test_cases
listlengths
0
100
import_str
listlengths
0
1
solution
stringlengths
0
620
suffix
stringlengths
0
655
tgt_lang
stringclasses
1 value
doc_string
stringclasses
164 values
compare_func
listlengths
0
0
prefix
stringlengths
65
1.63k
demos
listlengths
0
8
data_id
stringlengths
33
36
src_lang
stringclasses
1 value
task_name
stringclasses
1 value
dataset_name
stringclasses
1 value
entry_func
stringclasses
158 values
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
1: if i%2 == 1: odd += 1 for i in ls
t2: if i%2 == 0: even += 1 if even >= odd: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 for i in lst
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/1
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
r i in lst1: if i%2 == 1: odd += 1 for i in lst2: if i%2 == 0: even += 1 if even >= odd
: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 fo
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/2
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
in lst1: if i%2 == 1: odd += 1 for i in lst2:
if i%2 == 0: even += 1 if even >= odd: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 for i
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/3
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
in lst2: if i%2 == 0: even += 1 if even >=
odd: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 for i in lst1: if i%2 == 1: odd += 1 for i
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/4
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
odd += 1 for i in lst2: if i%2 == 0:
even += 1 if even >= odd: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 for i in lst1: if i%2 == 1:
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/5
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
in lst2: if i%2 == 0:
even += 1 if even >= odd: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 for i in lst1: if i%2 == 1: odd += 1 for i
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/6
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
odd += 1 for i in lst2: if i%2 ==
0: even += 1 if even >= odd: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 for i in lst1: if i%2 == 1:
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/7
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
return "YES" re
turn "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 for i in lst1: if i%2 == 1: odd += 1 for i in lst2: if i%2 == 0: even += 1 if even >= odd:
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/8
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
even = 0 for i in lst1:
if i%2 == 1: odd += 1 for i in lst2: if i%2 == 0: even += 1 if even >= odd: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/9
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ], [ "[1, 2, 3, 4], [2, 1, 4, 3]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 4]", "\"YES\"" ], [ "[5, 7, 3], [2, 6, 3]", "\"NO\"" ], [ "[3, 2, 6, 1, 8, 9], [3, 5, 5, 1, 1, 1]", "\"NO\"" ], [ "[100, 200], [200, 200]", "\"YES\"" ] ]
[]
== 1: odd += 1 for i in lst2: if i%2 == 0:
even += 1 if even >= odd: return "YES" return "NO"
python
In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO".
[]
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1 and lst2. If it is possible to exchange elements between the lst1 and lst2 to make all the elements of lst1 to be even, return "YES". Otherwise, return "NO". """ odd = 0 even = 0 for i in lst1: if i%2
[ [ "[1, 2, 3, 4], [1, 2, 3, 4]", "\"YES\"" ], [ "[1, 2, 3, 4], [1, 5, 3, 4]", "\"NO\"" ] ]
RandomSpanInfilling/HumanEval/110/10
python
code_infilling
HumanEval_RandomSpanInfilling
exchange
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
dict1={} list1=tes
t.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0: for i in list1: if(list1.count(i)==t): dict1[i]=t return dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/1
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
fo
r i in list1: if(list1.count(i)==t): dict1[i]=t return dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0:
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/2
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
dict1[i]=t return
dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0: for i in list1: if(list1.count(i)==t):
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/3
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
for i in list1: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0: for i in list1: if(list1.count
(i)==t): dict1[i]=t return dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/4
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
in list1
: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0: for i in list1: if(list1.count(i)==t): dict1[i]=t return dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0 for i
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/5
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
ount(i) if t>0: for i in list1: if(list1.count(i)==t): dict1[i]=t re
turn dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='': t=list1.c
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/6
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
: if(list1.count(i)==t):
dict1[i]=t return dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0: for i in list1
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/7
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
i!='': t=list1.count(i) if t>0: for i in list1: if(list1.count(i)==t): dict1[i]=t r
eturn dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/8
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
t=list1.count(i) if t>0: for i in list1: if(list1.count(i)==t):
dict1[i]=t return dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='':
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/9
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "'a b b a'", "{'a':2,'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'a b c d g'", "{'a': 1, 'b': 1, 'c': 1, 'd': 1, 'g': 1}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "'b b b b a'", "{'b': 4}" ], [ "'r t g'", "{'r': 1,'t': 1,'g': 1}" ], [ "''", "{}" ], [ "'a'", "{'a': 1}" ] ]
[]
for i in list1: if(list1.count(i)==t): dict1[i]=t return
dict1
python
Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them.
