id int64 1 3.58k | problem_description stringlengths 516 21.8k | instruction int64 0 3 | solution_c dict |
|---|---|---|---|
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int maxLen = 0;\n int n = s.size();\n int leftP = 0, rightP = 0;\n\n for(int i=0; i<n; i++){\n if(s[i] == '(') leftP++;\n if(s[i] == ')') rightP++;\n\n if(leftP == rightP){\... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int o = 0; // open brackets counter\n int c = 0; // close brackets counter\n int ans = 0; // store the max length in a single pass\n int fans = 0; // final answer\n\n // Left to right scan\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int left=0;\n int right=0;\n int j=0;\n int ans=0;\n while(j<s.size()){\n if(s[j]=='(')\n left++;\n else\n right++;\n if(left==right)\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int open =0 , close =0 ,maxi=0;\n for(int i=0;i<s.length();i++){\n if(s[i]=='('){\n open++;\n }\n else if(s[i]==')'){\n close++;\n }\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) \n {\n int l=0, r=0, m=0;\n\n for(int i=0; i<s.length(); i++)\n {\n if(s[i]=='(')\n {\n l++;\n }\n\n else if(s[i]==')')\n {\n r++... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\n bool fnc(string& s){\n stack<int>st;\n int j=0;\n while(j<s.size()){\n if(s[j]=='(')\n st.push('(');\n else{\n if(st.size()>0&&st.top()=='(')\n st.pop();\n else\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int n = s.size();\n int f[n + 1];\n memset(f, 0, sizeof(f));\n for (int i = 2; i <= n; ++i) {\n if (s[i - 1] == ')') {\n if (s[i - 2] == '(') {\n f[i] = f[i - 2]... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n \n stack<int> st;\n st.push(-1);\n int maxLength = 0;\n \n for (int i = 0; i < s.size(); ++i) {\n if (s[i] == '(') {\n st.push(i); \n } else {\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n stack<int> starts;\n starts.push(-1);\n int maxLen = 0;\n for (int i=0; i<s.size(); i++) {\n if (s[i] == '(') {\n starts.push(i);\n } else {\n starts.pop(... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int n=s.size();\n stack<int>st;\n int i=0;\n while(i<n){\n if(s[i]=='(')st.push(i);\n else if(s[i]==')'){\n if(st.empty() || s[st.top()]!='(')st.push(i);\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n stack<int> st;\n st.push(-1); // Base to calculate lengths\n int maxLength = 0;\n\n for (int i = 0; i < s.size(); i++) {\n if (s[i] == '(') {\n st.push(i); // Push index of '('\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n stack<int> st;\n for(int i=0; i<s.size(); i++){\n if(s[i] == '('){\n st.push(i);\n }\n else{\n if(!st.empty() && s[st.top()] == '('){\n st... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 0 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) \n {\n int ans = 0;\n stack<int> stk;\n\n for (int i = 0; i < s.size(); ++ i)\n {\n if( s[i] == ')' && stk.size() && s[stk.top()] == '(')\n {\n stk.pop();\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 1 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n vector<bool> nums(s.size(),false);\n stack<int> st;\n for(int i=0;i<s.size();i++)\n {\n if(s[i]=='(') st.push(i);\n else\n {\n if(!st.empty())\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 1 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n \n stack<int> st;\n st.push(-1);\n int maxLength = 0;\n \n for (int i = 0; i < s.size(); ++i) {\n if (s[i] == '(') {\n st.push(i); \n } else {\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 2 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n \n stack<int> st;\n st.push(-1);\n int maxLength = 0;\n \n for (int i = 0; i < s.size(); ++i) {\n if (s[i] == '(') {\n st.push(i); \n } else {\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 2 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n stack<int> st;\n for(int i=0; i<s.size(); i++){\n if(s[i] == '('){\n st.push(i);\n }\n else{\n if(!st.empty() && s[st.top()] == '('){\n st... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) \n {\n int ans = 0;\n const int n = s.size();\n stack<int> stk;\n\n for (int i = 0; i < n; ++ i)\n {\n if(s[i] == ')' && stk.size() && s[stk.top()] == '(')\n {\n s... