quiz stringlengths 282 811 | names listlengths 2 8 | knight_knave dict | solution listlengths 2 8 | solution_text stringlengths 37 171 | solution_text_format stringlengths 39 191 | cot_head stringclasses 1
value | cot_repeat_steps listlengths 2 123 | cot_foot stringclasses 1
value | statements stringlengths 58 390 | index int64 100 1.1k |
|---|---|---|---|---|---|---|---|---|---|---|
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Oliver, and Ethan. Oliver told you that Oliver is a knight or Ethan is a knave. In a statement by Ethan: "Oliver is a knight". So who is a knight and who is a knave? | [
"Oliver",
"Ethan"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Oliver is a knight, and Ethan is a knight. | (1) Oliver is a knight
(2) Ethan is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Oliver is a knight. No contradiction is found in their claim that Oliver is a knight or Ethan is a knave.",
"Assume Ethan is a knight. No contradiction is found in their claim that Oliver is a knight."
] | This leads to a feasible solution. | (('or', ('telling-truth', 0), ('lying', 1)), ('telling-truth', 0)) | 100 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Michael, and Jacob. Michael said, "Jacob is a knave." "Michael is a knave if and only if Michael is a knight," Jacob declared. So who is a knight and who is a knave? | [
"Michael",
"Jacob"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Michael is a knight, and Jacob is a knave. | (1) Michael is a knight
(2) Jacob is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Michael is a knight. No contradiction is found in their claim that Jacob is a knave.",
"Jacob cannot be a knight, because this would contradict the claim of Michael that Jacob is a knave.",
"Assume Jacob is a knave. No contradiction is found in their false claim that Michael is a knave if and only if Mi... | This leads to a feasible solution. | (('lying', 1), ('<=>', ('lying', 0), ('telling-truth', 0))) | 101 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Amelia, and Harper. Amelia was heard saying, "Harper is a knight or Harper is a knave". "Amelia is a knight and Amelia is a knave," Harper claimed. So who is a knight and who is a... | [
"Amelia",
"Harper"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Amelia is a knight, and Harper is a knave. | (1) Amelia is a knight
(2) Harper is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Amelia is a knight. No contradiction is found in their claim that Harper is a knight or Harper is a knave.",
"Harper cannot be a knight, because this would contradict the claim of their own that Amelia is a knight and Amelia is a knave.",
"Assume Harper is a knave. No contradiction is found in their fal... | This leads to a feasible solution. | (('or', ('telling-truth', 1), ('lying', 1)), ('and', ('telling-truth', 0), ('lying', 0))) | 102 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Logan, and Lily. Logan stated, "Lily is not a knave". Lily expressed that Logan is a knave and Lily is a knight. So who is a knight and who is a knave? | [
"Logan",
"Lily"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Logan is a knave, and Lily is a knave. | (1) Logan is a knave
(2) Lily is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Logan is a knight. No contradiction is found in their claim that Lily is not a knave.",
"Lily cannot be a knight, because this would contradict the claim of their own that Logan is a knave and Lily is a knight.",
"Lily cannot be a knave, because this would contradict the claim of Logan that Lily is not ... | This leads to a feasible solution. | (('not', ('lying', 1)), ('and', ('lying', 0), ('telling-truth', 1))) | 103 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Jack, and Evelyn. In Jack's words: "Evelyn is a knight or Evelyn is a knave". Evelyn asserted: "If Jack is a knave then Evelyn is a knight". So who is a knight and who is a knave? | [
"Jack",
"Evelyn"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Jack is a knight, and Evelyn is a knight. | (1) Jack is a knight
(2) Evelyn is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Jack is a knight. No contradiction is found in their claim that Evelyn is a knight or Evelyn is a knave.",
"Assume Evelyn is a knight. No contradiction is found in their claim that If Jack is a knave then Evelyn is a knight."
] | This leads to a feasible solution. | (('or', ('telling-truth', 1), ('lying', 1)), ('->', ('lying', 0), ('telling-truth', 1))) | 104 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Samuel, and Aria. In Samuel's words: "Aria is a knight if and only if Aria is a knave". Aria commented, "Samuel is a knave or Samuel is a knight". So who is a knight and who is a ... | [
"Samuel",
"Aria"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Samuel is a knave, and Aria is a knight. | (1) Samuel is a knave
(2) Aria is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Samuel cannot be a knight, because this would contradict the claim of their own that Aria is a knight if and only if Aria is a knave.",
"Assume Samuel is a knave. No contradiction is found in their false claim that Aria is a knight if and only if Aria is a knave.",
"Assume Aria is a knight. No contradiction is... | This leads to a feasible solution. | (('<=>', ('telling-truth', 1), ('lying', 1)), ('or', ('lying', 0), ('telling-truth', 0))) | 105 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Daniel, and Liam. In a statement by Daniel: "Liam is a knave if and only if Daniel is a knight". Liam said, "Daniel is a knight or Liam is a knight." So who is a knight and who is... | [
"Daniel",
"Liam"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Daniel is a knave, and Liam is a knave. | (1) Daniel is a knave
(2) Liam is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Daniel is a knight. No contradiction is found in their claim that Liam is a knave if and only if Daniel is a knight.",
"Liam cannot be a knight, because this would contradict the claim of Daniel that Liam is a knave if and only if Daniel is a knight.",
"Liam cannot be a knave, because this would contrad... | This leads to a feasible solution. | (('<=>', ('lying', 1), ('telling-truth', 0)), ('or', ('telling-truth', 0), ('telling-truth', 1))) | 106 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Ava, and Henry. Ava told you that Henry is a knight or Henry is a knave. "Ava is a knight if and only if Ava is a knave," Henry claimed. So who is a knight and who is a knave? | [
"Ava",
"Henry"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Ava is a knight, and Henry is a knave. | (1) Ava is a knight
(2) Henry is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Ava is a knight. No contradiction is found in their claim that Henry is a knight or Henry is a knave.",
"Henry cannot be a knight, because this would contradict the claim of their own that Ava is a knight if and only if Ava is a knave.",
"Assume Henry is a knave. No contradiction is found in their false... | This leads to a feasible solution. | (('or', ('telling-truth', 1), ('lying', 1)), ('<=>', ('telling-truth', 0), ('lying', 0))) | 107 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Penelope, and Alexander. Penelope asserted: "If Penelope is a knight then Alexander is a knight". According to Alexander, "Penelope is a knight". So who is a knight and who is a k... | [
"Penelope",
"Alexander"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Penelope is a knight, and Alexander is a knight. | (1) Penelope is a knight
(2) Alexander is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Penelope is a knight. No contradiction is found in their claim that If Penelope is a knight then Alexander is a knight.",
"Assume Alexander is a knight. No contradiction is found in their claim that Penelope is a knight."
] | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('telling-truth', 1)), ('telling-truth', 0)) | 108 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Riley, and Sophia. "Sophia is a knight if and only if Sophia is a knave" - Riley. Sophia remarked, "Riley is a knave or Sophia is a knight". So who is a knight and who is a knave? | [
"Riley",
"Sophia"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Riley is a knave, and Sophia is a knight. | (1) Riley is a knave
(2) Sophia is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Riley cannot be a knight, because this would contradict the claim of their own that Sophia is a knight if and only if Sophia is a knave.",
"Assume Riley is a knave. No contradiction is found in their false claim that Sophia is a knight if and only if Sophia is a knave.",
"Assume Sophia is a knight. No contradi... | This leads to a feasible solution. | (('<=>', ('telling-truth', 1), ('lying', 1)), ('or', ('lying', 0), ('telling-truth', 1))) | 109 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Liam, and Benjamin. Liam said that If Benjamin is a knave then Liam is a knight. "Liam is a knight or Liam is a knave," Benjamin declared. So who is a knight and who is a knave? | [
"Liam",
"Benjamin"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Liam is a knight, and Benjamin is a knight. | (1) Liam is a knight
(2) Benjamin is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Liam is a knight. No contradiction is found in their claim that If Benjamin is a knave then Liam is a knight.",
"Assume Benjamin is a knight. No contradiction is found in their claim that Liam is a knight or Liam is a knave."
] | This leads to a feasible solution. | (('->', ('lying', 1), ('telling-truth', 0)), ('or', ('telling-truth', 0), ('lying', 0))) | 110 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Scarlett, and Aria. "Aria is a knave and Aria is a knight," Scarlett mentioned. "Scarlett is a knight if and only if Scarlett is a knave" - Aria. So who is a knight and who is a k... | [
"Scarlett",
"Aria"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Scarlett is a knave, and Aria is a knave. | (1) Scarlett is a knave
(2) Aria is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Scarlett cannot be a knight, because this would contradict the claim of their own that Aria is a knave and Aria is a knight.",
"Assume Scarlett is a knave. No contradiction is found in their false claim that Aria is a knave and Aria is a knight.",
"Aria cannot be a knight, because this would contradict the cla... | This leads to a feasible solution. | (('and', ('lying', 1), ('telling-truth', 1)), ('<=>', ('telling-truth', 0), ('lying', 0))) | 111 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Harper, and Luke. Harper was heard saying, "Luke is a knight". "Harper is a knight if and only if Luke is a knight," Luke declared. So who is a knight and who is a knave? | [
"Harper",
"Luke"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Harper is a knight, and Luke is a knight. | (1) Harper is a knight
(2) Luke is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Harper is a knight. No contradiction is found in their claim that Luke is a knight.",
"Assume Luke is a knight. No contradiction is found in their claim that Harper is a knight if and only if Luke is a knight."
