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[
{
"content": "How to solve 10415 Eb Alto Saxophone Player?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 10415 Eb Alto Saxophone Player?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 10415 Eb Alto Saxophone Player in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 10415 Eb Alto Saxophone Player.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c'... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 10415 Eb Alto Saxophone Player.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 10415 Eb Alto Saxophone Player with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap =... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 10415 Eb Alto Saxophone Player.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 10415 Eb Alto Saxophone Player, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMa... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10415 Eb Alto Saxophone Player」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, 1, 1... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10415 Eb Alto Saxophone Player」的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, 1, ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「10415 Eb Alto Saxophone Player」？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「10415 Eb Alto Saxophone Player」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「10415 Eb Alto Saxophone Player」的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, 1... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「10415 Eb Alto Saxophone Player」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「10415 Eb Alto Saxophone Player」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「10415 Eb Alto Saxophone Player」的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10415 Eb Alto Saxophone Player 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, 1, 1,... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10415 Eb Alto Saxophone Player 的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, 1, 1... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 10415 Eb Alto Saxophone Player？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, 1... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 10415 Eb Alto Saxophone Player 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 10415 Eb Alto Saxophone Player 的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, 1... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 10415 Eb Alto Saxophone Player 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 10415 Eb Alto Saxophone Player 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {0, 0, 1, ... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 10415 Eb Alto Saxophone Player 的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <map>\n#include <vector>\nusing namespace std;\n\nint main() {\n // Initialize finger mappings for each note\n map<char, vector<int>> fingerMap = {\n {'c', {... | 10415 Eb Alto Saxophone Player | The problem involves simulating finger movements on a saxophone while playing different musical notes. Each note requires specific fingers to press buttons, and we need to count how many times each finger presses a button when transitioning between notes. A finger press is counted when a finger is needed for the curren... | The input starts with an integer t (1 ≤ t ≤ 1000) representing the number of test cases. Each test case consists of a string of musical notes (using characters c,d,e,f,g,a,b,C,D,E,F,G,A,B). Each string can have up to 200 notes. | For each test case, output 10 space-separated integers representing the number of button presses for fingers 1 through 10. | 3
cdefgab
BAGFEDC
CbCaDCDcCbCCbCbabcCCbCbabaee | 0 1 1 1 0 0 1 1 1 1
1 1 1 1 0 0 1 1 1 0
1 8 10 2 0 0 2 2 1 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"10420 List of Conquests\"?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"10420 List of Conquests\"?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"10420 List of Conquests\" in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"10420 List of Conquests\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n-... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"10420 List of Conquests\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n whi... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"10420 List of Conquests\" with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s)... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"10420 List of Conquests\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n whi... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"10420 List of Conquests\", generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin,... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 10420 List of Conquests?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 10420 List of Conquests?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--)... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 10420 List of Conquests in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 10420 List of Conquests.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 10420 List of Conquests.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 10420 List of Conquests with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 10420 List of Conquests.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 10420 List of Conquests, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10420 List of Conquests」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n getlin... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10420 List of Conquests」的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n getli... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「10420 List of Conquests」？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ge... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「10420 List of Conquests」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「10420 List of Conquests」的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n get... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「10420 List of Conquests」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「10420 List of Conquests」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ge... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「10420 List of Conquests」的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10420 List of Conquests 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n getline... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10420 List of Conquests 的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n getlin... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 10420 List of Conquests？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n get... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 10420 List of Conquests 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 10420 List of Conquests 的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n get... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 10420 List of Conquests 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 10420 List of Conquests 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ge... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 10420 List of Conquests 的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <sstream>\n#include <map>\nusing namespace std;\n \nint main() {\n int n;\n cin >> n;\n map <string, int> mp;\n string s;\n getline(cin, s);\n while (n--) {\n ... | 10420 List of Conquests | In Act I, Leporello is telling Donna Elvira about his master's long list of conquests:
