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20,132,901 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.68 mol, V=2.318 L, T=515.1 K | For an ideal gas, P V = n R T. With n = 3.68 mol, V = 2.318 L, T = 515.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 67.1 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,902 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.691 mol, V=30.99 L, T=386.2 K | For an ideal gas, P V = n R T. With n = 1.691 mol, V = 30.99 L, T = 386.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.73 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,903 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.817 mol, V=26.12 L, T=503.6 K | For an ideal gas, P V = n R T. With n = 3.817 mol, V = 26.12 L, T = 503.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.037 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,904 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.994 mol, V=46.15 L, T=281 K | For an ideal gas, P V = n R T. With n = 2.994 mol, V = 46.15 L, T = 281 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.496 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,905 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.4707 mol, V=18.7 L, T=420.9 K | For an ideal gas, P V = n R T. With n = 0.4707 mol, V = 18.7 L, T = 420.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.8692 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,906 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.241 mol, V=27.59 L, T=319.6 K | For an ideal gas, P V = n R T. With n = 1.241 mol, V = 27.59 L, T = 319.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.18 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,907 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.968 mol, V=41.64 L, T=555 K | For an ideal gas, P V = n R T. With n = 1.968 mol, V = 41.64 L, T = 555 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.152 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,908 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.481 mol, V=4.529 L, T=405.2 K | For an ideal gas, P V = n R T. With n = 1.481 mol, V = 4.529 L, T = 405.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 10.87 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,909 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.119 mol, V=24.7 L, T=534.1 K | For an ideal gas, P V = n R T. With n = 2.119 mol, V = 24.7 L, T = 534.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.76 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,910 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.956 mol, V=41.48 L, T=225.6 K | For an ideal gas, P V = n R T. With n = 0.956 mol, V = 41.48 L, T = 225.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.4268 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,911 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.782 mol, V=31.15 L, T=458.8 K | For an ideal gas, P V = n R T. With n = 1.782 mol, V = 31.15 L, T = 458.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.154 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,912 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.5989 mol, V=13.2 L, T=553.8 K | For an ideal gas, P V = n R T. With n = 0.5989 mol, V = 13.2 L, T = 553.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.061 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,913 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.386 mol, V=10.09 L, T=431.2 K | For an ideal gas, P V = n R T. With n = 1.386 mol, V = 10.09 L, T = 431.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.858 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,914 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.725 mol, V=1.694 L, T=318.3 K | For an ideal gas, P V = n R T. With n = 4.725 mol, V = 1.694 L, T = 318.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 72.87 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,915 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.848 mol, V=47.4 L, T=475.2 K | For an ideal gas, P V = n R T. With n = 3.848 mol, V = 47.4 L, T = 475.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.166 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,916 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.4 mol, V=2.448 L, T=469 K | For an ideal gas, P V = n R T. With n = 1.4 mol, V = 2.448 L, T = 469 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 22.02 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,917 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.705 mol, V=39.84 L, T=441.6 K | For an ideal gas, P V = n R T. With n = 4.705 mol, V = 39.84 L, T = 441.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.28 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,918 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.885 mol, V=32.97 L, T=209.2 K | For an ideal gas, P V = n R T. With n = 4.885 mol, V = 32.97 L, T = 209.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.543 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,919 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.922 mol, V=24.89 L, T=338.7 K | For an ideal gas, P V = n R T. With n = 2.922 mol, V = 24.89 L, T = 338.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.262 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,920 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.844 mol, V=7.407 L, T=355.4 K | For an ideal gas, P V = n R T. With n = 4.844 mol, V = 7.407 L, T = 355.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 19.08 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,921 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.413 mol, V=9.124 L, T=471.4 K | For an ideal gas, P V = n R T. With n = 1.413 mol, V = 9.124 L, T = 471.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.991 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,922 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.656 mol, V=12.09 L, T=232.6 K | For an ideal gas, P V = n R T. With n = 1.656 mol, V = 12.09 L, T = 232.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.614 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,923 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.04755 mol, V=6.335 L, T=377.9 K | For an ideal gas, P V = n R T. With n = 0.04755 mol, V = 6.335 L, T = 377.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.2327 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,924 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.025 mol, V=7.987 L, T=304.2 K | For an ideal gas, P V = n R T. With n = 2.025 mol, V = 7.987 L, T = 304.