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(i) Function \( f \) has at most one \( {\nabla }_{H} \) -derivative at \( \mathrm{t} \) .
Proof (i) The proof is easy and will be omitted.
No
(i) If \( \mathbb{T} = \mathbb{R} \), then \( f : \mathbb{R} \rightarrow {\mathbb{R}}_{\mathcal{F}} \) is \( {\nabla }_{H} \) -differentiable at \( t \) if and only if the limits\n\n\[ \mathop{\lim }\limits_{{h \rightarrow {0}^{ + }}}\frac{f\left( {t + h}\right) { \ominus }_{g}f\left( t\right) }{h}\text{ and }\mathop{\...
\[ {f}^{{\nabla }_{H}}\left( t\right) = \mathop{\lim }\limits_{{h \rightarrow {0}^{ + }}}\frac{f\left( {t + h}\right) { \ominus }_{g}f\left( t\right) }{h} = \mathop{\lim }\limits_{{h \rightarrow {0}^{ + }}}\frac{f\left( t\right) { \ominus }_{g}f\left( {t - h}\right) }{h}. \]
Yes
If \( f : \mathbb{T} \rightarrow {\mathbb{R}}_{\mathcal{F}} \) is defined by \( f\left( t\right) = \left\lbrack {0,{t}^{2}}\right\rbrack \) for all \( t \in \mathbb{T} \mathrel{\text{:=}} \left\{ {\frac{n}{2} : n \in {\mathbb{N}}_{0}}\right\} \) , then from Theorem 3.2 (ii), we have that \( f \) is \( {\nabla }_{H} \) ...
\[ {f}^{{\nabla }_{H}}\left( t\right) = \frac{f\left( t\right) { \ominus }_{g}{f}^{\rho }\left( t\right) }{\eta \left( t\right) } = \frac{\left\lbrack {0,{t}^{2}}\right\rbrack - \left\lbrack {0,{t}^{2} - t + \frac{1}{4}}\right\rbrack }{\frac{1}{2}} = \left\lbrack {0,{2t} - \frac{1}{2}}\right\rbrack . \]
Yes
Theorem 3.5 Assume that \( f, g : \mathbb{T} \rightarrow {\mathbb{R}}_{\mathcal{F}} \) are \( {\nabla }_{H} \) -differentiable at \( t \in {\mathbb{T}}_{k} \) . Then\n\n(i) for any constants \( {\lambda }_{1},{\lambda }_{2} \), the sum \( \left( {{\lambda }_{1}f \oplus {\lambda }_{2}g}\right) : \mathbb{T} \rightarrow {...
Proof (i) Since \( f \) and \( g \) are \( {\nabla }_{H} \) -differentiable at \( t \in {\mathbb{T}}_{k} \), for any \( \epsilon > 0 \), there exist neighborhoods \( {U}_{1} \) and \( {U}_{2} \) of \( t \) with\n\n\[ \n\left\{ \begin{array}{l} D\left\lbrack {{\lambda }_{1}f\left( {t + h}\right) { \ominus }_{g}{\lambda ...
Yes
Theorem 2.5 Every non-associative superalgebra \( \left( {A, \cdot }\right) \) has an Akivis superalgebra \( \left( {A,\circ ,\left\lbrack {-,-, - }\right\rbrack }\right) \) structure with respect to the operation defined by\n\n\[ x \circ y = x \cdot y - {\left( -1\right) }^{\left| x\right| \left| y\right| }y \cdot x, ...
Proof First, we proceed to verify that \
No
Lemma 2.6 Let \( \\left( {A, \\cdot }\\right) \) be a Leibniz superalgebra, and consider on \( \\left( {A, \\cdot }\\right) \) the operation \( \\left\\lbrack {x, y}\\right\\rbrack \\mathrel{\\text{:=}} x \\cdot y - {\\left( -1\\right) }^{\\left| x\\right| \\left| y\\right| }y \\cdot x \) for all \( x, y \\in {hg}\\lef...
Proof (i) Equation (2.1) implies that \n\n\[ \n\\left( {x \\cdot y}\\right) \\cdot z = x \\cdot \\left( {y \\cdot z}\\right) - {\\left( -1\\right) }^{\\left| x\\right| \\left| y\\right| }y \\cdot \\left( {x \\cdot z}\\right) . \n\] \n\n\\left( {2.13}\\right) \n\nLikewise, interchanging \( x \) and \( y \), we have \n\n...
Yes
Lemma 2.7 Let \( \left( {A, \cdot }\right) \) be a Leibniz superalgebra, \( \left( {A,\circ ,\left\lbrack {-,-, - }\right\rbrack }\right) \) be an Akivis super-algebra associated with Leibniz superalgebra \( \left( {A,}\right) \) . Then\n\n\[ \n{\circlearrowleft }_{x, y, z}{\left( -1\right) }^{\left| x\right| \left| z\...
Proof We get the result from equation (2.10).
No
Proposition 2.14 Let \( \left( {A, \prec , \succ }\right) \) be a dendriform superalgebra. Define two even bilinear maps \( * ,\left\lbrack {-, - }\right\rbrack : A \times A \rightarrow A \) such that \( x * y = x \prec y + y \succ x,\left\lbrack {x, y}\right\rbrack = {\left( -1\right) }^{\left| x\right| \left| y\right...
Proof Calculate directly,\n\n\[ \left\lbrack {x,\left\lbrack {y, z}\right\rbrack }\right\rbrack = {\left( -1\right) }^{\left| y\right| \left| z\right| + \left| x\right| \left( {\left| y\right| + \left| z\right| }\right) }\left( {z \prec y}\right) \prec x + {\left( -1\right) }^{\left| y\right| \left| z\right| + \left| x...
Yes
Theorem 3.4 Every (left) Leibniz superalgebra \( \left( {A, \cdot }\right) \) has a Lie-Yamaguti superalgebra structure \( \left( {A,\left\lbrack {-, - }\right\rbrack ,\{ -,-, - \} }\right) \) with respect to the operation defined by\n\n\[ \left\lbrack {x, y}\right\rbrack \mathrel{\text{:=}} x \cdot y - {\left( -1\righ...
Proof Equations (3.2), (2.1) and (2.8) imply\n\n\[ \{ x, y, z\} = - \left( {x \cdot y}\right) \cdot z. \]\n\n(3.3)\n\nMoreover, we have\n\n\[ \left\lbrack {x, y}\right\rbrack \cdot z = \left( {x \cdot y - {\left( -1\right) }^{\left| x\right| \left| y\right| }y \cdot x}\right) \cdot z = 2\left( {x \cdot y}\right) \cdot ...
Yes
Example 3.6 Let \( A = {A}_{\overline{0}} \oplus {A}_{\overline{1}} \) be a 3-dimensional superspace. \( {A}_{\overline{0}} = \operatorname{span}\left\{ {{e}_{1},{e}_{3}}\right\} \) , \( {A}_{\mathrm{I}} = \operatorname{span}\left\{ {e}_{2}\right\} \) . The nonzero product is given by \( {e}_{2} \cdot {e}_{3} = {e}_{2}...
By Theorem 2.8, when we define the binary operation and the ternary operation by (3.1) and (3.2), we get a Lie-Yamaguti superalgebra \( \left( {A,\left\lbrack {-, - }\right\rbrack ,\{ -,-, - \} }\right) \) with nonzero product\n\n\[ \left\lbrack {{e}_{2},{e}_{3}}\right\rbrack = 2{e}_{2} = - \left\lbrack {{e}_{3},{e}_{2...
No
Theorem 2.3 Let \( \vartheta \) denote a prime of \( {R}_{d},\delta = \sqrt{d}, D = - d \) . For an arbitrary positive integer \( n \), the equivalence classes of \( {R}_{d}/\left\langle {\vartheta }^{n}\right\rangle \) are of the following types:\n\n(1) \( {R}_{d}/\left\langle {\delta }^{2m}\right\rangle = \left\{ {\l...
Proof (1) As \( {\delta }^{2m} = {d}^{m} \), we get that \( \left\langle {\delta }^{2m}\right\rangle = \left\langle {D}^{m}\right\rangle \) . Suppose \( \alpha = {a}_{1} + {a}_{2}\sqrt{d} \in {R}_{d} \) , where \( {a}_{1},{a}_{2} \in \mathbb{Z} \) . Let \( {a}_{i} = {D}^{m}{k}_{i} + {r}_{i} \) with \( 0 \leq {r}_{i} \l...
Yes
To illustrate the case \( d = - {19}, q = {23} = \pi \bar{\pi } \) and \( n = 2 \), let \( \gamma = \) \( \frac{1}{2}\left( {{b}_{1} + {b}_{2}\sqrt{-{19}}}\right) \in {R}_{d} \), where \( {b}_{1} = 3 \) and \( {b}_{2} = 1 \). We give the equivalence class in \( {R}_{d}/\left\langle {\pi }^{2}\right\rangle \) which \( \...
Since \( \pi = 2 - \sqrt{-{19}} \) is a proper factor of \( q \) in \( {R}_{d},{\pi }^{2} = - {15} - 4\sqrt{-{19}} = \) \( \frac{-{30}}{2} - \frac{8}{2}\sqrt{-{19}} \) . Denoted by \( s = - {30}, t = - 8 \) . Substituting the values for \( s, t,{b}_{1},{b}_{2}, d, q \) and \( n \) into congruence (2.6), we get that \( ...
Yes
Theorem 2.6 Let \( \bar{R} = {R}_{d}/\left\langle {\left( \sqrt{d}\right) }^{n}\right\rangle, n \) is an arbitrary positive integer. Let \( D = - d \) . Then the unit groups \( U\left( \bar{R}\right) \) of \( \bar{R} \) are as the follows:\n\n(1) Let \( n = 1 \) . Then \( U\left( \bar{R}\right) \cong {\mathbb{Z}}_{D - ...
Proof (1) If \( n = 1 \), by Theorem 2.1 (2), \( \bar{R} \) is a field of order \( D = - d \), so \( \left| {U\left( \bar{R}\right) }\right| = D - 1 \) . Therefore, \( U\left( \bar{R}\right) \) is a cyclic group of order \( D - 1 \) and hence \( U\left( \bar{R}\right) \cong {\mathbb{Z}}_{D - 1} \) .
