id int64 1 14M | domain stringclasses 6
values | topic stringclasses 23
values | subtopic stringclasses 37
values | difficulty int64 1 8 | unit_type stringclasses 3
values | title stringlengths 14 86 | content stringlengths 203 553 | key_equations stringclasses 23
values | prerequisites stringclasses 29
values | learning_objective stringclasses 37
values |
|---|---|---|---|---|---|---|---|---|---|---|
8,001 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.4472 mol, V=37.24 L, T=391.7 K | For an ideal gas, P V = n R T. With n = 0.4472 mol, V = 37.24 L, T = 391.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.3859 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,002 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.668 mol, V=20.18 L, T=437 K | For an ideal gas, P V = n R T. With n = 4.668 mol, V = 20.18 L, T = 437 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 8.297 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,003 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.661 mol, V=11.61 L, T=594.8 K | For an ideal gas, P V = n R T. With n = 4.661 mol, V = 11.61 L, T = 594.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 19.59 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,004 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.07 mol, V=30.43 L, T=254.6 K | For an ideal gas, P V = n R T. With n = 4.07 mol, V = 30.43 L, T = 254.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.795 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,005 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.292 mol, V=39.8 L, T=350.4 K | For an ideal gas, P V = n R T. With n = 1.292 mol, V = 39.8 L, T = 350.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.9337 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,006 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.317 mol, V=3.107 L, T=562.4 K | For an ideal gas, P V = n R T. With n = 1.317 mol, V = 3.107 L, T = 562.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 19.57 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,007 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.942 mol, V=1.935 L, T=434.3 K | For an ideal gas, P V = n R T. With n = 2.942 mol, V = 1.935 L, T = 434.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 54.18 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,008 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.1943 mol, V=29.98 L, T=219.3 K | For an ideal gas, P V = n R T. With n = 0.1943 mol, V = 29.98 L, T = 219.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.1166 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,009 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.708 mol, V=1.34 L, T=291.2 K | For an ideal gas, P V = n R T. With n = 1.708 mol, V = 1.34 L, T = 291.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 30.46 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,010 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.531 mol, V=34.35 L, T=533.1 K | For an ideal gas, P V = n R T. With n = 4.531 mol, V = 34.35 L, T = 533.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.77 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,011 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.708 mol, V=4.707 L, T=238.1 K | For an ideal gas, P V = n R T. With n = 1.708 mol, V = 4.707 L, T = 238.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 7.091 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,012 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.976 mol, V=14.88 L, T=465.4 K | For an ideal gas, P V = n R T. With n = 2.976 mol, V = 14.88 L, T = 465.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 7.639 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,013 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.445 mol, V=19.8 L, T=460.2 K | For an ideal gas, P V = n R T. With n = 1.445 mol, V = 19.8 L, T = 460.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.755 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,014 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.683 mol, V=26.08 L, T=405.8 K | For an ideal gas, P V = n R T. With n = 3.683 mol, V = 26.08 L, T = 405.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.704 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,015 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.1 mol, V=42.05 L, T=575.7 K | For an ideal gas, P V = n R T. With n = 3.1 mol, V = 42.05 L, T = 575.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.483 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,016 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.079 mol, V=18.85 L, T=383.1 K | For an ideal gas, P V = n R T. With n = 3.079 mol, V = 18.85 L, T = 383.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.136 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,017 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.8618 mol, V=18.86 L, T=564.3 K | For an ideal gas, P V = n R T. With n = 0.8618 mol, V = 18.86 L, T = 564.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.116 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,018 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.878 mol, V=31.94 L, T=396.1 K | For an ideal gas, P V = n R T. With n = 3.878 mol, V = 31.94 L, T = 396.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.947 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,019 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.859 mol, V=6.758 L, T=501.7 K | For an ideal gas, P V = n R T. With n = 2.859 mol, V = 6.758 L, T = 501.