blob_id stringlengths 40 40 | repo_name stringlengths 5 127 | path stringlengths 2 523 | length_bytes int64 22 3.06M | score float64 3.5 5.34 | int_score int64 4 5 | text stringlengths 22 3.06M |
|---|---|---|---|---|---|---|
ee0ca87dc7393247fc507193b6ef22c4c97c1293 | MeitarEitan/Devops0803 | /9.py | 343 | 3.796875 | 4 | def saveNames():
inputUser = input("Enter your name:")
myNewFile = open("names.txt", "a")
myNewFile.write(inputUser + "\n")
myNewFile.close()
def printNames():
file = open("names.txt", "r")
for name in file.readlines():
print(name, end=" ")
file.close()
saveNames()
saveNames()
sa... |
17c0945cae7677615b0f2b181b12505ebfadb0fd | varunpsr/python-ds | /binary-search-tree.py | 2,061 | 4.0625 | 4 | class Node:
def __init__(self, value):
self.value = value
self.left = None
self.right = None
def __str__(self):
if self is not None:
return f"{self.value}"
else:
return "None"
class BinarySearchTree:
def __init__(self):
... |
6e49ad323b536ee1e669d1ce643959b66da67823 | python-fisika-uin/Fundamental | /fundamental001.py | 1,367 | 3.8125 | 4 | # Sintaks Sekuensial
print('Hello World!')
nama = 'Eko S.W'
usia = 40
Usia = 50 #ini berbeda dengan usia (huruf kecil)
print(nama, 'Usia=', usia)
# Sintaks bercabang
if usia <= 40:
print('Masih muda')
print('Usia belajar')
print('Usia mencari jatidiri')
else:
print('Tak muda lagi')
print('Banyakin tobat')
... |
bc8744b8265be788f974f5bd0a5c9b24f26da35d | xinzheshen/py3-practice | /src/cookbook/09_yuanbiancheng/decoretor0.py | 735 | 3.546875 | 4 | import time
from functools import wraps
def timethis(func):
'''
Decorator that reports the execution time.
'''
# 注意加不加@wraps的区别
@wraps(func)
def wrapper(*args, **kwargs):
start = time.time()
result = func(*args, **kwargs)
end = time.time()
print(func.__name__, en... |
03175236c641b680cf7e47e78e13c6f3bece9a72 | Aptegit/Assignment1 | /new_testcode.py | 751 | 4.09375 | 4 | #!/usr/bin/env python
# coding: utf-8
# In[1]:
obill =float(input('How much is your original bill? ')) #input string
# In[2]:
print(type(obill)) #to check the data type of variable
# In[3]:
tip = int(input('What percentage is your tip?')) #input string
# In[4]:
print(type(tip)) #to check the data typ... |
f7202c99351112f2da3783118059f6d02c040d1d | jameswong95/ICT1008 | /block_stack.py | 1,341 | 3.890625 | 4 | class Stack:
top = -1
def __init__(self):
self.top = -1
# this stack is implemented with Python list (array)
self.data = []
def size(self):
return len(self.data)
def push(self, value):
# increment the size of data using append()
self.data.append(value)... |
8e803130fffcc7f8139e4125c2e1fa451becba71 | binjun/LeetCode | /longestpalindromicsubstring.py | 1,196 | 4.0625 | 4 | # -*- coding: utf-8 -*-
"""
Given a string s, find the longest palindromic substring in s.
You may assume that the maximum length of s is 1000.
Example1:
Input: "babad"
Output: "bab"
Note: "aba" is also a valid answer.
Example2:
Input: "cbbd"
Output: "bb"
"""
import unittest
class Solution(object):
def longestPa... |
2512fbd72639a9c9d35adad3ddbb2c4e9b032ace | shivam-72/simple-python | /PYTHON FUN/lovecalculator.py | 798 | 3.890625 | 4 | print("Welcome to the Love Calculator!")
name1 = input("What is your name? \n")
name2 = input("What is their name? \n")
name1.lower()
name2.lower()
name3 = name1+name2
T = name3.count("t")
R = name3.count("r")
U = name3.count("u")
E = name3.count("e")
total = str(T+R+U+E)
L = name3.count("l")
O = name3.coun... |
e547651f91838d65f910be328522ef1e196652a4 | salemmp/memorize-words | /words.py | 1,626 | 3.71875 | 4 | import os
import sys
import time
lista = {"hello":"hola",
"word":"palabra",
"phone":"celular",
"hand":"mano",
"how":"como",
"people":"gente",
"leave":"salir",
"key":"tecla",
"understand":"entender",
"can":"poder",
"we... |
a383e4a8701f7c9ab85f7295dc309bb4609902f9 | lianhuo-yiyu/python-study | /study9 str/main.py | 464 | 4.09375 | 4 | #str的驻留机制 指相同的字符串只会占据一个内存空间，一个字符串只被创建一次，之后新的变量是获得之前的字符串的地址
a = 'python'
b = "python"
c = """python"""
print(id(a))
print(id(b))
print(id(c))
s1 = ''
s2 = ''
print(s1 == s2)
print(s1 is s2)
print(id(s1))
print(id(s2))
#理论上有特殊字符串不驻留，下面这个cmd不驻留，pycharm进行了优化
z1 = 'a%'
z2 = 'a%'
print(id(z1))
print(id(z2)) |
94c2379bf1ab91f31e7fcb57dee06b37b00d3a14 | lianhuo-yiyu/python-study | /study6 dict/main.py | 824 | 4.09375 | 4 | #字典 { } 可变序列 dict 以键值对的方式存储数据 ｛name : hhh｝:前面的叫键，：后面的叫值 字典是无序的序列 字典存储是key时经过hash计算