Yes
Theorem 2.7 Let \( p \in \mathbb{Z} \) be an odd prime satisfying the Legendre symbol \( \left( \frac{p}{-d}\right) = - 1 \) . Let \( \bar{R} = {R}_{d}/\left\langle {p}^{n}\right\rangle, n \geq 1 \) . Then \( U\left( \bar{R}\right) \cong {\mathbb{Z}}_{{p}^{2} - 1} \times {\mathbb{Z}}_{{p}^{n - 1}} \times {\mathbb{Z}}_{...
Proof For \( \alpha = \left\lbrack {a + b\sqrt{d}}\right\rbrack \in {R}_{d}/\left\langle {p}^{n}\right\rangle \), where \( 0 \leq a, b \leq {p}^{n} - 1 \), it is easy to prove that \( \alpha \) is a unit of \( \bar{R} \) if and only if \( p \nmid \left( {{a}^{2} - d{b}^{2}}\right) \) . So \( \left| {U\left( \bar{R}\rig...
Yes
Theorem 2.8 Let \( q \in \mathbb{Z} \) be a prime satisfying the Legendre symbol \( \left( \frac{q}{-d}\right) = 1 \) . Suppose that \( \pi \) is a proper factor of \( q \) . Let \( \bar{R} = {R}_{d}/\left\langle {\pi }^{n}\right\rangle, n \geq 1 \) .\n\n(1) Suppose \( q = 2 \) . Then \( U\left( \bar{R}\right) \cong {\...
Proof Applying Theorem 2.1 (4), we derive that \( \bar{R} \cong \mathbb{Z}/\left\langle {q}^{n}\right\rangle \) . So the theorem follows.
No
Theorem 2.9 Suppose \( d = - 3, - {11}, - {19}, - {43}, - {67}, - {163} \) . Let \( \bar{R} = {R}_{d}/\left\langle {2}^{n}\right\rangle, n \geq 2 \) . Then\n\n(1) \( U\left( \bar{R}\right) = {\bar{R}}_{1} \cup {\bar{R}}_{2} \cup {\bar{R}}_{3} \), where\n\n\( {\bar{R}}_{1} = \left\{ {\left\lbrack {{r}_{1} + {r}_{2}\sqrt...
Proof (1) If \( \alpha = \left\lbrack {{r}_{1} \pm {r}_{2}\sqrt{d}}\right\rbrack \in \bar{R} \), where \( {r}_{1},{r}_{2} \in \mathbb{Z} \), it is easy to show that \( \alpha \in U\left( \bar{R}\right) \) if and only if \( 2 \nmid N\left( \alpha \right) \), i.e., \( 2 \nmid \left( {{r}_{1}^{2} - d{r}_{2}^{2}}\right) \)...
Yes
Consider the following second-order four-point nonlinear ordinary differential equation \( \left\lbrack {{15},{29}}\right\rbrack \)\n\n\[ x\left( {1 - x}\right) {\mu }^{\prime \prime }\left( x\right) + 6{\mu }^{\prime }\left( x\right) + {2\mu }\left( x\right) + {\mu }^{2}\left( x\right) = f\left( x\right) ,\;0 \leq x \...
The exact solution is given by \( \mu \left( x\right) = \sinh \left( x\right) \) . In Table 1, we list the absolute errors at some different points obtained by the present method with \( k = 3 \) and \( M = 4,6,8,{10} \) . As we see from this table, it is clear that the result obtained by the present method is superior...
Yes
Consider the following third-order three-point nonlinear boundary value problems (see [13]) \( {\mu }^{\prime \prime \prime }\left( x\right) = {e}^{-x}{\mu }^{2}\left( x\right) ,0 \leq x \leq 1 \) with the following nonlinear conditions\n\n\[ \mu \left( 0\right) + 2{\mu }^{\prime 2}\left( \frac{1}{2}\right) - \mu \left...
The exact solution is \( \mu \left( x\right) = {e}^{x} \).
No
Consider the following fourth-order three-point linear boundary value problem \( \left\lbrack {{18},{22}}\right\rbrack \)\n\n\[ \n{\mu }^{\left( 4\right) }\left( x\right) = {e}^{x}{\mu }^{\prime \prime \prime }\left( x\right) - \mu \left( x\right) - {e}^{x}\cosh \left( x\right) + 2\sinh \left( x\right) + 1,0 \leq x \le...
The exact solution is \( \mu \left( x\right) = 1 + \sinh \left( x\right) \) . In Table 3, we compare the absolute errors at some different points obtained by the present method and reproducing kernel methods in [18] and differential transform method in [22]. In Figure 3, we show the maximum absolute errors at selected ...
Yes
Example 4 Consider the following fifth-order four-point boundary value problems [18]\n\n\\[ \n{\\mu }^{\\left( 5\\right) }\\left( x\\right) + \\sin \\left( {2x}\\right) {\\mu }^{\\prime \\prime \\prime }\\left( x\\right) - {\\mu }^{\\prime }\\left( x\\right) + \\cos \\left( {2x}\\right) \\mu \\left( x\\right) = - \\sin...
The exact solution is \\( \\mu \\left( x\\right) = \\sin x \\) . In Table 4, we compare the absolute errors at some different points obtained by the present method and the reproducing kernel method (RKM) in [18]. In Figure 4, we show the maximum absolute errors at selected points with \\( k = 3 \\) and \\( M = 3 \\) th...
Yes
Example 5 Consider following seventh-order three-point nonlinear boundary value problems [31]\n\n\\[ \n{\\mu }^{\\left( 7\\right) }\\left( x\\right) = \\mu \\left( x\\right) {\\mu }^{\\prime }\\left( x\\right) - {e}^{x}\\left( {6 + x - x{e}^{x} + {x}^{2}{e}^{x}}\\right) ,\\;0 \\leq x \\leq 1 \n\\]\n\nwith boundary cond...
The exact solution is \\( \\mu \\left( x\\right) = \\left( {1 - x}\\right) {e}^{x} \\) . In Table 5, we compare the absolute errors at some different points obtained by the present method and variational iteration method (VIM) in [31]. In Figure 5, we show the maximum absolute errors at selected points with \\( k = 3 \...
Yes
Lemma 2.2 (Non-homogeneous linear estimate) Let \( s \in \mathbb{R} \), there exists \( C > 0 \) such that, for any \( f \in {X}^{s, b - 1} \) ,
\[ {\begin{Vmatrix}{\theta }_{T}\left( t\right) {\int }_{0}^{t}V\left( t - {t}^{\prime }\right) f\left( {t}^{\prime }\right) \mathrm{d}{t}^{\prime }\end{Vmatrix}}_{{X}^{s, b}} \leq C{T}^{\frac{1 - {2b}}{2}}\parallel f{\parallel }_{{X}^{s, b - 1}} \]
No
Lemma 3.1 (see [4, Propositon 6.1]) Let \( H,{N}_{1},{N}_{2},{N}_{3},{L}_{1},{L}_{2},{L}_{3} > 0 \) obey (3.5)-(3.7) and let the dispersion relations be given by (3.4).\n\n(i) If \( {N}_{\max } \sim {N}_{\min } \) and \( {L}_{\max } \sim H \), then we have\n\n\[ \left( {3.3}\right) \lesssim {L}_{\min }^{\frac{1}{2}}{N}...
(3.8)
No
Proposition 3.1 For \( s > - 1 \) and \( u, v \in {X}^{s, b} \), there exists \( b \in \left( {1/2,1}\right) \) such that the bilinear inequality holds\n\n\[ \n{\begin{Vmatrix}{u}_{x}{v}_{x}\end{Vmatrix}}_{{X}^{s, b - 1}} \lesssim \parallel u{\parallel }_{{X}^{s, b}}\parallel v{\parallel }_{{X}^{s, b}}, \]\n\n(3.11)\n\...
Proof By Plancherel's formula and duality, it suffices to show that\n\n\[ \n{\begin{Vmatrix}\frac{\langle {\xi }_{1}{\rangle }^{-s}\langle {\xi }_{2}{\rangle }^{-s}\langle {\xi }_{3}{\rangle }^{s}{\xi }_{1}{\xi }_{2}}{\langle i\left( {{\tau }_{1} - {\xi }_{1}^{3}}\right) + {\xi }_{1}^{4} - {\xi }_{1}^{2}{\rangle }^{b}\...
Yes
Example 2 Let \( X \) be a finite set defined as \( X = \{ 1,2,3,4\} \) . Define \( d : X \times X \rightarrow \lbrack 0,\infty ) \) as\n\n\[ d\left( {1,1}\right) = d\left( {2,2}\right) = d\left( {3,3}\right) = d\left( {4,4}\right) = 0, \]\n\n\[ d\left( {1,2}\right) = d\left( {2,1}\right) = 3 \]\n\n\[ d\left( {2,3}\rig...
The function \( d \) is not a metric on \( X \) . Indeed, note that\n\n\[ 3 = d\left( {1,2}\right) \geq d\left( {1,3}\right) + d\left( {3,2}\right) = 1 + 1 = 2, \]\n\nthat is, the triangle inequality is not satisfied. However \( d \) is a generalized metric on \( X \) , moreover, \( \left( {X, d}\right) \) is a complet...
Yes
Lemma 3.1 Assume (A1)-(A3). Then \( {\widehat{\beta }}_{n},{\widehat{\theta }}_{n} \) and \( {\widehat{\sigma }}_{n}^{2} \), the QML estimators of \( \beta ,\theta \) and \( {\sigma }^{2} \) in model (1.1)-(1.2) exist. And as \( n \rightarrow \infty \) , \[ \left( {{\widehat{\mathcal{G}}}_{n},{\widehat{\sigma }}_{n}^{2...
Proof See Theorem 3.1 and Theorem 3.2 in Hu [8].
No
Lemma 4.1 (i) If \( \alpha < {\delta \eta } \), an optimal strategy does not exist and \( V\left( x\right) = \infty \) .
Proof This lemma can be proved analogously as in the proof of [11, Lemma 5.1].\n\n(i) Let \( {D}^{0} \in \mathcal{D} \) with the barrier \( b = 0 \) . We define the strategy \( {D}_{t}^{\left( 0, a\right) } = {D}_{t}^{0} + {at} \) for some \( a > 0 \) . Now, we have \( {R}_{t}^{\left( 0, a\right) } \leq 0 \) and\n\n\[ ...
