id
string
subject
string
topic
string
subtopic
string
difficulty
string
difficulty_labeling_method
string
question_type
string
question
string
options
dict
correct_answer
string
correct_answer_value
string
solution
string
option_explanations
dict
concepts_required
list
reasoning_steps
int64
answer_type
string
language
string
origin
string
generator
string
generator_template_id
string
verification_status
string
verification_note
string
difficulty_note
string
source_type
string
answer_validation
string
openstem_004601
physics
rotational_mechanics
disc_angular_acceleration
hard
provisional_template_level_label
single_correct_mcq
A uniform solid disc of mass 15 kg and radius 1 m is acted on by a constant torque of 53 N m about its central axis. Find its angular acceleration.
{ "A": "5.3 rad s⁻²", "B": "7.06667 rad s⁻²", "C": "-7.06667 rad s⁻²", "D": "14.13333 rad s⁻²" }
B
7.06667 rad s⁻²
For a solid disc, I=½MR²=½(15)(1)²=7.5 kg m². Using τ=Iα, α=53/7.5=7.06667 rad s⁻².
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 7.06667 rad s⁻², not 5.3 rad s⁻².", "B": "Correct. The worked calculation gives 7.06667 rad s⁻².", "C": "Incorrect. Substituting the stated values into the governing relation gives 7.06667 rad s⁻², not -7.06667 rad s⁻².", "D": "...
[ "moment of inertia", "rotational dynamics", "torque" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_disc_torque
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000796
mathematics
sequences_and_series
geometric_progression
hard
provisional_template_level_label
single_correct_mcq
A geometric progression has first term 8 and common ratio -2. What is the sum of its first 9 terms?
{ "A": "1368", "B": "684", "C": "1026", "D": "-1368" }
A
1368
For r≠1, Sₙ=a(rⁿ−1)/(r−1). Thus Sₙ=8(-2^9−1)/(-2−1)=1368.
{ "A": "Correct. The worked calculation gives 1368.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1368, not 684.", "C": "Incorrect. Substituting the stated values into the governing relation gives 1368, not 1026.", "D": "Incorrect. Substituting the stated values into the go...
[ "geometric progression", "finite geometric sum" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_gp_sum
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001516
mathematics
calculus
definite_integral_polynomial
very_hard
provisional_template_level_label
single_correct_mcq
Evaluate the definite integral ∫₀^5 (6x² +7x +3) dx.
{ "A": "354.5", "B": "282", "C": "528.75", "D": "352.5" }
D
352.5
An antiderivative is (6/3)x³+(7/2)x²+(3)x. Evaluating between 0 and 5 gives (6/3)(5)³+(7/2)(5)²+(3)(5)=352.5.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 352.5, not 354.5.", "B": "Incorrect. Substituting the stated values into the governing relation gives 352.5, not 282.", "C": "Incorrect. Substituting the stated values into the governing relation gives 352.5, not 528.75.", "D": ...
[ "definite integration", "power rule", "limits of integration" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_integral_poly
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_008710
chemistry
physical_chemistry
equilibrium_degree_dissociation
very_hard
provisional_template_level_label
single_correct_mcq
For A(g) ⇌ 2B(g), the initial concentration of A is 0.91 mol L⁻¹ and initially B is absent. At equilibrium, 72% of A has dissociated at constant volume. Find K_c.
{ "A": "6.7392", "B": "10.1088", "C": "13.4784", "D": "5.7392" }
A
6.7392
Let α=0.72. At equilibrium [A]=c₀(1−α) and [B]=2c₀α. Thus K_c=[B]²/[A]=4c₀α²/(1−α)=4(0.91)(0.72)²/(1−0.72)=6.7392.
{ "A": "Correct. The worked calculation gives 6.7392.", "B": "Incorrect. Substituting the stated values into the governing relation gives 6.7392, not 10.1088.", "C": "Incorrect. Substituting the stated values into the governing relation gives 6.7392, not 13.4784.", "D": "Incorrect. Substituting the stated value...
[ "chemical equilibrium", "equilibrium constant", "degree of dissociation" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_equilibrium_alpha
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006739
chemistry
stoichiometry
limiting_reagent_water
very_hard
provisional_template_level_label
single_correct_mcq
Hydrogen reacts with oxygen according to 2H₂ + O₂ → 2H₂O. If 46 mol H₂ and 9 mol O₂ are mixed and the reaction goes to completion, how many moles of H₂O form?
{ "A": "17 mol", "B": "18 mol", "C": "16 mol", "D": "9 mol" }
B
18 mol
From 2 mol H₂ and 1 mol O₂, 2 mol H₂O form. H₂ can produce 46 mol H₂O; O₂ can produce 18 mol H₂O. The limiting condition is O₂; product=18 mol.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 18 mol, not 17 mol.", "B": "Correct. The worked calculation gives 18 mol.", "C": "Incorrect. Substituting the stated values into the governing relation gives 18 mol, not 16 mol.", "D": "Incorrect. Substituting the stated values ...
[ "balanced chemical equations", "limiting reagent", "mole ratios" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_limiting_reagent
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006731
chemistry
stoichiometry
limiting_reagent_water
very_hard
provisional_template_level_label
single_correct_mcq
Hydrogen reacts with oxygen according to 2H₂ + O₂ → 2H₂O. If 27 mol H₂ and 34 mol O₂ are mixed and the reaction goes to completion, how many moles of H₂O form?
{ "A": "21.6 mol", "B": "27 mol", "C": "54 mol", "D": "20.25 mol" }
B
27 mol
From 2 mol H₂ and 1 mol O₂, 2 mol H₂O form. H₂ can produce 27 mol H₂O; O₂ can produce 68 mol H₂O. The limiting condition is H₂; product=27 mol.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 27 mol, not 21.6 mol.", "B": "Correct. The worked calculation gives 27 mol.", "C": "Incorrect. Substituting the stated values into the governing relation gives 27 mol, not 54 mol.", "D": "Incorrect. Substituting the stated value...
[ "balanced chemical equations", "limiting reagent", "mole ratios" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_limiting_reagent
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003902
physics
mechanics
work_energy_theorem
very_hard
provisional_template_level_label
single_correct_mcq
A 14 kg block initially moves at 6 m s⁻¹. A constant net force does 28 N of work over 19 m in the direction of motion. Find its final kinetic energy.
{ "A": "786 J", "B": "627.2 J", "C": "588 J", "D": "784 J" }
D
784 J
By the work–energy theorem, K_f=K_i+W=½mu²+Fs=½(14)(6)²+(28)(19)=784 J.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 784 J, not 786 J.", "B": "Incorrect. Substituting the stated values into the governing relation gives 784 J, not 627.2 J.", "C": "Incorrect. Substituting the stated values into the governing relation gives 784 J, not 588 J.", "D...
[ "work–energy theorem", "kinetic energy", "work by constant force" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_work_energy
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006381
physics
oscillations
mass_spring_period_over_pi
hard
provisional_template_level_label
single_correct_mcq
A mass of 18 kg is attached to an ideal spring of force constant 172 N m⁻¹ and oscillates horizontally without damping. What is the time period divided by π?
{ "A": "0.48525 s", "B": "0.647 s", "C": "2.647 s", "D": "-2.353 s" }
B
0.647 s
For a mass–spring oscillator, T=2π√(m/k). Therefore T/π=2√(18/172)=0.647 s.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.647 s, not 0.48525 s.", "B": "Correct. The worked calculation gives 0.647 s.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.647 s, not 2.647 s.", "D": "Incorrect. Substituting the stated ...
[ "simple harmonic motion", "mass–spring oscillator", "time period" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_shm_period
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009767
chemistry
inorganic_chemistry
complex_ion_oxidation_state
hard
provisional_template_level_label
single_correct_mcq
For a hypothetical coordination ion [Fe(Cl)_6]^+0, each Cl ligand has charge −1. Determine the formal oxidation state of Fe.
{ "A": "5", "B": "6", "C": "9", "D": "3" }
B
6
Let the formal oxidation state of Fe be x. Charge balance gives x+(6)(−1)=+0; hence x=0+6=+6.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 6, not 5.", "B": "Correct. The worked calculation gives 6.", "C": "Incorrect. Substituting the stated values into the governing relation gives 6, not 9.", "D": "Incorrect. Substituting the stated values into the governing relati...
[ "coordination compounds", "oxidation state", "charge balance" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_complex_oxidation
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_007903
chemistry
physical_chemistry
first_order_half_life
hard
provisional_template_level_label
single_correct_mcq
A first-order reaction has a half-life of 20 minutes. If the initial reactant concentration is 14 mmol L⁻¹, what concentration remains after 100 minutes?
{ "A": "1.4375 mmol L⁻¹", "B": "0.4375 mmol L⁻¹", "C": "1.04375 mmol L⁻¹", "D": "0.32812 mmol L⁻¹" }
B
0.4375 mmol L⁻¹
100 minutes corresponds to 5 half-lives. The remaining concentration is [A]₀(1/2)ⁿ=14/2^5=0.4375 mmol L⁻¹.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.4375 mmol L⁻¹, not 1.4375 mmol L⁻¹.", "B": "Correct. The worked calculation gives 0.4375 mmol L⁻¹.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.4375 mmol L⁻¹, not 1.04375 mmol L⁻¹.", "D...
[ "first-order kinetics", "half-life", "exponential decay" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_first_order_halflife
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001658
mathematics
calculus
definite_integral_polynomial
very_hard
provisional_template_level_label
single_correct_mcq
Evaluate the definite integral ∫₀^3 (-1x² +0x -4) dx.
{ "A": "-23", "B": "-20", "C": "21", "D": "-21" }
D
-21
An antiderivative is (-1/3)x³+(0/2)x²+(-4)x. Evaluating between 0 and 3 gives (-1/3)(3)³+(0/2)(3)²+(-4)(3)=-21.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -21, not -23.", "B": "Incorrect. Substituting the stated values into the governing relation gives -21, not -20.", "C": "Incorrect. Substituting the stated values into the governing relation gives -21, not 21.", "D": "Correct. Th...
[ "definite integration", "power rule", "limits of integration" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_integral_poly
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_007015
chemistry
physical_chemistry
ideal_gas_volume
hard
provisional_template_level_label
single_correct_mcq
Assuming ideal behaviour, what volume is occupied by 15 mol of gas at 497 K and 2.31 atm? Use R=0.082057 L atm mol⁻¹ K⁻¹.
