task_id
stringclasses
164 values
prompt
stringlengths
97
1.92k
entry_point
stringclasses
281 values
canonical_solution
stringclasses
414 values
test
stringclasses
164 values
partial
stringclasses
127 values
HumanEval/24
def largestDivisor(n: int) -> int: """ For a given number n, find the largest number that divides n evenly, smaller than n >>> largestDivisor(15) 5 """
largestDivisor
for i in reversed(range(n)): if n % i == 0: return i
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3) == 1 assert candidate(7) == 1 assert candidate(10) == 5 assert candidate(100) == 50 assert candidate(49) == 7
null
HumanEval/25
from typing import List def factorize(n: int) -> List[int]: """ Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the produc...
factorize
import math fact = [] i = 2 while i <= int(math.sqrt(n) + 1): if n % i == 0: fact.append(i) n //= i else: i += 1 if n > 1: fact.append(n) return fact
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(2) == [2] assert candidate(4) == [2, 2] assert candidate(8) == [2, 2, 2] assert candidate(3 * 19) == [3, 19] assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19] assert candidate(3 * 19 * 3 * 19 * ...
null
HumanEval/26
from typing import List def removeDuplicates(numbers: List[int]) -> List[int]: """ From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input. >>> removeDuplicates([1, 2, 3, 2, 4]) [1, 3, 4] """
removeDuplicates
import collections c = collections.Counter(numbers) return [n for n in numbers if c[n] <= 1]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4] assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
null
HumanEval/27
def flipCase(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flipCase('Hello') 'hELLO' """
flipCase
return string.swapcase()
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('Hello!') == 'hELLO!' assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'
null
HumanEval/28
from typing import List def concatenate(strings: List[str]) -> str: """ Concatenate list of strings into a single string >>> concatenate([]) '' >>> concatenate(['a', 'b', 'c']) 'abc' """
concatenate
return ''.join(strings)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == '' assert candidate(['x', 'y', 'z']) == 'xyz' assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'
null
HumanEval/29
from typing import List def filterByPrefix(strings: List[str], prefix: str) -> List[str]: """ Filter an input list of strings only for ones that start with a given prefix. >>> filterByPrefix([], 'a') [] >>> filterByPrefix(['abc', 'bcd', 'cde', 'array'], 'a') ['abc', 'array'] """
filterByPrefix
return [x for x in strings if x.startswith(prefix)]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([], 'john') == [] assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
null
HumanEval/30
def getPositive(l: list): """Return only positive numbers in the list. >>> getPositive([-1, 2, -4, 5, 6]) [2, 5, 6] >>> getPositive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) [5, 3, 2, 3, 9, 123, 1] """
getPositive
return [e for e in l if e > 0]
METADATA = {} def check(candidate): assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6] assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1] assert candidate([-1, -2]) == [] assert candidate([]) == []
null
HumanEval/31
def isPrime(n): """Return true if a given number is prime, and false otherwise. >>> isPrime(6) False >>> isPrime(101) True >>> isPrime(11) True >>> isPrime(13441) True >>> isPrime(61) True >>> isPrime(4) False >>> isPrime(1) False """
isPrime
if n < 2: return False for k in range(2, n - 1): if n % k == 0: return False return True
METADATA = {} def check(candidate): assert candidate(6) == False assert candidate(101) == True assert candidate(11) == True assert candidate(13441) == True assert candidate(61) == True assert candidate(4) == False assert candidate(1) == False assert candidate(5) == True assert ca...
null
HumanEval/32
import math def poly(xs: list, x: float): """ Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n """ return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def findZero(xs: list): """ xs are coefficients of a polynomial...
findZero
begin, end = -1., 1. while poly(xs, begin) * poly(xs, end) > 0: begin *= 2.0 end *= 2.0 while end - begin > 1e-10: center = (begin + end) / 2.0 if poly(xs, center) * poly(xs, begin) > 0: begin = center else: end = center return begin
METADATA = {} def check(candidate): import math import random rng = random.Random(42) import copy for _ in range(100): ncoeff = 2 * rng.randint(1, 4) coeffs = [] for _ in range(ncoeff): coeff = rng.randint(-10, 10) if coeff == 0: co...
null
HumanEval/33
def sortThird(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted. >>> sortThi...
sortThird
l = list(l) l[::3] = sorted(l[::3]) return l
METADATA = {} def check(candidate): assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3])) assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(so...
null
HumanEval/34
def unique(l: list): """Return sorted unique elements in a list >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123]) [0, 2, 3, 5, 9, 123] """
unique
return sorted(list(set(l)))
METADATA = {} def check(candidate): assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
null
HumanEval/35
def maxElement(l: list): """Return maximum element in the list. >>> maxElement([1, 2, 3]) 3 >>> maxElement([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) 123 """
maxElement
m = l[0] for e in l: if e > m: m = e return m
METADATA = {} def check(candidate): assert candidate([1, 2, 3]) == 3 assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124
null
HumanEval/36
def fizzBuzz(n: int): """Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13. >>> fizzBuzz(50) 0 >>> fizzBuzz(78) 2 >>> fizzBuzz(79) 3 """
fizzBuzz
ns = [] for i in range(n): if i % 11 == 0 or i % 13 == 0: ns.append(i) s = ''.join(list(map(str, ns))) ans = 0 for c in s: ans += (c == '7') return ans
METADATA = {} def check(candidate): assert candidate(50) == 0 assert candidate(78) == 2 assert candidate(79) == 3 assert candidate(100) == 3 assert candidate(200) == 6 assert candidate(4000) == 192 assert candidate(10000) == 639 assert candidate(100000) == 8026
null
HumanEval/37
def sortEven(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted. >>> sortEven([1, 2, 3]) [1, 2, 3] >>> sortEven([5, 6, 3, 4]) ...
sortEven
evens = l[::2] odds = l[1::2] evens.sort() ans = [] for e, o in zip(evens, odds): ans.extend([e, o]) if len(evens) > len(odds): ans.append(evens[-1]) return ans
METADATA = {} def check(candidate): assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3]) assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123]) assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 1...
null
HumanEval/38
def encode_cyclic(s: str): """ returns encoded string by cycling groups of three characters. """ # split string to groups. Each of length 3. groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)] # cycle elements in each group. Unless group has fewer elements than 3. ...
decodeCyclic
return encode_cyclic(encode_cyclic(s))
METADATA = {} def check(candidate): from random import randint, choice import string letters = string.ascii_lowercase for _ in range(100): str = ''.join(choice(letters) for i in range(randint(10, 20))) encoded_str = encode_cyclic(str) assert candidate(encoded_str) == str
null
HumanEval/39
def primeFib(n: int): """ primeFib returns n-th number that is a Fibonacci number and it's also prime. >>> primeFib(1) 2 >>> primeFib(2) 3 >>> primeFib(3) 5 >>> primeFib(4) 13 >>> primeFib(5) 89 """
primeFib
import math def is_prime(p): if p < 2: return False for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)): if p % k == 0: return False return True f = [0, 1] while True: f.append(f[-1] + f[-2]) if is_prime(f[-1]): ...