Yes
Theorem 1.4 If \( n = {p}^{\alpha }{q}^{\beta }{n}_{1} > {pq} \), then
\[ {\varphi }_{pq}\left( n\right) = \left\{ \begin{array}{ll} {\varphi }_{pq}\left( {n}_{1}\right) , & \alpha = \beta = 0; \\ {\varphi }_{q}\left( {n}_{1}\right) - {\varphi }_{pq}\left( {n}_{1}\right) , & \alpha = 1,\beta = 0; \\ {\varphi }_{p}\left( {n}_{1}\right) - {\varphi }_{pq}\left( {n}_{1}\right) , & \alpha = 0,...
Yes
Theorem 1.5 For \( n = {p}^{\alpha }{q}^{\beta }{n}_{1} > {pq} \) .
(1) If \( \alpha = \beta = 0 \), then\n\n\[ \n{\varphi }_{pq}\left( n\right) = \left\{ \begin{array}{ll} \frac{\varphi \left( n\right) }{pq}, & {p}_{i} \equiv 1\left( {\;\operatorname{mod}\;{pq}}\right) \left( {i = 1,\cdots, k}\right) ; \\ \frac{1}{pq}\varphi \left( n\right) + \frac{\left( {{pq} - 2}\right) {\left( -1\...
No
Lemma 2.4 Let \( \alpha > 0, m \in \mathbb{N} \) and \( D = d/{dx} \) . If the fractional derivatives \( \left( {{D}_{0 + }^{\alpha }y}\right) \left( t\right) \) and \( \left( {{D}_{0 + }^{\alpha + m}y}\right) \left( t\right) \) exist, then
\[ \left( {{D}^{m}{D}_{0 + }^{\alpha }y}\right) \left( t\right) = \left( {{D}_{0 + }^{\alpha + m}y}\right) \left( t\right) \]
Yes
Lemma 3.1 If \( u\left( {x, t}\right) \) is a positive solution of problems (1.1)-(1.2) in the domain \( D \) , then \( v\left( t\right) \) satisfies the fractional differential inequality\n\n\[ \frac{d}{dt}\left( {{D}_{0 + }^{\alpha }v\left( t\right) \omega \left( t\right) }\right) \leq \frac{\omega \left( t\right) }{...
Proof Let \( u\left( {x, t}\right) \) is a positive solution of problem (1.1)-(1.2) in the domain \( D \), then there exists \( {t}_{0} > 0 \), such that \( u\left( {x, t}\right) > 0 \) in \( \Omega \times \left\lbrack {{t}_{0},\infty }\right) \) . Integrating (1.1) with respect to \( x \) over \( \Omega \) yields\n\n\...
Yes
Lemma 3.2 If \( u\left( {x, t}\right) \) is a negative solution of problems (1.1)-(1.2) in the domain \( D \) , then \( v\left( t\right) \) satisfies the fractional differential inequality\n\n\[ \frac{d}{dt}\left( {{D}_{0 + }^{\alpha }v\left( t\right) \omega \left( t\right) }\right) \geq \frac{\omega \left( t\right) }{...
Proof Let \( u\left( {x, t}\right) \) is a negative solution of problems (1.1)-(1.2) in the domain \( D \), then there exists \( {\bar{t}}_{0} > 0 \), such that \( u\left( {x, t}\right) < 0 \) in \( \Omega \times \left\lbrack {{\bar{t}}_{0},\infty }\right) \) . Integrating (1.1) with respect to \( x \) over \( \Omega \...
Yes
Theorem 3.3 If inequality (3.1) has no eventually positive solutions and the inequality (3.3) has no eventually negative solutions, then every solution of problems (1.1)-(1.2) is oscillatory in \( D \) .
Proof Suppose to the contrary that there is a nonoscillatory solution \( u\left( {x, t}\right) \) of problems (1.1)-(1.2). It is obvious that there exists \( {\widetilde{t}}_{0} \) such that \( u\left( {x, t}\right) > 0 \) or \( u\left( {x, t}\right) < 0 \) for \( t \geq {\widetilde{t}}_{0} \). If \( u\left( {x, t}\rig...
Yes
Lemma 3.4 If\n\n\\[ \n\\mathop{\\liminf }\\limits_{{t \\rightarrow + \\infty }}{\\int }_{{t}_{1}}^{t}\\frac{M + {\\int }_{{t}_{1}}^{\\rho }\\frac{\\omega \\left( s\\right) }{r\\left( s\\right) }G\\left( s\\right) {ds}}{\\omega \\left( \\rho \\right) }{d\\rho } = - \\infty ,\n\\]\n\nthen inequality (3.1) has no eventual...
Proof Suppose to the contrary that (3.1) has a positive solution \\( v\\left( t\\right) \\), then there exists \\( {t}_{1} \\geq {t}_{0} \\) such that \\( v\\left( t\\right) > 0, t \\geq {t}_{1} \\) . Integrating both sides of (3.1) from \\( {t}_{1} \\) to \\( t \\), we obtain\n\n\\[ \n\\left( {{D}_{0 + }^{\\alpha }v\\...
Yes
Theorem 2.9 Under Assumptions 2.1-2.5, design sliding mode function \( s\left( t\right) = {D}_{t}^{q - 1}\left( {{e}_{1} + }\right. \) \( \left. {{e}_{2} + {e}_{3}}\right) \), choosing controller
Proof When the systems state moving on the sliding mode surface, \( s\left( t\right) = 0,\dot{s}\left( t\right) = 0 \) , then \( s\left( t\right) = {D}_{t}^{q - 1}\left( {{e}_{1} + {e}_{2} + {e}_{3}}\right) = 0 \), so we get \( {D}_{t}^{1 - q}{D}_{t}^{q - 1}\left( {{e}_{1} + {e}_{2} + {e}_{3}}\right) = 0 \), such that ...
Yes
Theorem 1.1 Suppose \( \\left\\{ {{X}_{n}, n \\geq 0}\\right\\} \) is a countable nonhomogeneous Markov chain taking values in \( S = \\{ 1,2,\\cdots \\} \) with initial distribution of (1.1) and transition matrices of (1.2). Assume that \( f \) is a real function satisfying \( \\left| {f\\left( x\\right) }\\right| \\l...
\[ \\mathop{\\lim }\\limits_{{n \\rightarrow \\infty }}\\mathop{\\sup }\\limits_{{m \\geq 0}}\\frac{1}{n}\\mathop{\\sum }\\limits_{{k = 1}}^{n}\\begin{Vmatrix}{{P}_{k + m} - P}\\end{Vmatrix} = 0 \] (1.4) and \[ \\theta = \\mathop{\\sum }\\limits_{{i \\in S}}\\pi \\left( i\\right) \\left\\lbrack {{f}^{2}\\left( i\\right...
Yes
Lemma 2.3 Assume that \( \\left\\{ {{X}_{n}, n \\geq 0}\\right\\} \) is a countable nonhomogeneous Markov chain taking values in \( S = \\{ 1,2,\\cdots \\} \) with initial distribution (1.1), and transition matrices (1.2). Suppose that \( P \) is a periodic strongly ergodic stochastic matrix, and \( R \) is matrix each...
\[ \\mathop{\\lim }\\limits_{{n \\rightarrow \\infty }}\\frac{1}{n}{L}_{n}\\left( i\\right) = \\pi \\left( i\\right) \\text{ a.e.. } \]
Yes
Theorem 3.1 Let \( H \) be a real Hilbert space, and \( K : H \rightarrow {2}^{H} \) be a set-valued mapping such that for each \( u \in H, K\left( u\right) \subset H \) is a closed convex set and \( f : H \rightarrow R \cup \{ + \infty \} \) be proper, convex and lower semicontinuous on \( K\left( u\right) \) . Let \(...
Proof Let \( F : H \rightarrow H \) be defined as follows\n\n\[ F\left( u\right) = u - {ahu} + a{P}_{K\left( u\right) }^{f,\rho }\left\lbrack {{hu} - \rho \left( {M\left( {{Au},{Bu}}\right) - N\left( {{Cu},{Du}}\right) }\right) }\right\rbrack ,\forall u \in H, \]\n\nwhere \( a > 0 \) is a constant. For any \( u, v \in ...
Yes
Theorem 4.1 Let \( H, K, M, N, A, B, C, D, h \) be same as in Theorem 3.1 and satisfy conditions (i)-(iv) in Theorem 3.1. If the following conditions hold\n\n(a) \( N \) is \( v \) - \( h \) -relaxed Lipschitz with respect to \( A \) and \( B \) ;\n\n(b) there exists \( 0 < k < \frac{\mu + v}{\beta + \gamma } \) such t...
Proof Let \( x = {P}_{K\left( {u}^{ * }\right) }^{f,\rho }\left\lbrack {{hu} - \rho \left( {M\left( {{Au},{Bu}}\right) - N\left( {{Cu},{Du}}\right) }\right) }\right\rbrack \) . Since \( {u}^{ * } \) is the solution of GIMQVI (2.1), then, for all \( \rho > 0 \), we have\n\n\[ \left\langle {\rho \left( {M\left( {A{u}^{ *...
Yes
Theorem 4.5 Let \( H, K, M, N, A, B, C, D, h \) be same as in Theorem 3.1 and satisfy conditions (i)-(iv) in Theorem 3.1 and condition (a) in Theorem 4.1. If the following condition holds\n\n(b3) there exists \( 0 < k < \frac{\mu + v}{\beta + \gamma } \) such that for any \( \rho > \frac{\alpha \left( {\alpha + {8k}}\r...
Proof Let \n\n\[ x = {hu} - {\rho y}, y = M\left( {{Au},{Bu}}\right) - N\left( {{Cu},{Du}}\right) , \]\n\n\[ {x}^{ * } = h{u}^{ * } - \rho {y}^{ * },{y}^{ * } = M\left( {A{u}^{ * }, B{u}^{ * }}\right) - N\left( {C{u}^{ * }, D{u}^{ * }}\right) . \]\n\nFrom the definition of \( e\left( {u,\rho }\right) \), we have\n\n\[ ...
