prob_desc_time_limit stringclasses 21
values | prob_desc_sample_outputs stringlengths 5 329 | src_uid stringlengths 32 32 | prob_desc_notes stringlengths 31 2.84k ⌀ | prob_desc_description stringlengths 121 3.8k | prob_desc_output_spec stringlengths 17 1.16k ⌀ | prob_desc_input_spec stringlengths 38 2.42k ⌀ | prob_desc_output_to stringclasses 3
values | prob_desc_input_from stringclasses 3
values | lang stringclasses 5
values | lang_cluster stringclasses 1
value | difficulty int64 -1 3.5k ⌀ | file_name stringclasses 111
values | code_uid stringlengths 32 32 | prob_desc_memory_limit stringclasses 11
values | prob_desc_sample_inputs stringlengths 5 802 | exec_outcome stringclasses 1
value | source_code stringlengths 29 58.4k | prob_desc_created_at stringlengths 10 10 | tags listlengths 1 5 | hidden_unit_tests stringclasses 1
value | labels listlengths 8 8 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
2 seconds | ["1\n0\n2\n3\n5\n141\n53384\n160909\n36"] | efdb966e414050c5e51e8beb7bb06b20 | NoteIn the first test case, the only special pair is $$$(3, 2)$$$.In the second test case, there are no special pairs.In the third test case, there are two special pairs: $$$(3, 2)$$$ and $$$(4, 3)$$$. | A pair of positive integers $$$(a,b)$$$ is called special if $$$\lfloor \frac{a}{b} \rfloor = a \bmod b$$$. Here, $$$\lfloor \frac{a}{b} \rfloor$$$ is the result of the integer division between $$$a$$$ and $$$b$$$, while $$$a \bmod b$$$ is its remainder.You are given two integers $$$x$$$ and $$$y$$$. Find the number of... | For each test case print the answer on a single line. | The first line contains a single integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases. The only line of the description of each test case contains two integers $$$x$$$, $$$y$$$ ($$$1 \le x,y \le 10^9$$$). | standard output | standard input | Python 3 | Python | 1,700 | train_092.jsonl | a4e271d3387f754cea40c0432268f71d | 256 megabytes | ["9\n3 4\n2 100\n4 3\n50 3\n12 4\n69 420\n12345 6789\n123456 789\n12345678 9"] | PASSED | for test_case in range(int(input())):
x,y = map(int,input().split())
res = 0
k = 1
while k*(k+1) < x and k < y:
res += min(y,x//k-1)-k
k += 1
print(res)
| 1613141400 | [
"number theory",
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1 second | ["3\n1\n7"] | ce9a0649ccfc956559254f324dfa02a7 | NoteFor the first integer the optimal choice is $$$b = 1$$$, then $$$a \oplus b = 3$$$, $$$a \> \& \> b = 0$$$, and the greatest common divisor of $$$3$$$ and $$$0$$$ is $$$3$$$.For the second integer one optimal choice is $$$b = 2$$$, then $$$a \oplus b = 1$$$, $$$a \> \& \> b = 2$$$, and the great... | Can the greatest common divisor and bitwise operations have anything in common? It is time to answer this question.Suppose you are given a positive integer $$$a$$$. You want to choose some integer $$$b$$$ from $$$1$$$ to $$$a - 1$$$ inclusive in such a way that the greatest common divisor (GCD) of integers $$$a \oplus ... | For each integer, print the answer in the same order as the integers are given in input. | The first line contains an integer $$$q$$$ ($$$1 \le q \le 10^3$$$) — the number of integers you need to compute the answer for. After that $$$q$$$ integers are given, one per line: $$$a_1, a_2, \ldots, a_q$$$ ($$$2 \le a_i \le 2^{25} - 1$$$) — the integers you need to compute the answer for. | standard output | standard input | Python 3 | Python | 1,500 | train_005.jsonl | c601e61ffe1146b3139782c911890e37 | 256 megabytes | ["3\n2\n3\n5"] | PASSED | # -*- coding: utf-8 -*-
"""
Created on Sun Oct 4 06:35:25 2020
@author: Dark Soul
"""
import math
q=int(input(''))
for _ in range(q):
n=int(input(''))
ans=-1
if n&(n+1)==0:
for i in range(2,int(math.sqrt(n))+1):
if n%i==0:
ans=n//i
break
if ans==... | 1549546500 | [
"number theory",
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1 second | ["9\n6\n1", "225\n2001\n6014\n6939"] | 6def7ffa0989d5c5bcab3ac456b231fb | NoteIn the example test, $$$n=2$$$. Thus, there are $$$3$$$ pigs at minute $$$1$$$, and $$$6$$$ pigs at minute $$$2$$$. There are three queries: $$$x=1$$$, $$$x=5$$$, and $$$x=6$$$.If the wolf wants to eat $$$1$$$ pig, he can do so in $$$3+6=9$$$ possible attack plans, depending on whether he arrives at minute $$$1$$$ ... | Three little pigs from all over the world are meeting for a convention! Every minute, a triple of 3 new pigs arrives on the convention floor. After the $$$n$$$-th minute, the convention ends.The big bad wolf has learned about this convention, and he has an attack plan. At some minute in the convention, he will arrive a... | You should print $$$q$$$ lines, with line $$$i$$$ representing the number of attack plans if the wolf wants to eat $$$x_i$$$ pigs. Since each query answer can be large, output each answer modulo $$$10^9+7$$$. | The first line of input contains two integers $$$n$$$ and $$$q$$$ ($$$1 \le n \le 10^6$$$, $$$1 \le q \le 2\cdot 10^5$$$), the number of minutes the convention lasts and the number of queries the wolf asks. Each of the next $$$q$$$ lines contains a single integer $$$x_i$$$ ($$$1 \le x_i \le 3n$$$), the number of pigs t... | standard output | standard input | PyPy 3 | Python | 2,500 | train_083.jsonl | 6ebee54968ad72be04e37731346968e1 | 512 megabytes | ["2 3\n1\n5\n6", "5 4\n2\n4\n6\n8"] | PASSED | import sys
import __pypy__
int_add = __pypy__.intop.int_add
int_sub = __pypy__.intop.int_sub
int_mul = __pypy__.intop.int_mul
def make_mod_mul(mod=10**9 + 7):
fmod_inv = 1.0 / mod
def mod_mul(a, b, c=0):
res = int_sub(int_add(int_mul(a, b), c), int_mul(mod, int(fmod_inv * a * b + fmod_inv * c)))
... | 1627828500 | [
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2 seconds | ["4 2 0", "16 9", "9999800001"] | faf1abdeb6f0cf34972d5cb981116186 | NoteOn the picture below show the state of the board after put each of the three rooks. The cells which painted with grey color is not under the attack. | Vasya has the square chessboard of size n × n and m rooks. Initially the chessboard is empty. Vasya will consequently put the rooks on the board one after another.The cell of the field is under rook's attack, if there is at least one rook located in the same row or in the same column with this cell. If there is a rook ... | Print m integer, the i-th of them should be equal to the number of cells that are not under attack after first i rooks are put. | The first line of the input contains two integers n and m (1 ≤ n ≤ 100 000, 1 ≤ m ≤ min(100 000, n2)) — the size of the board and the number of rooks. Each of the next m lines contains integers xi and yi (1 ≤ xi, yi ≤ n) — the number of the row and the number of the column where Vasya will put the i-th rook. Vasya put... | standard output | standard input | Python 3 | Python | 1,200 | train_012.jsonl | 65687845e1fa13e5cf9e419a39b69bdf | 256 megabytes | ["3 3\n1 1\n3 1\n2 2", "5 2\n1 5\n5 1", "100000 1\n300 400"] | PASSED | n, m = map(int, input().split())
ans = [n ** 2]
rows, cols = set(), set()
for i in range(m):
x, y = map(int, input().split())
res = ans[-1]
if x not in rows:
res -= (n - len(cols))
rows.add(x)
if y not in cols:
res -= (n - len(rows))
cols.add(y)
ans.append(res)
prin... | 1469205300 | [
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2 seconds | ["6", "0", "2"] | f44041707694eece7de0cc7c087f57d9 | NoteIn the first example, you can set $$$a_{1, 1} := 7, a_{1, 2} := 8$$$ and $$$a_{1, 3} := 9$$$ then shift the first, the second and the third columns cyclically, so the answer is $$$6$$$. It can be shown that you cannot achieve a better answer.In the second example, the matrix is already good so the answer is $$$0$$$... | You are given a rectangular matrix of size $$$n \times m$$$ consisting of integers from $$$1$$$ to $$$2 \cdot 10^5$$$.In one move, you can: choose any element of the matrix and change its value to any integer between $$$1$$$ and $$$n \cdot m$$$, inclusive; take any column and shift it one cell up cyclically (see the ... | Print one integer — the minimum number of moves required to obtain the matrix, where $$$a_{1, 1} = 1, a_{1, 2} = 2, \dots, a_{1, m} = m, a_{2, 1} = m + 1, a_{2, 2} = m + 2, \dots, a_{n, m} = n \cdot m$$$ ($$$a_{i, j} = (i - 1)m + j$$$). | The first line of the input contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n, m \le 2 \cdot 10^5, n \cdot m \le 2 \cdot 10^5$$$) — the size of the matrix. The next $$$n$$$ lines contain $$$m$$$ integers each. The number at the line $$$i$$$ and position $$$j$$$ is $$$a_{i, j}$$$ ($$$1 \le a_{i, j} \le 2 \cdot 10^5$... | standard output | standard input | PyPy 3 | Python | 1,900 | train_004.jsonl | fd525d26e93ea7482fa829b9eb3250df | 256 megabytes | ["3 3\n3 2 1\n1 2 3\n4 5 6", "4 3\n1 2 3\n4 5 6\n7 8 9\n10 11 12", "3 4\n1 6 3 4\n5 10 7 8\n9 2 11 12"] | PASSED | import sys
input = sys.stdin.readline
from collections import *
n, m = map(int, input().split())
a = [list(map(int, input().split())) for _ in range(n)]
ans = 0
for i in range(m):
l = [i+1]
for _ in range(n-1):
l.append(l[-1]+m)
s = set(l)
idx = defaultdict(int)
for j in ran... | 1579703700 | [
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4 seconds | ["YES\n3 1\n4 1\n1 2\n5 2\n2 6", "NO", "YES\n2 9\n2 10\n10 3\n3 1\n6 10\n8 2\n4 3\n5 6\n6 7", "YES\n2 5\n7 2\n3 7\n3 1\n1 6\n8 7\n4 3"] | a4849505bca48b408a5e8fb5aebf5cb6 | null | You are given three integers $$$n$$$, $$$d$$$ and $$$k$$$.Your task is to construct an undirected tree on $$$n$$$ vertices with diameter $$$d$$$ and degree of each vertex at most $$$k$$$, or say that it is impossible.An undirected tree is a connected undirected graph with $$$n - 1$$$ edges.Diameter of a tree is the max... | If there is no tree satisfying the conditions above, print only one word "NO" (without quotes). Otherwise in the first line print "YES" (without quotes), and then print $$$n - 1$$$ lines describing edges of a tree satisfying the conditions above. Vertices of the tree must be numbered from $$$1$$$ to $$$n$$$. You can pr... | The first line of the input contains three integers $$$n$$$, $$$d$$$ and $$$k$$$ ($$$1 \le n, d, k \le 4 \cdot 10^5$$$). | standard output | standard input | Python 2 | Python | 2,100 | train_002.jsonl | 67d367d8f6c84392f200638e9f4aab1b | 256 megabytes | ["6 3 3", "6 2 3", "10 4 3", "8 5 3"] | PASSED | n,d,k=map(int,raw_input().strip().split())
ans=[]
if (d>n-1):
print ("NO")
exit(0)
if (k<2 and n>2):
print ("NO")
exit(0)
l1=[0 for i in range(d+2)]
count=d
cnt=d+2
def insert(par,v,r,e):
global count
global cnt
if count==n-1:
print ("YES")
for o in ans:
print o[0],o[1]
exit(0)
else:
ans.append([par,... | 1530628500 | [
"graphs"
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0
] | |
1 second | ["NO\nYES\nNO\nYES\nYES"] | 26354d2628f26eb2eff9432bd46400d5 | NoteIn the first test case, $$$n = 1$$$, $$$k_1 = 0$$$ and $$$k_2 = 1$$$. It means that $$$2 \times 1$$$ board has black cell $$$(1, 1)$$$ and white cell $$$(2, 1)$$$. So, you can't place any white domino, since there is only one white cell.In the second test case, the board of the same size $$$2 \times 1$$$, but both ... | You have a board represented as a grid with $$$2 \times n$$$ cells.The first $$$k_1$$$ cells on the first row and first $$$k_2$$$ cells on the second row are colored in white. All other cells are colored in black.You have $$$w$$$ white dominoes ($$$2 \times 1$$$ tiles, both cells are colored in white) and $$$b$$$ black... | For each test case, print YES if it's possible to place all $$$w + b$$$ dominoes on the board and NO, otherwise. You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES are all recognized as positive answer). | The first line contains a single integer $$$t$$$ ($$$1 \le t \le 3000$$$) — the number of test cases. The first line of each test case contains three integers $$$n$$$, $$$k_1$$$ and $$$k_2$$$ ($$$1 \le n \le 1000$$$; $$$0 \le k_1, k_2 \le n$$$). The second line of each test case contains two integers $$$w$$$ and $$$b$$... | standard output | standard input | Python 3 | Python | 800 | train_104.jsonl | 66083bccd6f1853bc132b8d95906a948 | 256 megabytes | ["5\n1 0 1\n1 0\n1 1 1\n0 0\n3 0 0\n1 3\n4 3 1\n2 2\n5 4 3\n3 1"] | PASSED | t=int(input())
for y in range(t):
n,k1,k2=map(int,input().split())
w,b=map(int,input().split())
kw=k1+k2
to=kw//2
tob=(n*2-kw)//2
# print(to)
if w<=to:
# print("this w")
w=0
avil=to-w
else:
# print("w n")
print("NO")
continu... | 1616079000 | [
"math"
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0,
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1,
0,
0,
0,
0
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2 seconds | ["2", "2"] | 3cafbcf1a397def07d6a2d1dd5526281 | NoteIn the first sample you can delete any two squares that do not share a side. After that the set of painted squares is not connected anymore.The note to the second sample is shown on the figure below. To the left there is a picture of the initial set of squares. To the right there is a set with deleted squares. The ... | You've gotten an n × m sheet of squared paper. Some of its squares are painted. Let's mark the set of all painted squares as A. Set A is connected. Your task is to find the minimum number of squares that we can delete from set A to make it not connected.A set of painted squares is called connected, if for every two squ... | On the first line print the minimum number of squares that need to be deleted to make set A not connected. If it is impossible, print -1. | The first input line contains two space-separated integers n and m (1 ≤ n, m ≤ 50) — the sizes of the sheet of paper. Each of the next n lines contains m characters — the description of the sheet of paper: the j-th character of the i-th line equals either "#", if the corresponding square is painted (belongs to set A),... | standard output | standard input | Python 2 | Python | 1,700 | train_036.jsonl | e9dce08673ebe48f1007ef3c91a107f7 | 256 megabytes | ["5 4\n####\n#..#\n#..#\n#..#\n####", "5 5\n#####\n#...#\n#####\n#...#\n#####"] | PASSED | from sys import setrecursionlimit
setrecursionlimit(3000)
def main():
n,m = map(int, raw_input().split())
S, total = [], 0
for i in xrange(n):
t = map(lambda s: 1 if s == "#" else 0, raw_input())
S.append(t)
total += sum(t)
if total in (1,2):
print -1
retur... | 1338737400 | [
"trees",
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0,
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1
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1 second | ["7", "105", "761141116"] | 40a5e4b4193901cb3004dac24dba1d62 | NoteIn the first example, the answer is the sum of the first three numbers written out ($$$1 + 2 + 4 = 7$$$).In the second example, the numbers with numbers from $$$5$$$ to $$$14$$$: $$$5, 7, 9, 6, 8, 10, 12, 14, 16, 18$$$. Their sum is $$$105$$$. | Nazar, a student of the scientific lyceum of the Kingdom of Kremland, is known for his outstanding mathematical abilities. Today a math teacher gave him a very difficult task.Consider two infinite sets of numbers. The first set consists of odd positive numbers ($$$1, 3, 5, 7, \ldots$$$), and the second set consists of ... | Print a single integer — the answer modulo $$$1000000007$$$ ($$$10^9+7$$$). | The first line contains two integers $$$l$$$ and $$$r$$$ ($$$1 \leq l \leq r \leq 10^{18}$$$) — the range in which you need to find the sum. | standard output | standard input | PyPy 2 | Python | 1,800 | train_001.jsonl | 2722d2f1479cbd19c93dfd9142a191b1 | 256 megabytes | ["1 3", "5 14", "88005553535 99999999999"] | PASSED | def ways(l):
