prefix
stringlengths 65
1.8k
| suffix
stringclasses 839
values | solution
stringlengths 6
859
| test_cases
listlengths 0
100
| import_str
listlengths 0
1
| demos
listlengths 0
8
| entry_func
stringclasses 158
values | data_id
stringlengths 36
40
| doc_string
stringclasses 164
values | dataset_name
stringclasses 1
value | task_name
stringclasses 1
value | compare_func
listlengths 0
0
| src_lang
stringclasses 1
value | tgt_lang
stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
|
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L8_L15
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
|
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
else:
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L9_L9
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
|
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
else:
new_distance = abs(elem - elem2)
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L9_L10
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
|
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L9_L11
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
|
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L9_L12
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
|
return closest_pair
|
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L9_L13
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
|
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L9_L15
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
|
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
new_distance = abs(elem - elem2)
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L10_L10
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
|
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
new_distance = abs(elem - elem2)
if new_distance < distance:
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L10_L11
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
|
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L10_L12
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
|
return closest_pair
|
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L10_L13
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
|
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L10_L15
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
|
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
if new_distance < distance:
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L11_L11
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
|
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
if new_distance < distance:
distance = new_distance
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L11_L12
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
|
return closest_pair
|
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L11_L13
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
|
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L11_L15
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
|
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
distance = new_distance
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L12_L12
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
|
return closest_pair
|
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L12_L13
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
|
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L12_L15
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
|
return closest_pair
|
closest_pair = tuple(sorted([elem, elem2]))
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L13_L13
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
|
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L13_L15
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
"""
closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
|
return closest_pair
|
[
[
"[1.0, 2.0, 3.9, 4.0, 5.0, 2.2]",
"(3.9, 4.0)"
],
[
"[1.0, 2.0, 5.9, 4.0, 5.0]",
"(5.0, 5.9)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
],
[
"[1.1, 2.2, 3.1, 4.1, 5.1]",
"(2.2, 3.1)"
]
] |
[
"from typing import List, Tuple"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.2]",
"(2.0, 2.2)"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0, 2.0]",
"(2.0, 2.0)"
]
] |
find_closest_elements
|
MultiLineInfilling/HumanEval/20/L15_L15
|
From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
"""
|
max_number = max(numbers)
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
min_number = min(numbers)
|
[
[
"[2.0, 49.9]",
"[0.0, 1.0]"
],
[
"[100.0, 49.9]",
"[1.0, 0.0]"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
],
[
"[2.0, 1.0, 5.0, 3.0, 4.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
],
[
"[12.0, 11.0, 15.0, 13.0, 14.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
]
] |
[
"from typing import List"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
]
] |
rescale_to_unit
|
MultiLineInfilling/HumanEval/21/L0_L0
|
Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
"""
|
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
min_number = min(numbers)
max_number = max(numbers)
|
[
[
"[2.0, 49.9]",
"[0.0, 1.0]"
],
[
"[100.0, 49.9]",
"[1.0, 0.0]"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
],
[
"[2.0, 1.0, 5.0, 3.0, 4.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
],
[
"[12.0, 11.0, 15.0, 13.0, 14.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
]
] |
[
"from typing import List"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
]
] |
rescale_to_unit
|
MultiLineInfilling/HumanEval/21/L0_L1
|
Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
"""
|
min_number = min(numbers)
max_number = max(numbers)
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
[
[
"[2.0, 49.9]",
"[0.0, 1.0]"
],
[
"[100.0, 49.9]",
"[1.0, 0.0]"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
],
[
"[2.0, 1.0, 5.0, 3.0, 4.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
],
[
"[12.0, 11.0, 15.0, 13.0, 14.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
]
] |
[
"from typing import List"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
]
] |
rescale_to_unit
|
MultiLineInfilling/HumanEval/21/L0_L2
|
Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
"""
min_number = min(numbers)
|
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
max_number = max(numbers)
|
[
[
"[2.0, 49.9]",
"[0.0, 1.0]"
],
[
"[100.0, 49.9]",
"[1.0, 0.0]"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
],
[
"[2.0, 1.0, 5.0, 3.0, 4.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
],
[
"[12.0, 11.0, 15.0, 13.0, 14.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