#字典的键key不允许重复，只有值可以重复，后面的键值会覆盖相同的键名 列表可以按照自己的想法找地方插入元素，dict不行，它是无序的 字典空间换时间，内存浪费大
zidian = {'name' : 'python' , "nianling" : 24}
print(zidian)
c = dict(name = 'python', nian = 100)
print(type(c))
print(c)
#字典中的值获取
print... |
1f5f1540137ef46b49d62027955fa15f46dc14e1 | lianhuo-yiyu/python-study | /STUDY10 函数/递归函数.py | 393 | 3.875 | 4 | # Python 学习 1
# 2020/11/28 17:12
#递归函数 一个函数调用自己
#递归用来计算阶乘
def fac(n):
if n ==1:
return 1
else:
return n *fac(n - 1)
print(fac(6))
def text(n):
for i in range(1,n):
if i == 1 :
print('1')
elif i == 2 :
print('1','1')
elif i != 1 and i !=2 :
pr... |
5cd01bde10307074f0c003b09c034b799fb36965 | lianhuo-yiyu/python-study | /STUDY10 函数/main.py | 1,775 | 4.0625 | 4 | #函数的原理与利用
#函数的创建
#def 函数名([输入参数]):
# 函数体
# [return xxx]
def cale(a,b):
# c = a + b
c = a - b
return c
result = cale(10,20)
print(result)
#函数调用时的参数传递 创建的时候函数括号里面是def hhh(形参，形参)， 在函数的调用处，括号里面的是实参，实际参数 形参和实参的名字可以不相同
#参数的传递（实参的值传给形参）
#1 位置实参 如上例，按存放的第一个第二个位置传递
#2 关键字传参，就是将形参自行按需求赋值
result2 = cal... |
ea03689b8be9bd5fab6af7d4e20d2ceae0d8e88b | reesporte/euler | /3/p3.py | 534 | 4.125 | 4 | """
project euler problem 3
"""
def is_prime(num):
if num == 1:
return False
i = 2
while i*i <= num:
if num % i == 0:
return False
i += 1
return True
def get_largest_prime_factor(num):
largest = 0
i = 2
while i*i <= num:
if num%i == 0:
... |
8063a87ba1e389e833699bfdc6378698ae8490a7 | reesporte/euler | /19/p_19.py | 1,608 | 4.03125 | 4 | """
project euler problem 19
"""
def is_leap_year(year):
if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
return True
return False
def get_days_in_month(month, year):
months = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
if month == 2 and is_leap_year(year):
return 29
... |
567820cdb4e2c97509d232fe441e2f9b6a58a34b | jayden-nguyen/Homework2--NguyenQuangHuy | /homework4/serious2.py | 1,364 | 3.9375 | 4 | prices = {"banana" : 4,
"apple" : 2,
"orange" : 1.5,
"pear" : 3}
li = prices.keys()
purchased = {
"banana": 5,
"orange":3
}
print("YOU BOUGHT 5 BANANAS AND 3 ORANGES")
choice = "yes"
while choice.lower() != "no":
choice = input("Do you want more(yes or no, press no... |
d0131c5e298483388d06683c5f60046a570ba2eb | ErickHernandez/ProyectoCompiladores | /pyfiles/gcd.py | 290 | 4.09375 | 4 | # Program to compute the GCD
# Funcion que calcula el maximo comun divisor
def gcd(a, b):
if b == 0:
return a
else:
return gcd(b, a % b)
x = input("Introduzca un numero: ")
y = input("Introduzca otro numero: ")
z = gcd(x, y)
print "El maximo comun divisor es ", z
|
ed5d3fc73cc8479689a580b926346d098d467c71 | sajjanparida/DS-Algorithms | /Sorting/tripletwithlessthansum.py | 406 | 3.90625 | 4 |
# program to find the count of triplets with sum less than given number
def triplets_sum(arr,n,req_sum):
c=0
arr.sort()
for k in range(0,n-2):
i=k+1
j=n-1
while i<j:
if arr[k] + arr[i] + arr[j] < req_sum:
c += j-i
i += 1
else... |
2fc28c8c55ff62b44ecf16f3094d41dee4c3a012 | sajjanparida/DS-Algorithms | /LinkedList/Introduction.py | 428 | 3.953125 | 4 |
class Node:
def __init__(self,data):
self.data=data
self.next=None
class LinkedList:
def __init__(self):
self.head=None
def printList(self):
temp=self.head
while(temp):
print(temp.data)
temp = temp.next
llist = LinkedList()
first=Node(... |
c050dc01202dce89bf26ea6f125d3410d2177a50 | sajjanparida/DS-Algorithms | /Sorting/subarraysumcount.py | 390 | 3.6875 | 4 |
def countOfSubarray(arr,n):
i=-1
count=0
sum=0
freq={}
freq[sum]=1
while i < n-1:
i +=1
sum += arr[i]
if freq.get(sum) != None:
count += freq[sum]
freq[sum]=freq[sum]+1
else:
freq[sum]=1
return count
arr=[0,0,5,5,0,0]
pr... |
2529bc8fce8c1186cf9325d6ef1479f22adb9e1f | sajjanparida/DS-Algorithms | /Sorting/productarraypuzzle.py | 622 | 3.703125 | 4 | def productExceptSelf(nums, n):
#code here
zeroflag=0
product=1
if n==1:
return 1
for i in range(0,n):
if nums[i]!= 0 :
product *= nums[i]
else:
zeroflag += 1
if zeroflag==1:
for i in range(0,n):
if nums[i]==0:
... |
f6063a11518b1fcc2bc653ed3f505dddc9ad4dbf | sajjanparida/DS-Algorithms | /Arrays/Three_way_partition.py | 925 | 4.09375 | 4 | # Given an array of size n and a range [a, b]. The task is to partition the array around the range such that array is divided into three parts.
