Q
stringlengths
4
3.96k
A
stringlengths
1
3k
Result
stringclasses
4 values
Proposition 11.1.1. The composition\n\n\[ \n{C}_{n}^{\infty }\left( {X;R}\right) \overset{\partial }{ \rightarrow }{C}_{n - 1}^{\infty }\left( {X;R}\right) \overset{\partial }{ \rightarrow }{C}_{n - 2}^{\infty }\left( {X;R}\right) \n\]\n\nis zero, for all \( n \) .
Thus \( \left( {{C}_{ * }^{\infty }\left( {X;R}\right) ,\partial }\right) \) is a chain complex. Its homology modules, denoted \( {}^{2} \) by \( {H}_{ * }^{\infty }\left( {X;R}\right) \), are the cellular homology modules based on infinite chains.
No
Proposition 11.1.6. Let \( \lbrack 0,\infty ) \) have the usual CW complex structure (vertices \( n,1 \) -cells \( \left\lbrack {n, n + 1}\right\rbrack \) for each \( n \in \mathbb{N} \) ). For any orientation, \( {H}_{n}^{\infty }\left( {\lbrack 0,\infty }\right) ;R) = \) \( 0 \) for all \( n \) .
Proof. For \( n = 0 \) this follows from 11.1.4. For \( n > 1 \) it is trivial. For \( n = 1 \), it is obvious that \( \ker \left( {\partial : {C}_{1}^{\infty }\left( {\lbrack 0,\infty }\right) ;R}\right) \rightarrow {C}_{0}^{\infty }\left( {\lbrack 0,\infty }\right) ;R)) = 0 \) .
Yes
Theorem 11.1.9. Let \( f, g : X \rightarrow Y \) be CW-proper cellular maps between oriented CW complexes of locally finite type. Assume either (a) \( f \) and \( g \) are \( {CW} \) -proper homotopic or (b) \( f \) and \( g \) are properly homotopic where \( X \) is locally finite and \( Y \) is strongly locally finit...
Proof. Similar to that of 2.7.10: in place of 1.4.3, use 10.2.3 in Case (a) and 10.1.14 in Case (b).
No
Proposition 11.2.10. Let \( \mathcal{X} \) and \( \mathcal{Y} \) be inverse sequences. A morphism \( f \) : \( \mathcal{X} \rightarrow \mathcal{Y} \) of inv- \( \mathcal{C} \) induces an isomorphism of pro- \( \mathcal{C} \) iff for suitable subsequences as above there are morphisms \( {g}_{{m}_{k}} \) of \( \mathcal{C...
![3fadc665-adbe-41c9-a331-e3a1ca1b17aa_248_0.jpg](images/3fadc665-adbe-41c9-a331-e3a1ca1b17aa_248_0.jpg)
No
If \( \left\{ {G}_{n}\right\} \) is semistable then \( \underline{\lim }{}^{1}\left\{ {G}_{n}\right\} \) is trivial.
Assume \( \left\{ {G}_{n}\right\} \) is semistable and let \( \left( {x}_{n}\right) \in \mathop{\prod }\limits_{n}{G}_{n} \) . With \( \phi \) as in the definition of \
No
Proposition 11.3.4. In this situation, there is an exact sequence of pointed sets\n\n\[ \n\{ 1\} \rightarrow \mathop{\lim }\limits_{ \leftarrow }\left\{ {G}_{n}^{\prime }\right\} \overset{\mathop{\lim }\limits_{ \leftarrow }\left\{ {i}_{n}\right\} }{ \rightarrow }\mathop{\lim }\limits_{ \leftarrow }\left\{ {G}_{n}\righ...
Proof. This is a long but straightforward check that \( \delta \) is well defined and kernel \( = \) image in each position. See page 168 of [109] for details.
No
Proposition 11.3.7. Let \( {C}_{n}^{\prime } = 0 \) for all \( n \) . Then for each \( n \) there is a short exact sequence\n\n\[ 0 \rightarrow {\mathop{\lim }\limits_{ \leftarrow }}_{i}^{1}{H}_{n + 1}\left( {C}^{\left( i\right) }\right) \overset{\bar{a}}{ \rightarrow }{H}_{n}\left( C\right) \overset{\bar{b}}{ \rightar...
Proof. Since \( {C}_{n}^{\prime } = 0 \) for all \( n \) we have a short exact sequence of chain complexes\n\n\[ 0 \rightarrow C \rightarrow \mathop{\prod }\limits_{{i = 1}}^{\infty }{C}^{\left( i\right) }\overset{s}{ \rightarrow }\mathop{\prod }\limits_{{i = 1}}^{\infty }{C}^{\left( i\right) } \rightarrow 0 \]\n\ngivi...
Yes
Proposition 11.3.8. Let \( {C}_{n} = 0 \) for all \( n \) . Then for each \( n \) there is a short exact sequence\n\n\[ 0 \rightarrow {\mathop{\lim }\limits_{ \leftarrow }}_{i}^{1}{H}_{n}\left( {C}^{\left( i\right) }\right) \overset{a}{ \rightarrow }{H}_{n}\left( {C}^{\prime }\right) \overset{b}{ \rightarrow }\mathop{\...
Remark 11.3.9. Sometimes, one wants explicit descriptions of \( a \) and \( b \) in 11.3.8. The homomorphism \( a \) is induced by inclusion. To describe \( b \), we start with \( \left( {x}_{i}\right) \in \ker {\partial }^{\prime } = {Z}_{n}\left( {C}^{\prime }\right) \) representing an element of \( {H}_{n}\left( {C}...
No
Proposition 11.3.10. Let \( \left\{ {M}_{n}\right\} \) be an inverse sequence in the category \( R \) - modules, where each \( {M}_{n} \) is finitely generated. If \( R \) is a field, then \( \left\{ {M}_{n}\right\} \) is semistable, hence \( \mathop{\lim }\limits_{ \leftarrow }{}^{1}\left\{ {M}_{n}\right\} = 0 \) .
Proof. For each \( m \), the \( R \) -dimensions of the vector spaces image \( \left( {{M}_{n} \rightarrow {M}_{m}}\right) \) are non-increasing as \( n \) increases. Since \( {M}_{m} \) has finite \( R \) -dimension, this function of \( n \) becomes constant. Hence \( \left\{ {M}_{n}\right\} \) is semistable. Apply 11...
Yes
Proposition 11.3.11. Let \( R \) be a PID and let \( M \) be a finitely generated \( R \) - module. Then \( M \) is isomorphic to \( F \oplus \operatorname{tor}M \), where \( F \) is the direct sum of \( \rho \) copies of \( R \), tor \( M \) is the direct sum of \( \tau \) cyclic modules \( R/\left( {r}_{i}\right) \),...
Proof. The first part is well known. For the last part, there exists \( r \in R \) which annihilates tor \( M \) . So tor \( M \) is a module over the ring \( R/\left( r\right) \) . This latter ring satisfies the descending chain condition (see page 243 of [156]), hence so does tor \( M \) ; see p. 158 of [156].
Yes
Proposition 11.3.12. If \( \left\{ {M}_{n}\right\} \) is an inverse sequence of finitely generated torsion \( R \) -modules, where \( R \) is a PID, then \( \left\{ {M}_{n}\right\} \) is semistable. Hence \( \mathop{\lim }\limits_{n}{}^{1}\left\{ {M}_{n}\right\} = 0. \)
Proof. This is immediate from the last sentence of 11.3.11.
No
Proposition 11.4.2. Let \( X \) be path connected. Then \( {H}_{n}^{e}\left( {X;R}\right) = 0 \) for all \( n < 0 \) .
Proof. For \( n < - 1 \), this is trivial. For \( n = - 1 \), it follows from 11.1.3 together with the above exact sequence when \( {X}^{1} \) is infinite. When \( {X}^{1} \) is finite then \( {X}^{0} \) is finite, so \( {Z}_{-1}^{e} = {C}_{0}^{\infty } = {C}_{0} = {B}_{-1}^{e} \) .
Yes
Proposition 11.4.3. A path connected CW complex \( X \) having locally finite type is countable.
Proof. We begin with \( {X}^{1} \) . If \( {X}^{1} \) is infinite then, by 11.1.4, \( {X}^{1} \) is the union of countably many finite subcomplexes. Assume, inductively, that \( {X}^{n} \) is countable. Since \( {X}^{n + 1} \) is locally finite, each cell of \( {X}^{n} \) meets only finitely many \( \left( {n + 1}\righ...
No
Proposition 11.4.4. If \( X \) is strongly locally finite and \( A \) is finite then the \( {CW} \) neighborhood \( N\left( A\right) \) is finite.
