code string | generator string | label int64 | language string |
|---|---|---|---|
The code below passes all tests, but it is incomplete. Your job is to fill in the missing lines. Do not change anything else. If you do, it will not be graded.
def super_digit(n, k):
p = n*k
# Your code goes here
return x
if __name__ == '__main__':
first_multiple_input = input().rstrip().split()
... | Qwen/Qwen2.5-Coder-1.5B | 1 | Python |
To solve this problem, we need to determine if Polycarp can distribute `n` coins among his three sisters, Alice, Barbara, and Cerene, such that they all end up with the same number of coins.
Here's the step-by-step logic to solve this problem:
1. **Calculate the Target Coin Count:**
- First, find out the maximum n... | microsoft/Phi-3-medium-4k-instruct | 1 | Python |
N = int(input())
S = []
for _ in range(N):
s = input()
S.append(s)
class RollingHash:
def __init__(self, s, base=1007, mod=10 ** 9 + 7):
self.s = s
self.length = length = len(s)
self.base = base
self.mod = mod
self.h = h = [0] * (length + 1)
for i in range(length):
h[i + 1] = (h[i] * base + ord(s[i]... | human | 0 | Python |
class Solution {
public:
int minimizedMaximum(int n, vector<int>& quantities) {
int l = 1, r = 0;
for (int x : quantities) {
if (x > r) {
r = x;
}
}
while (l <= r) {
int m = (l + r) / 2;
int count = 0;
for (i... | human | 0 | C++ |
for function not including any explanation.
'''
def maximizing_score(n, m, a):
avg = sum(a) // n
a[0] = m
if sum(a) // n == avg:
return a[0]
a[0] = 0
for i in range(m, -1, -1):
a[0] = i
if sum(a) // n == avg:
return a[0]
if __name__ == "__main__":
t = int(i... | 01-ai/Yi-Coder-9B-Chat | 1 | Python |
, no explanations or text needed.
-
import sys
def min_light_radius(n, l, lanterns) -> float:
lanterns = sorted(lanterns)
light_radius = 0
max_dist = 0
for i in range(n-1):
dist = lanterns[i+1] - lanterns[i]
max_dist = max(max_dist, dist)
light_radius = max(light_radius, dist/... | microsoft/Phi-3-small-8k-instruct | 1 | Python |
from sys import stdin
inp = lambda : int(stdin.readline().strip())
lip = lambda : [int(i) for i in stdin.readline().strip().split(' ')]
sip = lambda : stdin.readline().strip()
for _ in range(inp()):
word = sip()
print(word if len(word) < 11 else word[0] + str(len(word) - 2) + word[-1])
| human | 0 | Python |
(W, H, N) = map(int, input().split())
b = 0
t = H
l = 0
r = W
for i in range(N):
(x, y, a) = map(int, input().split())
if a == 1:
l = max(l, x)
elif a == 2:
r = min(r, x)
elif a == 3:
b = max(b, y)
else:
assert a == 4
t = min(t, y)
print(max(t - b, 0) * max(r - l, 0))
| human | 0 | Python |
python
a=int(input())
for i in range(a):
first, second, third = map(int, input().split())
if first==0 or second==0 or third==0:
print(0)
elif first>=third or second>=third:
print(first+second+third)
else:
heap1=heap2=0
sum=0
while (second>=2)and(first>=1):
... | meta-llama/Llama-3.1-8B-Instruct | 1 | Python |
for i in range(int(input())):
n = int(input())
l1 = list(map(int, input().split()))
l2 = list(map(int, input().split()))
(val, r) = (0, 0)
for (x, y) in zip(l1, l2):
if x * y > val:
val = x * y
r = y
elif x * y == val:
if r < y:
r = y
else:
continue
print(l2.index(r) + 1)
| human | 0 | Python |
class Solution {
public int maxNumOfMarkedIndices(int[] nums) {
Arrays.sort(nums);
int n = nums.length;
int i = 0, j = n / 2;
int res = 0;
while (i < n / 2 && j < n) {
while (j < n && nums[j] < 2 * nums[i]) {
j++;
}
// Syste... | human | 0 | Java |
(n, k) = map(int, input().split())
a = list(map(int, input().split()))
info = [list(map(int, input().split())) for i in range(k)]
graph = [[] for i in range(n)]
for i in range(k):
(tmp_a, tmp_b) = info[i]
tmp_a -= 1
tmp_b -= 1
if a[tmp_a] == a[tmp_b]:
continue
if a[tmp_a] < a[tmp_b]:
(tmp_a, tmp_b) = (tmp_b, t... | human | 0 | Python |
def read():
(n, m) = map(int, input().split())
return (n, m)
def solve(n, m):
last = m % 10
p = [0] * 11
for i in range(1, 11):
p[i] = last * i % 10
dig_count = n // m
(full_rounds, rest) = divmod(dig_count, 10)
return full_rounds * sum(p[1:11]) + sum(p[1:rest + 1])
for t in range(int(input())):
result = so... | human | 0 | Python |
for i in range(n):
statement = input()
if statement == "++X":
x = x + 1
elif statement == "--X":
x = x - 1
print(x)
"""
