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Corollary 6.3.12 Let \( \mathcal{M} \vDash T \), and let \( \phi \left( \bar{v}\right) \) be an \( {\mathcal{L}}_{M} \) -formula with \( \operatorname{RM}\left( \phi \right) = \alpha \) and \( {\deg }_{\mathrm{M}}\left( \phi \right) = d \) . i) There is an \( {\mathcal{L}}_{M} \) -formula \( \theta \left( \bar{v}\right...
i) In our argument above, we had \( \psi \left( {\bar{v},\bar{w}}\right) \) and \( \bar{b} \in \mathbb{M} \) and an \( M \) -definable equivalence relation \( E \) with finitely many classes such that if \( \bar{a}E\bar{b} \), then \( \psi \left( {\mathbb{M},\bar{a}}\right) \) is a Morley rank \( \alpha \), Morley degr...
Yes
Lemma 6.3.14 Suppose that \( \mathcal{M} \vDash T, p \in {S}_{n}\left( M\right), M \subseteq B, q \in {S}_{n}\left( B\right) \) , \( p \subseteq q \), and \( q \) is definable over \( M \) . Then, \( q \) is a nonforking extension of \( p \) .
Proof There is \( r \in {S}_{n}\left( B\right) \) a nonforking extension of \( p \) that is definable over \( M \) . Because \( q \) and \( r \) both extend \( p \) ,\n\n\[ \mathcal{M} \vDash \forall \bar{w}{d}_{r}\phi \left( \bar{w}\right) \leftrightarrow {d}_{q}\phi \left( \bar{w}\right) \]\n\nfor all formulas \( \ph...
No
Lemma 6.3.16 (Monotonicity) If \( \bar{a}{ \downarrow }_{A}B \) and \( C \subseteq B \), then \( \bar{a}{ \downarrow }_{A}C \) .
Proof Because \( \operatorname{RM}\left( {\bar{a}/A}\right) \geq \operatorname{RM}\left( {\bar{a}/A \cup C}\right) \geq \operatorname{RM}\left( {\bar{a}/A \cup B}\right) \), if \( \operatorname{RM}\left( {\bar{a}/A}\right) = \) \( \operatorname{RM}\left( {\bar{a}/A \cup B}\right) \), then \( \operatorname{RM}\left( {\b...
Yes
Lemma 6.3.17 (Transitivity) \( \bar{a}{ \bot }_{A}\bar{b},\bar{c} \) if and only if \( \bar{a}{ \bot }_{A}\bar{b} \) and \( \bar{a}{ \bot }_{A,\bar{b}}\bar{c} \)
Proof Because \( \operatorname{RM}\left( {\bar{a}/A,\bar{b},\bar{c}}\right) \leq \operatorname{RM}\left( {\bar{a}/A,\bar{b}}\right) \leq \operatorname{RM}\left( {\bar{a}/A}\right) ,\operatorname{RM}\left( {\bar{a}/A}\right) = \) \( \operatorname{RM}\left( {\bar{a}/A,\bar{b},\bar{c}}\right) \) if and only if \( \operato...
Yes
Lemma 6.3.18 (Finite Basis) \( \bar{a}{ \downarrow }_{A}B \) if and only if \( \bar{a}{ \downarrow }_{A}{B}_{0} \) for all \( f \) i-nite \( {B}_{0} \subseteq B \) .
Proof\n\n\( \left( \Rightarrow \right) \) This is clear because for any \( {B}_{0} \subseteq B,\operatorname{RM}\left( {\bar{a}/A}\right) \leq \operatorname{RM}\left( {\bar{a}/A \cup {B}_{0}}\right) \leq \) \( \operatorname{RM}\left( {\bar{a}/A \cup B}\right) \).\n\n\( \left( \Leftarrow \right) \) Suppose that \( \bar{...
Yes
Corollary 6.3.20 \( \bar{a},\bar{b}{ \downarrow }_{A}C \) if and only if \( \bar{a}{ \downarrow }_{A}C \) and \( \bar{b}{ \downarrow }_{A,\bar{a}}C \) .
Proof Because forking occurs over a finite subset, it suffices to assume that \( C \) is a finite sequence \( \bar{c} \) .\n\n\[ \bar{a},\bar{b}{ \downarrow }_{A}\bar{c} \Leftrightarrow \bar{c}{ \downarrow }_{A}\bar{a},\bar{b}\;\text{ by symmetry } \]\n\n\[ \Leftrightarrow \bar{c}{ \downarrow }_{A}\bar{a}\text{ and }\b...
Yes
Corollary 6.3.21 For any \( \bar{a},\bar{a}{ \downarrow }_{A}\operatorname{acl}\left( A\right) \) .
Proof Suppose that \( \bar{b} \in \operatorname{acl}\left( A\right) \) . By Lemma 6.2.7 iii), \( \operatorname{RM}\left( {\bar{b}/A,\bar{a}}\right) = \) \( \operatorname{RM}\left( {\bar{b}/A}\right) = 0 \) . Thus, \( \bar{b}{ \downarrow }_{A}\bar{a} \) and, by symmetry, \( \bar{a}{ \downarrow }_{A}\bar{b} \) .
Yes
Theorem 6.4.5 (Uniqueness of Constructible Models) Suppose that \( A \subseteq \mathbb{M},\mathcal{M} \prec \mathbb{M},\mathcal{N} \prec \mathbb{M} \), and \( \mathcal{M} \) and \( \mathcal{N} \) are constructible over \( A \) . The identity map on \( A \) extends to an isomorphism between \( \mathcal{M} \) and \( \mat...
Proof Let \( \left( {{a}_{\alpha } : \alpha < \delta }\right) \) and \( \left( {{b}_{\alpha } : \alpha < \gamma }\right) \) be the constructions of \( \mathcal{M} \) and \( \mathcal{N} \) over \( A \) . Let \( \kappa = \left| M\right| \) . Let \( I = \{ f : X \rightarrow N : f \) is partial elementary, \( A \subset X, ...
Yes
Lemma 6.4.6 Let \( T \) be \( \omega \) -stable. If \( A \subseteq B, p \in {S}_{n}\left( A\right) ,{p}^{\prime } \in {S}_{n}\left( B\right) ,{p}^{\prime } \) is a nonforking extension of \( p \), and \( {p}^{\prime } \) is isolated, then \( p \) is isolated.
Proof We work in \( {\mathbb{M}}^{\text{eq }} \) . Let \( \phi \left( {\bar{v},\bar{b}}\right) \) isolate \( {p}^{\prime } \) . Let \( q = \operatorname{tp}\left( {\bar{b}/{\operatorname{acl}}^{\text{eq }}\left( A\right) }\right) \) . By Theorem 6.3.9, there is an \( {\mathcal{L}}_{{\operatorname{acl}}^{\text{eq }}\lef...
Yes
Theorem 6.4.8 (Uniqueness of Prime Models) Suppose that \( T \) is \( \omega \) - stable, \( A \subseteq \mathbb{M},{\mathcal{M}}_{0} \prec \mathbb{M},{\mathcal{M}}_{1} \prec \mathbb{M} \), and \( {\mathcal{M}}_{0} \) and \( {\mathcal{M}}_{1} \) are prime models over \( A \) . The identity map on \( A \) extends to an ...
Proof By Lemma 6.4.2, there is \( \mathcal{N} \prec \mathbb{M} \), a constructible model over \( A \) . Because each \( {\mathcal{M}}_{i} \) is prime over \( A \), we can find an elementary embedding of \( {\mathcal{M}}_{i} \) into \( \mathcal{N} \) . By the previous lemma, each \( {\mathcal{M}}_{i} \) is constructible...
Yes
Theorem 6.4.10 Let \( k \) be a differential field. There is \( K \supseteq k \) a differential closure of \( k \) . If \( K \) and \( L \) are differential closures of \( k \), then \( K \) and \( L \) are isomorphic over \( k \) . If \( K \) is a differential closure of \( k \), then \( \operatorname{tp}\left( {\bar{...
