id int64 1 14M | domain stringclasses 6
values | topic stringclasses 23
values | subtopic stringclasses 37
values | difficulty int64 1 8 | unit_type stringclasses 3
values | title stringlengths 14 86 | content stringlengths 203 553 | key_equations stringclasses 23
values | prerequisites stringclasses 29
values | learning_objective stringclasses 37
values |
|---|---|---|---|---|---|---|---|---|---|---|
1,101 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.643 mol, V=0.8945 L, T=421.2 K | For an ideal gas, P V = n R T. With n = 1.643 mol, V = 0.8945 L, T = 421.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 63.5 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,102 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.011 mol, V=15.54 L, T=425.5 K | For an ideal gas, P V = n R T. With n = 1.011 mol, V = 15.54 L, T = 425.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.272 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,103 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.117 mol, V=29.79 L, T=385.6 K | For an ideal gas, P V = n R T. With n = 3.117 mol, V = 29.79 L, T = 385.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.311 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,104 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.472 mol, V=10.17 L, T=509 K | For an ideal gas, P V = n R T. With n = 2.472 mol, V = 10.17 L, T = 509 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 10.15 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,105 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.503 mol, V=12.63 L, T=504.2 K | For an ideal gas, P V = n R T. With n = 4.503 mol, V = 12.63 L, T = 504.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 14.75 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,106 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.04183 mol, V=12.03 L, T=364 K | For an ideal gas, P V = n R T. With n = 0.04183 mol, V = 12.03 L, T = 364 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.1038 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,107 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.739 mol, V=43.92 L, T=535.8 K | For an ideal gas, P V = n R T. With n = 1.739 mol, V = 43.92 L, T = 535.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.741 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,108 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.755 mol, V=33.04 L, T=200.6 K | For an ideal gas, P V = n R T. With n = 4.755 mol, V = 33.04 L, T = 200.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.369 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,109 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.247 mol, V=5.645 L, T=490.9 K | For an ideal gas, P V = n R T. With n = 4.247 mol, V = 5.645 L, T = 490.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 30.3 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,110 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.654 mol, V=24.86 L, T=295.3 K | For an ideal gas, P V = n R T. With n = 2.654 mol, V = 24.86 L, T = 295.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.587 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,111 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.3089 mol, V=35.73 L, T=598.8 K | For an ideal gas, P V = n R T. With n = 0.3089 mol, V = 35.73 L, T = 598.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.4248 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,112 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.4742 mol, V=44.92 L, T=568.5 K | For an ideal gas, P V = n R T. With n = 0.4742 mol, V = 44.92 L, T = 568.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.4925 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,113 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.604 mol, V=18.94 L, T=480.3 K | For an ideal gas, P V = n R T. With n = 2.604 mol, V = 18.94 L, T = 480.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.419 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,114 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.873 mol, V=5.231 L, T=234 K | For an ideal gas, P V = n R T. With n = 4.873 mol, V = 5.231 L, T = 234 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 17.88 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,115 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.6762 mol, V=4.204 L, T=528 K | For an ideal gas, P V = n R T. With n = 0.6762 mol, V = 4.204 L, T = 528 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.969 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,116 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.843 mol, V=48.23 L, T=374 K | For an ideal gas, P V = n R T. With n = 2.843 mol, V = 48.23 L, T = 374 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.809 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,117 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.191 mol, V=16.09 L, T=304.4 K | For an ideal gas, P V = n R T. With n = 1.191 mol, V = 16.09 L, T = 304.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.849 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,118 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.006 mol, V=36.9 L, T=480.3 K | For an ideal gas, P V = n R T. With n = 4.006 mol, V = 36.9 L, T = 480.