#!/bin/python3
import math
import os
import random
import re
import sys
# Complete the solve function below.
def solve(n):
x = 0
for i in range(n):
stat... | microsoft/phi-2 | 1 | Python |
python
def check():
a, b, n, S = map(int, input().strip().split())
if a * n == S:
return 'YES'
elif (S - a * n) % n == 0 and (S - a * n) / n <= b:
return 'YES'
else:
return 'NO'
for i in range(int(input().strip())):
print(check()) | microsoft/Phi-3-small-8k-instruct | 1 | Python |
:
"""
def node: tuple
def linkedList(head):
s = ''
while (head):
s += str(head.data)
head = head.next
return int(s, 2) % 1000000007
if __name__ == '__main__':
for _ in range(int(input())):
n = int(input())
head = None
for _ in range(n):
data = int(in... | microsoft/Phi-3-small-8k-instruct | 1 | Python |
def fastio():
import sys
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
MOD = 10 ** 9 + 7
I = lambda : lis... | human | 0 | Python |
cpp
#include <iostream>
#include <numeric>
#include <fstream>
#include <math.h>
#include <queue>
#define maxx 1e9
#include <algorithm>
using namespace std;
long long m;
long N, A1;// A1 stores [60 90 9 ...]
bool c=0,t;
long long ans [327689]; | Qwen/Qwen2.5-Coder-1.5B | 1 | Python |
a = [int(f) for f in input().split(' ') if f]
b = [int(f) for f in input().split(' ') if f]
grid = [[(a[i] // x > k // b[i]) for x in range(1,max(max(a), k//min(b)))] for i in range(0,n)]
result = max(max(grid, grid.transpose(), key=lambda x: sum(x)))Using python 3.x,
Both codes give 10 - 100ms for 75% of _____'s test... | bigcode/starcoder2-15b | 1 | Python |
nstones = nstones_after = int(input())
previous = ''
for stone in input():
if previous == stone:
nstones_after -= 1
previous = stone
print(nstones - nstones_after)
| human | 0 | Python |
for C++
#include<bits/stdc++.h>
using namespace std;
int main(){
string s,t;
cin>>s>>t;
int n1=s.length();
for(int i=0;i<n1;i++){
for(int i=0;i<n1;i++){
if(s[i]==t[i]){
s=s.substr(0,i)+s.substr(i+1);
break;
}
}
}
int n2;
... | 01-ai/Yi-Coder-1.5B | 1 | Python |
class Solution:
def segregateEvenOdd(self, arr, n):
even = 0
odd = n - 1
while even < odd:
if arr[even] % 2 == 0:
even += 1
else:
(arr[even], arr[odd]) = (arr[odd], arr[even])
odd -= 1
arr.sort(key=lambda x: [x % 2, x])
return arr
| human | 0 | Python |
global a,b,x,y
while True:
try:
a,b,x,y=(int(x) for x in input().split())
except EOFError:
break
def solve():
max=(a + b) // 2
for size in range(1 , max
4
):
if size ** 2
==a+b:
max=(a - 1) * (b - 1
5
)
if x < size and y < size
and size
<x+y:
max=size
for sizei in range(1
4
):
if a >= b:
and siz... | bigcode/starcoder | 1 | Python |
s = int(input())
if s < 3:
print(4)
return
cnt = 1
val = s
while True:
if cnt > 1 and val == 1:
break
if val % 2 == 0:
val = val // 2
else:
val = val * 3 + 1
cnt += 1
print(cnt + 1)
| human | 0 | Python |
from collections import deque
n = int(input())
weights = list(map(int, input().split()))
weightsums = dict()
weights.insert(0, 0)
totalweight = sum(weights)
childrenof = dict()
parentof = dict()
adj = dict()
for _ in range(n - 1):
(n1, n2) = map(int, input().split())
if n1 in adj:
adj[n1].append(n2)