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\n public:\n int longestValidParentheses(string s) {\n const string s2 = \")\" + s;\n // dp[i] := the length of the longest valid parentheses in the substring\n // s2[1..i]\n vector<int> dp(s2.length());\n\n for (int i = 1; i < s2.length(); ++i)\n if (s2[i] == ')' && s2... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int ans=0, n = s.size();\n stack<int> st1,st2;\n st2.push(-1);\n for(int i=0;i<n;i++){\n if(s[i]=='(') {\n st1.push(i);\n }\n else {\n if(st1.s... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n vector<int> dp;\n dp.push_back(0);\n int ans = 0;\n for (int i = 1; i < s.size(); i++) {\n if (s[i] == '(') {\n dp.push_back(0);\n } else {\n int len = 0;... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n stack<int> open;\n int n = s.size();\n int ans = 0;\n vector<pair<int, int>> segs;\n for(int i = 0; i < n; i++){\n if(s[i] == ')' && open.size() == 0){\n while(open.size() > 0) open.pop();\n } e... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int n = s.size();\n\n stack<int> st;\n\n for(int i=0; i<n; i++){\n\nif(s[i]=='('){\n st.push(i);\n}else if(s[i]==')'){\n \n if(st.empty()){\n st.push(i);\n }else if(s[st.top()]=='('){\n s... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n vector<pair<int,int>>arr;\n stack<int>st;\n int n=s.size();\n for(int i=0;i<n;i++){\n if(s[i]=='('){\n st.push(i);\n }\n else{\n if(!st.empty()... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int maxValid = 0;\n stack<int> stk; // ( -> 0\n for (const auto c : s) {\n if (c == '(') {\n stk.push(0);\n } else if (c == ')') {\n // case 0: )\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n stack<pair<char,int>> S;\n\n //Sanitize string\n for(int i =0;i<s.size();i++)\n {\n if(s[i]==')')\n {\n if(!S.empty())\n {\n s[S.top().second]='#',\n... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int count = 0;\n if(s==\"\") return(0);\n stack<int> st;\n int res = 0;\n int cur = 0;\n for(char c:s){\n if(c=='(') {\n if(cur>0) {\n while( !st.e... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n stack<int> st;\n int ans = 0;\n for(char c : s) {\n if(c == '(') {\n st.push(-1);\n }\n else {\n int count = 0;\n if(!st.empty()) {\n ... |
32 | <p>Given a string containing just the characters <code>'('</code> and <code>')'</code>, return <em>the length of the longest valid (well-formed) parentheses </em><span data-keyword="substring-nonempty"><em>substring</em></span>.</p>
<p> </p>
<p><strong class="example">Example 1:</strong></p>
<pre... | 3 | {
"code": "class Solution {\npublic:\n int longestValidParentheses(string s) {\n int maxValid = 0;\n stack<int> stk; // ( -> 0\n for (const auto c : s) {\n if (c == '(') {\n stk.push(0);\n } else if (c == ')') {\n // case 0: )\n ... |
33 | <p>There is an integer array <code>nums</code> sorted in ascending order (with <strong>distinct</strong> values).</p>
<p>Prior to being passed to your function, <code>nums</code> is <strong>possibly rotated</strong> at an unknown pivot index <code>k</code> (<code>1 <= k < nums.length</code>) such that the result... | 0 | {
"code": "class Solution {\npublic:\n int search(vector<int>& nums, int target) {\n int n=nums.size();\n int left=0,mid,right=n-1;\n while(left<=right){\n mid=(left+right)/2;\n if(target==nums[mid])return mid;\n if(nums[left]<=nums[mid]){\n if(t... |
33 | <p>There is an integer array <code>nums</code> sorted in ascending order (with <strong>distinct</strong> values).</p>
<p>Prior to being passed to your function, <code>nums</code> is <strong>possibly rotated</strong> at an unknown pivot index <code>k</code> (<code>1 <= k < nums.length</code>) such that the result... | 0 | {
"code": "class Solution {\npublic:\n int search(vector<int>& nums, int target) {\n int n = nums.size();\n int l = 0;\n int h = n - 1;\n while(l <= h){\n int m = l + (h - l)/2;\n if(nums[m] == target){\n return m;\n }\n if(nums... |
33 | <p>There is an integer array <code>nums</code> sorted in ascending order (with <strong>distinct</strong> values).</p>
<p>Prior to being passed to your function, <code>nums</code> is <strong>possibly rotated</strong> at an unknown pivot index <code>k</code> (<code>1 <= k < nums.length</code>) such that the result... | 0 | {
