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Corollary 36.4. Let \( n > 1 \) . Let \( C \) be a subset of \( {\mathbf{R}}^{n} \) homeomorphic to \( {S}^{n - 1} \) . Then \( {\mathbf{R}}^{n} - C \) has precisely two components, of which \( C \) is the common boundary.
Proof. Step 1. We show first that if \( U \) is a connected open set in \( {S}^{n} \) , where \( n > 1 \), no point of \( U \) separates \( U \) .\n\nLet \( p \in U \) and suppose \( U - p \) is not connected. We derive a contradiction. Choose an open \( \epsilon \) -ball \( {B}_{\epsilon } \) centered at \( p \) and l...
Yes
Theorem 36.5 (Invariance of domain). Let \( U \) be open in \( {\mathbf{R}}^{n} \) ; let \( f : U \rightarrow {\mathbf{R}}^{n} \) be continuous and injective. Then \( f\left( U\right) \) is open in \( {\mathbf{R}}^{n} \) and \( f \) is an imbedding.
Proof. Without loss of generality, we can replace \( {\mathbf{R}}^{n} \) by \( {S}^{n} \) . Step 1. Given a point \( y \) of \( f\left( U\right) \), we show that \( f\left( U\right) \) contains a neighborhood of \( y \) . This proves that \( f\left( U\right) \) is open in \( {S}^{n} \) . Let \( x \) be the point of \( ...
Yes
Theorem 37.1. Let \( p : X \rightarrow Y \) be a quotient map. If \( p \) is a closed map, and if \( X \) is normal, then \( Y \) is normal.
Proof. If \( x \) is a point of \( X \), then \( x \) is closed in \( X \), so the one-point set \( p\left( x\right) \) is closed in \( Y \) (because \( p \) is a closed map). Thus \( Y \) is a \( {T}_{\mathrm{i}} \) -space.\n\nLet \( A \) and \( B \) be disjoint closed sets in \( Y \) . Then \( {p}^{-1}\left( A\right)...
Yes
Theorem 37.2. If \( X \) and \( Y \) are normal, then the adjunction space \( X{ \cup }_{f}Y \) is normal.
Proof. As usual, \( A \) is closed in \( X \) and \( f : A \rightarrow Y \) is continuous. Let \( B \) and \( C \) be disjoint closed sets in \( X{ \cup }_{f}Y \) . Let\n\n\[ \n{B}_{X} = {p}^{-1}\left( B\right) \cap X;\;{C}_{X} = {p}^{-1}\left( C\right) \cap X;\n\]\n\n\[ \n{B}_{Y} = {p}^{-1}\left( B\right) \cap Y;\;{C}...
Yes
Lemma 37.3. Let \( X \) be a set which is the union of the topological spaces \( \left\{ {X}_{\alpha }\right\} \) . (a) If there is a topological space \( {X}_{T} \) having \( X \) as its underlying set, and each \( {X}_{\alpha } \) is a subspace of \( {X}_{T} \), then \( X \) has a topology, of which the \( {X}_{\alph...
Proof. (a) Let us define a topological space \( {X}_{C} \) whose underlying set is \( X \) by declaring a set \( A \) to be closed in \( {X}_{C} \) if and only if its intersection with each \( {X}_{\alpha } \) is a closed set of \( {X}_{\alpha } \) . The collection of such sets contains arbitrary intersections and fini...
Yes
Theorem 37.4. Let \( X \) be a space that is the countable union of certain closed subspaces \( {X}_{n} \) . Suppose the topology of \( X \) is coherent with the spaces \( {X}_{n} \) . Then if each \( {X}_{i} \) is normal, so is \( X \) .
Proof. If \( p \) is a point of \( X \), then \( \{ p\} \cap {X}_{i} \) is closed in \( {X}_{i} \) for each \( i \), so \( \{ p\} \) is closed in \( X \) . Thus \( X \) is a \( {T}_{1} \) -space.\n\nLet \( A \) and \( B \) be disjoint closed sets in \( X \) . Define \( {Y}_{0} = A \cup B \), and for \( n > 0 \), define...
Yes
Lemma 38.1. Let \( X \) be a \( {CW} \) complex with open cells \( {e}_{\alpha } \) . A function \( f : X \rightarrow Y \) is continuous if and only if \( f \mid {\bar{e}}_{\alpha } \) is continuous for each \( \alpha \) . A function \( F : X \times I \rightarrow Y \) is continuous if and only if \( F \mid \left( {{\wi...
No
Consider the torus as a quotient space of a rectangle, as usual. See Figure 38.1. We can express \( T \) as a CW complex having a single open 2-cell (the image under \( \pi \) of the interior of the rectangle), two open 1-cells (the images of the open edges), and one 0-cell (the image of the vertices).
Conditions (1)-(3) hold at once.
No
Let \( K \) and \( L \) be simplicial complexes; suppose \( K \) is locally finite. The space \( X = \left| K\right| \times \left| L\right| \) can be expressed as a CW complex by taking the sets (Int \( \sigma \) ) \( \times \) (Int \( \tau \) ) as its cells, for \( \sigma \in K \) and \( \tau \in L \) .
In this case the characteristic maps\n\n\[ \n{f}_{\alpha } : {B}^{m} \rightarrow \sigma \times \tau \n\]\n\ncan be taken to be homeomorphisms. Furthermore, in this case \( \operatorname{Bd}\left( {\sigma \times \tau }\right) \) equals a union of open cells of lower dimension. Condition (3) is a consequence of Exercise ...
No
Definition. Let \( X \) be a CW complex. Let \( Y \) be a subspace of \( X \) that equals a union of open cells of \( X \) . Suppose that for each open cell \( {e}_{\alpha } \) of \( X \) contained in \( Y \), its closure is also contained in \( Y \) . Then we shall show that \( Y \) is a closed set in \( X \), and tha...
Clearly, \( Y \) is Hausdorff. If \( {e}_{\alpha } \) is an open \( m \) -cell of \( X \) contained in \( Y \), then its characteristic map \( {f}_{\alpha } : {B}^{m} \rightarrow X \) carries \( {B}^{m} \) onto \( {\bar{e}}_{\alpha } \), which is contained in \( Y \) by hypothesis. The open cells of \( X \) that inters...
Yes
We show that the space \( X \) cannot be triangulated; hence in particular, it is not triangulable as a CW complex.
Suppose \( h : \left| K\right| \rightarrow X \) is a triangulation. First we write \( X \) as the disjoint union\n\n\[X = \left( {A - C}\right) \cup C \cup {e}_{3}.\]\n\nNow if \( x \in {e}_{3} \), then \( {H}_{3}\left( {X, X - x}\right) \) is infinite cyclic, because \( x \) has a neighborhood homeomorphic to an open ...
Yes
Theorem 38.2. (a) Suppose \( X \) is a \( {CW} \) complex of dimension \( p \) . Then \( X \) is homeomorphic to an adjunction space formed from \( {X}^{p - 1} \) and a topological sum \( \sum {B}_{\alpha } \) of closed p-balls, by means of a continuous map \( g : \sum \operatorname{Bd}{B}_{\alpha } \rightarrow {X}^{p ...
Proof. (a) For each cell \( {e}_{\alpha } \) of \( X \) of dimension \( p \), one is given the characteristic map \( {f}_{\alpha } : {B}^{p} \rightarrow {\bar{e}}_{\alpha } \) . Let \( {B}_{\alpha } = {B}^{p} \times \{ \alpha \} \), and let \( \sum {B}_{\alpha } \) be the topological sum of these disjoint \( p \) -ball...
Yes
Theorem 38.3. (a) Let \( X \) be a \( {CW} \) complex. Then \( {X}^{p} \) is a closed subspace of \( {X}^{p + 1} \) for each \( p \), and \( X \) is the coherent union of the spaces \( {X}^{\mathrm{e}} \subset \) \( {X}^{1} \subset \cdots \) . It follows that \( X \) is normal.
Proof. (a) Suppose \( C \cap {X}^{p} \) is closed in \( {X}^{p} \) for each \( p \) . Then \( C \cap {\bar{e}}_{\alpha } \) is ciosed in \( {\bar{e}}_{\alpha } \) for each cell \( {e}_{\alpha } \) of dimension at most \( p \) . Since \( p \) is arbitrary, we con-ciude that \( C \) is closed in \( X \) . Thus \( X \) ha...
No
Consider the case where \( X \) is the space of a simplicial complex \( K \), and the open cells of \( X \) are the open simplices of \( K \) . Let \( {H}_{p} \) denote ordinary simplicial homology. We compute \( {H}_{p}\left( {{X}^{p},{X}^{p - 1}}\right) \) .
The simplicial chain group \( {C}_{i}\left( {{K}^{\left( p\right) },{K}^{\left( p - 1\right) }}\right) \) vanishes if \( t \neq p \), and it equals the chain group \( {C}_{p}\left( {K}^{\left( p\right) }\right) = {C}_{p}\left( K\right) \) when \( t = p \) . Therefore, \[ {H}_{p}\left( {{X}^{p},{X}^{p - 1}}\right) = {H}...