else:
adj[n1... | human | 0 | Python |
import sys
(a, b) = sys.stdin.readline().split()
a = int(a)
b = int(b)
if b - a >= 10:
print(0)
else:
input = [x % 10 for x in range(a + 1, b + 1)]
result = 1
for x in input:
result *= x
result %= 10
print(result)
| human | 0 | Python |
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public List<Integer> getAllElements(TreeNode root1, TreeNode root2) {
List<Integer> e1 = new ArrayList<>();
... | human | 0 | Java |
python
def maximumPerimeterTriangle(sticks):
sticks.sort(reverse=True)
for i in range(len(sticks) - 2):
if sticks[i] < sticks[i + 1] + sticks[i + 2]:
return [sticks[i + 2], sticks[i + 1], sticks[i]]
return [-1] | 01-ai/Yi-Coder-1.5B-Chat | 1 | Python |
class Solution:
def calcPower(self, n: int) -> List[int]:
ans = []
while n > 0:
m = n % 2
n //= 2
ans.append(m)
return ans[::-1]
def countPowers(self, n: int) -> List[int]:
powcount = Counter(self.calcPower(n))
ans = []
for q i... | microsoft/phi-2 | 1 | Python |
a = input().lower()
n = len(a)
g = 'aouiey'
b = []
for i in range(n):
n = len(a)
if a[i] not in g:
b.append('.')
b.append(a[i])
print(*b, sep='')
| human | 0 | Python |
from operator import itemgetter
N = int(input())
A = list(map(int, input().split()))
B = []
for (i, a) in enumerate(A):
B.append((i, a))
B.sort(reverse=True, key=itemgetter(1))
score = 0
for (n, (i, b)) in enumerate(B):
score += b * n + 1
print(score)
for (i, _) in B:
print(i + 1, end=' ')
print()
| human | 0 | Python |
In the 1st example:
The first operation will remove block 2 (costs 2). Then block 1 is also removed (costs 1+2=3), and block 3 is also removed (costs 4+6=10).
The second operation will remove block 1 (costs 1), and block 4 is also removed (costs 8+16=24).
The third operation will remove block 3 (costs 4). Then block 2... | 01-ai/Yi-Coder-1.5B-Chat | 1 | Python |
s = input()
n = len(s)
nb = 0
ok = True
for i in range(n):
ok = ok and s[i].isdigit()
for i in range(n - 2):
nb += s[i] == s[i + 2]
print(ok and n == 6 and (s[0] != '0') and (nb < 2))
| human | 0 | Python |
from collections import OrderedDict
class Solution:
def convert(self, arr, n):
b = sorted(arr)
d = OrderedDict()
for i in range(len(arr)):
d[b[i]] = i
l = [0] * len(arr)
for i in range(len(arr)):
l[i] = d[arr[i]]
arr[:] = l[:]
| human | 0 | Python |
for _ in range(t):
n = int(input())
a = list(map(int, input().split()))
c = 0
for i in range(len(a)-1):
if (a[i] + a[i+1]) % 2 == 1:
c += 1
print(c)
So this code was created by using 1 for loop and some conditions. | deepseek-ai/deepseek-coder-6.7b-base | 1 | Python |
for clarifications that the task is not over
4
*/
Function:
function upperOrLower(word) {
var lwrCase = []
var upprCase = []
var lwrUpprCase = []
for (var w = 0; w < word.length; ++w) {
word[w] === word[w].toLowerCase() ? lwrCase.push(word[w]) : upprCase.push(word[w])
}
word.replace(... | deepseek-ai/deepseek-coder-1.3b-base | 1 | Python |
.
Input Format
The first line contains a single integer $$$t$$$ ($$$1\leq t\leq 4096$$$) — the number of test cases.
For each test case, the first line contains a single integer $$$n$$$ ($$$1\leq n\leq 16$$$).