] | This leads to a feasible solution. | (('telling-truth', 1), ('<=>', ('telling-truth', 0), ('telling-truth', 1))) | 112 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Ava, and Charlotte. Ava expressed that Charlotte is a knave. Charlotte asserted: "Ava is a knight if and only if Charlotte is a knight". So who is a knight and who is a knave? | [
"Ava",
"Charlotte"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Ava is a knight, and Charlotte is a knave. | (1) Ava is a knight
(2) Charlotte is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Ava is a knight. No contradiction is found in their claim that Charlotte is a knave.",
"Charlotte cannot be a knight, because this would contradict the claim of Ava that Charlotte is a knave.",
"Assume Charlotte is a knave. No contradiction is found in their false claim that Ava is a knight if and only ... | This leads to a feasible solution. | (('lying', 1), ('<=>', ('telling-truth', 0), ('telling-truth', 1))) | 113 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Joseph, and Samuel. Joseph remarked, "Samuel is a knight and Samuel is a knave". Samuel expressed that Joseph is a knight if and only if Joseph is a knave. So who is a knight and ... | [
"Joseph",
"Samuel"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Joseph is a knave, and Samuel is a knave. | (1) Joseph is a knave
(2) Samuel is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Joseph cannot be a knight, because this would contradict the claim of their own that Samuel is a knight and Samuel is a knave.",
"Assume Joseph is a knave. No contradiction is found in their false claim that Samuel is a knight and Samuel is a knave.",
"Samuel cannot be a knight, because this would contradict t... | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('lying', 1)), ('<=>', ('telling-truth', 0), ('lying', 0))) | 114 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Sebastian, and Benjamin. "If Sebastian is a knight then Benjamin is a knave," Sebastian claimed. "Sebastian is a knight and Sebastian is a knave" - Benjamin. So who is a knight an... | [
"Sebastian",
"Benjamin"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Sebastian is a knight, and Benjamin is a knave. | (1) Sebastian is a knight
(2) Benjamin is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Sebastian is a knight. No contradiction is found in their claim that If Sebastian is a knight then Benjamin is a knave.",
"Benjamin cannot be a knight, because this would contradict the claim of Sebastian that If Sebastian is a knight then Benjamin is a knave.",
"Assume Benjamin is a knave. No contradic... | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('lying', 1)), ('and', ('telling-truth', 0), ('lying', 0))) | 115 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Amelia, and Jacob. Amelia said that Jacob is a knight and Jacob is a knave. Jacob commented, "If Amelia is a knave then Amelia is a knight". So who is a knight and who is a knave? | [
"Amelia",
"Jacob"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Amelia is a knave, and Jacob is a knave. | (1) Amelia is a knave
(2) Jacob is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Amelia cannot be a knight, because this would contradict the claim of their own that Jacob is a knight and Jacob is a knave.",
"Assume Amelia is a knave. No contradiction is found in their false claim that Jacob is a knight and Jacob is a knave.",
"Jacob cannot be a knight, because this would contradict the cl... | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('lying', 1)), ('->', ('lying', 0), ('telling-truth', 0))) | 116 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Abigail, and Harper. Abigail asserted: "If Abigail is a knight then Harper is a knight". According to Harper, "Abigail is a knight or Harper is a knight". So who is a knight and w... | [
"Abigail",
"Harper"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Abigail is a knight, and Harper is a knight. | (1) Abigail is a knight
(2) Harper is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Abigail is a knight. No contradiction is found in their claim that If Abigail is a knight then Harper is a knight.",
"Assume Harper is a knight. No contradiction is found in their claim that Abigail is a knight or Harper is a knight."
] | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('telling-truth', 1)), ('or', ('telling-truth', 0), ('telling-truth', 1))) | 117 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Scarlett, and Joseph. "Scarlett is a knight if and only if Joseph is a knave," Scarlett claimed. Joseph was heard saying, "If Scarlett is a knave then Joseph is a knight". So who ... | [
"Scarlett",
"Joseph"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Scarlett is a knave, and Joseph is a knave. | (1) Scarlett is a knave
(2) Joseph is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Scarlett is a knight. No contradiction is found in their claim that Scarlett is a knight if and only if Joseph is a knave.",
"Joseph cannot be a knight, because this would contradict the claim of Scarlett that Scarlett is a knight if and only if Joseph is a knave.",
"Joseph cannot be a knave, because th... | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('lying', 1)), ('->', ('lying', 0), ('telling-truth', 1))) | 118 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Daniel, and Riley. According to Daniel, "Riley is not a knight". "Daniel is a knight if and only if Riley is a knight," Riley declared. So who is a knight and who is a knave? | [
"Daniel",
"Riley"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Daniel is a knight, and Riley is a knave. | (1) Daniel is a knight
(2) Riley is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Daniel is a knight. No contradiction is found in their claim that Riley is not a knight.",
"Riley cannot be a knight, because this would contradict the claim of Daniel that Riley is not a knight.",
"Assume Riley is a knave. No contradiction is found in their false claim that Daniel is a knight if and on... | This leads to a feasible solution. | (('not', ('telling-truth', 1)), ('<=>', ('telling-truth', 0), ('telling-truth', 1))) | 119 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Elizabeth, and Oliver. "Oliver is not a knave," Elizabeth mentioned. Oliver remarked, "Oliver is a knight or Elizabeth is a knave". So who is a knight and who is a knave? | [
"Elizabeth",
"Oliver"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Elizabeth is a knight, and Oliver is a knight. | (1) Elizabeth is a knight
(2) Oliver is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Elizabeth is a knight. No contradiction is found in their claim that Oliver is not a knave.",
"Assume Oliver is a knight. No contradiction is found in their claim that Oliver is a knight or Elizabeth is a knave."
] | This leads to a feasible solution. | (('not', ('lying', 1)), ('or', ('telling-truth', 1), ('lying', 0))) | 120 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Daniel, and Abigail. According to Daniel, "Abigail is a knave and Abigail is a knight". Abigail noted, "Daniel is a knight or Daniel is a knave". So who is a knight and who is a k... | [
"Daniel",
"Abigail"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Daniel is a knave, and Abigail is a knight. | (1) Daniel is a knave
(2) Abigail is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Daniel cannot be a knight, because this would contradict the claim of their own that Abigail is a knave and Abigail is a knight.",
"Assume Daniel is a knave. No contradiction is found in their false claim that Abigail is a knave and Abigail is a knight.",
"Assume Abigail is a knight. No contradiction is found ... | This leads to a feasible solution. | (('and', ('lying', 1), ('telling-truth', 1)), ('or', ('telling-truth', 0), ('lying', 0))) | 121 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Sophia, and Logan. "Logan is a knight or Logan is a knave," Sophia declared. "Sophia is a knight or Sophia is a knave," Logan claimed. So who is a knight and who is a knave? | [
"Sophia",
"Logan"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Sophia is a knight, and Logan is a knight. | (1) Sophia is a knight
(2) Logan is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Sophia is a knight. No contradiction is found in their claim that Logan is a knight or Logan is a knave.",
"Assume Logan is a knight. No contradiction is found in their claim that Sophia is a knight or Sophia is a knave."
] | This leads to a feasible solution. | (('or', ('telling-truth', 1), ('lying', 1)), ('or', ('telling-truth', 0), ('lying', 0))) | 122 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Charlotte, and Alexander. Charlotte said, "If Alexander is a knight then Alexander is a knave." "Charlotte is a knight or Alexander is a knight," Alexander declared. So who is a k... | [
"Charlotte",
"Alexander"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Charlotte is a knave, and Alexander is a knight. | (1) Charlotte is a knave
(2) Alexander is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Charlotte is a knight. No contradiction is found in their claim that If Alexander is a knight then Alexander is a knave.",
"Alexander cannot be a knight, because this would contradict the claim of Charlotte that If Alexander is a knight then Alexander is a knave.",
"Alexander cannot be a knave, because ... | This leads to a feasible solution. | (('->', ('telling-truth', 1), ('lying', 1)), ('or', ('telling-truth', 0), ('telling-truth', 1))) | 123 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Charlotte, and Aiden. Charlotte told you that Aiden is a knave. Aiden stated, "Charlotte is a knave or Charlotte is a knight". So who is a knight and who is a knave? | [
"Charlotte",
"Aiden"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Charlotte is a knave, and Aiden is a knight. | (1) Charlotte is a knave
(2) Aiden is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Charlotte is a knight. No contradiction is found in their claim that Aiden is a knave.",
"Aiden cannot be a knight, because this would contradict the claim of Charlotte that Aiden is a knave.",
"Aiden cannot be a knave, because this would contradict the false claim of their own that Charlotte is a knave... | This leads to a feasible solution. | (('lying', 1), ('or', ('lying', 0), ('telling-truth', 0))) | 124 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Charlotte, and Scarlett. "Scarlett is a knight and Scarlett is a knave" - Charlotte. Scarlett stated, "Scarlett is a knight and Charlotte is a knight". So who is a knight and who ... | [
"Charlotte",
"Scarlett"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Charlotte is a knave, and Scarlett is a knave. | (1) Charlotte is a knave
(2) Scarlett is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Charlotte cannot be a knight, because this would contradict the claim of their own that Scarlett is a knight and Scarlett is a knave.",
"Assume Charlotte is a knave. No contradiction is found in their false claim that Scarlett is a knight and Scarlett is a knave.",
"Scarlett cannot be a knight, because this wo... | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('lying', 1)), ('and', ('telling-truth', 1), ('telling-truth', 0))) | 125 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Olivia, and Henry. Olivia asserted: "Henry is a knight or Henry is a knave". In Henry's words: "Olivia is a knave and Olivia is a knight". So who is a knight and who is a knave? | [
"Olivia",
"Henry"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Olivia is a knight, and Henry is a knave. | (1) Olivia is a knight
(2) Henry is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Olivia is a knight. No contradiction is found in their claim that Henry is a knight or Henry is a knave.",
"Henry cannot be a knight, because this would contradict the claim of their own that Olivia is a knave and Olivia is a knight.",
"Assume Henry is a knave. No contradiction is found in their false c... | This leads to a feasible solution. | (('or', ('telling-truth', 1), ('lying', 1)), ('and', ('lying', 0), ('telling-truth', 0))) | 126 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Daniel, and Lily. Daniel was heard saying, "If Lily is a knight then Lily is a knave". Lily was heard saying, "Lily is a knight or Daniel is a knight". So who is a knight and who ... | [
"Daniel",
"Lily"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Daniel is a knave, and Lily is a knight. | (1) Daniel is a knave
(2) Lily is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Daniel is a knight. No contradiction is found in their claim that If Lily is a knight then Lily is a knave.",
"Lily cannot be a knight, because this would contradict the claim of Daniel that If Lily is a knight then Lily is a knave.",
"Lily cannot be a knave, because this would contradict the false clai... | This leads to a feasible solution. | (('->', ('telling-truth', 1), ('lying', 1)), ('or', ('telling-truth', 1), ('telling-truth', 0))) | 127 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Jack, and Benjamin. Jack told you that Benjamin is a knight or Jack is a knight. Benjamin remarked, "If Jack is a knight then Jack is a knave". So who is a knight and who is a kna... | [
"Jack",
"Benjamin"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Jack is a knight, and Benjamin is a knave. | (1) Jack is a knight
(2) Benjamin is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Jack is a knight. No contradiction is found in their claim that Benjamin is a knight or Jack is a knight.",
"Benjamin cannot be a knight, because this would contradict the claim of their own that If Jack is a knight then Jack is a knave.",
"Assume Benjamin is a knave. No contradiction is found in their ... | This leads to a feasible solution. | (('or', ('telling-truth', 1), ('telling-truth', 0)), ('->', ('telling-truth', 0), ('lying', 0))) | 128 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Daniel, and Samuel. Daniel said, "Samuel is a knave or Samuel is a knight." Samuel said that Samuel is a knight or Daniel is a knight. So who is a knight and who is a knave? | [
"Daniel",
"Samuel"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Daniel is a knight, and Samuel is a knight. | (1) Daniel is a knight
(2) Samuel is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Daniel is a knight. No contradiction is found in their claim that Samuel is a knave or Samuel is a knight.",
"Assume Samuel is a knight. No contradiction is found in their claim that Samuel is a knight or Daniel is a knight."
