task_id
stringclasses
164 values
prompt
stringlengths
97
1.92k
entry_point
stringclasses
281 values
canonical_solution
stringclasses
414 values
test
stringclasses
164 values
partial
stringclasses
127 values
HumanEval/108
def count_nums(arr): """ Write a function count_nums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> count_nums([]) == 0 >>> count_nums([-1, 11,...
count_nums
n = [int(i) for i in str(n)] n[0] = n[0] * neg return sum(n) return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
def check(candidate): # Check some simple cases assert candidate([]) == 0 assert candidate([-1, -2, 0]) == 0 assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6 assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5 assert candidate([1, 100, 98, -7, 1, -1]) == 4 assert candidate([12, 23, 34, -45, -56, 0])...
def count_nums(arr): """ Write a function count_nums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> count_nums([]) == 0 >>...
HumanEval/109
def move_one_ball(arr): """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The numbers in the array will be randomly ordered. Your task is to determine if it is possible to get an array sorted in non-decreasing order by performing the following operation on the given array: You are allowed to p...
move_one_ball
min_index=arr.index(min_value) my_arr=arr[min_index:]+arr[0:min_index] for i in range(len(arr)): if my_arr[i]!=sorted_array[i]: return False return True
def check(candidate): # Check some simple cases assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([3, 5, 10, 1, 2])==True assert candidate([4, 3, 1, 2])==False # Check some edge cases that are easy to work out by hand. assert ca...
def move_one_ball(arr): """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The numbers in the array will be randomly ordered. Your task is to determine if it is possible to get an array sorted in non-decreasing order by performing the following operation on the given array: Yo...
HumanEval/110
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. ...
exchange
if i%2 == 0: even += 1 if even >= odd: return "YES" return "NO"
def check(candidate): # Check some simple cases assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES" assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO" assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES" assert candidate([5, 7, 3], [2, 6, 4]) == "YES" assert candidate([5, 7, 3], [2, 6, 3]...
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1...
HumanEval/111
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. Example: histogram('a b c') == {'a': 1, 'b': 1, 'c': 1} ...
histogram
t=list1.count(i) if t>0: for i in list1: if(list1.count(i)==t): dict1[i]=t return dict1
def check(candidate): # Check some simple cases assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)" assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)" assert candidate('a b c d g') == {'a': ...
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. Example: histogram('a b c') == {'a': 1, '...
HumanEval/112
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result...
reverse_delete
return (s,s[::-1] == s)
def check(candidate): assert candidate("abcde","ae") == ('bcd',False) assert candidate("abcdef", "b") == ('acdef',False) assert candidate("abcdedcba","ab") == ('cdedc',True) assert candidate("dwik","w") == ('dik',False) assert candidate("a","a") == ('',True) assert candidate("abcdedcba","") == ...
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple contai...
HumanEval/113
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. >>> odd_cou...
odd_count
n = sum(int(d)%2==1 for d in arr) res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
def check(candidate): # Check some simple cases assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1" assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput...
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. ...
HumanEval/114
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. Example minSubArraySum([2, 3, 4, 1, 2, 4]) == 1 minSubArraySum([-1, -2, -3]) == -6 """ max_sum = 0 s = 0 for num in nums: s += -num if (s < 0):
minSubArraySum
s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_sum return min_sum
def check(candidate): # Check some simple cases assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)" assert candidate([-1, -2, -3]) == -6 assert candidate([-1, -2, -3, 2, -10]) == -14 assert candidate([-9999999999999999]) == -9999999999999999 ass...
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. Example minSubArraySum([2, 3, 4, 1, 2, 4]) == 1 minSubArraySum([-1, -2, -3]) == -6 """ max_sum = 0 s = 0 for num in nums: s += -num if (s < 0):...
HumanEval/115
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is...
max_fill
return sum([math.ceil(sum(arr)/capacity) for arr in grid])
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error" assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error" assert candidate([[0,0,0], [0...
null
HumanEval/116
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. It must be implemented like this: >>> sort_array([1, 5, 2, 3, 4]) == [1, 2, 3, 4, 5] ...
sort_array
return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5] assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3] assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3] assert candidate([...
null
HumanEval/117
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. ...
select_words
n_consonants += 1 if n_consonants == n: result.append(word) return result
def check(candidate): # Check some simple cases assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4)) assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little l...
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an e...
HumanEval/118
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You ...
get_closest_vowel
for i in range(len(word)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] return ""
def check(candidate): # Check some simple cases assert candidate("yogurt") == "u" assert candidate("full") == "u" assert candidate("easy") == "" assert candidate("eAsy") == "" assert candidate("ali") == "" assert candidate("bad") == "a" assert candidate("most") == "o" assert candida...
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condit...
HumanEval/119
def match_parens(lst): ''' You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only ...
match_parens
if val < 0: return False return True if val == 0 else False S1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes' if check(S1) or check(S2) else 'No'
def check(candidate): # Check some simple cases assert candidate(['()(', ')']) == 'Yes' assert candidate([')', ')']) == 'No' assert candidate(['(()(())', '())())']) == 'No' assert candidate([')())', '(()()(']) == 'Yes' assert candidate(['(())))', '(()())((']) == 'Yes' assert candidate(['()'...
def match_parens(lst): ''' You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be...
HumanEval/120
def maximum(arr, k): """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: Input: arr = [-3, -4, 5], k = 3 Output: [-4, -3, 5] Example 2: Input: arr = [4, -4, 4], k = 2 Output: [4, 4] Example 3: Input: arr = [-...
maximum
arr.sort() ans = arr[-k:] return ans
def check(candidate): # Check some simple cases assert candidate([-3, -4, 5], 3) == [-4, -3, 5] assert candidate([4, -4, 4], 2) == [4, 4] assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2] assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123] assert candidate([-123, 20, 0 , 1, 2,...
def maximum(arr, k): """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: Input: arr = [-3, -4, 5], k = 3 Output: [-4, -3, 5] Example 2: Input: arr = [4, -4, 4], k = 2 Output:...
HumanEval/121
def solution(lst): """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions. Examples solution([5, 8, 7, 1]) ==> 12 solution([3, 3, 3, 3, 3]) ==> 9 solution([30, 13, 24, 321]) ==>0 """
solution
return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])
def check(candidate): # Check some simple cases assert candidate([5, 8, 7, 1]) == 12 assert candidate([3, 3, 3, 3, 3]) == 9 assert candidate([30, 13, 24, 321]) == 0 assert candidate([5, 9]) == 5 assert candidate([2, 4, 8]) == 0 assert candidate([30, 13, 23, 32]) == 23 assert candidat...
null
HumanEval/122
def add_elements(arr, k): """ Given a non-empty array of integers arr and an integer k, return the sum of the elements with at most two digits from the first k elements of arr. Example: Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4 Output: 24 # sum of 21 + 3 Constraints: 1. 1 <= len(arr) <= 100 2. 1 <=...
add_elements
return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)
def check(candidate): # Check some simple cases assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4 assert candidate([111,121,3,4000,5,6], 2) == 0 assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125 assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good fo...
null
HumanEval/123
def get_odd_collatz(n): """ Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence. The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined as follows: start with any positive integer n. Then each term is obtained from the previous term as fo...
get_odd_collatz
else: n = n*3 + 1 if n%2 == 1: odd_collatz.append(int(n)) return sorted(odd_collatz)
def check(candidate): # Check some simple cases assert candidate(14) == [1, 5, 7, 11, 13, 17] assert candidate(5) == [1, 5] assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate(...
def get_odd_collatz(n): """ Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence. The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined as follows: start with any positive integer n. Then each term is obtained from the prev...
