db_name
stringclasses 146
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|---|---|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the id of the customer who made the most orders.
#
### SQL:
#
# SELECT T1.customer_id FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Give me a list of id and status of orders which belong to the customer named "Jeramie".
#
### SQL:
#
# SELECT T2.order_id , T2.order_status FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.customer_name = "Jeramie"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which orders are made by the customer named "Jeramie"? Give me the order ids and status.
#
### SQL:
#
# SELECT T2.order_id , T2.order_status FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.customer_name = "Jeramie"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the dates of orders which belong to the customer named "Jeramie".
#
### SQL:
#
# SELECT T2.date_order_placed FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.customer_name = "Jeramie"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What are the dates of the orders made by the customer named "Jeramie"?
#
### SQL:
#
# SELECT T2.date_order_placed FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T1.customer_name = "Jeramie"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Give me the names of customers who have placed orders between 2009-01-01 and 2010-01-01.
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.date_order_placed >= "2009-01-01" AND T2.date_order_placed <= "2010-01-01"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which customers made orders between 2009-01-01 and 2010-01-01? Find their names.
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.date_order_placed >= "2009-01-01" AND T2.date_order_placed <= "2010-01-01"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Give me a list of distinct product ids from orders placed between 1975-01-01 and 1976-01-01?
#
### SQL:
#
# SELECT DISTINCT T2.product_id FROM orders AS T1 JOIN order_items AS T2 ON T1.order_id = T2.order_id WHERE T1.date_order_placed >= "1975-01-01" AND T1.date_order_placed <= "1976-01-01"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What are the distinct ids of products ordered between 1975-01-01 and 1976-01-01??
#
### SQL:
#
# SELECT DISTINCT T2.product_id FROM orders AS T1 JOIN order_items AS T2 ON T1.order_id = T2.order_id WHERE T1.date_order_placed >= "1975-01-01" AND T1.date_order_placed <= "1976-01-01"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the names of the customers who have order status both "On Road" and "Shipped".
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road" INTERSECT SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Shipped"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which customers have both "On Road" and "Shipped" as order status? List the customer names.
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road" INTERSECT SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Shipped"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the id of the customers who have order status both "On Road" and "Shipped".
#
### SQL:
#
# SELECT T1.customer_id FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road" INTERSECT SELECT T1.customer_id FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Shipped"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which customers have both "On Road" and "Shipped" as order status? List the customer ids.
#
### SQL:
#
# SELECT T1.customer_id FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "On Road" INTERSECT SELECT T1.customer_id FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status = "Shipped"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# When was the order placed whose shipment tracking number is 3452? Give me the date.
#
### SQL:
#
# SELECT T1.date_order_placed FROM orders AS T1 JOIN shipments AS T2 ON T1.order_id = T2.order_id WHERE T2.shipment_tracking_number = 3452
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# On which day was the order placed whose shipment tracking number is 3452?
#
### SQL:
#
# SELECT T1.date_order_placed FROM orders AS T1 JOIN shipments AS T2 ON T1.order_id = T2.order_id WHERE T2.shipment_tracking_number = 3452
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What is the placement date of the order whose invoice number is 10?
#
### SQL:
#
# SELECT T1.date_order_placed FROM orders AS T1 JOIN shipments AS T2 ON T1.order_id = T2.order_id WHERE T2.invoice_number = 10
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# On what day was the order with invoice number 10 placed?
#
### SQL:
#
# SELECT T1.date_order_placed FROM orders AS T1 JOIN shipments AS T2 ON T1.order_id = T2.order_id WHERE T2.invoice_number = 10
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# List the count and id of each product in all the orders.
#
### SQL:
#
# SELECT count(*) , T3.product_id FROM orders AS T1 JOIN order_items AS T2 JOIN products AS T3 ON T1.order_id = T2.order_id AND T2.product_id = T3.product_id GROUP BY T3.product_id
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# For each product, return its id and the number of times it was ordered.
#
### SQL:
#
# SELECT count(*) , T3.product_id FROM orders AS T1 JOIN order_items AS T2 JOIN products AS T3 ON T1.order_id = T2.order_id AND T2.product_id = T3.product_id GROUP BY T3.product_id
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# List the name and count of each product in all orders.
#
### SQL:
#
# SELECT T3.product_name , count(*) FROM orders AS T1 JOIN order_items AS T2 JOIN products AS T3 ON T1.order_id = T2.order_id AND T2.product_id = T3.product_id GROUP BY T3.product_id
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# For each product, show its name and the number of times it was ordered.