# 1) All elements smaller than a come first.
# 2) All elements in range a to b come next.
# 3) All elements greater than b appear in the end.
# The individual elements of three... |
bbeb124cd35e865c17ae7a9691022031b81ba553 | jonahtjandra/sudoku-solver | /Sudoku.py | 2,939 | 4.15625 | 4 | class Sudoku:
def __init__(self, board:'list[list]') -> None:
if (len(board) != 9 or len(board[0]) != 9): raise "Expected a 9 by 9 board"
self.board = board
self.iterations = []
# for printing out the 2d list representation of the board
def display(self, board:'list[list]'):
... |
18d4f634488453133535b594fdff3fb8d851f6af | Yokohama-Miyazawa/uec_django | /presen/veiw_tetris.py | 3,312 | 3.734375 | 4 | import tkinter as tk
from random import choice
class Game():
WIDTH = 300
HEIGHT = 500
def start(self):
self.speed = 150
self.new_game = True
self.root = tk.Tk()
self.root.title("Tetris")
self.canvas = tk.Canvas(
self.root,
width=Game.WIDTH... |
4e3ae8718dd37281e9b8dbf85d2df92c555efd48 | 50417/phd | /learn/challenges/020-highest-product.py | 953 | 3.5 | 4 | #!/usr/bin/env python3
from collections import deque
from typing import List
def approach1(lst: List[int]) -> int:
if not isinstance(lst, list):
raise TypeError
if len(lst) < 3:
raise ValueError
if any(x is None for x in lst):
raise TypeError
best = deque(sorted(lst[:3]))
for x in lst[3:]:
... |
54d2e882b8d9a188ffdef473ad3e6372c1d3f0fd | 50417/phd | /learn/challenges/018-list-binary-tree.py | 2,489 | 3.8125 | 4 | #!/usr/bin/env python3
from collections import deque
from typing import List
class Node(object):
def __init__(self, data):
self.data = data
self.left = None
self.right = None
def __lt__(self, rhs: "Node"):
return self.data < rhs.data
def __eq__(self, rhs: "Node"):
return self.data == rhs.... |
b490ccfe7a99436aa96f5e9ad6d04c83caaba021 | YinglunYin/MachineLearning-CS6140 | /2-Linear&RidgeRegression/src/problem2.py | 4,487 | 3.75 | 4 | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Wed Feb 14 12:32:58 2018
CS6140 Assignment2 Gradient Descent Problem2
@author: Garrett
"""
from sklearn import linear_model
import math
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
# reader
def dataset_reader(file):
return n... |
fd289fe5c232aa58735368aff954409d808adf02 | Black-Eagle-1/driving | /driving.py | 248 | 3.84375 | 4 | country = input('你所在的國家: ')
age = input('你的年齡: ')
age = int(age)
if country == '美國' and age >= 16:
print('你可以開車')
elif country == '台灣' and age >= 18:
print('你可以開車')
else:
print('你不能開車')
|
11ec0890ed9eb2c6540f1c8c34eb778c8302fd46 | wxmsummer/algorithm | /leetcode/hot/605_canPlaceFlowers.py | 851 | 4.0625 | 4 | # 605.种花问题
from typing import List
class Solution:
# 模拟法，如果该位置、该位置的前一个位置、该位置的后一个位置没种，就种上
def canPlaceFlowers(self, flowerbed: List[int], n: int) -> bool:
length = len(flowerbed)
count = 0
for i in range(length):
# 注意数组越界
if flowerbed[i] == 1 or (i > 0 and flower... |
87f761c182e6d122e69d9d5d9c44d896fd729655 | wxmsummer/algorithm | /leetcode/offer/offer14_cuttingRope.py | 759 | 3.90625 | 4 | # 剪绳子
import math
# 数学证明
# 任何大于1的数都可由2和3相加组成
# 当n>=5时,将它剪成2或3的绳子段,2(n-2) > n,3(n-3) > n,都大于他未拆分前的情况，
# 当n>=5时，3(n-3) >= 2(n-2),所以我们尽可能地多剪3的绳子段
# 当绳子长度被剪到只剩4时，2 * 2 = 4 > 1 * 3,所以没必要继续剪
class Solution:
def cuttingRope(self, n: int) -> int:
if n <= 3:
return n - 1
a = n // 3
b ... |
23b9938f61e413a65cee12d5501680271b7d622a | wxmsummer/algorithm | /leetcode/hot/222_countNodes.py | 1,281 | 3.6875 | 4 | # Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
# 层序遍历，暴力法
def countNodes(self, root: TreeNode) -> int:
if not root:
return 0
stack = [root]
coun... |
eeeace6a1d48324c28845d51b89535f2527a72e2 | wxmsummer/algorithm | /leetcode/hot/77_combine.py | 742 | 3.75 | 4 | # 组合
class Solution:
def combine(self, n: int, k: int) -> list:
# 回溯法，idx为当前元素，cur为当前解
def backtrack(idx, cur):
# 如果当前解符合要求，就加入解集
if len(cur) == k:
res.append(cur[:])
# 遍历当前位置后面的元素
for i in range(idx, n+1):
print('cur:'... |
8c80e03f0044efa8379d202302807430cb5b5ee4 | wxmsummer/algorithm | /leetcode/hot/49_groupAnagrams.py | 658 | 3.703125 | 4 | # 字母异位词分组
class Solution:
# 将单词转换为列表后按字典序排序
# 使用dic保存分组
def groupAnagrams(self, strs:list) -> list:
dic = {}
length = len(strs)
for i in range(length):
l = list(strs[i])
l.sort()
s = ''.join(l)
if s in dic:
dic[s].append... |
6d655a04136f2a2bf3f4ad5c6726e6c3cf886d5d | wxmsummer/algorithm | /leetcode/hot/383_ransom.py | 386 | 3.515625 | 4 | ransomNote = input()
magazine = input()
list_1 = list(ransomNote)
list_2 = list(magazine)
for i in range(len(list_1)):
print(list_1)
print(list_2)
if list_1[0] not in list_2:
print(0)
break
else:
list_2.remove(list_1[0])
del list_1[0]
continue
print(1)
# return n... |
c9941ccd8853940bc4b9f64f26c4783755349de7 | wxmsummer/algorithm | /leetcode/offer/offer56-1_singleNumber.py | 217 | 3.578125 | 4 | # 只出现一次的数字
class Solution:
def singleNumbers(self, nums: List[int]) -> int:
single_number = 0
for num in nums:
single_number ^= num
