id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__q8wBojpuXJIq89nw | A room is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the room? Choose the correct answer
A) 110 B) 124 C) 96 D) 117 E) 127 | <gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 + 24</gadget>
<output>624</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">400 + 32</gadget>
<output>432</output>
<gadget id="calculator">624 * 432</gadget>
<output>269_568</output>
<gadget id="calculator">gcd(624, 432)</gadget>
<output>48</output>
<gadget id="calculator">48 * 48</gadget>
<output>2_304</output>
<gadget id="calculator">269_568 / 2_304</gadget>
<output>117</output>
<result>D</result> | D | 117 | A room is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the room? | {
"A": "110",
"B": "124",
"C": "96",
"D": "117",
"E": "127"
} | divide(multiply(add(multiply(6, const_100), 24), add(multiply(4, const_100), 32)), multiply(gcd(add(multiply(6, const_100), 24), add(multiply(4, const_100), 32)), gcd(add(multiply(6, const_100), 24), add(multiply(4, const_100), 32)))) | multiply(n0,const_100)|multiply(n2,const_100)|add(n1,#0)|add(n3,#1)|gcd(#2,#3)|multiply(#2,#3)|multiply(#4,#4)|divide(#5,#6)| | "length = 6 m 24 cm = 624 cm width = 4 m 32 cm = 432 cm hcf of 624 and 432 = 48 number of square tiles required = ( 624 * 432 ) / ( 48 * 48 ) = 13 * 9 = 117 answer : d" | general |
math_qa__7Yfp5pi7p2oWaxCx | A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km Choices.
A) 200 km B) 222 km C) 224 km D) 248 km E) none of these | <gadget id="calculator">21 * 24</gadget>
<output>504</output>
<gadget id="calculator">504 * 10</gadget>
<output>5_040</output>
<gadget id="calculator">21 + 24</gadget>
<output>45</output>
<gadget id="calculator">5_040 / 45</gadget>
<output>112</output>
<gadget id="calculator">2 * 112</gadget>
<output>224</output>
<result>C</result> | C | 224 | A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km | {
"A": "200 km",
"B": "222 km",
"C": "224 km",
"D": "248 km",
"E": "none of these"
} | multiply(const_2, divide(multiply(multiply(21, 24), 10), add(21, 24))) | add(n1,n2)|multiply(n1,n2)|multiply(n0,#1)|divide(#2,#0)|multiply(#3,const_2)| | "explanation : let time taken to travel the first half = x hr then time taken to travel the second half = ( 10 - x ) hr distance covered in the the first half = 21 x [ because , distance = time * speed ] distance covered in the the second half = 24 ( 10 - x ) distance covered in the the first half = distance covered in the the second half so , 21 x = 24 ( 10 - x ) = > 45 x = 240 = > x = 16 / 3 total distance = 2 * 21 ( 16 / 3 ) = 224 km [ multiplied by 2 as 21 x was distance of half way ] option c" | physics |
math_qa__0RTXIZDzxBHDPDWe | Calculate how many seconds it will take for 4 bells to toll together again, given that they begin to toll together respectively at the intervals of 9, 10, 14 and 18 seconds. ? Choose the correct choice from the following answers.
A) 636
B) 631
C) 633
D) 610
E) 630 | <gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">9 * 10</gadget>
<output>90</output>
<gadget id="calculator">7 * 90</gadget>
<output>630</output>
<result>E</result> | E | 630 | Calculate how many seconds it will take for 4 bells to toll together again, given that they begin to toll together respectively at the intervals of 9, 10, 14 and 18 seconds. ? | {
"A": "636",
"B": "631",
"C": "633",
"D": "610",
"E": "630"
} | multiply(divide(14, const_2), multiply(9, 10)) | divide(n3,const_2)|multiply(n1,n2)|multiply(#0,#1) | lcm of 9 , 10 , 14 and 18 is 630 lcm = 630 answer : e | gain |
math_qa__bnq2p1FHuPEHJsvS | The size of a flat-screen tablet is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 8-inch flat-screen tablet than a square 7 -inch flat-screen tablet? Choose the most appropriate option
A) 7.6 B) 7.3 C) 7.2 D) 7.5 E) 8.0 | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">64 / 2</gadget>
<output>32</output>
<gadget id="calculator">7 ** 2</gadget>
<output>49</output>
<gadget id="calculator">49 / 2</gadget>
<output>49/2 = around 24.5</output>
<gadget id="calculator">32 - (49/2)</gadget>
<output>15/2 = around 7.5</output>
<result>D</result> | D | 7.5 | The size of a flat-screen tablet is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 8-inch flat-screen tablet than a square 7 -inch flat-screen tablet? | {
"A": "7.6",
"B": "7.3",
"C": "7.2",
"D": "7.5",
"E": "8.0"
} | subtract(divide(power(8, const_2), const_2), divide(power(7, const_2), const_2)) | power(n0,const_2)|power(n1,const_2)|divide(#0,const_2)|divide(#1,const_2)|subtract(#2,#3)| | "if we take a square with side length x and draw a diagonal , we get two isosceles right triangles . if we focus on one such right triangle , we see that the legs have length x . square 8 - inch flat - screen television the diagonal ( hypotenuse ) = 8 so , we can apply the pythagorean theorem to get x ² + x ² = 8 ² simplify : 2 x ² = 8 ² divide both sides by 2 to get : x ² = 8 ² / 2 since the area of the square = x ² , we can see that the area of this square is 8 ² / 2 square 7 - inch flat - screen television the diagonal ( hypotenuse ) = 7 so , we can apply the pythagorean theorem to get x ² + x ² = 7 ² simplify : 2 x ² = 7 ² divide both sides by 2 to get : x ² = 7 ² / 2 since the area of the square = x ² , we can see that the area of this square is 7 ² / 2 difference in areas = 8 ² / 2 - 7 ² / 2 = ( 8 ² - 7 ² ) / 2 = ( 64 - 49 ) / 2 = 15 / 2 = 7.5 d" | geometry |
math_qa__bIP46uFFy4jddp9X | If the wheel is 14 cm then the number of revolutions to cover a distance of 1672 cm is? Choose the correct option.
A) 22 B) 28 C) 19 D) 12 E) 88 | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">1 * 10</gadget>
<output>10</output>
<gadget id="calculator">300 + 10</gadget>
<output>310</output>
<gadget id="calculator">310 + 4</gadget>
<output>314</output>
<gadget id="calculator">314 / 100</gadget>
<output>157/50 = around 3.14</output>
<gadget id="calculator">2 * (157/50)</gadget>
<output>157/25 = around 6.28</output>
<gadget id="calculator">(157/25) * 14</gadget>
<output>2_198/25 = around 87.92</output>
<gadget id="calculator">1_672 / (2_198/25)</gadget>
<output>20_900/1_099 = around 19.017288</output>
<result>C</result> | C | 19 | If the wheel is 14 cm then the number of revolutions to cover a distance of 1672 cm is? | {
"A": "22",
"B": "28",
"C": "19",
"D": "12",
"E": "88"
} | divide(1672, multiply(multiply(const_2, divide(add(add(multiply(const_3, const_100), multiply(const_1, const_10)), const_4), const_100)), 14)) | multiply(const_100,const_3)|multiply(const_1,const_10)|add(#0,#1)|add(#2,const_4)|divide(#3,const_100)|multiply(#4,const_2)|multiply(n0,#5)|divide(n1,#6)| | "2 * 22 / 7 * 14 * x = 1672 = > x = 19 answer : c" | physics |
math_qa__gOxRD1KCPIuaWNsW | If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2016) = ? Choose the correct choice:
A) 2017
B) 2088
C) 270
D) 1881
E) 1781 | <gadget id="calculator">1 + 2_016</gadget>
<output>2_017</output>
<result>A</result> | A | 2,017 | If f(f(n)) + f(n) = 2n+3, f(0) = 1 then f(2016) = ? | {
"A": "2017",
"B": "2088",
"C": "270",
"D": "1881",
"E": "1781"
} | add(1, 2016) | add(n3,n4) | f ( f ( 0 ) ) + f ( 0 ) = 2 ( 0 ) + 3 ⇒ ⇒ f ( 1 ) = 3 - 1 = 2 , f ( 1 ) = 2 f ( f ( 1 ) ) + f ( 1 ) = 2 ( 1 ) + 3 ⇒ ⇒ f ( 2 ) = 5 - 2 = 3 , f ( 2 ) = 3 f ( f ( 2 ) ) + f ( 2 ) = 2 ( 2 ) + 3 ⇒ ⇒ f ( 3 ) = 7 - 3 = 4 , f ( 3 ) = 4 . . . . . . . . . . . . . . f ( 2016 ) = 2017 ans : a | general |
math_qa__qzyfNwxAhHjL3j1r | 75 percent of Andrea's living room floor is covered by a carpet that is 4 feet by 9 feet. What is the area of her living room floor? Choose the correct choice from the following
A) 48
B) 180 / 7
C) 50.4
D) 60
E) 90 | <gadget id="calculator">4 * 9</gadget>
<output>36</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">36 / (3/4)</gadget>
<output>48</output>
<result>A</result> | A | 48 | 75 percent of Andrea's living room floor is covered by a carpet that is 4 feet by 9 feet. What is the area of her living room floor? | {
"A": "48",
"B": "180 / 7",
"C": "50.4",
"D": "60",
"E": "90"
} | divide(multiply(4, 9), divide(75, const_100)) | divide(n0,const_100)|multiply(n1,n2)|divide(#1,#0) | 75 % of area of the floor = 4 * 9 square feet = 36 square feet i . e . 100 % area of floor = ( 36 / 75 ) * 100 = 48 square feet answer : option a | gain |
math_qa__E8w7HvAnWa8JFHZi | The radius of a sphere is increased by 10%. The surface area increases by? Choose the correct choice from the following answers.
A) 21 %
B) 31 %
C) 41 %
D) 51 %
E) none of these | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">4 * pi * ((11/10) ** 2)</gadget>
<output>121*pi/25 = around 15.205308</output>
<gadget id="calculator">4 * pi * (1 ** 2)</gadget>
<output>4*pi = around 12.566371</output>
<gadget id="calculator">(121*pi/25) - (4*pi)</gadget>
<output>21*pi/25 = around 2.638938</output>
<gadget id="calculator">(21*pi/25) / (4*pi)</gadget>
<output>21/100 = around 0.21</output>
<gadget id="calculator">(21/100) * 100</gadget>
<output>21</output>
<result>A</result> | A | 21 | The radius of a sphere is increased by 10%. The surface area increases by? | {
"A": "21 %",
"B": "31 %",
"C": "41 %",
"D": "51 %",
"E": "none of these"
} | multiply(divide(subtract(surface_sphere(add(const_1, divide(10, const_100))), surface_sphere(const_1)), surface_sphere(const_1)), const_100) | divide(n0,const_100)|surface_sphere(const_1)|add(#0,const_1)|surface_sphere(#2)|subtract(#3,#1)|divide(#4,#1)|multiply(#5,const_100) | since 4 x pi x radius x radius = surface area . therefore , net % change in area = ( x + y + xy / 100 ) % = [ 10 + 10 + ( 10 x 10 ) / 100 ] % or 21 % . answer : a | geometry |
math_qa__NC1pnUT4pc71Rk06 | There are 408 boys and 264 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed. Choose the correct option: A) 28 B) 32 C) 35 D) 30 E) 45 | <gadget id="calculator">408 + 264</gadget>
<output>672</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">672 / 24</gadget>
<output>28</output>
<result>A</result> | A | 28 | There are 408 boys and 264 girls in a school which are to be divided into equal sections of either boys or girls alone. Find the total number of sections thus formed. | {
"A": "28",
"B": "32",
"C": "35",
"D": "30",
"E": "45"
} | divide(add(408, 264), multiply(multiply(multiply(const_2, const_2), const_2), const_3)) | add(n0,n1)|multiply(const_2,const_2)|multiply(#1,const_2)|multiply(#2,const_3)|divide(#0,#3)| | "explanation : hcf ( 408 , 264 ) = 24 the number of boys or girls that can be placed in a section = 24 . thus the total number of sections is given by 408 / 24 + 264 / 24 = 17 + 11 = 28 answer : a" | general |
math_qa__VLcXUiAI6VHsxg5m | The speed at which a woman can row a boat in still water is 120 kmph. If she rows downstream, where the speed of current is 60 kmph, what time will he take to cover 500 metres?
Choices:
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">120 + 60</gadget>
<output>180</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">180 * (5/18)</gadget>
<output>50</output>
<gadget id="calculator">500 / 50</gadget>
<output>10</output>
<result>C</result> | C | 10 | The speed at which a woman can row a boat in still water is 120 kmph. If she rows downstream, where the speed of current is 60 kmph, what time will he take to cover 500 metres? | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | divide(500, multiply(add(120, 60), const_0_2778)) | add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1) | speed of the boat downstream = 120 + 60 = 180 kmph = 180 * 5 / 18 = 50 m / s hence time taken to cover 500 m = 500 / 50 = 10 seconds . answer : c | physics |
math_qa__W6meCXnTIhRkanWB | At a small company, 61 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married? Choose the correct choice from the following answers.
A) 5 / 16 B) 1 / 3 C) 9 / 20 D) 47 / 61 E) 5 / 7 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">61 / 100</gadget>
<output>61/100 = around 0.61</output>
<gadget id="calculator">1 - (61/100)</gadget>
<output>39/100 = around 0.39</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(39/100) * (1/3)</gadget>
<output>13/100 = around 0.13</output>
<gadget id="calculator">(3/5) - (13/100)</gadget>
<output>47/100 = around 0.47</output>
<gadget id="calculator">(47/100) / (61/100)</gadget>
<output>47/61 = around 0.770492</output>
<result>D</result> | D | 0.770492 | At a small company, 61 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married? | {
"A": "5 / 16",
"B": "1 / 3",
"C": "9 / 20",
"D": "47 / 61",
"E": "5 / 7"
} | divide(subtract(divide(60, const_100), multiply(subtract(const_1, divide(61, const_100)), subtract(const_1, divide(2, 3)))), divide(61, const_100)) | divide(n1,const_100)|divide(n0,const_100)|divide(n2,n3)|subtract(const_1,#1)|subtract(const_1,#2)|multiply(#3,#4)|subtract(#0,#5)|divide(#6,#1)| | "lets take total employees are 100 . given that , total women = 61 and total married = 60 . total men = 100 - 61 = 39 and single men = 2 / 3 * 39 = 26 . married men = total men - single men = 39 - 26 = 13 . married women = total married - married men = 60 - 13 = 47 . fraction of women are married = married women / total women = 47 / 61 = 5 / 7 . ans d" | gain |
math_qa__CMtl32TW548gpwpm | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 252 runs? Choose the correct answer
A) 6.25 B) 6.22 C) 5.5 D) 6.39 E) 6.13 | <gadget id="calculator">10 * 3.2</gadget>
<output>32</output>
<gadget id="calculator">252 - 32</gadget>
<output>220</output>
<gadget id="calculator">220 / 40</gadget>
<output>11/2 = around 5.5</output>
<result>C</result> | C | 5.5 | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 252 runs? | {
"A": "6.25",
"B": "6.22",
"C": "5.5",
"D": "6.39",
"E": "6.13"
} | divide(subtract(252, multiply(10, 3.2)), 40) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | "required run rate = [ 252 - ( 3.2 * 10 ) ] / 40 = 220 / 40 = 5.5 answer : c" | gain |
math_qa__IzR46HYGqAzThbUr | At what price must an article costing Rs.85.5 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price?
