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train_station
SELECT LOCATION , sum(number_of_platforms) , sum(total_passengers) FROM station GROUP BY LOCATION
Show all locations and the total number of platforms and passengers for all train stations in each location.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('Birmingham', 13, 36.331) ('Glasgow', 17, 29.658) ('London', 140, 498.50700000000006)
train_station
SELECT DISTINCT LOCATION FROM station WHERE number_of_platforms >= 15 AND total_passengers > 25
Show all locations that have train stations with at least 15 platforms and train stations with more than 25 total passengers.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('London',) ('Glasgow',)
train_station
SELECT LOCATION FROM station EXCEPT SELECT LOCATION FROM station WHERE number_of_platforms >= 15
Show all locations which don't have a train station with at least 15 platforms.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('Birmingham',)
train_station
SELECT LOCATION FROM station GROUP BY LOCATION ORDER BY count(*) DESC LIMIT 1
Show the location with most number of train stations.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('London',)
train_station
SELECT name , TIME , service FROM train
Show the name, time, and service for all trains.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('Ananthapuri Express', '17:15', 'Daily') ('Guruvayur Express', '22:10', 'Daily') ('Guruvayur Express', '4:49', 'Daily') ('Ananthapuri Express', '11:35', 'Daily') ('Jayanthi Janatha Express', '06:30', 'Daily') ('Island Express', '11:15', 'Daily') ('Madurai Fast Passenger', '21:49', 'Daily') ('Quilon Fast Passenger', '0...
train_station
SELECT count(*) FROM train
Show the number of trains
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
(11,)
train_station
SELECT name , service FROM train ORDER BY TIME
Show the name and service for all trains in order by time.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('Parasuram Express', 'Daily') ('Quilon Fast Passenger', 'Daily') ('Jayanthi Janatha Express', 'Daily') ('Jayanthi Janatha Express', 'Daily') ('Island Express', 'Daily') ('Ananthapuri Express', 'Daily') ('Island Express', 'Daily') ('Ananthapuri Express', 'Daily') ('Madurai Fast Passenger', 'Daily') ('Guruvayur Express'...
train_station
SELECT T2.name , count(*) FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id
Show the station name and number of trains in each station.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('London Waterloo', 3) ('London Victoria', 1) ('London Bridge', 1) ('London Euston', 1) ("London King's Cross", 1) ('Glasgow Central', 2) ('East Croydon', 2)
train_station
SELECT T2.name , T3.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id
show the train name and station name for each train.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('London Waterloo', 'Ananthapuri Express') ('London Waterloo', 'Guruvayur Express') ('London Waterloo', 'Guruvayur Express') ('London Victoria', 'Ananthapuri Express') ('London Bridge', 'Jayanthi Janatha Express') ('London Euston', 'Island Express') ("London King's Cross", 'Madurai Fast Passenger') ('Glasgow Central', ...
train_station
SELECT T3.name , T3.time FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T2.location = 'London' ORDER BY T3.time DESC
Show all train names and times in stations in London in descending order by train time.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('Guruvayur Express', '4:49') ('Guruvayur Express', '22:10') ('Madurai Fast Passenger', '21:49') ('Ananthapuri Express', '17:15') ('Ananthapuri Express', '11:35') ('Island Express', '11:15') ('Jayanthi Janatha Express', '10:38') ('Jayanthi Janatha Express', '06:30') ('Parasuram Express', '04:20')
train_station
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id ORDER BY count(*) DESC LIMIT 1
Show the station name with greatest number of trains.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('London Waterloo',)
train_station
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id GROUP BY T1.station_id HAVING count(*) >= 2
Show the station name with at least two trains.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('London Waterloo',) ('Glasgow Central',) ('East Croydon',)
train_station
SELECT LOCATION FROM station GROUP BY LOCATION HAVING count(*) = 1
Show all locations with only 1 station.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('Birmingham',) ('Glasgow',)
train_station
SELECT name FROM station WHERE station_id NOT IN (SELECT station_id FROM train_station)
Show station names without any trains.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('London Liverpool Street',) ('London Charing Cross',) ('Birmingham New Street',) ('London St Pancras',) ('Stratford',)
train_station
SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id = T1.train_id WHERE T3.Name = "Ananthapuri Express" INTERSECT SELECT T2.name FROM train_station AS T1 JOIN station AS T2 ON T1.station_id = T2.station_id JOIN train AS T3 ON T3.train_id =...
