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Lemma 4.9. Let \( L \) be a distributive lattice. Define\n\n\[ \nV\left( a\right) = \{ P \in X \mid a \notin P\} \text{, where}a \in L\text{.} \]\n\nThen \( V \) is injective; \( a \leqq b \) if and only if \( V\left( a\right) \subseteq V\left( b\right) ;V\left( {a \land b}\right) = V\left( a\right) \cap V\left( b\righ...
Proof. If \( P \) is a prime ideal, then \( a \land b \notin P \) if and only if \( a \notin P \) and \( b \notin P \) ; therefore \( V\left( {a \land b}\right) = V\left( a\right) \cap V\left( b\right) \) . If \( P \) is any ideal, then \( a \vee b \notin P \) if and only if \( a \notin P \) or \( b \notin P \) ; there...
Yes
Proposition 5.1. In a distributive lattice with a least element and a greatest element: (1) an element has at most one complement; (2) if \( {a}^{\prime } \) is the complement of \( a \) and \( {b}^{\prime } \) is the complement of \( b \), then \( {a}^{\prime } \vee {b}^{\prime } \) is the complement of \( a \land b \...
Proof. (1). If \( b \) and \( c \) are complements of \( a \), then\n\n\[ b = b \land \left( {a \vee c}\right) = \left( {b \land a}\right) \vee \left( {b \land c}\right) = b \land c \leqq c; \]\n\nexchanging \( b \) and \( c \) then yields \( c \leqq b \) . (2). By distributivity,\n\n\[ \left( {a \land b}\right) \land ...
Yes
Lemma 5.2. A Boolean ring is commutative and has characteristic 2.
Proof. If \( R \) is Boolean, then\n\n\[ x + x = \left( {x + x}\right) \left( {x + x}\right) = {x}^{2} + {x}^{2} + {x}^{2} + {x}^{2} = x + x + x + x \]\n\nand \( x + x = 0 \), for all \( x \in R \) . Then\n\n\[ x + y = \left( {x + y}\right) \left( {x + y}\right) = {x}^{2} + {xy} + {yx} + {y}^{2} = x + {xy} + {yx} + y, ...
Yes
Proposition 5.3. If \( R \) is a Boolean ring, then \( R \), partially ordered by \( x \leqq y \) if and only if \( {xy} = x \), is a Boolean lattice \( \mathrm{L}\left( R\right) \), in which \( x \land y = {xy}, x \vee y = \) \( x + y + {xy} \), and \( {x}^{\prime } = 1 - x \) .
The proof is an exercise.
No
Proposition 5.4 (Stone [1936]). If \( L \) is a Boolean lattice, then \( L \), with addition and multiplication\n\n\[ x + y = \left( {{x}^{\prime } \land y}\right) \vee \left( {x \land {y}^{\prime }}\right) ,{xy} = x \land y, \]\n\nis a Boolean ring \( \mathrm{R}\left( L\right) \) . Moreover, \( \mathrm{L}\left( {\math...
Proof. The addition on \( L \) is commutative; readers who love computation will delight in showing that it is associative. Moreover, \( x + 0 = x \) and \( x + x = 0 \) for all \( x \in L \) ; hence \( \left( {L, + }\right) \) is an abelian group.\n\nThe multiplication on \( L \) is commutative, associative, and idemp...
No
Theorem 5.5. A finite lattice \( L \) is Boolean if and only if \( L \cong {2}^{X} \) for some finite set \( X \) .
Proof. The lattice \( {2}^{X} \) is always Boolean. Conversely, let \( L \) be Boolean. By 4.5, \( L \cong \operatorname{Id}\left( S\right) \), where \( S = \operatorname{Irr}\left( L\right) \) is the partially ordered set of all atoms (irreducible elements) of \( L \) . Since the atoms of \( L \) satisfy no strict ine...
Yes
Theorem 5.6 (Birkhoff [1933]). A lattice \( L \) is Boolean if and only if it is isomorphic to a Boolean sublattice of \( {2}^{X} \) for some set \( X \) .
Proof. Let \( L \) be Boolean and let \( X \) be the set of all prime ideals of \( L \) . Define \( V : L \rightarrow {2}^{X} \) by \( V\left( x\right) = \{ P \in X \mid x \notin P\} \) . By 4.9 and 5.7 below, \( V \) is a homomorphism of Boolean lattices, so that \( \operatorname{Im}V \) is a Boolean sublattice of \( ...
No
Lemma 5.7. Let \( L \) be a Boolean lattice. The sets \[ V\left( a\right) = \{ P \in X \mid a \notin P\} \text{, where } a \in L \text{,} \] constitute a basis for a topology on the set \( X \) of all prime ideals of \( L \). Moreover, \( V\left( 0\right) = \varnothing, V\left( 1\right) = X \), and \( V\left( {a}^{\pri...
Proof. By 4.9, \( V\left( {a \land b}\right) = V\left( a\right) \cap V\left( b\right) \) for all \( a, b \in L \) ; hence the sets \( V\left( a\right) \) with \( a \in L \) constitute a basis of open sets for a topology on \( X \). If \( P \) is a prime ideal of \( L \), then \( 0 \in P \), since \( P \neq \varnothing ...
Yes
Proposition 5.8. The Stone space of a Boolean lattice is compact Hausdorff and totally disconnected.
Proof. Let \( X \) be the Stone space of a Boolean lattice \( L \) . If \( P \neq Q \) in \( X \), then, say, \( a \in P, a \notin Q \) for some \( a \in L \), and then \( Q \in V\left( a\right) \) and \( P \in V\left( {a}^{\prime }\right) = V{\left( a\right) }^{\prime } \) . Therefore \( X \) is Hausdorff. Moreover, e...
Yes
Theorem 5.9 (Stone [1934]). Every Boolean lattice is isomorphic to the lattice of closed and open subsets of its Stone space.
Proof. Let \( L \) be a Boolean lattice and let \( X \) be its Stone space. For every \( a \in L, V\left( a\right) \) is open in \( X \), and is closed in \( X \) since \( X \smallsetminus V\left( a\right) = V\left( {a}^{\prime }\right) \) is open. Conversely, if \( U \in \mathrm{L}\left( X\right) \) is a closed and op...
Yes
Proposition 1.3. Let \( A \) be a universal algebra of type \( T \) . For an equivalence relation \( \mathcal{E} \) on \( A \) the following conditions are equivalent:\n\n(1) there exists a type- \( T \) algebra structure on \( A/\mathcal{E} \) such that the canonical projection \( \pi : A \rightarrow A/\mathcal{E} \) ...
Proof. (1) implies (2); that (2) implies (3) follows from the definitions.\n\n(3) implies (1). Let \( Q = A/\mathcal{E} \) and let \( \pi : A \rightarrow Q \) be the projection. For every \( \omega \in T \) of arity \( n \) and every equivalence classes \( {E}_{1},\ldots ,{E}_{n} \), the set\n\n\[{\omega }_{A}\left( {{...
Yes
Theorem 1.8 (Homomorphism Theorem). If \( \varphi : A \rightarrow B \) is a homomorphism of universal algebras, then \( \ker \varphi \) is a congruence on \( A,\operatorname{Im}\varphi \) is a subalgebra of \( B \), and \[ A/\ker \varphi \cong \operatorname{Im}\varphi \] in fact, there is an isomorphism \( \theta : A/\...
Proof. First, \( \ker \varphi \) is a congruence on \( A \) by definition, and it is clear that \( \operatorname{Im}\varphi \) is a subalgebra of \( B \) . Let \( \theta : A/\ker \varphi \rightarrow \operatorname{Im}\varphi \) be the bijection that sends an equivalence class \( E \) of \( \ker \varphi \) to the sole el...
Yes
Proposition 2.1. Let \( X \) be a subset of a universal algebra \( A \) of type \( T \) . Define \( {S}_{k} \subseteq A \) for every integer \( k \geqq 0 \) by \( {S}_{0} = X \) ; if \( k > 0 \), then \( {S}_{k} \) is the set of all \( \omega \left( {{w}_{1},\ldots ,{w}_{n}}\right) \) in which \( \omega \in T \) has ar...
