Split (2)

train · 8.66k rows

db_name stringclasses 146 values	prompt stringlengths 310 4.81k
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # List the name of artworks whose type is not "Program Talent Show". # ### SQL: # # SELECT Name FROM artwork WHERE TYPE != "Program Talent Show" # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # What are the names and locations of festivals? # ### SQL: # # SELECT Festival_Name , LOCATION FROM festival_detail # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # What are the names of the chairs of festivals, sorted in ascending order of the year held? # ### SQL: # # SELECT Chair_Name FROM festival_detail ORDER BY YEAR ASC # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # What is the location of the festival with the largest number of audience? # ### SQL: # # SELECT LOCATION FROM festival_detail ORDER BY Num_of_Audience DESC LIMIT 1 # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # What are the names of festivals held in year 2007? # ### SQL: # # SELECT Festival_Name FROM festival_detail WHERE YEAR = 2007 # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # What is the average number of audience for festivals? # ### SQL: # # SELECT avg(Num_of_Audience) FROM festival_detail # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # Show the names of the three most recent festivals. # ### SQL: # # SELECT Festival_Name FROM festival_detail ORDER BY YEAR DESC LIMIT 3 # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # For each nomination, show the name of the artwork and name of the festival where it is nominated. # ### SQL: # # SELECT T2.Name , T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # Show distinct types of artworks that are nominated in festivals in 2007. # ### SQL: # # SELECT DISTINCT T2.Type FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID WHERE T3.Year = 2007 # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # Show the names of artworks in ascending order of the year they are nominated in. # ### SQL: # # SELECT T2.Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID ORDER BY T3.Year # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # Show the names of festivals that have nominated artworks of type "Program Talent Show". # ### SQL: # # SELECT T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID WHERE T2.Type = "Program Talent Show" # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # Show the ids and names of festivals that have at least two nominations for artworks. # ### SQL: # # SELECT T1.Festival_ID , T3.Festival_Name FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID GROUP BY T1.Festival_ID HAVING COUNT(*) >= 2 # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # Show the id, name of each festival and the number of artworks it has nominated. # ### SQL: # # SELECT T1.Festival_ID , T3.Festival_Name , COUNT(*) FROM nomination AS T1 JOIN artwork AS T2 ON T1.Artwork_ID = T2.Artwork_ID JOIN festival_detail AS T3 ON T1.Festival_ID = T3.Festival_ID GROUP BY T1.Festival_ID # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # Please show different types of artworks with the corresponding number of artworks of each type. # ### SQL: # # SELECT TYPE , COUNT(*) FROM artwork GROUP BY TYPE # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # List the most common type of artworks. # ### SQL: # # SELECT TYPE FROM artwork GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1 # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # List the year in which there are more than one festivals. # ### SQL: # # SELECT YEAR FROM festival_detail GROUP BY YEAR HAVING COUNT(*) > 1 # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # List the name of artworks that are not nominated. # ### SQL: # # SELECT Name FROM Artwork WHERE Artwork_ID NOT IN (SELECT Artwork_ID FROM nomination) # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # Show the number of audience in year 2008 or 2010. # ### SQL: # # SELECT Num_of_Audience FROM festival_detail WHERE YEAR = 2008 OR YEAR = 2010 # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # What are the total number of the audiences who visited any of the festivals? # ### SQL: # # SELECT sum(Num_of_Audience) FROM festival_detail # ### End.