Yes
Lemma 39.1. Given an open p-cell \( {e}_{\alpha } \) of \( X \), any characteristic map for \( {\varepsilon }_{\alpha } \) ,\n\n\[ \n{f}_{\alpha } : \left( {{B}^{p},{S}^{p - 1}}\right) \rightarrow \left( {{\bar{e}}_{\alpha },{\dot{e}}_{\alpha }}\right) ,\n\]\n\ninduces an isomorphism in relative homology.
Proof. If \( p = 0 \), the result is trivial. Let \( p > 0 \) . The point \( \mathbf{0} \) is the center of \( {B}^{p} \) ; let \( {\widehat{e}}_{\alpha } \) denote \( {f}_{\alpha }\left( \mathbf{0}\right) \) . Note that because \( {f}_{\alpha } \) is a quotient map, so is its restriction\n\n\[ \n{f}_{\alpha }^{\prime ...
Yes
Lemma 39.2. Let the map\n\n\[ f : {X}^{p - 1} \cup \sum {B}_{\alpha } \rightarrow {X}^{p} \]\n\nexpress \( {X}^{p} \) as the adjunction space obtained from \( {X}^{p - 1} \) and a topological sum of p-balls \( \sum {B}_{\alpha } \) via a map \( g : \sum {S}_{\alpha } \rightarrow {X}^{p - 1} \), where \( {S}_{\alpha } =...
Proof. The proof is similar to that of the preceding lemma. The restriction \( {f}^{\prime } \) of \( f \) to the space\n\n\[ {X}^{p - 1} \cup \sum \left( {{B}_{\alpha } - {\mathbf{0}}_{\alpha }}\right) \]\n\nwhere \( {\mathbf{0}}_{\alpha } \) is the center of \( {B}_{\alpha } \), is a quotient map. Furthermore, there ...
Yes
Theorem 39.3. The group \( {H}_{i}\left( {{X}^{p},{X}^{p - 1}}\right) \) vanishes for \( i \neq p \), and is free abelian for \( i = p \). If \( \gamma \) generates \( {H}_{p}\left( {{B}^{p},{S}^{p - 1}}\right) \), then the elements \( {\left( {f}_{\alpha }\right) }_{ * }\left( \gamma \right) \) form a basis for \( {H}...
Proof. The preceding lemma tells us that\n\n\[ \n{H}_{i}\left( {{X}^{p},{X}^{p - 1}}\right) \simeq {H}_{i}\left( {\sum {B}_{\alpha },\sum {S}_{\alpha }}\right) , \n\]\n\nwhere \( \sum {B}_{\alpha } \) is a topological sum of \( p \) -balls and \( {S}_{\alpha } = \operatorname{Bd}{B}_{\alpha } \). Because the sets \( {B...
Yes
Theorem 39.5. Let \( X \) be filtered by the subspaces \( {X}_{0} \subset X, \subset \cdots \) ; suppose that \( X \) is the space of a simplicial complex \( K \), and each subspace \( {X}_{p} \) is the space of a subcomplex of \( K \) of dimension at most \( p \) . Let \( {H}_{i} \) denote simplicial homology. Suppose...
Indeed. \( {H}_{p}\left( {{X}_{p},{X}_{p - 1}}\right) \) is the subgroup of \( {C}_{p}\left( K\right) \) consisting of all \( p \) -chains of \( K \) carried by \( {X}_{\rho } \) whose boundaries are carried by \( {X}_{\rho } - 1 \) .\n\nProof. Any compact set in \( X \) lies in a finite subcomplex of \( K \), so it li...
Yes
Theorem 40.1. The space \( {P}^{n} \) is a CW complex having one cell in each dimension \( 0 \leq j \leq n \) ; its \( j \) -skeleton is \( {P}^{j} \) .
Proof. The space \( {P}^{0} \) is obtained from the 2-point space \( {S}^{0} \) by identifying these two points. Thus \( {P}^{0} \) consists of a single point.\n\nWe proceed by induction. Suppose we restrict the map \( p : {S}^{n} \rightarrow {P}^{n} \) to the closed upper hemisphere \( {E}_{ + }^{n} \) of \( {S}^{n} \...
Yes
Theorem 40.2. The space \( {\mathrm{{CP}}}^{n} \) is a \( {CW} \) complex of dimension \( {2n} \) . It has one open cell in each even dimension \( {2j} \) for \( 0 \leq {2j} \leq {2n} \), and \( {\mathrm{{CP}}}^{j} \) is its \( {2j} \) - skeleton.
Proof. The space \( \mathbf{C}{P}^{0} \) is a single point. In general, we show that \( \mathbf{C}{P}^{n} - \) \( C{P}^{n - 1} \) is an open \( {2n} \) -cell, which we denote by \( {e}_{2n} \) . Consider the subset of \( {S}^{{2n} + 1} \) consisting of all points \( z = \left( {{z}_{1},\ldots ,{z}_{n + 1},0,\ldots }\ri...
Yes
The group \( {H}_{i}\left( {\mathbf{C}{P}^{a}}\right) \) is infinite cyclic if \( i \) is even and \( 0 \leq i \leq {2n} \) ; it vanishes otherwise. The group \( {H}_{i}\left( {\mathbf{C}{P}^{\infty }}\right) \) is infinite cyclic if \( i \) is even and \( i \geq 0 \) ; it vanishes otherwise.
The cellular chain group \( {D}_{i}\left( {\mathbf{C}{P}^{n}}\right) \) is infinite cyclic if \( i \) is even and \( 0 \leq i \leq {2n} \) ; otherwise, it vanishes. Therefore, every chain of this chain complex is a cycle, and no chain bounds. A similar computation applies to \( \mathbf{C}{P}^{\infty }. \cdot ▱
No
Lemma 40.4. Let \( p : {S}^{n} \rightarrow {P}^{n} \) be the quotient map \( \left( {n \geq 1}\right) \) . Let \( j : {P}^{n} \rightarrow \) \( \left( {{P}^{n},{P}^{n - 1}}\right) \) be inclusion. The composite homomorphism \[ {H}_{n}\left( {S}^{n}\right) \overset{{p}_{ * }}{ \rightarrow }{H}_{n}\left( {P}^{n}\right) \...
Chain-level proof. We assume that \( {S}^{n} \) is triangulated so that the antipodal map \( a : {S}^{n} \rightarrow {S}^{n} \) is simplicial, and that \( {P}^{n} \) is triangulated so that \( p : {S}^{n} \rightarrow {P}^{n} \) is simplicial. (See Lemma 40.7 following.) We use simplicial homology, Let \( {c}_{n} \) be ...
Yes
Theorem 40.5. The homomorphism\n\n\\[ \n{\\partial }_{ * } : {H}_{n + 1}\\left( {{P}^{n + 1},{P}^{n}}\\right) \\rightarrow {H}_{n}\\left( {{P}^{n},{P}^{n - 1}}\\right) \n\\]\n\nis zero if \\( n \\) is even, and carries a generator to twice a generator if \\( n \\) is odd.
Proof. The map \\( {p}^{\\prime } : \\left( {{E}_{ + }^{n + 1},{S}^{n}}\\right) \\rightarrow \\left( {{P}^{n + 1},{P}^{n}}\\right) \\) is a characteristic map for the open \\( n + 1 \\) cell of \\( {P}^{n + 1} \\) ; therefore, it induces a homology isomorphism. Consider the commutative diagram\n\n\\[ \n{H}_{n + 1}\\lef...
Yes
Theorem 40.6. The homology of projective space is as follows:\n\n\[ \n{\widetilde{H}}_{i}\left( {P}^{{2n} + 1}\right) \simeq \left\{ \begin{array}{ll} \mathbf{Z}/2 & \text{ if }i\text{ is odd and }0 < i < {2n} + 1, \\ \mathbf{Z} & \text{ if }i = {2n} + 1, \\ 0 & \text{ otherwise. } \end{array}\right. \]\n\n\[ \n{\widet...
Proof. The cellular chain group \( {D}_{i}\left( {P}^{\infty }\right) \) is infinite cyclic for \( i \geq 0 \), and the augmented chain complex has the form\n\n\[ \n: \rightarrow {D}_{2i}\left( {P}^{\infty }\right) \overset{2}{ \rightarrow }{D}_{{2i} - 1}\left( {P}^{\infty }\right) \overset{0}{ \rightarrow }\cdots \ove...
Yes
Lemma 40.7. The spaces \( {S}^{n} \) and \( {P}^{n} \) may be triangulated so that the antipodal map \( a : {S}^{n} \rightarrow {S}^{n} \) and the projection map \( p : {S}^{n} \rightarrow {P}^{n} \) are simplicial.
Proof. Step 1. We show first there is a complex \( L \) in \( {\mathbf{R}}^{n + 1} \) such that each reflection map\n\n\[ \n{\rho }_{i}\left( {{x}_{1},\ldots ,{x}_{i},\ldots ,{x}_{n + 1}}\right) = \left( {{x}_{1},\ldots , - {x}_{i},\ldots ,{x}_{n + 1}}\right) \n\] \ninduces a linear isomorphism of \( L \) with itself; ...