] | This leads to a feasible solution. | (('or', ('lying', 1), ('telling-truth', 1)), ('or', ('telling-truth', 1), ('telling-truth', 0))) | 129 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Liam, and Aria. "Aria is not a knave" - Liam. Aria asserted: "Aria is a knight if and only if Liam is a knight". So who is a knight and who is a knave? | [
"Liam",
"Aria"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Liam is a knight, and Aria is a knight. | (1) Liam is a knight
(2) Aria is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Liam is a knight. No contradiction is found in their claim that Aria is not a knave.",
"Assume Aria is a knight. No contradiction is found in their claim that Aria is a knight if and only if Liam is a knight."
] | This leads to a feasible solution. | (('not', ('lying', 1)), ('<=>', ('telling-truth', 1), ('telling-truth', 0))) | 130 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: William, and Noah. William expressed that Noah is a knave or Noah is a knight. In a statement by Noah: "William is a knight if and only if William is a knave". So who is a knight ... | [
"William",
"Noah"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | William is a knight, and Noah is a knave. | (1) William is a knight
(2) Noah is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume William is a knight. No contradiction is found in their claim that Noah is a knave or Noah is a knight.",
"Noah cannot be a knight, because this would contradict the claim of their own that William is a knight if and only if William is a knave.",
"Assume Noah is a knave. No contradiction is found in the... | This leads to a feasible solution. | (('or', ('lying', 1), ('telling-truth', 1)), ('<=>', ('telling-truth', 0), ('lying', 0))) | 131 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Mia, and Aria. "Mia is a knight or Aria is a knight," Mia declared. Aria said, "If Mia is a knight then Mia is a knave." So who is a knight and who is a knave? | [
"Mia",
"Aria"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Mia is a knight, and Aria is a knave. | (1) Mia is a knight
(2) Aria is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Mia is a knight. No contradiction is found in their claim that Mia is a knight or Aria is a knight.",
"Aria cannot be a knight, because this would contradict the claim of their own that If Mia is a knight then Mia is a knave.",
"Assume Aria is a knave. No contradiction is found in their false claim that... | This leads to a feasible solution. | (('or', ('telling-truth', 0), ('telling-truth', 1)), ('->', ('telling-truth', 0), ('lying', 0))) | 132 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Aurora, and Charlotte. Aurora noted, "Charlotte is a knight if and only if Aurora is a knight". As Charlotte put it, "If Charlotte is a knight then Aurora is a knight". So who is ... | [
"Aurora",
"Charlotte"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Aurora is a knight, and Charlotte is a knight. | (1) Aurora is a knight
(2) Charlotte is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Aurora is a knight. No contradiction is found in their claim that Charlotte is a knight if and only if Aurora is a knight.",
"Assume Charlotte is a knight. No contradiction is found in their claim that If Charlotte is a knight then Aurora is a knight."
] | This leads to a feasible solution. | (('<=>', ('telling-truth', 1), ('telling-truth', 0)), ('->', ('telling-truth', 1), ('telling-truth', 0))) | 133 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Chloe, and Jacob. Chloe stated, "Jacob is a knight and Jacob is a knave". Jacob asserted: "Chloe is a knave". So who is a knight and who is a knave? | [
"Chloe",
"Jacob"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Chloe is a knave, and Jacob is a knight. | (1) Chloe is a knave
(2) Jacob is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Chloe cannot be a knight, because this would contradict the claim of their own that Jacob is a knight and Jacob is a knave.",
"Assume Chloe is a knave. No contradiction is found in their false claim that Jacob is a knight and Jacob is a knave.",
"Assume Jacob is a knight. No contradiction is found in their cla... | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('lying', 1)), ('lying', 0)) | 134 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Liam, and Logan. Liam was heard saying, "Liam is a knight if and only if Logan is a knave". Logan said, "Liam is not a knave." So who is a knight and who is a knave? | [
"Liam",
"Logan"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Liam is a knave, and Logan is a knave. | (1) Liam is a knave
(2) Logan is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Liam is a knight. No contradiction is found in their claim that Liam is a knight if and only if Logan is a knave.",
"Logan cannot be a knight, because this would contradict the claim of Liam that Liam is a knight if and only if Logan is a knave.",
"Logan cannot be a knave, because this would contradict ... | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('lying', 1)), ('not', ('lying', 0))) | 135 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Samuel, and Isabella. "Isabella is a knight" - Samuel. Isabella said that Samuel is a knave and Isabella is a knight. So who is a knight and who is a knave? | [
"Samuel",
"Isabella"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Samuel is a knave, and Isabella is a knave. | (1) Samuel is a knave
(2) Isabella is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Samuel is a knight. No contradiction is found in their claim that Isabella is a knight.",
"Isabella cannot be a knight, because this would contradict the claim of their own that Samuel is a knave and Isabella is a knight.",
"Isabella cannot be a knave, because this would contradict the claim of Samuel t... | This leads to a feasible solution. | (('telling-truth', 1), ('and', ('lying', 0), ('telling-truth', 1))) | 136 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Benjamin, and Lily. In Benjamin's words: "If Lily is a knave then Lily is a knight". "Benjamin is a knave and Benjamin is a knight," Lily declared. So who is a knight and who is a... | [
"Benjamin",
"Lily"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Benjamin is a knave, and Lily is a knave. | (1) Benjamin is a knave
(2) Lily is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Benjamin is a knight. No contradiction is found in their claim that If Lily is a knave then Lily is a knight.",
"Lily cannot be a knight, because this would contradict the claim of their own that Benjamin is a knave and Benjamin is a knight.",
"Lily cannot be a knave, because this would contradict the c... | This leads to a feasible solution. | (('->', ('lying', 1), ('telling-truth', 1)), ('and', ('lying', 0), ('telling-truth', 0))) | 137 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Mason, and Zoey. Mason noted, "Zoey is a knight and Zoey is a knave". Zoey asserted: "Mason is a knight". So who is a knight and who is a knave? | [
"Mason",
"Zoey"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Mason is a knave, and Zoey is a knave. | (1) Mason is a knave
(2) Zoey is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Mason cannot be a knight, because this would contradict the claim of their own that Zoey is a knight and Zoey is a knave.",
"Assume Mason is a knave. No contradiction is found in their false claim that Zoey is a knight and Zoey is a knave.",
"Zoey cannot be a knight, because this would contradict the claim of ... | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('lying', 1)), ('telling-truth', 0)) | 138 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Sophia, and Charlotte. Sophia commented, "If Sophia is a knight then Charlotte is a knave". "Sophia is a knave and Sophia is a knight" - Charlotte. So who is a knight and who is a... | [
"Sophia",
"Charlotte"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Sophia is a knight, and Charlotte is a knave. | (1) Sophia is a knight
(2) Charlotte is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Sophia is a knight. No contradiction is found in their claim that If Sophia is a knight then Charlotte is a knave.",
"Charlotte cannot be a knight, because this would contradict the claim of Sophia that If Sophia is a knight then Charlotte is a knave.",
"Assume Charlotte is a knave. No contradiction is ... | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('lying', 1)), ('and', ('lying', 0), ('telling-truth', 0))) | 139 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: William, and David. As William put it, "David is a knave and David is a knight". David remarked, "If William is a knight then David is a knight". So who is a knight and who is a k... | [
"William",
"David"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | William is a knave, and David is a knight. | (1) William is a knave
(2) David is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"William cannot be a knight, because this would contradict the claim of their own that David is a knave and David is a knight.",
"Assume William is a knave. No contradiction is found in their false claim that David is a knave and David is a knight.",
"Assume David is a knight. No contradiction is found in their... | This leads to a feasible solution. | (('and', ('lying', 1), ('telling-truth', 1)), ('->', ('telling-truth', 0), ('telling-truth', 1))) | 140 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Sophia, and Noah. "If Sophia is a knight then Noah is a knave" - Sophia. Noah noted, "If Sophia is a knight then Noah is a knight". So who is a knight and who is a knave? | [
"Sophia",
"Noah"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Sophia is a knight, and Noah is a knave. | (1) Sophia is a knight
(2) Noah is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Sophia is a knight. No contradiction is found in their claim that If Sophia is a knight then Noah is a knave.",
"Noah cannot be a knight, because this would contradict the claim of Sophia that If Sophia is a knight then Noah is a knave.",
"Assume Noah is a knave. No contradiction is found in their false... | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('lying', 1)), ('->', ('telling-truth', 0), ('telling-truth', 1))) | 141 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Charlotte, and Evelyn. Charlotte noted, "If Charlotte is a knight then Evelyn is a knight". Evelyn noted, "Evelyn is a knight if and only if Charlotte is a knight". So who is a kn... | [
"Charlotte",
"Evelyn"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Charlotte is a knight, and Evelyn is a knight. | (1) Charlotte is a knight
(2) Evelyn is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Charlotte is a knight. No contradiction is found in their claim that If Charlotte is a knight then Evelyn is a knight.",
"Assume Evelyn is a knight. No contradiction is found in their claim that Evelyn is a knight if and only if Charlotte is a knight."
] | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('telling-truth', 1)), ('<=>', ('telling-truth', 1), ('telling-truth', 0))) | 142 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Daniel, and Jack. Daniel expressed that If Daniel is a knight then Jack is a knight. "Jack is a knight," Jack mentioned. So who is a knight and who is a knave? | [
"Daniel",
"Jack"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Daniel is a knight, and Jack is a knight. | (1) Daniel is a knight
(2) Jack is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Daniel is a knight. No contradiction is found in their claim that If Daniel is a knight then Jack is a knight.",
"Assume Jack is a knight. No contradiction is found in their claim that Jack is a knight."
] | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('telling-truth', 1)), ('telling-truth', 1)) | 143 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Evelyn, and Harper. "Harper is not a knight," Evelyn mentioned. In Harper's words: "Evelyn is a knave if and only if Evelyn is a knight". So who is a knight and who is a knave? | [
"Evelyn",
"Harper"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Evelyn is a knight, and Harper is a knave. | (1) Evelyn is a knight
(2) Harper is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Evelyn is a knight. No contradiction is found in their claim that Harper is not a knight.",
"Harper cannot be a knight, because this would contradict the claim of Evelyn that Harper is not a knight.",
"Assume Harper is a knave. No contradiction is found in their false claim that Evelyn is a knave if and... | This leads to a feasible solution. | (('not', ('telling-truth', 1)), ('<=>', ('lying', 0), ('telling-truth', 0))) | 144 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Avery, and Michael. "Avery is a knight if and only if Michael is a knave," Avery mentioned. "Avery is not a knight," Michael declared. So who is a knight and who is a knave? | [
"Avery",
"Michael"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Avery is a knight, and Michael is a knave. | (1) Avery is a knight
(2) Michael is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Avery is a knight. No contradiction is found in their claim that Avery is a knight if and only if Michael is a knave.",
"Michael cannot be a knight, because this would contradict the claim of Avery that Avery is a knight if and only if Michael is a knave.",
"Assume Michael is a knave. No contradiction i... | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('lying', 1)), ('not', ('telling-truth', 0))) | 145 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Elizabeth, and Aurora. According to Elizabeth, "Elizabeth is a knight if and only if Aurora is a knight". Aurora remarked, "Elizabeth is a knight". So who is a knight and who is a... | [
"Elizabeth",
"Aurora"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Elizabeth is a knight, and Aurora is a knight. | (1) Elizabeth is a knight
(2) Aurora is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Elizabeth is a knight. No contradiction is found in their claim that Elizabeth is a knight if and only if Aurora is a knight.",
"Assume Aurora is a knight. No contradiction is found in their claim that Elizabeth is a knight."
] | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('telling-truth', 1)), ('telling-truth', 0)) | 146 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Riley, and Benjamin. As Riley put it, "Riley is a knight or Benjamin is a knave". Benjamin asserted: "Riley is a knave if and only if Benjamin is a knight". So who is a knight and... | [
"Riley",
"Benjamin"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Riley is a knave, and Benjamin is a knight. | (1) Riley is a knave
(2) Benjamin is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Riley is a knight. No contradiction is found in their claim that Riley is a knight or Benjamin is a knave.",
"Benjamin cannot be a knight, because this would contradict the claim of their own that Riley is a knave if and only if Benjamin is a knight.",
"Benjamin cannot be a knave, because this would con... | This leads to a feasible solution. | (('or', ('telling-truth', 0), ('lying', 1)), ('<=>', ('lying', 0), ('telling-truth', 1))) | 147 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Penelope, and Oliver. Penelope said that Oliver is a knave if and only if Penelope is a knight. Oliver expressed that If Penelope is a knave then Penelope is a knight. So who is a... | [
"Penelope",
"Oliver"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Penelope is a knave, and Oliver is a knave. | (1) Penelope is a knave
(2) Oliver is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Penelope is a knight. No contradiction is found in their claim that Oliver is a knave if and only if Penelope is a knight.",
"Oliver cannot be a knight, because this would contradict the claim of Penelope that Oliver is a knave if and only if Penelope is a knight.",
"Oliver cannot be a knave, because th... | This leads to a feasible solution. | (('<=>', ('lying', 1), ('telling-truth', 0)), ('->', ('lying', 0), ('telling-truth', 0))) | 148 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Chloe, and James. As Chloe put it, "James is a knave". According to James, "Chloe is a knave if and only if James is a knight". So who is a knight and who is a knave? | [
"Chloe",
"James"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Chloe is a knave, and James is a knight. | (1) Chloe is a knave
(2) James is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Chloe is a knight. No contradiction is found in their claim that James is a knave.",
"James cannot be a knight, because this would contradict the claim of Chloe that James is a knave.",
"James cannot be a knave, because this would contradict the false claim of their own that Chloe is a knave if and only... | This leads to a feasible solution. | (('lying', 1), ('<=>', ('lying', 0), ('telling-truth', 1))) | 149 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Henry, and David. "David is a knave and David is a knight," Henry mentioned. In a statement by David: "Henry is a knave". So who is a knight and who is a knave? | [
"Henry",
"David"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Henry is a knave, and David is a knight. | (1) Henry is a knave
(2) David is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Henry cannot be a knight, because this would contradict the claim of their own that David is a knave and David is a knight.",
"Assume Henry is a knave. No contradiction is found in their false claim that David is a knave and David is a knight.",
"Assume David is a knight. No contradiction is found in their cla... | This leads to a feasible solution. | (('and', ('lying', 1), ('telling-truth', 1)), ('lying', 0)) | 150 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Evelyn, and Elizabeth. Evelyn told you that Evelyn is a knight if and only if Elizabeth is a knave. "Evelyn is a knight" - Elizabeth. So who is a knight and who is a knave? | [
"Evelyn",
"Elizabeth"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Evelyn is a knave, and Elizabeth is a knave. | (1) Evelyn is a knave
(2) Elizabeth is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Evelyn is a knight. No contradiction is found in their claim that Evelyn is a knight if and only if Elizabeth is a knave.",
"Elizabeth cannot be a knight, because this would contradict the claim of Evelyn that Evelyn is a knight if and only if Elizabeth is a knave.",
"Elizabeth cannot be a knave, becaus... | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('lying', 1)), ('telling-truth', 0)) | 151 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Jackson, and Elizabeth. As Jackson put it, "Elizabeth is a knave and Jackson is a knight". "If Jackson is a knave then Jackson is a knight," Elizabeth declared. So who is a knight... | [
"Jackson",
"Elizabeth"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Jackson is a knave, and Elizabeth is a knave. | (1) Jackson is a knave
(2) Elizabeth is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Jackson is a knight. No contradiction is found in their claim that Elizabeth is a knave and Jackson is a knight.",
"Elizabeth cannot be a knight, because this would contradict the claim of Jackson that Elizabeth is a knave and Jackson is a knight.",
"Elizabeth cannot be a knave, because this would contr... | This leads to a feasible solution. | (('and', ('lying', 1), ('telling-truth', 0)), ('->', ('lying', 0), ('telling-truth', 0))) | 152 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Aiden, and Emma. Aiden stated, "Aiden is a knight and Emma is a knight". "If Emma is a knight then Aiden is a knight" - Emma. So who is a knight and who is a knave? | [
"Aiden",
"Emma"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Aiden is a knight, and Emma is a knight. | (1) Aiden is a knight
(2) Emma is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Aiden is a knight. No contradiction is found in their claim that Aiden is a knight and Emma is a knight.",
"Assume Emma is a knight. No contradiction is found in their claim that If Emma is a knight then Aiden is a knight."
] | This leads to a feasible solution. | (('and', ('telling-truth', 0), ('telling-truth', 1)), ('->', ('telling-truth', 1), ('telling-truth', 0))) | 153 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Sebastian, and Ava. In a statement by Sebastian: "Ava is a knight". "If Sebastian is a knight then Ava is a knight," Ava declared. So who is a knight and who is a knave? | [
"Sebastian",
"Ava"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Sebastian is a knight, and Ava is a knight. | (1) Sebastian is a knight
(2) Ava is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Sebastian is a knight. No contradiction is found in their claim that Ava is a knight.",
"Assume Ava is a knight. No contradiction is found in their claim that If Sebastian is a knight then Ava is a knight."
] | This leads to a feasible solution. | (('telling-truth', 1), ('->', ('telling-truth', 0), ('telling-truth', 1))) | 154 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: James, and Oliver. James asserted: "If Oliver is a knave then Oliver is a knight". Oliver told you that James is a knight or James is a knave. So who is a knight and who is a knav... | [
"James",
"Oliver"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | James is a knight, and Oliver is a knight. | (1) James is a knight
(2) Oliver is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume James is a knight. No contradiction is found in their claim that If Oliver is a knave then Oliver is a knight.",
"Assume Oliver is a knight. No contradiction is found in their claim that James is a knight or James is a knave."
] | This leads to a feasible solution. | (('->', ('lying', 1), ('telling-truth', 1)), ('or', ('telling-truth', 0), ('lying', 0))) | 155 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Riley, and Matthew. "Matthew is a knave or Matthew is a knight," Riley claimed. Matthew remarked, "If Riley is a knave then Matthew is a knight". So who is a knight and who is a k... | [
"Riley",
"Matthew"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Riley is a knight, and Matthew is a knight. | (1) Riley is a knight
(2) Matthew is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Riley is a knight. No contradiction is found in their claim that Matthew is a knave or Matthew is a knight.",
"Assume Matthew is a knight. No contradiction is found in their claim that If Riley is a knave then Matthew is a knight."