Proof Because DCF is \( \omega \) -stable and a differential closure of \( k \) is a prime model of DCF over \( k \), this follows from the existence and uniqueness of prime model extensions for \( \omega \) -stable theories (Theorems 4.2.20 and 6.4.8).\n\nBecause the differential closure is a prime model over \( k \),...
Yes
Theorem 6.5.2 Suppose that \( I = \left( {{a}_{\alpha } : \alpha < \delta }\right) \) is an infinite Morley sequence for \( p \) over \( A \) . Then, \( I \) is an infinite set of indiscernibles.
Proof By Theorem 5.2.13, it suffices to show that \( I \) is a sequence of order indiscernibles. Let \( d = {\deg }_{\mathrm{M}}\left( p\right) \) . We will show by induction on \( n \) that \( \operatorname{tp}\left( {{a}_{{\alpha }_{1}},\ldots ,{a}_{{\alpha }_{n}}/A}\right) = \operatorname{tp}\left( {{a}_{{\beta }_{1...
Yes
Lemma 6.5.3 Suppose that \( I \) is an infinite set of indiscernibles over \( A \subset \) \( \mathbb{M} \) . For any \( \bar{b} \in \mathbb{M} \), there is a finite \( J \subset I \) such that \( I \smallsetminus J \) is a set of indiscernibles over \( A \cup \{ \bar{b}\} \) .
Proof Let \( p = \operatorname{tp}\left( {\bar{b}/A \cup I}\right) \) . There is a finite \( J \subset I \) such that \( p \mid A \cup J \) has the same Morley rank and degree as \( p \) . Let \( {x}_{1},\ldots ,{x}_{n},{y}_{1},\ldots ,{y}_{n} \subset I \smallsetminus J \) with \( {x}_{i} \neq {x}_{j} \) and \( {y}_{i}...
Yes
Theorem 6.6.37 If \( T \) is superstable, then\n\n\[ \mathrm{{RU}}\left( {\bar{a}/A,\bar{b}}\right) + \mathrm{{RU}}\left( {\bar{b}/A}\right) \leq \mathrm{{RU}}\left( {\bar{a},\bar{b}/A}\right) \leq \mathrm{{RU}}\left( {\bar{a}/A,\bar{b}}\right) \oplus \mathrm{{RU}}\left( {\bar{b}/A}\right) . \]
For a proof, see [18] 6.1.1.
No
Theorem 7.1.2 (Descending Chain Condition) If \( G \) is an \( \omega \) -stable group, then there is no infinite descending chain of definable subgroups \( G > {G}_{1} > {G}_{2} > \ldots \)
Proof Let \( \alpha = \operatorname{RM}\left( G\right) \) . Let \( {\eta }_{i} = \left( {\operatorname{RM}\left( {G}_{i}\right) ,{\deg }_{\mathrm{M}}\left( {G}_{i}\right) }\right) \) . If \( G > {G}_{1} > \) \( {G}_{2} > \ldots \) is a descending chain, then the remarks above show that \( {\eta }_{1}{ > }_{\text{lex }}...
Yes
Corollary 7.1.3 Suppose that \( G \) is an \( \omega \) -stable group and \( \sigma : G \rightarrow G \) is a definable injective group homomorphism. Then, \( \sigma \) is surjective.
Proof If not then, because \( {\sigma G} \cong G, G \supset {\sigma G} \supset {\sigma }^{2}G \supset \ldots \), contradicting the Descending Chain Condition.
Yes
Corollary 7.1.4 If \( G \) is an \( \omega \) -stable group and \( \left\{ {{H}_{i} : i \in I}\right\} \) is a collection of definable subgroups, then there is \( {I}_{0} \subseteq I \) finite such that
Proof If not we can find \( {i}_{0},{i}_{1},\ldots \) such that if \( {G}_{m} = {H}_{{i}_{0}} \cap \ldots \cap {H}_{{i}_{m}} \), then \( {G}_{0} > {G}_{1} > {G}_{2} > \ldots \)
No
Corollary 7.1.5 If \( G \) is an \( \omega \) -stable group and \( A \subseteq G \), then the centralizer \( C\left( A\right) \) is definable.
Proof Because\n\n\[ C\left( A\right) = \mathop{\bigcap }\limits_{{a \in A}}C\left( {\{ a\} }\right) \]\n\nthere are \( {a}_{1},\ldots ,{a}_{m} \in A \) such that \( C\left( A\right) = \left\{ {g \in G : g{a}_{i} = {a}_{i}g}\right. \) for \( i = \) \( 1,2,\ldots, m\} \).
Yes
If \( G \) is an \( \omega \) -stable group, there is \( {G}^{0} \leq G \) the smallest definable finite index subgroup of \( G \) . Moreover, \( {G}^{0} \) is a normal subgroup of \( G \) and definable over \( \varnothing \) .
Let \( \mathcal{H} = \left\{ {H \leq G : H\text{definable,}\left\lbrack {G : H}\right\rbrack < {\aleph }_{0}}\right\} \) . By Corollary 7.1.4, there are \( {H}_{1},\ldots ,{H}_{m} \in \mathcal{H} \) such that\n\n\[ \mathop{\bigcap }\limits_{{H \in \mathcal{H}}}H = {H}_{1} \cap \ldots \cap {H}_{m} \]\n\nLet \( {G}^{0} =...
Yes
Lemma 7.1.11 \( \operatorname{RM}\left( {\operatorname{Stab}\left( p\right) }\right) \leq \operatorname{RM}\left( p\right) \) .
Proof Let \( G \prec {G}_{1} \) with \( a, b \in {G}_{1} \) such that \( a \) realizes \( p, b \in \operatorname{Stab}\left( p\right) \) such that \( \operatorname{RM}\left( {b/G}\right) = \operatorname{RM}\left( {\operatorname{Stab}\left( p\right) }\right) \), and \( a \) and \( b \) are independent over \( G \) . The...
Yes
Lemma 7.1.12 \( \operatorname{Stab}\left( p\right) \leq {G}^{0} \) .
Proof Let \( a \in \operatorname{Stab}\left( p\right) \), and let \( \psi \left( v\right) \) define \( {G}^{0} \) . Let \( b \in G \) such that \( \psi \left( {{b}^{-1}v}\right) \in p \) . Thus \( \psi \left( {{b}^{-1}{av}}\right) \in p \) . Let \( G \prec H \) with \( c \in H \) realizing \( p \) . Then \( {b}^{-1}{ac...
Yes
Lemma 7.2.2 If \( \operatorname{tp}\left( {x/G}\right) \) is generic and \( a \in G \), then \( \operatorname{tp}\left( {{ax}/G}\right) \) and \( \operatorname{tp}\left( {{x}^{-1}/G}\right) \) are generic.
Proof The maps \( x \mapsto {ax} \) and \( x \mapsto {x}^{-1} \) are definable bijections and hence preserve Morley rank.
Yes
Lemma 7.2.3 \( p \in {S}_{1}\left( G\right) \) is generic if and only if \( \left\lbrack {G : \operatorname{Stab}\left( p\right) }\right\rbrack < {\aleph }_{0} \) .
Proof\n\n\( \left( \Leftarrow \right) \) If \( \operatorname{Stab}\left( p\right) \) has finite index, \( \operatorname{RM}\left( {\operatorname{Stab}\left( p\right) }\right) = \operatorname{RM}\left( G\right) \) . But \( \operatorname{RM}\left( {\operatorname{Stab}\left( p\right) }\right) \leq \operatorname{RM}\left( ...
Yes
Corollary 7.2.4 \( p \in {S}_{1}\left( G\right) \) is generic if and only if \( \operatorname{Stab}\left( p\right) = {G}^{0} \) .
## Proof\n\n\( \left( \Leftarrow \right) \) Clear from Lemma 7.2.3.\n\n\( \left( \Rightarrow \right) \) By Lemma 7.2.3, \( {G}^{0} \leq \operatorname{Stab}\left( p\right) \), and by Lemma 7.1.12, \( \operatorname{Stab}\left( p\right) \leq \)\n\n\( {G}^{0} \) .
