id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__BTUp6bpUvIxN4RTy | Find the lowest common multiple of 25, 35 and 50. Choose the correct choice:
A) 350
B) 420
C) 510
D) 320
E) 280 | <gadget id="calculator">lcm(25, 35)</gadget>
<output>175</output>
<gadget id="calculator">lcm(175, 50)</gadget>
<output>350</output>
<result>A</result> | A | 350 | Find the lowest common multiple of 25, 35 and 50. | {
"A": "350",
"B": "420",
"C": "510",
"D": "320",
"E": "280"
} | lcm(lcm(25, 35), 50) | lcm(n0,n1)|lcm(n2,#0) | lcm = 2 * 5 * 5 * 7 = 350 . answer is a | general |
math_qa__C60VBGJFiZDYUMAY | A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 580 pounds after processing, how many pounds did it weigh before processing?
Choose the most appropriate option.
A) 191 B) 355 C) 737 D) 892 E) 1,560 | <gadget id="calculator">580 * 100</gadget>
<output>58_000</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">58_000 / 65</gadget>
<output>11_600/13 = around 892.307692</output>
<result>D</result> | D | 892 | A side of beef lost 35 percent of its weight in processing. If the side of beef weighed 580 pounds after processing, how many pounds did it weigh before processing? | {
"A": "191",
"B": "355",
"C": "737",
"D": "892",
"E": "1,560"
} | divide(multiply(580, const_100), subtract(const_100, 35)) | multiply(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)| | "let weight of side of beef before processing = x ( 65 / 100 ) * x = 580 = > x = ( 580 * 100 ) / 65 = 892 answer d" | gain |
math_qa__sLh0gbnfIcf0Llh0 | Country X imported approximately $1.20 billion of goods in 1996. If Country X imported $288 million of goods in the first two months of 1997 and continued to import goods at the same rate for the rest of the year, by how much would Country Xs 1997 imports exceed those of 1996? Answers.
A) $ 24 million B) $ 120 million C) $ 144 million D) $ 240 million E) $ 528 million | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">288 * 6</gadget>
<output>1_728</output>
<gadget id="calculator">1.2 * 1_000</gadget>
<output>1_200</output>
<gadget id="calculator">1_728 - 1_200</gadget>
<output>528</output>
<result>E</result> | E | 528 | Country X imported approximately $1.20 billion of goods in 1996. If Country X imported $288 million of goods in the first two months of 1997 and continued to import goods at the same rate for the rest of the year, by how much would Country Xs 1997 imports exceed those of 1996? | {
"A": "$ 24 million",
"B": "$ 120 million",
"C": "$ 144 million",
"D": "$ 240 million",
"E": "$ 528 million"
} | subtract(multiply(288, divide(const_12, const_2)), multiply(1.20, const_1000)) | divide(const_12,const_2)|multiply(n0,const_1000)|multiply(n2,#0)|subtract(#2,#1)| | "convert units to millions as answer is in millions 1996 imports = $ 1.20 bill = $ 1200 mill i . e . 1200 / 12 = $ 100 mill / month 1997 imports = $ 288 mill / 2 month i . e . $ 144 mill / month difference / month = 144 - 100 = 44 difference / year = $ 44 mill * 12 = $ 528 mill answer : e" | general |
math_qa__Wv6noouPQPTR8HqO | A man rows his boat 72 km downstream and 30 km upstream, taking 3 hours each time. Find the speed of the stream?
Choose the correct choice from the following options:
A) 6 kmph B) 5 kmph C) 2 kmph D) 8 kmph E) 7 kmph | <gadget id="calculator">72 / 3</gadget>
<output>24</output>
<gadget id="calculator">30 / 3</gadget>
<output>10</output>
<gadget id="calculator">24 - 10</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<result>E</result> | E | 7 | A man rows his boat 72 km downstream and 30 km upstream, taking 3 hours each time. Find the speed of the stream? | {
"A": "6 kmph",
"B": "5 kmph",
"C": "2 kmph",
"D": "8 kmph",
"E": "7 kmph"
} | divide(subtract(divide(72, 3), divide(30, 3)), const_2) | divide(n0,n2)|divide(n1,n2)|subtract(#0,#1)|divide(#2,const_2)| | "speed downstream = d / t = 72 / ( 3 ) = 24 kmph speed upstream = d / t = 30 / ( 3 ) = 10 kmph the speed of the stream = ( 24 - 10 ) / 2 = 7 kmph answer : e" | physics |
math_qa__VF1mmqI2Aww325un | A certain fruit stand sold apples for $0.70 each and bananas for $0.60 each. If a customer purchased both apples and bananas from the stand for a total of $5.60, what total number of apples and bananas did the customer purchase?
Choose the correct choice from the following
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">0.7 * 2</gadget>
<output>1.4</output>
<gadget id="calculator">5.6 - 1.4</gadget>
<output>4.2</output>
<gadget id="calculator">4.2 / 0.6</gadget>
<output>7</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<result>B</result> | B | 9 | A certain fruit stand sold apples for $0.70 each and bananas for $0.60 each. If a customer purchased both apples and bananas from the stand for a total of $5.60, what total number of apples and bananas did the customer purchase? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | add(divide(subtract(5.60, multiply(0.70, const_2)), 0.60), const_2) | multiply(n0,const_2)|subtract(n2,#0)|divide(#1,n1)|add(#2,const_2)| | "let ' s start with 1 apple for $ 0.70 . let ' s subtract $ 0.70 from $ 5.60 until we get a multiple of $ 0.60 . $ 5.60 , $ 4.90 , $ 4.20 = 7 * $ 0.60 the customer purchased 7 bananas and 2 apples . the answer is b ." | other |
math_qa__GINo8WMrWvx4eCcC | 25 liters of a mixture is created by mixing Liquid P and Liquid Q in the ratio 3:2. How many liters of Liquid Q must be added to make the ratio 5:4? Choose the correct choice
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">25 * 3</gadget>
<output>75</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">75 / 5</gadget>
<output>15</output>
<gadget id="calculator">9 * 15</gadget>
<output>135</output>
<gadget id="calculator">135 / 5</gadget>
<output>27</output>
<gadget id="calculator">27 * 4</gadget>
<output>108</output>
<gadget id="calculator">108 / 9</gadget>
<output>12</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 5</gadget>
<output>10</output>
<gadget id="calculator">12 - 10</gadget>
<output>2</output>
<result>B</result> | B | 2 | 25 liters of a mixture is created by mixing Liquid P and Liquid Q in the ratio 3:2. How many liters of Liquid Q must be added to make the ratio 5:4? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(divide(multiply(divide(multiply(add(5, 4), divide(multiply(25, 3), add(3, 2))), 5), 4), add(5, 4)), divide(multiply(25, 2), add(3, 2))) | add(n3,n4)|add(n1,n2)|multiply(n0,n1)|multiply(n0,n2)|divide(#2,#1)|divide(#3,#1)|multiply(#0,#4)|divide(#6,n3)|multiply(n4,#7)|divide(#8,#0)|subtract(#9,#5)| | "let x be the amount of liquid q to be added . ( 2 / 5 ) * 25 + x = ( 4 / 9 ) * ( 25 + x ) 450 + 45 x = 500 + 20 x 25 x = 50 x = 2 the answer is b ." | general |
math_qa__jsxBhH7aSgzctJlk | Elena purchased Brand X pens for $4.00 apiece and brand Y for $2.20 apiece. If Elena purchased a total of 12 of these pens for $42.00, how many brand X pens did she purchase?
Choose the correct choice.
A) 4 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">4 * 12</gadget>
<output>48</output>
<gadget id="calculator">48 - 42</gadget>
<output>6</output>
<result>C</result> | C | 6 | Elena purchased Brand X pens for $4.00 apiece and brand Y for $2.20 apiece. If Elena purchased a total of 12 of these pens for $42.00, how many brand X pens did she purchase? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | subtract(multiply(4, 12), 42) | multiply(n0,n2)|subtract(#0,n3) | 4 x + 2.8 y = 42 - - > multiply by 2.5 ( to get the integers ) - - > 10 x + 7 y = 105 - - > only one positive integers solutions x = 6 and y = 5 ( how to solve : 7 y must have the last digit of 5 in order the last digit of the sum to be 5 ) . answer : c . | general |
math_qa__mgqHgZZnjokwn7pe | Walking at 5/6th of its usual speed a cab is 6mnts late. Find its usual time to cover the journey? Select the correct option:
A) 25 m B) 30 m C) 32 m D) 50 m E) 62 m | <gadget id="calculator">5 * 6</gadget>
<output>30</output>
<result>B</result> | B | 30 | Walking at 5/6th of its usual speed a cab is 6mnts late. Find its usual time to cover the journey? | {
"A": "25 m",
"B": "30 m",
"C": "32 m",
"D": "50 m",
"E": "62 m"
} | multiply(5, 6) | multiply(n0,n2)| | "new speed = 5 / 6 th of usual speed new time = 6 / 5 th of usual time 6 / 5 ut - ut = 6 m ut / 5 = 6 m ut = 30 m answer is b" | physics |
math_qa__jJqbkhtKwFdEgniF | What is the sum of the digits of integer k, if k = (10^50- 50) Choose one
A) 337 B) 437 C) 457 D) 537 E) 412 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">9 * 48</gadget>
<output>432</output>
<gadget id="calculator">432 + 10</gadget>
<output>442</output>
<result>B</result> | B | 437 | What is the sum of the digits of integer k, if k = (10^50- 50) | {
"A": "337",
"B": "437",
"C": "457",
"D": "537",
"E": "412"
} | add(multiply(subtract(10, const_1), subtract(50, const_2)), 10) | subtract(n0,const_1)|subtract(n1,const_2)|multiply(#0,#1)|add(#2,n0)| | "there are 51 digits in 10 ^ 50 when we subtract 50 from it , there will be 50 digits left . 10 ^ 50 can be written as 9999999 . . . . ( 50 times ) + 1 so , 10 ^ 50 - 50 = 9999999 . . . . ( 50 times ) + 1 - 50 = 9999999 . . . . ( 50 times ) - 49 consider the last 2 digits , 99 - 49 = 50 the last 2 digits will be 50 . and our number would be 99999 . . . . . . 99950 with 2 less 9 s after subtraction . number of 9 s left are 48 and the last two digits are 50 the sum of the digits will be ( 48 * 9 ) + 5 + 0 = 437 answer : - b" | general |
math_qa__9X2rBkmMKaYmuaTf | What is the least number which when divided by 6, 9, 12 and 18 leaves remainder 4 in each care? Pick one.
A) 30
B) 40
C) 36
D) 56
E) 66 | <gadget id="calculator">lcm(6, 9)</gadget>
<output>18</output>
<gadget id="calculator">lcm(12, 18)</gadget>
<output>36</output>
<gadget id="calculator">lcm(18, 36)</gadget>
<output>36</output>
<gadget id="calculator">36 + 4</gadget>
<output>40</output>
<result>B</result> | B | 40 | What is the least number which when divided by 6, 9, 12 and 18 leaves remainder 4 in each care? | {
"A": "30",
"B": "40",
"C": "36",
"D": "56",
"E": "66"
} | add(lcm(lcm(6, 9), lcm(12, 18)), 4) | lcm(n0,n1)|lcm(n2,n3)|lcm(#0,#1)|add(n4,#2)| | "explanation : lcm of 6 , 9 , 12 and 18 is 36 required number = 36 + 4 = 40 answer : option b" | general |
math_qa__tl92PfCcvoEmVLaJ | A bullet train 200 m long is running with a speed of 69 kmph. In what time will it pass a man who is running at 3 kmph in the direction opposite to that in which the bullet train is going? Choose the correct choice from the following answers: A) 10 sec B) 15 sec C) 12 sec D) 11 sec E) 16 sec | <gadget id="calculator">69 + 3</gadget>
<output>72</output>
<gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">200 / 20</gadget>
<output>10</output>
<result>A</result> | A | 10 | A bullet train 200 m long is running with a speed of 69 kmph. In what time will it pass a man who is running at 3 kmph in the direction opposite to that in which the bullet train is going? | {
"A": "10 sec",
"B": "15 sec",
"C": "12 sec",
"D": "11 sec",
"E": "16 sec"
} | divide(200, divide(multiply(add(69, 3), const_1000), const_3600)) | add(n1,n2)|multiply(#0,const_1000)|divide(#1,const_3600)|divide(n0,#2)| | "a 10 sec speed of the bullet train relative to man = ( 69 + 3 ) kmph = 72 * 5 / 18 m / sec = 60 / 3 m / sec . time taken by the bullet train to cross the man = time taken by it to cover 200 m at ( 60 / 3 ) m / sec = ( 200 * 3 / 60 ) sec = 10 sec" | physics |
math_qa__GZKYgBIjA2WsRBYi | In what time will a railway train 90 m long moving at the rate of 36 kmph pass a telegraph post on its way?
Choose the correct option: A) 8 sec B) 1 sec C) 9 sec D) 6 sec E) 2 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">90 / 10</gadget>
<output>9</output>
<result>C</result> | C | 9 | In what time will a railway train 90 m long moving at the rate of 36 kmph pass a telegraph post on its way? | {
"A": "8 sec",
"B": "1 sec",
"C": "9 sec",
"D": "6 sec",
"E": "2 sec"
} | divide(90, multiply(36, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 90 / 36 * 18 / 5 = 9 sec answer : c" | physics |
math_qa__kx2x1tmcl7nj0ste | After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6800. Find the actual price of the good.
Choose the correct choice from the following.
A) s . 6000 B) s . 9000 C) s . 10800 D) s . 9942 E) s . 9980 | <gadget id="calculator">6_800 * 100</gadget>
<output>680_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 * 10</gadget>
<output>800</output>
<gadget id="calculator">800 / 100</gadget>
<output>8</output>
<gadget id="calculator">80 - 8</gadget>
<output>72</output>
<gadget id="calculator">72 * 5</gadget>
<output>360</output>
<gadget id="calculator">360 / 100</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">72 - (18/5)</gadget>
<output>342/5 = around 68.4</output>
<gadget id="calculator">680_000 / (342/5)</gadget>
<output>1_700_000/171 = around 9_941.520468</output>
<result>D</result> | D | 9,942 | After successive discounts of 20%, 10% and 5% a certain good is sold for Rs. 6800. Find the actual price of the good. | {
"A": "s . 6000",
"B": "s . 9000",
"C": "s . 10800",
"D": "s . 9942",
"E": "s . 9980"
} | divide(multiply(6800, const_100), subtract(subtract(subtract(const_100, 20), divide(multiply(subtract(const_100, 20), 10), const_100)), divide(multiply(subtract(subtract(const_100, 20), divide(multiply(subtract(const_100, 20), 10), const_100)), 5), const_100))) | multiply(n3,const_100)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,const_100)|subtract(#1,#3)|multiply(n2,#4)|divide(#5,const_100)|subtract(#4,#6)|divide(#0,#7)| | "let actual price was 100 . after three successive discount this will become , 100 = = 20 % discount = > 80 = = 10 % discount = > 72 = = 5 % discount = 68.4 now compare , 68.4 = 6800 1 = 6800 / 68.4 100 = ( 6800 * 100 ) / 68.4 = rs . 9942 . answer : option d" | gain |
math_qa__kyFIWBjP1bHFTFKY | A can run 160 metre in 28 seconds and B in 32 seconds. By what distance A beat B?