#
### SQL:
#
# SELECT T3.product_name , count(*) FROM orders AS T1 JOIN order_items AS T2 JOIN products AS T3 ON T1.order_id = T2.order_id AND T2.product_id = T3.product_id GROUP BY T3.product_id
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the ids of orders which are shipped after 2000-01-01.
#
### SQL:
#
# SELECT order_id FROM shipments WHERE shipment_date > "2000-01-01"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which orders have shipment after 2000-01-01? Give me the order ids.
#
### SQL:
#
# SELECT order_id FROM shipments WHERE shipment_date > "2000-01-01"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the id of the order which is shipped most recently.
#
### SQL:
#
# SELECT order_id FROM shipments WHERE shipment_date = (SELECT max(shipment_date) FROM shipments)
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which order has the most recent shipment? Give me the order id.
#
### SQL:
#
# SELECT order_id FROM shipments WHERE shipment_date = (SELECT max(shipment_date) FROM shipments)
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# List the names of all distinct products in alphabetical order.
#
### SQL:
#
# SELECT DISTINCT product_name FROM products ORDER BY product_name
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Sort all the distinct products in alphabetical order.
#
### SQL:
#
# SELECT DISTINCT product_name FROM products ORDER BY product_name
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# List the ids of all distinct orders ordered by placed date.
#
### SQL:
#
# SELECT DISTINCT order_id FROM orders ORDER BY date_order_placed
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What are ids of the all distinct orders, sorted by placement date?
#
### SQL:
#
# SELECT DISTINCT order_id FROM orders ORDER BY date_order_placed
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What is the id of the order which has the most items?
#
### SQL:
#
# SELECT T1.order_id FROM orders AS T1 JOIN order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id ORDER BY count(*) DESC LIMIT 1
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which order deals with the most items? Return the order id.
#
### SQL:
#
# SELECT T1.order_id FROM orders AS T1 JOIN order_items AS T2 ON T1.order_id = T2.order_id GROUP BY T1.order_id ORDER BY count(*) DESC LIMIT 1
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What is the name of the customer who has the largest number of orders?
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the name of the customer who made the most orders.
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY count(*) DESC LIMIT 1
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the invoice numbers which are created before 1989-09-03 or after 2007-12-25.
#
### SQL:
#
# SELECT invoice_number FROM invoices WHERE invoice_date < "1989-09-03" OR invoice_date > "2007-12-25"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What are the invoice numbers created before 1989-09-03 or after 2007-12-25?
#
### SQL:
#
# SELECT invoice_number FROM invoices WHERE invoice_date < "1989-09-03" OR invoice_date > "2007-12-25"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the distinct details of invoices which are created before 1989-09-03 or after 2007-12-25.
#
### SQL:
#
# SELECT DISTINCT invoice_details FROM invoices WHERE invoice_date < "1989-09-03" OR invoice_date > "2007-12-25"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What are the distinct details of invoices created before 1989-09-03 or after 2007-12-25?
#
### SQL:
#
# SELECT DISTINCT invoice_details FROM invoices WHERE invoice_date < "1989-09-03" OR invoice_date > "2007-12-25"
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# For each customer who has at least two orders, find the customer name and number of orders made.
#
### SQL:
#
# SELECT T2.customer_name , count(*) FROM orders AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.customer_id HAVING count(*) >= 2
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which customers have made at least two orders? Give me each customer name and number of orders made.
#
### SQL:
#
# SELECT T2.customer_name , count(*) FROM orders AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.customer_id HAVING count(*) >= 2
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Find the name of the customers who have at most two orders.
#
### SQL:
#
# SELECT T2.customer_name FROM orders AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.customer_id HAVING count(*) <= 2
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What are the names of the customers who have made two or less orders?
#
### SQL:
#
# SELECT T2.customer_name FROM orders AS T1 JOIN customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.customer_id HAVING count(*) <= 2
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# List the names of the customers who have once bought product "food".
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 JOIN order_items AS T3 JOIN products AS T4 ON T1.customer_id = T2.customer_id AND T2.order_id = T3.order_id AND T3.product_id = T4.product_id WHERE T4.product_name = "food" GROUP BY T1.customer_id HAVING count(*) >= 1
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# What are the names of the customers who bought product "food" at least once?
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 JOIN order_items AS T3 JOIN products AS T4 ON T1.customer_id = T2.customer_id AND T2.order_id = T3.order_id AND T3.product_id = T4.product_id WHERE T4.product_name = "food" GROUP BY T1.customer_id HAVING count(*) >= 1
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# List the names of customers who have once canceled the purchase of the product "food" (the item status is "Cancel").