Each of the next $$$n\cdot 2^{n-1}$$$ lines contain two integers $$$u$$$ and $$$v$$$ ($$$0\leq u, v < 2^n$... | microsoft/Phi-3-mini-4k-instruct | 1 | C++ |
cpp
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int countValidTuples(const vector<int>& permutation) {
int n = permutation.size();
vector<int> counts(n, 0); // counts[i] will store the number of indices in (i, n] larger than permutation[i]
// First pass to count the in... | microsoft/Phi-3-medium-4k-instruct | 1 | C++ |
ar = list(map(int, input().strip().split(' ')))
ar.sort()
if ar[0] + ar[3] == ar[1] + ar[2]:
print('YES')
elif ar[3] == ar[0] + ar[1] + ar[2]:
print('YES')
else:
print('NO')
| human | 0 | Python |
. Time complexity = 1$ \cdot$ 10^9$
3 4 1 1
1 2 3 4 - > 1
3
1 2 3 3 3 3 - > 0
3
1 1 1 1 1 1 1 1 1 1 - > 0
-----Solution-----
'''
def maxx_min(a):
m = min value in the array
M = max value in the array
for i in range(0,n):
if a[i]<=100000:
f
else:
res+=1
return r... | 01-ai/Yi-Coder-1.5B | 1 | Python |
.
K=2 meant to mimic n**2 for index (not sure wht the repetition though w I dont think it helps here)
# editorial : https://www.geeksforgeeks.org/length-of-the-longest-contiguous-subarray-having-maximum-3-less-than-or-equal-to-2/
# just an altered version of that code ; that uses a stack, instead of keeping a 0's and ... | Qwen/Qwen2.5-Coder-1.5B | 1 | Python |
class Node:
def __init__(self,data):
self.data = data
self.children = []
def dfs(root,s):
if root.data == s:
return 1
count = 0
for child in root.children:
count += dfs(child,s)
return count
def solve(root,s):
return dfs(root,s)
def buildTree(s):
n,q,root =... | bigcode/starcoder | 1 | Python |
Evaluate bitwise AND of all numbers in the inclusive range between $a$ and $b$ given by $a$ and $b$, respectively. Assume $a$ and $b$ are integers in the inclusive range of [1, $2^{32}-1$].
Funcdef andProduct(a, b):
Return a & b
abc = [str(input()).split() for _ in range(int(input()))]
for i, j in abc:
a, b = ... | deepseek-ai/deepseek-coder-6.7b-base | 1 | Python |
class Solution:
def findLatestStep(self, arr: List[int], m: int) -> int:
n = len(arr)
length = [0] * (n + 2)
count = [0] * (n + 1)
ans = -1
for (step, index) in enumerate(arr):
left = length[index - 1]
right = length[index + 1]
length[index - left] = length[index + right] = left + right + 1
coun... | human | 0 | Python |
n = int(input())
if n >= 4:
print('YES')
if n % 2 == 0:
print('1 * 2 = 2')
print('2 * 3 = 6')
print('6 * 4 = 24')
m = (n - 4) // 2
for i in range(m):
print(str(4 + 2 * i + 2) + ' - ' + str(4 + 2 * i + 1) + ' = 1')
print('24 * 1 = 24')
else:
print('3 - 1 = 2')
print('5 - 2 = 3')
print('2 * 3 = 6... | human | 0 | Python |
for i in range(t):
n = int(input())
batva = list(map(int, input().split(' ')))
number = int(input())
plt = sorted(list(set(batva)))
atme = []
for i in plt:
if (batva.count(i) > 1):
count = batva.count(i)
atme.append(i)
... | meta-llama/Llama-3.2-3B | 1 | Python |
n = int(input())
kol = 0
b = []
summ = 0
for i in range(n):
b = [int(i) for i in input().split()]
summ = b[0] + b[1] + b[2]
if summ >= 2:
kol += 1
print(kol)
| human | 0 | Python |
while(in->has_next()){
string s = in->read();
if (s.length() == 1) sum += 1;
for (int i = 0; i < s.length() / 2; i++) if (s[i] == s[s.length - (1 + i)]) sum += 1;
All submissions for this problem are available.
Explanation
The first string is simply symmetric. The two-letter string "sx" is thus not symme... | codellama/CodeLlama-7b-hf | 1 | Python |
t = int(input())
for k in range(t):
(n, k) = map(int, input().split())
s = input()
count = 0
ones = []
for i in range(n):
if s[i] == '1':
ones.append(i)
if len(ones) == 0:
i = 0
while i < n:
count += 1
i += k + 1
elif len(ones) == 1:
ind = ones[0]
z = ind - 0
i = 0
while i < z and ind - i ... | human | 0 | Python |
import sys
sys.setrecursionlimit(10 ** 8)
INF = float('inf')
def bit(n, k):
return n >> k & 1
def solve(N: int, a: 'List[List[int]]'):
DP = [0] * (1 << N)
flag = [False] * (1 << N)
def rec(S):
if flag[S]:
return DP[S]
flag[S] = True
ans = 0
for i in range(N):
for j in range(i + 1, N):
if bit(S,... | human | 0 | Python |
def nameInStr(str, name):
return re.search(name, str) is not None# 5. The Most Frequent
Given an array of integers, find the most frequent element.