METADATA = {} def check(candidate): assert candidate(1) == 2 assert candidate(2) == 3 assert candidate(3) == 5 assert candidate(4) == 13 assert candidate(5) == 89 assert candidate(6) == 233 assert candidate(7) == 1597 assert candidate(8) == 28657 assert candidate(9) == 514229 ...
null
HumanEval/40
def triplesSumToZero(l: list): """ triplesSumToZero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise. >>> triplesSumToZero([1, 3, 5, 0]) False >>> triplesSumToZero([1, 3, -2, 1]) True >>> t...
triplesSumToZero
for i in range(len(l)): for j in range(i + 1, len(l)): for k in range(j + 1, len(l)): if l[i] + l[j] + l[k] == 0: return True return False
METADATA = {} def check(candidate): assert candidate([1, 3, 5, 0]) == False assert candidate([1, 3, 5, -1]) == False assert candidate([1, 3, -2, 1]) == True assert candidate([1, 2, 3, 7]) == False assert candidate([1, 2, 5, 7]) == False assert candidate([2, 4, -5, 3, 9, 7]) == True asser...
null
HumanEval/41
def carRaceCollision(n: int): """ Imagine a road that's a perfectly straight infinitely long line. n cars are driving left to right; simultaneously, a different set of n cars are driving right to left. The two sets of cars start out being very far from each other. All cars move in the same spe...
carRaceCollision
return n**2
METADATA = {} def check(candidate): assert candidate(2) == 4 assert candidate(3) == 9 assert candidate(4) == 16 assert candidate(8) == 64 assert candidate(10) == 100
null
HumanEval/42
def incrList(l: list): """Return list with elements incremented by 1. >>> incrList([1, 2, 3]) [2, 3, 4] >>> incrList([5, 3, 5, 2, 3, 3, 9, 0, 123]) [6, 4, 6, 3, 4, 4, 10, 1, 124] """
incrList
return [(e + 1) for e in l]
METADATA = {} def check(candidate): assert candidate([]) == [] assert candidate([3, 2, 1]) == [4, 3, 2] assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]
null
HumanEval/43
def pairsSumToZero(l): """ pairsSumToZero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise. >>> pairsSumToZero([1, 3, 5, 0]) False >>> pairsSumToZero([1, 3, -2, 1]) False >>> pairsSumToZero([1...
pairsSumToZero
for i, l1 in enumerate(l): for j in range(i + 1, len(l)): if l1 + l[j] == 0: return True return False
METADATA = {} def check(candidate): assert candidate([1, 3, 5, 0]) == False assert candidate([1, 3, -2, 1]) == False assert candidate([1, 2, 3, 7]) == False assert candidate([2, 4, -5, 3, 5, 7]) == True assert candidate([1]) == False assert candidate([-3, 9, -1, 3, 2, 30]) == True asser...
null
HumanEval/44
def changeBase(x: int, base: int): """Change numerical base of input number x to base. return string representation after the conversion. base numbers are less than 10. >>> changeBase(8, 3) '22' >>> changeBase(8, 2) '1000' >>> changeBase(7, 2) '111' """
changeBase
ret = "" while x > 0: ret = str(x % base) + ret x //= base return ret
METADATA = {} def check(candidate): assert candidate(8, 3) == "22" assert candidate(9, 3) == "100" assert candidate(234, 2) == "11101010" assert candidate(16, 2) == "10000" assert candidate(8, 2) == "1000" assert candidate(7, 2) == "111" for x in range(2, 8): assert candidate(x, ...
null
HumanEval/45
def triangleArea(a, h): """Given length of a side and high return area for a triangle. >>> triangleArea(5, 3) 7.5 """
triangleArea
return a * h / 2.0
METADATA = {} def check(candidate): assert candidate(5, 3) == 7.5 assert candidate(2, 2) == 2.0 assert candidate(10, 8) == 40.0
null
HumanEval/46
def fib4(n: int): """The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fib4(0) -> 0 fib4(1) -> 0 fib4(2) -> 2 fib4(3) -> 0 fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). Please write a function to efficiently compute the n-th el...
fib4
results = [0, 0, 2, 0] if n < 4: return results[n] for _ in range(4, n + 1): results.append(results[-1] + results[-2] + results[-3] + results[-4]) results.pop(0) return results[-1]
METADATA = {} def check(candidate): assert candidate(5) == 4 assert candidate(8) == 28 assert candidate(10) == 104 assert candidate(12) == 386
null
HumanEval/47
def median(l: list): """Return median of elements in the list l. >>> median([3, 1, 2, 4, 5]) 3 >>> median([-10, 4, 6, 1000, 10, 20]) 15.0 """
median
l = sorted(l) if len(l) % 2 == 1: return l[len(l) // 2] else: return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0
METADATA = {} def check(candidate): assert candidate([3, 1, 2, 4, 5]) == 3 assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0 assert candidate([5]) == 5 assert candidate([6, 5]) == 5.5 assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7
null
HumanEval/48
def isPalindrome(text: str): """ Checks if given string is a palindrome >>> isPalindrome('') True >>> isPalindrome('aba') True >>> isPalindrome('aaaaa') True >>> isPalindrome('zbcd') False """
isPalindrome
for i in range(len(text)): if text[i] != text[len(text) - 1 - i]: return False return True
METADATA = {} def check(candidate): assert candidate('') == True assert candidate('aba') == True assert candidate('aaaaa') == True assert candidate('zbcd') == False assert candidate('xywyx') == True assert candidate('xywyz') == False assert candidate('xywzx') == False
null
HumanEval/49
def modp(n: int, p: int): """Return 2^n modulo p (be aware of numerics). >>> modp(3, 5) 3 >>> modp(1101, 101) 2 >>> modp(0, 101) 1 >>> modp(3, 11) 8 >>> modp(100, 101) 1 """
modp
ret = 1 for i in range(n): ret = (2 * ret) % p return ret
METADATA = {} def check(candidate): assert candidate(3, 5) == 3 assert candidate(1101, 101) == 2 assert candidate(0, 101) == 1 assert candidate(3, 11) == 8 assert candidate(100, 101) == 1 assert candidate(30, 5) == 4 assert candidate(31, 5) == 3
null
HumanEval/50
def encode_shift(s: str): """ returns encoded string by shifting every character by 5 in the alphabet. """ return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s]) def decodeShift(s: str): """ takes as input string encoded with encode_shift function. Returns decoded stri...
decodeShift
return "".join([chr(((ord(ch) - 5 - ord("a")) % 26) + ord("a")) for ch in s])
METADATA = {} def check(candidate): from random import randint, choice import copy import string letters = string.ascii_lowercase for _ in range(100): str = ''.join(choice(letters) for i in range(randint(10, 20))) encoded_str = encode_shift(str) assert candidate(copy.dee...
null
HumanEval/51
def removeVowels(text): """ removeVowels is a function that takes string and returns string without vowels. >>> removeVowels('') '' >>> removeVowels("abcdef\nghijklm") 'bcdf\nghjklm' >>> removeVowels('abcdef') 'bcdf' >>> removeVowels('aaaaa') '' >>> removeVowels('aaBAA') ...
