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Proposition 43.2. If \( A, D \) and both Schur complements \( A - B{D}^{-1}C \) and \( D - C{A}^{-1}B \) are all invertible, then\n\n\[ \n{\left( \begin{array}{ll} A & B \\ C & D \end{array}\right) }^{-1} = \left( \begin{matrix} {\left( A - B{D}^{-1}C\right) }^{-1} & - {A}^{-1}B{\left( D - C{A}^{-1}B\right) }^{-1} \\ -...
If we set \( D = I \) and change \( B \) to \( - B \), we get\n\n\[ \n{\left( A + BC\right) }^{-1} = {A}^{-1} - {A}^{-1}B{\left( I - C{A}^{-1}B\right) }^{-1}C{A}^{-1},\n\]\n\na formula known as the matrix inversion lemma (see Boyd and Vandenberghe [29], Appendix C.4, especially C.4.3).
No
Proposition 43.3. For any symmetric matrix \( M \) of the form\n\n\[ M = \left( \begin{matrix} A & B \\ {B}^{\top } & C \end{matrix}\right) \]\n\nif \( C \) is invertible, then the following properties hold:\n\n(1) \( M \succ 0 \) iff \( C \succ 0 \) and \( A - B{C}^{-1}{B}^{\top } \succ 0 \) .\n\n(2) If \( C \succ 0 \...
Proof. (1) Observe that\n\n\[ {\left( \begin{matrix} I & B{C}^{-1} \\ 0 & I \end{matrix}\right) }^{-1} = \left( \begin{matrix} I & - B{C}^{-1} \\ 0 & I \end{matrix}\right) \]\n\nand we know that for any symmetric matrix \( T \) and any invertible matrix \( N \), the matrix \( T \) is positive definite \( \left( {T \suc...
Yes
Theorem 43.5. Given any symmetric matrix\n\n\[ \nM = \left( \begin{matrix} A & B \\ {B}^{\top } & C \end{matrix}\right) \n\]\n\nthe following conditions are equivalent:\n\n(1) \( M \succcurlyeq 0 \) ( \( M \) is positive semidefinite).\n\n(2) \( A \succcurlyeq 0,\;\left( {I - A{A}^{ + }}\right) B = 0,\;C - {B}^{\top }{...
If \( M \succcurlyeq 0 \) as in Theorem 43.5, then it is easy to check that we have the following factorizations (using the fact that \( {A}^{ + }A{A}^{ + } = {A}^{ + } \) and \( {C}^{ + }C{C}^{ + } = {C}^{ + } \) ):\n\n\[ \n\left( \begin{matrix} A & B \\ {B}^{\top } & C \end{matrix}\right) = \left( \begin{matrix} I & ...
Yes
Proposition 44.2. Every polyhedral cone \( C \) is closed.
Proof. This is proved by showing that\n\n1. Every primitive cone is closed.\n\nAssume that \( \\left( {{a}_{1},\\ldots ,{a}_{m}}\\right) \) are linearly independent vectors in \( {\\mathbb{R}}^{n} \), and consider any sequence \( {\\left( {x}^{\\left( k\\right) }\\right) }_{k \\geq 0} \n\n\\[ \n{x}^{\\left( k\\right) }...
Yes
Example 45.1.\n\n\\[ \n\\text{maximize}{x}_{1} + {x}_{2} \n\\]\n\nsubject to\n\n\\[ \n{x}_{2} - {x}_{1} \\leq 1 \n\\]\n\n\\[ \n{x}_{1} + 6{x}_{2} \\leq {15} \n\\]\n\n\\[ \n4{x}_{1} - {x}_{2} \\leq {10} \n\\]\n\n\\[ \n{x}_{1} \\geq 0,{x}_{2} \\geq 0 \n\\]\n\nand in matrix form\n\n\\[ \n\\text{maximize}\\left( \\begin{ar...
It turns out that \\( {x}_{1} = 3,{x}_{2} = 2 \\) yields the maximum of the objective function \\( {x}_{1} + {x}_{2} \\) , which is 5 . This is illustrated in Figure 45.1. Observe that the set of points that satisfy the above constraints is a convex region cut out by half planes determined by the lines of equations\n\n...
Yes
\[ \text{maximize}{x}_{1} + {x}_{2} \] \[ \text{subject to} \] \[ {x}_{2} - {x}_{1} \leq 1 \] \[ {x}_{1} \geq 0,{x}_{2} \geq 0 \]
Otherwise, we will prove shortly that if \( \mu \) is the least upper bound of the set \( \{ {cx} \in \mathbb{R} \mid \) \( x \in \mathcal{P}\left( {A, b}\right) \} \), then there is some \( p \in \mathcal{P}\left( {A, b}\right) \) such that \[ {cp} = \mu \] that is, the objective function \( x \mapsto {cx} \) has a ma...
No
\[ \mathop{\operatorname{maximize}}\limits_{0}\;\frac{1}{6}{x}_{1} + {x}_{2} \] subject to \[ {x}_{2} - {x}_{1} \leq 1 \] \[ {x}_{1} + 6{x}_{2} \leq {15} \] \[ 4{x}_{1} - {x}_{2} \leq {10} \] \[ {x}_{1} \geq 0,{x}_{2} \geq 0 \]
The proof that if the set \( \{ {cx} \in \mathbb{R} \mid x \in \mathcal{P}\left( {A, b}\right) \} \) is nonempty and bounded above, then there is an optimal solution \( p \in \mathcal{P}\left( {A, b}\right) \), is not as trivial as it might seem. It relies on the fact that a polyhedral cone is closed, a fact that was s...
No
Proposition 45.1. Let \( \left( {P}_{2}\right) \) be a linear program in standard form, with equality constraint \( {Ax} = b \) . If \( \mathcal{P}\left( {A, b}\right) \) is nonempty and bounded above, and if \( \mu \) is the least upper bound of the set \( \{ {cx} \in \mathbb{R} \mid x \in \mathcal{P}\left( {A, b}\rig...
Proof. Since \( \mu = \sup \{ {cx} \in \mathbb{R} \mid x \in \mathcal{P}\left( {A, b}\right) \} \), there is a sequence \( {\left( {x}^{\left( k\right) }\right) }_{k \geq 0} \) of vectors \( {x}^{\left( k\right) } \in \mathcal{P}\left( {A, b}\right) \) such that \( \mathop{\lim }\limits_{{k \mapsto \infty }}c{x}^{\left...
Yes
Proposition 45.2. Given any Standard Linear Program \( \left( {P}_{2}\right) \) where \( {Ax} = b \) and \( A \) is an \( m \times n \) matrix of rank \( m \), for any feasible solution \( x \), if \( {J}_{ > } = \left\{ {j \in \{ 1,\ldots, n\} \mid {x}_{j} > 0}\right\} \), then \( x \) is a basic feasible solution iff...
Proof. If \( x \) is a basic feasible solution, then there is some subset \( K \subseteq \{ 1,\ldots, n\} \) of size \( m \) such that the columns of \( {A}_{K} \) are linearly independent and \( {x}_{j} = 0 \) for all \( j \notin K \), so by definition, \( {J}_{ > } \subseteq K \), which implies that the columns of th...
Yes
Theorem 45.4. Let \( \left( {P}_{2}\right) \) be any standard linear program with objective function \( {cx} \), where \( {Ax} = b \) and \( A \) is an \( m \times n \) matrix of rank \( m \) . If \( \left( {P}_{2}\right) \) has some feasible solution and if it is bounded above, then some basic feasible solution \( \wi...
Proof. By Proposition 45.3, for any feasible solution \( x \) there is some basic feasible solution \( \widetilde{x} \) such that \( {cx} \leq c\widetilde{x} \) . But there are only finitely many basic feasible solutions, so one of them has to yield the maximum of the objective function.
Yes
Proposition 45.5. Let \( {Ax} = b \) be a linear system where \( A \) is an \( m \times n \) matrix of rank \( m \) . For any subset \( K \subseteq \{ 1,\ldots, n\} \) of size \( m \), if \( {A}_{K} \) is invertible, then there is at most one basic feasible solution \( x \in {\mathbb{R}}^{n} \) with \( {x}_{j} = 0 \) f...
Proof. In order for \( x \) to be feasible we must have \( {Ax} = b \) . Write \( N = \{ 1,\ldots, n\} - K,{x}_{K} \) for the vector consisting of the coordinates of \( x \) with indices in \( K \), and \( {x}_{N} \) for the vector consisting of the coordinates of \( x \) with indices in \( N \) . Then\n\n\[ \n{Ax} = {...
Yes
Theorem 45.6. Let \( \left( P\right) \) be a linear program in standard form, where \( {Ax} = b \) and \( A \) is an \( m \times n \) matrix of rank \( m \) . For every \( v \in \mathcal{P}\left( {A, b}\right) \), the following conditions are equivalent:\n\n(1) \( v \) is a vertex of the Polyhedron \( \mathcal{P}\left(...
Proof. First, assume that \( v \) is a vertex of \( \mathcal{P}\left( {A, b}\right) \), and let \( \varphi \left( x\right) = {cx} - \mu \) be a linear form such that \( {cy} < \mu \) for all \( y \in \mathcal{P}\left( {A, b}\right) \) and \( {cv} = \mu \) . This means that \( v \) is the unique point of \( \mathcal{P}\...
Yes
Theorem 45.7. Let \( \left( P\right) \) be a linear program in standard form, where \( {Ax} = b \) and \( A \) is an \( m \times n \) matrix of rank \( m \) . If \( \mathcal{P}\left( {A, b}\right) \) is nonempty (there is a feasible solution), then \( \mathcal{P}\left( {A, b}\right) \) has some vertex; equivalently, \(...