Yes
Corollary 2 Let \( f \in {F}_{\alpha }^{2} \), and \( {f}^{\prime },{f}^{\prime \prime } \in {F}_{\alpha }^{2} \), then we have\n\n\[ \n{\begin{Vmatrix}\frac{{f}^{\prime }}{\alpha } + zf\end{Vmatrix}}_{2,\alpha }{\begin{Vmatrix}\frac{{f}^{\prime }}{\alpha } - zf\end{Vmatrix}}_{2,\alpha } \geq {\left( \frac{\parallel f{...
Proof This follows directly from Theorem 3 by setting \( a = b = 0 \) .
No
Corollary 3 Let \( f \in {F}_{\alpha }^{2} \) and \( {f}^{\prime },{f}^{\prime \prime } \in {F}_{\alpha }^{2} \) . For any \( \delta > 0 \), then we have\n\n\[ \frac{\delta }{2}{\begin{Vmatrix}\frac{{f}^{\prime }}{\alpha } + zf\end{Vmatrix}}_{2,\alpha }^{2} + \frac{1}{2\delta }{\begin{Vmatrix}\frac{{f}^{\prime }}{\alph...
Proof From Corollary 2, we have the following estimates\n\n\[ {\left( \frac{\parallel f{\parallel }_{2,\alpha }^{4}}{{\alpha }^{2}} + {\left| \left\langle \frac{{f}^{\prime \prime }}{{\alpha }^{2}}, f\right\rangle - \left\langle {z}^{2}f, f\right\rangle \right| }^{2}\right) }^{\frac{1}{2}} \leq {\begin{Vmatrix}\frac{{f...
Yes
Corollary 7 Suppose \( f \) is any function in \( {F}_{\alpha }^{2} \), not identically zero, and \( {f}^{\prime },{f}^{\prime \prime } \in {F}_{\alpha }^{2} \) , then we have\n\n\[ \operatorname{dist}\left( {\frac{{f}^{\prime }}{\alpha } + {zf},\left\lbrack f\right\rbrack }\right) \operatorname{dist}\left( {\frac{{f}^...
Proof This is an equivalent state of Corollary 4, because\n\n\[ \operatorname{dist}\left( {\frac{{f}^{\prime }}{\alpha } + {zf},\left\lbrack f\right\rbrack }\right) = {\begin{Vmatrix}\frac{{f}^{\prime }}{\alpha } + zf\end{Vmatrix}}_{2,\alpha }\left| {\sin \left( {\theta }_{ + }\right) }\right| \]\n\nand\n\n\[ \operator...
Yes
Corollary 8 If \( f \) is any function in \( {F}_{\alpha }^{2} \), Suppose \( T \) is any operator on \( {F}_{\alpha }^{2} \) such that \( \left\lbrack {T,{T}^{ * }}\right\rbrack = {mI} \), then we have\n\n\[ \n{\begin{Vmatrix}Tf + {T}^{ * }f - af\end{Vmatrix}}_{2,\alpha }{\begin{Vmatrix}Tf - {T}^{ * }f + ibf\end{Vmatr...
Proof This follows from the proofs of Lemma 2 and Theorem 3.
No
Theorem 7 Let \( f,{f}^{\prime } \in {F}_{\alpha }^{2} \), for any \( a,{b}_{0},{b}_{1} \in \mathbb{C} \), then we have\n\n\[{\left\{ {\begin{Vmatrix}\frac{{f}^{\prime }}{\alpha } - \overline{{b}_{0}}f - \overline{{b}_{1}}zf\end{Vmatrix}}_{2,\alpha }^{2} + {\begin{Vmatrix}zf - {b}_{0}f - \frac{{b}_{1}{f}^{\prime }}{\al...
Proof By (3.10), we get\n\n\[ \langle \left\lbrack {A, B}\right\rbrack f, f\rangle = \langle \left\lbrack {A, B}\right\rbrack f, f\rangle + \langle \left\lbrack {B, V}\right\rbrack f, f\rangle + \langle \left\lbrack {U, A}\right\rbrack f, f\rangle + \langle \left\lbrack {V, U}\right\rbrack f, f\rangle \]\n\n\[ = \left\...
Yes
Theorem 1.1 (1) Let \( F \in \operatorname{Rat}\left( {{\mathbb{B}}^{n},{\mathbb{B}}^{N}}\right) \) with the geometric rank of \( F \) being \( {\kappa }_{0} \) and \( N = n + \frac{\left( {{2n} - {\kappa }_{0} - 1}\right) {\kappa }_{0}}{2}. \) Suppose that \( \frac{{\kappa }_{0}\left( {{\kappa }_{0} + 1}\right) }{2} <...
(2) Conversely, if \( F \) is defined by (1.1) and (1.2), then the map \( F \) is in \( \operatorname{Rat}\left( {{\mathbb{B}}^{n},{\mathbb{B}}^{N}}\right) \) with \( N = n + \frac{\left( {{2n} - {\kappa }_{0} - 1}\right) {\kappa }_{0}}{2} \) .
Yes
Lemma 2.1 Let \( F \in {\operatorname{Prop}}_{2}\left( {{\mathbb{H}}_{n},{\mathbb{H}}_{N}}\right) \) with \( 2 \leq n \leq N \) . For each \( p \in \partial {\mathbb{H}}_{n} \), there is an automorphism \( {\tau }_{p}^{* * } \in {\operatorname{Aut}}_{0}\left( {\mathbb{H}}_{N}\right) \) such that \( {F}_{p}^{* * } \math...
Now, we are in a position to the definition of the geometric rank. Write \( \mathcal{A}\left( p\right) \mathrel{\text{:=}} \) \( - {2i}{\left( {\left. \frac{{\partial }^{2}{\left( {f}_{p}\right) }_{l}^{* * }}{\partial {z}_{j}\partial w}\right| }_{0}\right) }_{1 \leq j, l \leq \left( {n - 1}\right) } \) . Then the geome...
Yes
Theorem 2.2 Suppose that \( F \in {\operatorname{Prop}}_{3}\left( {{\mathbb{H}}_{n},{\mathbb{H}}_{N}}\right) \) has geometric rank \( 1 \leq {\kappa }_{0} \leq n - 2 \) with \( F\left( 0\right) = 0 \) . Then there are \( \sigma \in \operatorname{Aut}\left( {\mathbb{H}}_{n}\right) \) and \( \tau \in \operatorname{Aut}\l...
\[ \left\{ \begin{array}{l} {f}_{l} = \mathop{\sum }\limits_{{j = 1}}^{{\kappa }_{0}}{z}_{j}{f}_{lj}^{ * }\left( {z, w}\right) ,\;l \leq {\kappa }_{0}, \\ {f}_{j} = {z}_{j},\text{ for }{\kappa }_{0} + 1 \leq j \leq n - 1, \\ {\phi }_{lk} = {\mu }_{lk}{z}_{l}{z}_{k} + \mathop{\sum }\limits_{{j = 1}}^{{\kappa }_{0}}{z}_{...
Yes
Theorem 2.2 [20] Let \( H \in \left( {1/2,1}\right) \) . Under Lipschitzian condition (2.8), for any \( {\mathcal{F}}_{0} \) - adapted function \( {u}_{0} \) such that \( \mathbb{E}\left\lbrack {{\int }_{D}{\left| {u}_{0}\left( x\right) \right| }^{2}{dx}}\right\rbrack < \infty \), eq. (1.1) has a unique adapted mild so...
\[ \mathop{\sup }\limits_{{\left( {t, x}\right) \rbrack \in \left\lbrack {0, T}\right\rbrack \times D}}\mathbb{E}\left\lbrack {\left| u\left( t, x\right) \right| }^{2}\right\rbrack < \infty . \]
No
Lemma 3.1 If \( K, L \in {\mathcal{K}}_{o}^{n}, p \geq 1,\tau \in \left\lbrack {-1,1}\right\rbrack \) and \( i, j = 0,1,\cdots, n - 1 \), then\n\n\[ \n{W}_{p, i}\left( {K,{\Pi }_{p, j}^{\tau }L}\right) = {W}_{p, j}\left( {L,{\Pi }_{p, i}^{\tau }K}\right) \n\]
Proof According to definitions (2.4) and (1.11), and using Fubini theorem, we get\n\n\[ \n{W}_{p, i}\left( {K,{\Pi }_{p, j}^{\tau }L}\right) = \frac{1}{n}{\int }_{{S}^{n - 1}}h{\left( {\Pi }_{p, j}^{\tau }L, u\right) }^{p}d{S}_{p, i}\left( {K, u}\right) \n\]\n\n\[ \n= \frac{1}{n}{\int }_{{S}^{n - 1}}{\alpha }_{n, p}\le...
Yes
Lemma 3.2 If \( K \in {\mathcal{K}}_{o}^{n}, p \geq 1,\tau \in \left\lbrack {-1,1}\right\rbrack \), real \( i \neq n \) and \( j = 0,1,\cdots, n - 1 \), then for any \( M \in {\mathcal{S}}_{o}^{n} \), \[ {W}_{p, j}\left( {K,{\Gamma }_{p, i}^{r}M}\right) = \frac{2{\omega }_{n}}{V\left( M\right) }{\widetilde{W}}_{-p, i}\...
Proof From definitions (2.4),(2.9) and (1.12), and using \( n{c}_{n - 2, p} = \left( {n + p}\right) {c}_{n, p} \), we have \[ {W}_{p, j}\left( {K,{\Gamma }_{p, i}^{\tau }M}\right) = \frac{1}{n}{\int }_{{S}^{n - 1}}{h}_{{\Gamma }_{p, i}^{\tau }M}^{p}\left( v\right) d{S}_{p, j}\left( {K, v}\right) \] \[ = \frac{{\gamma }...
Yes
Lemma 3.3 If \( K, L \in {\mathcal{S}}_{o}^{n}, p \geq 1,\tau \in \left\lbrack {-1,1}\right\rbrack \) and reals \( i, j \neq n \), then\n\n\[ \frac{{\widetilde{W}}_{-p, j}\left( {K,{\Gamma }_{p, i}^{\tau , * }L}\right) }{V\left( K\right) } = \frac{{\widetilde{W}}_{-p, i}\left( {L,{\Gamma }_{p, j}^{\tau , * }K}\right) }...