No
Lemma 7.2.6 If \( g \in G \), there are \( a, b \in \mathbb{G} \) generic over \( G \) such that \( g = {ab} \) .
Proof Let \( a \in \mathbb{G} \) be generic over \( G \) . Because \( x \mapsto g{x}^{-1} \) is a definable bijection, \( b = g{a}^{-1} \) is also generic over \( G \) and \( g = {ab} \) .
Yes
Corollary 7.2.7 Suppose that \( G \) is connected and \( A \subseteq G \) is a definable subset with \( \operatorname{RM}\left( A\right) = \operatorname{RM}\left( G\right) \) . Then \( G = A \cdot A = \{ {ab} : a, b \in A\} \) .
Proof Let \( \phi \left( v\right) \) be an \( {\mathcal{L}}_{G} \) -formula defining \( A \) . For any \( g \in G \), we can find \( a, b \in \mathbb{G} \) generic over \( G \) such that \( g = {ab} \) . Because there is a unique generic type, \( \phi \left( a\right) \) and \( \phi \left( b\right) \) . Thus \( \mathbb{...
Yes
Lemma 7.2.8 Let \( A \subseteq G \) be a definable generic subset of \( G \) . There are \( {a}_{1},\ldots ,{a}_{n} \in G \) such that \( G = {a}_{1}A \cup \ldots \cup {a}_{n}A \) .
Proof Because finitely many translates of \( {G}^{0} \) cover \( G \), we may, without loss of generality, assume that \( G \) is connected. Let \( \phi \left( v\right) \) be the \( {\mathcal{L}}_{G} \) -formula defining \( A \) . Let \( p \in {S}_{1}\left( G\right) \) be the unique generic type.\n\nClaim For any \( q ...
Yes
Theorem 7.2.11 If \( G \) is an infinite \( \omega \) -stable group with no proper definable infinite subgroups, then \( G \) is Abelian.
Proof Suppose not. Then, the center \( Z\left( G\right) \) is finite and for all \( a \in G \smallsetminus Z\left( G\right) \) , the centralizer \( C\left( a\right) = \{ g \in G : {ag} = {ga}\} \) is finite.\n\nLet \( a \in G \smallsetminus Z\left( G\right) \), and let \( b \) be generic over \( a \) .\n\nClaim \( {1b}...
Yes
Corollary 7.2.12 If \( G \) is an infinite \( \omega \) -stable group, then there is an infinite definable Abelian \( H \leq G \) .
Proof By the Descending Chain Condition, there is an infinite definable \( H \leq G \) with no infinite definable proper subgroups.
No
Corollary 7.2.13 If \( G \) is a group of Morley rank 1, then \( G \) is Abelian-by-finite (i.e., there is a definable Abelian subgroup of finite index).
Proof If \( \operatorname{RM}\left( G\right) = 1 \), then \( {G}^{0} \) is Abelian.
No
Corollary 7.2.14 If \( G \) is an infinite \( \omega \) -stable group with no definable infinite proper subgroups, then either \( G \) is a divisible Abelian group or every element of \( G \) has order \( p \) for some prime \( p \) .
Proof For any prime \( p,{G}^{p} = \left\{ {{g}^{p} : g \in G}\right\} \) is a definable subgroup and hence must either be finite or all of \( G \) . If \( {G}^{p} = G \), then every element is divisible by \( p \) . If \( G \) is \( p \) -divisible for all primes \( p \), then \( G \) is divisible. If \( {G}^{p} \) is...
Yes
Theorem 7.3.2 (Zil’ber’s Indecomposability Theorem) Let \( G \) be a group of finite Morley rank and \( \left( {{X}_{i} : i \in I}\right) \) a collection of definable indecomposable subsets of \( G \) each containing 1 . Then, the subgroup of \( G \) generated by \( \mathop{\bigcup }\limits_{{i \in I}}{X}_{i} \) is def...
Proof For each \( \sigma = \left( {{i}_{1},\ldots ,{i}_{n}}\right) \in {I}^{ < \omega } \), let \( {X}^{\sigma } = \left\{ {{x}_{1}\cdots {x}_{n} : {x}_{1} \in }\right. \) \( \left. {{X}_{{i}_{1}},\ldots ,{x}_{n} \in {X}_{{i}_{n}}}\right\} \) . Because \( \operatorname{RM}\left( G\right) \) is finite, there is a \( \si...
Yes
Lemma 7.3.3 Suppose that there is an \( \omega \) -stable action of \( \Gamma \) on a group \( G \) as a group of automorphisms, \( X \subseteq G \) is \( \Gamma \) -invariant, and for all definable \( \Gamma \) -invariant subgroups \( H \) of \( G \) either \( \left| {X/H}\right| = 1 \) or \( X/H \) is infinite. Then,...
Proof Suppose that \( H \) is a definable subgroup of \( G \) and \( 1 < \left| {X/H}\right| < {\aleph }_{0} \) . Suppose that \( X \subseteq {x}_{1}H \cup \ldots \cup {x}_{n}H \) . If \( \gamma \in \Gamma \) and \( x \in X \), then \( {\gamma }^{-1}x \in \) \( X \) . Thus, \( {\gamma }^{-1}x = {x}_{i}h \) for some \( ...
Yes
Corollary 7.3.4 Suppose that \( G \) is an \( \omega \) -stable group. If \( H \) is a definable connected subgroup of \( G \) and \( g \in G \), then \( {g}^{H} \) is indecomposable.
Proof The group \( H \) acts on \( G \) via conjugation, and \( {g}^{H} \) is invariant under this action. Thus, by the preceding lemma, it suffices to show that \( {g}^{H} \) is indecomposable for definable \( N \leq G \) where \( {hN}{h}^{-1} = N \) for all \( h \in H \) . Suppose that \( {g}^{H}/N \) is finite and \...
Yes
Corollary 7.3.5 If \( G \) is a connected group of finite Morley rank, then the commutator subgroup \( {G}^{\prime } \) is a connected definable subgroup of \( G \) .
Proof By Corollary 7.3.4, \( {g}^{G} \) is indecomposable. Thus, \( {g}^{-1}\left( {g}^{G}\right) \) is indecomposable, \( 1 \in {g}^{-1}\left( {g}^{G}\right) \) and \( {G}^{\prime } \) is the group generated by \( \left\{ {{g}^{-1}\left( {g}^{G}\right) }\right. \) : \( g \in G\} \) . By Zil’ber’s Indecomposability The...
Yes
Theorem 7.3.6 If \( G \) is an infinite non-Abelian group of finite Morley rank and \( G \) has no nontrivial definable normal subgroups, then \( G \) is simple.
Proof Because \( {G}^{0} \) is a normal subgroup of \( G, G \) is connected. For \( a \in G \) , let \( C\left( a\right) \) be the centralizer \( \{ g \in G : {ga} = {ag}\} \) . For \( g, h \in G,{a}^{g} = {a}^{h} \) if and only if \( g \in {hC}\left( a\right) \) . Suppose \( {a}^{G} \) is finite. Then, \( C\left( a\ri...
Yes
Theorem 7.3.15 If \( G \) is an infinite connected, solvable, nonnilpotent group of finite Morley rank, then \( G \) interprets an algebraically closed field.
Proof Let \( {Z}_{0}\left( G\right) \trianglelefteq {Z}_{1}\left( G\right) \ldots \) be the upper central series of \( G \) . Because \( G \) has finite Morley rank, there is an \( n \) such that \( \operatorname{RM}\left( {{Z}_{n}\left( G\right) }\right) \) is maximal. Then, \( {Z}_{n + 1}\left( G\right) /{Z}_{n}\left...
"No"
Lemma 7.4.3 If \( V \) is a variety, then \( V \) is interpretable in the algebraically closed field \( K \) .