Choose the correct choice from the following options:
A) 122.5
B) 142.5
C) 162.5
D) 182.5
E) 112.5 | <gadget id="calculator">85.5 * 25</gadget>
<output>2_137.5</output>
<gadget id="calculator">2_137.5 / 100</gadget>
<output>21.375</output>
<gadget id="calculator">85.5 + 21.375</gadget>
<output>106.875</output>
<gadget id="calculator">106.875 * 100</gadget>
<output>10_687.5</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">10_687.5 / 95</gadget>
<output>112.5</output>
<result>E</result> | E | 112.5 | At what price must an article costing Rs.85.5 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price? | {
"A": "122.5",
"B": "142.5",
"C": "162.5",
"D": "182.5",
"E": "112.5"
} | divide(multiply(add(85.5, divide(multiply(85.5, 25), const_100)), const_100), subtract(const_100, 5)) | multiply(n0,n2)|subtract(const_100,n1)|divide(#0,const_100)|add(n0,#2)|multiply(#3,const_100)|divide(#4,#1)| | "cp = 85.50 sp = 85.5 * ( 125 / 100 ) = 106.875 mp * ( 95 / 100 ) = 106.875 mp = 112.5 answer : e" | gain |
math_qa__Ti9sIWLAP7ieQ1YH | We have boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If we dispose of one blue box for one additional red box, the total number of berries would increase by 12, and the difference between the total number of strawberries and the total number of blueberries would increase by 76. Each blue box contains how many blueberries? Answers.
A) 26 B) 28 C) 30 D) 32 E) 34 | <gadget id="calculator">76 - 12</gadget>
<output>64</output>
<gadget id="calculator">64 / 2</gadget>
<output>32</output>
<result>D</result> | D | 32 | We have boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If we dispose of one blue box for one additional red box, the total number of berries would increase by 12, and the difference between the total number of strawberries and the total number of blueberries would increase by 76. Each blue box contains how many blueberries? | {
"A": "26",
"B": "28",
"C": "30",
"D": "32",
"E": "34"
} | divide(subtract(76, 12), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "let x be the number of blueberries in each blue box . then there are x + 12 strawberries in each red box . x + ( x + 12 ) = 76 x = 32 the answer is d ." | general |
math_qa__vyVZnJrN3Fr13dCn | 15 men take 20 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men? Choose the correct choice from the following answers
A) 27.57 B) 28.57 C) 29.57 D) 30.57 E) 32 | <gadget id="calculator">20 * 8</gadget>
<output>160</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">160 * 45</gadget>
<output>7_200</output>
<gadget id="calculator">21 * 2</gadget>
<output>42</output>
<gadget id="calculator">42 * 6</gadget>
<output>252</output>
<gadget id="calculator">7_200 / 252</gadget>
<output>200/7 = around 28.571429</output>
<gadget id="calculator">floor(200/7)</gadget>
<output>28</output>
<gadget id="calculator">28 + 1</gadget>
<output>29</output>
<result>B</result> | B | 28.57 | 15 men take 20 days of 8 hours each to do a piece of work. How many days of 6 hours each would 21 women take to do the same. If 3 women do as much work as 2 men? | {
"A": "27.57",
"B": "28.57",
"C": "29.57",
"D": "30.57",
"E": "32"
} | add(floor(divide(multiply(multiply(20, 8), multiply(15, 3)), multiply(multiply(21, 2), 6))), const_1) | multiply(n1,n2)|multiply(n0,n5)|multiply(n4,n6)|multiply(#0,#1)|multiply(n3,#2)|divide(#3,#4)|floor(#5)|add(#6,const_1) | 3 w = 2 m 15 m - - - - - - 20 * 8 hours 21 w - - - - - - x * 6 hours 14 m - - - - - - x * 6 15 * 20 * 8 = 14 * x * 6 x = 28.57 answer : b | physics |
math_qa__D7vXZogqfAeolxtt | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. States B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State ? Choose one:
A) 7600
B) 8000
C) 8400
D) data inadequate
E) none of these | <gadget id="calculator">7 - 6</gadget>
<output>1</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">80 / (1/100)</gadget>
<output>8_000</output>
<result>B</result> | B | 8,000 | In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. States B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State ? | {
"A": "7600",
"B": "8000",
"C": "8400",
"D": "data inadequate",
"E": "none of these"
} | divide(80, divide(subtract(7, 6), const_100)) | subtract(n1,n0)|divide(#0,const_100)|divide(n2,#1)| | "solution let the number of candidates appeared from each state be x . then , 7 % of x - 6 % of x = 80 ⇔ 1 % of x = 80 ⇔ x = 80 × 100 = 8000 . answer b" | general |
math_qa__WNo720UgDO38e7ZZ | A train leaves Mumabai at 9 am at a speed of 45 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 90 kmph. When and at what distance from Mumbai do the two trains meet? Choose one:
A) 287 B) 279 C) 90 D) 278 E) 379 | <gadget id="calculator">45 * 1</gadget>
<output>45</output>
<gadget id="calculator">90 - 45</gadget>
<output>45</output>
<gadget id="calculator">45 / 45</gadget>
<output>1</output>
<gadget id="calculator">1 * 90</gadget>
<output>90</output>
<result>C</result> | C | 90 | A train leaves Mumabai at 9 am at a speed of 45 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 90 kmph. When and at what distance from Mumbai do the two trains meet? | {
"A": "287",
"B": "279",
"C": "90",
"D": "278",
"E": "379"
} | multiply(divide(multiply(45, const_1), subtract(90, 45)), 90) | multiply(n1,const_1)|subtract(n2,n1)|divide(#0,#1)|multiply(n2,#2)| | "when the second train leaves mumbai the first train covers 45 * 1 = 45 km so , the distance between first train and second train is 45 km at 10.00 am time taken by the trains to meet = distance / relative speed = 45 / ( 90 - 45 ) = 1 hours so , the two trains meet at 2 p . m . the two trains meet 1 * 90 = 90 km away from mumbai . answer : c" | physics |
math_qa__gQ4rafaOB9Tai3ZA | In 1990 the budgets for projects Q and V were $660,000 and $860,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ? Options: A) 1992 B) 1993 C) 1994 D) 1995 E) 1996 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">1_990 + 60</gadget>
<output>2_050</output>
<result>D</result> | D | 1,995 | In 1990 the budgets for projects Q and V were $660,000 and $860,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ? | {
"A": "1992",
"B": "1993",
"C": "1994",
"D": "1995",
"E": "1996"
} | add(1990, multiply(10, multiply(const_2, const_3))) | multiply(const_2,const_3)|multiply(n3,#0)|add(n0,#1)| | "let the no of years it takes is x . 660 + 30 x = 860 - 10 x - - > 40 x = 200 and x = 5 . thus , it happens in 1995 . d ." | general |
math_qa__uxuhYOqAVuB38djI | If 0.10 of a number is equal to 0.070 of another number, the ratio of the numbers is : Choices: A) 2 : 3 B) 3 : 4 C) 7 : 10 D) 20 : 3 E) 30 : 7 | <gadget id="calculator">0.07 * 100</gadget>
<output>7</output>
<gadget id="calculator">0.1 * 100</gadget>
<output>10</output>
<gadget id="calculator">7 / 10</gadget>
<output>7/10 = around 0.7</output>
<result>C</result> | C | 0.7 | If 0.10 of a number is equal to 0.070 of another number, the ratio of the numbers is : | {
"A": "2 : 3",
"B": "3 : 4",
"C": "7 : 10",
"D": "20 : 3",
"E": "30 : 7"
} | divide(multiply(0.070, const_100), multiply(0.10, const_100)) | multiply(n1,const_100)|multiply(n0,const_100)|divide(#0,#1)| | "0.10 a = 0.070 b - > a / b = 0.07 / 0.10 = 7 / 10 : . a : b = 7 : 10 answer : c" | other |
math_qa__0z7OWbQggoTquxwU | A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 600. How much did he have with him in the beginning? Choose the correct choice from the following.
A) s 200 B) s 1500 C) s 300 D) s 450 E) s 550 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) / 5</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/3) - (2/15)</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">(8/15) / 4</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(8/15) - (2/15)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">600 / (2/5)</gadget>
<output>1_500</output>
<result>B</result> | B | 1,500 | A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 600. How much did he have with him in the beginning? | {
"A": "s 200",
"B": "s 1500",
"C": "s 300",
"D": "s 450",
"E": "s 550"
} | divide(600, subtract(subtract(subtract(1, divide(1, 3)), divide(subtract(1, divide(1, 3)), 5)), divide(subtract(subtract(1, divide(1, 3)), divide(subtract(1, divide(1, 3)), 5)), 4))) | divide(n0,n1)|subtract(n0,#0)|divide(#1,n3)|subtract(#1,#2)|divide(#3,n5)|subtract(#3,#4)|divide(n6,#5)| | "suppose the amount in the beginning was rs ’ x ’ money spent on clothes = rs 1 x / 3 balance = rs 2 x / 3 money spent on food = 1 / 5 of 2 x / 3 = rs 2 x / 15 balance = 2 x / 3 - 2 x / 15 = rs 8 x / 15 money spent on travel = 1 / 4 of 8 x / 15 = rs 2 x / 15 = 8 x / 15 - 2 x / 15 = 6 x / 15 = rs 2 x / 5 therefore 2 x / 5 = 100 = 1500 answer : b" | general |
math_qa__YerNhLGFvPwOqArv | A fruit drink is made of orange, watermelon, and grape juice, where 15 percent of the drink is orange juice and 60 percent is watermelon juice. If the drink is made with 30 ounces of grape juice, how many ounces is the drink total? Select the correct option:
A) 120
B) 160
C) 190
D) 200
E) 400 | <gadget id="calculator">30 * 15</gadget>
<output>450</output>
<gadget id="calculator">60 + 15</gadget>
<output>75</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">450 / 25</gadget>
<output>18</output>
<gadget id="calculator">30 + 18</gadget>
<output>48</output>
<gadget id="calculator">30 * 60</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 25</gadget>
<output>72</output>
<gadget id="calculator">48 + 72</gadget>
<output>120</output>
<result>A</result> | A | 120 | A fruit drink is made of orange, watermelon, and grape juice, where 15 percent of the drink is orange juice and 60 percent is watermelon juice. If the drink is made with 30 ounces of grape juice, how many ounces is the drink total? | {
"A": "120",
"B": "160",
"C": "190",
"D": "200",
"E": "400"
} | add(add(30, divide(multiply(30, 15), subtract(const_100, add(60, 15)))), divide(multiply(30, 60), subtract(const_100, add(60, 15)))) | add(n0,n1)|multiply(n0,n2)|multiply(n1,n2)|subtract(const_100,#0)|divide(#1,#3)|divide(#2,#3)|add(n2,#4)|add(#6,#5) | let the total number of ounces in the drink be x . % of orange = 15 % % of watermelon = 60 % % of grape = 100 % - 75 % = 25 % 0.25 x = 30 x = 120 therefore there are a total of 120 ounces in the drink . the answer is a . | general |
math_qa__XSSBsTyNa732XpxU | Sam invested Rs. 3000 @ 10% per annum for one year. If the interest is compounded half-yearly, then the amount received by Sam at the end of the year will be? Choose the most appropriate option.
A) 2554.0 B) 3387.0 C) 2503.0 D) 3307.5 E) 16537.11 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">(441/400) * 3_000</gadget>
<output>6_615/2 = around 3_307.5</output>
<result>D</result> | D | 3,307.5 | Sam invested Rs. 3000 @ 10% per annum for one year. If the interest is compounded half-yearly, then the amount received by Sam at the end of the year will be? | {
"A": "2554.0",
"B": "3387.0",
"C": "2503.0",
"D": "3307.5",
"E": "16537.11"
} | multiply(power(add(divide(divide(10, const_2), const_100), const_1), const_2), 3000) | divide(n1,const_2)|divide(#0,const_100)|add(#1,const_1)|power(#2,const_2)|multiply(n0,#3)| | "p = rs . 3000 ; r = 10 % p . a . = 5 % per half - year ; t = 1 year = 2 half - year amount = [ 3000 * ( 1 + 5 / 100 ) 2 ] = ( 3000 * 21 / 20 * 21 / 20 ) = rs . 3307.50 answer : d" | gain |
math_qa__CycSBIBeg4Bv7azt | A space shuttle orbits the earth at about 12 kilometers per second. This speed is equal to how many kilometers per hour?
Choose the correct choice from the following answers:
A) 480 B) 2,880 C) 4,800 D) 28,800 E) 43,200 | <gadget id="calculator">12 * 3_600</gadget>
<output>43_200</output>
<result>E</result> | E | 43,200 | A space shuttle orbits the earth at about 12 kilometers per second. This speed is equal to how many kilometers per hour? | {
"A": "480",
"B": "2,880",
"C": "4,800",
"D": "28,800",
"E": "43,200"
} | multiply(12, const_3600) | multiply(n0,const_3600)| | "seconds in 1 hours : 60 s in 1 min 60 min in 1 hr 60 * 60 = 3600 sec in 1 hr 12 * 3600 = 43,200 answer : e" | physics |
math_qa__iIa84Y5byPDUgLuG | If 213 × 16 = 3408, then 0.16 × 2.13 is equal to : Choose the correct choice from the following answers
A) 0.3408 B) 3.408 C) 34.08 D) 340.8 E) none of these | <gadget id="calculator">0.16 * 2.13</gadget>
<output>0.3408</output>
<result>A</result> | A | 0.3408 | If 213 × 16 = 3408, then 0.16 × 2.13 is equal to : | {
"A": "0.3408",
"B": "3.408",
"C": "34.08",
"D": "340.8",
"E": "none of these"
} | multiply(0.16, 2.13) | multiply(n4,n3)| | "solution 0.16 × 2.13 = ( 16 / 100 x 213 / 100 ) = ( 16 x 213 / 10000 ) = 3408 / 10000 = 0.3408 . answer a" | general |
math_qa__Age1KBkboGfzY3jN | What is the area of a square field whose diagonal of length 28 m? Answers:
A) 288 B) 289 C) 200 D) 112 E) 392 | <gadget id="calculator">28 ** 2</gadget>
<output>784</output>
<gadget id="calculator">784 / 2</gadget>
<output>392</output>
<result>E</result> | E | 392 | What is the area of a square field whose diagonal of length 28 m? | {
"A": "288",
"B": "289",
"C": "200",
"D": "112",
"E": "392"
} | divide(square_area(28), const_2) | square_area(n0)|divide(#0,const_2)| | "d 2 / 2 = ( 28 * 28 ) / 2 = 392 answer : e" | geometry |
math_qa__jxf3GipkhgD1vBGl | 16 machines can do a work in 10days. How many machines are needed to complete the work in 40days?
