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6,201 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 78.03 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 78.03 g therefore contains n = m / M = 78.03 / 18.02 = 4.331 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,202 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 86.3 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 86.3 g therefore contains n = m / M = 86.3 / 18.02 = 4.791 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,203 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 8.455 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 8.455 g therefore contains n = m / M = 8.455 / 18.02 = 0.4693 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,204 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 75.78 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 75.78 g therefore contains n = m / M = 75.78 / 58.44 = 1.297 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,205 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 8.198 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 8.198 g therefore contains n = m / M = 8.198 / 159.6 = 0.05137 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,206 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 48.13 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 48.13 g therefore contains n = m / M = 48.13 / 180.2 = 0.2672 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,207 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 43.95 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 43.95 g therefore contains n = m / M = 43.95 / 44.01 = 0.9988 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,208 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 64.79 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 64.79 g therefore contains n = m / M = 64.79 / 159.7 = 0.4057 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,209 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 78.77 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 78.77 g therefore contains n = m / M = 78.77 / 18.02 = 4.372 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,210 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 2.682 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 2.682 g therefore contains n = m / M = 2.682 / 159.6 = 0.0168 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,211 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 98.84 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 98.84 g therefore contains n = m / M = 98.84 / 58.44 = 1.691 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,212 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 37.97 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 37.97 g therefore contains n = m / M = 37.97 / 17.03 = 2.229 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,213 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 79.49 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 79.49 g therefore contains n = m / M = 79.49 / 44.01 = 1.806 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,214 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 64.6 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 64.6 g therefore contains n = m / M = 64.6 / 159.7 = 0.4045 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,215 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 26.15 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 26.15 g therefore contains n = m / M = 26.15 / 98.07 = 0.2667 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,216 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 54.62 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 54.62 g therefore contains n = m / M = 54.62 / 44.01 = 1.241 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,217 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 60.07 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 60.07 g therefore contains n = m / M = 60.07 / 58.44 = 1.028 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,218 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 54.05 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 54.05 g therefore contains n = m / M = 54.05 / 159.6 = 0.3386 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,219 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 49.16 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 49.16 g therefore contains n = m / M = 49.16 / 98.07 = 0.5013 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,220 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CO2 from mass 15.14 g | The molar mass of CO2 is 44.01 g/mol. A sample of mass 15.14 g therefore contains n = m / M = 15.14 / 44.01 = 0.3441 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,221 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 50.19 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 50.19 g therefore contains n = m / M = 50.19 / 98.07 = 0.5118 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,222 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 31.48 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 31.48 g therefore contains n = m / M = 31.48 / 18.02 = 1.747 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,223 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CaCO3 from mass 4.134 g | The molar mass of CaCO3 is 100.1 g/mol. A sample of mass 4.134 g therefore contains n = m / M = 4.134 / 100.1 = 0.04131 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,224 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 46.78 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 46.78 g therefore contains n = m / M = 46.78 / 16.04 = 2.916 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,225 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 59.96 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 59.96 g therefore contains n = m / M = 59.96 / 18.02 = 3.328 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,226 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 66.24 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 66.24 g therefore contains n = m / M = 66.24 / 18.02 = 3.677 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,227 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of C6H12O6 from mass 37.85 g | The molar mass of C6H12O6 is 180.2 g/mol. A sample of mass 37.85 g therefore contains n = m / M = 37.85 / 180.2 = 0.2101 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,228 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 8.96 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 8.96 g therefore contains n = m / M = 8.96 / 17.03 = 0.5261 