Split (2)

train · 8.66k rows

db_name stringclasses 146 values	prompt stringlengths 310 4.81k
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What kind of decor has the least number of reservations? # ### SQL: # # SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY count(T2.decor) ASC LIMIT 1; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What is the least popular kind of decor? # ### SQL: # # SELECT T2.decor FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T2.decor ORDER BY count(T2.decor) ASC LIMIT 1; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # List how many times the number of people in the room reached the maximum occupancy of the room. The number of people include adults and kids. # ### SQL: # # SELECT count(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # How many times the number of adults and kids staying in a room reached the maximum capacity of the room? # ### SQL: # # SELECT count(*) FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T2.maxOccupancy = T1.Adults + T1.Kids; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the first and last names of people who payed more than the rooms' base prices. # ### SQL: # # SELECT T1.firstname , T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0 # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What are the first and last names of people who payed more than the rooms' base prices? # ### SQL: # # SELECT T1.firstname , T1.lastname FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE T1.Rate - T2.basePrice > 0 # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # How many rooms are there? # ### SQL: # # SELECT count(*) FROM Rooms; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What is the total number of rooms available in this inn? # ### SQL: # # SELECT count(*) FROM Rooms; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the number of rooms with a king bed. # ### SQL: # # SELECT count(*) FROM Rooms WHERE bedType = "King"; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # How many rooms have a king bed? # ### SQL: # # SELECT count(*) FROM Rooms WHERE bedType = "King"; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the number of rooms for each bed type. # ### SQL: # # SELECT bedType , count(*) FROM Rooms GROUP BY bedType; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What are the number of rooms for each bed type? # ### SQL: # # SELECT bedType , count(*) FROM Rooms GROUP BY bedType; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the name of the room with the maximum occupancy. # ### SQL: # # SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What is the name of the room that can accommodate the most people? # ### SQL: # # SELECT roomName FROM Rooms ORDER BY maxOccupancy DESC LIMIT 1; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the id and name of the most expensive base price room. # ### SQL: # # SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Which room has the highest base price? # ### SQL: # # SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 1; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # List the type of bed and name of all traditional rooms. # ### SQL: # # SELECT roomName , bedType FROM Rooms WHERE decor = "traditional"; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What are the bed type and name of all the rooms with traditional decor? # ### SQL: # # SELECT roomName , bedType FROM Rooms WHERE decor = "traditional"; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the number of rooms with king bed for each decor type. # ### SQL: # # SELECT decor , count(*) FROM Rooms WHERE bedType = "King" GROUP BY decor; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # How many rooms have king beds? Report the number for each decor type. # ### SQL: # # SELECT decor , count(*) FROM Rooms WHERE bedType = "King" GROUP BY decor; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the average and minimum price of the rooms in different decor. # ### SQL: # # SELECT decor , avg(basePrice) , min(basePrice) FROM Rooms GROUP BY decor; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What is the average minimum and price of the rooms for each different decor. # ### SQL: # # SELECT decor , avg(basePrice) , min(basePrice) FROM Rooms GROUP BY decor; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # List the name of all rooms sorted by their prices. # ### SQL: # # SELECT roomName FROM Rooms ORDER BY basePrice; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Sort all the rooms according to the price. Just report the room names. # ### SQL: # # SELECT roomName FROM Rooms ORDER BY basePrice; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the number of rooms with price higher than 120 for different decor. # ### SQL: # # SELECT decor , count(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # How many rooms cost more than 120, for each different decor? # ### SQL: # # SELECT decor , count(*) FROM Rooms WHERE basePrice > 120 GROUP BY decor; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # For each bed type, find the average room price. # ### SQL: # # SELECT bedType , avg(basePrice) FROM Rooms GROUP BY bedType; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What is the average base price of rooms, for each bed type? # ### SQL: # # SELECT bedType , avg(basePrice) FROM Rooms GROUP BY bedType; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # List the name of rooms with king or queen bed. # ### SQL: # # SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen"; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What are the names of rooms that have either king or queen