Yes
Theorem 40.8. The space \( L\left( {n, k}\right) \) is a CW complex with one cell in each dimension \( 0,1,2,3 \) .
Proof. We first show that the quotient map \( p \) is closed, so that \( L\left( {n, k}\right) \) is Hausdorff (in fact, normal). Let \( A \) be closed in \( {B}^{3} \) . The saturation \( {p}^{-1}p\left( A\right) \) of \( A \) is the union of the set \( A \), the following subsets of \( {S}^{2} \) :\n\n\[ f\left( {{E}...
Yes
Theorem 41.1. Let \( f \) be a homomorphism; let \( \widetilde{f} \) be the dual homomorphism.\n\n(c): If \( f \) is surjective, then \( \widetilde{f} \) is injective. That is, exactness of\n\n\[ B\overset{f}{ \rightarrow }C \rightarrow 0 \]\n\nimplies exactness of\n\n\[ \operatorname{Hom}\left( {B, G}\right) \overset{...
Proof. (a) and (b) are immediate. To prove (c), suppose \( f \) is surjective. Let \( \psi \in \operatorname{Hom}\left( {C, G}\right) \) and suppose \( \widetilde{f}\left( \psi \right) = 0 = \psi \circ f \) . Then \( \psi \left( {f\left( b\right) }\right) = 0 \) for every \( b \in B \) . As \( b \) ranges over \( B \),...
Yes
Theorem 41.2. If the sequence\n\n\\( {x}^{\prime } = 1 \\)\n\\[ \nA\\overset{f}{ \\rightarrow }B\\overset{g.}{ \\rightarrow }C \\rightarrow 0 \n\\]\nM\n\nis exact, then the dual sequence\n\n\\[ \n\\operatorname{Hom}\\left( {A, G}\\right) \\overset{\\widetilde{f}}{ \\leftarrow }\\operatorname{Hom}\\left( {B, G}\\right) ...
Proof. Injectivity of \\( \\widetilde{g} \\) follows from the preceding theorem. We check exactness at \\( \\operatorname{Hom}\\left( {B, G}\\right) \\) . Because \\( h = g \\circ f \\) is the zero homomorphism, so is \\( \\widetilde{h} = \\widetilde{f} \\circ \\widetilde{g} \\) . On the other hand, supposing \\( \\wid...
Yes
Theorem 41.3. (a) One has the following isomorphisms:\n\n\[ \n\operatorname{Hom}\left( {{ \oplus }_{\alpha \in J}{A}_{\alpha }, G}\right) \simeq {\Pi }_{\alpha \in J}\operatorname{Hom}\left( {{A}_{\alpha }, G}\right) ,\n\]\n\n\[ \n\operatorname{Hom}\left( {A,{\Pi }_{\alpha \in J}{G}_{\alpha }}\right) \cong {\Pi }_{\alp...
Proof: Property (a) follows immediately from standard facts of algebra concerning homomorphisms of products.
No
Consider the complex \( K \) pictured in Figure 42.1. Let us compute the coboundaries of a few cochains. Let \( \left\{ {v}_{i}\right\} \) denote the set of vertices; let \( \left\{ {e}_{i}\right\} \) denote the edges, oriented as indicated; let \( \left\{ {\sigma }_{i}\right\} \) denote the 2-simplices, oriented as in...
\[ \delta {e}_{5}^{ * } = {\sigma }_{1}^{ * } - {\sigma }_{2}^{ * } \]
Yes
Consider the complex \( K \) pictured in Figure 42.3. We compute its cohomology groups. The general 0-cochain is a sum of the form \( {c}^{0} = \sum {n}_{i}{v}_{i}^{ * } \) . Since \( \left\langle {\delta {c}^{0},{e}_{i}}\right\rangle = \left\langle {{c}^{0},\partial {e}_{i}}\right\rangle \), we see that \( \delta {c}^...
Now let \( {c}^{1} \) be a 1-cochain; it is a cocycle, trivially. We show that \( {c}^{1} \) is cohomol-ogous to some multiple of \( {e}_{1}^{ * } \) . It suffices to show that \( {e}_{i}^{ * } \) is cohomologous to \( {e}_{1}^{ * } \) for each \( i \), and this can be done directly. For instance; \( {e}_{3}^{ * } \) i...
Yes
Let \( S \) denote the Klein bottle, represented by the labelled rectangle of Figure 42.4. We show that \( {H}^{2}\left( S\right) \) is nontrivial, whereas we know that \( {H}_{2}\left( S\right) = 0 \) .
Orient the 2-simplices of \( L \) counterclockwise. Use the induced orientation of the 2-simplices of \( S \), and let \( \gamma \) denote their sum. Now \( \gamma \) is not a cycle, because \( \partial \gamma = 2{z}_{1} \) , where \( {z}_{1} = \left\lbrack {a, d}\right\rbrack + \left\lbrack {d, e}\right\rbrack + \left...
Yes
Theorem 42.1. Let \( K \) be a complex. Then \( {H}^{ \circ }\left( {K;G}\right) \) equals the group of all 0 -cochains \( {c}^{0} \) such that \( \left\langle {{c}^{0}, v}\right\rangle = \left\langle {{c}^{0}, w}\right\rangle \) whenever \( v \) and \( w \) belong to the same component of \( \left| K\right| \) .
Proof. Note that \( {H}^{0}\left( {K;G}\right) \) equals the group of 0 -cocycles, because there are no coboundaries in dimension 0 . If \( v \) and \( w \) belong to the same component of \( \left\lbrack K\right\rbrack \), then there is a 1-chain \( {c}_{1} \) of \( K \) such that \( \partial {c}_{1} = v - w \) . Then...
Yes
Theorem 42.2. If \( \left| K\right| \) is connected, then \( {\widetilde{H}}^{0}\left( {K;G}\right) = 0 \) . More generally, for any complex \( K \) ,\n\n\[ \n{H}^{0}\left( {K;G}\right) \cong {\widetilde{H}}^{0}\left( {K;G}\right) \oplus G.\n\]
Proof. If \( \left| K\right| \) is connected, then \( {\widetilde{H}}_{0}\left( K\right) \) vanishes, so \( {C}_{1}\left( K\right) \rightarrow {C}_{0}\left( K\right) \rightarrow \) \( \mathbf{Z} \rightarrow 0 \) is exact. It follows that\n\n\[ \n{C}^{1}\left( {K;G}\right) \leftarrow {C}^{0}\left( {K;G}\right) \leftarro...
No
Theorem 43.1. Let \( K \) be a complex; let \( {K}_{0} \) be a subcomplex. There exists an exact sequence \[ \cdots \leftarrow {H}^{p}\left( {{K}_{0};G}\right) \leftarrow {H}^{p}\left( {K;G}\right) \leftarrow {H}^{p}\left( {K,{K}_{0};G}\right) \overset{{\delta }^{ * }}{ \leftarrow }{H}^{p - 1}\left( {{K}_{0};G}\right) ...
Proof. This theorem follows from applying the zig-zag lemma to the diagram ![dda81674-cb4b-472c-ab45-673c29afe7d0_269_0.jpg](images/dda81674-cb4b-472c-ab45-673c29afe7d0_269_0.jpg) Since \( i \) and \( j \) commute with \( \theta \), the dual maps \( \widetilde{i} \) and \( \widetilde{j} \) commute with \( \delta \) . T...
Yes
Consider the case of a square \( K \) modulo its boundary \( {K}_{0} \), as pictured in Figure 43.1. We treat the group of relative cochains as those cochains of \( K \) that are carried by \( K - {K}_{0} \). Both \( {\sigma }_{1}^{ * } \) and \( {\sigma }_{2}^{ * } \) are such cochains, and each is a cocycle (triviall...
\[ \delta {e}_{5}^{ * } = {\sigma }_{1}^{ * } - {\sigma }_{2}^{ * } \] Thus the group \( {H}^{2}\left( {K,{K}_{0}}\right) \) is infinite cyclic, and is generated by the cohomology class \( \left\{ {\sigma }_{1}^{ * }\right\} = \left\{ {\sigma }_{2}^{ * }\right\} \).
Yes
Consider the Möbius band \( M \) modulo its edge \( E \), as pictured in Figure 43.2. We calculate the cohomology of \( \left( {M, E}\right) \) and of \( M \) .
Each of the cochains \( {\sigma }_{i}^{ * } \) is a cocycle (trivially), so they form a basis for the group \( {Z}^{2}\left( {M, E}\right) \) of relative 2-cocycles. Similarly, \( {e}_{1}^{ * },\ldots ,{e}_{6}^{ * } \) form a basis for the group \( {C}^{1}\left( {M, E}\right) \) of relative 1-cochains. (The other 1-sim...
Yes
Theorem 44.1. Let \( \mathcal{C} \) and \( {\mathcal{C}}^{\prime } \) be chain complexes; let \( \phi : \mathcal{C} \rightarrow {\mathcal{C}}^{\prime } \) be \( a \) chain equivalence. Then \( {\phi }_{ * } \) and \( {\phi }^{ * } \) are isomorphisms of homology and cohomology, respectively. If \( \mathcal{O} \) and \(...