Proof. The proof relies on a trick, which is to add slack variables \( {x}_{n + 1},\ldots ,{x}_{n + m} \) and use the new objective function \( - \left( {{x}_{n + 1} + \cdots + {x}_{n + m}}\right) \) .\n\nIf we let \( \widehat{A} \) be the \( m \times \left( {m + n}\right) \) -matrix, and \( x,\bar{x} \), and \( \wideh...
Yes
maximize \( {x}_{2} \) subject to \[ - {x}_{1} + {x}_{2} + {x}_{3} = 0 \] \[ {x}_{1} + {x}_{4} = 2 \] \[ {x}_{1} \geq 0,{x}_{2} \geq 0,{x}_{3} \geq 0,{x}_{4} \geq 0. \]
The matrix \( A \) and the vector \( b \) are given by \[ A = \left( \begin{matrix} - 1 & 1 & 1 & 0 \\ 1 & 0 & 0 & 1 \end{matrix}\right) ,\;b = \left( \begin{array}{l} 0 \\ 2 \end{array}\right) \] and if \( x = \left( {0,0,0,2}\right) \), then \( {J}_{ > }\left( x\right) = \{ 4\} \) . There are two ways of forming a se...
No
Let \( \left( P\right) \) be the following linear program in standard form.\n\n\[ \n\text{maximize} {x}_{1} + {x}_{2} \n\]\n\nsubject to\n\n\[ \n- {x}_{1} + {x}_{2} + {x}_{3} = 1 \n\]\n\n\[ \n{x}_{1} + {x}_{4} = 3 \n\]\n\n\[ \n{x}_{2} + {x}_{5} = 2 \n\]\n\n\[ \n{x}_{1} \geq 0, {x}_{2} \geq 0, {x}_{3} \geq 0, {x}_{4} \g...
The vector \( {u}_{0} = \left( {0,0,1,3,2}\right) \) corresponding to the basis \( K = \{ 3,4,5\} \) is a basic feasible solution, and the corresponding value of the objective function is \( 0 + 0 = 0 \). Since the columns \( \left( {{A}^{3},{A}^{4},{A}^{5}}\right) \) corresponding to \( K = \{ 3,4,5\} \) are linearly ...
Yes
Example 46.3. Let \( \left( P\right) \) be the following linear program in standard form.\n\nmaximize \( {x}_{1} \)\n\nsubject to\n\n\[ \n{x}_{1} - {x}_{2} + {x}_{3} = 1 \n\]\n\n\[ \n- {x}_{1} + {x}_{2} + {x}_{4} = 2 \n\]\n\n\[ \n{x}_{1} \geq 0,{x}_{2} \geq 0,{x}_{3} \geq 0,{x}_{4} \geq 0. \n\]
The matrix \( A \) and the vector \( b \) are given by\n\n\[ \nA = \left( \begin{matrix} 1 & - 1 & 1 & 0 \\ - 1 & 1 & 0 & 1 \end{matrix}\right) ,\;b = \left( \begin{array}{l} 1 \\ 2 \end{array}\right) .\n\]\n\nThe vector \( {u}_{0} = \left( {0,0,1,2}\right) \) corresponding to the basis \( K = \{ 3,4\} \) is a basic fe...
Yes
Proposition 46.2. Given any Linear Program (P2) in standard form maximize \( \;{cx} \) subject to \( {Ax} = b \) and \( x \geq 0 \), where \( A \) is an \( m \times n \) matrix of rank \( m \), if \( \left( {u, K}\right) \) is a basic (not feasible) solution of \( \left( {P2}\right) \) and if \( {K}^{ + } = \left( {K -...
Proof. Without any loss of generality and to simplify notation assume that \( K = \left( {1,\ldots, m}\right) \) and write \( j \) for \( {j}^{ + } \) and \( \ell \) for \( {k}_{m} \) . Since \( {\gamma }_{K}^{i} = {A}_{K}^{-1}{A}^{i},{\gamma }_{{K}^{ + }}^{i} = {A}_{{K}^{ + }}^{-1}{A}^{i} \), and \( {A}_{{K}^{ + }} = ...
Yes
Proposition 47.1. Let \( C \subseteq {\mathbb{R}}^{n} \) be a closed nonempty cone. For any point \( a \in {\mathbb{R}}^{n} \), if \( a \notin C \) , then there is a linear hyperplane \( H \) (through 0) such that\n\n1. \( C \) lies in one of the two half-spaces determined by \( H \) .\n\n2. \( a \notin H \)\n\n3. a li...
Proposition 47.1 is an easy consequence of another separation theorem that asserts that given any two nonempty closed convex sets \( A \) and \( B \) with \( A \) compact, there is a hyperplane \( H \) strictly separating \( A \) and \( B \) (which means that \( A \cap H = \varnothing, B \cap H = \varnothing \), that \...
No
Proposition 47.2. (Farkas-Minkowski) Let \( C \subseteq {\mathbb{R}}^{n} \) be a nonempty polyhedral cone \( C = \) \( \operatorname{cone}\left( \left\{ {{a}_{1},\ldots ,{a}_{n}}\right\} \right) \) . For any point \( b \in {\mathbb{R}}^{n} \), if \( b \notin C \), then there is a linear hyperplane \( H \) (through 0) s...
A direct proof of the Farkas-Minkowski proposition not involving Proposition 47.1 is given at the end of this section.
Yes
Proposition 47.3. (Farkas Lemma, Version I) Let \( A \) be an \( m \times n \) matrix and let \( b \in {\mathbb{R}}^{m} \) be any vector. The linear system \( {Ax} = b \) has no solution \( x \geq 0 \) iff there is some nonzero linear form \( y \in {\left( {\mathbb{R}}^{m}\right) }^{ * } \) such that \( {yA} \geq {0}_{...
Proof. First, assume that there is some nonzero linear form \( y \in {\left( {\mathbb{R}}^{m}\right) }^{ * } \) such that \( {yA} \geq 0 \) and \( {yb} < 0 \) . If \( x \geq 0 \) is a solution of \( {Ax} = b \), then we get\n\n\[ \n{yAx} = {yb} \n\]\n\nbut if \( {yA} \geq 0 \) and \( x \geq 0 \), then \( {yAx} \geq 0 \...
Yes
Proposition 47.4. (Farkas Lemma, Version II) Let \( A \) be an \( m \times n \) matrix and let \( b \in {\mathbb{R}}^{m} \) be any vector. The system of inequalities \( {Ax} \leq b \) has no solution \( x \geq 0 \) iff there is some nonzero linear form \( y \in {\left( {\mathbb{R}}^{m}\right) }^{ * } \) such that \( y ...
Proof. We use the trick of linear programming which consists of adding \
No
Proposition 47.5. Let \( X \subseteq {\mathbb{R}}^{n} \) be any nonempty set and let \( a \in {\mathbb{R}}^{n} \) be any point. If \( X \) is closed, then there is some \( z \in X \) such that \( \parallel a - z\parallel = d\left( {a, X}\right) \) .
Proof. Since \( X \) is nonempty, pick any \( {x}_{0} \in X \), and let \( r = \begin{Vmatrix}{a - {x}_{0}}\end{Vmatrix} \) . If \( {B}_{r}\left( a\right) \) is the closed ball \( {B}_{r}\left( a\right) = \left\{ {x \in {\mathbb{R}}^{n} \mid \parallel x - a\parallel \leq r}\right\} \), then clearly\n\n\[ d\left( {a, X}...
Yes
Consider the linear program illustrated by Figure 47.2\n\n\\[ \n\\text{maximize}\\;2{x}_{1} + 3{x}_{2}\n\\]\n\nsubject to\n\n\\[ \n4{x}_{1} + 8{x}_{2} \\leq {12}\n\\]\n\n\\[ \n2{x}_{1} + {x}_{2} \\leq 3\n\\]\n\n\\[ \n3{x}_{1} + 2{x}_{2} \\leq 4\n\\]\n\n\\[ \n{x}_{1} \\geq 0,{x}_{2} \\geq 0\n\\]
It can be checked that \\( \\left( {{x}_{1},{x}_{2}}\\right) = \\left( {1/2,5/4}\\right) \\) is an optimal solution of the primal linear\n\nprogram, with the maximum value of the objective function \\( 2{x}_{1} + 3{x}_{2} \\) equal to \\( {19}/4 \\), and that \\( \\left( {{y}_{1},{y}_{2},{y}_{3}}\\right) = \\left( {5/{...
Yes
Theorem 47.8. Consider the Linear Program (P), maximize \( cx \) subject to \( Ax \leq b \) and \( x \geq 0 \), its equivalent version \( (P2) \) in standard form, maximize \( \widehat{c}\widehat{x} \) subject to \( \widehat{A}\widehat{x} = b \) and \( \widehat{x} \geq 0 \), where \( \widehat{A} \) is an \( m \times (n...
Proof. We know that \( K^* \) is a subset of \( \{ 1, \ldots, n + m \} \) consisting of \( m \) indices such that the corresponding columns of \( \widehat{A} \) are linearly independent. Let \( N^* = \{ 1, \ldots, n + m \} - K^* \). The simplex method terminates with an optimal solution in Case (A), namely when \( \wid...
Yes
Theorem 47.10. (Equilibrium Theorem) For any linear program (P) and its dual linear program (D) (with set of inequalities \( {Ax} \leq b \) where \( A \) is an \( m \times n \) matrix, and objective function \( x \mapsto {cx} \) ), for any feasible solution \( x \) of \( \left( P\right) \) and any feasible solution \( ...