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 JOIN order_items AS T3 JOIN products AS T4 ON T1.customer_id = T2.customer_id AND T2.order_id = T3.order_id AND T3.product_id = T4.product_id WHERE T3.order_item_status = "Cancel" AND T4.product_name = "food" GROUP BY T1.customer_id HAVING count(*) >= 1
#
### End.
|
tracking_orders
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# Customers ( customer_id, customer_name, customer_details )
# Invoices ( invoice_number, invoice_date, invoice_details )
# Orders ( order_id, customer_id, order_status, date_order_placed, order_details )
# Products ( product_id, product_name, product_details )
# Order_Items ( order_item_id, product_id, order_id, order_item_status, order_item_details )
# Shipments ( shipment_id, order_id, invoice_number, shipment_tracking_number, shipment_date, other_shipment_details )
# Shipment_Items ( shipment_id, order_item_id )
#
# Orders.customer_id can be joined with Customers.customer_id
# Order_Items.product_id can be joined with Products.product_id
# Order_Items.order_id can be joined with Orders.order_id
# Shipments.invoice_number can be joined with Invoices.invoice_number
# Shipments.order_id can be joined with Orders.order_id
# Shipment_Items.shipment_id can be joined with Shipments.shipment_id
# Shipment_Items.order_item_id can be joined with Order_Items.order_item_id
#
### Question:
#
# Which customers have ever canceled the purchase of the product "food" (the item status is "Cancel")?
#
### SQL:
#
# SELECT T1.customer_name FROM customers AS T1 JOIN orders AS T2 JOIN order_items AS T3 JOIN products AS T4 ON T1.customer_id = T2.customer_id AND T2.order_id = T3.order_id AND T3.product_id = T4.product_id WHERE T3.order_item_status = "Cancel" AND T4.product_name = "food" GROUP BY T1.customer_id HAVING count(*) >= 1
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# How many architects are female?
#
### SQL:
#
# SELECT count(*) FROM architect WHERE gender = 'female'
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# List the name, nationality and id of all male architects ordered by their names lexicographically.
#
### SQL:
#
# SELECT name , nationality , id FROM architect WHERE gender = 'male' ORDER BY name
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What is the maximum length in meters for the bridges and what are the architects' names?
#
### SQL:
#
# SELECT max(T1.length_meters) , T2.name FROM bridge AS T1 JOIN architect AS T2 ON T1.architect_id = T2.id
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What is the average length in feet of the bridges?
#
### SQL:
#
# SELECT avg(length_feet) FROM bridge
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What are the names and year of construction for the mills of 'Grondzeiler' type?
#
### SQL:
#
# SELECT name , built_year FROM mill WHERE TYPE = 'Grondzeiler'
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What are the distinct names and nationalities of the architects who have ever built a mill?
#
### SQL:
#
# SELECT DISTINCT T1.name , T1.nationality FROM architect AS T1 JOIN mill AS t2 ON T1.id = T2.architect_id
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What are the names of the mills which are not located in 'Donceel'?
#
### SQL:
#
# SELECT name FROM mill WHERE LOCATION != 'Donceel'
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What are the distinct types of mills that are built by American or Canadian architects?
#
### SQL:
#
# SELECT DISTINCT T1.type FROM mill AS T1 JOIN architect AS t2 ON T1.architect_id = T2.id WHERE T2.nationality = 'American' OR T2.nationality = 'Canadian'
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What are the ids and names of the architects who built at least 3 bridges ?
#
### SQL:
#
# SELECT T1.id , T1.name FROM architect AS T1 JOIN bridge AS T2 ON T1.id = T2.architect_id GROUP BY T1.id HAVING count(*) >= 3
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What is the id, name and nationality of the architect who built most mills?
#
### SQL:
#
# SELECT T1.id , T1.name , T1.nationality FROM architect AS T1 JOIN mill AS T2 ON T1.id = T2.architect_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What are the ids, names and genders of the architects who built two bridges or one mill?
#
### SQL:
#
# SELECT T1.id , T1.name , T1.gender FROM architect AS T1 JOIN bridge AS T2 ON T1.id = T2.architect_id GROUP BY T1.id HAVING count(*) = 2 UNION SELECT T1.id , T1.name , T1.gender FROM architect AS T1 JOIN mill AS T2 ON T1.id = T2.architect_id GROUP BY T1.id HAVING count(*) = 1
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What is the location of the bridge named 'Kolob Arch' or 'Rainbow Bridge'?
#
### SQL:
#
# SELECT LOCATION FROM bridge WHERE name = 'Kolob Arch' OR name = 'Rainbow Bridge'
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# Which of the mill names contains the french word 'Moulin'?