Proof. Since \( \phi \) is a chain equivalence, there is a chain map \( \psi : {\mathcal{C}}^{\prime } \rightarrow \mathcal{C} \) such that \( \phi \circ \psi \) and \( \psi \circ \phi \) are chain homotopic to identity maps. Then \( \widetilde{\psi } \circ \widetilde{\phi } \) and \( \widetilde{\phi } \circ \widetilde...
Yes
Theorem 44.2. Let \( \left( {K,{K}_{0}}\right) \) be a simplicial pair. Then \( \eta \) induces a cohomology isomorphism\n\n\[ \n{H}^{p}\left( {\mathcal{C}\left( {K,{K}_{0}}\right) ;G}\right) \overset{{\eta }^{ * }}{ \leftarrow }{H}^{p}\left( {\mathcal{S}\left( {\left| K\right| ,\left| {K}_{0}\right| }\right) ;G}\right...
Proof. The chain map \( \eta \) carries the oriented simplex \( \left\lbrack {{v}_{0},\ldots ,{v}_{p}}\right\rbrack \) of \( K \) to the linear singular simplex \( l\left( {{v}_{0},\ldots ,{v}_{p}}\right) \) of \( K \), provided \( {v}_{0} < \ldots < {v}_{p} \) in the chosen ordering. Because the chain complexes involv...
Yes
Theorem 45.1. Let \( \mathcal{C} \) and \( {\mathcal{C}}^{\prime } \) be free chain complexes. If \( \gamma : {H}_{\rho }\left( \mathcal{C}\right) \rightarrow \) \( {H}_{p}\left( {\mathcal{C}}^{\prime }\right) \) is a homomorphism defined for all \( p \), then there is a chain map \( \phi : \mathcal{C} \rightarrow {\ma...
Indeed, if \( \beta : {Z}_{\rho } \rightarrow {Z}_{\rho }^{\prime } \) is any homomorphism of cycle groups inducing \( \gamma \) , then \( \beta \) extends to a chain map \( \phi \) .\n\nProof. Let \( {Z}_{p} \) denote the \( p \) -cycles, and \( {B}_{p} \), the \( p \) -boundaries, in the chain complex \( \mathcal{C} ...
Yes
Corollary 45.2. Suppose \( \{ \mathcal{O},\epsilon \} \) and \( \left\{ {{\mathcal{C}}^{\prime },{\epsilon }^{\prime }}\right\} \) are free augmented chain complexes. If \( \gamma : {\widetilde{H}}_{p}\left( \mathcal{O}\right) \rightarrow {\widetilde{H}}_{p}\left( {\mathcal{O}}^{\prime }\right) \) is a homomorphism def...
Proof. Consider the augmented chain complexes obtained from \( \mathcal{C} \) and \( {\mathcal{C}}^{\prime } \) ; they have \( \mathbf{Z} \) as their \( \left( {-1}\right) \) -dimensional groups and \( \epsilon ,{\epsilon }^{\prime } \), respectively, as the boundary operators from dimension 0 to dimension -1 . We defi...
Yes
Lemma 45.3. Let\n\n\[ 0 \rightarrow \mathcal{C}\overset{\phi }{ \rightarrow }\mathcal{D} \rightarrow \mathcal{E} \rightarrow 0 \]\n\nbe an exact sequence of free chain complexes. If \( \phi \) induces homology isomorphisms in all dimensions, it induces cohomology isomorphisms as well.
Proof. The existence of the long exact sequence in homology and the fact that \( {\phi }_{ * } \) is an isomorphism imply that \( {H}_{p}\left( \mathcal{E}\right) = 0 \) for all \( p \) . To prove that \( {\phi }^{ * } \) is an isomorphism, it suffices to show that \( {H}^{p}\left( {\mathcal{E};G}\right) = 0 \) for all...
Yes
Lemma 45.4. Let \( \mathcal{C} \) and \( \mathcal{D} \) be free chain complexes; let \( \phi : \mathcal{C} \rightarrow \mathcal{D} \) be a chain map. There is a free chain complex \( {\mathcal{D}}^{\prime } \) and injective chain maps \( i : \mathcal{C} \rightarrow {\mathcal{D}}^{\prime } \) and \( j : \mathcal{D} \rig...
Proof. The definition of \( {\mathcal{D}}^{\prime } \) is one we shall simply \
No
Theorem 45.5. Let \( \mathcal{O} \) and \( \mathcal{D} \) be free chain complexes; let \( \phi : \mathcal{O} \rightarrow \mathcal{D} \) be a chain map. If \( \phi \) induces homology isomorphisms in all dimensions, then \( \phi \) induces cohomology isomorphisms in all dimensions.
Proof. Given \( \phi \), let \( i : \mathcal{O} \rightarrow {\mathcal{D}}^{\prime } \) and \( j : \mathcal{D} \rightarrow {\mathcal{D}}^{\prime } \) be as in the preceding lemma. One has exact sequences of free chain complexes\n\n\[ 0 \rightarrow \mathcal{C}\overset{i}{ \rightarrow }{\mathcal{D}}^{\prime } \rightarrow ...
Yes
Lemma 45.7. Let \( \mathcal{C} \) be a free chain complex. Then there is a natural exact sequence\n\n\[ 0 \leftarrow \operatorname{Hom}\left( {{H}_{\rho }\left( \mathcal{O}\right), G}\right) \overset{\kappa }{ \leftarrow }{H}^{\rho }\left( {\mathcal{O};G}\right) \leftarrow \ker \kappa \leftarrow 0.\n\]\nIt splits, but ...
Proof. We shall construct a homomorphism\n\n\[ {\lambda }^{ * } : \operatorname{Hom}\left( {{H}_{p}\left( \mathcal{C}\right), G}\right) \rightarrow {H}^{p}\left( {\mathcal{C};G}\right)\n\]\n\nsuch that \( \kappa \circ {\lambda }^{ * } \) is the identity. It follows that \( \kappa \) is surjective and that the sequence ...
Yes
Theorem 45.8. Let \( \mathcal{O} \) be a free chain complex. If \( {H}_{p}\left( \mathcal{O}\right) \) is free for all \( p \) , then \( k \) .is an isomorphism for all \( p \) .
Proof. Let \( \lambda : \mathcal{C} \rightarrow \mathcal{E} \) be as in the preceding lemma. Since the homology of \( \mathcal{O} \) is: free, \( \mathcal{E} \) is a free chain complex and Theorem 45.5 applies. Since the chain map \( \lambda : \mathcal{O} \rightarrow \mathcal{E} \) induces homology isomorphisms \( {\la...
Yes
Lemma 46.1. Let \( \mathcal{E} \) and \( \mathcal{F} \) be non-negative chain complexes. Suppose \( {E}_{p} \) is free for \( p > 0 \) and \( {H}_{p}\left( \mathcal{F}\right) = 0 \) for \( p > 0 \) . Then any two chain maps \( f, g : \mathcal{E} \rightarrow \mathcal{F} \) that agree in dimension 0 are chain homotopic.
Proof. Define \( D : {E}_{0} \rightarrow {F}_{1} \) to be zero. Then the equation \( \partial D + D\partial = \) \( g - f \) holds in dimension 0, because \( g = f \) in dimension 0 . Suppose \( D \) is defined in dimension \( p - 1 \), where \( p > 0 \) . Choose a basis for \( {E}_{p} \) . If \( e \) is a basis elemen...
Yes
Theorem 46.2. Let \( \mathcal{C} \) and \( \mathcal{D} \) be free chain complexes that vanish below a certain dimension; let \( \phi : \mathcal{O} \rightarrow \mathcal{D} \) be a chain map. If \( \phi \) induces homology isomorphisms in all dimensions, then \( \phi \) is a chain equivalence.
Proof. We return to the chain complex \( {\mathcal{D}}^{\prime } \) defined in the proof of Lemma 45.4 The inclusion mapping\n\n\[ i : {C}_{p} \rightarrow {D}_{p}^{\prime } = {C}_{p} \oplus {D}_{p} \oplus {C}_{p - 1} \]\n\nis chain homotopic to \( j \circ \phi \), where \( j : {D}_{p} \rightarrow {D}_{p}^{\prime } \) i...
Yes
Theorem 47.1. Let \( X \) be a \( {CW} \) complex; let \( \mathcal{D}\left( X\right) \) be its cellular chain complex. Then\n\n\[ \n{H}^{p}\left( {\mathcal{D}\left( X\right) ;G}\right) \simeq {H}^{p}\left( {X;G}\right) \n\]\n\nfor all p*and \( G \) . If \( X \) is a triangulable \( {CW} \) complex, triangulated by a co...
Proof. Both \( \mathcal{D}\left( X\right) \) and \( \mathcal{S}\left( X\right) \) are free chain complexes. Since their homology groups are isomorphic, so are their cohomology groups, by Corollary 45.6. In the case where \( X \) is triangulable, the inclusion map \( i : \mathcal{D}\left( X\right) \rightarrow \mathcal{O...