Proof. The collection \( \{ C\left( e\right) \mid e \) is a cell of \( X\} \) is locally finite, and \( A \) is compact.
No
Proposition 11.4.5. With \( X \) as above, let \( \left\{ {K}_{i}\right\} \) be a finite type filtration of \( X \) . Then, for each \( n,\left\{ {\left( {X - {K}_{i}}\right) \cap {X}^{n}}\right\} \) is a basis for the neighborhoods of the end of \( {X}^{n} \) .
Proof. First, we show that \( {U}_{i} \mathrel{\text{:=}} \left( {X - {K}_{i}}\right) \cap {X}^{n} = {X}^{n} - {K}_{i}^{n} \) is a neighborhood of the end of \( {X}^{n} \) . We have \( {X}^{n} - {U}_{i} \subset {N}_{{X}^{n}}\left( {K}_{i}^{n}\right) \), by 1.5.5. So \( \operatorname{cl}\left( {{X}^{n} - {U}_{i}}\right)...
Yes
Theorem 11.4.7. Let \( X \) be a countable oriented \( {CW} \) complex having locally finite type. Let \( \left\{ {K}_{i}\right\} \) be a finite type filtration of \( X \) . For each \( n \), there is a natural short exact sequence of \( R \) -modules\n\n\[ 0 \rightarrow {\mathop{\lim }\limits_{ \leftarrow }}_{i}^{1}\l...
Using the companion Theorem 11.3.8, we get a similar short exact sequence for \( {H}_{ * }^{e}\left( {X;R}\right) \) as follows. Consider the short exact sequences\n\n\[ 0 \rightarrow {C}_{n}\left( {X\overset{c}{ \sim }{K}_{i};R}\right) \rightarrow {C}_{n}\left( {X;R}\right) \rightarrow {C}_{n}\left( {X, X\overset{c}{ ...
Yes
Theorem 11.4.8. With hypotheses as in 11.4.7, we have, for each \( n \), a natural short exact sequence of \( R \) -modules:\n\n\[ 0 \rightarrow {\mathop{\lim }\limits_{ \leftarrow }}_{i}^{1}\left\{ {{H}_{n + 1}\left( {X\overset{c}{ \leftarrow }{K}_{i};R}\right) }\right\} \overset{a}{ \rightarrow }{H}_{n}^{e}\left( {X;...
Remark 11.4.9. Theorems 11.4.7 and 11.4.8 are the fundamental tools for computing \( {H}_{n}^{\infty }\left( {X;R}\right) \) and \( {H}_{n}^{e}\left( {X;R}\right) \) . In Remark 11.3.9, we stated the algebraic meaning of the homomorphisms \( a \) and \( b \) which occur in 11.3.8. These translate into geometric interpr...
No
Here is an example of a CW complex \( X \) which is not 1- movable at the end (see Fig. 11.3). \( X \) is the graph in \( {\mathbb{R}}^{2} \) having the points \( \{ \left( {i, j}\right) \mid i \in \mathbb{N}, j = 0 \) or 1 \( \} \) as vertices, and having the segments \( \left\lbrack {\left( {i, j}\right) ,\left( {i +...
The reduced Mayer-Vietoris sequence gives an exact sequence\n\n\[ 0 \rightarrow {H}_{1}\left( {X\overset{c}{ \hookrightarrow }{K}_{i + 1};R}\right) \oplus {H}_{1}\left( {{J}_{i};R}\right) \overset{{j}_{ * }}{ \rightarrow }{H}_{1}\left( {X\overset{c}{ \hookrightarrow }{K}_{i};R}\right) \rightarrow 0 \]\n\nThe restrictio...
Yes
To get an example of the exact sequence of 11.4.8 in which the \( {\underline{\lim }}^{1} \) term does not vanish, apply the above construction with \( {X}_{i} = {S}^{1} \) for all \( i \), and \( {f}_{i} \) the map of degree \( 2,{e}^{2\pi it} \mapsto {e}^{4\pi it} \) . The resulting \( T \) is the dyadic solenoid inv...
\[ 0 \rightarrow {\mathop{\lim }\limits_{ \leftarrow }}^{1}\{ \mathbb{Z}\overset{\times 2}{ \leftarrow }\mathbb{Z}\overset{\times 2}{ \leftarrow }\ldots \} \rightarrow {H}_{0}^{e}\left( {T;\mathbb{Z}}\right) \rightarrow \mathbb{Z} \rightarrow \mathbb{Z} \rightarrow 0. \] Since \( \left\{ {{\mathbb{Z}}^{\times 2}\overse...
Yes
Proposition 12.1.1. The composition\n\n\[ \n{C}_{n}^{\infty }\left( {X;R}\right) \overset{\delta }{ \rightarrow }{C}_{n + 1}^{\infty }\left( {X;R}\right) \overset{\delta }{ \rightarrow }{C}_{n + 2}^{\infty }\left( {X;R}\right) \n\]\n\nis zero for all \( n \) .
Proof. This follows from 2.3.3 and the corresponding statement for \( {\partial }^{ * } \) .
No
Theorem 12.1.9. [Homotopy Invariance] If \( f, g : X \rightarrow Y \) are homotopic cellular maps, then \( {f}^{ * } = {g}^{ * } : {H}^{ * }\left( {Y;R}\right) \rightarrow {H}^{ * }\left( {X;R}\right) \) . In particular, cellular cohomology is a topological invariant.
Proof. Although this theorem is analogous to 2.7.10, we prove it using 2.7.14 instead. The reason is explained in Remark 12.1.11 below.\n\nBy 1.4.3 there is a cellular homotopy \( F : X \times I \rightarrow Y \) from \( f \) to \( g \) . Let \( D \) be as in 2.7.14. Consider the diagram:\n\n![3fadc665-adbe-41c9-a331-e3...
Yes
Proposition 12.3.3. Let \( c \in {Z}_{n}^{\infty }\left( {X,\partial X;R}\right) \), let \( {e}_{\alpha }^{n} \) and \( {e}_{\beta }^{n} \) be \( n \) -cells in the same path component of \( X \), and let \( {r}_{\alpha },{r}_{\beta } \) be the coefficients of \( {e}_{\alpha }^{n} \) and \( {e}_{\beta }^{n} \) in c. Th...
Proof. First assume \( {e}_{\alpha }^{n} \cap {e}_{\beta }^{n} = {e}_{\gamma }^{n - 1} \) . Then \( {e}_{\gamma }^{n - 1} \) is not a face of any other \( n \) -cell. Since \( \partial c = 0 \) we get \( {r}_{\alpha }\left\lbrack {{e}_{\alpha }^{n} : {e}_{\gamma }^{n - 1}}\right\rbrack + {r}_{\beta }\left\lbrack {{e}_{...
Yes
Proposition 12.3.4. Let \( X \) be path connected. If \( c \) and \( {c}^{\prime } \) are fundamental cycles over \( R \) then, for some unit \( u \in R, c = u{c}^{\prime } \) .
Proof. Let the coefficient of \( {e}_{\alpha }^{n} \) in \( c \) [resp. \( {c}^{\prime } \) ] be the unit \( {u}_{\alpha } \) [resp. \( {u}_{\alpha }^{\prime } \) ]. Then \( c \) and \( {u}_{\alpha }{\left( {u}_{\alpha }^{\prime }\right) }^{-1}{c}^{\prime } \) have the same \( {e}_{\alpha }^{n} \) -coefficient, so the ...
Yes
Proposition 12.3.7. Let \( X \) be path connected. If \( {H}_{n}^{\infty }\left( {X,\partial X;R}\right) \neq 0 \) then \( X \) has a fundamental cycle over \( R \) ; i.e., \( X \) is \( R \) -orientable.
Proof. Let \( z = \mathop{\sum }\limits_{\alpha }{r}_{\alpha }{e}_{\alpha }^{n} \) be a non-zero relative cycle in \( X \) . Since \( \partial z = 0 \) ,\n\n\( {r}_{\alpha } = \pm {r}_{\beta } \) when \( {e}_{\alpha }^{n} \) and \( {e}_{\beta }^{n} \) share an \( \left( {n - 1}\right) \) -face. Since \( X \) is path co...
Yes
Proposition 12.3.10. Let \( X \) and \( Y \) be \( {CWn} \) -pseudomanifolds, and let \( f \) : \( \left( {X,\partial X}\right) \rightarrow \left( {Y,\partial Y}\right) \) be a cellular proper homotopy equivalence (of pairs). If \( c \in {Z}_{n}^{\infty }\left( {X,\partial X;R}\right) \) is a fundamental cycle for \( X...