Choose the correct choice from the following options:
A) 10
B) 6
C) 4
D) 7
E) 5 | <gadget id="calculator">16 * 10</gadget>
<output>160</output>
<gadget id="calculator">160 / 40</gadget>
<output>4</output>
<result>C</result> | C | 4 | 16 machines can do a work in 10days. How many machines are needed to complete the work in 40days? | {
"A": "10",
"B": "6",
"C": "4",
"D": "7",
"E": "5"
} | divide(multiply(16, 10), 40) | multiply(n0,n1)|divide(#0,n2)| | "required number of machines = 16 * 10 / 40 = 4 answer is c" | physics |
math_qa__zLMAvQOa8e7AZSqf | The salary of A, B, C, D, E is Rs. 8000, Rs. 5000, Rs. 15000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is
Choose the correct choice from the following answers
A) rs . 7000 B) rs . 8000 C) rs . 8800 D) rs . 9000 E) none | <gadget id="calculator">8_000 + 5_000</gadget>
<output>13_000</output>
<gadget id="calculator">13_000 + 15_000</gadget>
<output>28_000</output>
<gadget id="calculator">28_000 + 7_000</gadget>
<output>35_000</output>
<gadget id="calculator">35_000 + 9_000</gadget>
<output>44_000</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">44_000 / 5</gadget>
<output>8_800</output>
<result>C</result> | C | 8,800 | The salary of A, B, C, D, E is Rs. 8000, Rs. 5000, Rs. 15000, Rs. 7000, Rs. 9000 per month respectively, then the average salary of A, B, C, D, and E per month is | {
"A": "rs . 7000",
"B": "rs . 8000",
"C": "rs . 8800",
"D": "rs . 9000",
"E": "none"
} | divide(add(add(add(add(8000, 5000), 15000), 7000), 9000), add(const_4, const_1)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "answer average salary = 8000 + 5000 + 15000 + 7000 + 9000 / 5 = rs . 8800 correct option : c" | general |
math_qa__iVCVhDfMq3qO47nh | Total number of 4 digit number do not having the digit 3 or 6. Choose the correct choice from the following choices.
A) 22 B) 28 C) 27 D) 19 E) 11 | <gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 4</gadget>
<output>13</output>
<gadget id="calculator">13 + 3</gadget>
<output>16</output>
<gadget id="calculator">16 + 3</gadget>
<output>19</output>
<result>D</result> | D | 19 | Total number of 4 digit number do not having the digit 3 or 6. | {
"A": "22",
"B": "28",
"C": "27",
"D": "19",
"E": "11"
} | add(add(add(add(6, 3), 4), 3), 3) | add(n1,n2)|add(n0,#0)|add(n1,#1)|add(n1,#2) | answer : d | general |
math_qa__sNpFNYH3ptT9qa9P | The average weight of A, B and C is 43 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is: Options:
A) 33 kg B) 31 kg C) 32 kg D) 36 kg E) 37 kg | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">43 * 2</gadget>
<output>86</output>
<gadget id="calculator">80 + 86</gadget>
<output>166</output>
<gadget id="calculator">43 * 3</gadget>
<output>129</output>
<gadget id="calculator">166 - 129</gadget>
<output>37</output>
<result>E</result> | E | 37 | The average weight of A, B and C is 43 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is: | {
"A": "33 kg",
"B": "31 kg",
"C": "32 kg",
"D": "36 kg",
"E": "37 kg"
} | subtract(add(multiply(40, const_2), multiply(43, const_2)), multiply(43, const_3)) | multiply(n1,const_2)|multiply(n2,const_2)|multiply(n0,const_3)|add(#0,#1)|subtract(#3,#2)| | "let a , b , c represent their respective weights . then , we have : a + b + c = ( 45 x 3 ) = 129 . . . . ( i ) a + b = ( 40 x 2 ) = 80 . . . . ( ii ) b + c = ( 43 x 2 ) = 86 . . . . ( iii ) adding ( ii ) and ( iii ) , we get : a + 2 b + c = 166 . . . . ( iv ) subtracting ( i ) from ( iv ) , we get : b = 37 . b ' s weight = 37 kg . e" | general |
math_qa__kg2lvfNcpOrgasJl | A dog breeder currently has 9 breeding dogs. 6 of the dogs have exactly 1 littermate, and 3 of the dogs have exactly 2 littermates. If 2 dogs are selected at random, what is the probability R that both selected dogs are NOT littermates?
Choose the correct answer:
A) 1 / 6 B) 2 / 9 C) 5 / 6 D) 7 / 9 E) 8 / 9 | <gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<result>C</result> | C | 0.833333 | A dog breeder currently has 9 breeding dogs. 6 of the dogs have exactly 1 littermate, and 3 of the dogs have exactly 2 littermates. If 2 dogs are selected at random, what is the probability R that both selected dogs are NOT littermates? | {
"A": "1 / 6",
"B": "2 / 9",
"C": "5 / 6",
"D": "7 / 9",
"E": "8 / 9"
} | divide(const_5, 6) | divide(const_5,n1)| | "we have three pairs of dogs for the 6 with exactly one littermate , and one triplet , with each having exactly two littermates . so , in fact there are two types of dogs : those with one littermate - say a , and the others with two littermates - b . work with probabilities : choosing two dogs , we can have either one dog of type b or none ( we can not have two dogs both of type b ) . the probability of choosing one dog of type b and one of type a is 3 / 9 * 6 / 8 * 2 = 1 / 2 ( the factor of 2 for the two possibilities ba and ab ) . the probability r of choosing two dogs of type a which are not littermates is 6 / 9 * 4 / 8 = 1 / 3 ( choose one a , then another a which is n ' t the previous one ' s littermate ) . the required probability is 1 / 2 + 1 / 3 = 5 / 6 . find the probability for the complementary event : choose aa or bb . probability of choosing two dogs of type a who are littermates is 6 / 9 * 1 / 8 = 1 / 12 . probability of choosing two dogs of type b ( who necessarily are littermates ) is 3 / 9 * 2 / 8 = 1 / 12 . again , we obtain 1 - ( 1 / 12 + 1 / 12 ) = 5 / 6 . answer : c" | other |
math_qa__f3XJsv1Ui42Zf8Ot | A train running at the speed of 60 km/hr crosses a pole in 21 seconds. What is the length of the train?
Choices.
A) 350 m B) 278 m C) 876 m D) 150 m E) 267 m | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 21</gadget>
<output>350</output>
<result>A</result> | A | 350 | A train running at the speed of 60 km/hr crosses a pole in 21 seconds. What is the length of the train? | {
"A": "350 m",
"B": "278 m",
"C": "876 m",
"D": "150 m",
"E": "267 m"
} | multiply(divide(multiply(60, const_1000), const_3600), 21) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 60 * 5 / 18 ) m / sec = ( 50 / 3 ) m / sec length of the train = ( speed x time ) = ( 50 / 3 * 21 ) m = 350 m . answer : a" | physics |
math_qa__NMcIg8cHUhH35qqH | A military camp has a food reserve for 250 personnel for 40 days. If after 15 days 50 more personnel are added to the camp, find the number of days the reserve will last for? Choose the most appropriate option: A) 25 B) 67 C) 26 D) 29 E) 18 | <gadget id="calculator">40 - 15</gadget>
<output>25</output>
<gadget id="calculator">250 * 25</gadget>
<output>6_250</output>
<gadget id="calculator">250 + 50</gadget>
<output>300</output>
<gadget id="calculator">6_250 / 300</gadget>
<output>125/6 = around 20.833333</output>
<gadget id="calculator">(125/6) + 3</gadget>
<output>143/6 = around 23.833333</output>
<result>A</result> | A | 25 | A military camp has a food reserve for 250 personnel for 40 days. If after 15 days 50 more personnel are added to the camp, find the number of days the reserve will last for? | {
"A": "25",
"B": "67",
"C": "26",
"D": "29",
"E": "18"
} | add(divide(multiply(250, subtract(40, 15)), add(250, 50)), const_3) | add(n0,n3)|subtract(n1,n2)|multiply(n0,#1)|divide(#2,#0)|add(#3,const_3) | explanation : as the camp has a reserve for 250 personnel that can last for 40 days , after 10 days the reserve left for 250 personnel is for 30 days . now 50 more personnel are added in the camp . hence , the food reserve for 300 personnel will last for : 250 : 300 : : x : 30 … … . . ( it is an indirect proportion as less men means more days ) x = ( 250 * 30 ) / 300 x = 25 days answer : a | general |
math_qa__IGSi2AMFA8IgQrzX | What is x if x + 2y = 12 and y = 3? Select.
A) 10 B) 8 C) 6 D) 4 E) 2 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<result>C</result> | C | 6 | What is x if x + 2y = 12 and y = 3? | {
"A": "10",
"B": "8",
"C": "6",
"D": "4",
"E": "2"
} | subtract(12, multiply(2, 3)) | multiply(n0,n2)|subtract(n1,#0)| | "x = 12 - 2 y x = 12 - 6 . x = 6 answer : c" | general |
math_qa__La508TmqMQHI66gb | In how many years Rs 200 will produce the same interest at 10% as Rs. 1000 produce in 2 years at 12% Choose the correct choice:
A) 13
B) 9
C) 11
D) 12
E) 10 | <gadget id="calculator">1_000 * 12</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 / 100</gadget>
<output>120</output>
<gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 200</gadget>
<output>20</output>
<gadget id="calculator">240 / 20</gadget>
<output>12</output>
<result>D</result> | D | 12 | In how many years Rs 200 will produce the same interest at 10% as Rs. 1000 produce in 2 years at 12% | {
"A": "13",
"B": "9",
"C": "11",
"D": "12",
"E": "10"
} | divide(multiply(divide(multiply(1000, 12), const_100), 2), multiply(divide(10, const_100), 200)) | divide(n1,const_100)|multiply(n2,n4)|divide(#1,const_100)|multiply(n0,#0)|multiply(n3,#2)|divide(#4,#3) | explanation : clue : firstly we need to calculate the si with prinical 1000 , time 2 years and rate 12 % , it will be rs . 240 then we can get the time as time = ( 100 * 240 ) / ( 200 * 10 ) = 12 option d | gain |
math_qa__2tK8oegXCoKCaPlu | A store’s selling price of $2240 for a certain computer would yield a profit of 40 percent of the store’s cost for the computer. What selling price would yield a profit of 60 percent of the computer’s cost?
Select: A) $ 2400 B) $ 2464 C) $ 2560 D) $ 2732 E) $ 2800 | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">160 / 140</gadget>
<output>8/7 = around 1.142857</output>
<gadget id="calculator">2_240 * (8/7)</gadget>
<output>2_560</output>
<result>C</result> | C | 2,560 | A store’s selling price of $2240 for a certain computer would yield a profit of 40 percent of the store’s cost for the computer. What selling price would yield a profit of 60 percent of the computer’s cost? | {
"A": "$ 2400",
"B": "$ 2464",
"C": "$ 2560",
"D": "$ 2732",
"E": "$ 2800"
} | multiply(2240, divide(add(const_100, 60), add(const_100, 40))) | add(n2,const_100)|add(n1,const_100)|divide(#0,#1)|multiply(n0,#2)| | "1.4 x = 2240 x = 2240 / 1.4 so , 1.6 x = 2240 * 1.6 / 1.4 = 2560 answer : - c" | gain |
math_qa__AQ1KUfRw1eKSjTnV | A person buys 18 local tickets for Rs 110. Each first class ticket costs Rs 10 and each second class ticket costs Rs 3. What will another lot of 18 tickets in which the numbers of first class and second class tickets are interchanged cost?
Choose the correct option: A) 112 B) 118 C) 121 D) 124 E) none of these | <gadget id="calculator">18 * 3</gadget>
<output>54</output>
<gadget id="calculator">110 - 54</gadget>
<output>56</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">56 / 7</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">24 + 100</gadget>
<output>124</output>
<result>D</result> | D | 124 | A person buys 18 local tickets for Rs 110. Each first class ticket costs Rs 10 and each second class ticket costs Rs 3. What will another lot of 18 tickets in which the numbers of first class and second class tickets are interchanged cost? | {
"A": "112",
"B": "118",
"C": "121",
"D": "124",
"E": "none of these"
} | add(multiply(divide(subtract(110, multiply(18, 3)), subtract(10, 3)), 3), multiply(10, 10)) | multiply(n0,n3)|multiply(n2,n2)|subtract(n2,n3)|subtract(n1,#0)|divide(#3,#2)|multiply(n3,#4)|add(#5,#1) | explanation : let , there are x first class ticket and ( 18 - x ) second class tickets . then , 110 = 10 x + 3 ( 18 − x ) . = > 110 = 10 x + 54 − 3 x . = > 7 x = 56 . = > x = 8 . if the number of the first class and second class tickets are interchanged , then the total cost would be 10 × 10 + 3 × 8 = 124 . answer : d | physics |
math_qa__C4hkIvBCUlSifwOa | out of 3 given numbers , the first one is twice the second and 3 times the third . if the average of these numbers is 88 , then the difference between first and third is . Select the correct option.