By 2.1, every element of \( \langle X\rangle \) can be calculated in finitely many steps from elements of \( X \) and operations on \( A \) (using \( k \) operations when \( x \in {S}_{k} \) ). In general, this calculation can be performed in several different ways. The simplest way to construct an algebra of type \( T...
No
Proposition 2.2. If \( w \in {W}_{X}^{T} \), then \( w \in {W}_{Y}^{T} \) for some finite subset \( Y \) of \( X \) .
Proof. We have \( w \in {W}_{k} \) for some \( k \) and prove the result by induction on \( k \) . If \( w \in {W}_{0} \), then \( w \in X \) and \( Y = \{ w\} \) serves. If \( k > 0 \) and \( w \in {W}_{k} \), then \( w = \left( {\omega ,{w}_{1},\ldots ,{w}_{n}}\right) \), where \( \omega \in T \) has arity \( n \) an...
Yes
Proposition 2.3. The word algebra \( {W}_{X}^{T} \) of type \( T \) on a set \( X \) is generated by \( X \) . Moreover, every mapping of \( X \) into a universal algebra of type \( T \) extends uniquely to a homomorphism of \( {W}_{X}^{T} \) into \( A \) .
Proof. \( W = {W}_{X}^{T} \) is generated by \( X \), by 2.1. Let \( f \) be a mapping of \( X \) into a universal algebra \( A \) of type \( T \) . If \( \varphi : W \rightarrow A \) is a homomorphism that extends \( f \), then necessarily \( \varphi \left( x\right) = f\left( x\right) \) for all \( x \in X \) and \( \...
Yes
Proposition 3.1. Every variety is closed under subalgebras, homomorphic images, direct products, and directed unions.
Proof. Let \( \mathcal{V} = \mathrm{V}\left( \mathcal{J}\right) \) be the variety of all universal algebras \( A \) of type \( T \) that satisfy a set \( \mathcal{J} \subseteq {W}_{X}^{T} \times {W}_{X}^{T} \) of identities. An algebra \( A \) of type \( T \) belongs to \( \mathcal{V} \) if and only if \( \varphi \left...
Yes
Theorem 3.3. Let \( \mathcal{C} \) be a class of universal algebras of the same type, that is closed under isomorphisms, direct products, and subalgebras (for instance, a variety). For every set \( X \) there exists a universal algebra that is free on \( X \) in the class C.
Proof. We give a direct proof; a better proof will be found in Section XVI.10. Given a set \( X \), let \( {\left( {\mathcal{E}}_{i}\right) }_{i \in I} \) be the set of all congruences \( {\mathcal{E}}_{i} \) on \( {W}_{X}^{T} \) such that \( {W}_{X}^{T}/{\mathcal{E}}_{i} \in \mathcal{C} \) ; let \( {C}_{i} = {W}_{X}^{...
Yes
Theorem 3.4 (Birkhoff [1935]). A nonempty class of universal algebras of the same type is a variety if and only if it is closed under direct products, subalgebras, and homomorphic images.
Proof. First we prove the following: when \( F \) is free in a class \( \mathcal{C} \) on an infinite set, relations that hold in \( F \) yield identities that hold in every \( C \in \mathcal{C} \) :
No
(1) There exist homomorphisms \( \sigma : {W}_{Y}^{T} \rightarrow {W}_{X}^{T} \) and \( \mu : {W}_{X}^{T} \rightarrow {W}_{Y}^{T} \) such that \( \sigma \circ \mu \) is the identity on \( {W}_{X}^{T} \) and \( \mu \left( {\sigma \left( p\right) }\right) = p,\mu \left( {\sigma \left( q\right) }\right) = q \) .
Proof. (1). By 2.2, \( p, q \in {W}_{Z}^{T} \) for some finite subset \( Z \) of \( Y \) . There is an injection \( h : X \rightarrow Y \) such that \( h\left( X\right) \) contains \( Z \) . The inverse bijection \( h\left( X\right) \rightarrow X \) can be extended to a surjection \( g : Y \rightarrow X \) ; then \( g ...
Yes
Lemma 3.6. Let \( \mathcal{C} \) be a class of universal algebras of the same type \( T \), that is closed under isomorphisms, direct products, and subalgebras. Let A be a nonempty universal algebra of type \( T \) such that every identity that holds in every \( C \in \mathcal{C} \) also holds in \( A \) . Then \( A \)...
Proof. There is an infinite set \( Y \) and a mapping \( f \) of \( Y \) into \( A \) such that \( A \) is generated by \( f\left( Y\right) \) : indeed, \( A \) is generated by some subset \( S \) ; if \( S \) is infinite, then \( Y = S \) serves; otherwise, construct \( Y \) by adding new elements to \( S \), which \(...
Yes
Proposition 3.7. Let \( \mathcal{C} \) be a class of universal algebras of type \( T \) . The variety generated by \( \mathcal{C} \) consists of all homomorphic images of subalgebras of direct products of members of \( \mathcal{C} \) .
Proof. For any class \( \mathcal{C} \) of universal algebras of type \( T \) :\n\n(1) a homomorphic image of a homomorphic image of a member of \( \mathcal{C} \) is a homomorphic image of a member of \( \mathcal{C} \) ; symbolically, \( \mathrm{{HH}}\mathcal{C} \subseteq \mathrm{H}\mathcal{C} \) ;\n\n(2) a subalgebra o...
Yes
Proposition 4.1. Let \( {\left( {A}_{i}\right) }_{i \in I} \) be universal algebras of type \( T \) . A universal algebra \( A \) of type \( T \) is isomorphic to a subdirect product of \( {\left( {A}_{i}\right) }_{i \in I} \) if and only if there exist surjective homomorphisms \( {\varphi }_{i} : A \rightarrow {A}_{i}...
Proof. Let \( P \) be a subdirect product of \( {\left( {A}_{i}\right) }_{i \in I} \) . The inclusion homomorphism \( \iota : P \rightarrow \mathop{\prod }\limits_{{i \in I}}{A}_{i} \) and projections \( {\pi }_{j} : \mathop{\prod }\limits_{{i \in I}}{A}_{i} \rightarrow {A}_{j} \) yield surjective homomorphisms \( {\rh...
Yes
Proposition 4.3. A universal algebra \( A \) is subdirectly irreducible if and only if \( A \) has more than one element and the equality on \( A \) is not the intersection of congruences on \( A \) that are different from the equality.
The proof is an exercise in further deduction from Proposition 4.1.
No
Theorem 4.4 (Birkhoff [1944]). Every nonempty universal algebra is isomorphic to a subdirect product of subdirectly irreducible universal algebras. In any variety \( \mathcal{V} \), every nonempty universal algebra \( A \in \mathcal{V} \) is isomorphic to a subdirect product of subdirectly irreducible universal algebra...
Proof. Let \( A \) be a nonempty algebra of type \( T \) . By 1.5, the union of a chain of congruences on \( A \) is a congruence on \( A \) . Let \( a, b \in A, a \neq b \) of \( A \) . If \( {\left( {\mathcal{C}}_{i}\right) }_{i \in I} \) is a chain of congruences on \( A \), none of which contains the pair \( \left(...
Yes
An abelian group is subdirectly irreducible if and only if it is isomorphic to \( {\mathbb{Z}}_{{p}^{\infty }} \) or to \( {\mathbb{Z}}_{{p}^{n}} \) for some \( n > 0 \) .
Proof. Readers will verify that \( {\mathbb{Z}}_{{p}^{\infty }} \) and \( {\mathbb{Z}}_{{p}^{n}} \) (where \( n > 0 \) ) are subdirectly irreducible. Conversely, every abelian group \( A \) can, by X.4.9 and X.4.10, be embedded into a direct product of copies of \( \mathbb{Q} \) and \( {\mathbb{Z}}_{{p}^{\infty }} \) f...