return single_number
|
2cb11923ce346d66cf554b7556592494c52b2d05 | wxmsummer/algorithm | /leetcode/hot/139_wordBreak.py | 1,038 | 3.5625 | 4 | class Solution:
# 记忆化递归
# @functools.lru_cache(None) 禁止开启lru缓存机制
def wordBreak(self, s: str, wordDict: list) -> bool:
import functools
@functools.lru_cache(None)
def backTrack(s):
if not s:
return True
res = False
for i in range(1, ... |
8dd9a081d4078f7161cf36acf76d189d5afb2688 | wxmsummer/algorithm | /leetcode/hot/22-2_generateParenthesis.py | 2,096 | 3.5 | 4 | class Solution():
def generateParenthesis(self, n:int) -> list:
res, tmp = [], []
# left_num 表示还能放多少个左括号, right_num 表示还能放多少右括号
def backtrack(left_num1, right_num1, left_num2, right_num2):
print('tmp:', tmp)
# 如果左括号和右括号都放完了，说明这一轮回溯完成，将结果加入结果集
if left_num1 =... |
f944157689453208684072deb6b5f99a7ddff703 | wxmsummer/algorithm | /leetcode/hot/90_subsWithDup.py | 586 | 3.65625 | 4 | # 求子集2
# nums可能包含重复元素
class Solution:
def subsetsWithDup(self, nums: list) -> list:
def backTrack(start, tmp):
res.append(tmp[:])
for i in range(start, len(nums)):
if i > start and nums[i] == nums[i-1]:
continue
tmp.append(nums[i])... |
35b2f4d82df46090bec5b965bf24f1c21454834b | wxmsummer/algorithm | /leetcode/hot/976_largestPerimeter.py | 768 | 3.859375 | 4 | # 三角形的最大周长
class Solution:
def largestPerimeter(self, nums: list) -> int:
if len(nums) < 3:
return 0
nums.sort()
length = len(nums)
i, j, k = length-3, length-2, length-1
while i >= 0:
if nums[i] + nums[j] > nums[k]:
return nums[i] + n... |
1349e81c63782210f997a14b8040f55228b3e6e8 | wxmsummer/algorithm | /leetcode/offer/offer21_exchange.py | 787 | 3.78125 | 4 | # 调整数组顺序使奇数位于偶数前面
# 两次遍历
class Solution:
def exchange(self, nums: list) -> list:
newList = []
for num in nums:
if num % 2 == 1:
newList.append(num)
for num in nums:
if num % 2 == 0:
newList.append(num)
return newList
... |
38a37365f1df0a0e8911266f32d4482096c2789a | wxmsummer/algorithm | /leetcode/hot/12-2_romanToInt.py | 1,067 | 3.515625 | 4 | class Solution():
# 直接遍历，逐个翻译
def romanToInt(self, s:str) -> int:
# 由大到小构造罗马字字典
dic = {'M':1000, 'CM':900, 'D':500, 'CD':400, 'C':100, 'XC':90,
'L':50, 'XL':40, 'X':10, 'IX':9, 'V':5, 'IV':4, 'I':1}
tmp, res = '', 0
if not s:
return 0
i =... |
4f2dc89118ac9811a7705b9e003ee484bb68b3ff | wxmsummer/algorithm | /leetcode/array/binary_search.py | 643 | 3.5625 | 4 |
class Solution:
def binary_search(self, nums:list, target:int):
i, j = 0, len(nums)
while i < j:
m = (i + j) // 2
if nums[m] >= target:
j = m
else:
i = m + 1
if i == len(nums):
return -1
return i
if __n... |
b9498d588de3e9bf2cc8893544c744f29aa7d214 | wxmsummer/algorithm | /leetcode/offer/offer31_validateStackSequences.py | 942 | 3.734375 | 4 | # 栈的压入、弹出序列
class Solution:
def validateStackSequences(self, pushed: list, popped: list) -> bool:
newList = []
# 直接模拟，每次入栈后，循环判断栈顶元素是否等于弹出序列的当前元素，将符合弹出序列顺序的栈顶元素全部弹出。
for num in pushed:
newList.append(num)
while newList and newList[-1] == popped[0]:
de... |
9ae4eb3dde5360d1e3487db79a7cbb64fd97e2d6 | wxmsummer/algorithm | /leetcode/hot/73_setZeroes.py | 847 | 3.703125 | 4 | # 矩阵置零
class Solution:
def setZeroes(self, matrix: list) -> None:
row_len, col_len = len(matrix), len(matrix[0])
# 使用额外的两个行数组和列数组来存储行和列中的零信息
row_list = [1] * row_len
col_list = [1] * col_len
for i in range(row_len):
for j in range(col_len):
if ma... |
26edab3caee726fcd7a5e621c59c23a4b4409cbc | CcCc1996/myprogram | /2-oop/03.py | 2,142 | 3.5 | 4 | # -*- coding: utf-8 -*-
# Author: IMS2017-MJR
# Creation Date: 2019/4/23
# 多继承的例子
# 子类可以直接拥有父类的属性和方法，私有的属性和方法除外
class Bird():
def __init__(self, name):
self.name = name
def fly(self):
print("i can fly")
class Fish():
def __init__(self, name):
self.name = name
def swim(self):
... |
fe10575d95d37269565d10c9ee8ebe343edbb7b6 | francisco0522/holbertonschool-interview | /0x00-lockboxes/0-lockboxes.py | 531 | 3.796875 | 4 | #!/usr/bin/python3
""" Lockboxes """
def canUnlockAll(boxes):
"""
method that determines if all the boxes can be opened
"""
if not boxes:
return False
opened = {}
queue = [0]
while queue:
boxNum = queue.pop(0)
opened[boxNum] = 1
for key in boxes[boxNu... |
e4eab633f19ee8cdc500a7c8b48c8b2f7ace9fce | mp360/manitab | /scaleCan.py | 3,996 | 3.578125 | 4 | # from Tkinter import *
# # a subclass of Canvas for dealing with resizing of windows
# class ResizingCanvas(Canvas):
# def __init__(self,parent,**kwargs):
# Canvas.__init__(self,parent,**kwargs)
# self.bind("<Configure>", self.on_resize)
# self.height = self.winfo_reqheight()
# sel... |
b78ca51e2461286da4cfbb8f16610217e3db01dc | raseribanez/Youtube-Tutorials--Python-Basics--Wordlist-Generators | /wordlist_very_basic_nonrepeat.py | 177 | 3.953125 | 4 | # Ben Woodfield
# This basic list generator DOES NOT repeat characters in each result
import itertools
res = itertools.permutations('abc',3)
for i in res:
print ''.join(i)
|
c22b162d749ad8db0d4e74228899c6a7f94e56ec | comalvirdi/CPE101 | /LAB8/list_comp/funcs_objects.py | 377 | 3.8125 | 4 | # LAB 8