A) 92 B) 39 C) 87 D) 96 E) none | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">88 + 8</gadget>
<output>96</output>
<result>D</result> | D | 96 | out of 3 given numbers , the first one is twice the second and 3 times the third . if the average of these numbers is 88 , then the difference between first and third is . | {
"A": "92",
"B": "39",
"C": "87",
"D": "96",
"E": "none"
} | add(88, add(const_4, const_4)) | add(const_4,const_4)|add(n2,#0) | sum of three number is = 88 * 3 = 264 let three numbers are a , b , c and a is the highest and c is the lowest then , 2 b = a so b = a / 2 and 3 c = a so c = a / 3 we can write , a + b + c = 264 a + a / 2 + a / 3 = 264 11 a / 6 = 264 a = 144 so , c = 144 / 3 = 48 so there difference is = 144 - 48 = 96 answer d | general |
math_qa__J8Cz0vJhpg8jxOyV | The cost to park a car in a certain parking garage is $9.00 for up to 2 hours of parking and $1.75 for each hour in excess of 2 hours. What is the average (arithmetic mean) cost per hour to park a car in the parking garage for 9 hours? Choose one
A) $ 1.09 B) $ 1.67 C) $ 2.25 D) $ 2.36 E) $ 2.50 | <gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">1.75 * 7</gadget>
<output>12.25</output>
<gadget id="calculator">9 + 12.25</gadget>
<output>21.25</output>
<gadget id="calculator">21.25 / 9</gadget>
<output>2.361111</output>
<result>D</result> | D | 2.36 | The cost to park a car in a certain parking garage is $9.00 for up to 2 hours of parking and $1.75 for each hour in excess of 2 hours. What is the average (arithmetic mean) cost per hour to park a car in the parking garage for 9 hours? | {
"A": "$ 1.09",
"B": "$ 1.67",
"C": "$ 2.25",
"D": "$ 2.36",
"E": "$ 2.50"
} | divide(add(9.00, multiply(1.75, subtract(9, 2))), 9) | subtract(n4,n1)|multiply(n2,#0)|add(n0,#1)|divide(#2,n4)| | "total cost of parking for 9 hours = 9 $ for the first 2 hours and then 1.75 for ( 9 - 2 ) hours = 9 + 7 * 1.75 = 21.25 thus the average parking price = 21.25 / 9 = 2.36 $ d is the correct answer ." | general |
math_qa__4lQSddmvAeKId3Bg | Find the compound interest on $30000 in 2years at 4% per annum, the interest being compounded half-yearly? Choose the correct choice from the following answers.
A) $ 645.56 B) $ 824.32 C) $ 954.26 D) $ 2472.96 E) $ 1020.45 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) / 2</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) + 1</gadget>
<output>51/50 = around 1.02</output>
<gadget id="calculator">(51/50) ** 4</gadget>
<output>6_765_201/6_250_000 = around 1.082432</output>
<gadget id="calculator">(6_765_201/6_250_000) * 30_000</gadget>
<output>20_295_603/625 = around 32_472.9648</output>
<gadget id="calculator">(20_295_603/625) - 30_000</gadget>
<output>1_545_603/625 = around 2_472.9648</output>
<result>D</result> | D | 2,472.96 | Find the compound interest on $30000 in 2years at 4% per annum, the interest being compounded half-yearly? | {
"A": "$ 645.56",
"B": "$ 824.32",
"C": "$ 954.26",
"D": "$ 2472.96",
"E": "$ 1020.45"
} | subtract(multiply(power(add(divide(divide(4, const_100), 2), const_1), 4), 30000), 30000) | divide(n2,const_100)|divide(#0,n1)|add(#1,const_1)|power(#2,n2)|multiply(n0,#3)|subtract(#4,n0)| | "principle = $ 10000 rate = 2 % half yearly = 4 half years amount = 30000 * ( 1 + 2 / 100 ) ^ 4 = 30000 * 51 / 50 * 51 / 50 * 51 / 50 * 51 / 50 = $ 32472.96 c . i . = 32472.96 - 10000 = $ 2472.96 answer is d" | gain |
math_qa__aKq4DhMwKklslfgh | The average waight of A,B,C is 45 Kg. The avgwgt of A & B be 40Kg & that of B,C be 43Kg. Find the wgt of B. Choose the correct choice from the following choices:
A) 34 kg
B) 40 kg
C) 42 kg
D) 41 kg
E) 31 kg | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">45 * 3</gadget>
<output>135</output>
<gadget id="calculator">43 * 2</gadget>
<output>86</output>
<gadget id="calculator">135 - 86</gadget>
<output>49</output>
<gadget id="calculator">80 - 49</gadget>
<output>31</output>
<result>E</result> | E | 31 | The average waight of A,B,C is 45 Kg. The avgwgt of A & B be 40Kg & that of B,C be 43Kg. Find the wgt of B. | {
"A": "34 kg",
"B": "40 kg",
"C": "42 kg",
"D": "41 kg",
"E": "31 kg"
} | subtract(multiply(40, const_2), subtract(multiply(45, const_3), multiply(43, const_2))) | multiply(n1,const_2)|multiply(n0,const_3)|multiply(n2,const_2)|subtract(#1,#2)|subtract(#0,#3)| | ". let a , b , c represent their individual wgts . then , a + b + c = ( 45 * 3 ) kg = 135 kg a + b = ( 40 * 2 ) kg = 80 kg & b + c = ( 43 * 2 ) kg = 86 kg b = ( a + b ) + ( b + c ) - ( a + b + c ) = ( 80 + 86 - 135 ) kg = 31 kg . answer is e ." | general |
math_qa__nFKvbUV8bFZQLPfl | of the 600 residents of clermontville , 35 % watch the television show island survival , 40 % watch lovelost lawyers and 50 % watch medical emergency . if all residents watch at least one of these 3 shows and 18 % watch exactly 2 of these shows , then how many clermontville residents z watch all of the shows ? Choose the most appropriate option:
A) 150
B) 108
C) 42
D) 21
E) - 21 | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">600 * (7/20)</gadget>
<output>210</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">600 * (2/5)</gadget>
<output>240</output>
<gadget id="calculator">210 + 240</gadget>
<output>450</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">600 * (1/2)</gadget>
<output>300</output>
<gadget id="calculator">450 + 300</gadget>
<output>750</output>
<gadget id="calculator">750 - 600</gadget>
<output>150</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) * 600</gadget>
<output>108</output>
<gadget id="calculator">150 - 108</gadget>
<output>42</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<result>D</result> | D | 21 | of the 600 residents of clermontville , 35 % watch the television show island survival , 40 % watch lovelost lawyers and 50 % watch medical emergency . if all residents watch at least one of these 3 shows and 18 % watch exactly 2 of these shows , then how many clermontville residents z watch all of the shows ? | {
"A": "150",
"B": "108",
"C": "42",
"D": "21",
"E": "- 21"
} | divide(subtract(subtract(add(add(multiply(600, divide(35, const_100)), multiply(600, divide(40, const_100))), multiply(600, divide(50, const_100))), 600), multiply(divide(18, const_100), 600)), 2) | divide(n1,const_100)|divide(n2,const_100)|divide(n3,const_100)|divide(n5,const_100)|multiply(n0,#0)|multiply(n0,#1)|multiply(n0,#2)|multiply(n0,#3)|add(#4,#5)|add(#8,#6)|subtract(#9,n0)|subtract(#10,#7)|divide(#11,n6) | oa is d . 100 = a + b + c - ab - ac - bc + abc , which is the same as the following formula 100 = a + b + c + ( - ab - ac - bc + abc + abc + abc ) - 2 abc . the term between parantheses value 18 % so the equation to resolve is 100 = 35 + 40 + 50 - 18 - 2 abc therefore the value of abc is z = 3.5 % of 600 , is 21 . d is the correct answer | gain |
math_qa__6mFvnEsEc4pFwsJz | John's marks wrongly entered as 82 instead of 62. Due to that the average marks for the class got increased by half (1/2). The number of John in the class is? Choose the correct choice from the following answers:
A) 70
B) 78
C) 80
D) 84
E) 90 | <gadget id="calculator">82 - 62</gadget>
<output>20</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">20 / (1/2)</gadget>
<output>40</output>
<gadget id="calculator">40 * 2</gadget>
<output>80</output>
<result>C</result> | C | 80 | John's marks wrongly entered as 82 instead of 62. Due to that the average marks for the class got increased by half (1/2). The number of John in the class is? | {
"A": "70",
"B": "78",
"C": "80",
"D": "84",
"E": "90"
} | multiply(divide(subtract(82, 62), divide(1, 2)), 2) | divide(n2,n3)|subtract(n0,n1)|divide(#1,#0)|multiply(n3,#2) | otal increase in marks = x x 1 = x 2 2 x / 2 = ( 82 - 62 ) x / 2 = 40 x = 80 . c | general |
math_qa__fALPWzfZjPnkyJbf | A train running at the speed of 90 km/hr crosses a pole in 10 seconds. Find the length of the train. Choices:
A) 150 B) 180 C) 250 D) 200 E) 225 | <gadget id="calculator">90 * 1_000</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 / 3_600</gadget>
<output>25</output>
<gadget id="calculator">25 * 10</gadget>
<output>250</output>
<result>C</result> | C | 250 | A train running at the speed of 90 km/hr crosses a pole in 10 seconds. Find the length of the train. | {
"A": "150",
"B": "180",
"C": "250",
"D": "200",
"E": "225"
} | multiply(divide(multiply(90, const_1000), const_3600), 10) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 90 * ( 5 / 18 ) m / sec = 25 m / sec length of train ( distance ) = speed * time 25 * 10 = 250 meter answer : c" | physics |
math_qa__AdDSjFtKEnCDzVFP | If 65% of a number is greater than 5% of 60 by 23, what is the number? Choose the correct choice.
A) 65
B) 40
C) 55
D) 30
E) 60 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 5</gadget>
<output>3</output>
<gadget id="calculator">23 + 3</gadget>
<output>26</output>
<gadget id="calculator">26 / 65</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">100 * (2/5)</gadget>
<output>40</output>
<result>B</result> | B | 40 | If 65% of a number is greater than 5% of 60 by 23, what is the number? | {
"A": "65",
"B": "40",
"C": "55",
"D": "30",
"E": "60"
} | multiply(const_100, divide(add(23, multiply(divide(60, const_100), 5)), 65)) | divide(n2,const_100)|multiply(n1,#0)|add(n3,#1)|divide(#2,n0)|multiply(#3,const_100)| | "explanation : 65 / 100 * x - 5 / 100 * 60 = 23 65 / 100 * x - 3 = 23 65 / 100 * x = 26 x = 26 * 100 / 65 x = 40 answer : option b" | gain |
math_qa__vSGNuoyEdT3S8lq5 | 8 men and 2 boys working together can do 4 times as much work as a man and a boy . working capacity of man and boy is in the ratio Choose one.
A) 1 : 2 B) 1 : 3 C) 2 : 1 D) 2 : 3 E) none of these | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">2 / 4</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | 8 men and 2 boys working together can do 4 times as much work as a man and a boy . working capacity of man and boy is in the ratio | {
"A": "1 : 2",
"B": "1 : 3",
"C": "2 : 1",
"D": "2 : 3",
"E": "none of these"
} | divide(subtract(4, 2), subtract(8, 4)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1) | explanation : let 1 man 1 day work = x 1 boy 1 day work = y then 8 x + 2 y = 4 ( x + y ) = > 4 x = 2 y = > x / y = 2 / 4 = > x : y = 1 : 2 option a | other |
math_qa__cX0b8i9ljIDLAVvY | The difference between the place value and the face value of 7 in the numeral 856973 is Answers: A) 63 B) 6973 C) 5994 D) 6084 E) none of these | <gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">70 - 7</gadget>
<output>63</output>
<result>A</result> | A | 63 | The difference between the place value and the face value of 7 in the numeral 856973 is | {
"A": "63",
"B": "6973",
"C": "5994",
"D": "6084",
"E": "none of these"
} | subtract(multiply(const_10, 7), 7) | multiply(n0,const_10)|subtract(#0,n0) | ( place value of 7 ) - ( face value of 7 ) = ( 70 - 7 ) = 63 answer : option a | general |
math_qa__YnQ85rpYiMJYOd9o | If a person walks at 15 km/hr instead of 5 km/hr, he would have walked 20 km more. The actual distance traveled by him is? Choose the correct answer:
A) 50 km B) 76 km C) 18 km D) 10 km E) 97 km | <gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">20 / 10</gadget>
<output>2</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<result>D</result> | D | 10 | If a person walks at 15 km/hr instead of 5 km/hr, he would have walked 20 km more. The actual distance traveled by him is? | {
"A": "50 km",
"B": "76 km",
"C": "18 km",
"D": "10 km",
"E": "97 km"
} | multiply(5, divide(20, subtract(15, 5))) | subtract(n0,n1)|divide(n2,#0)|multiply(n1,#1)| | "let the actual distance traveled be x km . then , x / 5 = ( x + 20 ) / 15 10 x - 100 = > x = 10 km . answer : d" | general |
math_qa__Rg1zpiDxF0uGNebs | The diameter of a cylindrical tin is 4cm and height is 5 cm. Find the volume of the cylinder? Choose the correct choice from the following options: A) 33 B) 45 C) 20 D) 77 E) 21 | <gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">pi * (2 ** 2) * 5</gadget>
<output>20*pi = around 62.831853</output>
<gadget id="calculator">(20*pi) / pi</gadget>
<output>20</output>
<result>C</result> | C | 20 | The diameter of a cylindrical tin is 4cm and height is 5 cm. Find the volume of the cylinder? | {
"A": "33",
"B": "45",
"C": "20",
"D": "77",
"E": "21"
} | divide(volume_cylinder(divide(4, const_2), 5), const_pi) | divide(n0,const_2)|volume_cylinder(#0,n1)|divide(#1,const_pi)| | "r = 2 h = 5 π * 2 * 2 * 5 = 20 π cc answer : c" | geometry |
math_qa__WlJcPjnB0c2JqsV8 | 20% of a 6 litre solution and 60% of 4 litre solution are mixed. What percentage of the mixture of solution
Choose the correct option.
