_{n}{\left( \zeta - z\right) }^{n} \rightarrow 0 \) as \( n \rightarrow \infty \) . Hence for all suf...
Yes
Proposition 3 (The Abel-Dirichlet test for uniform convergence) A sufficient condition for uniform convergence on \( E \) of a series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{a}_{n}\left( x\right) {b}_{n}\left( x\right) \) whose terms are products of complex-valued functions \( {a}_{n} : X \rightarrow \mathbb{C} \)...
Proof The monotonicity of the sequence \( {b}_{n}\left( x\right) \) allows us to write an estimate analogous to (16.8) for each \( x \in E \) :\n\n\[ \n\left| {\mathop{\sum }\limits_{{k = n}}^{m}{a}_{k}\left( x\right) {b}_{k}\left( x\right) }\right| \leq 4\mathop{\max }\limits_{{n - 1 \leq k \leq m}}\left| {{A}_{k}\lef...
Yes
Proposition 4 (The so-called second Abel theorem on power series) If a power series \( \mathop{\sum }\limits_{{n = 0}}^{\infty }{c}_{n}{\left( z - {z}_{0}\right) }^{n} \) converges at a point \( \zeta \in \mathbb{C} \), then it converges uniformly on the closed interval with endpoints \( {z}_{0} \) and \( \zeta \) .
Proof We represent the points of this interval in the form \( {z}_{0} + \left( {\zeta - {z}_{0}}\right) t \), where \( 0 \leq t \leq 1 \) . Substituting this expression in the power series, we obtain the series \( \mathop{\sum }\limits_{{n = 0}}^{\infty }{c}_{n}{\left( \zeta - {z}_{0}\right) }^{n}{t}^{n} \) . By hypoth...
Yes
Theorem 1 Let \( \left\{ {{F}_{t};t \in T}\right\} \) be a family of functions \( {F}_{t} : X \rightarrow \mathbb{C} \) depending on a parameter \( t \) ; let \( {\mathcal{B}}_{X} \) be a base in \( X \) and \( {\mathcal{B}}_{T} \) a base in \( T \) . If the family converges uniformly on \( X \) over the base \( {\math...
Proof Since \( {F}_{t} \rightrightarrows F \) on \( X \) over \( {\mathcal{B}}_{T} \), by the Cauchy criterion, for every \( \varepsilon > 0 \) there exists \( {B}_{T} \) in \( {\mathcal{B}}_{T} \) such that\n\n\[ \left| {{F}_{{t}_{1}}\left( x\right) - {F}_{{t}_{2}}\left( x\right) }\right| < \varepsilon \]\n\n(16.18)\n...
Yes
Theorem 2 Let \( \\left\\{ {{f}_{t};t \\in T}\\right\\} \) be a family of functions \( {f}_{t} : X \\rightarrow \\mathbb{C} \) depending on the parameter \( t \) ; let \( \\mathcal{B} \) be a base in \( T \) . If \( {f}_{t} \\rightrightarrows f \) on \( X \) over the base \( \\mathcal{B} \) and the functions \( {f}_{t}...
Proof In this case the diagram (16.17) assumes the following specific form: ![069515e3-8cdb-49aa-894a-8b785cb78da5_399_0.jpg](images/069515e3-8cdb-49aa-894a-8b785cb78da5_399_0.jpg)\n\nHere all the limiting passages except the vertical passage on the right are defined by the hypotheses of Theorem 2 itself. The nontrivia...
Yes
Proposition 1 If a power series \( \mathop{\sum }\limits_{{n = 0}}^{\infty }{c}_{n}{\left( z - {z}_{0}\right) }^{n} \) converges at a point \( \zeta \), it converges uniformly on the closed interval \( \left\lbrack {{z}_{0},\zeta }\right\rbrack \) from \( {z}_{0} \) to \( \zeta \), and the sum of the series is continuo...
In particular, this means that if a numerical series \( \mathop{\sum }\limits_{{n = 0}}^{\infty }{c}_{n} \) converges, then the power series \( \mathop{\sum }\limits_{{n = 0}}^{\infty }{c}_{n}{x}^{n} \) converges uniformly on the closed interval \( 0 \leq x \leq 1 \) of the real axis and its sum \( s\left( x\right) = \...