# COMAL VIRDI
# EINAKIAN
# SECTION 01
from objects import *
import math
# calculates the euclidian distance between two point objects
# Object Object --> int
def distance(p1,p2):
return math.sqrt(((p1.x-p2.x)**2)+((p1.y-p2.y)**2))
def circles_overlap(c1, c2):
sumRadii = c1.radius + c2.radius
distanceCP = ... |
354d51e1558a6e332bf82000e9d874b3d6c87b4b | comalvirdi/CPE101 | /LAB3/logic.py | 351 | 4 | 4 | # LAB 3
# Name: Comal Virdi
# Instructor: S. Einakian
# Section: 01
# Determines whether or not an int is even
# int --> bool
def is_even(num):
return (num % 2 == 0)
#Determines whether or not a number falls within certain intervals
#float --> bool
def in_an_interval(num):
return (-2 <= num < 9 or 22 < num < 42... |
53da6c914c6b7139abf47e3b214b47725e93c50b | comalvirdi/CPE101 | /LAB4/loops/cubesTable.py | 1,518 | 4.3125 | 4 | # CPE 101 Lab 4
# Name:
def main():
table_size = get_table_size()
while table_size != 0:
first = get_first()
increment = get_increment()
show_table(table_size, first, increment)
table_size = get_table_size()
# Obtain a valid table size from the user
def get_table_size():
size = int(i... |
8b1b6df83a10e673536f70ac0e157b349269e975 | yanitsa-m/udemy-ML-AZ | /reinforcement_learning/upper_confidence_bound.py | 1,374 | 3.609375 | 4 | # Upper Confidence Bound (UCB) in Python
# Reinforcement learning algorithm
import numpy as np
import matplotlib.pyplot as plt
import pandas as pd
import math
# Importing the dataset
dataset = pd.read_csv('Ads_CTR_Optimisation.csv')
# Implementing UCB algorithm for advertisements data
N = 10000
d = 10
ads_selected ... |
f46f987cb4948763de2c63a6ad33ffddbe2ef8dd | yanitsa-m/udemy-ML-AZ | /regression/multiple_linear_reg.py | 2,557 | 3.921875 | 4 | """
Multiple Regression model in Python
"""
import numpy as np
import matplotlib.pyplot as plt
import pandas as pd
# Importing dataset - set up wd
dataset = pd.read_csv('50_Startups.csv')
X = dataset.iloc[:, :-1].values
Y = dataset.iloc[:, -1].values
# Encoding categorical data
# Encoding the Indep... |
94288149957696b01230c9cba3ae8c3c8257491e | gpapalois/ergasies-examinou | /exercise12 .py | 215 | 3.90625 | 4 | file = input("Δώσε ένα αρχείο ascii.")
for i in range(len(file)):
letter = file[len(file)-i -1]
number = ord(letter)
number2 = 128 - number
ascii = chr(number2)
print(ascii ,end ="") |
5c025aa292e6e3bd670d99670a744324cdc6e463 | monicarico-210/clase28febrero | /first.py | 281 | 3.9375 | 4 | print ("hola")
a=2+3j
b=1+1j
c=a*b
print(c)
x=2
print(x)
x=1.6
print(x)
print(a, b, sep="...")
print(a, b, sep="")
x=float(input("entre el valor para x: "))
print(3*x)
d=5
e=2
f=d/e
print (f)
h=d//e
print (h)
if x == d:
print("iguales")
if x > d or x < e:
print("son iguales")
|
74973b79560175b3bc94bafe84051865ff9f3a53 | ricardocodem/py-regex-exm | /ex3_findall_nome_idade.py | 301 | 3.671875 | 4 | #setup
import re
#entrada
texto = '''
Michelle tem 20 anos a sua irmã Monique tem 22 anos.
José, o avô delas, tem 77 anos e mora no apto 17.'''
#buscando idades
idades = re.findall(r"[0-9]{1,2}\s[a-z]+",texto)
print(idades)
#buscando nomes
nomes = re.findall(r"[A-Z][a-z]+\w",texto)
print(nomes) |
3000fd6a5f68d7f3ed0ae6fdeedf7421775e580a | CEASLIBRARY/Intermediate_Python | /MyPackage/uc_student.py | 1,303 | 3.921875 | 4 | # Fuction to get the first anme, last name and year of birth of a person
def demographics():
first_name = input('What is your First Name: ')
last_name = input('What is your Last Name: ')
year_of_birth = input('What is your Year of Birth: ')
return [first_name, last_name, year_of_birth]
# Fuction... |
3aa0b1d11997bdd1e2e305532851d37a490e7f87 | IvTema/Python-Programming | /lesson1.12_step7.py | 205 | 3.578125 | 4 | # https://stepik.org/lesson/5047/step/7?unit=1086
a = (input())
if (int(a[0])+int(a[1])+int(a[2])) == (int(a[-1])+int(a[-2])+int(a[-3])):
print("Счастливый")
else:
print("Обычный") |
115c5c1ae4b9ed7f13f7f974a27afa20fc1819d0 | IvTema/Python-Programming | /lesson2.1_step12.py | 141 | 3.5 | 4 | # https://stepik.org/lesson/3364/step/12?unit=947
a = int(input())
b = int(input())
c = 1
while c % a != 0 or c % b != 0:
c += 1
print(c) |
6a923de7af4f2325e939b02b4ec10118b0837170 | davidwilson826/TestRepository | /Challenge1.py | 300 | 3.65625 | 4 | done = "false"
cubes = [1]
sums = [1]
currentnum = 2
while done == "false":
cubes = cubes+currentnum**3
sums = sums+[x+currentnum**3 for x in cubes]
for x in sums.sort():
if sums.count(x) > 1 and done == "false":
print(x)
done = "true"
currentnum += 1 |
0edfe376bcc39c00986bae6a1016660ec1caec99 | robocvi/2021-1-Computacion-Distribuida- | /Practica00/src/Grafica.py | 1,596 | 3.953125 | 4 | #Computación Distribuida: Práctica 0
#Integrantes: Ocampo Villegas Roberto 316293336
# David Alvarado Torres 316167613
#Clase Gráfica, la cual contendra nuestra implementación de una Gráfica, los detalles
#de la implementación se encuentran en el readme.