Proof Due to considerations (2.9), (1.12), (2.1) and Fubini theorem, we obtain\n\n\[ \frac{{\widetilde{W}}_{-p, j}\left( {K,{\Gamma }_{p, i}^{\tau , * }L}\right) }{V\left( K\right) } \]\n\n\[ = \frac{1}{{nV}\left( K\right) }{\int }_{{S}^{n - 1}}{\rho }_{K}^{n + p - j}\left( u\right) {\rho }_{{\Gamma }_{p, i}^{r, * }L}^...
Yes
Theorem 1.1 Suppose that \( A \) and \( B \) satisfy either \( \left( {\mathrm{H}}_{1}\right) \) or \( \left( {\mathrm{H}}_{2}\right) . Then problem \( \left( \mathbf{P}\right) \) has a unique optimal control. Moreover,\n\n(i) If \( \mathrm{A} \) and \( \mathrm{B} \) satisfy \( \left( {\mathrm{H}}_{1}\right) ,{\mathbf{...
## 2 Proof of Theorem 1.1\n\nUnder hypothesis \( \left( {\mathrm{H}}_{1}\right) \) or \( \left( {\mathrm{H}}_{2}\right) \), by the same arguments as those in [16], we can show the existence and uniqueness of the optimal control of problem (P). We omit the proofs here. Next, we continue the proof of Theorem 1.1.\n\n(i) ...
No
Lemma 2.4 Let \( H \) be a vertex-induced subgraph of \( G \) . Then\n\n(1) \( r\left( H\right) \leq r\left( G\right) ,\;p\left( H\right) \leq p\left( G\right) \) and \( n\left( H\right) \leq n\left( G\right) \) .\n\n(2) If \( r\left( H\right) = r\left( G\right) \), then \( p\left( H\right) = p\left( G\right) \) and \(...
Proof Lemma 2.4 follows from Lemma 2.3 and from the inequality \( r\left( H\right) = p\left( H\right) + \) \( n\left( H\right) \leq p\left( G\right) + n\left( G\right) = r\left( G\right) .
Yes
Lemma 3.2 Let \( G \) be a connected graph. Then \( n\left( G\right) = 2 \) if and only if \( G \in \mathcal{M}\left( {\Omega }_{3}\right) \) , where \( {\Omega }_{3} = \left\{ {{K}_{3},{C}_{5},{H}_{1},{H}_{2},\cdots ,{H}_{7}}\right\} \), and the graphs \( {H}_{i}\left( {i = 1,2,\cdots ,7}\right) \) are defined in Figu...
Proof It is routine to verify that \( n\left( G\right) = 2 \) for \( G \in \left\{ {{K}_{3},{C}_{5}}\right\} \cup \left\{ {{H}_{i} \mid 1 \leq i \leq 7}\right\} \) . Thus the sufficiency follows from Lemma 2.6.\n\nTo prove the necessity, we note that \( r\left( G\right) > n\left( G\right) = 2 \) . If \( r\left( G\right...
Yes
Lemma 4.1 If \( H \) is a basic graph, then \( {\left( H \circ m\right) }^{U} \) is also a basic graph.
Proof For any \( i, j \in \{ 1,2,\cdots, n\} \), if \( i \neq j \), as \( H \) is a basic graph, then \( {N}_{H}\left( {v}_{i}\right) \neq \) \( {N}_{H}\left( {v}_{j}\right) \) . So \( {N}_{{\left( H \circ m\right) }^{U}}\left( {v}_{i}^{s}\right) \neq {N}_{{\left( H \circ m\right) }^{U}}\left( {v}_{j}^{t}\right) \left(...
Yes
Lemma 4.2 Let \( G \) be a connected graph with pendent vertices and \( n\left( G\right) = 3 \) . Then \( G \in \mathcal{M}\left( {\Omega }_{5}\right) \), where \( {\Omega }_{5} = \Gamma \left( {2{K}_{2}}\right) \cup \Gamma \left( {K}_{3}\right) \cup \Gamma \left( {C}_{5}\right) \cup \mathop{\bigcup }\limits_{{i = 1}}^...
Proof Without loss of generality, assume that \( G \) is a basic graph. Let \( H \) be the induced subgraph of \( G \) obtained by deleting the pendant vertex \( x \) together with the vertex \( y \) adjacent to it. By Lemma 2.7, we have \( n\left( H\right) = 2 \) . Furthermore, \( H \) does not have isolated vertices ...
Yes
Theorem 1.1 Let \( {f}_{0} \) be the initial datum with finite mass, energy and entropy and \( f\left( {t, v}\right) \) be any solution of the Cauchy problem (1.3). Then for all time \( t > 0, f\left( {t, v}\right) \), as a real function of \( v \) variable, is analytic in \( {\mathbb{R}}_{v}^{3} \) . Moreover, for all...
\[ {t}^{\left| \alpha \right| }{\begin{Vmatrix}{\partial }^{\alpha }f\left( t, v\right) \end{Vmatrix}}_{{L}^{2}\left( {\mathbb{R}}_{v}^{3}\right) } \leq {C}^{\left| \alpha \right| + 1}\left\lbrack {\left( {\left| \alpha \right| - 2}\right) !}\right\rbrack \] where \( \alpha \) is an arbitrary multi-indices in \( {\math...
Yes
Lemma 2.1 For all multi-indices \( \mu \in {\mathbb{N}}^{3},\left| \mu \right| \geq 2 \), we have\n\n\[ \mathop{\sum }\limits_{{1 \leq \left| \beta \right| \leq \left| \mu \right| - 1}}\frac{\left| \mu \right| }{{\left| \beta \right| }^{4}\left( {\left| \mu \right| - \left| \beta \right| }\right) } \leq {24} \]\n\n(2.1...
This lemma was proved in [5].
No
Lemma 2.2 There exist positive constants \( B,{C}_{1} \), and \( {C}_{2} > 0 \) with \( B \) depending only on the dimension and \( {C}_{1},{C}_{2} \) depending only on \( {M}_{0},{E}_{0},{H}_{0} \), and \( \gamma \) such that for all multi-indices \( \mu \in {\mathbb{N}}^{3} \) with \( \left| \mu \right| \geq 2 \) and...
\[ \frac{d}{dt}{\begin{Vmatrix}{\partial }^{\mu }f\left( t\right) \end{Vmatrix}}_{{L}^{2}}^{2} + {C}_{1}{\begin{Vmatrix}{\nabla }_{v}{\partial }^{\mu }f\left( t\right) \end{Vmatrix}}_{{L}_{\gamma }^{2}}^{2} \] \[ \leq {C}_{2}{\left| \mu \right| }^{2}{\begin{Vmatrix}{\nabla }_{v}{\partial }^{\mu - 1}f\left( t\right) \en...
Yes
Proposition 2.3 Let \( {f}_{0} \) be the initial datum with finite mass, energy and entropy and \( f\left( {t, v}\right) \) be any solution of the Cauchy problem (1.3). Then for all \( t \) in the interval \( \left\lbrack {0, T}\right\rbrack \) with \( T \) being an arbitrary nonnegative constant, there exists a consta...
Proof of Proposition 2.3 We use induction on \( \left| \alpha \right| \) to prove estimate (2.3). First, when we take\n\n\[ A = \mathop{\sup }\limits_{{t \in \left\lbrack {0, T}\right\rbrack }}\parallel f\left( {t, v}\right) {\parallel }_{{L}^{2}} + T\mathop{\sup }\limits_{{t \in \left\lbrack {0, T}\right\rbrack }}{\be...
Yes
Theorem 3.2 Let \( \widetilde{X} = \left\lbrack {{\widetilde{x}}^{ - },{\widetilde{x}}^{ + }}\right\rbrack \) and \( \widetilde{Y} = \left\lbrack {{\widetilde{y}}^{ - },{\widetilde{y}}^{ + }}\right\rbrack \) be two fuzzy random variables. Then \( {\widetilde{d}}_{H}\left( {\widetilde{X},\widetilde{Y}}\right) : \Omega \...
Proof Since \( \widetilde{X} = \left\lbrack {{\widetilde{x}}^{ - },{\widetilde{x}}^{ + }}\right\rbrack \) and \( \widetilde{Y} = \left\lbrack {{\widetilde{y}}^{ - },{\widetilde{y}}^{ + }}\right\rbrack \) are fuzzy random variables, \( {\widetilde{x}}^{ - },{\widetilde{x}}^{ + },{\widetilde{y}}^{ - } \) and \( {\widetil...
Yes
(1) \( E\left( \widetilde{A}\right) = \widetilde{A} \), where \( \widetilde{A} \) denote the fuzzy random variable which have the same outcome \( \widetilde{A} \) for all \( \omega \in \Omega \), i.e., \( \widetilde{A}\left( \omega \right) = \widetilde{A},\forall \omega \in \Omega \) ;
Proof (1) Let \( \widetilde{A} = \left\lbrack {{\widetilde{a}}^{ - },{\widetilde{a}}^{ + }}\right\rbrack \) . If for any \( \omega \in \Omega ,\widetilde{A}\left( \omega \right) = \widetilde{A} \), then \( {\widetilde{a}}^{ - }\left( \omega \right) = {\widetilde{a}}^{ - } \) and \( {\widetilde{a}}^{ + }\left( \omega \r...
Yes
Lemma 2.5 Let \( h \in C\left( {\left\lbrack {1, e}\right\rbrack ,\mathbb{R}}\right), u \in {C}_{\delta }^{3}\left( {\left\lbrack {1, e}\right\rbrack ,\mathbb{R}}\right) \) . Then the unique solution of the linear Caputo-Hadamard fractional differential equation \[ \left\{ \begin{array}{l} {}_{H}^{C}{D}_{1 + }^{\alpha ...
Proof In view of Lemma 2.4, applying \( {}^{H}{I}_{1 + }^{\alpha } \) to both sides of (2.2), \[ u\left( t\right) = {}^{H}{I}_{1 + }^{\alpha }h\left( t\right) + {c}_{0} + {c}_{1}\left( {\ln t}\right) + {c}_{2}{\left( \ln t\right) }^{2}, \] where \( {c}_{0},{c}_{1},{c}_{2} \in \mathbb{R} \) . The boundary condition \( u...