Proof Let \( V = {V}_{1} \cup \ldots \cup {V}_{n} \) with charts \( {f}_{i} : {V}_{i} \rightarrow {U}_{i} \), without loss of generality, there is an \( m \) such that each \( {U}_{i} \subseteq {K}^{m} \) . Let \( {a}_{1},\ldots ,{a}_{n} \in K \) be distinct, and let \( X = \left\{ {\left( {x, y}\right) \in {K}^{m + 1}...
Yes
Lemma 7.4.7 Suppose that \( V \) and \( W \) are varieties, \( {V}_{0} \subseteq V \) is open, and \( f : {V}_{0} \rightarrow W \) is a definable function. There is an affine open \( U \subseteq {V}_{0} \) such that \( f \mid U \) is a quasimorphism.
Proof Without loss of generality, we may assume that \( {V}_{0} \) is an affine open subset of \( V \), the closure of \( {V}_{0} \) is irreducible, \( {W}_{0} \) is an affine open subset of \( W \), and \( f : {V}_{0} \rightarrow {W}_{0} \) . By Proposition 3.2.14, there are quasirational functions \( {f}_{1},\ldots ,...
Yes
Lemma 7.4.9 A definable subgroup of an algebraic group is closed.
Proof Suppose that \( G \) is an algebraic group and \( H \leq G \) is definable. Let \( V \) be the closure of \( H \) in \( G \) . Suppose, for contradiction, that \( a \in V \smallsetminus H \) . By Exercise 6.6.14, \( \operatorname{RM}\left( {V \smallsetminus H}\right) < \operatorname{RM}\left( H\right) \) . Every ...
No
Lemma 7.4.10 A connected algebraic group is irreducible.
Proof Let \( G \) be a connected algebraic group. Let \( {V}_{1},\ldots ,{V}_{m} \) be the irreducible components of \( G \) . If \( a \in G \), then \( x \mapsto {ax} \) is continuous. Thus, each \( a{V}_{i} \) is irreducible and \( G = a{V}_{1} \cup \ldots \cup a{V}_{m} \) . Because the decomposition into irreducible...
Yes
Lemma 7.4.11 Suppose that \( K \) is an algebraically closed field of characteristic zero. Suppose that \( G \) is a variety, \( \left( {G, \cdot }\right) \) is a group, and \( \cdot \) is a morphism. Then, \( \left( {G, \cdot }\right) \) is an algebraic group.
Proof We must show that \( x \mapsto {x}^{-1} \) is a morphism. Let \( {G}^{0} \) be the connected component of \( G \), and let \( U \subseteq {G}^{0} \) be an affine open subset of \( {G}^{0} \) . Because \( {G}^{0} \) is irreducible, it is the closure of \( U \) . Thus, \( U \) is a generic subset of \( {G}^{0} \) ....
Yes
Lemma 7.4.12 Suppose that \( K \) is an algebraically closed field of characteristic zero, \( G \) and \( H \) are algebraic groups and \( f : G \rightarrow H \) is a definable group homomorphism, then \( f \) is a morphism.
Proof Let \( a \in {G}^{0} \) be generic. By Lemma 7.4.7, there is an affine open set \( U \) such that \( f \mid U \) is a morphism. Finitely many translates of \( U \) cover \( G \) . If \( x \in {aU} \), then \( f\left( x\right) \) is given by the composition\n\n\[ x \mapsto {a}^{-1}x \mapsto f\left( {{a}^{-1}x}\rig...
Yes
Lemma 7.4.13 Suppose that \( K \) is an algebraically closed field of characteristic zero, \( G \) is a constructible group, and \( {G}^{0} \) is definably isomorphic to an algebraic group; then, so is \( G \) .
Proof Let \( A \) be a set of representatives for \( G/{G}^{0} \) . For \( g \in G \), let \( i\left( g\right) \in A \) such that \( g \in i\left( g\right) {G}^{0} \) . We can choose \( A \) such that \( i\left( 1\right) = 1 \) and \( {a}^{-1} \in A \) for all \( a \in A \) . Then, \( G \) is the disjoint union \( \mat...
Yes
Theorem 7.4.14 Let \( K \) be an algebraically closed field of characteristic zero. If \( G \subseteq {K}^{n} \) is a constructible group, then \( G \) is definably isomorphic to an algebraic group.
Proof Without loss of generality, we may assume that \( G \) is connected. By quantifier elimination, \( G = \mathop{\bigcup }\limits_{{i = 1}}^{n}{F}_{i} \cap {O}_{i} \) where \( {F}_{i} \) is Zariski closed and irreducible and \( {O}_{i} \) is open. Let \( {V}_{1} \) be some \( {F}_{i} \cap {O}_{i} \) containing the ...
Yes
Corollary 7.4.16 If \( K \) is an algebraically closed field of characteristic zero, \( G \) is an algebraic group and \( H \leq G \) is an algebraic subgroup, then \( G/H \) is an algebraic group.
Proof Because \( G/H \) is interpretable, by elimination of imaginaries it is constructible and, by Theorem 7.4.14, it is isomorphic to an algebraic group.
No
Lemma 7.4.19 Let \( k \) be a differential field with constants \( {C}_{k} \) . Let \( f\left( X\right) \in \) \( k\{ X\} \) be a homogeneous linear differential polynomial of order \( n \) .\ni) The solutions to \( f\left( X\right) = 0 \) in \( k \) form a vector space over \( {C}_{k} \) of dimension at most \( n \) .
Proof i) and ii) are standard facts that can be found in any book on differential equations (for example, [39] or [65]).
No
Lemma 7.4.21 Let \( k \) be a differential field with algebraically closed constant field \( {C}_{k} \), and let \( f\left( X\right) = 0 \) be a homogeneous linear differential equation over \( k \) . There is \( l/k \) a Picard-Vessiot extension for \( f \) with \( l \) contained in the differential closure of \( k \)...
Proof Let \( K \) be the differential closure of \( k \) . By Exercise 6.6.32, \( {C}_{K} = \) \( {C}_{k} \) . By Lemma 7.4.19, we can find \( {x}_{1},\ldots ,{x}_{n} \in K \) a fundamental system of solutions for \( f\left( X\right) = 0 \) . Thus, \( l = k\left\langle {{x}_{1},\ldots ,{x}_{n}}\right\rangle \) is a Pic...
No
Theorem 7.4.22 Suppose that \( k \) is a differential field with algebraically closed constant field \( C \) . Let \( f\left( X\right) \in k\{ X\} \) be a homogeneous linear differential equation of order \( n \), and let \( l/k \) be a Picard-Vessiot extension for \( f \) . The differential Galois group \( G\left( {l/...
Proof Suppose that \( l = k\left\langle {{x}_{1},\ldots ,{x}_{n}}\right\rangle \), where \( {x}_{1},\ldots ,{x}_{n} \) is a fundamental system of solutions to linear equation \( f\left( X\right) = 0 \) . Because \( l/k \) is Picard-Vessiot, \( {C}_{l} = C \) .\n\nLet \( V = \{ y \in l : f\left( y\right) = 0\} \) . Then...
Yes
Lemma 7.4.25 \( \psi \left( \bar{v}\right) \) isolates \( \operatorname{tp}\left( {\bar{a}/\left\langle {k,{C}_{\mathbb{K}}}\right\rangle }\right) \) .
Proof Suppose, for contradiction, that \( \bar{b} \in k,\bar{c} \in {C}_{\mathbb{K}} \), and \( \phi \left( {\bar{v},\bar{b},\bar{c}}\right) \) and \( \neg \phi \left( {\bar{v},\bar{b},\bar{c}}\right) \) split \( \psi \left( \bar{v}\right) \) . Then\n\n\[ \n\mathbb{K} \vDash \exists \bar{c}\left( {\bigwedge {c}_{i}^{\p...
Yes
Theorem 7.5.3 Suppose that \( \mathbb{M} \) is \( \omega \) -stable and \( G \subseteq \mathbb{M} \) is an \( \bigwedge \) -definable group. Then, \( G \) is definable.
