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[
{
"content": "10101 Bangla Numbers 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x){... | 10101 Bangla Numbers | The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting. | The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999. | For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting. | 23764
45897458973958
| 1. 23 hajar 7 shata 64
2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10101 Bangla Numbers 的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll x)... | 10101 Bangla Numbers | The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting. | The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999. | For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting. | 23764
45897458973958
| 1. 23 hajar 7 shata 64
2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 10101 Bangla Numbers？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll... | 10101 Bangla Numbers | The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting. | The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999. | For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting. | 23764
45897458973958
| 1. 23 hajar 7 shata 64
2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 10101 Bangla Numbers 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2st... | 10101 Bangla Numbers | The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting. | The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999. | For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting. | 23764
45897458973958
| 1. 23 hajar 7 shata 64
2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 10101 Bangla Numbers 的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(ll... | 10101 Bangla Numbers | The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting. | The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999. | For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting. | 23764
45897458973958
| 1. 23 hajar 7 shata 64
2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 10101 Bangla Numbers 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2st... | 10101 Bangla Numbers | The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting. | The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999. | For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting. | 23764
45897458973958
| 1. 23 hajar 7 shata 64
2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 10101 Bangla Numbers 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring num2str(l... | 10101 Bangla Numbers | The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting. | The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999. | For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting. | 23764
45897458973958
| 1. 23 hajar 7 shata 64
2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 10101 Bangla Numbers 的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define ll long long\nint a[] = {10000000, 100000, 1000, 100};\nstring s[] = {\"kuti\", \"lakh\", \"hajar\", \"shata\"};\nstring ans;\n \nstring ... | 10101 Bangla Numbers | The problem involves converting a given non-negative number into its Bangla text representation using the terms 'kuti' (10,000,000), 'lakh' (100,000), 'hajar' (1,000), and 'shata' (100). The input consists of numbers up to 999,999,999,999,999, and the output must display the converted text with proper formatting. | The input file contains several test cases, each with a non-negative number ≤ 999,999,999,999,999. | For each test case, output the case number (starting from 1) followed by the Bangla text representation of the number. The output should use the terms 'kuti', 'lakh', 'hajar', and 'shata' appropriately, with proper spacing and formatting. | 23764
45897458973958
| 1. 23 hajar 7 shata 64
2. 45 lakh 89 hajar 7 shata 45 kuti 89 lakh 73 hajar 9 shata 58
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"10170 The Hotel with Infinite Rooms\"?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"10170 The Hotel with Infinite Rooms\"?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n c... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"10170 The Hotel with Infinite Rooms\" in C++?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cn... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"10170 The Hotel with Infinite Rooms\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"10170 The Hotel with Infinite Rooms\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"10170 The Hotel with Infinite Rooms\" with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"10170 The Hotel with Infinite Rooms\".",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"10170 The Hotel with Infinite Rooms\", generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 10170 The Hotel with Infinite Rooms?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 10170 The Hotel with Infinite Rooms?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 10170 The Hotel with Infinite Rooms in C++?",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 10170 The Hotel with Infinite Rooms.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 10170 The Hotel with Infinite Rooms.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n c... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 10170 The Hotel with Infinite Rooms with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
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| 3
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| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 10170 The Hotel with Infinite Rooms.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n c... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 10170 The Hotel with Infinite Rooms, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10170 The Hotel with Infinite Rooms」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n D -... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10170 The Hotel with Infinite Rooms」的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n D ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「10170 The Hotel with Infinite Rooms」？ ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「10170 The Hotel with Infinite Rooms」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「10170 The Hotel with Infinite Rooms」的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「10170 The Hotel with Infinite Rooms」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「10170 The Hotel with Infinite Rooms」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「10170 The Hotel with Infinite Rooms」的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10170 The Hotel with Infinite Rooms 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n D -=... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10170 The Hotel with Infinite Rooms 的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n D -... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 10170 The Hotel with Infinite Rooms？ ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 10170 The Hotel with Infinite Rooms 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 10170 The Hotel with Infinite Rooms 的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 10170 The Hotel with Infinite Rooms 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 10170 The Hotel with Infinite Rooms 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 10170 The Hotel with Infinite Rooms 的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\nusing namespace std;\n \nint main() {\n long long S, D, cnt;\n while (cin >> S >> D){\n cnt = S;\n D -= S;\n while (D > 0){\n cnt++;\n ... | 10170 The Hotel with Infinite Rooms | The problem involves a hotel with infinite rooms where groups rent rooms following specific rules. Each group has one more member than the previous group and stays for a number of days equal to its group size. Given the initial group size (S) and a specific day (D), the task is to determine the group size staying in th... | Each line of input contains two integers: S (1 ≤ S ≤ 10000) representing the initial group size, and D (1 ≤ D < 10¹⁵) representing the day number for which the group size needs to be determined. | For each input line, output the group size staying in the hotel on the D-th day. | 1 6
3 10
3 14
| 3
5
6
