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[
{
"content": "11321 Sort! Sort!! And Sort!!! 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n if ((x % M) != (y % M)){\n return (x % M) < (y % M);\n } else {\n if ((x % 2) * (y % 2)){... | 11321 Sort! Sort!! And Sort!!! | Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the... | The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two ... | For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also. | 15 3
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0 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "11321 Sort! Sort!! And Sort!!! 的解答是什麼?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n if ((x % M) != (y % M)){\n return (x % M) < (y % M);\n } else {\n if ((x % 2) * (y % 2))... | 11321 Sort! Sort!! And Sort!!! | Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the... | The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two ... | For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also. | 15 3
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0 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 11321 Sort! Sort!! And Sort!!!? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n if ((x % M) != (y % M)){\n return (x % M) < (y % M);\n } else {\n if ((x % 2) * (y % ... | 11321 Sort! Sort!! And Sort!!! | Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the... | The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two ... | For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also. | 15 3
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0 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 11321 Sort! Sort!! And Sort!!! 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n if ((x % M) != (y % M)){\n return (x % M) < (y % M);\n } else {\n if ((x % 2) * (... | 11321 Sort! Sort!! And Sort!!! | Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the... | The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two ... | For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also. | 15 3
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0 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 11321 Sort! Sort!! And Sort!!! 的解法嗎? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n if ((x % M) != (y % M)){\n return (x % M) < (y % M);\n } else {\n if ((x % 2) * (y % ... | 11321 Sort! Sort!! And Sort!!! | Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the... | The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two ... | For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also. | 15 3
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0 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 11321 Sort! Sort!! And Sort!!! 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n if ((x % M) != (y % M)){\n return (x % M) < (y % M);\n } else {\n if ((x % 2) * (... | 11321 Sort! Sort!! And Sort!!! | Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the... | The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two ... | For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also. | 15 3
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0 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 11321 Sort! Sort!! And Sort!!! 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n if ((x % M) != (y % M)){\n return (x % M) < (y % M);\n } else {\n if ((x % 2) * (y %... | 11321 Sort! Sort!! And Sort!!! | Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the... | The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two ... | For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also. | 15 3
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0 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 11321 Sort! Sort!! And Sort!!! 的C++程式碼,幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint N, M;\n \nbool cmp(int x, int y){\n if ((x % M) != (y % M)){\n return (x % M) < (y % M);\n } else {\n if ((x % ... | 11321 Sort! Sort!! And Sort!!! | Hmm! Here you are asked to do a simple sorting. You will be given N numbers and a positive integer M. You will have to sort the N numbers in ascending order of their modulo M value. If there is a tie between an odd number and an even number (that is their modulo M value is the same) then the odd number will precede the... | The input file contains 20 sets of inputs. Each set starts with two integers N (0 < N ≤ 10000) and M (0 < M ≤ 10000) which denotes how many numbers are within this set. Each of the next N lines contains one number each. These numbers should all fit in 32-bit signed integer. Input is terminated by a line containing two ... | For each set of input produce N + 1 lines of outputs. The first line of each set contains the value of N and M. The next N lines contain N numbers, sorted according to the rules mentioned above. Print the last two zeroes of the input file in the output file also. | 15 3
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0 0 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"11332 Summing Digits\"?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
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1234567892
0 | 2
2
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2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"11332 Summing Digits\"?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return sol... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"11332 Summing Digits\" in C++?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solv... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"11332 Summing Digits\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"11332 Summing Digits\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"11332 Summing Digits\" with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n e... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"11332 Summing Digits\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"11332 Summing Digits\", generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n ... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 11332 Summing Digits?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
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1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 11332 Summing Digits?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(r... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
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1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 11332 Summing Digits in C++?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(re... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
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1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 11332 Summing Digits.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 11332 Summing Digits.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return sol... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 11332 Summing Digits with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else ... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 11332 Summing Digits.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return sol... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 11332 Summing Digits, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n el... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「11332 Summing Digits」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \nint m... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「11332 Summing Digits」的解答是什麼?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \nint ... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「11332 Summing Digits」? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \ni... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「11332 Summing Digits」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n ... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「11332 Summing Digits」的解法嗎? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \nin... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「11332 Summing Digits」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n ... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「11332 Summing Digits」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \ni... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「11332 Summing Digits」的C++程式碼,幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "11332 Summing Digits 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \nint ma... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "11332 Summing Digits 的解答是什麼?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \nint m... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 11332 Summing Digits? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \nin... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 11332 Summing Digits 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n ... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 11332 Summing Digits 的解法嗎? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \nin... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 11332 Summing Digits 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n ... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 11332 Summing Digits 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\n}\n \ni... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 11332 Summing Digits 的C++程式碼,幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint solve(int x) {\n int ret = 0;\n while (x) {\n ret += x % 10;\n x /= 10;\n }\n if (ret < 10) return ret;\n else return solve(ret);\... | 11332 Summing Digits | For a positive integer n, let f(n) denote the sum of the digits of n when represented in base 10. It is easy to see that the sequence of numbers n, f(n), f(f(n)), f(f(f(n)))... eventually becomes a single digit number that repeats forever. Let this single digit be denoted g(n).