Proof. We may assume that \( X \) is path connected: otherwise work with each path component separately. Clearly, \( {f}_{\# }\left( c\right) \in {Z}_{n}^{\infty }\left( {Y,\partial Y;R}\right) \) . Hence, by 12.3.3, \( {f}_{\# }\left( c\right) = r.d \) where \( r \in R, d \in {C}_{n}^{\infty }\left( {Y;R}\right) \) an...
Yes
Proposition 12.3.11. If \( {H}_{n - 1}^{\infty }\left( {X,\partial X;{\mathbb{Z}}_{2}}\right) = 0 \) then \( X \) is orientable.
Proof (of 12.3.11). Let \( c = \mathop{\sum }\limits_{\alpha }{e}_{\alpha }^{n} \) where \( \alpha \) ranges over all the \( n \) -cells of\n\n\( X \) . Then \( \partial c = {2d} + e \), where \( d \) has support outside \( \partial X, e \) has support in \( \partial X \), and every coefficient in \( d \) and in \( e \...
Yes
Proposition 12.3.13. If \( X \) is non-orientable then \( {H}_{n - 1}^{\infty }\left( {X,\partial X;\mathbb{Z}}\right) \) contains an element of order 2.
Proof. We refer to the proof of 12.3.11. We have \( {2d} \in {B}_{n - 1}^{\infty }\left( {X,\partial X;\mathbb{Z}}\right) \) and \( d \in {Z}_{n - 1}^{\infty }\left( {X,\partial X;\mathbb{Z}}\right) \) . If \( d \) were itself a boundary, we would have \( b \) and \( f \) with \( \partial b = d + f \) . So \( \partial ...
No
Proposition 12.3.15. Let the n-pseudomanifold \( \widetilde{X} \) be orientable. Then \( X \) is orientable iff \( H = G \) .
Proof. Let \( c = \mathop{\sum }\limits_{{g,\alpha }}{r}_{\alpha, g}g{\widetilde{e}}_{\alpha }^{n} \) be a fundamental cycle (over \( \mathbb{Z} \) ) in \( \widetilde{X} \) . Then \( {r}_{\alpha, g} = \) \( \pm 1 \) . First, let \( H = G \) . Then \( {r}_{\alpha, g} = {r}_{\alpha ,1} \) for all \( g \in G \) . Let \( d...
Yes
Theorem 12.4.2. (Universal Coefficient Theorem in homology) With \( \left( {\left\{ {C}_{n}\right\} ,\partial }\right) \) and \( B \) as above, and each \( {C}_{n} \) free, there is a natural short exact sequence of \( R \) -modules\n\n\[ 0 \rightarrow B{ \otimes }_{R}{H}_{n}\left( C\right) \overset{\beta }{ \rightarro...
This sequence splits, naturally in \( B \) but unnaturally in \( C \) .
No
Theorem 12.4.5. (Universal Coefficient Theorem in cohomology) With \( \left( {\left\{ {C}_{n}\right\} ,\partial }\right) \) and \( B \) as above, and each \( {C}_{n} \) free, there is a natural short exact sequence of \( R \) -modules\n\n\[ 0 \rightarrow {\operatorname{Ext}}_{R}\left( {{H}_{n - 1}\left( C\right), B}\ri...
Remark 12.4.6. By examining the proofs of 12.4.2 and 12.4.5, one sees that the monomorphism \( \beta \) in 12.4.2 is given by \( \beta \left( {b\otimes \{ z\} }\right) = \{ z \otimes b\} \), where \( \{ \cdot \} \) denotes homology class; and the epimorphism \( \alpha \) in 12.2.5 is given by \( \alpha \left( {\{ f\} }...
No
Theorem 12.5.1. Let \( X \) be a CW complex, let \( R \) be a PID, and let \( M \) be an \( R \) -module. There is a short exact sequence of \( R \) -modules\n\n\[ 0 \rightarrow {\operatorname{Ext}}_{R}\left( {{H}_{n - 1}\left( {X;R}\right), M}\right) \rightarrow {H}^{n}\left( {X;M}\right) \rightarrow {\operatorname{Ho...
This is natural with respect to homotopy classes of maps. It splits, but unnaturally, with respect to \( M \) .
No
Proposition 12.5.5. Let \( R \) be a PID. Let \( \left\{ {M}_{n}\right\} \) be a pro-finitely generated inverse sequence of \( R \) -modules. Then \( \left\{ {M}_{n}\right\} \) is semistable iff \( \left\{ {\bar{M}}_{n}\right\} \) is semistable.
Proof. We may assume that each \( {M}_{n} \) is finitely generated. By 11.3.11, \( \left\{ {{M}_{n},{f}_{n}^{m}}\right\} \) can be replaced by \( \left\{ {{\bar{M}}_{n} \oplus \text{tor}{M}_{n},{\bar{f}}_{n}^{m} \oplus \left( {{f}_{n}^{m} \mid \text{tor}{M}_{n}}\right) }\right\} \) . By 11.3.12, \( \left\{ {\text{tor}{...
No
Proposition 12.5.7. Let \( R \) be a PID. A pro-finitely generated inverse sequence of \( R \) -modules \( \left\{ {M}_{n}\right\} \) is pro-torsion free iff the direct limit of the corresponding direct sequence \( \left\{ {{\operatorname{Ext}}_{R}\left( {{M}_{n}, R}\right) }\right\} \) is trivial.
Proof. This proof uses homological algebra not needed elsewhere in this book. We may assume that each \( {M}_{n} \) is finitely generated. By 11.3.11 and 12.4.3, \( \mathop{\lim }\limits_{ \rightarrow }\left\{ {{\operatorname{Ext}}_{R}\left( {{M}_{n}, R}\right) }\right\} = 0 \) iff \( \mathop{\lim }\limits_{ \rightarro...
Yes
Proposition 12.5.8. Let \( R \) be a PID. Let the inverse sequence of \( R \) -modules \( \left\{ {M}_{n}\right\} \) be pro-finitely generated.\n\n(a) \( \left\{ {M}_{n}\right\} \) is pro-torsion iff \( \mathop{\lim }\limits_{ \rightarrow }\left\{ {{\operatorname{Hom}}_{R}\left( {{M}_{n}, R}\right) }\right\} = 0 \) .\n...
Proof. The proofs are similar to that of 12.5.6.
No
Proposition 12.5.9. If \( {H}_{n}\left( {X;R}\right) \) is finitely generated and \( R \) is a PID, then \( {H}_{n}\left( {X - {K}_{i};R}\right) \) is finitely generated for all \( i \) . Hence \( \left\{ {{H}_{n}\left( {X - {K}_{i};R}\right) }\right\} \) is pro-finitely generated.
Proof. Replacing \( X \) by \( {X}^{n + 1} \), we may assume \( X \) is strongly locally finite. Then, by \( {11.4.4}, N\left( {K}_{i}\right) \) is finite. By \( {1.5.5}, X = N\left( {K}_{i}\right) \cup \left( {X - {K}_{i}}\right) \) . And \( N\left( {K}_{i}\right) \cap \left( {X - {K}_{i}}\right) \) is finite. The May...
Yes
Theorem 12.5.10. Let \( X \) be a countable \( {CW} \) complex having locally finite type, let \( R \) be a PID, let \( {H}_{n}\left( {X;R}\right) \) and \( {H}_{n - 1}\left( {X;R}\right) \) be finitely generated, and let \( \left\{ {K}_{i}\right\} \) be a finite type filtration of \( X \) . (i) \( {H}_{e}^{n}\left( {X...
Proof. By 12.5.9, \( \left\{ {{H}_{k}\left( {X - {K}_{i};R}\right) }\right\} \) is pro-finitely generated for \( k = n - 1 \) and \( n \) . (i) By the previous propositions and Sect. 12.2, \( \left\{ {{H}_{n}\left( {X - {K}_{i};R}\right) }\right\} \) is semistable iff \( \mathop{\lim }\limits_{ \rightarrow }\left\{ {{\...
Yes
Corollary 12.5.11. Let \( X \) be a path connected \( {CW} \) complex having locally finite type, and let \( R \) be a PID. Then \( {H}_{e}^{0}\left( {X;R}\right) \) is countably generated and free. If \( {H}_{1}\left( {X;R}\right) \) is finitely generated, then \( {H}_{e}^{1}\left( {X;R}\right) \) is torsion free.
Proof. By 11.4.3, \( X \) is countable. Applying 12.5.10 with \( n = 0 \) we find that \( {H}_{e}^{0}\left( {X;R}\right) \) is torsion free. To show that \( {H}_{e}^{0}\left( {X;R}\right) \) is free, we apply 12.5.6 so we must show that \( \left\{ {{H}_{0}\left( {X \circeq {K}_{i};R}\right) }\right\} \) is semistable. ...