Proof Let \( \mathop{\bigwedge }\limits_{{i \in I}}{\phi }_{i}\left( v\right) \) define \( G \) . Without loss of generality, we may assume that if \( {I}_{0} \subseteq I \) is finite, there is \( j \in I \) such that\n\n\[{\phi }_{j}\left( v\right) \rightarrow \mathop{\bigwedge }\limits_{{i \in {I}_{0}}}{\phi }_{i}\le...
Yes
Theorem 7.5.4 Suppose that \( T \) is \( \omega \) -stable and \( \mathbb{M} \) is a monster model of \( T \) . Let \( A \subset \mathbb{M} \), and let \( p \in {S}_{1}\left( A\right) \) be a stationary type (for notational simplicity, we will assume that \( A = \varnothing \), but this is no loss of generality). For \...
Proof Suppose that \( f \) and \( g \) are definable functions. We say that \( f \) and \( g \) have the same germ at \( p \) if and only if whenever \( A \) is large enough so that \( f \) and \( g \) are both defined over \( A \), and \( a \) realizes \( {p}_{A} \), then \( f\left( a\right) = g\left( a\right) \) . We...
Yes
Theorem 7.5.7 Suppose that there is a group configuration in \( {\mathbb{M}}^{\text{eq }} \) . Then, there is a rank one group definable in \( {\mathbb{M}}^{\text{eq }} \) .
We give an application of the group configuration in Theorem 8.3.1. Proofs of Hrushovski’s Theorem appear in [18] §4.5 and [76] §5.4.
No
Theorem 7.6.26 If \( G \) is a simple group of Morley rank 3, then\ni) \( G \) is a bad group, or\nii) \( G \) interprets an algebraically closed field \( K \) and \( G \) is definably isomorphic to \( {PS}{L}_{2}\left( K\right) \) .
For proofs of these results and more on groups of finite Morley rank, see [86] or [15].
No
Lemma 8.2.3 Suppose that \( X \subseteq \mathbb{M} \) is definable. There is \( \alpha \in {\mathbb{M}}^{\text{eq }} \) such that \( \alpha \) is a canonical base for \( X \) . Indeed, if \( X \) is \( A \) -definable, we can find a canonical base in \( {\operatorname{dcl}}^{\mathrm{{eq}}}\left( A\right) \) .
Proof Suppose that \( X \) is defined by the formula \( \phi \left( {\bar{x},\bar{a}}\right) \) . Let \( E \) be the equivalence relation\n\n\[ \bar{a}E\bar{b} \Leftrightarrow \left( {\phi \left( {\bar{x},\bar{a}}\right) \leftrightarrow \phi \left( {\bar{x},\bar{b}}\right) }\right) .\n\nLet \( \alpha = \bar{a}/E \in {\...
Yes
Lemma 8.2.4 If \( A \) is a canonical base for \( p \in {S}_{n}\left( \mathbb{M}\right) \), then \( B \) is a canonical base for \( p \) if and only if \( {\operatorname{dcl}}^{\mathrm{{eq}}}\left( A\right) = {\operatorname{dcl}}^{\mathrm{{eq}}}\left( B\right) \) .
Proof Suppose that \( C \subset \mathbb{M} \) and \( \left| C\right| < \left| \mathbb{M}\right| \) ; let \( \operatorname{Aut}\left( {\mathbb{M}/C}\right) \) denote the automorphisms of \( \mathbb{M} \) fixing \( C \) pointwise. The proof of Proposition 4.3.25 generalized to \( {\mathbb{M}}^{\text{eq }} \) shows that\n...
Yes
Lemma 8.2.6 Suppose that \( \mathbb{M} \) is \( \omega \) -stable and \( p \in {S}_{n}\left( \mathbb{M}\right) \) . Then, \( p \) has a canonical base in \( {\mathbb{M}}^{\text{eq }} \) .
Proof For each \( \mathcal{L} \) -formula \( \phi \left( {\bar{v},\bar{w}}\right) \), let \( {X}_{\phi } = \{ \bar{a} \in \mathbb{M} : \phi \left( {\bar{v},\bar{a}}\right) \in p\} \) . By definability of types, \( {X}_{\phi } \) is definable. If \( \sigma \) is an automorphism of \( \mathbb{M} \), then \( {\sigma p} = ...
Yes
Theorem 8.2.7 Suppose that \( \mathbb{M} \) is \( \omega \) -stable and \( p \in {S}_{n}\left( \mathbb{M}\right) \) does not fork over \( A \subseteq \mathbb{M} \) . There is \( \alpha \in {\operatorname{acl}}^{\mathrm{{eq}}}\left( A\right) \), a canonical base for \( p \) . If \( p \mid A \) is stationary, then we can...
Proof Suppose that \( \phi \left( {\bar{v},\bar{w}}\right) \) is an \( \mathcal{L} \) -formula such that \( \phi \left( {\bar{v},\bar{a}}\right) \in p \) and \( \operatorname{RM}\left( {\phi \left( {\bar{v},\bar{a}}\right) }\right) = \operatorname{RM}\left( p\right) \) . Let \( X = \{ \bar{b} : \phi \left( {\bar{v},\ba...
Yes
Lemma 8.2.9 Let \( \mathbb{M} \) be a strongly minimal set and let \( X \subset \mathbb{M} \) be infinite. Suppose that \( E \) is an \( \varnothing \) -definable equivalence relation on \( {\mathbb{M}}^{m} \) . Let \( \overline{a} \in {\mathbb{M}}^{m} \) and \( \alpha = \bar{a}/E \) . There is a finite \( C \subset {\...
In particular, if \( {\mathbb{M}}_{X} \) is \( \mathbb{M} \) viewed as an \( {\mathcal{L}}_{X} \) -structure, then for every \( \alpha \in {\mathbb{M}}_{X}^{\text{eq }} \) there is \( \bar{d} \in \mathbb{M} \) such that \( {\operatorname{acl}}^{\text{eq }}\left( {\alpha, X}\right) = {\operatorname{acl}}^{\text{eq }}\le...
Yes
Theorem 8.2.11 Let \( D \subseteq {\mathbb{M}}^{n} \) be a strongly minimal set. The following are equivalent:\n\ni) for some small \( B \subset D \), the pregeometry \( {D}_{B} \) is modular;\n\nii) \( D \) is linear;\n\niii) for any \( b \in D \smallsetminus \operatorname{acl}\left( \varnothing \right) ,{D}_{b} \) is...
Proof Often when we want to prove things about arbitrary strongly minimal sets \( D \subseteq {\mathbb{M}}^{n} \), we instead assume that \( \mathbb{M} \) is strongly minimal. This is no great loss of generality. By extending the language, we may assume that \( D \) is \( \varnothing \) -definable. By Corollary 6.3.7, ...
Yes
Lemma 8.2.13 Suppose that \( T \) is \( \omega \) -stable. The following are equivalent.\n\ni) \( T \) is one-based.\n\nii) For all \( \bar{a} \in {\mathbb{M}}^{\text{eq }} \) and \( B \subseteq {\mathbb{M}}^{\text{eq }} \), if \( \operatorname{tp}\left( {\bar{a}/B}\right) \) is stationary, then \( \operatorname{cb}\le...
i) \( \Rightarrow \) ii) Let \( A = {\operatorname{acl}}^{\text{eq }}\left( \bar{a}\right) \) . Because \( \operatorname{tp}\left( {\bar{a}/{\operatorname{acl}}^{\text{eq }}\left( B\right) }\right) \) does not fork over \( B \) , we may without loss of generality assume that \( B = {\operatorname{acl}}^{\mathrm{{eq}}}\...
Yes
Theorem 8.2.15 Suppose that \( T \) is uncountably categorical and \( \mathbb{M} \) is the monster model of \( T \) . The following are equivalent.\n\ni) \( T \) is one-based.\n\nii) Every strongly minimal \( D \subseteq {\mathbb{M}}^{n} \) is locally modular.\n\niii) Some strongly minimal \( D \subseteq {\mathbb{M}}^{...
For a proof, see Theorem 4.3.1 in [18].
No
Corollary 8.3.4 If \( \mathbb{G} \) is an \( \omega \) -stable, one-based group, then there are at most countably many definable subgroups of \( {\mathbb{G}}^{n} \) .