Yes
Corollary 47.2. Let \( n > 0 \) . Then\n\n\[ \n{H}^{i}\left( {{S}^{n};G}\right) \simeq G\text{ for }i = 0\text{ and }i = n,\n\]\n\n\[ \n{H}^{i}\left( {{B}^{n},{S}^{n - 1};G}\right) \simeq G\text{for}i = n.\n\]\n\nThese cohomology groups vanish for other values of \( i \) .
Proof. The first statement follows from the fact that the cellular chain complex of \( {S}^{n} \) is infinite cyclic in dimensions 0 and \( n \) and vanishes otherwise, and all the boundary operators vanish. The second then follows from the long exact sequence in reduced cohomology, using the fact that the reduced coho...
Yes
Let \( X \) denote either the torus \( T \) or the Klein bottle \( S \), expressed as a CW complex having one open cell in dimension 2, two in dimension 1, and one in dimension 0 . We computed the cellular chain complex of \( X \), in Example 2 of \( §{39} \), to be of the form\n\n\[ \cdots \rightarrow 0 \rightarrow \m...
Let \( \gamma \) generate \( {D}_{2}\left( X\right) \) ; let \( {w}_{1} \) and \( {z}_{1} \) be a basis for \( {D}_{1}\left( X\right) \) . We know \( {\partial }_{2} \) and \( {\partial }_{1} \) vanish in the case of the torus. Passing to the dual sequence, we compute\n\n\[ {H}^{2}\left( {T;G}\right) \simeq G,\;{H}^{1}...
Yes
Generators for the cohomology of the torus. We represent \( T \) as a quotient, space of the rectangle, as in the preceding example. Let \( {w}_{1} \) and \( {z}_{1} \) be as in that example. The cochains \( {w}^{1} \) and \( {z}^{1} \) pictured in Figure 47.2 are cocycles of \( T \), by direct computation.
Furthermore, when evaluated on the cycles \( {w}_{1} \) and \( {z}_{1} \) that generate \( {D}_{1}\left( X\right) \), we have \[ \left\langle {{w}^{1},{w}_{1}}\right\rangle = 1\;\text{ and }\;\left\langle {{w}^{1},{z}_{1}}\right\rangle = 0, \] \[ \left\langle {{z}^{1},{w}_{1}}\right\rangle = 0\;\text{ and }\;\left\lang...
Yes
Generators for the cohomology of the Klein bottle, with integer coefficients. We follow the pattern of the preceding example. Switch the labels \( d \) and \( \dot{e} \) on the right side of the rectangles in Figure 47.2 so they represent the Klein bottle. Then \( {w}^{1} \) still represents a cocycle; it generates \( ...
(More generally, the cochain \( \sum {n}_{i}{\sigma }_{i}^{ * } \) represents the non-zero element of \( {H}^{2}\left( S\right) \) if and only if \( \sum {n}_{i} \) is odd.)
No
Generators for the cohomology of the Klein bottle, with \( \mathbf{Z}/2 \) coefficients. The cohomology groups are given by \[ {H}^{2}\left( {S;\mathbf{Z}/2}\right) \cong \mathbf{Z}/2,\;{H}^{\prime }\left( {S;\mathbf{Z}/2}\right) \cong \mathbf{Z}/2 \oplus \mathbf{Z}/2,\;{H}^{ \circ }\left( {S;\mathbf{Z}/2}\right) \cong...
The pattern of the preceding argument applies to show that the cochains \( {w}^{1} \) and \( {z}^{1} \) of Figure 47.2 generate the 1-dimensional cohomology. (You can erase the arrows if you like, since \( 1 = - 1 \) in the group \( \mathbf{Z}/2 \) . Thus there is no problem in making \( {z}^{1} \) a cocycle.) The coch...
No
The cohomology of \( {P}^{2} \) with \( \mathbf{Z}/2 \) coefficients. One has\n\n\[ \n{H}^{i}\left( {{P}^{2};\mathbf{Z}/2}\right) \simeq \mathbf{Z}/2\;\text{ for }\;i = 0,1,2.\n\]
If \( \sigma \) is a 2-simplex, the cochain \( {\sigma }^{ * } \) generates the 2-dimensional group. And the co-\ncycle pictured in Figure 47.3 generates \( {H}^{1}\left( {{P}^{2};\mathbf{Z}/2}\right) \), for its value is 1 on the cycle\n\n\[ \n\left\lbrack {a, b}\right\rbrack + \left\lbrack {b, c}\right\rbrack + \left...
Yes
Now suppose \( A \) is an additive group and \( R \) is a commutative ring with unity. We say \( A \) has the structure of module over \( R \) if there is a binary operation \( {}^{ \circ }R \times A \rightarrow A \) (written as scalar multiplication) such that for \( \alpha ,\beta \in R \) and \( a, b \in A \), we hav...
(1) \( \alpha \left( {a + b}\right) = {\alpha a} + {\alpha b} \). (2) \( \left( {\alpha + \beta }\right) a = {\alpha a} + {\beta a} \). (3) \( \alpha \left( {\beta a}\right) = \left( {\alpha \cdot \beta }\right) a \). (4) \( {1a} = a \).
Yes
Given \( R \), it can always be considered as an \( R \) -module over itself. More generally, the cartesian product \( {R}^{n} \) becomes an \( R \) -module if we define
\[ \alpha \left( {{\beta }_{1},\ldots ,{\beta }_{n}}\right) = \left( {\alpha {\beta }_{1},\ldots ,\alpha {\beta }_{n}}\right) . \]
Yes
Theorem 48.1. Cup product of cochains is bilinear and associative. The cochain \( {z}^{0} \) whose value is 1 on each singular 0 -simplex acts as a unity element. Furthermore, the following coboundary formula holds:\n\n(*) \n\n\[ \delta \left( {{c}^{p} \cup {c}^{q}}\right) = \left( {\delta {c}^{p}}\right) \cup {c}^{q} ...
Proof. Bilinearity is immediate, since two cochains are added by adding their values, and multiplication in \( R \) is distributive. Associativity is also immediate; the value of \( \left( {{c}^{p} \cup {c}^{q}}\right) \cup {c}^{r} \) on \( T : {\Delta }_{p + q + r} \rightarrow X \) equals the product of \n\n\[ \left\l...
Yes
Theorem 48.2. The cochain cup product induces an operation\n\n\[ \n{H}^{p}\left( {X;R}\right) \times {H}^{q}\left( {X;R}\right) \overset{ \cup }{ \rightarrow }{H}^{p + q}\left( {X;R}\right) \n\]\n\nthat is bilinear and associative. The cohomology class \( \left\{ {z}^{0}\right\} \) acts as a unity element.
Proof. If \( {z}^{p} \) and \( {z}^{q} \) are cocycles, then their cup product is a cocycle as weli, since\n\n\[ \n\delta \left( {{z}^{p} \cup {z}^{q}}\right) = \delta {z}^{p} \cup {z}^{q} + {\left( -1\right) }^{p}{z}^{p} \cup \delta {z}^{q} = 0. \n\]\n\nThe cohomology class of this product depends only on the cohomolo...
Yes
Theorem 49.1. Given an ordering of the vertices of \( K \), the corresponding simplicial cup product is bilinear and associative. The cochain \( {z}^{0} \) whose value is 1 on each vertex of \( K \) acts as a unity element. The coboundary formula \( \left( *\right) \) of Theorem 48.1 holds. If \( \eta : {C}_{p}\left( K...
Proof. The proofs are straightforward. Only the coboundary formula requires comment. One can prove it by the same computations we used in proving Theorem 48.1; only slight changes of notation are needed. Alternatively, one can use the fact that since \( \eta \) carries basis elements to basis elements, \( \eta \) is in...
No
Theorem 49.2. The simplicial cup product induces an operation\n\n\[ \n{H}^{p}\left( {K;R}\right) \times {H}^{q}\left( {K;R}\right) \hookrightarrow {H}^{p + q}\left( {K;R}\right) \]\nthat is bilinear and associative. It is independent of the ordering of vertices of \( K \) . The cohomology class \( \left\{ {z}^{0}\right...
Proof. The existence of \( \cup \) follows from the coboundary formula as before. The chain map \( \eta \) induces an isomorphism \( {\eta }^{ * } \) of singular with simplicial cohomology that preserves cup products. Since \( {\eta }^{ * } \) is independent of the chosen ordering in \( K \), so is the cup product in s...
Yes
Consider the torus \( T \) . Let \( {w}^{1} \) and \( {z}^{1} \) denote the cocycles pictured in Figure 49.1. We know that \( \alpha = \left\{ {w}^{t}\right\} \) and \( \beta = \left\{ {z}^{t}\right\} \) generate \( {H}^{t}\left( T\right) \) . If we orient each 2-simplex counterclockwise, then \( \Lambda = \left\{ {\si...
Order the vertices of \( T \) alphabetically. Using this ordering, we compute the \( \cdots \) value of \( {w}^{1} \cup {z}^{1} \) on each oriented 2 -simplex \( \sigma \) . Note that \( \left\langle {{w}^{1} \cup {z}^{1},\sigma }\right\rangle = 0 \) unless a face of \( \sigma \) is in the carrier of \( {w}^{1} \) and ...