"This is the list of the beauties my master has loved, a list I've made out myself: take a look, read it with me. In Italy six hundred and forty, in Germany two hundred and thirty-one, a hundred in France, ninety-one in Turkey; but ... | The input consists of at most 2000 lines. The first line contains a number n, indicating that there will be n more lines. Each following line, with at most 75 characters, contains a country (the first word) and the name of a woman (the rest of the words in the line) Giovanni loved. You may assume that the name of all c... | The output consists of lines in alphabetical order. Each line starts with the name of a country, followed by the total number of women Giovanni loved in that country, separated by a space. | 3
Spain Donna Elvira
England Jane Doe
Spain Donna Anna | England 1
Spain 2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"10642 Can You Solve It?\"?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \":... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"10642 Can You Solve It?\"?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" <<... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"10642 Can You Solve It?\" in C++?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"10642 Can You Solve It?\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << C... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"10642 Can You Solve It?\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"10642 Can You Solve It?\" with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout <... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"10642 Can You Solve It?\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"10642 Can You Solve It?\", generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cou... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 10642 Can You Solve It??",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 10642 Can You Solve It??",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Cas... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 10642 Can You Solve It? in C++?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 10642 Can You Solve It?.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 10642 Can You Solve It?.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" <<... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 10642 Can You Solve It? with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 10642 Can You Solve It?.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" <<... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 10642 Can You Solve It?, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout <<... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10642 Can You Solve It?」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10642 Can You Solve It?」的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「10642 Can You Solve It?」？ ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「10642 Can You Solve It?」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \"... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「10642 Can You Solve It?」的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「10642 Can You Solve It?」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \"... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「10642 Can You Solve It?」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「10642 Can You Solve It?」的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10642 Can You Solve It? 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10642 Can You Solve It? 的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 10642 Can You Solve It?？ ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 10642 Can You Solve It? 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \"... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 10642 Can You Solve It? 的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 10642 Can You Solve It? 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \"... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 10642 Can You Solve It? 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << \": \";\n... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 10642 Can You Solve It? 的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T;\n long long x, y, n, step1, step2;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cout << \"Case \" << Case << ... | 10642 Can You Solve It? | First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle,
total_number_of_step(s) needed=number_of i... | The first line in the input is the number of test cases n (0<n≤500) to handle. Following there are n lines each containing four integers (0≤each_integer≤100000) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in ... | For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle. | 3
0 0 0 1
0 0 1 0
0 0 0 2 | Case 1: 1
Case 2: 2
Case 3: 3 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"10783 Odd Sum\"?",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a += 1;\n ... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"10783 Odd Sum\"?",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a += ... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"10783 Odd Sum\" in C++?",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a += 1... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"10783 Odd Sum\".",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a += 1;... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"10783 Odd Sum\".",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"10783 Odd Sum\" with explanations.",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n ... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"10783 Odd Sum\".",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"10783 Odd Sum\", generate it for me.",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 10783 Odd Sum?",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a += 1;\n }\n ... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 10783 Odd Sum?",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a += 1;\n... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 10783 Odd Sum in C++?",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a += 1;\n ... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 10783 Odd Sum.",
"role": "user"
},
{
"content": "#include<iostream>\nusing namespace std;\n \nint main(){\n int T;\n cin >> T;\n for (int i = 1; i <= T; i++) {\n int a, b;\n cin >> a >> b;\n if (a % 2 == 0) {\n a += 1;\n ... | 10783 Odd Sum | Given a range [a, b], you are to find the summation of all the odd integers in this range. For example, the summation of all the odd integers in the range [3, 9] is 3 + 5 + 7 + 9 = 24. | There can be at multiple test cases. The first line of input gives you the number of test cases, T (1 ≤ T ≤ 100). Then T test cases follow. Each test case consists of 2 integers a and b (0 ≤ a ≤ b ≤ 100) in two separate lines. | For each test case you are to print one line of output – the serial number of the test case followed by the summation of the odd integers in the range [a, b]. | 2
1
5
3
5 | Case 1: 9
Case 2: 8 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
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