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,229 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of Fe2O3 from mass 27.58 g | The molar mass of Fe2O3 is 159.7 g/mol. A sample of mass 27.58 g therefore contains n = m / M = 27.58 / 159.7 = 0.1727 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,230 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 40.58 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 40.58 g therefore contains n = m / M = 40.58 / 58.44 = 0.6944 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,231 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CuSO4 from mass 12.38 g | The molar mass of CuSO4 is 159.6 g/mol. A sample of mass 12.38 g therefore contains n = m / M = 12.38 / 159.6 = 0.07758 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,232 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of CH4 from mass 15.01 g | The molar mass of CH4 is 16.04 g/mol. A sample of mass 15.01 g therefore contains n = m / M = 15.01 / 16.04 = 0.9358 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,233 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2SO4 from mass 51.22 g | The molar mass of H2SO4 is 98.07 g/mol. A sample of mass 51.22 g therefore contains n = m / M = 51.22 / 98.07 = 0.5222 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,234 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NH3 from mass 37.02 g | The molar mass of NH3 is 17.03 g/mol. A sample of mass 37.02 g therefore contains n = m / M = 37.02 / 17.03 = 2.174 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,235 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of H2O from mass 36.68 g | The molar mass of H2O is 18.02 g/mol. A sample of mass 36.68 g therefore contains n = m / M = 36.68 / 18.02 = 2.036 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,236 | chemistry | stoichiometry | mole_concept | 3 | worked_example | Moles of NaCl from mass 78.54 g | The molar mass of NaCl is 58.44 g/mol. A sample of mass 78.54 g therefore contains n = m / M = 78.54 / 58.44 = 1.344 mol. The mole is the SI unit for amount of substance and links macroscopic mass to number of entities via Avogadro's constant. | n = m / M | atomic masses; chemical formulas | Convert between mass and moles for a pure compound. |
6,237 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.883 mol, V=35.86 L, T=216.7 K | For an ideal gas, P V = n R T. With n = 1.883 mol, V = 35.86 L, T = 216.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.9339 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,238 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.129 mol, V=10.79 L, T=221.2 K | For an ideal gas, P V = n R T. With n = 3.129 mol, V = 10.79 L, T = 221.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.263 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,239 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.057 mol, V=28.13 L, T=542.4 K | For an ideal gas, P V = n R T. With n = 2.057 mol, V = 28.13 L, T = 542.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.254 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,240 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.094 mol, V=1.341 L, T=514.6 K | For an ideal gas, P V = n R T. With n = 3.094 mol, V = 1.341 L, T = 514.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 97.42 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,241 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.126 mol, V=46.96 L, T=454.5 K | For an ideal gas, P V = n R T. With n = 3.126 mol, V = 46.96 L, T = 454.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.482 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,242 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.624 mol, V=3.693 L, T=273.9 K | For an ideal gas, P V = n R T. With n = 4.624 mol, V = 3.693 L, T = 273.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 28.14 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,243 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.346 mol, V=6.559 L, T=218.8 K | For an ideal gas, P V = n R T. With n = 1.346 mol, V = 6.559 L, T = 218.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.685 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,244 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.964 mol, V=6.651 L, T=534 K | For an ideal gas, P V = n R T. With n = 1.964 mol, V = 6.651 L, T = 534 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 12.94 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,245 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.783 mol, V=0.7461 L, T=411.7 K | For an ideal gas, P V = n R T. With n = 2.783 mol, V = 0.7461 L, T = 411.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 126 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,246 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.132 mol, V=42.92 L, T=303.5 K | For an ideal gas, P V = n R T. With n = 3.132 mol, V = 42.92 L, T = 303.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.817 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,247 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.8955 mol, V=25.17 L, T=579.4 K | For an ideal gas, P V = n R T. With n = 0.8955 mol, V = 25.17 L, T = 579.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.691 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,248 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.655 mol, V=19.22 L, T=406.3 K | For an ideal gas, P V = n R T. With n = 4.655 mol, V = 19.22 L, T = 406.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 8.076 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,249 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.822 mol, V=3.676 L, T=411.3 K | For an ideal gas, P V = n R T. With n = 3.822 mol, V = 3.676 L, T = 411.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 35.09 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,250 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.346 mol, V=3.744 L, T=261.9 K | For an ideal gas, P V = n R T. With n = 1.346 mol, V = 3.744 L, T = 261.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 7.73 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,251 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.486 mol, V=15.11 L, T=447.6 K | For an ideal gas, P V = n R T. With n = 3.486 mol, V = 15.11 L, T = 447.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 8.475 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,252 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.8626 mol, V=33.64 L, T=428.6 K | For an ideal gas, P V = n R T. With n = 0.8626 mol, V = 33.64 L, T = 428.