id int64 1 3.58k | problem_description stringlengths 516 21.8k | instruction int64 0 3 | solution_c dict |
|---|---|---|---|
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "#include <vector>\n#include <queue>\n\nusing namespace std;\n\nclass Solution {\nprivate:\n struct Compare {\n bool operator()(const vector<int>& a, const vector<int>& b) const {\n if (a[0] == b[0]) return a[1] > b[1];\n return a[0] < b[0];\n }\n };\n\npublic:\n ... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>properties) \n {\n vector<pair<int,int>>pairs;\n pair<int,int>temp;\n int i,j;\n for(i=0;i<properties.size();i++)\n {\n temp.first=properties[i][0];\n temp.second=propert... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n static bool comp(vector<int>&a,vector<int>&b)\n {\n if(a[0]==b[0])return a[1]>b[1];\n return a[0]<b[0];\n }\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n stack<vector<int>> st;\n sort(properties.begin(),properties.end()... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "#include <ranges>\nclass Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n std::map<int, std::vector<int>, std::greater<int>> characters{};\n for(const auto& vec : properties) {\n characters[vec[0]].push_back(vec[1]);\n }\n auto highest_defense = std::r... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n map<int, vector<int>> bucket;\n for(auto &i: properties){\n bucket[i[0]].push_back(i[1]);\n }\n int maxdef = 0;\n int ret = 0;\n for(auto i = bucket.rbegin(); ... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\n using vi = vector<int>;\n using vvi = vector<vi>;\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n map<int,vi> mp;\n sort(properties.begin(), properties.end(), [](const vi& a, const vi& b){\n return a[0] < b[0] || (a[0] == b[0] ... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\n using vi = vector<int>;\n using vvi = vector<vi>;\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n map<int,vi> mp;\n sort(properties.begin(), properties.end(), [](const vi& a, const vi& b){\n return a[0] < b[0] || (a[0] == b[0] ... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& A) {\n sort(begin(A), end(A), [](auto &a, auto &b) { return a[0] < b[0]; });\n multiset<int> s;\n for (auto &a : A) s.insert(a[1]);\n int N = A.size(), ans = 0;\n for (int i = 0; i < N; ) {\n ... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& p) {\n int n=p.size();\n\n vector<pair<int,int>>v;\n for(auto x:p){\n v.push_back({x[0],-x[1]});\n }\n\n sort(v.begin(),v.end());\n set<int>s;\n int ans=0;\n\n f... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>&arr) {\n int ans=0;\n sort(arr.begin(),arr.end());\n vector<int>maxVal(100001,0);\n vector<vector<int>>nums;\n for(int i=0;i<arr.size();i++){\n int st=arr[i][0];int maxi=arr[i][1];\n ... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n int ans = 0;\n int N = properties.size();\n auto cmp = [](vector<int>& x, vector<int>& y){\n if (x[0] == y[0]) return x[1] > y[1];\n return x[0] < y[0];\n };\n ... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n int n = properties.size();\n // vector<vector<int>> sort1;\n vector<vector<int>> sort2;\n // sort1 = properties;\n // sort(sort1.begin(), sort1.end(), [](vector<int>& a, vector<... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n int n = properties.size();\n if(n == 0) return 0;\n \n int maxAttackValue = 0;\n for(auto it: properties) {\n maxAttackValue = max(maxAttackValue, it[0]);\n }... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n vector<int> def(1e5+2);\n for(const auto v: properties) def[v[0]] = max(v[1], def[v[0]]); //choose max\n for(int i=1e5+1; i>0; --i) def[i-1] = max(def[i-1], def[i]); \n //printf(\"(%d,... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n int numberOfWeakCharacters(vector<vector<int>>& properties) {\n vector<int> def(1e5+2);\n for(const auto v: properties) def[v[0]] = max(v[1], def[v[0]]); //choose max\n for(int i=1e5+1; i>0; --i) def[i-1] = max(def[i-1], def[i]); \n //printf(\"(%d,... |
2,123 | <p>You are playing a game that contains multiple characters, and each of the characters has <strong>two</strong> main properties: <strong>attack</strong> and <strong>defense</strong>. You are given a 2D integer array <code>properties</code> where <code>properties[i] = [attack<sub>i</sub>, defense<sub>i</sub>]</code> re... | 3 | {