{ "A": "266.82032 L", "B": "317.78438 L", "C": "27.48203 L", "D": "264.82032 L" }
D
264.82032 L
PV=nRT, so V=nRT/P=(15)(0.082057)(497)/(2.31)=264.82032 L.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 264.82032 L, not 266.82032 L.", "B": "Incorrect. Substituting the stated values into the governing relation gives 264.82032 L, not 317.78438 L.", "C": "Incorrect. Substituting the stated values into the governing relation gives 26...
[ "ideal gas equation", "unit consistency" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_ideal_gas
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006562
physics
oscillations
mass_spring_period_over_pi
hard
provisional_template_level_label
single_correct_mcq
A mass of 14 kg is attached to an ideal spring of force constant 347 N m⁻¹ and oscillates horizontally without damping. What is the time period divided by π?
{ "A": "0.60259 s", "B": "0.40173 s", "C": "-0.59827 s", "D": "1.40173 s" }
B
0.40173 s
For a mass–spring oscillator, T=2π√(m/k). Therefore T/π=2√(14/347)=0.40173 s.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.40173 s, not 0.60259 s.", "B": "Correct. The worked calculation gives 0.40173 s.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.40173 s, not -0.59827 s.", "D": "Incorrect. Substituting th...
[ "simple harmonic motion", "mass–spring oscillator", "time period" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_shm_period
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001911
mathematics
combinatorics
binomial_coefficient
hard
provisional_template_level_label
single_correct_mcq
How many distinct subsets containing exactly 4 elements can be selected from a set of 13 distinct elements?
{ "A": "858", "B": "714", "C": "1430", "D": "715" }
D
715
Order does not matter, so the count is C(13,4)=13!/[4!(9)!]=715.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 715, not 858.", "B": "Incorrect. Substituting the stated values into the governing relation gives 715, not 714.", "C": "Incorrect. Substituting the stated values into the governing relation gives 715, not 1430.", "D": "Correct. ...
[ "combinations", "factorials" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_combinations
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002851
mathematics
vectors
dot_product
hard
provisional_template_level_label
single_correct_mcq
Given vectors u=(-7, 2, 2) and v=(5, 0, 0), calculate u·v.
{ "A": "-26.25", "B": "-42", "C": "-33", "D": "-35" }
D
-35
The dot product is the sum of corresponding component products: (-7)(5)+(2)(0)+(2)(0)=-35.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -35, not -26.25.", "B": "Incorrect. Substituting the stated values into the governing relation gives -35, not -42.", "C": "Incorrect. Substituting the stated values into the governing relation gives -35, not -33.", "D": "Correct...
[ "three-dimensional vectors", "scalar product" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_vector_dot
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005622
physics
electrostatics
capacitor_energy
hard
provisional_template_level_label
single_correct_mcq
A 7 μF capacitor is charged to a potential difference of 37 V. Calculate the energy stored, expressed in μJ.
{ "A": "480.15 μJ", "B": "4791.5 μJ", "C": "4792.5 μJ", "D": "3833.2 μJ" }
B
4791.5 μJ
U=½CV². Since C=7 μF, U in μJ is ½×7×(37)²=4791.5 μJ.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 4791.5 μJ, not 480.15 μJ.", "B": "Correct. The worked calculation gives 4791.5 μJ.", "C": "Incorrect. Substituting the stated values into the governing relation gives 4791.5 μJ, not 4792.5 μJ.", "D": "Incorrect. Substituting the...
[ "capacitance", "energy stored in a capacitor" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_capacitor_energy
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_004551
physics
rotational_mechanics
disc_angular_acceleration
hard
provisional_template_level_label
single_correct_mcq
A uniform solid disc of mass 4 kg and radius 2 m is acted on by a constant torque of 42 N m about its central axis. Find its angular acceleration.
{ "A": "2.625 rad s⁻²", "B": "7.25 rad s⁻²", "C": "5.25 rad s⁻²", "D": "6.25 rad s⁻²" }
C
5.25 rad s⁻²
For a solid disc, I=½MR²=½(4)(2)²=8 kg m². Using τ=Iα, α=42/8=5.25 rad s⁻².
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 5.25 rad s⁻², not 2.625 rad s⁻².", "B": "Incorrect. Substituting the stated values into the governing relation gives 5.25 rad s⁻², not 7.25 rad s⁻².", "C": "Correct. The worked calculation gives 5.25 rad s⁻².", "D": "Incorrect. ...
[ "moment of inertia", "rotational dynamics", "torque" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_disc_torque
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_008679
chemistry
physical_chemistry
equilibrium_degree_dissociation
very_hard
provisional_template_level_label
single_correct_mcq
For A(g) ⇌ 2B(g), the initial concentration of A is 0.64 mol L⁻¹ and initially B is absent. At equilibrium, 31% of A has dissociated at constant volume. Find K_c.
{ "A": "-0.35654", "B": "0.53482", "C": "-1.64346", "D": "0.35654" }
D
0.35654
Let α=0.31. At equilibrium [A]=c₀(1−α) and [B]=2c₀α. Thus K_c=[B]²/[A]=4c₀α²/(1−α)=4(0.64)(0.31)²/(1−0.31)=0.35654.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.35654, not -0.35654.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.35654, not 0.53482.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.35654, not -1.6...
[ "chemical equilibrium", "equilibrium constant", "degree of dissociation" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_equilibrium_alpha
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001336
mathematics
calculus
polynomial_differentiation
hard
provisional_template_level_label
single_correct_mcq
Let f(x)=7x³ -9x² -2x+7. Evaluate f′(-1).
{ "A": "29.6", "B": "74", "C": "36", "D": "37" }
D
37
Differentiate: f′(x)=3(7)x²+2(-9)x+(-2). At x=-1, f′(-1)=3(7)(-1)²+2(-9)(-1)+(-2)=37.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 37, not 29.6.", "B": "Incorrect. Substituting the stated values into the governing relation gives 37, not 74.", "C": "Incorrect. Substituting the stated values into the governing relation gives 37, not 36.", "D": "Correct. The w...
[ "power rule", "polynomial derivative" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_derivative_cubic
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_008088
chemistry
physical_chemistry
faradays_law_copper
very_hard
provisional_template_level_label
single_correct_mcq
An aqueous Cu²⁺ solution is electrolysed using a current of 5 A for 22833 s. Assuming 100% current efficiency, calculate the mass of copper deposited. Use M(Cu)=63.5 g mol⁻¹ and F=96500 C mol⁻¹.
{ "A": "28.17154 g", "B": "38.56206 g", "C": "37.56206 g", "D": "-37.56206 g" }
C
37.56206 g
Cu²⁺+2e⁻→Cu, so z=2. By Faraday's law m=MIt/(zF)=63.5×5×22833/(2×96500)=37.56206 g.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 37.56206 g, not 28.17154 g.", "B": "Incorrect. Substituting the stated values into the governing relation gives 37.56206 g, not 38.56206 g.", "C": "Correct. The worked calculation gives 37.56206 g.", "D": "Incorrect. Substitutin...
[ "electrolysis", "Faraday's laws", "redox stoichiometry" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_faraday_copper
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003793
physics
mechanics
work_energy_theorem
very_hard
provisional_template_level_label
single_correct_mcq
A 10 kg block initially moves at 4 m s⁻¹. A constant net force does 12 N of work over 11 m in the direction of motion. Find its final kinetic energy.
{ "A": "212 J", "B": "214 J", "C": "169.6 J", "D": "22.2 J" }
A
212 J
By the work–energy theorem, K_f=K_i+W=½mu²+Fs=½(10)(4)²+(12)(11)=212 J.
{ "A": "Correct. The worked calculation gives 212 J.", "B": "Incorrect. Substituting the stated values into the governing relation gives 212 J, not 214 J.", "C": "Incorrect. Substituting the stated values into the governing relation gives 212 J, not 169.6 J.", "D": "Incorrect. Substituting the stated values int...
[ "work–energy theorem", "kinetic energy", "work by constant force" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_work_energy
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002585
mathematics
linear_algebra
2x2_determinant
hard
provisional_template_level_label
single_correct_mcq
Find the determinant of the matrix [[8, 1], [8, 0]].
{ "A": "-5", "B": "-16", "C": "-6", "D": "-8" }
D
-8
For a 2×2 matrix [[a,b],[c,d]], det=ad−bc. Here it is (8)(0)−(1)(8)=-8.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -8, not -5.", "B": "Incorrect. Substituting the stated values into the governing relation gives -8, not -16.", "C": "Incorrect. Substituting the stated values into the governing relation gives -8, not -6.", "D": "Correct. The wo...
[ "determinants", "matrix operations" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_determinant_2x2
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006442
physics
oscillations
mass_spring_period_over_pi
hard
provisional_template_level_label
single_correct_mcq
A mass of 7 kg is attached to an ideal spring of force constant 65 N m⁻¹ and oscillates horizontally without damping. What is the time period divided by π?
{ "A": "3.65633 s", "B": "0.65633 s", "C": "1.06563 s", "D": "-1.34367 s" }
B
0.65633 s
For a mass–spring oscillator, T=2π√(m/k). Therefore T/π=2√(7/65)=0.65633 s.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.65633 s, not 3.65633 s.", "B": "Correct. The worked calculation gives 0.65633 s.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.65633 s, not 1.06563 s.", "D": "Incorrect. Substituting the...
[ "simple harmonic motion", "mass–spring oscillator", "time period" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_shm_period
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001527
mathematics
calculus
definite_integral_polynomial
very_hard
provisional_template_level_label
single_correct_mcq
Evaluate the definite integral ∫₀^2 (-4x² +0x +7) dx.
{ "A": "6.66667", "B": "2.5", "C": "3.33333", "D": "2.33333" }
C
3.33333
An antiderivative is (-4/3)x³+(0/2)x²+(7)x. Evaluating between 0 and 2 gives (-4/3)(2)³+(0/2)(2)²+(7)(2)=3.33333.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 3.33333, not 6.66667.", "B": "Incorrect. Substituting the stated values into the governing relation gives 3.33333, not 2.5.", "C": "Correct. The worked calculation gives 3.33333.", "D": "Incorrect. Substituting the stated values...