More specifically,
* given an array ``A`` of ``N`` elements, return the element that appears most frequently in the array.
* If there is a tie, return the element t... | bigcode/starcoder2-3b | 1 | Python |
if the two names are different.
def is_vowel(char):
return char in ['a', 'e', 'i', 'o', 'u']
def is_consonant(char):
return char not in ['a', 'e', 'i', 'o', 'u']
def can_transform(s, t):
for i in range(len(s)):
if is_vowel(s[i]) != is_vowel(t[i]):
return False
if is_consonant(s... | Qwen/Qwen2.5-Coder-1.5B | 1 | Python |
s = input()
d = {'.': '0', '-.': '1', '--': '2'}
ans = ''
cur = ''
for i in s:
cur += i
if cur in d.keys():
ans += d[cur]
cur = ''
print(ans)
| human | 0 | Python |
x = int(input(), 2)
count = 0
while x != 1:
if x % 2 == 0:
x //= 2
else:
x += 1
count += 1
print(count)
if __name__ == "__main__":
main() | google/codegemma-2b | 1 | Python |
import math
v = [int(i) for i in input().split()]
a = v[0]
b = v[1]
n = 0
while a > 0 and b > 0:
if a >= b:
t = int(math.floor(a / b))
a = a - t * b
n += t
else:
t = int(math.floor(b / a))
b = b - t * a
n += t
print(n)
| human | 0 | Python |
python
def tictactoe(moves):
def check_winner(board, player):
# Check rows and columns
for i in range(3):
if all(board[i][j] == player for j in range(3)) or all(board[j][i] == player for j in range(3)):
return True
# Check diagonals
if all(board[i][i] == p... | microsoft/Phi-3-medium-4k-instruct | 1 | Python |
n = int(input())
from sys import *
lst = [int(x) for x in stdin.readline().split()]
lst1 = []
lst2 = []
lst3 = []
c = 0
mk = 10000000000
for j in range(0, n):
i = lst[j]
if i > 0:
lst1.append(str(j + 1))
elif i < 0:
lst2.append(str(j + 1))
if abs(i) < mk:
t = str(j + 1)
mk = abs(i)
else:
lst3.append(s... | human | 0 | Python |
def numTriplets(self, nums1: List[int], nums2: List[int]) -> int:
"""
"""
Given two arrays of integers nums1 and nums2, return the number of triplets formed (type 1 and type 2) under the following rules:
Type 1: Triplet (i, j, k) if nums1[i]2 == nums2[j] * nums2[k] where 0 <= i < nums1.length and 0 <= j < k < nums2.... | 01-ai/Yi-Coder-9B | 1 | Python |
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
def __init__(self, file):
self.newlines = 0
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = 'x' in file.mode or 'r' not in file.mode
self.write = self.buffer.write if self.writable else None
def read... | human | 0 | Python |
using namespace std;
int main(){
int t;cin>>t;
while(t--){
int n;cin>>n;
int v[n]={0};
int sum=0;
for(int i=n-1;i>0;i--){
cin>>v[i];
i--;
}
for(int j=0;j<n;++j){
if(v[j]%2!=1){
sum+=v[j];
}
}... | microsoft/phi-2 | 1 | C++ |
from math import gcd
N = int(input())
mod = 1000000007
ans = 1
P = dict()
M = dict()
zero = 0
zero1 = 0
zero2 = 0
for i in range(N):
(a, b) = map(int, input().split())
if a == 0 and b == 0:
zero += 1
elif a == 0 and b != 0:
zero1 += 1
elif a != 0 and b == 0:
zero2 += 1
elif a > 0 and b < 0 or (a < 0 and b > ... | human | 0 | Python |
import sys
for _ in range(int(sys.stdin.readline())):