if l == 0:
return 0
count = 0
p=l
while p>=2:
p=p/2
count += 1
odd=count/2
even=count/2
if count%2==1:
odd += 1
ans=0
odd_terms=(pow(4,odd)-1)/3
even_terms=(2*(pow(4,even)-1))/3
total=odd_terms+even_terms
ans += pow(odd_terms,2... | 1555601700 | [
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5 seconds | ["3\n\n4\n\n5\n\n\n1\n\n4\n\n6"] | 7a9b559eb3b601590e22eb128f2bf307 | NoteTest Case 1:In this case, the hidden password is $$$2$$$.The first query is $$$3$$$. It is not equal to the current password. So, $$$0$$$ is returned, and the password is changed to $$$1$$$ since $$$2\oplus_2 1=3$$$.The second query is $$$4$$$. It is not equal to the current password. So, $$$0$$$ is returned, and t... | This is the hard version of the problem. The only difference is that here $$$2\leq k\leq 100$$$. You can make hacks only if both the versions of the problem are solved.This is an interactive problem!Every decimal number has a base $$$k$$$ equivalent. The individual digits of a base $$$k$$$ number are called $$$k$$$-its... | null | The first line of input contains a single integer $$$t$$$ ($$$1\leq t\leq 10\,000$$$) denoting the number of test cases. $$$t$$$ test cases follow. The first line of each test case contains two integers $$$n$$$ ($$$1\leq n\leq 2\cdot 10^5$$$) and $$$k$$$ $$$(2\leq k\leq 100)$$$. It is guaranteed that the sum of $$$n$$$... | standard output | standard input | PyPy 2 | Python | 2,200 | train_091.jsonl | 36f6ccc85cec8eb345d82cf04662655e | 256 megabytes | ["2\n5 2\n\n0\n\n0\n\n1\n5 3\n\n0\n\n0\n\n1"] | PASSED | from __future__ import division, print_function
import os,sys
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
from __builtin__ import xrange as range
from future_builtins import ascii, filter, hex, map, oct, zip
from bisect import bisect_left as lower_bound, bisect_right as upper_bound
... | 1625668500 | [
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1 second | ["2.5000000000", "2.0000000000"] | d79166497eb61d81fdfa4ef80ec1c8e8 | NoteConsider the second sample. At d = 2 the first lantern will light the segment [0, 4] of the street, and the second lantern will light segment [3, 5]. Thus, the whole street will be lit. | Vanya walks late at night along a straight street of length l, lit by n lanterns. Consider the coordinate system with the beginning of the street corresponding to the point 0, and its end corresponding to the point l. Then the i-th lantern is at the point ai. The lantern lights all points of the street that are at the ... | Print the minimum light radius d, needed to light the whole street. The answer will be considered correct if its absolute or relative error doesn't exceed 10 - 9. | The first line contains two integers n, l (1 ≤ n ≤ 1000, 1 ≤ l ≤ 109) — the number of lanterns and the length of the street respectively. The next line contains n integers ai (0 ≤ ai ≤ l). Multiple lanterns can be located at the same point. The lanterns may be located at the ends of the street. | standard output | standard input | PyPy 2 | Python | 1,200 | train_000.jsonl | 3bc2feb6d2d9d557e6445f1256210d72 | 256 megabytes | ["7 15\n15 5 3 7 9 14 0", "2 5\n2 5"] | PASSED | y=int(raw_input().split()[1])
b=raw_input().split()
for c in range(len(b)):
b[c]=int(b[c])
b.sort()
p=float(b[0]-0)
q=float(y-b[-1])
#print p,q
z=0
ans=0
while z+1<=len(b)-1:
m=b[z+1]-b[z]
if m>ans:
ans=m
z+=1
ans=ans/2.0
#print ans
print max(p,q,ans) | 1417451400 | [
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1 second | ["12", "9", "4", "4", "3"] | c9c65223b8575676647fe943f8dff25a | null | You have to restore the wall. The wall consists of $$$N$$$ pillars of bricks, the height of the $$$i$$$-th pillar is initially equal to $$$h_{i}$$$, the height is measured in number of bricks. After the restoration all the $$$N$$$ pillars should have equal heights.You are allowed the following operations: put a brick o... | Print one integer — the minimal cost of restoration. | The first line of input contains four integers $$$N$$$, $$$A$$$, $$$R$$$, $$$M$$$ ($$$1 \le N \le 10^{5}$$$, $$$0 \le A, R, M \le 10^{4}$$$) — the number of pillars and the costs of operations. The second line contains $$$N$$$ integers $$$h_{i}$$$ ($$$0 \le h_{i} \le 10^{9}$$$) — initial heights of pillars. | standard output | standard input | PyPy 3 | Python | 2,100 | train_039.jsonl | 138a8320d475768651c6b25222c1b33e | 256 megabytes | ["3 1 100 100\n1 3 8", "3 100 1 100\n1 3 8", "3 100 100 1\n1 3 8", "5 1 2 4\n5 5 3 6 5", "5 1 2 2\n5 5 3 6 5"] | PASSED | # https://codeforces.com/contest/1355/problem/E
import bisect
def func(val):
cost = 0
toAdd,toRemove = 0,0
lessEqual = bisect.bisect_right(arr,val)
greater = n - lessEqual
toAdd = (lessEqual * val) - dp[lessEqual]
toRemove = (total - dp[lessEqual]) - (greater * val)
if toRemove >= toAdd:
... | 1589628900 | [
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2 seconds | ["0", "2 1 3\n\n0"] | aea7e7220a8534c1053e8755a70dd499 | NoteWhen $$$n = 3$$$, any John's move can be reversed, thus $$$R(3) = 0$$$, and terminating the game immediately is correct.$$$R(4) = 1$$$, and one strategy to achieve this result is shown in the second sample case.Blank lines in sample interactions are for clarity and should not be printed. | This is an interactive problem.John and his imaginary friend play a game. There are $$$n$$$ lamps arranged in a circle. Lamps are numbered $$$1$$$ through $$$n$$$ in clockwise order, that is, lamps $$$i$$$ and $$$i + 1$$$ are adjacent for any $$$i = 1, \ldots, n - 1$$$, and also lamps $$$n$$$ and $$$1$$$ are adjacent. ... | null | null | standard output | standard input | Python 3 | Python | 2,600 | train_009.jsonl | adc11f1a9809409cbfd0da723c56abc9 | 512 megabytes | ["3", "4\n\n1"] | PASSED | #lizhou
n = int(input())
a = [0]*n
r = max(int(n-k-n/k+1) for k in range(1, n+1))
for i in range(1, n+1):
if int(n-i-n/i+1) == r:
k = i
break
def query(b):
for x in b:
a[x] = 1
print(k, end = " ")
print(*[x+1 for x in b])
x = int(input())-1
for i in range(k):
... | 1592491500 | [
"math",
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0
] | |
1 second | ["4\n0\n1\n14"] | 9ca9df1ab3760edb8e7adc3be533c576 | NoteIn the first test case, there are three ways to draw the $$$2$$$ additional chords, shown below (black chords are the ones initially drawn, while red chords are the new ones): We see that the third way gives the maximum number of intersections, namely $$$4$$$.In the second test case, there are no more chords to dr... | On a circle lie $$$2n$$$ distinct points, with the following property: however you choose $$$3$$$ chords that connect $$$3$$$ disjoint pairs of points, no point strictly inside the circle belongs to all $$$3$$$ chords. The points are numbered $$$1, \, 2, \, \dots, \, 2n$$$ in clockwise order.Initially, $$$k$$$ chords c... | For each test case, output the maximum number of intersections that can be obtained by drawing $$$n - k$$$ additional chords. | The first line contains a single integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases. Then $$$t$$$ test cases follow. The first line of each test case contains two integers $$$n$$$ and $$$k$$$ ($$$1 \le n \le 100$$$, $$$0 \le k \le n$$$) — half the number of points and the number of chords initially draw... | standard output | standard input | PyPy 3-64 | Python | 1,800 | train_098.jsonl | 34dad85d1d2e8c565c3605b1aa09d1bd | 256 megabytes | ["4\n4 2\n8 2\n1 5\n1 1\n2 1\n2 0\n10 6\n14 6\n2 20\n9 10\n13 18\n15 12\n11 7"] | PASSED | import sys
input = sys.stdin.readline
inf = float('inf')
def getInt():
return int(input())
def getStr():
return input().strip()
def getList(split=True):
s = getStr()
if split:
s = s.split()
return map(int, s)
t = getInt()
# t = 1
def solve():
n, k = getList()
a = [sorted(g... | 1627223700 | [
"geometry"
] | [
0,
1,
0,
0,
0,
0,
0,
0
] | |
2 seconds | ["ross rachel\njoey rachel\njoey phoebe\njoey monica\njoey chandler", "icm codeforces\nicm technex"] | 3c06e3cb2d8468e738b736a9bf88b4ca | NoteIn first example, the killer starts with ross and rachel. After day 1, ross is killed and joey appears. After day 2, rachel is killed and phoebe appears. After day 3, phoebe is killed and monica appears. After day 4, monica is killed and chandler appears. | Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers of deduction, he came to know that the killer has a strategy for selecting his next victim.The killer starts with two potential victims on his first day, selects one of these two, kills selected vi... | Output n + 1 lines, the i-th line should contain the two persons from which the killer selects for the i-th murder. The (n + 1)-th line should contain the two persons from which the next victim is selected. In each line, the two names can be printed in any order. | First line of input contains two names (length of each of them doesn't exceed 10), the two initials potential victims. Next line contains integer n (1 ≤ n ≤ 1000), the number of days. Next n lines contains two names (length of each of them doesn't exceed 10), first being the person murdered on this day and the second b... | standard output | standard input | PyPy 2 | Python | 900 | train_005.jsonl | 09bab30e474f73e8ae26b4980bbdfffd | 256 megabytes | ["ross rachel\n4\nross joey\nrachel phoebe\nphoebe monica\nmonica chandler", "icm codeforces\n1\ncodeforces technex"] | PASSED | now_list = raw_input().split(' ')
n = int(raw_input())
print ' '.join(now_list)
for i in xrange(n):
x, y = raw_input().split(' ')
now_list.remove(x)
now_list.append(y)
print ' '.join(now_list)
| 1487861100 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
1 second | ["5\n60\n1439\n1180\n1"] | f4982de28aca7080342eb1d0ff87734c | null | New Year is coming and you are excited to know how many minutes remain before the New Year. You know that currently the clock shows $$$h$$$ hours and $$$m$$$ minutes, where $$$0 \le hh < 24$$$ and $$$0 \le mm < 60$$$. We use 24-hour time format!Your task is to find the number of minutes before the New Year. You k... | For each test case, print the answer on it — the number of minutes before the New Year. | The first line of the input contains one integer $$$t$$$ ($$$1 \le t \le 1439$$$) — the number of test cases. The following $$$t$$$ lines describe test cases. The $$$i$$$-th line contains the time as two integers $$$h$$$ and $$$m$$$ ($$$0 \le h < 24$$$, $$$0 \le m < 60$$$). It is guaranteed that this time is not ... | standard output | standard input | Python 3 | Python | 800 | train_015.jsonl | 55ad85192ed602a3b20444f16f87e522 | 256 megabytes | ["5\n23 55\n23 0\n0 1\n4 20\n23 59"] | PASSED | testCase = int(input())
Output = 0
while testCase != 0:
H, Min = map(int, input().split())
if 0 <= H < 24 and 0 <= Min < 60:
Output = ((23-H) * 60) + (60 - Min)
print(Output)
testCase = testCase - 1
| 1577552700 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["First", "First", "Second"] | 2de867c08946eade5f674a98b377343d | null | Andrew, Fedor and Alex are inventive guys. Now they invent the game with strings for two players.Given a group of n non-empty strings. During the game two players build the word together, initially the word is empty. The players move in turns. On his step player must add a single letter in the end of the word, the resu... | If the player who moves first wins, print "First", otherwise print "Second" (without the quotes). | The first line contains two integers, n and k (1 ≤ n ≤ 105; 1 ≤ k ≤ 109). Each of the next n lines contains a single non-empty string from the given group. The total length of all strings from the group doesn't exceed 105. Each string of the group consists only of lowercase English letters. | standard output | standard input | Python 3 | Python | 1,900 | train_017.jsonl | f9c87f3bd177e15c586a426c71170373 | 256 megabytes | ["2 3\na\nb", "3 1\na\nb\nc", "1 2\nab"] | PASSED | N = 100000
Z = 26
#别用这玩意儿: trie = [[0] * Z] * N 巨坑!https://www.cnblogs.com/PyLearn/p/7795552.html
trie = [[0 for i in range(Z)] for j in range(N)]
n = 0
k = 0
nodeNum = 0
def insertNode():
u = 0
string = input()
global nodeNum
for i in range(len(string)):
c = ord(string[i]) - ord('a')
if trie[u][c] == 0:
... | 1407511800 | [
"games",
"strings",
"trees"
] | [
1,
0,
0,
0,
0,
0,
1,
1
] | |
3 seconds | ["3.4142135624", "37.7044021497"] | 51c355a5b56f9b1599e7d985f0b7c04e | null | In Medieval times existed the tradition of burning witches at steaks together with their pets, black cats. By the end of the 15-th century the population of black cats ceased to exist. The difficulty of the situation led to creating the EIC - the Emergency Inquisitory Commission.The resolution #666 says that a white ca... | Print a single number, the answer to the problem, perimeter of the union of triangles. Your answer should differ from the correct one in no more than 10 - 6. | The first input line contains a single integer n (0 ≤ n ≤ 100). It is the number of spots on the cat's fur. The i-th of the last n lines contains 6 integers: x1i, y1i, x2i, y2i, x3i, y3i. They are the coordinates of the i-th triangular spot (0 < xji, yji < 105). | standard output | standard input | Python 2 | Python | 2,300 | train_002.jsonl | 55208628c101d596b3c0e3b7a6bad399 | 256 megabytes | ["1\n1 1 2 1 1 2", "3\n3 3 10 3 3 10\n1 1 9 4 5 6\n2 2 11 7 6 11"] | PASSED | from math import *
eps=1e-14
n = input()
l = [map(int,raw_input().split()) for _ in xrange(n)]
res = 0
def isect(a1,b1,c1,x1,y1,x2,y2):
a2,b2,c2=y1-y2,x2-x1,x1*y2-y1*x2
d = a1*b2-a2*b1
if d==0: return None, None
x = -1.0*(c1*b2-c2*b1)/d
y = -1.0*(c2*a1-a2*c1)/d
#print x1,y1,x2,y2,x,y
if min(... | 1298649600 | [
"geometry"
] | [
0,
1,
0,
0,
0,
0,
0,
0
] | |
2 seconds | ["unique\n5", "not unique"] | bfbd7a73e65d240ee7e8c83cc68ca0a1 | NoteIn the second example the answer is not unique. For example, if α = 10, we'll have such a sequence as 1, 2, 3, and if α = 14, the sequence will be 1, 2, 4. | Every year a race takes place on the motorway between cities A and B. This year Vanya decided to take part in the race and drive his own car that has been around and bears its own noble name — The Huff-puffer.So, Vasya leaves city A on the Huff-puffer, besides, at the very beginning he fills the petrol tank with α lite... | Print in the first line "unique" (without quotes) if the answer can be determined uniquely. In the second line print the number of the station where the next stop will take place. If the answer is not unique, print in the first line "not unique". | The first line contains an integer n (1 ≤ n ≤ 1000) which represents the number of petrol stations where Vanya has stopped. The next line has n space-separated integers which represent the numbers of the stations. The numbers are positive and do not exceed 106, they are given in the increasing order. No two numbers in ... | standard output | standard input | Python 2 | Python | 1,800 | train_006.jsonl | e6c9662e1079a38a6394080ee9d5b85e | 256 megabytes | ["3\n1 2 4", "2\n1 2"] | PASSED | I = lambda: map(int, raw_input().split())