[ "definite integration", "power rule", "limits of integration" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_integral_poly
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_008933
chemistry
physical_chemistry
equilibrium_degree_dissociation
very_hard
provisional_template_level_label
single_correct_mcq
For A(g) ⇌ 2B(g), the initial concentration of A is 1.39 mol L⁻¹ and initially B is absent. At equilibrium, 36% of A has dissociated at constant volume. Find K_c.
{ "A": "1.68885", "B": "4.1259", "C": "1.1259", "D": "2.1259" }
C
1.1259
Let α=0.36. At equilibrium [A]=c₀(1−α) and [B]=2c₀α. Thus K_c=[B]²/[A]=4c₀α²/(1−α)=4(1.39)(0.36)²/(1−0.36)=1.1259.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1.1259, not 1.68885.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1.1259, not 4.1259.", "C": "Correct. The worked calculation gives 1.1259.", "D": "Incorrect. Substituting the stated values...
[ "chemical equilibrium", "equilibrium constant", "degree of dissociation" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_equilibrium_alpha
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_007781
chemistry
physical_chemistry
first_order_half_life
hard
provisional_template_level_label
single_correct_mcq
A first-order reaction has a half-life of 20 minutes. If the initial reactant concentration is 39 mmol L⁻¹, what concentration remains after 140 minutes?
{ "A": "0.60938 mmol L⁻¹", "B": "0.30469 mmol L⁻¹", "C": "0.45703 mmol L⁻¹", "D": "0.15234 mmol L⁻¹" }
B
0.30469 mmol L⁻¹
140 minutes corresponds to 7 half-lives. The remaining concentration is [A]₀(1/2)ⁿ=39/2^7=0.30469 mmol L⁻¹.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.30469 mmol L⁻¹, not 0.60938 mmol L⁻¹.", "B": "Correct. The worked calculation gives 0.30469 mmol L⁻¹.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.30469 mmol L⁻¹, not 0.45703 mmol L⁻¹.", ...
[ "first-order kinetics", "half-life", "exponential decay" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_first_order_halflife
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009845
chemistry
inorganic_chemistry
complex_ion_oxidation_state
hard
provisional_template_level_label
single_correct_mcq
For a hypothetical coordination ion [Fe(Cl)_4]^-2, each Cl ligand has charge −1. Determine the formal oxidation state of Fe.
{ "A": "-2", "B": "2", "C": "1.5", "D": "4" }
B
2
Let the formal oxidation state of Fe be x. Charge balance gives x+(4)(−1)=-2; hence x=-2+4=+2.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 2, not -2.", "B": "Correct. The worked calculation gives 2.", "C": "Incorrect. Substituting the stated values into the governing relation gives 2, not 1.5.", "D": "Incorrect. Substituting the stated values into the governing rel...
[ "coordination compounds", "oxidation state", "charge balance" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_complex_oxidation
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006554
physics
oscillations
mass_spring_period_over_pi
hard
provisional_template_level_label
single_correct_mcq
A mass of 17 kg is attached to an ideal spring of force constant 289 N m⁻¹ and oscillates horizontally without damping. What is the time period divided by π?
{ "A": "0.48507 s", "B": "3.48507 s", "C": "0.24254 s", "D": "1.04851 s" }
A
0.48507 s
For a mass–spring oscillator, T=2π√(m/k). Therefore T/π=2√(17/289)=0.48507 s.
{ "A": "Correct. The worked calculation gives 0.48507 s.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.48507 s, not 3.48507 s.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.48507 s, not 0.24254 s.", "D": "Incorrect. Substituting the...
[ "simple harmonic motion", "mass–spring oscillator", "time period" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_shm_period
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005010
physics
electrostatics
coulombs_law
hard
provisional_template_level_label
single_correct_mcq
Two point charges of +4 μC and +7 μC are separated by 6 cm in vacuum. Using k=9×10⁹ N m² C⁻², find the magnitude of the electrostatic force.
{ "A": "56 N", "B": "70 N", "C": "69 N", "D": "105 N" }
B
70 N
Convert charges to coulombs and distance to metres. F=k|q₁q₂|/r²=9×10⁹(4×10⁻⁶)(7×10⁻⁶)/(6×10⁻²)²=70 N.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 70 N, not 56 N.", "B": "Correct. The worked calculation gives 70 N.", "C": "Incorrect. Substituting the stated values into the governing relation gives 70 N, not 69 N.", "D": "Incorrect. Substituting the stated values into the g...
[ "Coulomb's law", "SI unit conversion", "inverse-square law" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_coulomb
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002086
mathematics
probability
same_colour_without_replacement
very_hard
provisional_template_level_label
single_correct_mcq
A bag contains 3 red, 7 blue and 4 green balls. Two balls are drawn uniformly at random without replacement. What is the probability that both have the same colour?
{ "A": "-1.67033", "B": "0.16484", "C": "0.32967", "D": "2.32967" }
C
0.32967
Favourable pairs = C(3,2)+C(7,2)+C(4,2)=30. Total pairs=C(14,2)=91. Therefore P=30/91=0.32967.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.32967, not -1.67033.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.32967, not 0.16484.", "C": "Correct. The worked calculation gives 0.32967.", "D": "Incorrect. Substituting the stated v...
[ "classical probability", "combinations", "without replacement" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_probability_colours
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009138
chemistry
physical_chemistry
nernst_equation_298K
hard
provisional_template_level_label
single_correct_mcq
At 298 K, a galvanic cell has E°cell=1.43 V, transfers 1 electrons, and has reaction quotient Q=10^6. Using E=E°−(0.0591/n)log₁₀Q, calculate Ecell.
{ "A": "-0.9246 V", "B": "1.0754 V", "C": "1.6131 V", "D": "-1.9246 V" }
B
1.0754 V
Apply the Nernst equation: E=1.43−(0.0591/1)(6)=1.0754 V.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1.0754 V, not -0.9246 V.", "B": "Correct. The worked calculation gives 1.0754 V.", "C": "Incorrect. Substituting the stated values into the governing relation gives 1.0754 V, not 1.6131 V.", "D": "Incorrect. Substituting the sta...
[ "electrochemical cells", "Nernst equation", "logarithms" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_nernst
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005621
physics
electrostatics
capacitor_energy
hard
provisional_template_level_label
single_correct_mcq
A 12 μF capacitor is charged to a potential difference of 27 V. Calculate the energy stored, expressed in μJ.
{ "A": "-4374 μJ", "B": "4376 μJ", "C": "8748 μJ", "D": "4374 μJ" }
D
4374 μJ
U=½CV². Since C=12 μF, U in μJ is ½×12×(27)²=4374 μJ.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 4374 μJ, not -4374 μJ.", "B": "Incorrect. Substituting the stated values into the governing relation gives 4374 μJ, not 4376 μJ.", "C": "Incorrect. Substituting the stated values into the governing relation gives 4374 μJ, not 8748...
[ "capacitance", "energy stored in a capacitor" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_capacitor_energy
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000600
mathematics
sequences_and_series
arithmetic_progression
hard
provisional_template_level_label
single_correct_mcq
An arithmetic progression has first term 28 and common difference 8. Find the sum of its first 33 terms.
{ "A": "4118.4", "B": "5150", "C": "515.8", "D": "5148" }
D
5148
Use Sₙ = n/2[2a+(n−1)d]. Substituting a=28, d=8, n=33: Sₙ=33/2[2(28)+(33−1)(8)]=5148.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 5148, not 4118.4.", "B": "Incorrect. Substituting the stated values into the governing relation gives 5148, not 5150.", "C": "Incorrect. Substituting the stated values into the governing relation gives 5148, not 515.8.", "D": "C...
[ "arithmetic progression", "finite series" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_ap_sum
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006450
physics
oscillations
mass_spring_period_over_pi
hard
provisional_template_level_label
single_correct_mcq
A mass of 1 kg is attached to an ideal spring of force constant 364 N m⁻¹ and oscillates horizontally without damping. What is the time period divided by π?
{ "A": "2.10483 s", "B": "3.10483 s", "C": "0.10483 s", "D": "-0.10483 s" }
C
0.10483 s
For a mass–spring oscillator, T=2π√(m/k). Therefore T/π=2√(1/364)=0.10483 s.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.10483 s, not 2.10483 s.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.10483 s, not 3.10483 s.", "C": "Correct. The worked calculation gives 0.10483 s.", "D": "Incorrect. Substituting the...
[ "simple harmonic motion", "mass–spring oscillator", "time period" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_shm_period
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_004885
physics
electricity
series_parallel_circuit
very_hard
provisional_template_level_label
single_correct_mcq
Resistors 7 Ω and 13 Ω are connected in series; this combination is connected in parallel with a 8 Ω resistor across a 9 V ideal battery. Find the total current supplied by the battery.
{ "A": "2.575 A", "B": "1.18125 A", "C": "1.575 A", "D": "-1.425 A" }
C
1.575 A
Series branch resistance=7+13=20 Ω. Parallel equivalent R_eq=(20×8)/(20+8)=5.71429 Ω. Total current I=V/R_eq=9/5.71429=1.575 A.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1.575 A, not 2.575 A.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1.575 A, not 1.18125 A.", "C": "Correct. The worked calculation gives 1.575 A.", "D": "Incorrect. Substituting the stated ...
[ "series resistors", "parallel resistors", "Ohm's law" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_series_parallel
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002704
mathematics
vectors
dot_product
hard
provisional_template_level_label
single_correct_mcq
Given vectors u=(0, 0, -4) and v=(0, 0, 5), calculate u·v.
{ "A": "-16", "B": "20", "C": "-19", "D": "-20" }
D
-20
The dot product is the sum of corresponding component products: (0)(0)+(0)(0)+(-4)(5)=-20.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -20, not -16.", "B": "Incorrect. Substituting the stated values into the governing relation gives -20, not 20.", "C": "Incorrect. Substituting the stated values into the governing relation gives -20, not -19.", "D": "Correct. Th...
[ "three-dimensional vectors", "scalar product" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_vector_dot
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006517
physics
oscillations
mass_spring_period_over_pi
hard
provisional_template_level_label
single_correct_mcq
A mass of 6 kg is attached to an ideal spring of force constant 1042 N m⁻¹ and oscillates horizontally without damping. What is the time period divided by π?
{ "A": "-2.84823 s", "B": "0.07588 s", "C": "0.15177 s", "D": "0.22765 s" }
C
0.15177 s
For a mass–spring oscillator, T=2π√(m/k). Therefore T/π=2√(6/1042)=0.15177 s.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.15177 s, not -2.84823 s.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.15177 s, not 0.07588 s.", "C": "Correct. The worked calculation gives 0.15177 s.", "D": "Incorrect. Substituting th...