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.279 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,119 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.597 mol, V=4.197 L, T=308.8 K | For an ideal gas, P V = n R T. With n = 1.597 mol, V = 4.197 L, T = 308.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 9.642 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,120 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.022 mol, V=29.44 L, T=512 K | For an ideal gas, P V = n R T. With n = 1.022 mol, V = 29.44 L, T = 512 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.458 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,121 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.7855 mol, V=23.57 L, T=265.7 K | For an ideal gas, P V = n R T. With n = 0.7855 mol, V = 23.57 L, T = 265.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.7267 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,122 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.038 mol, V=48.25 L, T=414.4 K | For an ideal gas, P V = n R T. With n = 2.038 mol, V = 48.25 L, T = 414.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.437 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,123 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.046 mol, V=13.62 L, T=323.3 K | For an ideal gas, P V = n R T. With n = 1.046 mol, V = 13.62 L, T = 323.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.038 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,124 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.6084 mol, V=34.46 L, T=263 K | For an ideal gas, P V = n R T. With n = 0.6084 mol, V = 34.46 L, T = 263 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.3811 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,125 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.134 mol, V=2.496 L, T=478.8 K | For an ideal gas, P V = n R T. With n = 4.134 mol, V = 2.496 L, T = 478.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 65.05 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
1,126 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.03219 M | A strong monoprotic acid is fully dissociated. At concentration 0.03219 mol/L, [H⁺] = 0.03219 M and pH = −log₁₀[H⁺] = 1.492. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,127 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 9.6246e-04 M | A strong monoprotic acid is fully dissociated. At concentration 9.6246e-04 mol/L, [H⁺] = 9.6246e-04 M and pH = −log₁₀[H⁺] = 3.017. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,128 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.8778e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.8778e-04 mol/L, [H⁺] = 1.8778e-04 M and pH = −log₁₀[H⁺] = 3.726. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,129 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 5.5546e-04 M | A strong monoprotic acid is fully dissociated. At concentration 5.5546e-04 mol/L, [H⁺] = 5.5546e-04 M and pH = −log₁₀[H⁺] = 3.255. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,130 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001167 M | A strong monoprotic acid is fully dissociated. At concentration 0.001167 mol/L, [H⁺] = 0.001167 M and pH = −log₁₀[H⁺] = 2.933. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,131 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.00347 M | A strong monoprotic acid is fully dissociated. At concentration 0.00347 mol/L, [H⁺] = 0.00347 M and pH = −log₁₀[H⁺] = 2.46. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,132 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01075 M | A strong monoprotic acid is fully dissociated. At concentration 0.01075 mol/L, [H⁺] = 0.01075 M and pH = −log₁₀[H⁺] = 1.968. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,133 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 6.0325e-04 M | A strong monoprotic acid is fully dissociated. At concentration 6.0325e-04 mol/L, [H⁺] = 6.0325e-04 M and pH = −log₁₀[H⁺] = 3.219. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,134 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.09376 M | A strong monoprotic acid is fully dissociated. At concentration 0.09376 mol/L, [H⁺] = 0.09376 M and pH = −log₁₀[H⁺] = 1.028. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,135 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.2395e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.2395e-04 mol/L, [H⁺] = 1.2395e-04 M and pH = −log₁₀[H⁺] = 3.907. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,136 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001634 M | A strong monoprotic acid is fully dissociated. At concentration 0.001634 mol/L, [H⁺] = 0.001634 M and pH = −log₁₀[H⁺] = 2.787. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,137 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002273 M | A strong monoprotic acid is fully dissociated. At concentration 0.002273 mol/L, [H⁺] = 0.002273 M and pH = −log₁₀[H⁺] = 2.643. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,138 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01755 M | A strong monoprotic acid is fully dissociated. At concentration 0.01755 mol/L, [H⁺] = 0.01755 M and pH = −log₁₀[H⁺] = 1.756. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,139 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 5.6177e-04 M | A strong monoprotic acid is fully dissociated. At concentration 5.6177e-04 mol/L, [H⁺] = 5.6177e-04 M and pH = −log₁₀[H⁺] = 3.25. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,140 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002433 M | A strong monoprotic acid is fully dissociated. At concentration 0.002433 mol/L, [H⁺] = 0.002433 M and pH = −log₁₀[H⁺] = 2.614. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,141 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.0258 M | A strong monoprotic acid is fully dissociated. At concentration 0.0258 mol/L, [H⁺] = 0.0258 M and pH = −log₁₀[H⁺] = 1.588. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,142 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.6265e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.6265e-04 mol/L, [H⁺] = 2.6265e-04 M and pH = −log₁₀[H⁺] = 3.581. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,143 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.0861e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.0861e-04 mol/L, [H⁺] = 1.0861e-04 M and pH = −log₁₀[H⁺] = 3.964. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,144 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.03098 M | A strong monoprotic acid is fully dissociated. At concentration 0.03098 mol/L, [H⁺] = 0.03098 M and pH = −log₁₀[H⁺] = 1.509. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,145 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.08865 M | A strong monoprotic acid is fully dissociated. At concentration 0.08865 mol/L, [H⁺] = 0.08865 M and pH = −log₁₀[H⁺] = 1.052. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,146 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.4669e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.4669e-04 mol/L, [H⁺] = 2.4669e-04 M and pH = −log₁₀[H⁺] = 3.608. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,147 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02958 M | A strong monoprotic acid is fully dissociated. At concentration 0.02958 mol/L, [H⁺] = 0.02958 M and pH = −log₁₀[H⁺] = 1.529. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,148 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001308 M | A strong monoprotic acid is fully dissociated. At concentration 0.001308 mol/L, [H⁺] = 0.001308 M and pH = −log₁₀[H⁺] = 2.883. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,149 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.007778 M | A strong monoprotic acid is fully dissociated. At concentration 0.007778 mol/L, [H⁺] = 0.007778 M and pH = −log₁₀[H⁺] = 2.109. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,150 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.008591 M | A strong monoprotic acid is fully dissociated. At concentration 0.008591 mol/L, [H⁺] = 0.008591 M and pH = −log₁₀[H⁺] = 2.066. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,151 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.005584 M | A strong monoprotic acid is fully dissociated. At concentration 0.005584 mol/L, [H⁺] = 0.005584 M and pH = −log₁₀[H⁺] = 2.253. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,152 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 5.9767e-04 M | A strong monoprotic acid is fully dissociated. At concentration 5.9767e-04 mol/L, [H⁺] = 5.9767e-04 M and pH = −log₁₀[H⁺] = 3.224. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,153 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02743 M | A strong monoprotic acid is fully dissociated. At concentration 0.02743 mol/L, [H⁺] = 0.02743 M and pH = −log₁₀[H⁺] = 1.562. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,154 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.1625e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.1625e-04 mol/L, [H⁺] = 1.1625e-04 M and pH = −log₁₀[H⁺] = 3.935. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,155 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.5610e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.5610e-04 mol/L, [H⁺] = 1.5610e-04 M and pH = −log₁₀[H⁺] = 3.807. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,156 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.05099 M | A strong monoprotic acid is fully dissociated. At concentration 0.05099 mol/L, [H⁺] = 0.05099 M and pH = −log₁₀[H⁺] = 1.293. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,157 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002139 M | A strong monoprotic acid is fully dissociated. At concentration 0.002139 mol/L, [H⁺] = 0.002139 M and pH = −log₁₀[H⁺] = 2.67. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,158 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.4343e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.4343e-04 mol/L, [H⁺] = 2.4343e-04 M and pH = −log₁₀[H⁺] = 3.614. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,159 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.05191 M | A strong monoprotic acid is fully dissociated. At concentration 0.05191 mol/L, [H⁺] = 0.05191 M and pH = −log₁₀[H⁺] = 1.285. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,160 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.03077 M | A strong monoprotic acid is fully dissociated. At concentration 0.03077 mol/L, [H⁺] = 0.03077 M and pH = −log₁₀[H⁺] = 1.512. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,161 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 9.8776e-04 M | A strong monoprotic acid is fully dissociated. At concentration 9.8776e-04 mol/L, [H⁺] = 9.8776e-04 M and pH = −log₁₀[H⁺] = 3.005. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,162 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.3430e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.3430e-04 mol/L, [H⁺] = 1.3430e-04 M and pH = −log₁₀[H⁺] = 3.872. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,163 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002415 M | A strong monoprotic acid is fully dissociated. At concentration 0.002415 mol/L, [H⁺] = 0.002415 M and pH = −log₁₀[H⁺] = 2.617. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,164 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.1913e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.1913e-04 mol/L, [H⁺] = 3.1913e-04 M and pH = −log₁₀[H⁺] = 3.496. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,165 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.005268 M | A strong monoprotic acid is fully dissociated. At concentration 0.005268 mol/L, [H⁺] = 0.005268 M and pH = −log₁₀[H⁺] = 2.278. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,166 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02918 M | A strong monoprotic acid is fully dissociated. At concentration 0.02918 mol/L, [H⁺] = 0.02918 M and pH = −log₁₀[H⁺] = 1.535. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,167 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001531 M | A strong monoprotic acid is fully dissociated. At concentration 0.001531 mol/L, [H⁺] = 0.001531 M and pH = −log₁₀[H⁺] = 2.815. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,168 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.2259e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.2259e-04 mol/L, [H⁺] = 1.2259e-04 M and pH = −log₁₀[H⁺] = 3.912. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,169 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01121 M | A strong monoprotic acid is fully dissociated. At concentration 0.01121 mol/L, [H⁺] = 0.01121 M and pH = −log₁₀[H⁺] = 1.95. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,170 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.2993e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.2993e-04 mol/L, [H⁺] = 3.2993e-04 M and pH = −log₁₀[H⁺] = 3.482. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,171 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 4.4071e-04 M | A strong monoprotic acid is fully dissociated. At concentration 4.4071e-04 mol/L, [H⁺] = 4.4071e-04 M and pH = −log₁₀[H⁺] = 3.356. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,172 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.6430e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.6430e-04 mol/L, [H⁺] = 3.6430e-04 M and pH = −log₁₀[H⁺] = 3.439. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,173 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 6.9114e-04 M | A strong monoprotic acid is fully dissociated. At concentration 6.9114e-04 mol/L, [H⁺] = 6.9114e-04 M and pH = −log₁₀[H⁺] = 3.16. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,174 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.0447 M | A strong monoprotic acid is fully dissociated. At concentration 0.0447 mol/L, [H⁺] = 0.0447 M and pH = −log₁₀[H⁺] = 1.35. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,175 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.2704e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.2704e-04 mol/L, [H⁺] = 1.2704e-04 M and pH = −log₁₀[H⁺] = 3.896. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,176 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.007203 M | A strong monoprotic acid is fully dissociated. At concentration 0.007203 mol/L, [H⁺] = 0.007203 M and pH = −log₁₀[H⁺] = 2.142. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,177 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 5.4620e-04 M | A strong monoprotic acid is fully dissociated. At concentration 5.4620e-04 mol/L, [H⁺] = 5.4620e-04 M and pH = −log₁₀[H⁺] = 3.263. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,178 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 7.6792e-04 M | A strong monoprotic acid is fully dissociated. At concentration 7.6792e-04 mol/L, [H⁺] = 7.6792e-04 M and pH = −log₁₀[H⁺] = 3.115. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,179 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001722 M | A strong monoprotic acid is fully dissociated. At concentration 0.001722 mol/L, [H⁺] = 0.001722 M and pH = −log₁₀[H⁺] = 2.764. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,180 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.004488 M | A strong monoprotic acid is fully dissociated. At concentration 0.004488 mol/L, [H⁺] = 0.004488 M and pH = −log₁₀[H⁺] = 2.348. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,181 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.5238e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.5238e-04 mol/L, [H⁺] = 1.5238e-04 M and pH = −log₁₀[H⁺] = 3.817. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,182 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 6.9076e-04 M | A strong monoprotic acid is fully dissociated. At concentration 6.9076e-04 mol/L, [H⁺] = 6.9076e-04 M and pH = −log₁₀[H⁺] = 3.161. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,183 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.5805e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.5805e-04 mol/L, [H⁺] = 2.5805e-04 M and pH = −log₁₀[H⁺] = 3.588. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,184 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.9662e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.9662e-04 mol/L, [H⁺] = 3.9662e-04 M and pH = −log₁₀[H⁺] = 3.402. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,185 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.04508 M | A strong monoprotic acid is fully dissociated. At concentration 0.04508 mol/L, [H⁺] = 0.04508 M and pH = −log₁₀[H⁺] = 1.346. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,186 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.00378 M | A strong monoprotic acid is fully dissociated. At concentration 0.00378 mol/L, [H⁺] = 0.00378 M and pH = −log₁₀[H⁺] = 2.423. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,187 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.007803 M | A strong monoprotic acid is fully dissociated. At concentration 0.007803 mol/L, [H⁺] = 0.007803 M and pH = −log₁₀[H⁺] = 2.108. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,188 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.0255 M | A strong monoprotic acid is fully dissociated. At concentration 0.0255 mol/L, [H⁺] = 0.0255 M and pH = −log₁₀[H⁺] = 1.593. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,189 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02424 M | A strong monoprotic acid is fully dissociated. At concentration 0.02424 mol/L, [H⁺] = 0.02424 M and pH = −log₁₀[H⁺] = 1.615. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,190 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.09294 M | A strong monoprotic acid is fully dissociated. At concentration 0.09294 mol/L, [H⁺] = 0.09294 M and pH = −log₁₀[H⁺] = 1.032. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,191 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02217 M | A strong monoprotic acid is fully dissociated. At concentration 0.02217 mol/L, [H⁺] = 0.02217 M and pH = −log₁₀[H⁺] = 1.654. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,192 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001195 M | A strong monoprotic acid is fully dissociated. At concentration 0.001195 mol/L, [H⁺] = 0.001195 M and pH = −log₁₀[H⁺] = 2.923. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,193 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.004301 M | A strong monoprotic acid is fully dissociated. At concentration 0.004301 mol/L, [H⁺] = 0.004301 M and pH = −log₁₀[H⁺] = 2.366. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,194 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002845 M | A strong monoprotic acid is fully dissociated. At concentration 0.002845 mol/L, [H⁺] = 0.002845 M and pH = −log₁₀[H⁺] = 2.546. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,195 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.05471 M | A strong monoprotic acid is fully dissociated. At concentration 0.05471 mol/L, [H⁺] = 0.05471 M and pH = −log₁₀[H⁺] = 1.262. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,196 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.003215 M | A strong monoprotic acid is fully dissociated. At concentration 0.003215 mol/L, [H⁺] = 0.003215 M and pH = −log₁₀[H⁺] = 2.493. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,197 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001463 M | A strong monoprotic acid is fully dissociated. At concentration 0.001463 mol/L, [H⁺] = 0.001463 M and pH = −log₁₀[H⁺] = 2.835. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,198 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.4630e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.4630e-04 mol/L, [H⁺] = 3.4630e-04 M and pH = −log₁₀[H⁺] = 3.461. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,199 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 9.0497e-04 M | A strong monoprotic acid is fully dissociated. At concentration 9.0497e-04 mol/L, [H⁺] = 9.0497e-04 M and pH = −log₁₀[H⁺] = 3.043. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
1,200 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 4.5400e-04 M | A strong monoprotic acid is fully dissociated. At concentration 4.5400e-04 mol/L, [H⁺] = 4.5400e-04 M and pH = −log₁₀[H⁺] = 3.343. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.