bed? # ### SQL: # # SELECT roomName FROM Rooms WHERE bedType = "King" OR bedType = "Queen"; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # How many different types of beds are there? # ### SQL: # # SELECT count(DISTINCT bedType) FROM Rooms; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the number of distinct bed types available in this inn. # ### SQL: # # SELECT count(DISTINCT bedType) FROM Rooms; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the name and id of the top 3 expensive rooms. # ### SQL: # # SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What are the name and id of the three highest priced rooms? # ### SQL: # # SELECT RoomId , roomName FROM Rooms ORDER BY basePrice DESC LIMIT 3; # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the name of rooms whose price is higher than the average price. # ### SQL: # # SELECT roomName FROM Rooms WHERE basePrice > ( SELECT avg(basePrice) FROM Rooms ); # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What are the name of rooms that cost more than the average. # ### SQL: # # SELECT roomName FROM Rooms WHERE basePrice > ( SELECT avg(basePrice) FROM Rooms ); # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the number of rooms that do not have any reservation. # ### SQL: # # SELECT count(*) FROM rooms WHERE roomid NOT IN (SELECT DISTINCT room FROM reservations) # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # How many rooms have not had any reservation yet? # ### SQL: # # SELECT count(*) FROM rooms WHERE roomid NOT IN (SELECT DISTINCT room FROM reservations) # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Return the name and number of reservations made for each of the rooms. # ### SQL: # # SELECT T2.roomName , count(*) , T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # For each room, find its name and the number of times reservations were made for it. # ### SQL: # # SELECT T2.roomName , count(*) , T1.Room FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the names of rooms that have been reserved for more than 60 times. # ### SQL: # # SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING count(*) > 60 # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What are the names of rooms whose reservation frequency exceeds 60 times? # ### SQL: # # SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId GROUP BY T1.Room HAVING count(*) > 60 # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the name of rooms whose base price is between 120 and 150. # ### SQL: # # SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150 # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Which rooms cost between 120 and 150? Give me the room names. # ### SQL: # # SELECT roomname FROM rooms WHERE baseprice BETWEEN 120 AND 150 # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # Find the name of rooms booked by some customers whose first name contains ROY. # ### SQL: # # SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%' # ### End.
inn_1	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Rooms ( RoomId, roomName, beds, bedType, maxOccupancy, basePrice, decor ) # Reservations ( Code, Room, CheckIn, CheckOut, Rate, LastName, FirstName, Adults, Kids ) # # Reservations.Room can be joined with Rooms.RoomId # ### Question: # # What are the name of rooms booked by customers whose first name has "ROY" in part? # ### SQL: # # SELECT T2.roomName FROM Reservations AS T1 JOIN Rooms AS T2 ON T1.Room = T2.RoomId WHERE firstname LIKE '%ROY%' # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # what are the details of the cmi masters that have the cross reference code 'Tax'? # ### SQL: # # SELECT T1.cmi_details FROM Customer_Master_Index AS T1 JOIN CMI_Cross_References AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T2.source_system_code = 'Tax' # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # What is the cmi cross reference id that is related to at least one council tax entry? List the cross reference id and source system code. # ### SQL: # # SELECT T1.cmi_cross_ref_id , T1.source_system_code FROM CMI_Cross_References AS T1 JOIN Council_Tax AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T1.cmi_cross_ref_id HAVING count(*) >= 1 # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # How many business rates are related to each cmi cross reference? List cross reference id, master customer id and the n # ### SQL: # # SELECT T2.cmi_cross_ref_id , T2.master_customer_id , count(*) FROM Business_Rates AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id GROUP BY T2.cmi_cross_ref_id # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # What is the tax source system code related to the benefits and overpayments? List the code and the benifit id, order by benifit id. # ### SQL: # # SELECT T1.source_system_code , T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Benefits_Overpayments AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id ORDER BY T2.council_tax_id # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # Wat is the tax source system code and master customer id of the taxes related to each parking fine id? # ### SQL: # # SELECT T1.source_system_code , T1.master_customer_id , T2.council_tax_id FROM CMI_Cross_References AS T1 JOIN Parking_Fines AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # What are the renting arrears tax ids related to the customer master index whose detail is not 'Schmidt, Kertzmann and Lubowitz'? # ### SQL: # # SELECT T1.council_tax_id FROM Rent_Arrears AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id JOIN Customer_Master_Index AS T3 ON T3.master_customer_id = T2.master_customer_id