[ "simple harmonic motion", "mass–spring oscillator", "time period" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_shm_period
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003165
mathematics
complex_numbers
real_part_of_complex_quotient
very_hard
provisional_template_level_label
single_correct_mcq
Let z=(1+3i)/(1+11i). What is Re(z), the real part of z?
{ "A": "0.27869", "B": "0.13934", "C": "-0.72131", "D": "1.02787" }
A
0.27869
Multiply numerator and denominator by the conjugate (1-11i). Then Re(z)=(ac+bd)/(c²+d²)=((1)(1)+(3)(11))/(1²+(11)²)=0.27869.
{ "A": "Correct. The worked calculation gives 0.27869.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.27869, not 0.13934.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.27869, not -0.72131.", "D": "Incorrect. Substituting the stated v...
[ "complex conjugate", "complex division", "real and imaginary parts" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_complex_quotient
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_004604
physics
rotational_mechanics
disc_angular_acceleration
hard
provisional_template_level_label
single_correct_mcq
A uniform solid disc of mass 4 kg and radius 2 m is acted on by a constant torque of 80 N m about its central axis. Find its angular acceleration.
{ "A": "20 rad s⁻²", "B": "9 rad s⁻²", "C": "10 rad s⁻²", "D": "11 rad s⁻²" }
C
10 rad s⁻²
For a solid disc, I=½MR²=½(4)(2)²=8 kg m². Using τ=Iα, α=80/8=10 rad s⁻².
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 10 rad s⁻², not 20 rad s⁻².", "B": "Incorrect. Substituting the stated values into the governing relation gives 10 rad s⁻², not 9 rad s⁻².", "C": "Correct. The worked calculation gives 10 rad s⁻².", "D": "Incorrect. Substituting...
[ "moment of inertia", "rotational dynamics", "torque" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_disc_torque
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003640
physics
mechanics
projectile_range
hard
provisional_template_level_label
single_correct_mcq
A projectile is launched from level ground at 95 m s⁻¹ at 60° to the horizontal. Take g=10 m s⁻². Find its horizontal range.
{ "A": "1172.38189 m", "B": "781.58793 m", "C": "780.58793 m", "D": "1563.17585 m" }
B
781.58793 m
Range R=u²sin(2θ)/g. Substituting u=95, θ=60° and g=10 gives R=(95)²sin(120°)/10=781.58793 m.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 781.58793 m, not 1172.38189 m.", "B": "Correct. The worked calculation gives 781.58793 m.", "C": "Incorrect. Substituting the stated values into the governing relation gives 781.58793 m, not 780.58793 m.", "D": "Incorrect. Subst...
[ "projectile motion", "range equation", "trigonometry" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_projectile_range
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001831
mathematics
combinatorics
binomial_coefficient
hard
provisional_template_level_label
single_correct_mcq
How many distinct subsets containing exactly 10 elements can be selected from a set of 68 distinct elements?
{ "A": "29075238421.8", "B": "290752384208", "C": "290752384206", "D": "232601907366.39999" }
B
290752384208
Order does not matter, so the count is C(68,10)=68!/[10!(58)!]=290752384208.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 290752384208, not 29075238421.8.", "B": "Correct. The worked calculation gives 290752384208.", "C": "Incorrect. Substituting the stated values into the governing relation gives 290752384208, not 290752384206.", "D": "Incorrect. ...
[ "combinations", "factorials" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_combinations
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009456
chemistry
organic_chemistry
degree_of_unsaturation
very_hard
provisional_template_level_label
single_correct_mcq
Assuming a neutral closed-shell formula, calculate the degree of unsaturation (DBE) for C_17H_15X_1. Treat X as the total number of monovalent halogen atoms.
{ "A": "11", "B": "15", "C": "8", "D": "10" }
D
10
Use DBE=(2C+2+N−H−X)/2. Substitution gives (2×17+2+0−15−1)/2=10.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 10, not 11.", "B": "Incorrect. Substituting the stated values into the governing relation gives 10, not 15.", "C": "Incorrect. Substituting the stated values into the governing relation gives 10, not 8.", "D": "Correct. The work...
[ "molecular formula", "degree of unsaturation", "organic structure" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_dbe
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_007925
chemistry
physical_chemistry
first_order_half_life
hard
provisional_template_level_label
single_correct_mcq
A first-order reaction has a half-life of 20 minutes. If the initial reactant concentration is 12 mmol L⁻¹, what concentration remains after 100 minutes?
{ "A": "0.1875 mmol L⁻¹", "B": "-0.375 mmol L⁻¹", "C": "0.375 mmol L⁻¹", "D": "3.375 mmol L⁻¹" }
C
0.375 mmol L⁻¹
100 minutes corresponds to 5 half-lives. The remaining concentration is [A]₀(1/2)ⁿ=12/2^5=0.375 mmol L⁻¹.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.375 mmol L⁻¹, not 0.1875 mmol L⁻¹.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.375 mmol L⁻¹, not -0.375 mmol L⁻¹.", "C": "Correct. The worked calculation gives 0.375 mmol L⁻¹.", "D": "...
[ "first-order kinetics", "half-life", "exponential decay" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_first_order_halflife
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002442
mathematics
linear_algebra
2x2_determinant
hard
provisional_template_level_label
single_correct_mcq
Find the determinant of the matrix [[1, 4], [8, 3]].
{ "A": "-28", "B": "-58", "C": "-23.2", "D": "-29" }
D
-29
For a 2×2 matrix [[a,b],[c,d]], det=ad−bc. Here it is (1)(3)−(4)(8)=-29.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -29, not -28.", "B": "Incorrect. Substituting the stated values into the governing relation gives -29, not -58.", "C": "Incorrect. Substituting the stated values into the governing relation gives -29, not -23.2.", "D": "Correct....
[ "determinants", "matrix operations" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_determinant_2x2
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002791
mathematics
vectors
dot_product
hard
provisional_template_level_label
single_correct_mcq
Given vectors u=(-4, -5, 7) and v=(-1, -5, 9), calculate u·v.
{ "A": "92", "B": "73.6", "C": "138", "D": "46" }
A
92
The dot product is the sum of corresponding component products: (-4)(-1)+(-5)(-5)+(7)(9)=92.
{ "A": "Correct. The worked calculation gives 92.", "B": "Incorrect. Substituting the stated values into the governing relation gives 92, not 73.6.", "C": "Incorrect. Substituting the stated values into the governing relation gives 92, not 138.", "D": "Incorrect. Substituting the stated values into the governin...
[ "three-dimensional vectors", "scalar product" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_vector_dot
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000111
mathematics
algebra
quadratic_roots
hard
provisional_template_level_label
single_correct_mcq
For the quadratic equation 5x^2 +0x +11=0, let its roots be α and β. What is α²+β²?
{ "A": "-2.2", "B": "-4.4", "C": "-6.6", "D": "0.56" }
B
-4.4
By Vieta's relations, α+β = 0/5 and αβ = 11/5. Then α²+β²=(α+β)²−2αβ = (0/5)²−2(11/5) = -4.4.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -4.4, not -2.2.", "B": "Correct. The worked calculation gives -4.4.", "C": "Incorrect. Substituting the stated values into the governing relation gives -4.4, not -6.6.", "D": "Incorrect. Substituting the stated values into the g...
[ "Vieta's formulas", "symmetric polynomial expressions" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_quadratic_vieta
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005160
physics
electrostatics
coulombs_law
hard
provisional_template_level_label
single_correct_mcq
Two point charges of +5 μC and +4 μC are separated by 8 cm in vacuum. Using k=9×10⁹ N m² C⁻², find the magnitude of the electrostatic force.
{ "A": "-28.125 N", "B": "14.0625 N", "C": "28.125 N", "D": "21.09375 N" }
C
28.125 N
Convert charges to coulombs and distance to metres. F=k|q₁q₂|/r²=9×10⁹(5×10⁻⁶)(4×10⁻⁶)/(8×10⁻²)²=28.125 N.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 28.125 N, not -28.125 N.", "B": "Incorrect. Substituting the stated values into the governing relation gives 28.125 N, not 14.0625 N.", "C": "Correct. The worked calculation gives 28.125 N.", "D": "Incorrect. Substituting the st...
[ "Coulomb's law", "SI unit conversion", "inverse-square law" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_coulomb
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_004999
physics
electricity
series_parallel_circuit
very_hard
provisional_template_level_label
single_correct_mcq
Resistors 8 Ω and 8 Ω are connected in series; this combination is connected in parallel with a 8 Ω resistor across a 36 V ideal battery. Find the total current supplied by the battery.
{ "A": "1.675 A", "B": "3.375 A", "C": "6.75 A", "D": "10.125 A" }
C
6.75 A
Series branch resistance=8+8=16 Ω. Parallel equivalent R_eq=(16×8)/(16+8)=5.33333 Ω. Total current I=V/R_eq=36/5.33333=6.75 A.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 6.75 A, not 1.675 A.", "B": "Incorrect. Substituting the stated values into the governing relation gives 6.75 A, not 3.375 A.", "C": "Correct. The worked calculation gives 6.75 A.", "D": "Incorrect. Substituting the stated value...
[ "series resistors", "parallel resistors", "Ohm's law" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_series_parallel
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003601
physics
mechanics
projectile_range
hard
provisional_template_level_label
single_correct_mcq
A projectile is launched from level ground at 118 m s⁻¹ at 65° to the horizontal. Take g=10 m s⁻². Find its horizontal range.
{ "A": "1599.96042 m", "B": "1066.64028 m", "C": "107.66403 m", "D": "1067.64028 m" }
B
1066.64028 m
Range R=u²sin(2θ)/g. Substituting u=118, θ=65° and g=10 gives R=(118)²sin(130°)/10=1066.64028 m.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1066.64028 m, not 1599.96042 m.", "B": "Correct. The worked calculation gives 1066.64028 m.", "C": "Incorrect. Substituting the stated values into the governing relation gives 1066.64028 m, not 107.66403 m.", "D": "Incorrect. Su...
