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stringlengths 65
1.8k
| suffix
stringclasses 839
values | solution
stringlengths 6
859
| test_cases
listlengths 0
100
| import_str
listlengths 0
1
| demos
listlengths 0
8
| entry_func
stringclasses 158
values | data_id
stringlengths 36
40
| doc_string
stringclasses 164
values | dataset_name
stringclasses 1
value | task_name
stringclasses 1
value | compare_func
listlengths 0
0
| src_lang
stringclasses 1
value | tgt_lang
stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
|
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L3_L4
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
|
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L3_L5
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
|
return word[i]
return ""
|
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L3_L6
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
|
return ""
|
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L3_L7
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
|
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L3_L8
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
|
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
for i in range(len(word)-2, 0, -1):
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L4_L4
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
|
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L4_L5
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
|
return word[i]
return ""
|
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L4_L6
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
|
return ""
|
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L4_L7
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
|
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L4_L8
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
|
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
if word[i] in vowels:
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L5_L5
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
|
return word[i]
return ""
|
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L5_L6
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
|
return ""
|
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L5_L7
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
|
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L5_L8
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
|
return word[i]
return ""
|
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L6_L6
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
|
return ""
|
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L6_L7
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
|
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L6_L8
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
|
return ""
|
return word[i]
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L7_L7
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
|
return word[i]
return ""
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L7_L8
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
"""
if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
|
return ""
|
[
[
"\"yogurt\"",
"\"u\""
],
[
"\"full\"",
"\"u\""
],
[
"\"easy\"",
"\"\""
],
[
"\"eAsy\"",
"\"\""
],
[
"\"ali\"",
"\"\""
],
[
"\"bad\"",
"\"a\""
],
[
"\"most\"",
"\"o\""
],
[
"\"ab\"",
"\"\""
],
[
"\"ba\"",
"\"\""
],
[
"\"quick\"",
"\"\""
],
[
"\"anime\"",
"\"i\""
],
[
"\"Asia\"",
"\"\""
],
[
"\"Above\"",
"\"o\""
]
] |
[] |
[
[
"\"yogurt\"",
"> \"u\""
],
[
"\"FULL\"",
"> \"U\""
],
[
"\"quick\"",
"> \"\""
],
[
"\"ab\"",
"> \"\""
]
] |
get_closest_vowel
|
MultiLineInfilling/HumanEval/118/L8_L8
|
You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condition.
You may assume that the given string contains English letter only.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L0
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L1
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L2
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L3
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L4
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L5
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L6
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L7
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
|
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L0_L13
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L1
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L2
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L3
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
val = val + 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L4
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L5
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L6
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L7
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
|
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L1_L13
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L2
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L3
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
val = val + 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L4
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
val = val + 1
else:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L5
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L6
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L7
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
|
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L2_L13
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L3
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
val = val + 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L4
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
val = val + 1
else:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L5
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
val = val + 1
else:
val = val - 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L6
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L7
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
|
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L3_L13
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val + 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L4
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val + 1
else:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L5
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val + 1
else:
val = val - 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L6
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val + 1
else:
val = val - 1
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L7
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
|
val = val + 1
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L4_L13
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
else:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L5_L5
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
else:
val = val - 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L5_L6
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
else:
val = val - 1
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L5_L7
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
else:
val = val - 1
if val < 0:
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L5_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L5_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L5_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L5_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
|
else:
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L5_L13
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val - 1
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L6_L6
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val - 1
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L6_L7
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val - 1
if val < 0:
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L6_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L6_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L6_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L6_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
|
val = val - 1
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L6_L13
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if val < 0:
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L7_L7
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if val < 0:
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L7_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if val < 0:
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L7_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L7_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L7_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
|
if val < 0:
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L7_L13
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
return False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L8_L8
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
return False
return True if val == 0 else False
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L8_L9
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L8_L11
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def match_parens(lst):
"""
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
"""
def check(s):
val = 0
for i in s:
if i == '(':
val = val + 1
else:
val = val - 1
if val < 0:
|
return 'Yes' if check(S1) or check(S2) else 'No'
|
return False
return True if val == 0 else False
S1 = lst[0] + lst[1]
S2 = lst[1] + lst[0]
|
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
],
[
"['(()(())', '())())']",
"'No'"
],
[
"[')())', '(()()(']",
"'Yes'"
],
[
"['(())))', '(()())((']",
"'Yes'"
],
[
"['()', '())']",
"'No'"
],
[
"['(()(', '()))()']",
"'Yes'"
],
[
"['((((', '((())']",
"'No'"
],
[
"[')(()', '(()(']",
"'No'"
],
[
"[')(', ')(']",
"'No'"
],
[
"['(', ')']",
"'Yes'"
],
[
"[')', '(']",
"'Yes'"
]
] |
[] |
[
[
"['()(', ')']",
"'Yes'"
],
[
"[')', ')']",
"'No'"
]
] |
match_parens
|
MultiLineInfilling/HumanEval/119/L8_L12
|
You are given a list of two strings, both strings consist of open
parentheses '(' or close parentheses ')' only.
Your job is to check if it is possible to concatenate the two strings in
some order, that the resulting string will be good.
A string S is considered to be good if and only if all parentheses in S
are balanced. For example: the string '(())()' is good, while the string
'())' is not.
Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
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