WHERE T3.cmi_details != 'Schmidt , Kertzmann and Lubowitz' # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # What are the register ids of electoral registries that have the cross reference source system code 'Electoral' or 'Tax'? # ### SQL: # # SELECT T1.electoral_register_id FROM Electoral_Register AS T1 JOIN CMI_Cross_References AS T2 ON T1.cmi_cross_ref_id = T2.cmi_cross_ref_id WHERE T2.source_system_code = 'Electoral' OR T2.source_system_code = 'Tax' # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # How many different source system code for the cmi cross references are there? # ### SQL: # # SELECT count(DISTINCT source_system_code) FROM CMI_cross_references # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # List all information about customer master index, and sort them by details in descending order. # ### SQL: # # SELECT * FROM customer_master_index ORDER BY cmi_details DESC # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # List the council tax ids and their related cmi cross references of all the parking fines. # ### SQL: # # SELECT council_tax_id , cmi_cross_ref_id FROM parking_fines # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # How many council taxes are collected for renting arrears ? # ### SQL: # # SELECT count(*) FROM rent_arrears # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # What are the distinct cross reference source system codes which are related to the master customer details 'Gottlieb, Becker and Wyman'? # ### SQL: # # SELECT DISTINCT T2.source_system_code FROM customer_master_index AS T1 JOIN cmi_cross_references AS T2 ON T1.master_customer_id = T2.master_customer_id WHERE T1.cmi_details = 'Gottlieb , Becker and Wyman' # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # Which cmi cross reference id is not related to any parking taxes? # ### SQL: # # SELECT cmi_cross_ref_id FROM cmi_cross_references EXCEPT SELECT cmi_cross_ref_id FROM parking_fines # ### End.
local_govt_mdm	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Customer_Master_Index ( master_customer_id, cmi_details ) # CMI_Cross_References ( cmi_cross_ref_id, master_customer_id, source_system_code ) # Council_Tax ( council_tax_id, cmi_cross_ref_id ) # Business_Rates ( business_rates_id, cmi_cross_ref_id ) # Benefits_Overpayments ( council_tax_id, cmi_cross_ref_id ) # Parking_Fines ( council_tax_id, cmi_cross_ref_id ) # Rent_Arrears ( council_tax_id, cmi_cross_ref_id ) # Electoral_Register ( electoral_register_id, cmi_cross_ref_id ) # # CMI_Cross_References.master_customer_id can be joined with Customer_Master_Index.master_customer_id # Council_Tax.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Business_Rates.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Benefits_Overpayments.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Parking_Fines.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Rent_Arrears.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # Electoral_Register.cmi_cross_ref_id can be joined with CMI_Cross_References.cmi_cross_ref_id # ### Question: # # Which distinct source system code includes the substring 'en'? # ### SQL: # # SELECT DISTINCT source_system_code FROM cmi_cross_references WHERE source_system_code LIKE '%en%' # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # How many parties are there? # ### SQL: # # SELECT count(*) FROM party # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Count the number of parties. # ### SQL: # # SELECT count(*) FROM party # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # List the themes of parties in ascending order of number of hosts. # ### SQL: # # SELECT Party_Theme FROM party ORDER BY Number_of_hosts ASC # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # What are the themes of parties ordered by the number of hosts in ascending manner? # ### SQL: # # SELECT Party_Theme FROM party ORDER BY Number_of_hosts ASC # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # What are the themes and locations of parties? # ### SQL: # # SELECT Party_Theme , LOCATION FROM party # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Give me the theme and location of each party. # ### SQL: # # SELECT Party_Theme , LOCATION FROM party # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show the first year and last year of parties with theme "Spring" or "Teqnology". # ### SQL: # # SELECT First_year , Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology" # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # What are the first year and last year of the parties whose theme is "Spring" or "Teqnology"? # ### SQL: # # SELECT First_year , Last_year FROM party WHERE Party_Theme = "Spring" OR Party_Theme = "Teqnology" # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # What is the average number of hosts for parties? # ### SQL: # # SELECT avg(Number_of_hosts) FROM party # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Compute the average number of hosts for parties. # ### SQL: # # SELECT avg(Number_of_hosts) FROM party # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # What is the location of the party with the most hosts? # ### SQL: # # SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Which party had the most hosts? Give me the party location. # ### SQL: # # SELECT LOCATION FROM party ORDER BY Number_of_hosts DESC LIMIT 1 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show different nationalities along with the number of hosts of each nationality. # ### SQL: # # SELECT Nationality , COUNT(*) FROM HOST GROUP BY Nationality # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # How many hosts does each