class Grafica():
numVertices = 0
listaVerti... |
e9cb86ab9b68ed4b6f0c061f48629cb0eb270316 | lguychard/loispy | /src/loispy/interpreter/procedure.py | 2,279 | 4.28125 | 4 | from environment import Environment
class Procedure(object):
"""
Represents a loisp procedure. A procedure encapsulates a body (sequence of
instructions) and a list of arguments. A procedure may be called: the body
of the procedure is evaluated in the context of an environment, and given
"""
... |
cf06a980834902dedeb9b90610423b373cb382cc | shahakshay11/Array-3 | /rotate_array_kplaces.py | 820 | 3.9375 | 4 | """
// Time Complexity : O(n) n is length of shorter array
// Space Complexity : O(1)
// Did this code successfully run on Leetcode : Yes
// Any problem you faced while coding this :
// Your code here along with comments explaining your approach
Algorithm Explanation
Reverse the array
Swap the elements from 0 to k-1
... |
a4656e6ed4e97500a444824c2df8750cabc6fae2 | Heisenberg27074/Web-Scraping-with-Python3 | /urllibwork.py | 560 | 3.625 | 4 | @Imorting urllib modules
import urllib.request, urllib.parse, urllib.error
url=input('Enter')
#urllib.request() is used for requesting a URL and urlopen() for opening a new URL
#fhand is url handle here as in files it was file handle
#Here we do not write encode() as urllib.request.urlopen() does it automatically
fha... |
2fa3fbd312b86064da4f77d85dd226575de9dcaf | Heisenberg27074/Web-Scraping-with-Python3 | /lists/maxmin.py | 724 | 4.3125 | 4 | #Rewrite the program that prompts the user for a list of
#numbers and prints out the maximum and minimum of the numbers at
#the end when the user enters “done”. Write the program to store the
#numbers the user enters in a list and use the max() and min() functions to
#compute the maximum and minimum numbers after t... |
2620b59600f82e82bdf14d2e8602c1a76c721659 | Heisenberg27074/Web-Scraping-with-Python3 | /diction/9.py | 253 | 3.53125 | 4 |
st=input('Enter anything u want to:')
di=dict()
for something in st:
#if something not in di:
# di[something]=1
#else:
# di[something]=di[something]+1
di[something]=di.get(something,0)+1
print(di)
|
356eff040a055c24f3b56603bcb7061b97f9f326 | Heisenberg27074/Web-Scraping-with-Python3 | /string/trawhile.py | 409 | 3.921875 | 4 | index=0
st='czeckoslowakia'
while index<len(st): #index<=len(st)-1 /same
# print(st[index])
index=index+1
#Write a while loop that starts at the last character in the
#string and works its way backwards to the first character in the string,
#printing each letter on a separate line, except... |
c7a61e4190cec3569060c6d8b123e1181516fcb2 | Heisenberg27074/Web-Scraping-with-Python3 | /tuples/10.2.1.py | 869 | 3.875 | 4 | #Write a program to read through the mbox-short.txt and figure out the distribution by hour of the
# day for each of the messages. You can pull the hour out from the 'From ' line by finding the time
# and then splitting the string a second time using a colon.
#From stephen.marquard@uct.ac.za Sat Jan 5 09:14:16 2008... |
75a6883fb38db72e5775e46f6e94e49a3c4a9978 | dimitardanailov/google-python-class | /python-dict-file.py | 1,842 | 4.53125 | 5 | # https://developers.google.com/edu/python/dict-files#dict-hash-table
## Can build up a dict by starting with the empty dict {}
## and storing key / value pairs into the dict like this:
## dict[key] = value-for-that-key
dict = {}
dict['a'] = 'alpha'
dict['g'] = 'gamma'
dict['o'] = 'omega'
print dict ## {'a': ... |
f47a6d7abe7ec178fa212157da6b64bb3b5dc084 | fdloopes/Praticas_Machine_Learning | /Python/Linear_Regression/multi_features/main.py | 3,485 | 3.953125 | 4 | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Thu Mar 4 00:50:26 2021
@author: fdlopes
This program aims to implement a linear regression in a set of property
price data by city, in order to be able to predict how much the value of
each property will be according to the size and number of rooms.
X... |
eb3f91c0d395abf93d5c447b8883ab8e29ab4a80 | rupeshvins/Coursera-Machine-Learning-Python | /CSR ML/WEEK#2/Machine Learning Assignment#1/Python/ex1_multi.py | 2,808 | 3.59375 | 4 | # -*- coding: utf-8 -*-
"""
Created on Fri Jul 13 00:40:12 2018
@author: Mohammad Wasil Saleem
"""
import pandas as pd
import matplotlib.pyplot as plot
import numpy as np
import featureNormalize as fp
import gradientDescentMulti as gdm
import normalEqn as ne
# Getting the data and plotting it.
# x - profit
# y - po... |
978d281ef1061cfcb2afb78537b15b6f26553e03 | openGDA/gda-core | /uk.ac.gda.bimorph/scripts/bimorphtest/__init__.py | 668 | 3.78125 | 4 |
class Float(float):
"""Helper class for comparing calls with float arguments"""
def __new__(self, value, tol=1e-8):
return float.__new__(self, value)
def __init__(self, value, tol=1e-8):
float.__init__(self, value)
self.value = value
self.tol = tol
def __eq__(self, other... |
8c209d8fa3290af3dcbaf91942d376ded835706e | pbeth92/SSI | /prct06/multiplicar.py | 2,844 | 3.65625 | 4 | class Multiplicar():
def __init__(self, a1, a2, alg):
if self.check_bin(a1):
self.b1 = a1
self.b2 = a2
else:
self.b1 = self.convertir_binario(a1)
self.b2 = self.convertir_binario(a2)
print(self.b1)
print(self.b2)
self.a1... |
767b0082ff51d6363ff88022e7debb5f943b6338 | pbeth92/SSI | /prct11/prct11.py | 567 | 3.609375 | 4 | """
Pablo Bethencourt Díaz
alu0100658705@ull.edu.es
Práctica 11: Implementar el cifrado de clave pública RSA.