HumanEval/124
def valid_date(date): """You have to write a function which validates a given date string and returns True if the date is valid otherwise False. The date is valid if all of the following rules are satisfied: 1. The date string is not empty. 2. The number of days is not less than 1 or higher than 31 days for month...
valid_date
if month in [4,6,9,11] and day < 1 or day > 30: return False if month == 2 and day < 1 or day > 29: return False except: return False return True
def check(candidate): # Check some simple cases assert candidate('03-11-2000') == True assert candidate('15-01-2012') == False assert candidate('04-0-2040') == False assert candidate('06-04-2020') == True assert candidate('01-01-2007') == True assert candidate('03-32-2011') == False ...
def valid_date(date): """You have to write a function which validates a given date string and returns True if the date is valid otherwise False. The date is valid if all of the following rules are satisfied: 1. The date string is not empty. 2. The number of days is not less than 1 or higher than 31...
HumanEval/125
def split_words(txt): ''' Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25 Ex...
split_words
return txt.replace(',',' ').split() else: return len([i for i in txt if i.islower() and ord(i)%2 == 0])
def check(candidate): assert candidate("Hello world!") == ["Hello","world!"] assert candidate("Hello,world!") == ["Hello","world!"] assert candidate("Hello world,!") == ["Hello","world,!"] assert candidate("Hello,Hello,world !") == ["Hello,Hello,world","!"] assert candidate("abcdef") == 3 asser...
def split_words(txt): ''' Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the alphabet, ord('a') = 0, ord('b') = 1, ... ord('...
HumanEval/126
def is_sorted(lst): ''' Given a list of numbers, return whether or not they are sorted in ascending order. If list has more than 1 duplicate of the same number, return False. Assume no negative numbers and only integers. Examples is_sorted([5]) ➞ True is_sorted([1, 2, 3, 4, 5]) ➞ True is_sorted([1, 3, 2, 4, 5...
is_sorted
if all(lst[i-1] <= lst[i] for i in range(1, len(lst))): return True else: return False
def check(candidate): # Check some simple cases assert candidate([5]) == True assert candidate([1, 2, 3, 4, 5]) == True assert candidate([1, 3, 2, 4, 5]) == False assert candidate([1, 2, 3, 4, 5, 6]) == True assert candidate([1, 2, 3, 4, 5, 6, 7]) == True assert candidate([1, 3, 2, 4, 5, 6,...
def is_sorted(lst): ''' Given a list of numbers, return whether or not they are sorted in ascending order. If list has more than 1 duplicate of the same number, return False. Assume no negative numbers and only integers. Examples is_sorted([5]) ➞ True is_sorted([1, 2, 3, 4, 5]) ➞ True ...
HumanEval/127
def intersection(interval1, interval2): """You are given two intervals, where each interval is a pair of integers. For example, interval = (start, end) = (1, 2). The given intervals are closed which means that the interval (start, end) includes both start and end. For each given interval, it is assumed that its s...
intersection
return True l = max(interval1[0], interval2[0]) r = min(interval1[1], interval2[1]) length = r - l if length > 0 and is_prime(length): return "YES" return "NO"
def check(candidate): # Check some simple cases assert candidate((1, 2), (2, 3)) == "NO" assert candidate((-1, 1), (0, 4)) == "NO" assert candidate((-3, -1), (-5, 5)) == "YES" assert candidate((-2, 2), (-4, 0)) == "YES" # Check some edge cases that are easy to work out by hand. assert cand...
def intersection(interval1, interval2): """You are given two intervals, where each interval is a pair of integers. For example, interval = (start, end) = (1, 2). The given intervals are closed which means that the interval (start, end) includes both start and end. For each given interval, it is ass...
HumanEval/128
def prod_signs(arr): """ You are given an array arr of integers and you need to return sum of magnitudes of integers multiplied by product of all signs of each number in the array, represented by 1, -1 or 0. Note: return None for empty arr. Example: >>> prod_signs([1, 2, 2, -4]) == -9 >>> prod_signs([0, 1]) =...
prod_signs
prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr))) return prod * sum([abs(i) for i in arr])
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1, 2, 2, -4]) == -9 assert candidate([0, 1]) == 0 assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10 assert candidate([]) == None assert candidate([2, 4,1, ...
def prod_signs(arr): """ You are given an array arr of integers and you need to return sum of magnitudes of integers multiplied by product of all signs of each number in the array, represented by 1, -1 or 0. Note: return None for empty arr. Example: >>> prod_signs([1, 2, 2, -4]) == -9 ...
HumanEval/129
def minPath(grid, k): """ Given a grid with N rows and N columns (N >= 2) and a positive integer k, each cell of the grid contains a value. Every integer in the range [1, N * N] inclusive appears exactly once on the cells of the grid. You have to find the minimum path of length k in the grid. You can start fro...
minPath
temp.append(grid[i + 1][j]) if j != n - 1: temp.append(grid[i][j + 1]) val = min(temp) ans = [] for i in range(k): if i % 2 == 0: ans.append(1) else: ans.append(val) return ans
def check(candidate): # Check some simple cases print assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1] assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1] assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2] assert can...
def minPath(grid, k): """ Given a grid with N rows and N columns (N >= 2) and a positive integer k, each cell of the grid contains a value. Every integer in the range [1, N * N] inclusive appears exactly once on the cells of the grid. You have to find the minimum path of length k in the grid. You...
HumanEval/130
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + tri(n - 2) + tri(n...
tri
if i % 2 == 0: my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
def check(candidate): # Check some simple cases assert candidate(3) == [1, 3, 2.0, 8.0] assert candidate(4) == [1, 3, 2.0, 8.0, 3.0] assert candidate(5) == [1, 3, 2.0, 8.0, 3.0, 15.0] assert candidate(6) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0] assert candidate(7) == [1, 3, 2.0, 8.0, 3.0, 15.0,...
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + ...
HumanEval/131
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. For example: digits(1) == 1 digits(4) == 0 digits(235) == 15 """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1:
digits
product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
def check(candidate): # Check some simple cases assert candidate(5) == 5 assert candidate(54) == 5 assert candidate(120) ==1 assert candidate(5014) == 5 assert candidate(98765) == 315 assert candidate(5576543) == 2625 # Check some edge cases that are easy to work out by hand. asser...
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. For example: digits(1) == 1 digits(4) == 0 digits(235) == 15 """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_di...
HumanEval/132
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[]]]]]]][[[[[]') ➞ ...
is_nested
i = 0 l = len(closing_bracket_index) for idx in opening_bracket_index: if i < l and idx < closing_bracket_index[i]: cnt += 1 i += 1 return cnt >= 2
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
HumanEval/133
def sum_squares(lst): """You are given a list of numbers. You need to return the sum of squared numbers in the given list, round each element in the list to the upper int(Ceiling) first. Examples: For lst = [1,2,3] the output should be 14 For lst = [1,4,9] the output should be 98 For lst = [1,3,5,7] the output...
sum_squares
for i in lst: squared += math.ceil(i)**2 return squared
def check(candidate): # Check some simple cases assert candidate([1,2,3])==14, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1.0,2,3])==14, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1,3,5,7])==84, "This prints if this assert fails 1 (goo...
def sum_squares(lst): """You are given a list of numbers. You need to return the sum of squared numbers in the given list, round each element in the list to the upper int(Ceiling) first. Examples: For lst = [1,2,3] the output should be 14 For lst = [1,4,9] the output should be 98 For lst =...
HumanEval/134
def check_if_last_char_is_a_letter(txt): ''' Create a function that returns True if the last character of a given string is an alphabetical character and is not a part of a word, and False otherwise. Note: "word" is a group of characters separated by space. Examples: check_if_last_char_is_a_letter("apple pie")...
check_if_last_char_is_a_letter
check = txt.split(' ')[-1] return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False
def check(candidate): # Check some simple cases assert candidate("apple") == False assert candidate("apple pi e") == True assert candidate("eeeee") == False assert candidate("A") == True assert candidate("Pumpkin pie ") == False assert candidate("Pumpkin pie 1") == False assert candidat...
def check_if_last_char_is_a_letter(txt): ''' Create a function that returns True if the last character of a given string is an alphabetical character and is not a part of a word, and False otherwise. Note: "word" is a group of characters separated by space. Examples: check_if_last_char_is_...