] | This leads to a feasible solution. | (('or', ('lying', 1), ('telling-truth', 1)), ('->', ('lying', 0), ('telling-truth', 1))) | 156 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Jackson, and Michael. Jackson said, "If Jackson is a knight then Michael is a knave." Michael noted, "Jackson is not a knight". So who is a knight and who is a knave? | [
"Jackson",
"Michael"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Jackson is a knight, and Michael is a knave. | (1) Jackson is a knight
(2) Michael is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Jackson is a knight. No contradiction is found in their claim that If Jackson is a knight then Michael is a knave.",
"Michael cannot be a knight, because this would contradict the claim of Jackson that If Jackson is a knight then Michael is a knave.",
"Assume Michael is a knave. No contradiction is foun... | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('lying', 1)), ('not', ('telling-truth', 0))) | 157 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Penelope, and Alexander. Penelope said, "Alexander is a knight." "Penelope is a knave if and only if Penelope is a knight," Alexander declared. So who is a knight and who is a kna... | [
"Penelope",
"Alexander"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Penelope is a knave, and Alexander is a knave. | (1) Penelope is a knave
(2) Alexander is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Penelope is a knight. No contradiction is found in their claim that Alexander is a knight.",
"Alexander cannot be a knight, because this would contradict the claim of their own that Penelope is a knave if and only if Penelope is a knight.",
"Alexander cannot be a knave, because this would contradict the... | This leads to a feasible solution. | (('telling-truth', 1), ('<=>', ('lying', 0), ('telling-truth', 0))) | 158 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Aria, and Noah. "Noah is not a knight," Aria mentioned. "Aria is a knave if and only if Noah is a knight," Noah declared. So who is a knight and who is a knave? | [
"Aria",
"Noah"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Aria is a knave, and Noah is a knight. | (1) Aria is a knave
(2) Noah is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Aria is a knight. No contradiction is found in their claim that Noah is not a knight.",
"Noah cannot be a knight, because this would contradict the claim of Aria that Noah is not a knight.",
"Noah cannot be a knave, because this would contradict the false claim of their own that Aria is a knave if and o... | This leads to a feasible solution. | (('not', ('telling-truth', 1)), ('<=>', ('lying', 0), ('telling-truth', 1))) | 159 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Noah, and Jackson. Noah stated, "Jackson is a knave if and only if Noah is a knight". Jackson told you that If Noah is a knight then Noah is a knave. So who is a knight and who is... | [
"Noah",
"Jackson"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Noah is a knight, and Jackson is a knave. | (1) Noah is a knight
(2) Jackson is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Noah is a knight. No contradiction is found in their claim that Jackson is a knave if and only if Noah is a knight.",
"Jackson cannot be a knight, because this would contradict the claim of Noah that Jackson is a knave if and only if Noah is a knight.",
"Assume Jackson is a knave. No contradiction is fo... | This leads to a feasible solution. | (('<=>', ('lying', 1), ('telling-truth', 0)), ('->', ('telling-truth', 0), ('lying', 0))) | 160 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Ava, and Ethan. Ava asserted: "Ava is a knight if and only if Ethan is a knave". Ethan said, "Ethan is a knight or Ava is a knave." So who is a knight and who is a knave? | [
"Ava",
"Ethan"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Ava is a knight, and Ethan is a knave. | (1) Ava is a knight
(2) Ethan is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Ava is a knight. No contradiction is found in their claim that Ava is a knight if and only if Ethan is a knave.",
"Ethan cannot be a knight, because this would contradict the claim of Ava that Ava is a knight if and only if Ethan is a knave.",
"Assume Ethan is a knave. No contradiction is found in their... | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('lying', 1)), ('or', ('telling-truth', 1), ('lying', 0))) | 161 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Abigail, and Victoria. Abigail noted, "If Victoria is a knave then Victoria is a knight". In a statement by Victoria: "Victoria is a knight and Abigail is a knave". So who is a kn... | [
"Abigail",
"Victoria"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Abigail is a knave, and Victoria is a knave. | (1) Abigail is a knave
(2) Victoria is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Abigail is a knight. No contradiction is found in their claim that If Victoria is a knave then Victoria is a knight.",
"Victoria cannot be a knight, because this would contradict the claim of their own that Victoria is a knight and Abigail is a knave.",
"Victoria cannot be a knave, because this would co... | This leads to a feasible solution. | (('->', ('lying', 1), ('telling-truth', 1)), ('and', ('telling-truth', 1), ('lying', 0))) | 162 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Joseph, and Jackson. "If Jackson is a knight then Joseph is a knight" - Joseph. "If Jackson is a knight then Joseph is a knight," Jackson claimed. So who is a knight and who is a ... | [
"Joseph",
"Jackson"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Joseph is a knight, and Jackson is a knight. | (1) Joseph is a knight
(2) Jackson is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Joseph is a knight. No contradiction is found in their claim that If Jackson is a knight then Joseph is a knight.",
"Assume Jackson is a knight. No contradiction is found in their claim that If Jackson is a knight then Joseph is a knight."
] | This leads to a feasible solution. | (('->', ('telling-truth', 1), ('telling-truth', 0)), ('->', ('telling-truth', 1), ('telling-truth', 0))) | 163 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Noah, and Charlotte. Noah told you that Charlotte is a knight and Noah is a knight. Charlotte was heard saying, "Charlotte is a knight if and only if Noah is a knight". So who is ... | [
"Noah",
"Charlotte"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Noah is a knight, and Charlotte is a knight. | (1) Noah is a knight
(2) Charlotte is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Noah is a knight. No contradiction is found in their claim that Charlotte is a knight and Noah is a knight.",
"Assume Charlotte is a knight. No contradiction is found in their claim that Charlotte is a knight if and only if Noah is a knight."
] | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('telling-truth', 0)), ('<=>', ('telling-truth', 1), ('telling-truth', 0))) | 164 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Avery, and Chloe. Avery said that Chloe is a knight and Chloe is a knave. "Avery is not a knight," Chloe mentioned. So who is a knight and who is a knave? | [
"Avery",
"Chloe"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Avery is a knave, and Chloe is a knight. | (1) Avery is a knave
(2) Chloe is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Avery cannot be a knight, because this would contradict the claim of their own that Chloe is a knight and Chloe is a knave.",
"Assume Avery is a knave. No contradiction is found in their false claim that Chloe is a knight and Chloe is a knave.",
"Assume Chloe is a knight. No contradiction is found in their cla... | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('lying', 1)), ('not', ('telling-truth', 0))) | 165 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Evelyn, and Ava. "If Evelyn is a knight then Ava is a knight," Evelyn claimed. Ava told you that Ava is a knight or Evelyn is a knight. So who is a knight and who is a knave? | [
"Evelyn",
"Ava"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Evelyn is a knight, and Ava is a knight. | (1) Evelyn is a knight
(2) Ava is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Evelyn is a knight. No contradiction is found in their claim that If Evelyn is a knight then Ava is a knight.",
"Assume Ava is a knight. No contradiction is found in their claim that Ava is a knight or Evelyn is a knight."
] | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('telling-truth', 1)), ('or', ('telling-truth', 1), ('telling-truth', 0))) | 166 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Matthew, and Victoria. In Matthew's words: "Victoria is not a knight". In Victoria's words: "Victoria is a knight and Matthew is a knight". So who is a knight and who is a knave? | [
"Matthew",
"Victoria"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Matthew is a knight, and Victoria is a knave. | (1) Matthew is a knight
(2) Victoria is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Matthew is a knight. No contradiction is found in their claim that Victoria is not a knight.",
"Victoria cannot be a knight, because this would contradict the claim of Matthew that Victoria is not a knight.",
"Assume Victoria is a knave. No contradiction is found in their false claim that Victoria is a ... | This leads to a feasible solution. | (('not', ('telling-truth', 1)), ('and', ('telling-truth', 1), ('telling-truth', 0))) | 167 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Daniel, and William. "William is a knight or Daniel is a knight," Daniel declared. William expressed that Daniel is a knight or Daniel is a knave. So who is a knight and who is a ... | [
"Daniel",
"William"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Daniel is a knight, and William is a knight. | (1) Daniel is a knight
(2) William is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Daniel is a knight. No contradiction is found in their claim that William is a knight or Daniel is a knight.",
"Assume William is a knight. No contradiction is found in their claim that Daniel is a knight or Daniel is a knave."
] | This leads to a feasible solution. | (('or', ('telling-truth', 1), ('telling-truth', 0)), ('or', ('telling-truth', 0), ('lying', 0))) | 168 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Luke, and Alexander. Luke said, "If Luke is a knight then Alexander is a knave." Alexander said, "Alexander is a knight and Luke is a knight." So who is a knight and who is a knav... | [
"Luke",
"Alexander"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Luke is a knight, and Alexander is a knave. | (1) Luke is a knight
(2) Alexander is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Luke is a knight. No contradiction is found in their claim that If Luke is a knight then Alexander is a knave.",
"Alexander cannot be a knight, because this would contradict the claim of Luke that If Luke is a knight then Alexander is a knave.",
"Assume Alexander is a knave. No contradiction is found in... | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('lying', 1)), ('and', ('telling-truth', 1), ('telling-truth', 0))) | 169 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Mia, and Samuel. Mia expressed that Mia is a knight and Samuel is a knight. Samuel expressed that Mia is a knight and Mia is a knave. So who is a knight and who is a knave? | [
"Mia",
"Samuel"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Mia is a knave, and Samuel is a knave. | (1) Mia is a knave
(2) Samuel is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Mia is a knight. No contradiction is found in their claim that Mia is a knight and Samuel is a knight.",
"Samuel cannot be a knight, because this would contradict the claim of their own that Mia is a knight and Mia is a knave.",
"Samuel cannot be a knave, because this would contradict the claim of Mia t... | This leads to a feasible solution. | (('and', ('telling-truth', 0), ('telling-truth', 1)), ('and', ('telling-truth', 0), ('lying', 0))) | 170 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Liam, and Henry. According to Liam, "Liam is a knight if and only if Henry is a knight". Henry said, "Liam is not a knave." So who is a knight and who is a knave? | [
"Liam",
"Henry"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Liam is a knight, and Henry is a knight. | (1) Liam is a knight
(2) Henry is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Liam is a knight. No contradiction is found in their claim that Liam is a knight if and only if Henry is a knight.",
"Assume Henry is a knight. No contradiction is found in their claim that Liam is not a knave."
] | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('telling-truth', 1)), ('not', ('lying', 0))) | 171 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Olivia, and Joseph. "If Joseph is a knight then Olivia is a knight" - Olivia. Joseph commented, "Olivia is a knave if and only if Olivia is a knight". So who is a knight and who i... | [
"Olivia",
"Joseph"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Olivia is a knight, and Joseph is a knave. | (1) Olivia is a knight
(2) Joseph is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Olivia is a knight. No contradiction is found in their claim that If Joseph is a knight then Olivia is a knight.",
"Joseph cannot be a knight, because this would contradict the claim of their own that Olivia is a knave if and only if Olivia is a knight.",
"Assume Joseph is a knave. No contradiction is f... | This leads to a feasible solution. | (('->', ('telling-truth', 1), ('telling-truth', 0)), ('<=>', ('lying', 0), ('telling-truth', 0))) | 172 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Jack, and Jackson. "Jack is a knight and Jackson is a knave," Jack claimed. Jackson told you that Jack is not a knave. So who is a knight and who is a knave? | [
"Jack",
"Jackson"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Jack is a knave, and Jackson is a knave. | (1) Jack is a knave
(2) Jackson is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Jack is a knight. No contradiction is found in their claim that Jack is a knight and Jackson is a knave.",
"Jackson cannot be a knight, because this would contradict the claim of Jack that Jack is a knight and Jackson is a knave.",
"Jackson cannot be a knave, because this would contradict the false clai... | This leads to a feasible solution. | (('and', ('telling-truth', 0), ('lying', 1)), ('not', ('lying', 0))) | 173 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Evelyn, and Ethan. In a statement by Evelyn: "Evelyn is a knight if and only if Ethan is a knave". As Ethan put it, "Ethan is a knight if and only if Evelyn is a knave". So who is... | [
"Evelyn",
"Ethan"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Evelyn is a knave, and Ethan is a knave. | (1) Evelyn is a knave
(2) Ethan is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Evelyn is a knight. No contradiction is found in their claim that Evelyn is a knight if and only if Ethan is a knave.",
"Ethan cannot be a knight, because this would contradict the claim of Evelyn that Evelyn is a knight if and only if Ethan is a knave.",
"Ethan cannot be a knave, because this would con... | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('lying', 1)), ('<=>', ('telling-truth', 1), ('lying', 0))) | 174 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Avery, and Aurora. Avery commented, "If Aurora is a knight then Avery is a knight". According to Aurora, "Avery is a knight and Avery is a knave". So who is a knight and who is a ... | [
"Avery",
"Aurora"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Avery is a knight, and Aurora is a knave. | (1) Avery is a knight
(2) Aurora is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Avery is a knight. No contradiction is found in their claim that If Aurora is a knight then Avery is a knight.",
"Aurora cannot be a knight, because this would contradict the claim of their own that Avery is a knight and Avery is a knave.",
"Assume Aurora is a knave. No contradiction is found in their f... | This leads to a feasible solution. | (('->', ('telling-truth', 1), ('telling-truth', 0)), ('and', ('telling-truth', 0), ('lying', 0))) | 175 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Isabella, and Evelyn. In a statement by Isabella: "Evelyn is not a knight". Evelyn stated, "Isabella is a knave or Isabella is a knight". So who is a knight and who is a knave? | [
"Isabella",
"Evelyn"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Isabella is a knave, and Evelyn is a knight. | (1) Isabella is a knave
(2) Evelyn is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Isabella is a knight. No contradiction is found in their claim that Evelyn is not a knight.",
"Evelyn cannot be a knight, because this would contradict the claim of Isabella that Evelyn is not a knight.",
"Evelyn cannot be a knave, because this would contradict the false claim of their own that Isabella... | This leads to a feasible solution. | (('not', ('telling-truth', 1)), ('or', ('lying', 0), ('telling-truth', 0))) | 176 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Samuel, and Scarlett. "If Scarlett is a knave then Samuel is a knight," Samuel declared. "Samuel is not a knight," Scarlett declared. So who is a knight and who is a knave? | [
"Samuel",
"Scarlett"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Samuel is a knight, and Scarlett is a knave. | (1) Samuel is a knight
(2) Scarlett is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Samuel is a knight. No contradiction is found in their claim that If Scarlett is a knave then Samuel is a knight.",
"Scarlett cannot be a knight, because this would contradict the claim of their own that Samuel is not a knight.",
"Assume Scarlett is a knave. No contradiction is found in their false clai... | This leads to a feasible solution. | (('->', ('lying', 1), ('telling-truth', 0)), ('not', ('telling-truth', 0))) | 177 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: James, and Samuel. James expressed that Samuel is a knight or James is a knight. "James is a knave or James is a knight," Samuel claimed. So who is a knight and who is a knave? | [
"James",
"Samuel"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | James is a knight, and Samuel is a knight. | (1) James is a knight
(2) Samuel is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume James is a knight. No contradiction is found in their claim that Samuel is a knight or James is a knight.",
"Assume Samuel is a knight. No contradiction is found in their claim that James is a knave or James is a knight."
] | This leads to a feasible solution. | (('or', ('telling-truth', 1), ('telling-truth', 0)), ('or', ('lying', 0), ('telling-truth', 0))) | 178 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Harper, and Zoey. Harper commented, "Zoey is a knave if and only if Zoey is a knight". Zoey was heard saying, "Harper is a knave or Harper is a knight". So who is a knight and who... | [
"Harper",
"Zoey"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Harper is a knave, and Zoey is a knight. | (1) Harper is a knave
(2) Zoey is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Harper cannot be a knight, because this would contradict the claim of their own that Zoey is a knave if and only if Zoey is a knight.",
"Assume Harper is a knave. No contradiction is found in their false claim that Zoey is a knave if and only if Zoey is a knight.",
"Assume Zoey is a knight. No contradiction is... | This leads to a feasible solution. | (('<=>', ('lying', 1), ('telling-truth', 1)), ('or', ('lying', 0), ('telling-truth', 0))) | 179 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Riley, and Elizabeth. Riley stated, "If Elizabeth is a knave then Elizabeth is a knight". Elizabeth stated, "Riley is a knave or Riley is a knight". So who is a knight and who is ... | [
"Riley",
"Elizabeth"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Riley is a knight, and Elizabeth is a knight. | (1) Riley is a knight
(2) Elizabeth is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Riley is a knight. No contradiction is found in their claim that If Elizabeth is a knave then Elizabeth is a knight.",
"Assume Elizabeth is a knight. No contradiction is found in their claim that Riley is a knave or Riley is a knight."
] | This leads to a feasible solution. | (('->', ('lying', 1), ('telling-truth', 1)), ('or', ('lying', 0), ('telling-truth', 0))) | 180 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Harper, and Elizabeth. Harper remarked, "Elizabeth is a knight and Elizabeth is a knave". According to Elizabeth, "Elizabeth is a knight or Harper is a knave". So who is a knight ... | [
"Harper",
"Elizabeth"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Harper is a knave, and Elizabeth is a knight. | (1) Harper is a knave
(2) Elizabeth is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Harper cannot be a knight, because this would contradict the claim of their own that Elizabeth is a knight and Elizabeth is a knave.",
"Assume Harper is a knave. No contradiction is found in their false claim that Elizabeth is a knight and Elizabeth is a knave.",
"Assume Elizabeth is a knight. No contradiction... | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('lying', 1)), ('or', ('telling-truth', 1), ('lying', 0))) | 181 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Avery, and Liam. In Avery's words: "Avery is a knight or Liam is a knight". In a statement by Liam: "Liam is a knight if and only if Avery is a knave". So who is a knight and who ... | [
"Avery",
"Liam"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Avery is a knave, and Liam is a knave. | (1) Avery is a knave
(2) Liam is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Avery is a knight. No contradiction is found in their claim that Avery is a knight or Liam is a knight.",
"Liam cannot be a knight, because this would contradict the claim of their own that Liam is a knight if and only if Avery is a knave.",
"Liam cannot be a knave, because this would contradict the fal... | This leads to a feasible solution. | (('or', ('telling-truth', 0), ('telling-truth', 1)), ('<=>', ('telling-truth', 1), ('lying', 0))) | 182 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Sophia, and Emily. In Sophia's words: "If Emily is a knight then Emily is a knave". Emily stated, "If Sophia is a knave then Emily is a knight". So who is a knight and who is a kn... | [
"Sophia",
"Emily"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Sophia is a knave, and Emily is a knight. | (1) Sophia is a knave
(2) Emily is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Sophia is a knight. No contradiction is found in their claim that If Emily is a knight then Emily is a knave.",
"Emily cannot be a knight, because this would contradict the claim of Sophia that If Emily is a knight then Emily is a knave.",
"Emily cannot be a knave, because this would contradict the fals... | This leads to a feasible solution. | (('->', ('telling-truth', 1), ('lying', 1)), ('->', ('lying', 0), ('telling-truth', 1))) | 183 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Ella, and Jacob. "Jacob is a knave," Ella declared. Jacob asserted: "If Jacob is a knight then Ella is a knave". So who is a knight and who is a knave? | [
"Ella",
"Jacob"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Ella is a knave, and Jacob is a knight. | (1) Ella is a knave
(2) Jacob is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Ella is a knight. No contradiction is found in their claim that Jacob is a knave.",
"Jacob cannot be a knight, because this would contradict the claim of Ella that Jacob is a knave.",
"Jacob cannot be a knave, because this would contradict the false claim of their own that If Jacob is a knight then Ella... | This leads to a feasible solution. | (('lying', 1), ('->', ('telling-truth', 1), ('lying', 0))) | 184 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Jack, and Aria. "If Jack is a knight then Aria is a knave," Jack declared. Aria told you that Jack is a knave. So who is a knight and who is a knave? | [
"Jack",
"Aria"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Jack is a knight, and Aria is a knave. | (1) Jack is a knight
(2) Aria is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Jack is a knight. No contradiction is found in their claim that If Jack is a knight then Aria is a knave.",
"Aria cannot be a knight, because this would contradict the claim of Jack that If Jack is a knight then Aria is a knave.",
"Assume Aria is a knave. No contradiction is found in their false claim t... | This leads to a feasible solution. | (('->', ('telling-truth', 0), ('lying', 1)), ('lying', 0)) | 185 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Ava, and Lucas. Ava told you that Lucas is a knight. "Lucas is a knight and Ava is a knave," Lucas mentioned. So who is a knight and who is a knave? | [
"Ava",
"Lucas"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Ava is a knave, and Lucas is a knave. | (1) Ava is a knave
(2) Lucas is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Ava is a knight. No contradiction is found in their claim that Lucas is a knight.",
"Lucas cannot be a knight, because this would contradict the claim of their own that Lucas is a knight and Ava is a knave.",
"Lucas cannot be a knave, because this would contradict the claim of Ava that Lucas is a knight... | This leads to a feasible solution. | (('telling-truth', 1), ('and', ('telling-truth', 1), ('lying', 0))) | 186 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Mason, and Oliver. "Oliver is a knave if and only if Oliver is a knight," Mason mentioned. "Mason is a knight if and only if Mason is a knave," Oliver declared. So who is a knight... | [
"Mason",
"Oliver"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Mason is a knave, and Oliver is a knave. | (1) Mason is a knave
(2) Oliver is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Mason cannot be a knight, because this would contradict the claim of their own that Oliver is a knave if and only if Oliver is a knight.",
"Assume Mason is a knave. No contradiction is found in their false claim that Oliver is a knave if and only if Oliver is a knight.",
"Oliver cannot be a knight, because thi... | This leads to a feasible solution. | (('<=>', ('lying', 1), ('telling-truth', 1)), ('<=>', ('telling-truth', 0), ('lying', 0))) | 187 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Amelia, and Aurora. "Aurora is not a knave," Amelia mentioned. Aurora said, "Amelia is a knave or Amelia is a knight." So who is a knight and who is a knave? | [
"Amelia",
"Aurora"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Amelia is a knight, and Aurora is a knight. | (1) Amelia is a knight
(2) Aurora is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Amelia is a knight. No contradiction is found in their claim that Aurora is not a knave.",
"Assume Aurora is a knight. No contradiction is found in their claim that Amelia is a knave or Amelia is a knight."