Yes
Theorem 3.4 Assume that assumptions of Theorem 3.3 are satisfied. Then fractional nonlinear differential equation (1.1) has at least one solution in \( C\left( {\left\lbrack {1, e}\right\rbrack ,\mathbb{R}}\right) \) .
Proof By the hypotheses and Theorem 3.3, we induct \( {X}_{\left( \underline{u},\bar{u}\right) } \neq \varnothing \), then the solution set of fractional integral equation (2.6) is nonempty in \( C\left( {\left\lbrack {1, e}\right\rbrack ,\mathbb{R}}\right) \) . It follows from the solution set of (2.6) together with L...
Yes
Consider the following nonlinear Caputo-Hadamard fractional differential equation\n\n\[ \left\{ \begin{array}{l} {}_{H}^{C}{D}_{1 + }^{\frac{5}{2}}u\left( t\right) = \frac{\left( \sqrt{t} + \ln t\right) }{{\left( t + 3\right) }^{3}}\frac{{u}^{2}}{\left| u\right| + 1},1 \leq t \leq e, \\ u\left( 1\right) = {u}^{\prime }...
here \( \alpha = \frac{5}{2},\lambda = 1, f\left( {t, u}\right) = \frac{\left( \sqrt{t} + \ln t\right) }{{\left( t + 3\right) }^{3}}\frac{{u}^{2}}{\left| u\right| + 1},1 \leq t \leq e \) . One can easily calculate \( Q = \) \( \frac{24}{{15}\sqrt{\pi }\left( {3 - e}\right) } \approx {3.2} \) . Clearly \( f \) is a cont...
Yes
Consider the problem\n\n\\[ \n\\left\\{ \\begin{array}{l} {}_{H}^{C}{D}_{1 + }^{\\frac{5}{2}}u\\left( t\\right) = \\frac{{t}^{4}}{{16}\\sqrt{\\pi }}\\left( {\\left| u\\right| + 1}\\right) , \\\\ u\\left( 1\\right) = {u}^{\\prime }\\left( 1\\right) = 0, u\\left( e\\right) = \\frac{1}{\\left( 6 - 2e\\right) }{\\int }_{1}...
Proof Where \\( \\alpha = \\frac{5}{2},\\;\\lambda = \\frac{1}{\\left( 6 - 2e\\right) },\\;f\\left( {t, u}\\right) = \\frac{{t}^{4}}{{16}\\sqrt{\\pi }}\\left( {\\left| u\\right| + 1}\\right) ,\\;t \\in \\left\\lbrack {1, e}\\right\\rbrack ,\\;f \\) is continuous and nondecreasing with respect to \\( u \\) . Thus\n\n\\[...
Yes
Lemma 4.1 \( \mathop{\lim }\limits_{{A, B \rightarrow 0}}{\rho }_{ * }^{AB} = + \infty \) .
Proof Eliminating \( {u}_{ * }^{AB} \) in the second equation of (4.1) and (4.2) gives\n\n\[ \n{u}_{ + } - {u}_{ - } = - \sqrt{\frac{{\rho }_{ * }^{AB} - {\rho }_{ - }}{{\rho }_{ * }^{AB}{\rho }_{ - }}\left( {A\left( {{\left( {\rho }_{ * }^{AB}\right) }^{n} - {\rho }_{ - }^{n}}\right) - B\left( {\frac{1}{{\left( {\rho ...
Yes
Lemma 4.3\n\n\\[ \n\\mathop{\\lim }\\limits_{{A, B \\rightarrow 0}}{u}_{ * }^{AB} = \\mathop{\\lim }\\limits_{{A, B \\rightarrow 0}}{\\sigma }_{1}^{AB} = \\mathop{\\lim }\\limits_{{A, B \\rightarrow 0}}{\\sigma }_{2}^{AB} = \\sigma .\n\\]
Proof From the first equation of (4.1) and (4.2) for \\( {S}_{1} \\) and \\( {S}_{2} \\), by Lemma 4.1, we have\n\n\\[ \n\\mathop{\\lim }\\limits_{{A, B \\rightarrow 0}}{\\sigma }_{1}^{AB} = \\mathop{\\lim }\\limits_{{A, B \\rightarrow 0}}\\frac{{\\rho }_{ * }^{AB}{u}_{ * }^{AB} - {\\rho }_{ - }{u}_{ - }}{{\\rho }_{ * ...
Yes
\[ \mathop{\lim }\limits_{{A, B \rightarrow 0}}{\int }_{{x}_{1}^{AB}}^{{x}_{2}^{AB}}{\rho }_{ * }^{AB}{dx} = \sqrt{{\rho }_{ + }{\rho }_{ - }}\left( {{u}_{ - } - {u}_{ + }}\right) t \]
Proof Here we only prove the case for \( {\rho }_{ + } \neq {\rho }_{ - } \) . The first equation of the Rankine-Hugoniot condition (3.11) for \( {S}_{1} \) and \( {S}_{2} \) read\n\n\[ \left\{ \begin{array}{l} {\sigma }_{1}^{AB}\left( {{\rho }_{ * }^{AB} - {\rho }_{ - }}\right) = {\rho }_{ * }^{AB}{u}_{ * }^{AB} - {\r...
Yes
Theorem 4.2 Let \( {u}_{ - } < {u}_{ + } \) and \( \left( {{\rho }_{ + },{u}_{ + }}\right) \in \mathrm{I}\left( {{\rho }_{ - },{\mathrm{u}}_{ - }}\right) \) . For any fixed \( A, B > 0 \), assume that \( \left( {{\rho }^{AB},{u}^{AB}}\right) \) is the two-rarefaction wave Riemann solution of (1.1)-(1.2) with Riemann da...
Indeed, if \( \mathop{\lim }\limits_{{A, B \rightarrow 0}}{\rho }_{ * }^{AB} = K \in \left( {0,\min \left\{ {{\rho }_{ - },{\rho }_{ + }}\right\} }\right) \), then (4.17) leads to \( {u}_{ + } - {u}_{ - } = 0 \), which contradicts with \( {u}_{ - } < {u}_{ + } \) . Thus \( \mathop{\lim }\limits_{{A, B \rightarrow 0}}{\...
Yes
Lemma 5.1 When \( \left( {{\rho }_{ + },{u}_{ + }}\right) \in \mathrm{V}\left( {{\rho }_{ - },{\mathrm{u}}_{ - }}\right) \), there exists a positive parameter \( {A}_{0} \) such that \( \left( {{\rho }_{ + },{u}_{ + }}\right) \in {S}_{1}{S}_{2}\left( {{\rho }_{ - },{u}_{ - }}\right) \) when \( 0 < A < {A}_{0} \) .
Proof From \( \left( {{\rho }_{ + },{u}_{ + }}\right) \in \mathrm{V}\left( {{\rho }_{ - },{\mathrm{u}}_{ - }}\right) \), we have\n\n\[ \n{u}_{ + } + \sqrt{B}{\rho }_{ + }^{-\frac{\alpha + 1}{2}} \leq {u}_{ - } - \sqrt{B}{\rho }_{ - }^{-\frac{\alpha + 1}{2}} \n\]\n\n(5.1)\n\nthen\n\n\[ \n{\left( {u}_{ - } - {u}_{ + }\ri...
Yes
Lemma 5.2 \( \mathop{\lim }\limits_{{A \rightarrow 0}}{\rho }_{ * }^{A} = + \infty \) .
Proof Eliminating \( {u}_{ * }^{A} \) in the second equation of (5.7) and (5.8) gives\n\n\[ \n{u}_{ - } - {u}_{ + } = \sqrt{\frac{{\rho }_{ * }^{A} - {\rho }_{ - }}{{\rho }_{ * }^{A}{\rho }_{ - }}\left( {A\left( {{\left( {\rho }_{ * }^{A}\right) }^{n} - {\rho }_{ - }^{n}}\right) - B\left( {\frac{1}{{\left( {\rho }_{ * ...
Yes
Lemma 5.4 Let \( \mathop{\lim }\limits_{{A \rightarrow 0}}{u}_{ * }^{A} = \widehat{{\sigma }^{B}} \), then\n\n\[ \mathop{\lim }\limits_{{A \rightarrow 0}}{u}_{ * }^{A} = \mathop{\lim }\limits_{{A \rightarrow 0}}{\sigma }_{1}^{A} = \mathop{\lim }\limits_{{A \rightarrow 0}}{\sigma }_{2}^{A} = \widehat{{\sigma }^{B}} \in ...
Proof From the second equation of (5.7) for \( {S}_{1} \), by Lemmas 4.2 and 4.3, we have\n\n\[ \mathop{\lim }\limits_{{A \rightarrow 0}}{u}_{ * }^{A} = {u}_{ - } - \mathop{\lim }\limits_{{A \rightarrow 0}}\sqrt{\frac{{\rho }_{ * }^{A} - {\rho }_{ - }}{{\rho }_{ * }^{A}{\rho }_{ - }}\left( {A\left( {{\left( {\rho }_{ *...
Yes
Lemma 5.5 For \( \widehat{{\sigma }^{B}} \) mentioned in Lemma 5.4,\n\n\[ \widehat{{\sigma }^{B}} = {\sigma }^{B} = \frac{{\rho }_{ + }{u}_{ + } - {\rho }_{ - }{u}_{ - } + {\left\{ {\rho }_{ + }{\rho }_{ - }\left( {\left( {u}_{ + } - {u}_{ - }\right) }^{2} - \left( \frac{1}{{\rho }_{ + }} - \frac{1}{{\rho }_{ - }}\righ...
Proof Letting \( \mathop{\lim }\limits_{{A \rightarrow 0}}A{\left( {\rho }_{ * }^{A}\right) }^{n} = L \), by Lemma 5.4, from (5.12) and (5.13) we have\n\n\[ \mathop{\lim }\limits_{{A \rightarrow 0}}{u}_{ * }^{A} = {u}_{ - } - \sqrt{\frac{1}{{\rho }_{ - }}\left( {L + \frac{B}{{\rho }_{ - }^{\alpha }}}\right) } = {u}_{ +...