Yes
Lemma 13.2.2. Let \( {e}_{\alpha }^{k} \) and \( {e}_{\beta }^{k - 1} \) be cells of \( X \), and let \( g,\bar{g} \in G \) . Then \( \left\lbrack {{Hg}{\widetilde{e}}_{\alpha }^{k}}\right. \) : \( \left. {H\bar{g}{\widetilde{e}}_{\beta }^{k - 1}}\right\rbrack = \mathop{\sum }\limits_{{h \in H}}\left\lbrack {g{\widetil...
Proof.\n\n\[ \partial \left( {g{\widetilde{e}}_{\alpha }^{k}}\right) = \mathop{\sum }\limits_{{h \in H}}\left\lbrack {g{\widetilde{e}}_{\alpha }^{k} : h\bar{g}{\widetilde{e}}_{\beta }^{k - 1}}\right\rbrack h\bar{g}{\widetilde{e}}_{\beta }^{k - 1} + \text{ other terms. } \]\n\n\[ {\left( {p}_{H}\right) }_{\# }\partial \...
Yes
Corollary 13.2.3. Let \( X \) be a \( K\left( {G,1}\right) \) -complex. Then, for all \( k \) ,\n\n\[ \n{H}_{k}\left( {\bar{X}\left( H\right) ;R}\right) \cong {H}_{k}\left( {G, R\left( {H \smallsetminus G}\right) }\right) .\n\]\n\nIf \( X \) has finite type then\n\n\[ \n{H}_{k}^{\infty }\left( {\bar{X}\left( H\right) ;...
Proof. \( {C}_{ * }\left( {\widetilde{X};R}\right) \) gives a free \( {RG} \) -resolution of \( R \) . Apply 13.2.1.
No
Proposition 13.2.4. Let \( X \) be \( \left( {n - 1}\right) \) -aspherical. Then for all \( k \leq n - 1 \) , \( {H}_{k}\left( {\bar{X}\left( H\right) ;R}\right) \cong {H}_{k}\left( {G, R\left( {H \smallsetminus G}\right) }\right) \) . If \( {X}^{n} \) is finite, the other conclusions of 13.2.3 hold for \( k \leq n - 1...
Proof. By 7.1.5 there is a \( K\left( {G,1}\right) \) -complex \( Y \) with \( {Y}^{n} = {X}^{n} \) . The first claim follows from 13.2.1. If \( {X}^{n} \) is finite, \( \partial : {C}_{k}^{\infty }\left( {\bar{Y}\left( H\right) ;R}\right) \rightarrow {C}_{k - 1}^{\infty }\left( {\bar{Y}\left( H\right) ;R}\right) \) is...
Yes
Proposition 13.2.5. Let \( H \leq G \) . Then, for all \( k \) ,\n\n\[ \n{H}_{k}\left( {G, R\left( {H \smallsetminus G}\right) }\right) \cong {H}_{k}\left( {H, R}\right) \n\]
Proof. Let \( X \) be a \( K\left( {G,1}\right) \) -complex. By 13.2.1, we have \( {H}_{k}\left( {\bar{X}\left( H\right) ;R}\right) \cong \) \( {H}_{k}\left( {G, R\left( {H \smallsetminus G}\right) }\right) \) and (applying 13.2.1 with \( H \) replacing \( G \) ) \( {H}_{k}\left( {\bar{X}\left( H\right) ;R}\right) \con...
Yes
Corollary 13.2.7. For \( k > 1,{H}_{k}\left( {G, R{G}^{ * }}\right) \cong {H}_{k}\left( {G, R{G}^{e}}\right) \) . If \( G \) is infinite and finitely generated then \( {H}_{1}\left( {G, R{G}^{e}}\right) \cong {H}_{1}\left( {G, R{G}^{ \frown }}\right) \oplus R \) .
Proof. For \( k > 1 \), the claim follows from 13.2.6 and the preceding remarks. The claim for \( k = 1 \) also follows from 13.2.6, because, by 13.2.3 (with \( n = 0 \) ) and 11.1.3, \( {H}_{0}\left( {G, R{G}^{ \sim }}\right) = 0 \) when \( G \) is infinite and finitely generated.
No
Proposition 13.2.11. Let \( H \leq G.{H}^{0}\left( {G, R\left( {H \smallsetminus G}\right) }\right) = 0 \) [resp. \( \cong R \) ] iff \( H \) has infinite [resp. finite] index in \( G \) . In particular, \( {H}^{0}\left( {G,{RG}}\right) = 0 \) [resp. \( \cong R \) ] iff \( G \) is infinite [resp. finite].
Proof. Let \( \left( {X, v}\right) \) be a \( K\left( {G,1}\right) \) -complex having one vertex. By 8.1.2 we see that \( {H}^{0}\left( {G, R\left( {H \smallsetminus G}\right) }\right) \) is the module of cocycles in \( {\operatorname{Hom}}_{G}\left( {{C}_{0}\left( {\widetilde{X};R}\right), R\left( {H \smallsetminus G}...
Yes
Corollary 13.2.13. For \( k > 1,{H}^{k}\left( {G,{RG}}\right) \cong {H}^{k - 1}\left( {G, R{G}^{e}}\right) \) . If \( G \) is infinite, \( {H}^{0}\left( {G, R{G}^{e}}\right) \cong {H}^{1}\left( {G,{RG}}\right) \oplus R \) .
Proof. The first part is clear. For the last part, the short exact sequence splits.
No
Proposition 13.2.14. Let \( H \leq G \) where \( H \) has type \( {F}_{n} \) . If \( H \) has finite index in \( G \) then for \( k \leq n,{H}^{k}\left( {G,{RG}}\right) \cong {H}^{k}\left( {H,{RH}}\right) \) .
Proof. By 7.2.4, \( G \) has type \( {F}_{n} \) iff \( H \) has type \( {F}_{n} \) . Let \( X \) be as in 13.2.9 with \( {X}^{n} \) finite and \( {\pi }_{1}\left( {X, v}\right) \cong G \) . By 13.2.9, \( {H}^{k}\left( {G,{\left( RG\right) }^{e}}\right) \cong {H}_{e}^{k}\left( {\widetilde{X};R}\right) \cong \) \( {H}^{k...
Yes
Proposition 13.2.17. If \( R \) is a PID there is a free \( R \) -module \( F \) such that \( {H}_{f}^{n}\left( {{\widetilde{X}}^{n};R}\right) \cong {H}^{n}\left( {G,{RG}}\right) \oplus F \) . Thus \( {H}^{n}\left( {G,{RG}}\right) \) is free over \( R \) iff \( {H}_{f}^{n}\left( {{\widetilde{X}}^{n};R}\right) \) is fre...
Proof. We will find \( F \) such that \( {H}^{n - 1}\left( {G, R{G}^{e}}\right) \oplus F \cong {H}_{f}^{n}\left( {{\widetilde{X}}^{n};R}\right) \) ; by 13.2.13 this is enough. For any PID \( R,{H}^{n - 1}\left( {G, R{G}^{e}}\right) \cong {H}_{e}^{n - 1}\left( {{\widetilde{X}}^{n};R}\right) \) by 13.2.9. From Sect. 12.2...
No
Proposition 13.2.19. Let \( X \) be a \( K\left( {G,1}\right) \) -complex with finite \( n \) -skeleton. As \( R \) -modules, \( {H}_{e}^{n}\left( {{\widetilde{X}}^{n};R}\right) \) is torsion free iff \( {H}^{n + 1}\left( {G,{RG}}\right) \) is torsion free.
Proof. By 13.2.13, \( {H}^{n + 1}\left( {G,{RG}}\right) \) is torsion free iff \( {H}^{n}\left( {G, R{G}^{e}}\right) \) is torsion free. By 13.2.8 and 13.2.9, there is a short exact sequence of cochain complexes\n\n\[ 0 \rightarrow A \rightarrow {C}_{n}^{\infty }\left( {\widetilde{X};R}\right) /{C}_{n}\left( {\widetild...
Yes
Proposition 13.3.1. If \( G \) is finite, \( {H}^{n}\left( {G,{RG}}\right) = 0 \) for all \( n > 0 \) .
Proof. By 7.2.5, there is a \( K\left( {G,1}\right) \) -complex \( X \) of finite type. Since \( G \) is finite, 3.2.13 implies that \( \widetilde{X} \) also has finite type, so \( {H}_{f}^{n}\left( {\widetilde{X};R}\right) = {H}^{n}\left( {\widetilde{X};R}\right) = 0 \) for all \( n > 0 \) . Apply 13.2.9.