"""
from rsa import RSA
def menu():
print("Algoritmo RSA. \n 1.Cifrar mensaje \n 2.Descifrar mensaje \n 3.Salir")
opc = input("Opción: ")
if opc == '1':
mensaje = input("\nInt... |
c7668e86b91ed2fbcaa51d0d4811ae448d0f2a14 | RobDBennett/DS-Unit-3-Sprint-1-Software-Engineering | /module4-software-testing-documentation-and-licensing/arithmetic.py | 1,941 | 4.21875 | 4 | #!/usr/bin/env python
# Create a class SimpleOperations which takes two arguements:
# 1. 'a' (an integer)
# 2. 'b' (an integer)
# Create methods for (a, b) which will:
# 1. Add
# 2. Subtract
# 3. Multiply
# 4. Divide
# Create a child class Complex which will inherit from SimpleOperations
# and take (a, b) as argueme... |
26e6b4897c75fcc9aff4f845a5fc2a57a4983780 | ROOTBEER626/Tic-Tac-Toe | /FinalTTT.py | 10,308 | 3.8125 | 4 | import sys
import random
#This class will be placeholder for the board values
class mySquare():
EMPTY = ' '
X = 'X'
O = 'O'
#class to get the current player and positions
class Action:
def __init__(self, player, position):
self.player = player
sel... |
264890b97e175eefb09864a743fa924d8d8563a8 | TongyunHuang/LeetCode-Note | /Jan11.py | 2,520 | 3.5625 | 4 | # Jan 11
# 53. Maximum Subarray
def maxSubArray(nums):
"""
:type nums: List[int]
:rtype: int
"""
maxSum, maxIdx, arrSum, arrIdx = nums[0], 0, 0, 0
L = []
for i in range(len(nums)):
if i == 0:
L.append((0, nums[i]))
else:
newSum = L[i-1][1] + nums[i]
... |
f7d2976af17d464b0ff2bf35afe67b1b49c712e3 | TongyunHuang/LeetCode-Note | /Jan18.py | 1,869 | 3.546875 | 4 | # 122. Best time to Buy and Sell Stocks
def maxProfit(prices):
"""
:type prices: List[int]
:rtype: int
"""
if len(prices) <= 0:
return 0
if len(prices) ==2:
if prices[1]-prices[0] >0:
return prices[1]-prices[0]
return 0
total = 0
localMin, localMax = p... |
45c0ab4712ef1601e7b7679fdc3ad638866415a7 | bps10/base | /files/files.py | 1,689 | 3.9375 | 4 | import glob as glob
import os
def getAllFiles(dirName, suffix = None, subdirectories = 1):
"""
Get a list of path names of all files in a directory.
:param Directory: a directory.
:type Directory: str
:param suffix: find only files with a specific ending.
:type suffix: str
:param subd... |
5a937360687f171ef3081dbbc613ee4a9b7b7af0 | kaminosekai54/Modelisation-of-Interaction-of-O2-fish-aglae- | /functions.py | 3,516 | 3.90625 | 4 | # This file is composed of the usefull function
################################################
# import of the package
# for the mathematical computation
import numpy as np
# import for the plot
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import axes3d
# importing the odeint package to resolv our equat... |
b3caf3831004632892e925a98b66858fb7f6a38e | RamonCz/Ciencias | /EstructurasDiscretas/Practica9/funciones.py | 2,984 | 3.953125 | 4 | """
--Estructuras Discretas 2018-1
--Profesor: Laura Freidberg Gojman
--Ayudante: Ricardo Jimenez Mendez
--Practica 9
--Alumno: Cruz Perez Ramon
--No. de Cuenta: 31508148
"""
import types
"""
La funcion distancia de la pracica 1
"""
def distancia((x1,y1),(x2,y2)):
r = (((x2-x1)*(x2-x1)) + ((y2-y1)*(y2-y1)) )**(0.5... |
282257b7beba48fd0d324e45872c4dd6c37c08bd | AdamISZ/matasano-solutions | /challenges/matasano6.py | 5,485 | 3.6875 | 4 | import base64
import binascii
import matasano3
def count_nonzero_bits(a):
'''a should be a hex string
returned will be how many non zero
bits are in the binary representation'''
return sum([bin(x).count('1') for x in map(ord,a.decode('hex'))])
def hamming_distance(a,b):
'''Given two strings a,... |
09ec9d5dcd7c3b4dd6a922b41f8d5c4437fcd14c | SinaSarparast/CPFSO | /JupyterNotebook/bagOfWords.py | 1,151 | 3.796875 | 4 | from sklearn.feature_extraction.text import CountVectorizer
def get_word_bag_vector(list_of_string, stop_words=None, max_features=None):
"""
returns a vectorizer object
To get vocabulary list: vectorizer.get_feature_names()
To get vocabulary dict: vectorizer.vocabulary_
To convert a list... |
cb118d8ffde483159094a69c572e6e0b8654e143 | ashigirl96/fagents | /fagents/snippets/multi_process.py | 857 | 3.734375 | 4 | """Snippets for how to code multi process"""
import multiprocessing
import time
def _worker(i):
print("I'm {0}'th worker".format(i))
time.sleep(1)
return
def f(conn):
conn.send([42, None, 'hello'])
conn.close()
def main1():
parent_conn, child_conn = multiprocessing.Pipe()
p = multiprocessing.Process... |
eb2c8203183b49044ab87ff7a8a0181f2ced1aa5 | OskarLundberg/Intentionally-Bad-Name-Generator | /Intentionally Bad Name Generator.py | 1,418 | 3.75 | 4 | import time
import random
import os
def clear():
return os.system('cls' if os.name == 'nt' else 'clear')
# approx 44.4% chance of crashing
def counting():
problem = False
for num in range(1, 101):
clear()
print("picking one of all the possible names")
print("Loadin... |
1893fdb59156c0bb9f78af01183b1a23e670b779 | chsergey/xmlcls | /xmlcls/xml_elem.py | 4,054 | 3.5 | 4 | # -*- coding: utf-8 -*-
"""
Base class for wrappers over XML elements
If class name ends with 'List' then:
- class must contains '_list_item_class' attribute with class name
- class constructor returns list of objects with type of '_list_item_class' attribute's value
If 'xpath' attribute is None - the root el... |
12deaeb9f12fd624459faade33c7d07ac6d9b2e6 | csteinberg23/Lab5- | /test_arraylist.py | 4,271 | 4.34375 | 4 | #!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Wed Sep 30 08:35:53 2020
@author: christina
"""
"""
This program tests various functionality of an array list
implemented in the arraylist.py.