Yes
Proposition 2 (Dini’s \( {}^{2} \) theorem) If a sequence of continuous functions on a compact set converges monotonically to a continuous function, then the convergence is uniform.
Proof For definiteness suppose that \( {f}_{n} \) is a nondecreasing sequence converging to \( f \) . We fix an arbitrary \( \varepsilon > 0 \), and for every point \( x \) of the compact set \( K \) we find an index \( {n}_{x} \) such that \( 0 \leq f\left( x\right) - {f}_{{n}_{x}}\left( x\right) < \varepsilon \) . Si...
Yes
Corollary 3 If the terms of the series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{a}_{n}\left( x\right) \) are nonnegative functions \( {a}_{n} \) : \( K \rightarrow \mathbb{R} \) that are continuous on a compact set \( K \) and the series converges to a continuous function on \( K \), then it converges uniformly on ...
Proof The partial sums \( {s}_{n}\left( x\right) = \mathop{\sum }\limits_{{k = 1}}^{n}{a}_{k}\left( x\right) \) of this series satisfy the hypotheses of Dini's theorem.
Yes
Example 3 We shall show that the sequence of functions \( {f}_{n}\left( x\right) = n\left( {1 - {x}^{1/n}}\right) \) tends to \( f\left( x\right) = \ln \frac{1}{x} \) as \( n \rightarrow + \infty \) uniformly on each closed interval \( \left\lbrack {a, b}\right\rbrack \) contained in the interval \( 0 < x < \infty \) .
Proof For fixed \( x > 0 \) the function \( {x}^{t} = {\mathrm{e}}^{t\ln x} \) is convex with respect to \( t \), so that the ratio \( \frac{{x}^{t} - {x}^{0}}{t - 0} \) (the slope of the chord) is nonincreasing as \( t \rightarrow + 0 \) and tends to \( \ln x \) .\n\nHence \( {f}_{n}\left( x\right) \nearrow \ln \frac{...
Yes
Corollary 4 If the series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{f}_{n}\left( x\right) \) consisting of integrable functions on a closed interval \( \left\lbrack {a, b}\right\rbrack \subset \mathbb{R} \) converges uniformly on that closed interval, then its sum is also integrable on \( \left\lbrack {a, b}\right\r...
\[ {\int }_{a}^{b}\left( {\mathop{\sum }\limits_{{n = 1}}^{\infty }{f}_{n}\left( x\right) }\right) \mathrm{d}x = \mathop{\sum }\limits_{{n = 1}}^{\infty }{\int }_{a}^{b}{f}_{n}\left( x\right) \mathrm{d}x. \]
Yes
Using the theorem just proved, we can nevertheless obtain a very simple representation of this function as a power series.
To do this, we remark that\n\n\\[ \n\\frac{\\sin t}{t} = \\mathop{\\sum }\\limits_{{n = 0}}^{\\infty }\\frac{{\\left( -1\\right) }^{n}}{\\left( {{2n} + 1}\\right) !}{t}^{2n} \n\\]\n\n(16.28)\n\nand the series on the right-hand side converges uniformly on every closed interval \\( \\left\\lbrack {-a, a}\\right\\rbrack \...
Yes
Corollary 5 If the series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }{f}_{n}\left( x\right) \) of functions \( {f}_{n} : X \rightarrow \mathbb{C} \) that are differentiable on a bounded convex subset \( X \) (contained in \( \mathbb{R},\mathbb{C} \), or any other normed vector space) converges at even one point \( x \...
\[ {\left( \mathop{\sum }\limits_{{n = 1}}^{\infty }{f}_{n}\left( x\right) \right) }^{\prime }\left( x\right) = \mathop{\sum }\limits_{{n = 1}}^{\infty }{f}_{n}^{\prime }\left( x\right) \] This follows from Theorem 4 and the definitions of the sum and uniform convergence of a series, together with the linearity of the ...
Yes
Proposition 3 Let \( K \subset \mathbb{C} \) be the convergence disk for a power series \( \mathop{\sum }\limits_{{n = 0}}^{\infty }{c}_{n}(z - \) \( {\left. {z}_{0}\right) }^{n} \) . If \( K \) contains more than just the point \( {z}_{0} \), then the sum of the series \( f\left( z\right) \) is differentiable inside \...
