task
stringclasses
5 values
input
stringlengths
89
339
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1nc(CNC(=O)c2cccc(NC(=O)[C@H]3C[C@H]3C)c2)c(C)s1 ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CCN(C(=O)c1cccc(I)c1)[C@@H]1CCS(=O)(=O)C1 ### Response: 2
ring_counting
### Instruction: Count the five-membered rings in the following molecule. Cc1ccc(N2CCN(c3nccn4c(=O)n(CC(=O)NC5CCCCC5)nc34)CC2)cc1 ### Response: 1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. C[C@H]1CCCC[NH+]1CC(=O)N(C)c1nc2ccccc2s1 ### Response: 1
functional_group
### Instruction: Does the molecule contain a amide group? Cc1noc(C)c1[C@@H](C)NC(=O)CCCNC(=O)C1CC1 ### Response: Yes
functional_group
### Instruction: Does the molecule contain a sulfonyl group? CCCc1nc(-c2cc(Cl)cs2)nc(NC)c1Br ### Response: No
canonicalization
### Instruction: Canonicalize the following SMILES string. N1(S(=O)([C@@H](C[NH3+])C)=O)CC(CC1)(C)C ### Response: C[C@H](C[NH3+])S(=O)(=O)N1CCC(C)(C)C1
functional_group
### Instruction: Does the molecule contain a aromatic_ring group? Cc1c(NC(=O)CSc2nc3sc4c(c3c(=O)[nH]2)CCCC4)c(=O)n(-c2ccccc2)n1C ### Response: Yes
functional_group
### Instruction: Does the molecule contain a aldehyde group? Cc1ccc2ncc(C(=O)Nc3ncccc3OCc3ccncc3)n2c1 ### Response: No
functional_group
### Instruction: Does the molecule contain a halide group? Cc1nn(-c2ccccc2F)c2ncc3c(c12)C(=O)N(c1ccc(C(C)C)cc1)C3=O ### Response: Yes
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? C[C@@H](Sc1nnc(-c2c[nH]c3ccccc23)n1C1CC1)c1ccccc1 ### Response: 2
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [12*]S(=O)(=O)c1c(C)[nH]c(=O)[nH]c1=O Fragment 2: [5*]N1CCN([5*])CC1 ### Response: COc1ccc(N2CCN(S(=O)(=O)c3c(C)[nH]c(=O)[nH]c3=O)CC2)cc1
functional_group
### Instruction: Does the molecule contain a halide group? Nn1c(SCc2ccc(F)cc2)nnc1-c1ccccn1 ### Response: Yes
functional_group
### Instruction: Does the molecule contain a halide group? O=C(c1cccnc1Cl)N(CC1CCC1)c1ccccc1 ### Response: Yes
functional_group
### Instruction: Does the molecule contain a halide group? Cc1ccc(C(=O)COc2ccc(Cl)cc2N2C(=O)[C@H]3CCCC[C@@H]3C2=O)cc1 ### Response: Yes
ring_counting
### Instruction: Count the five-membered rings in the following molecule. O=C(Nc1ccc(F)cc1)N[C@H]1CCN(Cc2cnc(Cl)s2)C1 ### Response: 2
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? C[C@H]([NH2+]CCNC(=O)c1ccco1)c1nccs1 ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. N1(C(Cc2cc(O)c(C)cc2)=O)C[C@H](CCC1)N1C(=O)NCC1 ### Response: Cc1ccc(CC(=O)N2CCC[C@H](N3CCNC3=O)C2)cc1O
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]NC[C@@H]1CCS(=O)(=O)C1 Fragment 2: [4*]C[C@@H]1CCS(=O)(=O)C1 ### Response: O=C(NC[C@@H]1CCS(=O)(=O)C1)N1CCC(CO)CC1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1cc(SCc2ccccc2)ncc1N ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. [C@H](C)([NH2+]C)c1c(OCCN2CCOCC2)ccc(c1)F ### Response: C[NH2+][C@H](C)c1cc(F)ccc1OCCN1CCOCC1