"code": "class Solution {\npublic:\n\n int numberOfWeakCharacters(vector<vector<int>>& v) {\n map<int,vector<int>> mp;\n int mx=0;\n for(auto &x:v)\n {\n int a=x[0];\n int b=x[1];\n mp[a].push_back(b);\n }\n int ans=0;\n mx=-1;\n ... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 0 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n int l = 0;\n for (int r = 0; r < word.size(); r++) {\n if (word[r] == ch) {\n while (l <= r) {\n swap(word[r], word[l]);\n l++;\n r-... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 0 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n auto wordOcc = word.find(ch);\n reverse(word.begin(), word.begin() + wordOcc + 1);\n return word;\n }\n};",
"memory": "7500"
} |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 0 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n int n = word.size();\n int i = 0;\n \n // Find the first occurrence of 'ch'\n while (i < n && word[i] != ch) {\n i++;\n }\n \n // If 'ch' is found, reverse the su... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 0 | {
"code": "class Solution {\npublic:\n void swapy(string &word,int l,int r)\n {\n while(l < r)\n {\n swap(word[l],word[r]);\n l++;\n r--;\n }\n }\n\n string reversePrefix(string word, char ch) \n {\n int ind = 0;\n for(int i=0;i<word.l... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 0 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n int index = 0;\n for(int i = 0 ; i<word.length() ;i++){\n if(word[i]==ch){\n index = i;\n break;\n }\n else{\n continue;\n }\n... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 0 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n int n=word.size();\n int id=0;\n for(int i=0;i<n;i++){\n if(word[i]==ch){\n id=i;\n break;\n }\n }\n reverse(word.begin(),word.begin()+id+1);\... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 1 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n auto it = std::find(word.begin(), word.end(), ch);\n\n if (it == word.end()) \n return word;\n\n int j = std::distance(word.begin(), it);\n\n int i = 0;\n while (i < j) {\n ... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 1 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n int l = 0;\n for(int r = 0; r < word.size(); r++) {\n if(word[r] == ch) {\n while(l <= r) {\n swap(word[r], word[l]);\n l++;\n r--;\... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 3 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n ios_base::sync_with_stdio(false);\n cin.tie(NULL);\n int k=0;\n int n=word.size();\n \n for(int i=0;i<=n-1;i++)\n {\n \n if(word[i]!=ch)\n {\n ... |
2,128 | <p>Given a <strong>0-indexed</strong> string <code>word</code> and a character <code>ch</code>, <strong>reverse</strong> the segment of <code>word</code> that starts at index <code>0</code> and ends at the index of the <strong>first occurrence</strong> of <code>ch</code> (<strong>inclusive</strong>). If the character <... | 3 | {
"code": "class Solution {\npublic:\n string reversePrefix(string word, char ch) {\n \n stack<char> st;\n \n for(int i=0;i<word.size();i++) {\n if(word[i]!=ch){\n st.push(word[i]);\n\n }\n else{\n \n break;\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "static const bool Booster = [](){\n std::ios_base::sync_with_stdio(false);\n std::cout.tie(nullptr);\n std::cin.tie(nullptr);\n return true;\n}();\n\ninline bool is_digit(const char c) {\n return (c >= '0') && (c <= '9');\n}\n\nstatic bool Solver = [](){\n std::ofstream out(\"user.out\");... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "static const bool Booster = [](){\n std::ios_base::sync_with_stdio(false);\n std::cout.tie(nullptr);\n std::cin.tie(nullptr);\n return true;\n}();\n\ninline bool is_digit(const char c) {\n return (c >= '0') && (c <= '9');\n}\n\nstatic bool Solver = [](){\n std::ofstream out(\"user.out\");... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "#pragma GCC optimize(\"O3,unroll-loops\")\n#pragma GCC target(\"avx2,bmi,bmi2,lzcnt,popcnt\")\nstatic const bool __boost = []() {\n\tcin.tie(nullptr);\n\tcout.tie(nullptr);\n\treturn std::ios_base::sync_with_stdio(false);\n\t}();\n\n\nconst size_t BUFFER_SIZE = 0x6fafffff;\nalignas(std::max_align_t) char b... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx2,tune=native\")\n\nbool init() {\n std::ios_base::sync_with_stdio(false);\n std::cout.tie(nullptr);\n return true;\n}\n\nclass Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum = 0;\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx2,tune=native\")\n\nbool init() {\n std::ios_base::sync_with_stdio(false);\n std::cout.tie(nullptr);\n return true;\n}\n\nclass Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int remainingSu... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum = 0;\n for (int x: rolls) {\n sum += x;\n }\n int remainingSum = mean * (n + rolls.size()) - sum;\n if (remainingSum < n || remainingSum > 6 * n) {\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "#pragma GCC optimize(\"Ofast\")\n#pragma GCC target(\"avx2,tune=native\")\n\nbool init() {\n std::ios_base::sync_with_stdio(false);\n std::cout.tie(nullptr);\n return true;\n}\n\nclass Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum = 0;\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls_m, const int mean, const int n) {\n // mean = sum(rolls_m + rolls_n) / (n + m)\n // mean = [ sum(rolls_m) + sum(rolls_n) ] / (n + m)\n // mean * (n + m) - sum(rolls_m) = sum(rolls_n)\n\n const int sum_rol... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls_m, const int mean, const int n) {\n // mean = sum(rolls_m + rolls_n) / (n + m)\n // mean = [ sum(rolls_m) + sum(rolls_n) ] / (n + m)\n // mean * (n + m) - sum(rolls_m) = sum(rolls_n)\n\n const int sum_rol... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "#define NO_SAN __attribute__((no_sanitize(\"undefined\", \"address\", \"coverage\", \"thread\")))\n#define INL __attribute__((always_inline))\n\nclass Solution {\npublic:\n static vector<int> missingRolls(vector<int>& rolls, const uint8_t mean, const uint n) NO_SAN {\n const uint m = rolls.size()... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "static const int _ = []() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.tie(nullptr);\n return 0;\n}();\n\nclass Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int tot = mean * (m + n);\n tot -= acc... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "#define NO_SAN __attribute__((no_sanitize(\"undefined\", \"address\", \"coverage\", \"thread\")))\n#define INL __attribute__((always_inline))\n\nclass Solution {\npublic:\n static vector<int> missingRolls(vector<int>& rolls, const uint8_t mean, const uint n) NO_SAN {\n const uint m = rolls.size()... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "static const int _ = []() {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n cout.tie(nullptr);\n return 0;\n}();\n\n// vector<int> res{};\n\nclass Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int tot = mean * (... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m=rolls.size();\n int totalSum=mean*(m+n);\n int sum=0;\n for(int i=0;i<m;i++){\n sum+=rolls[i];\n }\n int remSum=totalSum-sum;\n if(remSum<n || r... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int s = (n + m) * mean - accumulate(rolls.begin(), rolls.end(), 0);\n if (s > n * 6 || s < n) {\n return {};\n }\n vector<int> ans(n, s / n)... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "\n#include <span>\n#include <array>\n#include <vector>\nusing namespace std;\n\n/*\n The code will run faster with ios::sync_with_stdio(0).\n However, this should not be used in production code and interactive problems.\n In this particular problem, it is ok to apply ios::sync_with_stdio(0).\n\n Many of th... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum = accumulate(rolls.begin(),rolls.end(),0);\n int missing=(mean*(rolls.size()+n))-sum;\n if(missing>n*6 || missing<n) return {};\n auto [q,r]=div(missing,n);\n vector<i... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n)\n {\n int m = rolls.size();\n vector<int> out;\n int sum_m = 0;\n\n for(int i = 0; i < m; i++){\n sum_m += rolls[i];\n }\n\n int sum_n = mean * (m + n) - sum_... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int sum = 0;\n for(int r:rolls){\n sum += r;\n } \n\n int expectedSum = mean*(n+m);\n int missSum = expectedSum - sum;\n if(mi... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum=0;\n int i;\n int m=rolls.size();\n for(i=0;i<m;i++)sum+=rolls[i];\n int total=mean*(m+n);\n int miss=total-sum;\n if(miss<n || miss>6*n)return {};\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n const int m = rolls.size();\n const int totalSum = mean * (m + n);\n\n int remaining = totalSum - std::accumulate(rolls.begin(), rolls.end(), 0);\n if ( remaining > 6 * n || remainin... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum = 0;\n for (int i = 0; i < rolls.size(); i++) {\n sum = sum + rolls[i];\n }\n // Find the remaining sum.\n int remainingSum = mean * (n + rolls.size()) - su... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 0 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int rem = (mean*(m+n));\n for(auto it:rolls)\n {\n rem -= it;\n if(rem<0) return {};\n }\n if(rem > (n*6) || rem<(n)) retu... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 1 | {
"code": "int sum(std::vector<int>& array) {\n long long sum_of_numbers = 0; \n long long min = 0;\n\n for (auto& num : array) {\n sum_of_numbers += num; \n\n\n if (sum_of_numbers > INT_MAX)\n return INT_MAX; \n }\n\n return sum_of_numbers % 2147483647;\n}\n\n\nclass Solutio... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 1 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> res;\n int remain = (n+rolls.size())*mean;\n for(auto i:rolls)\n remain -= i;\n if(remain > 6*n || remain < n)\n return {};\n res.resize(n, r... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n Solution() {\n std::ios_base::sync_with_stdio(false);\n std::cin.tie(NULL);\n std::cout.tie(NULL);\n }\n\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) \n {\n const int MAX_missing_sum = n * 6;\n const int MIN_missi... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n ios::sync_with_stdio(false);\n cin.tie(nullptr);\n int sum = mean * (rolls.size() + n) - n;\n for (auto roll : rolls) {\n sum -= roll;\n }\n if (sum > n * 5 ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n Solution() {\n std::ios_base::sync_with_stdio(false);\n std::cin.tie(NULL);\n std::cout.tie(NULL);\n }\n\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) \n {\n const int MAX_missing_sum = n * 6;\n const int MIN_missi... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m_sum = accumulate(rolls.begin(), rolls.end(), 0);\n int n_sum = mean * (n + rolls.size()) - m_sum;\n if(n_sum < n) return {};\n vector<int> answer(n, 1);\n int curr_sum =... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum = std::accumulate(rolls.begin(),rolls.end(),0);\n int z = mean * (n + rolls.size()) - sum;\n if ((z+n-1)/n > 6 || z < n)\n return vector<int>();\n int remainder = ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int totalmean = mean * (n + m);\n for (auto g : rolls) {\n totalmean -= g;\n }\n if (6 * n < totalmean || totalmean < 0)\n return... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int sum = mean * (n + m);\n int msum = accumulate(rolls.begin(), rolls.end(), 0);\n int nsum = sum - msum;\n\n if (sum <= msum)\n return {};... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sumInp = std::accumulate(rolls.begin(), rolls.end(), 0);\n int S0 = mean * (rolls.size() + n) - sumInp;\n\n vector<int> res;\n res.reserve(n);\n if (S0 < n) {\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int s=0;\n for(int it:rolls) s+=it;\n int m=rolls.size();\n int sum=mean*(m+n)-s;\n\n if(sum>n*6 || sum<n) return {};\n if(sum/6==n && sum%6==0){\n vector<in... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int rem = (mean*(m+n));\n for(auto it:rolls)\n {\n rem -= it;\n if(rem<0) return {};\n }\n vector<int>ans(n);\n if(... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int sum_n = ((mean) * (n + m )) - (accumulate(rolls.begin(), rolls.end(), 0));\n if(sum_n <= 0) return {};\n vector<int> ans(n);\n int n_i = sum_n / n;... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum = accumulate(rolls.begin() , rolls.end() ,0);\n int total = (rolls.size()+n)*mean;\n int tohave = total - sum; \n int val = n*6;\n if(tohave > val || tohave<0){\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n){\n ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n int sum = accumulate(rolls.begin() , rolls.end() ,0);\n int total = (rolls.size()+n)*mean;\n int tohave = total - sum; \n int ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sumSoFar = std::reduce(rolls.begin(), rolls.end());\n int target = mean*(rolls.size()+n);\n int missing = target-sumSoFar;\n \n int curr = 6*n;\n if(curr < missing)... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n unordered_set<int> set(rolls.begin(), rolls.end());\n int sum = (n+rolls.size())*mean;\n for(int i:rolls){\n sum -= i;\n }\n if(sum > n * 6 || sum < n) return {};\n... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int currSum = accumulate(rolls.begin(), rolls.end(), 0);\n int totalSum = mean * (n + rolls.size());\n int remSum = totalSum - currSum;\n\n if(remSum > n*6) {\n return {};... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m=rolls.size();\n // vector<int>ans(n,1);\n vector<int>ans(n);\n int req_sum=(m+n)*mean;\n int given_sum=accumulate(rolls.begin(),rolls.end(),0);\n req_sum=req_sum-given_sum;\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> ans(n,1);\n int m=rolls.size();\n\n int left = (mean * (m+n));\n int sum=0;\n for(int i=0;i<rolls.size();i++){\n sum+=rolls[i];\n }\n\n if... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum=0,count=0;\n vector<int>ans(n);\n for(int i=0;i<rolls.size();i++) {\n sum+=rolls[i];\n }\n int or_sum=(rolls.size()+n)*mean;\n int diff=or_sum-sum;\n... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> result(n);\n int m = rolls.size();\n int sum = accumulate(rolls.begin(), rolls.end(), 0);\n\n int remSum = mean*(n + m) - sum;\n for (int& n_roll : result) {\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> result(n);\n int remSum = mean*(n + rolls.size()) - accumulate(rolls.begin(), rolls.end(), 0);\n \n for (int& n_roll : result) {\n int ithRoll = floor(remSum /... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& v, int mean, int n) {\n int totalelements=v.size()+n;\n vector<int>ans(n);\n int sum=0;\n int totalsum=mean*totalelements;\n for(int i=0;i<v.size();i++){\n sum+=v[i];\n }\n cout<... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> result(n);\n int m = rolls.size();\n int sum = accumulate(rolls.begin(), rolls.end(), 0);\n\n int remSum = mean*(n + m) - sum;\n for (int& n_roll : result) {\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m=rolls.size();\n int sm=0;\n for(int val: rolls) sm+=val;\n int sn = mean*(n+m) - sm;\n vector<int> ans(n);\n int avgVal=sn/n;\n // cout<<sn<<\" \"<<n<<\" \... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int msum = accumulate(rolls.begin(),rolls.end(),0);\n int m = rolls.size();\n int nsum = ((mean*(m+n)) - msum);\n vector<int> ans(n);\n int k = nsum/n;\n cout<<k<<\" \"... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> a(n);\n int sum = (n+rolls.size())*mean - accumulate(rolls.begin(),rolls.end(),0);\n int nm = sum/n, rem = sum%n;\n if((rem && nm>5) || nm>6 || nm<=0)return {};\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int totalLength=rolls.size()+n;\n int rem=totalLength*mean;\n for(auto it:rolls){\n rem-=it;\n }\n\n if(rem<0) return {};\n // cout<<rem;\n\n vector<i... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int>result(n);\n int totalsum=0;\n for(int i=0;i<rolls.size();i++){\n totalsum=totalsum+rolls[i];\n }\n int m=rolls.size();\n int len=n+m;\n in... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int>result(n);\n int totalsum=0;\n for(int i=0;i<rolls.size();i++){\n totalsum=totalsum+rolls[i];\n }\n int m=rolls.size();\n int len=n+m;\n in... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> ans (n , 0);\n int m = rolls.size();\n int sum1 = (mean*(m+n));\n for (int it : rolls ) sum1 -= it;\n\n // x = mean * (m+n) - sum1 \n if (sum1 < n || sum1... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> ans (n , 0);\n int m = rolls.size();\n int sum1 = (mean*(m+n));\n for (int it : rolls ) sum1 -= it;\n\n // x = mean * (m+n) - sum1 \n if (sum1 < n || sum1... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int>rs(n);\n int m = rolls.size();\n int sm_m = accumulate(rolls.begin(),rolls.end(),0);\n int sm_n = (mean*(m+n)) - sm_m;\n if(sm_n < 0) return {};\n if(sm_n ==... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m=rolls.size();\n int sum=0;\n for(auto x:rolls)sum+=x;\n int rem=(mean*(n+m))-sum;\n vector<int>ans(n,0);\n if(rem<n)return{};\n int per=rem/n;\n fo... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum=0;\n int m=rolls.size();\n // vector<int>ans;\n for(int i=0;i<rolls.size();i++){\n sum+=rolls[i];\n }\n int x=((mean)*(m+n))-sum;\n \n int p... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum=0;\n int m=rolls.size();\n // vector<int>ans;\n for(int i=0;i<rolls.size();i++){\n sum+=rolls[i];\n }\n int x=((mean)*(m+n))-sum;\n \n int p... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int sum = accumulate(rolls.begin(), rolls.end(), 0);\n int m = rolls.size();\n int target = mean * (m + n) - sum;\n if (target < n || target > 6 * n) return {};\n if (target %... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> ans={};\n int sum=0;\n for(int a:rolls){\n sum+=a;\n }\n if(sum+n*1 > mean*(rolls.size()+n) || sum+n*6 < mean*(rolls.size()+n)){\n return ans... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> ans={};\n int sum=0;\n for(int a:rolls){\n sum+=a;\n }\n if(sum+n*1 > mean*(rolls.size()+n) || sum+n*6 < mean*(rolls.size()+n)){\n return ans... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\n\n vector<int> makeSum(int sumLeft, int spotsLeft) {\n vector<int> res;\n\n if (sumLeft > spotsLeft * 6 || spotsLeft > sumLeft)\n return res; // return empty res if solution not possible\n\n while (spotsLeft > 0) {\n // fill all remaining spot... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> ans={};\n int sum=0;\n for(int a:rolls){\n sum+=a;\n }\n if(sum+n*1 > mean*(rolls.size()+n) || sum+n*6 < mean*(rolls.size()+n)){\n return ans... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int m = rolls.size();\n int total = (n + m) * mean;\n int nsum = total;\n for(int x: rolls)\n nsum -= x;\n \n if(nsum < n || nsum > 6*n)\n return ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int> ans={};\n int sum=0;\n for(int a:rolls){\n sum+=a;\n }\n if(sum+n*1 > mean*(rolls.size()+n) || sum+n*6 < mean*(rolls.size()+n)){\n return ans... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int all = mean * (rolls.size() + n);\n for (int i : rolls) all -= i;\n\n vector<int> ans;\n if (all < n || all > n * 6) return ans;\n all -= n;\n while (all) {\n ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n // vector<int>callmeanytime(vector<int>v,int n){\n // reverse(v.begin(),v.end());\n // vector<int>nums;\n // nums.push_back(6);\n // int number=v[0]-6;\n // for(int i=1;i<n;i++){\n // if( number>0 && nums[i-1]+number>6){\n // ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n // vector<int>callmeanytime(vector<int>v,int n){\n // reverse(v.begin(),v.end());\n // vector<int>nums;\n // nums.push_back(6);\n // int number=v[0]-6;\n // for(int i=1;i<n;i++){\n // if( number>0 && nums[i-1]+number>6){\n // ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n vector<int>ans;\n vector<int>res(n,1);\n int m = rolls.size();\n cout<<m<<endl;\n int total = m+n;\n int totalSum = total*mean;\n int mSum = 0;\n for(int ... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int> rolls, int mean, int n) {\n int sum = 0;\n int m = rolls.size();\n for(int& result : rolls){\n sum += result;\n }\n\n int missingSum = (m + n) * mean - sum;\n\n if(missingSum < n || miss... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int>& rolls, int mean, int n) {\n int a = accumulate(rolls.begin(), rolls.end(), 0);\n vector<int> ans(n, 1), ans2;\n int tot = mean * (rolls.size() + n);\n int rem = tot - a;\n cout<<rem<<endl<<n;\n if... |
2,155 | <p>You have observations of <code>n + m</code> <strong>6-sided</strong> dice rolls with each face numbered from <code>1</code> to <code>6</code>. <code>n</code> of the observations went missing, and you only have the observations of <code>m</code> rolls. Fortunately, you have also calculated the <strong>average value</... | 2 | {
"code": "class Solution {\npublic:\n vector<int> missingRolls(vector<int> rolls, int mean, int n) {\n int rollsSum = accumulate(rolls.begin(), rolls.end(), 0);\n int missingSum = mean * (rolls.size() + n) - rollsSum;\n if (missingSum < n || missingSum > 6 * n) {\n return {};\n }\n auto [quo, re... |
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