Yes
Consider now the Klein bottle \( S \) . Let us compute the cohomology ring with \( \mathbf{Z}/2 \) coefficients. We know that \( {H}^{1}\left( {S;\mathbf{Z}/2}\right) \) is generated by the cocycles \( {w}^{1} \) and \( {z}^{1} \) pictured in Figure 49.3. Furthermore, \( {H}^{2}\left( {S;\mathbf{Z}/2}\right) \) is gene...
Some of the computations we carried out in Example 1 apply without change, provided we reduce the coefficients modulo 2 . In particular,\n\n\[ \n{w}^{1} \cup {z}^{1} = {\left\lbrack g, h, i\right\rbrack }^{ * },\text{ and } \n\]\n\n\[ \n{w}^{1} \cup {y}^{1} = 0 \n\]\n\nwhere \( {y}^{1} \) is the cochain pictured in Fig...
Yes
Consider the connected sum \( {P}^{2}\# {P}^{2} \) . We compute its cohomology ring with \( \mathbf{Z}/2 \) coefficients.
Let us express \( {P}^{2}\# {P}^{2} \) as a CW complex \( X \) having one cell in dimension 0 , one cell in dimension 2 , and two cells in dimension 1 . See Figure 49.4. Fundamental cycles for the 1-cells of \( X \) are \[ {w}^{1} = \left\lbrack {a, b}\right\rbrack + \left\lbrack {b, c}\right\rbrack + \left\lbrack {c, ...
Yes
Example 4. Consider the space \( X \) pictured in Figure 49.5; it is the union of two topological circles and a topological 2-sphere with a point in common. It is called the wedge product \( {S}^{1} \vee {S}^{1} \vee {S}^{2} \) . The space \( X \) can be expressed as a CW complex with one cell in dimension 0 , one cell...
It follows that the homology groups and cohomology groups of \( X \) are isomorphic to those of \( T \) . However, their cohomology rings are not isomorphic. For it is easy to see that the cohomology ring of \( X \) is trivial. Consider the cocycles\n\n\[ \n{w}^{\\prime } = {\\left\\lbrack b, c\\right\\rbrack }^{ * }\\...
Yes
Theorem 50.2. There is an isomorphism\n\n\[ \n\mathbf{Z} \otimes G \cong G \n\]\n\nthat maps \( n \otimes g \) to \( {ng} \) ; it is natural with respect to homomorphisms of \( G \) .
Proof. The function mapping \( \mathbf{Z} \times G \) to \( G \) that sends \( \left( {n, g}\right) \) to \( {ng} \) is bilinear, so it induces a homomorphism \( \phi : \mathbf{Z} \otimes G \rightarrow G \) sending \( n \otimes g \) to \( {ng} \) .\n\nLet \( \psi : G \rightarrow \mathbf{Z} \otimes G \) be defined by th...
Yes
Lemma 50.3. Suppose the homomorphisms \( \phi : B \rightarrow C \) and \( {\phi }^{\prime } : {B}^{\prime } \rightarrow {C}^{\prime } \) are surjective. Then\n\n\[ \phi \otimes {\phi }^{\prime } : B \otimes {B}^{\prime } \rightarrow C \otimes {C}^{\prime } \]\n\n is surjective, and its kernel is the subgroup of \( B \o...
Proof. Let \( G \) denote the subgroup of \( B \otimes {B}^{\prime } \) generated by these elements \( b \otimes {b}^{\prime } \) . Clearly \( \phi \otimes {\phi }^{\prime } \) maps \( G \) to zero, so it induces a homomorphism\n\n\[ \Phi : \left( {B \otimes {B}^{\prime }}\right) /G \rightarrow C \otimes {C}^{\prime }....
Yes
Theorem 50.4. Suppose the sequence\n\n\[ A\overset{\phi }{ \rightarrow }B\overset{\psi }{ \rightarrow }C \rightarrow 0 \]\n\nis exact. Then the sequence\n\n\[ A \otimes G\xrightarrow[]{\phi \otimes {i}_{G}}B \otimes G\xrightarrow[]{\psi \otimes {i}_{G}}C \otimes G \rightarrow 0 \]\n\nis exact. If \( \phi \) is injectiv...
Proof. The preceding lemma implies that \( \psi \otimes {i}_{G} \) is surjective, and that its kernel is the subgroup \( D \) of \( B \otimes G \) generated by all elements of the form \( b \otimes g \) for \( b \in k \) ker \( \psi \) . The image of \( \phi \otimes {i}_{G} \) is the subgroup \( E \) generated by all e...
Yes
Corollary 50.5. There is a natural isomorphism\n\n\[ \mathbf{Z}/m \otimes G \cong G/{mG}. \]
Proof. We take the exact sequence\n\n\[ 0 \rightarrow \mathbf{Z}\overset{m}{ \rightarrow }\mathbf{Z} \rightarrow \mathbf{Z}/m \rightarrow 0 \]\n\nand tensor it with \( G \), obtaining the exact sequence\n\n\[ \mathbf{Z} \otimes G\xrightarrow[]{m \otimes {i}_{G}}\mathbf{Z} \otimes G \rightarrow \mathbf{Z}/m \otimes G \r...
Yes
Theorem 50.6. One has the following natural isomorphisms:\n\n(a) \( A \otimes B \cong B \otimes A \) .
(a) The map \( A \times B \rightarrow B \times A \) sending \( \left( {a, b}\right) \) to \( \left( {b, a}\right) \) induces an isomorphism of \( F\left( {A, B}\right) \) with \( F\left( {B, A}\right) \) that carries \( R\left( {A, B}\right) \) onto \( R\left( {B, A}\right) \) .
Yes
Theorem 50.8. If \( A \) is free abelian with basis \( \left\{ {a}_{i}\right\} \) and \( B \) is free abelian with basis \( \left\{ {b}_{j}\right\} \), then \( A \otimes B \) is free abelian with basis \( \left\{ {{a}_{i} \otimes {b}_{j}}\right\} \) .
Proof. Let \( \left\langle {a}_{i}\right\rangle \) and \( \left\langle {b}_{j}\right\rangle \) denote the infinite cyclic subgroups of \( A \) and \( B \) generated by \( {a}_{i} \) and \( {b}_{j} \), respectively. Then\n\n\[ A = \oplus \left\langle {a}_{i}\right\rangle \;\text{ and }\;B = \oplus \left\langle {b}_{j}\r...
Yes
Theorem 51.1. Let \( \mathcal{C} \) and \( \mathcal{D} \) be free chain complexes. If the chain map \( \phi : \mathcal{O} \rightarrow \mathcal{D} \) induces homology isomorphisms in all dimensions, so does the chain map\n\n\[ \phi \otimes {i}_{G} : \mathcal{C} \otimes G \rightarrow \mathcal{D} \otimes G. \]
Proof. Step 1. We first consider the case where we have a short exact sequence\n\n\[ 0 \rightarrow \mathcal{C} \rightarrow \mathcal{D} \rightarrow \mathcal{E} \rightarrow 0 \]\n\nof free chain complexes. We know that \( {H}_{p}\left( \mathcal{E}\right) = 0 \) for all \( p \), and we wish to prove that \( {H}_{p}\left( ...
Yes
Theorem 52.1. There is a function that assigns, to each free resolution\n\n\[ \n0 \rightarrow R\xrightarrow[]{\phi }F\xrightarrow[]{\psi }A \rightarrow 0 \]\n\nof the abelian group \( A \), and to each abelian group \( B \), an exact sequence\n\n\[ \n0 \leftarrow \operatorname{Ext}\left( {A, B}\right) \overset{\pi }{ \...
We shall prove this theorem shortly. It will then be used to derive the other properties of the Ext functor, and to compute it.
No
Lemma 52.2. Suppose one is given a homomorphism\n\n![dda81674-cb4b-472c-ab45-673c29afe7d0_325_0.jpg](images/dda81674-cb4b-472c-ab45-673c29afe7d0_325_0.jpg)\n\nof free resolutions of \( A \) and \( {A}^{\prime } \), respectively, and a homomorphism \( \delta : {B}^{\prime } \rightarrow B \) . Then there is a unique homo...
Proof. Functoriality of Hom shows that the two right squares of the preceding diagram commute. Therefore, \( \operatorname{Hom}\left( {\alpha ,\delta }\right) \) induces a homomorphism \( \epsilon \) of cokernels.\n\nWe show \( \epsilon \) is independent of the choice of \( \alpha \) and \( \beta \) . Suppose \( \left\...