functional_group
### Instruction: Does the molecule contain a halide group? CC[C@@H](NC(=O)C[C@H](C)NC(=O)C1CCCC1)c1ccc(C)c(F)c1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. C(Oc1ccc(cc1)OCC(N1CCN(CC1)c1nccn1-c1cccc(Cl)c1)=O)C ### Response: CCOc1ccc(OCC(=O)N2CCN(c3nccn3-c3cccc(Cl)c3)CC2)cc1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? OC[C@H]1CCC[C@@H]1Nc1cc(C(F)(F)F)nc2ncnn12 ### Response: 1
functional_group
### Instruction: Does the molecule contain a halide group? CC(C)OCCS(=O)(=O)N(C)Cc1ccc(O)cc1 ### Response: No
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CC(C)(C[N+](C)(C)C)[C@@H]1O[C@H]2CCCC[C@@H]2C2=C1CCCC2 ### Response: 3
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*][NH+](C)C Fragment 2: [4*]Cc1cccnc1 ### Response: C[NH+](C)[C@@H]1CC[C@@H](NC(=O)c2ccc(SCc3cccnc3)cc2)C1
functional_group
### Instruction: Does the molecule contain a amide group? CCONC(=O)[C@@H]1CC[C@H]2CCCC[C@@H]2[NH2+]1 ### Response: Yes
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1ccc(CN(CCc2ccccc2)C(=O)[C@H](C)NC(N)=O)s1 ### Response: 3
canonicalization
### Instruction: Canonicalize the following SMILES string. C1(=S)S/C(=C\NCc2ccc(cc2)OC)C(=N1)[O-] ### Response: COc1ccc(CN/C=C2\SC(=S)N=C2[O-])cc1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COCCN1CCC[C@](O)(CN2CCN(c3nc(C)cc(C)n3)CC2)C1=O ### Response: 2
ring_counting
### Instruction: Count the six-membered rings in the following molecule. COc1ccc([C@@H](C[NH3+])C(C)C)cc1OC ### Response: 1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? C[C@@H]1CCC[C@@H](C)N1S(=O)(=O)c1ccc(Br)cc1 ### Response: 1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. N#C/C(C(=O)C=C1CCSCC1)=C(/[O-])Nc1ccccn1 ### Response: 0
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? O=C(NCCc1cnn(-c2ccccc2)c1)[C@@H]1CC(=O)N(Cc2ccco2)C1 ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. [C@@H]1(C[C@@H](/C(C)=C\CC[NH2+]C)CCC1)S(C)(=O)=O ### Response: C[NH2+]CC/C=C(/C)[C@H]1CCC[C@@H](S(C)(=O)=O)C1
functional_group
### Instruction: Does the molecule contain a aldehyde group? CN(Cc1[nH]cc(-c2ccc(Br)cc2)[nH+]1)C[C@H]1CCOC1 ### Response: No
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [4*]Cc1cccc(N[5*])c1 Fragment 2: [1*]C(C)=O ### Response: CC(=O)Nc1cccc(CN[C@H]2CC[NH+]([C@@H](C)c3ccccc3)C2)c1
canonicalization
### Instruction: Canonicalize the following SMILES string. O=C(N/N=C/c1ccc(cc1)Oc1ccccc1)OCC ### Response: CCOC(=O)N/N=C/c1ccc(Oc2ccccc2)cc1
canonicalization
### Instruction: Canonicalize the following SMILES string. OCC1([NH+](C)Cc2c(nn(C)c2OC)C)CCSCC1 ### Response: COc1c(C[NH+](C)C2(CO)CCSCC2)c(C)nn1C
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1nnc(CSCc2ccc(F)cc2F)n1C ### Response: 1
canonicalization