HumanEval/135
def can_arrange(arr): """Create a function which returns the largest index of an element which is not greater than or equal to the element immediately preceding it. If no such element exists then return -1. The given array will not contain duplicate values. Examples: can_arrange([1,2,4,3,5]) = 3 can_arrange([1...
can_arrange
if arr[i]<arr[i-1]: ind=i i+=1 return ind
def check(candidate): # Check some simple cases assert candidate([1,2,4,3,5])==3 assert candidate([1,2,4,5])==-1 assert candidate([1,4,2,5,6,7,8,9,10])==2 assert candidate([4,8,5,7,3])==4 # Check some edge cases that are easy to work out by hand. assert candidate([])==-1
def can_arrange(arr): """Create a function which returns the largest index of an element which is not greater than or equal to the element immediately preceding it. If no such element exists then return -1. The given array will not contain duplicate values. Examples: can_arrange([1,2,4,3,5]) =...
HumanEval/136
def largest_smallest_integers(lst): ''' Create a function that returns a tuple (a, b), where 'a' is the largest of negative integers, and 'b' is the smallest of positive integers in a list. If there is no negative or positive integers, return them as None. Examples: largest_smallest_integers([2, 4, 1, 3, 5, 7]...
largest_smallest_integers
largest = list(filter(lambda x: x > 0, lst)) return (max(smallest) if smallest else None, min(largest) if largest else None)
def check(candidate): # Check some simple cases assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1) assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1) assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1) assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2) assert candidate([7, 3, 8, 4, 9, 2, 5, -...
def largest_smallest_integers(lst): ''' Create a function that returns a tuple (a, b), where 'a' is the largest of negative integers, and 'b' is the smallest of positive integers in a list. If there is no negative or positive integers, return them as None. Examples: largest_smallest_intege...
HumanEval/137
def compare_one(a, b): """ Create a function that takes integers, floats, or strings representing real numbers, and returns the larger variable in its given variable type. Return None if the values are equal. Note: If a real number is represented as a string, the floating point might be . or , compare_one(1, 2....
compare_one
if isinstance(temp_b, str): temp_b = temp_b.replace(',','.') if float(temp_a) == float(temp_b): return None return a if float(temp_a) > float(temp_b) else b
def check(candidate): # Check some simple cases assert candidate(1, 2) == 2 assert candidate(1, 2.5) == 2.5 assert candidate(2, 3) == 3 assert candidate(5, 6) == 6 assert candidate(1, "2,3") == "2,3" assert candidate("5,1", "6") == "6" assert candidate("1", "2") == "2" assert candid...
def compare_one(a, b): """ Create a function that takes integers, floats, or strings representing real numbers, and returns the larger variable in its given variable type. Return None if the values are equal. Note: If a real number is represented as a string, the floating point might be . or , ...
HumanEval/138
def is_equal_to_sum_even(n): """Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers Example is_equal_to_sum_even(4) == False is_equal_to_sum_even(6) == False is_equal_to_sum_even(8) == True """
is_equal_to_sum_even
return n%2 == 0 and n >= 8
def check(candidate): assert candidate(4) == False assert candidate(6) == False assert candidate(8) == True assert candidate(10) == True assert candidate(11) == False assert candidate(12) == True assert candidate(13) == False assert candidate(16) == True
null
HumanEval/139
def special_factorial(n): """The Brazilian factorial is defined as: brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1! where n > 0 For example: >>> special_factorial(4) 288 The function will receive an integer as input and should return the special factorial of this integer. """ fact_i = 1 special_f...
special_factorial
fact_i *= i special_fact *= fact_i return special_fact
def check(candidate): # Check some simple cases assert candidate(4) == 288, "Test 4" assert candidate(5) == 34560, "Test 5" assert candidate(7) == 125411328000, "Test 7" # Check some edge cases that are easy to work out by hand. assert candidate(1) == 1, "Test 1"
def special_factorial(n): """The Brazilian factorial is defined as: brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1! where n > 0 For example: >>> special_factorial(4) 288 The function will receive an integer as input and should return the special factorial of this integer. ...
HumanEval/140
def fix_spaces(text): """ Given a string text, replace all spaces in it with underscores, and if a string has more than 2 consecutive spaces, then replace all consecutive spaces with - fix_spaces("Example") == "Example" fix_spaces("Example 1") == "Example_1" fix_spaces(" Example 2") == "_Example_2" fix...
fix_spaces
new_text += "_"*(end - start)+text[i] else: new_text += text[i] start, end = i+1, i+1 i+=1 if end - start > 2: new_text += "-" elif end - start > 0: new_text += "_" return new_text
def check(candidate): # Check some simple cases assert candidate("Example") == "Example", "This prints if this assert fails 1 (good for debugging!)" assert candidate("Mudasir Hanif ") == "Mudasir_Hanif_", "This prints if this assert fails 2 (good for debugging!)" assert candidate("Yellow Yellow Dirty ...
def fix_spaces(text): """ Given a string text, replace all spaces in it with underscores, and if a string has more than 2 consecutive spaces, then replace all consecutive spaces with - fix_spaces("Example") == "Example" fix_spaces("Example 1") == "Example_1" fix_spaces(" Example 2")...
HumanEval/141
def file_name_check(file_name): """Create a function which takes a string representing a file's name, and returns 'Yes' if the the file's name is valid, and returns 'No' otherwise. A file's name is considered to be valid if and only if all the following conditions are met: - There should not be more than three d...
file_name_check
return 'No' if not lst[0][0].isalpha(): return 'No' t = len([x for x in lst[0] if x.isdigit()]) if t > 3: return 'No' return 'Yes'
def check(candidate): # Check some simple cases assert candidate("example.txt") == 'Yes' assert candidate("1example.dll") == 'No' assert candidate('s1sdf3.asd') == 'No' assert candidate('K.dll') == 'Yes' assert candidate('MY16FILE3.exe') == 'Yes' assert candidate('His12FILE94.exe') == 'No' ...
def file_name_check(file_name): """Create a function which takes a string representing a file's name, and returns 'Yes' if the the file's name is valid, and returns 'No' otherwise. A file's name is considered to be valid if and only if all the following conditions are met: - There should not be mo...
HumanEval/142
def sum_squares(lst): """" This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not change the entries in th...
sum_squares
elif i % 4 == 0 and i%3 != 0: result.append(lst[i]**3) else: result.append(lst[i]) return sum(result)
def check(candidate): # Check some simple cases assert candidate([1,2,3]) == 6 assert candidate([1,4,9]) == 14 assert candidate([]) == 0 assert candidate([1,1,1,1,1,1,1,1,1]) == 9 assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3 assert candidate([0]) == 0 assert candidate([-1,-...
def sum_squares(lst): """" This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not change the e...
HumanEval/143
def words_in_sentence(sentence): """ You are given a string representing a sentence, the sentence contains some words separated by a space, and you have to return a string that contains the words from the original sentence, whose lengths are prime numbers, the order of the words in the new string should be the s...
words_in_sentence
for i in range(2, len(word)): if len(word)%i == 0: flg = 1 if flg == 0 or len(word) == 2: new_lst.append(word) return " ".join(new_lst)
def check(candidate): # Check some simple cases assert candidate("This is a test") == "is" assert candidate("lets go for swimming") == "go for" assert candidate("there is no place available here") == "there is no place" assert candidate("Hi I am Hussein") == "Hi am Hussein" assert candidate("go...
def words_in_sentence(sentence): """ You are given a string representing a sentence, the sentence contains some words separated by a space, and you have to return a string that contains the words from the original sentence, whose lengths are prime numbers, the order of the words in the new stri...