"code": "class Solution {\npublic:\n int search(vector<int>& nums, int key) {\n int n=nums.size();\n int s=0, e=n-1;\n while(s<=e){\n int mid=(s+e)/2;\n if(nums[mid]==key) return mid;\n if(nums[s]<=nums[mid]){\n if(nums[s]<=key && nums[mid]>=ke... |
33 | <p>There is an integer array <code>nums</code> sorted in ascending order (with <strong>distinct</strong> values).</p>
<p>Prior to being passed to your function, <code>nums</code> is <strong>possibly rotated</strong> at an unknown pivot index <code>k</code> (<code>1 <= k < nums.length</code>) such that the result... | 0 | {
"code": "class Solution {\npublic:\n int search(vector<int>& nums, int target) {\n for(int i=0;i<nums.size();i++){\n if(nums[i] == target){\n return i;\n }\n }\n return -1;\n }\n};",
"memory": "13700"
} |
33 | <p>There is an integer array <code>nums</code> sorted in ascending order (with <strong>distinct</strong> values).</p>
<p>Prior to being passed to your function, <code>nums</code> is <strong>possibly rotated</strong> at an unknown pivot index <code>k</code> (<code>1 <= k < nums.length</code>) such that the result... | 0 | {
"code": "class Solution {\npublic:\n\n int search(vector<int>& nums, int target) {\n int n=nums.size();\n int low=0,high=n-1;\n while(low<=high){\n int mid=(low+high)/2;\n if(nums[mid]==target) return mid;\n if(nums[low] <= nums[mid]){\n if(num... |
33 | <p>There is an integer array <code>nums</code> sorted in ascending order (with <strong>distinct</strong> values).</p>
<p>Prior to being passed to your function, <code>nums</code> is <strong>possibly rotated</strong> at an unknown pivot index <code>k</code> (<code>1 <= k < nums.length</code>) such that the result... | 0 | {
"code": "class Solution {\npublic:\n int search(vector<int>& nums, int target) {\n int pivot = 0;\n int left = 0;\n int right = nums.size() - 1;\n\n if (nums[left] <= nums[right]) {\n pivot = 0; \n }\n\n // find the pivot \n while (left <= right) {\n ... |
33 | <p>There is an integer array <code>nums</code> sorted in ascending order (with <strong>distinct</strong> values).</p>
<p>Prior to being passed to your function, <code>nums</code> is <strong>possibly rotated</strong> at an unknown pivot index <code>k</code> (<code>1 <= k < nums.length</code>) such that the result... | 0 | {
"code": "class Solution {\npublic:\n int search(vector<int>& nums, int target) {\n int n = nums.size() - 1;\n int i=0;\n int j = n; \n\n while(i<=j){\n int mid = i+(j-i)/2;\n \n if(nums[mid] == target){\n \n return mid;\n ... |
33 | <p>There is an integer array <code>nums</code> sorted in ascending order (with <strong>distinct</strong> values).</p>
<p>Prior to being passed to your function, <code>nums</code> is <strong>possibly rotated</strong> at an unknown pivot index <code>k</code> (<code>1 <= k < nums.length</code>) such that the result... | 0 | {
"code": "class Solution {\npublic:\n int search(vector<int>& nums, int target) {\n int n = nums.size();\n int low = 0;\n int high = n-1;\n while(low<=high){\n int mid =(low+high)/2;\n if(nums[mid]==target) return mid;\n if(nums[low]<=nums[mid]){\n ... |
34 | <p>Given an array of integers <code>nums</code> sorted in non-decreasing order, find the starting and ending position of a given <code>target</code> value.</p>
<p>If <code>target</code> is not found in the array, return <code>[-1, -1]</code>.</p>
<p>You must write an algorithm with <code>O(log n)</code> run... | 0 | {
"code": "class Solution {\n int binf(vector<int> &arr, int target){\n if(arr[0]==target) return 0;\n int k = arr.size()-1;\n int idx = 0;\n while(k>0){\n cout<<k<<endl;\n if(idx+k<arr.size() && arr[idx + k]<target) idx+=k;\n int t = (k%2!=0);\n ... |
34 | <p>Given an array of integers <code>nums</code> sorted in non-decreasing order, find the starting and ending position of a given <code>target</code> value.</p>
<p>If <code>target</code> is not found in the array, return <code>[-1, -1]</code>.</p>
<p>You must write an algorithm with <code>O(log n)</code> run... | 0 | {
"code": "class Solution {\npublic:\n vector<int> searchRange(vector<int>& nums, int target) {\n auto lb = lower_bound(nums.begin(), nums.end(), target);\n\n if (lb == nums.end() || *lb != target) {\n return {-1, -1};\n }\n auto ub = upper_bound(nums.begin(), nums.end(), tar... |