entertainment_awards	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # festival_detail ( Festival_ID, Festival_Name, Chair_Name, Location, Year, Num_of_Audience ) # artwork ( Artwork_ID, Type, Name ) # nomination ( Artwork_ID, Festival_ID, Result ) # # nomination.Festival_ID can be joined with festival_detail.Festival_ID # nomination.Artwork_ID can be joined with artwork.Artwork_ID # ### Question: # # In which year are there festivals both inside the 'United States' and outside the 'United States'? # ### SQL: # # SELECT YEAR FROM festival_detail WHERE LOCATION = 'United States' INTERSECT SELECT YEAR FROM festival_detail WHERE LOCATION != 'United States' # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # How many premises are there? # ### SQL: # # SELECT count(*) FROM premises # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are all the distinct premise types? # ### SQL: # # SELECT DISTINCT premises_type FROM premises # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Find the types and details for all premises and order by the premise type. # ### SQL: # # SELECT premises_type , premise_details FROM premises ORDER BY premises_type # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show each premise type and the number of premises in that type. # ### SQL: # # SELECT premises_type , count(*) FROM premises GROUP BY premises_type # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show all distinct product categories along with the number of mailshots in each category. # ### SQL: # # SELECT product_category , count(*) FROM mailshot_campaigns GROUP BY product_category # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show the name and phone of the customer without any mailshot. # ### SQL: # # SELECT customer_name , customer_phone FROM customers WHERE customer_id NOT IN (SELECT customer_id FROM mailshot_customers) # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show the name and phone for customers with a mailshot with outcome code 'No Response'. # ### SQL: # # SELECT T1.customer_name , T1.customer_phone FROM customers AS T1 JOIN mailshot_customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.outcome_code = 'No Response' # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show the outcome code of mailshots along with the number of mailshots in each outcome code. # ### SQL: # # SELECT outcome_code , count(*) FROM mailshot_customers GROUP BY outcome_code # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show the names of customers who have at least 2 mailshots with outcome code 'Order'. # ### SQL: # # SELECT T2.customer_name FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id WHERE outcome_code = 'Order' GROUP BY T1.customer_id HAVING count(*) >= 2 # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show the names of customers who have the most mailshots. # ### SQL: # # SELECT T2.customer_name FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1 # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the name and payment method of customers who have both mailshots in 'Order' outcome and mailshots in 'No Response' outcome. # ### SQL: # # SELECT T2.customer_name , T2.payment_method FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.outcome_code = 'Order' INTERSECT SELECT T2.customer_name , T2.payment_method FROM mailshot_customers AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.outcome_code = 'No Response' # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show the premise type and address type code for all customer addresses. # ### SQL: # # SELECT T2.premises_type , T1.address_type_code FROM customer_addresses AS T1 JOIN premises AS T2 ON T1.premise_id = T2.premise_id # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # What are the distinct address type codes for all customer addresses? # ### SQL: # # SELECT DISTINCT address_type_code FROM customer_addresses # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show the shipping charge and customer id for customer orders with order status Cancelled or Paid. # ### SQL: # # SELECT order_shipping_charges , customer_id FROM customer_orders WHERE order_status_code = 'Cancelled' OR order_status_code = 'Paid' # ### End.
customers_campaigns_ecommerce	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Premises ( premise_id, premises_type, premise_details ) # Products ( product_id, product_category, product_name ) # Customers ( customer_id, payment_method, customer_name, customer_phone, customer_email, customer_address, customer_login, customer_password ) # Mailshot_Campaigns ( mailshot_id, product_category, mailshot_name, mailshot_start_date, mailshot_end_date ) # Customer_Addresses ( customer_id, premise_id, date_address_from, address_type_code, date_address_to ) # Customer_Orders ( order_id, customer_id, order_status_code, shipping_method_code, order_placed_datetime, order_delivered_datetime, order_shipping_charges ) # Mailshot_Customers ( mailshot_id, customer_id, outcome_code, mailshot_customer_date ) # Order_Items ( item_id, order_item_status_code, order_id, product_id, item_status_code, item_delivered_datetime, item_order_quantity ) # # Customer_Addresses.customer_id can be joined with Customers.customer_id # Customer_Addresses.premise_id can be joined with Premises.premise_id # Customer_Orders.customer_id can be joined with Customers.customer_id # Mailshot_Customers.mailshot_id can be joined with Mailshot_Campaigns.mailshot_id # Mailshot_Customers.customer_id can be joined with Customers.customer_id # Order_Items.order_id can be joined with Customer_Orders.order_id # Order_Items.product_id can be joined with Products.product_id # ### Question: # # Show the names of customers having an order with shipping method FedEx and order status Paid. # ### SQL: # # SELECT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE shipping_method_code = 'FedEx' AND order_status_code = 'Paid' # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # How many courses are there in total? # ### SQL: # # SELECT count(*) FROM COURSE # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Count the number of courses. # ### SQL: # # SELECT count(*) FROM COURSE # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # How many courses have more than 2 credits? # ### SQL: # # SELECT count(*) FROM COURSE WHERE Credits > 2 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Count the number of courses with more than 2 credits. # ### SQL: # # SELECT count(*) FROM COURSE WHERE Credits > 2 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # List all names of courses with 1 credit? # ### SQL: # # SELECT CName FROM COURSE WHERE Credits = 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the names of courses with 1 credit? # ### SQL: # # SELECT CName FROM COURSE WHERE Credits = 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Which courses are taught on days MTW? # ### SQL: # # SELECT CName FROM COURSE WHERE Days = "MTW" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the course names for courses taught on MTW? # ### SQL: # # SELECT CName FROM COURSE WHERE Days = "MTW" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What is the number of departments in Division "AS"? # ### SQL: # # SELECT count(*) FROM DEPARTMENT WHERE Division = "AS" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # How many departments are in the division AS? # ### SQL: # # SELECT count(*) FROM DEPARTMENT WHERE Division = "AS" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the phones of departments in Room 268? # ### SQL: # # SELECT DPhone FROM DEPARTMENT WHERE Room = 268 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Give the phones for departments in room 268. # ### SQL: # # SELECT DPhone FROM DEPARTMENT WHERE Room = 268 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the number of students that have at least one grade "B". # ### SQL: # # SELECT COUNT(DISTINCT StuID) FROM ENROLLED_IN WHERE Grade = "B" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # How many students have had at least one "B" grade? # ### SQL: # # SELECT COUNT(DISTINCT StuID) FROM ENROLLED_IN WHERE Grade = "B" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the max and min grade point for all letter grade. # ### SQL: # # SELECT max(gradepoint) , min(gradepoint) FROM GRADECONVERSION # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the maximum and minumum grade points? # ### SQL: # # SELECT max(gradepoint) , min(gradepoint) FROM GRADECONVERSION # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the first names of students whose first names contain letter "a". # ### SQL: # # SELECT DISTINCT Fname FROM STUDENT WHERE Fname LIKE '%a%' # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the first names for students who have an "a" in their first name? # ### SQL: # # SELECT DISTINCT Fname FROM STUDENT WHERE Fname LIKE '%a%' # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the first names and last names of male (sex is M) faculties who live in building NEB. # ### SQL: # # SELECT Fname , Lname FROM FACULTY WHERE sex = "M" AND Building = "NEB" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the full names of faculties with sex M and who live in building NEB? # ### SQL: # # SELECT Fname , Lname FROM FACULTY WHERE sex = "M" AND Building = "NEB" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the rooms of faculties with rank professor who live in building NEB. # ### SQL: # # SELECT Room FROM FACULTY WHERE Rank = "Professor" AND Building = "NEB" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the rooms for members of the faculty who are professors and who live in building NEB? # ### SQL: # # SELECT Room FROM FACULTY WHERE Rank = "Professor" AND Building = "NEB" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the department name that is in Building "Mergenthaler". # ### SQL: # # SELECT DName FROM DEPARTMENT WHERE Building = "Mergenthaler" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What is the name of the department in the Building Mergenthaler? # ### SQL: # # SELECT DName FROM DEPARTMENT WHERE Building = "Mergenthaler" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # List all information about courses sorted by credits in the ascending order. # ### SQL: # # SELECT * FROM COURSE ORDER BY Credits # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What is all the information about courses, ordered by credits ascending? # ### SQL: # # SELECT * FROM COURSE ORDER BY Credits # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # List the course name of courses sorted by credits. # ### SQL: # # SELECT CName FROM COURSE ORDER BY Credits # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the course names, ordered by credits? # ### SQL: # # SELECT CName FROM COURSE ORDER BY Credits # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the first name of students in the descending order of age. # ### SQL: # # SELECT Fname FROM STUDENT ORDER BY Age DESC # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the first names of students, ordered by age from greatest to least? # ### SQL: # # SELECT Fname FROM STUDENT ORDER BY Age DESC # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the last name of female (sex is F) students in the descending order of age. # ### SQL: # # SELECT LName FROM STUDENT WHERE Sex = "F" ORDER BY Age DESC # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the last names of female students, ordered by age descending? # ### SQL: # # SELECT LName FROM STUDENT WHERE Sex = "F" ORDER BY Age DESC # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the last names of faculties in building Barton in alphabetic order. # ### SQL: # # SELECT Lname FROM FACULTY WHERE Building = "Barton" ORDER BY Lname # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the last names of faculty in building Barton, sorted by last name? # ### SQL: # # SELECT Lname FROM FACULTY WHERE Building = "Barton" ORDER BY Lname # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the first names of faculties of rank Professor in alphabetic order. # ### SQL: # # SELECT Fname FROM FACULTY WHERE Rank = "Professor" ORDER BY Fname # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the first names for all faculty professors, ordered by first name? # ### SQL: # # SELECT Fname FROM FACULTY WHERE Rank = "Professor" ORDER BY Fname # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the name of the department that has the biggest number of students minored in? # ### SQL: # # SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What is the name of the department with the most students minoring in it? # ### SQL: # # SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY count(*) DESC LIMIT 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the name of the department that has no students minored in? # ### SQL: # # SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What is the name of the department htat has no students minoring in it? # ### SQL: # # SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the name of the department that has