What are the names of the stations which serve both "Ananthapuri Express" and "Guruvayur Express" trains?
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('London Waterloo',)
train_station
SELECT T2.name FROM train_station AS T1 JOIN train AS T2 ON T1.train_id = T2.train_id WHERE T1.station_id NOT IN (SELECT T4.station_id FROM train_station AS T3 JOIN station AS T4 ON T3.station_id = T4.station_id WHERE t4.location = "London")
Find the names of the trains that do not pass any station located in London.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('Quilon Fast Passenger',) ('Island Express',)
train_station
SELECT name , LOCATION FROM station ORDER BY Annual_entry_exit , Annual_interchanges
List the names and locations of all stations ordered by their yearly entry exit and interchange amounts.
PRAGMA foreign_keys = ON; CREATE TABLE "station" ( "Station_ID" int, "Name" text, "Annual_entry_exit" real, "Annual_interchanges" real, "Total_Passengers" real, "Location" text, "Main_Services" text, "Number_of_Platforms" int, PRIMARY KEY ("Station_ID") ); CREATE TABLE "train" ( "Train_ID" int, "Name" text, "Time" te...
('East Croydon', 'London') ('Stratford', 'London') ('London St Pancras', 'London') ('Glasgow Central', 'Glasgow') ("London King's Cross", 'London') ('Birmingham New Street', 'Birmingham') ('London Euston', 'London') ('London Charing Cross', 'London') ('London Bridge', 'London') ('London Liverpool Street', 'London') ('L...
driving_school
SELECT vehicle_id FROM Vehicles;
List all vehicle id
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(1,) (2,) (3,)
driving_school
SELECT vehicle_id FROM Vehicles;
What are the ids of all vehicles?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(1,) (2,) (3,)
driving_school
SELECT count(*) FROM Vehicles;
How many vehicle in total?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(3,)
driving_school
SELECT count(*) FROM Vehicles;
How many vehicles exist?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(3,)
driving_school
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1;
Show the detail of vehicle with id 1.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Van',)
driving_school
SELECT vehicle_details FROM Vehicles WHERE vehicle_id = 1;
What are the details of the car with id 1?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Van',)
driving_school
SELECT first_name , middle_name , last_name FROM Staff;
List the first name middle name and last name of all staff.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Janessa', 'Amara', 'Sawayn') ('Camylle', 'Icie', 'Weissnat') ('Kaitlin', 'Stephania', 'Mertz') ('Rebekah', 'Sherwood', 'Hermann') ('Jedidiah', 'Dejon', 'Herzog') ('Eulalia', 'Tre', 'Maggio') ('Queenie', 'Madelyn', 'Macejkovic') ('Titus', 'Duane', 'Durgan') ('Margie', 'Caesar', 'Doyle') ('Jaleel', 'Maiya', 'Rogahn') (...
driving_school
SELECT first_name , middle_name , last_name FROM Staff;
What are the first, middle, and last names of all staff?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Janessa', 'Amara', 'Sawayn') ('Camylle', 'Icie', 'Weissnat') ('Kaitlin', 'Stephania', 'Mertz') ('Rebekah', 'Sherwood', 'Hermann') ('Jedidiah', 'Dejon', 'Herzog') ('Eulalia', 'Tre', 'Maggio') ('Queenie', 'Madelyn', 'Macejkovic') ('Titus', 'Duane', 'Durgan') ('Margie', 'Caesar', 'Doyle') ('Jaleel', 'Maiya', 'Rogahn') (...