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.329 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,925 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.746 mol, V=21.66 L, T=328.4 K | For an ideal gas, P V = n R T. With n = 4.746 mol, V = 21.66 L, T = 328.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.907 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,926 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.545 mol, V=20.68 L, T=471 K | For an ideal gas, P V = n R T. With n = 3.545 mol, V = 20.68 L, T = 471 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.625 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,927 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.385 mol, V=14.71 L, T=468 K | For an ideal gas, P V = n R T. With n = 2.385 mol, V = 14.71 L, T = 468 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.225 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,928 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.677 mol, V=47.7 L, T=572.7 K | For an ideal gas, P V = n R T. With n = 4.677 mol, V = 47.7 L, T = 572.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.607 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,929 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.721 mol, V=9.955 L, T=317.3 K | For an ideal gas, P V = n R T. With n = 3.721 mol, V = 9.955 L, T = 317.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 9.732 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,930 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.974 mol, V=41.4 L, T=274.3 K | For an ideal gas, P V = n R T. With n = 2.974 mol, V = 41.4 L, T = 274.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.617 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,931 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.7093 mol, V=23 L, T=413 K | For an ideal gas, P V = n R T. With n = 0.7093 mol, V = 23 L, T = 413 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.045 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,932 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.8208 mol, V=39.09 L, T=410.3 K | For an ideal gas, P V = n R T. With n = 0.8208 mol, V = 39.09 L, T = 410.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.7069 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,933 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.026 mol, V=17.77 L, T=254.1 K | For an ideal gas, P V = n R T. With n = 1.026 mol, V = 17.77 L, T = 254.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.204 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,934 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.486 mol, V=28.57 L, T=569.5 K | For an ideal gas, P V = n R T. With n = 1.486 mol, V = 28.57 L, T = 569.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.431 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,935 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.325 mol, V=3.085 L, T=405.8 K | For an ideal gas, P V = n R T. With n = 2.325 mol, V = 3.085 L, T = 405.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 25.1 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,936 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.7964 mol, V=11.07 L, T=291.6 K | For an ideal gas, P V = n R T. With n = 0.7964 mol, V = 11.07 L, T = 291.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.721 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,937 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.122 mol, V=24.13 L, T=258.7 K | For an ideal gas, P V = n R T. With n = 2.122 mol, V = 24.13 L, T = 258.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.866 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,938 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.463 mol, V=43.08 L, T=241.2 K | For an ideal gas, P V = n R T. With n = 1.463 mol, V = 43.08 L, T = 241.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.6719 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,939 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.696 mol, V=26.85 L, T=307.3 K | For an ideal gas, P V = n R T. With n = 1.696 mol, V = 26.85 L, T = 307.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.593 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,940 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.017 mol, V=10.94 L, T=405.3 K | For an ideal gas, P V = n R T. With n = 3.017 mol, V = 10.94 L, T = 405.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 9.17 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,941 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.407 mol, V=48.76 L, T=526.7 K | For an ideal gas, P V = n R T. With n = 1.407 mol, V = 48.76 L, T = 526.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.248 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,942 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.298 mol, V=32.47 L, T=533.8 K | For an ideal gas, P V = n R T. With n = 2.298 mol, V = 32.47 L, T = 533.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.1 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,943 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.338 mol, V=18.34 L, T=449.2 K | For an ideal gas, P V = n R T. With n = 3.338 mol, V = 18.34 L, T = 449.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.709 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,944 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.419 mol, V=4.635 L, T=469.5 K | For an ideal gas, P V = n R T. With n = 3.419 mol, V = 4.635 L, T = 469.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 28.42 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,945 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.566 mol, V=20.74 L, T=373.8 K | For an ideal gas, P V = n R T. With n = 3.566 mol, V = 20.74 L, T = 373.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.272 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,946 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.39 mol, V=39.9 L, T=232 K | For an ideal gas, P V = n R T. With n = 4.39 mol, V = 39.9 L, T = 232 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.095 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,947 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.775 mol, V=16.25 L, T=546.8 K | For an ideal gas, P V = n R T. With n = 1.775 mol, V = 16.25 L, T = 546.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.902 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,948 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.698 mol, V=5.282 L, T=272.4 K | For an ideal gas, P V = n R T. With n = 3.698 mol, V = 5.282 L, T = 272.