Yes
Lemma 5.6\n\n\[ \mathop{\lim }\limits_{{A \rightarrow 0}}{\int }_{{x}_{1}^{A}}^{{x}_{2}^{A}}{\rho }_{ * }^{A}{dx} = {w}_{0}^{B}t \]\n\n(5.19)\n\n\[ \mathop{\lim }\limits_{{A \rightarrow 0}}{\int }_{{x}_{1}^{A}}^{{x}_{2}^{A}}{\rho }_{ * }^{A}{u}_{ * }^{A}{dx} = {w}_{0}^{B}{\sigma }^{B}t. \]\n\n\( \left( {5.20}\right) \)
Proof Here we only prove the case for \( {\rho }_{ + } \neq {\rho }_{ - } \) . Similar to the proof of Lemma 4.4, taking account into (3.11) and (5.18), we have\n\n\[ \mathop{\lim }\limits_{{A \rightarrow 0}}{\rho }_{ * }^{A}\left( {{\sigma }_{2}^{A} - {\sigma }_{1}^{A}}\right) = \mathop{\lim }\limits_{{A \rightarrow 0...
Yes
Lemma 2.1 Let \( \Omega \) be a bounded Lipschitz domain in \( {R}^{2} \) or \( {R}^{3} \) . Let \( M, K \) be two positive real numbers and \( \rho \) a non-negative function such that\n\n\[ 0 < M \leq {M}_{\rho } = {\int }_{\Omega }{\rho dx},\;{\int }_{\Omega }{\rho }^{\gamma }{dx} \leq K\;\text{ for a certain }\gamm...
Proof see [11].
No
Lemma 2.2 Let \( v \in {W}^{1, p}\left( {\Omega }_{\varepsilon }\right) \) . Then we have\n\n\[ \parallel v{\parallel }_{{L}^{q}\left( {\Omega }_{\varepsilon }\right) } \leq C\left( {\left| {{\int }_{{\Omega }_{\varepsilon }}{vdx}}\right| + {\varepsilon }^{n\left( {\frac{1}{q} - \frac{1}{p}}\right) }\parallel \nabla v{...
Proof Obviously, it is enough to show\n\n\[ \parallel v{\parallel }_{{L}^{q}\left( {\Omega }_{\varepsilon }\right) } \leq C{\varepsilon }^{n\left( {\frac{1}{q} - \frac{1}{p}}\right) }\parallel \nabla v{\parallel }_{{L}^{p}\left( {\Omega }_{\varepsilon }\right) },\;v \in {W}^{1, p}\left( {\Omega }_{\varepsilon }\right) ...
Yes
Lemma 2.1 The energy functional \( {I}_{\mu } \) is coercive and bounded below on \( {N}_{\mu } \) .
Proof For \( u \in {N}_{\mu } \), by the Hölder inequality and Sobolev embedding theorem, we can deduce\n\n\[ \n{I}_{\mu }\left( u\right) = \frac{1}{p}\parallel u{\parallel }^{p} - \frac{1}{q}{\int }_{{\mathbb{R}}^{N}}{f}_{\mu }{\left| u\right| }^{q}{dx} - \frac{1}{r}{\int }_{{\mathbb{R}}^{N}}g{\left| u\right| }^{r}{dx...
Yes
Lemma 2.2 (i) If \( u \in {N}_{\mu }^{ + } \), then \( {\int }_{{\mathbb{R}}^{N}}{f}_{\mu }\left( x\right) {\left| u\right| }^{q}{dx} > 0 \) .
Proof By (2.1) we can easily derive these results.
No
Lemma 2.3 (i) For all \( \mu \in \left( {0,{L}_{1}}\right) \), we have \( {N}_{\mu }^{0} = \varnothing \) and \( {\alpha }^{ + } < 0 \) .
Proof (i) Suppose the contrary. We may assume that there exists \( {\mu }_{ * } \in \left( {0,{L}_{1}}\right) \) such that \( {N}_{{\mu }_{ * }}^{0} \neq \varnothing \) . Thus, for each \( u \in {N}_{{\mu }_{ * }}^{0} \), by the Hölder and Sobolev inequalities, we can obtain\n\n\[ 0 = \left\langle {{\Psi }^{\prime }\le...
Yes
Lemma 2.4 For each \( u \in {\mathbf{W}}_{a}^{1, p}\left( {\mathbb{R}}^{N}\right) \smallsetminus \{ 0\} \), we have\n\n(i) if \( {\int }_{{\mathbb{R}}^{N}}{f}_{\mu }{\left| u\right| }^{q}{dx} \leq 0 \), then there exists a unique \( {t}^{ - } = {t}^{ - }\left( u\right) > {t}_{\max } \) such that \( {t}^{ - }u \in \) \(...
Proof (i) The equation \( {m}_{u}\left( t\right) = {\int }_{{\mathbb{R}}^{N}}{f}_{\mu }{\left| u\right| }^{q}{dx} \) admits a unique solution \( {t}^{ - } > {t}_{\max } \) and \( {m}_{u}^{\prime }\left( {t}^{ - }\right) < 0 \) . Thus \( {t}^{ - }u \in {N}_{\mu }^{ - } \), and (2.9) holds by Lemma 2.3.
Yes
For \( 0 \leq a < \frac{N - p}{p},0 \leq \lambda < \bar{\lambda } \), problem (3.1) has radially symmetric ground states\n\n\[ \n{u}_{\epsilon }\left( x\right) = {\epsilon }^{-\left( {\frac{N - p}{p} - a}\right) }{v}_{\epsilon }\left( \frac{x}{\epsilon }\right) ,\;\forall \epsilon > 0, \n\]\nsatisfying\n\n\[ \n{\int }_...
Proof As in [19], we can prove that the limiting problem (3.1) has radially symmetric ground states, by which \( {S}_{\lambda } \) can be achieved. Let \( u\left( \xi \right) \) be a radial solution to (3.1). Then we get that\n\n\[ \n{\left( {\xi }^{N - 1 - {ap}}{\left| {u}^{\prime }\right| }^{p - 2}{u}^{\prime }\right...
Yes
Proposition 3.2 (i) If \( \mu \in \left( {0,{L}_{1}}\right) \), then \( {I}_{\mu } \) has a (P.S.) \( {}_{\alpha } \) -sequence \( {\left\{ {u}_{n}\right\} }_{n \in \mathbb{N}} \subset {N}_{\mu } \) .
Proof The proof is similar to the argument of Proposition 3.3 in [20].
No
Lemma 3.4 (i) \( \mathop{\lim }\limits_{{l \rightarrow 0}}{\begin{Vmatrix}{u}_{l}\end{Vmatrix}}^{p} = {S}_{\lambda }^{\frac{r}{r - p}} \) uniformly in \( e \in {\mathbb{S}}^{N - 1} \) ;
We refer to the argument of Lemma 4.2 in He and Yang (see [21]).
No
Theorem 4.2 For \( \mu \in \left( {0,{L}_{2}}\right) ,\left( {1.1}\right) \) has a positive solution \( {u}_{\mu }^{ - } \in {N}_{\mu }^{ - } \) such that \( {I}_{\mu }\left( {u}_{\mu }^{ - }\right) = {\alpha }^{ - }. \)
Proof By Ekeland's variational principle [22], there exists a minimizing sequence \( {\left\{ {u}_{n}\right\} }_{n \in \mathbb{N}} \subset {N}_{\mu }^{ - } \) such that\n\n\[ \n{I}_{\mu }\left( {u}_{n}\right) = {\alpha }^{ - } + o\left( 1\right) \;\text{ and }\;{I}_{\mu }^{\prime }\left( {u}_{n}\right) = o\left( 1\righ...
Yes
Lemma 5.2 Assume that \( \left\{ {u}_{n}\right\} \) is a minimizing sequence in \( {N}_{0} \) for \( {I}_{0} \) . Then\n\n(i) \( {\int }_{{\mathbb{R}}^{N}}{f}_{ - }{\left| {u}_{n}\right| }^{q}{dx} = o\left( 1\right) \) ;\n\n(ii) \( {\int }_{{\mathbb{R}}^{N}}\left( {1 - g}\right) {\left| {u}_{n}\right| }^{r}{dx} = o\lef...
Proof For each \( n \), there exists a unique \( {t}_{n} > 0 \) such that \( {t}_{n}{u}_{n} \in {N}^{\infty } \), that is,\n\n\[ \n{t}_{n}^{p}{\begin{Vmatrix}{u}_{n}\end{Vmatrix}}^{p} = {t}_{n}^{r}{\int }_{{\mathbb{R}}^{N}}{\left| {u}_{n}\right| }^{r}{dx}.\n\]\n\nBy Lemma 2.4 (i), we have\n\n\[ \n{I}_{0}\left( {u}_{n}\...
Yes
Lemma 5.3 There exists \( {d}_{0} < 0 \) such that for \( u \in {N}_{0}\left( {d}_{0}\right) \), we have\n\n\[ \n{\int }_{{\mathbb{R}}^{N}}\frac{x}{{\left| x\right| }^{1 - {ap}}}\left( {{\left| x\right| }^{-{ap}}{\left| \nabla u\right| }^{p} - \frac{\lambda }{{\left| x\right| }^{p\left( {a + 1}\right) }}{u}^{p}}\right)...
Proof Suppose the contrary. We may assume that there exists a sequence \( {\left\{ {u}_{n}\right\} }_{n \in \mathbb{N}} \subset \) \( {N}_{0} \) such that \( {I}_{0}\left( {u}_{n}\right) = \left( {\frac{1}{p} - \frac{1}{r}}\right) {S}_{\lambda }^{\frac{r}{r - p}} + o\left( 1\right) \) and \( {\int }_{{\mathbb{R}}^{N}}\...
Yes
Lemma 5.5 There exists \( {\mu }_{0} \in \left( {0,{L}_{2}}\right) \) such that for each \( \mu \in \left( {0,{\mu }_{0}}\right) \) and \( u \in {N}_{\mu }^{ - }\left( {\alpha }^{ + }\right) \) ,\n\n\[ \n{\int }_{{\mathbb{R}}^{N}}\frac{x}{{\left| x\right| }^{1 - {ap}}}\left( {{\left| x\right| }^{-{ap}}{\left| \nabla u\...