Proof. First, assume that \( \left( { * }_{D}\right) \) and \( \left( { * }_{P}\right) \) hold. The equations in \( \left( { * }_{D}\right) \) say that \( {y}_{i} = 0 \) unless \( \mathop{\sum }\limits_{{j = 1}}^{n}{a}_{ij}{x}_{j} = {b}_{i} \), hence \[ {yb} = \mathop{\sum }\limits_{{i = 1}}^{m}{y}_{i}{b}_{i} = \mathop...
Yes
Theorem 47.11. Consider the linear program (P2) in standard form\n\nmaximize \( \;{cx} \)\n\n\[ \text{subject to}{Ax} = b\text{and}x \geq 0\text{,} \]\nand its dual \( \left( D\right) \) given by\n\n\[ \text{minimize}{yb} \]\n\n\[ \text{subject to}{yA} \geq c\text{,} \]\n\nwhere \( y \in {\left( {\mathbb{R}}^{m}\right)...
Proof. The proof of Theorem 47.8 applies with \( A \) instead of \( \widehat{A} \) and we can show that\n\n\[ {c}_{{K}^{ * }}{A}_{{K}^{ * }}^{-1}{A}_{{N}^{ * }} \geq {c}_{{N}^{ * }} \]\n\nand that \( {y}^{ * } = {c}_{{K}^{ * }}{A}_{{K}^{ * }}^{-1} \) satisfies, \( c{u}^{ * } = {y}^{ * }b \), and\n\n\[ {y}^{ * }{A}_{{K}...
Yes
Proposition 47.13. Every \( j \in J \) such that \( {A}^{j} \) is in the basis of the optimal solution \( {\xi }^{ * } \) belongs to the next index set \( {J}^{ + } \) .
Proof. Such an index \( j \in J \) correspond to a variable \( {\xi }_{j} \) such that \( {\xi }_{j} > 0 \), so by complementary slackness, the constraint \( {z}^{ * }{A}^{j} \geq 0 \) of the dual program \( \left( {DRP}\right) \) must be an equality, that is, \( {z}^{ * }{A}^{j} = 0 \) . But then, we have\n\n\[ \n{y}^...
Yes
Consider the following linear program in standard form:\n\nMaximize \( \; - {x}_{1} - 3{x}_{2} - 3{x}_{3} - {x}_{4} \)\n\nsubject to \( \left( \begin{matrix} 3 & 4 & - 3 & 1 \\ 3 & - 2 & 6 & - 1 \\ 6 & 4 & 0 & 1 \end{matrix}\right) \left( \begin{array}{l} {x}_{1} \\ {x}_{2} \\ {x}_{3} \\ {x}_{4} \end{array}\right) = \l...
The associated dual program \( \left( D\right) \) is\n\n\[ \text{Minimize}\;2{y}_{1} + {y}_{2} + 4{y}_{3} \]\n\n\[ \text{subject to}\;\left( \begin{array}{lll} {y}_{1} & {y}_{2} & {y}_{3} \end{array}\right) \left( \begin{matrix} 3 & 4 & - 3 & 1 \\ 3 & - 2 & 6 & - 1 \\ 6 & 4 & 0 & 1 \end{matrix}\right) \geq \left( \begi...
Yes
The space \( {l}^{2} \) of all countably infinite sequences \( x = {\left( {x}_{i}\right) }_{i \in \mathbb{N}} \) of complex numbers such that \( \mathop{\sum }\limits_{{i = 0}}^{\infty }{\left| {x}_{i}\right| }^{2} < \infty \) is a Hilbert space.
It will be shown later that the map \( \varphi : {l}^{2} \times {l}^{2} \rightarrow \mathbb{C} \) defined such that\n\n\[ \varphi \left( {{\left( {x}_{i}\right) }_{i \in \mathbb{N}},{\left( {y}_{i}\right) }_{i \in \mathbb{N}}}\right) = \mathop{\sum }\limits_{{i = 0}}^{\infty }{x}_{i}\overline{{y}_{i}} \]\n\nis well def...
No
Theorem 48.1. Given a Hermitian space \( \left( {E,\langle -, - \rangle }\right) \) (resp. Euclidean space), there is a Hilbert space \( \left( {{E}_{h},\langle -, - {\rangle }_{h}}\right) \) and a linear map \( \varphi : E \rightarrow {E}_{h} \), such that\n\n\[ \langle u, v\rangle = \langle \varphi \left( u\right) ,\...
Proof. Let \( \left( {\widehat{E},\parallel {\parallel }_{\widehat{E}}}\right) \) be the Banach space, and let \( \varphi : E \rightarrow \widehat{E} \) be the linear isometry, given by Theorem 37.63. Let \( \parallel u\parallel = \sqrt{\langle u, u\rangle } \) and \( {E}_{h} = \widehat{E} \) . If \( E \) is a real vec...
Yes
Proposition 48.3. If \( E \) is a Hermitian space, given any \( d,\delta \in \mathbb{R} \) such that \( 0 \leq \delta < d \), let\n\n\[ B = \{ u \in E \mid \parallel u\parallel < d\} \;\text{ and }\;C = \{ u \in E \mid \parallel u\parallel \leq d + \delta \} .\n\]\n\nFor any convex set such \( A \) that \( A \subseteq ...
Proof. Since \( A \) is convex, \( \frac{1}{2}\left( {u + v}\right) \in A \) if \( u, v \in A \), and thus, \( \begin{Vmatrix}{\frac{1}{2}\left( {u + v}\right) }\end{Vmatrix} \geq d \) . From the parallelogram inequality written in the form\n\n\[ {\begin{Vmatrix}\frac{1}{2}\left( u + v\right) \end{Vmatrix}}^{2} + {\beg...
Yes
Proposition 48.5. (Projection lemma) Let \( E \) be a Hilbert space.\n\n(1) For any nonempty convex and closed subset \( X \subseteq E \), for any \( u \in E \), there is a unique vector \( {p}_{X}\left( u\right) \in X \) such that\n\n\[ \begin{Vmatrix}{u - {p}_{X}\left( u\right) }\end{Vmatrix} = \mathop{\inf }\limits_...
Proof. (1) Let \( d = \mathop{\inf }\limits_{{v \in X}}\parallel u - v\parallel = d\left( {u, X}\right) \) . We define a sequence \( {X}_{n} \) of subsets of \( X \) as\n\nfollows: for every \( n \geq 1 \) ,\n\n\[ {X}_{n} = \left\{ {v \in X \mid \parallel u - v\parallel \leq d + \frac{1}{n}}\right\} . \]\n\nIt is immed...
Yes
Proposition 48.6. Let \( E \) be a Hilbert space. For any nonempty convex and closed subset \( X \subseteq E \), the map \( {p}_{X} : E \rightarrow X \) is continuous. In fact, \( {p}_{X} \) satisfies the Lipschitz condition \[ \begin{Vmatrix}{{p}_{X}\left( v\right) - {p}_{X}\left( u\right) }\end{Vmatrix} \leq \paralle...
Proof. For any two vectors \( u, v \in E \), let \( x = {p}_{X}\left( u\right) - u, y = {p}_{X}\left( v\right) - {p}_{X}\left( u\right) \), and \( z = v - {p}_{X}\left( v\right) \). Clearly, (as illustrated in Figure 48.6), \[ v - u = x + y + z, \] and from Proposition 48.5 (2), we also have \[ \Re \langle x, y\rangle ...
Yes
Proposition 48.7. Let \( E \) be a Hilbert space.\n\n(1) For any closed subspace \( V \subseteq E \), we have \( E = V \oplus {V}^{ \bot } \), and the map \( {p}_{V} : E \rightarrow V \) is linear and continuous.\n\n(2) For any \( u \in E \), the projection \( {p}_{V}\left( u\right) \) is the unique vector \( w \in E \...
Proof. (1) First, we prove that \( u - {p}_{V}\left( u\right) \in {V}^{ \bot } \) for all \( u \in E \) . For any \( v \in V \), since \( V \) is a subspace, \( z = {p}_{V}\left( u\right) + {\lambda v} \in V \) for all \( \lambda \in \mathbb{C} \), and since \( V \) is convex and nonempty (since it is a subspace), and ...
Yes
Proposition 48.10. Given a Hilbert space \( E \), for every continuous linear map \( f : E \rightarrow E \) , there is a unique continuous linear map \( {f}^{ * } : E \rightarrow E \), such that\n\n\[ \langle f\left( u\right), v\rangle = \left\langle {u,{f}^{ * }\left( v\right) }\right\rangle \;\text{ for all }u, v \in...
Proof. The proof is adapted from Rudin [139] (Section 12.9). By the Cauchy-Schwarz inequality\n\n\[ \left| {\langle x, y\rangle }\right| \leq \parallel x\parallel \parallel y\parallel \]\n\nwe see that the sesquilinear map \( \left( {x, y}\right) \mapsto \langle x, y\rangle \) on \( E \times E \) is continuous. Let \( ...
Yes
Theorem 48.11. (Farkas-Minkowski Lemma in Hilbert Spaces) Let \( \\left( {V,\\langle -, - \\rangle }\\right) \) be a real Hilbert space. For any finite sequence of vectors \( \\left( {{a}_{1},\\ldots ,{a}_{m}}\\right) \) with \( {a}_{i} \\in V \), if \( C \) is the polyhedral cone \( C = \\operatorname{cone}\\left( {{a...
Proof. We follow Ciarlet [41] (Chapter 9, Theorem 9.1.1). We already established in Proposition 44.2 that the polyhedral cone \( C = \\operatorname{cone}\\left( {{a}_{1},\\ldots ,{a}_{m}}\\right) \) is closed. Next we claim the following:\n\nClaim: If \( C \) is a nonempty, closed, convex subset of a Hilbert space \( V...
