Quantum Entropy
Collection
Quantum random bytes with signed receipts, and datasets whose origin anyone can verify. • 9 items • Updated
task_id stringlengths 11 13 | prompt stringlengths 130 926 | canonical_solution stringlengths 23 575 | test stringlengths 117 1.31k | entry_point stringlengths 3 30 | _lr_source_index int64 0 163 |
|---|---|---|---|---|---|
HumanEval/0 | from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ... | for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
distance = abs(elem - elem2)
if distance < threshold:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True
assert candidate([1.0, 2.0, 5.9, 4.0,... | has_close_elements | 0 |
HumanEval/1 | from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace... | result = []
current_string = []
current_depth = 0
for c in paren_string:
if c == '(':
current_depth += 1
current_string.append(c)
elif c == ')':
current_depth -= 1
current_string.append(c)
if current_depth == 0:
... |
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('(()()) ((())) () ((())()())') == [
'(()())', '((()))', '()', '((())()())'
]
assert candidate('() (()) ((())) (((())))') == [
'()', '(())', '((()))', '(((())))'
]
assert candidate('(()... | separate_paren_groups | 1 |
HumanEval/5 | from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
| if not numbers:
return []
result = []
for n in numbers[:-1]:
result.append(n)
result.append(delimeter)
result.append(numbers[-1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 7) == []
assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]
assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]
| intersperse | 5 |
HumanEval/12 | from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
>>> longest(['a', 'b', 'c'])
'a... | if not strings:
return None
maxlen = max(len(x) for x in strings)
for s in strings:
if len(s) == maxlen:
return s
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == None
assert candidate(['x', 'y', 'z']) == 'x'
assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'
| longest | 12 |
HumanEval/14 | from typing import List
def all_prefixes(string: str) -> List[str]:
""" Return list of all prefixes from shortest to longest of the input string
>>> all_prefixes('abc')
['a', 'ab', 'abc']
"""
| result = []
for i in range(len(string)):
result.append(string[:i+1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == []
assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']
assert candidate('WWW') == ['W', 'WW', 'WWW']
| all_prefixes | 14 |
HumanEval/20 | from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([... | closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
... |
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
assert candidate([1.0, 2.0, 3.0, 4.0,... | find_closest_elements | 20 |
HumanEval/23 |
def strlen(string: str) -> int:
""" Return length of given string
>>> strlen('')
0
>>> strlen('abc')
3
"""
| return len(string)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == 0
assert candidate('x') == 1
assert candidate('asdasnakj') == 9
| strlen | 23 |
HumanEval/24 |
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
>>> largest_divisor(15)
5
"""
| for i in reversed(range(n)):
if n % i == 0:
return i
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3) == 1
assert candidate(7) == 1
assert candidate(10) == 5
assert candidate(100) == 50
assert candidate(49) == 7
| largest_divisor | 24 |
HumanEval/25 | from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the produc... | import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(2) == [2]
assert candidate(4) == [2, 2]
assert candidate(8) == [2, 2, 2]
assert candidate(3 * 19) == [3, 19]
assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]
assert candidate(3 * 19 * 3 * 19 * ... | factorize | 25 |
HumanEval/26 | from typing import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
| import collections
c = collections.Counter(numbers)
return [n for n in numbers if c[n] <= 1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
| remove_duplicates | 26 |
HumanEval/29 | from typing import List
def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:
""" Filter an input list of strings only for ones that start with a given prefix.
>>> filter_by_prefix([], 'a')
[]
>>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')
['abc', 'array']
"""
| return [x for x in strings if x.startswith(prefix)]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 'john') == []
assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
| filter_by_prefix | 29 |
HumanEval/31 |
def is_prime(n):
"""Return true if a given number is prime, and false otherwise.