removeVowels
return "".join([s for s in text if s.lower() not in ["a", "e", "i", "o", "u"]])
METADATA = {} def check(candidate): assert candidate('') == '' assert candidate("abcdef\nghijklm") == 'bcdf\nghjklm' assert candidate('fedcba') == 'fdcb' assert candidate('eeeee') == '' assert candidate('acBAA') == 'cB' assert candidate('EcBOO') == 'cB' assert candidate('ybcd') == 'ybcd'...
null
HumanEval/52
def belowThreshold(l: list, t: int): """Return True if all numbers in the list l are below threshold t. >>> belowThreshold([1, 2, 4, 10], 100) True >>> belowThreshold([1, 20, 4, 10], 5) False """
belowThreshold
for e in l: if e >= t: return False return True
METADATA = {} def check(candidate): assert candidate([1, 2, 4, 10], 100) assert not candidate([1, 20, 4, 10], 5) assert candidate([1, 20, 4, 10], 21) assert candidate([1, 20, 4, 10], 22) assert candidate([1, 8, 4, 10], 11) assert not candidate([1, 8, 4, 10], 10)
null
HumanEval/53
def add(x: int, y: int): """Add two numbers x and y >>> add(2, 3) 5 >>> add(5, 7) 12 """
add
return x + y
METADATA = {} def check(candidate): import random assert candidate(0, 1) == 1 assert candidate(1, 0) == 1 assert candidate(2, 3) == 5 assert candidate(5, 7) == 12 assert candidate(7, 5) == 12 for i in range(100): x, y = random.randint(0, 1000), random.randint(0, 1000) a...
null
HumanEval/54
def sameChars(s0: str, s1: str): """ Check if two words have the same characters. >>> sameChars('eabcdzzzz', 'dddzzzzzzzddeddabc') True >>> sameChars('abcd', 'dddddddabc') True >>> sameChars('dddddddabc', 'abcd') True >>> sameChars('eabcd', 'dddddddabc') False >>> sameChars...
sameChars
return set(s0) == set(s1)
METADATA = {} def check(candidate): assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True assert candidate('abcd', 'dddddddabc') == True assert candidate('dddddddabc', 'abcd') == True assert candidate('eabcd', 'dddddddabc') == False assert candidate('abcd', 'dddddddabcf') == False asse...
null
HumanEval/55
def fib(n: int): """Return n-th Fibonacci number. >>> fib(10) 55 >>> fib(1) 1 >>> fib(8) 21 """
fib
if n == 0: return 0 if n == 1: return 1 return fib(n - 1) + fib(n - 2)
METADATA = {} def check(candidate): assert candidate(10) == 55 assert candidate(1) == 1 assert candidate(8) == 21 assert candidate(11) == 89 assert candidate(12) == 144
null
HumanEval/56
def correctBracketing(brackets: str): """ brackets is a string of "<" and ">". return True if every opening bracket has a corresponding closing bracket. >>> correctBracketing("<") False >>> correctBracketing("<>") True >>> correctBracketing("<<><>>") True >>> correctBracketing("><...
correctBracketing
depth = 0 for b in brackets: if b == "<": depth += 1 else: depth -= 1 if depth < 0: return False return depth == 0
METADATA = {} def check(candidate): assert candidate("<>") assert candidate("<<><>>") assert candidate("<><><<><>><>") assert candidate("<><><<<><><>><>><<><><<>>>") assert not candidate("<<<><>>>>") assert not candidate("><<>") assert not candidate("<") assert not candidate("<<<<") ...
null
HumanEval/57
def monotonic(l: list): """Return True is list elements are monotonically increasing or decreasing. >>> monotonic([1, 2, 4, 20]) True >>> monotonic([1, 20, 4, 10]) False >>> monotonic([4, 1, 0, -10]) True """
monotonic
if l == sorted(l) or l == sorted(l, reverse=True): return True return False
METADATA = {} def check(candidate): assert candidate([1, 2, 4, 10]) == True assert candidate([1, 2, 4, 20]) == True assert candidate([1, 20, 4, 10]) == False assert candidate([4, 1, 0, -10]) == True assert candidate([4, 1, 1, 0]) == True assert candidate([1, 2, 3, 2, 5, 60]) == False ass...
null
HumanEval/58
def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """
common
ret = set() for e1 in l1: for e2 in l2: if e1 == e2: ret.add(e1) return sorted(list(ret))
METADATA = {} def check(candidate): assert candidate([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653] assert candidate([5, 3, 2, 8], [3, 2]) == [2, 3] assert candidate([4, 3, 2, 8], [3, 2, 4]) == [2, 3, 4] assert candidate([4, 3, 2, 8], []) == []
null
HumanEval/59
def largestPrimeFactor(n: int): """Return the largest prime factor of n. Assume n > 1 and is not a prime. >>> largestPrimeFactor(13195) 29 >>> largestPrimeFactor(2048) 2 """
largestPrimeFactor
def is_prime(k): if k < 2: return False for i in range(2, k - 1): if k % i == 0: return False return True largest = 1 for j in range(2, n + 1): if n % j == 0 and is_prime(j): largest = max(largest, j) return largest
METADATA = {} def check(candidate): assert candidate(15) == 5 assert candidate(27) == 3 assert candidate(63) == 7 assert candidate(330) == 11 assert candidate(13195) == 29
null
HumanEval/60
def sumToN(n: int): """sumToN is a function that sums numbers from 1 to n. >>> sumToN(30) 465 >>> sumToN(100) 5050 >>> sumToN(5) 15 >>> sumToN(10) 55 >>> sumToN(1) 1 """
sumToN
return sum(range(n + 1))
METADATA = {} def check(candidate): assert candidate(1) == 1 assert candidate(6) == 21 assert candidate(11) == 66 assert candidate(30) == 465 assert candidate(100) == 5050
null
HumanEval/61
def correctBracketing(brackets: str): """ brackets is a string of "(" and ")". return True if every opening bracket has a corresponding closing bracket. >>> correctBracketing("(") False >>> correctBracketing("()") True >>> correctBracketing("(()())") True >>> correctBracketing(")(...
correctBracketing
depth = 0 for b in brackets: if b == "(": depth += 1 else: depth -= 1 if depth < 0: return False return depth == 0
METADATA = {} def check(candidate): assert candidate("()") assert candidate("(()())") assert candidate("()()(()())()") assert candidate("()()((()()())())(()()(()))") assert not candidate("((()())))") assert not candidate(")(()") assert not candidate("(") assert not candidate("((((") ...
null
HumanEval/62
def derivative(xs: list): """ xs represent coefficients of a polynomial. xs[0] + xs[1] * x + xs[2] * x^2 + .... Return derivative of this polynomial in the same form. >>> derivative([3, 1, 2, 4, 5]) [1, 4, 12, 20] >>> derivative([1, 2, 3]) [2, 6] """
derivative
return [(i * x) for i, x in enumerate(xs)][1:]
METADATA = {} def check(candidate): assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20] assert candidate([1, 2, 3]) == [2, 6] assert candidate([3, 2, 1]) == [2, 2] assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16] assert candidate([1]) == []
null
HumanEval/63
def fibfib(n: int): """The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fibfib(0) == 0 fibfib(1) == 0 fibfib(2) == 1 fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3). Please write a function to efficiently compute the n-th element of th...