Proof Since \( {\overline{\lim }}_{n \rightarrow \infty }\sqrt[{n - 1}]{n\left| {c}_{n}\right| } = \mathop{\lim }\limits_{{n \rightarrow \infty }}\sqrt[n]{\left| {c}_{n}\right| } \), it follows from the Cauchy-Hadamard formula (Theorem 2 of Sect. 16.2.2 that the power series \( \mathop{\sum }\limits_{{n = 1}}^{\infty }...
Yes
The Bessel function \( {J}_{n}\left( x\right), n \in \mathbb{N} \), is a solution of Bessel’s \( {}^{3} \) equation\n\n\[ \n{x}^{2}{y}^{\prime \prime } + x{y}^{\prime } + \left( {{x}^{2} - {n}^{2}}\right) y = 0.\n\]
Let us attempt to solve this equation, for example, for \( n = 0 \), as a power series \( y = \mathop{\sum }\limits_{{k = 0}}^{\infty }{c}_{k}{x}^{k} \) . Applying formula (16.29) successively, after elementary transformations, we arrive at the relation\n\n\[ \n{c}_{1} + \mathop{\sum }\limits_{{k = 0}}^{\infty }\left( ...
Yes
Example 3 If the family \( \left\{ {{f}_{\alpha } : \left\lbrack {a, b}\right\rbrack \rightarrow \mathbb{R};\alpha \in A}\right\} \) of differentiable functions \( {f}_{\alpha } \) is such that the family \( \left\{ {{f}_{\alpha }^{\prime };\alpha \in A}\right\} \) of their derivatives is uniformly bounded by a constan...
as follows from the mean-value theorem, and hence the original family is equicontinuous on the closed interval \( \left\lbrack {a, b}\right\rbrack \) .
Yes
Lemma 1 Let \( K \) and \( Y \) be metric spaces, with \( K \) compact. A necessary condition for the sequence \( \left\{ {{f}_{n};n \in \mathbb{N}}\right\} \) of continuous functions \( {f}_{n} : K \rightarrow Y \) to converge uniformly on \( K \) is that the family \( \left\{ {{f}_{n};n \in \mathbb{N}}\right\} \) be ...
Proof Let \( {f}_{n} \rightrightarrows f \) on \( K \) . By Theorem 2 of Sect. 16.3, we conclude that \( f \in \) \( C\left( {K, Y}\right) \) . It follows from the uniform continuity of \( f \) on the compact set \( K \) that for every \( \varepsilon > 0 \) there exists \( \delta > 0 \) such that \( \left( {{d}_{K}\lef...
Yes
Theorem 1 (Arzelà-Ascoli) Let \( \mathcal{F} \) be a family of functions \( f : K \rightarrow Y \) defined on a compact metric space \( K \) with values in a complete metric space \( Y \) . A necessary and sufficient condition for every sequence \( \left\{ {{f}_{n} \in \mathcal{F};n \in \mathbb{N}}\right\} \) to contai...
Proof Necessity. If \( \mathcal{F} \) were not a totally bounded family, one could obviously construct a sequence \( \left\{ {{f}_{n};n \in \mathbb{N}}\right\} \) of functions \( {f}_{n} \in \mathcal{F} \) that would not be totally bounded and from which (see the lemma) one could not extract a uniformly convergence sub...
Yes
Example 5 Although Theorem 2 still requires a nontrivial proof (given below), one can at least conclude from the uniform continuity of any function \( f \in C\left( {\left\lbrack {a, b}\right\rbrack ,\mathbb{R}}\right) \) that the piecewise-linear continuous real-valued functions on the interval \( \left\lbrack {a, b}\...
Proof We first remark that if \( f, g \in C\left( {\left\lbrack {a, b}\right\rbrack ,\mathbb{R}}\right) ,\alpha \in \mathbb{R} \), and the functions \( f \) and \( g \) admit a uniform approximation (with arbitrary accuracy) by polynomials, then the continuous functions \( f + g, f \cdot g \), and \( {\alpha f} \) also...