>>> is_prime(6)
False
>>> is_prime(101)
True
>>> is_prime(11)
True
>>> is_prime(13441)
True
>>> is_prime(61)
True
>>> is_prime(4)
False
>>> is_prime(1)
False
"""
| if n < 2:
return False
for k in range(2, n - 1):
if n % k == 0:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate(6) == False
assert candidate(101) == True
assert candidate(11) == True
assert candidate(13441) == True
assert candidate(61) == True
assert candidate(4) == False
assert candidate(1) == False
assert candidate(5) == True
assert ca... | is_prime | 31 |
HumanEval/32 | import math
def poly(xs: list, x: float):
"""
Evaluates polynomial with coefficients xs at point x.
return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
"""
return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])
def find_zero(xs: list):
""" xs are coefficients of a polynomia... | begin, end = -1., 1.
while poly(xs, begin) * poly(xs, end) > 0:
begin *= 2.0
end *= 2.0
while end - begin > 1e-10:
center = (begin + end) / 2.0
if poly(xs, center) * poly(xs, begin) > 0:
begin = center
else:
end = center
return begin
|
METADATA = {}
def check(candidate):
import math
import random
rng = random.Random(42)
import copy
for _ in range(100):
ncoeff = 2 * rng.randint(1, 4)
coeffs = []
for _ in range(ncoeff):
coeff = rng.randint(-10, 10)
if coeff == 0:
co... | find_zero | 32 |
HumanEval/34 |
def unique(l: list):
"""Return sorted unique elements in a list
>>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])
[0, 2, 3, 5, 9, 123]
"""
| return sorted(list(set(l)))
|
METADATA = {}
def check(candidate):
assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
| unique | 34 |
HumanEval/42 |
def incr_list(l: list):
"""Return list with elements incremented by 1.
>>> incr_list([1, 2, 3])
[2, 3, 4]
>>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])
[6, 4, 6, 3, 4, 4, 10, 1, 124]
"""
| return [(e + 1) for e in l]
|
METADATA = {}
def check(candidate):
assert candidate([]) == []
assert candidate([3, 2, 1]) == [4, 3, 2]
assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]
| incr_list | 42 |
HumanEval/43 |
def pairs_sum_to_zero(l):
"""
pairs_sum_to_zero takes a list of integers as an input.
it returns True if there are two distinct elements in the list that
sum to zero, and False otherwise.
>>> pairs_sum_to_zero([1, 3, 5, 0])
False
>>> pairs_sum_to_zero([1, 3, -2, 1])
False
>>> pairs... | for i, l1 in enumerate(l):
for j in range(i + 1, len(l)):
if l1 + l[j] == 0:
return True
return False
|
METADATA = {}
def check(candidate):
assert candidate([1, 3, 5, 0]) == False
assert candidate([1, 3, -2, 1]) == False
assert candidate([1, 2, 3, 7]) == False
assert candidate([2, 4, -5, 3, 5, 7]) == True
assert candidate([1]) == False
assert candidate([-3, 9, -1, 3, 2, 30]) == True
asser... | pairs_sum_to_zero | 43 |
HumanEval/45 |
def triangle_area(a, h):
"""Given length of a side and high return area for a triangle.
>>> triangle_area(5, 3)
7.5
"""
| return a * h / 2.0
|
METADATA = {}
def check(candidate):
assert candidate(5, 3) == 7.5
assert candidate(2, 2) == 2.0
assert candidate(10, 8) == 40.0
| triangle_area | 45 |
HumanEval/48 |
def is_palindrome(text: str):
"""
Checks if given string is a palindrome
>>> is_palindrome('')
True
>>> is_palindrome('aba')
True
>>> is_palindrome('aaaaa')
True
>>> is_palindrome('zbcd')
False
"""
| for i in range(len(text)):
if text[i] != text[len(text) - 1 - i]:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate('') == True
assert candidate('aba') == True
assert candidate('aaaaa') == True
assert candidate('zbcd') == False
assert candidate('xywyx') == True
assert candidate('xywyz') == False
assert candidate('xywzx') == False
| is_palindrome | 48 |
HumanEval/49 |
def modp(n: int, p: int):
"""Return 2^n modulo p (be aware of numerics).