HumanEval/144
def simplify(x, n): """Your task is to implement a function that will simplify the expression x * n. The function returns True if x * n evaluates to a whole number and False otherwise. Both x and n, are string representation of a fraction, and have the following format, <numerator>/<denominator> where both numerat...
simplify
denom = int(b) * int(d) if (numerator/denom == int(numerator/denom)): return True return False
def check(candidate): # Check some simple cases assert candidate("1/5", "5/1") == True, 'test1' assert candidate("1/6", "2/1") == False, 'test2' assert candidate("5/1", "3/1") == True, 'test3' assert candidate("7/10", "10/2") == False, 'test4' assert candidate("2/10", "50/10") == True, 'test5' ...
def simplify(x, n): """Your task is to implement a function that will simplify the expression x * n. The function returns True if x * n evaluates to a whole number and False otherwise. Both x and n, are string representation of a fraction, and have the following format, <numerator>/<denominator> where ...
HumanEval/145
def order_by_points(nums): """ Write a function which sorts the given list of integers in ascending order according to the sum of their digits. Note: if there are several items with similar sum of their digits, order them based on their index in original list. For example: >>> order_by_points([1, 11, -1, -11, ...
order_by_points
n = [int(i) for i in str(n)] n[0] = n[0] * neg return sum(n) return sorted(nums, key=digits_sum)
def check(candidate): # Check some simple cases assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11] assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457] assert candidate([]) == [] assert candidate([1,...
def order_by_points(nums): """ Write a function which sorts the given list of integers in ascending order according to the sum of their digits. Note: if there are several items with similar sum of their digits, order them based on their index in original list. For example: >>> order_by_poi...
HumanEval/146
def specialFilter(nums): """Write a function that takes an array of numbers as input and returns the number of elements in the array that are greater than 10 and both first and last digits of a number are odd (1, 3, 5, 7, 9). For example: specialFilter([15, -73, 14, -15]) => 1 specialFilter([33, -2, -3, 45, 2...
specialFilter
number_as_string = str(num) if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits: count += 1 return count
def check(candidate): # Check some simple cases assert candidate([5, -2, 1, -5]) == 0 assert candidate([15, -73, 14, -15]) == 1 assert candidate([33, -2, -3, 45, 21, 109]) == 2 assert candidate([43, -12, 93, 125, 121, 109]) == 4 assert candidate([71, -2, -33, 75, 21, 19]) == 3 # Check s...
def specialFilter(nums): """Write a function that takes an array of numbers as input and returns the number of elements in the array that are greater than 10 and both first and last digits of a number are odd (1, 3, 5, 7, 9). For example: specialFilter([15, -73, 14, -15]) => 1 specialFilter(...
HumanEval/147
def get_max_triples(n): """ You are given a positive integer n. You have to create an integer array a of length n. For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1. Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, and a[i] + a[j] + a[k] is a multiple of 3. Example : Input: n =...
get_max_triples
for k in range(j+1,n): if (A[i]+A[j]+A[k])%3 == 0: ans += [(A[i],A[j],A[k])] return len(ans)
def check(candidate): assert candidate(5) == 1 assert candidate(6) == 4 assert candidate(10) == 36 assert candidate(100) == 53361
def get_max_triples(n): """ You are given a positive integer n. You have to create an integer array a of length n. For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1. Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, and a[i] + a[j] + a[k] is a multiple of 3. ...
HumanEval/148
def bf(planet1, planet2): ''' There are eight planets in our solar system: the closerst to the Sun is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, Uranus, Neptune. Write a function that takes two planet names as strings planet1 and planet2. The function should return a tuple containing a...
bf
planet2_index = planet_names.index(planet2) if planet1_index < planet2_index: return (planet_names[planet1_index + 1: planet2_index]) else: return (planet_names[planet2_index + 1 : planet1_index])
def check(candidate): # Check some simple cases assert candidate("Jupiter", "Neptune") == ("Saturn", "Uranus"), "First test error: " + str(len(candidate("Jupiter", "Neptune"))) assert candidate("Earth", "Mercury") == ("Venus",), "Second test error: " + str(candidate("Earth", "Mercury")) assert ...
def bf(planet1, planet2): ''' There are eight planets in our solar system: the closerst to the Sun is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, Uranus, Neptune. Write a function that takes two planet names as strings planet1 and planet2. The function should return a ...
HumanEval/149
def sorted_list_sum(lst): """Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order, The list is always a list of strings and never an array of numbers, and it may contain duplicates. The order of the li...
sorted_list_sum
if len(i)%2 == 0: new_lst.append(i) return sorted(new_lst, key=len)
def check(candidate): # Check some simple cases assert candidate(["aa", "a", "aaa"]) == ["aa"] assert candidate(["school", "AI", "asdf", "b"]) == ["AI", "asdf", "school"] assert candidate(["d", "b", "c", "a"]) == [] assert candidate(["d", "dcba", "abcd", "a"]) == ["abcd", "dcba"] # Check some ...
def sorted_list_sum(lst): """Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order, The list is always a list of strings and never an array of numbers, and it may contain duplicates. T...
HumanEval/150
def x_or_y(n, x, y): """A simple program which should return the value of x if n is a prime number and should return the value of y otherwise. Examples: for x_or_y(7, 34, 12) == 34 for x_or_y(15, 8, 5) == 5 """ if n == 1: return y for i in range(2, n): if n % i == 0:
x_or_y
return y break else: return x
def check(candidate): # Check some simple cases assert candidate(7, 34, 12) == 34 assert candidate(15, 8, 5) == 5 assert candidate(3, 33, 5212) == 33 assert candidate(1259, 3, 52) == 3 assert candidate(7919, -1, 12) == -1 assert candidate(3609, 1245, 583) == 583 assert candidate(91, 56,...
def x_or_y(n, x, y): """A simple program which should return the value of x if n is a prime number and should return the value of y otherwise. Examples: for x_or_y(7, 34, 12) == 34 for x_or_y(15, 8, 5) == 5 """ if n == 1: return y for i in range(2, n): if n % i ==...
HumanEval/151
def double_the_difference(lst): ''' Given a list of numbers, return the sum of squares of the numbers in the list that are odd. Ignore numbers that are negative or not integers. double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10 double_the_difference([-1, -2, 0]) == 0 double_the_difference([9, -2]) =...
double_the_difference
return sum([i**2 for i in lst if i > 0 and i%2!=0 and "." not in str(i)])
def check(candidate): # Check some simple cases assert candidate([]) == 0 , "This prints if this assert fails 1 (good for debugging!)" assert candidate([5, 4]) == 25 , "This prints if this assert fails 2 (good for debugging!)" assert candidate([0.1, 0.2, 0.3]) == 0 , "This prints if this assert fails 3...
null
HumanEval/152
def compare(game,guess): """I think we all remember that feeling when the result of some long-awaited event is finally known. The feelings and thoughts you have at that moment are definitely worth noting down and comparing. Your task is to determine if a person correctly guessed the results of a number of matches....
compare
return [abs(x-y) for x,y in zip(game,guess)]
def check(candidate): # Check some simple cases assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], "This prints if this assert fails 1 (good for debugging!)" assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], "This prints if this assert fails 1 (good for debugging!)" assert candi...
null
HumanEval/153
def Strongest_Extension(class_name, extensions): """You will be given the name of a class (a string) and a list of extensions. The extensions are to be used to load additional classes to the class. The strength of the extension is as follows: Let CAP be the number of the uppercase letters in the extension's name, ...
Strongest_Extension
strong = s my_val = val ans = class_name + "." + strong return ans
def check(candidate): # Check some simple cases assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe' assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe' assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__'...
def Strongest_Extension(class_name, extensions): """You will be given the name of a class (a string) and a list of extensions. The extensions are to be used to load additional classes to the class. The strength of the extension is as follows: Let CAP be the number of the uppercase letters in the extens...
HumanEval/154
def cycpattern_check(a , b): """You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word cycpattern_check("abcd","abd") => False cycpattern_check("hello","ell") => True cycpattern_check("whassup","psus") => False cycpattern_check("abab","baa") => T...
cycpattern_check
for j in range(l + 1): if a[i:i+l] == pat[j:j+l]: return True return False
def check(candidate): # Check some simple cases #assert True, "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. #assert True, "This prints if this assert fails 2 (also good for debugging!)" assert candidate("xyzw","xyw") == False...
def cycpattern_check(a , b): """You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word cycpattern_check("abcd","abd") => False cycpattern_check("hello","ell") => True cycpattern_check("whassup","psus") => False cycpattern_check("ab...