Choose the correct option.
A) 38 metre B) 28 metre C) 20 metre D) 15 metre E) 28 metre | <gadget id="calculator">160 / 32</gadget>
<output>5</output>
<gadget id="calculator">5 * 28</gadget>
<output>140</output>
<gadget id="calculator">160 - 140</gadget>
<output>20</output>
<result>C</result> | C | 20 | A can run 160 metre in 28 seconds and B in 32 seconds. By what distance A beat B? | {
"A": "38 metre",
"B": "28 metre",
"C": "20 metre",
"D": "15 metre",
"E": "28 metre"
} | subtract(160, multiply(divide(160, 32), 28)) | divide(n0,n2)|multiply(n1,#0)|subtract(n0,#1)| | "clearly , a beats b by 4 seconds now find out how much b will run in these 4 seconds speed of b = distance / time taken by b = 160 / 32 = 5 m / s distance covered by b in 4 seconds = speed ã — time = 5 ã — 4 = 20 metre i . e . , a beat b by 20 metre answer is c" | physics |
math_qa__r8sq65SHYMd5OnI4 | A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used?
Choose the correct answer.
A) 20 B) 30 C) 40 D) 50 E) 60 | <gadget id="calculator">20 * 8</gadget>
<output>160</output>
<gadget id="calculator">6 * 20</gadget>
<output>120</output>
<gadget id="calculator">160 - 120</gadget>
<output>40</output>
<result>C</result> | C | 40 | A club wants to mix 20 pounds of candy worth $8.00 per pound with candy worth $5.00 per pound to reduce the cost of the mixture to $6.00 per pound. How many pounds of the $5.00 per pound candy should be used? | {
"A": "20",
"B": "30",
"C": "40",
"D": "50",
"E": "60"
} | subtract(multiply(20, 8), multiply(6, 20)) | multiply(n0,n1)|multiply(n0,n3)|subtract(#0,#1) | let number of pounds of 5 $ candy to be used be w 6 = ( 20 * 8 + 5 * w ) / ( 20 + w ) = > 120 + 6 w = 160 + 5 w = > w = 40 answer c | general |
math_qa__4oa2HPrBgYnRIHsr | A student gets 60% in one subject, 70% in the other. To get an overall of 70% how much should get in third subject.
Choose the correct choice from the following choices: A) 75 % B) 80 % C) 45 % D) 55 % E) 65 % | <gadget id="calculator">70 * 3</gadget>
<output>210</output>
<gadget id="calculator">60 + 70</gadget>
<output>130</output>
<gadget id="calculator">210 - 130</gadget>
<output>80</output>
<result>B</result> | B | 80 | A student gets 60% in one subject, 70% in the other. To get an overall of 70% how much should get in third subject. | {
"A": "75 %",
"B": "80 %",
"C": "45 %",
"D": "55 %",
"E": "65 %"
} | subtract(multiply(70, const_3), add(60, 70)) | add(n0,n1)|multiply(n2,const_3)|subtract(#1,#0)| | "let the 3 rd subject % = x 60 + 70 + x = 3 * 70 130 + x = 210 x = 210 - 130 = 80 answer : b" | gain |
math_qa__MeKv5Ap3FM10xR3x | If A's height is 30% less than that of B, how much percent B's height is more than that of A? Choose the most appropriate option.
A) 42.85 % B) 66.68 % C) 66.766 % D) 86.66 % E) 66.65 % | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">30 / 70</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 100</gadget>
<output>300/7 = around 42.857143</output>
<result>A</result> | A | 42.85 | If A's height is 30% less than that of B, how much percent B's height is more than that of A? | {
"A": "42.85 %",
"B": "66.68 %",
"C": "66.766 %",
"D": "86.66 %",
"E": "66.65 %"
} | multiply(divide(30, subtract(const_100, 30)), const_100) | subtract(const_100,n0)|divide(n0,#0)|multiply(#1,const_100) | excess of b ' s height over a ' s = [ ( 30 / ( 100 - 30 ) ] x 100 % = 42.85 % answer : a ) | general |
math_qa__Gk3JwVwE1IxlzFC2 | Of the 65 cars on a car lot, 45 have air-bag, 30 have power windows, and 12 have both air-bag and power windows. How many of the cars on the lot have neither air-bag nor power windows? Choose the correct choice from the following.
A) 8 B) 2 C) 10 D) 15 E) 18 | <gadget id="calculator">45 + 30</gadget>
<output>75</output>
<gadget id="calculator">75 - 12</gadget>
<output>63</output>
<gadget id="calculator">65 - 63</gadget>
<output>2</output>
<result>B</result> | B | 2 | Of the 65 cars on a car lot, 45 have air-bag, 30 have power windows, and 12 have both air-bag and power windows. How many of the cars on the lot have neither air-bag nor power windows? | {
"A": "8",
"B": "2",
"C": "10",
"D": "15",
"E": "18"
} | subtract(65, subtract(add(45, 30), 12)) | add(n1,n2)|subtract(#0,n3)|subtract(n0,#1) | total - neither = all air bag + all power windows - both or 65 - neither = 45 + 30 - 12 = 63 . = > neither = 2 , hence b . answer : b | other |
math_qa__ZeEA9frB8z5PIbqC | A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?
Choose the correct choice from the following options.
A) 315 B) 339 C) 288 D) 299 E) 111 | <gadget id="calculator">700 / 2</gadget>
<output>350</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">350 * (1/5)</gadget>
<output>70</output>
<gadget id="calculator">700 - 70</gadget>
<output>630</output>
<gadget id="calculator">630 / 2</gadget>
<output>315</output>
<result>A</result> | A | 315 | A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares? | {
"A": "315",
"B": "339",
"C": "288",
"D": "299",
"E": "111"
} | divide(subtract(700, multiply(divide(700, const_2), divide(const_1, add(const_1, const_4)))), const_2) | add(const_1,const_4)|divide(n0,const_2)|divide(const_1,#0)|multiply(#1,#2)|subtract(n0,#3)|divide(#4,const_2) | explanation : let the areas of the two parts be x and ( 700 - x ) hectares therefore , so , the two parts are 385 and 315 . hence , area of the smaller = 315 hectares answer : a ) 315 | general |
math_qa__tkypo9NBDH43qdUl | If 2994 ÷ 14.5 = 177, then 29.94 ÷ 1.45 = ? Pick one
A) 17.1 B) 17.3 C) 17.5 D) 17.7 E) 17.2 | <gadget id="calculator">14.5 / 1.45</gadget>
<output>10</output>
<gadget id="calculator">177 / 10</gadget>
<output>177/10 = around 17.7</output>
<result>D</result> | D | 17.7 | If 2994 ÷ 14.5 = 177, then 29.94 ÷ 1.45 = ? | {
"A": "17.1",
"B": "17.3",
"C": "17.5",
"D": "17.7",
"E": "17.2"
} | divide(177, divide(14.5, 1.45)) | divide(n1,n4)|divide(n2,#0)| | "29.94 / 1.45 = 299.4 / 14.5 = ( 2994 / 14.5 ) x 1 / 10 ) [ here , substitute 177 in the place of 2994 / 14.5 ] = 177 / 10 = 17.7 answer is d ." | general |
math_qa__zInTc4ocWmYnbQjp | A part-time employee whose hourly wage was decreased by 20 percent decided to increase the number of hours worked per week so that the employee's total income did not change. By what percent T should the number of hours worked be increased? Choose the correct choice from the following choices.
A) 12.5 %
B) 20 %
C) 25 %
D) 50 %
E) 100 % | <gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 10</gadget>
<output>8</output>
<gadget id="calculator">40 / 8</gadget>
<output>5</output>
<gadget id="calculator">5 - 4</gadget>
<output>1</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | A part-time employee whose hourly wage was decreased by 20 percent decided to increase the number of hours worked per week so that the employee's total income did not change. By what percent T should the number of hours worked be increased? | {
"A": "12.5 %",
"B": "20 %",
"C": "25 %",
"D": "50 %",
"E": "100 %"
} | multiply(divide(subtract(divide(multiply(const_10, const_4), multiply(divide(subtract(const_100, 20), const_100), const_10)), const_4), const_4), const_100) | multiply(const_10,const_4)|subtract(const_100,n0)|divide(#1,const_100)|multiply(#2,const_10)|divide(#0,#3)|subtract(#4,const_4)|divide(#5,const_4)|multiply(#6,const_100) | correct answer : c solution : c . we can set up equations for income before and after the wage reduction . initially , the employee earns w wage and works h hours per week . after the reduction , the employee earns . 8 w wage and works x hours . by setting these equations equal to each other , we can determine the increase in hours worked : wh = . 8 wx ( divide both sides by . 8 w ) 1.25 h = x we know that the new number of hours worked t will be 25 % greater than the original number . the answer is c . | general |
math_qa__lkjxUefcDtDNrapi | Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ?
Choose the correct choice from the following answers.
A) 9 / 10 B) 6 / 10 C) 2 / 10 D) 3 / 10 E) 5 / 10 | <gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<result>D</result> | D | 0.3 | Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ? | {
"A": "9 / 10",
"B": "6 / 10",
"C": "2 / 10",
"D": "3 / 10",
"E": "5 / 10"
} | divide(const_3.0, const_10) | divide(const_3.0,const_10)| | "explanation : here , s = { 1 , 2 , 3 , 4 , . . . . , 19 , 20 } = > n ( s ) = 20 let e = event of getting a multiple of 4 or 15 = multiples od 4 are { 4 , 8 , 12 , 16 , 20 } and multiples of 15 means multiples of 3 and 5 = { 3 , 6 , 9 , 12 , 15 , 18 , 5 , 10 , 15 , 20 } . = the common multiple is only ( 15 ) . = > e = n ( e ) = 6 required probability = p ( e ) = n ( e ) / n ( s ) = 6 / 20 = 3 / 10 . answer is d" | general |
math_qa__rG3EJDAyyHrD9KAR | Cole drove from home to work at an average speed of 75 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 4 hours, how many minutes did it take Cole to drive to work? Choose the correct choice from the following answers
A) 66
B) 70
C) 95
D) 112
E) 140 | <gadget id="calculator">105 * 4</gadget>
<output>420</output>
<gadget id="calculator">75 + 105</gadget>
<output>180</output>
<gadget id="calculator">420 / 180</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">(7/3) * 60</gadget>
<output>140</output>
<result>E</result> | E | 140 | Cole drove from home to work at an average speed of 75 kmh. He then returned home at an average speed of 105 kmh. If the round trip took a total of 4 hours, how many minutes did it take Cole to drive to work? | {
"A": "66",
"B": "70",
"C": "95",
"D": "112",
"E": "140"
} | multiply(divide(multiply(105, 4), add(75, 105)), const_60) | add(n0,n1)|multiply(n1,n2)|divide(#1,#0)|multiply(#2,const_60) | first round distance travelled ( say ) = d speed = 75 k / h time taken , t 2 = d / 75 hr second round distance traveled = d ( same distance ) speed = 105 k / h time taken , t 2 = d / 105 hr total time taken = 4 hrs therefore , 4 = d / 75 + d / 105 lcm of 75 and 105 = 525 4 = d / 75 + d / 105 = > 4 = 7 d / 525 + 5 d / 525 = > d = 525 / 3 km therefore , t 1 = d / 75 = > t 1 = 525 / ( 3 x 75 ) = > t 1 = ( 7 x 60 ) / 3 - - in minutes = > t 1 = 140 minutes . e | physics |
math_qa__OKxt9SwSOOgPSBwU | In the xy-coordinate system, if (m, n) and (m + 2, n + k) are two points on the line with the equation x = 2y + 5, then k = Choose the correct choice from the following options.
A) 1 / 2 B) 1 C) 2 D) 5 / 2 E) 4 | <gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">7 - 5</gadget>
<output>2</output>
<gadget id="calculator">2 / 2</gadget>
<output>1</output>
<result>B</result> | B | 1 | In the xy-coordinate system, if (m, n) and (m + 2, n + k) are two points on the line with the equation x = 2y + 5, then k = | {
"A": "1 / 2",
"B": "1",
"C": "2",
"D": "5 / 2",
"E": "4"
} | divide(subtract(add(5, 2), 5), 2) | add(n0,n2)|subtract(#0,n2)|divide(#1,n1)| | "the equation of the line can be re written as y = ( 1 / 2 ) x - 5 / 2 . slope = 1 / 2 , which means for every 1 unit increase in the y co - ordinate , x will increase by 2 units . hence k = 1 . answer : b" | general |
math_qa__dhQfO3RBHfGdOeN7 | $600 is divided amongst A,B and C so that A may get 2/3 as much as B and C together, B may get 6/9 as much as A and C together, then the share of A is Choose the correct choice from the following options:
A) $ 100 B) $ 150 C) $ 125 D) $ 200 E) $ 240 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) + 1</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">600 / (5/3)</gadget>
<output>360</output>
<gadget id="calculator">360 * (2/3)</gadget>
<output>240</output>
<result>E</result> | E | 240 | $600 is divided amongst A,B and C so that A may get 2/3 as much as B and C together, B may get 6/9 as much as A and C together, then the share of A is | {
"A": "$ 100",
"B": "$ 150",
"C": "$ 125",
"D": "$ 200",
"E": "$ 240"
} | multiply(divide(600, add(divide(2, 3), const_1)), divide(2, 3)) | divide(n1,n2)|add(#0,const_1)|divide(n0,#1)|multiply(#2,#0)| | "a : ( b + c ) = 2 : 3 a ' s share = 600 * 2 / 5 = $ 240 answer is e" | general |
math_qa__r8K9nOBQ3JiZUlYl | The speed of a boat in still water is 20 km/hr and the rate of current is 5 km/hr. The distance travelled downstream in 12 minutes is: Choose the correct choice from the following options.