>>> modp(3, 5)
3
>>> modp(1101, 101)
2
>>> modp(0, 101)
1
>>> modp(3, 11)
8
>>> modp(100, 101)
1
"""
| ret = 1
for i in range(n):
ret = (2 * ret) % p
return ret
|
METADATA = {}
def check(candidate):
assert candidate(3, 5) == 3
assert candidate(1101, 101) == 2
assert candidate(0, 101) == 1
assert candidate(3, 11) == 8
assert candidate(100, 101) == 1
assert candidate(30, 5) == 4
assert candidate(31, 5) == 3
| modp | 49 |
HumanEval/55 |
def fib(n: int):
"""Return n-th Fibonacci number.
>>> fib(10)
55
>>> fib(1)
1
>>> fib(8)
21
"""
| if n == 0:
return 0
if n == 1:
return 1
return fib(n - 1) + fib(n - 2)
|
METADATA = {}
def check(candidate):
assert candidate(10) == 55
assert candidate(1) == 1
assert candidate(8) == 21
assert candidate(11) == 89
assert candidate(12) == 144
| fib | 55 |
HumanEval/59 |
def largest_prime_factor(n: int):
"""Return the largest prime factor of n. Assume n > 1 and is not a prime.
>>> largest_prime_factor(13195)
29
>>> largest_prime_factor(2048)
2
"""
| def is_prime(k):
if k < 2:
return False
for i in range(2, k - 1):
if k % i == 0:
return False
return True
largest = 1
for j in range(2, n + 1):
if n % j == 0 and is_prime(j):
largest = max(largest, j)
return largest
|
METADATA = {}
def check(candidate):
assert candidate(15) == 5
assert candidate(27) == 3
assert candidate(63) == 7
assert candidate(330) == 11
assert candidate(13195) == 29
| largest_prime_factor | 59 |
HumanEval/61 |
def correct_bracketing(brackets: str):
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("(")
False
>>> correct_bracketing("()")
True
>>> correct_bracketing("(()())")
True
>>> correct_bracketin... | depth = 0
for b in brackets:
if b == "(":
depth += 1
else:
depth -= 1
if depth < 0:
return False
return depth == 0
|
METADATA = {}
def check(candidate):
assert candidate("()")
assert candidate("(()())")
assert candidate("()()(()())()")
assert candidate("()()((()()())())(()()(()))")
assert not candidate("((()())))")
assert not candidate(")(()")
assert not candidate("(")
assert not candidate("((((")
... | correct_bracketing | 61 |
HumanEval/62 |
def derivative(xs: list):
""" xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
>>> derivative([3, 1, 2, 4, 5])
[1, 4, 12, 20]
>>> derivative([1, 2, 3])
[2, 6]
"""
| return [(i * x) for i, x in enumerate(xs)][1:]
|
METADATA = {}
def check(candidate):
assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]
assert candidate([1, 2, 3]) == [2, 6]
assert candidate([3, 2, 1]) == [2, 2]
assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]
assert candidate([1]) == []
| derivative | 62 |
HumanEval/71 |
def triangle_area(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the thi... | if a + b <= c or a + c <= b or b + c <= a:
return -1
s = (a + b + c)/2
area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
area = round(area, 2)
return area
| def check(candidate):
# Check some simple cases
assert candidate(3, 4, 5) == 6.00, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(1, 2, 10) == -1
assert candidate(4, 8, 5) == 8.18
assert candidate(2, 2, 2) == 1.73
assert candidate(1, 2, 3) == -1
assert candidate... | triangle_area | 71 |
HumanEval/72 |
def will_it_fly(q,w):
'''
Write a function that returns True if the object q will fly, and False otherwise.