HumanEval/155
def even_odd_count(num): """Given an integer. return a tuple that has the number of even and odd digits respectively. Example: even_odd_count(-12) ==> (1, 1) even_odd_count(123) ==> (1, 2) """ even_count = 0 odd_count = 0 for i in str(abs(num)): if int(i)%2==0:
even_odd_count
even_count +=1 else: odd_count +=1 return (even_count, odd_count)
def check(candidate): # Check some simple cases assert candidate(7) == (0, 1) assert candidate(-78) == (1, 1) assert candidate(3452) == (2, 2) assert candidate(346211) == (3, 3) assert candidate(-345821) == (3, 3) assert candidate(-2) == (1, 0) assert candidate(-45347) == (2, 3) ass...
def even_odd_count(num): """Given an integer. return a tuple that has the number of even and odd digits respectively. Example: even_odd_count(-12) ==> (1, 1) even_odd_count(123) ==> (1, 2) """ even_count = 0 odd_count = 0 for i in str(abs(num)): if int(i)%2==0: ...
HumanEval/156
def int_to_mini_roman(number): """ Given a positive integer, obtain its roman numeral equivalent as a string, and return it in lowercase. Restrictions: 1 <= num <= 1000 Examples: >>> int_to_mini_roman(19) == 'xix' >>> int_to_mini_roman(152) == 'clii' >>> int_to_mini_roman(426) == 'cdxxvi' """ num = [1, 4, 5...
int_to_mini_roman
div = number // num[i] number %= num[i] while div: res += sym[i] div -= 1 i -= 1 return res.lower()
def check(candidate): # Check some simple cases assert candidate(19) == 'xix' assert candidate(152) == 'clii' assert candidate(251) == 'ccli' assert candidate(426) == 'cdxxvi' assert candidate(500) == 'd' assert candidate(1) == 'i' assert candidate(4) == 'iv' assert candidate(43) ==...
def int_to_mini_roman(number): """ Given a positive integer, obtain its roman numeral equivalent as a string, and return it in lowercase. Restrictions: 1 <= num <= 1000 Examples: >>> int_to_mini_roman(19) == 'xix' >>> int_to_mini_roman(152) == 'clii' >>> int_to_mini_roman(426) == 'cdxx...
HumanEval/157
def right_angle_triangle(a, b, c): ''' Given the lengths of the three sides of a triangle. Return True if the three sides form a right-angled triangle, False otherwise. A right-angled triangle is a triangle in which one angle is right angle or 90 degree. Example: right_angle_triangle(3, 4, 5) == True right_an...
right_angle_triangle
return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b
def check(candidate): # Check some simple cases assert candidate(3, 4, 5) == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(1, 2, 3) == False assert candidate(10, 6, 8) == True assert candidate(2, 2, 2) == False assert candidate(7, 24, 25) == True assert c...
null
HumanEval/158
def find_max(words): """Write a function that accepts a list of strings. The list contains different words. Return the word with maximum number of unique characters. If multiple strings have maximum number of unique characters, return the one which comes first in lexicographical order. find_max(["name", "of", "s...
find_max
return sorted(words, key = lambda x: (-len(set(x)), x))[0]
def check(candidate): # Check some simple cases assert (candidate(["name", "of", "string"]) == "string"), "t1" assert (candidate(["name", "enam", "game"]) == "enam"), 't2' assert (candidate(["aaaaaaa", "bb", "cc"]) == "aaaaaaa"), 't3' assert (candidate(["abc", "cba"]) == "abc"), 't4' assert (ca...
null
HumanEval/159
def eat(number, need, remaining): """ You're a hungry rabbit, and you already have eaten a certain number of carrots, but now you need to eat more carrots to complete the day's meals. you should return an array of [ total number of eaten carrots after your meals, the number of carrots left after your meal...
eat
else: return [ number + remaining , 0]
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(5, 6, 10) == [11, 4], "Error" assert candidate(4, 8, 9) == [12, 1], "Error" assert candidate(1, 10, 10) == [11, 0], "Error" assert candidate(2, 11, 5) == [7, ...
def eat(number, need, remaining): """ You're a hungry rabbit, and you already have eaten a certain number of carrots, but now you need to eat more carrots to complete the day's meals. you should return an array of [ total number of eaten carrots after your meals, the...
HumanEval/160
def do_algebra(operator, operand): """ Given two lists operator, and operand. The first list has basic algebra operations, and the second list is a list of integers. Use the two given lists to build the algebric expression and return the evaluation of this expression. The basic algebra operations: Addition ( ...
do_algebra
expression+= oprt + str(oprn) return eval(expression)
def check(candidate): # Check some simple cases assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37 assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9 assert candidate(['//', '*'], [7, 3, 4]) == 8, "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are eas...
def do_algebra(operator, operand): """ Given two lists operator, and operand. The first list has basic algebra operations, and the second list is a list of integers. Use the two given lists to build the algebric expression and return the evaluation of this expression. The basic algebra operation...
HumanEval/161
def solve(s): """You are given a string s. if s[i] is a letter, reverse its case from lower to upper or vise versa, otherwise keep it as it is. If the string contains no letters, reverse the string. The function should return the resulted string. Examples solve("1234") = "4321" solve("ab") = "AB" solve("#a@C...
solve
idx += 1 s = "" for i in new_str: s += i if flg == 0: return s[len(s)::-1] return s
def check(candidate): # Check some simple cases assert candidate("AsDf") == "aSdF" assert candidate("1234") == "4321" assert candidate("ab") == "AB" assert candidate("#a@C") == "#A@c" assert candidate("#AsdfW^45") == "#aSDFw^45" assert candidate("#6@2") == "2@6#" # Check some edge case...
def solve(s): """You are given a string s. if s[i] is a letter, reverse its case from lower to upper or vise versa, otherwise keep it as it is. If the string contains no letters, reverse the string. The function should return the resulted string. Examples solve("1234") = "4321" solve("...
HumanEval/162
def string_to_md5(text): """ Given a string 'text', return its md5 hash equivalent string. If 'text' is an empty string, return None. >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62' """ import hashlib
string_to_md5
return hashlib.md5(text.encode('ascii')).hexdigest() if text else None
def check(candidate): # Check some simple cases assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62' assert candidate('') == None assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888' assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99' # Check some edg...
def string_to_md5(text): """ Given a string 'text', return its md5 hash equivalent string. If 'text' is an empty string, return None. >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62' """ import hashlib # print('@@this is the line to split##') return hashlib.md5(te...
HumanEval/163
def generate_integers(a, b): """ Given two positive integers a and b, return the even digits between a and b, in ascending order. For example: generate_integers(2, 8) => [2, 4, 6, 8] generate_integers(8, 2) => [2, 4, 6, 8] generate_integers(10, 14) => [] """ lower = max(2, min(a, b)) upper = min(8, max(a, b...
generate_integers
return [i for i in range(lower, upper+1) if i % 2 == 0]
def check(candidate): # Check some simple cases assert candidate(2, 10) == [2, 4, 6, 8], "Test 1" assert candidate(10, 2) == [2, 4, 6, 8], "Test 2" assert candidate(132, 2) == [2, 4, 6, 8], "Test 3" assert candidate(17,89) == [], "Test 4" # Check some edge cases that are easy to work out by ha...
def generate_integers(a, b): """ Given two positive integers a and b, return the even digits between a and b, in ascending order. For example: generate_integers(2, 8) => [2, 4, 6, 8] generate_integers(8, 2) => [2, 4, 6, 8] generate_integers(10, 14) => [] """ lower = max(2, min(a, b...