Yes
Proposition 49.1. Let \( U \) be a nonempty, closed subset of \( {\mathbb{R}}^{n} \), and let \( J : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \) be a continuous function which is coercive if \( U \) is unbounded. Then there is a least one element \( u \in {\mathbb{R}}^{n} \) such that\n\n\[ u \in U\;\text{ and }\;J\left...
Proof. Since \( U \neq \varnothing \), pick any \( {u}_{0} \in U \) . Since \( J \) is coercive, there is some \( r > 0 \) such that for all \( v \in {\mathbb{R}}^{n} \), if \( \parallel v\parallel > r \) then \( J\left( {u}_{0}\right) < J\left( v\right) \) . It follows that \( J \) is minimized over the set\n\n\[ {U}_...
Yes
Proposition 49.3. If \( J \) is a quadratic functional, then\n\n\[ J\left( {u + {\rho v}}\right) = \frac{{\rho }^{2}}{2}a\left( {v, v}\right) + \rho \left( {a\left( {u, v}\right) - h\left( v\right) }\right) + J\left( u\right) . \]
Proof. Since \( a \) is symmetric bilinear and \( h \) is linear, we have\n\n\[ J\left( {u + {\rho v}}\right) = \frac{1}{2}a\left( {u + {\rho v}, u + {\rho v}}\right) - h\left( {u + {\rho v}}\right) \]\n\n\[ \frac{{\rho }^{2}}{2}a\left( {v, v}\right) + {\rho a}\left( {u, v}\right) + \frac{1}{2}a\left( {u, u}\right) - h...
Yes
Theorem 49.4. Given any Hilbert space \( V \), let \( J : V \rightarrow \mathbb{R} \) be a quadratic functional of the form\n\n\[ J\left( v\right) = \frac{1}{2}a\left( {v, v}\right) - h\left( v\right) \]\n\nAssume that there is some real number \( \alpha > 0 \) such that\n\n\[ a\left( {v, v}\right) \geq \alpha \paralle...
Proof. The key point is that the bilinear form \( a \) is actually an inner product in \( V \) . This is because it is positive definite, since \( \left( { * }_{\alpha }\right) \) implies that\n\n\[ \sqrt{\alpha }\parallel v\parallel \leq {\left( a\left( v, v\right) \right) }^{1/2} \]\n\nand on the other hand the conti...
Yes
Let \( V \) be a Hilbert space. (1) An elliptic functional \( J : V \rightarrow \mathbb{R} \) is strictly convex and coercice. Furthermore, it satisfies the identity \[ J\left( v\right) - J\left( u\right) \geq \left\langle {\nabla {J}_{u}, v - u}\right\rangle + \frac{\alpha }{2}\parallel v - u{\parallel }^{2}\;\text{ f...
Since \( J \) is a \( {C}^{1} \) -function, by Taylor’s formula with integral remainder in the case \( m = 0 \) (Theorem 39.25), we get \[ J\left( v\right) - J\left( u\right) = {\int }_{0}^{1}d{J}_{u + t\left( {v - u}\right) }\left( {v - u}\right) {dt} \] \[ = {\int }_{0}^{1}\left\langle {\nabla {J}_{u + t\left( {v - u...
Yes
Proposition 49.11. If \( J \) is a quadratic elliptic functional of the form\n\n\[ J\left( v\right) = \frac{1}{2}a\left( {v, v}\right) - h\left( v\right) \]\n\nthen given \( {d}_{k} \), there is a unique \( {\rho }_{k} \) solving the line search in Step (2).
Proof. This is because, by Proposition 49.3, we have\n\n\[ J\left( {{u}_{k} + \rho {d}_{k}}\right) = \frac{{\rho }^{2}}{2}a\left( {{d}_{k},{d}_{k}}\right) + \rho \left\langle {\nabla {J}_{{u}_{k}},{d}_{k}}\right\rangle + J\left( {u}_{k}\right) ,\]\n\nand since \( a\left( {{d}_{k},{d}_{k}}\right) > 0 \) (because \( J \)...
Yes
Proposition 49.14. Let \( J : V \rightarrow \mathbb{R} \) be a continuously differentiable functional defined on a Hilbert space \( V \) . Suppose there exists two constants \( \alpha > 0 \) and \( M > 0 \) such that\n\n\[ \left\langle {\nabla {J}_{v} - \nabla {J}_{u}, v - u}\right\rangle \geq \alpha \parallel v - u{\p...
Proof. By hypothesis the functional \( J \) is elliptic, so by Theorem 49.8(2) it has a unique minimum \( u \) characterized by the fact that \( \nabla {J}_{u} = 0 \) . Then since \( {u}_{k + 1} = {u}_{k} - {\rho }_{k}\nabla {J}_{{u}_{k}} \), we can write\n\n\[ {u}_{k + 1} - u = \left( {{u}_{k} - u}\right) - {\rho }_{k...
Yes
Proposition 49.15. Assume that \( \nabla {J}_{{u}_{i}} \neq 0 \) for \( i = 0,\ldots, k \) . Then the minimization problem, find \( {u}_{k + 1} \) such that\n\n\[ \n{u}_{k + 1} \in {u}_{k} + {\mathcal{G}}_{k}\;\text{ and }\;J\left( {u}_{k + 1}\right) = \mathop{\inf }\limits_{{v \in {u}_{k} + {\mathcal{G}}_{k}}}J\left( ...
Proof. The affine space \( {u}_{\ell } + {\mathcal{G}}_{\ell } \) is closed and convex, and since \( J \) is a quadratic elliptic functional it is coercise and strictly convex, so by Theorem 49.8(2) it has a unique minimum in \( {u}_{\ell } + {\mathcal{G}}_{\ell } \) . This minimum \( {u}_{\ell + 1} \) is also the mini...
Yes
Let \( J : {\mathbb{R}}^{2} \rightarrow \mathbb{R} \) be the function given by\n\n\[ J\left( {{v}_{1},{v}_{2}}\right) = \frac{1}{2}\left( {{\alpha }_{1}{v}_{1}^{2} + {\alpha }_{2}{v}_{2}^{2}}\right) \]\n\nwhere \( 0 < {\alpha }_{1} < {\alpha }_{2} \). The minimum of \( J \) is attained at \( \left( {0,0}\right) \). Unl...
Observe that\n\n\[ \nabla {J}_{\left( {v}_{1},{v}_{2}\right) } = \left( \begin{array}{l} {\alpha }_{1}{v}_{1} \\ {\alpha }_{2}{v}_{2} \end{array}\right) . \]\n\nAs a consequence, given \( {u}_{k} \), the line search for finding \( {\rho }_{k} \) and \( {u}_{k + 1} \) yields \( {u}_{k + 1} = \left( {0,0}\right) \) iff t...
Yes
Proposition 49.16. Assume that \( \nabla {J}_{{u}_{i}} \neq 0 \) for \( i = 0,\ldots, k \), and let \( {\Delta }_{\ell } = {u}_{\ell + 1} - {u}_{\ell } \), for \( \ell = 0,\ldots, k \). Then \( {\Delta }_{\ell } \neq 0 \) for \( \ell = 0,\ldots, k \), and\n\n\[ \left\langle {A{\Delta }_{\ell },{\Delta }_{i}}\right\rang...
Proof. Since \( J \) is a quadratic functional we have\n\n\[ \nabla {J}_{v + w} = A\left( {v + w}\right) - b = {Av} - b + {Aw} = \nabla {J}_{v} + {Aw}. \]\n\nIt follows that\n\n\[ \nabla {J}_{{u}_{\ell + 1}} = \nabla {J}_{{u}_{\ell } + {\Delta }_{\ell }} = \nabla {J}_{{u}_{\ell }} + A{\Delta }_{\ell },\;0 \leq \ell \le...
Yes
Proposition 49.17. Assume that \( \nabla {J}_{{u}_{i}} \neq 0 \) for \( i = 0,\ldots, k \) . If we write\n\n\[ \n{d}_{\ell } = \mathop{\sum }\limits_{{i = 0}}^{{\ell - 1}}{\lambda }_{i}^{\ell }\nabla {J}_{{u}_{i}} + \nabla {J}_{{u}_{\ell }},\;0 \leq \ell \leq k,\n\]\n\nthen we have\n\n\[ \n\text{(} \dagger \text{)}\;\l...
Proof. Since by \( \left( { * }_{4}\right) \) we have \( {\Delta }_{k} = {\delta }_{k}^{k}{d}_{k},{\delta }_{k}^{k} \neq 0 \) ,(by Proposition 49.16) we have\n\n\[ \n\left\langle {A{\Delta }_{\ell },{\Delta }_{i}}\right\rangle = 0,\;0 \leq i < \ell \leq k.\n\]\n\nBy \( \left( { * }_{1}\right) \) we have \( \nabla {J}_{...
Yes
Let us take the example of Section 49.6 and apply the conjugate gradient procedure. Recall that\n\n\\[ \nJ\\left( {x, y}\\right) = \\frac{1}{2}\\left( \\begin{array}{ll} x & y \\end{array}\\right) \\left( \\begin{array}{ll} 3 & 2 \\\\ 2 & 6 \\end{array}\\right) \\left( \\begin{array}{l} x \\\\ y \\end{array}\\right) - ...
Step 1 involves calculating\n\n\\[ \n{\\rho }_{0} = \\frac{\\left\\langle \\nabla {J}_{{u}_{0}},{d}_{0}\\right\\rangle }{\\left\\langle A{d}_{0},{d}_{0}\\right\\rangle } = \\frac{13}{75} \n\\]\n\n\\[ \n{u}_{1} = {u}_{0} - {\\rho }_{0}{d}_{0} = \\left( {-2, - 2}\\right) - \\frac{13}{75}\\left( {-{12}, - 8}\\right) = \\l...