The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
will_it_fly([1, 2], 5) ➞ False
... | if sum(q) > w:
return False
i, j = 0, len(q)-1
while i<j:
if q[i] != q[j]:
return False
i+=1
j-=1
return True
| def check(candidate):
# Check some simple cases
assert candidate([3, 2, 3], 9) is True
assert candidate([1, 2], 5) is False
assert candidate([3], 5) is True
assert candidate([3, 2, 3], 1) is False
# Check some edge cases that are easy to work out by hand.
assert candidate([1, 2, 3], 6) is... | will_it_fly | 72 |
HumanEval/73 |
def smallest_change(arr):
"""
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For... | ans = 0
for i in range(len(arr) // 2):
if arr[i] != arr[len(arr) - i - 1]:
ans += 1
return ans
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3,5,4,7,9,6]) == 4
assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
assert candidate([1, 4, 2]) == 1
assert candidate([1, 4, 4, 2]) == 1
# Check some edge cases that are easy to work out by hand.
assert candidate([1, 2, 3, 2... | smallest_change | 73 |
HumanEval/79 |
def decimal_to_binary(decimal):
"""You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of charac... | return "db" + bin(decimal)[2:] + "db"
| def check(candidate):
# Check some simple cases
assert candidate(0) == "db0db"
assert candidate(32) == "db100000db"
assert candidate(103) == "db1100111db"
assert candidate(15) == "db1111db", "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to wor... | decimal_to_binary | 79 |
HumanEval/87 |
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] su... | coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]
return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])
| def check(candidate):
# Check some simple cases
assert candidate([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
assert candidate([
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,2,3,4,5,6],
... | get_row | 87 |
HumanEval/90 |
def next_smallest(lst):
"""
You are given a list of integers.
Write a function next_smallest() that returns the 2nd smallest element of the list.
Return None if there is no such element.
next_smallest([1, 2, 3, 4, 5]) == 2
next_smallest([5, 1, 4, 3, 2]) == 2
next_smallest([]) == None
... | lst = sorted(set(lst))
return None if len(lst) < 2 else lst[1]
| def check(candidate):
# Check some simple cases
assert candidate([1, 2, 3, 4, 5]) == 2
assert candidate([5, 1, 4, 3, 2]) == 2
assert candidate([]) == None
assert candidate([1, 1]) == None
assert candidate([1,1,1,1,0]) == 1
assert candidate([1, 0**0]) == None
assert candidate([-35, 34, 1... | next_smallest | 90 |
HumanEval/91 |
def is_bored(S):
"""
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
>>> is_bored("Hello world")
0
>>> is_bored("The sky is blue. The ... | import re
sentences = re.split(r'[.?!]\s*', S)
return sum(sentence[0:2] == 'I ' for sentence in sentences)
| def check(candidate):
# Check some simple cases
assert candidate("Hello world") == 0, "Test 1"
assert candidate("Is the sky blue?") == 0, "Test 2"
assert candidate("I love It !") == 1, "Test 3"
assert candidate("bIt") == 0, "Test 4"
assert candidate("I feel good today. I will be productive. wil... | is_bored | 91 |
HumanEval/97 |
def multiply(a, b):
"""Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(148, 412) should return 16.
multiply(19, 28) should return 72.
multiply(2020, 1851) should return 0.
multiply(14,-15) ... | return abs(a % 10) * abs(b % 10)
| def check(candidate):
# Check some simple cases
assert candidate(148, 412) == 16, "First test error: " + str(candidate(148, 412))
assert candidate(19, 28) == 72, "Second test error: " + str(candidate(19, 28))
assert candidate(2020, 1851) == 0, "Third test error: " + str(c... | multiply | 97 |
HumanEval/98 |
def count_upper(s):
"""
Given a string s, count the number of uppercase vowels in even indices.
For example:
count_upper('aBCdEf') returns 1
count_upper('abcdefg') returns 0
count_upper('dBBE') returns 0
"""
| count = 0
for i in range(0,len(s),2):
if s[i] in "AEIOU":
count += 1
return count
| def check(candidate):
# Check some simple cases
assert candidate('aBCdEf') == 1
assert candidate('abcdefg') == 0
assert candidate('dBBE') == 0
assert candidate('B') == 0
assert candidate('U') == 1
assert candidate('') == 0
assert candidate('EEEE') == 2
# Check some edge cases th... | count_upper | 98 |
HumanEval/101 |
def words_string(s):
"""
You will be given a string of words separated by commas or spaces. Your task is
to split the string into words and return an array of the words.