No
Theorem 13.3.2. Let \( n \geq 0 \) and let \( G \) be a group of type \( {F}_{n} \) ; when \( n = 0 \) assume \( G \) is countable. Let \( X \) be an \( \left( {n - 1}\right) \) -aspherical \( {CW} \) complex with finite \( n \) -skeleton whose fundamental group is isomorphic to \( G \) . Let \( \left\{ {K}_{i}\right\}...
Proof. Combine 12.5.11 (applied to the appropriate skeleton), 13.2.9 and 13.2.13. For the case \( k = n + 1 \) in (ii), use 13.2.19. There are a few details to be worked out in (iii) and (iv) when \( k = 1 \) (details concerning the behavior of \( {\widetilde{H}}_{0} \) ); we leave these as an exercise.\n\nThe hypothes...
No
Proposition 13.4.7. This correspondence induces a bijection \( \mathcal{E}\left( Y\right) \rightarrow \mathop{\lim }\limits_{ \leftarrow }\left\{ {{\pi }_{0}\left( {Y - {L}_{i}}\right) }\right\} \)
By 13.4.4, \( \left\{ {{\pi }_{0}\left( {Y - {L}_{i}}\right) }\right\} \) is an inverse sequence of finite sets. If each is regarded as a discrete space and the inverse limit is interpreted in the category Spaces then, via the bijection of 13.4.7, \( \mathcal{E}\left( Y\right) \) becomes a compact totally disconnected ...
No
Proposition 13.4.8. Let \( Y \) have \( m \) ends where \( 0 \leq m \leq \infty \) . For all \( i, Y - {L}_{i} \) has finitely many path components. When \( m < \infty \), there exists \( {i}_{0} \) such that whenever a finite subcomplex \( K \) contains \( {L}_{{i}_{0}}, Y\overset{c}{ \sim }K \) has exactly \( m \) un...
Proof. The first sentence follows from 13.4.4 (or from the discussion preceding 11.1.4). The rest follows from 13.4.7; to see this, observe that a compact path component of \( Y \triangleq {L}_{i} \) lies in \( {L}_{j} \) for some \( j \) .
No
Proposition 13.4.10. Let \( Y \) have \( m \) ends, where \( m < \infty \) . Let \( K \) and \( L \) be finite subcomplexes of \( Y \) such that each of \( Y\overset{c}{ \backsim }K \) and \( Y\overset{c}{ \backsim }L \) has \( m \) unbounded path components \( {C}_{1},\cdots ,{C}_{m} \) and \( {D}_{1},\cdots ,{D}_{m} ...
Proof. By 13.4.9, we may assume \( Y - K \) and \( Y - L \) have no bounded path components. If \( m = 1, Y - \left( {{C}_{1} \cap {D}_{1}}\right) = K \cup L \) which is compact. The subcomplex \( {C}_{1} - c\left( {{C}_{1} \cap {D}_{1}}\right) \) is therefore a closed subset of a compact set. Now let \( m \geq 2 \) . ...
Yes
Proposition 13.4.11. Let \( R \) be a PID. \( Y \) has \( m \) ends iff \( {H}_{e}^{0}\left( {Y;R}\right) \) is a free \( R \) - module of rank \( m \) . \( Y \) has infinitely many ends iff \( {H}_{e}^{0}\left( {Y;R}\right) \) is free of countably infinite rank.
Proof. We saw in 12.5.11 that \( {H}_{e}^{0}\left( {Y;R}\right) \) is free. First, let \( m \) be finite. By 12.5.10 (iv), \( {H}_{e}^{0}\left( {Y;R}\right) \) has rank \( m \) iff \( \left\{ {{H}_{0}\left( {Y - {L}_{i};R}\right) }\right\} \) is stable with free inverse limit of rank \( m \), iff \( \left\{ {{\pi }_{0}...
Yes
Proposition 13.4.13. If \( Z \) is a compact totally disconnected metrizable space, there is an inverse sequence \( \left\{ {Z}_{n}\right\} \) of finite discrete spaces whose inverse limit is homeomorphic to \( Z \) .
Proof. Pick a metric for \( Z \) . By 13.4.12, for each \( n \geq 1 \) there is a finite cover \( {\mathcal{Z}}_{n} \) of \( Z \) by pairwise disjoint closed-and-open sets of diameter \( \leq \frac{1}{n} \), and these \( {\mathcal{Z}}_{n} \) ’s can be chosen inductively so that each member of \( {\mathcal{Z}}_{n + 1} \...
Yes
Proposition 13.5.2. If \( H \) has finite index in \( G \), then \( H \) and \( G \) have the same number of ends.
Proof. \( X \) and its finite covering space \( \bar{X}\left( H\right) \) have the same universal cover.
No
Proposition 13.5.3. The R-module \( {H}^{1}\left( {G,{RG}}\right) \) is countably generated and free.
Proof. Apply the first two parts of 13.3.2 and the following lemma.
No
Lemma 13.5.4. Let \( Y \) be a path connected countable \( {CW} \) complex of locally finite type, and let \( \left\{ {L}_{i}\right\} \) be a finite type filtration of \( Y \) . Then \( \left\{ {{H}_{0}\left( {Y - {L}_{i};R}\right) }\right\} \) is semistable.
Proof. By 12.5.9, each \( {H}_{0}\left( {Y \triangleq {L}_{i};R}\right) \) is finitely generated and free. The image of each bond \( {H}_{0}\left( {Y \circeq {L}_{j};R}\right) \rightarrow {H}_{0}\left( {Y \circeq {L}_{i};R}\right) \) is a direct summand generated by the finite number of path components of \( Y - {L}_{i...
Yes
The number of ends of a finite group is 0 . The number of ends of an infinite finitely generated group \( G \) is well defined and equals \( 1 + {\operatorname{rank}}_{R}\left( {{H}^{1}\left( {G,{RG}}\right) }\right) \) .
For a finite group, the result follows from 3.2.13 and 13.4.2. Assume \( G \) is infinite. Let \( \rho \) be a non-negative integer. We use both the result and the notation of 13.3.2: \( {H}^{1}\left( {G,{RG}}\right) \) has rank \( \rho \) iff \( \left\{ {{\widetilde{H}}_{0}\left( {{\widetilde{X}}^{1} - {K}_{i};R}\righ...
Yes
The groups \( {\mathbb{Z}}^{n}\left( {n > 1}\right) \) have one end. The group \( \mathbb{Z} \) has two ends. A free group of rank \( n > 1 \) has infinitely many ends.
To see this, consider the universal covers of \( {T}^{n},{S}^{1} \) and the \( n \) -fold wedge of circles; the last is an infinite tree every vertex of which has valence \( {2n} \) .
No
Theorem 13.5.7. The number of ends of a finitely generated group is 0,1,2 or \( \infty \) . Hence for \( G \) infinite and finitely generated, the \( R \) -module \( {H}^{1}\left( {G,{RG}}\right) \) is isomorphic to 0 or \( R \) or \( {\bigoplus }_{1}^{\infty }R \) .
Proof. Suppose \( G \) has \( m \) ends where \( 3 \leq m < \infty \) . Let \( \Gamma \) be the Cayley graph of \( G \) with respect to a finite set of generators. By 13.5.5, \( G \) is infinite, hence \( \Gamma \) is infinite. By 13.4.9, there is a finite path connected subgraph \( K \) of \( \Gamma \) such that \( {}...
Yes
Proposition 13.5.11. If \( N \) is a normal subgroup of \( G \) then the number of ends of the pair \( \left( {G, N}\right) \) is equal to the number of ends of the group \( G/N \) .
Proof. Let \( f : \left( {X, x}\right) \rightarrow \left( {Y, y}\right) \) be a cellular map between 2-dimensional complexes having the following properties: each of \( X \) and \( Y \) has just one vertex, the base point; \( f \mid : {X}^{1} \rightarrow {Y}^{1} \) is an isomorphism of finite graphs (i.e., a homeomorph...
Yes
Corollary 13.5.12. The number of ends of a finitely generated group \( G \) is the number of ends of any path connected free \( {}^{20} \) G-CW complex whose quotient by the action of \( G \) is a finite \( {CW} \) complex.
Proof. Let \( \bar{Z} \) be the free \( G \) -CW complex and \( Z \) the finite quotient. Write \( H = {\pi }_{1}\left( {Z, z}\right) \) . By covering space theory (see Sect. 3.4), there is a short exact sequence of groups \( N \rightarrowtail H \twoheadrightarrow G \) such that \( \bar{Z} = \bar{Z}\left( N\right) \) ....
Yes
For each \( n \geq 3 \) we describe a pair of groups \( \left( {G, H}\right) \) having \( n \) ends. Let \( X \) be a closed path connected orientable surface of genus \( g \) and let \( Y \) be a compact subsurface (i.e., \( {\operatorname{cl}}_{X}\left( {X - Y}\right) \) is also a surface) whose boundary consists of ...