Proof Any definable subgroup \( H \) has a canonical base in \( {\operatorname{acl}}^{\mathrm{{eq}}}\left( \varnothing \right) \) . Because our language is countable, \( {\operatorname{acl}}^{\mathrm{{eq}}}\left( \varnothing \right) \) is countable and there are only countably many definable subgroups.
Yes
Lemma 8.3.5 If \( \mathbb{G} \) is a connected one-based \( \omega \) -stable group, then \( \mathbb{G} \) is Abelian. Thus every one-based \( \omega \) -stable group is Abelian-by-finite.
Proof For \( g \in \mathbb{G} \), let \( {H}_{g} = \left\{ {\left( {h,{g}^{-1}{hg}}\right) : h \in \mathbb{G}}\right\} \subseteq \mathbb{G} \times \mathbb{G} \) . Then, \( {H}_{g} = {H}_{h} \) if and only if \( g/Z\left( \mathbb{G}\right) = h/Z\left( \mathbb{G}\right) \) . If \( \mathbb{G} \) is non-Abelian, then \( Z\...
Yes
Corollary 8.3.7 Suppose that \( p \in {S}_{n}\left( G\right) \) then, there is \( \bar{b} \in {G}^{n} \) such that “ \( v \in \operatorname{Stab}\left( p\right) \bar{b} \) ” \( \in p \) .
Proof As we argued above, the group \( {G}^{n} \) is also one-based, and we can view \( p \) as a 1-type over \( {G}^{n} \) and apply the previous lemma.
No
Theorem 8.3.9 If \( G \) is an \( \omega \) -stable one-based group and \( X \subseteq {G}^{n} \) is definable, then \( X \) is a finite Boolean combination of cosets of definable subgroups \( H \leq {G}^{n} \) .
Proof This follows from Corollary 8.3.8 and Exercise 4.5.13.
No
Theorem 8.3.20 Suppose that \( K \) is a differentially closed field and \( A \) is a simple Abelian variety defined over \( K \) that is not isomorphic to an Abelian variety defined over \( C \) . Let \( {A}^{\# } \) be the closure in the Kolchin topology of the torsion points of \( A \) . Then, \( {A}^{\# } \) is a o...
The results of Manin and Buium show that \( {A}^{\# } \) is a finite Morley rank group with no infinite definable subgroups. There are two cases to consider. If all strongly minimal subsets of \( {A}^{\# } \) are locally modular, then \( {A}^{\# } \) is one-based. If there is any nonlocally modular strongly minimal sub...
Yes
Theorem 8.3.21 Let \( K \) and \( k \) be algebraically closed fields of characteristic zero with \( k \subseteq K \) . Let \( A \) be a simple \( A \) belian variety defined over \( K \) that is not isomorphic to an Abelian variety defined over the algebraic closure of \( k \) . If \( V \subset A \) is a proper subvar...
Proof We can define a derivation \( \delta \) on \( K \) such that the constant field is \( k \) (see [58] X §7). If \( \widehat{K} \) is the differential closure of \( \left( {K,\delta }\right) \), then, by Exercise 6.6.32, the constant field of \( \widehat{K} \) is \( k \) . Thus, replacing \( K \) by \( \widehat{K} ...
Yes
Theorem 1.2 (Topological Invariance of Dimension). A nonempty n-dimensional topological manifold cannot be homeomorphic to an \( m \) -dimensional manifold unless \( m = n \) .
For the proof, see Theorem 17.26. In Chapter 2, we will also prove a related but weaker theorem (diffeomorphism invariance of dimension, Theorem 2.17). See also [LeeTM, Chap. 13] for a different proof of Theorem 1.2 using singular homology theory.
No
Example 1.3 (Graphs of Continuous Functions). Let \( U \subseteq {\mathbb{R}}^{n} \) be an open subset, and let \( f : U \rightarrow {\mathbb{R}}^{k} \) be a continuous function. The graph of \( f \) is the subset of \( {\mathbb{R}}^{n} \times {\mathbb{R}}^{k} \) defined by\n\n\[ \Gamma \left( f\right) = \left\{ {\left...
Because \( \varphi \) is the restriction of a continuous map, it is continuous; and it is a homeomorphism because it has a continuous inverse given by \( {\varphi }^{-1}\left( x\right) = \left( {x, f\left( x\right) }\right) \) . Thus \( \Gamma \left( f\right) \) is a topological manifold of dimension \( n \) . In fact,...
Yes
For each integer \( n \geq 0 \), the unit \( n \)-sphere \( {\mathbb{S}}^{n} \) is Hausdorff and second-countable because it is a topological subspace of \( {\mathbb{R}}^{n + 1} \). To show that it is locally Euclidean, for each index \( i = 1,\ldots, n + 1 \) let \( {U}_{i}^{ + } \) denote the subset of \( {\mathbb{R}...
Let \( f : {\mathbb{B}}^{n} \rightarrow \mathbb{R} \) be the continuous function\n\n\[ f\left( u\right) = \sqrt{1 - {\left| u\right| }^{2}} \]\n\nThen for each \( i = 1,\ldots, n + 1 \), it is easy to check that \( {U}_{i}^{ + } \cap {\mathbb{S}}^{n} \) is the graph of the function\n\n\[ {x}^{i} = f\left( {{x}^{1},\ldo...
Yes
Example 1.5 (Projective Spaces). The \( n \) -dimensional real projective space, denoted by \( {\mathbb{{RP}}}^{n} \) (or sometimes just \( {\mathbb{P}}^{n} \) ), is defined as the set of 1-dimensional linear subspaces of \( {\mathbb{R}}^{n + 1} \), with the quotient topology determined by the natural map \( \pi : {\ma...
For each \( i = 1,\ldots, n + 1 \), let \( {\widetilde{U}}_{i} \subseteq {\mathbb{R}}^{n + 1} \smallsetminus \{ 0\} \) be the set where \( {x}^{i} \neq 0 \) , and let \( {U}_{i} = \pi \left( {\widetilde{U}}_{i}\right) \subseteq {\mathbb{{RP}}}^{n} \) . Since \( {\widetilde{U}}_{i} \) is a saturated open subset, \( {U}_...
Yes
Example 1.8 (Product Manifolds). Suppose \( {M}_{1},\ldots ,{M}_{k} \) are topological manifolds of dimensions \( {n}_{1},\ldots ,{n}_{k} \), respectively. The product space \( {M}_{1} \times \cdots \times {M}_{k} \) is shown to be a topological manifold of dimension \( {n}_{1} + \cdots + {n}_{k} \) as follows.
It is Hausdorff and second-countable by Propositions A. 17 and A.23, so only the locally Euclidean property needs to be checked. Given any point \( \left( {{p}_{1},\ldots ,{p}_{k}}\right) \in \) \( {M}_{1} \times \cdots \times {M}_{k} \), we can choose a coordinate chart \( \left( {{U}_{i},{\varphi }_{i}}\right) \) for...
Yes
Lemma 1.10. Every topological manifold has a countable basis of precompact coordinate balls.
Proof. Let \( M \) be a topological \( n \) -manifold. First we consider the special case in which \( M \) can be covered by a single chart. Suppose \( \varphi : M \rightarrow \widehat{U} \subseteq {\mathbb{R}}^{n} \) is a global coordinate map, and let \( \mathcal{B} \) be the collection of all open balls \( {B}_{r}\l...
Yes
Proposition 1.11. Let \( M \) be a topological manifold.\n\n(a) \( M \) is locally path-connected.\n\n(b) \( M \) is connected if and only if it is path-connected.\n\n(c) The components of \( M \) are the same as its path components.\n\n(d) \( M \) has countably many components, each of which is an open subset of \( M ...
Proof. Since each coordinate ball is path-connected, (a) follows from the fact that \( M \) has a basis of coordinate balls. Parts (b) and (c) are immediate consequences of (a) and Proposition A.43. To prove (d), note that each component is open in \( M \) by Proposition A.43, so the collection of components is an open...