For example:
words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
words_string("One, two, three, fo... | if not s:
return []
s_list = []
for letter in s:
if letter == ',':
s_list.append(' ')
else:
s_list.append(letter)
s_list = "".join(s_list)
return s_list.split()
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate("Hi, my name is John") == ["Hi", "my", "name", "is", "John"]
assert candidate("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"]
... | words_string | 101 |
HumanEval/103 |
def rounded_avg(n, m):
"""You are given two positive integers n and m, and your task is to compute the
average of the integers from n through m (including n and m).
Round the answer to the nearest integer and convert that to binary.
If n is greater than m, return -1.
Example:
rounded_avg(1, 5)... | if m < n:
return -1
summation = 0
for i in range(n, m+1):
summation += i
return bin(round(summation/(m - n + 1)))
| def check(candidate):
# Check some simple cases
assert candidate(1, 5) == "0b11"
assert candidate(7, 13) == "0b1010"
assert candidate(964,977) == "0b1111001010"
assert candidate(996,997) == "0b1111100100"
assert candidate(560,851) == "0b1011000010"
assert candidate(185,546) == "0b101101110"... | rounded_avg | 103 |
HumanEval/105 |
def by_length(arr):
"""
Given an array of integers, sort the integers that are between 1 and 9 inclusive,
reverse the resulting array, and then replace each digit by its corresponding name from
"One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine".
For example:
arr = [2, 1, ... | dic = {
1: "One",
2: "Two",
3: "Three",
4: "Four",
5: "Five",
6: "Six",
7: "Seven",
8: "Eight",
9: "Nine",
}
sorted_arr = sorted(arr, reverse=True)
new_arr = []
for var in sorted_arr:
try:
new_arr.append(dic[... | def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"], "Error"
assert candidate([]) == [], "Error"
assert candidate([1, -1 ,... | by_length | 105 |
HumanEval/107 |
def even_odd_palindrome(n):
"""
Given a positive integer n, return a tuple that has the number of even and odd
integer palindromes that fall within the range(1, n), inclusive.
Example 1:
Input: 3
Output: (1, 2)
Explanation:
Integer palindrome are 1, 2, 3. one of them i... | def is_palindrome(n):
return str(n) == str(n)[::-1]
even_palindrome_count = 0
odd_palindrome_count = 0
for i in range(1, n+1):
if i%2 == 1 and is_palindrome(i):
odd_palindrome_count += 1
elif i%2 == 0 and is_palindrome(i):
even_palindrome_count += 1
... | def check(candidate):
# Check some simple cases
assert candidate(123) == (8, 13)
assert candidate(12) == (4, 6)
assert candidate(3) == (1, 2)
assert candidate(63) == (6, 8)
assert candidate(25) == (5, 6)
assert candidate(19) == (4, 6)
assert candidate(9) == (4, 5), "This prints if this ... | even_odd_palindrome | 107 |
HumanEval/114 |
def minSubArraySum(nums):
"""
Given an array of integers nums, find the minimum sum of any non-empty sub-array
of nums.
Example
minSubArraySum([2, 3, 4, 1, 2, 4]) == 1
minSubArraySum([-1, -2, -3]) == -6
"""
| max_sum = 0
s = 0
for num in nums:
s += -num
if (s < 0):
s = 0
max_sum = max(s, max_sum)
if max_sum == 0:
max_sum = max(-i for i in nums)
min_sum = -max_sum
return min_sum
| def check(candidate):
# Check some simple cases
assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([-1, -2, -3]) == -6
assert candidate([-1, -2, -3, 2, -10]) == -14
assert candidate([-9999999999999999]) == -9999999999999999
ass... | minSubArraySum | 114 |
HumanEval/117 |
def select_words(s, n):
"""Given a string s and a natural number n, you have been tasked to implement
a function that returns a list of all words from string s that contain exactly
n consonants, in order these words appear in the string s.
