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EN_B00000_S03252_W000095 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So you can also use this angle as well because that angle is between B and I.",
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EN_B00000_S03252_W000096 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " 180 minus 30 is 150. And it turns out that sine of 150 and sine of 30, they're both equal to one half. So it doesn't matter. So whether you choose this angle, which is between... | EN_B00000_S03252_W000096.mp3 | [
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EN_B00000_S03252_W000097 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Which is, uh, 2.5 meters times the strength of the magnetic field, which is, uh, 2 times 10 to the minus 3 multiplied by a sine of 30.",
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EN_B00000_S03252_W000098 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " And so that's going to be the force exerted on this current carrying wire.",
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EN_B00000_S03252_W000099 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Number four, a current of 35 amps flows due west in a wire that experiences a magnetic force of 0.75 newtons per meter.",
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EN_B00000_S03252_W000100 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " What is the strength of the magnetic field which is directed to itself?",
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EN_B00000_S03252_W000101 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " And the current is directed west. And the magnetic field is directed south.",
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EN_B00000_S03252_W000102 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Alright, right angles to each other because it's 90 degrees, sine 90 is 1. So we don't need the sine portion of this equation. Now we're given the force per meter.",
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EN_B00000_S03252_W000103 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000104 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000105 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 3.956,
"id": "EN_B00000_S03252_W000105",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " We have the current, which is 35 amps. So we gotta solve for B.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000105.mp3"
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EN_B00000_S03252_W000106 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So anytime you have the force per unit length, or newtons per meter,",
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EN_B00000_S03252_W000107 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " Make sure you understand that it's F divided by L. The entire thing is F over L. So you might see that expression in this chapter in a few problems. Now what is the direction ... | EN_B00000_S03252_W000107.mp3 | [
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EN_B00000_S03252_W000108 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " We know the current flows west, the monadic field is south. So the force is either into the page or out of the page.",
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EN_B00000_S03252_W000109 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " So what you want to do is you want to direct your forefingers south and your thumb west. And the force should come out of the page.",
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EN_B00000_S03252_W000110 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " So you want your thumb facing this way, and the forefingers facing this way. Using your right hand, if you do that,",
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EN_B00000_S03252_W000111 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " The force should come out of the palm of your hand. So make sure the current is aligned with your thumb. The magnetic field is aligned with",
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EN_B00000_S03252_W000112 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " You have four fingers, and then the force should come out of the palm of your hand. That's out of the page.",
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EN_B00000_S03252_W000113 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " Now let's say if we have a rectangular metal loop.",
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EN_B00000_S03252_W000114 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " With a current that flows in the metal loop clockwise. So in this section, the current's going up, here it's going down, here it's directed towards the right, and here it's dir... | EN_B00000_S03252_W000114.mp3 | [
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EN_B00000_S03252_W000115 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Now let's say the monadic field is directed into the page. So I'm going to put an x everywhere.",
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EN_B00000_S03252_W000116 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " This rectangular loop move, if initially it's at rest, will it move towards the right? Will it begin moving towards the left? Up or down? What would you say?",
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EN_B00000_S03252_W000117 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Or of the metal loop. Let's see what the magnetic force on that portion is directed.",
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EN_B00000_S03252_W000118 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So what you want to do is you want to place your thumb facing south. You want the four fingers of your hand to be going into the page. And the monadic force should be directed... | EN_B00000_S03252_W000118.mp3 | [
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EN_B00000_S03252_W000119 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So you want your four fingers going into the page. You want your thumb going south.",
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EN_B00000_S03252_W000120 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So, make sure the magnetic field, or your four fingers is going into the page. And your thumb is in the direction of the current.",
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EN_B00000_S03252_W000121 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 5.518,
"id": "EN_B00000_S03252_W000121",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " And that is out of the palm of your right hand. And it should be directed east, if you do it correctly.",
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EN_B00000_S03252_W000122 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " So make sure you try that and make sure you can master this right hand rule.",
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EN_B00000_S03252_W000123 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Now, for the other side, the left side, everything is the same except the current.",
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EN_B00000_S03252_W000124 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000125 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000126 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " There's no magnetic field in that region, so therefore there's no force.",
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EN_B00000_S03252_W000127 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000128 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000129 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000130 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000131 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000132 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000133 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " We talked about how to calculate the magnetic force on a current carrying wire.",