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"10189 Minesweeper\"?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Cas... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"10189 Minesweeper\"?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n i... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"10189 Minesweeper\" in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n in... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"10189 Minesweeper\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"10189 Minesweeper\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"10189 Minesweeper\" with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint m... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"10189 Minesweeper\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"10189 Minesweeper\", generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nin... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 10189 Minesweeper?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 10189 Minesweeper?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 10189 Minesweeper in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n,... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 10189 Minesweeper.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 10189 Minesweeper.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n i... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 10189 Minesweeper with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main(... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 10189 Minesweeper.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n i... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 10189 Minesweeper, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint ma... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10189 Minesweeper」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;\n ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10189 Minesweeper」的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;\n ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「10189 Minesweeper」？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「10189 Minesweeper」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case =... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「10189 Minesweeper」的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;\... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「10189 Minesweeper」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case =... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「10189 Minesweeper」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「10189 Minesweeper」的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10189 Minesweeper 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;\n ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10189 Minesweeper 的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;\n ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 10189 Minesweeper？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;\... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 10189 Minesweeper 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case =... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道 10189 Minesweeper 的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;\... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫 10189 Minesweeper 的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case =... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成 10189 Minesweeper 的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, Case = 1;... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要 10189 Minesweeper 的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <cstring>\nusing namespace std;\nchar a[105][105];\nint b[105][105];\nint dx[] = {1, -1, 0, 0, -1, 1, -1, 1};\nint dy[] = {0, 0, 1, -1, 1, 1, -1, -1};\n \nint main() {\n int n, m, ... | 10189 Minesweeper | The problem involves simulating the Minesweeper game. Given a grid where mines are marked with '*' and safe spots with '.', the task is to generate a grid where each safe spot shows the number of adjacent mines (including diagonally adjacent mines). The solution requires processing multiple grids until a grid with dime... | The input consists of multiple grids. Each grid starts with two integers n and m (0 < n, m ≤ 100) representing the grid dimensions. The next n lines contain m characters each (either '*' or '.'). The input ends when n = m = 0. | For each grid, output the grid number (starting from 1) followed by the processed grid where each '.' is replaced by the count of adjacent mines. Separate the output for each grid with a blank line. | 4 4
*...
....
*...
....
3 5
**...
.....
.*...
0 0
| Field #1:
*100
2210
1*10
1110
Field #2:
**100
33200
1*100
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve \"10190 Divide, But Not Quite Conquer!\"?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for \"10190 Divide, But Not Quite Conquer!\"?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement \"10190 Divide, But Not Quite Conquer!\" in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for \"10190 Divide, But Not Quite Conquer!\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for \"10190 Divide, But Not Quite Conquer!\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for \"10190 Divide, But Not Quite Conquer!\" with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for \"10190 Divide, But Not Quite Conquer!\".",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for \"10190 Divide, But Not Quite Conquer!\", generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to solve 10190 Divide, But Not Quite Conquer!?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "What is the solution for 10190 Divide, But Not Quite Conquer!?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "How to implement 10190 Divide, But Not Quite Conquer! in C++?",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Give me a C++ code for 10190 Divide, But Not Quite Conquer!.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Do you know the solution for 10190 Divide, But Not Quite Conquer!.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Show me the code for 10190 Divide, But Not Quite Conquer! with explanations.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = fals... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "Generate a code solution for 10190 Divide, But Not Quite Conquer!.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "I need a C++ code for 10190 Divide, But Not Quite Conquer!, generate it for me.",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = f... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10190 Divide, But Not Quite Conquer!」要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || m == 0... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "「10190 Divide, But Not Quite Conquer!」的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || m == ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作「10190 Divide, But Not Quite Conquer!」？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || m ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個「10190 Divide, But Not Quite Conquer!」的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 ||... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "你知道「10190 Divide, But Not Quite Conquer!」的解法嗎？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || m =... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "撰寫「10190 Divide, But Not Quite Conquer!」的程式碼並附帶說明。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 ||... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "生成「10190 Divide, But Not Quite Conquer!」的程式碼解答。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || m ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "我需要「10190 Divide, But Not Quite Conquer!」的C++程式碼，幫我生成一個。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n =... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10190 Divide, But Not Quite Conquer! 要怎麼解? ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || m == 0 ... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "10190 Divide, But Not Quite Conquer! 的解答是什麼？",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || m == 0... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "如何用C++實作 10190 Divide, But Not Quite Conquer!？ ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 || m =... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
[
{
"content": "給我一個 10190 Divide, But Not Quite Conquer! 的C++程式碼。 ",
"role": "user"
},
{
"content": "#include <iostream>\n#include <vector>\nusing namespace std;\n \nint main() {\n int n, m;\n while (cin >> n >> m){\n vector <int> ans;\n bool boring = false;\n if (n == 0 ||... | 10190 Divide, But Not Quite Conquer! | The problem requires dividing an integer n by another integer m repeatedly until n becomes 1, generating a sequence of numbers. The sequence must satisfy the following conditions:
1. Each term after the first must be the previous term divided by m.
2. Each term (except the last) must be divisible by m.
3. The sequence ... | The input consists of multiple lines, each containing two non-negative integers n and m (both less than 2,000,000,000). The input continues until the end of file. | For each pair (n, m), output the sequence if it meets all conditions, separated by spaces. If the sequence is invalid, output 'Boring!'. | 125 5
30 3
80 2
81 3
| 125 25 5 1
Boring!
Boring!
81 27 9 3 1
| One star | Online Judge | https://onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=0 | Yui Huang's Website | https://yuihuang.com/cpe-level-1/ | null | null | null |
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