#
### SQL:
#
# SELECT name FROM mill WHERE name LIKE '%Moulin%'
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What are the distinct name of the mills built by the architects who have also built a bridge longer than 80 meters?
#
### SQL:
#
# SELECT DISTINCT T1.name FROM mill AS T1 JOIN architect AS t2 ON T1.architect_id = T2.id JOIN bridge AS T3 ON T3.architect_id = T2.id WHERE T3.length_meters > 80
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# What is the most common mill type, and how many are there?
#
### SQL:
#
# SELECT TYPE , count(*) FROM mill GROUP BY TYPE ORDER BY count(*) DESC LIMIT 1
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# How many architects haven't built a mill before year 1850?
#
### SQL:
#
# SELECT count(*) FROM architect WHERE id NOT IN ( SELECT architect_id FROM mill WHERE built_year < 1850 );
#
### End.
|
architecture
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# architect ( id, name, nationality, gender )
# bridge ( architect_id, id, name, location, length_meters, length_feet )
# mill ( architect_id, id, location, name, type, built_year, notes )
#
# bridge.architect_id can be joined with architect.id
# mill.architect_id can be joined with architect.id
#
### Question:
#
# show the name of all bridges that was designed by american archtect, and sort the result by the bridge feet length.
#
### SQL:
#
# SELECT t1.name FROM bridge AS t1 JOIN architect AS t2 ON t1.architect_id = t2.id WHERE t2.nationality = 'American' ORDER BY t1.length_feet
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# How many book clubs are there?
#
### SQL:
#
# SELECT count(*) FROM book_club
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Count the number of book clubs.
#
### SQL:
#
# SELECT count(*) FROM book_club
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# show the titles, and authors or editors for all books made after the year 1989.
#
### SQL:
#
# SELECT book_title , author_or_editor FROM book_club WHERE YEAR > 1989
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What are the titles and authors or editors that correspond to books made after 1989?
#
### SQL:
#
# SELECT book_title , author_or_editor FROM book_club WHERE YEAR > 1989
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show all distinct publishers for books.
#
### SQL:
#
# SELECT DISTINCT publisher FROM book_club
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What are all the different book publishers?
#
### SQL:
#
# SELECT DISTINCT publisher FROM book_club
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show the years, book titles, and publishers for all books, in descending order by year.
#
### SQL:
#
# SELECT YEAR , book_title , publisher FROM book_club ORDER BY YEAR DESC
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What are the years, titles, and publishers for all books, ordered by year descending?
#
### SQL:
#
# SELECT YEAR , book_title , publisher FROM book_club ORDER BY YEAR DESC
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show all publishers and the number of books for each publisher.
#
### SQL:
#
# SELECT publisher , count(*) FROM book_club GROUP BY publisher
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# How many books are there for each publisher?
#
### SQL:
#
# SELECT publisher , count(*) FROM book_club GROUP BY publisher
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What is the publisher with most number of books?
#
### SQL:
#
# SELECT publisher FROM book_club GROUP BY publisher ORDER BY count(*) DESC LIMIT 1
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Return the publisher that has published the most books.
#
### SQL:
#
# SELECT publisher FROM book_club GROUP BY publisher ORDER BY count(*) DESC LIMIT 1
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show all book categories and the number of books in each category.
#
### SQL:
#
# SELECT category , count(*) FROM book_club GROUP BY category
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# How many books fall into each category?
#
### SQL:
#
# SELECT category , count(*) FROM book_club GROUP BY category
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# List categories that have at least two books after year 1989.
#
### SQL:
#
# SELECT category FROM book_club WHERE YEAR > 1989 GROUP BY category HAVING count(*) >= 2
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What categories have two or more corresponding books that were made after 1989?
#
### SQL:
#
# SELECT category FROM book_club WHERE YEAR > 1989 GROUP BY category HAVING count(*) >= 2
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show publishers with a book published in 1989 and a book in 1990.
#
### SQL:
#
# SELECT publisher FROM book_club WHERE YEAR = 1989 INTERSECT SELECT publisher FROM book_club WHERE YEAR = 1990
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What are the publishers who have published a book in both 1989 and 1990?
#
### SQL:
#
# SELECT publisher FROM book_club WHERE YEAR = 1989 INTERSECT SELECT publisher FROM book_club WHERE YEAR = 1990
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show all publishers which do not have a book in 1989.
#
### SQL:
#
# SELECT publisher FROM book_club EXCEPT SELECT publisher FROM book_club WHERE YEAR = 1989
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Which publishers did not publish a book in 1989?