HumanEval/0
from typing import List def has_close_elements(numbers: List[float], threshold: float) -> bool: """ Check if in given list of numbers, are any two numbers closer to each other than given threshold. >>> has_close_elements([1.0, 2.0, 3.0], 0.5) False >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) Tru...
has_close_elements
if distance < threshold: return True return False
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True assert candidate([1.0, 2.0, 5.9, 4.0,...
from typing import List def has_close_elements(numbers: List[float], threshold: float) -> bool: """ Check if in given list of numbers, are any two numbers closer to each other than given threshold. >>> has_close_elements([1.0, 2.0, 3.0], 0.5) False >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ...
HumanEval/1
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace is prope...
separate_paren_groups
elif c == ')': current_depth -= 1 current_string.append(c) if current_depth == 0: result.append(''.join(current_string)) current_string.clear() return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('(()()) ((())) () ((())()())') == [ '(()())', '((()))', '()', '((())()())' ] assert candidate('() (()) ((())) (((())))') == [ '()', '(())', '((()))', '(((())))' ] assert candidate('(()...
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace...
HumanEval/2
def truncate_number(number: float) -> float: """ Given a positive floating point number, it can be decomposed into and integer part (largest integer smaller than given number) and decimals (leftover part always smaller than 1). Return the decimal part of the number. >>> truncate_number(3.5) 0.5 """
truncate_number
return number % 1.0
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3.5) == 0.5 assert abs(candidate(1.33) - 0.33) < 1e-6 assert abs(candidate(123.456) - 0.456) < 1e-6
null
HumanEval/3
from typing import List def below_zero(operations: List[int]) -> bool: """ You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return True. Otherw...
below_zero
if balance < 0: return True return False
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == False assert candidate([1, 2, -3, 1, 2, -3]) == False assert candidate([1, 2, -4, 5, 6]) == True assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False assert candidate([1, -1, 2, -2, 5, -5, 4...
from typing import List def below_zero(operations: List[int]) -> bool: """ You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return Tru...
HumanEval/4
from typing import List def mean_absolute_deviation(numbers: List[float]) -> float: """ For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset. Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case): MAD ...
mean_absolute_deviation
return sum(abs(x - mean) for x in numbers) / len(numbers)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6 assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6 assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6
from typing import List def mean_absolute_deviation(numbers: List[float]) -> float: """ For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset. Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this ...
HumanEval/5
from typing import List def intersperse(numbers: List[int], delimeter: int) -> List[int]: """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers' >>> intersperse([], 4) [] >>> intersperse([1, 2, 3], 4) [1, 4, 2, 4, 3] """ if not numbers: return [] result = [] for n ...
intersperse
result.append(n) result.append(delimeter) result.append(numbers[-1]) return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([], 7) == [] assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2] assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]
from typing import List def intersperse(numbers: List[int], delimeter: int) -> List[int]: """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers' >>> intersperse([], 4) [] >>> intersperse([1, 2, 3], 4) [1, 4, 2, 4, 3] """ if not numbers: retur...
HumanEval/6
from typing import List def parse_nested_parens(paren_string: str) -> List[int]: """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces. For each of the group, output the deepest level of nesting of parentheses. E.g. (()()) has maximum two levels of nesting wh...
parse_nested_parens
max_depth = max(depth, max_depth) else: depth -= 1 return max_depth return [parse_paren_group(x) for x in paren_string.split(' ') if x]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3] assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4] assert candidate('(()(())((())))') == [4]
from typing import List def parse_nested_parens(paren_string: str) -> List[int]: """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces. For each of the group, output the deepest level of nesting of parentheses. E.g. (()()) has maximum two levels of n...
HumanEval/7
from typing import List def filter_by_substring(strings: List[str], substring: str) -> List[str]: """ Filter an input list of strings only for ones that contain given substring >>> filter_by_substring([], 'a') [] >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a') ['abc', 'bacd', 'array'] """
filter_by_substring
return [x for x in strings if substring in x]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([], 'john') == [] assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx'] assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx...
null
HumanEval/8
from typing import List, Tuple def sum_product(numbers: List[int]) -> Tuple[int, int]: """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list. Empty sum should be equal to 0 and empty product should be equal to 1. >>> sum_product([]) (0, 1) >>> sum_produc...
sum_product
for n in numbers: sum_value += n prod_value *= n return sum_value, prod_value
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == (0, 1) assert candidate([1, 1, 1]) == (3, 1) assert candidate([100, 0]) == (100, 0) assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7) assert candidate([10]) == (10, 10)
from typing import List, Tuple def sum_product(numbers: List[int]) -> Tuple[int, int]: """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list. Empty sum should be equal to 0 and empty product should be equal to 1. >>> sum_product([]) (0, 1) ...
HumanEval/9
from typing import List, Tuple def rolling_max(numbers: List[int]) -> List[int]: """ From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence. >>> rolling_max([1, 2, 3, 2, 3, 4, 2]) [1, 2, 3, 3, 3, 4, 4] """ running_max = None result = [] for n in num...
rolling_max
else: running_max = max(running_max, n) result.append(running_max) return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4] assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4] assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]
from typing import List, Tuple def rolling_max(numbers: List[int]) -> List[int]: """ From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence. >>> rolling_max([1, 2, 3, 2, 3, 4, 2]) [1, 2, 3, 3, 3, 4, 4] """ running_max = None resul...
HumanEval/10
def is_palindrome(string: str) -> bool: """ Test if given string is a palindrome """ return string == string[::-1] def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string that is a pali...
make_palindrome
while not is_palindrome(string[beginning_of_suffix:]): beginning_of_suffix += 1 return string + string[:beginning_of_suffix][::-1]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('x') == 'x' assert candidate('xyz') == 'xyzyx' assert candidate('xyx') == 'xyx' assert candidate('jerry') == 'jerryrrej'
def is_palindrome(string: str) -> bool: """ Test if given string is a palindrome """ return string == string[::-1] def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string...
HumanEval/11
from typing import List def string_xor(a: str, b: str) -> str: """ Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string. >>> string_xor('010', '110') '100' """ def xor(i, j): if i == j: return '0'
string_xor
else: return '1' return ''.join(xor(x, y) for x, y in zip(a, b))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('111000', '101010') == '010010' assert candidate('1', '1') == '0' assert candidate('0101', '0000') == '0101'
from typing import List def string_xor(a: str, b: str) -> str: """ Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string. >>> string_xor('010', '110') '100' """ def xor(i, j): if i == j: return '0' ...
HumanEval/12
from typing import List, Optional def longest(strings: List[str]) -> Optional[str]: """ Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty. >>> longest([]) >>> longest(['a', 'b', 'c']) 'a' >>> longest(...
longest
maxlen = max(len(x) for x in strings) for s in strings: if len(s) == maxlen: return s
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == None assert candidate(['x', 'y', 'z']) == 'x' assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'
from typing import List, Optional def longest(strings: List[str]) -> Optional[str]: """ Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty. >>> longest([]) >>> longest(['a', 'b', 'c']) 'a...
HumanEval/13
def greatest_common_divisor(a: int, b: int) -> int: """ Return a greatest common divisor of two integers a and b >>> greatest_common_divisor(3, 5) 1 >>> greatest_common_divisor(25, 15) 5 """ while b:
greatest_common_divisor
a, b = b, a % b return a
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3, 7) == 1 assert candidate(10, 15) == 5 assert candidate(49, 14) == 7 assert candidate(144, 60) == 12
def greatest_common_divisor(a: int, b: int) -> int: """ Return a greatest common divisor of two integers a and b >>> greatest_common_divisor(3, 5) 1 >>> greatest_common_divisor(25, 15) 5 """ while b: # print('@@this is the line to split##') a, b = b, a % b return a
HumanEval/14
from typing import List def all_prefixes(string: str) -> List[str]: """ Return list of all prefixes from shortest to longest of the input string >>> all_prefixes('abc') ['a', 'ab', 'abc'] """ result = []
all_prefixes
for i in range(len(string)): result.append(string[:i+1]) return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == [] assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh'] assert candidate('WWW') == ['W', 'WW', 'WWW']
from typing import List def all_prefixes(string: str) -> List[str]: """ Return list of all prefixes from shortest to longest of the input string >>> all_prefixes('abc') ['a', 'ab', 'abc'] """ result = [] # print('@@this is the line to split##') for i in range(len(string)): result....