A) 36 %
B) 35 %
C) 34 %
D) 33 %
E) 32 % | <gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">240 / 100</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(12/5) + (6/5)</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">(18/5) / 10</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/25) * 100</gadget>
<output>36</output>
<result>A</result> | A | 36 | 20% of a 6 litre solution and 60% of 4 litre solution are mixed. What percentage of the mixture of solution | {
"A": "36 %",
"B": "35 %",
"C": "34 %",
"D": "33 %",
"E": "32 %"
} | multiply(divide(add(divide(multiply(60, 4), const_100), divide(multiply(20, 6), const_100)), add(6, 4)), const_100) | add(n1,n3)|multiply(n2,n3)|multiply(n0,n1)|divide(#1,const_100)|divide(#2,const_100)|add(#3,#4)|divide(#5,#0)|multiply(#6,const_100) | 20 % of 6 litre is ( 6 * 20 / 100 ) = 1.2 litre 60 % of 4 litre is ( 60 * 4 / 100 ) = 2.4 litre the mixture is 3.6 litre so the percentage is ( 3.6 * 100 / 10 ) = 36 % answer : a | gain |
math_qa__wGu0azVY3hUHYzr2 | Population of a city decreases by 10% at the end of first year and increases by 10% at the end of second year and again decreases by 10% at the end of third year. If the population of the city at the end of third year is 4455, then what was the population of the city at the beginning of the first year? Answers: A) 5000 B) 4500 C) 4950 D) 1000 E) 2000 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(9/10) * (11/10)</gadget>
<output>99/100 = around 0.99</output>
<gadget id="calculator">(99/100) * (9/10)</gadget>
<output>891/1_000 = around 0.891</output>
<gadget id="calculator">4_455 / (891/1_000)</gadget>
<output>5_000</output>
<result>A</result> | A | 5,000 | Population of a city decreases by 10% at the end of first year and increases by 10% at the end of second year and again decreases by 10% at the end of third year. If the population of the city at the end of third year is 4455, then what was the population of the city at the beginning of the first year? | {
"A": "5000",
"B": "4500",
"C": "4950",
"D": "1000",
"E": "2000"
} | divide(4455, multiply(multiply(subtract(const_1, divide(10, const_100)), add(const_1, divide(10, const_100))), subtract(const_1, divide(10, const_100)))) | divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#0)|multiply(#1,#2)|multiply(#3,#2)|divide(n3,#4) | m . f = 90 / 100 * 110 * 100 * 90 / 100 = 81 * 11 / 1000 population before 3 yrs = i . q / m . f = 4455 * 1000 / 81 * 11 = 5000 answer : a | gain |
math_qa__zitot6IMAQXzgfLX | A contractor is engaged for 30days on the condition that he receives Rs.25 for each dayhe works &is fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many dayswas he absent? Pick
A) 8 B) 10 C) 15 D) 17 E) 19 | <gadget id="calculator">7.5 * 30</gadget>
<output>225</output>
<gadget id="calculator">225 + 425</gadget>
<output>650</output>
<gadget id="calculator">7.5 + 25</gadget>
<output>32.5</output>
<gadget id="calculator">650 / 32.5</gadget>
<output>20</output>
<gadget id="calculator">30 - 20</gadget>
<output>10</output>
<result>B</result> | B | 10 | A contractor is engaged for 30days on the condition that he receives Rs.25 for each dayhe works &is fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many dayswas he absent? | {
"A": "8",
"B": "10",
"C": "15",
"D": "17",
"E": "19"
} | subtract(30, divide(add(multiply(7.5, 30), 425), add(7.5, 25))) | add(n1,n2)|multiply(n0,n2)|add(n3,#1)|divide(#2,#0)|subtract(n0,#3) | 30 * 25 = 750 425 - - - - - - - - - - - 325 25 + 7.50 = 32.5 325 / 32.5 = 10 b | physics |
math_qa__NdU3jSt5M8QVqUtE | Stalin and Heather are 20 miles apart and walk towards each other along the same route. Stalin walks at constant rate that is 1 mile per hour faster than heather's constant rate of 5 miles/hour. If Heather starts her journey 20 minutes after Stalin, how far from the original destination has Heather walked when the two meet?
Answers.
A) 4 miles
B) 6 miles
C) 9 miles
D) 10 miles
E) 12 mile | <gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 60</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 20</gadget>
<output>2</output>
<gadget id="calculator">20 - 2</gadget>
<output>18</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">18 / 11</gadget>
<output>18/11 = around 1.636364</output>
<gadget id="calculator">(18/11) * 5</gadget>
<output>90/11 = around 8.181818</output>
<gadget id="calculator">(90/11) / 2</gadget>
<output>45/11 = around 4.090909</output>
<result>A</result> | A | 4 | Stalin and Heather are 20 miles apart and walk towards each other along the same route. Stalin walks at constant rate that is 1 mile per hour faster than heather's constant rate of 5 miles/hour. If Heather starts her journey 20 minutes after Stalin, how far from the original destination has Heather walked when the two meet? | {
"A": "4 miles",
"B": "6 miles",
"C": "9 miles",
"D": "10 miles",
"E": "12 mile"
} | divide(multiply(divide(subtract(20, multiply(divide(add(1, 5), const_60), 20)), add(5, add(1, 5))), 5), const_2) | add(n1,n2)|add(n2,#0)|divide(#0,const_60)|multiply(n0,#2)|subtract(n0,#3)|divide(#4,#1)|multiply(n2,#5)|divide(#6,const_2) | original distance between s and h = 20 miles . speed of s = 5 + 1 = 6 mph , speed of h = 5 mph . time traveled by h = t hours - - - > time traveled by s = t + 20 / 60 = t + 2 / 6 hours . now , the total distances traveled by s and h = 20 miles - - - > 6 * ( t + 2 / 6 ) + 5 * t = 20 - - - > t = 8 / 11 hours . thus h has traveled for 8 / 11 hours giving you a total distance for h = 5 * 8 / 11 ~ 4 miles . a is thus the correct answer . p . s . : based on the wording of the question , you should calculatehow far from theoriginal destination has heather walkedwhen the two meet . ' original destination ' for h does not make any sense . original destination for h was situated at a distance of 20 miles . | physics |
math_qa__g9UMt2W5UqNFrMEV | A bag marked at $240 is sold for $120. The rate of discount is?
Select.
A) 10 %
B) 25 %
C) 20 %
D) 50 %
E) 45 % | <gadget id="calculator">240 - 120</gadget>
<output>120</output>
<gadget id="calculator">120 / 240</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>D</result> | D | 50 | A bag marked at $240 is sold for $120. The rate of discount is? | {
"A": "10 %",
"B": "25 %",
"C": "20 %",
"D": "50 %",
"E": "45 %"
} | multiply(divide(subtract(240, 120), 240), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "rate of discount = 120 / 240 * 100 = 50 % answer is d" | gain |
math_qa__gqJI0MdoHwALVhlZ | The average weight of 8 person's increases by 2 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? Choose the correct choice from the following choices:
A) 70 kg
B) 80 kg
C) 81 kg
D) 90 kg
E) 91 kg | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">16 + 65</gadget>
<output>81</output>
<result>C</result> | C | 81 | The average weight of 8 person's increases by 2 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person? | {
"A": "70 kg",
"B": "80 kg",
"C": "81 kg",
"D": "90 kg",
"E": "91 kg"
} | add(multiply(8, 2), 65) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 8 x 2 ) kg = 16 kg . weight of new person = ( 65 + 16 ) kg = 81 kg . c )" | general |
math_qa__RbX56hp3lSva2uPj | A man buy a book in Rs50 & sale it Rs100. What is the rate of profit ???
Choose one:
A) 10 % B) 100 % C) 30 % D) 25 % E) 28 % | <gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 50</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<result>B</result> | B | 100 | A man buy a book in Rs50 & sale it Rs100. What is the rate of profit ??? | {
"A": "10 %",
"B": "100 %",
"C": "30 %",
"D": "25 %",
"E": "28 %"
} | multiply(divide(subtract(100, 50), 50), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "cp = 50 sp = 100 profit = 100 - 50 = 50 % = 50 / 50 * 100 = 100 % answer : b" | gain |
math_qa__su9bleqkNf8NuNlc | A group of students was interviewed for that if it was asked whether or not they speak French and / or English. Among those who speak French, 20 speak English well, while 60 of them do not speak English. If 60% of students do not speak French, how many students were surveyed?
Choose the correct choice from the following answers
A) 250
B) 225
C) 175
D) 195
E) 200 | <gadget id="calculator">20 + 60</gadget>
<output>80</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">80 / (2/5)</gadget>
<output>200</output>
<result>E</result> | E | 200 | A group of students was interviewed for that if it was asked whether or not they speak French and / or English. Among those who speak French, 20 speak English well, while 60 of them do not speak English. If 60% of students do not speak French, how many students were surveyed? | {
"A": "250",
"B": "225",
"C": "175",
"D": "195",
"E": "200"
} | divide(add(20, 60), divide(subtract(const_100, 60), const_100)) | add(n0,n1)|subtract(const_100,n2)|divide(#1,const_100)|divide(#0,#2)| | "number of students who speak french are 60 + 20 = 80 of total students , the percentage of students who do not speak french was 60 % - - > percentage of who do is 40 % 80 - - - - - - - 40 % x - - - - - - - 100 % x = 80 * 100 / 40 = 200 = number of all students answer is e" | gain |
math_qa__Otw4KfEsqsZ8inhz | The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.2 kg. The weight of the new student is Select the correct option
A) 4 kg B) 21.6 kg C) 22.4 kg D) 21 kg E) none of these | <gadget id="calculator">29 + 1</gadget>
<output>30</output>
<gadget id="calculator">30 * 27.2</gadget>
<output>816</output>
<gadget id="calculator">29 * 28</gadget>
<output>812</output>
<gadget id="calculator">816 - 812</gadget>
<output>4</output>
<result>A</result> | A | 4 | The average weight of 29 students is 28 kg. By the admission of a new student, the average weight is reduced to 27.2 kg. The weight of the new student is | {
"A": "4 kg",
"B": "21.6 kg",
"C": "22.4 kg",
"D": "21 kg",
"E": "none of these"
} | subtract(multiply(add(29, const_1), 27.2), multiply(29, 28)) | add(n0,const_1)|multiply(n0,n1)|multiply(n2,#0)|subtract(#2,#1)| | "exp . the total weight of 29 students = 29 * 28 the total weight of 30 students = 30 * 27.2 weight of the new student = ( 30 * 27.2 – 29 * 28 ) = 816 - 812 = 4 answer : a" | general |
math_qa__hDe7hFerEAqLDAdf | The average expenditure of a labourer for 6 months was 80 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income i Choices
A) 70 B) 72 C) 75 D) 78 E) 80 | <gadget id="calculator">80 * 6</gadget>
<output>480</output>
<gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">480 + 240</gadget>
<output>720</output>
<gadget id="calculator">720 + 30</gadget>
<output>750</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">750 / 10</gadget>
<output>75</output>
<result>C</result> | C | 75 | The average expenditure of a labourer for 6 months was 80 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income i | {
"A": "70",
"B": "72",
"C": "75",
"D": "78",
"E": "80"
} | divide(add(add(multiply(80, 6), multiply(60, 4)), 30), add(6, 4)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|add(n4,#3)|divide(#4,#0)| | "income of 6 months = ( 6 × 80 ) – debt = 480 – debt income of the man for next 4 months = 4 × 60 + debt + 30 = 270 + debt ∴ income of 10 months = 750 average monthly income = 750 ÷ 10 = 75 answer c" | general |
math_qa__5WgrKjRfXK5a9lra | The length of a rectangle is halved, while its breadth is tripled. Wa tis the % changein area?
Choose the correct choice from the following
A) 40 % B) 45 % C) 50 % D) 65 % E) 70 % | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 * (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) / 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>C</result> | C | 50 | The length of a rectangle is halved, while its breadth is tripled. Wa tis the % changein area? | {
"A": "40 %",
"B": "45 %",
"C": "50 %",
"D": "65 %",
"E": "70 %"
} | multiply(divide(subtract(multiply(const_3, divide(const_1, const_2)), const_1), const_1), const_100) | divide(const_1,const_2)|multiply(#0,const_3)|subtract(#1,const_1)|divide(#2,const_1)|multiply(#3,const_100)| | "let original length = x and original breadth = y . original area = xy . new length = x . 2 new breadth = 3 y . new area = x x 3 y = 3 xy . 2 2 increase % = 1 xy x 1 x 100 % = 50 % . 2 xy c" | geometry |
math_qa__HToJu41KCdavYOtx | A man saves 25% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 10%, he is only able to save Rs. 175 per month. What is his monthly salary? Choose the most appropriate option.
A) rs . 1000
B) rs . 2000
C) rs . 1500
D) rs . 3000
E) rs . 3100 | <gadget id="calculator">175 * 100</gadget>
<output>17_500</output>
<gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">75 * (1/10)</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">75 + (15/2)</gadget>
<output>165/2 = around 82.5</output>
<gadget id="calculator">100 - (165/2)</gadget>
<output>35/2 = around 17.5</output>
<gadget id="calculator">17_500 / (35/2)</gadget>
<output>1_000</output>
<result>A</result> | A | 1,000 | A man saves 25% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 10%, he is only able to save Rs. 175 per month. What is his monthly salary? | {
"A": "rs . 1000",
"B": "rs . 2000",
"C": "rs . 1500",
"D": "rs . 3000",
"E": "rs . 3100"
} | divide(multiply(175, const_100), subtract(const_100, add(subtract(const_100, 25), multiply(subtract(const_100, 25), divide(10, const_100))))) | divide(n1,const_100)|multiply(n2,const_100)|subtract(const_100,n0)|multiply(#0,#2)|add(#3,#2)|subtract(const_100,#4)|divide(#1,#5)| | "income = rs . 100 expenditure = rs . 75 savings = rs . 25 present expenditure 75 + 75 * ( 10 / 100 ) = rs . 82.5 present savings = 100 – 82.50 = rs . 17.50 if savings is rs . 17.50 , salary = rs . 100 if savings is rs . 175 , salary = 100 / 17.5 * 175 = 1000 answer : a" | general |
math_qa__VgRZITEA98WwfTP3 | A 15% stock yielding 12% is quoted at: Select the correct option:
A) s . 83.33 B) s . 110 C) s . 112 D) s . 125 E) s . 140 | <gadget id="calculator">100 / 12</gadget>
<output>25/3 = around 8.333333</output>
<gadget id="calculator">(25/3) * 15</gadget>
<output>125</output>
<result>D</result> | D | 125 | A 15% stock yielding 12% is quoted at: | {
"A": "s . 83.33",
"B": "s . 110",
"C": "s . 112",
"D": "s . 125",
"E": "s . 140"
} | multiply(divide(const_100, 12), 15) | divide(const_100,n1)|multiply(n0,#0)| | "income of rs 12 on investment of rs 100 income of rs 15 on investment of ? = ( 15 * 100 ) / 12 = 125 answer : d" | gain |
math_qa__elUVuLhKZnDPw2sa | On June 1 a bicycle dealer noted that the number of bicycles in stock had decreased by 2 for each of the past 5 months. If the stock continues to decrease at the same rate for the rest of the year, how many fewer bicycles will be in stock on September 1 than were in stock on January 1?