n = input()
S = [None]*n
S = I()
#print S
counter = 1
decr = 0
alpha = 0.0
lower = 0.0
for i in xrange(n):
if(i == 0):
alpha = 10*S[0]+10
decr = 10*S[0]
counter += 1
else:
decr = 10*(S[i]-S[i-1]) + decr
alpha = min(alpha,(decr +... | 1292140800 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["abab\n-1\naaa\nab\nz"] | 8d4cdf75f726b59a8fcc374e1417374a | NoteThe first test case was explained in the statement.In the second test case, the answer does not exist. | You are given $$$n$$$ strings $$$a_1, a_2, \ldots, a_n$$$: all of them have the same length $$$m$$$. The strings consist of lowercase English letters.Find any string $$$s$$$ of length $$$m$$$ such that each of the given $$$n$$$ strings differs from $$$s$$$ in at most one position. Formally, for each given string $$$a_i... | Print $$$t$$$ answers to the test cases. Each answer (if it exists) is a string of length $$$m$$$ consisting of lowercase English letters. If there are several answers, print any of them. If the answer does not exist, print "-1" ("minus one", without quotes). | The first line contains an integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases. Then $$$t$$$ test cases follow. Each test case starts with a line containing two positive integers $$$n$$$ ($$$1 \le n \le 10$$$) and $$$m$$$ ($$$1 \le m \le 10$$$) — the number of strings and their length. Then follow $$$n$$... | standard output | standard input | PyPy 3 | Python | 1,700 | train_007.jsonl | 8611089238d9864067855d6f2391005d | 256 megabytes | ["5\n2 4\nabac\nzbab\n2 4\naaaa\nbbbb\n3 3\nbaa\naaa\naab\n2 2\nab\nbb\n3 1\na\nb\nc"] | PASSED | import string
for _ in range(int(input())):
n,m=map(int,input().split())
s=[input() for _ in range(n)]
totry=string.ascii_lowercase
for i in range(m):
t1=0
for l in totry:
ans=s[0][:i]+l+s[0][i+1:]
t=0
for st in s:
r=0
f... | 1590327300 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
4 seconds | ["2\n0\n13\n1\n4\n7\n0"] | a7ae834884ce801ffe111bd8161e89d2 | NoteIn the first test case, the optimal array is $$$p = [1, 1, 1, 2, 2]$$$. The resulting array of values of $$$\lfloor \frac{a_i}{p_i} \rfloor$$$ is $$$[4, 5, 6, 4, 5]$$$. The cost of $$$p$$$ is $$$\max\limits_{1 \le i \le n}(\lfloor \frac{a_i}{p_i} \rfloor) - \min\limits_{1 \le i \le n}(\lfloor \frac{a_i}{p_i} \rfloo... | This is the hard version of the problem. The only difference between the versions is the constraints on $$$n$$$, $$$k$$$, $$$a_i$$$, and the sum of $$$n$$$ over all test cases. You can make hacks only if both versions of the problem are solved.Note the unusual memory limit.You are given an array of integers $$$a_1, a_2... | For each test case, print a single integer — the minimum possible cost of an array $$$p$$$ satisfying the condition above. | The first line contains a single integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases. The first line of each test case contains two integers $$$n$$$ and $$$k$$$ ($$$1 \le n, k \le 10^5$$$). The second line contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$1 \le a_1 \le a_2 \le \ldots \le a_n \le ... | standard output | standard input | PyPy 3-64 | Python | 2,400 | train_093.jsonl | c3378cdf501f3cc31c0ea5e47090e67f | 64 megabytes | ["7\n\n5 2\n\n4 5 6 8 11\n\n5 12\n\n4 5 6 8 11\n\n3 1\n\n2 9 15\n\n7 3\n\n2 3 5 5 6 9 10\n\n6 56\n\n54 286 527 1436 2450 2681\n\n3 95\n\n16 340 2241\n\n2 2\n\n1 3"] | PASSED | #!/usr/bin/env python3
import sys
import heapq
input = sys.stdin.readline # to read input quickly
def ceiling_division(numer, denom):
return -((-numer)//denom)
mask = 2**18 - 1
m0 = mask
m1 = mask << 18
m2 = mask << 36
def ungroup(x):
return (x&m2) >> 36, (x&m1) >> 18, (x&m0)
def gr... | 1658154900 | [
"number theory",
"math"
] | [
0,
0,
0,
1,
1,
0,
0,
0
] | |
1 second | ["110110", "01100011", "01"] | 6ac00fcd4a483f9f446e692d05fd31a4 | NoteIn the first example there are two occurrences, one starting from first position and one starting from fourth position.In the second example there is only one occurrence, which starts from third position. Note, that the answer is not unique. For example, if we move the first day (which is a day off) to the last pos... | The new camp by widely-known over the country Spring Programming Camp is going to start soon. Hence, all the team of friendly curators and teachers started composing the camp's schedule. After some continuous discussion, they came up with a schedule $$$s$$$, which can be represented as a binary string, in which the $$$... | In the only line print the schedule having the largest number of substrings equal to $$$t$$$. Printed schedule should consist of characters '0' and '1' only and the number of zeros should be equal to the number of zeros in $$$s$$$ and the number of ones should be equal to the number of ones in $$$s$$$. In case there mu... | The first line contains string $$$s$$$ ($$$1 \leqslant |s| \leqslant 500\,000$$$), denoting the current project of the camp's schedule. The second line contains string $$$t$$$ ($$$1 \leqslant |t| \leqslant 500\,000$$$), denoting the optimal schedule according to Gleb. Strings $$$s$$$ and $$$t$$$ contain characters '0' ... | standard output | standard input | Python 3 | Python | 1,600 | train_054.jsonl | 0b72121ba7e0922a43d287ce4565e9c3 | 512 megabytes | ["101101\n110", "10010110\n100011", "10\n11100"] | PASSED | import sys
def count_bits(s):
return [s.count("0"), s.count("1")]
# 1 - in case where a >= b
# 0 - otherwise
def compare_bits_count(a, b):
if a[0] >= b[0] and a[1] >= b[1]:
return 1
else:
return 0
def subtract_bits_count(a, b):
return [a[0] - b[0], a[1] - b[1]]
def z_function(s):... | 1552035900 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
1 second | ["Yes\nNo\nYes"] | 34aa41871ee50f06e8acbd5eee94b493 | NoteThe first two sets are desribed in the statement.The third set produces garland "RBRG", for example. | Polycarp is sad — New Year is coming in few days but there is still no snow in his city. To bring himself New Year mood, he decided to decorate his house with some garlands.The local store introduced a new service this year, called "Build your own garland". So you can buy some red, green and blue lamps, provide them an... | Print $$$t$$$ lines — for each set of lamps print "Yes" if the store workers can build a garland from them and "No" otherwise. | The first line contains a single integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of sets of lamps Polycarp has bought. Each of the next $$$t$$$ lines contains three integers $$$r$$$, $$$g$$$ and $$$b$$$ ($$$1 \le r, g, b \le 10^9$$$) — the number of red, green and blue lamps in the set, respectively. | standard output | standard input | Python 3 | Python | 900 | train_000.jsonl | d53ffbdbe544d9997b359900cde00fa8 | 256 megabytes | ["3\n3 3 3\n1 10 2\n2 1 1"] | PASSED | t=int(input())
for _ in range(t):
l=list(map(int,input().split()))
if 2*max(l)<=sum(l)+1:
print('Yes')
else:
print('No') | 1577457600 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["3", "0 2 4", "-1", "13 15 17 19 21"] | e5ac0312381701a25970dd9a98cda3d4 | NoteIn the first test case, the only solution is that everyone is friends with everyone. That is why Bob should have $$$3$$$ friends.In the second test case, there are three possible solutions (apart from symmetries): $$$a$$$ is friend of $$$b$$$, $$$c$$$ is friend of $$$d$$$, and Bob has no friends, or $$$a$$$ is a... | Bob is an active user of the social network Faithbug. On this network, people are able to engage in a mutual friendship. That is, if $$$a$$$ is a friend of $$$b$$$, then $$$b$$$ is also a friend of $$$a$$$. Each user thus has a non-negative amount of friends.This morning, somebody anonymously sent Bob the following lin... | Print all possible values of $$$a_{n+1}$$$ — the amount of people that Bob can be friend of, in increasing order. If no solution exists, output $$$-1$$$. | The first line contains one integer $$$n$$$ ($$$1 \leq n \leq 5 \cdot 10^5$$$), the number of people on the network excluding Bob. The second line contains $$$n$$$ numbers $$$a_1,a_2, \dots, a_n$$$ ($$$0 \leq a_i \leq n$$$), with $$$a_i$$$ being the number of people that person $$$i$$$ is a friend of. | standard output | standard input | Python 3 | Python | 2,400 | train_033.jsonl | d179a722084be6092d643ecc0adb97fb | 256 megabytes | ["3\n3 3 3", "4\n1 1 1 1", "2\n0 2", "35\n21 26 18 4 28 2 15 13 16 25 6 32 11 5 31 17 9 3 24 33 14 27 29 1 20 4 12 7 10 30 34 8 19 23 22"] | PASSED | def main():
n=int(input())
a=list(map(int,input().split()))
a.sort(reverse=True)
mod=sum(a)%2
counts=[0]*(n+1)
for guy in a:
counts[guy]+=1
cumcounts=[counts[0]]
for i in range(n):
cumcounts.append(cumcounts[-1]+counts[i+1])
partialsums=[0]
curr=0
for i in ran... | 1546180500 | [
"math",
"graphs"
] | [
0,
0,
1,
1,
0,
0,
0,
0
] | |
1 second | ["NO", "YES"] | 9cf8b711a3fcf5dd5059f323f107a0bd | null | You have matrix a of size n × n. Let's number the rows of the matrix from 1 to n from top to bottom, let's number the columns from 1 to n from left to right. Let's use aij to represent the element on the intersection of the i-th row and the j-th column. Matrix a meets the following two conditions: for any numbers i, ... | If there is a positive integer k ≥ 1, such that matrix ak is strictly positive, print "YES" (without the quotes). Otherwise, print "NO" (without the quotes). | The first line contains integer n (2 ≤ n ≤ 2000) — the number of rows and columns in matrix a. The next n lines contain the description of the rows of matrix a. The i-th line contains n non-negative integers ai1, ai2, ..., ain (0 ≤ aij ≤ 50). It is guaranteed that . | standard output | standard input | PyPy 2 | Python | 2,200 | train_077.jsonl | 7c3a71881ab6ade147d41ec0b2f50cc6 | 256 megabytes | ["2\n1 0\n0 1", "5\n4 5 6 1 2\n1 2 3 4 5\n6 4 1 2 4\n1 1 1 1 1\n4 4 4 4 4"] | PASSED | #!py2
def solve(N, A):
graph = [set() for _ in xrange(N)]
rgraph = [set() for _ in xrange(N)]
for u, row in enumerate(A):
for v, val in enumerate(row):
if val:
graph[u].add(v)
rgraph[v].add(u)
# Try to write row 0 in terms of row i
stack... | 1394983800 | [
"math",
"graphs"
] | [
0,
0,
1,
1,
0,
0,
0,
0
] | |
15 seconds | ["RL", "DLDDLLLRRRUURU", "IMPOSSIBLE"] | 61689578b2623e750eced6f770fda2cc | NoteIn the first sample two cyclic ways for the Robot with the length 2 exist — "UD" and "RL". The second cycle is lexicographically less. In the second sample the Robot should move in the following way: down, left, down, down, left, left, left, right, right, right, up, up, right, up. In the third sample the Robot can'... | The Robot is in a rectangular maze of size n × m. Each cell of the maze is either empty or occupied by an obstacle. The Robot can move between neighboring cells on the side left (the symbol "L"), right (the symbol "R"), up (the symbol "U") or down (the symbol "D"). The Robot can move to the cell only if it is empty. In... | Print the lexicographically minimum Robot's way with the length exactly k, which starts and ends in the cell where initially Robot is. If there is no such way, print "IMPOSSIBLE"(without quotes). | The first line contains three integers n, m and k (1 ≤ n, m ≤ 1000, 1 ≤ k ≤ 106) — the size of the maze and the length of the cycle. Each of the following n lines contains m symbols — the description of the maze. If the symbol equals to "." the current cell is empty. If the symbol equals to "*" the current cell is occ... | standard output | standard input | Python 3 | Python | 1,700 | train_077.jsonl | e6341ca044cd6a9a4d20792b5bfdde8a | 256 megabytes | ["2 3 2\n.**\nX..", "5 6 14\n..***.\n*...X.\n..*...\n..*.**\n....*.", "3 3 4\n***\n*X*\n***"] | PASSED | from queue import Queue
import sys
#sys.stdin = open('input.txt')
n, m, k = map(lambda x: int(x), input().split(' '))
if k&1:
print('IMPOSSIBLE')
sys.exit()
s = [None]*n
for i in range(n):
s[i] = [None]*m
t = input()
for j in range(m):
s[i][j] = t[j]
if t[j] == 'X': x, y = j, i
def bfs(x, y):
re... | 1488628800 | [
"graphs"
] | [
0,
0,
1,
0,
0,
0,
0,
0
] | |
2 seconds | ["YES", "NO"] | c659bdeda1c1da08cfc7f71367222332 | Note First example: you can simply swap two letters in string "ab". So we get "ba". Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b". | Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.Dwarf Misha ... | Print "YES", if the dwarves belong to the same race. Otherwise, print "NO". | The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters. The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters. The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that corr... | standard output | standard input | Python 3 | Python | 1,100 | train_005.jsonl | 74f9f2db9474289817555c34f9037caf | 256 megabytes | ["ab\nba", "aa\nab"] | PASSED | p=input()
p=p.replace('',' ')
p=p.split()
q=input()
q=q.replace('',' ')
q=q.split()
if len(p)==len(q):
c=0
l=[]
for i in range(len(p)):
if p[i]!=q[i]:
c+=1
l.append(p[i])
l.append(q[i])
if c==2:
d=0
for i in range(4):
if l.count(l[i... | 1336145400 | [
"strings"
] | [
0,
0,
0,
0,
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0,
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0
] | |
2 seconds | ["()", "(()(()))", "()()"] | cf1c39e85eded68515aae9eceac73313 | NoteIn the first sample the cursor is initially at position 5. Consider actions of the editor: command "R" — the cursor moves to the position 6 on the right; command "D" — the deletion of brackets from the position 5 to the position 6. After that CBS takes the form (())(), the cursor is at the position 5; command "L... | Recently Polycarp started to develop a text editor that works only with correct bracket sequences (abbreviated as CBS). Note that a bracket sequence is correct if it is possible to get a correct mathematical expression by adding "+"-s and "1"-s to it. For example, sequences "(())()", "()" and "(()(()))" are correct, wh... | Print the correct bracket sequence, obtained as a result of applying all operations to the initial sequence. | The first line contains three positive integers n, m and p (2 ≤ n ≤ 500 000, 1 ≤ m ≤ 500 000, 1 ≤ p ≤ n) — the number of brackets in the correct bracket sequence, the number of operations and the initial position of cursor. Positions in the sequence are numbered from left to right, starting from one. It is guaranteed t... | standard output | standard input | Python 3 | Python | 1,700 | train_059.jsonl | 370a247f79c018a6b474d2a1688db039 | 256 megabytes | ["8 4 5\n(())()()\nRDLD", "12 5 3\n((()())(()))\nRRDLD", "8 8 8\n(())()()\nLLLLLLDD"] | PASSED | class Node:
def __init__(self, index):
self.left = index - 1
self.right = index + 1
self.pair = -1
if __name__ == "__main__":
n, m, p = map(int, input().split())
brackets = input()
operations = input()
nodes = [Node(i) for i in range(n + 1)]
stack = []
for i in ran... | 1462464300 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