HumanEval/15
def string_sequence(n: int) -> str: """ Return a string containing space-delimited numbers starting from 0 upto n inclusive. >>> string_sequence(0) '0' >>> string_sequence(5) '0 1 2 3 4 5' """
string_sequence
return ' '.join([str(x) for x in range(n + 1)])
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(0) == '0' assert candidate(3) == '0 1 2 3' assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'
null
HumanEval/16
def count_distinct_characters(string: str) -> int: """ Given a string, find out how many distinct characters (regardless of case) does it consist of >>> count_distinct_characters('xyzXYZ') 3 >>> count_distinct_characters('Jerry') 4 """
count_distinct_characters
return len(set(string.lower()))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == 0 assert candidate('abcde') == 5 assert candidate('abcde' + 'cade' + 'CADE') == 5 assert candidate('aaaaAAAAaaaa') == 1 assert candidate('Jerry jERRY JeRRRY') == 5
null
HumanEval/17
from typing import List def parse_music(music_string: str) -> List[int]: """ Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: 'o' - whole no...
parse_music
return [note_map[x] for x in music_string.split(' ') if x]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == [] assert candidate('o o o o') == [4, 4, 4, 4] assert candidate('.| .| .| .|') == [1, 1, 1, 1] assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4] assert candidate('o| .| o| .| ...
from typing import List def parse_music(music_string: str) -> List[int]: """ Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: ...
HumanEval/18
def how_many_times(string: str, substring: str) -> int: """ Find how many times a given substring can be found in the original string. Count overlaping cases. >>> how_many_times('', 'a') 0 >>> how_many_times('aaa', 'a') 3 >>> how_many_times('aaaa', 'aa') 3 """ times = 0 for i in range(len(string) - len(sub...
how_many_times
if string[i:i+len(substring)] == substring: times += 1 return times
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('', 'x') == 0 assert candidate('xyxyxyx', 'x') == 4 assert candidate('cacacacac', 'cac') == 4 assert candidate('john doe', 'john') == 1
def how_many_times(string: str, substring: str) -> int: """ Find how many times a given substring can be found in the original string. Count overlaping cases. >>> how_many_times('', 'a') 0 >>> how_many_times('aaa', 'a') 3 >>> how_many_times('aaaa', 'aa') 3 """ times = 0 for i ...
HumanEval/19
from typing import List def sort_numbers(numbers: str) -> str: """ Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest >>> sort_numb...
sort_numbers
'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9 } return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('three') == 'three' assert candidate('three five nine') == 'three five nine' assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine' assert ...
from typing import List def sort_numbers(numbers: str) -> str: """ Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest >...
HumanEval/20
from typing import List, Tuple def find_closest_elements(numbers: List[float]) -> Tuple[float, float]: """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number). >>> find_closest_elements([1.0, 2.0,...
find_closest_elements
closest_pair = tuple(sorted([elem, elem2])) else: new_distance = abs(elem - elem2) if new_distance < distance: distance = new_distance closest_pair = tuple(sorted([elem, elem2])) return close...
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0) assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9) assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2) assert candidate([1.0, 2.0, 3.0, 4.0,...
from typing import List, Tuple def find_closest_elements(numbers: List[float]) -> Tuple[float, float]: """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number). >>> find_closest_elements([...
HumanEval/21
from typing import List def rescale_to_unit(numbers: List[float]) -> List[float]: """ Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1 >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0]) [0.0, 0.25, 0.5, 0...
rescale_to_unit
max_number = max(numbers) return [(x - min_number) / (max_number - min_number) for x in numbers]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([2.0, 49.9]) == [0.0, 1.0] assert candidate([100.0, 49.9]) == [1.0, 0.0] assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0] assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0....
from typing import List def rescale_to_unit(numbers: List[float]) -> List[float]: """ Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1 >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0]) [0.0, ...
HumanEval/22
from typing import List, Any def filter_integers(values: List[Any]) -> List[int]: """ Filter given list of any python values only for integers >>> filter_integers(['a', 3.14, 5]) [5] >>> filter_integers([1, 2, 3, 'abc', {}, []]) [1, 2, 3] """
filter_integers
return [x for x in values if isinstance(x, int)]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9] assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]
null
HumanEval/23
def strlen(string: str) -> int: """ Return length of given string >>> strlen('') 0 >>> strlen('abc') 3 """
strlen
return len(string)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == 0 assert candidate('x') == 1 assert candidate('asdasnakj') == 9
null
HumanEval/24
def largest_divisor(n: int) -> int: """ For a given number n, find the largest number that divides n evenly, smaller than n >>> largest_divisor(15) 5 """ for i in reversed(range(n)):
largest_divisor
if n % i == 0: return i
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3) == 1 assert candidate(7) == 1 assert candidate(10) == 5 assert candidate(100) == 50 assert candidate(49) == 7
def largest_divisor(n: int) -> int: """ For a given number n, find the largest number that divides n evenly, smaller than n >>> largest_divisor(15) 5 """ for i in reversed(range(n)): # print('@@this is the line to split##') if n % i == 0: return i
HumanEval/25
from typing import List def factorize(n: int) -> List[int]: """ Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the product of all ...
factorize
n //= i else: i += 1 if n > 1: fact.append(n) return fact
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(2) == [2] assert candidate(4) == [2, 2] assert candidate(8) == [2, 2, 2] assert candidate(3 * 19) == [3, 19] assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19] assert candidate(3 * 19 * 3 * 19 * ...
from typing import List def factorize(n: int) -> List[int]: """ Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the produc...
HumanEval/26
from typing import List def remove_duplicates(numbers: List[int]) -> List[int]: """ From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input. >>> remove_duplicates([1, 2, 3, 2, 4]) [1, 3, 4] """ import collections
remove_duplicates
c = collections.Counter(numbers) return [n for n in numbers if c[n] <= 1]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4] assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
from typing import List def remove_duplicates(numbers: List[int]) -> List[int]: """ From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input. >>> remove_duplicates([1, 2, 3, 2, 4]) [1, 3, 4] """ import collections # print(...
HumanEval/27
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flip_case('Hello') 'hELLO' """
flip_case
return string.swapcase()
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('Hello!') == 'hELLO!' assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'
null
HumanEval/28
from typing import List def concatenate(strings: List[str]) -> str: """ Concatenate list of strings into a single string >>> concatenate([]) '' >>> concatenate(['a', 'b', 'c']) 'abc' """
concatenate
return ''.join(strings)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == '' assert candidate(['x', 'y', 'z']) == 'xyz' assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'
null
HumanEval/29
from typing import List def filter_by_prefix(strings: List[str], prefix: str) -> List[str]: """ Filter an input list of strings only for ones that start with a given prefix. >>> filter_by_prefix([], 'a') [] >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a') ['abc', 'array'] """
filter_by_prefix
return [x for x in strings if x.startswith(prefix)]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([], 'john') == [] assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
null
HumanEval/30
def get_positive(l: list): """Return only positive numbers in the list. >>> get_positive([-1, 2, -4, 5, 6]) [2, 5, 6] >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) [5, 3, 2, 3, 9, 123, 1] """
get_positive
return [e for e in l if e > 0]
METADATA = {} def check(candidate): assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6] assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1] assert candidate([-1, -2]) == [] assert candidate([]) == []
null
HumanEval/31
def is_prime(n): """Return true if a given number is prime, and false otherwise. >>> is_prime(6) False >>> is_prime(101) True >>> is_prime(11) True >>> is_prime(13441) True >>> is_prime(61) True >>> is_prime(4) False >>> is_prime(1) False """ if n < 2: return False for k in range(2, n - 1):
is_prime
if n % k == 0: return False return True
METADATA = {} def check(candidate): assert candidate(6) == False assert candidate(101) == True assert candidate(11) == True assert candidate(13441) == True assert candidate(61) == True assert candidate(4) == False assert candidate(1) == False assert candidate(5) == True assert ca...
def is_prime(n): """Return true if a given number is prime, and false otherwise. >>> is_prime(6) False >>> is_prime(101) True >>> is_prime(11) True >>> is_prime(13441) True >>> is_prime(61) True >>> is_prime(4) False >>> is_prime(1) False """ if n < ...