nationality have? List the nationality and the count. # ### SQL: # # SELECT Nationality , COUNT(*) FROM HOST GROUP BY Nationality # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show the most common nationality of hosts. # ### SQL: # # SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Which nationality has the most hosts? # ### SQL: # # SELECT Nationality FROM HOST GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show the nations that have both hosts older than 45 and hosts younger than 35. # ### SQL: # # SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Which nations have both hosts of age above 45 and hosts of age below 35? # ### SQL: # # SELECT Nationality FROM HOST WHERE Age > 45 INTERSECT SELECT Nationality FROM HOST WHERE Age < 35 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show the themes of parties and the names of the party hosts. # ### SQL: # # SELECT T3.Party_Theme , T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # For each party, return its theme and the name of its host. # ### SQL: # # SELECT T3.Party_Theme , T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show the locations of parties and the names of the party hosts in ascending order of the age of the host. # ### SQL: # # SELECT T3.Location , T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # For each party, find its location and the name of its host. Sort the result in ascending order of the age of the host. # ### SQL: # # SELECT T3.Location , T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID ORDER BY T2.Age # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show the locations of parties with hosts older than 50. # ### SQL: # # SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Which parties have hosts of age above 50? Give me the party locations. # ### SQL: # # SELECT T3.Location FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T2.Age > 50 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show the host names for parties with number of hosts greater than 20. # ### SQL: # # SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Which parties have more than 20 hosts? Give me the host names for these parties. # ### SQL: # # SELECT T2.Name FROM party_host AS T1 JOIN HOST AS T2 ON T1.Host_ID = T2.Host_ID JOIN party AS T3 ON T1.Party_ID = T3.Party_ID WHERE T3.Number_of_hosts > 20 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # Show the name and the nationality of the oldest host. # ### SQL: # # SELECT Name , Nationality FROM HOST ORDER BY Age DESC LIMIT 1 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # What are the name and the nationality of the host of the highest age? # ### SQL: # # SELECT Name , Nationality FROM HOST ORDER BY Age DESC LIMIT 1 # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # List the names of hosts who did not serve as a host of any party in our record. # ### SQL: # # SELECT Name FROM HOST WHERE Host_ID NOT IN (SELECT Host_ID FROM party_host) # ### End.
party_host	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # party ( Party_ID, Party_Theme, Location, First_year, Last_year, Number_of_hosts ) # host ( Host_ID, Name, Nationality, Age ) # party_host ( Party_ID, Host_ID, Is_Main_in_Charge ) # # party_host.Party_ID can be joined with party.Party_ID # party_host.Host_ID can be joined with host.Host_ID # ### Question: # # What are the names of hosts who did not host any party in our record? # ### SQL: # # SELECT Name FROM HOST WHERE Host_ID NOT IN (SELECT Host_ID FROM party_host) # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # How many regions do we have? # ### SQL: # # SELECT count(*) FROM region # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # Count the number of regions. # ### SQL: # # SELECT count(*) FROM region # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # Show all region code and region name sorted by the codes. # ### SQL: # # SELECT region_code , region_name FROM region ORDER BY region_code # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # What are the codes and names for all regions, sorted by codes? # ### SQL: # # SELECT region_code , region_name FROM region ORDER BY region_code # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # List all region names in alphabetical order. # ### SQL: # # SELECT region_name FROM region ORDER BY region_name # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # What are the names of the regions in alphabetical order? # ### SQL: # # SELECT region_name FROM region ORDER BY region_name # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # Show names for all regions except for Denmark. # ### SQL: # # SELECT region_name FROM region WHERE region_name != 'Denmark' # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # Return the names of all regions other than Denmark. # ### SQL: # # SELECT region_name FROM region WHERE region_name != 'Denmark' # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # How many storms had death records? # ### SQL: # # SELECT count(*) FROM storm WHERE Number_Deaths > 0 # ### End.
storm_record	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # storm ( Storm_ID, Name, Dates_active, Max_speed, Damage_millions_USD, Number_Deaths ) # region ( Region_id, Region_code, Region_name ) # affected_region ( Region_id, Storm_ID, Number_city_affected ) # # affected_region.Storm_ID can be joined with storm.Storm_ID # affected_region.Region_id can be joined with region.Region_id # ### Question: # # Count the number of storms in which at least 1 person died. # ### SQL: # # SELECT count(*) FROM storm WHERE Number_Deaths > 0 # ### End.

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