Consider the covering projection \( {q}_{H} : \bar{X}\left( H\right) \rightarrow X \), with base point \( \bar{x} \) over \( x \) . By 3.4.10 the path component \( {Y}_{\bar{x}} \) of \( {q}_{H}^{-1}\left( Y\right) \) is a copy of \( Y \) which \
No
Proposition 13.5.15. If \( N \) is a finite normal subgroup of \( G \), then the number of ends of \( \left( {G, N}\right) \) is equal to the number of ends of \( G \) . Hence \( G \) and \( G/N \) have the same number of ends.
Proof. If \( G \) is finite, both numbers are 0 . Assume \( G \) is infinite. Then \( {p}_{N} \) : \( {\widetilde{X}}^{1} \rightarrow \bar{X}{\left( N\right) }^{1} \) is a finite-to-one covering projection, hence a proper map. The induced function \( {}^{21}{p}_{N\# } : \mathcal{E}\left( {\widetilde{X}}^{1}\right) \rig...
Yes
Proposition 13.5.17. The R-module \( {H}^{1}\left( {G, R\left( {H \smallsetminus G}\right) }\right) \) is free.
Proof. By 13.2.12 we have an exact sequence\n\n\[ \n{H}^{1}(G, R({H\smallsetminus G}{)}^{\hat{} })\overset{i}{\leftarrow }{H}^{1}(G, R({H\smallsetminus G}))\overset{j}{\leftarrow }{H}^{0}(G, R({H\smallsetminus G}{)}^{e})\overset{k}{\leftarrow }{H}^{0}(G, R({H\smallsetminus G}{)}^{\hat{} })\overset{r}{\leftarrow }{H}^{0...
Yes
Proposition 13.5.19. Let \( H \), generated by \( h \), be an infinite cyclic subgroup of the one-ended finitely generated group \( G \) . Then the number of ends of \( \left( {G, H}\right) \) equals \( 1 + {\operatorname{rank}}_{\mathbb{Z}}\left( {{H}^{1}\left( {G,\mathbb{Z}\left( {H \smallsetminus G}\right) }\right) ...
Proof. First, assume \( G \) is finitely presented. Then \( X \) can be taken to have finite 2-skeleton and, by 13.2.9 and 13.5.18, we are to show that\n\n\[ i : {H}_{f}^{1}\left( {\bar{X}\left( H\right) ;\mathbb{Z}}\right) \rightarrow {H}^{1}\left( {\bar{X}\left( H\right) ;\mathbb{Z}}\right) \]\n\nis zero. By 13.2.10 ...
No
Proposition 13.5.20. Let \( H \) be a subgroup of infinite index in the finitely generated group \( G \) . Assume that whenever there is a short exact sequence \( N \rightarrowtail H \rightarrow \mathbb{Z} \) then the pair \( \left( {G, N}\right) \) has one end. Then the number of ends of \( \left( {G, H}\right) \) equ...
Proof. The proof is the same as that of 13.5.19. In that proof, we used only the facts that \( H \) had infinite index in \( G \) and that the covering space \( \bar{X} \) (ker \( \phi \) ) had one end. The details are an exercise.
No
Theorem 13.6.2. The graph \( T \) is a tree. The function \( \left( {E, \leq }\right) \mapsto T \) from Tree Posets to Trees is inverse to \( \Phi \) .
Proof. For distinct edges \( \sigma \) and \( \tau \) of \( T \) we have \( \sigma \vdash \tau \) iff there is a two-edge edge path \( \left( {\sigma ,\tau }\right) \) . By 13.6.1 it follows that, for general \( \sigma \) and \( \tau ,\sigma \leq \tau \) iff there is a reduced edge path in \( T \) starting with \( \sig...
No
Corollary 13.6.4. There are almost invariant sets \( U \) such that both \( U \) and \( {U}^{c} \) are infinite.
Proof. Since \( \Gamma \) has more than one end, we can pick a finite path connected subgraph \( \Delta \) of \( \Gamma \) and let \( {Z}_{1},\ldots ,{Z}_{m} \) be the unbounded path components of \( \Gamma \overset{c}{ \sim }\Delta \) with \( m \geq 2 \) . Let \( U = {Z}_{1}^{0} \), the set of vertices of \( {Z}_{1} \...
Yes
Proposition 13.6.5. Let \( {U}_{0} \) and \( {U}_{1} \) be almost invariant. Then for almost all \( g \in G \) at least one of the following is true: \( g{U}_{1} \subseteq {U}_{0}, g{U}_{1}^{c} \subseteq {U}_{0}, g{U}_{1} \subseteq {U}_{0}^{c} \) , \( g{U}_{1}^{c} \subseteq {U}_{0}^{c} \)
Proof. If \( {U}_{0} \) or \( {U}_{0}^{c} \) is empty the Proposition is trivial, so we assume they are non-empty. For \( i = 0 \) or 1 let \( {\Delta }_{i} \) be a finite path connected full subgraph of \( \Gamma \) containing the support of \( \delta {U}_{i} \) . Then for almost all \( g \in {U}_{0} \) we have (i) \(...
Yes
Proposition 13.6.6. Let \( H = \{ g \in G \mid {gU} \triangleq U\} \) . If \( G \) has infinitely many ends then \( H \) is finite.
Proof. Recall that both \( U \) and \( {U}^{c} \) are infinite. We will show that if \( H \) is infinite then \( G \) has an infinite cyclic subgroup of finite index, implying \( G \) has two ends by 13.5.9.\n\nWe may assume that \( H \cap U \) is infinite and that \( 1 \in U \) . By (the proof of) 13.6.5 we have \( {g...
Yes
Proposition 13.6.7. Let \( G \) have infinitely many ends. If \( V, W \) and \( X \) are infinite almost invariant sets with infinite complements, then \( \{ g \in G \mid V \subseteq \) \( {gW}\overset{a}{ \subseteq }X\} \) is finite.
Proof. We may assume \( V \subseteq X \) and, enlarging \( V \) if necessary, that \( V ⊄ X \) . Let \( V \subseteq {gW} \subseteq X \) . Then either \( {gW} ⊄ X \) or \( V ⊄ {gW} \) . It is enough to show that \( \{ g \in G \mid {gW}\overset{a}{ \subseteq }X \) and \( {gW} ⊄ X\} \) and \( \{ g \in G \mid V\overset{a}{...
Yes
Proposition 13.6.8. If \( {U}_{1} \supseteq {U}_{2} \supseteq \cdots \) are narrow sets, and if \( V \mathrel{\text{:=}} \bigcap {U}_{n} \) is non-empty, then the sequence stabilizes, i.e., for some \( N,{U}_{n} = {U}_{N} \) for all \( n \geq N \) .
Proof. If an edge \( e \) lies in the support of \( {\delta V} \) then one vertex of \( e \) lies in every \( {U}_{n} \), while there is an integer \( N \) such that the other vertex of \( e \) does not lie in \( {U}_{n} \) when \( n \geq N \) . Thus \( e \) is in the support of \( \delta {U}_{n} \) when \( n \geq N \)...
Yes
Proposition 13.6.9. Fix \( {g}_{0} \in G \) . Let \( U \) be a minimal narrow set containing \( {g}_{0} \) . For any narrow set \( V \) at least one of the following holds: \( U \subseteq V, U \subseteq {V}^{c} \) , \( {U}^{c} \subseteq V,{U}^{c} \subseteq {V}^{c} \)
Proof. Write \( {W}_{1} = U \cap V,{W}_{2} = U \cap {V}^{c},{W}_{3} = {U}^{c} \cap V \), and \( {W}_{4} = {U}^{c} \cap {V}^{c} \) . We are to prove that one of the \( {W}_{i} \) is finite. The support of \( \delta {W}_{i} \) lies in the union of the supports of \( {\delta U} \) and \( {\delta V} \) . Since the sets \( ...
Yes
Theorem 13.6.10. Let \( G \) be a finitely generated group with infinitely many ends. There is an almost invariant set \( U \subseteq G \) with respect to which the \( G \) -poset \( \left( {E, \leq }\right) \) is a \( G \) -(tree poset).
Let \( T \) be the \( G \) -tree determined by \( \left( {E, \leq }\right) \) in 13.6.10 via the function \( \Phi \) . The stabilizer of \( \left\lbrack U\right\rbrack \in E \) is \( \left\{ {g \in G \mid {gU} \triangleq U}\right\} \) ; this is finite by 13.6.6. So edge stabilizers in \( T \) are finite.\n\nFrom the de...
Yes
Proposition 13.7.2. \( Z \) is the mapping torus of \( j : Y \rightarrow Y \) .