fibfib
if n == 0: return 0 if n == 1: return 0 if n == 2: return 1 return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)
METADATA = {} def check(candidate): assert candidate(2) == 1 assert candidate(1) == 0 assert candidate(5) == 4 assert candidate(8) == 24 assert candidate(10) == 81 assert candidate(12) == 274 assert candidate(14) == 927
null
HumanEval/64
FIX = """ Add more test cases. """ def vowelsCount(s): """Write a function vowelsCount which takes a string representing a word as input and returns the number of vowels in the string. Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the giv...
vowelsCount
vowels = "aeiouAEIOU" n_vowels = sum(c in vowels for c in s) if s[-1] == 'y' or s[-1] == 'Y': n_vowels += 1 return n_vowels
def check(candidate): # Check some simple cases assert candidate("abcde") == 2, "Test 1" assert candidate("Alone") == 3, "Test 2" assert candidate("key") == 2, "Test 3" assert candidate("bye") == 1, "Test 4" assert candidate("keY") == 2, "Test 5" assert candidate("bYe") == 1, "Test 6" a...
null
HumanEval/65
def circularShift(x, shift): """Circular shift the digits of the integer x, shift the digits right by shift and return the result as a string. If shift > number of digits, return digits reversed. >>> circularShift(12, 1) "21" >>> circularShift(12, 2) "12" """
circularShift
s = str(x) if shift > len(s): return s[::-1] else: return s[len(s) - shift:] + s[:len(s) - shift]
def check(candidate): # Check some simple cases assert candidate(100, 2) == "001" assert candidate(12, 2) == "12" assert candidate(97, 8) == "79" assert candidate(12, 1) == "21", "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by han...
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HumanEval/66
def digit_sum(s): """Task Write a function that takes a string as input and returns the sum of the upper characters only' ASCII codes. Examples: digit_sum("") => 0 digit_sum("abAB") => 131 digit_sum("abcCd") => 67 digit_sum("helloE") => 69 digit_sum("woArBld") =...
digit_sum
if s == "": return 0 return sum(ord(char) if char.isupper() else 0 for char in s)
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate("") == 0, "Error" assert candidate("abAB") == 131, "Error" assert candidate("abcCd") == 67, "Error" assert candidate("helloE") == 69, "Error" assert candi...
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HumanEval/67
def fruitDistribution(s,n): """ In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the oranges and apples an...
fruitDistribution
lis = list() for i in s.split(' '): if i.isdigit(): lis.append(int(i)) return n - sum(lis)
def check(candidate): # Check some simple cases assert candidate("5 apples and 6 oranges",19) == 8 assert candidate("5 apples and 6 oranges",21) == 10 assert candidate("0 apples and 1 oranges",3) == 2 assert candidate("1 apples and 0 oranges",3) == 2 assert candidate("2 apples and 3 oranges",10...
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HumanEval/68
def pluck(arr): """ "Given an array representing a branch of a tree that has non-negative integer nodes your task is to pluck one of the nodes and return it. The plucked node should be the node with the smallest even value. If multiple nodes with the same smallest even value are found return the no...
pluck
if(len(arr) == 0): return [] evens = list(filter(lambda x: x%2 == 0, arr)) if(evens == []): return [] return [min(evens), arr.index(min(evens))]
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([4,2,3]) == [2, 1], "Error" assert candidate([1,2,3]) == [2, 1], "Error" assert candidate([]) == [], "Error" assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], "...
null
HumanEval/69
def search(lst): ''' You are given a non-empty list of positive integers. Return the greatest integer that is greater than zero, and has a frequency greater than or equal to the value of the integer itself. The frequency of an integer is the number of times it appears in the list. If no such a va...
search
frq = [0] * (max(lst) + 1) for i in lst: frq[i] += 1; ans = -1 for i in range(1, len(frq)): if frq[i] >= i: ans = i return ans
def check(candidate): # manually generated tests assert candidate([5, 5, 5, 5, 1]) == 1 assert candidate([4, 1, 4, 1, 4, 4]) == 4 assert candidate([3, 3]) == -1 assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8 assert candidate([2, 3, 3, 2, 2]) == 2 # automatically generated tests assert...
null
HumanEval/70
def strangeSortList(lst): ''' Given list of integers, return list in strange order. Strange sorting, is when you start with the minimum value, then maximum of the remaining integers, then minimum and so on. Examples: strangeSortList([1, 2, 3, 4]) == [1, 4, 2, 3] strangeSortList([5, 5, 5, 5...
strangeSortList
res, switch = [], True while lst: res.append(min(lst) if switch else max(lst)) lst.remove(res[-1]) switch = not switch return res
def check(candidate): # Check some simple cases assert candidate([1, 2, 3, 4]) == [1, 4, 2, 3] assert candidate([5, 6, 7, 8, 9]) == [5, 9, 6, 8, 7] assert candidate([1, 2, 3, 4, 5]) == [1, 5, 2, 4, 3] assert candidate([5, 6, 7, 8, 9, 1]) == [1, 9, 5, 8, 6, 7] assert candidate([5, 5, 5, 5]) == [...
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HumanEval/71
def triangleArea(a, b, c): ''' Given the lengths of the three sides of a triangle. Return the area of the triangle rounded to 2 decimal points if the three sides form a valid triangle. Otherwise return -1 Three sides make a valid triangle when the sum of any two sides is greater than the thir...
triangleArea
if a + b <= c or a + c <= b or b + c <= a: return -1 s = (a + b + c)/2 area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 area = round(area, 2) return area
def check(candidate): # Check some simple cases assert candidate(3, 4, 5) == 6.00, "This prints if this assert fails 1 (good for debugging!)" assert candidate(1, 2, 10) == -1 assert candidate(4, 8, 5) == 8.18 assert candidate(2, 2, 2) == 1.73 assert candidate(1, 2, 3) == -1 assert candidate...
null
HumanEval/72
def willItFly(q,w): ''' Write a function that returns True if the object q will fly, and False otherwise. The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w. Example: willItFly([1, 2], 5) ➞ False # ...
willItFly
if sum(q) > w: return False i, j = 0, len(q)-1 while i<j: if q[i] != q[j]: return False i+=1 j-=1 return True
def check(candidate): # Check some simple cases assert candidate([3, 2, 3], 9) is True assert candidate([1, 2], 5) is False assert candidate([3], 5) is True assert candidate([3, 2, 3], 1) is False # Check some edge cases that are easy to work out by hand. assert candidate([1, 2, 3], 6) is...
null
HumanEval/73
def smallestChange(arr): """ Given an array arr of integers, find the minimum number of elements that need to be changed to make the array palindromic. A palindromic array is an array that is read the same backwards and forwards. In one change, you can change one element to any other element. For ...
smallestChange
ans = 0 for i in range(len(arr) // 2): if arr[i] != arr[len(arr) - i - 1]: ans += 1 return ans
def check(candidate): # Check some simple cases assert candidate([1,2,3,5,4,7,9,6]) == 4 assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1 assert candidate([1, 4, 2]) == 1 assert candidate([1, 4, 4, 2]) == 1 # Check some edge cases that are easy to work out by hand. assert candidate([1, 2, 3, 2...