[]
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. """ dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0:
[ [ "'a b c'", "{'a': 1, 'b': 1, 'c': 1}" ], [ "'a b b a'", "{'a': 2, 'b': 2}" ], [ "'a b c a b'", "{'a': 2, 'b': 2}" ], [ "'b b b b a'", "{'b': 4}" ], [ "''", "{}" ] ]
RandomSpanInfilling/HumanEval/111/10
python
code_infilling
HumanEval_RandomSpanInfilling
histogram
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
not in c])
return (s,s[::-1] == s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s = ''.join([char for char in s if char
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/1
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
if char not in c]) return (s
,s[::-1] == s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s = ''.join([char for char in s
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/2
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
in s if char not in c]) return (s,s[::-1]
== s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s = ''.join([char for char
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/3
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
t in c])
return (s,s[::-1] == s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s = ''.join([char for char in s if char no
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/4
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
turn (s,s[::-1] ==
s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s = ''.join([char for char in s if char not in c]) re
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/5
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
r in s if char not in c])
return (s,s[::-1] == s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s = ''.join([char for cha
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/6
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
join
([char for char in s if char not in c]) return (s,s[::-1] == s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s = ''.
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/7
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
(
[char for char in s if char not in c]) return (s,s[::-1] == s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s = ''.join
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/8
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
''.
join([char for char in s if char not in c]) return (s,s[::-1] == s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """ s =
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/9
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "\"abcde\", \"ae\"", "('bcd',False)" ], [ "\"abcdef\", \"b\"", "('acdef',False)" ], [ "\"abcdedcba\", \"ab\"", "('cdedc',True)" ], [ "\"dwik\", \"w\"", "('dik',False)" ], [ "\"a\", \"a\"", "('',True)" ], [ "\"abcdedcba\", \"\"", "('abcdedcba',True)" ], [ "\"abcdedcba\", \"v\"", "('abcdedcba',True)" ], [ "\"vabba\", \"v\"", "('abba',True)" ], [ "\"mamma\", \"mia\"", "(\"\", True)" ] ]
[]
s = ''.join([char for char in s if char not in c]) return (s,s[::-1] == s)
python
Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check.
[]
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple containing the result string and True/False for the check. """
[ [ "'abcde', 'ae'", "('bcd', False)" ], [ "'abcdef', 'b'", "('acdef',False)" ], [ "'abcdedcba', 'ab'", "('cdedc',True)" ] ]
RandomSpanInfilling/HumanEval/112/10
python
code_infilling
HumanEval_RandomSpanInfilling
reverse_delete
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
st: n = sum(int(d)%2==1 for d in arr) res.append("the number of odd elements " + str(n) + "n the s
tr"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for arr in l
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/1
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
rr in lst: n = sum(int(d)%2==1 for d in arr) res.appe
nd("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for a
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/2
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
er of odd e
lements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for arr in lst: n = sum(int(d)%2==1 for d in arr) res.append("the numb
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/3
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
res = [] for arr in lst: n = sum(int(d)%2==1 for d in arr) res.append("the number of odd elem
ents " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/4
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
er of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return
res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for arr in lst: n = sum(int(d)%2==1 for d in arr) res.append("the numb
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/5
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
d in arr) res.append("the number o
f odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for arr in lst: n = sum(int(d)%2==1 for
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/6
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
st: n = sum(int(d)%2==1 for d in arr) res.append("the number of odd element
s " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for arr in l
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/7
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
res.append("the number of odd elements " + str(n) + "n the str"+
str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for arr in lst: n = sum(int(d)%2==1 for d in arr)
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/8
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
tr(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.
") return res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for arr in lst: n = sum(int(d)%2==1 for d in arr) res.append("the number of odd elements " + str(n) + "n the str"+ s
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/9
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\", \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]" ], [ "['271', '137', '314']", "[\n 'the number of odd elements 2n the str2ng 2 of the 2nput.',\n 'the number of odd elements 3n the str3ng 3 of the 3nput.',\n 'the number of odd elements 2n the str2ng 2 of the 2nput.'\n ]" ] ]
[]
retur
n res
python
Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input.