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 17.42 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,020 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.596 mol, V=29.82 L, T=244.5 K | For an ideal gas, P V = n R T. With n = 2.596 mol, V = 29.82 L, T = 244.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.747 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,021 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.904 mol, V=37.39 L, T=228.6 K | For an ideal gas, P V = n R T. With n = 0.904 mol, V = 37.39 L, T = 228.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.4535 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,022 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.319 mol, V=33.19 L, T=415.5 K | For an ideal gas, P V = n R T. With n = 2.319 mol, V = 33.19 L, T = 415.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.383 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,023 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.316 mol, V=4.162 L, T=452.5 K | For an ideal gas, P V = n R T. With n = 3.316 mol, V = 4.162 L, T = 452.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 29.58 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,024 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.6969 mol, V=9.783 L, T=411.5 K | For an ideal gas, P V = n R T. With n = 0.6969 mol, V = 9.783 L, T = 411.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.406 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,025 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.046 mol, V=44.99 L, T=544 K | For an ideal gas, P V = n R T. With n = 3.046 mol, V = 44.99 L, T = 544 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.022 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,026 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.316 mol, V=37.66 L, T=570.5 K | For an ideal gas, P V = n R T. With n = 2.316 mol, V = 37.66 L, T = 570.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.879 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,027 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.65 mol, V=13.5 L, T=566.4 K | For an ideal gas, P V = n R T. With n = 2.65 mol, V = 13.5 L, T = 566.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 9.122 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,028 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.65 mol, V=13.66 L, T=239.6 K | For an ideal gas, P V = n R T. With n = 1.65 mol, V = 13.66 L, T = 239.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.375 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,029 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.631 mol, V=38.15 L, T=370.2 K | For an ideal gas, P V = n R T. With n = 4.631 mol, V = 38.15 L, T = 370.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.687 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,030 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.8078 mol, V=49.11 L, T=598 K | For an ideal gas, P V = n R T. With n = 0.8078 mol, V = 49.11 L, T = 598 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.8071 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,031 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.533 mol, V=11.27 L, T=272.9 K | For an ideal gas, P V = n R T. With n = 0.533 mol, V = 11.27 L, T = 272.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.059 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,032 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.1581 mol, V=17.42 L, T=411.3 K | For an ideal gas, P V = n R T. With n = 0.1581 mol, V = 17.42 L, T = 411.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.3064 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,033 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.178 mol, V=38.88 L, T=414.6 K | For an ideal gas, P V = n R T. With n = 2.178 mol, V = 38.88 L, T = 414.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.905 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,034 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.895 mol, V=49.3 L, T=443.9 K | For an ideal gas, P V = n R T. With n = 2.895 mol, V = 49.3 L, T = 443.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.139 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,035 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.173 mol, V=47.29 L, T=231.9 K | For an ideal gas, P V = n R T. With n = 4.173 mol, V = 47.29 L, T = 231.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.679 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,036 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.689 mol, V=41.14 L, T=204.5 K | For an ideal gas, P V = n R T. With n = 1.689 mol, V = 41.14 L, T = 204.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.6892 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,037 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.692 mol, V=45.89 L, T=446.9 K | For an ideal gas, P V = n R T. With n = 3.692 mol, V = 45.89 L, T = 446.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.95 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,038 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.831 mol, V=31.7 L, T=488.1 K | For an ideal gas, P V = n R T. With n = 4.831 mol, V = 31.7 L, T = 488.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.103 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,039 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.843 mol, V=23.67 L, T=242.1 K | For an ideal gas, P V = n R T. With n = 0.843 mol, V = 23.67 L, T = 242.