[ "projectile motion", "range equation", "trigonometry" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_projectile_range
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_004510
physics
rotational_mechanics
disc_angular_acceleration
hard
provisional_template_level_label
single_correct_mcq
A uniform solid disc of mass 7 kg and radius 5 m is acted on by a constant torque of 95 N m about its central axis. Find its angular acceleration.
{ "A": "3.08571 rad s⁻²", "B": "0.54286 rad s⁻²", "C": "0.08571 rad s⁻²", "D": "1.08571 rad s⁻²" }
D
1.08571 rad s⁻²
For a solid disc, I=½MR²=½(7)(5)²=87.5 kg m². Using τ=Iα, α=95/87.5=1.08571 rad s⁻².
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1.08571 rad s⁻², not 3.08571 rad s⁻².", "B": "Incorrect. Substituting the stated values into the governing relation gives 1.08571 rad s⁻², not 0.54286 rad s⁻².", "C": "Incorrect. Substituting the stated values into the governing r...
[ "moment of inertia", "rotational dynamics", "torque" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_disc_torque
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002302
mathematics
probability
same_colour_without_replacement
very_hard
provisional_template_level_label
single_correct_mcq
A bag contains 4 red, 12 blue and 11 green balls. Two balls are drawn uniformly at random without replacement. What is the probability that both have the same colour?
{ "A": "0.36182", "B": "-0.63818", "C": "-2.63818", "D": "-0.36182" }
A
0.36182
Favourable pairs = C(4,2)+C(12,2)+C(11,2)=127. Total pairs=C(27,2)=351. Therefore P=127/351=0.36182.
{ "A": "Correct. The worked calculation gives 0.36182.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.36182, not -0.63818.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.36182, not -2.63818.", "D": "Incorrect. Substituting the stated ...
[ "classical probability", "combinations", "without replacement" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_probability_colours
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_004879
physics
electricity
series_parallel_circuit
very_hard
provisional_template_level_label
single_correct_mcq
Resistors 10 Ω and 11 Ω are connected in series; this combination is connected in parallel with a 16 Ω resistor across a 18 V ideal battery. Find the total current supplied by the battery.
{ "A": "2.98214 A", "B": "2.97321 A", "C": "1.98214 A", "D": "-0.01786 A" }
C
1.98214 A
Series branch resistance=10+11=21 Ω. Parallel equivalent R_eq=(21×16)/(21+16)=9.08108 Ω. Total current I=V/R_eq=18/9.08108=1.98214 A.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1.98214 A, not 2.98214 A.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1.98214 A, not 2.97321 A.", "C": "Correct. The worked calculation gives 1.98214 A.", "D": "Incorrect. Substituting the...
[ "series resistors", "parallel resistors", "Ohm's law" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_series_parallel
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009580
chemistry
organic_chemistry
degree_of_unsaturation
very_hard
provisional_template_level_label
single_correct_mcq
Assuming a neutral closed-shell formula, calculate the degree of unsaturation (DBE) for C_16H_5N_1X_4. Treat X as the total number of monovalent halogen atoms.
{ "A": "13", "B": "11", "C": "26", "D": "14" }
A
13
Use DBE=(2C+2+N−H−X)/2. Substitution gives (2×16+2+1−5−4)/2=13.
{ "A": "Correct. The worked calculation gives 13.", "B": "Incorrect. Substituting the stated values into the governing relation gives 13, not 11.", "C": "Incorrect. Substituting the stated values into the governing relation gives 13, not 26.", "D": "Incorrect. Substituting the stated values into the governing r...
[ "molecular formula", "degree of unsaturation", "organic structure" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_dbe
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006097
physics
ray_optics
convex_lens_magnification
very_hard
provisional_template_level_label
single_correct_mcq
A real object is placed 42 cm in front of a thin convex lens of focal length 11 cm. Using the Cartesian sign convention, what is the magnitude of the linear magnification?
{ "A": "0.70968", "B": "2.35484", "C": "0.26613", "D": "0.35484" }
D
0.35484
Using distances as positive magnitudes, 1/f=1/v+1/u gives v=uf/(u−f)=(42)(11)/(42−11)=14.90323 cm. Thus |m|=v/u=14.90323/42=0.35484.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.35484, not 0.70968.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.35484, not 2.35484.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.35484, not 0.266...
[ "thin lens equation", "linear magnification", "real image" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_lens_magnification
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001928
mathematics
combinatorics
binomial_coefficient
hard
provisional_template_level_label
single_correct_mcq
How many distinct subsets containing exactly 11 elements can be selected from a set of 88 distinct elements?
{ "A": "38407210034169.60156", "B": "16003004180904", "C": "48009012542712", "D": "32006008361808" }
D
32006008361808
Order does not matter, so the count is C(88,11)=88!/[11!(77)!]=32006008361808.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 32006008361808, not 38407210034169.60156.", "B": "Incorrect. Substituting the stated values into the governing relation gives 32006008361808, not 16003004180904.", "C": "Incorrect. Substituting the stated values into the governing...
[ "combinations", "factorials" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_combinations
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005540
physics
electrostatics
capacitor_energy
hard
provisional_template_level_label
single_correct_mcq
A 39 μF capacitor is charged to a potential difference of 8 V. Calculate the energy stored, expressed in μJ.
{ "A": "1872 μJ", "B": "125.8 μJ", "C": "1246 μJ", "D": "1248 μJ" }
D
1248 μJ
U=½CV². Since C=39 μF, U in μJ is ½×39×(8)²=1248 μJ.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1248 μJ, not 1872 μJ.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1248 μJ, not 125.8 μJ.", "C": "Incorrect. Substituting the stated values into the governing relation gives 1248 μJ, not 1246...
[ "capacitance", "energy stored in a capacitor" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_capacitor_energy
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001139
mathematics
calculus
polynomial_differentiation
hard
provisional_template_level_label
single_correct_mcq
Let f(x)=4x³ +5x² +10x+7. Evaluate f′(0).
{ "A": "15", "B": "9", "C": "10", "D": "5" }
C
10
Differentiate: f′(x)=3(4)x²+2(5)x+(10). At x=0, f′(0)=3(4)(0)²+2(5)(0)+(10)=10.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 10, not 15.", "B": "Incorrect. Substituting the stated values into the governing relation gives 10, not 9.", "C": "Correct. The worked calculation gives 10.", "D": "Incorrect. Substituting the stated values into the governing re...
[ "power rule", "polynomial derivative" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_derivative_cubic
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_004247
physics
mechanics
inclined_plane_with_friction
very_hard
provisional_template_level_label
single_correct_mcq
A 10 kg block slides down a 37° rough incline. The coefficient of kinetic friction is 0.28. Taking g=10 m s⁻², find the net force down the plane. Use sin37°=0.6 and cos37°=0.8.
{ "A": "75.2 N", "B": "35.6 N", "C": "37.6 N", "D": "45.12 N" }
C
37.6 N
Net force=mg(sinθ−μcosθ)=10×10×(0.6−0.28×0.8)=37.6 N.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 37.6 N, not 75.2 N.", "B": "Incorrect. Substituting the stated values into the governing relation gives 37.6 N, not 35.6 N.", "C": "Correct. The worked calculation gives 37.6 N.", "D": "Incorrect. Substituting the stated values ...
[ "Newton's laws", "inclined plane", "kinetic friction" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_incline_friction
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001281
mathematics
calculus
polynomial_differentiation
hard
provisional_template_level_label
single_correct_mcq
Let f(x)=3x³ -6x² -1x+7. Evaluate f′(2).
{ "A": "-11", "B": "9", "C": "2.1", "D": "11" }
D
11
Differentiate: f′(x)=3(3)x²+2(-6)x+(-1). At x=2, f′(2)=3(3)(2)²+2(-6)(2)+(-1)=11.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 11, not -11.", "B": "Incorrect. Substituting the stated values into the governing relation gives 11, not 9.", "C": "Incorrect. Substituting the stated values into the governing relation gives 11, not 2.1.", "D": "Correct. The wo...
[ "power rule", "polynomial derivative" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_derivative_cubic
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002699
mathematics
vectors
dot_product
hard
provisional_template_level_label
single_correct_mcq
Given vectors u=(-7, 5, -6) and v=(-2, 1, 3), calculate u·v.
{ "A": "1.5", "B": "1", "C": "4", "D": "-1" }
B
1
The dot product is the sum of corresponding component products: (-7)(-2)+(5)(1)+(-6)(3)=1.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1, not 1.5.", "B": "Correct. The worked calculation gives 1.", "C": "Incorrect. Substituting the stated values into the governing relation gives 1, not 4.", "D": "Incorrect. Substituting the stated values into the governing rela...
[ "three-dimensional vectors", "scalar product" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_vector_dot
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000640
mathematics
sequences_and_series
arithmetic_progression
hard
provisional_template_level_label
single_correct_mcq
An arithmetic progression has first term 6 and common difference 15. Find the sum of its first 13 terms.
{ "A": "936", "B": "2496", "C": "1248", "D": "1246" }
C
1248
Use Sₙ = n/2[2a+(n−1)d]. Substituting a=6, d=15, n=13: Sₙ=13/2[2(6)+(13−1)(15)]=1248.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1248, not 936.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1248, not 2496.", "C": "Correct. The worked calculation gives 1248.", "D": "Incorrect. Substituting the stated values into the go...
[ "arithmetic progression", "finite series" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_ap_sum
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000156
mathematics
algebra
quadratic_roots
hard
provisional_template_level_label
single_correct_mcq
For the quadratic equation 6x^2 +17x -9=0, let its roots be α and β. What is α²+β²?
{ "A": "14.02778", "B": "13.02778", "C": "10.02778", "D": "11.02778" }
D
11.02778
By Vieta's relations, α+β = -17/6 and αβ = -9/6. Then α²+β²=(α+β)²−2αβ = (-17/6)²−2(-9/6) = 11.02778.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 11.02778, not 14.02778.", "B": "Incorrect. Substituting the stated values into the governing relation gives 11.02778, not 13.02778.", "C": "Incorrect. Substituting the stated values into the governing relation gives 11.02778, not ...
[ "Vieta's formulas", "symmetric polynomial expressions" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_quadratic_vieta
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003250
mathematics
complex_numbers
real_part_of_complex_quotient
very_hard
provisional_template_level_label
single_correct_mcq
Let z=(-15+9i)/(6+3i). What is Re(z), the real part of z?