Yes
Lemma 2 If an algebra \( A \) of real (resp. complex) functions on \( X \) separates the points of \( X \) and does not vanish on \( X \), then for any two distinct points \( {x}_{1},{x}_{2} \in X \) and any real (resp. complex) numbers \( {c}_{1},{c}_{2} \) there is a function \( f \) in \( A \) such that \( f\left( {...
Proof It obviously suffices to prove the lemma when \( {c}_{1} = 0,{c}_{2} = 1 \) and when \( {c}_{1} = 1,{c}_{2} = 0 \) . By the symmetry of the hypotheses on \( {x}_{1} \) and \( {x}_{2} \), we consider only the case \( {c}_{1} = 1,{c}_{2} = 0 \) . We begin by remarking that \( A \) contains a special function \( s \...
Yes
Theorem 3 (Stone \( {}^{8} \) ) Let \( A \) be an algebra of continuous real-valued functions defined on a compact set \( K \) . If \( A \) separates the points of \( K \) and does not vanish on \( K \) , then \( A \) is an everywhere-dense subspace of \( C\left( {K,\mathbb{R}}\right) \) .
Proof Let \( \bar{A} \) be the closure of the set \( A \subset C\left( {K,\mathbb{R}}\right) \) in \( C\left( {K,\mathbb{R}}\right) \), that is, \( \bar{A} \) consists of the continuous functions \( f \in C\left( {K,\mathbb{R}}\right) \) that can be approximated uniformly with arbitrary precision by functions of \( A \...
Yes
Proposition 1 Let \( P = \left\{ {\left( {x, y}\right) \in {\mathbb{R}}^{2} \mid a \leq x \leq b \land c \leq y \leq d}\right\} \) be a rectangle in the plane \( {\mathbb{R}}^{2} \) . If the function \( f : P \rightarrow \mathbb{R} \) is continuous, that is, if \( f \in C\left( {P,\mathbb{R}}\right) \), then the functi...
Proof It follows from the uniform continuity of the function \( f \) on the compact set \( P \) that \( {\varphi }_{y}\left( x\right) \mathrel{\text{:=}} f\left( {x, y}\right) \rightrightarrows f\left( {x,{y}_{0}}\right) = : {\varphi }_{{y}_{0}}\left( x\right) \) on \( \left\lbrack {a, b}\right\rbrack \) as \( y \right...
Yes
If a function \( f \) belongs to the class \( {C}^{\left( 1\right) }\left( {U,\mathbb{R}}\right) \) in a neighborhood \( U \) of the point \( {x}_{0} \), then in some neighborhood of \( {x}_{0} \) it can be represented in the form\n\n\[ f\left( x\right) = f\left( {x}_{0}\right) + \varphi \left( x\right) \left( {x - {x}...
Equality (17.3) follows easily from the Newton-Leibniz formula\n\n\[ f\left( {{x}_{0} + h}\right) - f\left( {x}_{0}\right) = {\int }_{0}^{1}{f}^{\prime }\left( {{x}_{0} + {th}}\right) \mathrm{d}t \cdot h \]\n\nand Proposition 1 applied to the function \( F\left( h\right) = {\int }_{0}^{1}{f}^{\prime }\left( {{x}_{0} + ...
Yes
Proposition 2 If the function \( f : P \rightarrow \mathbb{R} \) is continuous and has a continuous partial derivative with respect to \( y \) on the rectangle \( P = \left\{ {\left( {x, y}\right) \in {\mathbb{R}}^{2} \mid a \leq x \leq b \land c \leq }\right. \) \( y \leq d\} \), then the integral (17.2) belongs to \(...
Proof We shall verify directly that if \( {y}_{0} \in \left\lbrack {c, d}\right\rbrack \), then \( {F}^{\prime }\left( {y}_{0}\right) \) can be computed by formula (17.5):\n\n\[ \n\left| {F\left( {{y}_{0} + h}\right) - F\left( {y}_{0}\right) - \left( {{\int }_{a}^{b}\frac{\partial f}{\partial y}\left( {x,{y}_{0}}\right...