] | This leads to a feasible solution. | (('not', ('lying', 1)), ('or', ('lying', 0), ('telling-truth', 0))) | 188 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Amelia, and Jacob. "Jacob is a knight and Jacob is a knave," Amelia declared. In a statement by Jacob: "If Amelia is a knight then Jacob is a knight". So who is a knight and who i... | [
"Amelia",
"Jacob"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Amelia is a knave, and Jacob is a knight. | (1) Amelia is a knave
(2) Jacob is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Amelia cannot be a knight, because this would contradict the claim of their own that Jacob is a knight and Jacob is a knave.",
"Assume Amelia is a knave. No contradiction is found in their false claim that Jacob is a knight and Jacob is a knave.",
"Assume Jacob is a knight. No contradiction is found in their c... | This leads to a feasible solution. | (('and', ('telling-truth', 1), ('lying', 1)), ('->', ('telling-truth', 0), ('telling-truth', 1))) | 189 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Scarlett, and William. In Scarlett's words: "William is a knight if and only if William is a knave". William was heard saying, "If Scarlett is a knave then Scarlett is a knight". ... | [
"Scarlett",
"William"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Scarlett is a knave, and William is a knave. | (1) Scarlett is a knave
(2) William is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Scarlett cannot be a knight, because this would contradict the claim of their own that William is a knight if and only if William is a knave.",
"Assume Scarlett is a knave. No contradiction is found in their false claim that William is a knight if and only if William is a knave.",
"William cannot be a knight, ... | This leads to a feasible solution. | (('<=>', ('telling-truth', 1), ('lying', 1)), ('->', ('lying', 0), ('telling-truth', 0))) | 190 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Mason, and Harper. In a statement by Mason: "Harper is a knave and Mason is a knight". Harper stated, "Mason is a knight or Mason is a knave". So who is a knight and who is a knav... | [
"Mason",
"Harper"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Mason is a knave, and Harper is a knight. | (1) Mason is a knave
(2) Harper is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Mason is a knight. No contradiction is found in their claim that Harper is a knave and Mason is a knight.",
"Harper cannot be a knight, because this would contradict the claim of Mason that Harper is a knave and Mason is a knight.",
"Harper cannot be a knave, because this would contradict the false clai... | This leads to a feasible solution. | (('and', ('lying', 1), ('telling-truth', 0)), ('or', ('telling-truth', 0), ('lying', 0))) | 191 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Luke, and Grace. Luke told you that Grace is a knave or Grace is a knight. Grace asserted: "If Grace is a knight then Luke is a knight". So who is a knight and who is a knave? | [
"Luke",
"Grace"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Luke is a knight, and Grace is a knight. | (1) Luke is a knight
(2) Grace is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Luke is a knight. No contradiction is found in their claim that Grace is a knave or Grace is a knight.",
"Assume Grace is a knight. No contradiction is found in their claim that If Grace is a knight then Luke is a knight."
] | This leads to a feasible solution. | (('or', ('lying', 1), ('telling-truth', 1)), ('->', ('telling-truth', 1), ('telling-truth', 0))) | 192 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Avery, and James. Avery stated, "James is a knave". James remarked, "James is a knight and Avery is a knight". So who is a knight and who is a knave? | [
"Avery",
"James"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Avery is a knight, and James is a knave. | (1) Avery is a knight
(2) James is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Avery is a knight. No contradiction is found in their claim that James is a knave.",
"James cannot be a knight, because this would contradict the claim of Avery that James is a knave.",
"Assume James is a knave. No contradiction is found in their false claim that James is a knight and Avery is a knight.... | This leads to a feasible solution. | (('lying', 1), ('and', ('telling-truth', 1), ('telling-truth', 0))) | 193 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Jackson, and Lily. "Lily is a knave or Jackson is a knight," Jackson declared. Lily said, "Jackson is a knight." So who is a knight and who is a knave? | [
"Jackson",
"Lily"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Jackson is a knight, and Lily is a knight. | (1) Jackson is a knight
(2) Lily is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Jackson is a knight. No contradiction is found in their claim that Lily is a knave or Jackson is a knight.",
"Assume Lily is a knight. No contradiction is found in their claim that Jackson is a knight."
] | This leads to a feasible solution. | (('or', ('lying', 1), ('telling-truth', 0)), ('telling-truth', 0)) | 194 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Owen, and Scarlett. Owen expressed that Owen is a knight and Scarlett is a knave. Scarlett said that If Scarlett is a knight then Owen is a knave. So who is a knight and who is a ... | [
"Owen",
"Scarlett"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
true
] | Owen is a knave, and Scarlett is a knight. | (1) Owen is a knave
(2) Scarlett is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Owen is a knight. No contradiction is found in their claim that Owen is a knight and Scarlett is a knave.",
"Scarlett cannot be a knight, because this would contradict the claim of Owen that Owen is a knight and Scarlett is a knave.",
"Scarlett cannot be a knave, because this would contradict the false ... | This leads to a feasible solution. | (('and', ('telling-truth', 0), ('lying', 1)), ('->', ('telling-truth', 1), ('lying', 0))) | 195 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Emma, and Isabella. According to Emma, "If Isabella is a knight then Emma is a knight". Isabella stated, "If Emma is a knave then Emma is a knight". So who is a knight and who is ... | [
"Emma",
"Isabella"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Emma is a knight, and Isabella is a knight. | (1) Emma is a knight
(2) Isabella is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Emma is a knight. No contradiction is found in their claim that If Isabella is a knight then Emma is a knight.",
"Assume Isabella is a knight. No contradiction is found in their claim that If Emma is a knave then Emma is a knight."
] | This leads to a feasible solution. | (('->', ('telling-truth', 1), ('telling-truth', 0)), ('->', ('lying', 0), ('telling-truth', 0))) | 196 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Noah, and Matthew. "Matthew is a knight," Noah mentioned. Matthew commented, "Noah is a knight if and only if Noah is a knave". So who is a knight and who is a knave? | [
"Noah",
"Matthew"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
false,
false
] | Noah is a knave, and Matthew is a knave. | (1) Noah is a knave
(2) Matthew is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Noah is a knight. No contradiction is found in their claim that Matthew is a knight.",
"Matthew cannot be a knight, because this would contradict the claim of their own that Noah is a knight if and only if Noah is a knave.",
"Matthew cannot be a knave, because this would contradict the claim of Noah tha... | This leads to a feasible solution. | (('telling-truth', 1), ('<=>', ('telling-truth', 0), ('lying', 0))) | 197 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Liam, and David. Liam said that David is a knave or Liam is a knight. David asserted: "If David is a knight then Liam is a knight". So who is a knight and who is a knave? | [
"Liam",
"David"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
true
] | Liam is a knight, and David is a knight. | (1) Liam is a knight
(2) David is a knight | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Liam is a knight. No contradiction is found in their claim that David is a knave or Liam is a knight.",
"Assume David is a knight. No contradiction is found in their claim that If David is a knight then Liam is a knight."