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.7077 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,040 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.2445 mol, V=28.23 L, T=326.2 K | For an ideal gas, P V = n R T. With n = 0.2445 mol, V = 28.23 L, T = 326.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.2318 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,041 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.132 mol, V=10.78 L, T=369.2 K | For an ideal gas, P V = n R T. With n = 2.132 mol, V = 10.78 L, T = 369.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.99 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,042 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.117 mol, V=31.59 L, T=349.5 K | For an ideal gas, P V = n R T. With n = 4.117 mol, V = 31.59 L, T = 349.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.738 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,043 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.288 mol, V=27.15 L, T=497.8 K | For an ideal gas, P V = n R T. With n = 3.288 mol, V = 27.15 L, T = 497.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.947 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,044 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.1131 mol, V=48.08 L, T=488.8 K | For an ideal gas, P V = n R T. With n = 0.1131 mol, V = 48.08 L, T = 488.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.09437 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,045 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.06932 mol, V=16.26 L, T=534.5 K | For an ideal gas, P V = n R T. With n = 0.06932 mol, V = 16.26 L, T = 534.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.187 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,046 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.6414 mol, V=37.43 L, T=357.8 K | For an ideal gas, P V = n R T. With n = 0.6414 mol, V = 37.43 L, T = 357.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.5031 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,047 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.6165 mol, V=39.47 L, T=430.3 K | For an ideal gas, P V = n R T. With n = 0.6165 mol, V = 39.47 L, T = 430.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.5515 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,048 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.4083 mol, V=42.95 L, T=299.4 K | For an ideal gas, P V = n R T. With n = 0.4083 mol, V = 42.95 L, T = 299.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.2336 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,049 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.637 mol, V=23.98 L, T=429.4 K | For an ideal gas, P V = n R T. With n = 0.637 mol, V = 23.98 L, T = 429.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.936 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,050 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.6807 mol, V=17.8 L, T=546.5 K | For an ideal gas, P V = n R T. With n = 0.6807 mol, V = 17.8 L, T = 546.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.714 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,051 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.224 mol, V=28.91 L, T=370.6 K | For an ideal gas, P V = n R T. With n = 1.224 mol, V = 28.91 L, T = 370.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.288 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,052 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.454 mol, V=26.98 L, T=331.2 K | For an ideal gas, P V = n R T. With n = 3.454 mol, V = 26.98 L, T = 331.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.479 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,053 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.5143 mol, V=6.589 L, T=400.9 K | For an ideal gas, P V = n R T. With n = 0.5143 mol, V = 6.589 L, T = 400.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.568 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,054 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.424 mol, V=7.214 L, T=224.4 K | For an ideal gas, P V = n R T. With n = 1.424 mol, V = 7.214 L, T = 224.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.635 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,055 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.069 mol, V=20.32 L, T=384.4 K | For an ideal gas, P V = n R T. With n = 1.069 mol, V = 20.32 L, T = 384.4 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.659 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,056 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.53 mol, V=39.86 L, T=573.1 K | For an ideal gas, P V = n R T. With n = 4.53 mol, V = 39.86 L, T = 573.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.345 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,057 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.659 mol, V=38 L, T=282.3 K | For an ideal gas, P V = n R T. With n = 2.659 mol, V = 38 L, T = 282.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.621 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,058 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.7079 mol, V=11.24 L, T=375.9 K | For an ideal gas, P V = n R T. With n = 0.7079 mol, V = 11.24 L, T = 375.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.942 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,059 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.75 mol, V=20.35 L, T=488.2 K | For an ideal gas, P V = n R T. With n = 1.75 mol, V = 20.35 L, T = 488.