Yes
Example 2 Let us verify that the function \( u\left( x\right) = {\int }_{0}^{\pi }\cos \left( {{n\varphi } - x\sin \varphi }\right) \mathrm{d}\varphi \) satisfies Bessel’s equation \( {x}^{2}{u}^{\prime \prime } + x{u}^{\prime } + \left( {{x}^{2} - {n}^{2}}\right) u = 0 \) .
Indeed, after carrying out the differentiation with formula (17.5) and making simple transformations we find\n\n\[ \n- {x}^{2}{\int }_{0}^{\pi }{\sin }^{2}\varphi \cos \left( {{n\varphi } - x\sin \varphi }\right) \mathrm{d}\varphi + x{\int }_{0}^{\pi }\sin \varphi \sin \left( {{n\varphi } - x\sin \varphi }\right) \math...
Yes
The complete elliptic integrals\n\n\[ E\\left( k\\right) = {\\int }_{0}^{\\pi /2}\\sqrt{1 - {k}^{2}{\\sin }^{2}\\varphi }\\mathrm{d}\\varphi ,\\;K\\left( k\\right) = {\\int }_{0}^{\\pi /2}\\frac{\\mathrm{d}\\varphi }{\\sqrt{1 - {k}^{2}{\\sin }^{2}\\varphi }} \]\n\nas functions of the parameter \( k,0 < k < 1 \), called...
Let us verify, for example, the first of these. By formula (17.5)\n\n\[ \\frac{\\mathrm{d}E}{\\mathrm{\\;d}k} = - {\\int }_{0}^{\\pi /2}k{\\sin }^{2}\\varphi \\cdot {\\left( 1 - {k}^{2}{\\sin }^{2}\\varphi \\right) }^{-1/2}\\mathrm{\\;d}\\varphi = \]\n\n\[ = \\frac{1}{k}{\\int }_{0}^{\\pi /2}{\\left( 1 - {k}^{2}{\\sin ...
Yes
Let \[ F\left( \alpha \right) = {\int }_{0}^{\pi /2}\ln \left( {{\alpha }^{2} - {\sin }^{2}\varphi }\right) \mathrm{d}\varphi \;\left( {\alpha > 1}\right) .
According to formula (17.5) \[ {F}^{\prime }\left( \alpha \right) = {\int }_{0}^{\pi /2}\frac{{2\alpha }\mathrm{d}\varphi }{{\alpha }^{2} - {\sin }^{2}\varphi } = \frac{\pi }{\sqrt{{\alpha }^{2} - 1}}, \] from which we find \( F\left( \alpha \right) = \pi \ln \left( {\alpha + \sqrt{{\alpha }^{2} - 1}}\right) + c \) . T...
Yes
Let \[ {F}_{n}\left( x\right) = \frac{1}{\left( {n - 1}\right) !}{\int }_{0}^{x}{\left( x - t\right) }^{n - 1}f\left( t\right) \mathrm{d}t, \] where \( n \in \mathbb{N} \) and \( f \) is a function that is continuous on the interval of integration. Let us verify that \( {F}_{n}^{\left( n\right) }\left( x\right) = f\lef...
For \( n = 1 \) we have \( {F}_{1}\left( x\right) = {\int }_{0}^{x}f\left( t\right) \mathrm{d}t \) and \( {F}_{1}^{\prime }\left( x\right) = f\left( x\right) \). By formula (17.8) we find for \( n > 1 \) that \[ {F}_{n}^{\prime }\left( x\right) = \frac{1}{\left( {n - 1}\right) !}{\left( x - x\right) }^{n - 1}f\left( x\...
Yes
Proposition 3 If the function \( f : P \rightarrow \mathbb{R} \) is continuous in the rectangle \( P = \) \( \left\{ {\left( {x, y}\right) \in {\mathbb{R}}^{2} \mid a \leq x \leq b \land c \leq y \leq d}\right\} \), then the integral (17.2) is integrable over the closed interval \( \left\lbrack {c, d}\right\rbrack \) a...
Proof From the point of view of multiple integrals, Eq. (17.9) is an elementary version of Fubini's theorem. However, we shall give a proof of (17.9) that justifies it independently of Fubini's theorem.\n\nConsider the functions\n\n\[ \n\varphi \left( u\right) = {\int }_{c}^{u}\left( {{\int }_{a}^{b}f\left( {x, y}\righ...
Yes