No
Every distributive lattice is isomorphic to a subdirect product of two-element lattices. A distributive lattice is subdirectly irreducible if and only if it has just two elements.
Proof. To each prime ideal \( P \neq \varnothing, L \) of a distributive lattice \( L \) there corresponds a lattice homomorphism \( {\varphi }_{P} \) of \( L \) onto \( {L}_{2} \), defined by \( {\varphi }_{P}\left( x\right) = 0 \) if \( x \in P,{\varphi }_{P}\left( x\right) = 1 \) if \( x \notin P \) . The homomorphi...
Yes
Lemma 4.7. Let \( F \) be the free commutative semigroup on \( {X}_{1},\ldots ,{X}_{n} \) . Every congruence \( \mathcal{E} \) on \( F \) is induced by an ideal of \( \mathbb{Z}\left\lbrack {{X}_{1},\ldots ,{X}_{n}}\right\rbrack \) . Every commutative semigroup with \( n \) generators is determined by an ideal of \( \m...
Proof. Let \( \mathfrak{E} \) be the ideal of \( \mathbb{Z}\left\lbrack {{X}_{1},\ldots ,{X}_{n}}\right\rbrack \) generated by all binomials \( {X}^{a} - {X}^{b} \) such that \( {X}^{a}\mathcal{E}{X}^{b} \) in \( F \) . The ideal \( \mathfrak{E} \) induces a congruence \( \overline{\mathcal{E}} \) on \( F \), in which ...
Yes
Every commutative semigroup with \( n \) generators has a sub-direct decomposition into finitely many commutative semigroups determined by primary ideals of \( \mathbb{Z}\left\lbrack {{X}_{1},\ldots ,{X}_{n}}\right\rbrack \) .
Let \( S \) be a commutative semigroup with \( n \) generators \( {x}_{1},\ldots ,{x}_{n} \). By 4.7, \( S \cong F/\mathcal{E} \), where \( \mathcal{E} \) is induced by an ideal \( \mathfrak{E} \) of \( \mathbb{Z}\left\lbrack {{X}_{1},\ldots ,{X}_{n}}\right\rbrack \). In the Noetherian ring \( \mathbb{Z}\left\lbrack {{...
Yes
Proposition 1.2. In the category Grps of groups and homomorphisms, a morphism is a monomorphism if and only if it is injective.
Proof. Let \( \mu : A \rightarrow B \) be a monomorphism in Grps. Assume that \( \mu \left( x\right) = \) \( \mu \left( y\right) \) . Since \( \mathbb{Z} \) is free on \( \{ 1\} \) there exist homomorphisms \( \alpha ,\beta : \mathbb{Z} \rightarrow A \) such that \( \alpha \left( 1\right) = x \) and \( \beta \left( 1\r...
Yes
Proposition 1.3. In the category Grps of groups and homomorphisms, a morphism is an epimorphism if and only if it is surjective.
Proof. Surjective homomorphisms are epimorphisms. Conversely, let \( \varphi \) : \( G \rightarrow H \) be a homomorphism of groups that is not surjective. Construct isomorphic copies \( {H}_{1},{H}_{2} \) of \( H \) that contain \( \operatorname{Im}\varphi \) as a subgroup and satisfy \( {H}_{1} \cap {H}_{2} = \operat...
Yes
Proposition 3.2. Let \( \mathcal{C} \) be a category and let \( \mathcal{G} \) be a [small] graph. Every diagram \( D : \mathcal{G} \rightarrow \mathcal{C} \) extends uniquely to a functor \( \widehat{D} : \widehat{\mathcal{G}} \rightarrow \mathcal{C} \) ; every morphism \( D \rightarrow E \) of diagrams over \( \mathc...
Proof. The objects of \( \widehat{\mathcal{G}} \) are the vertices of \( \mathcal{G} \), and the morphisms of \( \widehat{\mathcal{G}} \) are the empty paths \( \left( {i, i}\right) \) and all nonempty paths \( \left( {i,{a}_{1},\ldots ,{a}_{n}, j}\right) \) . The latter are compositions in \( \widehat{\mathcal{G}} : \...
Yes
Proposition 4.1. The category Sets is complete; in fact, in Sets, a limit can be assigned to every diagram.
Proof. Let \( D \) be a diagram in Sets over a graph \( \mathcal{G} \) . Let \( P = \mathop{\prod }\limits_{{i \in \mathcal{G}}}{D}_{i} \) be the Cartesian product (where \
No
Proposition 4.4. A category that has products and equalizers is complete. If in a category \( \mathcal{C} \) a product can be assigned to every family of objects of \( \mathcal{C} \), and an equalizer can be assigned to every pair of coterminal morphisms of \( \mathcal{C} \), then a limit can be assigned to every diagr...
Proof. Let \( \mathcal{G} \) be a graph, let \( E \) be the set of its edges, and let \( o, d \) be the origin and destination mappings of \( \mathcal{G} \), so that \( a : o\left( a\right) \rightarrow d\left( a\right) \) for every edge \( a \) . Let \( D \) be a diagram over \( \mathcal{G} \) . Let \( P = \mathop{\pro...
Yes
Proposition 4.6. The category \( {}_{R} \) Mods is cocomplete; in fact, in \( {}_{R} \) Mods, a colimit can be assigned to every diagram.
Proof. Let \( D \) be a diagram in \( {}_{R} \) Mods over a graph \( \mathcal{G} \) . Let \( S = {\bigoplus }_{i \in \mathcal{G}}{D}_{i} \) be the direct sum and let \( {\iota }_{i} : {D}_{i} \rightarrow S \) be the injections. Let \( K \) be the submodule of \( S \) generated by all \( {\iota }_{j}\left( {{D}_{a}\left...
Yes
Proposition 4.7. Let \( \mathcal{G} \) be a graph and let \( \mathcal{C} \) be a category in which a limit can be assigned to every diagram over \( \mathcal{G} \) . There is a limit functor from Diag \( \left( {\mathcal{G},\mathcal{C}}\right) \) to \( \mathcal{C} \) that assigns to each diagram \( D \) over \( \mathcal...
Dually, if a colimit can be assigned to every diagram over \( \mathcal{G} \), then there is a colimit functor Diag \( \left( {\mathcal{G},\mathcal{C}}\right) \rightarrow \mathcal{C} \) .
No
Proposition 5.1. For objects \( A, B, P \) of an additive category the following conditions are equivalent:\n\n(1) There exist morphisms \( \pi : P \rightarrow A \) and \( \rho : P \rightarrow A \) such that \( P \) is a product of \( A \) and \( B \) with projections \( \pi \) and \( \rho \) .\n\n(2) There exist morph...
Proof. (1) implies (3). The universal property of products yields morphisms \( \iota : A \rightarrow P,\kappa : B \rightarrow P \) such that \( {\pi \iota } = {1}_{A},{\rho \iota } = 0,{\pi \kappa } = 0 \), and \( {\rho \kappa } = {1}_{B} \) . Then \( \pi \left( {{\iota \pi } + {\kappa \rho }}\right) = \pi ,\rho \left(...
Yes
Proposition 5.2. If \( \alpha ,\beta : A \rightarrow B \) are morphisms of an additive category, and the biproducts \( A \oplus A \) and \( B \oplus B \) exist, then \( \alpha + \beta = {\nabla }_{B}\left( {\alpha \oplus \beta }\right) {\Delta }_{A} \) .
Proof. Let \( \pi ,\rho : A \oplus A \rightarrow A \) and \( {\pi }^{\prime },{\rho }^{\prime } : B \oplus B \rightarrow B \) be the projections, and let \( {\iota }^{\prime },{\kappa }^{\prime } : B \rightarrow B \oplus B \) be the injections. By 5.1, \( {\iota }^{\prime }{\pi }^{\prime } + {\kappa }^{\prime }{\rho }^...
Yes
Proposition 5.3. An abelian category has finite limits and colimits.