#
### SQL:
#
# SELECT publisher FROM book_club EXCEPT SELECT publisher FROM book_club WHERE YEAR = 1989
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show all movie titles, years, and directors, ordered by budget.
#
### SQL:
#
# SELECT title , YEAR , director FROM movie ORDER BY budget_million
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What are the titles, years, and directors of all movies, ordered by budget in millions?
#
### SQL:
#
# SELECT title , YEAR , director FROM movie ORDER BY budget_million
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# How many movie directors are there?
#
### SQL:
#
# SELECT COUNT (DISTINCT director) FROM movie
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Count the number of different directors.
#
### SQL:
#
# SELECT COUNT (DISTINCT director) FROM movie
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What is the title and director for the movie with highest worldwide gross in the year 2000 or before?
#
### SQL:
#
# SELECT title , director FROM movie WHERE YEAR <= 2000 ORDER BY gross_worldwide DESC LIMIT 1
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Return the title and director of the movie released in the year 2000 or earlier that had the highest worldwide gross.
#
### SQL:
#
# SELECT title , director FROM movie WHERE YEAR <= 2000 ORDER BY gross_worldwide DESC LIMIT 1
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show all director names who have a movie in both year 1999 and 2000.
#
### SQL:
#
# SELECT director FROM movie WHERE YEAR = 2000 INTERSECT SELECT director FROM movie WHERE YEAR = 1999
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Which directors had a movie both in the year 1999 and 2000?
#
### SQL:
#
# SELECT director FROM movie WHERE YEAR = 2000 INTERSECT SELECT director FROM movie WHERE YEAR = 1999
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show all director names who have a movie in the year 1999 or 2000.
#
### SQL:
#
# SELECT director FROM movie WHERE YEAR = 1999 OR YEAR = 2000
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Which directors had a movie in either 1999 or 2000?
#
### SQL:
#
# SELECT director FROM movie WHERE YEAR = 1999 OR YEAR = 2000
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What is the average, maximum, and minimum budget for all movies before 2000.
#
### SQL:
#
# SELECT avg(budget_million) , max(budget_million) , min(budget_million) FROM movie WHERE YEAR < 2000
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Return the average, maximum, and minimum budgets in millions for movies made before the year 2000.
#
### SQL:
#
# SELECT avg(budget_million) , max(budget_million) , min(budget_million) FROM movie WHERE YEAR < 2000
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# List all company names with a book published by Alyson.
#
### SQL:
#
# SELECT T1.company_name FROM culture_company AS T1 JOIN book_club AS T2 ON T1.book_club_id = T2.book_club_id WHERE T2.publisher = 'Alyson'
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What are all the company names that have a book published by Alyson?
#
### SQL:
#
# SELECT T1.company_name FROM culture_company AS T1 JOIN book_club AS T2 ON T1.book_club_id = T2.book_club_id WHERE T2.publisher = 'Alyson'
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show the movie titles and book titles for all companies in China.
#
### SQL:
#
# SELECT T1.title , T3.book_title FROM movie AS T1 JOIN culture_company AS T2 ON T1.movie_id = T2.movie_id JOIN book_club AS T3 ON T3.book_club_id = T2.book_club_id WHERE T2.incorporated_in = 'China'
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What are the titles of movies and books corresponding to companies incorporated in China?
#
### SQL:
#
# SELECT T1.title , T3.book_title FROM movie AS T1 JOIN culture_company AS T2 ON T1.movie_id = T2.movie_id JOIN book_club AS T3 ON T3.book_club_id = T2.book_club_id WHERE T2.incorporated_in = 'China'
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# Show all company names with a movie directed in year 1999.
#
### SQL:
#
# SELECT T2.company_name FROM movie AS T1 JOIN culture_company AS T2 ON T1.movie_id = T2.movie_id WHERE T1.year = 1999
#
### End.
|
culture_company
|
### Complete SQL query only and with no explanation
### SQL tables followed by foreign key information:
#
# book_club ( book_club_id, Year, Author_or_Editor, Book_Title, Publisher, Category, Result )
# movie ( movie_id, Title, Year, Director, Budget_million, Gross_worldwide )
# culture_company ( Company_name, Type, Incorporated_in, Group_Equity_Shareholding, book_club_id, movie_id )
#
# culture_company.movie_id can be joined with movie.movie_id
# culture_company.book_club_id can be joined with book_club.book_club_id
#
### Question:
#
# What are all company names that have a corresponding movie directed in the year 1999?
#
### SQL:
#
# SELECT T2.company_name FROM movie AS T1 JOIN culture_company AS T2 ON T1.movie_id = T2.movie_id WHERE T1.year = 1999
#
### End.
|
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