1 second | ["1", "1999982505"] | 54e9c6f24c430c5124d840b5a65a1bc4 | NoteIn the first example, we first reorder $$$\{1, 3, 2\}$$$ into $$$\{1, 2, 3\}$$$, then increment $$$a_2$$$ to $$$4$$$ with cost $$$1$$$ to get a power sequence $$$\{1, 2, 4\}$$$. | Let's call a list of positive integers $$$a_0, a_1, ..., a_{n-1}$$$ a power sequence if there is a positive integer $$$c$$$, so that for every $$$0 \le i \le n-1$$$ then $$$a_i = c^i$$$.Given a list of $$$n$$$ positive integers $$$a_0, a_1, ..., a_{n-1}$$$, you are allowed to: Reorder the list (i.e. pick a permutation... | Print the minimum cost to transform $$$a_0, a_1, ..., a_{n-1}$$$ into a power sequence. | The first line contains an integer $$$n$$$ ($$$3 \le n \le 10^5$$$). The second line contains $$$n$$$ integers $$$a_0, a_1, ..., a_{n-1}$$$ ($$$1 \le a_i \le 10^9$$$). | standard output | standard input | PyPy 3 | Python | 1,500 | train_001.jsonl | 3b75768ab9d2fa9782acad40a87ed191 | 256 megabytes | ["3\n1 3 2", "3\n1000000000 1000000000 1000000000"] | PASSED | import copy
import math
n = int(input())
nums = list(map(int,input().split()))
nums.sort()
f_1 = 0
for i in range(n):
f_1 += math.fabs(1 - nums[i])
term = f_1 + nums[-1]
max_c = math.floor(math.pow(term,1/(n-1)))
cost2 = float('inf')
prev_cost = 0
for c in range(1,max_c+1):
cost = 0
for i in range(n)... | 1598798100 | [
"number theory",
"math"
] | [
0,
0,
0,
1,
1,
0,
0,
0
] | |
1 second | ["YES\nYES\nNO\nNO"] | c0ad2a6d14b0c9e09af2221d88a34d52 | NoteIn the first test case, you can form one packet with $$$1$$$ red and $$$1$$$ blue bean. The absolute difference $$$|1 - 1| = 0 \le d$$$.In the second test case, you can form two packets: $$$1$$$ red and $$$4$$$ blue beans in the first packet and $$$1$$$ red and $$$3$$$ blue beans in the second one.In the third test... | You have $$$r$$$ red and $$$b$$$ blue beans. You'd like to distribute them among several (maybe, one) packets in such a way that each packet: has at least one red bean (or the number of red beans $$$r_i \ge 1$$$); has at least one blue bean (or the number of blue beans $$$b_i \ge 1$$$); the number of red and blue b... | For each test case, if you can distribute all beans, print YES. Otherwise, print NO. You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES are all recognized as positive answer). | The first line contains the single integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases. The first and only line of each test case contains three integers $$$r$$$, $$$b$$$, and $$$d$$$ ($$$1 \le r, b \le 10^9$$$; $$$0 \le d \le 10^9$$$) — the number of red and blue beans and the maximum absolute differen... | standard output | standard input | Python 3 | Python | 800 | train_101.jsonl | a149ae3b91445d8dcb18e6884f39240a | 256 megabytes | ["4\n1 1 0\n2 7 3\n6 1 4\n5 4 0"] | PASSED | for i in range(int(input())):
arr = [int(_) for _ in input().split()]
if abs(arr[0] / min(arr[:2]) - arr[1] / min(arr[:2])) <= arr[2]:
print('YES')
else:
print('NO')
# val = abs(arr[0] / 2 - arr[1] / 2) <= arr[2]
| 1619706900 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["1.931851653\n3.196226611\n126.687663595"] | c466c909fff92353ea676b643ca76908 | null | The statement of this problem is the same as the statement of problem C1. The only difference is that, in problem C1, $$$n$$$ is always even, and in C2, $$$n$$$ is always odd.You are given a regular polygon with $$$2 \cdot n$$$ vertices (it's convex and has equal sides and equal angles) and all its sides have length $$... | Print $$$T$$$ real numbers — one per test case. For each test case, print the minimum length of a side of the square $$$2n$$$-gon can be embedded in. Your answer will be considered correct if its absolute or relative error doesn't exceed $$$10^{-6}$$$. | The first line contains a single integer $$$T$$$ ($$$1 \le T \le 200$$$) — the number of test cases. Next $$$T$$$ lines contain descriptions of test cases — one per line. Each line contains single odd integer $$$n$$$ ($$$3 \le n \le 199$$$). Don't forget you need to embed $$$2n$$$-gon, not an $$$n$$$-gon. | standard output | standard input | PyPy 3 | Python | 2,000 | train_004.jsonl | acd939ebac1b4aafb82d9aa8b69f4f7c | 256 megabytes | ["3\n3\n5\n199"] | PASSED | from math import sin,radians
def C2(n):
interiorangle = 360/(2*n)
side = sin(radians(45))
angle = 45
number = (n-1)/2
for i in range(int(number)):
angle += interiorangle
if angle > 90:
angle = 180 - angle
side += sin(radians(angle))
angle = 180 - a... | 1589707200 | [
"geometry",
"math"
] | [
0,
1,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["a", "bc", "b"] | 161f3f76bfe141899ad0773545b38c03 | NoteIn the second sample before string "bc" follow strings "a", "ab", "abc", "b". | One day in the IT lesson Anna and Maria learned about the lexicographic order.String x is lexicographically less than string y, if either x is a prefix of y (and x ≠ y), or there exists such i (1 ≤ i ≤ min(|x|, |y|)), that xi < yi, and for any j (1 ≤ j < i) xj = yj. Here |a| denotes the length of the string a. Th... | Print the string Anna and Maria need — the k-th (in the lexicographical order) substring of the given string. If the total number of substrings is less than k, print a string saying "No such line." (without the quotes). | The first line contains a non-empty string that only consists of small Latin letters ("a"-"z"), whose length does not exceed 105. The second line contains the only integer k (1 ≤ k ≤ 105). | standard output | standard input | Python 3 | Python | 2,100 | train_018.jsonl | f2c521438dade5afc86d45edc3340ba6 | 256 megabytes | ["aa\n2", "abc\n5", "abab\n7"] | PASSED | # -*- coding: utf-8 -*-
"""
Created on Sat May 7 16:53:11 2016
@author: Alex
"""
from heapq import heappush,heappop,heapify
string = input()
l = len(string)
k = int(input())
A = l*(l+1)/2
if A<k:
print("No such line.")
else:
heap = [(string[i],i+1) for i in range(l)]
heapify(heap)
cnt = 0
while cn... | 1321337400 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
2 seconds | ["YES\n25.5000000000\n10.0000000000 4.5000000000 0.0000000000", "NO", "YES\n0.0000000000\n1.0000000000 2.0000000000 3.0000000000"] | 6e2a8aa58ed8cd308cb482e4c24cbbbb | null | Brothers Fred and George Weasley once got into the sporting goods store and opened a box of Quidditch balls. After long and painful experiments they found out that the Golden Snitch is not enchanted at all. It is simply a programmed device. It always moves along the same trajectory, which is a polyline with vertices at... | If Harry Potter can catch the snitch while it is moving along the polyline (including the end (xn, yn, zn)), print "YES" in the first line (without the quotes). Print in the second line t, which is the earliest moment of time, when Harry will be able to catch the snitch. On the third line print three numbers X, Y, Z, t... | The first line contains a single integer n (1 ≤ n ≤ 10000). The following n + 1 lines contain the coordinates xi, yi, zi, separated by single spaces. The coordinates of any two consecutive points do not coincide. The next line contains the velocities vp and vs, the last line contains Px, Py, Pz, separated by single spa... | standard output | standard input | Python 2 | Python | 2,100 | train_060.jsonl | 87d9b7abd9713d16eff012c23009e499 | 256 megabytes | ["4\n0 0 0\n0 10 0\n10 10 0\n10 0 0\n0 0 0\n1 1\n5 5 25", "4\n0 0 0\n0 10 0\n10 10 0\n10 0 0\n0 0 0\n1 1\n5 5 50", "1\n1 2 3\n4 5 6\n20 10\n1 2 3"] | PASSED | import math,sys
eps = 1e-8
n = input()
al = [map(int,raw_input().split()) for i in xrange(n+1)]
vp,vs = map(int,raw_input().split())
px,py,pz = p0 = map(int,raw_input().split())
al = [(x-px,y-py,z-pz) for x,y,z in al]
d3=lambda x,y,z:x*x+y*y+z*z
t0,ts = 0,0
rt = None
for i in range(n):
c = [y-x for x,y in... | 1299340800 | [
"geometry"
] | [
0,
1,
0,
0,
0,
0,
0,
0
] | |
2 seconds | ["164", "27"] | 28c555fefd5c36697a5082c61d8a82b3 | NoteIn the first sample, one of the optimal solutions is to divide those $$$4$$$ numbers into $$$2$$$ groups $$$\{2, 8\}, \{5, 3\}$$$. Thus the answer is $$$(2 + 8)^2 + (5 + 3)^2 = 164$$$.In the second sample, one of the optimal solutions is to divide those $$$6$$$ numbers into $$$3$$$ groups $$$\{1, 2\}, \{1, 2\}, \{1... | Lunar New Year is approaching, and Bob is struggling with his homework – a number division problem.There are $$$n$$$ positive integers $$$a_1, a_2, \ldots, a_n$$$ on Bob's homework paper, where $$$n$$$ is always an even number. Bob is asked to divide those numbers into groups, where each group must contain at least $$$... | A single line containing one integer, denoting the minimum of the sum of the square of $$$s_j$$$, which is $$$$$$\sum_{i = j}^{m} s_j^2,$$$$$$ where $$$m$$$ is the number of groups. | The first line contains an even integer $$$n$$$ ($$$2 \leq n \leq 3 \cdot 10^5$$$), denoting that there are $$$n$$$ integers on Bob's homework paper. The second line contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$1 \leq a_i \leq 10^4$$$), describing the numbers you need to deal with. | standard output | standard input | PyPy 3 | Python | 900 | train_004.jsonl | 1d7642edf48293b29f51ec811b2d01c3 | 256 megabytes | ["4\n8 5 2 3", "6\n1 1 1 2 2 2"] | PASSED |
n = int(input())
a = list(map(int, input().split(" ")))
a.sort()
min_sum = 0
i = 0
j = n - 1
while i <= j:
if i == j:
min_sum += a[j]
else:
min_sum += (a[i] + a[j]) ** 2
i += 1
j -= 1
print(min_sum) | 1548938100 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["4", "9"] | dceeb739a56bb799550138aa8c127996 | NoteIn the first example, students could choose three sets with drinks $$$1$$$, $$$1$$$ and $$$2$$$ (so they will have two sets with two drinks of the type $$$1$$$ each and one set with two drinks of the type $$$2$$$, so portions will be $$$1, 1, 1, 1, 2, 2$$$). This way all students except the second one will get thei... | Old timers of Summer Informatics School can remember previous camps in which each student was given a drink of his choice on the vechorka (late-evening meal). Or may be the story was more complicated?There are $$$n$$$ students living in a building, and for each of them the favorite drink $$$a_i$$$ is known. So you know... | Print exactly one integer — the maximum number of students that can get a favorite drink. | The first line of the input contains two integers $$$n$$$ and $$$k$$$ ($$$1 \le n, k \le 1\,000$$$) — the number of students in the building and the number of different drinks. The next $$$n$$$ lines contain student's favorite drinks. The $$$i$$$-th line contains a single integer from $$$1$$$ to $$$k$$$ — the type of t... | standard output | standard input | Python 3 | Python | 1,000 | train_021.jsonl | 31aeedb9329d4f4d7680c66eb3cba918 | 256 megabytes | ["5 3\n1\n3\n1\n1\n2", "10 3\n2\n1\n3\n2\n3\n3\n1\n3\n1\n2"] | PASSED | import math
n, k = map(int, input().split())
a = [0] * k
for i in range(n):
temp = int(input())
a[temp-1] += 1
nSet = math.ceil(n/2)
ans = 0
# First deal with situation where a[i] > 1
for i in range(k):
while a[i] > 1 and nSet > 0:
ans += 2
nSet -= 1
a[i] -= 2
# Then deal with only ... | 1563374100 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["1 2\n1 2\n1 3\n2 3"] | b01fb9d4d78a02e3c634800b4b177d75 | NoteNote that you can add the same edge that you cut.In the first test case, after cutting and adding the same edge, the vertex $$$2$$$ is still the only centroid.In the second test case, the vertex $$$2$$$ becomes the only centroid after cutting the edge between vertices $$$1$$$ and $$$3$$$ and adding the edge between... | Fishing Prince loves trees, and he especially loves trees with only one centroid. The tree is a connected graph without cycles.A vertex is a centroid of a tree only when you cut this vertex (remove it and remove all edges from this vertex), the size of the largest connected component of the remaining graph is the small... | For each test case, print two lines. In the first line print two integers $$$x_1, y_1$$$ ($$$1 \leq x_1, y_1 \leq n$$$), which means you cut the edge between vertices $$$x_1$$$ and $$$y_1$$$. There should exist edge connecting vertices $$$x_1$$$ and $$$y_1$$$. In the second line print two integers $$$x_2, y_2$$$ ($$$1 ... | The input consists of multiple test cases. The first line contains an integer $$$t$$$ ($$$1\leq t\leq 10^4$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$3\leq n\leq 10^5$$$) — the number of vertices. Each of the next $$$n-1$$$... | standard output | standard input | PyPy 3 | Python | 1,700 | train_029.jsonl | 51565fc3d42f0f25dcc38f6c43bb0be3 | 512 megabytes | ["2\n5\n1 2\n1 3\n2 4\n2 5\n6\n1 2\n1 3\n1 4\n2 5\n2 6"] | PASSED | ######################################################
############Created by Devesh Kumar###################
#############devesh1102@gmail.com####################
##########For CodeForces(Devesh1102)#################
#####################2020#############################
###############################################... | 1599918300 | [
"trees",
"graphs"
] | [
0,
0,
1,
0,
0,
0,
0,
1
] | |
1 second | ["YES\nNO\nYES"] | eba7fc8d103ba3d643c1424cbbebf571 | null | There are n employees working in company "X" (let's number them from 1 to n for convenience). Initially the employees didn't have any relationships among each other. On each of m next days one of the following events took place: either employee y became the boss of employee x (at that, employee x didn't have a boss be... | For each query of the third type print "YES" if the employee signed the document package and "NO" otherwise. Print all the words without the quotes. | The first line contains two integers n and m (1 ≤ n, m ≤ 105) — the number of employees and the number of events. Each of the next m lines contains the description of one event (the events are given in the chronological order). The first number of the line determines the type of event t (1 ≤ t ≤ 3). If t = 1, then ... | standard output | standard input | Python 3 | Python | 2,100 | train_051.jsonl | eacbdc33f4e998b7bd6f37c7a294131b | 512 megabytes | ["4 9\n1 4 3\n2 4\n3 3 1\n1 2 3\n2 2\n3 1 2\n1 3 1\n2 2\n3 1 3"] | PASSED | n, m = map(int, input().split())
ev = [tuple(map(int, input().split())) for _ in range(m)]
g = [[] for _ in range(n + 1)]
qry = [[] for _ in range(m + 1)]
roots = set(range(1, n + 1))
qcnt = 0
for e in ev:
if e[0] == 1:
g[e[2]].append(e[1])
roots.remove(e[1])
elif e[0] == 3:
qry[e[2]].append((qcnt, e[1]))
qc... | 1410535800 | [
"trees",
"graphs"
] | [
0,
0,
1,
0,
0,
0,
0,
1
] | |