### Instruction: Canonicalize the following SMILES string. O(C(=O)C1[C@H](C(=C(OC=1N)C)C(OC(C)(C)C)=O)c1ccc(C#N)cc1)C ### Response: COC(=O)C1=C(N)OC(C)=C(C(=O)OC(C)(C)C)[C@@H]1c1ccc(C#N)cc1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. COc1cc(OC)c(NC(=O)Nc2c(-c3cccnc3)[nH]c3ccccc23)cc1Cl ### Response: 1
ring_counting
### Instruction: Count the five-membered rings in the following molecule. O=C(Cc1ccccc1Cl)/N=C1/S[C@H]2CS(=O)(=O)C[C@H]2N1Cc1ccc(F)cc1 ### Response: 2
functional_group
### Instruction: Does the molecule contain a amide group? O=C(c1ccc(Br)nc1)N1CCC[C@H]1c1cccnc1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. c1cc(NCC(=O)N/N=C/c2cn(C)nc2)ccc1OC ### Response: COc1ccc(NCC(=O)N/N=C/c2cnn(C)c2)cc1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]Nc1ccc([16*])c(Cl)c1 Fragment 2: [1*]C(=O)c1ccc([16*])cc1 ### Response: NC(=O)c1ccc(C(=O)Nc2ccc(N3CCSCC3)c(Cl)c2)cc1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [9*]n1nc(O)c2c1N=C(C)S[C@@H]2c1cccnc1 Fragment 2: [15*]C1CCCC1 ### Response: CC1=Nc2c(c(O)nn2C2CCCC2)[C@@H](c2cccnc2)S1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. O=C1[C@@H](Sc2nncn2C2CC2)CCN1c1ccccc1 ### Response: 1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC[C@H](C)NS(=O)(=O)c1ccc(NC(=O)C2CCN(C(=O)c3cccs3)CC2)cc1 ### Response: 2
functional_group
### Instruction: Does the molecule contain a hydroxyl group? Oc1ccc(C[C@@H]2CCC[C@H](O)C2)cc1 ### Response: Yes
functional_group
### Instruction: Does the molecule contain a amide group? O=C(NCCN1CC[NH2+]CC1)N1CCCCCC1 ### Response: Yes
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]Nc1ccccc1C Fragment 2: [1*]C(=O)[C@H]1CCCN1C([1*])=O ### Response: Cc1ccc(NC(=O)N2CCC[C@@H]2C(=O)Nc2ccccc2C)cc1
functional_group
### Instruction: Does the molecule contain a nitro group? Cc1cc([N+](=O)[O-])ccc1C(=O)Nc1cnn(CC(C)C)c1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. C1(C(OCC)=O)[C@@H](c2ccccc2)[C@@H](NN=1)C(=O)c1ccc(OC)cc1 ### Response: CCOC(=O)C1=NN[C@@H](C(=O)c2ccc(OC)cc2)[C@@H]1c1ccccc1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [16*]c1ccc(C)c(Br)c1 Fragment 2: [1*]C(=O)N[5*] ### Response: Cc1ccc(NC(=O)NCCCN2CCOCC2)cc1Br
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [1*]C(=O)CC[8*] Fragment 2: [5*]N[C@H]([8*])C1CCOCC1 ### Response: COc1ccc([C@@H](NC(=O)CCc2cc(F)ccc2F)C2CCOCC2)cc1
canonicalization
### Instruction: Canonicalize the following SMILES string. c1(nc(c(cc1)OCC(=O)N[C@H](C)CC)C[C@H]([NH3+])C)C ### Response: CC[C@@H](C)NC(=O)COc1ccc(C)nc1C[C@@H](C)[NH3+]
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? O[C@H]1CSc2nc(-c3ccccc3)nn2C1 ### Response: 0
functional_group
### Instruction: Does the molecule contain a sulfonyl group? C/C=C(\C)C(=O)N1CCN(Cc2cc(OC)cc(OC)c2)CC1 ### Response: No
functional_group
### Instruction: Does the molecule contain a phenol group? CC(C)OC[C@@H]([NH3+])[C@H]1CCc2ccccc2C1 ### Response: No
functional_group