] | This leads to a feasible solution. | (('or', ('lying', 1), ('telling-truth', 0)), ('->', ('telling-truth', 1), ('telling-truth', 0))) | 198 |
A very special island is inhabited only by knights and knaves. Knights always tell the truth, and knaves always lie. You meet 2 inhabitants: Elizabeth, and Noah. Elizabeth told you that Elizabeth is a knight if and only if Noah is a knave. "Elizabeth is a knave," Noah claimed. So who is a knight and who is a knave? | [
"Elizabeth",
"Noah"
] | {
"knight": "knight",
"knave": "knave",
"a_knight": "a knight",
"a_knave": "a knave",
"Knight": "Knight",
"Knave": "Knave"
} | [
true,
false
] | Elizabeth is a knight, and Noah is a knave. | (1) Elizabeth is a knight
(2) Noah is a knave | Let's think step by step, by considering whether each person is lying and if that leads to contradiction. | [
"Assume Elizabeth is a knight. No contradiction is found in their claim that Elizabeth is a knight if and only if Noah is a knave.",
"Noah cannot be a knight, because this would contradict the claim of Elizabeth that Elizabeth is a knight if and only if Noah is a knave.",
"Assume Noah is a knave. No contradicti... | This leads to a feasible solution. | (('<=>', ('telling-truth', 0), ('lying', 1)), ('lying', 0)) | 199 |
Logical reasoning training pool
Public logical-reasoning problems with checkable answers, from six datasets, read at the pinned revisions named below and laid out twice. Train on either layer or on both.
pool.jsonl
Every source rewritten into one shape, 579910 rows, one JSON object per line. A row is one of three kinds and carries the fields its kind needs.
| Field | What it holds |
|---|---|
id |
a row identifier unique within this file |
kind |
entailment, choice or open |
premises, conclusion |
an entailment row: what is given, and what is asked about |
passage, question, options |
a choice row: the text, the question, the answer options as a list of strings |
question |
an open row: the puzzle, answered in words rather than by a label |
answer |
True, False or Uncertain for an entailment row, the letter of the correct option for a choice row (A for the first option listed), the answer written out for an open row |
subject |
the label the source gives the row, such as its reasoning depth |
source |
the name of the source directory the row came from |
source_repo, source_revision |
the dataset and the revision it was read at |
source_subset, source_split, source_id |
where the row sits in that set |
provenance_class |
how the row came to exist |
licence |
the licence of the source it came from |
By kind: 565851 entailment rows, 7859 choice rows and 6200 open rows. Rows are deduplicated across sources on the problem text together with its option set, keeping the first source that carries the problem in the order of the sections below. The file is written one source after another in that same order, so a sequential read of its first rows trains on one source.
Three of the sources publish their own label words. They are written into the common vocabulary
here: unknown and neutral become Uncertain, entailment becomes True, and contradiction and not
entailment become False. The raw layer keeps whatever each source wrote. One source reasons
under the closed-world assumption, so its False means the problem's rules do not entail the
conclusion rather than that they entail its negation, which its section below repeats.
sources/
The same data as published, minus only the rows the filtering below removed, 1096561 rows, one directory per source, holding the files at the paths, in the format and with the columns its own repository publishes. Nothing else here was renamed, reshaped, relabelled or deduplicated. Use this layer if you want a field the rewritten one drops, such as the proof trees, the first-order- logic formalisations or the worked chains of reasoning, or if you would rather map the labels yourself.
The sources
sources/folio
Expert-written first-order-logic entailment problems, each a block of premises in plain English,
one conclusion, and a label saying whether the premises make the conclusion true, false or
neither, with a parallel formalisation of both in first-order logic. From tasksource/folio at
revision 295b95fb4fe9be4ff3f933b73142d142cf6b2c97, files folio_v2_train.jsonl. 219 rows here,
of which 219 also appear in pool.jsonl. Provenance class human, licence cc-by-sa-4.0. Its
own fields are story_id, premises, premises-FOL, conclusion, conclusion-FOL, label and example_id.
Worth knowing. The project repository licenses the work under Creative Commons Attribution- ShareAlike 4.0 while the authors' own dataset page tags it mit, and the stricter of the two is what the pool composes against. Several rows share one block of premises and differ only in the conclusion, which is how the set is built, so a random split of these rows is not an independent split.
sources/logiqa2
Logical reasoning questions from the Chinese civil service entrance examination, professionally
translated into English and checked by human experts, each a short passage, a question about it
and four options. From datatune/LogiQA2.0 at revision
edbf6440d36a03f715c0c9d479f421f2ece87d6a, files MRC/train.txt. 8438 rows here, of which 7859
also appear in pool.jsonl. Provenance class human, licence unknown. Its own fields are id,
text for the passage, question, options, answer as a zero-based index, type.
Worth knowing. The copy read here tags itself mit and the project repository publishes no licence file at all, so the tag covers the packaging rather than the examining bodies' rights in the underlying questions. The published train file, 12567 rows upstream before the filtering below, repeats 903 of its problems, the same passage, question and options behind a different id and never a byte-identical line. Among the 8438 rows kept here the rewritten layer drops 570 such repeats by its normalised, order-insensitive key and the raw layer keeps them. The file also reuses 148 of its ids, each on two different problems, so id is not a key.
sources/proofwriter
Generated theories of facts and rules in plain English with a question about them, under the open-
world assumption, so the answer is true, false or unknown, at reasoning depths from zero to five
plus a hand-written natural-language variant. From tasksource/proofwriter at revision
ee4d22d49b8486786cbc01c0b6f6f6266e56f3bd, files
data/train-00000-of-00002-6176cf3d78f48858.parquet,
data/train-00001-of-00002-901eaba2151bde61.parquet. 585552 rows here, of which 376806 also
appear in pool.jsonl. Provenance class rule-generated, licence unknown. Its own fields are
id, maxD, NFact, NRule, theory, question, answer, QDep, QLen, allProofs for the proof trees, and
config naming the depth.
Worth knowing. The release ships no licence file and the copy read here carries no licence tag. Its own README describes it as an updated version of the RuleTaker datasets, which the Allen Institute for AI publishes under Apache 2.0, so redistribution rests on that statement rather than on a licence for this release. Many rows share one theory and differ only in the question.
sources/ruletaker
The earlier generated theories the set above updates, under the closed-world assumption, so a
question is either entailed by the theory or not, at reasoning depths from zero to five plus a
hand-written natural-language variant. From tasksource/ruletaker at revision
a3e0880baeb6ec3d478f4c4d85afe04b21b6cf7f, files
data/train-00000-of-00001-52adaa842dd7ed92.parquet. 480152 rows here, of which 176827 also
appear in pool.jsonl. Provenance class rule-generated, licence apache-2.0. Its own fields
are context, question, label of entailment or not entailment, and config.
Worth knowing. Closed world, so its not entailment label covers both a false statement and one the theory says nothing about, which the two labels of the rewritten layer keep apart from the three- way labels of the other sources. It overlaps the set above by construction and the rewritten layer deduplicates across the two.
sources/logicnli
Generated first-order-logic entailment problems in plain English, built so that the answer follows
from the logic rather than from world knowledge, with facts about named people followed by rules
over them. From tasksource/LogicNLI at revision ac9d30ac7351c5f9bb31970b7ae82182b8b4f5e8,
files data/train-00000-of-00001-05a75d620743c1d1.parquet. 16000 rows here, of which 11999 also
appear in pool.jsonl. Provenance class rule-generated, licence unknown. Its own fields are
premise, hypothesis, and label of entailment, contradiction, neutral or self_contradiction.
Worth knowing. Neither the copy read here nor the project repository declares a licence. A quarter of its rows carry the label self_contradiction, which says the premises contradict each other rather than saying anything about the hypothesis. Those rows have no place in a three-way label vocabulary and are dropped from the rewritten layer and kept in the raw one.
sources/knights_and_knaves
Generated knights-and-knaves puzzles, in which every inhabitant either always tells the truth or
always lies and their statements about one another fix who is which, from two to eight
inhabitants, each with the unique solution written out and a worked chain of reasoning beside it.
From K-and-K/knights-and-knaves at revision 2f68547989981b1af37cb3dde5fdefa847aa8619, files
train/people2_num200.jsonl, train/people3_num1000.jsonl, train/people4_num1000.jsonl,
train/people5_num1000.jsonl, train/people6_num1000.jsonl, train/people7_num1000.jsonl,
train/people8_num1000.jsonl. 6200 rows here, of which 6200 also appear in pool.jsonl.
Provenance class rule-generated, licence cc-by-nc-sa-4.0. Its own fields are quiz, names,
knight_knave for the wording used, solution as a list of booleans, solution_text,
solution_text_format, statements, index, and cot_head, cot_repeat_steps and cot_foot for the
worked reasoning.
Worth knowing. Non-commercial and share-alike, which is what makes the pool as a whole non- commercial. The puzzles come from one generator, so their surface wording repeats heavily across rows and a model can learn the wording rather than the reasoning.
Provenance and licences
Two of the six sources are problems written by people, one set by domain experts and one by the
boards of a national examination and its professional translators. The other four are the output
of programs that build a problem and its answer together, which is the provenance class rule- generated and which is most of the rows. Nothing in the pool was generated by a language model,
and no answer anywhere in it was produced by a model: every key is either a human annotation or
the generator's own record of the answer it built the problem around.
The pool as a whole is offered under cc-by-nc-sa-4.0, which is the most restrictive term its
sources compose to. The sources themselves are cc-by-sa-4.0 for the expert-written entailment set,
apache-2.0 for the closed-world generated set, cc-by-nc-sa-4.0 for the knights-and-knaves set, and
an undeclared licence for the examination questions, the open-world generated set and the
generated entailment set, none of which publishes a licence at its own project repository. Each
rewritten row carries its own in the licence field and each directory under sources/ is one
source, so a subset under a single licence can be selected. Attribution for the share-alike
sources goes to the authors named in each source's own citation, and questions taken from national
examinations remain the property of the boards that wrote them.
Filtering
Rows whose text duplicated or overlapped the text of a problem in a held-out collection were
removed before publication, from both layers alike, by an exact whole-text match (1257 rows)
followed by a word 8-gram overlap check (3654 rows). Both checks read the premises and the
conclusion, or the passage and the question, and never the options. An 8-gram carried by more than
one held-out problem is a stock phrase rather than a problem, so it was left out of that check,
and the 4286 rows whose only overlap was such a phrase were counted and kept. The held-out
collection is not distributed here. Nothing else was filtered: no reasoning depth, no subject and
no difficulty was selected for or against, so the pool still holds the easiest depth-zero
generated rows beside the hardest examination questions, and the subject field is how to select
what you want. That field is the source's own configuration label. For the ProofWriter rows the
labels are depth-0, depth-1, depth-2, depth-5, NatLang and depth-3ext-NatLang, and the last of
these is a mixed bag holding the depth-3 theories together with some depth-1 and depth-2 ones
(their ids carry D3, D2 and D1), so a ProofWriter depth-3 subset cannot be selected by subject
alone, while the RuleTaker rows carry depth-3 and depth-3ext labels of their own.
Two warnings a reader should carry into training. Four of the six sources come from generators, so their wording repeats heavily and a model can learn the surface pattern rather than the reasoning, which is the finding the knights-and-knaves authors published about their own set. And several sources build many rows on one block of premises, differing only in what is asked, so a random split of these rows does not give independent train and held-out halves.
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