[]
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. """ res = [] for arr in lst: n = sum(int(d)%2==1 for d in arr) res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.")
[ [ "['1234567']", "[\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]" ], [ "['3',\"11111111\"]", "[\"the number of odd elements 1n the str1ng 1 of the 1nput.\"," ] ]
RandomSpanInfilling/HumanEval/113/10
python
code_infilling
HumanEval_RandomSpanInfilling
odd_count
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
or num in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_sum retur
n min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0 s = 0 f
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/1
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
s = 0 for num in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0:
max_sum = max(-i for i in nums) min_sum = -max_sum return min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/2
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) m
in_sum = -max_sum return min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0 s = 0 for num
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/3
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_sum
return min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0 s = 0 for num in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum)
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/4
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
um in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_sum
return min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0 s = 0 for n
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/5
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
x_sum = max(s, max_sum) if max_su
m == 0: max_sum = max(-i for i in nums) min_sum = -max_sum return min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0 s = 0 for num in nums: s += -num if (s < 0): s = 0 ma
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/6
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_sum return min_
sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0 s = 0 for num in nums: s += -num
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/7
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
s = 0
max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_sum return min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0 s = 0 for num in nums: s += -num if (s < 0):
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/8
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
max_sum = 0 s = 0 for num in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_s
um return min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/9
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ], [ "[-1, -2, -3, 2, -10]", "-14" ], [ "[-9999999999999999]", "-9999999999999999" ], [ "[0, 10, 20, 1000000]", "0" ], [ "[-1, -2, -3, 10, -5]", "-6" ], [ "[100, -1, -2, -3, 10, -5]", "-6" ], [ "[10, 11, 13, 8, 3, 4]", "3" ], [ "[100, -33, 32, -1, 0, -2]", "-33" ], [ "[-10]", "-10" ], [ "[7]", "7" ], [ "[1, -1]", "-1" ] ]
[]
nums)
min_sum = -max_sum return min_sum
python
Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums.
[]
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. """ max_sum = 0 s = 0 for num in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in
[ [ "[2, 3, 4, 1, 2, 4]", "1" ], [ "[-1, -2, -3]", "-6" ] ]
RandomSpanInfilling/HumanEval/114/10
python
code_infilling
HumanEval_RandomSpanInfilling
minSubArraySum
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
return
sum([math.ceil(sum(arr)/capacity) for arr in grid])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/1
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
r in grid]
)
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """ return sum([math.ceil(sum(arr)/capacity) for ar
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/2
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
eil
(sum(arr)/capacity) for arr in grid])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """ return sum([math.c
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/3
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
return sum([m
ath.ceil(sum(arr)/capacity) for arr in grid])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/4
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
eturn sum([math.ceil(sum(arr)/capacity) for arr i
n grid])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """ r
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/5
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
ceil(sum(arr)
/capacity) for arr in grid])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """ return sum([math.
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/6
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
([math.ceil(sum(arr)/capacit
y) for arr in grid])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """ return sum
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/7
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
ceil(sum(arr)/capacity) for arr in gri
d])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """ return sum([math.
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/8
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
apacity) for ar
r in grid])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """ return sum([math.ceil(sum(arr)/c
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/9
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ], [ "[[1,1,1,1], [1,1,1,1]], 2", "4" ], [ "[[1,1,1,1], [1,1,1,1]], 9", "2" ] ]
[ "import math" ]
sum([math.ceil(sum(arr)/capaci
ty) for arr in grid])
python
You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets.