driving_school
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the birthday of the staff member with first name as Janessa and last name as Sawayn?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('2010-12-08 16:55:14',)
driving_school
SELECT date_of_birth FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the date of birth for the staff member named Janessa Sawayn?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('2010-12-08 16:55:14',)
driving_school
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the staff member with first name as Janessa and last name as Sawayn join the company?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('2017-04-27 03:21:26',)
driving_school
SELECT date_joined_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the staff member named Janessa Sawayn join the company?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('2017-04-27 03:21:26',)
driving_school
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the staff member with first name as Janessa and last name as Sawayn leave the company?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('2018-03-23 22:53:12',)
driving_school
SELECT date_left_staff FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
When did the staff member Janessa Sawayn leave the company?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('2018-03-23 22:53:12',)
driving_school
SELECT count(*) FROM Staff WHERE first_name = "Ludie";
How many staff have the first name Ludie?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(1,)
driving_school
SELECT count(*) FROM Staff WHERE first_name = "Ludie";
How many employees have a first name of Ludie?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(1,)
driving_school
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the nickname of staff with first name as Janessa and last name as Sawayn?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('thompson.constantin',)
driving_school
SELECT nickname FROM Staff WHERE first_name = "Janessa" AND last_name = "Sawayn";
What is the nickname of the employee named Janessa Sawayn?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('thompson.constantin',)
driving_school
SELECT count(*) FROM Staff;
How many staff in total?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(15,)
driving_school
SELECT count(*) FROM Staff;
How many employees are there?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(15,)
driving_school
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
Which city does staff with first name as Janessa and last name as Sawayn live?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Damianfort',)
driving_school
SELECT T1.city FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
In what city does Janessa Sawayn live?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Damianfort',)
driving_school
SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
Which country and state does staff with first name as Janessa and last name as Sawayn lived?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('USA', 'Connecticut')
driving_school
SELECT T1.country , T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
In which country and state does Janessa Sawayn live?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('USA', 'Connecticut')
driving_school
SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin";
How long is the total lesson time took by customer with first name as Rylan and last name as Goodwin?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(11,)
driving_school
SELECT sum(T1.lesson_time) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin";
How long is the total lesson time took by the customer named Rylan Goodwin?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(11,)
driving_school
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
What is the zip code of staff with first name as Janessa and last name as Sawayn lived?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('61121',)
driving_school
SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
What is the zip code of the hosue of the employee named Janessa Sawayn?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('61121',)
driving_school
SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia";
How many staff live in state Georgia?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(2,)
driving_school
SELECT count(*) FROM Addresses WHERE state_province_county = "Georgia";
How many employees live in Georgia?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(2,)
driving_school
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
Find out the first name and last name of staff lived in city Damianfort.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Janessa', 'Sawayn') ('Jedidiah', 'Herzog')
driving_school
SELECT T2.first_name , T2.last_name FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id WHERE T1.city = "Damianfort";
What is the first and last name of all employees who live in the city Damianfort?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Janessa', 'Sawayn') ('Jedidiah', 'Herzog')
driving_school
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
Which city lives most of staffs? List the city name and number of staffs.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Port Melyssa', 4)
driving_school
SELECT T1.city , count(*) FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.city ORDER BY count(*) DESC LIMIT 1;
In which city do the most employees live and how many of them live there?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Port Melyssa', 4)
driving_school
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
List the states which have between 2 to 4 staffs living there.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Connecticut',) ('Louisiana',)
driving_school
SELECT T1.state_province_county FROM Addresses AS T1 JOIN Staff AS T2 ON T1.address_id = T2.staff_address_id GROUP BY T1.state_province_county HAVING count(*) BETWEEN 2 AND 4;
What are the names of the states that have 2 to 4 employees living there?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Connecticut',) ('Louisiana',)
driving_school
SELECT first_name , last_name FROM Customers;
List the first name and last name of all customers.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Carole', 'Bernhard') ('Genevieve', 'Terry') ('Clara', 'Ortiz') ('Jordy', 'Tromp') ('Millie', 'Bruen') ('Amya', 'Spinka') ('Marina', 'Koelpin') ('Dianna', 'Trantow') ('Leif', 'Mertz') ('Rylan', 'Goodwin') ('Ray', 'Kohler') ('Omer', 'Leuschke') ('Sigrid', 'Schmeler') ('Estelle', 'Grant') ('Dameon', 'Sanford')
driving_school
SELECT first_name , last_name FROM Customers;
What are the first and last names for all customers?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Carole', 'Bernhard') ('Genevieve', 'Terry') ('Clara', 'Ortiz') ('Jordy', 'Tromp') ('Millie', 'Bruen') ('Amya', 'Spinka') ('Marina', 'Koelpin') ('Dianna', 'Trantow') ('Leif', 'Mertz') ('Rylan', 'Goodwin') ('Ray', 'Kohler') ('Omer', 'Leuschke') ('Sigrid', 'Schmeler') ('Estelle', 'Grant') ('Dameon', 'Sanford')
driving_school
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
List email address and birthday of customer whose first name as Carole.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('everette.goyette@example.org', '1998-12-15 13:24:40')
driving_school
SELECT email_address , date_of_birth FROM Customers WHERE first_name = "Carole"
What are the email addresses and date of births for all customers who have a first name of Carole?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('everette.goyette@example.org', '1998-12-15 13:24:40')
driving_school
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
List phone number and email address of customer with more than 2000 outstanding balance.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('+14(5)2351480248', 'huel.jana@example.org') ('374-483-2758x85087', 'hilario.sporer@example.org') ('218.550.1362', 'afranecki@example.com') ('1-618-535-9750', 'asha.kilback@example.org') ('1-673-962-8158x7646', 'kozey.citlalli@example.org') ('(662)490-3108', 'mayert.judy@example.com') ('206-054-0689x05861', 'kroberts@...