]
] |
[
"from typing import List"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
]
] |
rescale_to_unit
|
MultiLineInfilling/HumanEval/21/L1_L1
|
Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
"""
min_number = min(numbers)
|
max_number = max(numbers)
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
[
[
"[2.0, 49.9]",
"[0.0, 1.0]"
],
[
"[100.0, 49.9]",
"[1.0, 0.0]"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
],
[
"[2.0, 1.0, 5.0, 3.0, 4.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
],
[
"[12.0, 11.0, 15.0, 13.0, 14.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
]
] |
[
"from typing import List"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
]
] |
rescale_to_unit
|
MultiLineInfilling/HumanEval/21/L1_L2
|
Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
"""
min_number = min(numbers)
max_number = max(numbers)
|
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
[
[
"[2.0, 49.9]",
"[0.0, 1.0]"
],
[
"[100.0, 49.9]",
"[1.0, 0.0]"
],
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
],
[
"[2.0, 1.0, 5.0, 3.0, 4.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
],
[
"[12.0, 11.0, 15.0, 13.0, 14.0]",
"[0.25, 0.0, 1.0, 0.5, 0.75]"
]
] |
[
"from typing import List"
] |
[
[
"[1.0, 2.0, 3.0, 4.0, 5.0]",
"[0.0, 0.25, 0.5, 0.75, 1.0]"
]
] |
rescale_to_unit
|
MultiLineInfilling/HumanEval/21/L2_L2
|
Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List, Any
def filter_integers(values: List[Any]) -> List[int]:
""" Filter given list of any python values only for integers
"""
|
return [x for x in values if isinstance(x, int)]
|
[
[
"[]",
"[]"
],
[
"[4, {}, [], 23.2, 9, 'adasd']",
"[4, 9]"
],
[
"[3, 'c', 3, 3, 'a', 'b']",
"[3, 3, 3]"
]
] |
[
"from typing import List, Any"
] |
[
[
"['a', 3.14, 5]",
"[5]"
],
[
"[1, 2, 3, 'abc', {}, []]",
"[1, 2, 3]"
]
] |
filter_integers
|
MultiLineInfilling/HumanEval/22/L0_L0
|
Filter given list of any python values only for integers
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def strlen(string: str) -> int:
""" Return length of given string
"""
|
return len(string)
|
[
[
"''",
"0"
],
[
"'x'",
"1"
],
[
"'asdasnakj'",
"9"
]
] |
[] |
[
[
"''",
"0"
],
[
"'abc'",
"3"
]
] |
strlen
|
MultiLineInfilling/HumanEval/23/L0_L0
|
Return length of given string
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
"""
|
if n % i == 0:
return i
|
for i in reversed(range(n)):
|
[
[
"3",
"1"
],
[
"7",
"1"
],
[
"10",
"5"
],
[
"100",
"50"
],
[
"49",
"7"
]
] |
[] |
[
[
"15",
"5"
]
] |
largest_divisor
|
MultiLineInfilling/HumanEval/24/L0_L0
|
For a given number n, find the largest number that divides n evenly, smaller than n
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
"""
|
return i
|
for i in reversed(range(n)):
if n % i == 0:
|
[
[
"3",
"1"
],
[
"7",
"1"
],
[
"10",
"5"
],
[
"100",
"50"
],
[
"49",
"7"
]
] |
[] |
[
[
"15",
"5"
]
] |
largest_divisor
|
MultiLineInfilling/HumanEval/24/L0_L1
|
For a given number n, find the largest number that divides n evenly, smaller than n
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
"""
|
for i in reversed(range(n)):
if n % i == 0:
return i
|
[
[
"3",
"1"
],
[
"7",
"1"
],
[
"10",
"5"
],
[
"100",
"50"
],
[
"49",
"7"
]
] |
[] |
[
[
"15",
"5"
]
] |
largest_divisor
|
MultiLineInfilling/HumanEval/24/L0_L2
|
For a given number n, find the largest number that divides n evenly, smaller than n
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
"""
for i in reversed(range(n)):
|
return i
|
if n % i == 0:
|
[
[
"3",
"1"
],
[
"7",
"1"
],
[
"10",
"5"
],
[
"100",
"50"
],
[
"49",
"7"
]
] |
[] |
[
[
"15",
"5"
]
] |
largest_divisor
|
MultiLineInfilling/HumanEval/24/L1_L1
|
For a given number n, find the largest number that divides n evenly, smaller than n
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
"""
for i in reversed(range(n)):
|
if n % i == 0:
return i
|
[
[
"3",
"1"
],
[
"7",
"1"
],
[
"10",
"5"
],
[
"100",
"50"
],
[
"49",
"7"
]
] |
[] |
[
[
"15",
"5"
]
] |
largest_divisor
|
MultiLineInfilling/HumanEval/24/L1_L2
|
For a given number n, find the largest number that divides n evenly, smaller than n
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
"""
for i in reversed(range(n)):
if n % i == 0:
|
return i
|
[
[
"3",
"1"
],
[
"7",
"1"
],
[
"10",
"5"
],
[
"100",
"50"
],
[
"49",
"7"
]
] |
[] |
[
[
"15",
"5"
]
] |
largest_divisor
|
MultiLineInfilling/HumanEval/24/L2_L2
|
For a given number n, find the largest number that divides n evenly, smaller than n
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
import math
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L0
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
import math
fact = []
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L1
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
import math
fact = []
i = 2
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L2
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L3
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L4
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L5
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L6
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
i += 1
if n > 1:
fact.append(n)
return fact
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L7
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
if n > 1:
fact.append(n)
return fact
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L8
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
fact.append(n)
return fact
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L10
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
return fact
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L11
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
|
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L0_L12
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
fact = []
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L1
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
fact = []
i = 2
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L2
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L3
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L4
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L5
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L6
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
i += 1
if n > 1:
fact.append(n)
return fact
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L7
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
if n > 1:
fact.append(n)
return fact