Proof. In an abelian category, every nonempty finite family \( {A}_{1},\ldots ,{A}_{n} \) has a product \( \left( {\ldots \left( {\left( {{A}_{1} \times {A}_{2}}\right) \times {A}_{3}}\right) \times \ldots }\right) \times {A}_{n} \) . The empty sequence also has a product, the zero object. Hence an abelian category has...
Yes
Lemma 5.4. Let \( \mu \) be a monomorphism and let \( \sigma \) be an epimorphism. In an abelian category, \( \mu \) is a kernel of \( \sigma \) if and only if \( \sigma \) is a cokernel of \( \mu \) .
Proof. First, \( \sigma \) is a cokernel of some \( \alpha \) . Assume that \( \mu \) is a kernel of \( \sigma \) . Then \( {\sigma \mu } = 0 \), and \( \alpha \) factors through \( \mu : \alpha = {\mu \xi } \), since \( {\sigma \alpha } = 0 \) . If \( {\varphi \mu } = 0 \) , then \( {\varphi \alpha } = 0 \) and \( \va...
Yes
Proposition 5.5. A morphism of an abelian category is a monomorphism if and only if it has a kernel that is a zero morphism; an epimorphism if and only if it has a cokernel that is a zero morphism; an isomorphism if and only if it is both a monomorphism and an epimorphism.
Proof. We prove the last part and leave the first two parts as exercises. In any category, an isomorphism is both a monomorphism and an epimorphism. Conversely, let \( \alpha : A \rightarrow B \) be both a monomorphism and an epimorphism of an abelian category. Let \( \gamma \) be a cokernel of \( \alpha \) . Then \( {...
No
Proposition 5.6 (Homomorphism Theorem). Let \( \alpha \) be a morphism of an abelian category; let \( \iota \) be an image of \( \alpha \), and let \( \rho \) be a coimage of \( \alpha \) . There exists a unique isomorphism \( \theta \) such that \( \alpha = {\iota \theta \rho } \) .
Proof. Construct the following diagram:\n\n![5e708ed9-3d6d-4f59-a748-eaac13dfd780_615_0.jpg](images/5e708ed9-3d6d-4f59-a748-eaac13dfd780_615_0.jpg)\n\nLet \( \kappa : K \rightarrow A \) and \( \gamma : B \rightarrow C \) be a kernel and cokernel of \( \alpha : A \rightarrow B \) . Let \( \iota : I \rightarrow B \) be a...
Yes
Proposition 6.1. For two functors \( F : \mathcal{A} \rightarrow \mathcal{C} \) and \( G : \mathcal{C} \rightarrow \mathcal{A} \) the following conditions are equivalent:\n\n(1) there exists a natural transformation \( \eta : {1}_{\mathcal{A}} \rightarrow G \circ F \) such that for every morphism \( \alpha : A \rightar...
Proof. (1) implies (2). Applying (1) to \( {1}_{G\left( C\right) } : G\left( C\right) \rightarrow G\left( C\right) \) yields a morphism \( {\varepsilon }_{C} : F\left( {G\left( C\right) }\right) \rightarrow C \), unique such that\n\n\[ G\left( {\varepsilon }_{C}\right) {\eta }_{G\left( C\right) } = {1}_{G\left( C\right...
Yes
Proposition 6.2. Any two left adjoints of the same functor are naturally isomorphic. Any two right adjoints of the same functor are naturally isomorphic.
This follows from the universal properties.
No
Proposition 6.6. Every right adjoint functor preserves limits. Every left adjoint functor preserves colimits.
Proof. Let \( F : \mathcal{A} \rightarrow \mathcal{C} \) be a left adjoint of \( G : \mathcal{C} \rightarrow \mathcal{A} \), and let \( \lambda : L \rightarrow D \) be a limit cone of a diagram \( D \) in \( \mathcal{C} \) over some graph \( \mathcal{G} \). We want to show that \( G\left( \lambda \right) : G\left( L\ri...
Yes
Proposition 7.1. In every category, any two initial objects are isomorphic, and any two terminal objects are isomorphic.
Proof. Let \( A \) and \( B \) be initial objects. There exists a morphism \( \alpha : A \rightarrow B \) and a morphism \( \beta : B \rightarrow A \) . Then \( {1}_{A} \) and \( {\beta \alpha } \) are morphisms from \( A \) to \( A \) ; since \( A \) is an initial object, \( {\beta \alpha } = {1}_{A} \) . Similarly, \...
Yes
Proposition 7.2. A locally small, complete category \( \mathcal{C} \) has an initial object if and only if it satisfies the solution set condition:\n\nthere exists a set \( \mathcal{S} \) of objects of \( \mathcal{C} \) such that there is for every object \( A \) of \( \mathcal{C} \) at least one morphism from some \( ...
Proof. If \( \mathcal{C} \) has an initial object \( C \), then \( \{ C\} \) is a solution set. Conversely, let \( \mathcal{C} \) have a solution set \( \mathcal{S} \) . Since \( \mathcal{C} \) is complete, \( \mathcal{S} \) has a product \( P \) in \( \mathcal{C} \) . Then \( \{ P\} \) is a solution set: for every obj...
Yes
Lemma 7.4. Let \( \mathcal{C} \) be a locally small category in which a limit can be assigned to every diagram, let \( G : \mathcal{C} \rightarrow \mathcal{A} \) be a functor, and let \( A \) be an object of \( \mathcal{A} \) . If \( G \) preserves limits, then a limit can be assigned to every diagram in \( \left( {A \...
Proof. Let \( \Delta \) be a diagram in \( \left( {A \downarrow G}\right) \) over a graph \( \mathcal{G} \) . For every vertex \( i \) of \( \mathcal{G},{\Delta }_{i} = \left( {{\delta }_{i},{D}_{i}}\right) \), where \( {\delta }_{i} : A \rightarrow G\left( {D}_{i}\right) \) ; for every edge \( a : i \rightarrow j \) ,...
Yes
Proposition 8.1 Let \( \\left( {F, G,\\eta ,\\varepsilon }\\right) \) be an adjunction from \( \\mathcal{A} \) to \( \\mathcal{C} \) . Let \( T = {GF} \) and \( \\mu = {G\\varepsilon F} : {TT} \\rightarrow T \) . The following diagrams commute: ![5e708ed9-3d6d-4f59-a748-eaac13dfd780_625_0.jpg](images/5e708ed9-3d6d-4f59...
Proof. Since \( \\varepsilon \) is a natural transformation, the square below left commutes ![5e708ed9-3d6d-4f59-a748-eaac13dfd780_625_1.jpg](images/5e708ed9-3d6d-4f59-a748-eaac13dfd780_625_1.jpg) ![5e708ed9-3d6d-4f59-a748-eaac13dfd780_625_2.jpg](images/5e708ed9-3d6d-4f59-a748-eaac13dfd780_625_2.jpg)\n\nfor every objec...
Yes
Proposition 8.2. Let \( \\left( {F, G,\\eta ,\\varepsilon }\\right) \) be an adjunction from \( \\mathcal{A} \) to \( \\mathcal{C} \) and let \( \\left( {T,\\eta ,\\mu }\\right) = \\left( {{GF},\\eta ,{G\\varepsilon F}}\\right) \) be the triple it induces on \( \\mathcal{A} \). For every object \( C \) of \( \\mathcal{...
Proof. The diagrams below commute, the first since \( \\varepsilon \) is a natural transformation, the second by 6.5; hence \( \\left( {{GC}, G{\\varepsilon }_{C}}\\right) \) is a \( T \) -algebra. ![5e708ed9-3d6d-4f59-a748-eaac13dfd780_626_4.jpg](images/5e708ed9-3d6d-4f59-a748-eaac13dfd780_626_4.jpg)\n\nIf \( \\gamma ...