34 | <p>Given an array of integers <code>nums</code> sorted in non-decreasing order, find the starting and ending position of a given <code>target</code> value.</p>
<p>If <code>target</code> is not found in the array, return <code>[-1, -1]</code>.</p>
<p>You must write an algorithm with <code>O(log n)</code> run... | 0 | {
"code": "class Solution {\npublic:\n vector<int> searchRange(vector<int>& nums, int target) {\n int lb = lower_bound(nums.begin(), nums.end(), target) - nums.begin();\n int ub = upper_bound(nums.begin(), nums.end(), target) - nums.begin();\n\n if (lb == nums.size() || nums[lb] != target){\n ... |
34 | <p>Given an array of integers <code>nums</code> sorted in non-decreasing order, find the starting and ending position of a given <code>target</code> value.</p>
<p>If <code>target</code> is not found in the array, return <code>[-1, -1]</code>.</p>
<p>You must write an algorithm with <code>O(log n)</code> run... | 0 | {
"code": "class Solution {\npublic:\n vector<int> searchRange(vector<int>& arr, int target) {\n vector<int>v(2,-1); //vector to return friest and last index of element.\n int lo=0,hi=arr.size()-1;\n while(lo<=hi){ // Find first Position\n int mid=lo+(hi-lo)/2;\n if(arr[... |
34 | <p>Given an array of integers <code>nums</code> sorted in non-decreasing order, find the starting and ending position of a given <code>target</code> value.</p>
<p>If <code>target</code> is not found in the array, return <code>[-1, -1]</code>.</p>
<p>You must write an algorithm with <code>O(log n)</code> run... | 0 | {
"code": "class Solution {\npublic:\n vector<int> searchRange(vector<int>& arr, int target) {\n vector<int>v(2,-1); //vector to return friest and last index of element.\n int lo=0,hi=arr.size()-1;\n while(lo<=hi){ // Find first Position\n int mid=lo+(hi-lo)/2;\n if(arr[... |
34 | <p>Given an array of integers <code>nums</code> sorted in non-decreasing order, find the starting and ending position of a given <code>target</code> value.</p>
<p>If <code>target</code> is not found in the array, return <code>[-1, -1]</code>.</p>
<p>You must write an algorithm with <code>O(log n)</code> run... | 0 | {
"code": "class Solution {\npublic:\n \n int findFirst(vector<int>& nums, int target) {\n int left = 0, right = nums.size() - 1;\n int index = -1;\n \n while (left <= right) {\n int mid = left + (right - left) / 2;\n if (nums[mid] == target) {\n ... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 0 | {
"code": "class Solution {\n public:\n int searchInsert(vector<int>& nums, int target) {\n int l = 0;\n int r = nums.size();\n\n while (l < r) {\n const int m = (l + r) / 2;\n if (nums[m] == target)\n return m;\n if (nums[m] < target)\n l = m + 1;\n else\n r = m;\n ... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 0 | {
"code": "class Solution {\npublic:\n int searchInsert(vector<int>& nums, int target) {\n int i = 0;\n int j = nums.size()-1;\n\n while (i <= j) {\n if (i + 1 == j && j - 1 == i) {\n if (target > nums[i] && target < nums[j]) {\n return i+1;\n ... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 0 | {
"code": "class Solution\n{\npublic:\n int searchInsert(vector<int>& nums, int target)\n {\n int start=0,end=nums.size()-1,mid,idx= nums.size();\n while(start<=end)\n {\n mid=(start+end)/2;\n if(nums[mid]==target)\n {\n idx=mid;\n break;\n ... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 0 | {
"code": "class Solution {\npublic:\n int searchInsert(vector<int>& nums, int target) {\n \n if(nums[0]>target)return 0;\n int n=nums.size();\n if(nums[n-1]<target)return n;\n for(int i=0;i<nums.size();i++){\n if(nums[i]==target){\n cout<<\"hhhh\"<<endl... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 0 | {
"code": "class Solution \n{\npublic:\n int searchInsert(std::vector<int>& nums, int target) \n {\n int result = 0;\n\n for (int i = 0; i < nums.size(); i++)\n {\n \n\n if (nums[i] == target)\n {\n \n result= i;\n ... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 0 | {
"code": "class Solution {\npublic:\n int searchInsert(vector<int>& nums, int target) {\n int i=0;\n for(i=0;i<nums.size();i++){\n if(nums[i]==target){\n break;\n }\n else if(nums[i]>target){\n break;\n }\n }\n retur... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 0 | {