(n, k) = map(int, sys.stdin.readline().strip().split())
if n % 2 == 0:
print(k % n if k % n else n)
continue
period = n // 2
conflict = (k - 1) // period
print((k + conflict) % n if (k + conflict) % n else n)
| human | 0 | Python |
public class Solution {
private static class State implements Comparable<State> {
int r;
int c;
int dir;
int distance;
String path;
public State(int r, int c, int dir, int distance, String path) {
this.r = r;
this.c = c;
th... | human | 0 | Java |
t = int(input())
for _ in range(t):
(n, m) = map(int, input().split())
sn = set()
sm = set()
for i in range(n):
a = [int(s) for s in input().split()]
j = 0
for el in a:
if el == 1:
sn.add(i)
sm.add(j)
j += 1
n -= len(sn)
m -= len(sm)
k = min(m, n)
if k % 2 == 0:
print('Vivek')
else:
pri... | human | 0 | Python |
n = int(input())
data = []
for i in range(n):
data.append([int(i) for i in input().split()])
x = []
y = []
for i in range(n):
x.append(data[i][0])
y.append(data[i][1])
x = set(x)
y = set(y)
if len(x) < 2 or len(y) < 2:
print(-1)
else:
print((max(x) - min(x)) * (max(y) - min(y)))
| human | 0 | Python |
from functools import reduce
def main():
N=int(input())
for _ in range(N):
r,c=map(int,input().split())
M=[list(map(int,input().split())) for _ in range(r)]
L=[reduce(lambda x,y:x^y, (M[s-k][k] for k in range(max(s-r+1,0),min(s,c-1)+1))) for s in range(r+c-1)]
print("J... | human | 0 | Python |
def solve():
a,b,c = input()
if (c == a[:]) or (b==c[:]):
return True
while t!= 0:
t =t-1
if( solve() ):
print("YES")
else :print("NO")/CodeChef Problems Solutions/COOKMACH_2017.py
#https(input()))://www.codechef.com/problems/COOKMACH
def fun(N) :
return int... | bigcode/starcoder2-7b | 1 | Python |
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
H,W,N = map(int,readline().split())
sr,sc = map(int,readline().split())
S = readline().rstrip().decode()
T = readline().rstrip().decode()
if sr > 1:
if S.count('U') != T.count('D'):
print('NO')
... | bigcode/starcoder2-15b | 1 | Python |
python
import sys
sys.setrecursionlimit(10**6)
MOD = 10**9 + 7
N = 2 * 10**5
INF = 10**9
class SegTree:
_count = 1
def query(self, left, right, node):
if right < left:
return
if left <= node[0] and node[1] <= right:
# max_possible = node[2] + self.query(node[0... | Qwen/Qwen2.5-Coder-1.5B-Instruct | 1 | Python |
(N, K) = map(int, input().split())
S = input()
if N == 1 and K >= 1:
print(0)
exit()
T = ''
for (i, s) in enumerate(S):
if i == 0:
if K >= 1 and s != '1':
K -= 1
T += '1'
else:
T += s
elif K >= 1 and s != '0':
K -= 1
T += '0'
else:
T += s
print(T)
| human | 0 | Python |
h, m = int(h), int(m)
while True:
m += 1
if m == 60:
m = 0
h += 1
if h == 24:
h = 0
if str(h) == str(h)[::-1] and str(m) == str(m)[::-1]:
break
print(f'{h:02d}:{m:02d}') | bigcode/starcoder2-15b | 1 | Python |
!
Please read provided information carefully before providing lengthy code. We will evaluate code based on certain factors like "Correctness", "Efficiency", and "Readability".
Let's start solving it!