Select the correct option:
A) 18 B) 12 C) 20 D) 32 E) 36 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<result>A</result> | A | 18 | On June 1 a bicycle dealer noted that the number of bicycles in stock had decreased by 2 for each of the past 5 months. If the stock continues to decrease at the same rate for the rest of the year, how many fewer bicycles will be in stock on September 1 than were in stock on January 1? | {
"A": "18",
"B": "12",
"C": "20",
"D": "32",
"E": "36"
} | multiply(subtract(const_10, 1), 2) | subtract(const_10,n0)|multiply(n1,#0)| | "jan 1 = c feb 1 = c - 2 march 1 = c - 4 april 1 = c - 8 may 1 = c - 10 june 1 = c - 12 july 1 = c - 14 aug 1 = c - 16 sept 1 = c - 18 difference between stock on september 1 than were in stock on january 1 will be - c - ( c - 18 ) = 18 hence answer will be ( a )" | gain |
math_qa__7U7Hvi3wrVzKG7Ob | Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.92 at the candy store. What is John’s weekly allowance? Choose the correct choice from the following options: A) $ 2.55 B) $ 2.85 C) $ 3.15 D) $ 3.45 E) $ 3.75 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/3) * (2/5)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(3/5) + (2/15)</gadget>
<output>11/15 = around 0.733333</output>
<gadget id="calculator">1 - (11/15)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">0.92 / (4/15)</gadget>
<output>3.45</output>
<result>D</result> | D | 3.45 | Having received his weekly allowance, John spent 3/5 of his allowance at the arcade. The next day he spent one third of his remaining allowance at the toy store, and then spent his last $0.92 at the candy store. What is John’s weekly allowance? | {
"A": "$ 2.55",
"B": "$ 2.85",
"C": "$ 3.15",
"D": "$ 3.45",
"E": "$ 3.75"
} | divide(0.92, subtract(const_1, add(divide(3, 5), multiply(divide(const_1, 3), subtract(const_1, divide(3, 5)))))) | divide(n0,n1)|divide(const_1,n0)|subtract(const_1,#0)|multiply(#1,#2)|add(#0,#3)|subtract(const_1,#4)|divide(n2,#5)| | "x = 3 x / 5 + 1 / 3 * 2 x / 5 + 92 4 x / 15 = 92 x = 345 = $ 3.45 the answer is d ." | general |
math_qa__0w09Otqr58u6fdx5 | a salesman ’ s terms were changed from a flat commission of 5 % on all his sales to a fixed salary of rs . 1300 plus 2.5 % commission on all sales exceeding rs . 4000 . if his remuneration as per new scheme was rs . 600 more than that by the previous schema , his sales were worth ? Choose the correct choice from the following answers.
A) 12028
B) 12000
C) 12019
D) 12197
E) 18000 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">2.5 / 100</gadget>
<output>0.025</output>
<gadget id="calculator">4_000 * 0.025</gadget>
<output>100</output>
<gadget id="calculator">1_000 - 100</gadget>
<output>900</output>
<gadget id="calculator">900 - 600</gadget>
<output>300</output>
<gadget id="calculator">300 / 0.025</gadget>
<output>12_000</output>
<result>C</result> | C | 12,019 | a salesman ’ s terms were changed from a flat commission of 5 % on all his sales to a fixed salary of rs . 1300 plus 2.5 % commission on all sales exceeding rs . 4000 . if his remuneration as per new scheme was rs . 600 more than that by the previous schema , his sales were worth ? | {
"A": "12028",
"B": "12000",
"C": "12019",
"D": "12197",
"E": "18000"
} | divide(subtract(subtract(multiply(const_100, const_10), multiply(4000, divide(2.5, const_100))), 600), divide(2.5, const_100)) | divide(n2,const_100)|multiply(const_10,const_100)|multiply(n3,#0)|subtract(#1,#2)|subtract(#3,n4)|divide(#4,#0) | [ 1300 + ( x - 4000 ) * ( 2.5 / 100 ) ] - x * ( 5 / 100 ) = 600 x = 18000 answer : c | general |
math_qa__XkW6t56HNLhA9wDs | A sum fetched a total simple interest of 4020.75 at the rate of 9 %.p.a. in 5 years. What is the sum? Choose the correct choice from the following answers.
A) 5768 B) 8925 C) 2345 D) 6474 E) 8935 | <gadget id="calculator">4_020.75 * 100</gadget>
<output>402_075</output>
<gadget id="calculator">402_075 / 9</gadget>
<output>44_675</output>
<gadget id="calculator">44_675 / 5</gadget>
<output>8_935</output>
<result>E</result> | E | 8,935 | A sum fetched a total simple interest of 4020.75 at the rate of 9 %.p.a. in 5 years. What is the sum? | {
"A": "5768",
"B": "8925",
"C": "2345",
"D": "6474",
"E": "8935"
} | divide(divide(multiply(4020.75, const_100), 9), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "principal = ( 100 x 4020.75 ) / ( 9 x 5 ) = 402075 / 45 = 8935 . answer e" | gain |
math_qa__X7BLZdsIJpnt4MdE | Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/11 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21? Options
A) 21 B) 35 C) 33 D) 60 E) 65 | <gadget id="calculator">7 * 11</gadget>
<output>77</output>
<gadget id="calculator">77 * 3</gadget>
<output>231</output>
<gadget id="calculator">231 / 7</gadget>
<output>33</output>
<result>C</result> | C | 33 | Exactly 3/7 of the people in the room are under the age of 21, and exactly 5/11 of the people in the room are over the age of 65. If the total number of the people in the room is greater than 50 and less than 100, how many people in the room are under the age of 21? | {
"A": "21",
"B": "35",
"C": "33",
"D": "60",
"E": "65"
} | divide(multiply(multiply(7, 11), 3), 7) | multiply(n1,n4)|multiply(n0,#0)|divide(#1,n1) | the total number of the people in the room must be a multiple of both 7 and 11 ( in order 3 / 7 and 5 / 11 of the number to be an integer ) , thus the total number of the people must be a multiple of lcm of 7 and 11 , which is 77 . since , the total number of the people in the room is greater than 50 and less than 100 , then there are 77 people in the room . therefore there are 3 / 7 * 77 = 33 people in the room under the age of 21 . answer : c . | general |
math_qa__A0CnOC7G3JsV7iL3 | One night 15 percent of the female officers on a police force were on duty. If 300 officers were on duty that night and half of these were female officers, how many female officers were on the police force?
Options.
A) 90 B) 180 C) 270 D) 500 E) 1,000 | <gadget id="calculator">300 / 2</gadget>
<output>150</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">150 / (3/20)</gadget>
<output>1_000</output>
<result>E</result> | E | 1,000 | One night 15 percent of the female officers on a police force were on duty. If 300 officers were on duty that night and half of these were female officers, how many female officers were on the police force? | {
"A": "90",
"B": "180",
"C": "270",
"D": "500",
"E": "1,000"
} | divide(divide(300, const_2), divide(15, const_100)) | divide(n1,const_2)|divide(n0,const_100)|divide(#0,#1)| | "let total number of female officers in the police force = f total number of officers on duty on that night = 300 number of female officers on duty on that night = 300 / 2 = 150 ( 15 / 100 ) * f = 150 = > f = 1000 answer e" | gain |
math_qa__n5c8QsSclw8BxyPL | With # andeach representing different digits in the problem below, the difference between #and ## is 801. What is the value of?
#
-##
____
812 Choose the correct choice from the following answers.
A) 7
B) 8
C) 9
D) 10
E) 11 | <gadget id="calculator">812 - 801</gadget>
<output>11</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<result>C</result> | C | 9 | With # andeach representing different digits in the problem below, the difference between #and ## is 801. What is the value of?
#
-##
____
812 | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | subtract(subtract(812, 801), const_2) | subtract(n1,n0)|subtract(#0,const_2) | 100 x - ( 10 x + x ) - - - - - - - - - - - 89 x = 801 x = 9 c | general |
math_qa__qyKvS1wWR7mFkgrm | A cat leaps 5 leaps for every 4 leaps of a dog, but 3 leaps of the dog are equal to 4 leaps of the cat. What is the ratio of the speed of the cat to that of the dog? Choose the correct choice from the following answers: A) 11 : 15 B) 15 : 11 C) 16 : 15 D) 15 : 16 E) 11 : 16 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 5</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">(15/4) / 4</gadget>
<output>15/16 = around 0.9375</output>
<result>D</result> | D | 0.9375 | A cat leaps 5 leaps for every 4 leaps of a dog, but 3 leaps of the dog are equal to 4 leaps of the cat. What is the ratio of the speed of the cat to that of the dog? | {
"A": "11 : 15",
"B": "15 : 11",
"C": "16 : 15",
"D": "15 : 16",
"E": "11 : 16"
} | divide(multiply(divide(3, 4), 5), 4) | divide(n2,n3)|multiply(n0,#0)|divide(#1,n1)| | "solution : given ; 3 dog = 4 cat ; or , dog / cat = 4 / 3 ; let cat ' s 1 leap = 3 meter and dogs 1 leap = 4 meter . then , ratio of speed of cat and dog = 3 * 5 / 4 * 4 = 15 : 16 . ' ' answer : option d" | other |
math_qa__NbDvlbmyZnOyvJNm | (√97+√486)/√54=? Options: A) 2 √ 2 B) 2 √ 3 C) 3 √ 2 D) 3 √ 3 E) 13 / 3 | <gadget id="calculator">97 ** (1/2)</gadget>
<output>sqrt(97) = around 9.848858</output>
<gadget id="calculator">486 ** (1/2)</gadget>
<output>9*sqrt(6) = around 22.045408</output>
<gadget id="calculator">(sqrt(97)) + (9*sqrt(6))</gadget>
<output>sqrt(97) + 9*sqrt(6) = around 31.894265</output>
<gadget id="calculator">54 ** (1/2)</gadget>
<output>3*sqrt(6) = around 7.348469</output>
<gadget id="calculator">(sqrt(97) + 9*sqrt(6)) / (3*sqrt(6))</gadget>
<output>sqrt(6)*(sqrt(97) + 9*sqrt(6))/18 = around 4.34026</output>
<result>E</result> | E | 4.333333 | (√97+√486)/√54=? | {
"A": "2 √ 2",
"B": "2 √ 3",
"C": "3 √ 2",
"D": "3 √ 3",
"E": "13 / 3"
} | divide(add(sqrt(97), sqrt(486)), sqrt(54)) | sqrt(n0)|sqrt(n1)|sqrt(n2)|add(#0,#1)|divide(#3,#2)| | "( √ 96 + √ 486 ) / √ 54 = ( 4 √ 6 + 9 √ 6 ) / 3 √ 6 = 13 √ 6 / 3 √ 6 = 13 / 3 hence , the correct answer is e ." | general |
math_qa__3adrTDvMu6n4vlYr | A secret can be told only 2 persons in 5 minutes .the same person tells to 2 more persons and so on . How long will take to tell it to 768 persons ? Choose one
A) 25 min B) 32 min C) 33 min D) 34 min E) 35 min | <gadget id="calculator">2 + 5</gadget>
<output>7</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<result>E</result> | E | 35 | A secret can be told only 2 persons in 5 minutes .the same person tells to 2 more persons and so on . How long will take to tell it to 768 persons ? | {
"A": "25 min",
"B": "32 min",
"C": "33 min",
"D": "34 min",
"E": "35 min"
} | multiply(add(2, 5), 5) | add(n0,n1)|multiply(n1,#0) | at start one person will tell to 2 persons , it will take 5 min , now that 1 + 2 = 3 persons will tell this to next 6 persons , then 1 + 2 + 6 = 9 persons will tell to next 18 persons , then 1 + 2 + 6 + 18 = 27 persons to 54 similarly 1 + 2 + 6 + 18 + 54 = 81 persons will tell this to 162 persons similarly 1 + 2 + 6 + 18 + 54 + 162 = 243 persons will tell this to 486 persons , upto this step total persons who have listened this secret = 2 + 6 + 18 + 54 + 162 + 486 = 728 , and total time taken upto this step = 5 * 6 = 30 min , now next 5 min will be sufficient to tell this message to next 40 persons so total time taken = 35 min answer : e | physics |
math_qa__mfIOYbWQlE0XwYMM | In what time will a train 110 m long cross an electric pole, it its speed be 144 km/hr?
Select:
A) 2.35 sec B) 2.85 sec C) 7.5 sec D) 2.75 sec E) 1.5 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">110 / 40</gadget>
<output>11/4 = around 2.75</output>
<result>D</result> | D | 2.75 | In what time will a train 110 m long cross an electric pole, it its speed be 144 km/hr? | {
"A": "2.35 sec",
"B": "2.85 sec",
"C": "7.5 sec",
"D": "2.75 sec",
"E": "1.5 sec"
} | divide(110, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 144 * 5 / 18 = 40 m / sec time taken = 110 / 40 = 2.75 sec . answer : d" | physics |
math_qa__JxsPVneATWNsqoBh | Find the smallest number which when divided by 13 and 15 leaves respective remainders of 2 and 4
Choose the correct choice from the following choices.