driving_school
SELECT phone_number , email_address FROM Customers WHERE amount_outstanding > 2000;
What are the phone numbers and email addresses of all customers who have an outstanding balance of more than 2000?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('+14(5)2351480248', 'huel.jana@example.org') ('374-483-2758x85087', 'hilario.sporer@example.org') ('218.550.1362', 'afranecki@example.com') ('1-618-535-9750', 'asha.kilback@example.org') ('1-673-962-8158x7646', 'kozey.citlalli@example.org') ('(662)490-3108', 'mayert.judy@example.com') ('206-054-0689x05861', 'kroberts@...
driving_school
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
What is the status code, mobile phone number and email address of customer with last name as Kohler or first name as Marina?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Bad Customer', '848-099-2095x785', 'mayert.judy@example.com') ('Good Customer', '577-584-4864', 'karina.carroll@example.net')
driving_school
SELECT customer_status_code , cell_mobile_phone_number , email_address FROM Customers WHERE first_name = "Marina" OR last_name = "Kohler"
What is the status code, phone number, and email address of the customer whose last name is Kohler or whose first name is Marina?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Bad Customer', '848-099-2095x785', 'mayert.judy@example.com') ('Good Customer', '577-584-4864', 'karina.carroll@example.net')
driving_school
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
When are the birthdays of customer who are classified as 'Good Customer' status?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('1994-06-21 01:34:56',) ('1993-02-07 05:40:26',) ('1993-03-08 08:48:42',) ('1994-05-07 01:32:16',) ('1988-09-19 14:45:56',) ('1996-05-23 01:21:54',)
driving_school
SELECT date_of_birth FROM Customers WHERE customer_status_code = 'Good Customer'
What is the date of birth of every customer whose status code is 'Good Customer'?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('1994-06-21 01:34:56',) ('1993-02-07 05:40:26',) ('1993-03-08 08:48:42',) ('1994-05-07 01:32:16',) ('1988-09-19 14:45:56',) ('1996-05-23 01:21:54',)
driving_school
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
When did customer with first name as Carole and last name as Bernhard became a customer?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('2016-05-11 17:03:48',)
driving_school
SELECT date_became_customer FROM Customers WHERE first_name = "Carole" AND last_name = "Bernhard";
When did Carole Bernhard first become a customer?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('2016-05-11 17:03:48',)
driving_school
SELECT count(*) FROM Customers;
How many customers in total?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(15,)
driving_school
SELECT count(*) FROM Customers;
How many customers are there?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(15,)
driving_school
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
List all customer status codes and the number of customers having each status code.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Bad Customer', 9) ('Good Customer', 6)
driving_school
SELECT customer_status_code , count(*) FROM Customers GROUP BY customer_status_code;
For each customer status code, how many customers are classified that way?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Bad Customer', 9) ('Good Customer', 6)
driving_school
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
Which customer status code has least number of customers?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Good Customer',)
driving_school
SELECT customer_status_code FROM Customers GROUP BY customer_status_code ORDER BY count(*) ASC LIMIT 1;
What is the status code with the least number of customers?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Good Customer',)
driving_school
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
How many lessons taken by customer with first name as Rylan and last name as Goodwin were completed?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(1,)
driving_school
SELECT count(*) FROM Lessons AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Rylan" AND T2.last_name = "Goodwin" AND T1.lesson_status_code = "Completed";
How many lessons did the customer Ryan Goodwin complete?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(1,)
driving_school
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
What is maximum, minimum and average amount of outstanding of customer?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(9500.0, 255.0, 5643.733333333334)
driving_school
SELECT max(amount_outstanding) , min(amount_outstanding) , avg(amount_outstanding) FROM Customers;
What is the maximum, minimum, and average amount of money outsanding for all customers?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(9500.0, 255.0, 5643.733333333334)
driving_school
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
List the first name and last name of customers have the amount of outstanding between 1000 and 3000.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Rylan', 'Goodwin') ('Omer', 'Leuschke') ('Sigrid', 'Schmeler')
driving_school
SELECT first_name , last_name FROM Customers WHERE amount_outstanding BETWEEN 1000 AND 3000;
What are the first and last names of all customers with between 1000 and 3000 dollars outstanding?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Rylan', 'Goodwin') ('Omer', 'Leuschke') ('Sigrid', 'Schmeler')
driving_school
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