### Instruction: Does the molecule contain a ether group? COCCCNC(=O)Cn1cccc1[C@@H](C)O ### Response: Yes
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [16*]c1ccccc1 Fragment 2: [12*]S(=O)(=O)c1cccc(F)c1 ### Response: O=S(=O)(Nc1nc(-c2ccccc2)cs1)c1cccc(F)c1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COC(=O)CCc1cs/c(=N\S(=O)(=O)c2cc(C)c(C)s2)[nH]1 ### Response: 3
canonicalization
### Instruction: Canonicalize the following SMILES string. c1cc(ccc1)[C@H](C)CC(Nc1c(F)cccc1Br)=O ### Response: C[C@H](CC(=O)Nc1c(F)cccc1Br)c1ccccc1
canonicalization
### Instruction: Canonicalize the following SMILES string. C#CCOc1ccc(cc1OC)/C=N/O ### Response: C#CCOc1ccc(/C=N/O)cc1OC
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CC(C)[C@H](C(=O)N[C@@H](C)c1ccc2c(c1)OCCO2)N1CCCC1=O ### Response: 4
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1cccc(NC(=O)C(=O)NCCc2cn3ccccc3n2)c1 ### Response: 2
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CCC[C@@H](C)NC(=O)[C@@H]1CCCN(C(=O)Nc2ccc(C)c(OCC)c2)C1 ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. FC(Oc1cccc(NC(=O)NCCc2sccc2)c1)F ### Response: O=C(NCCc1cccs1)Nc1cccc(OC(F)F)c1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Cc1ccc(NC(=O)[C@H](NC(=O)c2ccc(F)cc2)C(C)C)cc1-n1cnnn1 ### Response: 4
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC[C@H]1NC(=O)[C@H](CC)N(Cc2cscc2C)C1=O ### Response: 1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. O=C1N=C([O-])[C@]2(Cc3cc([N+](=O)[O-])ccc3N3CCOC[C@@H]32)C(=O)N1c1ccc(Cl)cc1 ### Response: 5
ring_counting
### Instruction: Count the six-membered rings in the following molecule. CC(=O)c1cc(F)c(C)cc1N1CCO[C@H](C)C1 ### Response: 2
functional_group
### Instruction: Does the molecule contain a nitro group? CNC(=O)c1ccc(N2CCN(Cc3cc(=O)n4ccsc4[nH+]3)CC2)c([N+](=O)[O-])c1 ### Response: Yes
canonicalization
### Instruction: Canonicalize the following SMILES string. CN(C)S(=O)(=O)N1CC[NH+](CCc2c(C(F)(F)F)cccc2)CC1 ### Response: CN(C)S(=O)(=O)N1CC[NH+](CCc2ccccc2C(F)(F)F)CC1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. Cc1cc(C(F)F)n2ncc(C(=O)Nc3cnn(Cc4ccc(Cl)cc4Cl)c3)c2n1 ### Response: 2
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? COc1ccc(-c2n[nH]cc2C(=O)N[C@@H](C)c2ccccc2)cc1 ### Response: 2
canonicalization
### Instruction: Canonicalize the following SMILES string. Fc1c(ccc([C@@H]2[C@@H](CCO2)NC(NCCC[S@@](C)=O)=O)c1)Cl ### Response: C[S@@](=O)CCCNC(=O)N[C@@H]1CCO[C@@H]1c1ccc(Cl)c(F)c1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? O=C(N[C@H](c1ccccc1)c1ccco1)c1ccc(N2CCNC2=O)cc1 ### Response: 1
functional_group