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L8
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
fact.append(n)
return fact
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L10
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
return fact
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L11
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
|
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L1_L12
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
i = 2
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L2
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
i = 2
while i <= int(math.sqrt(n) + 1):
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L3
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L4
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L5
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L6
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
i += 1
if n > 1:
fact.append(n)
return fact
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L7
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
if n > 1:
fact.append(n)
return fact
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L8
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
fact.append(n)
return fact
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L10
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
return fact
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L11
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
|
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L2_L12
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
while i <= int(math.sqrt(n) + 1):
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L3
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L4
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L5
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L6
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
i += 1
if n > 1:
fact.append(n)
return fact
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L7
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
if n > 1:
fact.append(n)
return fact
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L8
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
fact.append(n)
return fact
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L10
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
return fact
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L11
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
|
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L3_L12
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
if n % i == 0:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L4_L4
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
if n % i == 0:
fact.append(i)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L4_L5
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
if n % i == 0:
fact.append(i)
n //= i
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L4_L6
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
i += 1
if n > 1:
fact.append(n)
return fact
|
if n % i == 0:
fact.append(i)
n //= i
else:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L4_L7
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
if n > 1:
fact.append(n)
return fact
|
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L4_L8
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
fact.append(n)
return fact
|
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L4_L10
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
return fact
|
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L4_L11
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
|
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L4_L12
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
fact.append(i)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L5_L5
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
fact.append(i)
n //= i
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L5_L6
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
i += 1
if n > 1:
fact.append(n)
return fact
|
fact.append(i)
n //= i
else:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L5_L7
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
if n > 1:
fact.append(n)
return fact
|
fact.append(i)
n //= i
else:
i += 1
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L5_L8
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
fact.append(n)
return fact
|
fact.append(i)
n //= i
else:
i += 1
if n > 1:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L5_L10
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
return fact
|
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L5_L11
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
|
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L5_L12
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
n //= i
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L6_L6
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
i += 1
if n > 1:
fact.append(n)
return fact
|
n //= i
else:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L6_L7
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
if n > 1:
fact.append(n)
return fact
|
n //= i
else:
i += 1
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L6_L8
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
fact.append(n)
return fact
|
n //= i
else:
i += 1
if n > 1:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L6_L10
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
return fact
|
n //= i
else:
i += 1
if n > 1:
fact.append(n)
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L6_L11
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
|
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L6_L12
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
|
from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
"""
import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
|
i += 1
if n > 1:
fact.append(n)
return fact
|
else:
|
[
[
"2",
"[2]"
],
[
"4",
"[2, 2]"
],
[
"8",
"[2, 2, 2]"
],
[
"3 * 19",
"[3, 19]"
],
[
"3 * 19 * 3 * 19",
"[3, 3, 19, 19]"
],
[
"3 * 19 * 3 * 19 * 3 * 19",
"[3, 3, 3, 19, 19, 19]"
],
[
"3 * 19 * 19 * 19",
"[3, 19, 19, 19]"
],
[
"3 * 2 * 3",
"[2, 3, 3]"
]
] |
[
"from typing import List"
] |
[
[
"8",
"[2, 2, 2]"
],
[
"25",
"[5, 5]"
],
[
"70",
"[2, 5, 7]"
]
] |
factorize
|
MultiLineInfilling/HumanEval/25/L7_L7
|
Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
|
HumanEval_MultiLineInfilling
|
code_infilling
|
[] |
python
|
python
|
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