Yes
Proposition 49.18. Let \( J : V \rightarrow \mathbb{R} \) be a continuously differentiable functional defined on a Hilbert space \( V \), and let \( U \) be nonempty, convex, closed subset of \( V \). Suppose there exists two constants \( \alpha > 0 \) and \( M > 0 \) such that\n\n\[ \left\langle {\nabla {J}_{v} - \nab...
Proof. For every \( {\rho }_{k} \geq 0 \), define the function \( {g}_{k} : V \rightarrow U \) by\n\n\[ {g}_{k}\left( v\right) = {p}_{U}\left( {v - {\rho }_{k}\nabla {J}_{v}}\right) \]\n\nBy Proposition 48.6, the projection map \( {p}_{U} \) has Lipschitz constant 1, so using the inequalities assumed to hold in the pro...
Yes
Example 50.1. In \( V = {\mathbb{R}}^{2} \), let \( {\varphi }_{1} \) and \( {\varphi }_{2} \) be given by\n\n\[ \n{\varphi }_{1}\left( {{u}_{1},{u}_{2}}\right) = - {u}_{1} - {u}_{2} \n\] \n\n\[ \n{\varphi }_{2}\left( {{u}_{1},{u}_{2}}\right) = {u}_{1}\left( {{u}_{1}^{2} + {u}_{2}^{2}}\right) - \left( {{u}_{1}^{2} - {u...
The region \( U \) is shown in Figure 50.4 and is bounded by the curve given by the equation \( {\varphi }_{1}\left( {{u}_{1},{u}_{2}}\right) = 0 \), that is, \( - {u}_{1} - {u}_{2} = 0 \), the line of slope -1 through the origin, and the curve given by the equation \( {u}_{1}\left( {{u}_{1}^{2} + {u}_{2}^{2}}\right) -...
Yes
Proposition 50.1. Let \( U \) be any nonempty subset of a normed vector space \( V \). (1) For any \( u \in U \), the cone \( C\left( u\right) \) of feasible directions at \( u \) is closed.
Proof. (1) Let \( {\left( {w}_{n}\right) }_{n \geq 0} \) be a sequence of vectors \( {w}_{n} \in C\left( u\right) \) converging to a limit \( w \in V \). We may assume that \( w \neq 0 \), since \( 0 \in C\left( u\right) \) by definition, and thus we may also assume that \( {w}_{n} \neq 0 \) for all \( n \geq 0 \). By ...
Yes
Consider the region \( U \subseteq {\mathbb{R}}^{2} \) determined by the two curves given by \[ {\varphi }_{1}\left( {{u}_{1},{u}_{2}}\right) = {u}_{2} - \max \left( {0,{u}_{1}^{3}}\right) \] \[ {\varphi }_{2}\left( {{u}_{1},{u}_{2}}\right) = {u}_{1}^{4} - {u}_{2} \]
We have \( I\left( {0,0}\right) = \{ 1,2\} \), and since \( {\left( {\varphi }_{1}\right) }_{\left( 0,0\right) }^{\prime }\left( {{w}_{1},{w}_{2}}\right) = \left( \begin{array}{ll} 0 & 1 \end{array}\right) \left( \begin{array}{l} {w}_{1} \\ {w}_{2} \end{array}\right) = {w}_{2} \) and \( {\left( {\varphi }_{2}^{\prime }...
Yes
Proposition 50.2. Let \( u \) be any point of the set\n\n\[ U = \\left\\{ {x \\in \\Omega \\mid {\\varphi }_{i}\\left( x\\right) \\leq 0,1 \\leq i \\leq m}\\right\\} \]\n\nwhere \( \\Omega \) is an open subset of the normed vector space \( V \), and assume that the functions \( {\\varphi }_{i} \) are differentiable at ...
Proof. (1) For every \( i \\in I\\left( u\\right) \), since \( {\\varphi }_{i}\\left( v\\right) \\leq 0 \) for all \( v \\in U \) and \( {\\varphi }_{i}\\left( u\\right) = 0 \), the function \( - {\\varphi }_{i} \) has a local minimum at \( u \) with respect to \( U \), so by Proposition 50.1(2), we have\n\n\[ {\\left(...
Yes
Proposition 50.4. (Farkas-Minkowski) Let \( V \) be a Euclidean space of finite dimension with inner product \( \langle - , - \rangle \) (more generally, a Hilbert space). For any finite family \( \left( {{a}_{1},\ldots ,{a}_{m}}\right) \) of \( m \) vectors \( {a}_{i} \in V \) and any vector \( b \in V \), for any \( ...
Proposition 50.4 is the special case of Theorem 48.11 which holds for real Hilbert spaces.
Yes
Theorem 50.5. Let \( {\varphi }_{i} : \Omega \rightarrow \mathbb{R} \) be \( m \) constraints defined on some open subset \( \Omega \) of a finite-dimensional Euclidean vector space \( V \) (more generally, a real Hilbert space \( V \) ), let \( J : \Omega \rightarrow \mathbb{R} \) be some function, and let \( U \) be ...
Proof. By Proposition 50.1(2), we have\n\n\[ {J}_{u}^{\prime }\left( w\right) \geq 0\;\text{ for all }w \in C\left( u\right) ,\]\n\n\( \left( { * }_{1}\right) \)\n\nand by Proposition \( {50.2}\left( 2\right) \), we have \( C\left( u\right) = {C}^{ * }\left( u\right) \), where\n\n\[ {C}^{ * }\left( u\right) = \left\{ {...
Yes
Theorem 50.6. Let \( {\varphi }_{i} : \Omega \rightarrow \mathbb{R} \) be \( m \) convex constraints defined on some open convex subset \( \Omega \) of a finite-dimensional Euclidean vector space \( V \) (more generally, a real Hilbert space \( V \) ), let \( J : \Omega \rightarrow \mathbb{R} \) be some function, let \...
Proof. (1) It suffices to prove that if the convex constraints are qualified according to Definition 50.6 , then they are qualified according to Definition 50.5 , since in this case we can apply Theorem 50.5.\n\nIf \( v \in \Omega \) is a vector such that Condition (b) of Definition 50.6 holds and if \( v \neq u \), fo...
Yes
Proposition 50.7. If \( U \) is given by\n\n\[ U = \{ x \in \Omega \mid {Ax} \leq b\} \]\n\nwhere \( \Omega \) is an open convex subset of \( {\mathbb{R}}^{n} \) and \( A \) is an \( m \times n \) matrix, and if \( J \) is differentiable at \( u \) and \( J \) has a local minimum at \( u \), then there exist some vecto...
If the function \( J \) is convex, then the above conditions are also sufficient for \( J \) to have a minimum at \( u \in U \) .
No
We would like to find necessary conditions for \( {f}_{\mu } \) to have a maximum on\n\n\[ U = \\left\\{ {x \\in {\\mathbb{R}}_{+ + }^{n} \\mid {Ax} = b}\\right\\} \]\n\nor equivalently to solve the following problem:\n\n\[ \\text{maximize}\\{f}_{\\mu }\\left( x\\right) \]\n\n\[ \\text{subject to} \]\n\n\[ {Ax} = b \]\...
Since maximizing \( {f}_{\mu } \) is equivalent to minimizing \( - {f}_{\mu } \), by Proposition 50.9, if \( x \) is an optimal of the above problem then there is some \( y \\in {\\mathbb{R}}^{m} \) such that\n\n\[ - \\nabla {f}_{\\mu }\\left( x\\right) + {A}^{\\top }y = 0. \]\n\nSince\n\n\[ \\nabla {f}_{\\mu }\\left( ...
Yes
Proposition 50.11. If \( \left( {w, b,\delta }\right) \) is an optimal solution of Problem \( \left( {\mathrm{{SVM}}}_{h1}\right) \), so in particular \( \delta > 0 \), then we must have \( \parallel w\parallel = 1 \) .
Proof. First, if \( w = 0 \), then we get the two inequalities\n\n\[ \n- b \geq \delta ,\;b \geq \delta , \n\]\n\nwhich imply that \( b \leq - \delta \) and \( b \geq \delta \) for some positive \( \delta \), which is impossible. But then, if \( w \neq 0 \) and \( \parallel w\parallel < 1 \), by dividing both sides of ...
Yes
Theorem 50.12. If two disjoint subsets of \( p \) blue points \( {\left\{ {u}_{i}\right\} }_{i = 1}^{p} \) and \( q \) red points \( {\left\{ {v}_{j}\right\} }_{j = 1}^{q} \) are linearly separable, then Problem \( \left( {\mathrm{{SVM}}}_{h1}\right) \) has a unique optimal solution consisting of a hyperplane of equati...
Proof. Our proof is adapted from Vapnik [180] (Chapter 10, Theorem 10.1). For any separating hyperplane \( H \), since\n\n\[ \nd\left( {{u}_{i}, H}\right) = {w}^{\top }{u}_{i} - b \n\]\n\n\[ \ni = 1,\ldots, p \n\]\n\n\[ \nd\left( {{v}_{j}, H}\right) = - {w}^{\top }{v}_{j} + b\;j = 1,\ldots, q, \n\]\nand since the small...
Yes
Proposition 50.13. If \( \left( {u,\lambda }\right) \) is a saddle point of a function \( L : \Omega \times M \rightarrow \mathbb{R} \), then\n\n\[ \mathop{\sup }\limits_{{\mu \in M}}\mathop{\inf }\limits_{{v \in \Omega }}L\left( {v,\mu }\right) = L\left( {u,\lambda }\right) = \mathop{\inf }\limits_{{v \in \Omega }}\ma...