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.446 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,060 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.234 mol, V=40.02 L, T=341.3 K | For an ideal gas, P V = n R T. With n = 1.234 mol, V = 40.02 L, T = 341.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.8636 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,061 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.3112 mol, V=17.03 L, T=202.8 K | For an ideal gas, P V = n R T. With n = 0.3112 mol, V = 17.03 L, T = 202.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.3042 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,062 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.616 mol, V=37.69 L, T=549.5 K | For an ideal gas, P V = n R T. With n = 1.616 mol, V = 37.69 L, T = 549.5 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.933 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,063 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=4.855 mol, V=31.83 L, T=236.1 K | For an ideal gas, P V = n R T. With n = 4.855 mol, V = 31.83 L, T = 236.1 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.956 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,064 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.467 mol, V=4.754 L, T=466.3 K | For an ideal gas, P V = n R T. With n = 1.467 mol, V = 4.754 L, T = 466.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 11.8 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,065 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.678 mol, V=19.09 L, T=354.3 K | For an ideal gas, P V = n R T. With n = 1.678 mol, V = 19.09 L, T = 354.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 2.556 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,066 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.928 mol, V=18.17 L, T=427.2 K | For an ideal gas, P V = n R T. With n = 2.928 mol, V = 18.17 L, T = 427.2 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.648 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,067 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.951 mol, V=19.3 L, T=246.3 K | For an ideal gas, P V = n R T. With n = 3.951 mol, V = 19.3 L, T = 246.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 4.137 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,068 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.238 mol, V=30.87 L, T=582.6 K | For an ideal gas, P V = n R T. With n = 1.238 mol, V = 30.87 L, T = 582.6 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 1.918 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,069 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.304 mol, V=45.6 L, T=535.3 K | For an ideal gas, P V = n R T. With n = 3.304 mol, V = 45.6 L, T = 535.3 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 3.183 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,070 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=2.363 mol, V=1.895 L, T=272.7 K | For an ideal gas, P V = n R T. With n = 2.363 mol, V = 1.895 L, T = 272.7 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 27.91 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,071 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=0.8005 mol, V=49.84 L, T=437.8 K | For an ideal gas, P V = n R T. With n = 0.8005 mol, V = 49.84 L, T = 437.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 0.577 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,072 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=3.254 mol, V=17.48 L, T=363.9 K | For an ideal gas, P V = n R T. With n = 3.254 mol, V = 17.48 L, T = 363.9 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 5.559 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,073 | chemistry | gases | ideal_gas_law | 4 | worked_example | Ideal-gas pressure for n=1.254 mol, V=4.569 L, T=270.8 K | For an ideal gas, P V = n R T. With n = 1.254 mol, V = 4.569 L, T = 270.8 K and R = 0.082057 L·atm·mol⁻¹·K⁻¹, the pressure is P = n R T / V = 6.101 atm. Real gases approach ideal behavior at low pressure and high temperature relative to their critical points. | P V = n R T | mole_concept | Apply the ideal-gas law to compute pressure, volume, or temperature. |
8,074 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02641 M | A strong monoprotic acid is fully dissociated. At concentration 0.02641 mol/L, [H⁺] = 0.02641 M and pH = −log₁₀[H⁺] = 1.578. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,075 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 5.8786e-04 M | A strong monoprotic acid is fully dissociated. At concentration 5.8786e-04 mol/L, [H⁺] = 5.8786e-04 M and pH = −log₁₀[H⁺] = 3.231. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,076 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.02825 M | A strong monoprotic acid is fully dissociated. At concentration 0.02825 mol/L, [H⁺] = 0.02825 M and pH = −log₁₀[H⁺] = 1.549. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,077 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01119 M | A strong monoprotic acid is fully dissociated. At concentration 0.01119 mol/L, [H⁺] = 0.01119 M and pH = −log₁₀[H⁺] = 1.951. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,078 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.6968e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.6968e-04 mol/L, [H⁺] = 1.6968e-04 M and pH = −log₁₀[H⁺] = 3.77. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,079 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.04785 M | A strong monoprotic acid is fully dissociated. At concentration 0.04785 mol/L, [H⁺] = 0.04785 M and pH = −log₁₀[H⁺] = 1.32. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,080 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.007419 M | A strong monoprotic acid is fully dissociated. At concentration 0.007419 mol/L, [H⁺] = 0.007419 M and pH = −log₁₀[H⁺] = 2.13. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,081 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.01229 M | A strong monoprotic acid is fully dissociated. At concentration 0.01229 mol/L, [H⁺] = 0.01229 M and pH = −log₁₀[H⁺] = 1.91. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,082 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.07528 M | A strong monoprotic acid is fully dissociated. At concentration 0.07528 mol/L, [H⁺] = 0.07528 M and pH = −log₁₀[H⁺] = 1.123. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,083 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 9.3323e-04 M | A strong monoprotic acid is fully dissociated. At concentration 9.3323e-04 mol/L, [H⁺] = 9.3323e-04 M and pH = −log₁₀[H⁺] = 3.03. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,084 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.04731 M | A strong monoprotic acid is fully dissociated. At concentration 0.04731 mol/L, [H⁺] = 0.04731 M and pH = −log₁₀[H⁺] = 1.325. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,085 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.00101 M | A strong monoprotic acid is fully dissociated. At concentration 0.00101 mol/L, [H⁺] = 0.00101 M and pH = −log₁₀[H⁺] = 2.996. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,086 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.04136 M | A strong monoprotic acid is fully dissociated. At concentration 0.04136 mol/L, [H⁺] = 0.04136 M and pH = −log₁₀[H⁺] = 1.383. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,087 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.008025 M | A strong monoprotic acid is fully dissociated. At concentration 0.008025 mol/L, [H⁺] = 0.008025 M and pH = −log₁₀[H⁺] = 2.096. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,088 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 7.9221e-04 M | A strong monoprotic acid is fully dissociated. At concentration 7.9221e-04 mol/L, [H⁺] = 7.9221e-04 M and pH = −log₁₀[H⁺] = 3.101. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,089 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.03053 M | A strong monoprotic acid is fully dissociated. At concentration 0.03053 mol/L, [H⁺] = 0.03053 M and pH = −log₁₀[H⁺] = 1.515. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,090 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.3445e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.3445e-04 mol/L, [H⁺] = 1.3445e-04 M and pH = −log₁₀[H⁺] = 3.871. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,091 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.001318 M | A strong monoprotic acid is fully dissociated. At concentration 0.001318 mol/L, [H⁺] = 0.001318 M and pH = −log₁₀[H⁺] = 2.88. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,092 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 2.3622e-04 M | A strong monoprotic acid is fully dissociated. At concentration 2.3622e-04 mol/L, [H⁺] = 2.3622e-04 M and pH = −log₁₀[H⁺] = 3.627. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,093 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 3.6875e-04 M | A strong monoprotic acid is fully dissociated. At concentration 3.6875e-04 mol/L, [H⁺] = 3.6875e-04 M and pH = −log₁₀[H⁺] = 3.433. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,094 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.004793 M | A strong monoprotic acid is fully dissociated. At concentration 0.004793 mol/L, [H⁺] = 0.004793 M and pH = −log₁₀[H⁺] = 2.319. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,095 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 1.0085e-04 M | A strong monoprotic acid is fully dissociated. At concentration 1.0085e-04 mol/L, [H⁺] = 1.0085e-04 M and pH = −log₁₀[H⁺] = 3.996. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,096 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.00296 M | A strong monoprotic acid is fully dissociated. At concentration 0.00296 mol/L, [H⁺] = 0.00296 M and pH = −log₁₀[H⁺] = 2.529. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,097 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 4.3851e-04 M | A strong monoprotic acid is fully dissociated. At concentration 4.3851e-04 mol/L, [H⁺] = 4.3851e-04 M and pH = −log₁₀[H⁺] = 3.358. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,098 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 6.1969e-04 M | A strong monoprotic acid is fully dissociated. At concentration 6.1969e-04 mol/L, [H⁺] = 6.1969e-04 M and pH = −log₁₀[H⁺] = 3.208. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,099 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 0.002883 M | A strong monoprotic acid is fully dissociated. At concentration 0.002883 mol/L, [H⁺] = 0.002883 M and pH = −log₁₀[H⁺] = 2.54. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
8,100 | chemistry | acids_bases | strong_acid_ph | 4 | worked_example | pH of strong acid at concentration 4.2227e-04 M | A strong monoprotic acid is fully dissociated. At concentration 4.2227e-04 mol/L, [H⁺] = 4.2227e-04 M and pH = −log₁₀[H⁺] = 3.374. This relation follows directly from the definition of pH and the complete dissociation assumption. | pH = -log10 [H+] | mole_concept; logarithmic functions | Calculate the pH of a strong monoprotic acid solution. |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.