Yes
Proposition 1.12 (Manifolds Are Locally Compact). Every topological manifold is locally compact.
Proof. Lemma 1.10 showed that every manifold has a basis of precompact open subsets.
No
Theorem 1.15 (Manifolds Are Paracompact). Every topological manifold is paracompact. In fact, given a topological manifold \( M \), an open cover \( X \) of \( M \) , and any basis \( \mathcal{B} \) for the topology of \( M \), there exists a countable, locally finite open refinement of \( X \) consisting of elements o...
Proof. Given \( M, X \), and \( \mathcal{B} \) as in the hypothesis of the theorem, let \( {\left( {K}_{j}\right) }_{j = 1}^{\infty } \) be an exhaustion of \( M \) by compact sets (Proposition A.60). For each \( j \), let \( {V}_{j} \doteq {\bar{K}}_{j + 1} \smallsetminus \) Int \( {K}_{j} \) and \( {W}_{j} = \operato...
Yes
Proposition 1.17. Let \( M \) be a topological manifold.\n\n(a) Every smooth atlas \( \mathcal{A} \) for \( M \) is contained in a unique maximal smooth atlas, called the smooth structure determined by \( \mathcal{A} \) .
Proof. Let \( \mathcal{A} \) be a smooth atlas for \( M \), and let \( \overline{\mathcal{A}} \) denote the set of all charts that are smoothly compatible with every chart in \( \mathcal{A} \) . To show that \( \overline{\mathcal{A}} \) is a smooth atlas, we need to show that any two charts of \( \overline{\mathcal{A}}...
Yes
For each nonnegative integer \( n \), the Euclidean space \( {\mathbb{R}}^{n} \) is a smooth \( n \)-manifold with the smooth structure determined by the atlas consisting of the single chart \( \left( {{\mathbb{R}}^{n},{\operatorname{Id}}_{{\mathbb{R}}^{n}}}\right) \).
We call this the standard smooth structure on \( {\mathbb{R}}^{n} \) and the resulting coordinate map standard coordinates. Unless we explicitly specify otherwise, we always use this smooth structure on \( {\mathbb{R}}^{n} \). With respect to this smooth structure, the smooth coordinate charts for \( {\mathbb{R}}^{n} \...
Yes
Consider the homeomorphism \( \psi : \mathbb{R} \rightarrow \mathbb{R} \) given by\n\n\[ \psi \left( x\right) = {x}^{3}. \]\n\nThe atlas consisting of the single chart \( \left( {\mathbb{R},\psi }\right) \) defines a smooth structure on \( \mathbb{R} \).
This chart is not smoothly compatible with the standard smooth structure, because the transition map \( {\operatorname{Id}}_{\mathbb{R}} \circ {\psi }^{-1}\left( y\right) = {y}^{1/3} \) is not smooth at the origin. Therefore, the smooth structure defined on \( \mathbb{R} \) by \( \psi \) is not the same as the standard...
Yes
Let \( M \) be a smooth \( n \) -manifold and let \( U \subseteq M \) be any open subset. Define an atlas on \( U \) by \[ {\mathcal{A}}_{U} = \{ \text{ smooth charts }\left( {V,\varphi }\right) \text{ for }M\text{ such that }V \subseteq U\} . \]
Every point \( p \in U \) is contained in the domain of some chart \( \left( {W,\varphi }\right) \) for \( M \) ; if we set \( V = W \cap U \), then \( \left( {V,{\left. \varphi \right| }_{V}}\right) \) is a chart in \( {\mathcal{A}}_{U} \) whose domain contains \( p \) . Therefore, \( U \) is covered by the domains of...
Yes
Example 1.27 (The General Linear Group). The general linear group \( \mathrm{{GL}}\left( {n,\mathbb{R}}\right) \) is the set of invertible \( n \times n \) matrices with real entries.
It is a smooth \( {n}^{2} \) -dimensional manifold because it is an open subset of the \( {n}^{2} \) -dimensional vector space \( \mathrm{M}\left( {n,\mathbb{R}}\right) \) , namely the set where the (continuous) determinant function is nonzero.
Yes
If \( U \subseteq {\mathbb{R}}^{n} \) is an open subset and \( f : U \rightarrow {\mathbb{R}}^{k} \) is a smooth function, we have already observed above (Example 1.3) that the graph of \( f \) is a topological \( n \) -manifold in the subspace topology.
Since \( \Gamma \left( f\right) \) is covered by the single graph coordinate chart \( \varphi : \Gamma \left( f\right) \rightarrow U \) (the restriction of \( {\pi }_{1} \) ), we can put a canonical smooth structure on \( \Gamma \left( f\right) \) by declaring the graph coordinate chart \( \left( {\Gamma \left( f\right...
Yes
We showed in Example 1.4 that the \( n \)-sphere \( {\mathbb{S}}^{n} \subseteq {\mathbb{R}}^{n + 1} \) is a topological \( n \)-manifold. We put a smooth structure on \( {\mathbb{S}}^{n} \) as follows. For each \( i = 1,\ldots, n + 1 \), let \( \left( {{U}_{i}^{ \pm },{\varphi }_{i}^{ \pm }}\right) \) denote the graph ...
In the case \( i < j \), we get \[ {\varphi }_{i}^{ \pm } \circ {\left( {\varphi }_{j}^{ \pm }\right) }^{-1}\left( {{u}^{1},\ldots ,{u}^{n}}\right) = \left( {{u}^{1},\ldots ,\widehat{{u}^{i}},\ldots , \pm \sqrt{1 - {\left| u\right| }^{2}},\ldots ,{u}^{n}}\right) \] (with the square root in the \( j \) th position), and...
Yes
Example 1.32 (Level Sets). The preceding example can be generalized as follows. Suppose \( U \subseteq {\mathbb{R}}^{n} \) is an open subset and \( \Phi : U \rightarrow \mathbb{R} \) is a smooth function. For any \( c \in \mathbb{R} \), the set \( {\Phi }^{-1}\left( c\right) \) is called a level set of \( \Phi \) . Cho...
Because \( {D\Phi }\left( a\right) \) is a row matrix whose entries are the partial derivatives \( \left( {\partial \Phi /\partial {x}^{1}\left( a\right) ,\ldots ,\partial \Phi /\partial {x}^{n}\left( a\right) }\right) \), for each \( a \in M \) there is some \( i \) such that \( \partial \Phi /\partial {x}^{i}\left( a...
Yes
The \( n \)-dimensional real projective space \( {\mathbb{{RP}}}^{n} \) is a topological \( n \)-manifold by Example 1.5. Let us check that the coordinate charts \( \left( {{U}_{i},{\varphi }_{i}}\right) \) constructed in that example are all smoothly compatible.
Assuming for convenience that \( i > j \), it is straightforward to compute that\n\n\[ \n{\varphi }_{j} \circ {\varphi }_{i}^{-1}\left( {{u}^{1},\ldots ,{u}^{n}}\right) = \left( {\frac{{u}^{1}}{{u}^{j}},\ldots ,\frac{{u}^{j - 1}}{{u}^{j}},\frac{{u}^{j + 1}}{{u}^{j}},\ldots ,\frac{{u}^{i - 1}}{{u}^{j}},\frac{1}{{u}^{j}}...
Yes
Example 1.34 (Smooth Product Manifolds). If \( {M}_{1},\ldots ,{M}_{k} \) are smooth manifolds of dimensions \( {n}_{1},\ldots ,{n}_{k} \), respectively, we showed in Example 1.8 that the product space \( {M}_{1} \times \cdots \times {M}_{k} \) is a topological manifold of dimension \( {n}_{1} + \cdots + {n}_{k} \), wi...
\[ \left( {{\psi }_{1} \times \cdots \times {\psi }_{k}}\right) \circ {\left( {\varphi }_{1} \times \cdots \times {\varphi }_{k}\right) }^{-1} = \left( {{\psi }_{1} \circ {\varphi }_{1}^{-1}}\right) \times \cdots \times \left( {{\psi }_{k} \circ {\varphi }_{k}^{-1}}\right) , \] which is a smooth map. This defines a nat...