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 15.65 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,949 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.365 mol, V=1.029 L, T=515.3 K | For an ideal gas, P V = n R T. With n = 3.365 mol, V = 1.029 L, T = 515.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 138.3 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,950 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.425 mol, V=30.48 L, T=357.4 K | For an ideal gas, P V = n R T. With n = 4.425 mol, V = 30.48 L, T = 357.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.257 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,951 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.277 mol, V=45.78 L, T=510.6 K | For an ideal gas, P V = n R T. With n = 4.277 mol, V = 45.78 L, T = 510.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.915 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,952 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.578 mol, V=37.88 L, T=479.9 K | For an ideal gas, P V = n R T. With n = 1.578 mol, V = 37.88 L, T = 479.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.64 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,953 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.25 mol, V=42.49 L, T=523.9 K | For an ideal gas, P V = n R T. With n = 4.25 mol, V = 42.49 L, T = 523.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.3 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,954 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.224 mol, V=26.71 L, T=306.1 K | For an ideal gas, P V = n R T. With n = 4.224 mol, V = 26.71 L, T = 306.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.973 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,955 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.579 mol, V=47.29 L, T=221.7 K | For an ideal gas, P V = n R T. With n = 1.579 mol, V = 47.29 L, T = 221.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.6075 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
20,132,956 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.1758e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.1758e-04 mol/L, [H⁺] = 3.1758e-04 M and pH = −log₁₀[H⁺] = 3.498. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,957 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.06046 M | A strong monoprotic acid is fully dissociated. At concentration 0.06046 mol/L, [H⁺] = 0.06046 M and pH = −log₁₀[H⁺] = 1.219. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,958 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.00138 M | A strong monoprotic acid is fully dissociated. At concentration 0.00138 mol/L, [H⁺] = 0.00138 M and pH = −log₁₀[H⁺] = 2.86. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,959 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001227 M | A strong monoprotic acid is fully dissociated. At concentration 0.001227 mol/L, [H⁺] = 0.001227 M and pH = −log₁₀[H⁺] = 2.911. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,960 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.04738 M | A strong monoprotic acid is fully dissociated. At concentration 0.04738 mol/L, [H⁺] = 0.04738 M and pH = −log₁₀[H⁺] = 1.324. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,961 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.1373e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.1373e-04 mol/L, [H⁺] = 1.1373e-04 M and pH = −log₁₀[H⁺] = 3.944. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,962 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02185 M | A strong monoprotic acid is fully dissociated. At concentration 0.02185 mol/L, [H⁺] = 0.02185 M and pH = −log₁₀[H⁺] = 1.661. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,963 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 6.4788e-04 M | A strong monoprotic acid is fully dissociated. At concentration 6.4788e-04 mol/L, [H⁺] = 6.4788e-04 M and pH = −log₁₀[H⁺] = 3.189. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,964 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.6813e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.6813e-04 mol/L, [H⁺] = 3.6813e-04 M and pH = −log₁₀[H⁺] = 3.434. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,965 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.0283 M | A strong monoprotic acid is fully dissociated. At concentration 0.0283 mol/L, [H⁺] = 0.0283 M and pH = −log₁₀[H⁺] = 1.548. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,966 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 6.2541e-04 M | A strong monoprotic acid is fully dissociated. At concentration 6.2541e-04 mol/L, [H⁺] = 6.2541e-04 M and pH = −log₁₀[H⁺] = 3.204. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,967 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.9649e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.9649e-04 mol/L, [H⁺] = 3.9649e-04 M and pH = −log₁₀[H⁺] = 3.402. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,968 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 7.4748e-04 M | A strong monoprotic acid is fully dissociated. At concentration 7.4748e-04 mol/L, [H⁺] = 7.4748e-04 M and pH = −log₁₀[H⁺] = 3.126. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,969 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.3504e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.3504e-04 mol/L, [H⁺] = 1.3504e-04 M and pH = −log₁₀[H⁺] = 3.87. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,970 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.07489 M | A strong monoprotic acid is fully dissociated. At concentration 0.07489 mol/L, [H⁺] = 0.07489 M and pH = −log₁₀[H⁺] = 1.126. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,971 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01258 M | A strong monoprotic acid is fully dissociated. At concentration 0.01258 mol/L, [H⁺] = 0.01258 M and pH = −log₁₀[H⁺] = 1.9. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,972 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 6.3247e-04 M | A strong monoprotic acid is fully dissociated. At concentration 6.3247e-04 mol/L, [H⁺] = 6.3247e-04 M and pH = −log₁₀[H⁺] = 3.199. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,973 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 7.4066e-04 M | A strong monoprotic acid is fully dissociated. At concentration 7.4066e-04 mol/L, [H⁺] = 7.4066e-04 M and pH = −log₁₀[H⁺] = 3.13. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,974 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.0653 M | A strong monoprotic acid is fully dissociated. At concentration 0.0653 mol/L, [H⁺] = 0.0653 M and pH = −log₁₀[H⁺] = 1.185. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,975 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.004298 M | A strong monoprotic acid is fully dissociated. At concentration 0.004298 mol/L, [H⁺] = 0.004298 M and pH = −log₁₀[H⁺] = 2.367. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,976 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02927 M | A strong monoprotic acid is fully dissociated. At concentration 0.02927 mol/L, [H⁺] = 0.02927 M and pH = −log₁₀[H⁺] = 1.534. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,977 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01404 M | A strong monoprotic acid is fully dissociated. At concentration 0.01404 mol/L, [H⁺] = 0.01404 M and pH = −log₁₀[H⁺] = 1.852. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,978 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.08295 M | A strong monoprotic acid is fully dissociated. At concentration 0.08295 mol/L, [H⁺] = 0.08295 M and pH = −log₁₀[H⁺] = 1.081. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,979 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.0445 M | A strong monoprotic acid is fully dissociated. At concentration 0.0445 mol/L, [H⁺] = 0.0445 M and pH = −log₁₀[H⁺] = 1.352. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,980 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.3143e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.3143e-04 mol/L, [H⁺] = 1.3143e-04 M and pH = −log₁₀[H⁺] = 3.881. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,981 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.08663 M | A strong monoprotic acid is fully dissociated. At concentration 0.08663 mol/L, [H⁺] = 0.08663 M and pH = −log₁₀[H⁺] = 1.062. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,982 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002012 M | A strong monoprotic acid is fully dissociated. At concentration 0.002012 mol/L, [H⁺] = 0.002012 M and pH = −log₁₀[H⁺] = 2.696. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,983 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.0122e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.0122e-04 mol/L, [H⁺] = 2.0122e-04 M and pH = −log₁₀[H⁺] = 3.696. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,984 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.003412 M | A strong monoprotic acid is fully dissociated. At concentration 0.003412 mol/L, [H⁺] = 0.003412 M and pH = −log₁₀[H⁺] = 2.467. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,985 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.008338 M | A strong monoprotic acid is fully dissociated. At concentration 0.008338 mol/L, [H⁺] = 0.008338 M and pH = −log₁₀[H⁺] = 2.079. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,986 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.6266e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.6266e-04 mol/L, [H⁺] = 3.6266e-04 M and pH = −log₁₀[H⁺] = 3.44. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,987 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01312 M | A strong monoprotic acid is fully dissociated. At concentration 0.01312 mol/L, [H⁺] = 0.01312 M and pH = −log₁₀[H⁺] = 1.882. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,988 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.3721e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.3721e-04 mol/L, [H⁺] = 3.3721e-04 M and pH = −log₁₀[H⁺] = 3.472. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,989 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01039 M | A strong monoprotic acid is fully dissociated. At concentration 0.01039 mol/L, [H⁺] = 0.01039 M and pH = −log₁₀[H⁺] = 1.983. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,990 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.00609 M | A strong monoprotic acid is fully dissociated. At concentration 0.00609 mol/L, [H⁺] = 0.00609 M and pH = −log₁₀[H⁺] = 2.215. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,991 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.2500e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.2500e-04 mol/L, [H⁺] = 1.2500e-04 M and pH = −log₁₀[H⁺] = 3.903. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,992 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02117 M | A strong monoprotic acid is fully dissociated. At concentration 0.02117 mol/L, [H⁺] = 0.02117 M and pH = −log₁₀[H⁺] = 1.674. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,993 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.006166 M | A strong monoprotic acid is fully dissociated. At concentration 0.006166 mol/L, [H⁺] = 0.006166 M and pH = −log₁₀[H⁺] = 2.21. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,994 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.0483 M | A strong monoprotic acid is fully dissociated. At concentration 0.0483 mol/L, [H⁺] = 0.0483 M and pH = −log₁₀[H⁺] = 1.316. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,995 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001828 M | A strong monoprotic acid is fully dissociated. At concentration 0.001828 mol/L, [H⁺] = 0.001828 M and pH = −log₁₀[H⁺] = 2.738. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,996 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02887 M | A strong monoprotic acid is fully dissociated. At concentration 0.02887 mol/L, [H⁺] = 0.02887 M and pH = −log₁₀[H⁺] = 1.54. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,997 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.09096 M | A strong monoprotic acid is fully dissociated. At concentration 0.09096 mol/L, [H⁺] = 0.09096 M and pH = −log₁₀[H⁺] = 1.041. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,998 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01004 M | A strong monoprotic acid is fully dissociated. At concentration 0.01004 mol/L, [H⁺] = 0.01004 M and pH = −log₁₀[H⁺] = 1.998. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,132,999 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.007327 M | A strong monoprotic acid is fully dissociated. At concentration 0.007327 mol/L, [H⁺] = 0.007327 M and pH = −log₁₀[H⁺] = 2.135. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
20,133,000 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002019 M | A strong monoprotic acid is fully dissociated. At concentration 0.002019 mol/L, [H⁺] = 0.002019 M and pH = −log₁₀[H⁺] = 2.695. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
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