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.9018 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,253 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.655 mol, V=8.35 L, T=363.1 K | For an ideal gas, P V = n R T. With n = 3.655 mol, V = 8.35 L, T = 363.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 13.04 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,254 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.221 mol, V=35.99 L, T=367.9 K | For an ideal gas, P V = n R T. With n = 1.221 mol, V = 35.99 L, T = 367.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.024 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,255 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.848 mol, V=26.65 L, T=490.1 K | For an ideal gas, P V = n R T. With n = 1.848 mol, V = 26.65 L, T = 490.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.788 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,256 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.077 mol, V=39.03 L, T=323.8 K | For an ideal gas, P V = n R T. With n = 1.077 mol, V = 39.03 L, T = 323.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.7335 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,257 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.42 mol, V=41.19 L, T=549.4 K | For an ideal gas, P V = n R T. With n = 0.42 mol, V = 41.19 L, T = 549.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.4597 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,258 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.465 mol, V=19.8 L, T=592.9 K | For an ideal gas, P V = n R T. With n = 1.465 mol, V = 19.8 L, T = 592.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.6 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,259 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.78 mol, V=38 L, T=500.1 K | For an ideal gas, P V = n R T. With n = 1.78 mol, V = 38 L, T = 500.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.922 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,260 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.333 mol, V=20.46 L, T=216.9 K | For an ideal gas, P V = n R T. With n = 4.333 mol, V = 20.46 L, T = 216.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.769 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,261 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.153 mol, V=17.33 L, T=470.3 K | For an ideal gas, P V = n R T. With n = 1.153 mol, V = 17.33 L, T = 470.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.568 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,262 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.419 mol, V=47.98 L, T=317.5 K | For an ideal gas, P V = n R T. With n = 3.419 mol, V = 47.98 L, T = 317.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.857 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,263 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.558 mol, V=4.688 L, T=209.3 K | For an ideal gas, P V = n R T. With n = 4.558 mol, V = 4.688 L, T = 209.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 16.7 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,264 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.893 mol, V=14.35 L, T=364.5 K | For an ideal gas, P V = n R T. With n = 1.893 mol, V = 14.35 L, T = 364.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.945 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,265 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.46 mol, V=40.83 L, T=430.3 K | For an ideal gas, P V = n R T. With n = 1.46 mol, V = 40.83 L, T = 430.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.263 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,266 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.531 mol, V=38.72 L, T=567.2 K | For an ideal gas, P V = n R T. With n = 2.531 mol, V = 38.72 L, T = 567.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.043 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,267 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.657 mol, V=28.03 L, T=347.3 K | For an ideal gas, P V = n R T. With n = 3.657 mol, V = 28.03 L, T = 347.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.719 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,268 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.51 mol, V=49.12 L, T=271.4 K | For an ideal gas, P V = n R T. With n = 2.51 mol, V = 49.12 L, T = 271.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.138 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,269 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.664 mol, V=23.55 L, T=589 K | For an ideal gas, P V = n R T. With n = 1.664 mol, V = 23.55 L, T = 589 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.416 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,270 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.16 mol, V=34.57 L, T=224.6 K | For an ideal gas, P V = n R T. With n = 4.16 mol, V = 34.57 L, T = 224.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.218 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,271 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.1973 mol, V=3.347 L, T=474.7 K | For an ideal gas, P V = n R T. With n = 0.1973 mol, V = 3.347 L, T = 474.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.296 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,272 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.266 mol, V=45.87 L, T=295.5 K | For an ideal gas, P V = n R T. With n = 4.266 mol, V = 45.87 L, T = 295.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.256 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,273 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.053 mol, V=18.08 L, T=506 K | For an ideal gas, P V = n R T. With n = 1.053 mol, V = 18.08 L, T = 506 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.418 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,274 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.144 mol, V=16.1 L, T=303.1 K | For an ideal gas, P V = n R T. With n = 4.144 mol, V = 16.1 L, T = 303.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.404 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,275 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.547 mol, V=11.48 L, T=357.9 K | For an ideal gas, P V = n R T. With n = 3.547 mol, V = 11.48 L, T = 357.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 9.072 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,276 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.7157 mol, V=5.181 L, T=240.9 K | For an ideal gas, P V = n R T. With n = 0.7157 mol, V = 5.181 L, T = 240.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.73 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,277 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.003 mol, V=36.2 L, T=410.5 K | For an ideal gas, P V = n R T. With n = 3.003 mol, V = 36.2 L, T = 410.