List first name and last name of customers lived in city Lockmanfurt.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Sigrid', 'Schmeler')
driving_school
SELECT T1.first_name , T1.last_name FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T2.city = "Lockmanfurt";
What are the first and last names of all customers who lived in Lockmanfurt?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Sigrid', 'Schmeler')
driving_school
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
Which country does customer with first name as Carole and last name as Bernhard lived in?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('USA',)
driving_school
SELECT T2.country FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is the country in which the customer Carole Bernhard lived?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('USA',)
driving_school
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is zip code of customer with first name as Carole and last name as Bernhard?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('75074',)
driving_school
SELECT T2.zip_postcode FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id WHERE T1.first_name = "Carole" AND T1.last_name = "Bernhard"
What is the zip code of the customer Carole Bernhard?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('75074',)
driving_school
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
Which city does has most number of customers?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('South Richieport',)
driving_school
SELECT T2.city FROM Customers AS T1 JOIN Addresses AS T2 ON T1.customer_address_id = T2.address_id GROUP BY T2.city ORDER BY count(*) DESC LIMIT 1;
What is the city with the most customers?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('South Richieport',)
driving_school
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
How much in total does customer with first name as Carole and last name as Bernhard paid?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(9886.62,)
driving_school
SELECT sum(T1.amount_payment) FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.first_name = "Carole" AND T2.last_name = "Bernhard"
What is the total amount of moeny paid by the customer Carole Bernhard?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(9886.62,)
driving_school
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
List the number of customers that did not have any payment history.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(4,)
driving_school
SELECT count(*) FROM Customers WHERE customer_id NOT IN ( SELECT customer_id FROM Customer_Payments );
How many customers have no payment histories?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(4,)
driving_school
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
List first name and last name of customers that have more than 2 payments.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Estelle', 'Grant')
driving_school
SELECT T2.first_name , T2.last_name FROM Customer_Payments AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING count(*) > 2;
What are the first and last names of all customers with more than 2 payments?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Estelle', 'Grant')
driving_school
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
List all payment methods and number of payments using each payment methods.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Credit Card', 5) ('Direct Debit', 10)
driving_school
SELECT payment_method_code , count(*) FROM Customer_Payments GROUP BY payment_method_code;
For each payment method, how many payments were made?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
('Credit Card', 5) ('Direct Debit', 10)
driving_school
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
How many lessons were in cancelled state?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(9,)
driving_school
SELECT count(*) FROM Lessons WHERE lesson_status_code = "Cancelled";
How many lessons have been cancelled?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(9,)
driving_school
SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%";
List lesson id of all lessons taught by staff with first name as Janessa, last name as Sawayn and nickname containing letter 's'.
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(4,)
driving_school
SELECT T1.lesson_id FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn" AND nickname LIKE "%s%";
What are the the lesson ids of all staff taught by Janessa Sawayn whose nickname has the letter s?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(4,)
driving_school
SELECT count(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%a%"
How many lessons taught by staff whose first name has letter 'a' in it?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(5,)
driving_school
SELECT count(*) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name LIKE "%a%"
How many lessons were taught by a staff member whose first name has the letter 'a' in it?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(5,)
driving_school
SELECT sum(lesson_time) FROM Lessons AS T1 JOIN Staff AS T2 ON T1.staff_id = T2.staff_id WHERE T2.first_name = "Janessa" AND T2.last_name = "Sawayn";
How long is the total lesson time taught by staff with first name as Janessa and last name as Sawayn?
PRAGMA foreign_keys = ON; CREATE TABLE `Addresses` ( `address_id` INTEGER PRIMARY KEY, `line_1_number_building` VARCHAR(80), `city` VARCHAR(50), `zip_postcode` VARCHAR(20), `state_province_county` VARCHAR(50), `country` VARCHAR(50) ); INSERT INTO Addresses (`address_id`, `line_1_number_building`, `city`, `zip_postc...
(9,)