2 seconds | ["12 14", "8"] | 9eccd64bb49b74ed0eed3dbf6636f07d | NoteIn the first example, for $$$f(3)$$$, we consider four possible polygons: ($$$p_1, p_2, p_3$$$), with perimeter $$$12$$$. ($$$p_1, p_2, p_4$$$), with perimeter $$$8$$$. ($$$p_1, p_3, p_4$$$), with perimeter $$$12$$$. ($$$p_2, p_3, p_4$$$), with perimeter $$$12$$$. For $$$f(4)$$$, there is only one option, taki... | You are given $$$n$$$ points on the plane. The polygon formed from all the $$$n$$$ points is strictly convex, that is, the polygon is convex, and there are no three collinear points (i.e. lying in the same straight line). The points are numbered from $$$1$$$ to $$$n$$$, in clockwise order.We define the distance between... | For each $$$i$$$ ($$$3\leq i\leq n$$$), output $$$f(i)$$$. | The first line contains a single integer $$$n$$$ ($$$3 \leq n \leq 3\cdot 10^5$$$) — the number of points. Each of the next $$$n$$$ lines contains two integers $$$x_i$$$ and $$$y_i$$$ ($$$-10^8 \leq x_i, y_i \leq 10^8$$$) — the coordinates of point $$$p_i$$$. The set of points is guaranteed to be convex, all points ar... | standard output | standard input | Python 2 | Python | 2,100 | train_026.jsonl | bd41715d0639fbd0991e1924adcb4216 | 256 megabytes | ["4\n2 4\n4 3\n3 0\n1 3", "3\n0 0\n0 2\n2 0"] | PASSED | n = int(raw_input())
X = []
Y = []
for _ in range(n):
x,y = map(int,raw_input().strip(' ').strip('\n').split(' '))
X.append(x)
Y.append(y)
maxx,minx = max(X),min(X)
maxy,miny = max(Y),min(Y)
ans = -10e18
for i in range(n):
dx = max(maxx-X[i],X[i]-minx)
dy = max(maxy-Y[i],Y[i]-miny)
ans = max(an... | 1541355000 | [
"geometry"
] | [
0,
1,
0,
0,
0,
0,
0,
0
] | |
2 seconds | ["1", "24"] | f5cb28bf83f3b1b7c7df4037e65bddf2 | NoteIn the first example, there is only one non-empty subset {1} with cost 11 = 1.In the second example, there are seven non-empty subsets.- {1} with cost 12 = 1- {2} with cost 12 = 1- {1, 2} with cost 22 = 4- {3} with cost 12 = 1- {1, 3} with cost 22 = 4- {2, 3} with cost 22 = 4- {1, 2, 3} with cost 32 = 9The total co... | You have a team of N people. For a particular task, you can pick any non-empty subset of people. The cost of having x people for the task is xk. Output the sum of costs over all non-empty subsets of people. | Output the sum of costs for all non empty subsets modulo 109 + 7. | Only line of input contains two integers N (1 ≤ N ≤ 109) representing total number of people and k (1 ≤ k ≤ 5000). | standard output | standard input | PyPy 2 | Python | 2,400 | train_036.jsonl | 88fc6f288789e850ed1f3dbb9b506b14 | 256 megabytes | ["1 1", "3 2"] | PASSED | import sys
range = xrange
input = raw_input
N,K = [int(x) for x in input().split()]
MOD = 10**9+7
coeff = [0]*(K+1)
coeff[0] = 1
for iters in range(K):
#print coeff
for i in reversed(range(iters+1)):
coeff[i+1] += coeff[i]
coeff[i]= coeff[i]*i%MOD
#print coeff
mod2inv = 500000004
pow2 = pow... | 1518705300 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["3", "1680"] | faf2c92c3a61ba5e33160bc7a18ad928 | NoteIn the first sample, we have 2 balls of color 1, 2 balls of color 2, and 1 ball of color 3. The three ways for Kyoya are: 1 2 1 2 31 1 2 2 32 1 1 2 3 | Kyoya Ootori has a bag with n colored balls that are colored with k different colors. The colors are labeled from 1 to k. Balls of the same color are indistinguishable. He draws balls from the bag one by one until the bag is empty. He noticed that he drew the last ball of color i before drawing the last ball of color i... | A single integer, the number of ways that Kyoya can draw the balls from the bag as described in the statement, modulo 1 000 000 007. | The first line of input will have one integer k (1 ≤ k ≤ 1000) the number of colors. Then, k lines will follow. The i-th line will contain ci, the number of balls of the i-th color (1 ≤ ci ≤ 1000). The total number of balls doesn't exceed 1000. | standard output | standard input | Python 2 | Python | 1,500 | train_029.jsonl | 6ff623793a4889c1c5c6550fa317c279 | 256 megabytes | ["3\n2\n2\n1", "4\n1\n2\n3\n4"] | PASSED | import math
ncol = int(raw_input())
#print ncol
col = []
n = 0
for i in range(0,ncol):
col.append(int(raw_input()))
n += col[i]
#print n
m = 1
length = col[0]
for i in range(1,ncol):
k2 = col[i]
m *= math.factorial(length+k2-1)/(math.factorial(k2-1)*math.factorial(length))
length += k2
m = m%1000... | 1435163400 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["7 7\n1 2 3\n2 3 2\n3 4 2\n2 4 4", "7 13\n1 2 2\n1 3 4\n1 4 3\n4 5 4"] | c0eec5938787a63fce3052b7e209eda3 | NoteThe graph of sample 1: Shortest path sequence: {1, 2, 3, 4}. MST edges are marked with an asterisk (*).Definition of terms used in the problem statement:A shortest path in an undirected graph is a sequence of vertices (v1, v2, ... , vk) such that vi is adjacent to vi + 1 1 ≤ i < k and the sum of weight is mini... | Jamie has recently found undirected weighted graphs with the following properties very interesting: The graph is connected and contains exactly n vertices and m edges. All edge weights are integers and are in range [1, 109] inclusive. The length of shortest path from 1 to n is a prime number. The sum of edges' weig... | In the first line output 2 integers sp, mstw (1 ≤ sp, mstw ≤ 1014) — the length of the shortest path and the sum of edges' weights in the minimum spanning tree. In the next m lines output the edges of the graph. In each line output 3 integers u, v, w (1 ≤ u, v ≤ n, 1 ≤ w ≤ 109) describing the edge connecting u and v an... | First line of input contains 2 integers n, m — the required number of vertices and edges. | standard output | standard input | Python 2 | Python | 1,600 | train_002.jsonl | 5b26c2c16cca9df949466059016f9c87 | 256 megabytes | ["4 4", "5 4"] | PASSED | def main():
n, m = map(int, raw_input().split())
if n == 2:
print 2, 2
print 1, 2, 2
quit()
else:
print 2, 100003
for i in xrange(2, n - 1):
print 1, i, 1
print 1, n - 1, 100003 - n + 1
print 1, n, 2
c, d = 2, 3
for _ in xrange(m - n + 1):
... | 1516372500 | [
"graphs"
] | [
0,
0,
1,
0,
0,
0,
0,
0
] | |
5 seconds | ["7 8 9 4 5 6 1 2 3"] | 32077a3111c3f28ad56eab0c085a882d | null | You are given a permutation of the numbers 1, 2, ..., n and m pairs of positions (aj, bj).At each step you can choose a pair from the given positions and swap the numbers in that positions. What is the lexicographically maximal permutation one can get?Let p and q be two permutations of the numbers 1, 2, ..., n. p is le... | Print the only line with n distinct integers p'i (1 ≤ p'i ≤ n) — the lexicographically maximal permutation one can get. | The first line contains two integers n and m (1 ≤ n, m ≤ 106) — the length of the permutation p and the number of pairs of positions. The second line contains n distinct integers pi (1 ≤ pi ≤ n) — the elements of the permutation p. Each of the last m lines contains two integers (aj, bj) (1 ≤ aj, bj ≤ n) — the pairs of ... | standard output | standard input | PyPy 2 | Python | 1,700 | train_036.jsonl | 5f3adb1f8b18c3213117f90794273be5 | 256 megabytes | ["9 6\n1 2 3 4 5 6 7 8 9\n1 4\n4 7\n2 5\n5 8\n3 6\n6 9"] | PASSED | n, m = map(int, raw_input().split())
val = [_ for _ in map(int, raw_input().split())]
adj = [[] for _ in range(n)]
for i in range(m):
a, b = map(int, raw_input().split())
adj[a - 1].append(b - 1)
adj[b - 1].append(a - 1)
vis = [False for _ in range(n)]
for v in range(n):
if vis[v] or len(adj[v]) == 0... | 1468425600 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["? 1 2 1 1 1 3\n? 1 2 2 1 2 3\n? 1 2 3 1 3 3\n? 1 1 1 1 1 2\n! 2"] | f1b4048e5cd2aa0a533af9d08f7d58ba | NoteIn the example test the matrix $$$a$$$ of size $$$3 \times 4$$$ is equal to: 1 2 1 23 3 3 32 1 2 1 | This is an interactive problem.There exists a matrix $$$a$$$ of size $$$n \times m$$$ ($$$n$$$ rows and $$$m$$$ columns), you know only numbers $$$n$$$ and $$$m$$$. The rows of the matrix are numbered from $$$1$$$ to $$$n$$$ from top to bottom, and columns of the matrix are numbered from $$$1$$$ to $$$m$$$ from left to... | When ready, print a line with an exclamation mark ('!') and then the answer — the number of suitable pairs $$$(r, c)$$$. After that your program should terminate. | The first line contains two integers $$$n$$$ and $$$m$$$ ($$$1 \le n, m \le 1000$$$) — the number of rows and columns, respectively. | standard output | standard input | Python 3 | Python | 2,600 | train_105.jsonl | 69807fc8ec9bc8172ce430138c0a162a | 256 megabytes | ["3 4\n1\n1\n1\n0"] | PASSED | import sys
input = sys.stdin.readline
def solve():
r, c = map(int, input().split())
r1 = r
r2 = r
i = 2
while True:
if r2 % i == 0:
while r2 % i == 0:
r2 //= i
while r1 % i == 0:
#print('r',i)
if i == 2:
print('?',r1//i,c,1,1,r1//i+1,1)
sys.stdout.flush()
if i... | 1615039500 | [
"number theory"
] | [
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1,
0,
0,
0
] | |
2 seconds | ["4", "20"] | ecbc339ad8064681789075f9234c269a | null | In one one-dimensional world there are n platforms. Platform with index k (platforms are numbered from 1) is a segment with coordinates [(k - 1)m, (k - 1)m + l], and l < m. Grasshopper Bob starts to jump along the platforms from point 0, with each jump he moves exactly d units right. Find out the coordinate of the p... | Output the coordinates of the point, where the grosshopper will fall down. Don't forget that if Bob finds himself on the platform edge, he doesn't fall down. | The first input line contains 4 integer numbers n, d, m, l (1 ≤ n, d, m, l ≤ 106, l < m) — respectively: amount of platforms, length of the grasshopper Bob's jump, and numbers m and l needed to find coordinates of the k-th platform: [(k - 1)m, (k - 1)m + l]. | standard output | standard input | PyPy 3 | Python | 1,700 | train_038.jsonl | a2b652b157428b0c0ef5c47464f7a96e | 64 megabytes | ["2 2 5 3", "5 4 11 8"] | PASSED | #Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
import collections
from itertools import permutations
from collections import defaultdict
from collections import deque
import threadi... | 1276700400 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
3 seconds | ["3 1 1 \n700000000 700000000 \n0 0 0 0 0 \n0 0 2 1 0 \n0 0 \n9 9 999999990 \n0 0 0 \n3 1 3 1 1 1 \n0 0", "0 1 1 0 0 0 0 0 \n0 0 0 0 0 0 0 0 0 \n0 0 0 3 1 1 3 0 0 \n0 2 0 0 2 5 9 1 4"] | 9be594097a1b2249c4227bde12c5552c | NoteIn the first test case of the first sample there is only one segment of color $$$2$$$, and all other segments have color $$$1$$$. Therefore, for segments of color $$$1$$$, the answer is equal to the distance to the $$$3$$$rd segment, and for $$$3$$$rd one, the answer is equal to the minimum of the distances to segm... | Dmitry has $$$n$$$ segments of different colors on the coordinate axis $$$Ox$$$. Each segment is characterized by three integers $$$l_i$$$, $$$r_i$$$ and $$$c_i$$$ ($$$1 \le l_i \le r_i \le 10^9, 1 \le c_i \le n$$$), where $$$l_i$$$ and $$$r_i$$$ are are the coordinates of the ends of the $$$i$$$-th segment, and $$$c_i... | For each test case, on a separate line print $$$n$$$ integers, where the $$$i$$$-th number is equal to the distance from the $$$i$$$-th segment to the nearest segment of a different color. | The first line of the input contains an integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases in the test. The descriptions of the test cases follow. The first line of description of each test case contains one integer $$$n$$$ ($$$2 \le n \le 2 \cdot 10^5$$$) — the number of segments. The next $$$n$$$ lin... | standard output | standard input | Python 3 | Python | 2,000 | train_084.jsonl | ee26ba0f05f2664ce9bc05badfd3fa9d | 256 megabytes | ["9\n\n3\n\n1 2 1\n\n3 4 1\n\n5 6 2\n\n2\n\n100000000 200000000 1\n\n900000000 1000000000 2\n\n5\n\n1 2 1\n\n2 3 2\n\n3 4 3\n\n4 5 4\n\n5 6 5\n\n5\n\n1 5 1\n\n4 9 2\n\n1 2 1\n\n8 9 2\n\n5 7 3\n\n2\n\n1 100 2\n\n10 90 1\n\n3\n\n1 1 1\n\n10 10 2\n\n1000000000 1000000000 3\n\n3\n\n3 4 1\n\n2 5 1\n\n1 6 2\n\n6\n\n5 6 2\n\n... | PASSED | t = int(input())
def dist(i,j):
if i >= j:
return 0
else:
return j-i
while t > 0:
n = int(input())
seg = []
for i in range(n):
seg.append(list(map(int,input().split()))+[i+1])
seg.sort(key=lambda x:(x[0],x[1]))
color = {}
i = 0
while i < n:
... | 1665498900 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
3 seconds | ["4", "629909355", "675837193"] | 7ad1f3f220c12a68c1242a22f4fd7761 | NoteFor the first sample case, the first player has $$$4$$$ possible moves. No matter what the first player plays, the second player only has $$$1$$$ possible move, so there are $$$4$$$ possible games. | Omkar and Akmar are playing a game on a circular board with $$$n$$$ ($$$2 \leq n \leq 10^6$$$) cells. The cells are numbered from $$$1$$$ to $$$n$$$ so that for each $$$i$$$ ($$$1 \leq i \leq n-1$$$) cell $$$i$$$ is adjacent to cell $$$i+1$$$ and cell $$$1$$$ is adjacent to cell $$$n$$$. Initially, each cell is empty.O... | Output a single integer — the number of possible distinct games where both players play optimally modulo $$$10^9+7$$$. | The only line will contain an integer $$$n$$$ ($$$2 \leq n \leq 10^6$$$) — the number of cells on the board. | standard output | standard input | Python 3 | Python | 2,600 | train_094.jsonl | 0ca1ebea0d32ae542243957267a7ece4 | 256 megabytes | ["2", "69420", "42069"] | PASSED | from math import factorial
def win(a):
bw = None;bc = 0
for i in range(len(a)):
if a[i] is None:
for j in range(2):
if a[i-1] == j or a[(i+1)%len(a)] == j:continue
a[i] = j;w, c = win(a);a[i] = None
if bw != False:
bw = w
if w == False:bc = c
else:bc += c
else:bc += c
... | 1622990100 | [
"geometry",
"math",
"games"
] | [
1,
1,
0,
1,
0,
0,
0,
0
] | |
1 second | ["10\n0\n4"] | 128d9ad5e5dfe4943e16fcc6a103e51b | NoteIn the first test case, we initially have a piece of size $$$1$$$, so all final pieces must have size $$$1$$$. The total number of steps is: $$$0 + 1 + 2 + 3 + 4 = 10$$$.In the second test case, we have just one piece, so we don't need to do anything, and the answer is $$$0$$$ steps.In the third test case, one of t... | There are $$$n$$$ pieces of tangerine peel, the $$$i$$$-th of them has size $$$a_i$$$. In one step it is possible to divide one piece of size $$$x$$$ into two pieces of positive integer sizes $$$y$$$ and $$$z$$$ so that $$$y + z = x$$$.You want that for each pair of pieces, their sizes differ strictly less than twice. ... | For each test case, output a single line containing the minimum number of steps. | The first line of the input contains a single integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases. The description of test cases follows. The first line of each test case contains the integer $$$n$$$ ($$$1 \le n \le 100$$$). Then one line follows, containing $$$n$$$ integers $$$a_1 \le a_2 \le \ldots \le... | standard output | standard input | Python 3 | Python | 900 | train_098.jsonl | c178e0e806b0ecf466dece9e12880c67 | 256 megabytes | ["3\n\n5\n\n1 2 3 4 5\n\n1\n\n1033\n\n5\n\n600 900 1300 2000 2550"] | PASSED | def f(x,m):
if x%(2*m-1)!=0:
return x//(2*m-1)
else:
return x//(2*m-1)-1
N=int(input())
for i in range(N):
n=int(input())
L=list(map(int,input().split()))
M=max(L)
m=min(L)
L1=[x for x in L if x>=2*m]
Lm=[m for i in range(len(L1))]
L2=list(map(f,L1,Lm))