Proof. Apply 6.1.3. The space \( {q}_{1}^{-1}\left( v\right) \) is a copy of \( Y \), and \( Z \) is obtained by attaching \( Y \times {B}^{1} \) via the attaching maps id on \( Y \times \{ - 1\} \) and \( j \) on \( Y \times \{ 1\} \) .
Yes
Proposition 13.7.4. There is a homeomorphism \( h : \mathbb{R} \times \left( {J \smallsetminus Y}\right) \rightarrow Z \) which is fiber preserving; i.e., \( {q}_{2} \circ h \) is projection on the \( J \smallsetminus Y \) factor.
Proof (of 13.7.4). There is certainly a fiber preserving homeomorphism \( {h}_{0} \) : \( \mathbb{R} \times {\left( J \smallsetminus Y\right) }^{0} \rightarrow {q}_{2}^{-1}\left( {\left( J \smallsetminus Y\right) }^{0}\right) \) . Moreover, we can choose \( {h}_{0} \) to be order preserving on each fiber \( \left( {\ma...
Yes
Lemma 13.7.5. Let \( H : {S}^{n} \times \mathbb{R} \rightarrow {S}^{n} \times \mathbb{R} \) be a homeomorphism of the form \( H\left( {x, t}\right) = \left( {x,{H}_{x}\left( t\right) }\right) \) where each homeomorphism \( {H}_{x} : \mathbb{R} \rightarrow \mathbb{R} \) is order preserving. Then \( H \) extends to a hom...
Proof. Note that when \( n > 0 \) the hypothesis on each \( {H}_{x} \) holds iff it holds on one \( {H}_{x} \) ; but we also need this lemma for \( n = 0 \) . The required \( \widehat{H} \) is given by the formula \( \widehat{H}\left( {x, t}\right) = \left( {x,\left( {1 - \left| x\right| }\right) t + \left| x\right| {H...
Yes
Proposition 13.7.6. If \( W \) is a countable \( {CW} \) complex of locally finite type, then for all \( n,{H}_{f}^{n}\left( {W;R}\right) \cong {H}_{f}^{n + 1}\left( {W \times \mathbb{R};R}\right) \) .
Proof. This follows from 12.6.1. Here is a short direct proof. Let \( \left\{ {K}_{i}\right\} \) be a finite type filtration of \( W \) . Then \( \left\{ {{K}_{i} \times \left\lbrack {-i, i}\right\rbrack }\right\} \) is a finite type filtration of \( W \times \mathbb{R} \) . Fix \( i \), and let \( {X}_{i} = \left( {W ...
Yes
Proposition 13.7.8. Assume \( {Y}^{2} \) does not have two ends. If \( {j}^{ * } : {H}_{e}^{1}\left( {Y;R}\right) \rightarrow \) \( {H}_{e}^{1}\left( {Y;R}\right) \) agrees with the identity on a non-trivial \( R \) -submodule, \( A \), then either \( A \cong R \) or \( J \smallsetminus Y \) has more than one end.
Proof. Recall that \( Y \) is assumed to be simply connected. The space \( J \smallsetminus Y \) is not compact (i.e., does not have 0 ends) because \( Y \) does not have two ends; see 13.5.9. Assuming \( J \smallsetminus Y \) has one end, we must show \( A \cong R \) . We have an exact sequence\n\n\[ \n{H}^{1}\left( {...
Yes
Proposition 13.7.9. Assume \( {Y}^{2} \) has one end. If \( {j}^{ * } : {H}_{e}^{1}\left( {Y;R}\right) \rightarrow {H}_{e}^{1}\left( {Y;R}\right) \) agrees with the identity on a non-trivial \( R \) -submodule \( A \), then \( A \) is a free \( R \) -module.
Proof. Consider the first exact sequence given in the proof of 13.7.8. The monomorphism \( \alpha \) splits by 12.2.3, and we have seen that \( {H}^{1}\left( {J \smallsetminus Y;R}\right) \) is isomorphic to \( R \) . Moreover, \( {H}_{e}^{0}\left( {J \smallsetminus Y;R}\right) \) is free, by 12.5.11. Thus \( {H}_{f}^{...
Yes
Theorem 13.7.12. (Farrell’s Theorem) Let the finitely presented group \( G \) act freely on \( \widetilde{X} \) with compact quotient. Assume \( G \) has an element of infinite order. \( {}^{26} \) Then the abelian group \( {H}_{e}^{1}\left( {\widetilde{X};\mathbb{Z}}\right) \) is trivial or is isomorphic to \( \mathbb...
Proof. By 12.4.8 and 12.2.2, there is a monomorphism of \( {\mathbb{Z}}_{2} \) -modules \( \beta \) : \( {\mathbb{Z}}_{2}{ \otimes }_{\mathbb{Z}}{H}_{e}^{1}\left( {\widetilde{X};\mathbb{Z}}\right) \rightarrow {H}_{e}^{1}\left( {\widetilde{X};{\mathbb{Z}}_{2}}\right) \) . In fact, by naturality of the universal coeffici...
Yes
Proposition 13.8.3. Let \( f : X \rightarrow {\Delta }^{n} \) be an aspherical model over \( {\Delta }^{n} \) and let \( \left( {K,\pi }\right) \) be a simplicial complex over \( \mathbf{n} \) . Then \( X\bigtriangleup \left| K\right| \) is non-empty and each of its path components is aspherical. Moreover, for any non-...
Proof (of 13.8.3). First we handle the special case in which \( K \) is a simplex, i.e., \( K = \bar{\sigma } \) for some \( \sigma \in K \) . Then for any non-empty subcomplex \( L \) of \( \bar{\sigma } \) , \( X\bigtriangleup \left| L\right| = {f}^{-1}\left( {\left| \pi \right| \left( \left| L\right| \right) }\right...
Yes
Lemma 13.9.2. \( {F}_{\sigma \left( T\right) } = {N}_{K}\left( {K\left( T\right) }\right) \) .
Proof. Let \( \tau \) be a simplex of \( {F}_{\sigma \left( T\right) } \) . Then \( \tau \) is a simplex of \( {F}_{\{ s\} } \) for some \( s \in T \) , so \( \tau \) is a face of a simplex \( \mu \) whose initial vertex is \( \langle \{ s\} \rangle \) . Thus \( \tau \) is a face of a simplex which shares a vertex with...
Yes
Proposition 13.9.3. When \( \langle T\rangle \) is a non-trivial finite standard subgroup of \( G,\left| {F}_{\sigma \left( T\right) }\right| \) is a \( {PL}\left( {d - 1}\right) \) -ball.
Proof (Sketch). This requires knowledge of piecewise linear topology, in particular, of regular neighborhoods in PL manifolds; we have set things up so that references are easily given. By 13.9.2, \( {F}_{\sigma \left( T\right) } \) is the simplicial neighborhood of \( K\left( T\right) \) in the closed combinatorial \(...
Yes
Proposition 13.9.4. Each \( {A}_{n} \) is a finite connected closed combinatorial manifold of dimension \( d - 1 \) . \( {A}_{n} \) is orientable iff \( \left| L\right| \) is orientable.
Proof. The proof is by induction on \( n \), starting with \( {A}_{0} = K = \operatorname{sd}L \) . Assume the Proposition for \( {A}_{n} \) . Let \( {B}_{n + 1} = {g}_{n + 1}{F}_{\sigma \left( {B\left( {g}_{n + 1}\right) }\right) } \) . The full subcomplex of \( D \) generated by \( {A}_{n} \) and \( {g}_{n + 1}F \) c...
Yes
Corollary 13.9.6. The group \( G \) has one end, \( {H}^{2}\left( {G,\mathbb{Z}G}\right) \) is free abelian, and every torsion free subgroup of finite index in \( G \) has geometric dimension \( d \) .
Proof. By 13.5.2 and 13.5.5, \( G \) has one end. We have \( {H}^{2}\left( {G,\mathbb{Z}G}\right) \) free abelian because \( {H}^{1}\left( {\left| L\right| ;\mathbb{Z}}\right) \) is (finitely generated and) free abelian. Let \( H \) be a torsion free subgroup of finite index (see 9.1.10). By 9.1.11, \( H \) has geometr...
Yes
Proposition 13.9.7. (a) If \( {M}_{1} \) and \( {M}_{2} \) are orientable then \( {M}_{1}\# {M}_{2} \) is orientable; \( {f}^{ * } : {H}^{n}\left( {M}_{1}\right) \rightarrow {H}^{n}\left( {{M}_{1}\# {M}_{2}}\right) \) is an isomorphism, and for \( i \leq n - 1 \) the following diagram commutes
Proof. We make some comments, leaving the rest to the reader.\n\n(i) \( {H}^{n}\left( {M}_{2}\right) \) is infinite cyclic if \( {M}_{2} \) is orientable, and has order 2 if \( {M}_{2} \) is nonorientable. Indeed, the map \( {f}^{ * } : {H}^{n}\left( {{B}_{2}^{n}, S}\right) \rightarrow {H}^{n}\left( {M}_{2}\right) \) c...