A) 9 B) 5 C) 7 D) 6 E) 51 | <gadget id="calculator">12 / 60</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">(1/5) * 25</gadget>
<output>5</output>
<result>B</result> | B | 5 | The speed of a boat in still water is 20 km/hr and the rate of current is 5 km/hr. The distance travelled downstream in 12 minutes is: | {
"A": "9",
"B": "5",
"C": "7",
"D": "6",
"E": "51"
} | multiply(divide(12, const_60), add(20, 5)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "explanation : speed downstream = ( 20 + 5 ) kmph = 25 kmph distance travelled = ( 25 * ( 12 / 60 ) ) km = 5 km . answer : b" | physics |
math_qa__kmEFWatU1NSHhhEW | A sum was put at simple interest at a certain rate for 6 years Had it been put at 4% higher rate, it would have fetched 144 more. Find the sum. Choose the correct choice:
A) 500 B) 600 C) 700 D) 800 E) 900 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) * 6</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">144 / (6/25)</gadget>
<output>600</output>
<result>B</result> | B | 600 | A sum was put at simple interest at a certain rate for 6 years Had it been put at 4% higher rate, it would have fetched 144 more. Find the sum. | {
"A": "500",
"B": "600",
"C": "700",
"D": "800",
"E": "900"
} | divide(144, multiply(divide(4, const_100), 6)) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)| | "difference in s . i . = p × t / 100 ( r 1 − r 2 ) ⇒ 144 = p × 6 x 4 / 100 ( ∵ r 1 - r 2 = 2 ) ⇒ p = 144 × 100 / 6 × 4 = 600 answer b" | gain |
math_qa__kXsSILoXSCT1pNeH | What least no. must be subtracted from 427398 so that remaining no.is divisible by 10? Choose the correct option.
A) 8
B) 9
C) 7
D) 6
E) 3 | <gadget id="calculator">427_398 / 10</gadget>
<output>213_699/5 = around 42_739.8</output>
<gadget id="calculator">floor(213_699/5)</gadget>
<output>42_739</output>
<gadget id="calculator">42_739 * 10</gadget>
<output>427_390</output>
<gadget id="calculator">427_398 - 427_390</gadget>
<output>8</output>
<result>A</result> | A | 8 | What least no. must be subtracted from 427398 so that remaining no.is divisible by 10? | {
"A": "8",
"B": "9",
"C": "7",
"D": "6",
"E": "3"
} | subtract(427398, multiply(floor(divide(427398, 10)), 10)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "explanation : on dividing 427398 by 10 we get the remainder 8 , so 8 should be subtracted option a" | general |
math_qa__i84li6NntfmO0NRV | The number of students enrolled at school XX this year is 7 percent more than it was last year. The number of students enrolled at school YY this year is 3 percent more than it was last year. If school XX grew by 40 more students than school YY did, and if there were 4000 total enrolled students last year at both schools, how many students were enrolled at school YY last year? Choose the correct option:
A) 480 B) 1600 C) 1920 D) 2080 E) 2400 | <gadget id="calculator">7 * 4_000</gadget>
<output>28_000</output>
<gadget id="calculator">28_000 - 4_000</gadget>
<output>24_000</output>
<gadget id="calculator">7 + 3</gadget>
<output>10</output>
<gadget id="calculator">24_000 / 10</gadget>
<output>2_400</output>
<result>E</result> | E | 2,400 | The number of students enrolled at school XX this year is 7 percent more than it was last year. The number of students enrolled at school YY this year is 3 percent more than it was last year. If school XX grew by 40 more students than school YY did, and if there were 4000 total enrolled students last year at both schools, how many students were enrolled at school YY last year? | {
"A": "480",
"B": "1600",
"C": "1920",
"D": "2080",
"E": "2400"
} | divide(subtract(multiply(7, 4000), 4000), add(7, 3)) | add(n0,n1)|multiply(n0,n3)|subtract(#1,n3)|divide(#2,#0) | given info : no . of students enrolled in school x is = 7 % more than previous year ' s strength = 7 x / 100 no . of students enrolled in school y is = 3 % more than previous year ' s strength = 3 y / 100 given that ` ` this year ' ' school x have 40 students more than school y . so the increase in strength can be written as 7 x / 100 = 40 + 3 y / 100 7 x = 4000 + 3 y . . . . . . . . . . . . . . . . . . . . ( 1 ) and total students on previous year are x + y = 4000 . . . . . . . . . . . . . . . . . . . . . . ( 2 ) equating & solving we get , y = 2400 ans is e | general |
math_qa__1we4xOxQnC7z954v | A 20 litre mixture of milk and water contains milk and water in the ratio 3 : 2. 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more. At the end of the two removal and replacement, what is the ratio T of milk and water in the resultant mixture?
Choose the correct choice from the following.
A) 17 : 3 B) 9 : 1 C) 3 : 17 D) 5 : 3 E) 11 : 2 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">(3/5) * 10</gadget>
<output>6</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<gadget id="calculator">16 / 20</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 10</gadget>
<output>8</output>
<gadget id="calculator">8 + 10</gadget>
<output>18</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 10</gadget>
<output>4</output>
<gadget id="calculator">4 / 20</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 10</gadget>
<output>2</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<result>B</result> | B | 9 | A 20 litre mixture of milk and water contains milk and water in the ratio 3 : 2. 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more. At the end of the two removal and replacement, what is the ratio T of milk and water in the resultant mixture? | {
"A": "17 : 3",
"B": "9 : 1",
"C": "3 : 17",
"D": "5 : 3",
"E": "11 : 2"
} | divide(add(multiply(divide(add(multiply(divide(3, add(3, 2)), subtract(20, 10)), 10), 20), subtract(20, 10)), 10), multiply(divide(multiply(divide(2, add(3, 2)), subtract(20, 10)), 20), subtract(20, 10))) | add(n1,n2)|subtract(n0,n3)|divide(n1,#0)|divide(n2,#0)|multiply(#2,#1)|multiply(#3,#1)|add(n3,#4)|divide(#5,n0)|divide(#6,n0)|multiply(#7,#1)|multiply(#8,#1)|add(n3,#10)|divide(#11,#9)| | "he 20 litre mixture contains milk and water in the ratio of 3 : 2 . therefore , there will be 12 litres of milk in the mixture and 8 litres of water in the mixture . step 1 . when 10 litres of the mixture is removed , 6 litres of milk is removed and 4 litres of water is removed . therefore , there will be 6 litres of milk and 4 litres of water left in the container . it is then replaced with pure milk of 10 litres . now the container will have 16 litres of milk and 4 litres of water . step 2 . when 10 litres of the new mixture is removed , 8 litres of milk and 2 litres of water is removed . the container will have 8 litres of milk and 2 litres of water in it . now 10 litres of pure milk is added . therefore , the container will have 18 litres of milk and 2 litres of water in it at the end of the second step . therefore , the ratio of milk and water is 18 : 2 or 9 : 1 . shortcut . we are essentially replacing water in the mixture with pure milk . let w _ o be the amount of water in the mixture originally = 8 litres . let w _ r be the amount of water in the mixture after the replacements have taken place . then , { w _ r } / { w _ o } = ( 1 - r / m ) ^ n where r is the amount of the mixture replaced by milk in each of the steps , m is the total volume of the mixture and n is the number of times the cycle is repeated . hence , { w _ r } / { w _ o } = ( 1 / 2 ) ^ 2 = 1 / 4 therefore , tw _ r = { w _ o } / 4 = 8 / 4 = 2 litres . b" | general |
math_qa__26LSexvD7SBfRXU2 | The average runs scored by a batsman in 35 matches is 36. In the next 14 matches the batsman scored an average of 15 runs. Find his average in all the 30 matches? Choose one
A) 31 B) 35 C) 29 D) 25 E) 30 | <gadget id="calculator">36 * 35</gadget>
<output>1_260</output>
<gadget id="calculator">15 * 14</gadget>
<output>210</output>
<gadget id="calculator">1_260 + 210</gadget>
<output>1_470</output>
<gadget id="calculator">35 + 14</gadget>
<output>49</output>
<gadget id="calculator">1_470 / 49</gadget>
<output>30</output>
<result>E</result> | E | 30 | The average runs scored by a batsman in 35 matches is 36. In the next 14 matches the batsman scored an average of 15 runs. Find his average in all the 30 matches? | {
"A": "31",
"B": "35",
"C": "29",
"D": "25",
"E": "30"
} | divide(add(multiply(36, 35), multiply(15, 14)), add(35, 14)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | total score of the batsman in 35 matches = 1260 . total score of the batsman in the next 14 matches = 210 . total score of the batsman in the 30 matches = 1470 . average score of the batsman = 1470 / 49 = 30 . answer : e | general |
math_qa__YwNX3aDjTu391Hel | The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 18, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers? Choose the correct choice from the following answers:
A) 16 B) 23 C) 19 D) 20 E) 22 | <gadget id="calculator">18 * 5</gadget>
<output>90</output>
<gadget id="calculator">90 - 40</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 2</gadget>
<output>23</output>
<result>B</result> | B | 23 | The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 18, and k < m < r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers? | {
"A": "16",
"B": "23",
"C": "19",
"D": "20",
"E": "22"
} | subtract(divide(subtract(multiply(18, 5), 40), const_2), const_2) | multiply(n0,n1)|subtract(#0,n2)|divide(#1,const_2)|subtract(#2,const_2)| | "we need to find the median which is the third value when the numbers are in increasing order . since k < m < r < s < t , the median would be r . the average of the positive integers is 18 which means that in effect , all numbers are equal to 18 . if the largest number is 40 , it is 22 more than 18 . we need r to be maximum so k and m should be as small as possible to get the average of 16 . since all the numbers are positive integers , k and m can not be less than 1 and 2 respectively . 1 is 17 less than 18 and 2 is 16 less than 18 which means k and m combined are 33 less than the average . 40 is already 22 more than 18 and hence we only have 33 - 22 = 11 extra to distribute between r and s . since s must be greater than r , r can be 18 + 5 = 23 and s can be 18 + 6 = 24 . so r is 23 answer ( b )" | general |
math_qa__JSDJvVpPba8Z825r | How many positive integers less than 7,000 are there in which the sum of the digits equals 5? Choose the correct answer:
A) 52 B) 54 C) 56 D) 58 E) 60 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<result>C</result> | C | 56 | How many positive integers less than 7,000 are there in which the sum of the digits equals 5? | {
"A": "52",
"B": "54",
"C": "56",
"D": "58",
"E": "60"
} | divide(factorial(subtract(add(const_4, 5), const_1)), multiply(factorial(5), factorial(subtract(const_4, const_1)))) | add(n1,const_4)|factorial(n1)|subtract(const_4,const_1)|factorial(#2)|subtract(#0,const_1)|factorial(#4)|multiply(#1,#3)|divide(#5,#6)| | "basically , the question asks how many 4 digit numbers ( including those in the form 0 xxx , 00 xx , and 000 x ) have digits which add up to 5 . think about the question this way : we know that there is a total of 5 to be spread among the 4 digits , we just have to determine the number of ways it can be spread . let x represent a sum of 1 , and | represent a seperator between two digits . as a result , we will have 5 x ' s ( digits add up to the 5 ) , and 3 | ' s ( 3 digit seperators ) . so , for example : xx | x | x | x = 2111 | | xxx | xx = 0032 etc . there are 8 c 3 ways to determine where to place the separators . hence , the answer is 8 c 3 = 56 . c" | general |
math_qa__qzuE8dKhjongt1Wg | By selling 16 pencils for a rupee a man loses 28%. How many for a rupee should he sell in order to gain 28%? Choose the correct choice from the following options:
A) 8 B) 9 C) 7 D) 6 E) 4 | <gadget id="calculator">100 + 28</gadget>
<output>128</output>
<gadget id="calculator">100 - 28</gadget>
<output>72</output>
<gadget id="calculator">1 / 72</gadget>
<output>1/72 = around 0.013889</output>
<gadget id="calculator">128 * (1/72)</gadget>
<output>16/9 = around 1.777778</output>
<gadget id="calculator">1 / (16/9)</gadget>
<output>9/16 = around 0.5625</output>
<gadget id="calculator">(9/16) * 16</gadget>
<output>9</output>
<result>B</result> | B | 9 | By selling 16 pencils for a rupee a man loses 28%. How many for a rupee should he sell in order to gain 28%? | {
"A": "8",
"B": "9",
"C": "7",
"D": "6",
"E": "4"
} | multiply(divide(const_1, multiply(add(const_100, 28), divide(const_1, subtract(const_100, 28)))), 16) | add(n2,const_100)|subtract(const_100,n1)|divide(const_1,#1)|multiply(#0,#2)|divide(const_1,#3)|multiply(n0,#4)| | "72 % - - - 16 128 % - - - ? 72 / 128 * 16 = 9 answer : b" | gain |
math_qa__KDzaYt1W61XEs879 | A parking garage rents parking spaces for $10 per week or $24 per month. How much does a person save in a year by renting by the month rather than by the week? Pick one:
A) $ 140
B) $ 160
C) $ 220
D) $ 232
E) $ 260 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">50 + 2</gadget>
<output>52</output>
<gadget id="calculator">52 * 10</gadget>
<output>520</output>
<gadget id="calculator">24 * 12</gadget>
<output>288</output>
<gadget id="calculator">520 - 288</gadget>
<output>232</output>
<result>D</result> | D | 232 | A parking garage rents parking spaces for $10 per week or $24 per month. How much does a person save in a year by renting by the month rather than by the week? | {
"A": "$ 140",
"B": "$ 160",
"C": "$ 220",
"D": "$ 232",
"E": "$ 260"
} | subtract(multiply(add(multiply(10, add(const_3, const_2)), const_2), 10), multiply(24, const_12)) | add(const_2,const_3)|multiply(n1,const_12)|multiply(#0,n0)|add(#2,const_2)|multiply(n0,#3)|subtract(#4,#1)| | "10 $ per week ! an year has 52 weeks . annual charges per year = 52 * 10 = 520 $ 30 $ per month ! an year has 12 months . annual charges per year = 12 * 24 = 288 $ 520 - 288 = 232 ans d" | general |
math_qa__FarjUWOWOv9PREmg | A boat running downstream covers a distance of 12 km in 2 hours while for covering the same distance upstream, it takes 3 hours. What is the speed of the boat in still water? Options: A) 8 kmph B) 5 kmph C) 4 kmph D) 6 kmph E) 7 kmph | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>B</result> | B | 5 | A boat running downstream covers a distance of 12 km in 2 hours while for covering the same distance upstream, it takes 3 hours. What is the speed of the boat in still water? | {
"A": "8 kmph",
"B": "5 kmph",
"C": "4 kmph",
"D": "6 kmph",
"E": "7 kmph"
} | divide(add(divide(12, 2), divide(12, 3)), 2) | divide(n0,n1)|divide(n0,n2)|add(#0,#1)|divide(#2,n1)| | "speed downstream = 12 / 2 = 6 kmph speed upstream = 12 / 3 = 4 kmph speed of the boat in still water = 6 + 4 / 2 = 5 kmph answer : b" | physics |
math_qa__nwf2nxBXYh5W2iR0 | What is the area of a square field whose diagonal of length 20 m?