[]
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capacity. Your task is to use the buckets to empty the wells. Output the number of times you need to lower the buckets. """ return
[ [ "[[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1", "6" ], [ "[[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2", "5" ], [ "[[0,0,0], [0,0,0]], 5", "0" ] ]
RandomSpanInfilling/HumanEval/115/10
python
code_infilling
HumanEval_RandomSpanInfilling
max_fill
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
x: bin
(x)[2:].count('1'))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ return sorted(sorted(arr), key=lambda
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/1
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
mbda x:
bin(x)[2:].count('1'))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ return sorted(sorted(arr), key=la
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/2
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
, key
=lambda x: bin(x)[2:].count('1'))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ return sorted(sorted(arr)
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/3
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
eturn sorted(sorted(arr)
, key=lambda x: bin(x)[2:].count('1'))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ r
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/4
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
turn sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1')
)
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ re
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/5
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
rted(sorted(arr), key=lambda x: bin(x)
[2:].count('1'))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ return so
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/6
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
ted(so
rted(arr), key=lambda x: bin(x)[2:].count('1'))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ return sor
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/7
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
=lambda x: bin(x)[2:].count('1'
))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ return sorted(sorted(arr), key
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/8
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
return sorted(sorted(arr), key
=lambda x: bin(x)[2:].count('1'))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/9
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "[1,5,2,3,4]", "[1, 2, 4, 3, 5]" ], [ "[-2,-3,-4,-5,-6]", "[-4, -2, -6, -5, -3]" ], [ "[1,0,2,3,4]", "[0, 1, 2, 4, 3]" ], [ "[]", "[]" ], [ "[2,5,77,4,5,3,5,7,2,3,4]", "[2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77]" ], [ "[3,6,44,12,32,5]", "[32, 3, 5, 6, 12, 44]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ], [ "[2,4,8,16,32]", "[2, 4, 8, 16, 32]" ] ]
[]
n sorted(s
orted(arr), key=lambda x: bin(x)[2:].count('1'))
python
In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value.
[]
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. """ retur
[ [ "[1, 5, 2, 3, 4]", "[1, 2, 3, 4, 5]" ], [ "[-2, -3, -4, -5, -6]", "[-6, -5, -4, -3, -2]" ] ]
RandomSpanInfilling/HumanEval/116/10
python
code_infilling
HumanEval_RandomSpanInfilling
sort_array
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
word in s.split(): n_consonants = 0 for i in range(0, len(word)): if word[i].lower() not in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) return resul
t
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/1
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
"]: n_consonants += 1 if n_consonants == n: result.a
ppend(word) return result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for word in s.split(): n_consonants = 0 for i in range(0, len(word)): if word[i].lower() not in ["a","e","i","o","u
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/2
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
len(word)): if word[i].lower() not in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) r
eturn result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for word in s.split(): n_consonants = 0 for i in range(0,
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/3
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
if word[i].lower() not in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n:
result.append(word) return result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for word in s.split(): n_consonants = 0 for i in range(0, len(word)):
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/4
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
word in s.split(): n_consonants = 0 for i in range(0, len(word)): if word[i].lower() not
in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) return result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/5
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
word in s.split(): n_consonants = 0 for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) return result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/6
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
fo
r i in range(0, len(word)): if word[i].lower() not in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) return result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for word in s.split(): n_consonants = 0
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/7
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
= [] for word in s.split(): n_consonants = 0 for i in range(0, len(word)): if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1 if n_consonants == n: result.append(word) return result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/8
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
en(word)): if word[i
].lower() not in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) return result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for word in s.split(): n_consonants = 0 for i in range(0, l
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/9
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"Mary had a little lamb\", 4", "[\"little\"]" ], [ "\"Mary had a little lamb\", 3", "[\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "[]" ], [ "\"Hello world\", 4", "[\"world\"]" ], [ "\"Uncle sam\", 3", "[\"Uncle\"]" ], [ "\"\", 4", "[]" ], [ "\"a b c d e f\", 1", "[\"b\", \"c\", \"d\", \"f\"]" ] ]
[]
0, len(word)): if word[i].lower() not
in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) return result
python
Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces.