No
Theorem 13.11.1. \( {H}^{ * }\left( {F,{RF}}\right) = 0 \) .
Proof. The proof requires a return to the notation of Sect. 9.3. We sketch it, leaving the reader to fill in the details. \( {}^{31} \)\n\nFor \( b \in B \) let \( \lambda \left( b\right) \) be the smallest integer such that an expansion of \( b \) of length \( \lambda \left( b\right) \) has the form \( \left\lbrack {{...
No
Proposition 14.1.2. Let \( \left( {X,\mathcal{K}}\right) \) and \( \left( {Y,\mathcal{L}}\right) \) be topologically well filtered Hausdorff spaces where each \( {K}_{i} \) and each \( {L}_{j} \) is compact. A map \( f : X \rightarrow Y \) is filtered iff it is proper.
Proof. Use Lemma 14.1.1 and the fact that compact subsets of Hausdorff spaces are closed. Note that two of the four conditions in the definition of filtered map hold trivially.
No
Proposition 14.1.4. If \( X \) is a strongly locally finite \( {CW} \) complex and \( \left( {X,\mathcal{K}}\right) \) is topologically well filtered then \( E\left( \mathcal{K}\right) \) and \( S\left( \mathcal{K}\right) \) are filtrations of \( X \) .
Proof. The only non-trivial part in the envelope case involves showing that \( \mathop{\bigcap }\limits_{i}E\left( {K}_{i}\right) = \varnothing \) . Suppose otherwise. Since this intersection is a subcomplex of \( X \) it contains a vertex \( v \) . It is not hard to see that \( E\left( {K}_{i}\right) = \bigcup \left\{...
Yes
Let \( X \) be a rigid \( G \) -CW complex such that \( G \smallsetminus X \) is finite, let \( M = \mathbb{R} \) where a left action of \( G \) on \( \mathbb{R} \) by translations is given, let \( \mathcal{L} = \left\{ {L}_{i}\right\} \) where \( i \in \mathbb{Z} \) and \( {L}_{i} \mathrel{\text{:=}} \left( {-\infty, ...
A particular case is this. Assume \( G \) has type \( {F}_{n}, X \) is the \( n \) -skeleton of the universal cover of a \( K\left( {G,1}\right) \) -complex which has finite \( n \) -skeleton, \( \chi : G \rightarrow \mathbb{R} \) is a character (i.e., a homomorphism into the additive group of real numbers), and the \(...
No
Lemma 14.1.9. Let \( \\left( {X,\\mathcal{K}}\\right) \) be a well filtered \( {CW} \) complex and let \( F : X \\times I \\rightarrow \) \( X \) be a (cellular) CW-Lipschitz homotopy with \( {F}_{0} = {\\mathrm{{id}}}_{X} \). Then \( F \) is CW-filtered.
Proof. We need only check that \( F \\mid {X}^{n} \\times I \) is filtered for given \( n \). Let \( m \) be such that for every cell \( e \) of \( {X}^{n} \) the carrier \( C\\left( {F\\left( {e \\times I}\\right) }\\right) \) contains at most \( m \) cells. Since \( F\\left( {e \\times I}\\right) \) is path connected...
Yes
Lemma 14.1.10. Let \( f : \left( {X,\mathcal{K}}\right) \rightarrow \left( {Y,\mathcal{L}}\right) \) be a (cellular) CW-filtered map and let \( g : Y \rightarrow X \) be a cellular map such that \( g \circ f \) and \( f \circ g \) are \( {CW} \) -filtered maps which are CW-filtered homotopic to the appropriate identity...
Proof. Given \( {L}_{i} \) we seek \( {K}_{j} \) such that \( g\left( {L}_{i}\right) \subset {K}_{j} \) . There exists \( k \) such that \( {fg}\left( {L}_{i}\right) \subset {L}_{k} \) and there exists \( j \) such that \( f\left( {X - {K}_{j}}\right) \subset Y - {L}_{k} \) . So \( g\left( {L}_{i}\right) \subset {K}_{j...
Yes
Proposition 14.1.12. If \( {h}_{1} : {X}_{1} \rightarrow \mathbb{R} \) and \( {h}_{2} : {X}_{2} \rightarrow \mathbb{R} \) both satisfy these conditions (for \( X \) and \( h \) above), there is a cellular map \( f : {X}_{1} \rightarrow {X}_{2} \) which is a CW-filtered \( \left( {n - 1}\right) \) -equivalence \( \left(...
Proof. By 7.1.8 and the \( n \) -equivalence version of Example 14.1.7, there is a CW-Lipschitz (cellular) \( \left( {n - 1}\right) \) -equivalence \( f : {X}_{2} \rightarrow {X}_{1} \), and \( f \) is CW-filtered as a map \( \left( {{X}_{2},{f}^{-1}{h}_{1}^{-1}\mathcal{L}}\right) \rightarrow \left( {{X}_{1},{h}_{1}^{-...
Yes
Proposition 14.2.3. The homology and cohomology theories \( {H}_{ * }^{\mathcal{K}}\left( {X;R}\right) \), \( {H}_{ * }^{\mathcal{K}, e}\left( {X;R}\right) ,{H}_{\mathcal{K}}^{ * }\left( {X;R}\right) \) and \( {H}_{\mathcal{K}, e}^{ * }\left( {X;R}\right) \) are filtered homotopy invariants.
The more complete version of 14.2.3 in which the categories and functors are described explicitly is left to the reader.
No
Example 14.2.5. We continue the discussion of Example 14.1.5. In Sect. 13.2 we met the right \( {RG} \) -module \( {\left( RG\right) }^{ \sim } \) . Elements of \( {\left( RG\right) }^{ \sim } \) are written as \( \mathop{\sum }\limits_{{g \in G}}{r}_{g}g \) with each \( {r}_{g} \in R \) . Those where all but finitely ...
One checks that the multiplication in \( {RG} \) does extend to \( {\left( RG\right) }_{\chi } \), making the latter a ring called the Novikov ring defined by \( \chi \) . Regarding this ring as a right \( G \) -module (via right multiplication by elements of \( G \) ) and using the notation of 14.1.5 , it is clear tha...
Yes
Proposition 14.3.2. \( \\left( {Y,\\mathcal{L}}\\right) \) is regular iff the inverse sequence of sets \( \\left\\{ {{\\pi }_{0}\\left( {Y \\triangleq {L}_{i}}\\right) }\\right\\} \) is semistable.
Proof. For each \( i \), we write \( {\\pi }_{0}\\left( {Y - {L}_{i}}\\right) = {B}_{i} \\cup {U}_{i} \) where \( {B}_{i} \) is the set of \( \\mathcal{L} \) - bounded path components and \( {U}_{i} \) is the set of \( \\mathcal{L} \) -unbounded path components. If \( \\left( {Y,\\mathcal{L}}\\right) \) is regular then...
Yes
Proposition 14.3.7. Let \( R \) be a PID and let \( \mathcal{L} \) be regular. For \( m < \infty ,\left( {Y,\mathcal{L}}\right) \) has \( m \) filtered ends iff \( {H}_{\mathcal{L}, e}^{0}\left( {Y;R}\right) \) is a free \( R \) -module of rank \( m;\left( {Y,\mathcal{L}}\right) \) has \( \infty \) filtered ends iff \(...
Proof. First, assume \( m < \infty \) . By 14.3.4, the following are equivalent:\n\n(i). \( \left( {Y,\mathcal{L}}\right) \) has \( m \) filtered ends;\n\n(ii). \( \left\{ {{\pi }_{0}\left( {Y - {L}_{i}}\right) }\right\} \) is stable with inverse limit having \( m \) elements;\n\n(iii). \( \left\{ {{H}_{0}\left( {Y - {...
Yes
Proposition 14.4.1. \( {\psi }_{ * }^{H} \) and \( {\psi }_{ * }^{H, e} \) induce isomorphisms\n\n\[ \n{H}_{\mathcal{L}}^{ * }\left( {\widetilde{X};R}\right) \rightarrow {H}^{ * }\left( {G,{R}^{H}{\left( G\right) }^{ \frown }}\right) \]\n\nand\n\n\[ \n{H}_{\mathcal{L}, e}^{ * }\left( {\widetilde{X};R}\right) \rightarro...
By a proof similar to that of 13.2.11 one shows:
No