Proof. First we prove that the following inequality always holds:\n\n\[ \mathop{\sup }\limits_{{\mu \in M}}\mathop{\inf }\limits_{{v \in \Omega }}L\left( {v,\mu }\right) \leq \mathop{\inf }\limits_{{v \in \Omega }}\mathop{\sup }\limits_{{\mu \in M}}L\left( {v,\mu }\right) \]\n\n\( \left( { * }_{1}\right) \)\n\nPick any...
Yes
(1) If \( \left( {u,\lambda }\right) \in \Omega \times {\mathbb{R}}_{ + }^{m} \) is a saddle point of the Lagrangian \( L \) associated with Problem \( \left( P\right) \) , then \( u \in U, u \) is a solution of Problem \( \left( P\right) \), and \( J\left( u\right) = L\left( {u,\lambda }\right) \) .
Proof. (1) Since \( \left( {u,\lambda }\right) \) is a saddle point of \( L \) we have \( \mathop{\sup }\limits_{{\mu \in {\mathbb{R}}_{ + }^{m}}}L\left( {u,\mu }\right) = L\left( {u,\lambda }\right) \) which implies that \( L\left( {u,\mu }\right) \leq L\left( {u,\lambda }\right) \) for all \( \mu \in {\mathbb{R}}_{ +...
Yes
Consider the Linear Program \( \\left( P\\right) \)\n\n\\[ \n\\text{minimize}\\,{c}^{\\top }v\n\\]\n\n\\[ \n\\text{subject to}\\,{Av} \\leq b, v \\geq 0\\text{,}\n\\]
where \( A \) is an \( m \\times n \) matrix. The constraints \( v \\geq 0 \) are rewritten as \( - {v}_{i} \\leq 0 \), so we introduce Lagrange multipliers \( \\mu \\in {\\mathbb{R}}_{ + }^{m} \) and \( \\nu \\in {\\mathbb{R}}_{ + }^{n} \), and we have the Lagrangian\n\n\\[ \nL\\left( {v,\\mu ,\\nu }\\right) = {c}^{\\...
Yes
Proposition 50.15. (Complementary Slackness) Given the Minimization Problem (P)\n\n\\[ \n\\text{minimize}\\;J\\left( v\\right) \n\\]\n\n\\[ \n\\text{subject to}{\\varphi }_{i}\\left( v\\right) \\leq 0,\\;i = 1,\\ldots, m\\text{,}\n\\]\n\nand its Dual Problem (D)\n\n\\[ \n\\text{maximize}\\;G\\left( \\mu \\right) \n\\]\...
Proof. Since \\( J\\left( u\\right) = G\\left( \\lambda \\right) \\) we have\n\n\\[ \nJ\\left( u\\right) = G\\left( \\lambda \\right) \n\\]\n\n\\[ \n= \\mathop{\\inf }\\limits_{{v \\in \\Omega }}\\left( {J\\left( v\\right) + \\mathop{\\sum }\\limits_{{i = 1}}^{m}{\\lambda }_{i}{\\varphi }_{i}\\left( v\\right) }\\right)...
Yes
Theorem 50.16. Consider the Minimization Problem (P):\n\n\\[ \n\\text{minimize}\\;J\\left( v\\right) \n\\]\n\n\\[ \n\\text{subject to}{\\varphi }_{i}\\left( v\\right) \\leq 0,\\;i = 1,\\ldots, m\\text{,}\n\\]\n\nwhere the functions \\( J \\) and \\( {\\varphi }_{i} \\) are defined on some open subset \\( \\Omega \\) of...
Proof. (1) Our goal is to prove that for any solution \\( \\lambda \\) of Problem \\( \\left( D\\right) \\), the pair \\( \\left( {{u}_{\\lambda },\\lambda }\\right) \\) is a saddle point of \\( L \\) . By Theorem 50.14(1), the point \\( {u}_{\\lambda } \\in U \\) is a solution of Problem \\( \\left( P\\right) \\) .\n\...
Yes
Consider the quadratic objective function\n\n\[ J\left( v\right) = \frac{1}{2}{v}^{\top }{Av} - {v}^{\top }b \]\n\nwhere \( A \) is an \( n \times n \) matrix which is symmetric positive definite, \( b \in {\mathbb{R}}^{n} \), and the constraints are affine inequality constraints of the form\n\n\[ {Cv} \leq d \]\n\nwhe...
Since \( A \) is symmetric positive definite, \( J \) is strictly convex, as implied by Proposition 40.9 (see Example 40.1). The Lagrangian of this quadratic optimization problem is given by\n\n\[ L\left( {v,\mu }\right) = \frac{1}{2}{v}^{\top }{Av} - {v}^{\top }b + {\left( Cv - d\right) }^{\top }\mu \]\n\n\[ = \frac{1...
Yes
Theorem 50.17. Let \( {\varphi }_{i} : \Omega \rightarrow \mathbb{R} \) be \( m \) convex inequality constraints and \( {\psi }_{j} : \Omega \rightarrow \mathbb{R} \) be \( p \) affine equality constraints defined on some open convex subset \( \Omega \) of a finite-dimensional Euclidean vector space \( V \) (more gener...
Equivalently, in terms of gradients, the above conditions are expressed as\n\n\[ \\nabla {J}_{u} + \\mathop{\\sum }\\limits_{{i = 1}}^{m}{\\lambda }_{i}\\nabla {\\left( {\\varphi }_{i}\\right) }_{u} + \\mathop{\\sum }\\limits_{{j = 1}}^{p}{\\nu }_{j}\\nabla {\\left( {\\psi }_{j}\\right) }_{u} = 0 \]\n\nand\n\n\[ \\math...
Yes
Proposition 50.19. Consider Problem (P), \n\n\[ \n\\text{minimize}\;J\\left( v\\right) \n\] \n\n\[ \n\\text{subject to}{Av} \\leq b \n\] \n\n\[ \n{Cv} = d, \n\] \n\nwith affine inequality and equality constraints (with \( A \) an \( m \\times n \) matrix, \( C \) an \( p \\times n \) matrix, \( \\left. {b \\in {\\mathb...
Proof. The Lagrangian associated with the above program is \n\n\[ \nL\\left( {v,\\lambda ,\\nu }\\right) = J\\left( v\\right) + {\\left( Av - b\\right) }^{\\top }\\lambda + {\\left( Cv - d\\right) }^{\\top }\\nu \n\] \n\n\[ \n= - {b}^{\\top }\\lambda - {d}^{\\top }\\nu + J\\left( v\\right) + {\\left( {A}^{\\top }\\lamb...
Yes
Consider the following problem:\n\n\[ \text{minimize}\parallel v\parallel \]\n\n\[ \text{subject to}{Av} = b\text{,} \]
Using the result of Example 50.8(6), we obtain\n\n\[ G\left( \nu \right) = - {b}^{\top }\nu - {\begin{Vmatrix}-{A}^{\top }\nu \end{Vmatrix}}^{ * }, \]\n\nthat is,\n\n\[ G\left( \nu \right) = \left\{ \begin{array}{ll} - {b}^{\top }\nu & \text{ if }{\begin{Vmatrix}{A}^{\top }\nu \end{Vmatrix}}^{D} \leq 1 \\ - \infty & \t...
Yes
As a concrete example, consider the following unconstrained program:\n\n\[ \text{ minimize }f\left( x\right) = \log \left( {\mathop{\sum }\limits_{{i = 1}}^{n}{e}^{{\left( {A}^{i}\right) }^{\top }x + {b}_{i}}}\right) \] \n\nwhere \( {A}^{i} \) is a column vector in \( {\mathbb{R}}^{n} \).
We reformulate the problem by introducing new variables and equality constraints as follows:\n\n\[ \text{ minimize }\;f\left( y\right) = \log \left( {\mathop{\sum }\limits_{{i = 1}}^{n}{e}^{{y}_{i}}}\right) \] \n\n\[ \text{subject to} \] \n\n\[ {Ax} + b = y, \] \n\nwhere \( A \) is the \( n \times n \) matrix whose col...
Yes
Similarly the unconstrained norm minimization problem\n\n\[ \n\\text{minimize}\\parallel {Ax} - b\\parallel \\text{,}\n\]\n\nwhere \( \\parallel \\parallel \) is any norm on \( {\\mathbb{R}}^{m} \), has a dual function which is a constant, and is not useful. This problem can be reformulated as\n\nminimize \( \\parallel...
By Example 50.8(6), the conjugate of the norm is given by\n\n\[ \n\\parallel y{\\parallel }^{ * } = \\left\\{ \\begin{array}{ll} 0 & \\text{ if }\\parallel y{\\parallel }^{D} \\leq 1 \\\\ + \\infty & \\text{ otherwise,} \\end{array}\\right.\n\]\n\nso the dual of the reformulated program is:\n\n\[ \n\\text{maximize}\;{b...
Yes
The norm minimization of Example 50.13 can be reformulated as\n\n\\[ \n\\text{minimize}\\;\\frac{1}{2}\\parallel y{\\parallel }^{2} \n\\]\n\n\\[ \n\\text{subject to} \n\\]\n\n\\[ \n{Ax} - b = y. \n\\]
This program is obviously equivalent to the original one. By Example 50.8(7), the conjugate of the square norm is given by\n\n\\[ \n\\frac{1}{2}{\\left( \\parallel y{\\parallel }^{D}\\right) }^{2} \n\\]\n\nso the dual of the reformulated program is\n\n\\[ \n\\text{maximize}\\; - \\frac{1}{2}{\\left( \\parallel \\mu {\\...