Assume the student has completed the array list implementation.
Xiannong Meng
2019-11-14
"""
from arraylist im... |
46e3119db13c6cf91480abd401f1e750cda69eea | bhagya97/newProj5409 | /fibonacci.py | 1,246 | 3.703125 | 4 | import time
import logging
import random
fibonacci()
def fibonacci():
logging.basicConfig(filename="logfile.log",level=logging.DEBUG)
starting_time=time.time()
### generate random numbers each time
input1= random.randint(0,100)
### taking input from file
#input_file= open("fib_in... |
8150ef9af406dee91979fef3539286e7e92551ef | mnoskoski/scripts-template-python | /function-print-string.py | 274 | 3.796875 | 4 | print("hello, world!".upper()) # set all text to upper
print("The itsy bitsy spider\nclimbed up the waterspout.")
print("My", "name", "is", "Monty", "Python.", sep="-")
print("Monty", "Python.", sep="*", end="*\n")
print("Programming","Essentials","in",sep="***",end="...") |
5ca276e780a1214a9393eeb006ad6ce8e9760cb4 | mnoskoski/scripts-template-python | /06exercicio.py | 529 | 3.984375 | 4 | """
Estruturas logiscas
and (e)
or (ou)
not (nao)
operadores unarios
- not
operadores binarios
- and, or, is
Para o and ambos valores precisam ser True
Para o or um ou outro valor precisa ser True
Para o not o valor do booleano é invertido, se for True vira false e for false vira True
Para o is o valor é compa... |
8c6aff095e83e240fbf00a05b5bec40ff2adec66 | sazemlame/Take-Home-Challenge | /takehome.py | 9,324 | 4.21875 | 4 | """
Automated Parking System:
This application helps you manage a parking lot of n slots. The program has the following functionalities:
1. Park a car in empty slot and store the licence plate number and age of the driver
2. Record which car has left the parking spot
3. Search for the slot nu... |
51309c0f241bd6641845e18b6e7655bc787e1b1c | it-worker-tango/PythonBase | /day03/Day03_2.py | 717 | 3.578125 | 4 | # -*- coding: utf-8 -*-
"""
Created on Sat Dec 29 21:50:00 2018
@author: Tango
"""
# = 简单的赋值运算符
x = 20
y = x
print("x:",x)
print("y:",y)
print("-" * 30)
# =+ 加赋值 x+=y 等价于 x= x +y
x += y
print("x:",x)
print("y:",y)
print("x+=y:",x)
print("-" * 30)
# -= 减赋值 x-=y 等价于 x=x -y
x = 20
y = 5
x-=y
print("x:",x)
print("y:",y)... |
5739eba75117bb3040d6e93e6be2e109749a08e6 | it-worker-tango/PythonBase | /day10/demo3.py | 308 | 3.59375 | 4 | hello = "你好啊朋友" # 定义一个全局变量
def read():
'''看书的功能'''
hello = '你好啊朋友，一起看书吧。'
print(hello)
if __name__ == "__main__":
print("我去书店。。。。")
read()
print("我回家...")
hello = "吃饭。。。"
print(hello) |
c95e2097506e549414b9cd73079c1d793e2fd098 | it-worker-tango/PythonBase | /day11/demo2.py | 203 | 3.859375 | 4 | # 读取文件中的指定个数的字符
with open("demo.txt", 'r') as file:
string = file.read(3) # 读取前3个字符
print("前3个字符为:", string) # 运行结果：前3个字符为: abc |
92e01c676746653ac390ca7482cd9764c3c73bab | it-worker-tango/PythonBase | /day06/demo4.py | 301 | 3.515625 | 4 | # -*- coding: utf-8 -*-
"""
Created on Tue Jan 1 21:30:35 2019
@author: Tango
if 嵌套
"""
number = int(input("请输入去年的销量:"))
if number >= 1000:
print("销量不错")
else:
if number >= 500:
print("销量还过得去")
else:
print("还需要努力啊")
|
1ff7a6d9db89df7d52d699d83f84871d3f82234f | carlos8410/Python_Class | /IntroGUI/GUI_Intr.py | 1,483 | 3.984375 | 4 | """Write a GUI-based program that provides two Entry fields, a button and a label.
When the button is clicked, the value of each Entry should (if possible) be converted into a float.
If both conversions succeed, the label should change to the sum of the two numbers.
Otherwise it should read "***ERROR***."""
from tkin... |
2b35e0b81932a55bef05b180b3048c152fe7d5ba | jvansteeter/CS-360 | /python/htbin/headlines.py | 335 | 3.546875 | 4 | #!/usr/bin/env python
import requests
from bs4 import BeautifulSoup
print "Content-type: text/html"
print
print "<h1>Headlines</h1>"
request = requests.get("http://news.google.com")
soup = BeautifulSoup(request.content, 'html.parser')
results = soup.find_all("span", {"class":"titletext"})
for i in results:
print s... |
2b88a13415abe1fbd15bbf70e50e05ae1cb8395a | IRC-SPHERE/sphere-challenge | /visualise_data.py | 12,500 | 3.546875 | 4 | import numpy as np
import pandas as pd
import seaborn as sns
import matplotlib.pyplot as pl
import itertools as it
import json
import os
def slice_df(df, start_end):
"""
This slices a dataframe when the index column is the time. This function slices the dataframe 'df' between a window
defined by the '... |
69a48b8681be3c0a77a2be589519d1a2e35533db | sreetamadas/sample_Python_code | /get_threshold_kneeCurve.py | 4,897 | 4 | 4 | ### calculate threshold X from knee curve ###
## GOOGLE: how to find knee of a curve in noisy data
# method 1: analytical (distance calculation with original data - may be affected by noise in data)
# method 2: distance calculation with Y from curve fitted to original data
# method 3: https://www1.icsi.berkeley.edu/~... |
8a60d618f47ce9917bf2c8021b2863585af07672 | sreesindhu-sabbineni/python-hackerrank | /TextWrap.py | 511 | 4.21875 | 4 | #You are given a string s and width w.
#Your task is to wrap the string into a paragraph of width w.
import textwrap
def wrap(string, max_width):
splittedstring = [string[i:i+max_width] for i in range(0,len(string),max_width)]
returnstring = ""
for st in splittedstring:
returnstring += s... |
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