Yes
Theorem 52.3. (a) There are natural isomorphisms\n\n\[ \n\operatorname{Ext}\left( {\oplus {A}_{\alpha }, B}\right) \simeq \Pi \operatorname{Ext}\left( {{A}_{\alpha }, B}\right) ,\n\]\n\n\[ \n\operatorname{Ext}\left( {A,\Pi {B}_{\alpha }}\right) \cong \Pi \operatorname{Ext}\left( {A,{B}_{\alpha }}\right) .\n\]
In the proof, we shall use the fact that direct sums and direct products of exact sequences are exact, and the fact that a direct sum (but not a direct product) of free abelian groups is free abelian.\n\n(a) Let \( 0 \rightarrow {R}_{\alpha } \rightarrow {F}_{\alpha } \rightarrow {A}_{\alpha } \rightarrow 0 \) be a fre...
Yes
Corollary 53.3. Let \( \\mathcal{C} \) and \( \\mathcal{D} \) be free chain complexes; let \( \\phi : \\mathcal{C} \\rightarrow \\mathcal{D} \) be a chain map. If \( {\\phi }_{ * } : {H}_{i}\\left( \\mathcal{O}\\right) \\rightarrow {H}_{i}\\left( \\mathcal{D}\\right) \) is an isomorphism for \( i = p \) and \( i = p - ...
Proof. Apply naturality of the universal coefficient sequence and the Five-lemma.
No
Lemma 53.4. Let \( \mathcal{O} \) be a chain complex. Let\n\n\[ \omega : \operatorname{Hom}\left( {{C}_{p}, F}\right) \rightarrow {\operatorname{Hom}}_{F}\left( {{C}_{p} \otimes F, F}\right) \]\n\nbe defined by the equation\n\n\[ \left\langle {\omega \left( f\right) ,{c}_{p} \otimes \alpha }\right\rangle = \left\langle...
Proof. Strictly speaking, we use the preceding formula to define \( \omega \left( f\right) \) :as a function on the cartesian product \( {C}_{p} \times F \), and note that it is bilinear. To check that \( \omega \left( f\right) \) is a linear transformation, we compute\n\n\[ \left\langle {\omega \left( f\right) ,\alpha...
Yes
Theorem 53.5. Let \( \mathcal{O} \) be a free chain complex; let \( F \) be a field. Then there is a natural vector space isomorphism \[ {\operatorname{Hom}}_{F}\left( {{H}_{p}\left( {\mathcal{O};F}\right), F}\right) \leftarrow {H}^{p}\left( {\mathcal{O};F}\right) . \]
Proof. We imitate the proof of the universal coefficient theorem. First, we note that if \[ 0 \rightarrow A \rightarrow B \rightarrow C \rightarrow 0 \] is a short exact sequence of vector spaces over \( F \) and linear transformations, then for any vector space \( V \) over \( F \), the dual sequence \[ 0 \leftarrow {...
Yes
Corollary 53.6. If \( \left( {X, A}\right) \) is a topological pair, there is a natural vector space isomorphism\n\n\[ \n{\operatorname{Hom}}_{F}\left( {{H}_{p}\left( {X, A;F}\right), F}\right) \leftarrow {H}^{p}\left( {X, A;F}\right) .\n\]
This theorem shows that if \( F \) is a field, then the vector space \( {H}^{p}\left( {X, A;F}\right) \) can be identified in a natural way with the dual vector space of the vector space \( {H}_{p}\left( {X, A;F}\right) \) . In the case where the dimension of \( {H}_{p}\left( {X, A;F}\right) \) is finite, this means th...
Yes
Lemma 54.2. Given a homomorphism of free resolutions\n\n![dda81674-cb4b-472c-ab45-673c29afe7d0_337_0.jpg](images/dda81674-cb4b-472c-ab45-673c29afe7d0_337_0.jpg)\n\nand a homomorphism \( \\delta : B \\rightarrow {B}^{\\prime } \\), there exists a unique homomorphism \( \\epsilon \) making the following diagram commute: ...
Proof. Functoriality of \( \\otimes \) shows the two right-hand squares of the preceding diagram commute. Therefore, \( \\alpha \\otimes \\delta \) induces a homomorphism \( \\epsilon \) of kernels.\n\nThe proof that \( {\\epsilon }^{\\prime } \) is independent of the choice of \( \\alpha \) and \( \\beta \) proceeds a...
Yes
Lemma 54.3. There is a function assigning to each short exact sequence of abelian groups\n\n\[ 0 \rightarrow A \rightarrow B \rightarrow C \rightarrow 0 \]\nand each abelian group \( D \), an exact sequence\n\n\[ 0 \rightarrow D * A \rightarrow D * B \rightarrow D * C \rightarrow D \otimes A \rightarrow D \otimes B \ri...
Proof. This result is analogous to the theorem stated in Exercise 4 of §52. Let\n\n\[ 0 \rightarrow R\overset{\phi }{ \rightarrow }F \rightarrow D \rightarrow 0 \]\n\nbe a free resolution of \( D \) . Because \( R \) and \( F \) are free, we have horizontal exactness in the diagram\n\n\[ 0 \rightarrow R \otimes A \righ...
Yes
Theorem 54.4. (a) There is a natural isomorphism\n\n\[ A * B \cong B * A. \]
(a) Apply the preceding lemma to the free resolution \( 0 \rightarrow R \rightarrow F \rightarrow \) \( A \rightarrow 0 \) of \( A \) . One obtains a six-term exact sequence. The first terms\n\n\[ 0 \rightarrow B * R \rightarrow B * F \]\n\nvanish because \( R \) and \( F \) are torsion-free. What remains is the exact ...
Yes
Theorem 55.1 (The universal coefficient theorem for homology). Let \( \mathcal{C} \) be a free chain complex; let \( G \) be an abelian group. There is an exact sequence\n\n\[ 0 \rightarrow {H}_{p}\left( \mathcal{C}\right) \otimes G \rightarrow {H}_{p}\left( {\mathcal{C};G}\right) \rightarrow {H}_{p - 1}\left( \mathcal...
One can give a direct proof of this theorem that is very similar to the proof of the universal coefficient theorem for cohomology. Instead, we shall postpone the proof, and derive it from a more general theorem called the Künneth theorem, which we shall prove in \( §{58} \) .
No
Corollary 55.3. Let \( \mathcal{C} \) and \( \mathcal{D} \) be free chain complexes; let \( \phi : \mathcal{C} \rightarrow \mathcal{D} \) be a chain map. If \( {\phi }_{ * } : {H}_{i}\left( \mathcal{O}\right) \rightarrow {H}_{i}\left( \mathcal{D}\right) \) is an isomorphism for \( i = p \) and \( i = p - 1 \) , then \n...
Proof. This result follows from naturality of the universal coefficient sequence and the Five-lemma.
No
Theorem 56.2. The preceding theorem holds if the hypothesis that \( \mathcal{C} \) is finitely generated in each dimension is replaced by the hypothesis that @wan-ishes below a certain dimension, and the homology of \( \mathcal{O} \) is finitely generated in each dimension.
To prove this theorem, we need the following lemma:\n\nLemma 56.3. Let \( \mat
No
Lemma 56.3. Let \( \mathcal{C} \) be a free chain complex such that \( {H}_{i}\left( \mathcal{C}\right) \) is finitely generated for each \( i \) . Then there is a free chain complex \( {\mathcal{C}}^{\prime } \) that is finitely generated in each dimension, whose homology is isomorphic to that of \( \mathcal{O} \) . I...
Proof. Let \( {\beta }_{p} \) be the betti number of \( {H}_{p}\left( \mathcal{O}\right) \), and let \( {t}_{1}^{\left( p\right) },\ldots ,{t}_{{k}_{p}}^{\left( p\right) } \) be its torsion coefficients. Let \( {U}_{p},{V}_{p} \), and \( {W}_{p} \) be free abelian groups, where \( {U}_{p} \) has rank \( {k}_{p - 1} \),...
Yes
Lemma 58.1. Let \( \mathcal{C} \) and \( {\mathcal{C}}^{\prime } \) be chain complexes such that in each dimension the cycles form a direct summand in the chains. (This occurs, for instance, when \( Q \) and \( {Q}^{\prime } \) are free.) Then\n\n\[ \Theta : { \oplus }_{\rho + q = m}{H}_{\rho }\left( \mathcal{O}\right)...
Proof. We define a homomorphism \( \lambda \) in the opposite direction to \( \Theta \), such that \( \lambda \circ \theta \) equals the identity. This suffices.\n\nLet \( {Z}_{p} \) denote the group of \( p \) -cycles in \( \mathcal{O} \) ; let \( {Z}_{q}^{\prime } \) denote the \( q \) -cycles in \( {\mathcal{O}}^{\p...
Yes
Corollary 58.3. Let \( \mathcal{O},{\mathcal{O}}^{\prime },\mathcal{D},{\mathcal{D}}^{\prime } \) be chain complexes with \( \mathcal{O} \) and \( \mathcal{D} \) -free; let \( \phi : \mathcal{C} \rightarrow \mathcal{D} \) and \( {\phi }^{\prime } : {\mathcal{C}}^{\prime } \rightarrow {\mathcal{D}}^{\prime } \) be chain...
Proof. We apply naturality of the Künneth sequence, and the Rive-lemma.
No
Let \( K \) and \( L \) be simplicial complexes, with \( K \) or \( L \) locally finite. The results of the preceding section show that the chain complex \( \mathcal{O}\left( K\right) \otimes \mathcal{O}\left( L\right) \) can be used to compute the homology of \( \left| K\right| \times \left| L\right| \) .