A) 187 B) 197 C) 184 D) 219 E) 227 | <gadget id="calculator">13 * 15</gadget>
<output>195</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">195 - 11</gadget>
<output>184</output>
<result>C</result> | C | 184 | Find the smallest number which when divided by 13 and 15 leaves respective remainders of 2 and 4 | {
"A": "187",
"B": "197",
"C": "184",
"D": "219",
"E": "227"
} | subtract(multiply(13, 15), add(const_10, const_1)) | add(const_1,const_10)|multiply(n0,n1)|subtract(#1,#0) | let ' n ' is the smallest number which divided by 13 and 15 leaves respective remainders of 2 and 4 . required number = ( lcm of 13 and 15 ) - ( common difference of divisors and remainders ) = ( 195 ) - ( 11 ) = 184 . answer : c | general |
math_qa__Kl0jwPhWJDEdEw6H | If Sharon's weekly salary increased by 16 percent, she would earn $406 per week. If instead, her weekly salary were to increase by 20 percent, how much would she earn per week? Answers: A) $ 420 B) $ 382 C) $ 385 D) $ 392 E) $ 399 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">1 + (4/25)</gadget>
<output>29/25 = around 1.16</output>
<gadget id="calculator">406 / (29/25)</gadget>
<output>350</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 350</gadget>
<output>70</output>
<gadget id="calculator">350 + 70</gadget>
<output>420</output>
<result>A</result> | A | 420 | If Sharon's weekly salary increased by 16 percent, she would earn $406 per week. If instead, her weekly salary were to increase by 20 percent, how much would she earn per week? | {
"A": "$ 420",
"B": "$ 382",
"C": "$ 385",
"D": "$ 392",
"E": "$ 399"
} | add(divide(406, add(const_1, divide(16, const_100))), multiply(divide(20, const_100), divide(406, add(const_1, divide(16, const_100))))) | divide(n0,const_100)|divide(n2,const_100)|add(#0,const_1)|divide(n1,#2)|multiply(#1,#3)|add(#3,#4)| | "( 406 / 116 ) 120 = 420 in this case long division does not take much time . ( 406 / 116 ) = 3.5 35 * 12 = 420 ( 350 + 70 ) answer a" | general |
math_qa__dPbOol8IVQOjG8VJ | A student has to obtain 60% of the total marks to pass. He got 160 marks and failed by 20 marks. The maximum marks are? Choose one: A) 210 B) 280 C) 300 D) 320 E) 340 | <gadget id="calculator">160 + 20</gadget>
<output>180</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">180 / (3/5)</gadget>
<output>300</output>
<result>C</result> | C | 300 | A student has to obtain 60% of the total marks to pass. He got 160 marks and failed by 20 marks. The maximum marks are? | {
"A": "210",
"B": "280",
"C": "300",
"D": "320",
"E": "340"
} | divide(add(160, 20), divide(60, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "let the maximum marks be x then , 60 % of x = 160 + 20 60 x / 100 = 180 60 x = 180 * 100 = 18000 x = 300 answer is c" | general |
math_qa__zm5RxocFEEHbaDTO | In a renowned city, the average birth rate is 7 people every two seconds and the death rate is 2 people every two seconds. Estimate the size of the population net increase that occurs in one day. Choose one
A) 215,000 B) 216,000 C) 217,000 D) 218,000 E) 219,000 | <gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 3_600</gadget>
<output>18_000</output>
<gadget id="calculator">18_000 * 12</gadget>
<output>216_000</output>
<result>B</result> | B | 216,000 | In a renowned city, the average birth rate is 7 people every two seconds and the death rate is 2 people every two seconds. Estimate the size of the population net increase that occurs in one day. | {
"A": "215,000",
"B": "216,000",
"C": "217,000",
"D": "218,000",
"E": "219,000"
} | multiply(multiply(subtract(7, const_2), const_3600), const_12) | subtract(n0,const_2)|multiply(#0,const_3600)|multiply(#1,const_12) | this question can be modified so that the birth rate is given every m seconds and the death rate is given every n seconds . for this particular question : increase in the population every 2 seconds = 7 - 2 = 5 people . total 2 second interval in a day = 24 * 60 * 60 / 2 = 43,200 population increase = 43,200 * 5 = 216,000 . hence b . | general |
math_qa__3oKqj9sUAcxO2RTk | two trains of equal are running on parallel lines in the same direction at 46 km / hr and 36 km / hr . the faster train passes the slower train in 36.00001 sec . the length of each train is ? Choose the correct choice from the following answers:
A) 50 B) 99 C) 77 D) 26 E) 23 | <gadget id="calculator">46 - 36</gadget>
<output>10</output>
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 / 3_600</gadget>
<output>25/9 = around 2.777778</output>
<gadget id="calculator">36.00001 * (25/9)</gadget>
<output>100.000028</output>
<gadget id="calculator">100.000028 / 2</gadget>
<output>50.000014</output>
<result>A</result> | A | 50 | two trains of equal are running on parallel lines in the same direction at 46 km / hr and 36 km / hr . the faster train passes the slower train in 36.00001 sec . the length of each train is ? | {
"A": "50",
"B": "99",
"C": "77",
"D": "26",
"E": "23"
} | divide(multiply(36.00001, divide(multiply(subtract(46, 36), const_1000), const_3600)), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "let the length of each train be x m . then , distance covered = 2 x m . relative speed = 46 - 36 = 10 km / hr . = 10 * 5 / 18 = 25 / 9 m / sec . 2 x / 36 = 25 / 9 = > x = 50 . answer : a" | general |
math_qa__YSLqxZHOHzfyTX7l | Two numbers N and 14 have LCM = 56 and GCF = 10. Find N. Choose the correct answer:
A) 24
B) 40
C) 44
D) 54
E) 64 | <gadget id="calculator">56 * 10</gadget>
<output>560</output>
<gadget id="calculator">560 / 14</gadget>
<output>40</output>
<result>B</result> | B | 40 | Two numbers N and 14 have LCM = 56 and GCF = 10. Find N. | {
"A": "24",
"B": "40",
"C": "44",
"D": "54",
"E": "64"
} | divide(multiply(56, 10), 14) | multiply(n1,n2)|divide(#0,n0)| | "the product of two integers is equal to the product of their lcm and gcf . hence . 14 × n = 56 × 10 n = 56 × 10 / 14 = 40 correct answer b" | physics |
math_qa__F00G49GL5x7MZy43 | If 3 people can do 3 times of a particular work in 3 days, then how many days would it take 5 people to do 5 times of that particular work? Choose one:
A) 1
B) 2
C) 3
D) 5
E) 8 | <gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">3 * 1</gadget>
<output>3</output>
<result>C</result> | C | 3 | If 3 people can do 3 times of a particular work in 3 days, then how many days would it take 5 people to do 5 times of that particular work? | {
"A": "1",
"B": "2",
"C": "3",
"D": "5",
"E": "8"
} | multiply(3, divide(5, 5)) | divide(n3,n3)|multiply(n0,#0) | 3 people can do the work one time in one day . 1 person can do 1 / 3 of the work in one day . 5 people can do 5 / 3 of the work in one day . 5 people can do 5 times the work in 3 days . the answer is c . | physics |
math_qa__7qPFSMfG3XzNVO8N | The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 8748 sq. m, the cost of fencing the field @ 25 paise per metre is Choose the correct choice
A) rs . 55.50 B) rs . 67.50 C) rs . 86.50 D) rs . 94.50 E) none of these | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">8_748 / 12</gadget>
<output>729</output>
<gadget id="calculator">729 ** (1/2)</gadget>
<output>27</output>
<gadget id="calculator">3 * 27</gadget>
<output>81</output>
<gadget id="calculator">4 * 27</gadget>
<output>108</output>
<gadget id="calculator">2 * (81 + 108)</gadget>
<output>378</output>
<gadget id="calculator">378 * 25</gadget>
<output>9_450</output>
<gadget id="calculator">9_450 / 100</gadget>
<output>189/2 = around 94.5</output>
<result>D</result> | D | 94.5 | The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 8748 sq. m, the cost of fencing the field @ 25 paise per metre is | {
"A": "rs . 55.50",
"B": "rs . 67.50",
"C": "rs . 86.50",
"D": "rs . 94.50",
"E": "none of these"
} | divide(multiply(rectangle_perimeter(multiply(3, sqrt(divide(8748, multiply(3, 4)))), multiply(4, sqrt(divide(8748, multiply(3, 4))))), 25), const_100) | multiply(n0,n1)|divide(n2,#0)|sqrt(#1)|multiply(n0,#2)|multiply(n1,#2)|rectangle_perimeter(#3,#4)|multiply(n3,#5)|divide(#6,const_100)| | "solution let length = ( 3 x ) metres and breadth = ( 4 x ) metres . then , 3 x × 4 x = 8748 ⇔ 12 x 2 = 8748 ⇔ x 2 = 729 ⇔ x = 27 . so , length = 81 m and breadth = 108 m . perimeter = [ 2 ( 81 + 108 ) ] m = 378 m . ∴ cost of fencing = rs . ( 0.25 × 378 ) = rs . 94.50 . answer d" | physics |
math_qa__HYJSlDUy1f3FdtSB | If 10 men do a work in 80 days, in how many days will 20 men do it?
Choices:
A) 18 days
B) 38 days
C) 40 days
D) 48 days
E) 50 days | <gadget id="calculator">10 * 80</gadget>
<output>800</output>
<gadget id="calculator">800 / 20</gadget>
<output>40</output>
<result>C</result> | C | 40 | If 10 men do a work in 80 days, in how many days will 20 men do it? | {
"A": "18 days",
"B": "38 days",
"C": "40 days",
"D": "48 days",
"E": "50 days"
} | divide(multiply(10, 80), 20) | multiply(n0,n1)|divide(#0,n2)| | "10 * 80 = 20 * x x = 40 days answer : c" | physics |
math_qa__6BnhZwWh7dFT6xe0 | A trader sells 60 meters of cloth for Rs. 8400 at the profit of Rs. 12 per metre of cloth. What is the cost price of one metre of cloth?
Options:
A) 128
B) 140
C) 123
D) 110
E) 150 | <gadget id="calculator">8_400 / 60</gadget>
<output>140</output>
<gadget id="calculator">140 - 12</gadget>
<output>128</output>
<result>A</result> | A | 128 | A trader sells 60 meters of cloth for Rs. 8400 at the profit of Rs. 12 per metre of cloth. What is the cost price of one metre of cloth? | {
"A": "128",
"B": "140",
"C": "123",
"D": "110",
"E": "150"
} | subtract(divide(8400, 60), 12) | divide(n1,n0)|subtract(#0,n2)| | "sp of 1 m of cloth = 8400 / 60 = rs . 140 cp of 1 m of cloth = sp of 1 m of cloth - profit on 1 m of cloth = rs . 140 - rs . 12 = rs . 128 . answer : a" | physics |
math_qa__6GLXvv8SQPf1201j | A car covers a distance of 624 km in 6 ½ hours. Find its speed?
Choose the correct choice from the following answers: A) 104 B) 190 C) 109 D) 278 E) 211 | <gadget id="calculator">624 / 6</gadget>
<output>104</output>
<result>C</result> | C | 109 | A car covers a distance of 624 km in 6 ½ hours. Find its speed? | {
"A": "104",
"B": "190",
"C": "109",
"D": "278",
"E": "211"
} | divide(624, 6) | divide(n0,n1) | explanation : 624 / 6 = 104 kmph answer : c | physics |
math_qa__2SZ6Syum6WMJeH6N | When average age of 23 members are 0, how many members greater than 0? Choices.
A) 17 B) 22 C) 21 D) 24 E) 25 | <gadget id="calculator">23 - 1</gadget>
<output>22</output>
<result>B</result> | B | 22 | When average age of 23 members are 0, how many members greater than 0? | {
"A": "17",
"B": "22",
"C": "21",
"D": "24",
"E": "25"
} | subtract(23, const_1) | subtract(n0,const_1)| | "average of 23 numbers = 0 . sum of 23 numbers ( 0 x 23 ) = 0 . it is quite possible that 22 of these numbers may be positive and if their sum is a then 23 rd number is ( - a ) answer is 22 ( b )" | general |
math_qa__ODRditjMlMZw0tar | During the first two weeks of January, the total rainfall in Springdale was 35 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall during the second week of January?
Answers:
A) 5 inches B) 6 inches C) 9 inches D) 10 inches E) 21 inches | <gadget id="calculator">1 + 1.5</gadget>
<output>2.5</output>
<gadget id="calculator">1.5 / 2.5</gadget>
<output>0.6</output>
<gadget id="calculator">35 * 0.6</gadget>
<output>21</output>
<result>E</result> | E | 21 | During the first two weeks of January, the total rainfall in Springdale was 35 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall during the second week of January? | {
"A": "5 inches",
"B": "6 inches",
"C": "9 inches",
"D": "10 inches",
"E": "21 inches"
} | multiply(35, divide(1.5, add(const_1, 1.5))) | add(n1,const_1)|divide(n1,#0)|multiply(n0,#1) | total rainfall in 2 weeks = 35 inches . assume the rainfall in second week = 1 . x rainfall in first week = x total rainfall = 2.5 x = 35 inches x = 14 and 1.5 x = 21 rainfall during second week = 21 inches option e | general |
math_qa__lAqQ7PHFnwLOs0tq | if you roll one fair 6 - sided die , what is the probability that the number is even or less than 3 ? Choose the correct choice: A) 2 / 3 B) 1 / 2 C) 3 / 4 D) 5 / 6 E) 1 / 3 | <gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/2) + (1/6)</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | if you roll one fair 6 - sided die , what is the probability that the number is even or less than 3 ? | {
"A": "2 / 3",
"B": "1 / 2",
"C": "3 / 4",
"D": "5 / 6",
"E": "1 / 3"
} | add(divide(const_3, 6), divide(const_1, 6)) | divide(const_3,n0)|divide(const_1,n0)|add(#0,#1) | the numbers which satisfy the conditions are 1 , 2 , 4 , and 6 . the probability is 4 / 6 = 2 / 3 the answer is a . | probability |
math_qa__ya5CgIJPEdZjwMEC | A fifth of Arun’s marks in mathematics exceed a third of his marks in English by 20.If he got 260 marks in two subjects together how many marks did he got in English? Choose the correct choice from the following answers
A) 12080 B) 18060 C) 20060 D) 20040 E) none of them | <gadget id="calculator">260 * 20</gadget>
<output>5_200</output>
<gadget id="calculator">5_200 * 2</gadget>
<output>10_400</output>
<gadget id="calculator">10_400 * 2</gadget>
<output>20_800</output>
<result>C</result> | C | 20,060 | A fifth of Arun’s marks in mathematics exceed a third of his marks in English by 20.If he got 260 marks in two subjects together how many marks did he got in English? | {
"A": "12080",
"B": "18060",
"C": "20060",
"D": "20040",
"E": "none of them"
} | multiply(multiply(multiply(260, 20), const_2), const_2) | multiply(n0,n1)|multiply(#0,const_2)|multiply(#1,const_2) | let arun â € ™ s marks in mathematics and english be x and y then ( 1 / 5 ) x - ( 1 / 3 ) y = 20 3 x - 5 y = 300 â € ¦ â € ¦ > ( 1 ) x + y = 260 â € ¦ â € ¦ . > ( 2 ) solving ( 1 ) and ( 2 ) x = 200 and y = 60 answer is c . | general |
math_qa__Zn5GYBHYxfOCIlkd | In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony?