{ "A": "-1.4", "B": "0.86", "C": "-2.1", "D": "-3.4" }
A
-1.4
Multiply numerator and denominator by the conjugate (6-3i). Then Re(z)=(ac+bd)/(c²+d²)=((-15)(6)+(9)(3))/(6²+(3)²)=-1.4.
{ "A": "Correct. The worked calculation gives -1.4.", "B": "Incorrect. Substituting the stated values into the governing relation gives -1.4, not 0.86.", "C": "Incorrect. Substituting the stated values into the governing relation gives -1.4, not -2.1.", "D": "Incorrect. Substituting the stated values into the g...
[ "complex conjugate", "complex division", "real and imaginary parts" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_complex_quotient
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002540
mathematics
linear_algebra
2x2_determinant
hard
provisional_template_level_label
single_correct_mcq
Find the determinant of the matrix [[1, -7], [2, -7]].
{ "A": "5", "B": "7", "C": "6", "D": "10.5" }
B
7
For a 2×2 matrix [[a,b],[c,d]], det=ad−bc. Here it is (1)(-7)−(-7)(2)=7.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 7, not 5.", "B": "Correct. The worked calculation gives 7.", "C": "Incorrect. Substituting the stated values into the governing relation gives 7, not 6.", "D": "Incorrect. Substituting the stated values into the governing relati...
[ "determinants", "matrix operations" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_determinant_2x2
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002420
mathematics
linear_algebra
2x2_determinant
hard
provisional_template_level_label
single_correct_mcq
Find the determinant of the matrix [[4, -3], [4, 0]].
{ "A": "15", "B": "13", "C": "12", "D": "9" }
C
12
For a 2×2 matrix [[a,b],[c,d]], det=ad−bc. Here it is (4)(0)−(-3)(4)=12.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 12, not 15.", "B": "Incorrect. Substituting the stated values into the governing relation gives 12, not 13.", "C": "Correct. The worked calculation gives 12.", "D": "Incorrect. Substituting the stated values into the governing r...
[ "determinants", "matrix operations" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_determinant_2x2
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_008739
chemistry
physical_chemistry
equilibrium_degree_dissociation
very_hard
provisional_template_level_label
single_correct_mcq
For A(g) ⇌ 2B(g), the initial concentration of A is 1.24 mol L⁻¹ and initially B is absent. At equilibrium, 19% of A has dissociated at constant volume. Find K_c.
{ "A": "-0.22106", "B": "0.44211", "C": "1.22106", "D": "0.22106" }
D
0.22106
Let α=0.19. At equilibrium [A]=c₀(1−α) and [B]=2c₀α. Thus K_c=[B]²/[A]=4c₀α²/(1−α)=4(1.24)(0.19)²/(1−0.19)=0.22106.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.22106, not -0.22106.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.22106, not 0.44211.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.22106, not 1.22...
[ "chemical equilibrium", "equilibrium constant", "degree of dissociation" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_equilibrium_alpha
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000510
mathematics
sequences_and_series
arithmetic_progression
hard
provisional_template_level_label
single_correct_mcq
An arithmetic progression has first term 30 and common difference 14. Find the sum of its first 22 terms.
{ "A": "3894", "B": "3893", "C": "2920.5", "D": "1947" }
A
3894
Use Sₙ = n/2[2a+(n−1)d]. Substituting a=30, d=14, n=22: Sₙ=22/2[2(30)+(22−1)(14)]=3894.
{ "A": "Correct. The worked calculation gives 3894.", "B": "Incorrect. Substituting the stated values into the governing relation gives 3894, not 3893.", "C": "Incorrect. Substituting the stated values into the governing relation gives 3894, not 2920.5.", "D": "Incorrect. Substituting the stated values into the...
[ "arithmetic progression", "finite series" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_ap_sum
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005730
physics
thermodynamics
ideal_gas_isochoric_pressure
hard
provisional_template_level_label
single_correct_mcq
A fixed amount of ideal gas is kept in a rigid container. Its pressure is 1.2 atm at 284 K. What is its pressure at 726 K?
{ "A": "1.06761 atm", "B": "4.06761 atm", "C": "1.30676 atm", "D": "3.06761 atm" }
D
3.06761 atm
At constant volume, P/T is constant. P₂=P₁T₂/T₁=(1.2)(726)/(284)=3.06761 atm.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 3.06761 atm, not 1.06761 atm.", "B": "Incorrect. Substituting the stated values into the governing relation gives 3.06761 atm, not 4.06761 atm.", "C": "Incorrect. Substituting the stated values into the governing relation gives 3....
[ "ideal gas law", "isochoric process", "absolute temperature" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_isochoric_gas
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000751
mathematics
sequences_and_series
geometric_progression
hard
provisional_template_level_label
single_correct_mcq
A geometric progression has first term 8 and common ratio 4. What is the sum of its first 5 terms?
{ "A": "273.8", "B": "2728", "C": "1364", "D": "5456" }
B
2728
For r≠1, Sₙ=a(rⁿ−1)/(r−1). Thus Sₙ=8(4^5−1)/(4−1)=2728.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 2728, not 273.8.", "B": "Correct. The worked calculation gives 2728.", "C": "Incorrect. Substituting the stated values into the governing relation gives 2728, not 1364.", "D": "Incorrect. Substituting the stated values into the ...
[ "geometric progression", "finite geometric sum" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_gp_sum
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000493
mathematics
sequences_and_series
arithmetic_progression
hard
provisional_template_level_label
single_correct_mcq
An arithmetic progression has first term 19 and common difference 10. Find the sum of its first 28 terms.
{ "A": "4312", "B": "432.2", "C": "4314", "D": "-4312" }
A
4312
Use Sₙ = n/2[2a+(n−1)d]. Substituting a=19, d=10, n=28: Sₙ=28/2[2(19)+(28−1)(10)]=4312.
{ "A": "Correct. The worked calculation gives 4312.", "B": "Incorrect. Substituting the stated values into the governing relation gives 4312, not 432.2.", "C": "Incorrect. Substituting the stated values into the governing relation gives 4312, not 4314.", "D": "Incorrect. Substituting the stated values into the ...
[ "arithmetic progression", "finite series" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_ap_sum
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001403
mathematics
calculus
definite_integral_polynomial
very_hard
provisional_template_level_label
single_correct_mcq
Evaluate the definite integral ∫₀^6 (-4x² +6x -4) dx.
{ "A": "-163.2", "B": "-204", "C": "-19.4", "D": "-205" }
B
-204
An antiderivative is (-4/3)x³+(6/2)x²+(-4)x. Evaluating between 0 and 6 gives (-4/3)(6)³+(6/2)(6)²+(-4)(6)=-204.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -204, not -163.2.", "B": "Correct. The worked calculation gives -204.", "C": "Incorrect. Substituting the stated values into the governing relation gives -204, not -19.4.", "D": "Incorrect. Substituting the stated values into th...
[ "definite integration", "power rule", "limits of integration" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_integral_poly
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002488
mathematics
linear_algebra
2x2_determinant
hard
provisional_template_level_label
single_correct_mcq
Find the determinant of the matrix [[7, -3], [8, -4]].
{ "A": "4", "B": "-3", "C": "-6", "D": "-4" }
D
-4
For a 2×2 matrix [[a,b],[c,d]], det=ad−bc. Here it is (7)(-4)−(-3)(8)=-4.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -4, not 4.", "B": "Incorrect. Substituting the stated values into the governing relation gives -4, not -3.", "C": "Incorrect. Substituting the stated values into the governing relation gives -4, not -6.", "D": "Correct. The work...
[ "determinants", "matrix operations" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_determinant_2x2
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003865
physics
mechanics
work_energy_theorem
very_hard
provisional_template_level_label
single_correct_mcq
A 4 kg block initially moves at 8 m s⁻¹. A constant net force does 18 N of work over 17 m in the direction of motion. Find its final kinetic energy.
{ "A": "44.4 J", "B": "520.8 J", "C": "436 J", "D": "434 J" }
D
434 J
By the work–energy theorem, K_f=K_i+W=½mu²+Fs=½(4)(8)²+(18)(17)=434 J.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 434 J, not 44.4 J.", "B": "Incorrect. Substituting the stated values into the governing relation gives 434 J, not 520.8 J.", "C": "Incorrect. Substituting the stated values into the governing relation gives 434 J, not 436 J.", "...
[ "work–energy theorem", "kinetic energy", "work by constant force" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_work_energy
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003939
physics
mechanics
work_energy_theorem
very_hard
provisional_template_level_label
single_correct_mcq
A 13 kg block initially moves at 0 m s⁻¹. A constant net force does 15 N of work over 4 m in the direction of motion. Find its final kinetic energy.
{ "A": "7 J", "B": "59 J", "C": "60 J", "D": "61 J" }
C
60 J
By the work–energy theorem, K_f=K_i+W=½mu²+Fs=½(13)(0)²+(15)(4)=60 J.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 60 J, not 7 J.", "B": "Incorrect. Substituting the stated values into the governing relation gives 60 J, not 59 J.", "C": "Correct. The worked calculation gives 60 J.", "D": "Incorrect. Substituting the stated values into the go...
[ "work–energy theorem", "kinetic energy", "work by constant force" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_work_energy
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005778
physics
thermodynamics
ideal_gas_isochoric_pressure
hard
provisional_template_level_label
single_correct_mcq
A fixed amount of ideal gas is kept in a rigid container. Its pressure is 3.3 atm at 222 K. What is its pressure at 344 K?
{ "A": "-5.11351 atm", "B": "5.11351 atm", "C": "3.83514 atm", "D": "6.11351 atm" }
B
5.11351 atm
At constant volume, P/T is constant. P₂=P₁T₂/T₁=(3.3)(344)/(222)=5.11351 atm.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 5.11351 atm, not -5.11351 atm.", "B": "Correct. The worked calculation gives 5.11351 atm.", "C": "Incorrect. Substituting the stated values into the governing relation gives 5.11351 atm, not 3.83514 atm.", "D": "Incorrect. Subst...
[ "ideal gas law", "isochoric process", "absolute temperature" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_isochoric_gas
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000994
mathematics
sequences_and_series
geometric_progression
hard
provisional_template_level_label
single_correct_mcq
A geometric progression has first term 8 and common ratio -2. What is the sum of its first 12 terms?