Pick: A) 288 B) 289 C) 200 D) 112 E) 178 | <gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">400 / 2</gadget>
<output>200</output>
<result>C</result> | C | 200 | What is the area of a square field whose diagonal of length 20 m? | {
"A": "288",
"B": "289",
"C": "200",
"D": "112",
"E": "178"
} | divide(square_area(20), const_2) | square_area(n0)|divide(#0,const_2) | d 2 / 2 = ( 20 * 20 ) / 2 = 200 answer : c | geometry |
math_qa__FU0QJmFsxEyZaGlg | A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest. what is the rate of interest ? Pick:
A) 3 % B) 4 % C) 5 % D) 6 % E) 7 % | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">15 * 1_000</gadget>
<output>15_000</output>
<gadget id="calculator">5 * 100</gadget>
<output>500</output>
<gadget id="calculator">15_000 + 500</gadget>
<output>15_500</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 * 1_000</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 + 500</gadget>
<output>12_500</output>
<gadget id="calculator">15_500 - 12_500</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 12_500</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">(6/25) / 4</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) * 100</gadget>
<output>6</output>
<result>D</result> | D | 6 | A sum of Rs. 12,500 amounts to Rs. 15,500 in 4 years at the rate of simple interest. what is the rate of interest ? | {
"A": "3 %",
"B": "4 %",
"C": "5 %",
"D": "6 %",
"E": "7 %"
} | multiply(divide(divide(subtract(add(multiply(multiply(add(const_2, const_3), const_3), multiply(multiply(add(const_2, const_3), const_2), const_100)), multiply(add(const_2, const_3), const_100)), add(multiply(multiply(const_3, const_4), multiply(multiply(add(const_2, const_3), const_2), const_100)), multiply(add(const_2, const_3), const_100))), add(multiply(multiply(const_3, const_4), multiply(multiply(add(const_2, const_3), const_2), const_100)), multiply(add(const_2, const_3), const_100))), 4), const_100) | add(const_2,const_3)|multiply(const_3,const_4)|multiply(#0,const_3)|multiply(#0,const_2)|multiply(#0,const_100)|multiply(#3,const_100)|multiply(#2,#5)|multiply(#1,#5)|add(#6,#4)|add(#7,#4)|subtract(#8,#9)|divide(#10,#9)|divide(#11,n2)|multiply(#12,const_100) | s . i . = rs . ( 15500 - 12500 ) = rs . 3000 . rate = ( 100 x 3000 ) / ( 12500 x 4 ) % = 6 % answer : d | gain |
math_qa__StGW6PwGPtlVBu3g | Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a. Pick one:
A) loss of rs . 200 B) loss of rs . 100 C) profit of rs . 100 D) profit of rs . 200 E) none of these | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 - (1/25)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">15_000 * (24/25)</gadget>
<output>14_400</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">8_000 * (11/10)</gadget>
<output>8_800</output>
<gadget id="calculator">14_400 + 8_800</gadget>
<output>23_200</output>
<gadget id="calculator">15_000 + 8_000</gadget>
<output>23_000</output>
<gadget id="calculator">23_200 - 23_000</gadget>
<output>200</output>
<result>D</result> | D | 200 | Ravi purchased a refrigerator and a mobile phone for Rs. 15000 and Rs. 8000 respectively. He sold the refrigerator at a loss of 4 percent and the mobile phone at a profit of 10 percent. Overall he make a. | {
"A": "loss of rs . 200",
"B": "loss of rs . 100",
"C": "profit of rs . 100",
"D": "profit of rs . 200",
"E": "none of these"
} | subtract(add(multiply(15000, subtract(const_1, divide(4, const_100))), multiply(8000, add(const_1, divide(10, const_100)))), add(15000, 8000)) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|add(#2,const_1)|subtract(const_1,#1)|multiply(n0,#4)|multiply(n1,#3)|add(#5,#6)|subtract(#7,#0)| | "let the sp of the refrigerator and the mobile phone be rs . r and rs . m respectively . r = 15000 ( 1 - 4 / 100 ) = 15000 - 600 m = 8000 ( 1 + 10 / 100 ) = 8000 + 800 total sp - total cp = r + m - ( 15000 + 8000 ) = - 600 + 800 = rs . 200 as this is positive , an overall profit of rs . 200 was made . answer : d" | gain |
math_qa__2Behmi8p6zSAf3cp | Tim came second in Math. When his mother asked him how much he had scored, he answered that he got the sum of the first 8 even numbers. His mother immediately worked out the answer. How much had he scored in Math? Options.
A) 80 B) 90 C) 30 D) 72 E) 60 | <gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">9 * 8</gadget>
<output>72</output>
<result>D</result> | D | 72 | Tim came second in Math. When his mother asked him how much he had scored, he answered that he got the sum of the first 8 even numbers. His mother immediately worked out the answer. How much had he scored in Math? | {
"A": "80",
"B": "90",
"C": "30",
"D": "72",
"E": "60"
} | multiply(add(8, const_1), 8) | add(n0,const_1)|multiply(n0,#0) | d 72 sum = ( n x n ) + n hence , 8 x 8 = 64 + 8 = 72 | physics |
math_qa__6dnjfKNKZuVZy0OF | 22 percent of 300
Choose the correct option.
A) 50 B) 55 C) 62 D) 77 E) 66 | <gadget id="calculator">22 * 300</gadget>
<output>6_600</output>
<gadget id="calculator">6_600 / 100</gadget>
<output>66</output>
<result>E</result> | E | 66 | 22 percent of 300 | {
"A": "50",
"B": "55",
"C": "62",
"D": "77",
"E": "66"
} | divide(multiply(22, 300), const_100) | multiply(n0,n1)|divide(#0,const_100)| | 1 % of 300 = 3 22 % of 300 = 22 * 3 = 66 answer : e | gain |
math_qa__OuYdUo0AEg1L0KBt | Working individually, Allison can sew dresses for 9 hours and Al can sew dresses in 12 hours. If Allison and Al work together but independently at the task for 3 hours, at which point Al leaves, how many remaining hours will it take Allison to complete the task alone?
Select.
A) 45 / 12 B) 23 / 12 C) 40 / 33 D) 34 / 12 E) 43 / 5 | <gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/9) + (1/12)</gadget>
<output>7/36 = around 0.194444</output>
<gadget id="calculator">(7/36) * 3</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">1 - (7/12)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) / (1/9)</gadget>
<output>15/4 = around 3.75</output>
<result>A</result> | A | 3.75 | Working individually, Allison can sew dresses for 9 hours and Al can sew dresses in 12 hours. If Allison and Al work together but independently at the task for 3 hours, at which point Al leaves, how many remaining hours will it take Allison to complete the task alone? | {
"A": "45 / 12",
"B": "23 / 12",
"C": "40 / 33",
"D": "34 / 12",
"E": "43 / 5"
} | divide(subtract(const_1, multiply(add(divide(const_1, 9), divide(const_1, 12)), 3)), divide(const_1, 9)) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|multiply(n2,#2)|subtract(const_1,#3)|divide(#4,#0) | in first 3 hrs al will finish 3 / 12 = 1 / 4 of work and allison will finish 3 / 9 = 1 / 3 work so total 1 / 4 + 1 / 3 = 7 / 12 work is finished and 1 - 7 / 12 = 5 / 12 work remaining . now allison will take ( 5 / 12 ) * 9 = 45 / 12 hrs to finish it . so answer is a . | physics |
math_qa__nGcDHKJrUMgrJHq2 | 3 friends are planning to attend a concert . if another friend also goes with them , they will get a group discount on their tickets . if the new total price of the tickets with the group discount is the same as the original total price of the tickets without the group discount , how much is the discount ? Answers: A) 5 % B) 10 % C) 20 % D) 25 % E) 33 % | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>D</result> | D | 25 | 3 friends are planning to attend a concert . if another friend also goes with them , they will get a group discount on their tickets . if the new total price of the tickets with the group discount is the same as the original total price of the tickets without the group discount , how much is the discount ? | {
"A": "5 %",
"B": "10 %",
"C": "20 %",
"D": "25 %",
"E": "33 %"
} | multiply(subtract(const_1, divide(const_3, add(3, const_1))), const_100) | add(n0,const_1)|divide(const_3,#0)|subtract(const_1,#1)|multiply(#2,const_100) | let x be the original price of one ticket . the total original cost is 3 x . the new cost is 4 y , where y is the discounted price of one ticket . 3 x = 4 y y = 3 x / 4 = 0.75 x which is a discount of 25 % . the answer is d . | general |
math_qa__szB5H0K6Iy0leM8e | The true discount on a bill of Rs. 540 is Rs. 90. The banker's discount is: Pick:
A) rs . 60 B) rs . 108 C) rs . 110 D) rs . 112 E) rs . 122 | <gadget id="calculator">540 - 90</gadget>
<output>450</output>
<gadget id="calculator">90 / 450</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 540</gadget>
<output>108</output>
<result>B</result> | B | 108 | The true discount on a bill of Rs. 540 is Rs. 90. The banker's discount is: | {
"A": "rs . 60",
"B": "rs . 108",
"C": "rs . 110",
"D": "rs . 112",
"E": "rs . 122"
} | multiply(divide(90, subtract(540, 90)), 540) | subtract(n0,n1)|divide(n1,#0)|multiply(n0,#1)| | "p . w . = rs . ( 540 - 90 ) = rs . 450 . s . i . on rs . 450 = rs . 90 . s . i . on rs . 540 = rs . ( 90 / 450 ) x 540 = rs . 108 . b . d . = rs . 108 . answer : b" | gain |
math_qa__DXgJpTYXfrVjAi9W | When positive integer x is divided by positive integer y, the remainder is 3. If x/y = 96.15, what is the value of y? Choose the correct choice from the following:
A) 96 B) 75 C) 48 D) 25 E) 20 | <gadget id="calculator">floor(96.15)</gadget>
<output>96</output>
<gadget id="calculator">96.15 - 96</gadget>
<output>0.15</output>
<gadget id="calculator">3 / 0.15</gadget>
<output>20</output>
<result>E</result> | E | 20 | When positive integer x is divided by positive integer y, the remainder is 3. If x/y = 96.15, what is the value of y? | {
"A": "96",
"B": "75",
"C": "48",
"D": "25",
"E": "20"
} | divide(3, subtract(96.15, floor(96.15))) | floor(n1)|subtract(n1,#0)|divide(n0,#1) | by the definition of a remainder , the remainder here is equal to 3 / y . the remainder in decimal form is given as . 15 therefore , 3 / y = . 15 solve for y and get 20 . e | general |
math_qa__OejPXU0WO4t8y67Z | fetched a total simple interest of Rs. 4216.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum? Choose the correct choice from the following
A) rs . 8928 B) rs . 89228 C) rs . 8911 D) rs . 8925 E) rs . 8922 | <gadget id="calculator">4_216.25 * 100</gadget>
<output>421_625</output>
<gadget id="calculator">9 * 5</gadget>
<output>45</output>
<gadget id="calculator">421_625 / 45</gadget>
<output>84_325/9 = around 9_369.444444</output>
<result>D</result> | D | 8,925 | fetched a total simple interest of Rs. 4216.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum? | {
"A": "rs . 8928",
"B": "rs . 89228",
"C": "rs . 8911",
"D": "rs . 8925",
"E": "rs . 8922"
} | divide(multiply(4216.25, const_100), multiply(9, 5)) | multiply(n0,const_100)|multiply(n1,n2)|divide(#0,#1) | explanation : principal = rs . = rs . = rs . 8925 answer : d | gain |
math_qa__3FHxWX6Ub2cNxByM | The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is? Select:
A) 16
B) 18
C) 19
D) 22
E) 24 | <gadget id="calculator">36 - 26</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">15 + 1</gadget>
<output>16</output>
<result>A</result> | A | 16 | The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is? | {
"A": "16",
"B": "18",
"C": "19",
"D": "22",
"E": "24"
} | add(15, divide(subtract(36, 26), 10)) | subtract(n2,n3)|divide(#0,n0)|add(n1,#1)| | "explanation : 10 * 15 + 36 – 26 = 160 / 10 = 16 a )" | general |
math_qa__RKMAoV6KTBMCSHmj | If x is 20 percent greater than 98, then x = Pick
A) 68 B) 70.4 C) 86 D) 105.6 E) 117.6 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 98</gadget>
<output>98/5 = around 19.6</output>
<gadget id="calculator">98 + (98/5)</gadget>
<output>588/5 = around 117.6</output>
<result>E</result> | E | 117.6 | If x is 20 percent greater than 98, then x = | {
"A": "68",
"B": "70.4",
"C": "86",
"D": "105.6",
"E": "117.6"
} | add(98, multiply(divide(20, const_100), 98)) | divide(n0,const_100)|multiply(n1,#0)|add(n1,#1)| | "x = 98 * 1.2 = 117.6 so the answer is e ." | general |
math_qa__OD3cYrN6wvCXMC73 | 30 pens and 75 pencils were purchased for 450. If the average price of a pencil was 2.00, find the average price of a pen. Pick one:
A) 10 B) 11 C) 12 D) 13 E) 14 | <gadget id="calculator">75 * 2</gadget>
<output>150</output>
<gadget id="calculator">450 - 150</gadget>
<output>300</output>
<gadget id="calculator">300 / 30</gadget>
<output>10</output>
<result>A</result> | A | 10 | 30 pens and 75 pencils were purchased for 450. If the average price of a pencil was 2.00, find the average price of a pen. | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | divide(subtract(450, multiply(75, const_2)), 30) | multiply(n1,const_2)|subtract(n2,#0)|divide(#1,n0) | since average price of a pencil = 2 ∴ price of 75 pencils = 150 ∴ price of 30 pens = ( 450 – 150 ) = 300 ∴ average price of a pen = 360 ⁄ 60 = 10 answer a | general |
math_qa__yI8l4jp6PvJl24u6 | A person is traveling at 100 km/hr and reached his destiny in 5 then find the distance? Select: A) 250 km B) 300 km C) 500 km D) 450 km E) 350 km | <gadget id="calculator">100 * 5</gadget>
<output>500</output>
<result>C</result> | C | 500 | A person is traveling at 100 km/hr and reached his destiny in 5 then find the distance? | {
"A": "250 km",
"B": "300 km",
"C": "500 km",
"D": "450 km",
"E": "350 km"
} | multiply(100, 5) | multiply(n0,n1)| | "t = 5 hr s = 100 km / hr d = t * s = 100 * 5 = 500 km answer is c" | physics |
math_qa__u5fVo0A7XBxmFHCS | A man can row downstream at the rate of 18 Kmph and upstream at 6 Kmph. Find the man’s rate in still water and rate of current? Select the correct option
A) 8.5 B) 6.0 C) 9.5 D) 9.0 E) 8.25 | <gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>B</result> | B | 6 | A man can row downstream at the rate of 18 Kmph and upstream at 6 Kmph. Find the man’s rate in still water and rate of current? | {
"A": "8.5",
"B": "6.0",
"C": "9.5",
"D": "9.0",
"E": "8.25"
} | divide(subtract(18, 6), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "rate of still water = 1 / 2 ( down stream + upstream ) = 1 / 2 ( 18 + 6 ) = 12 kmph rate of current = 1 / 2 ( down stream - upstream ) = 1 / 2 ( 18 - 6 ) = 1 / 2 ( 12 ) = 6 kmph answer is b ." | gain |
math_qa__90IYF5cBZqW21w1T | What is the smallest number H which when increased by 5 is completely divisible by 8, 11 and 24?
