| { |
| "id": 3311, |
| "name": "ant_on_the_boundary", |
| "difficulty": "Easy", |
| "link": "https://leetcode.com/problems/ant-on-the-boundary/", |
| "date": "2024-01-28 00:00:00", |
| "task_description": "An ant is on a boundary. It sometimes goes **left** and sometimes **right**. You are given an array of **non-zero** integers `nums`. The ant starts reading `nums` from the first element of it to its end. At each step, it moves according to the value of the current element: If `nums[i] < 0`, it moves **left** by `-nums[i]` units. If `nums[i] > 0`, it moves **right** by `nums[i]` units. Return _the number of times the ant **returns** to the boundary._ **Notes:** There is an infinite space on both sides of the boundary. We check whether the ant is on the boundary only after it has moved `|nums[i]|` units. In other words, if the ant crosses the boundary during its movement, it does not count. **Example 1:** ``` **Input:** nums = [2,3,-5] **Output:** 1 **Explanation:** After the first step, the ant is 2 steps to the right of the boundary. After the second step, the ant is 5 steps to the right of the boundary. After the third step, the ant is on the boundary. So the answer is 1. ``` **Example 2:** ``` **Input:** nums = [3,2,-3,-4] **Output:** 0 **Explanation:** After the first step, the ant is 3 steps to the right of the boundary. After the second step, the ant is 5 steps to the right of the boundary. After the third step, the ant is 2 steps to the right of the boundary. After the fourth step, the ant is 2 steps to the left of the boundary. The ant never returned to the boundary, so the answer is 0. ``` **Constraints:** `1 <= nums.length <= 100` `-10 <= nums[i] <= 10` `nums[i] != 0`", |
| "public_test_cases": [ |
| { |
| "label": "Example 1", |
| "input": "nums = [2,3,-5]", |
| "output": "1 " |
| }, |
| { |
| "label": "Example 2", |
| "input": "nums = [3,2,-3,-4]", |
| "output": "0 " |
| } |
| ], |
| "private_test_cases": [ |
| { |
| "input": [ |
| -10, |
| 9, |
| -10, |
| 10, |
| 1, |
| -8, |
| 5, |
| 9, |
| -7, |
| -9, |
| 2, |
| -8, |
| -1, |
| -5, |
| -7, |
| 7, |
| -5, |
| -2, |
| -3, |
| 9, |
| -9, |
| -9, |
| 9, |
| -3, |
| -7, |
| -6, |
| -9, |
| -7, |
| 0, |
| 4, |
| -1, |
| -10, |
| 0, |
| 8, |
| 8, |
| -7, |
| -1, |
| 3, |
| 8, |
| -3, |
| -1, |
| -6 |
| ], |
| "output": 1 |
| }, |
| { |
| "input": [ |
| -6, |
| 0, |
| 7, |
| -4, |
| -2, |
| 5, |
| 3, |
| 4, |
| 3, |
| -7, |
| 4, |
| -6, |
| 7, |
| 8, |
| -1, |
| 5, |
| 1, |
| 10, |
| -7, |
| -6, |
| 1, |
| -5, |
| 3, |
| 8, |
| -6, |
| 5, |
| -8, |
| 10, |
| -4, |
| 3, |
| -10, |
| -3, |
| -1, |
| 10, |
| 9, |
| 10, |
| -9, |
| 10, |
| -3, |
| -3, |
| -6, |
| 0, |
| 7, |
| 4, |
| 2, |
| 0, |
| 7, |
| 2, |
| -6 |
| ], |
| "output": 1 |
| }, |
| { |
| "input": [ |
| -2, |
| 5, |
| 1, |
| -2, |
| 7, |
| -6, |
| 6, |
| 2, |
| -2, |
| -10, |
| 10, |
| 8, |
| -3, |
| 6 |
| ], |
| "output": 0 |
| }, |
| { |
| "input": [ |
| -2, |
| -7, |
| -7, |
| -10, |
| -10 |
| ], |
| "output": 0 |
| }, |
| { |
| "input": [ |
| -10, |
| -9, |
| 0 |
| ], |
| "output": 0 |
| } |
| ], |
| "haskell_template": "returnToBoundaryCount :: [Int] -> Int\nreturnToBoundaryCount nums ", |
| "ocaml_template": "let returnToBoundaryCount (nums: int list) : int = ", |
| "scala_template": "def returnToBoundaryCount(nums: List[Int]): Int = { \n \n}", |
| "java_template": "class Solution {\n public int returnToBoundaryCount(int[] nums) {\n \n }\n}", |
| "python_template": "class Solution(object):\n def returnToBoundaryCount(self, nums):\n \"\"\"\n :type nums: List[int]\n :rtype: int\n \"\"\"\n " |
| } |