null
HumanEval/74
def totalMatch(lst1, lst2): ''' Write a function that accepts two lists of strings and returns the list that has total number of chars in the all strings of the list less than the other list. if the two lists have the same number of chars, return the first list. Examples totalMatch([], []) ➞...
totalMatch
l1 = 0 for st in lst1: l1 += len(st) l2 = 0 for st in lst2: l2 += len(st) if l1 <= l2: return lst1 else: return lst2
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([], []) == [] assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi'] assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin...
null
HumanEval/75
def isMultiplyPrime(a): """Write a function that returns true if the given number is the multiplication of 3 prime numbers and false otherwise. Knowing that (a) is less then 100. Example: isMultiplyPrime(30) == True 30 = 2 * 3 * 5 """
isMultiplyPrime
def is_prime(n): for j in range(2,n): if n%j == 0: return False return True for i in range(2,101): if not is_prime(i): continue for j in range(2,101): if not is_prime(j): continue for k in range(2,101): if not i...
def check(candidate): assert candidate(5) == False assert candidate(30) == True assert candidate(8) == True assert candidate(10) == False assert candidate(125) == True assert candidate(3 * 5 * 7) == True assert candidate(3 * 6 * 7) == False assert candidate(9 * 9 * 9) == False asser...
null
HumanEval/76
def isSimplePower(x, n): """Your task is to write a function that returns true if a number x is a simple power of n and false in other cases. x is a simple power of n if n**int=x For example: isSimplePower(1, 4) => true isSimplePower(2, 2) => true isSimplePower(8, 2) => true isSimplePow...
isSimplePower
if (n == 1): return (x == 1) power = 1 while (power < x): power = power * n return (power == x)
def check(candidate): # Check some simple cases assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)" assert candidate(4, 2)==True, "This prints if this assert fails 1 (...
null
HumanEval/77
def iscube(a): ''' Write a function that takes an integer a and returns True if this ingeger is a cube of some integer number. Note: you may assume the input is always valid. Examples: iscube(1) ==> True iscube(2) ==> False iscube(-1) ==> True iscube(64) ==> True iscube(0) ==> ...
iscube
a = abs(a) return int(round(a ** (1. / 3))) ** 3 == a
def check(candidate): # Check some simple cases assert candidate(1) == True, "First test error: " + str(candidate(1)) assert candidate(2) == False, "Second test error: " + str(candidate(2)) assert candidate(-1) == True, "Third test error: " + str(candidate(-1)) assert candidate(64) == True, "Fourth...
null
HumanEval/78
def hexKey(num): """You have been tasked to write a function that receives a hexadecimal number as a string and counts the number of hexadecimal digits that are primes (prime number, or a prime, is a natural number greater than 1 that is not a product of two smaller natural numbers). Hexadecimal...
hexKey
primes = ('2', '3', '5', '7', 'B', 'D') total = 0 for i in range(0, len(num)): if num[i] in primes: total += 1 return total
def check(candidate): # Check some simple cases assert candidate("AB") == 1, "First test error: " + str(candidate("AB")) assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E")) assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33")) ...
null
HumanEval/79
def decimalToBinary(decimal): """You will be given a number in decimal form and your task is to convert it to binary format. The function should return a string, with each character representing a binary number. Each character in the string will be '0' or '1'. There will be an extra couple of characte...
decimalToBinary
return "db" + bin(decimal)[2:] + "db"
def check(candidate): # Check some simple cases assert candidate(0) == "db0db" assert candidate(32) == "db100000db" assert candidate(103) == "db1100111db" assert candidate(15) == "db1111db", "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to wor...
null
HumanEval/80
def isHappy(s): """You are given a string s. Your task is to check if the string is happy or not. A string is happy if its length is at least 3 and every 3 consecutive letters are distinct For example: isHappy(a) => False isHappy(aa) => False isHappy(abcd) => True isHappy(aabb) => False...
isHappy
if len(s) < 3: return False for i in range(len(s) - 2): if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]: return False return True
def check(candidate): # Check some simple cases assert candidate("a") == False , "a" assert candidate("aa") == False , "aa" assert candidate("abcd") == True , "abcd" assert candidate("aabb") == False , "aabb" assert candidate("adb") == True , "adb" assert candidate("xyy") == False , "xyy" ...
null
HumanEval/81
def numericalLetterGrade(grades): """It is the last week of the semester and the teacher has to give the grades to students. The teacher has been making her own algorithm for grading. The only problem is, she has lost the code she used for grading. She has given you a list of GPAs for some students and...
numericalLetterGrade
letter_grade = [] for gpa in grades: if gpa == 4.0: letter_grade.append("A+") elif gpa > 3.7: letter_grade.append("A") elif gpa > 3.3: letter_grade.append("A-") elif gpa > 3.0: letter_grade.append("B+") elif gpa > 2.7: ...
def check(candidate): # Check some simple cases assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-'] assert candidate([1.2]) == ['D+'] assert candidate([0.5]) == ['D-'] assert candidate([0.0]) == ['E'] assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+'] ...
null
HumanEval/82
def primeLength(string): """Write a function that takes a string and returns True if the string length is a prime number or False otherwise Examples primeLength('Hello') == True primeLength('abcdcba') == True primeLength('kittens') == True primeLength('orange') == False """
primeLength
l = len(string) if l == 0 or l == 1: return False for i in range(2, l): if l % i == 0: return False return True
def check(candidate): # Check some simple cases assert candidate('Hello') == True assert candidate('abcdcba') == True assert candidate('kittens') == True assert candidate('orange') == False assert candidate('wow') == True assert candidate('world') == True assert candidate('MadaM') == Tr...
null
HumanEval/83
def startsOneEnds(n): """ Given a positive integer n, return the count of the numbers of n-digit positive integers that start or end with 1. """
startsOneEnds
if n == 1: return 1 return 18 * (10 ** (n - 2))
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(1) == 1 assert candidate(2) == 18 assert candidate(3) == 180 assert candidate(4) == 1800 assert candidate(5) == 18000 # Check some edge cases that ar...
null
HumanEval/84
def solve(N): """Given a positive integer N, return the total sum of its digits in binary. Example For N = 1000, the sum of digits will be 1 the output should be "1". For N = 150, the sum of digits will be 6 the output should be "110". For N = 147, the sum of digits will be 12 the ...
solve
return bin(sum(int(i) for i in str(N)))[2:]
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(1000) == "1", "Error" assert candidate(150) == "110", "Error" assert candidate(147) == "1100", "Error" # Check some edge cases that are easy to work out by h...
null
HumanEval/85
def add(lst): """Given a non-empty list of integers lst. add the even elements that are at odd indices.. Examples: add([4, 2, 6, 7]) ==> 2 """
add
return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])
def check(candidate): # Check some simple cases assert candidate([4, 88]) == 88 assert candidate([4, 5, 6, 7, 2, 122]) == 122 assert candidate([4, 0, 6, 7]) == 0 assert candidate([4, 4, 6, 8]) == 12 # Check some edge cases that are easy to work out by hand.
null
HumanEval/86
def antiShuffle(s): """ Write a function that takes a string and returns an ordered version of it. Ordered version of string, is a string where all words (separated by space) are replaced by a new word where all the characters arranged in ascending order based on ascii value. Note: You should k...