Since \( \mathcal{O}\left( K\right) \) and \( \mathcal{O}\left( L\right) \) are free, tie Künneth theorem implies that\n\n\[ \n{H}_{m}\left( {\left| K\right| \times \left| L\right| }\right) \cong { \oplus }_{p + q = m}\left\lbrack {{H}_{p}\left( K\right) \otimes {H}_{q}\left( L\right) \oplus {H}_{p - 1}\left( K\right) ...
Yes
In particular, for the product \( {S}^{r} \times {S}^{s} \), we have\n\n\[ \n{H}_{m}\left( {{S}^{r} \times {S}^{s}}\right) \cong { \oplus }_{p + q = m}{H}_{p}\left( {S}^{r}\right) \otimes {H}_{q}\left( {S}^{s}\right) .\n\]
Hence if \( r \neq s \) ,\n\n\[ \n{H}_{m}\left( {{S}^{r} \times {S}^{s}}\right) \simeq \left\{ \begin{array}{ll} \mathbf{Z} & \text{ if }m = 0, r, s, r + s, \\ 0 & \text{ otherwise. } \end{array}\right.\n\]\n\n\[ \n{H}_{m}\left( {{S}^{r} \times {S}^{r}}\right) \simeq \left\{ \begin{array}{ll} \mathbf{Z} & \text{ if }m ...
Yes
Theorem 58.4. Suppose the chain complexes & and & are vector spaces over the field \( F \), and the boundary operators are vector space homomorphisms. Then \( {H}_{\rho }\left( \mathcal{E}\right) \) and \( {H}_{q}\left( {\mathcal{E}}^{\prime }\right) \) are vector spaces over \( F \), and there is a natural isomorphism...
Proof. The proof of the Künneth theorem proceeds unchanged through its first four steps, if \( \otimes \) is replaced throughout by \( { \otimes }_{F} \) . A change first appears in Step 5, where we take the sequence\n\n\[ \n0 \rightarrow {B}_{p} \rightarrow {Z}_{p} \rightarrow {H}_{p}\left( \mathcal{E}\right) \rightar...
Yes
If \( K \) and \( L \) are simplicial complexes, with \( K \) or \( L \) locally finite, there is a vector space isomorphism\n\n\[ \oplus _{p + q = m}{H}_{p}\left( {K;F}\right) \otimes _{F}{H}_{q}\left( {L;F}\right) \rightarrow {H}_{m}\left( {\left| K\right| \times \left| L\right| ;F}\right) . \]
This fact follows from the preceding theorem, once we note that since for all \( i \) ,\n\n\[ {H}_{i}\left( {\mathcal{C}\left( K\right) \otimes \mathcal{C}\left( L\right) }\right) \simeq {H}_{i}\left( {\left| K\right| \times \left| L\right| }\right) , \]\n\nthe same holds with arbitrary coefficients \( F \), by Theorem...
No
Lemma 59.1. If \( \{ \mathcal{O},\epsilon \} \) and \( \left\{ {{\mathcal{O}}^{\prime },{\epsilon }^{\prime }}\right\} \) are acyclic augmented chain complexes, and if \( \mathcal{C} \) is free, then \( \left\{ {\mathcal{C} \otimes {\mathcal{C}}^{\prime },\bar{\epsilon }}\right\} \) is acyclic.
Proof. We show that \( {H}_{m}\left( {\mathcal{C} \otimes {\mathcal{C}}^{\prime }}\right) \) is infinite cyclic if \( m = 0 \), and vanishes otherwise. This proves that \( \mathcal{O} \otimes {\mathcal{O}}^{\prime } \) is acyclic relative to any augmentation.\n\nWe can apply the Künneth theorem, since \( \mathcal{O} \)...
Yes
Theorem 59.3 (The Künneth theorem for topological spaces). Given topological spaces \( X, Y \), there is an exact sequence\n\n\[ 0 \rightarrow { \oplus }_{p + q = m}{H}_{p}\left( X\right) \otimes {H}_{q}\left( Y\right) \rightarrow {H}_{m}\left( {X \times Y}\right) \rightarrow \]\n\n\[ { \oplus }_{p + q = m}{H}_{p - 1}\...
It is natural with respect to homomorphisms induced by continuous maps. It splits, but not naturally.\n\nThe monomorphism\n\n\[ {H}_{p}\left( X\right) \otimes {H}_{q}\left( Y\right) \rightarrow {H}_{m}\left( {X \times Y}\right) \]\nof this theorem is called the homology cross product. It equals the composite\n\n\[ {H}_...
No
Theorem 59.5. Let \( {\pi }_{1} : X \times Y \rightarrow X \) and \( {\pi }_{2} : X \times Y \rightarrow Y \) be projections. Define\n\n\[ \nu : {S}_{m}\left( {X \times Y}\right) \rightarrow { \oplus }_{p + q = m}{S}_{p}\left( X\right) \otimes {S}_{q}\left( Y\right) \]\n\nby the equation\n\n\[ \nu \left( T\right) = \ma...
Proof. That \( \nu \) is natural and augmentation-preserving is easy to check. The fact that \( \nu \) is a chain map is a straightforward computation, about as messy as such computations usually are. In fact, when one computes directly, one finds that the expression for \( \bar{\partial }\nu \left( T\right) \) equals ...
Yes
Lemma 60.1. The homomorphism \( \theta \) is a natural cochain map.
Proof. Let \( \phi \in \operatorname{Hom}\left( {{C}_{p}, R}\right) \) and \( \psi \in \operatorname{Hom}\left( {{C}_{q}^{\prime }, R}\right) \), where \( p + q = m \) . Let \( r + s = m + 1 \) . We compute\n\n\[ \left\langle {\theta \left( {\bar{\delta }\left( {\phi \otimes \psi }\right) }\right) ,{c}_{r} \otimes {c}_...
Yes
Theorem 60.3 (The Künneth theorem for cohomology). Let \( \mathcal{C} \) and \( {\mathcal{C}}^{\prime } \) be chain complexes that vanish below a certain dimension. Suppose \( \mathcal{O} \) is free and finitely generated in each dimension. Then there is a natural exact sequence\n\n\[ 0 \hookrightarrow {\bigoplus }_{p ...
Proof. Let \( \mathcal{E} \) and \( {\mathcal{E}}^{\prime } \) be the chain complexes whose chain groups in dimen-, sion \( - p \) are defined by the equations\n\n\[ {E}_{-p} = \operatorname{Hom}\left( {{C}_{p},\mathbf{Z}}\right) \;\text{ and }\;{E}_{-p}^{\prime } = \operatorname{Hom}\left( {{C}_{p}^{\prime },\mathbf{Z...
Yes
Corollary 60.4. In the preceding theorem, the hypothesis that @ be finitely generated in each dimension can be replaced by the hypothesis that \( {H}_{i}\left( \mathcal{C}\right) \) be finitely generated for each i. Similarly, the hypothesis that \( {\mathcal{C}}^{\prime } \) be finitely generated in each dimension can...
Proof. The proof is similar to that of Theorem 56.2. If \( \mathcal{O} \) is free and vanishes below a certain dimension, and \( {H}_{i}\left( \mathcal{O}\right) \) is finitely generated for each \( i \), we choose a free chain complex \( \mathcal{D} \) that vanishes below a certain dimension such that \( {H}_{i}\left(...
No
Lemma 61.1. The cochain cross product is given by the formula\n\n\[ \n\\left\\langle {{c}^{p} \\times {c}^{q}, T}\\right\\rangle = \\left\\langle {{c}^{p},{\\pi }_{1} \\circ T \\circ l\\left( {{\\epsilon }_{0},\\ldots ,{\\epsilon }_{p}}\\right) }\\right\\rangle \\cdot \\left\\langle {{c}^{q},{\\pi }_{2} \\circ T \\circ...
This result holds for \( \\left( {\\mathbf{Z}, G}\\right) \) coefficients as well. In words, it says that the value of \( {c}^{p} \\times {c}^{q} \) on \( T \) equals the value of \( {c}^{p} \) on the front face of the first component of \( T \), times the value of \( {c}^{q} \) on the back face of the second component...
No
Theorem 61.2. (a) If \( \lambda : X \times Y \rightarrow Y \times X \) is the map that reverses coordinates, then\n\n\[{\lambda }^{ * }\left( {{\beta }^{q} \times {\alpha }^{p}}\right) = {\left( -1\right) }^{pq}{\alpha }^{p} \times {\beta }^{q}.\]
Proof. (a) Consider the chain maps\n\n\[\\begin{matrix} {\\left( \\mathcal{S}\\left( X\\right) \\otimes \\mathcal{S}\\left( Y\\right) \\right) }_{m} \\leftarrow {S}_{m}\\left( {X \\times Y}\\right) \\\\ {\\left( \\omega \\right) }_{m} \\leftarrow {S}_{m}\\left( {Y \\times X}\\right) , \\end{matrix}\n\nwhere we define \...
No