"code": "#include <vector>\nusing namespace std;\n\nclass Solution {\npublic:\n int searchInsert(vector<int>& nums, int target) {\n int left = 0;\n int right = nums.size() - 1;\n \n while (left <= right) {\n int mid = left + (right - left) / 2;\n \n if... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 0 | {
"code": "class Solution {\npublic:\n int searchInsert(vector<int>& nums, int target) {\n int n = nums.size();\n int low=0;\n int high=n-1;\n int ans = n;\n while(low <= high){\n int mid = (low+high)/2;\n if(nums[mid] >= target){\n ans = mid;... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 1 | {
"code": "class Solution {\npublic:\n int searchInsert(vector<int>& nums, int target) {\n int left = 0;\n int right = nums.size() - 1;\n while (left <= right) {\n int new_index = (right - left) / 2 + left;\n if (nums[new_index] == target) {\n return new_in... |
35 | <p>Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.</p>
<p>You must write an algorithm with <code>O(log n)</code> runtime complexity.</p>
<p> </p>
<p><strong class="example">Ex... | 1 | {
"code": "class Solution {\npublic:\n int searchInsert(vector<int>& nums, int target) {\n\n auto it = lower_bound(nums.begin(),nums.end(),target);\n return distance(nums.begin(),it);\n }\n};",
"memory": "12400"
} |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n bool check[11] = {0};\n for (int i = 0; i < 9; i++) {\n for (int x = 0; x <= 9; x++)\n check[x] = 0;\n for (int j = 0; j < 9; j++) {\n if (board[i][j] != '.')... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isSafe(vector<vector<char>>& board, int i, int j, int n, int m,\n char val) {\n // Check row\n for (int x = 0; x < m; x++) {\n if (x != j && board[i][x] == val) // Avoid current cell\n return false;\n }\n\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool st[9];\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i=0; i<9;i++){\n memset(st, 0, sizeof st);\n for(int j=0;j<9;j++){\n if(board[i][j]!='.'){\n int t=board[i][j]-'1';\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n int zton[10] = {0};\n int i, j, k, l, x;\n for(i = 0; i < 9; i+=3){\n for(j = 0; j < 9; j+=3){\n for(k = i; k<i+3; k++){\n for(l = j; l<j+3; l++){\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for (int r = 0; r < board.size(); r++) {\n for (int c = 0; c < board[0].size(); c++) {\n if (board[r][c] != '.') {\n char temp = board[r][c];\n board[r][... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isSafe(int row,int col , vector<vector<char>>& board, int val){\n for(int i=0;i<9;i++){\n if(i !=row && board[i][col]==val+'0')return false;\n if(i!=col && board[row][i]==val+'0')return false;\n int newRow = 3*(row/3)+i/3;\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for (int i = 0; i < board.size(); ++i) {\n for (int j = 0; j < board[0].size(); ++j) {\n if (board[i][j] != '.') {\n // check row\n for (int k = 0; k < b... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i = 0;i < 9;i++){\n for(int j = 0;j < 9;j++){\n char ele1 = board[i][j];\n if(ele1 == '.'){\n continue;\n }\n for(int k... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool check(vector<vector<char>>& board, int row, int col) {\n // Check row and column\n for (int i = 0; i < 9; i++) {\n if (i != col && board[row][i] == board[row][col]) return false;\n if (i != row && board[i][col] == board[row][col]) return false;\n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n bool m[9][9] = {0}, m2[9][9] = {0}, m3[9][9] = {0};\n for(int i=0;i<9;i++){\n for(int j=0;j<9;j++){\n if(board[i][j] != '.'){\n int num = board[i][j]-'0'-1;\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n const int num = 9;\n // Initialize boolean arrays to track digits in each row, column, and subgrid\n bool row[num][num] = {false};\n bool col[num][num] = {false};\n bool subGrid[num][num] =... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n const int count = 9;\n bool row[count][count] = {false};\n bool col[count][count] = {false};\n bool sub[count][count] = {false};\n\n for(int r = 0; r < count; r++) {\n for(int c ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n const int num = 9;\n // Initialize boolean arrays to track digits in each row, column, and subgrid\n bool row[num][num] = {false};\n bool col[num][num] = {false};\n bool subGrid[num][num] =... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n bool m[9][9] = {0}, m2[9][9] = {0}, m3[9][9] = {0};\n for(int i=0;i<9;i++){\n for(int j=0;j<9;j++){\n if(board[i][j] != '.'){\n int num = board[i][j]-'0'-1;\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n this->board = board;\n for(int i = 0;i<3;i++) {\n for(int j = 0;j<3;j++) {\n if(!check_grid(i, j)) return false;\n }\n }\n for(int i = 0;i<9;i++) {\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\nbool check(vector<vector<char>>& board,int x,int y){\n int rows=board.size();\n int col=board[0].size();\n char val=board[x][y];\n //up\n int rowx=x-1;\n while(rowx>=0){\n if(board[rowx][y]==val)return 0;\n rowx--;\n }\n //down\n rowx=x+1;... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<int>> sq(3, vector<int>(3, 0));\n vector<int> row(9, 0), column(9, 0);\n const int bitmask = (1 << 10) - 1; \n\n for(int i = 0; i < 9; i++){\n for(int j = 0; j < 9; j++){\... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<int> blocks[10];\n\n for(int i=0;i<9;i++){\n for(int j=0;j<9;j++){\n if(board[i][j]-'0' >=1 && board[i][j]-'0'<=9){\n int block = 3*(j/3) + (i/3);\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool is_valid_elem(const vector<char>& elem) {\n int size = elem.size();\n if (size == 1) return true;\n else if (size == 2) return elem[0] != elem[1];\n\n array<bool, 9> appearences;\n appearences.fill(false);\n for (char c : elem) {... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i = 0 ; i < 9; i++){\n vector<bool> vi(10,false);\n vector<bool> vj(10,false);\n for(int j = 0 ; j < 9 ; j++){\n if(board[i][j] != '.') {\n \n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 0 | {
"code": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n /* check row validity */\n for (int i = 0; i < board.size(); i++) {\n vector<bool> mark(10);\n /* check row validity */\n for... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n\n// Three Cases so 3 condtions.\n int rowcase[9][9] ={0};\n int colcase[9][9] = {0};\n int gridcase[9][9] = {0};\n\n for(int i=0;i<board.size();i++){\n for(int j=0;j<board[0].si... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i = 0 ; i < 9; i++){\n vector<bool> vi(10,false);\n vector<bool> vj(10,false);\n for(int j = 0 ; j < 9 ; j++){\n if(board[i][j] != '.') {\n \n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i = 0 ; i < 9; i++){\n vector<bool> vi(10,false);\n vector<bool> vj(10,false);\n for(int j = 0 ; j < 9 ; j++){\n if(board[i][j] != '.') {\n \n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i = 0 ; i < 9; i++){\n vector<bool> vi(10,false);\n vector<bool> vj(10,false);\n for(int j = 0 ; j < 9 ; j++){\n if(board[i][j] != '.') {\n \n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution\n{\npublic:\n bool isValidSudoku(vector<vector<char>>& board)\n {\n // Each row.\n for (int r = 0; r < 9; r++)\n {\n vector<int> palette(10, 0);\n for (int c = 0; c < 9; c++)\n {\n if (board[r][c] != '.')\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n unordered_map<char,int> m;\n for(int i=0;i<9;i++){\n m.clear();\n for(int j=0;j<9;j++){\n if(board[i][j]!='.'){\n m[board[i][j]]++;\n }\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n int n =9;\n for(int i=0;i<n;i++){\n vector<int> clm(10,0);\n vector<int> row(10,0);\n for(int j=0;j<9;j++){\n int c = board[i][j]-'0';\n if(c>0&&c<10){\n if(clm[c]<1){\... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i = 0 ; i < 9; i++){\n vector<bool> vi(10,false);\n vector<bool> vj(10,false);\n for(int j = 0 ; j < 9 ; j++){\n if(board[i][j] != '.') {\n \n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "#include <vector>\n#include <unordered_set>\nusing namespace std;\n\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n unordered_set<char> rowSet;\n unordered_set<char> colSet;\n unordered_set<char> boxSet;\n for (int i = 0; i < 9; ++i) {\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "#include <vector>\n#include <unordered_set>\nusing namespace std;\n\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n unordered_set<char> rowSet;\n unordered_set<char> colSet;\n unordered_set<char> boxSet;\n for (int i = 0; i < 9; ++i) {\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "#include <vector>\n#include <unordered_set>\nusing namespace std;\n\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n unordered_set<char> rowSet;\n unordered_set<char> colSet;\n unordered_set<char> boxSet;\n for (int i = 0; i < 9; ++i) {\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n char valueH,valueV,value;\n unordered_set<char> horizontal;\n unordered_set<char> vertical;\n for (int i = 0; i < 9; i++) {\n \n horizontal.clear();\n vertical.clear();\n\n\n for (int ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i = 0; i < 9; i+=3){\n for(int j = 0; j < 9; j+=3){\n set<char> box;\n for(int k = i; k<i+3; k++){\n for(int l = j; l<j+3; l++){\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "#include <vector>\n#include <unordered_set>\nusing namespace std;\n\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n unordered_set<char> rowSet;\n unordered_set<char> colSet;\n unordered_set<char> boxSet;\n for (int i = 0; i < 9; ++i) {\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isvalidrow(vector<vector<int>>& s, int r) {\n vector<int> a(10, 0);\n for (int j = 0; j < 9; j++) {\n\n int x = s[r][j];\n a[x]++;\n if (a[x] > 1 && x != 0)\n return false;\n }\n\n return true;\n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n for(int i = 0; i < 9; i+=3){\n for(int j = 0; j < 9; j+=3){\n set<char> box;\n for(int k = i; k<i+3; k++){\n for(int l = j; l<j+3; l++){\n ... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n \n map<char, int> map_row;\n map<char, int> map_col;\n map<char, int> map_box;\n\n for(int i=0;i<9;i++)\n {\n map_row.clear();\n map_col.clear();\n m... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<bool>> row(9, vector<bool>(9, false));\n vector<vector<bool>> col(9, vector<bool>(9, false));\n vector<vector<bool>> sub(9, vector<bool>(9, false));\n for (int i = 0; i < 9; ++i) {... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<bool>> row(9, vector<bool>(9, false));\n vector<vector<bool>> col(9, vector<bool>(9, false));\n vector<vector<bool>> sub(9, vector<bool>(9, false));\n for (int i = 0; i < 9; ++i) {\n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "/*\n Valid? 1-9 once in a row, a column, and a square.\n\n O(n^2) time, O(n) space\n*/\n\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n int n = board.size();\n vector<vector<bool>> rowCheck(n, vector<bool>(n, false));\n vector<vector<bool>> co... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<bool>> row(9, vector<bool>(9, false));\n vector<vector<bool>> col(9, vector<bool>(9, false));\n vector<vector<bool>> sub(9, vector<bool>(9, false));\n for (int i = 0; i < 9; ++i) {... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<bool>> row(9, vector<bool>(9, false));\n vector<vector<bool>> col(9, vector<bool>(9, false));\n vector<vector<bool>> sub(9, vector<bool>(9, false));\n for (int i = 0; i < 9; ++i) {... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<bool>> rows(9, vector<bool>(9, false));\n vector<vector<bool>> cols(9, vector<bool>(9, false));\n vector<vector<bool>> boxes(9, vector<bool>(9, false));\n\n for (int i=0; i<board.siz... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "class Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<bool>> row(9, vector<bool>(9, false));\n vector<vector<bool>> col(9, vector<bool>(9, false));\n vector<vector<bool>> sub(9, vector<bool>(9, false));\n for (int i = 0; i < 9; ++i) {\n... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<bool>> row(9, vector<bool>(9, false));\n vector<vector<bool>> col(9, vector<bool>(9, false));\n vector<vector<bool>> sub(9, vector<bool>(9, false));\n for (int i = 0; i < 9; ++i) {... |
36 | <p>Determine if a <code>9 x 9</code> Sudoku board is valid. Only the filled cells need to be validated <strong>according to the following rules</strong>:</p>
<ol>
<li>Each row must contain the digits <code>1-9</code> without repetition.</li>
<li>Each column must contain the digits&... | 1 | {
"code": "\nclass Solution {\npublic:\n bool isValidSudoku(vector<vector<char>>& board) {\n vector<vector<bool>> row(9, vector<bool>(9, false));\n vector<vector<bool>> col(9, vector<bool>(9, false));\n vector<vector<bool>> sub(9, vector<bool>(9, false));\n for (int i = 0; i < 9; ++i) {... |
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