If the string s is empty then the function should return an e... | result = []
for word in s.split():
n_consonants = 0
for i in range(0, len(word)):
if word[i].lower() not in ["a","e","i","o","u"]:
n_consonants += 1
if n_consonants == n:
result.append(word)
return result
| def check(candidate):
# Check some simple cases
assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4))
assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little l... | select_words | 117 |
HumanEval/118 |
def get_closest_vowel(word):
"""You are given a word. Your task is to find the closest vowel that stands between
two consonants from the right side of the word (case sensitive).
Vowels in the beginning and ending doesn't count. Return empty string if you didn't
find any vowel met the above condit... | if len(word) < 3:
return ""
vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'}
for i in range(len(word)-2, 0, -1):
if word[i] in vowels:
if (word[i+1] not in vowels) and (word[i-1] not in vowels):
return word[i]
return ""
| def check(candidate):
# Check some simple cases
assert candidate("yogurt") == "u"
assert candidate("full") == "u"
assert candidate("easy") == ""
assert candidate("eAsy") == ""
assert candidate("ali") == ""
assert candidate("bad") == "a"
assert candidate("most") == "o"
assert candida... | get_closest_vowel | 118 |
HumanEval/125 |
def split_words(txt):
'''
Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you
should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the
alphabet, ord('a') = 0, ord('b') = 1, ... ord('... | if " " in txt:
return txt.split()
elif "," in txt:
return txt.replace(',',' ').split()
else:
return len([i for i in txt if i.islower() and ord(i)%2 == 0])
| def check(candidate):
assert candidate("Hello world!") == ["Hello","world!"]
assert candidate("Hello,world!") == ["Hello","world!"]
assert candidate("Hello world,!") == ["Hello","world,!"]
assert candidate("Hello,Hello,world !") == ["Hello,Hello,world","!"]
assert candidate("abcdef") == 3
asser... | split_words | 125 |
HumanEval/127 |
def intersection(interval1, interval2):
"""You are given two intervals,
where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).
The given intervals are closed which means that the interval (start, end)
includes both start and end.
For each given interval, it is ass... | def is_prime(num):
if num == 1 or num == 0:
return False
if num == 2:
return True
for i in range(2, num):
if num%i == 0:
return False
return True
l = max(interval1[0], interval2[0])
r = min(interval1[1], interval2[1])
l... | def check(candidate):
# Check some simple cases
assert candidate((1, 2), (2, 3)) == "NO"
assert candidate((-1, 1), (0, 4)) == "NO"
assert candidate((-3, -1), (-5, 5)) == "YES"
assert candidate((-2, 2), (-4, 0)) == "YES"
# Check some edge cases that are easy to work out by hand.
assert cand... | intersection | 127 |
HumanEval/128 |
def prod_signs(arr):
"""
You are given an array arr of integers and you need to return
sum of magnitudes of integers multiplied by product of all signs
of each number in the array, represented by 1, -1 or 0.
Note: return None for empty arr.
Example:
>>> prod_signs([1, 2, 2, -4]) == -9
... | if not arr: return None
prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr)))
return prod * sum([abs(i) for i in arr])
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1, 2, 2, -4]) == -9
assert candidate([0, 1]) == 0
assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10
assert candidate([]) == None
assert candidate([2, 4,1, ... | prod_signs | 128 |
HumanEval/133 |
def sum_squares(lst):
"""You are given a list of numbers.
You need to return the sum of squared numbers in the given list,
round each element in the list to the upper int(Ceiling) first.
Examples:
For lst = [1,2,3] the output should be 14
For lst = [1,4,9] the output should be 98
For lst =... | import math
squared = 0
for i in lst:
squared += math.ceil(i)**2
return squared
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1.0,2,3])==14, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([1,3,5,7])==84, "This prints if this assert fails 1 (goo... | sum_squares | 133 |
HumanEval/134 |
def check_if_last_char_is_a_letter(txt):
'''
Create a function that returns True if the last character
of a given string is an alphabetical character and is not
a part of a word, and False otherwise.