Choose the correct choice from the following answers:
A) 264 B) 259 C) 269 D) 270 E) 282 | <gadget id="calculator">lcm(8, 11)</gadget>
<output>88</output>
<gadget id="calculator">lcm(88, 24)</gadget>
<output>264</output>
<gadget id="calculator">264 - 5</gadget>
<output>259</output>
<result>B</result> | B | 259 | What is the smallest number H which when increased by 5 is completely divisible by 8, 11 and 24? | {
"A": "264",
"B": "259",
"C": "269",
"D": "270",
"E": "282"
} | subtract(lcm(lcm(8, 11), 24), 5) | lcm(n1,n2)|lcm(n3,#0)|subtract(#1,n0) | this question includes a number of great number property shortcuts that you can take advantage of : 1 ) the question asks for the smallest number that , when increased by 5 is divisible by 8 , 11 and 24 . since the answers are numbers , we can test the answers . 2 ) any number that is divisible by 24 is also divisible by 8 , so we really just need to consider the 11 and the 24 . 3 ) to be divisible by 24 , the end number must be even . since we ' re adding 5 to get to that end number , the starting number must be odd . the last shortcut allows us to eliminate answers a , d and e . between answers b and c , testing b first will prove that , when increased by 5 , the end sum is divisible by both 11 and 24 . final answer : b | general |
math_qa__GSkzr0O8sgqV71aG | The cost price of a radio is Rs.1500 and it was sold for Rs.1290, find the loss %? Choose the correct choice: A) 14 % B) 16 % C) 17 % D) 78 % E) 28 % | <gadget id="calculator">1_500 - 1_290</gadget>
<output>210</output>
<gadget id="calculator">210 / 1_500</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/50) * 100</gadget>
<output>14</output>
<result>A</result> | A | 14 | The cost price of a radio is Rs.1500 and it was sold for Rs.1290, find the loss %? | {
"A": "14 %",
"B": "16 %",
"C": "17 %",
"D": "78 %",
"E": "28 %"
} | multiply(divide(subtract(1500, 1290), 1500), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "1500 - - - - 210 100 - - - - ? = > 14 % answer : a" | gain |
math_qa__o58RsHhzwFJlgc0I | In an election a candidate who gets 60% of the votes is elected by a majority of 900 votes. What is the total number of votes polled? Answers:
A) 4500 B) 5200 C) 6900 D) 7520 E) 6000 | <gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">900 / (1/5)</gadget>
<output>4_500</output>
<result>A</result> | A | 4,500 | In an election a candidate who gets 60% of the votes is elected by a majority of 900 votes. What is the total number of votes polled? | {
"A": "4500",
"B": "5200",
"C": "6900",
"D": "7520",
"E": "6000"
} | divide(900, divide(subtract(60, subtract(const_100, 60)), const_100)) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)| | "let the total number of votes polled be x then , votes polled by other candidate = ( 100 - 60 ) % of x = 40 % of x 60 % of x - 40 % of x = 900 20 x / 100 = 900 x = 900 * 100 / 20 = 4500 answer is a" | gain |
math_qa__M3vAl3hPAGtoMTkK | The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is:
Choose the correct choice from the following answers:
A) 1.2 km B) 2.4 km C) 3.2 km D) 3.6 km E) 4.6 km | <gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">12 / 60</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">18 * (1/5)</gadget>
<output>18/5 = around 3.6</output>
<result>D</result> | D | 3.6 | The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is: | {
"A": "1.2 km",
"B": "2.4 km",
"C": "3.2 km",
"D": "3.6 km",
"E": "4.6 km"
} | multiply(add(15, 3), divide(12, const_60)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "speed downstream = ( 15 + 3 ) kmph = 18 kmph . distance travelled = 18 x 12 / 60 km = 3.6 km . answer : d" | physics |
math_qa__Pso45iBAd5lZ8R9t | 10 men, working 7 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the same work in 12 days? Choose the correct choice from the following choices.
A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">70 * 18</gadget>
<output>1_260</output>
<gadget id="calculator">15 * 12</gadget>
<output>180</output>
<gadget id="calculator">1_260 / 180</gadget>
<output>7</output>
<result>B</result> | B | 7 | 10 men, working 7 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the same work in 12 days? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | divide(multiply(multiply(10, 7), 18), multiply(15, 12)) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|divide(#2,#1) | the number of hours required to complete the work is 10 * 7 * 18 = 1260 15 × 12 × ( x ) = 1260 x = 7 the answer is b . | physics |
math_qa__MXg9zoQv6vz5Ao4R | Calculate the value of n from the below equation: y^4−20y+1=22
Select the correct option.
A) 5 B) 3 C) 6 D) 2 E) 1 | <gadget id="calculator">22 - 1</gadget>
<output>21</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">21 / 21</gadget>
<output>1</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<result>B</result> | B | 3 | Calculate the value of n from the below equation: y^4−20y+1=22 | {
"A": "5",
"B": "3",
"C": "6",
"D": "2",
"E": "1"
} | subtract(4, divide(subtract(22, 1), add(20, 1))) | add(n1,n2)|subtract(n3,n2)|divide(#1,#0)|subtract(n0,#2) | use elimination method to find the correct option . you find that of all the options 3 is the correct value for y answer : b | general |
math_qa__ZHPnJsYVwOQXLS30 | The list price of an article is Rs.67. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
Choices
A) 3.86 % B) 4.86 % C) 5.86 % D) 6.86 % E) 7.86 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">67 * (1/10)</gadget>
<output>67/10 = around 6.7</output>
<gadget id="calculator">67 - (67/10)</gadget>
<output>603/10 = around 60.3</output>
<gadget id="calculator">(603/10) - 56.16</gadget>
<output>4.14</output>
<gadget id="calculator">4.14 / (603/10)</gadget>
<output>0.068657</output>
<gadget id="calculator">0.068657 * 100</gadget>
<output>6.8657</output>
<result>D</result> | D | 6.86 | The list price of an article is Rs.67. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is? | {
"A": "3.86 %",
"B": "4.86 %",
"C": "5.86 %",
"D": "6.86 %",
"E": "7.86 %"
} | multiply(divide(subtract(subtract(67, multiply(67, divide(10, const_100))), 56.16), subtract(67, multiply(67, divide(10, const_100)))), const_100) | divide(n2,const_100)|multiply(n0,#0)|subtract(n0,#1)|subtract(#2,n1)|divide(#3,#2)|multiply(#4,const_100) | 67 * ( 90 / 100 ) * ( ( 100 - x ) / 100 ) = 56.16 x = 6.86 % answer : d | gain |
math_qa__PofqKrxdyMFHIJuv | Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many W miles will Tom drive before Karen wins the bet?
Select the correct option: A) 15 B) 18 C) 21 D) 24 E) 27 | <gadget id="calculator">45 / 60</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 4</gadget>
<output>3</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">60 / 60</gadget>
<output>1</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">7 / (1/4)</gadget>
<output>28</output>
<gadget id="calculator">28 - 4</gadget>
<output>24</output>
<result>D</result> | D | 24 | Karen places a bet with Tom that she will beat Tom in a car race by 4 miles even if Karen starts 4 minutes late. Assuming that Karen drives at an average speed of 60 mph and Tom drives at an average speed of 45 mph, how many W miles will Tom drive before Karen wins the bet? | {
"A": "15",
"B": "18",
"C": "21",
"D": "24",
"E": "27"
} | subtract(divide(add(multiply(divide(45, 60), 4), 4), subtract(divide(60, 60), divide(45, 60))), 4) | divide(n3,n2)|divide(n2,n2)|multiply(n0,#0)|subtract(#1,#0)|add(n0,#2)|divide(#4,#3)|subtract(#5,n0)| | "let k and t be the speeds of karen and tom respectively . t be the time that karen will travel - - - - > t + 4 / 60 will be the total time tom will travel by the time the distance between karen and tom is 4 miles . thus , per the question , k ( t ) - t ( t + 4 / 60 ) = 4 - - - > t = 7 / 15 hours thus the distance traveled by tom when karen is 4 miles ahead of him w : t * ( t + 4 / 60 ) = 45 ( 7 / 15 + 4 / 60 ) = 24 miles . d is the correct answer ." | physics |
math_qa__33HcwgqsSON5pmRC | Rectangle A has sides a and b, and rectangle B has sides c and d. If a/c=b/d=2/3, what is the ratio of rectangle A’s area to rectangle B’s area? Choose one
A) 4 / 9 B) 2 / 3 C) 3 / 2 D) 9 / 2 E) 9 / 4 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>
<result>A</result> | A | 0.444444 | Rectangle A has sides a and b, and rectangle B has sides c and d. If a/c=b/d=2/3, what is the ratio of rectangle A’s area to rectangle B’s area? | {
"A": "4 / 9",
"B": "2 / 3",
"C": "3 / 2",
"D": "9 / 2",
"E": "9 / 4"
} | divide(power(2, const_2), power(3, const_2)) | power(n0,const_2)|power(n1,const_2)|divide(#0,#1)| | "the area of rectangle a is ab . c = 3 a / 2 and d = 3 b / 2 . the area of rectangle b is cd = 9 ab / 4 . the ratio of rectangle a ' s area to rectangle b ' s area is ab / ( 9 ab / 4 ) = 4 / 9 . the answer is a ." | geometry |
math_qa__U67EaphgDtQg1dny | The probability that event A occurs is 0.4, and the probability that events A and B both occur is 0.25. If the probability that either event A or event B occurs is 0.8, what is the probability that event B will occur? Choose the correct choice from the following answers.
A) 0.05
B) 0.15
C) 0.45
D) 0.5
E) 0.65 | <gadget id="calculator">0.8 + 0.25</gadget>
<output>1.05</output>
<gadget id="calculator">1.05 - 0.4</gadget>
<output>0.65</output>
<result>E</result> | E | 0.65 | The probability that event A occurs is 0.4, and the probability that events A and B both occur is 0.25. If the probability that either event A or event B occurs is 0.8, what is the probability that event B will occur? | {
"A": "0.05",
"B": "0.15",
"C": "0.45",
"D": "0.5",
"E": "0.65"
} | subtract(add(0.8, 0.25), 0.4) | add(n1,n2)|subtract(#0,n0)| | "p ( a or b ) = p ( a ) + p ( b ) - p ( a n b ) 0.8 = 0.4 + p ( b ) - 0.25 p ( b ) = 0.65 ans : e" | other |
math_qa__dgZ2f6fnn3BliDao | A lemonade stand sold only small and large cups of lemonade on Tuesday. 1/5 of the cups sold were small and the rest were large. If the large cups were sold for 7/6 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups? Choose the correct choice from the following answers.