Yes
If \( \left( {T,\eta ,\mu }\right) \) is a triple on a category \( \mathcal{A} \), then \( T \) -algebras and their homomorphisms are the objects and morphisms of a category \( {\mathcal{A}}^{T} \) ; moreover, there is an adjunction \( \left( {{F}^{T},{G}^{T},{\eta }^{T},{\varepsilon }^{T}}\right) \) from \( \mathcal{A...
Proof. It is immediate that \( T \) -algebras and their homomorphisms constitute a category \( {\mathcal{A}}^{T} \) with a forgetful functor \( {G}^{T} : {\mathcal{A}}^{T} \rightarrow \mathcal{A} \) . The definition of triples shows that \( {F}^{T}A = \left( {{TA},{\mu }_{A}}\right) \) is a \( T \) -algebra. If \( \alp...
Yes
Proposition 8.4. Let \( \left( {F, G,\eta ,\varepsilon }\right) \) be an adjunction from \( \mathcal{A} \) to \( \mathcal{C} \) and let \( \left( {T,\eta ,\mu }\right) = \left( {{GF},\eta ,{G\varepsilon F}}\right) \) be the triple it induces on \( \mathcal{A} \) . There is a unique functor \( Q : \mathcal{C} \rightarro...
Proof. By 8.2, \( \left( {{GC}, G{\varepsilon }_{C}}\right) \) is a \( T \) -algebra for every object \( C \) of \( \mathcal{C} \), and, if \( \gamma : C \rightarrow D \) is a morphism of \( \mathcal{C} \), then \( {G\gamma } : \left( {{GC}, G{\varepsilon }_{C}}\right) \rightarrow \left( {{GD}, G{\varepsilon }_{D}}\rig...
Yes
Proposition 9.1. (1) If \( \left( {A,\varphi }\right) \) is a T-algebra, then \( \varphi \) is a split coequalizer of \( {\mu }_{A} \) and \( {T\varphi } \).
Proof. (1). We saw that \( \varphi \) is a split coequalizer of \( \alpha = {\mu }_{A} \) and \( \beta = {T\varphi } \), with \( v = {\eta }_{A} \) and \( \kappa = {\eta }_{TA} \) . \( ▱ \)
Yes
Proposition 9.2. The functor \( {G}^{T} \) creates coequalizers of pairs \( \alpha ,\beta \) with a split coequalizer in \( \mathcal{A} \) .
Proof. Let \( \alpha ,\beta : \left( {A,\varphi }\right) \rightarrow \left( {B,\psi }\right) \) be homomorphisms of \( T \) -algebras that have a split coequalizer \( \sigma : B \rightarrow C \) in \( \mathcal{A} \) . We need to show that there is a unique \( T \) -algebra \( \left( {C,\chi }\right) \) such that \( \si...
Yes
Theorem 9.3 (Beck). A functor \( G : \mathcal{C} \rightarrow \mathcal{A} \) with a left adjoint is tripleable if and only if it creates coequalizers of pairs \( \alpha ,\beta \) such that \( {G\alpha },{G\beta } \) have a split coequalizer in \( \mathcal{A} \) .
Theorem 9.3 follows from Proposition 9.2 and from a result that is similar to Proposition 8.4:
No
Proposition 9.5. The forgetful functor from Grps to Sets is tripleable.
Proof. We show that this functor creates coequalizers of pairs \( \alpha ,\beta : G \rightarrow H \) of group homomorphisms that have a split coequalizer \( \sigma : H \rightarrow K \) in Sets .\n\nLet \( {m}_{G} : G \times G \rightarrow G \) and \( {m}_{H} : H \times H \rightarrow H \) be the group operations on \( G ...
Yes
Proposition 10.1. If \( \mathcal{C} \) is a class of universal algebras of type \( T \) that is closed under products and subalgebras (for instance, a variety), then \( \mathcal{C} \) is complete; in fact, a limit can be assigned to every diagram in \( \mathcal{C} \), and the forgetful functor from C to Sets preserves ...
Proof. Let \( D \) be a diagram in \( \mathcal{C} \) over a graph \( \mathcal{G} \) . Let \( P = \mathop{\prod }\limits_{{i \in \mathcal{G}}}{D}_{i} \) be the direct product, with projections \( {\pi }_{i} : P \rightarrow {D}_{i} \) and componentwise operations,\n\n\[ \omega \left( {{\left( {x}_{1i}\right) }_{i \in \ma...
Yes
Theorem 10.2. Let \( \mathcal{C} \) be a class of universal algebras of the same type, that is closed under isomorphisms, direct products, and subalgebras (for instance, a variety). The forgetful functor from \( \mathcal{C} \) to Sets has a left adjoint. Hence there is for every set \( X \) a universal algebra that is ...
Proof. We show that the forgetful functor \( G : \mathcal{C} \rightarrow \) Sets has a left adjoint \( F \) ; then \( F \) assigns to each set \( X \) an algebra \( {F}_{X} \in \mathcal{C} \) that is free on \( X \) in the class \( \mathcal{C} \) : for every mapping \( f \) of \( X \) into a universal algebra \( A \in ...
Yes
Theorem 10.4. For every variety \( \mathcal{V} \), the forgetful functor from \( \mathcal{V} \) to Sets is tripleable.
Proof. We invoke Beck’s theorem. Let \( \mathcal{V} \) be a variety of type \( T \) . The forgetful functor from \( \mathcal{V} \) to Sets has a left adjoint by 10.2 ; we show that it creates coequalizers of pairs \( \alpha ,\beta : A \rightarrow B \) of homomorphisms of algebras \( A, B \in \mathcal{V} \) , which have...
Yes
Proposition 1.1. For a partially ordered set \( X \) the following conditions are equivalent:\n\n(1) every infinite ascending sequence \( {x}_{1} \leqq {x}_{2} \leqq \cdots \leqq {x}_{n} \leqq {x}_{n + 1} \leqq \cdots \) of elements of \( X \) terminates (is eventually stationary): there exists \( N > 0 \) such that \(...
Proof. (1) implies (2), since a strictly ascending infinite sequence cannot terminate.\n\n(2) implies (3). If the nonempty set \( S \) in (c) has no maximal element, then one can choose \( {x}_{1} \in S \) ; since \( {x}_{1} \) is not maximal in \( S \) one can choose \( {x}_{1} < {x}_{2} \in S \) ; since \( {x}_{2} \)...
Yes
Proposition 1.2. The subgroups of a group \( G \) satisfy the ascending chain condition if and only if every subgroup of \( G \) is finitely generated.
Proof. Assume that every subgroup of \( G \) is finitely generated, and let \( {H}_{1} \subseteq \) \( {H}_{2} \subseteq \cdots \subseteq {H}_{n} \subseteq {H}_{n + 1} \subseteq \cdots \) be an infinite ascending sequence of subgroups of \( G \) . The union \( H = \mathop{\bigcup }\limits_{{n > 0}}{H}_{n} \) is a subgr...
Yes
Proposition 2.1. The axiom of choice is equivalent to the following statement: when \( I \) is a nonempty set, and \( {\left( {S}_{i}\right) }_{i \in I} \) is a family of nonempty sets, then \( \mathop{\prod }\limits_{{i \in I}}{S}_{i} \) is nonempty.
Proof. Recall that \( \mathop{\prod }\limits_{{i \in I}}{S}_{i} \) is the set of all mappings (usually written as families) that assign to each \( i \in I \) some element of \( {S}_{i} \) . If \( I \neq \varnothing \) and \( {S}_{i} \neq \varnothing \) for all \( i \), and the axiom of choice holds, then \( \mathop{\bi...
Yes
Corollary 2.3. Every equivalence relation has a cross section.
Proof. Let \( X \) be a set with an equivalence relation. Let \( \mathcal{S} \) be the set of all subsets \( S \) of \( X \) such that every equivalence class contains at most one element of \( S \) . Then \( \mathcal{S} \neq \varnothing \), since \( \varnothing \in \mathcal{S} \) . Partially order \( \mathcal{S} \) by...