Note: "word" is a group of characters separated by space.
Examples:
check_if_last_char_is_... |
check = txt.split(' ')[-1]
return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False
| def check(candidate):
# Check some simple cases
assert candidate("apple") == False
assert candidate("apple pi e") == True
assert candidate("eeeee") == False
assert candidate("A") == True
assert candidate("Pumpkin pie ") == False
assert candidate("Pumpkin pie 1") == False
assert candidat... | check_if_last_char_is_a_letter | 134 |
HumanEval/138 |
def is_equal_to_sum_even(n):
"""Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers
Example
is_equal_to_sum_even(4) == False
is_equal_to_sum_even(6) == False
is_equal_to_sum_even(8) == True
"""
| return n%2 == 0 and n >= 8
| def check(candidate):
assert candidate(4) == False
assert candidate(6) == False
assert candidate(8) == True
assert candidate(10) == True
assert candidate(11) == False
assert candidate(12) == True
assert candidate(13) == False
assert candidate(16) == True
| is_equal_to_sum_even | 138 |
HumanEval/140 |
def fix_spaces(text):
"""
Given a string text, replace all spaces in it with underscores,
and if a string has more than 2 consecutive spaces,
then replace all consecutive spaces with -
fix_spaces("Example") == "Example"
fix_spaces("Example 1") == "Example_1"
fix_spaces(" Example 2")... | new_text = ""
i = 0
start, end = 0, 0
while i < len(text):
if text[i] == " ":
end += 1
else:
if end - start > 2:
new_text += "-"+text[i]
elif end - start > 0:
new_text += "_"*(end - start)+text[i]
else:
... | def check(candidate):
# Check some simple cases
assert candidate("Example") == "Example", "This prints if this assert fails 1 (good for debugging!)"
assert candidate("Mudasir Hanif ") == "Mudasir_Hanif_", "This prints if this assert fails 2 (good for debugging!)"
assert candidate("Yellow Yellow Dirty ... | fix_spaces | 140 |
HumanEval/145 |
def order_by_points(nums):
"""
Write a function which sorts the given list of integers
in ascending order according to the sum of their digits.
Note: if there are several items with similar sum of their digits,
order them based on their index in original list.
For example:
>>> order_by_poi... | def digits_sum(n):
neg = 1
if n < 0: n, neg = -1 * n, -1
n = [int(i) for i in str(n)]
n[0] = n[0] * neg
return sum(n)
return sorted(nums, key=digits_sum)
| def check(candidate):
# Check some simple cases
assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11]
assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457]
assert candidate([]) == []
assert candidate([1,... | order_by_points | 145 |
HumanEval/147 |
def get_max_triples(n):
"""
You are given a positive integer n. You have to create an integer array a of length n.
For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
Return the number of triples (a[i], a[j], a[k]) of a where i < j < k,
and a[i] + a[j] + a[k] is a multiple of 3.
... | A = [i*i - i + 1 for i in range(1,n+1)]
ans = []
for i in range(n):
for j in range(i+1,n):
for k in range(j+1,n):
if (A[i]+A[j]+A[k])%3 == 0:
ans += [(A[i],A[j],A[k])]
return len(ans)
| def check(candidate):
assert candidate(5) == 1
assert candidate(6) == 4
assert candidate(10) == 36
assert candidate(100) == 53361
| get_max_triples | 147 |
HumanEval/151 |
def double_the_difference(lst):
'''
Given a list of numbers, return the sum of squares of the numbers
in the list that are odd. Ignore numbers that are negative or not integers.
double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10
double_the_difference([-1, -2, 0]) == 0
double_the_dif... | return sum([i**2 for i in lst if i > 0 and i%2!=0 and "." not in str(i)])
| def check(candidate):
# Check some simple cases
assert candidate([]) == 0 , "This prints if this assert fails 1 (good for debugging!)"
assert candidate([5, 4]) == 25 , "This prints if this assert fails 2 (good for debugging!)"
assert candidate([0.1, 0.2, 0.3]) == 0 , "This prints if this assert fails 3... | double_the_difference | 151 |
HumanEval/163 |
def generate_integers(a, b):
"""
Given two positive integers a and b, return the even digits between a
and b, in ascending order.