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EN_B00000_S03252_W000134 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " But what about the monadic force on a single point charge? Because any move in charge will create a monadic field.",
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EN_B00000_S03252_W000135 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " So let's go ahead and come up with an equation. Let's start with this equation, f is equal to iLb sine beta.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000135... | EN_B00000_S03252_W000135.mp3 | [
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EN_B00000_S03252_W000136 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3771,
"duration": 4.805,
"id": "EN_B00000_S03252_W000136",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " It is defined as the amount of electric charge that flows per unit time.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000136.mp3"
} | EN_B00000_S03252_W000136.mp3 | [
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EN_B00000_S03252_W000137 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.1635,
"duration": 4.72,
"id": "EN_B00000_S03252_W000137",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " And capital Q is the total amount of charge. It can be due to many charge particles.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000137.mp3"
} | EN_B00000_S03252_W000137.mp3 | [
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EN_B00000_S03252_W000138 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3134,
"duration": 14.72,
"id": "EN_B00000_S03252_W000138",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " So capital Q is going to be equal to lowercase q, which is the magnitude of each charged particle times n, which is the number of charged particles. And that will give you the ... | EN_B00000_S03252_W000138.mp3 | [
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EN_B00000_S03252_W000139 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.2928,
"duration": 4.176,
"id": "EN_B00000_S03252_W000139",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Now, distance is equal to the speed multiplied by the time.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000139.mp3"
} | EN_B00000_S03252_W000139.mp3 | [
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EN_B00000_S03252_W000140 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.2217,
"duration": 9.643,
"id": "EN_B00000_S03252_W000140",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " And left could be thought of as distance. They're both measured in meters. So we can replace L with VT. So let's replace I.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000... | EN_B00000_S03252_W000140.mp3 | [
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EN_B00000_S03252_W000141 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3735,
"duration": 4.261,
"id": "EN_B00000_S03252_W000141",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Now if you want to find the magnetic force on a single point charge,",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000141.mp3"
} | EN_B00000_S03252_W000141.mp3 | [
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EN_B00000_S03252_W000142 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 6.214,
"id": "EN_B00000_S03252_W000142",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " That means there's only one charged particle, so n is one. So when n is one, we can get rid of it.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000142.mp3"
} | EN_B00000_S03252_W000142.mp3 | [
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EN_B00000_S03252_W000143 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 6.095,
"id": "EN_B00000_S03252_W000143",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " So that's how you can calculate the magnetic force on a moving charged particle when it's inside a magnetic field.",
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EN_B00000_S03252_W000144 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 10.985,
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"language": "en",
"speaker": "EN_B00000_S03252",
"text": " And let's say it's moving towards the right, and also the monadic field is directed towards the right. If these two are parallel, sine zero",
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EN_B00000_S03252_W000145 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3502,
"duration": 6.35,
"id": "EN_B00000_S03252_W000145",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Is equal to zero. So there's gonna be no magnetic force. They have to be perpendicular.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000145.mp3"
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EN_B00000_S03252_W000146 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3196,
"duration": 6.01,
"id": "EN_B00000_S03252_W000146",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Now, if the proton is moving at an angle relative to the magnetic field,",
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EN_B00000_S03252_W000147 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3854,
"duration": 5.263,
"id": "EN_B00000_S03252_W000147",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " And then you can use the equation f is equal to bqv sine theta.",
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EN_B00000_S03252_W000148 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 4.194,
"id": "EN_B00000_S03252_W000148",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Where theta is the angle between the magnetic field and the velocity vector.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000148.mp3"
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EN_B00000_S03252_W000149 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 5.043,
"id": "EN_B00000_S03252_W000149",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Now let's say if the proton, it's moving perpendicular to the magnetic field.",
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EN_B00000_S03252_W000150 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3512,
"duration": 6.418,
"id": "EN_B00000_S03252_W000150",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " That is, they're at right angles, or 90 degrees relative to each other. Sine 90 is 1.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000150.mp3"
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EN_B00000_S03252_W000151 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 6.859,
"id": "EN_B00000_S03252_W000151",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " So the monetic force will have its maximum value at this point. And it's equal to simply bqv.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000151.mp3"
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EN_B00000_S03252_W000152 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 3.888,
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"language": "en",
"speaker": "EN_B00000_S03252",
"text": " We have a proton, and it's moving towards the right.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000152.mp3"
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EN_B00000_S03252_W000153 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " And the magnetic force, or rather, the magnetic field, is directed north. What is the direction of the magnetic force?",
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EN_B00000_S03252_W000154 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " It has to be in the z direction. If the velocity is in the x direction, and if the magnetic field is in the y direction, the magnetic force has to be in the z direction. And yo... | EN_B00000_S03252_W000154.mp3 | [
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EN_B00000_S03252_W000155 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.0247,
"duration": 3.888,
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"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Think of velocity as the current, so to speak. That's where the charged particles are moving.",