A) 7 / 16 B) 7 / 15 C) 10 / 21 D) 14 / 17 E) 1 / 2 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 10</gadget>
<output>2</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">7 / 6</gadget>
<output>7/6 = around 1.166667</output>
<gadget id="calculator">(7/6) * 2</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">8 * (7/3)</gadget>
<output>56/3 = around 18.666667</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + (56/3)</gadget>
<output>68/3 = around 22.666667</output>
<gadget id="calculator">(56/3) / (68/3)</gadget>
<output>14/17 = around 0.823529</output>
<result>D</result> | D | 0.823529 | A lemonade stand sold only small and large cups of lemonade on Tuesday. 1/5 of the cups sold were small and the rest were large. If the large cups were sold for 7/6 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups? | {
"A": "7 / 16",
"B": "7 / 15",
"C": "10 / 21",
"D": "14 / 17",
"E": "1 / 2"
} | divide(multiply(subtract(const_10, multiply(divide(1, 5), const_10)), multiply(divide(7, 6), multiply(divide(1, 5), const_10))), add(multiply(multiply(divide(1, 5), const_10), multiply(divide(1, 5), const_10)), multiply(subtract(const_10, multiply(divide(1, 5), const_10)), multiply(divide(7, 6), multiply(divide(1, 5), const_10))))) | divide(n2,n3)|divide(n0,n1)|multiply(#1,const_10)|multiply(#0,#2)|multiply(#2,#2)|subtract(const_10,#2)|multiply(#3,#5)|add(#4,#6)|divide(#6,#7) | let the total # of cups be 10 . # of small cups sold 1 / 5 * 10 = 2 ; # of large cups sold 10 - 2 = 8 ; let the price of small cup be $ 6 , then the price of larges cup would be 7 / 6 * 6 = $ 7 ; revenue from small cups : 2 * $ 6 = $ 12 ; revenue from large cups cups : 8 * $ 7 = $ 56 ; fraction of total revenue from large cups : 56 / ( 56 + 12 ) = 14 / 17 . answer : d . | general |
math_qa__vAbJwVbTxoLf18fE | 12 is 4% of a, and 4 is 12% of b. c equals b/a. What is the value of c? Choose the correct choice from the following choices: A) 1 / 2 B) 1 / 3 C) 1 / 6 D) 1 / 9 E) 1 / 12 | <gadget id="calculator">4 / 12</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">12 / 4</gadget>
<output>3</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">(100/3) / 300</gadget>
<output>1/9 = around 0.111111</output>
<result>D</result> | D | 0.111111 | 12 is 4% of a, and 4 is 12% of b. c equals b/a. What is the value of c? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 6",
"D": "1 / 9",
"E": "1 / 12"
} | divide(multiply(divide(4, 12), const_100), multiply(divide(12, 4), const_100)) | divide(n1,n0)|divide(n0,n1)|multiply(#0,const_100)|multiply(#1,const_100)|divide(#2,#3)| | "4 a / 100 = 12 a = 300 12 b / 100 = 4 b = 100 / 3 c = b / a = 100 / ( 3 * 300 ) = 1 / 9 the answer is d ." | general |
math_qa__y9WFtA2tq9TJqfHV | A contractor undertook to make 15 km of roadway in 40 weeks. In 10 weeks, 3 km was complete by 180 men working 8 hours a day. The men then agreed to work 1 hour a day overtime, And some boys were engaged to assist them, the work was finished in the stipulated time(40 weeks). How many boys were employed, if the work of 3 boys is equal to that of 2 men? Choose the correct choice from the following answers
A) 48 B) 50 C) 22 D) 27 E) 221 | <gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) / 180</gadget>
<output>1/600 = around 0.001667</output>
<gadget id="calculator">(1/600) / 8</gadget>
<output>1/4_800 = around 0.000208</output>
<gadget id="calculator">8 + 1</gadget>
<output>9</output>
<gadget id="calculator">(1/4_800) * 9</gadget>
<output>3/1_600 = around 0.001875</output>
<gadget id="calculator">40 - 10</gadget>
<output>30</output>
<gadget id="calculator">(3/1_600) * 30</gadget>
<output>9/160 = around 0.05625</output>
<gadget id="calculator">180 * (9/160)</gadget>
<output>81/8 = around 10.125</output>
<gadget id="calculator">3 + (81/8)</gadget>
<output>105/8 = around 13.125</output>
<gadget id="calculator">15 - (105/8)</gadget>
<output>15/8 = around 1.875</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * (3/1_600)</gadget>
<output>1/800 = around 0.00125</output>
<gadget id="calculator">30 * (1/800)</gadget>
<output>3/80 = around 0.0375</output>
<gadget id="calculator">(15/8) / (3/80)</gadget>
<output>50</output>
<result>B</result> | B | 50 | A contractor undertook to make 15 km of roadway in 40 weeks. In 10 weeks, 3 km was complete by 180 men working 8 hours a day. The men then agreed to work 1 hour a day overtime, And some boys were engaged to assist them, the work was finished in the stipulated time(40 weeks). How many boys were employed, if the work of 3 boys is equal to that of 2 men? | {
"A": "48",
"B": "50",
"C": "22",
"D": "27",
"E": "221"
} | divide(subtract(15, add(3, multiply(180, multiply(multiply(divide(divide(divide(3, 10), 180), 8), add(8, 1)), subtract(40, 10))))), multiply(subtract(40, 10), multiply(divide(2, 3), multiply(divide(divide(divide(3, 10), 180), 8), add(8, 1))))) | add(n5,n6)|divide(n3,n2)|divide(n9,n3)|subtract(n1,n2)|divide(#1,n4)|divide(#4,n5)|multiply(#0,#5)|multiply(#6,#3)|multiply(#2,#6)|multiply(n4,#7)|multiply(#8,#3)|add(n3,#9)|subtract(n0,#11)|divide(#12,#10) | explanation : let the capacity of man = 3 units , and boy = 2 units per hour . now total work = 3 × 180 × 8 × 7 × 10 = 3 km . - - - - - - - ( 1 ) let k boys were recruited . now total work = ( 3 × 180 + 2 × k ) × 9 × 7 × 30 = 12 km . - - - - - - ( 2 ) by dividing 2 nd equation by 1 st , ⇒ ( 540 + 2 k ) × 9 × 7 × 303 × 180 × 8 × 7 × 10 = 4 ( 540 + 2 k ) × 9 × 7 × 303 × 180 × 8 × 7 × 10 = 4 ⇒ k = 50 answer : b | physics |
math_qa__DfgDTpMtMtVIcoXu | Find the least number of complete years in which a sum of money put out at 33.3% compound interest will be more than double of itself? Choices:
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">log(2)</gadget>
<output>log(2) = around 0.693147</output>
<gadget id="calculator">33.3 / 100</gadget>
<output>0.333</output>
<gadget id="calculator">1 + 0.333</gadget>
<output>1.333</output>
<gadget id="calculator">log(1.333)</gadget>
<output>0.287432</output>
<gadget id="calculator">log(2) / 0.287432</gadget>
<output>3.47908374850399*log(2) = around 2.411517</output>
<gadget id="calculator">(3.47908374850399*log(2)) + 1</gadget>
<output>1 + 3.47908374850399*log(2) = around 3.411517</output>
<gadget id="calculator">floor(1 + 3.47908374850399*log(2))</gadget>
<output>3</output>
<result>A</result> | A | 3 | Find the least number of complete years in which a sum of money put out at 33.3% compound interest will be more than double of itself? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | floor(add(divide(log(const_2), log(add(const_1, divide(33.3, const_100)))), const_1)) | divide(n0,const_100)|log(const_2)|add(#0,const_1)|log(#2)|divide(#1,#3)|add(#4,const_1)|floor(#5)| | "3 years answer : a" | general |
math_qa__5RNgx7Sh5sutq44I | If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability W that N is divisible by 3? Choose the correct option:
A) 1 / 3
B) ¼
C) 9 / 25
D) 5 / 16
E) 0 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">5 / 16</gadget>
<output>5/16 = around 0.3125</output>
<result>D</result> | D | 0.3125 | If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability W that N is divisible by 3? | {
"A": "1 / 3",
"B": "¼",
"C": "9 / 25",
"D": "5 / 16",
"E": "0"
} | divide(add(3, const_2), multiply(const_4, const_4)) | add(n0,const_2)|multiply(const_4,const_4)|divide(#0,#1) | prime digits are : 2 , 3 , 5 , 7 total number of 2 digit # s with both digits prime are : 4 * 4 = 16 out of these numbers divisible by 3 = 33 , 27 , 57 , 72 and 75 . i had to find the numbers manually using the 4 numbers above . = > prob = 5 / 16 . ans d . took me 3 : 20 mins . | general |
math_qa__1w5S3QXcWq8Cs9Ek | A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.170. Find the unknown rate of two towels? Answers.
A) 400 B) 650 C) 500 D) 550 E) 600 | <gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 170</gadget>
<output>1_700</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">1_700 - 750</gadget>
<output>950</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">950 - 300</gadget>
<output>650</output>
<result>B</result> | B | 650 | A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.170. Find the unknown rate of two towels? | {
"A": "400",
"B": "650",
"C": "500",
"D": "550",
"E": "600"
} | subtract(subtract(multiply(add(add(3, 5), const_2), 170), multiply(5, 150)), multiply(3, 100)) | add(n0,n2)|multiply(n2,n3)|multiply(n0,n1)|add(#0,const_2)|multiply(n4,#3)|subtract(#4,#1)|subtract(#5,#2)| | "10 * 170 = 1700 3 * 100 + 5 * 150 = 1050 1700 – 1050 = 650 b" | general |
math_qa__UUoKlCcFOI0lnxyu | A grocer has a sale of Rs. 5266, Rs. 5768, Rs. 5922, Rs. 5678 and Rs. 6029 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5600? Pick.
A) 4637 B) 4737 C) 4937 D) 5937 E) 5978 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 5_600</gadget>
<output>33_600</output>
<gadget id="calculator">5_266 + 5_768</gadget>
<output>11_034</output>
<gadget id="calculator">11_034 + 5_922</gadget>
<output>16_956</output>
<gadget id="calculator">16_956 + 5_678</gadget>
<output>22_634</output>
<gadget id="calculator">22_634 + 6_029</gadget>
<output>28_663</output>
<gadget id="calculator">33_600 - 28_663</gadget>
<output>4_937</output>
<result>C</result> | C | 4,937 | A grocer has a sale of Rs. 5266, Rs. 5768, Rs. 5922, Rs. 5678 and Rs. 6029 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5600? | {
"A": "4637",
"B": "4737",
"C": "4937",
"D": "5937",
"E": "5978"
} | subtract(multiply(add(5, const_1), 5600), add(add(add(add(5266, 5768), 5922), 5678), 6029)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "total sale for 5 months = rs . ( 5266 + 5768 + 5922 + 5678 + 6029 ) = rs . 28663 . required sale = rs . [ ( 5600 x 6 ) - 28663 ] = rs . ( 33600 - 28663 ) = rs . 4937 . answer : c" | general |
math_qa__OUkeXM15gDQJWTdu | In a certain pond, 40 fish were caught, tagged, and returned to the pond. A few days later, 40 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond? Pick
A) 400
B) 800
C) 1250
D) 2500
E) 10 000 | <gadget id="calculator">2 / 40</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">40 / (1/20)</gadget>
<output>800</output>
<result>B</result> | B | 800 | In a certain pond, 40 fish were caught, tagged, and returned to the pond. A few days later, 40 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond? | {
"A": "400",
"B": "800",
"C": "1250",
"D": "2500",
"E": "10 000"
} | divide(40, divide(2, 40)) | divide(n2,n1)|divide(n0,#0)| | "the percent of tagged fish in the second catch is 2 / 40 * 100 = 5 % . we are told that 5 % approximates the percent of tagged fish in the pond . since there are 40 tagged fish , then we have 0.05 x = 40 - - > x = 800 . answer : b ." | gain |
math_qa__J2rN7UqWIKDcoV1y | The Guests at a football banquet consumed a total of 327 pounds of food. if no individual guest consumed more than 2 pounds of food, What is the minimum number of guests that could have attended the banquet? Choices:
A) 160
B) 161
C) 162
D) 163
E) 164 | <gadget id="calculator">327 / 2</gadget>
<output>327/2 = around 163.5</output>
<gadget id="calculator">floor(327/2)</gadget>
<output>163</output>
<gadget id="calculator">163 + 1</gadget>
<output>164</output>
<result>E</result> | E | 164 | The Guests at a football banquet consumed a total of 327 pounds of food. if no individual guest consumed more than 2 pounds of food, What is the minimum number of guests that could have attended the banquet? | {
"A": "160",
"B": "161",
"C": "162",
"D": "163",
"E": "164"
} | add(floor(divide(327, 2)), const_1) | divide(n0,n1)|floor(#0)|add(#1,const_1) | to minimize one quantity maximize other . 163 * 2 ( max possible amount of food a guest could consume ) = 326 pounds , so there must be more than 163 guests , next integer is 164 . answer : e . | general |
math_qa__VDDilfLUHwk5aHyR | A report consists of 20 sheets each of 55 lines and each such line consist of 65 characters. This report is retyped into sheets each of 65 lines such that each line consists of 70 characters. The percentage reduction in number of sheets is closest to Choose the most appropriate option
A) 20 B) 5 C) 30 D) 35 E) 67 | <gadget id="calculator">20 * 55</gadget>
<output>1_100</output>
<gadget id="calculator">1_100 * 65</gadget>
<output>71_500</output>
<gadget id="calculator">71_500 / 70</gadget>
<output>7_150/7 = around 1_021.428571</output>
<gadget id="calculator">(7_150/7) / 65</gadget>
<output>110/7 = around 15.714286</output>
<gadget id="calculator">20 - (110/7)</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">400 / 20</gadget>
<output>20</output>
<result>A</result> | A | 20 | A report consists of 20 sheets each of 55 lines and each such line consist of 65 characters. This report is retyped into sheets each of 65 lines such that each line consists of 70 characters. The percentage reduction in number of sheets is closest to | {
"A": "20",
"B": "5",
"C": "30",
"D": "35",
"E": "67"
} | divide(multiply(floor(subtract(20, divide(divide(multiply(multiply(20, 55), 65), 70), 65))), const_100), 20) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n4)|divide(#2,n2)|subtract(n0,#3)|floor(#4)|multiply(#5,const_100)|divide(#6,n0) | explanation : total no of characters = 20 * 55 * 65 . from the problem it is clear that 20 * 55 * 65 = x * 65 * 70 . we get x = 15.6 ∼ 16 because these are sheets . therefore 4 less sheets . hencde , there is 20 % decrease in number of sheets . answer : a | gain |
math_qa__LP2IjIiGI83KxbgW | Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 184 cms. What was the ratio Q of men to women? Choose the correct choice from the following choices.
A) 5 : 2 B) 5 : 1 C) 4 : 3 D) 4 : 1 E) 3 : 1 | <gadget id="calculator">180 - 170</gadget>
<output>10</output>
<gadget id="calculator">184 - 180</gadget>
<output>4</output>
<gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<result>A</result> | A | 2.5 | Students at a school were on average 180 cm tall. The average female height was 170 cm, and the average male height was 184 cms. What was the ratio Q of men to women? | {
"A": "5 : 2",
"B": "5 : 1",
"C": "4 : 3",
"D": "4 : 1",
"E": "3 : 1"
} | divide(subtract(180, 170), subtract(184, 180)) | subtract(n0,n1)|subtract(n2,n0)|divide(#0,#1)| | ( a ) q = 184 x 5 + 170 x 2 = 1260 . a | general |
math_qa__iDL7iKAYjuNptMG0 | By weight, liquid X makes up 0.7 percent of solution P and 1.2 percent of solution Q. If 200 grams of solution P are mixed with 800 grams of solution Q, then liquid X accounts for what percent of the weight of the resulting solution? Choices:
A) 1.2 % B) 1.1 % C) 1.0 % D) 0.9 % E) 0.8 % | <gadget id="calculator">1.2 * 800</gadget>
<output>960</output>
<gadget id="calculator">960 / 100</gadget>
<output>48/5 = around 9.6</output>
<gadget id="calculator">1 + (48/5)</gadget>
<output>53/5 = around 10.6</output>
<gadget id="calculator">(53/5) / 1_000</gadget>
<output>53/5_000 = around 0.0106</output>
<gadget id="calculator">(53/5_000) * 100</gadget>
<output>53/50 = around 1.06</output>
<result>B</result> | B | 1.1 | By weight, liquid X makes up 0.7 percent of solution P and 1.2 percent of solution Q. If 200 grams of solution P are mixed with 800 grams of solution Q, then liquid X accounts for what percent of the weight of the resulting solution? | {
"A": "1.2 %",
"B": "1.1 %",
"C": "1.0 %",
"D": "0.9 %",
"E": "0.8 %"
} | multiply(divide(add(const_1, divide(multiply(1.2, 800), const_100)), const_1000), const_100) | multiply(n1,n3)|divide(#0,const_100)|add(#1,const_1)|divide(#2,const_1000)|multiply(#3,const_100)| | "the number of grams of liquid x is 0.7 ( 200 ) / 100 + 1.2 ( 800 ) / 100 = 1.4 + 9.6 = 11 grams . 11 / 1000 = 1.1 % the answer is b ." | gain |
math_qa__wEfq3SG5k3p7WaHF | A courtyard is 20 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is? Options.