the fewest members. # ### SQL: # # SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What is the name of the department with the fewest members? # ### SQL: # # SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY count(*) ASC LIMIT 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the rank of the faculty that the fewest faculties belong to. # ### SQL: # # SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What is the least common faculty rank? # ### SQL: # # SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY count(*) ASC LIMIT 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the first and last names of the instructors who teach the top 3 number of courses? # ### SQL: # # SELECT T2.Fname , T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the full names of the 3 instructors who teach the most courses? # ### SQL: # # SELECT T2.Fname , T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 3 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Which building does the instructor who teaches the most number of courses live in? # ### SQL: # # SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Give the building that the instructor who teaches the greatest number of courses lives in. # ### SQL: # # SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY count(*) DESC LIMIT 1 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the name of courses that have at least five enrollments? # ### SQL: # # SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID = T2.CID GROUP BY T2.CID HAVING COUNT(*) >= 5 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Give the names of the courses with at least five enrollments. # ### SQL: # # SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID = T2.CID GROUP BY T2.CID HAVING COUNT(*) >= 5 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the first name and last name of the instructor of course that has course name # ### SQL: # # SELECT T2.Fname , T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID WHERE T1.CName = "COMPUTER LITERACY" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What is the full name of the instructor who has a course named COMPUTER LITERACY? # ### SQL: # # SELECT T2.Fname , T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID WHERE T1.CName = "COMPUTER LITERACY" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the department name and room of the course INTRODUCTION TO COMPUTER SCIENCE. # ### SQL: # # SELECT T2.Dname , T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO = T2.DNO WHERE T1.CName = "INTRODUCTION TO COMPUTER SCIENCE" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the department name and room for the course INTRODUCTION TO COMPUTER SCIENCE? # ### SQL: # # SELECT T2.Dname , T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO = T2.DNO WHERE T1.CName = "INTRODUCTION TO COMPUTER SCIENCE" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the student first and last names and grade points of all enrollments. # ### SQL: # # SELECT T3.Fname , T3.LName , T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the full names and gradepoints for all enrollments? # ### SQL: # # SELECT T3.Fname , T3.LName , T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the distinct student first names of all students that have grade point at least 3.8 in one course. # ### SQL: # # SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T2.gradepoint >= 3.8 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the distinct first names for students with a grade point of 3.8 or above in at least one course? # ### SQL: # # SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T2.gradepoint >= 3.8 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the full names of faculties who are members of department with department number 520. # ### SQL: # # SELECT T1.Fname , T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID = T2.FacID WHERE T2.DNO = 520 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the full names of faculty members who are a part of department 520? # ### SQL: # # SELECT T1.Fname , T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID = T2.FacID WHERE T2.DNO = 520 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the first names and last names of the students that minor in the department with DNO 140. # ### SQL: # # SELECT T2.Fname , T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID = T2.StuID WHERE T1.DNO = 140 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the full names of students minoring in department 140? # ### SQL: # # SELECT T2.Fname , T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID = T2.StuID WHERE T1.DNO = 140 # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the last names of faculties who are members of computer science department. # ### SQL: # # SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO = T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID = T3.FacID WHERE T1.DName = "Computer Science" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # What are the last names of faculty who are part of the computer science department? # ### SQL: # # SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO = T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID = T3.FacID WHERE T1.DName = "Computer Science" # ### End.
college_3	### Complete SQL query only and with no explanation ### SQL tables followed by foreign key information: # # Student ( StuID, LName, Fname, Age, Sex, Major, Advisor, city_code ) # Faculty ( FacID, Lname, Fname, Rank, Sex, Phone, Room, Building ) # Department ( DNO, Division, DName, Room, Building, DPhone ) # Member_of ( FacID, DNO, Appt_Type ) # Course ( CID, CName, Credits, Instructor, Days, Hours, DNO ) # Minor_in ( StuID, DNO ) # Enrolled_in ( StuID, CID, Grade ) # Gradeconversion ( lettergrade, gradepoint ) # # Member_of.DNO can be joined with Department.DNO # Member_of.FacID can be joined with Faculty.FacID # Course.DNO can be joined with Department.DNO # Course.Instructor can be joined with Faculty.FacID # Minor_in.DNO can be joined with Department.DNO # Minor_in.StuID can be joined with Student.StuID # Enrolled_in.Grade can be joined with Gradeconversion.lettergrade # Enrolled_in.CID can be joined with Course.CID # Enrolled_in.StuID can be joined with Student.StuID # ### Question: # # Find the average grade point of student whose last name is Smith. # ### SQL: # # SELECT avg(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T3.LName = "Smith" # ### End.

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