... | 1664721300 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["1\n2\n2\n10\n5\n9"] | 1f29461c42665523d0a4d56b13f7e480 | NoteIn the first example, Tanya can eat candies for one day only. She can eat any pair of candies this day because all of them have different colors.In the second example, Tanya can eat candies for two days. For example, she can eat red and green candies on the first day, and green and blue candies on the second day.In... | You have three piles of candies: red, green and blue candies: the first pile contains only red candies and there are $$$r$$$ candies in it, the second pile contains only green candies and there are $$$g$$$ candies in it, the third pile contains only blue candies and there are $$$b$$$ candies in it. Each day Tanya ea... | Print $$$t$$$ integers: the $$$i$$$-th printed integer is the answer on the $$$i$$$-th test case in the input. | The first line contains integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases in the input. Then $$$t$$$ test cases follow. Each test case is given as a separate line of the input. It contains three integers $$$r$$$, $$$g$$$ and $$$b$$$ ($$$1 \le r, g, b \le 10^8$$$) — the number of red, green and blue ca... | standard output | standard input | PyPy 3 | Python | 1,100 | train_008.jsonl | 78c76e91c876168cff4ab60aae4818a6 | 256 megabytes | ["6\n1 1 1\n1 2 1\n4 1 1\n7 4 10\n8 1 4\n8 2 8"] | PASSED | n = int(input())
for _ in range(n):
a = list(map(int, input().split()))
a = sorted(a)
if(a[0]+a[1] >= a[2]):
print(sum(a)//2);
else:
print(sum(a)-a[2]);
| 1575038100 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["3", "9", "130653412"] | 1b336555c94d5d5198abe5426ff6fa7a | NoteFor a detailed definition of bitwise AND we recommend to take a look in the corresponding article in Wikipedia.In the first sample, there are 3 possible solutions: z&_ = 61&63 = 61 = z _&z = 63&61 = 61 = z z&z = 61&61 = 61 = z | While walking down the street Vanya saw a label "Hide&Seek". Because he is a programmer, he used & as a bitwise AND for these two words represented as a integers in base 64 and got new word. Now Vanya thinks of some string s and wants to know the number of pairs of words of length |s| (length of s), such that t... | Print a single integer — the number of possible pairs of words, such that their bitwise AND is equal to string s modulo 109 + 7. | The only line of the input contains a single word s (1 ≤ |s| ≤ 100 000), consisting of digits, lowercase and uppercase English letters, characters '-' and '_'. | standard output | standard input | PyPy 2 | Python | 1,500 | train_007.jsonl | 7f2ae05a46346d3040611ddacd32d9cc | 256 megabytes | ["z", "V_V", "Codeforces"] | PASSED | s = raw_input()
d = 0
ans = 1
for c in map(ord, s):
d = 0
if ord("0") <= c <= ord("9"):
d += c - ord("0")
elif ord("A") <= c <= ord("Z"):
d += c - ord("A") + 10
elif ord("a") <= c <= ord("z"):
d += c - ord("a") + 36
elif ord("-") == c:
d += 62
else:
d += 63
ans *= pow(3, format(d, "06b").count("0"), ... | 1464798900 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
2 seconds | ["Yes\nNo\nYes\nYes\nNo\nYes\nNo\nNo\nYes\nNo"] | 2d27f3530aa140be0add639a1edfd880 | NoteThe first test case is clarified above.In the second test case, it is impossible to make all array elements equal.In the third test case, you need to apply this operation once to all elements equal to $$$5$$$.In the fourth test case, you need to apply this operation to all elements until they become equal to $$$8$$... | You are given an array of $$$n$$$ integers $$$a_1, a_2, \dots, a_n$$$You can apply the following operation an arbitrary number of times: select an index $$$i$$$ ($$$1 \le i \le n$$$) and replace the value of the element $$$a_i$$$ with the value $$$a_i + (a_i \bmod 10)$$$, where $$$a_i \bmod 10$$$ is the remainder of ... | For each test case print: YES if it is possible to make all array elements equal; NO otherwise. You can print YES and NO in any case (for example, the strings yEs, yes, Yes and YES will be recognized as a positive answer) . | The first line contains one integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of test cases. What follows is a description of each test case. The first line of each test case contains one integer $$$n$$$ ($$$1 \le n \le 2 \cdot 10^5$$$) — the size of the array. The second line of each test case contains $$$n$$$ int... | standard output | standard input | PyPy 3-64 | Python | 1,400 | train_103.jsonl | 3d2093b68a460abe765d08ba42298b9f | 256 megabytes | ["10\n\n2\n\n6 11\n\n3\n\n2 18 22\n\n5\n\n5 10 5 10 5\n\n4\n\n1 2 4 8\n\n2\n\n4 5\n\n3\n\n93 96 102\n\n2\n\n40 6\n\n2\n\n50 30\n\n2\n\n22 44\n\n2\n\n1 5"] | PASSED | t = int(input())
for ti in range(t):
n = int(input())
a = sorted(list(map(int, input().split())))
is0 = False
res = "YES"
while a[0] % 10 != 2:
a[0] += a[0] % 10
if a[0] % 10 == 0:
is0 = True
break
for i in range(n - 1):
while a[i + 1] ... | 1659364500 | [
"number theory",
"math"
] | [
0,
0,
0,
1,
1,
0,
0,
0
] | |
2 seconds | ["1\n2"] | 7b80d3f3cd4f93e4277c76c76dc41f42 | NoteIn the first test case, you can do the following to achieve a length of $$$1$$$:Pick $$$i=2$$$ to get $$$[2, 4, 1]$$$Pick $$$i=1$$$ to get $$$[6, 1]$$$Pick $$$i=1$$$ to get $$$[7]$$$In the second test case, you can't perform any operations because there is no valid $$$i$$$ that satisfies the requirements mentioned ... | Lord Omkar has permitted you to enter the Holy Church of Omkar! To test your worthiness, Omkar gives you a password which you must interpret!A password is an array $$$a$$$ of $$$n$$$ positive integers. You apply the following operation to the array: pick any two adjacent numbers that are not equal to each other and rep... | For each password, print one integer: the shortest possible length of the password after some number of operations. | Each test contains multiple test cases. The first line contains the number of test cases $$$t$$$ ($$$1 \le t \le 100$$$). Description of the test cases follows. The first line of each test case contains an integer $$$n$$$ ($$$1 \leq n \leq 2 \cdot 10^5$$$) — the length of the password. The second line of each test case... | standard output | standard input | PyPy 2 | Python | 800 | train_003.jsonl | 581c7f544173e2b83ed06c0109da7265 | 256 megabytes | ["2\n4\n2 1 3 1\n2\n420 420"] | PASSED | from __future__ import division, print_function
import os,sys
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
from __builtin__ import xrange as range
from future_builtins import ascii, filter, hex, map, oct, zip
def ii(): return int(input())
def si(): return input()
def mi(): return map(in... | 1597588500 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["ACC\nACC\nACC\nWA\nACC\nACC\nWA", "WA\nACC\nACC"] | 95ccc87fe9e431f9c6eeffeaf049f797 | null | After the contest in comparing numbers, Shapur's teacher found out that he is a real genius and that no one could possibly do the calculations faster than him even using a super computer!Some days before the contest, the teacher took a very simple-looking exam and all his n students took part in the exam. The teacher g... | For each student write in a different line. Print "WA" if his answer is wrong or "ACC" if his answer is OK. | The first three lines contain a string each. These are the initial strings. They consists only of lowercase and uppercase Latin letters and signs ("-", ";" and "_"). All the initial strings have length from 1 to 100, inclusively. In the fourth line there is a single integer n (0 ≤ n ≤ 1000), the number of students. Nex... | standard output | standard input | PyPy 3 | Python | 1,300 | train_030.jsonl | c6f70d857fd53d32b24fe65ee7a5aa54 | 256 megabytes | ["Iran_\nPersian;\nW_o;n;d;e;r;f;u;l;\n7\nWonderfulPersianIran\nwonderful_PersIAN_IRAN;;_\nWONDERFUL___IRAN__PERSIAN__;;\nIra__Persiann__Wonderful\nWonder;;fulPersian___;I;r;a;n;\n__________IranPersianWonderful__________\nPersianIran_is_Wonderful", "Shapur;;\nis___\na_genius\n3\nShapur__a_is___geniUs\nis___shapur___a__... | PASSED | def s():
import re,itertools
pattern = re.compile('[^a-z]+')
def st(x):
return pattern.sub('',x.lower())
s = set([''.join(i)for i in itertools.permutations([st(input())for _ in range(3)])])
for i in range(int(input())):
print('ACC'if st(input()) in s else 'WA')
s() | 1298390400 | [
"strings"
] | [
0,
0,
0,
0,
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0,
1,
0
] | |
2 seconds | ["1", "5"] | c15ad483441864b3222eb62723b598e1 | NoteIn the first example the only element can be removed. | You are given a permutation p of length n. Remove one element from permutation to make the number of records the maximum possible.We remind that in a sequence of numbers a1, a2, ..., ak the element ai is a record if for every integer j (1 ≤ j < i) the following holds: aj < ai. | Print the only integer — the element that should be removed to make the number of records the maximum possible. If there are multiple such elements, print the smallest one. | The first line contains the only integer n (1 ≤ n ≤ 105) — the length of the permutation. The second line contains n integers p1, p2, ..., pn (1 ≤ pi ≤ n) — the permutation. All the integers are distinct. | standard output | standard input | Python 3 | Python | 1,700 | train_005.jsonl | ce3aabd502c6918c7a3f96acb2c5ac21 | 256 megabytes | ["1\n1", "5\n5 1 2 3 4"] | PASSED | import sys
cases = sys.stdin.readline()
my_list = [int(a) for a in sys.stdin.readline().split(" ")]
#my_list = [4, 5, 3, 2, 1]
max_val_a = my_list[0]
max_val_b = 0
my_counts = dict()
for x in my_list:
my_counts[x] = 0
my_counts[max_val_a] = -1
for x in my_list:
#print(my_counts)
if(x > max_val_a):
my_cou... | 1513008300 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["3 6\n4 5\n3 4\n1 9\n2 3\n4 5\n6 10"] | 96fac9f9377bf03e144067bf93716d3d | NoteIn the first test case, $$$b = \{3+6, 4+5\} = \{9, 9\}$$$ and $$$\mathrm{gcd}(9, 9) = 9$$$.In the second test case, $$$b = \{9+10\} = \{19\}$$$ and $$$\mathrm{gcd}(19) = 19$$$.In the third test case, $$$b = \{1+2, 3+3, 4+5, 90+3\} = \{3, 6, 9, 93\}$$$ and $$$\mathrm{gcd}(3, 6, 9, 93) = 3$$$. | Ashish has an array $$$a$$$ of consisting of $$$2n$$$ positive integers. He wants to compress $$$a$$$ into an array $$$b$$$ of size $$$n-1$$$. To do this, he first discards exactly $$$2$$$ (any two) elements from $$$a$$$. He then performs the following operation until there are no elements left in $$$a$$$: Remove any... | For each test case, output $$$n-1$$$ lines — the operations performed to compress the array $$$a$$$ to the array $$$b$$$. The initial discard of the two elements is not an operation, you don't need to output anything about it. The $$$i$$$-th line should contain two integers, the indices ($$$1$$$ —based) of the two elem... | The first line contains a single integer $$$t$$$ ($$$1 \leq t \leq 10$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains a single integer $$$n$$$ ($$$2 \leq n \leq 1000$$$). The second line of each test case contains $$$2n$$$ integers $$$a_1, a_2, \ldots... | standard output | standard input | Python 3 | Python | 1,100 | train_016.jsonl | 9b97c90fcc9a49511e40527837170e52 | 256 megabytes | ["3\n3\n1 2 3 4 5 6\n2\n5 7 9 10\n5\n1 3 3 4 5 90 100 101 2 3"] | PASSED | # cook your dish here
T=int(input())
for _ in range(T):
n=int(input())
s=list(map(int,input().split()))
odd=[]
even=[]
for i in range(len(s)):
if(s[i]%2!=0):
odd.append(i+1)
else:
even.append(i+1)
count=0
for i in range(0,len(odd)-1,2):
if(... | 1592663700 | [
"number theory",
"math"
] | [
0,
0,
0,
1,
1,
0,
0,
0
] | |
2 seconds | ["3\n1\n3\n0"] | e0de8a6441614d1e41a53223b5fa576b | NoteThe first test case is explained in the statements.In the second test case, you need to make one move for $$$i=2$$$.The third test case you need to make three moves: the first move: $$$i=9$$$; the second move: $$$i=9$$$; the third move: $$$i=2$$$. In the fourth test case, the values $$$c_0$$$, $$$c_1$$$ and $$$... | You are given a number $$$n$$$ (divisible by $$$3$$$) and an array $$$a[1 \dots n]$$$. In one move, you can increase any of the array elements by one. Formally, you choose the index $$$i$$$ ($$$1 \le i \le n$$$) and replace $$$a_i$$$ with $$$a_i + 1$$$. You can choose the same index $$$i$$$ multiple times for different... | For each test case, output one integer — the minimum number of moves that must be made for the $$$a$$$ array to make it have balanced remainders. | The first line contains one integer $$$t$$$ ($$$1 \le t \le 10^4$$$). Then $$$t$$$ test cases follow. The first line of each test case contains one integer $$$n$$$ ($$$3 \le n \le 3 \cdot 10^4$$$) — the length of the array $$$a$$$. It is guaranteed that the number $$$n$$$ is divisible by $$$3$$$. The next line contains... | standard output | standard input | PyPy 3-64 | Python | 1,000 | train_098.jsonl | 4c879f2d0fbc86b5275d7ea344a96adf | 256 megabytes | ["4\n6\n0 2 5 5 4 8\n6\n2 0 2 1 0 0\n9\n7 1 3 4 2 10 3 9 6\n6\n0 1 2 3 4 5"] | PASSED | for _ in range(int(input())):
n = int(input())
arr = list(map(int, input().split()))
count = 0
ht = {0: 0, 1: 0, 2: 0}
for i in arr:
ht[i % 3] += 1
while True:
# print(ht)
diff = 1
if ht[0] == ht[1] == ht[2]:
print(count)
break
if h... | 1613486100 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["Yes", "No", "Yes"] | bedb98780a71d7027798d14aa5f1f100 | NoteThe picture below illustrates one of the possible trees for the first example. The picture below illustrates one of the possible trees for the third example. | Dima the hamster enjoys nibbling different things: cages, sticks, bad problemsetters and even trees!Recently he found a binary search tree and instinctively nibbled all of its edges, hence messing up the vertices. Dima knows that if Andrew, who has been thoroughly assembling the tree for a long time, comes home and see... | If it is possible to reassemble the binary search tree, such that the greatest common divisor of any two vertices connected by the edge is greater than $$$1$$$, print "Yes" (quotes for clarity). Otherwise, print "No" (quotes for clarity). | The first line contains the number of vertices $$$n$$$ ($$$2 \le n \le 700$$$). The second line features $$$n$$$ distinct integers $$$a_i$$$ ($$$2 \le a_i \le 10^9$$$) — the values of vertices in ascending order. | standard output | standard input | PyPy 3 | Python | 2,100 | train_061.jsonl | c3d37b01356f6d8acc95dce16f758cde | 256 megabytes | ["6\n3 6 9 18 36 108", "2\n7 17", "9\n4 8 10 12 15 18 33 44 81"] | PASSED | from sys import stdin
from math import gcd
n=int(stdin.readline())
a=[int(x) for x in stdin.readline().split()]
c = []
ld=[]
rd=[]
def check(l, r, e):
if r == l: return c[l][e] > 0
if e < l and ld[l][r-l] != 0:
return ld[l][r-l] == 1
elif e > r and rd[l][r-l] != 0:
return rd[l][r-l] == 1
... | 1534685700 | [
"number theory",
"math",
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] | [
0,
0,
0,
1,
1,
0,
0,
1
] | |
1 second | ["1337\n0"] | edf394051c6b35f593abd4c34b091eae | NoteIn the first test case you can perform the following sequence of operations: first, second, first. This way you spend $$$391 + 555 + 391 = 1337$$$ dollars.In the second test case both integers are equal to zero initially, so you dont' have to spend money. | You are given two integers $$$x$$$ and $$$y$$$. You can perform two types of operations: Pay $$$a$$$ dollars and increase or decrease any of these integers by $$$1$$$. For example, if $$$x = 0$$$ and $$$y = 7$$$ there are four possible outcomes after this operation: $$$x = 0$$$, $$$y = 6$$$; $$$x = 0$$$, $$$y = 8$... | For each test case print one integer — the minimum amount of dollars you have to spend. | The first line contains one integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of testcases. The first line of each test case contains two integers $$$x$$$ and $$$y$$$ ($$$0 \le x, y \le 10^9$$$). The second line of each test case contains two integers $$$a$$$ and $$$b$$$ ($$$1 \le a, b \le 10^9$$$). | standard output | standard input | Python 3 | Python | 1,000 | train_017.jsonl | fce6803770ef2dfbdcde7627ba335e5f | 256 megabytes | ["2\n1 3\n391 555\n0 0\n9 4"] | PASSED | t=int(input())