For example:
generate_integers(2, 8) => [2, 4, 6, 8]
generate_integers(8, 2) => [2, 4, 6, 8]
generate_integers(10, 14) => []
"""
| lower = max(2, min(a, b))
upper = min(8, max(a, b))
return [i for i in range(lower, upper+1) if i % 2 == 0]
| def check(candidate):
# Check some simple cases
assert candidate(2, 10) == [2, 4, 6, 8], "Test 1"
assert candidate(10, 2) == [2, 4, 6, 8], "Test 2"
assert candidate(132, 2) == [2, 4, 6, 8], "Test 3"
assert candidate(17,89) == [], "Test 4"
# Check some edge cases that are easy to work out by ha... | generate_integers | 163 |
HumanEval: 50 random coding problems (Light Rider QEC)
50 rows chosen at random from the 164 rows of the test split of openai/openai_humaneval, revision 7dce6050a7d6. The rows are unchanged; _lr_source_index gives each row's position in the source split.
The rows keep the source dataset's MIT license (license text).
The dataset was generated from a seed drawn from lightrider_qec_001 through
Light Rider. The seed comes with a signed receipt, so anyone
can check where the data came from and regenerate it exactly.
Provenance
| Entropy source | lightrider_qec_001 |
| Drawn | 2026-10-19 17:54 UTC |
| Light Rider request | lr_sreq_6cb1bbc4600040e9976989b6e5ad1878 |
| Seed | b1f221d8a44e7f0bc700b7bbaa5db86e1de175802ad0ef8e3be2a6d45f880210 |
| Generator | eval_subset/1 |
| Rows | 50 |
Parameters:
{
"source_dataset": "openai/openai_humaneval",
"config": null,
"split": "test",
"revision": "7dce6050a7d6d172f3cc5c32aa97f52fa1a2e544",
"source_num_rows": 164,
"n": 50,
"requested": {
"n": 50,
"fraction": null
}
}
Full technical record
| Receipt signature | Ed25519, key fingerprint (SHA-256) 363b9750db0acd16ab188e4ecc8a58e4f811b28f5870cfc3ba4522274a11645e |
| Output commitment (signed) | sha256:fe18a9c3ba4b7621c635f13f78658d7a764d2ee954f6dca9f74f5505c23321fa |
| Commitment salt | 44f820d6869436a0b767fe766d2eb268fe624a1f521516aa88a1ed37eed227ef |
| Generator stream | LR-ChaCha20 v1, domain eval_subset |
| Content hash (lr-canonical-jsonl/1) | 6a82365610d04ae75fbe0b8349ff9be8313c9d50a169ca030fe00deee01760a9 |
| Built with | lightrider-huggingface 0.1.1, lightrider 1.6.2, pyarrow 26.0.0 |
The complete record is in lightrider_provenance.json. The signed receipt, exactly as
issued, is in receipt.json.
How to verify
pip install lightrider-huggingface
import lightrider_huggingface as lrhf
print(lrhf.verify("LightRiderInc/humaneval-random-sample-iqm-qec"))
This needs no Light Rider account. It prints each check as PASS or FAIL.
For a subset of a very large dataset, lrhf.verify(..., indices_only=True) skips re-downloading the source.
How verification works
- The receipt is genuine. Light Rider signs every draw's receipt (Ed25519). The public key is at entropy.lightriderinc.com/api/v1/public-key.
- The seed is that draw's output. The signed receipt includes a hash of the exact bytes drawn, so a seed from any other draw doesn't match.
- The data follows from the seed. Generation is deterministic, so
verifyrebuilds every row from the seed and parameters and compares it with the published data.
What this doesn't claim
That quantum randomness makes this dataset better than one built with a good classical generator. It's an alternative source whose origin you can check. A receipt also can't show that the publisher drew only once; its timestamp shows when the draw happened.
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