antiShuffle
return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])
def check(candidate): # Check some simple cases assert candidate('Hi') == 'Hi' assert candidate('hello') == 'ehllo' assert candidate('number') == 'bemnru' assert candidate('abcd') == 'abcd' assert candidate('Hello World!!!') == 'Hello !!!Wdlor' assert candidate('') == '' assert candidat...
null
HumanEval/87
def getRow(lst, x): """ You are given a 2 dimensional data, as a nested lists, which is similar to matrix, however, unlike matrices, each row may contain a different number of columns. Given lst, and integer x, find integers x in the list, and return list of tuples, [(x1, y1), (x2, y2) ...] suc...
getRow
coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x] return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])
def check(candidate): # Check some simple cases assert candidate([ [1,2,3,4,5,6], [1,2,3,4,1,6], [1,2,3,4,5,1] ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)] assert candidate([ [1,2,3,4,5,6], [1,2,3,4,5,6], [1,2,3,4,5,6], [1,2,3,4,5,6], ...
null
HumanEval/88
def sortArray(array): """ Given an array of non-negative integers, return a copy of the given array after sorting, you will sort the given array in ascending order if the sum( first index value, last index value) is odd, or sort it in descending order if the sum( first index value, last index value) is...
sortArray
return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0)
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([]) == [], "Error" assert candidate([5]) == [5], "Error" assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], "Error" assert candidate([2, 4, 3, 0, 1, ...
null
HumanEval/89
def encrypt(s): """Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places. For example: encrypt('hi') returns 'lm' ...
encrypt
d = 'abcdefghijklmnopqrstuvwxyz' out = '' for c in s: if c in d: out += d[(d.index(c)+2*2) % 26] else: out += c return out
def check(candidate): # Check some simple cases assert candidate('hi') == 'lm', "This prints if this assert fails 1 (good for debugging!)" assert candidate('asdfghjkl') == 'ewhjklnop', "This prints if this assert fails 1 (good for debugging!)" assert candidate('gf') == 'kj', "This prints if this assert...
null
HumanEval/90
def nextSmallest(lst): """ You are given a list of integers. Write a function nextSmallest() that returns the 2nd smallest element of the list. Return None if there is no such element. nextSmallest([1, 2, 3, 4, 5]) == 2 nextSmallest([5, 1, 4, 3, 2]) == 2 nextSmallest([]) == None ne...
nextSmallest
lst = sorted(set(lst)) return None if len(lst) < 2 else lst[1]
def check(candidate): # Check some simple cases assert candidate([1, 2, 3, 4, 5]) == 2 assert candidate([5, 1, 4, 3, 2]) == 2 assert candidate([]) == None assert candidate([1, 1]) == None assert candidate([1,1,1,1,0]) == 1 assert candidate([1, 0**0]) == None assert candidate([-35, 34, 1...
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HumanEval/91
def isBored(S): """ You'll be given a string of words, and your task is to count the number of boredoms. A boredom is a sentence that starts with the word "I". Sentences are delimited by '.', '?' or '!'. For example: >>> isBored("Hello world") 0 >>> isBored("The sky is blue. The sun...
isBored
import re sentences = re.split(r'[.?!]\s*', S) return sum(sentence[0:2] == 'I ' for sentence in sentences)
def check(candidate): # Check some simple cases assert candidate("Hello world") == 0, "Test 1" assert candidate("Is the sky blue?") == 0, "Test 2" assert candidate("I love It !") == 1, "Test 3" assert candidate("bIt") == 0, "Test 4" assert candidate("I feel good today. I will be productive. wil...
null
HumanEval/92
def anyInt(x, y, z): ''' Create a function that takes 3 numbers. Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers. Returns false in any other cases. Examples anyInt(5, 2, 7) ➞ True anyInt(3, 2, 2) ➞ False anyInt(3, -2, 1) ➞...
anyInt
if isinstance(x,int) and isinstance(y,int) and isinstance(z,int): if (x+y==z) or (x+z==y) or (y+z==x): return True return False return False
def check(candidate): # Check some simple cases assert candidate(2, 3, 1)==True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(2.5, 2, 3)==False, "This prints if this assert fails 2 (good for debugging!)" assert candidate(1.5, 5, 3.5)==False, "This prints if this assert fa...
null
HumanEval/93
def encode(message): """ Write a function that takes a message, and encodes in such a way that it swaps case of all letters, replaces all vowels in the message with the letter that appears 2 places ahead of that vowel in the english alphabet. Assume only letters. Examples: >>>...
encode
vowels = "aeiouAEIOU" vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels]) message = message.swapcase() return ''.join([vowels_replace[i] if i in vowels else i for i in message])
def check(candidate): # Check some simple cases assert candidate('TEST') == 'tgst', "This prints if this assert fails 1 (good for debugging!)" assert candidate('Mudasir') == 'mWDCSKR', "This prints if this assert fails 2 (good for debugging!)" assert candidate('YES') == 'ygs', "This prints if this asse...
null
HumanEval/94
def skjkasdkd(lst): """You are given a list of integers. You need to find the largest prime value and return the sum of its digits. Examples: For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10 For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output shoul...
skjkasdkd
def isPrime(n): for i in range(2,int(n**0.5)+1): if n%i==0: return False return True maxx = 0 i = 0 while i < len(lst): if(lst[i] > maxx and isPrime(lst[i])): maxx = lst[i] i+=1 result = sum(int(digit) for digit in str(maxx)) ...
def check(candidate): # Check some simple cases assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]...
null
HumanEval/95
def checkDictCase(dict): """ Given a dictionary, return True if all keys are strings in lower case or all keys are strings in upper case, else return False. The function should return False is the given dictionary is empty. Examples: checkDictCase({"a":"apple", "b":"banana"}) should return Tru...
checkDictCase
if len(dict.keys()) == 0: return False else: state = "start" for key in dict.keys(): if isinstance(key, str) == False: state = "mixed" break if state == "start": if key.isupper(): state = "upper"...
def check(candidate): # Check some simple cases assert candidate({"p":"pineapple", "b":"banana"}) == True, "First test error: " + str(candidate({"p":"pineapple", "b":"banana"})) assert candidate({"p":"pineapple", "A":"banana", "B":"banana"}) == False, "Second test error: " + str(candidate({"p":"pineapple",...
null
HumanEval/96
def countUpTo(n): """Implement a function that takes an non-negative integer and returns an array of the first n integers that are prime numbers and less than n. for example: countUpTo(5) => [2,3] countUpTo(11) => [2,3,5,7] countUpTo(0) => [] countUpTo(20) => [2,3,5,7,11,13,17,19] count...
countUpTo
primes = [] for i in range(2, n): is_prime = True for j in range(2, i): if i % j == 0: is_prime = False break if is_prime: primes.append(i) return primes
def check(candidate): assert candidate(5) == [2,3] assert candidate(6) == [2,3,5] assert candidate(7) == [2,3,5] assert candidate(10) == [2,3,5,7] assert candidate(0) == [] assert candidate(22) == [2,3,5,7,11,13,17,19] assert candidate(1) == [] assert candidate(18) == [2,3,5,7,11,13,17]...