while(t>0):
t=t-1
l=[]
x,y=map(int,input().split())
a,b=map(int,input().split())
if(x==0 and y==0):
print(x)
elif(x>y):
a1=x-y
a1=a1*a
b1=y
b1=b1*b
l.append(abs(a1)+b1)
a1=x*a
b1=y*a
l.append(abs(a1)+b1)
... | 1587911700 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["42", "7"] | 9044eacc1833c667985c343a71fb4a58 | NoteThe image for the first example: Several key points are marked blue, the answer contains some non-marked points as well.The image for the second example: | You are given $$$n$$$ segments on a Cartesian plane. Each segment's endpoints have integer coordinates. Segments can intersect with each other. No two segments lie on the same line.Count the number of distinct points with integer coordinates, which are covered by at least one segment. | Print a single integer — the number of distinct points with integer coordinates, which are covered by at least one segment. | The first line contains a single integer $$$n$$$ ($$$1 \le n \le 1000$$$) — the number of segments. Each of the next $$$n$$$ lines contains four integers $$$Ax_i, Ay_i, Bx_i, By_i$$$ ($$$-10^6 \le Ax_i, Ay_i, Bx_i, By_i \le 10^6$$$) — the coordinates of the endpoints $$$A$$$, $$$B$$$ ($$$A \ne B$$$) of the $$$i$$$-th s... | standard output | standard input | PyPy 3 | Python | 2,400 | train_030.jsonl | e8da77cb46ac51e2c16d6199d540469a | 256 megabytes | ["9\n0 0 4 4\n-1 5 4 0\n4 0 4 4\n5 2 11 2\n6 1 6 7\n5 6 11 6\n10 1 10 7\n7 0 9 8\n10 -1 11 -1", "4\n-1 2 1 2\n-1 0 1 0\n-1 0 0 3\n0 3 1 0"] | PASSED | from math import gcd
from bisect import *
class Point:
def __init__(self, x, y):
self.x, self.y = x, y
def __add__(self, val):
return Point(self.x + val.x, self.y + val.y)
def __sub__(self, val):
return Point(self.x - val.x, self.y - val.y)
def __mul__(self, ratio):
retu... | 1536330900 | [
"number theory",
"geometry"
] | [
0,
1,
0,
0,
1,
0,
0,
0
] | |
1 second | ["2\n1 2 \n1\n3", "3\n4 1 3 \n2\n5 2"] | 0937a7e2f912fc094cc4275fd47cd457 | NoteLet's consider the first sample test. There we send the first and the second boy to the first team and the third boy to the second team. Let's check all three conditions of a fair division. The first limitation is fulfilled (all boys play), the second limitation on the sizes of groups (|2 - 1| = 1 ≤ 1) is fulfilled... | Petya loves football very much, especially when his parents aren't home. Each morning he comes to the yard, gathers his friends and they play all day. From time to time they have a break to have some food or do some chores (for example, water the flowers).The key in football is to divide into teams fairly before the ga... | On the first line print an integer x — the number of boys playing for the first team. On the second line print x integers — the individual numbers of boys playing for the first team. On the third line print an integer y — the number of boys playing for the second team, on the fourth line print y integers — the individu... | The first line contains the only integer n (2 ≤ n ≤ 105) which represents the number of guys in the yard. The next line contains n positive space-separated integers, ai (1 ≤ ai ≤ 104), the i-th number represents the i-th boy's playing skills. | standard output | standard input | Python 3 | Python | 1,500 | train_024.jsonl | e090f3bd4d35427b7cdf99338edfc957 | 256 megabytes | ["3\n1 2 1", "5\n2 3 3 1 1"] | PASSED | n = int(input())
a = list(map(int, input().split()))
all = []
for i in range(n):
all.append([a[i], i + 1])
all.sort(key = lambda x: x[0])
team_1 = []
team_2 = []
for i in range(n):
if i % 2 == 0:
team_1.append(all[i][1])
else:
team_2.append(all[i][1])
print(len(team_1))
print(*team_1)
pri... | 1328886000 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["YES\nNO"] | 465f1c612fa43313005d90cc8e9e6a24 | NoteHere is a visualization of the first test case (the orange values denote the initial values and the blue ones the desired values): One possible order of operations to obtain the desired values for each node is the following: Operation $$$1$$$: Add $$$2$$$ to nodes $$$2$$$ and $$$3$$$. Operation $$$2$$$: Add $$$... | You have a connected undirected graph made of $$$n$$$ nodes and $$$m$$$ edges. The $$$i$$$-th node has a value $$$v_i$$$ and a target value $$$t_i$$$.In an operation, you can choose an edge $$$(i, j)$$$ and add $$$k$$$ to both $$$v_i$$$ and $$$v_j$$$, where $$$k$$$ can be any integer. In particular, $$$k$$$ can be nega... | For each test case, if it is possible for every node to reach its target after some number of operations, print "YES". Otherwise, print "NO". | The first line contains a single integer $$$t$$$ ($$$1 \leq t \leq 1000$$$), the number of test cases. Then the test cases follow. The first line of each test case contains two integers $$$n$$$, $$$m$$$ ($$$2 \leq n \leq 2\cdot 10^5$$$, $$$n-1\leq m\leq \min(2\cdot 10^5, \frac{n(n-1)}{2})$$$) — the number of nodes and ... | standard output | standard input | PyPy 3 | Python | 2,200 | train_084.jsonl | 24f06b8c054eb9061543f625a56e741c | 256 megabytes | ["2\n4 4\n5 1 2 -3\n3 3 10 1\n1 2\n1 4\n3 2\n3 4\n4 4\n5 8 6 6\n-3 1 15 4\n1 2\n1 4\n3 2\n3 4"] | PASSED | import bisect
import copy
import decimal
import fractions
import heapq
import itertools
import math
import random
import sys
from collections import Counter, deque,defaultdict
from functools import lru_cache,reduce
from heapq import heappush,heappop,heapify,heappushpop,_heappop_max,_heapify_max
def _heappus... | 1624026900 | [
"math",
"graphs"
] | [
0,
0,
1,
1,
0,
0,
0,
0
] | |
1 second | ["2\n2 3", "1\n2"] | dd26f45869b73137e5e5cc6820cdc2e4 | null | Erelong Leha was bored by calculating of the greatest common divisor of two factorials. Therefore he decided to solve some crosswords. It's well known that it is a very interesting occupation though it can be very difficult from time to time. In the course of solving one of the crosswords, Leha had to solve a simple ta... | In the first line print single integer k — the minimal number of symbols that need to be replaced. In the second line print k distinct integers denoting the positions of symbols in the string s which need to be replaced. Print the positions in any order. If there are several solutions print any of them. The numbering o... | The first line contains two integers n and m (1 ≤ n ≤ m ≤ 1000) — the length of the string s and the length of the string t correspondingly. The second line contains n lowercase English letters — string s. The third line contains m lowercase English letters — string t. | standard output | standard input | PyPy 2 | Python | 1,000 | train_012.jsonl | 06d50f5fefee68e61096267cc049b0c9 | 256 megabytes | ["3 5\nabc\nxaybz", "4 10\nabcd\nebceabazcd"] | PASSED | n, m = map(int, raw_input().split())
s = raw_input()
t = raw_input()
ans = float('inf')
pos = []
for i in xrange(m-n+1):
count = 0
tempPos = []
for j in xrange(n):
if t[i+j] != s[j]:
count += 1
tempPos.append(j+1)
if count < ans:
ans = count
pos = tempP... | 1499011500 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
1 second | ["3"] | 5ea0351ac9f949dedae1928bfb7ebffa | null | Let's introduce the designation , where x is a string, n is a positive integer and operation " + " is the string concatenation operation. For example, [abc, 2] = abcabc.We'll say that string s can be obtained from string t, if we can remove some characters from string t and obtain string s. For example, strings ab and ... | In a single line print an integer — the largest number p. If the required value of p doesn't exist, print 0. | The first line contains two integers b, d (1 ≤ b, d ≤ 107). The second line contains string a. The third line contains string c. The given strings are not empty and consist of lowercase English letters. Their lengths do not exceed 100. | standard output | standard input | Python 2 | Python | 2,000 | train_028.jsonl | 9a74738784a0838c806bfede442df63f | 256 megabytes | ["10 3\nabab\nbab"] | PASSED |
from itertools import repeat,chain
from fractions import gcd
def eternal(c,d, n = None):
while True:
yield chain.from_iterable(repeat(c,d))
def cyclic_array(arr):
n = len(arr)
def cyclar(i):
return arr[i % n]
return cyclar
def find_repeat(enum,q_r_gen, a_n):
a... | 1370619000 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
1 second | ["Bob\nAlice\nAlice"] | 4c5187193cf7f2d2721cedbb15b2a1c3 | NoteIn the first testcase, in her turn, Alice can only choose $$$i = 2$$$, making the array equal $$$[1, 0]$$$. Then Bob, in his turn, will also choose $$$i = 2$$$ and make the array equal $$$[0, 0]$$$. As $$$a_1 = 0$$$, Alice loses.In the second testcase, once again, players can only choose $$$i = 2$$$. Then the array... | Alice and Bob are playing a game on an array $$$a$$$ of $$$n$$$ positive integers. Alice and Bob make alternating moves with Alice going first.In his/her turn, the player makes the following move: If $$$a_1 = 0$$$, the player loses the game, otherwise: Player chooses some $$$i$$$ with $$$2\le i \le n$$$. Then player de... | For each test case, if Alice will win the game, output "Alice". Otherwise, output "Bob". You can output each letter in any case. For example, "alIcE", "Alice", "alice" will all be considered identical. | The input consists of multiple test cases. The first line contains a single integer $$$t$$$ $$$(1 \leq t \leq 2 \cdot 10^4)$$$ — the number of test cases. The description of the test cases follows. The first line of each test case contains a single integer $$$n$$$ $$$(2 \leq n \leq 10^5)$$$ — the length of the array ... | standard output | standard input | Python 3 | Python | 1,200 | train_087.jsonl | 9f687f7bb394d63b4df6f246c7bbbc5f | 256 megabytes | ["3\n\n2\n\n1 1\n\n2\n\n2 1\n\n3\n\n5 4 4"] | PASSED | for i in range(int(input())):
n=int(input())
l=list(map(int,input().split()))
d=min(l)
if d==l[0]:
print("Bob")
else:
print("Alice") | 1667572500 | [
"games"
] | [
1,
0,
0,
0,
0,
0,
0,
0
] | |
1 second | ["1", "8"] | 3b7cafc280a9b0dba567863c80b978b0 | NoteIn the second example, there are six one-element sets. Additionally, there are two two-element sets, the first one consists of the first and the third cells of the first row, the second one consists of the first and the third cells of the second row. To sum up, there are 8 sets. | You are given n × m table. Each cell of the table is colored white or black. Find the number of non-empty sets of cells such that: All cells in a set have the same color. Every two cells in a set share row or column. | Output single integer — the number of non-empty sets from the problem description. | The first line of input contains integers n and m (1 ≤ n, m ≤ 50) — the number of rows and the number of columns correspondingly. The next n lines of input contain descriptions of rows. There are m integers, separated by spaces, in each line. The number equals 0 if the corresponding cell is colored white and equals 1 i... | standard output | standard input | PyPy 2 | Python | 1,300 | train_015.jsonl | 0a5a4486701e3377db660db3213414ac | 256 megabytes | ["1 1\n0", "2 3\n1 0 1\n0 1 0"] | PASSED | n,m = map(int, raw_input().split(" "))
a =[]
for i in range(n):
b = map(int, raw_input().split(" "))
a.append(b)
ans=0
for i in range(n):
d={1:0, 0:0}
for j in a[i]:
if j==0:
d[0]+=1
else:
d[1]+=1
ans+=pow(2,d[0])-1
ans+=pow(2,d[1])-1
c =[[] for i in range... | 1503592500 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["1227\n-1\n17703\n2237344218521717191"] | 8f00837e04627e445dfb8b6cd0216640 | NoteIn the first test case of the example, $$$1227$$$ is already an ebne number (as $$$1 + 2 + 2 + 7 = 12$$$, $$$12$$$ is divisible by $$$2$$$, while in the same time, $$$1227$$$ is not divisible by $$$2$$$) so we don't need to delete any digits. Answers such as $$$127$$$ and $$$17$$$ will also be accepted.In the secon... | Let's define a number ebne (even but not even) if and only if its sum of digits is divisible by $$$2$$$ but the number itself is not divisible by $$$2$$$. For example, $$$13$$$, $$$1227$$$, $$$185217$$$ are ebne numbers, while $$$12$$$, $$$2$$$, $$$177013$$$, $$$265918$$$ are not. If you're still unsure what ebne numbe... | For each test case given in the input print the answer in the following format: If it is impossible to create an ebne number, print "-1" (without quotes); Otherwise, print the resulting number after deleting some, possibly zero, but not all digits. This number should be ebne. If there are multiple answers, you can pri... | The input consists of multiple test cases. The first line contains a single integer $$$t$$$ ($$$1 \le t \le 1000$$$) — the number of test cases. The description of the test cases follows. The first line of each test case contains a single integer $$$n$$$ ($$$1 \le n \le 3000$$$) — the number of digits in the original... | standard output | standard input | Python 3 | Python | 900 | train_005.jsonl | 43ca9ecef047c647f9aaa3a015cbf9dc | 256 megabytes | ["4\n4\n1227\n1\n0\n6\n177013\n24\n222373204424185217171912"] | PASSED | t =int(input())
while t!=0:
t-=1
n=int(input())
s=input()
ar=[]
sar=[]
for i in s:
if i!='0':
ar.append(int(i))
sar.append(i)
if len(ar)==0 or len(ar)==1 :
print(-1)
continue
else:
tsum=sum(ar)
if tsum%2==0 and ar[l... | 1580652300 | [
"math",
"strings"
] | [
0,
0,
0,
1,
0,
0,
1,
0
] | |
2 seconds | ["11.084259940083", "33.121375178000"] | ae8687ed3cb5df080fb6ee79b040cef1 | NoteConsider the first sample.Adil will use the following path: .Bera will use the following path: .Adil's path will be units long, while Bera's path will be units long. | It was recycling day in Kekoland. To celebrate it Adil and Bera went to Central Perk where they can take bottles from the ground and put them into a recycling bin.We can think Central Perk as coordinate plane. There are n bottles on the ground, the i-th bottle is located at position (xi, yi). Both Adil and Bera can car... | Print one real number — the minimum possible total distance Adil and Bera need to walk in order to put all bottles into recycling bin. Your answer will be considered correct if its absolute or relative error does not exceed 10 - 6. Namely: let's assume that your answer is a, and the answer of the jury is b. The checker... | First line of the input contains six integers ax, ay, bx, by, tx and ty (0 ≤ ax, ay, bx, by, tx, ty ≤ 109) — initial positions of Adil, Bera and recycling bin respectively. The second line contains a single integer n (1 ≤ n ≤ 100 000) — the number of bottles on the ground. Then follow n lines, each of them contains two... | standard output | standard input | Python 3 | Python | 1,800 | train_000.jsonl | 8694d69785e15093f3cc9909d405f96b | 256 megabytes | ["3 1 1 2 0 0\n3\n1 1\n2 1\n2 3", "5 0 4 2 2 0\n5\n5 2\n3 0\n5 5\n3 5\n3 3"] | PASSED | ax,ay,bx,by,tx,ty=map(int,input().split())