Yes
Lemma 1.35 (Smooth Manifold Chart Lemma). Let \( M \) be a set, and suppose we are given a collection \( \left\{ {U}_{\alpha }\right\} \) of subsets of \( M \) together with maps \( {\varphi }_{\alpha } : {U}_{\alpha } \rightarrow {\mathbb{R}}^{n} \), such that the following properties are satisfied:\n\n(i) For each \(...
Proof. We define the topology by taking all sets of the form \( {\varphi }_{\alpha }^{-1}\left( V\right) \), with \( V \) an open subset of \( {\mathbb{R}}^{n} \), as a basis. To prove that this is a basis for a topology, we need to show that for any point \( p \) in the intersection of two basis sets \( {\varphi }_{\a...
Yes
Theorem 1.37 (Topological Invariance of the Boundary). If \( M \) is a topological manifold with boundary, then each point of \( M \) is either a boundary point or an interior point, but not both. Thus \( \partial M \) and \( \operatorname{Int}M \) are disjoint sets whose union is \( M \) .
For the proof, see Problem 17-9.
No
Proposition 1.45. Suppose \( {M}_{1},\ldots ,{M}_{k} \) are smooth manifolds and \( N \) is a smooth manifold with boundary. Then \( {M}_{1} \times \cdots \times {M}_{k} \times N \) is a smooth manifold with boundary, and \( \partial \left( {{M}_{1} \times \cdots \times {M}_{k} \times N}\right) = {M}_{1} \times \cdots ...
Proof. Problem 1-12.
No
Theorem 1.46 (Smooth Invariance of the Boundary). Suppose \( M \) is a smooth manifold with boundary and \( p \in M \) . If there is some smooth chart \( \left( {U,\varphi }\right) \) for \( M \) such that \( \varphi \left( U\right) \subseteq {\mathbb{H}}^{n} \) and \( \varphi \left( p\right) \in \partial {\mathbb{H}}^...
Proof. Suppose on the contrary that \( p \) is in the domain of a smooth interior chart \( \left( {U,\psi }\right) \) and also in the domain of a smooth boundary chart \( \left( {V,\varphi }\right) \) such that \( \varphi \left( p\right) \in \) \( \partial {\mathbb{H}}^{n} \) . Let \( \tau = \varphi \circ {\psi }^{-1} ...
Yes
Proposition 2.4. Every smooth map is continuous.
Proof. Suppose \( M \) and \( N \) are smooth manifolds with or without boundary, and \( F : M \rightarrow N \) is smooth. Given \( p \in M \), smoothness of \( F \) means there are smooth charts \( \left( {U,\varphi }\right) \) containing \( p \) and \( \left( {V,\psi }\right) \) containing \( F\left( p\right) \), suc...
Yes
Proposition 2.10. Let \( M, N \), and \( P \) be smooth manifolds with or without boundary.\n\n(d) If \( F : M \rightarrow N \) and \( G : N \rightarrow P \) are smooth, then so is \( G \circ F : M \rightarrow P \) .
Proof. We prove (d) and leave the rest as exercises. Let \( F : M \rightarrow N \) and \( G : N \rightarrow \) \( P \) be smooth maps, and let \( p \in M \) . By definition of smoothness of \( G \), there exist smooth charts \( \left( {V,\theta }\right) \) containing \( F\left( p\right) \) and \( \left( {W,\psi }\right...
No
Proposition 2.12. Suppose \( {M}_{1},\ldots ,{M}_{k} \) and \( N \) are smooth manifolds with or without boundary, such that at most one of \( {M}_{1},\ldots ,{M}_{k} \) has nonempty boundary. For each \( i \), let \( {\pi }_{i} : {M}_{1} \times \cdots \times {M}_{k} \rightarrow {M}_{i} \) denote the projection onto th...
## Proof. Problem 2-2.
No
Theorem 2.17 (Diffeomorphism Invariance of Dimension). A nonempty smooth manifold of dimension \( m \) cannot be diffeomorphic to an \( n \) -dimensional smooth manifold unless \( m = n \).
Proof. Suppose \( M \) is a nonempty smooth \( m \) -manifold, \( N \) is a nonempty smooth \( n \) - manifold, and \( F : M \rightarrow N \) is a diffeomorphism. Choose any point \( p \in M \), and let \( \left( {U,\varphi }\right) \) and \( \left( {V,\psi }\right) \) be smooth coordinate charts containing \( p \) and...
Yes
Theorem 2.18 (Diffeomorphism Invariance of the Boundary). Suppose \( M \) and \( N \) are smooth manifolds with boundary and \( F : M \rightarrow N \) is a diffeomorphism. Then \( F\left( {\partial M}\right) = \partial N \), and \( F \) restricts to a diffeomorphism from \( \operatorname{Int}M \) to \( \operatorname{In...
## - Exercise 2.19. Use Theorem 1.46 to prove the preceding theorem.
No
Lemma 2.20. The function \( f : \mathbb{R} \rightarrow \mathbb{R} \) defined by\n\n\[ f\left( t\right) = \left\{ \begin{array}{ll} {e}^{-1/t}, & t > 0 \\ 0, & t \leq 0 \end{array}\right. \]\n\nis smooth.
Proof. The function in question is pictured in Fig. 2.4. It is smooth on \( \mathbb{R} \smallsetminus \{ 0\} \) by composition, so we need only show \( f \) has continuous derivatives of all orders at the origin. Because existence of the \( \left( {k + 1}\right) \) st derivative implies continuity of the \( k \) th, it...
Yes
Lemma 2.21. Given any real numbers \( {r}_{1} \) and \( {r}_{2} \) such that \( {r}_{1} < {r}_{2} \), there exists a smooth function \( h : \mathbb{R} \rightarrow \mathbb{R} \) such that \( h\left( t\right) \equiv 1 \) for \( t \leq {r}_{1},0 < h\left( t\right) < 1 \) for \( {r}_{1} < \) \( t < {r}_{2} \), and \( h\lef...
Proof. Let \( f \) be the function of the previous lemma, and set\n\n\[ h\left( t\right) = \frac{f\left( {{r}_{2} - t}\right) }{f\left( {{r}_{2} - t}\right) + f\left( {t - {r}_{1}}\right) }.\]\n\n(See Fig. 2.5.) Note that the denominator is positive for all \( t \), because at least one of the expressions \( {r}_{2} - ...
Yes
Lemma 2.22. Given any positive real numbers \( {r}_{1} < {r}_{2} \), there is a smooth function \( H : {\mathbb{R}}^{n} \rightarrow \mathbb{R} \) such that \( H \equiv 1 \) on \( {\bar{B}}_{{r}_{1}}\left( 0\right) ,0 < H\left( x\right) < 1 \) for all \( x \in {B}_{{r}_{2}}\left( 0\right) \smallsetminus {\bar{B}}_{{r}_{...
Proof. Just set \( H\left( x\right) = h\left( \left| x\right| \right) \), where \( h \) is the function of the preceding lemma. Clearly, \( H \) is smooth on \( {\mathbb{R}}^{n} \smallsetminus \{ 0\} \), because it is a composition of smooth functions there. Since it is identically equal to 1 on \( {B}_{{r}_{1}}\left( ...
Yes
Proposition 2.25 (Existence of Smooth Bump Functions). Let \( M \) be a smooth manifold with or without boundary. For any closed subset \( A \subseteq M \) and any open subset \( U \) containing \( A \), there exists a smooth bump function for \( A \) supported in \( U \) .
Proof. Let \( {U}_{0} = U \) and \( {U}_{1} = M \smallsetminus A \), and let \( \left\{ {{\psi }_{0},{\psi }_{1}}\right\} \) be a smooth partition of unity subordinate to the open cover \( \left\{ {{U}_{0},{U}_{1}}\right\} \) . Because \( {\psi }_{1} \equiv 0 \) on \( A \) and thus \( {\psi }_{0} = \) \( \mathop{\sum }...
Yes