Proof For \( u \in {N}_{\mu }^{ - }\left( {\alpha }^{ + }\right) \), by Lemma 2.4 (i), there exists \( {t}_{0}^{ - }\left( u\right) > 0 \) such that \( {t}_{0}^{ - }\left( u\right) u \in \) \( {N}_{0} \) . Moreover, by Lemma 5.4 and the Hölder inequality and Sobolev embedding theorem, we have\n\n\[ \n{I}_{\mu }\left( u...
Yes
Lemma 6.5 There exists a sequence \( \left\{ {\sigma }_{l}\right\} \subset {\mathbb{R}}^{ + } \) with \( {\sigma }_{l} \rightarrow 0 \) as \( l \rightarrow \infty \) such that \[ {\varphi }_{\mu }\left( {\mathbb{S}}^{N - 1}\right) \subset \left\lbrack {{I}_{\mu } \leq {\alpha }^{ + } + \left( {\frac{1}{p} - \frac{1}{r}...
Proof By Proposition 4.1, for \( l > {l}_{0} \), we have \( {u}_{\mu }^{ + } + {t}_{ * }{u}_{l} \in {N}_{\mu }^{ - } \) and \[ \mathop{\sup }\limits_{{t \geq 0}}{I}_{\mu }\left( {{u}_{\mu }^{ + } + t{u}_{l}}\right) < {\alpha }^{ + } + \left( {\frac{1}{p} - \frac{1}{r}}\right) {S}_{\lambda }^{\frac{r}{r - p}}\;\text{ un...
Yes
Lemma 6.7 For \( \mu \in \left( {0,{\mu }_{0}}\right) \) and \( l > {l}_{ * } \), the energy functional \( {I}_{\mu } \) admits at least two critical points in \( \left\lbrack {{I}_{\mu } < {\alpha }^{ + } + \left( {\frac{1}{p} - \frac{1}{r}}\right) {S}_{\lambda }^{\frac{r}{r - p}}}\right\rbrack \) .
Proof It is easy to deduce from Lemmas 6.3, 6.4, 6.6 and Proposition 3.2.
No
Theorem 1 If \( p \geq 3 \), then there exists a constant \( C > 0 \), depending only on \( q \), such that the following holds: let \( N \in \mathbb{N} \) with \( N \geq 2 \) and \( A \subseteq {\mathbb{G}}_{N}^{2} \) . If \( \left( {A - A}\right) \cap \left\{ {\left( {d,{d}^{2}}\right) : d \in {\mathbb{A}}^{ \times }...
By adapting the lifting argument in [6], we deduce the following analogue of Theorem \( \mathrm{C} \) from Theorem 1.
No
Lemma 1 For \( M \in {\mathbb{N}}_{ + } \) and \( \omega \in {\mathbb{K}}_{\infty } \), we have\n\n\[ \mathop{\sum }\limits_{{d \in {\mathbb{G}}_{M}}}e\left( {\omega d}\right) = \left\{ \begin{array}{ll} {q}^{M}, & \text{ if }\operatorname{ord}\{ \omega \} < - M \\ 0, & \text{ otherwise. } \end{array}\right. \]
Proof This is \( \left\lbrack {{10}\text{, Lemma 7}}\right\rbrack \) .
No
Lemma 2 Let \( N \in {\mathbb{N}}_{ + } \) and \( \alpha = \left( {{\alpha }_{1},{\alpha }_{2}}\right) \in {\mathbb{T}}^{2} \) . Let \( b \in {\mathbb{A}}^{ \times } \) and \( m = \left( {{m}_{1},{m}_{2}}\right) \in {\mathbb{A}}^{2} \) with \( \gcd \left( {b,{m}_{1},{m}_{2}}\right) = 1 \) . Suppose that ord \( b \leq N...
Proof Write \( \beta = \left( {{\beta }_{1},{\beta }_{2}}\right) = \alpha - \frac{1}{b}m \) . Then\n\n\[ {S}_{N}\left( \alpha \right) = \mathop{\sum }\limits_{{t \in {\mathbb{G}}_{\text{ord }b}}}e\left( {\frac{1}{b}m\overrightarrow{t}}\right) \mathop{\sum }\limits_{{s \in {\mathbb{G}}_{N - \text{ ord }b}}}e\left( {\bet...
Yes
Lemma 3 Let \( {r}_{1},{r}_{2} \in \mathbb{N} \) . Then for any \( \alpha = \left( {{\alpha }_{1},{\alpha }_{2}}\right) \in {\mathbb{T}}^{2} \), there exists \( \left( {b,{m}_{1},{m}_{2}}\right) \in {\mathbb{A}}^{3} \) with the following properties\n\n(i) \( b \) is monic and or \( \mathrm{d}b \leq {r}_{1} + {r}_{2} \)...
Proof For \( 1 \leq j \leq 2 \), let \( {\mathbb{T}}_{j} = \left\{ {\omega \in \mathbb{T} : \operatorname{ord}\omega \leq - {r}_{j} - 1}\right\} \) . Then \( {\mathbb{T}}_{j} \) is a subgroup of \( \mathbb{T} \) . Also, \( \left| {\mathbb{T}/{\mathbb{T}}_{j}}\right| = {q}^{{r}_{j}} \).\n\nNote that \( \left| {\mathop{\...
Yes
Lemma 4 Let \( {a}_{1},{a}_{2},{b}_{1},{b}_{2} \in \mathbb{A} \) with \( {b}_{1},{b}_{2} \neq 0 \) and \( \gcd \left( {{b}_{1},{a}_{1}}\right) = \gcd \left( {{b}_{2},{a}_{2}}\right) = 1 \) . Let \( m = \left( {{m}_{1},{m}_{2}}\right) \in {\mathbb{A}}^{2} \) . Suppose that \( \gcd \left( {{b}_{1},{m}_{1},{m}_{2}}\right)...
Proof Since \( \gcd \left( {{b}_{1},{b}_{2}}\right) = 1,{b}_{2} + {b}_{1}\mathbb{A} \) is invertible in the ring \( {\mathbb{H}}_{1} = \mathbb{A}/{b}_{1}\mathbb{A} \) . Thus,\n\n\[ G\left( {\frac{{a}_{1}}{{b}_{1}}, m}\right) = \mathop{\sum }\limits_{{d + {b}_{1}\mathbb{A} \in {\mathbb{H}}_{1}}}e\left( {\frac{{a}_{1}}{{...
Yes
Lemma 5 Let \( a, b \in \mathbb{A} \) with \( b \neq 0 \) and \( \gcd \left( {b, a}\right) = 1 \) . Let \( m = \left( {{m}_{1},{m}_{2}}\right) \in {\mathbb{A}}^{2} \) . Suppose that \( \gcd \left( {b,{m}_{1},{m}_{2}}\right) = 1 \) . If \( p \geq 3 \) and \( b \) is irreducible, then we have \[ \left| {G\left( {\frac{a}...
Proof Since \( b \) is irreducible and \( \gcd \left( {b, a}\right) = 1 \), it follows that \( a \neq 0 \) . We divide into two cases.\n\nCase 1 Suppose that \( b \mid {m}_{2} \) . Since \( \gcd \left( {b,{m}_{1},{m}_{2}}\right) = 1, b \nmid {m}_{1} \) . By Lemma 1, we have \[ G\left( {\frac{a}{b}, m}\right) = \mathop{...
Yes
Proposition 7 Let \( a, b \in \mathbb{A} \) with \( b \neq 0 \) and \( \gcd \left( {b, a}\right) = 1 \) . Let \( m = \left( {{m}_{1},{m}_{2}}\right) \in {\mathbb{A}}^{2} \) . Suppose that \( \gcd \left( {b,{m}_{1},{m}_{2}}\right) = 1 \) . If \( p \geq 3 \), then we have\n\n\[ \left| {G\left( {\frac{a}{b}, m}\right) }\r...
Proof Without loss of generality, we assume that \( a \neq 0 \) and ord \( b \geq 1 \) . Also, \( b \) is monic. There exist \( \iota ,{j}_{1},\cdots ,{j}_{\iota } \in {\mathbb{N}}_{ + } \) and distinct monic irreducible polynomials \( {\sigma }_{1},\cdots ,{\sigma }_{\iota } \) in \( \mathbb{A} \) such that \( b = \ma...
Yes
Lemma 8 Let \( b,{b}^{\prime } \in \mathcal{B} \). Suppose that \( \left( {{a}_{1},{a}_{2}}\right) \in {\mathcal{A}}_{b} \) and \( \left( {{a}_{1}^{\prime },{a}_{2}^{\prime }}\right) \in {\mathcal{A}}_{{b}^{\prime }} \). If \( \left( {b,{a}_{1},{a}_{2}}\right) \neq \left( {{b}^{\prime },{a}_{1}^{\prime },{a}_{2}^{\prim...
Proof To prove the lemma, we suppose the contrary. Then there exists \[ \left( {{\alpha }_{1},{\alpha }_{2}}\right) \in F\left( {b,{a}_{1},{a}_{2}}\right) \cap F\left( {{b}^{\prime },{a}_{1}^{\prime },{a}_{2}^{\prime }}\right) . \] Let \( 1 \leq j \leq 2 \). Since \[ \left| {\frac{{a}_{j}}{b} - \frac{{a}_{j}^{\prime }}...
Yes
Proposition 9 If \( b \in \mathcal{B} \), then for any \( \alpha \in {F}_{b} \), we have\n\n\[ \left| {{S}_{N}\left( \alpha \right) }\right| \leq {q}^{N}{\left| b\right| }^{-1/2}. \]
Proof Write \( \left( {{\alpha }_{1},{\alpha }_{2}}\right) = \alpha \) . Take \( a = \left( {{a}_{1},{a}_{2}}\right) \in {\mathcal{A}}_{b} \) such that \( \alpha \in F\left( {b,{a}_{1},{a}_{2}}\right) \) . Since\n\n\[ \left| {{\alpha }_{2} - \frac{{a}_{2}}{b}}\right| < {q}^{-{2M}}{\left| b\right| }^{-1} \leq {q}^{-N}{\...
Yes