Yes
Theorem 50.20. Suppose \( J : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \) is an elliptic functional, which means that \( J \) is continuously differentiable on \( {\mathbb{R}}^{n} \), and there is some constant \( \alpha > 0 \) such that\n\n\[ \left\langle {\nabla {J}_{v} - \nabla {J}_{u}, v - u}\right\rangle \geq \alph...
Proof.\n\nStep 1. We establish algebraic conditions relating the unique minimizer \( u \in U \) of \( J \) over \( U \) and some \( \lambda \in {\mathbb{R}}_{ + }^{m} \) such that \( \left( {u,\lambda }\right) \) is a saddle point.\n\nSince \( J \) is elliptic and \( U \) is nonempty closed and convex, by Theorem 49.8,...
No
Example 51.1. The above fact is illustrated by the function \( f : \mathbb{R} \rightarrow \mathbb{R} \cup \{ - \infty , + \infty \} \) where\n\n\[ f\left( x\right) = \left\{ \begin{array}{ll} - {x}^{2} & \text{ if }x \geq 0 \\ + \infty & \text{ if }x < 0 \end{array}\right. \]\n\nThe epigraph of this function is illustr...
If \( f \) is a convex function, since \( \operatorname{dom}\left( f\right) \) is the image of \( \operatorname{epi}\left( f\right) \) by a linear map (a projection), it is convex.\n\nBy definition, \( \operatorname{\mathbf{e} \mathbf{p} \mathbf{i} }\left( {f \mid S}\right) \) is convex iff for any \( \left( {{x}_{1},{...
Yes
Here is an example of an improper convex function \( f : \mathbb{R} \rightarrow \mathbb{R} \cup \{ - \infty , + \infty \} \) :\n\n\[ f\left( x\right) = \left\{ \begin{array}{ll} - \infty & \text{ if }\left| x\right| < 1 \\ 0 & \text{ if }\left| x\right| = 1 \\ + \infty & \text{ if }\left| x\right| > 1 \end{array}\right...
Observe that \( \operatorname{dom}\left( f\right) = \left\lbrack {-1,1}\right\rbrack \), and that \( \operatorname{epi}\left( f\right) \) is not closed. See Figure 51.4.
Yes
For an example of Propositions 51.6 and 51.5, let \( f : \mathbb{R} \rightarrow \mathbb{R} \cup \{ + \infty \} \) be the proper convex function\n\n\[ f\left( x\right) = \left\{ \begin{array}{ll} {x}^{2} & \text{ if }x < 1 \\ + \infty & \text{ if }\left| x\right| \geq 1 \end{array}\right. \]\n\nThen \( \operatorname{cl}...
and \( \operatorname{cl}f\left( x\right) = f\left( x\right) \) whenever \( x \in \left( {-\infty ,1}\right) = \operatorname{relint}\left( {\operatorname{dom}\left( f\right) }\right) = \operatorname{dom}\left( f\right) \) . Furthermore, since \( \operatorname{relint}\left( {\operatorname{dom}\left( f\right) }\right) = \...
Yes
Consider the proper convex function (on \( {\mathbb{R}}^{2} \) ) given by\n\n\[ f\left( {x, y}\right) = \left\{ \begin{array}{ll} {y}^{2}/\left( {2x}\right) & \text{ if }x > 0 \\ 0 & \text{ if }x = 0, y = 0 \\ + \infty & \text{ otherwise. } \end{array}\right. \]
The function \( f \) is continuous on the open right half-plane \( \left\{ {\left( {x, y}\right) \in {\mathbb{R}}^{2} \mid x > 0}\right\} \), but not at \( \left( {0,0}\right) \) . The limit of \( f\left( {x, y}\right) \) when \( \left( {x, y}\right) \) approaches \( \left( {0,0}\right) \) on the parabola of equation \...
Yes
Proposition 51.9. Let \( \varphi : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \) be a nonconstant affine form. Then the map \( \omega : {\mathbb{R}}^{n + 1} \rightarrow \) \( \mathbb{R} \) given by\n\n\[ \omega \left( {x,\alpha }\right) = \varphi \left( x\right) - \alpha ,\;x \in {\mathbb{R}}^{n},\alpha \in \mathbb{R}, \]...
Proof. Indeed, \( \varphi \) is of the form \( \varphi \left( x\right) = h\left( x\right) + c \) for some nonzero linear form \( h \), so\n\n\[ \omega \left( {x,\alpha }\right) = h\left( x\right) - \alpha + c. \]\n\nSince \( h \) is linear, the map \( \left( {x,\alpha }\right) = h\left( x\right) - \alpha \) is obviousl...
Yes
The \( {\ell }^{2} \) norm \( f\left( x\right) = \parallel x{\parallel }_{2} \) is subdifferentiable for all \( x \in {\mathbb{R}}^{n} \), in fact differentiable for all \( x \neq 0 \) . For \( x = 0 \), the set \( \partial f\left( 0\right) \) consists of all \( u \in {\mathbb{R}}^{n} \) such that
\[ \parallel z{\parallel }_{2} \geq \langle z, u\rangle \;\text{ for all }z \in {\mathbb{R}}^{n}, \] namely (by Cauchy-Schwarz), the Euclidean unit ball \( \left\{ {u \in {\mathbb{R}}^{n} \mid \parallel u{\parallel }_{2} \leq 1}\right\} \) . See Figure 51.14.
Yes
For the \( {\ell }^{\infty } \) norm if \( f\left( x\right) = \parallel x{\parallel }_{\infty } \), we leave it as an exercise to show that \( \partial f\left( 0\right) \) is the polyhedron
\[ \partial f\left( 0\right) = \operatorname{conv}\left\{ {\pm {e}_{1},\ldots , \pm {e}_{n}}\right\} . \]
No
The following function is an example of a proper convex function which is not subdifferentiable everywhere:
\[ f\left( x\right) = \left\{ \begin{array}{ll} - {\left( 1 - {\left| x\right| }^{2}\right) }^{1/2} & \text{ if }\left| x\right| \leq 1 \\ + \infty & \text{ otherwise. } \end{array}\right. \]
Yes
The subdifferential of an indicator function is interesting. Let \( C \) be a nonempty convex set. By definition, \( u \in \partial {I}_{C}\left( x\right) \) iff\n\n\[ \n{I}_{C}\left( z\right) \geq {I}_{C}\left( x\right) + \langle z - x, u\rangle \;\text{ for all }z \in {\mathbb{R}}^{n}.\n\]
Since \( C \) is nonempty, there is some \( z \in C \) such that \( {I}_{C}\left( z\right) = 0 \), so the above condition implies that \( x \in C \) (otherwise \( {I}_{C}\left( x\right) = + \infty \) but \( 0 \geq + \infty + \langle z - u, u\rangle \) is impossible), so \( 0 \geq \langle z - x, u\rangle \) for all \( z...
Yes
The subdifferentials of the indicator function \( f \) of the nonnegative orthant of \( {\mathbb{R}}^{n} \) reveal a connection to complementary slackness conditions. Recall that this indicator function is given by\n\n\[ f\left( {{x}_{1},\ldots ,{x}_{n}}\right) = \left\{ \begin{array}{ll} 0 & \text{ if }{x}_{i} \geq 0,...
By Example 51.8, the subgradients \( y \) of \( f \) at \( x \geq 0 \) form the normal cone to the nonnegative orthant at \( x \) . This means that \( y \in {N}_{C}\left( x\right) \) iff\n\n\[ \langle z - x, y\rangle \leq 0\;\text{ for all }z \geq 0 \]\n\niff\n\n\[ \langle z, y\rangle \leq \langle x, y\rangle \;\text{ ...
Yes
Theorem 51.10. (Minkowski) Let \( C \) be a nonempty convex set in \( {\mathbb{R}}^{n} \) . For any point \( a \in \) \( C - \operatorname{relint}\left( C\right) \), there is a supporting hyperplane \( H \) to \( C \) at a.
Theorem 51.10 is proven in Rockafellar [136] (Theorem 11.6). See also Berger [11] (Proposition 11.5.2). The proof is not as simple as one might expect, and is based on a geometric version of the Hahn-Banach theorem.
Yes
Proposition 51.11. Let \( C \) be any nonempty convex set in \( {\mathbb{R}}^{n} \) . For any \( x \in \mathbf{{relint}}\left( C\right) \) and any \( y \in \bar{C} \), we have \( \left( {1 - \lambda }\right) x + {\lambda y} \in \mathbf{{relint}}\left( C\right) \) for all \( \lambda \) such that \( 0 \leq \lambda < 1 \)...
Proposition 51.11 is proven in Rockafellar [136] (Theorem 6.1). The proof is not difficult but quite technical.
No
Proposition 51.12. For any proper convex function \( f \) on \( {\mathbb{R}}^{n} \), we have\n\n\[ \operatorname{relint}\left( {\operatorname{epi}\left( f\right) }\right) = \left\{ {\left( {x,\mu }\right) \in {\mathbb{R}}^{n + 1} \mid x \in \operatorname{relint}\left( {\operatorname{dom}\left( f\right) }\right), f\left...
Proof. Proposition 51.12 is proven in Rockafellar [136] (Lemma 7.3). By working in the affine hull of \( \mathbf{{epi}}\left( f\right) \), the statement of Proposition 51.12 is equivalent to\n\n\[ \operatorname{int}\left( {\mathbf{{epi}}\left( f\right) }\right) = \left\{ {\left( {x,\mu }\right) \in {\mathbb{R}}^{m + 1}...