Yes
Proposition 3.2. If \( \alpha \) and \( \beta \) are ordinal numbers, then \( \alpha \in \beta \) if and only \( \alpha \subsetneqq \beta \) . Hence the class Ord of all ordinal numbers is totally ordered, with \( \alpha < \beta \) if and only if \( \alpha \in \beta \) .
Proof. Since \( \beta \) is transitive, \( \alpha \in \beta \) implies \( \alpha \subseteq \beta \) ; moreover, \( \alpha \notin \alpha \) (otherwise, \( \alpha < \alpha \) in \( \beta \) ), whence \( \alpha \subsetneqq \beta \) . Conversely, assume \( \alpha \subsetneqq \beta \) . Then \( \beta \smallsetminus \alpha \...
Yes
Proposition 3.3. Every nonempty class of ordinal numbers has a least element.
Proof. Let \( \mathcal{C} \) be a nonempty class of ordinals. Let \( \alpha \in \mathcal{C} \) . We may assume that \( \alpha \) is not the least element of \( \mathcal{C} \) . Then \( \mathcal{C} \cap \alpha \neq \varnothing \) and \( \mathcal{C} \cap \alpha \subseteq \alpha \) has a least element \( \gamma \) . In fa...
Yes
Proposition 3.4. The union of a set of ordinal numbers is an ordinal number.
Proof. Let \( S \) be a set of ordinal numbers. Then \( v = \mathop{\bigcup }\limits_{{\sigma \in S}}\sigma \) is a set. By 3.2, \( S \) is a chain, and any two elements of \( S \) are elements of some \( \sigma \in S \). It follows that \( v \) is transitive, and is totally ordered, with \( x < y \) in \( v \) if and ...
Yes
Corollary 3.5. The class Ord of all ordinal numbers is not a set.
Proof. Let \( \alpha \) be an ordinal. The successor \( \beta = \alpha \cup \{ \alpha \} \) of \( \alpha \) is also an ordinal, as readers will verify. The result follows from this and 3.4. If \( {Ord} \) were a set, then \( \mathop{\bigcup }\limits_{{\alpha \in \text{ Ord }}}\alpha \) would be an ordinal number, and w...
No
Lemma 3.6. A subset \( S \) of a well ordered set \( X \) is a lower section of \( X \) if and only if either \( S = X \) or \( S = X\left( a\right) \) for some \( a \in X \) .
Proof. Let \( S \neq X \) be a lower section. Then \( X \smallsetminus S \) has a least element \( a \) . If \( x < a \), then \( x \in S \) : otherwise, \( a \) would not be the least element of \( X \smallsetminus S \) . If \( x \in S \), then \( x < a \) : otherwise, \( a \leqq x \in S \) and \( a \in S \) . Thus \(...
Yes
Lemma 3.7. Let \( S \) and \( T \) be lower sections of a well ordered set \( X \) . If \( S \cong T \) , then \( S = T \) .
Proof. Let \( S \neq T \) and let \( \theta : S \rightarrow T \) be an isomorphism. By \( {3.6}, S \subseteq T \) or \( T \subseteq S \), and we may exchange \( S \) and \( T \) if necessary and assume that \( S \nsubseteq T \) . Then we cannot have \( \theta \left( x\right) = x \) for all \( x \in S \), and the set \(...
Yes
Proposition 3.9. If \( \alpha \) is an ordinal number, then so is \( \alpha \cup \{ \alpha \} \) ; in fact, \( \alpha \cup \{ \alpha \} \) is the least ordinal \( \beta > \alpha \) .
The proof is an exercise for our avid readers.
No
Proposition 3.10. An ordinal number \( \alpha \) is a successor if and only if it has a greatest element; then the greatest element of \( \alpha \) is \( \mathop{\bigcup }\limits_{{\gamma < \alpha }}\gamma < \alpha \) and \( \alpha \) is its successor. Otherwise, \( \mathop{\bigcup }\limits_{{\gamma < \alpha }}\gamma =...
Proof. A successor \( \alpha = \beta \cup \{ \beta \} \) has a greatest element \( \beta \) . Conversely, assume that \( \alpha \) has a greatest element \( \beta \) . Then \( {\mathop{\bigcup }\limits_{{\gamma < \alpha }}}^{\prime } = \beta < \alpha \), and \( \beta < \delta \) implies \( \delta \geqq \alpha \), since...
Yes
Proposition 4.1. Let \( \mathcal{C} \) be a class of ordinal numbers such that\n\n(1) \( 0 \in \mathcal{C} \) ;\n\n(2) \( \alpha \in \mathcal{C} \) implies \( \alpha + 1 \in \mathcal{C} \) ;\n\n(3) if \( \alpha \) is a limit ordinal and \( \beta \in \mathcal{C} \) for all \( \beta < \alpha \), then \( \alpha \in \mathc...
Proof. If \( \mathcal{C} \neq \) Ord, then Ord \( \smallsetminus \mathcal{C} \) has a least element \( \alpha \), by 3.3. Then \( \mathcal{C} \) contains every \( \beta < \alpha \) . But \( \alpha \neq 0 \), by (1); \( \alpha \) is not a successor ordinal, by (2); and \( \alpha \) is not a limit ordinal, by (3). Theref...
Yes
Lemma 4.4. No set can contain a transfinite sequence \( {\left( {x}_{\alpha }\right) }_{\alpha \in \text{ Ord }} \) indexed by all ordinals, such that \( {x}_{\alpha } \neq {x}_{\beta } \) whenever \( \alpha \neq \beta \) .
Proof. In the next section we shall see that such a sequence would force the poor set to have entirely too many elements. For now we argue as follows. Let \( X \) be the subset of all \( {x}_{\alpha } \) . Order \( X \) so that \( {x}_{\alpha } < {x}_{\beta } \) if and only if \( \alpha < \beta \) . Then \( X \) is wel...
No
Proposition 5.1. Let \( {I}_{n} = \{ 1,2,\ldots, n\} \) . If \( m < n \), then \( {I}_{m} \) has fewer elements than \( {I}_{n} \) ; in fact, there is no injection \( {I}_{n} \rightarrow {I}_{m} \) .
Proof. This is not obvious since we have not established that we can count elements as usual. What is obvious is that \( {I}_{m} \subseteq {I}_{n} \) has at most as many elements as \( {I}_{n} \) . We prove by induction on \( m \) that there is no injection \( f : {I}_{n} \rightarrow {I}_{m} \) .\n\nIf \( m = 0 < n \),...
Yes
Proposition 5.2 (Cantor [1883]). Every set \( X \) has fewer elements than the set \( {2}^{X} \) of all its subsets.
Proof. There is an injection \( x \mapsto \{ x\} \) of \( X \) into \( {2}^{X} \) . To show that \( X \) has fewer elements than \( {2}^{X} \) we prove that there is no bijection of \( X \) onto \( {2}^{X} \) . Let \( f : X \rightarrow {2}^{X} \) be any mapping. Then \( S = \{ x \in X \mid x \notin f\left( x\right) \} ...
Yes
Theorem 5.3 (Cantor-Bernstein). Let \( X \) and \( Y \) be sets. If there exist an injection of \( X \) into \( Y \) and an injection of \( Y \) into \( X \), then there exists a bijection of \( X \) onto \( Y \) .
Proof. We may assume that \( X \) and \( Y \) are disjoint. Let \( f : X \rightarrow Y \) and \( g : Y \rightarrow X \) be injections. Arrange \( X \cup Y \) into disjoint families in which every element of one set begets (all by itself) one child in the other set. This imagery is due to Halmos. The child of \( x \in X...
Yes
For every set \( X \) there exists a unique cardinal number \( \left| X\right| \) such that there is a bijection of \( X \) onto \( \left| X\right| \) .
By the axiom of choice, every set \( X \) can be well ordered (Theorem 2.4) and has the same number of elements as an ordinal number, by 3.9. The least ordinal number \( \kappa \) with this property is a cardinal number (since all ordinals \( \alpha < \kappa \) have fewer elements). Moreover, \( \kappa \) is the only c...