HumanEval/32
import math def poly(xs: list, x: float): """ Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n """ return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def find_zero(xs: list): """ xs are coefficients of a polynomial. find_zero find...
find_zero
center = (begin + end) / 2.0 if poly(xs, center) * poly(xs, begin) > 0: begin = center else: end = center return begin
METADATA = {} def check(candidate): import math import random rng = random.Random(42) import copy for _ in range(100): ncoeff = 2 * rng.randint(1, 4) coeffs = [] for _ in range(ncoeff): coeff = rng.randint(-10, 10) if coeff == 0: co...
import math def poly(xs: list, x: float): """ Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n """ return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def find_zero(xs: list): """ xs are coefficients of a polynomia...
HumanEval/33
def sort_third(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted. >>> sort_third([1, 2, ...
sort_third
l[::3] = sorted(l[::3]) return l
METADATA = {} def check(candidate): assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3])) assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(so...
def sort_third(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted. >>> sort_t...
HumanEval/34
def unique(l: list): """Return sorted unique elements in a list >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123]) [0, 2, 3, 5, 9, 123] """
unique
return sorted(list(set(l)))
METADATA = {} def check(candidate): assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
null
HumanEval/35
def max_element(l: list): """Return maximum element in the list. >>> max_element([1, 2, 3]) 3 >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) 123 """ m = l[0] for e in l:
max_element
if e > m: m = e return m
METADATA = {} def check(candidate): assert candidate([1, 2, 3]) == 3 assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124
def max_element(l: list): """Return maximum element in the list. >>> max_element([1, 2, 3]) 3 >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) 123 """ m = l[0] for e in l: # print('@@this is the line to split##') if e > m: m = e return m
HumanEval/36
def fizz_buzz(n: int): """Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13. >>> fizz_buzz(50) 0 >>> fizz_buzz(78) 2 >>> fizz_buzz(79) 3 """ ns = [] for i in range(n): if i % 11 == 0 or i % 13 == 0: ns.append(i)
fizz_buzz
s = ''.join(list(map(str, ns))) ans = 0 for c in s: ans += (c == '7') return ans
METADATA = {} def check(candidate): assert candidate(50) == 0 assert candidate(78) == 2 assert candidate(79) == 3 assert candidate(100) == 3 assert candidate(200) == 6 assert candidate(4000) == 192 assert candidate(10000) == 639 assert candidate(100000) == 8026
def fizz_buzz(n: int): """Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13. >>> fizz_buzz(50) 0 >>> fizz_buzz(78) 2 >>> fizz_buzz(79) 3 """ ns = [] for i in range(n): if i % 11 == 0 or i % 13 == 0: ns.app...
HumanEval/37
def sort_even(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted. >>> sort_even([1, 2, 3]) [1, 2, 3] >>> sort_even([5, 6, 3, 4]) [3, 6, 5, 4] """...
sort_even
for e, o in zip(evens, odds): ans.extend([e, o]) if len(evens) > len(odds): ans.append(evens[-1]) return ans
METADATA = {} def check(candidate): assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3]) assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123]) assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 1...
def sort_even(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted. >>> sort_even([1, 2, 3]) [1, 2, 3] >>> sort_even([5, 6, 3, 4]) ...
HumanEval/38
def encode_cyclic(s: str): """ returns encoded string by cycling groups of three characters. """ # split string to groups. Each of length 3. groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)] # cycle elements in each group. Unless group has fewer elements than 3. groups = [(group[...
decode_cyclic
return encode_cyclic(encode_cyclic(s))
METADATA = {} def check(candidate): from random import randint, choice import string letters = string.ascii_lowercase for _ in range(100): str = ''.join(choice(letters) for i in range(randint(10, 20))) encoded_str = encode_cyclic(str) assert candidate(encoded_str) == str
null
HumanEval/39
def prime_fib(n: int): """ prime_fib returns n-th number that is a Fibonacci number and it's also prime. >>> prime_fib(1) 2 >>> prime_fib(2) 3 >>> prime_fib(3) 5 >>> prime_fib(4) 13 >>> prime_fib(5) 89 """ import math def is_prime(p): if p < 2: return False for k in range(2, min(int(math.sqrt(p...
prime_fib
return True f = [0, 1] while True: f.append(f[-1] + f[-2]) if is_prime(f[-1]): n -= 1 if n == 0: return f[-1]
METADATA = {} def check(candidate): assert candidate(1) == 2 assert candidate(2) == 3 assert candidate(3) == 5 assert candidate(4) == 13 assert candidate(5) == 89 assert candidate(6) == 233 assert candidate(7) == 1597 assert candidate(8) == 28657 assert candidate(9) == 514229 ...
def prime_fib(n: int): """ prime_fib returns n-th number that is a Fibonacci number and it's also prime. >>> prime_fib(1) 2 >>> prime_fib(2) 3 >>> prime_fib(3) 5 >>> prime_fib(4) 13 >>> prime_fib(5) 89 """ import math def is_prime(p): if p < 2: ...
HumanEval/40
def triples_sum_to_zero(l: list): """ triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise. >>> triples_sum_to_zero([1, 3, 5, 0]) False >>> triples_sum_to_zero([1, 3, -2, 1]) True >>> triples_sum_to_z...
triples_sum_to_zero
if l[i] + l[j] + l[k] == 0: return True return False
METADATA = {} def check(candidate): assert candidate([1, 3, 5, 0]) == False assert candidate([1, 3, 5, -1]) == False assert candidate([1, 3, -2, 1]) == True assert candidate([1, 2, 3, 7]) == False assert candidate([1, 2, 5, 7]) == False assert candidate([2, 4, -5, 3, 9, 7]) == True asser...
def triples_sum_to_zero(l: list): """ triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise. >>> triples_sum_to_zero([1, 3, 5, 0]) False >>> triples_sum_to_zero([1, 3, -2, 1]) Tr...
HumanEval/41
def car_race_collision(n: int): """ Imagine a road that's a perfectly straight infinitely long line. n cars are driving left to right; simultaneously, a different set of n cars are driving right to left. The two sets of cars start out being very far from each other. All cars move in the same speed. Two cars...
car_race_collision
return n**2
METADATA = {} def check(candidate): assert candidate(2) == 4 assert candidate(3) == 9 assert candidate(4) == 16 assert candidate(8) == 64 assert candidate(10) == 100
null
HumanEval/42
def incr_list(l: list): """Return list with elements incremented by 1. >>> incr_list([1, 2, 3]) [2, 3, 4] >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123]) [6, 4, 6, 3, 4, 4, 10, 1, 124] """
incr_list
return [(e + 1) for e in l]
METADATA = {} def check(candidate): assert candidate([]) == [] assert candidate([3, 2, 1]) == [4, 3, 2] assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]
null
HumanEval/43
def pairs_sum_to_zero(l): """ pairs_sum_to_zero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise. >>> pairs_sum_to_zero([1, 3, 5, 0]) False >>> pairs_sum_to_zero([1, 3, -2, 1]) False >>> pairs_sum_to_zero([1, 2, 3, 7]) ...
pairs_sum_to_zero
if l1 + l[j] == 0: return True return False
METADATA = {} def check(candidate): assert candidate([1, 3, 5, 0]) == False assert candidate([1, 3, -2, 1]) == False assert candidate([1, 2, 3, 7]) == False assert candidate([2, 4, -5, 3, 5, 7]) == True assert candidate([1]) == False assert candidate([-3, 9, -1, 3, 2, 30]) == True asser...
def pairs_sum_to_zero(l): """ pairs_sum_to_zero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise. >>> pairs_sum_to_zero([1, 3, 5, 0]) False >>> pairs_sum_to_zero([1, 3, -2, 1]) False >>> pairs...