For example, consider n = 1234567892. Th... | Each line of input contains a single positive integer n at most 2,000,000,000. Input is terminated by n = 0 which should not be processed. | For each such integer, you are to output a single line containing g(n). | 2
11
47
1234567892
0 | 2
2
2
2 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"11349 Symmetric Matrix\"?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"11349 Symmetric Matrix\"?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"11349 Symmetric Matrix\" in C++?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"11349 Symmetric Matrix\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n]... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"11349 Symmetric Matrix\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long lon... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"11349 Symmetric Matrix\" with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"11349 Symmetric Matrix\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long lon... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"11349 Symmetric Matrix\", generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 11349 Symmetric Matrix?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 11349 Symmetric Matrix?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 11349 Symmetric Matrix in C++?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n]... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 11349 Symmetric Matrix.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 11349 Symmetric Matrix.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 11349 Symmetric Matrix with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n lo... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 11349 Symmetric Matrix.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 11349 Symmetric Matrix, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「11349 Symmetric Matrix」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n bool f... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「11349 Symmetric Matrix」的解答是什麼?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n bool ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「11349 Symmetric Matrix」? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n bo... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「11349 Symmetric Matrix」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「11349 Symmetric Matrix」的解法嗎? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n boo... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「11349 Symmetric Matrix」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「11349 Symmetric Matrix」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n bo... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「11349 Symmetric Matrix」的C++程式碼,幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "11349 Symmetric Matrix 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n bool fl... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "11349 Symmetric Matrix 的解答是什麼?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n bool f... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 11349 Symmetric Matrix? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n boo... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 11349 Symmetric Matrix 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 11349 Symmetric Matrix 的解法嗎? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n boo... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 11349 Symmetric Matrix 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 11349 Symmetric Matrix 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n bo... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 11349 Symmetric Matrix 的C++程式碼,幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n int T, n;\n char ch;\n cin >> T;\n for (int Case = 1; Case <= T; Case++){\n cin >> ch >> ch >> n;\n long long a[n][n];\n ... | 11349 Symmetric Matrix | You're given a square matrix M. Elements of this matrix are Mij:{0 < i < n, 0 < j < n}. In this problem you'll have to find out whether the given matrix is symmetric or not.
Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. ... | First line of input contains number of test cases T ≤ 300. Then T test cases follow each described in the following way. The first line of each test case contains n - the dimension of square matrix. Then n lines follow each of them containing row i. Row contains exactly n elements separated by a space character. j-th n... | For each test case output one line 'Test #t: S'. Where t is the test number starting from 1. Line S is equal to 'Symmetric' if matrix is symmetric and 'Non-symmetric' in any other case. | 2 N = 3 5 1 3 2 0 2 3 1 5 N = 3 5 1 3 2 0 2 0 1 5 | Test #1: Symmetric. Test #2: Non-symmetric. | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"11417 GCD\"?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G =... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"11417 GCD\"?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"11417 GCD\" in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"11417 GCD\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"11417 GCD\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"11417 GCD\" with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"11417 GCD\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"11417 GCD\", generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 11417 GCD?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 11417 GCD?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 11417 GCD in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 11417 GCD.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 11417 GCD.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 11417 GCD with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 11417 GCD.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 11417 GCD, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「11417 GCD」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「11417 GCD」的解答是什麼?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「11417 GCD」? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「11417 GCD」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「11417 GCD」的解法嗎? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「11417 GCD」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「11417 GCD」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「11417 GCD」的C++程式碼,幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "11417 GCD 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "11417 GCD 的解答是什麼?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 11417 GCD? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;\n ... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 11417 GCD 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n \nint GCD(int x, int y) {\n while ((x %= y) && (y %= x));\n return x + y;\n}\n \nint main() {\n int N, G;\n while (cin >> N && N) {\n G = 0;... | 11417 GCD | Given the value of N, you will have to find the value of G. The definition of G is given below:
G = Σ from i=1 to i<N Σ from j=i+1 to j≤N GCD(i,j)
Here GCD(i,j) means the greatest common divisor of integer i and integer j.
For those who have trouble understanding summation notation, the meaning of G is given in the ... | The input file contains at most 100 lines of inputs. Each line contains an integer N (1 < N < 501). The meaning of N is given in the problem statement. Input is terminated by a line containing a single zero. This zero should not be processed. | For each line of input produce one line of output. This line contains the value of G for corresponding N. | 10
100
500
0 | 67
13015
442011 | One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
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