# Solution
```python
def sort_integers_by_name(nums):
# TODO
# sort the input list by name of the numbers
... | Qwen/Qwen2.5-Coder-7B-Instruct | 1 | Python |
import sys
import operator
if __name__ == '__main__':
n = int(raw_input())
ar = map(int, raw_input().split())
common = reduce(lambda x, y: operator.__gcd__(x, y), ar)
print common
import math
import sys
if __name__ == '__main__':
n = int(raw_input())
ar = map(int, raw_input().split())
#pr... | bigcode/starcoder | 1 | Python |
def main():
n = int(input())
(v, *a) = [int(i) for i in input().split()]
for i in range(1002):
t = max(a)
if v > t:
print(i)
break
a.append(t - 1)
a.remove(t)
v += 1
main()
| human | 0 | Python |
def P1_C1():
t = input()
for _ in range(t):
n = input()
s = input()
#It calculates
print(s2('1' + s[1:], int(s[0])-1))
def P1_C2():
#The puzzle didn't give any statement
t = int(input())
for _ in range(t):
n = input()
s = input()
print(sum(s2(... | microsoft/phi-2 | 1 | Python |
n = int(input())
s = input()
zeros = 0
um = 0
for i in range(n):
if s[i] == '0':
zeros += 1
if s[i] == '1':
um += 1
print(abs(zeros - um))
| human | 0 | Python |
for the example:
ret = GetPlacing(3, 1337, 75275197)
print ret[0], ret[1], ret[2],
print ret[3], ret[4],
print ret[5], ret[6],
print ret[7], ret[8]
To answer
def answer(A, B):
c = 1
ans = []
while(B>=c):
ans.append(c)
c = (3 * c + 1)%998244353
return ans | 01-ai/Yi-Coder-1.5B | 1 | Python |
n = int(input())
(*l,) = map(int, input().split())
l.sort()
mod = 10 ** 9 + 7
A = 2 ** (n // 2) % mod
for i in range(n):
if i + (i - n + 1) % 2 != l[i]:
A = 0
print(A)
| human | 0 | Python |
import heapq as hq
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
#def inp():
# return(int(input()))
def inlt():
return(list(map(int,input().split())))
#def insr():
# s = input()
# return(list(s[:len(s) - 1]))
#def invr():
# return(map(int,input()... | human | 0 | Python |
(K, N) = map(int, input().split())
As = list(map(int, input().split()))
As.append(K + As[0])
print(K - max([y - x for (x, y) in zip(As, As[1:])]))
| human | 0 | Python |
def sol(x, y, l):
aux = y - x
if aux == 0:
ans = l[x - 1] % 2
elif aux == 1:
if l[x] == 0:
ans = 1
else:
ans = l[x - 1] % 2
elif l[x] == 0:
if l[x + 1] == 0:
ans == l[x - 1] % 2
else:
ans = 1
else:
ans = l[x - 1] % 2
return ('Even', 'Odd')[ans]
int(input())
l = list(map(int, input().split(... | human | 0 | Python |
python
def reorder_sequences(A, B):
A_dict = {value: index for index, value in enumerate(A)}
B_sorted = sorted(B, key=lambda x: A_dict[x])
if len(B_sorted) != len(set(B_sorted)):
return 'No'
return 'Yes', ' '.join(map(str, B_sorted))
N = int(input())
A = list(map(int, input().split()))
B = l... | microsoft/Phi-3.5-mini-instruct | 1 | Python |
def acmTeam(topic):
n, m = len(topic), len(topic[0])
max_topics = 0
team_count = 0
for i in range(n):
for j in range(i + 1, n):
topics_known = sum(int(a) | int(b) for a, b in zip(topic[i], topic[j]))
if topics_known > max_topics:
max_topics = topics_k... | codellama/CodeLlama-70b-Instruct-hf | 1 | Python |
n = int(input())
s = int(input()))
k = s<strong>%2</strong>
<strong>if k!=0</strong>
print("NO")
<strong>else</strong>
print("YES")
a = list(map(int, input().split()[:n]))
print(a)
k = s%2
<strong>if k!=0</strong>
print("NO")
<strong>else</strong>
print("YES")
p = k/n
print(int(p))
PS : this code is capable of helpin... | google/codegemma-7b | 1 | Python |
- no comments necessary
Solution: To determine the minimum number of cards to be flipped, we must consider two scenarios: when vowels can invalidate the assertion, and when they don't.
Here is the step-by-step explanation of the approach:
1. If we encounter a vowel, we must consider this a potential falsehood.
2. I... | microsoft/Phi-3.5-mini-instruct | 1 | Python |
T = int(input())
while T > 0:
n = int(input())
arr = list(map(int, input().split()))
count = [0] * 101
for x in arr:
count[x] += 1
res = 0
final = 0
for i in range(101):
final = i
if count[i] == 0:
break
else:
count[i] -= 1
res += final
final = 0
for i in range(101):
final = i
if count[i] ==... | human | 0 | Python |
python
for x in range(int(input())):
print(int.bit_length(int(input()))) | meta-llama/Llama-3.1-8B-Instruct | 1 | Python |
in file (python):
coins_needed, my_sum, others_sum, i = 1 , 0 , 0, -1
coins_list = [int(word.strip()) for word in raw_input("").split(",")]
raw_input("");
for coins_num,coin in enumerate(coins_list):
coins_needed+=1;
my_sum += coins_list[i];
if my_sum <= others_sum and ( my_sum == others_sum) or (coins_num==... | meta-llama/Llama-3.1-8B-Instruct | 1 | Python |
t = int(input())
for _ in range(t):
(r, g, b, m) = list(map(int, input().split()))
ar = list(map(int, input().split()))
ag = list(map(int, input().split()))
ab = list(map(int, input().split()))
mxr = max(ar)
mxg = max(ag)
mxb = max(ab)
for i in range(m):
if mxr >= mxg and mxr >= mxb:
mxr //= 2
elif mxg >... | human | 0 | Python |
:
# Read input
my_input = input()
# Initialize variables
integer_part, decimal_part = '', ''
# Extract integer and decimal parts
if '.' in my_input:
integer_part, decimal_part = my_input.split('.')