Yes
A direct product of finitely many countable sets is countable. A union of countably many countable sets is countable.
The elements of \( \mathbb{N} \times \mathbb{N} \) can be arranged by increasing sums into a sequence \( \left( {1,1}\right) ;\left( {1,2}\right) ,\left( {2,1}\right) ;\left( {1,3}\right) ,\left( {2,2}\right) ,\left( {3,1}\right) ;\ldots \) Thus \( \mathbb{N} \times \mathbb{N} \) is countable. If now \( X \) and \( Y \...
Yes
Proposition 5.6 (Cantor [1873]). \( \mathbb{R} \) is not countable.
Proof. Let \( X \) be the set of all real numbers with a decimal expansion \( 0.{d}_{1}{d}_{2}\ldots {d}_{n}\ldots \) in which every digit \( {d}_{n} \) is either 0 or 1 . Every such \( 0.{d}_{1}{d}_{2}\ldots {d}_{n}\ldots \) is determined by a subset \( \left\{ {n \in \mathbb{N} \mid {d}_{n} = 1}\right\} \) of \( \mat...
Yes
Proposition 5.8. Let \( \kappa \) and \( \lambda \) be cardinal numbers. If \( \kappa \) or \( \lambda \) is infinite, then \( \kappa + \lambda = \max \left( {\kappa ,\lambda }\right) \) .
Proof. We show that \( \kappa + \kappa = \kappa \) when \( \kappa \) is infinite. Then \( \lambda \leqq \kappa \) implies \( \kappa \leqq \kappa + \lambda \leqq \kappa + \kappa = \kappa \) and \( \kappa + \lambda = \kappa \), and 5.8 holds.\n\nFor every set \( X,\left| X\right| + \left| X\right| = \left| {2 \times X}\r...
Yes
Proposition 5.9. Let \( \kappa \) and \( \lambda \) be nonzero cardinal numbers. If \( \kappa \) or \( \lambda \) is infinite, then \( {\kappa \lambda } = \max \left( {\kappa ,\lambda }\right) \) .
Proof. We show that \( {\kappa \kappa } = \kappa \) when \( \kappa \) is infinite. Then \( 1 \leqq \lambda \leqq \kappa \) implies \( \kappa \leqq {\kappa \lambda } \leqq {\kappa \kappa } = \kappa \) and \( {\kappa \lambda } = \kappa \), and 5.9 holds.\n\nLet \( A \) be an infinite set. As in the proof of 5.8, let \( \...
Yes
Corollary 5.10. An infinite set \( X \) has \( \left| X\right| \) finite subsets; moreover, there are \( \left| X\right| \) finite sequences of elements of \( X \) .
Proof. The set \( X \) has at least \( \left| X\right| \) finite subsets, since it has \( \left| X\right| \) subsets with one element. On the other hand, \( X \) has \( 1 \leqq \left| X\right| \) empty subset, \( \left| X\right| \) subsets with one element, at most \( \left| X\right| \left| X\right| = \left| X\right| \...
Yes
Proposition 1.2.1. Let \( q : A \coprod {B}^{n}\left( \mathcal{A}\right) \rightarrow Y \) be the quotient map taking each point to its equivalence class. Then \( q \mid A : A \rightarrow Y \) is a closed embedding, and \( q \mid {B}^{n}\left( \mathcal{A}\right) - {S}^{n - 1}\left( \mathcal{A}\right) \) is an open embed...
Proof. Equivalence classes in \( A\coprod {B}^{n}\left( \mathcal{A}\right) \) have the form \( \{ a\} \cup {f}^{-1}\left( a\right) \) with \( a \in A \), or the form \( \{ z\} \) with \( z \in {B}^{n}\left( \mathcal{A}\right) - {S}^{n - 1}\left( \mathcal{A}\right) \) . Thus \( q \mid A \) and \( q \mid \) \( {B}^{n}\le...
Yes
Proposition 1.2.2. If \( A \) is Hausdorff, \( Y \) is Hausdorff. Hence \( {e}_{\alpha }^{n} = {\operatorname{cl}}_{Y}{\overset{ \circ }{e}}_{\alpha }^{n} \) .
Proof. Let \( {y}_{1} \neq {y}_{2} \in Y \) . We seek saturated disjoint open subsets \( {U}_{1},{U}_{2} \subset \) \( {B}^{n}\left( \mathcal{A}\right) \coprod A \) whose images contain \( {y}_{1} \) and \( {y}_{2} \) respectively. There are three cases: (i) \( {q}^{-1}\left( \overrightarrow{{y}_{i}}\right) = \left\{ {...
Yes
Proposition 1.2.3. Let \( f = p \mid {S}^{n - 1}\left( \mathcal{A}\right) : {S}^{n - 1}\left( \mathcal{A}\right) \rightarrow A \) . Let \( X \) be the space obtained by attaching \( {B}^{n}\left( \mathcal{A}\right) \) to \( A \) using \( f \) . Let \( q : A \coprod {B}^{n}\left( \mathcal{A}\right) \rightarrow X \) be t...
Proof. Consider the following commutative diagram:\n\n![3fadc665-adbe-41c9-a331-e3a1ca1b17aa_24_0.jpg](images/3fadc665-adbe-41c9-a331-e3a1ca1b17aa_24_0.jpg)\n\n\n\n![3fadc665-adbe-41c9-a331-e3a1ca1b17aa_25_0.jpg](images/3fadc665-adbe-41c9-a331-e3a1ca1b17aa_25_0.jpg)\n\nFig. 1.1.\n\nBy definition of \( p \) and \( q \),...
Yes
Example 1.2.4. Let \( \left( {Y, A}\right) = \left( {{B}^{2},{S}^{1}}\right) \) . Here \( Y \) is obtained from \( A \) by attaching 2-cells, since we can take \( p : {S}^{1} \coprod {B}^{2} \rightarrow Y \) to be the identity on \( {B}^{2} \) and the inclusion on \( {S}^{1} \) . The corresponding attaching map \( f : ...
For example, define \( h : I \times I \rightarrow I \) by \( \left( {x,0}\right) \mapsto 0,\left( {x,\frac{1}{3}}\right) \mapsto \frac{1}{3} + \frac{x}{6},\left( {x,\frac{2}{3}}\right) \mapsto \frac{2}{3} - \frac{x}{6},\left( {x,1}\right) \mapsto 1 \) , and for each \( x, h \) linear on the segments \( \{ x\} \times \l...
Yes
Proposition 1.2.5. Let \( A \) be Hausdorff and let \( Y \) be obtained from \( A \) by attaching n-cells. Then the space \( Y \) has the weak topology with respect to \( \left\{ {{e}_{\alpha }^{n} \mid \alpha \in \mathcal{A}}\right\} \cup \{ A\} . \)
Proof. First, we check that \( \left\{ {{e}_{\alpha }^{n} \mid \alpha \in \mathcal{A}}\right\} \cup \{ A\} \) is suitable for defining a weak topology (see Sect. 1.1). By 1.2.1, \( A \) inherits its original topology from \( Y \) . When \( \alpha \neq \beta ,{e}_{\alpha }^{n} \cap {e}_{\beta }^{n} = {e}_{\alpha }^{n} \...
Yes
Proposition 1.2.6. Let \( A \) be Hausdorff and let \( Y \) be obtained from \( A \) by attaching n-cells. Any compact subset of \( Y \) lies in the union of \( A \) and finitely many cells of \( \left( {Y, A}\right) \) .
Proof. Suppose this were false. Then there would be a compact subset \( C \) of \( Y \) such that \( C \cap {\overset{ \circ }{e}}_{\alpha }^{n} \neq \varnothing \) for infinitely many values of \( \alpha \) . For each such \( \alpha \), pick \( {x}_{\alpha } \in {e}_{\alpha }^{n} \cap C \) . Let \( D \) be the set of ...