### Instruction: Does the molecule contain a aromatic_ring group? O=C(c1ccc(CN2CCc3sccc3C2)cc1)N1CCCC1 ### Response: Yes
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [16*]c1ccccc1F Fragment 2: [5*]N[C@@H]([8*])c1ccccc1F ### Response: Cc1nc([C@H](NC(=O)[C@H]2CCO[C@@H]2C)c2ccccc2F)no1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [5*]NCCC1=c2ccccc2=[NH+]C1 Fragment 2: [8*]CC1=c2ccccc2=[NH+]C1 ### Response: O=C(NCCC1=c2ccccc2=[NH+]C1)[C@@H]1N[C@@H](CC2=c3ccccc3=[NH+]C2)NO1
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? Nc1ccc(N2CCOCC2)nc1 ### Response: 0
functional_group
### Instruction: Does the molecule contain a ether group? COC(=O)[C@@H]1CCCC[C@H]1NC(=O)CCC(=O)c1ccc(F)cc1F ### Response: Yes
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? C[NH+](C)[C@@H]1CC[C@@H](NC(=O)c2ccc(SCc3cccnc3)cc2)C1 ### Response: 1
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [16*]c1cc(F)ccc1F Fragment 2: [16*]c1ccc(F)cc1 ### Response: C[C@@H]([NH2+]Cc1ccn(-c2ccc(F)cc2)n1)c1cc(F)ccc1F
functional_group
### Instruction: Does the molecule contain a phenol group? C[C@@H](Oc1cccc(Cl)c1)C(=O)Nc1cccc(S(=O)(=O)N(C)C)c1 ### Response: No
ring_counting
### Instruction: Count the six-membered rings in the following molecule. O=S1(=O)C[C@H]([C@@H](CCl)c2ccc(Cl)cc2)c2ccccc21 ### Response: 2
functional_group
### Instruction: Does the molecule contain a ketone group? Cc1nc2ccc(NC(=O)c3ccc4c(c3)C(=O)c3ccccc3-4)cc2o1 ### Response: Yes
functional_group
### Instruction: Does the molecule contain a aromatic_ring group? c1ccc(-c2cc(CSC[C@H]3CCCO3)on2)cc1 ### Response: Yes
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [14*]c1cccs1 Fragment 2: [13*][C@@H]1CCC[NH2+]1 ### Response: C[C@H](Cc1cccs1)[NH2+][C@H]1CCC[C@@H]1[C@@H]1CCC[NH2+]1
functional_group
### Instruction: Does the molecule contain a amide group? C[C@H]1CCN(C(=O)NCCC(=O)N2CCCCC2)[C@@H](C)C1 ### Response: Yes
functional_group
### Instruction: Does the molecule contain a phenol group? Cc1occc1C(=O)N/N=C/c1cc(Br)cc([N+](=O)[O-])c1[O-] ### Response: No
functional_group
### Instruction: Does the molecule contain a aromatic_ring group? COc1cc(OC)c(N[C@H](C)C(=O)c2c[nH]c3ccccc23)cc1F ### Response: Yes
chain_length
### Instruction: What is the length of the longest acyclic carbon chain in the molecule? CS(=O)(=O)NC[C@@H]1CCCCN1c1nc2ccccc2o1 ### Response: 1
functional_group
### Instruction: Does the molecule contain a ether group? Cc1ccc(NC(=O)C[C@H](c2cccc(F)c2)n2cccc2)cc1F ### Response: No
fragment_assembly
### Instruction: Assemble these two molecular fragments into a single molecule. Fragment 1: [16*]c1c(F)cccc1F Fragment 2: [1*]C(=O)C[4*] ### Response: C[C@@H](Cc1c(F)cccc1F)NC(=O)C[NH+]1CCc2sccc2C1
ring_counting
### Instruction: Count the six-membered rings in the following molecule. C[C@H]1CC[C@H](CO)C[NH+]1Cc1cc2c(cc1O)OCO2 ### Response: 2
ring_counting
### Instruction: Count the five-membered rings in the following molecule. CCN1C(=O)[C@@H](CC(=O)Nc2cccc(OC)c2)S/C1=N\S(=O)(=O)c1ccc(Cl)s1 ### Response: 2