null
HumanEval/97
def multiply(a, b): """Complete the function that takes two integers and returns the product of their unit digits. Assume the input is always valid. Examples: multiply(148, 412) should return 16. multiply(19, 28) should return 72. multiply(2020, 1851) should return 0. multiply(14,-15) ...
multiply
return abs(a % 10) * abs(b % 10)
def check(candidate): # Check some simple cases assert candidate(148, 412) == 16, "First test error: " + str(candidate(148, 412)) assert candidate(19, 28) == 72, "Second test error: " + str(candidate(19, 28)) assert candidate(2020, 1851) == 0, "Third test error: " + str(c...
null
HumanEval/98
def countUpper(s): """ Given a string s, count the number of uppercase vowels in even indices. For example: countUpper('aBCdEf') returns 1 countUpper('abcdefg') returns 0 countUpper('dBBE') returns 0 """
countUpper
count = 0 for i in range(0,len(s),2): if s[i] in "AEIOU": count += 1 return count
def check(candidate): # Check some simple cases assert candidate('aBCdEf') == 1 assert candidate('abcdefg') == 0 assert candidate('dBBE') == 0 assert candidate('B') == 0 assert candidate('U') == 1 assert candidate('') == 0 assert candidate('EEEE') == 2 # Check some edge cases th...
null
HumanEval/99
def closestInteger(value): ''' Create a function that takes a value (string) representing a number and returns the closest integer to it. If the number is equidistant from two integers, round it away from zero. Examples >>> closestInteger("10") 10 >>> closestInteger("15.3") 15 ...
closestInteger
from math import floor, ceil if value.count('.') == 1: # remove trailing zeros while (value[-1] == '0'): value = value[:-1] num = float(value) if value[-2:] == '.5': if num > 0: res = ceil(num) else: res = floor(num) elif len(valu...
def check(candidate): # Check some simple cases assert candidate("10") == 10, "Test 1" assert candidate("14.5") == 15, "Test 2" assert candidate("-15.5") == -16, "Test 3" assert candidate("15.3") == 15, "Test 3" # Check some edge cases that are easy to work out by hand. assert candidate("0...
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HumanEval/100
def makeAPile(n): """ Given a positive integer n, you have to make a pile of n levels of stones. The first level has n stones. The number of stones in the next level is: - the next odd number if n is odd. - the next even number if n is even. Return the number of stones in each level...
makeAPile
return [n + 2*i for i in range(n)]
def check(candidate): # Check some simple cases assert candidate(3) == [3, 5, 7], "Test 3" assert candidate(4) == [4,6,8,10], "Test 4" assert candidate(5) == [5, 7, 9, 11, 13] assert candidate(6) == [6, 8, 10, 12, 14, 16] assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22] # Check some ...
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HumanEval/101
def wordsString(s): """ You will be given a string of words separated by commas or spaces. Your task is to split the string into words and return an array of the words. For example: wordsString("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] wordsString("One, two, three, four,...
wordsString
if not s: return [] s_list = [] for letter in s: if letter == ',': s_list.append(' ') else: s_list.append(letter) s_list = "".join(s_list) return s_list.split()
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] assert candidate("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] ...
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HumanEval/102
def chooseNum(x, y): """This function takes two positive numbers x and y and returns the biggest even integer number that is in the range [x, y] inclusive. If there's no such number, then the function should return -1. For example: chooseNum(12, 15) = 14 chooseNum(13, 12) = -1 """
chooseNum
if x > y: return -1 if y % 2 == 0: return y if x == y: return -1 return y - 1
def check(candidate): # Check some simple cases assert candidate(12, 15) == 14 assert candidate(13, 12) == -1 assert candidate(33, 12354) == 12354 assert candidate(5234, 5233) == -1 assert candidate(6, 29) == 28 assert candidate(27, 10) == -1 # Check some edge cases that are easy to wo...
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HumanEval/103
def roundedAvg(n, m): """You are given two positive integers n and m, and your task is to compute the average of the integers from n through m (including n and m). Round the answer to the nearest integer and convert that to binary. If n is greater than m, return -1. Example: roundedAvg(1, 5) =...
roundedAvg
if m < n: return -1 summation = 0 for i in range(n, m+1): summation += i return bin(round(summation/(m - n + 1)))
def check(candidate): # Check some simple cases assert candidate(1, 5) == "0b11" assert candidate(7, 13) == "0b1010" assert candidate(964,977) == "0b1111001010" assert candidate(996,997) == "0b1111100100" assert candidate(560,851) == "0b1011000010" assert candidate(185,546) == "0b101101110"...
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HumanEval/104
def uniqueDigits(x): """Given a list of positive integers x. return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> uniqueDigits([15, 33, 1422, 1]) [1, 15, 33] >>> uniqueDigits([152, 323, 1422, 10]) ...
uniqueDigits
odd_digit_elements = [] for i in x: if all (int(c) % 2 == 1 for c in str(i)): odd_digit_elements.append(i) return sorted(odd_digit_elements)
def check(candidate): # Check some simple cases assert candidate([15, 33, 1422, 1]) == [1, 15, 33] assert candidate([152, 323, 1422, 10]) == [] assert candidate([12345, 2033, 111, 151]) == [111, 151] assert candidate([135, 103, 31]) == [31, 135] # Check some edge cases that are easy to work ou...
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HumanEval/105
def byLength(arr): """ Given an array of integers, sort the integers that are between 1 and 9 inclusive, reverse the resulting array, and then replace each digit by its corresponding name from "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". For example: arr = [2, 1, 1...
byLength
dic = { 1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine", } sorted_arr = sorted(arr, reverse=True) new_arr = [] for var in sorted_arr: try: new_arr.append(dic[...
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"], "Error" assert candidate([]) == [], "Error" assert candidate([1, -1 ,...
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HumanEval/106
def f(n): """ Implement the function f that takes n as a parameter, and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even or the sum of numbers from 1 to i otherwise. i starts from 1. the factorial of i is the multiplication of the numbers fr...
f
ret = [] for i in range(1,n+1): if i%2 == 0: x = 1 for j in range(1,i+1): x *= j ret += [x] else: x = 0 for j in range(1,i+1): x += j ret += [x] return ret
def check(candidate): assert candidate(5) == [1, 2, 6, 24, 15] assert candidate(7) == [1, 2, 6, 24, 15, 720, 28] assert candidate(1) == [1] assert candidate(3) == [1, 2, 6]
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HumanEval/107
def evenOddPalindrome(n): """ Given a positive integer n, return a tuple that has the number of even and odd integer palindromes that fall within the range(1, n), inclusive. Example 1: Input: 3 Output: (1, 2) Explanation: Integer palindrome are 1, 2, 3. one of them is ...
evenOddPalindrome
def is_palindrome(n): return str(n) == str(n)[::-1] even_palindrome_count = 0 odd_palindrome_count = 0 for i in range(1, n+1): if i%2 == 1 and is_palindrome(i): odd_palindrome_count += 1 elif i%2 == 0 and is_palindrome(i): even_palindrome_count += 1 ...
def check(candidate): # Check some simple cases assert candidate(123) == (8, 13) assert candidate(12) == (4, 6) assert candidate(3) == (1, 2) assert candidate(63) == (6, 8) assert candidate(25) == (5, 6) assert candidate(19) == (4, 6) assert candidate(9) == (4, 5), "This prints if this ...