A) 16000
B) 27778
C) 20000
D) 27999
E) 17799 | <gadget id="calculator">20 * 100</gadget>
<output>2_000</output>
<gadget id="calculator">16 * 100</gadget>
<output>1_600</output>
<gadget id="calculator">2_000 * 1_600</gadget>
<output>3_200_000</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">3_200_000 / 200</gadget>
<output>16_000</output>
<result>A</result> | A | 16,000 | A courtyard is 20 meter long and 16 meter board is to be paved with bricks of dimensions 20 cm by 10 cm. The total number of bricks required is? | {
"A": "16000",
"B": "27778",
"C": "20000",
"D": "27999",
"E": "17799"
} | divide(multiply(multiply(20, const_100), multiply(16, const_100)), multiply(20, 10)) | multiply(n0,const_100)|multiply(n1,const_100)|multiply(n2,n3)|multiply(#0,#1)|divide(#3,#2)| | "number of bricks = courtyard area / 1 brick area = ( 2000 × 1600 / 20 × 10 ) = 16000 answer : a" | physics |
math_qa__WpO9AvWXiwBqg6cU | A car takes 4 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Pick:
A) 92 kmph
B) 98 kmph
C) 90 kmph
D) 80 kmph
E) 82 kmph | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">540 / 6</gadget>
<output>90</output>
<result>C</result> | C | 90 | A car takes 4 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "92 kmph",
"B": "98 kmph",
"C": "90 kmph",
"D": "80 kmph",
"E": "82 kmph"
} | divide(540, divide(multiply(4, 3), 2)) | multiply(n0,n2)|divide(#0,n3)|divide(n1,#1)| | "time = 4 distence = 540 3 / 2 of 4 hours = 4 * 3 / 2 = 6 hours required speed = 540 / 6 = 90 kmph c )" | physics |
math_qa__9v00qRfv8Sot11l4 | 36 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? Choose the correct choice: A) 44 B) 77 C) 66 D) 55 E) 37 | <gadget id="calculator">36 * 8</gadget>
<output>288</output>
<gadget id="calculator">288 / 30</gadget>
<output>48/5 = around 9.6</output>
<gadget id="calculator">(48/5) * 50</gadget>
<output>480</output>
<gadget id="calculator">480 / 6</gadget>
<output>80</output>
<gadget id="calculator">80 - 36</gadget>
<output>44</output>
<result>A</result> | A | 44 | 36 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? | {
"A": "44",
"B": "77",
"C": "66",
"D": "55",
"E": "37"
} | subtract(divide(multiply(divide(multiply(36, 8), 30), 50), 6), 36) | multiply(n0,n1)|divide(#0,n2)|multiply(n3,#1)|divide(#2,n4)|subtract(#3,n0)| | "( 36 * 8 ) / 30 = ( x * 6 ) / 50 = > x = 80 80 – 36 = 44 answer : a" | physics |
math_qa__T2nEkViG8PpRJ3tS | Square A has an area of 121 square centimeters. Square B has a perimeter of 16 centimeters. If square B is placed within square A and a random point is chosen within square A, what is the probability the point is not within square B? Choose the correct choice:
A) 9 / 25 B) 1 / 5 C) 16 / 121 D) 105 / 121 E) 6 / 25 | <gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">121 - 16</gadget>
<output>105</output>
<gadget id="calculator">105 / 121</gadget>
<output>105/121 = around 0.867769</output>
<result>D</result> | D | 0.867769 | Square A has an area of 121 square centimeters. Square B has a perimeter of 16 centimeters. If square B is placed within square A and a random point is chosen within square A, what is the probability the point is not within square B? | {
"A": "9 / 25",
"B": "1 / 5",
"C": "16 / 121",
"D": "105 / 121",
"E": "6 / 25"
} | divide(subtract(121, power(divide(16, const_4), const_2)), 121) | divide(n1,const_4)|power(#0,const_2)|subtract(n0,#1)|divide(#2,n0)| | "i guess it ' s mean that square b is placed within square aentirely . since , the perimeter of b is 16 , then its side is 16 / 4 = 4 and the area is 4 ^ 2 = 16 ; empty space between the squares is 121 - 16 = 105 square centimeters , so if a random point is in this area then it wo n ' t be within square b : p = favorable / total = 105 / 121 . answer : d ." | geometry |
math_qa__jVqwg2U0dL72XcbC | 20% of a number is more than 40% of 140 by 80. Find the number?
Choose the correct choice from the following answers:
A) 680 B) 620 C) 652 D) 520 E) 458 | <gadget id="calculator">140 * 40</gadget>
<output>5_600</output>
<gadget id="calculator">5_600 / 100</gadget>
<output>56</output>
<gadget id="calculator">56 + 80</gadget>
<output>136</output>
<gadget id="calculator">136 * 100</gadget>
<output>13_600</output>
<gadget id="calculator">13_600 / 20</gadget>
<output>680</output>
<result>A</result> | A | 680 | 20% of a number is more than 40% of 140 by 80. Find the number? | {
"A": "680",
"B": "620",
"C": "652",
"D": "520",
"E": "458"
} | divide(multiply(add(divide(multiply(140, 40), const_100), 80), const_100), 20) | multiply(n1,n2)|divide(#0,const_100)|add(n3,#1)|multiply(#2,const_100)|divide(#3,n0)| | "( 20 / 100 ) * x – ( 40 / 100 ) * 140 = 80 1 / 5 x = 136 x = 680 answer : a" | gain |
math_qa__Hedd3qa0oeYqPUlS | The average salary/head of allthe workers in a workshop is Rs.850, if the average salary/head of 7technician is Rs.1000 and the average salary/head of the rest is Rs.780, the total no. of workers in the work-shop is ?
Choose the correct choice from the following answers: A) 18 B) 20 C) 22 D) 23 E) 25 | <gadget id="calculator">7 * 1_000</gadget>
<output>7_000</output>
<gadget id="calculator">7 * 780</gadget>
<output>5_460</output>
<gadget id="calculator">7_000 - 5_460</gadget>
<output>1_540</output>
<gadget id="calculator">850 - 780</gadget>
<output>70</output>
<gadget id="calculator">1_540 / 70</gadget>
<output>22</output>
<result>C</result> | C | 22 | The average salary/head of allthe workers in a workshop is Rs.850, if the average salary/head of 7technician is Rs.1000 and the average salary/head of the rest is Rs.780, the total no. of workers in the work-shop is ? | {
"A": "18",
"B": "20",
"C": "22",
"D": "23",
"E": "25"
} | divide(subtract(multiply(7, 1000), multiply(7, 780)), subtract(850, 780)) | multiply(n1,n2)|multiply(n1,n3)|subtract(n0,n3)|subtract(#0,#1)|divide(#3,#2) | let the total number of workers be y . so sum of salary for all workers = sum of salary of 7 technician + sum of salary for other y - 7 workers . 7 x 1000 + 780 ( y - 7 ) = 850 y ⇒ 7000 + 780 y - 5460 = 850 y ⇒ 70 y = 1540 ∴ y = 22 so total number of workers = 22 c | general |
math_qa__fjUghMrjwV6JsX8e | The average weight of 6 students decreases by 3 kg when one of them weighing 80 kg is replaced by a new student. The weight of the student is Pick
A) 62 kg
B) 60 kg
C) 70 kg
D) 72 kg
E) none of these | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">80 - 18</gadget>
<output>62</output>
<result>A</result> | A | 62 | The average weight of 6 students decreases by 3 kg when one of them weighing 80 kg is replaced by a new student. The weight of the student is | {
"A": "62 kg",
"B": "60 kg",
"C": "70 kg",
"D": "72 kg",
"E": "none of these"
} | subtract(80, multiply(6, 3)) | multiply(n0,n1)|subtract(n2,#0)| | "explanation : let the weight of student be x kg . given , difference in average weight = 3 kg = > ( 80 - x ) / 6 = 3 = > x = 62 answer : a" | general |
math_qa__lc13lrgayQLvooMd | If 20 honey bees make 20 grams of honey in 20 days, then 1 honey bee will make 1 gram of honey in how many days?
Select.
A) 1
B) 3.5
C) 20
D) 49
E) 30 | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / (1/20)</gadget>
<output>20</output>
<result>C</result> | C | 20 | If 20 honey bees make 20 grams of honey in 20 days, then 1 honey bee will make 1 gram of honey in how many days? | {
"A": "1",
"B": "3.5",
"C": "20",
"D": "49",
"E": "30"
} | divide(1, divide(1, 20)) | divide(n3,n0)|divide(n3,#0) | explanation : let the required number days be x . less honey bees , more days ( indirect proportion ) less honey , less days ( direct proportion ) honey bees 1 : 20 : : 20 : x honey 20 : 1 = > 1 x 20 x x = 20 x 1 x 20 = > x = 20 . answer : c | physics |
math_qa__UHvo2UkdtskQvmqq | A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 60% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?
Choose the correct choice from the following options
A) 7 : 15 B) 7 : 10 C) 7 : 8 D) 7 : 4 E) 7 : 2 | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">160 / 100</gadget>
<output>8/5 = around 1.6</output>
<gadget id="calculator">36 / (8/5)</gadget>
<output>45/2 = around 22.5</output>
<gadget id="calculator">33 - (45/2)</gadget>
<output>21/2 = around 10.5</output>
<gadget id="calculator">(21/2) / (45/2)</gadget>
<output>7/15 = around 0.466667</output>
<result>A</result> | A | 0.466667 | A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 60% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk? | {
"A": "7 : 15",
"B": "7 : 10",
"C": "7 : 8",
"D": "7 : 4",
"E": "7 : 2"
} | divide(subtract(33, divide(36, divide(add(const_100, 60), const_100))), divide(36, divide(add(const_100, 60), const_100))) | add(n1,const_100)|divide(#0,const_100)|divide(n2,#1)|subtract(n0,#2)|divide(#3,#2)| | "first of all , let ' s consider 1 liter of the stuff he is going to sell - - - naive customers think it ' s pure milk , but we know it ' s some milk - water mixture . he is going to sell this liter of milk - water for $ 36 . this $ 36 should be a 60 % increase over cost . here , we need to think about percentage increases as multipliers . using multipliers ( cost ) * 1.60 = $ 36 cost = 36 / 1.6 = $ 22.5 if he wants a 60 % increase over cost on the sale of one liter of his milk - water , the cost has to be $ 22.5 well , a liter of milk costs $ 33 , so if he is going to use just $ 30 of milk in his mixture , that ' s 22.5 / 33 = 15 / 22 of a liter . if milk is 15 / 22 of the liter , then water is 7 / 22 of the liter , and the ratio of water to milk is 7 : 15 . answer choice ( a )" | gain |
math_qa__krTXsEH69hHMgkFy | In Town X, 65 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?
Choose the correct choice from the following answers: A) 16 % B) 27 % C) 32 % D) 40 % E) 52 % | <gadget id="calculator">65 - 48</gadget>
<output>17</output>
<gadget id="calculator">17 / 65</gadget>
<output>17/65 = around 0.261538</output>
<gadget id="calculator">(17/65) * 100</gadget>
<output>340/13 = around 26.153846</output>
<result>B</result> | B | 27 | In Town X, 65 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females? | {
"A": "16 %",
"B": "27 %",
"C": "32 %",
"D": "40 %",
"E": "52 %"
} | multiply(divide(subtract(65, 48), 65), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "we are asked to find the percentage of females in employed people . total employed people 65 % , out of which 48 are employed males , hence 17 % are employed females . ( employed females ) / ( total employed people ) = 17 / 64 = 27 % answer : b ." | gain |
math_qa__itxoTQkP3yA0lcaC | out of 3 consecutive odd numbers 9 times the first number is equal to addition of twice the third number and adding 9 to twice the second . what is the first number ?
Choose the correct choice.
A) 20 / 21 B) 23 / 25 C) 24 / 23 D) 22 / 5 E) 21 / 5 | <gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">27 - 6</gadget>
<output>21</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">21 / 5</gadget>
<output>21/5 = around 4.2</output>
<result>E</result> | E | 4.2 | out of 3 consecutive odd numbers 9 times the first number is equal to addition of twice the third number and adding 9 to twice the second . what is the first number ? | {
"A": "20 / 21",
"B": "23 / 25",
"C": "24 / 23",
"D": "22 / 5",
"E": "21 / 5"
} | divide(subtract(multiply(9, 3), multiply(const_2, const_3)), add(3, const_2)) | add(n0,const_2)|multiply(n0,n1)|multiply(const_2,const_3)|subtract(#1,#2)|divide(#3,#0) | description : = > 9 x = 2 ( x + 2 ) + 9 + 2 ( x + 4 ) = > 9 x = 4 x + 21 = > 5 x = 21 x = 21 / 5 answer e | general |
math_qa__sjQLBYQhTQx5U8NB | Find the LCM of 23,46,827 Choose the correct choice from the following options:
A) 227
B) 83
C) 23
D) 827
E) none of these | <gadget id="calculator">23 * 4</gadget>
<output>92</output>
<gadget id="calculator">92 - 4</gadget>
<output>88</output>
<gadget id="calculator">88 - 4</gadget>
<output>84</output>
<gadget id="calculator">84 - 1</gadget>
<output>83</output>
<result>B</result> | B | 83 | Find the LCM of 23,46,827 | {
"A": "227",
"B": "83",
"C": "23",
"D": "827",
"E": "none of these"
} | subtract(subtract(subtract(multiply(23, const_4), const_4), const_4), const_1) | multiply(n0,const_4)|subtract(#0,const_4)|subtract(#1,const_4)|subtract(#2,const_1) | explanation : whenever we have to solve this sort of question , remember the formula . lcm = \ \ begin { aligned } \ \ frac { hcf of denominators } { lcm of numerators } \ \ end { aligned } so answers will be option 2 , please also give attention to the difference in formula of hcf and lcm answer : option b | physics |
math_qa__eZVnpimavmBQ6D39 | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is Choose the correct choice.
A) 3220 B) 4830 C) 5120 D) 6420 E) none | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">48 - 16</gadget>
<output>32</output>
<gadget id="calculator">36 - 16</gadget>
<output>20</output>
<gadget id="calculator">32 * 20 * 8</gadget>
<output>5_120</output>
<result>C</result> | C | 5,120 | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is | {
"A": "3220",
"B": "4830",
"C": "5120",
"D": "6420",
"E": "none"
} | volume_rectangular_prism(subtract(48, multiply(8, const_2)), subtract(36, multiply(8, const_2)), 8) | multiply(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|volume_rectangular_prism(n2,#1,#2)| | "solution clearly , l = ( 48 - 16 ) m = 32 m ‹ = › b = ( 36 - 16 ) m = 20 m , ‹ = › h = 8 m . . volume of the box = ( 32 x 20 x 8 ) m 3 = 5120 m 3 . answer c" | geometry |
math_qa__uwaGlLBZbGcLTAA1 | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 312 votes. Find the number of votes casted to the winning candidate? Choose the correct choice from the following options.