{ "A": "-21840", "B": "-10919", "C": "-10920", "D": "-10918" }
C
-10920
For r≠1, Sₙ=a(rⁿ−1)/(r−1). Thus Sₙ=8(-2^12−1)/(-2−1)=-10920.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -10920, not -21840.", "B": "Incorrect. Substituting the stated values into the governing relation gives -10920, not -10919.", "C": "Correct. The worked calculation gives -10920.", "D": "Incorrect. Substituting the stated values ...
[ "geometric progression", "finite geometric sum" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_gp_sum
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003634
physics
mechanics
projectile_range
hard
provisional_template_level_label
single_correct_mcq
A projectile is launched from level ground at 114 m s⁻¹ at 45° to the horizontal. Take g=10 m s⁻². Find its horizontal range.
{ "A": "1949.4 m", "B": "1301.6 m", "C": "1298.6 m", "D": "1299.6 m" }
D
1299.6 m
Range R=u²sin(2θ)/g. Substituting u=114, θ=45° and g=10 gives R=(114)²sin(90°)/10=1299.6 m.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1299.6 m, not 1949.4 m.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1299.6 m, not 1301.6 m.", "C": "Incorrect. Substituting the stated values into the governing relation gives 1299.6 m, not ...
[ "projectile motion", "range equation", "trigonometry" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_projectile_range
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002202
mathematics
probability
same_colour_without_replacement
very_hard
provisional_template_level_label
single_correct_mcq
A bag contains 10 red, 12 blue and 4 green balls. Two balls are drawn uniformly at random without replacement. What is the probability that both have the same colour?
{ "A": "0.36", "B": "1.036", "C": "-1.64", "D": "0.72" }
A
0.36
Favourable pairs = C(10,2)+C(12,2)+C(4,2)=117. Total pairs=C(26,2)=325. Therefore P=117/325=0.36.
{ "A": "Correct. The worked calculation gives 0.36.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.36, not 1.036.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.36, not -1.64.", "D": "Incorrect. Substituting the stated values into the...
[ "classical probability", "combinations", "without replacement" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_probability_colours
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_007670
chemistry
physical_chemistry
first_order_half_life
hard
provisional_template_level_label
single_correct_mcq
A first-order reaction has a half-life of 20 minutes. If the initial reactant concentration is 48 mmol L⁻¹, what concentration remains after 140 minutes?
{ "A": "2.375 mmol L⁻¹", "B": "0.75 mmol L⁻¹", "C": "0.375 mmol L⁻¹", "D": "0.5625 mmol L⁻¹" }
C
0.375 mmol L⁻¹
140 minutes corresponds to 7 half-lives. The remaining concentration is [A]₀(1/2)ⁿ=48/2^7=0.375 mmol L⁻¹.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.375 mmol L⁻¹, not 2.375 mmol L⁻¹.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.375 mmol L⁻¹, not 0.75 mmol L⁻¹.", "C": "Correct. The worked calculation gives 0.375 mmol L⁻¹.", "D": "Inc...
[ "first-order kinetics", "half-life", "exponential decay" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_first_order_halflife
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_006180
physics
ray_optics
convex_lens_magnification
very_hard
provisional_template_level_label
single_correct_mcq
A real object is placed 31 cm in front of a thin convex lens of focal length 16 cm. Using the Cartesian sign convention, what is the magnitude of the linear magnification?
{ "A": "-1.93333", "B": "2.13333", "C": "1.06667", "D": "1.10667" }
C
1.06667
Using distances as positive magnitudes, 1/f=1/v+1/u gives v=uf/(u−f)=(31)(16)/(31−16)=33.06667 cm. Thus |m|=v/u=33.06667/31=1.06667.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 1.06667, not -1.93333.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1.06667, not 2.13333.", "C": "Correct. The worked calculation gives 1.06667.", "D": "Incorrect. Substituting the stated v...
[ "thin lens equation", "linear magnification", "real image" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_lens_magnification
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_008319
chemistry
physical_chemistry
faradays_law_copper
very_hard
provisional_template_level_label
single_correct_mcq
An aqueous Cu²⁺ solution is electrolysed using a current of 5 A for 20914 s. Assuming 100% current efficiency, calculate the mass of copper deposited. Use M(Cu)=63.5 g mol⁻¹ and F=96500 C mol⁻¹.
{ "A": "34.40516 g", "B": "36.40516 g", "C": "27.52412 g", "D": "25.80387 g" }
A
34.40516 g
Cu²⁺+2e⁻→Cu, so z=2. By Faraday's law m=MIt/(zF)=63.5×5×20914/(2×96500)=34.40516 g.
{ "A": "Correct. The worked calculation gives 34.40516 g.", "B": "Incorrect. Substituting the stated values into the governing relation gives 34.40516 g, not 36.40516 g.", "C": "Incorrect. Substituting the stated values into the governing relation gives 34.40516 g, not 27.52412 g.", "D": "Incorrect. Substitutin...
[ "electrolysis", "Faraday's laws", "redox stoichiometry" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_faraday_copper
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009715
chemistry
inorganic_chemistry
complex_ion_oxidation_state
hard
provisional_template_level_label
single_correct_mcq
For a hypothetical coordination ion [Co(OH)_6]^+3, each OH ligand has charge −1. Determine the formal oxidation state of Co.
{ "A": "12", "B": "8", "C": "6.75", "D": "9" }
D
9
Let the formal oxidation state of Co be x. Charge balance gives x+(6)(−1)=+3; hence x=3+6=+9.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 9, not 12.", "B": "Incorrect. Substituting the stated values into the governing relation gives 9, not 8.", "C": "Incorrect. Substituting the stated values into the governing relation gives 9, not 6.75.", "D": "Correct. The worke...
[ "coordination compounds", "oxidation state", "charge balance" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_complex_oxidation
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005782
physics
thermodynamics
ideal_gas_isochoric_pressure
hard
provisional_template_level_label
single_correct_mcq
A fixed amount of ideal gas is kept in a rigid container. Its pressure is 2.4 atm at 201 K. What is its pressure at 698 K?
{ "A": "1.83343 atm", "B": "-8.33433 atm", "C": "8.33433 atm", "D": "7.33433 atm" }
C
8.33433 atm
At constant volume, P/T is constant. P₂=P₁T₂/T₁=(2.4)(698)/(201)=8.33433 atm.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 8.33433 atm, not 1.83343 atm.", "B": "Incorrect. Substituting the stated values into the governing relation gives 8.33433 atm, not -8.33433 atm.", "C": "Correct. The worked calculation gives 8.33433 atm.", "D": "Incorrect. Subst...
[ "ideal gas law", "isochoric process", "absolute temperature" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_isochoric_gas
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009462
chemistry
organic_chemistry
degree_of_unsaturation
very_hard
provisional_template_level_label
single_correct_mcq
Assuming a neutral closed-shell formula, calculate the degree of unsaturation (DBE) for C_6H_3X_1. Treat X as the total number of monovalent halogen atoms.
{ "A": "6", "B": "5", "C": "2.5", "D": "-5" }
B
5
Use DBE=(2C+2+N−H−X)/2. Substitution gives (2×6+2+0−3−1)/2=5.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 5, not 6.", "B": "Correct. The worked calculation gives 5.", "C": "Incorrect. Substituting the stated values into the governing relation gives 5, not 2.5.", "D": "Incorrect. Substituting the stated values into the governing rela...
[ "molecular formula", "degree of unsaturation", "organic structure" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_dbe
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002562
mathematics
linear_algebra
2x2_determinant
hard
provisional_template_level_label
single_correct_mcq
Find the determinant of the matrix [[2, -7], [7, 0]].
{ "A": "98", "B": "49", "C": "73.5", "D": "47" }
B
49
For a 2×2 matrix [[a,b],[c,d]], det=ad−bc. Here it is (2)(0)−(-7)(7)=49.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 49, not 98.", "B": "Correct. The worked calculation gives 49.", "C": "Incorrect. Substituting the stated values into the governing relation gives 49, not 73.5.", "D": "Incorrect. Substituting the stated values into the governing...
[ "determinants", "matrix operations" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_determinant_2x2
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001146
mathematics
calculus
polynomial_differentiation
hard
provisional_template_level_label
single_correct_mcq
Let f(x)=-5x³ -7x² +6x+7. Evaluate f′(2).
{ "A": "-65.6", "B": "-82", "C": "-123", "D": "-41" }
B
-82
Differentiate: f′(x)=3(-5)x²+2(-7)x+(6). At x=2, f′(2)=3(-5)(2)²+2(-7)(2)+(6)=-82.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -82, not -65.6.", "B": "Correct. The worked calculation gives -82.", "C": "Incorrect. Substituting the stated values into the governing relation gives -82, not -123.", "D": "Incorrect. Substituting the stated values into the gov...
[ "power rule", "polynomial derivative" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_derivative_cubic
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_005116
physics
electrostatics
coulombs_law
hard
provisional_template_level_label
single_correct_mcq
Two point charges of +3 μC and +8 μC are separated by 12 cm in vacuum. Using k=9×10⁹ N m² C⁻², find the magnitude of the electrostatic force.
{ "A": "-15 N", "B": "15 N", "C": "14 N", "D": "2.5 N" }
B
15 N
Convert charges to coulombs and distance to metres. F=k|q₁q₂|/r²=9×10⁹(3×10⁻⁶)(8×10⁻⁶)/(12×10⁻²)²=15 N.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 15 N, not -15 N.", "B": "Correct. The worked calculation gives 15 N.", "C": "Incorrect. Substituting the stated values into the governing relation gives 15 N, not 14 N.", "D": "Incorrect. Substituting the stated values into the ...
[ "Coulomb's law", "SI unit conversion", "inverse-square law" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
physics_coulomb
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003335
mathematics
complex_numbers
real_part_of_complex_quotient
very_hard
provisional_template_level_label
single_correct_mcq
Let z=(-4+9i)/(3+11i). What is Re(z), the real part of z?
{ "A": "1.33846", "B": "-0.66923", "C": "0.66923", "D": "3.66923" }
C
0.66923
Multiply numerator and denominator by the conjugate (3-11i). Then Re(z)=(ac+bd)/(c²+d²)=((-4)(3)+(9)(11))/(3²+(11)²)=0.66923.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.66923, not 1.33846.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.66923, not -0.66923.", "C": "Correct. The worked calculation gives 0.66923.", "D": "Incorrect. Substituting the stated v...