Choose the correct option: A) 1 : 7 B) 1 : 1 C) 1 : 2 D) 1 : 9 E) 1 : 3 | <gadget id="calculator">8 + 27</gadget>
<output>35</output>
<gadget id="calculator">70 / 35</gadget>
<output>2</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">70 / 7</gadget>
<output>10</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">16 - 6</gadget>
<output>10</output>
<gadget id="calculator">2 * 27</gadget>
<output>54</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">54 - 24</gadget>
<output>30</output>
<gadget id="calculator">10 / 30</gadget>
<output>1/3 = around 0.333333</output>
<result>E</result> | E | 0.333333 | In a colony of 70 residents, the ratio of the number of men and women is 4:3. Among the women, the ratio of the educated to the uneducated is 1:4. If the ratio of the number of education to uneducated persons is 8:27, then find the ratio of the number of educated and uneducated men in the colony? | {
"A": "1 : 7",
"B": "1 : 1",
"C": "1 : 2",
"D": "1 : 9",
"E": "1 : 3"
} | divide(subtract(multiply(divide(70, add(8, 27)), 8), divide(multiply(divide(70, add(4, 3)), 3), add(1, 4))), subtract(multiply(divide(70, add(8, 27)), 27), multiply(divide(multiply(divide(70, add(4, 3)), 3), add(1, 4)), 4))) | add(n5,n6)|add(n1,n2)|add(n1,n3)|divide(n0,#0)|divide(n0,#1)|multiply(n5,#3)|multiply(n2,#4)|multiply(n6,#3)|divide(#6,#2)|multiply(n1,#8)|subtract(#5,#8)|subtract(#7,#9)|divide(#10,#11)| | "number of men in the colony = 4 / 7 ( 70 ) = 40 number of women in the colony = 3 / 7 ( 70 ) = 30 number of educated women in the colony = 1 / 5 ( 30 ) = 6 number of uneducated women in the colony = 4 / 5 ( 30 ) = 24 number of educated persons in the colony = 8 / 35 ( 70 ) = 16 as 6 females are educated , remaining 10 educated persons must be men . number of uneducated men in the colony = 40 - 10 = 30 number of educated men and uneducated men are in the ratio 10 : 30 = > 1 : 3 answer : e" | other |
math_qa__nWa8dSPj41rpOXGs | 40 persons like apple. 7 like orange and mango dislike apple. 10 like mango and apple and dislike orange. 4 like all. How many people like apple? Choose the correct choice from the following:
A) 47 B) 46 C) 54 D) 58 E) 62 | <gadget id="calculator">40 - 3</gadget>
<output>37</output>
<gadget id="calculator">37 + 7</gadget>
<output>44</output>
<gadget id="calculator">10 - 7</gadget>
<output>3</output>
<gadget id="calculator">44 + 3</gadget>
<output>47</output>
<result>A</result> | A | 47 | 40 persons like apple. 7 like orange and mango dislike apple. 10 like mango and apple and dislike orange. 4 like all. How many people like apple? | {
"A": "47",
"B": "46",
"C": "54",
"D": "58",
"E": "62"
} | add(add(subtract(40, const_3), 7), subtract(10, 7)) | subtract(n0,const_3)|subtract(n2,n1)|add(n1,#0)|add(#2,#1)| | "orange + mango - apple = 7 mango + apple - orange = 10 apple = 40 orange + mango + apple = 4 40 + 10 + 4 - 7 = 47 like apple answer : a" | general |
math_qa__OYpIpztQU2tvxfDB | A girl goes to her school from her house at a speed of 6km/hr and returns at a speed of 4 km/hr. If she takes 10 hours in going and coming back, the distance between her school and house is Choose the correct choice from the following answers: A) 12 kms B) 16 kms C) 20 kms D) 24 kms E) none of above | <gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">10 * 24</gadget>
<output>240</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">240 / 10</gadget>
<output>24</output>
<result>D</result> | D | 24 | A girl goes to her school from her house at a speed of 6km/hr and returns at a speed of 4 km/hr. If she takes 10 hours in going and coming back, the distance between her school and house is | {
"A": "12 kms",
"B": "16 kms",
"C": "20 kms",
"D": "24 kms",
"E": "none of above"
} | divide(multiply(10, multiply(6, 4)), add(6, 4)) | add(n0,n1)|multiply(n0,n1)|multiply(n2,#1)|divide(#2,#0) | let distance be d 10 = d / 4 + d / 6 answer : d | physics |
math_qa__eOdWG4XOoxQVrhZE | If x = -6 and y = -3, what is the value of 4(x-y)^2 - xy ?
Pick one: A) 20 B) 18 C) 17 D) 22 E) 23 | <gadget id="calculator">-6</gadget>
<output>-6</output>
<gadget id="calculator">-3</gadget>
<output>-3</output>
<gadget id="calculator">(-6) - (-3)</gadget>
<output>-3</output>
<gadget id="calculator">(-3) ** 2</gadget>
<output>9</output>
<gadget id="calculator">9 * 4</gadget>
<output>36</output>
<gadget id="calculator">(-6) * (-3)</gadget>
<output>18</output>
<gadget id="calculator">36 - 18</gadget>
<output>18</output>
<result>B</result> | B | 18 | If x = -6 and y = -3, what is the value of 4(x-y)^2 - xy ? | {
"A": "20",
"B": "18",
"C": "17",
"D": "22",
"E": "23"
} | subtract(multiply(power(subtract(negate(6), negate(3)), 2), 4), multiply(negate(6), negate(3))) | negate(n0)|negate(n1)|multiply(#0,#1)|subtract(#0,#1)|power(#3,n3)|multiply(n2,#4)|subtract(#5,#2) | x = - 6 and y = - 3 x - y = - 6 - ( - 3 ) = - 6 + 3 = - 3 x * y = - 6 * - 3 = 18 now we apply it in the equation 4 ( x - y ) ^ 2 - xy = 4 ( - 3 ) ^ 2 - 18 = = > 4 * 9 - 18 = 36 - 18 = 18 answer : b | general |
math_qa__lElvDQHVjAOEuFgl | If the sum of the 4th term and the 12th term of an arithmetic progression is 12, what is the sum of the first 15 terms of the progression? Choose the correct choice from the following answers
A) 90 B) 80 C) 70 D) 60 E) 50 | <gadget id="calculator">15 / 2</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(15/2) * 12</gadget>
<output>90</output>
<result>A</result> | A | 90 | If the sum of the 4th term and the 12th term of an arithmetic progression is 12, what is the sum of the first 15 terms of the progression? | {
"A": "90",
"B": "80",
"C": "70",
"D": "60",
"E": "50"
} | multiply(divide(15, const_2), 12) | divide(n3,const_2)|multiply(n2,#0)| | "4 th term + 12 th term = 12 i . e . , ( a + 3 d ) + ( a + 11 d ) = 12 now , sum of first 15 terms = ( 15 / 2 ) * [ 2 a + ( 15 - 1 ) d ] = ( 15 / 2 ) * [ 2 a + 14 d ] = ( 15 / 2 ) * 12 - - - - - - - - - - - - - - - from ( 1 ) = 90 answer : a" | general |
math_qa__EChIUTIhrnT5rlUo | The edges of a cuboid are 2 cm, 5 cm and 8 cm. Find the volume of the cuboid? Select the correct option: A) 90 B) 80 C) 40 D) 120 E) 70 | <gadget id="calculator">2 * 5 * 8</gadget>
<output>80</output>
<result>B</result> | B | 80 | The edges of a cuboid are 2 cm, 5 cm and 8 cm. Find the volume of the cuboid? | {
"A": "90",
"B": "80",
"C": "40",
"D": "120",
"E": "70"
} | volume_rectangular_prism(2, 5, 8) | volume_rectangular_prism(n0,n1,n2)| | "2 * 5 * 8 = 80 answer : b" | physics |
math_qa__IyKPtDOC1BH78amM | A can do a work in 21 days and B alone can do it 28 days, they begin the work together, but A left after some days. B completed the remaining work in 21 days. After how many days did A leave ? Pick one.
A) 10 B) 8 C) 3 D) 15 E) 16 | <gadget id="calculator">1 / 28</gadget>
<output>1/28 = around 0.035714</output>
<gadget id="calculator">(1/28) * 21</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 21</gadget>
<output>1/21 = around 0.047619</output>
<gadget id="calculator">(1/21) + (1/28)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/4) / (1/12)</gadget>
<output>3</output>
<result>C</result> | C | 3 | A can do a work in 21 days and B alone can do it 28 days, they begin the work together, but A left after some days. B completed the remaining work in 21 days. After how many days did A leave ? | {
"A": "10",
"B": "8",
"C": "3",
"D": "15",
"E": "16"
} | divide(subtract(const_1, multiply(speed(const_1, 28), 21)), add(speed(const_1, 21), speed(const_1, 28))) | speed(const_1,n1)|speed(const_1,n0)|add(#1,#0)|multiply(n0,#0)|subtract(const_1,#3)|divide(#4,#2) | explanation : ( a + b ) 1 day work = { 1 / 21 + 1 / 28 } = 1 / 12 = 12 days is required for a & b b ’ s 1 day work = 1 / 28 b ’ s 21 days work = 21 / 28 1 - 21 / 28 = 7 / 28 - 1 / 4 1 / 4 * 12 = 3 days answer : option c | physics |
math_qa__hocnc3pAEpFD7NnO | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 9 sec. What is the length of the platform? Choose one:
A) 389 m
B) 350 m
C) 289 m
D) 799 m
E) 1000 m | <gadget id="calculator">300 / 9</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">(100/3) * 39</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 - 300</gadget>
<output>1_000</output>
<result>E</result> | E | 1,000 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 9 sec. What is the length of the platform? | {
"A": "389 m",
"B": "350 m",
"C": "289 m",
"D": "799 m",
"E": "1000 m"
} | subtract(multiply(speed(300, 9), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0) | speed = 300 / 9 = 100 / 3 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 100 / 3 = > x = 1000 m . answer : e | physics |
math_qa__nV6oB0JUIOsE3RSP | A and B’s salaries together amount to Rs. 4,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is A’s salary? Choose the correct choice from the following choices
A) 2777 B) 1500 C) 3000 D) 2776 E) 2881 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<gadget id="calculator">40 * 100</gadget>
<output>4_000</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">1 - (17/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">4_000 * (3/20)</gadget>
<output>600</output>
<gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">1 - (19/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + (3/20)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">600 / (1/5)</gadget>
<output>3_000</output>
<result>C</result> | C | 3,000 | A and B’s salaries together amount to Rs. 4,000. A spends 95% of his salary and B spends 85% of his. If now their savings are the same, what is A’s salary? | {
"A": "2777",
"B": "1500",
"C": "3000",
"D": "2776",
"E": "2881"
} | divide(multiply(multiply(multiply(const_2, multiply(const_4, add(const_2, const_3))), const_100), subtract(const_1, divide(85, const_100))), add(subtract(const_1, divide(95, const_100)), subtract(const_1, divide(85, const_100)))) | add(const_2,const_3)|divide(n2,const_100)|divide(n1,const_100)|multiply(#0,const_4)|subtract(const_1,#1)|subtract(const_1,#2)|add(#5,#4)|multiply(#3,const_2)|multiply(#7,const_100)|multiply(#8,#4)|divide(#9,#6) | ( 5 / 100 ) a = ( 15 / 100 ) b a = 3 b a + b = 4000 4 b = 4000 = > b = 1000 a = 3000 answer c | gain |
math_qa__gsPSXcA7DuCWVbtG | The telephone company wants to add an area code composed of 2 letters to every phone number. In order to do so, the company chose a special sign language containing 324 different signs. If the company used 322 of the signs fully and two remained unused, how many additional area codes can be created if the company uses all 324 signs?
Options:
A) 246
B) 248
C) 1292
D) 15,128
E) 30,256 | <gadget id="calculator">324 - 322</gadget>
<output>2</output>
<gadget id="calculator">322 * 2</gadget>
<output>644</output>
<gadget id="calculator">644 * 2</gadget>
<output>1_288</output>
<result>C</result> | C | 1,292 | The telephone company wants to add an area code composed of 2 letters to every phone number. In order to do so, the company chose a special sign language containing 324 different signs. If the company used 322 of the signs fully and two remained unused, how many additional area codes can be created if the company uses all 324 signs? | {
"A": "246",
"B": "248",
"C": "1292",
"D": "15,128",
"E": "30,256"
} | multiply(multiply(322, subtract(324, 322)), subtract(324, 322)) | subtract(n1,n2)|multiply(n2,#0)|multiply(#1,#0)| | "# of 2 - letter codes possible from 324 different signs = 324 * 324 . # of 2 - letter codes possible from 322 different signs = 322 * 322 . the difference = 324 ^ 2 - 322 ^ 2 = ( 324 - 322 ) ( 324 + 322 ) = 1292 . answer : c ." | general |
math_qa__K9Ohk1RkAxGYN4WN | The toll T, in dollars, for a truck using a certain bridge is given by the formula T =3.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 4 wheels on each of its other axles? Choose the correct answer:
A) $ 2.50
B) $ 3.00
C) $ 3.50
D) $ 4.00
E) $ 5.00 | <gadget id="calculator">18 - 2</gadget>
<output>16</output>
<gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">0.5 * 3</gadget>
<output>1.5</output>
<gadget id="calculator">3.5 + 1.5</gadget>
<output>5</output>
<result>E</result> | E | 5 | The toll T, in dollars, for a truck using a certain bridge is given by the formula T =3.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 4 wheels on each of its other axles? | {
"A": "$ 2.50",
"B": "$ 3.00",
"C": "$ 3.50",
"D": "$ 4.00",
"E": "$ 5.00"
} | add(3.5, multiply(0.5, subtract(add(divide(subtract(18, 2), 4), const_1), 2))) | subtract(n3,n2)|divide(#0,n5)|add(#1,const_1)|subtract(#2,n2)|multiply(n1,#3)|add(n0,#4) | number of wheels in truck = 18 number of wheels on its front axle = 2 number of wheels remaining = 16 number of axles remaining axles = 16 / 4 = 4 total number of axles = 5 t = 3.50 + 0.50 ( x − 2 ) = 3.50 + . 5 * 3 = 3.5 + 1.5 = 5 $ answer e | general |
math_qa__JP4zMNvsxNFCVpo6 | A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 4t seconds, then what is the length of the platform? Choose the correct choice from the following answers:
A) 0.5 l
B) l
C) 1.5 l
D) 2 l
E) 3 l | <gadget id="calculator">4 - 1</gadget>
<output>3</output>
<result>E</result> | E | 3 | A train of length L is traveling at a constant velocity and passes a pole in t seconds. If the same train travelling at the same velocity passes a platform in 4t seconds, then what is the length of the platform? | {
"A": "0.5 l",
"B": "l",
"C": "1.5 l",
"D": "2 l",
"E": "3 l"
} | subtract(4, const_1) | subtract(n0,const_1)| | "the train passes a pole in t seconds , so velocity v = l / t ( l + p ) / v = 4 t ( l + p ) / ( l / t ) = 4 t p = 3 l the answer is e ." | physics |
math_qa__BudAZpc4EeYExTCt | In feb Mrs Bil's earnings were 70 percent of the Bil family's total income. In June Mrs Bil earned 10 percent more than in May. If the rest of the family's income was the same both months, then, in June, Mrs Bil's earnings were approximately what percent of the Bil family's total income ? Select.
A) 72 B) 34 C) 78 D) 37 E) 27 | <gadget id="calculator">70 / 10</gadget>
<output>7</output>
<gadget id="calculator">70 + 7</gadget>
<output>77</output>
<gadget id="calculator">100 + 7</gadget>
<output>107</output>
<gadget id="calculator">77 / 107</gadget>
<output>77/107 = around 0.719626</output>
<gadget id="calculator">(77/107) * 100</gadget>
<output>7_700/107 = around 71.962617</output>
<result>A</result> | A | 72 | In feb Mrs Bil's earnings were 70 percent of the Bil family's total income. In June Mrs Bil earned 10 percent more than in May. If the rest of the family's income was the same both months, then, in June, Mrs Bil's earnings were approximately what percent of the Bil family's total income ? | {
"A": "72",
"B": "34",
"C": "78",
"D": "37",
"E": "27"
} | multiply(divide(add(70, divide(70, 10)), add(const_100, divide(70, 10))), const_100) | divide(n0,n1)|add(n0,#0)|add(#0,const_100)|divide(#1,#2)|multiply(#3,const_100) | lets say the family income is 100 in may , bil earned 70 family income is 30 in june , bil earned 10 % more than may , so it is ( 70 + 10 * 70 / 100 = 77 ) family income is same 30 in june bil ' s income percent is 77 * 100 / 107 ~ 72 ans is a | general |
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