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HumanEval/108
def countNums(arr): """ Write a function countNums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> countNums([]) == 0 >>> c...
countNums
def digits_sum(n): neg = 1 if n < 0: n, neg = -1 * n, -1 n = [int(i) for i in str(n)] n[0] = n[0] * neg return sum(n) return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
def check(candidate): # Check some simple cases assert candidate([]) == 0 assert candidate([-1, -2, 0]) == 0 assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6 assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5 assert candidate([1, 100, 98, -7, 1, -1]) == 4 assert candidate([12, 23, 34, -45, -56, 0])...
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HumanEval/109
def moveOneBall(arr): """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The numbers in the array will be randomly ordered. Your task is to determine if it is possible to get an array sorted in non-decreasing order by performing the following operation on the given array: You ...
moveOneBall
if len(arr)==0: return True sorted_array=sorted(arr) my_arr=[] min_value=min(arr) min_index=arr.index(min_value) my_arr=arr[min_index:]+arr[0:min_index] for i in range(len(arr)): if my_arr[i]!=sorted_array[i]: return False return True
def check(candidate): # Check some simple cases assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([3, 5, 10, 1, 2])==True assert candidate([4, 3, 1, 2])==False # Check some edge cases that are easy to work out by hand. assert ca...
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HumanEval/110
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1...
exchange
odd = 0 even = 0 for i in lst1: if i%2 == 1: odd += 1 for i in lst2: if i%2 == 0: even += 1 if even >= odd: return "YES" return "NO"
def check(candidate): # Check some simple cases assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES" assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO" assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES" assert candidate([5, 7, 3], [2, 6, 4]) == "YES" assert candidate([5, 7, 3], [2, 6, 3]...
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HumanEval/111
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. Example: histogram('a b c') == {'a': 1, '...
histogram
dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0: for i in list1: if(list1.count(i)==t): dict1[i]=t return dict1
def check(candidate): # Check some simple cases assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)" assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)" assert candidate('a b c d g') == {'a': ...
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HumanEval/112
def reverseDelete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple contain...
reverseDelete
s = ''.join([char for char in s if char not in c]) return (s,s[::-1] == s)
def check(candidate): assert candidate("abcde","ae") == ('bcd',False) assert candidate("abcdef", "b") == ('acdef',False) assert candidate("abcdedcba","ab") == ('cdedc',True) assert candidate("dwik","w") == ('dik',False) assert candidate("a","a") == ('',True) assert candidate("abcdedcba","") == ...
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HumanEval/113
def oddCount(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. ...
oddCount
res = [] for arr in lst: n = sum(int(d)%2==1 for d in arr) res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
def check(candidate): # Check some simple cases assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1" assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput...
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HumanEval/114
def min_sub_array_sum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. Example min_sub_array_sum([2, 3, 4, 1, 2, 4]) == 1 min_sub_array_sum([-1, -2, -3]) == -6 """
min_sub_array_sum
max_sum = 0 s = 0 for num in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_sum return min_sum
def check(candidate): # Check some simple cases assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)" assert candidate([-1, -2, -3]) == -6 assert candidate([-1, -2, -3, 2, -10]) == -14 assert candidate([-9999999999999999]) == -9999999999999999 ass...
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HumanEval/115
def maxFill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capaci...
maxFill
return sum([math.ceil(sum(arr)/capacity) for arr in grid])
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error" assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error" assert candidate([[0,0,0], [0...
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HumanEval/116
def sortArray(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. It must be implemented like this: >>> sortArray([1, 5, 2, 3, 4]) == [...
sortArray
return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5] assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3] assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3] assert candidate([...
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HumanEval/117
def selectWords(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an em...
selectWords
result = [] for word in s.split(): n_consonants = 0 for i in range(0, len(word)): if word[i].lower() not in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) return result
def check(candidate): # Check some simple cases assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4)) assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little l...
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HumanEval/118
def getClosestVowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above conditio...
getClosestVowel
if len(word) < 3: return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] return ""
def check(candidate): # Check some simple cases assert candidate("yogurt") == "u" assert candidate("full") == "u" assert candidate("easy") == "" assert candidate("eAsy") == "" assert candidate("ali") == "" assert candidate("bad") == "a" assert candidate("most") == "o" assert candida...
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HumanEval/119
def matchParens(lst): ''' You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be ...
matchParens
def check(s): val = 0 for i in s: if i == '(': val = val + 1 else: val = val - 1 if val < 0: return False return True if val == 0 else False S1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes'...
def check(candidate): # Check some simple cases assert candidate(['()(', ')']) == 'Yes' assert candidate([')', ')']) == 'No' assert candidate(['(()(())', '())())']) == 'No' assert candidate([')())', '(()()(']) == 'Yes' assert candidate(['(())))', '(()())((']) == 'Yes' assert candidate(['()'...
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HumanEval/120
def maximum(arr, k): """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: Input: arr = [-3, -4, 5], k = 3 Output: [-4, -3, 5] Example 2: Input: arr = [4, -4, 4], k = 2 Output:...
maximum
if k == 0: return [] arr.sort() ans = arr[-k:] return ans
def check(candidate): # Check some simple cases assert candidate([-3, -4, 5], 3) == [-4, -3, 5] assert candidate([4, -4, 4], 2) == [4, 4] assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2] assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123] assert candidate([-123, 20, 0 , 1, 2,...
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HumanEval/121
def solution(lst): """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions. Examples solution([5, 8, 7, 1]) ==> 12 solution([3, 3, 3, 3, 3]) ==> 9 solution([30, 13, 24, 321]) ==>0 """
solution
return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])
def check(candidate): # Check some simple cases assert candidate([5, 8, 7, 1]) == 12 assert candidate([3, 3, 3, 3, 3]) == 9 assert candidate([30, 13, 24, 321]) == 0 assert candidate([5, 9]) == 5 assert candidate([2, 4, 8]) == 0 assert candidate([30, 13, 23, 32]) == 23 assert candidat...
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HumanEval/122
def addElements(arr, k): """ Given a non-empty array of integers arr and an integer k, return the sum of the elements with at most two digits from the first k elements of arr. Example: Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4 Output: 24 # sum of 21 + 3 Constraints: 1...
addElements
return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)
def check(candidate): # Check some simple cases assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4 assert candidate([111,121,3,4000,5,6], 2) == 0 assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125 assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good fo...
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HumanEval/123
def getOddCollatz(n): """ Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence. The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined as follows: start with any positive integer n. Then each term is obtained from the previo...
getOddCollatz
if n%2==0: odd_collatz = [] else: odd_collatz = [n] while n > 1: if n % 2 == 0: n = n/2 else: n = n*3 + 1 if n%2 == 1: odd_collatz.append(int(n)) return sorted(odd_collatz)
def check(candidate): # Check some simple cases assert candidate(14) == [1, 5, 7, 11, 13, 17] assert candidate(5) == [1, 5] assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate(...
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