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EN_B00000_S03252_W000156 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000157 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So if you orient your right hand this way, the 4 should come out of the palm of your right hand. And so, it should come out of the page.",
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EN_B00000_S03252_W000158 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000159 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " Simply reverse the direction of the magnetic force, if you need to find it.",
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EN_B00000_S03252_W000160 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " For a positively charged particle, it's gonna work in the exact same way as the right hand rule directs it. Number five.",
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EN_B00000_S03252_W000161 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " A proton moves east with a speed of 4 times 10 to the 6th meters per second.",
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EN_B00000_S03252_W000162 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " In the monadic field of 2 times 10 to the minus 4 Teslas, directed into the page.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000162.mp3"
} | EN_B00000_S03252_W000162.mp3 | [
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EN_B00000_S03252_W000163 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"duration": 3.158,
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"speaker": "EN_B00000_S03252",
"text": " What is the magnitude of the magnetic force acting on a proton?",
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EN_B00000_S03252_W000164 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000165 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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} | EN_B00000_S03252_W000165.mp3 | [
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EN_B00000_S03252_W000166 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000167 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000168 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000169 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000170 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " And the speed of the proton is 4 times 10 to the 6 meters per second.",
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EN_B00000_S03252_W000171 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"speaker": "EN_B00000_S03252",
"text": " So we just gotta multiply these tree numbers.",
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EN_B00000_S03252_W000172 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " So that's the magnetic force acting on the proton.",
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EN_B00000_S03252_W000173 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000174 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " Is directed everywhere into the page. So let's say there's an X everywhere.",
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EN_B00000_S03252_W000175 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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"text": " What's gonna happen? Where is the monadic force? So if you direct your thumb towards the right, and your four fingers into the page, the monadic force will be directed north."... | EN_B00000_S03252_W000175.mp3 | [
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EN_B00000_S03252_W000177 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000178 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000181 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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EN_B00000_S03252_W000182 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
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3308,
1162,
303,
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3531,
2934,
418,
3070,
472,
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2181,
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215... | [
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EN_B00000_S03252_W000186 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.1219,
"duration": 10.628,
"id": "EN_B00000_S03252_W000186",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Fc, the centripetal force. The centripetal force is provided by the magnetic force in this particular example.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000... | EN_B00000_S03252_W000186.mp3 | [
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EN_B00000_S03252_W000187 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.1871,
"duration": 8.964,
"id": "EN_B00000_S03252_W000187",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " The centripetal force is equal to MV squared divided by R, which is the radius of the circle. The magnetic force is equal to BQV. Now,",
"wav": "EN_B00000/EN_B00000_S03252/mp... | EN_B00000_S03252_W000187.mp3 | [
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EN_B00000_S03252_W000188 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3564,
"duration": 19.135,
"id": "EN_B00000_S03252_W000188",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Because the magnetic field and the velocity are perpendicular, we don't have to worry about the sine portion of this equation. Now what we're going to do is multiply both side... | EN_B00000_S03252_W000188.mp3 | [
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EN_B00000_S03252_W000189 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.2374,
"duration": 10.272,
"id": "EN_B00000_S03252_W000189",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " So mv divided by r is equal to bq. So multiplying both sides by r, we have this equation.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000189.mp3"
} | EN_B00000_S03252_W000189.mp3 | [
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EN_B00000_S03252_W000190 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3436,
"duration": 12.428,
"id": "EN_B00000_S03252_W000190",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " So make sure you, uh, write down this equation. mv is equal to bqr. Because in this format, you can solve for anything. So let's say if we want to find the radius of the circl... | EN_B00000_S03252_W000190.mp3 | [
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EN_B00000_S03252_W000191 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3565,
"duration": 3.276,
"id": "EN_B00000_S03252_W000191",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " All we need to do is divide both sides by bq.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000191.mp3"
} | EN_B00000_S03252_W000191.mp3 | [
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EN_B00000_S03252_W000192 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.2252,
"duration": 9.134,
"id": "EN_B00000_S03252_W000192",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " So the radius of the circle is equal to the mass of the charged particle times the velocity divided by the magnetic field times the charge.",
"wav": "EN_B00000/EN_B00000_S032... | EN_B00000_S03252_W000192.mp3 | [
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EN_B00000_S03252_W000193 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.245,
"duration": 3.871,
"id": "EN_B00000_S03252_W000193",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " Moves with a speed of 5 times 10 to the 6 meters per second.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000193.mp3"
} | EN_B00000_S03252_W000193.mp3 | [
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EN_B00000_S03252_W000194 | hf://datasets/amphion/Emilia-Dataset@bcaad00d13e7c101485990a46e88f5884ffed3fc/EN/EN-B000002.tar | {
"dnsmos": 3.3255,
"duration": 3.973,
"id": "EN_B00000_S03252_W000194",
"language": "en",
"speaker": "EN_B00000_S03252",
"text": " And if it's moving perpendicular to a magnetic field, it's gonna move in a circle.",
"wav": "EN_B00000/EN_B00000_S03252/mp3/EN_B00000_S03252_W000194.mp3"
} | EN_B00000_S03252_W000194.mp3 | [
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