Yes
Theorem 51.13. Let \( f \) be a proper convex function on \( {\mathbb{R}}^{n} \) . For any \( x \in \operatorname{relint}\left( {\operatorname{dom}\left( f\right) }\right) \) , there is a nonvertical supporting hyperplane \( \mathcal{H} \) to \( \mathbf{{epi}}\left( f\right) \) at \( \left( {x, f\left( x\right) }\right...
Proof. By Proposition 51.13, for any \( x \in \operatorname{relint}\left( {\operatorname{dom}\left( f\right) }\right) \), we have \( \left( {x,\mu }\right) \in \operatorname{relint}\left( {\operatorname{epi}\left( f\right) }\right) \) for all \( \mu \in \mathbb{R} \) such that \( f\left( x\right) < \mu \) . Since by de...
Yes
Proposition 51.14. Let \( f : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \cup \{ - \infty , + \infty \} \) be a convex function. For any \( x \in {\mathbb{R}}^{n} \) , if \( f\left( x\right) \) is finite, then the function\n\n\[ \lambda \mapsto \frac{f\left( {x + {\lambda u}}\right) - f\left( x\right) }{\lambda } \]\n\nis...
Proposition 51.14 is proven in Rockafellar [136] (Theorem 23.1). The proof is not difficult but not very informative.
Yes
Let \( f : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \cup \{ - \infty , + \infty \} \) be a convex function. For any \( x \in {\mathbb{R}}^{n} \) , if \( f\left( x\right) \) is finite, then a vector \( u \in {\mathbb{R}}^{n} \) is a subgradient to \( f \) at \( x \) if and only if\n\n\[ \n{f}^{\prime }\left( {x;y}\right)...
Sketch of proof. Proposition 51.15 is proven in Rockafellar [136] (Theorem 23.2). We prove the inequality. If we write \( z = x + {\lambda y} \) with \( \lambda > 0 \), then the subgradient inequality implies\n\n\[ \nf\left( {x + {\lambda u}}\right) \geq f\left( x\right) + \langle z - x, u\rangle = f\left( x\right) + \...
Yes
If \( f \) is the celebrated ReLU function (ramp function) from deep learning defined so that \[ \operatorname{ReLU}\left( x\right) = \max \{ x,0\} = \left\{ \begin{array}{ll} 0 & \text{ if }x < 0 \\ x & \text{ if }x \geq 0 \end{array}\right. \] then \( \partial \operatorname{ReLU}\left( 0\right) = \left\lbrack {0,1}\r...
The function ReLU is differentiable for \( x \neq 0 \) , with \( \operatorname{ReL}{\mathrm{U}}^{\prime }\left( x\right) = 0 \) if \( x < 0 \) and \( \operatorname{ReL}{\mathrm{U}}^{\prime }\left( x\right) = 1 \) if \( x > 0 \).
Yes
Proposition 51.16. Let \( f : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \cup \{ - \infty , + \infty \} \) be a convex function. For any \( x \in {\mathbb{R}}^{n} \), if \( f\left( x\right) \) is finite and if \( f \) is subdifferentiable at \( x \), then \( f \) is proper. If \( f \) is not subdifferentiable at \( x \), ...
Proposition 51.16 is proven in Rockafellar [136] (Theorem 23.3). It confirms that improper convex functions are rather pathological objects, because if a convex function is subdifferentiable for some \( x \) such that \( f\left( x\right) \) is finite, then \( f \) must be proper. This is because if \( f\left( x\right) ...
Yes
Theorem 51.17. Let \( f : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \cup \{ + \infty \} \) be a proper convex function. For any \( x \notin \operatorname{dom}\left( f\right) \) , we have \( \partial f\left( x\right) = \varnothing \) . For any \( x \in \operatorname{relint}\left( {\operatorname{dom}\left( f\right) }\right...
Theorem 51.17 is proven in Rockafellar [136] (Theorem 23.4).
Yes
Consider the proper convex function defined on \( {\mathbb{R}}^{2} \) given by\n\n\[ f\left( {x, y}\right) = \max \{ g\left( x\right) ,\left| y\right| \}\]\n\nwhere\n\n\[ g\left( x\right) = \left\{ \begin{array}{ll} 1 - \sqrt{x} & \text{ if }x \geq 0 \\ + \infty & \text{ if }x < 0 \end{array}\right.\]
It is easy to see that \( \operatorname{dom}\left( f\right) = \left\{ {\left( {x, y}\right) \in {\mathbb{R}}^{2} \mid x \geq 0}\right\} \), but\n\n\( \operatorname{dom}\left( {\partial f}\right) = \left\{ {\left( {x, y}\right) \in {\mathbb{R}}^{2} \mid x \geq 0}\right\} - \{ \left( {0, y}\right) \mid - 1 < y < 1\} \), ...
Yes
Theorem 51.18. Let \( f \) be a convex function on \( {\mathbb{R}}^{n} \), and let \( x \in {\mathbb{R}}^{n} \) such that \( f\left( x\right) \) is finite. If \( f \) is differentiable at \( x \) then \( \partial f\left( x\right) = \left\{ {\nabla {f}_{x}}\right\} \) (where \( \nabla {f}_{x} \) is the gradient of \( f ...
The first direction is easy to prove. Indeed, if \( f \) is differentiable at \( x \), then\n\n\[ {f}^{\prime }\left( {x;y}\right) = \left\langle {y,\nabla {f}_{x}}\right\rangle \;\text{ for all }y \in {\mathbb{R}}^{n}, \]\n\nso by Proposition 51.15, a vector \( u \) is a subgradient at \( x \) iff\n\n\[ \left\langle {...
Yes
Theorem 51.20. Let \( f \) be a proper convex function on \( {\mathbb{R}}^{n} \), and let \( D \) be the set of vectors where \( f \) is differentiable. Then \( D \) is a dense subset of \( \operatorname{int}\left( {\operatorname{dom}\left( f\right) }\right) \), and its complement in \( \operatorname{int}\left( {\opera...
Theorem 51.20 is proven in Rockafellar [136] (Theorem 25.5).
Yes
Proposition 51.22. Let \( {f}_{1},\ldots ,{f}_{n} \) be proper convex functions on \( {\mathbb{R}}^{n} \), and let \( f = {f}_{1} + \cdots + {f}_{n} \) . For \( x \in {\mathbb{R}}^{n} \), we have\n\n\[ \partial f\left( x\right) \supseteq \partial {f}_{1}\left( x\right) + \cdots + \partial {f}_{n}\left( x\right) \]\n\nI...
Proposition 51.22 is proven in Rockafellar [136] (Theorem 23.8).
Yes
Proposition 51.23. Let \( f \) be the function given by \( f\left( x\right) = h\left( {Ax}\right) \) for all \( x \in {\mathbb{R}}^{n} \), where \( h \) is a proper convex function on \( {\mathbb{R}}^{m} \) and \( A \) is an \( m \times n \) matrix. Then\n\n\[ \partial f\left( x\right) \supseteq {A}^{\top }\left( {\par...
Proposition 51.23 is proven in Rockafellar [136] (Theorem 23.9).
Yes
Proposition 51.24. Let \( f \) be a proper convex function on \( {\mathbb{R}}^{n} \), and let \( x \in {\mathbb{R}}^{n} \) be a vector such that \( f \) is subdifferentiable at \( x \) but \( f \) does not achieve its minimum at \( x \) . Then the normal cone \( {N}_{C}\left( x\right) \) at \( x \) to the sublevel set ...
Proposition 51.24 is proven in Rockafellar [136] (Theorem 23.7).
Yes
Proposition 51.31. Let \( f : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \cup \{ + \infty \} \) be any proper convex function. For any \( \epsilon > 0 \) , if \( {h}_{x} \) is given by\n\n\[ \n{h}_{x}\left( y\right) = f\left( {x + y}\right) - f\left( x\right) ,\;\text{ for all }y \in {\mathbb{R}}^{n},\n\]\n\nthen\n\n\[ \n...
Proof. We have\n\n\[ \n{h}_{x}^{ * }\left( y\right) = \mathop{\sup }\limits_{{z \in {\mathbb{R}}^{n}}}\left( {\langle y, z\rangle - {h}_{x}\left( z\right) }\right)\n\]\n\n\[ \n= \mathop{\sup }\limits_{{z \in {\mathbb{R}}^{n}}}\left( {\langle y, z\rangle - f\left( {x + z}\right) + f\left( x\right) }\right)\n\]\n\n\[ \n=...
Yes
Proposition 51.32. Let \( f \) be a closed and proper convex function, and let \( x \in {\mathbb{R}}^{n} \) such that \( f\left( x\right) \) is finite. Then
\[ {f}^{\prime }\left( {x;y}\right) = \mathop{\lim }\limits_{{\epsilon \downarrow 0}}{\delta }^{ * }\left( {y \mid {\partial }_{\epsilon }f\left( x\right) }\right) = \mathop{\lim }\limits_{{\epsilon \downarrow 0}}{I}_{{\partial }_{\epsilon }f\left( x\right) }^{ * }\left( y\right) \;\text{ for all }y \in {\mathbb{R}}^{n...
No
Proposition 51.33. Let \( f \) be a proper convex function over \( {\mathbb{R}}^{n} \) . A vector \( x \in {\mathbb{R}}^{n} \) belongs to the minimum set of \( f \) iff\n\n\[ 0 \in \partial f\left( x\right) \]\n\niff \( f\left( x\right) \) is finite and\n\n\[ {f}^{\prime }\left( {x;y}\right) \geq 0\;\text{ for all }y \...
Of course, if \( f \) is differentiable at \( x \), then \( \partial f\left( x\right) = \left\{ {\nabla {f}_{x}}\right\} \), and we obtain the well-known condition \( \nabla {f}_{x} = 0 \) .
Yes