[ "complex conjugate", "complex division", "real and imaginary parts" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_complex_quotient
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_003051
mathematics
complex_numbers
real_part_of_complex_quotient
very_hard
provisional_template_level_label
single_correct_mcq
Let z=(8+5i)/(5+6i). What is Re(z), the real part of z?
{ "A": "1.14754", "B": "4.14754", "C": "0.14754", "D": "-1.14754" }
A
1.14754
Multiply numerator and denominator by the conjugate (5-6i). Then Re(z)=(ac+bd)/(c²+d²)=((8)(5)+(5)(6))/(5²+(6)²)=1.14754.
{ "A": "Correct. The worked calculation gives 1.14754.", "B": "Incorrect. Substituting the stated values into the governing relation gives 1.14754, not 4.14754.", "C": "Incorrect. Substituting the stated values into the governing relation gives 1.14754, not 0.14754.", "D": "Incorrect. Substituting the stated va...
[ "complex conjugate", "complex division", "real and imaginary parts" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_complex_quotient
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000121
mathematics
algebra
quadratic_roots
hard
provisional_template_level_label
single_correct_mcq
For the quadratic equation 7x^2 -1x -8=0, let its roots be α and β. What is α²+β²?
{ "A": "-0.69388", "B": "1.23061", "C": "-2.30612", "D": "2.30612" }
D
2.30612
By Vieta's relations, α+β = 1/7 and αβ = -8/7. Then α²+β²=(α+β)²−2αβ = (1/7)²−2(-8/7) = 2.30612.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 2.30612, not -0.69388.", "B": "Incorrect. Substituting the stated values into the governing relation gives 2.30612, not 1.23061.", "C": "Incorrect. Substituting the stated values into the governing relation gives 2.30612, not -2.3...
[ "Vieta's formulas", "symmetric polynomial expressions" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_quadratic_vieta
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002991
mathematics
vectors
dot_product
hard
provisional_template_level_label
single_correct_mcq
Given vectors u=(8, 5, 8) and v=(-5, -5, 6), calculate u·v.
{ "A": "-16", "B": "17", "C": "-0.7", "D": "-17" }
D
-17
The dot product is the sum of corresponding component products: (8)(-5)+(5)(-5)+(8)(6)=-17.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -17, not -16.", "B": "Incorrect. Substituting the stated values into the governing relation gives -17, not 17.", "C": "Incorrect. Substituting the stated values into the governing relation gives -17, not -0.7.", "D": "Correct. T...
[ "three-dimensional vectors", "scalar product" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_vector_dot
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_008735
chemistry
physical_chemistry
equilibrium_degree_dissociation
very_hard
provisional_template_level_label
single_correct_mcq
For A(g) ⇌ 2B(g), the initial concentration of A is 1.88 mol L⁻¹ and initially B is absent. At equilibrium, 47% of A has dissociated at constant volume. Find K_c.
{ "A": "1.56714", "B": "0.13428", "C": "3.13428", "D": "1.13428" }
C
3.13428
Let α=0.47. At equilibrium [A]=c₀(1−α) and [B]=2c₀α. Thus K_c=[B]²/[A]=4c₀α²/(1−α)=4(1.88)(0.47)²/(1−0.47)=3.13428.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 3.13428, not 1.56714.", "B": "Incorrect. Substituting the stated values into the governing relation gives 3.13428, not 0.13428.", "C": "Correct. The worked calculation gives 3.13428.", "D": "Incorrect. Substituting the stated va...
[ "chemical equilibrium", "equilibrium constant", "degree of dissociation" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_equilibrium_alpha
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001128
mathematics
calculus
polynomial_differentiation
hard
provisional_template_level_label
single_correct_mcq
Let f(x)=3x³ -4x² -8x+7. Evaluate f′(0).
{ "A": "-16", "B": "-11", "C": "-8", "D": "-9" }
C
-8
Differentiate: f′(x)=3(3)x²+2(-4)x+(-8). At x=0, f′(0)=3(3)(0)²+2(-4)(0)+(-8)=-8.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives -8, not -16.", "B": "Incorrect. Substituting the stated values into the governing relation gives -8, not -11.", "C": "Correct. The worked calculation gives -8.", "D": "Incorrect. Substituting the stated values into the governing...
[ "power rule", "polynomial derivative" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_derivative_cubic
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_002316
mathematics
probability
same_colour_without_replacement
very_hard
provisional_template_level_label
single_correct_mcq
A bag contains 12 red, 9 blue and 10 green balls. Two balls are drawn uniformly at random without replacement. What is the probability that both have the same colour?
{ "A": "0.15806", "B": "0.63226", "C": "-0.31613", "D": "0.31613" }
D
0.31613
Favourable pairs = C(12,2)+C(9,2)+C(10,2)=147. Total pairs=C(31,2)=465. Therefore P=147/465=0.31613.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.31613, not 0.15806.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.31613, not 0.63226.", "C": "Incorrect. Substituting the stated values into the governing relation gives 0.31613, not -0.31...
[ "classical probability", "combinations", "without replacement" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_probability_colours
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009523
chemistry
organic_chemistry
degree_of_unsaturation
very_hard
provisional_template_level_label
single_correct_mcq
Assuming a neutral closed-shell formula, calculate the degree of unsaturation (DBE) for C_17H_8N_1X_3. Treat X as the total number of monovalent halogen atoms.
{ "A": "9.75", "B": "13", "C": "19.5", "D": "6.5" }
B
13
Use DBE=(2C+2+N−H−X)/2. Substitution gives (2×17+2+1−8−3)/2=13.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 13, not 9.75.", "B": "Correct. The worked calculation gives 13.", "C": "Incorrect. Substituting the stated values into the governing relation gives 13, not 19.5.", "D": "Incorrect. Substituting the stated values into the governi...
[ "molecular formula", "degree of unsaturation", "organic structure" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_dbe
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000197
mathematics
algebra
quadratic_roots
hard
provisional_template_level_label
single_correct_mcq
For the quadratic equation 1x^2 +12x +4=0, let its roots be α and β. What is α²+β²?
{ "A": "135", "B": "136", "C": "204", "D": "138" }
B
136
By Vieta's relations, α+β = -12/1 and αβ = 4/1. Then α²+β²=(α+β)²−2αβ = (-12/1)²−2(4/1) = 136.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 136, not 135.", "B": "Correct. The worked calculation gives 136.", "C": "Incorrect. Substituting the stated values into the governing relation gives 136, not 204.", "D": "Incorrect. Substituting the stated values into the govern...
[ "Vieta's formulas", "symmetric polynomial expressions" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_quadratic_vieta
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_009060
chemistry
physical_chemistry
nernst_equation_298K
hard
provisional_template_level_label
single_correct_mcq
At 298 K, a galvanic cell has E°cell=0.58 V, transfers 1 electrons, and has reaction quotient Q=10^6. Using E=E°−(0.0591/n)log₁₀Q, calculate Ecell.
{ "A": "1.2254 V", "B": "0.3381 V", "C": "0.2254 V", "D": "-0.2254 V" }
C
0.2254 V
Apply the Nernst equation: E=0.58−(0.0591/1)(6)=0.2254 V.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 0.2254 V, not 1.2254 V.", "B": "Incorrect. Substituting the stated values into the governing relation gives 0.2254 V, not 0.3381 V.", "C": "Correct. The worked calculation gives 0.2254 V.", "D": "Incorrect. Substituting the stat...
[ "electrochemical cells", "Nernst equation", "logarithms" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_nernst
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_001913
mathematics
combinatorics
binomial_coefficient
hard
provisional_template_level_label
single_correct_mcq
How many distinct subsets containing exactly 9 elements can be selected from a set of 89 distinct elements?
{ "A": "508501820613.59998", "B": "635627275767", "C": "762752730920.40002", "D": "-635627275767" }
B
635627275767
Order does not matter, so the count is C(89,9)=89!/[9!(80)!]=635627275767.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 635627275767, not 508501820613.59998.", "B": "Correct. The worked calculation gives 635627275767.", "C": "Incorrect. Substituting the stated values into the governing relation gives 635627275767, not 762752730920.40002.", "D": "...
[ "combinations", "factorials" ]
2
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_combinations
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_000990
mathematics
sequences_and_series
geometric_progression
hard
provisional_template_level_label
single_correct_mcq
A geometric progression has first term 7 and common ratio 5. What is the sum of its first 9 terms?
{ "A": "4101560.4", "B": "5126950.5", "C": "3417967", "D": "2563475.25" }
C
3417967
For r≠1, Sₙ=a(rⁿ−1)/(r−1). Thus Sₙ=7(5^9−1)/(5−1)=3417967.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 3417967, not 4101560.4.", "B": "Incorrect. Substituting the stated values into the governing relation gives 3417967, not 5126950.5.", "C": "Correct. The worked calculation gives 3417967.", "D": "Incorrect. Substituting the state...
[ "geometric progression", "finite geometric sum" ]
3
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
math_gp_sum
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value
openstem_008954
chemistry
physical_chemistry
equilibrium_degree_dissociation
very_hard
provisional_template_level_label
single_correct_mcq
For A(g) ⇌ 2B(g), the initial concentration of A is 1.65 mol L⁻¹ and initially B is absent. At equilibrium, 62% of A has dissociated at constant volume. Find K_c.
{ "A": "9.67642", "B": "3.33821", "C": "6.67642", "D": "13.35284" }
C
6.67642
Let α=0.62. At equilibrium [A]=c₀(1−α) and [B]=2c₀α. Thus K_c=[B]²/[A]=4c₀α²/(1−α)=4(1.65)(0.62)²/(1−0.62)=6.67642.
{ "A": "Incorrect. Substituting the stated values into the governing relation gives 6.67642, not 9.67642.", "B": "Incorrect. Substituting the stated values into the governing relation gives 6.67642, not 3.33821.", "C": "Correct. The worked calculation gives 6.67642.", "D": "Incorrect. Substituting the stated va...
[ "chemical equilibrium", "equilibrium constant", "degree of dissociation" ]
4
numeric
en
synthetic_parametric
AxiloLabz deterministic STEM question generator
chem_equilibrium_alpha
template_formula_generated_structurally_validated_not_expert_reviewed
Answer is computed by the explicit equation in the generator template; this is not an independent expert proof.
Difficulty is approximate and not independently calibrated by JEE examiners; no ultra-hard claim is made in v0.1.
original_synthetic_question
correct_answer_option_matches_generated_numeric_value