integer_part = integer_part.replace('-', '')
else:
integer_part = my_input.replace('-', '')
# Complement f... | microsoft/Phi-3.5-mini-instruct | 1 | Python |
mport functools
mport operator
"""
def addArrays(inputStr):
a, b = map(int, inputStr.strip().split())
return a + b
if __name__ == '__main__':
numOfTests = int(input())
tests = []
for i in range(numOfTests):
tests.append(input())
for test in tests:
print(addArrays(test)) | 01-ai/Yi-Coder-9B | 1 | Python |
A = input()
A = sorted(A)
S = []
counter = 0
for i in range(len(A)):
if A[i] in A[i + 1:]:
continue
else:
counter += 1
if counter % 2 == 0:
print('CHAT WITH HER!')
else:
print('IGNORE HIM!')
| human | 0 | Python |
t = int(input())
while t > 0:
t -= 1
[n, x, y] = list(map(int, input().split(' ')))
d = 0
for i in range(n, 1, -1):
if (y - x) % (i - 1) == 0:
d = (y - x) // (i - 1)
n -= i
break
res = []
a0 = x
an = y
while a0 <= an:
res.append(a0)
a0 += d
a0 = x - d
while n != 0 and a0 > 0:
res.append(a0)
... | human | 0 | Python |
from __future__ import division, print_function
import os, sys
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
from __builtin__ import xrange as range
from future_builtins import ascii, filter, hex, map, oct, zip
def ii():
return int(input())
def si():
return input()
def mi():
return map(int, input()... | human | 0 | Python |
class Solution:
def preToInfix(self, pre_exp):
count = 0
stack = []
for ele in pre_exp[::-1]:
if ele in ['^', '*', '/', '+', '-']:
op1 = stack.pop()
op2 = stack.pop()
stack.append('(' + op1 + ele + op2 + ')')
else:
stack.append(ele)
return stack.pop()
| human | 0 | Python |
import string
n = int(input())
s = input().lower()
print("YES" if set(string.ascii_lowercase).issubset(set(s)) else "NO") | codellama/CodeLlama-34b-Instruct-hf | 1 | Python |
path = Divmod(int(stdin.readline()), 257)[1]
stdin.close()
stdout.write(str(chr(path)))
path = int(input()) % 257
for x in divmod(path, 10):
print(x, end='')
def func(num, mod):
return num - math.trunc(num/mod) * mod
s = 0
digits = map(int, str(num))
if digits == []:
return 1
if ... | codellama/CodeLlama-7b-hf | 1 | Python |
python
for _ in range(int(input())):
n, x, a, b = map(int, input().split())
d = abs(b-a)
if x >= d:
print(d)
elif (n-d) <= x:
print(n-d)
else:
print(d) | microsoft/Phi-3.5-mini-instruct | 1 | Python |
for this case is: 0<|endoftext|>class Solution(object):
def backtracking(self, idx, targ, k, ret):
if k<=0:
return
if k==1:
if targ%idx==0:
ret.append([targ/idx])
else:
for i in xrange(1, floor(targ/idx)+1):
if len(ret[i-1])==0:
return
if (ret[i-1][0]+i-1)*idx==targ and ret[i-1][0]+i-1... | 01-ai/Yi-Coder-1.5B | 1 | Python |
#include <bits/stdc++.h>
using namespace std;
const int MAX = 1000001;
const long long M = 998244353;
long long ft[MAX];
long long ftinv[MAX];
long long modpow(long long n, long long k, long long MOD) {
long long ans = 1;
while (k > 0) {
if (k & 1) ans = (ans*n) % MOD;
n = (n*n) % MOD; k >>= 1... | human | 0 | C++ |
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