Yes
Proposition 1.2.8. Let \( \left( {Y, A}\right) \) be a Hausdorff pair such that \( \left\{ {{e}_{\alpha }^{ \circ } \mid \alpha \in \mathcal{A}}\right\} \) , the set of path components of \( Y - A \), is finite. Let \( n \in \mathbb{N}.Y \) is obtained from \( A \) by attaching \( n \) -cells if \( A \) is closed in \(...
Proof. \
No
Proposition 1.2.9. Let \( \left( {Y, A}\right) ,\left\{ {{e}_{\alpha } \mid \alpha \in \mathcal{A}}\right\} \) and \( n \in \mathbb{N} \) be as in 1.2.7, and let \( {p}_{\alpha } : \left( {{B}^{n},{S}^{n - 1}}\right) \rightarrow \left( {A \cup {e}_{\alpha }, A}\right) \) be a map such that \( {p}_{\alpha } \) maps \( {...
Proof. Since \( {B}^{n} \) is compact, \( {p}_{\alpha } : {B}^{n} \rightarrow {e}_{\alpha }^{n} \) is a quotient map. The restriction \( {p}_{\alpha } \mid : {B}^{n} - {S}^{n - 1} \rightarrow {\overset{ \circ }{e}}_{\alpha }^{n} \) is a bijective quotient map, hence a homeomorphism.
Yes
Proposition 1.2.12. A CW complex \( X \) has the weak topology with respect to its cells.
Proof. This is proved for \( n \) -dimensional CW complexes by induction on \( n \) , using 1.2.5. For an arbitrary CW complex \( X, U \subset X \) is open iff \( U \cap {X}^{n} \) is open in \( {X}^{n} \) for all \( n \), iff \( U \cap {e}^{i} \) is open in \( {e}^{i} \) for every \( i \) -cell \( {e}^{i} \) of \( X \...
Yes
Proposition 1.2.13. A compact subset of a CW complex lies in the union of finitely many cells. In particular, a CW complex is finite iff its underlying space is compact.
Proof. Suppose this were false. Then there would be a compact subset \( C \) of \( X \) such that \( C \cap {\overset{ \circ }{e}}_{\alpha } \neq \varnothing \) for infinitely many values of \( \alpha \) (where \( \left\{ {{e}_{\alpha } \mid \alpha \in \mathcal{A}}\right\} \) is the set of cells of \( X \) ). For each ...
Yes
Proposition 1.2.14. Let \( X \) be a Hausdorff space and let \( \left\{ {{e}_{\alpha } \mid \alpha \in \mathcal{A}}\right\} \) be a family of subspaces with the following properties:\n\n(i) \( X = \mathop{\bigcup }\limits_{\alpha }\left\{ {\overset{ \circ }{e}}_{\alpha }\right\} \) and \( {\overset{ \circ }{e}}_{\alpha...
Proof. Let \( A \subset {X}^{0} \) and let \( {e}_{\alpha } \) be a cell of \( X \) . Then \( A \cap {e}_{\alpha } \) is finite by (iv), hence compact, hence closed in \( {e}_{\alpha } \) . So \( A \) is closed in \( X \), hence also in \( {X}^{0} \) . So \( {X}^{0} \) is discrete.\n\nNext, we show that \( {X}^{n} \) h...
No
Proposition 1.2.20. Let \( \left( {X,\left\{ {X}^{n}\right\} }\right) \) be a CW complex, let \( \left\{ {{e}_{\alpha } \mid \alpha \in \mathcal{A}}\right\} \) be the set of cells of \( X \), let \( \mathcal{B} \subset \mathcal{A} \), let \( A = \cup \left\{ {{\overset{ \circ }{e}}_{\alpha } \mid \alpha \in \mathcal{B}...
Proof. We verify the axioms (i)-(iv) in the definition of a CW complex. Axioms (i) and (iii) clearly hold. To verify Axiom (ii), we show by induction that \( {A}^{n} \) is obtained from \( {A}^{n - 1} \) by attaching \( n \) -cells and that \( {A}^{n} \) is closed in \( {X}^{n} \) . This is clear when \( n = 0 \) ; ass...
Yes
Proposition 1.2.21. Each path component of a CW complex \( X \) is a subcomplex, an open subset of \( X \), and a closed subset of \( X \). Hence, a non-empty \( {CW} \) complex is connected iff it is path connected.
Proof. The first part is clear. For the rest, let \( A \) be a path component of the CW complex \( X \). Cells are path connected, being the images of balls under maps. Hence, for each cell \( e \) of \( X \), either \( e \cap A = e \) or \( e \cap A = \varnothing \). This proves \( A \) is both open and closed in \( X...
Yes
Proposition 1.2.22. If there exist pairwise disjoint open sets \( {U}_{\alpha } \subset X \) such that, for each \( \alpha ,{A}_{\alpha } \subset {U}_{\alpha } \), then \( \left( {X/ \sim ,\left\{ {\left( X/ \sim \right) }^{n}\right\} }\right) \) is a CW complex. In particular, if \( A \) is a subcomplex of \( X \), th...
Proof. Apply 1.2.14. The Hausdorff property is clear under these hypotheses.\n\nWith this CW structure, \( X/ \sim \) is the quotient complex.
No
Proposition 1.2.23. Let \( \left( {X, A}\right) \) be a CW pair and let the n-cells of \( X \) which are not cells of \( A \) be indexed by \( \mathcal{A} \) . Let \( \left\{ {{h}_{\alpha } : {B}_{\alpha }^{n} \rightarrow {e}_{\alpha }^{n} \mid \alpha \in \mathcal{A}}\right\} \) be a set of characteristic maps for thos...
Proof. By 1.2.7, \( {X}^{n} \cup A \) is obtained from \( {X}^{n - 1} \cup A \) by attaching \( n \) -cells. The result follows from the properties of the quotient topology stated in Sect. 1.1.
No
Proposition 1.3.1. Homotopy is an equivalence relation on the set of maps from \( X \) to \( Y \) .
Proof. Given \( f : X \rightarrow Y \), define \( F : f \simeq f \) by \( F\left( {x, t}\right) = f\left( x\right) \) for all \( t \in I \) ; \( F = f \circ \) (projection: \( X \times I \rightarrow X \) ), the composition of two maps. So \( F \) is a map. Thus reflexivity. Given \( F : f \simeq g \), define \( {F}^{\p...
Yes
Proposition 1.3.3. Let \( {f}_{0},{f}_{1} : \left( {X, A}\right) \rightarrow \left( {Y, B}\right) \) be homotopic rel \( {X}^{\prime } \), let \( {g}_{0},{g}_{1} : \left( {Y, B}\right) \rightarrow \left( {Z, C}\right) \) be homotopic rel \( {Y}^{\prime } \), where \( {f}_{0}\left( {X}^{\prime }\right) \subset {Y}^{\pri...
Proof. Let \( F : {f}_{0} \simeq {f}_{1} \) and \( G : {g}_{0} \simeq {g}_{1} \) be homotopies which behave as required on \( A, B, C \) and \( {X}^{\prime } \) . Let \( p : X \times I \rightarrow I \) be projection. Let \( \left( {F, p}\right) \) : \( X \times I \rightarrow Y \times I \) denote the function \( \left( ...
Yes
The spaces \( \mathbb{R},{\mathbb{R}}_{ + } \), and \( I \) are contractible.
Hence also (by 1.3.6) \( {\mathbb{R}}^{n},{\mathbb{R}}_{ + }^{n} \) and \( {B}^{n} \) are contractible. If \( p \in {S}^{n} \), then \( {S}^{n} - \{ p\} \) is homeomorphic to \( {\mathbb{R}}^{n} \) ; hence \( {S}^{n} - \{ p\} \) is contractible.
No
Proposition 1.3.8. If \( A \) is a strong deformation retract of \( X \) then \( A \hookrightarrow X \) is a homotopy equivalence.
Proof. In the notation above, \( r \) is a homotopy inverse for inclusion.
No