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.794 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,278 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.939 mol, V=30.52 L, T=417.8 K | For an ideal gas, P V = n R T. With n = 3.939 mol, V = 30.52 L, T = 417.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.424 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,279 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.001 mol, V=31.73 L, T=437.3 K | For an ideal gas, P V = n R T. With n = 1.001 mol, V = 31.73 L, T = 437.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.132 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,280 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.998 mol, V=20.55 L, T=286.7 K | For an ideal gas, P V = n R T. With n = 0.998 mol, V = 20.55 L, T = 286.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.143 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,281 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.622 mol, V=44.18 L, T=290.3 K | For an ideal gas, P V = n R T. With n = 1.622 mol, V = 44.18 L, T = 290.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.8745 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,282 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.276 mol, V=47.83 L, T=489.3 K | For an ideal gas, P V = n R T. With n = 4.276 mol, V = 47.83 L, T = 489.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.589 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,283 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.591 mol, V=25.49 L, T=444.8 K | For an ideal gas, P V = n R T. With n = 4.591 mol, V = 25.49 L, T = 444.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.573 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,284 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.794 mol, V=19.77 L, T=331 K | For an ideal gas, P V = n R T. With n = 3.794 mol, V = 19.77 L, T = 331 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.212 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,285 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.314 mol, V=20.66 L, T=400.3 K | For an ideal gas, P V = n R T. With n = 2.314 mol, V = 20.66 L, T = 400.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.679 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,286 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.767 mol, V=44.65 L, T=545.6 K | For an ideal gas, P V = n R T. With n = 2.767 mol, V = 44.65 L, T = 545.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.775 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,287 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.06325 mol, V=41.11 L, T=273.9 K | For an ideal gas, P V = n R T. With n = 0.06325 mol, V = 41.11 L, T = 273.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.03459 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,288 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.986 mol, V=5.784 L, T=211.8 K | For an ideal gas, P V = n R T. With n = 4.986 mol, V = 5.784 L, T = 211.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 14.98 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,289 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.895 mol, V=6.831 L, T=244.8 K | For an ideal gas, P V = n R T. With n = 3.895 mol, V = 6.831 L, T = 244.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 11.45 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,290 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.99 mol, V=12.6 L, T=569.7 K | For an ideal gas, P V = n R T. With n = 2.99 mol, V = 12.6 L, T = 569.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 11.1 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,291 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.893 mol, V=35.29 L, T=388.9 K | For an ideal gas, P V = n R T. With n = 1.893 mol, V = 35.29 L, T = 388.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.712 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,292 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.327 mol, V=48.96 L, T=313.5 K | For an ideal gas, P V = n R T. With n = 1.327 mol, V = 48.96 L, T = 313.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.697 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,293 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.6073 mol, V=21.07 L, T=489.9 K | For an ideal gas, P V = n R T. With n = 0.6073 mol, V = 21.07 L, T = 489.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.159 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,294 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.02534 mol, V=11.08 L, T=448.4 K | For an ideal gas, P V = n R T. With n = 0.02534 mol, V = 11.08 L, T = 448.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.08417 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,295 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.846 mol, V=7.129 L, T=516.8 K | For an ideal gas, P V = n R T. With n = 1.846 mol, V = 7.129 L, T = 516.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 10.98 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,296 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.2991 mol, V=4.01 L, T=324.5 K | For an ideal gas, P V = n R T. With n = 0.2991 mol, V = 4.01 L, T = 324.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.986 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,297 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.6246 mol, V=38.71 L, T=410.4 K | For an ideal gas, P V = n R T. With n = 0.6246 mol, V = 38.71 L, T = 410.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.5434 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,298 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.441 mol, V=11.68 L, T=415.7 K | For an ideal gas, P V = n R T. With n = 1.441 mol, V = 11.68 L, T = 415.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.21 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,299 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.991 mol, V=41.98 L, T=390.9 K | For an ideal gas, P V = n R T. With n = 1.991 mol, V = 41.98 L, T = 390.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.521 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
6,300 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.937 mol, V=20.66 L, T=502.6 K | For an ideal gas, P V = n R T. With n = 2.937 mol, V = 20.66 L, T = 502.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.863 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
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