A) 806 B) 744 C) 912 D) 1200 E) 1400 | <gadget id="calculator">100 - 62</gadget>
<output>38</output>
<gadget id="calculator">62 - 38</gadget>
<output>24</output>
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">312 / (6/25)</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 * 62</gadget>
<output>80_600</output>
<gadget id="calculator">80_600 / 100</gadget>
<output>806</output>
<result>A</result> | A | 806 | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 312 votes. Find the number of votes casted to the winning candidate? | {
"A": "806",
"B": "744",
"C": "912",
"D": "1200",
"E": "1400"
} | divide(multiply(divide(312, divide(subtract(62, subtract(const_100, 62)), const_100)), 62), const_100) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)| | "w = 62 % l = 38 % 62 % - 38 % = 24 % 24 % - - - - - - - - 312 62 % - - - - - - - - ? = > 806 answer : a" | gain |
math_qa__m6RHp2NBFsPTKULC | If x/(9p) is an odd prime number, where x is a positive integer and p is a prime number, what is the least value of x? Choose the most appropriate option.
A) 54 B) 33 C) 44 D) 66 E) 99 | <gadget id="calculator">3 * 9</gadget>
<output>27</output>
<gadget id="calculator">27 * 2</gadget>
<output>54</output>
<result>A</result> | A | 54 | If x/(9p) is an odd prime number, where x is a positive integer and p is a prime number, what is the least value of x? | {
"A": "54",
"B": "33",
"C": "44",
"D": "66",
"E": "99"
} | multiply(multiply(const_3, 9), const_2) | multiply(n0,const_3)|multiply(#0,const_2)| | "x / ( 9 p ) = odd prime number x = odd prime number * 9 p least value of x = lowest odd prime number * 9 * lowest value of p = 3 * 9 * 2 = 54 answer a" | general |
math_qa__u05XjBEFokJcavWY | Rs.900 is divided among Maya, Annie, Saiji so that Maya receives half as much as Annie and Annie half as much as Saiji. Then Saiji’s share is : Choose the correct choice from the following options
A) rs . 200 B) rs . 300 C) rs . 400 D) rs . 600 E) rs . 500 | <gadget id="calculator">900 / 100</gadget>
<output>9</output>
<gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">900 * (4/9)</gadget>
<output>400</output>
<result>C</result> | C | 400 | Rs.900 is divided among Maya, Annie, Saiji so that Maya receives half as much as Annie and Annie half as much as Saiji. Then Saiji’s share is : | {
"A": "rs . 200",
"B": "rs . 300",
"C": "rs . 400",
"D": "rs . 600",
"E": "rs . 500"
} | multiply(900, divide(const_4, divide(900, const_100))) | divide(n0,const_100)|divide(const_4,#0)|multiply(n0,#1) | let saiji = x . then , annie = x / 2 and maya = x / 4 . therefore , maya : annie : saiji = x / 4 : x / 2 : x = 1 : 2 : 4 . therefore , saiji ’ s share = rs . 900 * 4 / 9 = rs . 400 . answer : c | general |
math_qa__ZOW6LFN961EatBzA | A company has two models of computers, model M and model N. Operating at a constant rate, a model M computer can complete a certain task in 24 minutes and a model N computer can complete the same task in 12 minutes. If the company used the same number of each model of computer to complete the task in 1 minute, how many model M computers were used? Select.
A) 3 B) 4 C) 5 D) 8 E) 6 | <gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/12) + (1/24)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<result>D</result> | D | 8 | A company has two models of computers, model M and model N. Operating at a constant rate, a model M computer can complete a certain task in 24 minutes and a model N computer can complete the same task in 12 minutes. If the company used the same number of each model of computer to complete the task in 1 minute, how many model M computers were used? | {
"A": "3",
"B": "4",
"C": "5",
"D": "8",
"E": "6"
} | inverse(add(inverse(12), inverse(24))) | inverse(n1)|inverse(n0)|add(#0,#1)|inverse(#2) | let ' s say 1 work is processing 24 gb of data . model m : 1 gb per min model n : 2 gb per min working together , 1 m and 1 n = 3 gb per min so , 8 times as many computers would work at 18 gb per min . so no . of m = 8 answer is d | physics |
math_qa__JoMVNRHRhUZ1S0Hf | In a kilometer race, A beats B by 200 meters or 10 seconds. What time does A take to complete the race? Select: A) 180 sec B) 190 sec C) 290 sec D) 490 sec E) 40 sec | <gadget id="calculator">1 * 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">200 / 10</gadget>
<output>20</output>
<gadget id="calculator">1_000 / 20</gadget>
<output>50</output>
<gadget id="calculator">50 - 10</gadget>
<output>40</output>
<result>E</result> | E | 40 | In a kilometer race, A beats B by 200 meters or 10 seconds. What time does A take to complete the race? | {
"A": "180 sec",
"B": "190 sec",
"C": "290 sec",
"D": "490 sec",
"E": "40 sec"
} | subtract(divide(multiply(const_1, const_1000), divide(200, 10)), 10) | divide(n0,n1)|multiply(const_1,const_1000)|divide(#1,#0)|subtract(#2,n1)| | "time taken by b run 1000 meters = ( 1000 * 10 ) / 200 = 50 sec . time taken by a = 50 - 10 = 40 sec . answer : e" | physics |
math_qa__KqpZDCHRC1zPMJzK | If a car went the first third of the distance at 80 kmh, the second third at 15 kmh, and the last third at 48 kmh, what was the average speed of the car for the entire trip?
Choose the correct choice from the following
A) 30 kmh B) 40 kmh C) 42 kmh D) 44 kmh E) 50 kmh | <gadget id="calculator">1 / 80</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/80) + (1/15)</gadget>
<output>19/240 = around 0.079167</output>
<gadget id="calculator">1 / 48</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">(19/240) + (1/48)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">3 / (1/10)</gadget>
<output>30</output>
<result>A</result> | A | 30 | If a car went the first third of the distance at 80 kmh, the second third at 15 kmh, and the last third at 48 kmh, what was the average speed of the car for the entire trip? | {
"A": "30 kmh",
"B": "40 kmh",
"C": "42 kmh",
"D": "44 kmh",
"E": "50 kmh"
} | divide(const_3, add(add(divide(const_1, 80), divide(const_1, 15)), divide(const_1, 48))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2)|divide(const_3,#4)| | "assume d / 3 = 240 ( this number is convenient because it is divisible by 80 , 15 and 48 ) so : 240 = 80 * t 1 = 3 hrs 240 = 15 * t 2 = 16 hrs 240 = 48 * t 3 = 5 hrs t = t 1 + t 2 + t 3 = 24 hrs d = rt ( 240 * 3 ) = r * 24 r = 30 answer : a" | physics |
math_qa__uxmIkEt8Zqxhmc3D | In a school with 5 classes, each class has 2 students less than the previous class. How many students are there in the largest class if the total number of students at school is 100? Options.
A) 24 B) 25 C) 26 D) 27 E) 28 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 5</gadget>
<output>16</output>
<gadget id="calculator">16 + 8</gadget>
<output>24</output>
<result>A</result> | A | 24 | In a school with 5 classes, each class has 2 students less than the previous class. How many students are there in the largest class if the total number of students at school is 100? | {
"A": "24",
"B": "25",
"C": "26",
"D": "27",
"E": "28"
} | add(divide(subtract(100, add(add(add(2, add(2, 2)), add(add(2, 2), 2)), add(add(add(2, 2), 2), 2))), 5), add(add(add(2, 2), 2), 2)) | add(n1,n1)|add(n1,#0)|add(n1,#1)|add(#1,#1)|add(#3,#2)|subtract(n2,#4)|divide(#5,n0)|add(#2,#6) | let x be the number of students in the largest class . then x + ( x - 2 ) + ( x - 4 ) + ( x - 6 ) + ( x - 8 ) = 100 5 x - 20 = 100 5 x = 120 x = 24 the answer is a . | general |
math_qa__ZbPr5ZMnppNy8zTK | Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 7 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n? Pick:
A) 4 B) 5 C) 6 D) 7 E) 8 | <gadget id="calculator">7 + 1</gadget>
<output>8</output>
<result>E</result> | E | 8 | Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 7 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | add(7, const_1) | add(n0,const_1)| | "if n = 8 mark sold 1 box and ann sold 6 boxes total 7 < 8 answer : e" | general |
math_qa__adGGm4BvLyAj1lFU | Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 19 = f(x – 4) ? Choices:
A) 2
B) 4
C) 6
D) 8
E) 10 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 19</gadget>
<output>29</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 5</gadget>
<output>17</output>
<gadget id="calculator">29 - 17</gadget>
<output>12</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">3 * 1</gadget>
<output>3</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<result>B</result> | B | 4 | Given f(x) = 3x – 5, for what value of x does 2*[f(x)] – 19 = f(x – 4) ? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | divide(subtract(add(multiply(2, 5), 19), add(multiply(const_3, 4), 5)), subtract(multiply(2, 3), multiply(3, const_1))) | multiply(n1,n2)|multiply(n4,const_3)|multiply(n0,n2)|multiply(n0,const_1)|add(n3,#0)|add(n1,#1)|subtract(#2,#3)|subtract(#4,#5)|divide(#7,#6) | 2 ( 3 x - 5 ) - 19 = 3 ( x - 4 ) - 5 3 x = 12 x = 4 the answer is b . | general |
math_qa__Ld5MS1w2ix9qfb0R | A committee is reviewing a total of 20x black-and-white films and 8y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction of the selected films are in color? Pick:
A) 40 / 41
B) 20 / 41
C) 30 / 41
D) 60 / 41
E) 80 / 41 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 8</gadget>
<output>41/5 = around 8.2</output>
<gadget id="calculator">8 / (41/5)</gadget>
<output>40/41 = around 0.97561</output>
<result>A</result> | A | 0.97561 | A committee is reviewing a total of 20x black-and-white films and 8y color films for a festival. If the committee selects y/x% of the black-and-white films and all of the color films, what fraction of the selected films are in color? | {
"A": "40 / 41",
"B": "20 / 41",
"C": "30 / 41",
"D": "60 / 41",
"E": "80 / 41"
} | divide(8, add(divide(20, const_100), 8)) | divide(n0,const_100)|add(n1,#0)|divide(n1,#1)| | "say x = y = 10 . in this case we would have : 20 x = 200 black - and - white films ; 8 y = 80 color films . y / x % = 10 / 10 % = 1 % of the black - and - white films , so 2 black - and - white films and all 80 color films , thus total of 82 films were selected . color films thus compose 80 / 82 = 40 / 41 of the selected films . answer : a" | general |
math_qa__UubQJreQJb8ezGIE | There are 780 male and female participants in a meeting. Half the female participants and one-quarterof the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female?
Options
A) 130 B) 100 C) 125 D) 175 E) 225 | <gadget id="calculator">780 / 3</gadget>
<output>260</output>
<gadget id="calculator">260 * 4</gadget>
<output>1_040</output>
<gadget id="calculator">1_040 - 780</gadget>
<output>260</output>
<gadget id="calculator">260 / 2</gadget>
<output>130</output>
<result>A</result> | A | 130 | There are 780 male and female participants in a meeting. Half the female participants and one-quarterof the male participants are Democrats. One-third of all the participants are Democrats. How many of the Democrats are female? | {
"A": "130",
"B": "100",
"C": "125",
"D": "175",
"E": "225"
} | divide(subtract(multiply(divide(780, const_3), const_4), 780), const_2) | divide(n0,const_3)|multiply(#0,const_4)|subtract(#1,n0)|divide(#2,const_2)| | "let m be the number of male participants and f be the number of female articipants in the meeting . thetotal number of participants is given as 780 . hence , we have m + f = 780 now , we have that half the female participants and one - quarter of the male participants are democrats . let d equal the number of the democrats . then we have the equation f / 2 + m / 4 = d now , we have that one - third of the total participants are democrats . hence , we have the equation d = 780 / 3 = 260 solving the three equations yields the solution f = 260 , m = 520 , and d = 260 . the number of female democratic participants equals half the female participants equals 260 / 2 = 130 . answer : a" | general |
math_qa__IYmnXRiSqeDdoHOA | There are 680 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school? Choose the correct option
A) 425 B) 345 C) 375 D) 380 E) 400 | <gadget id="calculator">680 / 5</gadget>
<output>136</output>
<gadget id="calculator">136 * 3</gadget>
<output>408</output>
<result>A</result> | A | 425 | There are 680 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school? | {
"A": "425",
"B": "345",
"C": "375",
"D": "380",
"E": "400"
} | multiply(divide(680, 5), 3) | divide(n0,n2)|multiply(n1,#0)| | "in order to obtain a ratio of boys to girls equal to 3 : 5 , the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys . the total number of boys and girls is 680 . hence 3 x + 5 x = 680 solve for x 8 x = 680 x = 85 number of boys 3 x = 3 × 85 = 255 number of girls 5 x = 5 × 85 = 425 a" | other |
math_qa__b2dn21jfUXEj7uzl | in a clothing store , there are 6 different colored neckties ( orange , yellow , green , blue , and indigo ) and 5 different colored shirts ( orange , yellow , green , blue , and indigo ) that must be packed into boxes for gifts . if each box can only fit one necktie and one shirt , what is the probability that all of the boxes will contain a necktie and a shirt of the same color ? Choose the correct choice from the following answers:
A) 719 / 720 B) 1 / 120 C) 2 / 233 D) 3 / 543 E) 1 / 720 | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 4</gadget>
<output>120</output>
<gadget id="calculator">1 / 120</gadget>
<output>1/120 = around 0.008333</output>
<result>B</result> | B | 0.008333 | in a clothing store , there are 6 different colored neckties ( orange , yellow , green , blue , and indigo ) and 5 different colored shirts ( orange , yellow , green , blue , and indigo ) that must be packed into boxes for gifts . if each box can only fit one necktie and one shirt , what is the probability that all of the boxes will contain a necktie and a shirt of the same color ? | {
"A": "719 / 720",
"B": "1 / 120",
"C": "2 / 233",
"D": "3 / 543",
"E": "1 / 720"
} | divide(const_1, multiply(multiply(6, 5), const_4)) | multiply(n0,n1)|multiply(#0,const_4)|divide(const_1,#1) | 5 ties and 5 shirts . . . red tie can take any of 5 shirts . . orange can take any of the remaining 4 shirts yellow any of remaining 3 . . and so on till last indigo chooses the 1 remaining . . total ways = 5 * 4 * 3 * 2 * 1 = 120 out of this 120 , only 1 way will have same colour tie and shirt . . prob = 1 / 120 b | general |
math_qa__JgEvArNTHwBTKwby | 325 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees Select the correct option: A) 13 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">26 - 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">325 / 25</gadget>
<output>13</output>
<result>A</result> | A | 13 | 325 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees | {
"A": "13",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(325, add(subtract(26, 2), const_1)) | subtract(n1,n2)|add(#0,const_1)|divide(n0,#1)| | "26 trees have 25 gaps between them , required distance ( 325 / 25 ) = 13 a" | physics |
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