[]
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an empty list. Note: you may assume the input string contains only letters and spaces. """ result = [] for word in s.split(): n_consonants = 0 for i in range(
[ [ "\"Mary had a little lamb\", 4", "> [\"little\"]" ], [ "\"Mary had a little lamb\", 3", "> [\"Mary\", \"lamb\"]" ], [ "\"simple white space\", 2", "> []" ], [ "\"Hello world\", 4", "> [\"world\"]" ], [ "\"Uncle sam\", 3", "> [\"Uncle\"]" ] ]
RandomSpanInfilling/HumanEval/117/10
python
code_infilling
HumanEval_RandomSpanInfilling
select_words
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
3:
return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) <
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/1
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
if wor
d[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) < 3: return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1):
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/2
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) < 3: return ""
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/3
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
"e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(w
ord)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) < 3: return "" vowels = {"a",
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/4
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] retu
rn ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) < 3: return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1):
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/5
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
if len(word) < 3: return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): re
turn word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/6
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
ord)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): ret
urn word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) < 3: return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(w
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/7
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) < 3: return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1): if word[i] in vowels:
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/8
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
"a", "e", "i", "o", "u", "A
", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) < 3: return "" vowels = {
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/9
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "\"yogurt\"", "\"u\"" ], [ "\"full\"", "\"u\"" ], [ "\"easy\"", "\"\"" ], [ "\"eAsy\"", "\"\"" ], [ "\"ali\"", "\"\"" ], [ "\"bad\"", "\"a\"" ], [ "\"most\"", "\"o\"" ], [ "\"ab\"", "\"\"" ], [ "\"ba\"", "\"\"" ], [ "\"quick\"", "\"\"" ], [ "\"anime\"", "\"i\"" ], [ "\"Asia\"", "\"\"" ], [ "\"Above\"", "\"o\"" ] ]
[]
, 'I'} for i in range(len(word)-2, 0, -1):
if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] return ""
python
You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only.
[]
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condition. You may assume that the given string contains English letter only. """ if len(word) < 3: return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U'
[ [ "\"yogurt\"", "> \"u\"" ], [ "\"FULL\"", "> \"U\"" ], [ "\"quick\"", "> \"\"" ], [ "\"ab\"", "> \"\"" ] ]
RandomSpanInfilling/HumanEval/118/10
python
code_infilling
HumanEval_RandomSpanInfilling
get_closest_vowel
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
1 if val < 0: return False return True if val == 0 else False S1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes' if chec
k(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s: if i == '(': val = val + 1 else: val = val -
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/1
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
return False return True if val == 0 else False S1 =
lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s: if i == '(': val = val + 1 else: val = val - 1 if val < 0:
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/2
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
val = val + 1 else: val = val - 1 if val < 0: return False return True if val == 0 else Fals
e S1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s: if i == '(':
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/3
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
al = val + 1 else: val = val - 1 if val < 0: return False return True if val == 0 else False S
1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s: if i == '(': v
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/4
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
al + 1 else: val = val - 1 if val < 0: return False return True if val == 0 else False S
1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s: if i == '(': val = v
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/5
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
for i in s: if i == '(': val = val + 1 else: val = val - 1 if val < 0: return False return True if val == 0 else False S1 = lst[0] +
lst[1] S2 = lst[1] + lst[0] return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/6
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
val + 1 else: val = val - 1 if val < 0: return False return True if val == 0 else False S1 = lst[0] + lst[1] S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s: if i == '(': val =
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/7
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
turn True if val == 0 else False S1 = lst[0] + lst[1] S2 = lst[1] + lst[0]
return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s: if i == '(': val = val + 1 else: val = val - 1 if val < 0: return False re
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/8
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
se: val = val - 1 if val < 0: return False return True
if val == 0 else False S1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s: if i == '(': val = val + 1 el
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/9
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ], [ "['(()(())', '())())']", "'No'" ], [ "[')())', '(()()(']", "'Yes'" ], [ "['(())))', '(()())((']", "'Yes'" ], [ "['()', '())']", "'No'" ], [ "['(()(', '()))()']", "'Yes'" ], [ "['((((', '((())']", "'No'" ], [ "[')(()', '(()(']", "'No'" ], [ "[')(', ')(']", "'No'" ], [ "['(', ')']", "'Yes'" ], [ "[')', '(']", "'Yes'" ] ]
[]
if i == '(': val = val + 1 else: val = val - 1 if val <
0: return False return True if val == 0 else False S1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes' if check(S1) or check(S2) else 'No'
python
You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.
[]
def match_parens(lst): """ You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be good if and only if all parentheses in S are balanced. For example: the string '(())()' is good, while the string '())' is not. Return 'Yes' if there's a way to make a good string, and return 'No' otherwise. """ def check(s): val = 0 for i in s:
[ [ "['()(', ')']", "'Yes'" ], [ "[')', ')']", "'No'" ] ]
RandomSpanInfilling/HumanEval/119/10
python
code_infilling
HumanEval_RandomSpanInfilling
match_parens