n=int(input())
l=[tuple(map(int,input().split())) for _ in range(n)]
a,b=[],[]
for i in range(n):
x,y=l[i]
lt=((tx-x)*(tx-x)+(ty-y)*(ty-y))**0.5
la=((ax-x)*(ax-x)+(ay-y)*(ay-y))**0.5
lb=((bx-x)*(bx-x)+(by-y)*(by-y))**0.5
a+=[(la-lt,i)]
b+=[(lb-lt,i)]
a.sort();b.sor... | 1462984500 | [
"geometry"
] | [
0,
1,
0,
0,
0,
0,
0,
0
] | |
1 second | ["141", "25", "183"] | de6361f522936eac3d88b7268b8c2793 | NoteIn sample case one it's optimal to use autocompletion for the first instance of «snowboarding» after typing up «sn» and for the second instance of «snowboarding» after typing up «snowb». This will save 7 clicks.In sample case two it doesn't matter whether to use autocompletion or not. | Arcady is a copywriter. His today's task is to type up an already well-designed story using his favorite text editor.Arcady types words, punctuation signs and spaces one after another. Each letter and each sign (including line feed) requires one keyboard click in order to be printed. Moreover, when Arcady has a non-emp... | Print a single integer — the minimum number of clicks. | The only line contains Arcady's text, consisting only of lowercase latin letters, spaces, line feeds and the following punctuation signs: «.», «,», «?», «!», «'» and «-». The total amount of symbols doesn't exceed 3·105. It's guaranteed that all lines are non-empty. | standard output | standard input | Python 3 | Python | 1,900 | train_035.jsonl | 55d9a0f55e02784d19864ca9f406eea2 | 256 megabytes | ["snow affects sports such as skiing, snowboarding, and snowmachine travel.\nsnowboarding is a recreational activity and olympic and paralympic sport.", "'co-co-co, codeforces?!'", "thun-thun-thunder, thunder, thunder\nthunder, thun-, thunder\nthun-thun-thunder, thunder\nthunder, feel the thunder\nlightning then the th... | PASSED | class Ddict:
def __init__(self):
self.dicts={}
def add(self,key):
d=self.dicts
for i in key:
if i not in d:
d[i]={}
d=d[i]
d[' ']=''
def find(self,key):
if key=='':
return '',''
d=self.dicts
q=[]
... | 1519486500 | [
"trees",
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
1
] | |
1 second | ["0\n1\n12\n499999999"] | c34db7897f051b0de2f49f2696c6ee2f | NoteIn the first test case, the only allowed pair is $$$(a, b) = (1, 1)$$$, for which $$$a \bmod b = 1 \bmod 1 = 0$$$.In the second test case, the optimal choice is pair $$$(a, b) = (1000000000, 999999999)$$$, for which $$$a \bmod b = 1$$$. | You are given two integers $$$l$$$ and $$$r$$$, $$$l\le r$$$. Find the largest possible value of $$$a \bmod b$$$ over all pairs $$$(a, b)$$$ of integers for which $$$r\ge a \ge b \ge l$$$.As a reminder, $$$a \bmod b$$$ is a remainder we get when dividing $$$a$$$ by $$$b$$$. For example, $$$26 \bmod 8 = 2$$$. | For every test case, output the largest possible value of $$$a \bmod b$$$ over all pairs $$$(a, b)$$$ of integers for which $$$r\ge a \ge b \ge l$$$. | Each test contains multiple test cases. The first line contains one positive integer $$$t$$$ $$$(1\le t\le 10^4)$$$, denoting the number of test cases. Description of the test cases follows. The only line of each test case contains two integers $$$l$$$, $$$r$$$ ($$$1\le l \le r \le 10^9$$$). | standard output | standard input | Python 3 | Python | 800 | train_086.jsonl | 49df8e8d76f98d081f15aa806539cd06 | 256 megabytes | ["4\n1 1\n999999999 1000000000\n8 26\n1 999999999"] | PASSED | import os, sys
import math
from io import BytesIO, IOBase
from collections import Counter
# Fast IO Region
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "... | 1629988500 | [
"math"
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0,
0,
0,
1,
0,
0,
0,
0
] | |
3 seconds | ["27", "9"] | 0cc9e1f64f615806d07e657be7386f5b | NoteIn the first sample the result equals (1 + 08) + (10 + 8) = 27.In the second sample the result equals 1 + 0 + 8 = 9. | Vasya is sitting on an extremely boring math class. To have fun, he took a piece of paper and wrote out n numbers on a single line. After that, Vasya began to write out different ways to put pluses ("+") in the line between certain digits in the line so that the result was a correct arithmetic expression; formally, no ... | Print the answer to the problem modulo 109 + 7. | The first line contains two integers, n and k (0 ≤ k < n ≤ 105). The second line contains a string consisting of n digits. | standard output | standard input | Python 3 | Python | 2,200 | train_002.jsonl | fece09dfb0961b9b215cffd62afd564f | 256 megabytes | ["3 1\n108", "3 2\n108"] | PASSED | n, k = map(int, input().split())
t = list(map(int, input()))
p, d = 1, 10 ** 9 + 7
s, f = 0, [1] * n
for i in range(2, n): f[i] = (i * f[i - 1]) % d
c = lambda a, b: 0 if a > b else (f[b] * pow(f[a] * f[b - a], d - 2, d)) % d
if k:
u = [0] * (n + 1)
p = [1] * (n + 1)
for i in range(n):
u[i] = (p[i] ... | 1425279600 | [
"number theory",
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0
] | |
1 second | ["1", "2", "-1"] | 9115965ff3421230eac37b22328c6153 | NoteIn the first example, the greatest common divisor is $$$1$$$ in the beginning. You can remove $$$1$$$ so that the greatest common divisor is enlarged to $$$2$$$. The answer is $$$1$$$.In the second example, the greatest common divisor is $$$3$$$ in the beginning. You can remove $$$6$$$ and $$$9$$$ so that the great... | Mr. F has $$$n$$$ positive integers, $$$a_1, a_2, \ldots, a_n$$$.He thinks the greatest common divisor of these integers is too small. So he wants to enlarge it by removing some of the integers.But this problem is too simple for him, so he does not want to do it by himself. If you help him, he will give you some scores... | Print an integer — the minimum number of integers you need to remove so that the greatest common divisor of the remaining integers is bigger than that of all integers. You should not remove all of the integers. If there is no solution, print «-1» (without quotes). | The first line contains an integer $$$n$$$ ($$$2 \leq n \leq 3 \cdot 10^5$$$) — the number of integers Mr. F has. The second line contains $$$n$$$ integers, $$$a_1, a_2, \ldots, a_n$$$ ($$$1 \leq a_i \leq 1.5 \cdot 10^7$$$). | standard output | standard input | PyPy 2 | Python | 1,800 | train_009.jsonl | a7be496d9cfe2abb4ffed5d77715e8f0 | 256 megabytes | ["3\n1 2 4", "4\n6 9 15 30", "3\n1 1 1"] | PASSED | def gcd(a, b):
while b:
c = a%b
a = b
b = c
return a
import sys
raw_input = sys.stdin.readline
sieve = [0] * (15000001)
i = 2
while i <= 15000000:
sieve[i] = 2
i += 2
i = 3
while i < 15000000:
if sieve[i]:
i += 2
continue
sieve[i] = i
j = i*i
whi... | 1537540500 | [
"number theory"
] | [
0,
0,
0,
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1,
0,
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0
] | |
2 seconds | ["10\n1 2 3", "99\n2 1", "-9\n3 5 6 1 9 4 10 7 8 2"] | 5ebae703049e9ab4547df87861034176 | null | Captain Fint is involved in another treasure hunt, but have found only one strange problem. The problem may be connected to the treasure's location or may not. That's why captain Flint decided to leave the solving the problem to his crew and offered an absurdly high reward: one day off. The problem itself sounds like t... | In the first line, print the maximum $$$ans$$$ you can get. In the second line, print the order of operations: $$$n$$$ different integers $$$p_1, p_2, \ldots, p_n$$$ ($$$1 \le p_i \le n$$$). The $$$p_i$$$ is the position which should be chosen at the $$$i$$$-th step. If there are multiple orders, print any of them. | The first line contains the integer $$$n$$$ ($$$1 \le n \le 2 \cdot 10^5$$$) — the length of arrays $$$a$$$ and $$$b$$$. The second line contains $$$n$$$ integers $$$a_1, a_2, \ldots, a_n$$$ ($$$−10^6 \le a_i \le 10^6$$$). The third line contains $$$n$$$ integers $$$b_1, b_2, \ldots, b_n$$$ ($$$1 \le b_i \le n$$$ or $$... | standard output | standard input | PyPy 3 | Python | 2,000 | train_039.jsonl | d4a99228d2d306cb7e9777c1de2019dd | 256 megabytes | ["3\n1 2 3\n2 3 -1", "2\n-1 100\n2 -1", "10\n-10 -1 2 2 5 -2 -3 -4 2 -6\n-1 -1 2 2 -1 5 5 7 7 9"] | PASSED | import sys;input=sys.stdin.readline
N, = map(int, input().split())
X = [0]+list(map(int, input().split()))
Y = [0]+list(map(int, input().split()))
st = []
G = [set() for _ in range(N+1)]
for i in range(1, N+1):
if Y[i] < 0:
st.append(i)
else:
G[Y[i]].add(i)
ato = []
R = []
W = [0]*(N+1)
for s i... | 1596119700 | [
"trees",
"graphs"
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0,
0,
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1
] | |
2 seconds | ["2 1\n3 1 2\n1 6 5 8 3 2 4 7"] | 0903a40d72c19a9d1cc1147d01ea94a7 | NoteIn the first testcase, there exists only one permutation $$$q$$$ such that each liked song is rating higher than each disliked song: song $$$1$$$ gets rating $$$2$$$ and song $$$2$$$ gets rating $$$1$$$. $$$\sum\limits_{i=1}^n |p_i-q_i|=|1-2|+|2-1|=2$$$.In the second testcase, Monocarp liked all songs, so all permu... | Berland Music is a music streaming service built specifically to support Berland local artist. Its developers are currently working on a song recommendation module.So imagine Monocarp got recommended $$$n$$$ songs, numbered from $$$1$$$ to $$$n$$$. The $$$i$$$-th song had its predicted rating equal to $$$p_i$$$, where ... | For each testcase, print a permutation $$$q$$$ — the re-evaluated ratings of the songs. If there are multiple answers such that $$$\sum\limits_{i=1}^n |p_i-q_i|$$$ is minimum possible, you can print any of them. | The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^4$$$) — the number of testcases. The first line of each testcase contains a single integer $$$n$$$ ($$$1 \le n \le 2 \cdot 10^5$$$) — the number of songs. The second line of each testcase contains $$$n$$$ integers $$$p_1, p_2, \dots, p_n$$$ ($$$1 \le p... | standard output | standard input | Python 3 | Python | 1,000 | train_085.jsonl | 654feabfa49f056eedf2d0f1a93f911a | 256 megabytes | ["3\n2\n1 2\n10\n3\n3 1 2\n111\n8\n2 3 1 8 5 4 7 6\n01110001"] | PASSED | t= int(input())
for i in range(t):
n= int(input())
p= [int(x) for x in input().split()]
s= [int(x) for x in input()]
l= sorted([[s[i], p[i], i] for i in range(n)])
q= [0] * n
for i in range(n):
q[l[i][2]] = i+1
print(*q)
| 1640615700 | [
"math"
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0
] | |
2 seconds | ["6.00000000", "6.50000000"] | 822e8f394a59329fa05c96d7fb35797e | NoteIn the first sample, one of the optimal solutions is to move candidate 1 to the first city and candidate 2 to the second.In the second sample, the optimal solution is to pick candidates 3 and 4 for the first city, and candidate 2 for the second one. Thus we obtain (a3 + a4) / 2 + a2 = (3 + 2) / 2 + 4 = 6.5 | Local authorities have heard a lot about combinatorial abilities of Ostap Bender so they decided to ask his help in the question of urbanization. There are n people who plan to move to the cities. The wealth of the i of them is equal to ai. Authorities plan to build two cities, first for n1 people and second for n2 peo... | Print one real value — the maximum possible sum of arithmetic means of wealth of cities' residents. You answer will be considered correct if its absolute or relative error does not exceed 10 - 6. Namely: let's assume that your answer is a, and the answer of the jury is b. The checker program will consider your answer ... | The first line of the input contains three integers n, n1 and n2 (1 ≤ n, n1, n2 ≤ 100 000, n1 + n2 ≤ n) — the number of candidates who want to move to the cities, the planned number of residents of the first city and the planned number of residents of the second city. The second line contains n integers a1, a2, ..., an... | standard output | standard input | Python 3 | Python | 1,100 | train_016.jsonl | e1b7cfed7e781d598b5f66b0a56bf9ed | 256 megabytes | ["2 1 1\n1 5", "4 2 1\n1 4 2 3"] | PASSED | i = lambda: map(int, input().split())
n, x, y = i()
a = sorted(i())[::-1]
if x > y:
x, y = y, x
print(sum(a[:x])/x + sum(a[x:][:y])/y)
| 1480264500 | [
"number theory"
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1 second | ["3\n1 4\n3 2\n7 1", "3\n1 3\n2 2\n3 1"] | 3fb70a77e4de4851ed93f988140df221 | null | You have a string s = s1s2...s|s|, where |s| is the length of string s, and si its i-th character. Let's introduce several definitions: A substring s[i..j] (1 ≤ i ≤ j ≤ |s|) of string s is string sisi + 1...sj. The prefix of string s of length l (1 ≤ l ≤ |s|) is string s[1..l]. The suffix of string s of length l (1 ... | In the first line, print integer k (0 ≤ k ≤ |s|) — the number of prefixes that match a suffix of string s. Next print k lines, in each line print two integers li ci. Numbers li ci mean that the prefix of the length li matches the suffix of length li and occurs in string s as a substring ci times. Print pairs li ci in t... | The single line contains a sequence of characters s1s2...s|s| (1 ≤ |s| ≤ 105) — string s. The string only consists of uppercase English letters. | standard output | standard input | Python 3 | Python | 2,000 | train_054.jsonl | 34ca44611c717c1b164a2ddb50108653 | 256 megabytes | ["ABACABA", "AAA"] | PASSED |
def z_advanced(s):
"""An advanced computation of Z-values of a string."""
Z = [0] * len(s)
Z[0] = len(s)
rt = 0
lt = 0
for k in range(1, len(s)):
if k > rt:
# If k is outside the current Z-box, do naive computation.
n = 0
while n + k < len(s) and s... | 1400167800 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
1 second | ["YES\n1 0\n2 3\n4 1", "NO"] | 5c026adda2ae3d7b707d5054bd84db3f | NoteIn the first example area of the triangle should be equal to $$$\frac{nm}{k} = 4$$$. The triangle mentioned in the output is pictured below: In the second example there is no triangle with area $$$\frac{nm}{k} = \frac{16}{7}$$$. | Vasya has got three integers $$$n$$$, $$$m$$$ and $$$k$$$. He'd like to find three integer points $$$(x_1, y_1)$$$, $$$(x_2, y_2)$$$, $$$(x_3, y_3)$$$, such that $$$0 \le x_1, x_2, x_3 \le n$$$, $$$0 \le y_1, y_2, y_3 \le m$$$ and the area of the triangle formed by these points is equal to $$$\frac{nm}{k}$$$.Help Vasya... | If there are no such points, print "NO". Otherwise print "YES" in the first line. The next three lines should contain integers $$$x_i, y_i$$$ — coordinates of the points, one point per line. If there are multiple solutions, print any of them. You can print each letter in any case (upper or lower). | The single line contains three integers $$$n$$$, $$$m$$$, $$$k$$$ ($$$1\le n, m \le 10^9$$$, $$$2 \le k \le 10^9$$$). | standard output | standard input | PyPy 3 | Python | 1,800 | train_005.jsonl | 3ab5974739b59a2f7707451462505fae | 256 megabytes | ["4 3 3", "4 4 7"] | PASSED | #Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
from fractions import Fraction
import collections
from itertools import permutations
from collections import defaultdict
BUFSIZE = 8192
class FastIO(IOBase):
... | 1537707900 | [
"number theory",
"geometry"
] | [
0,
1,
0,
0,
1,
0,
0,
0
] | |
1 second | ["-2", "10"] | a12103bd632fa73a7faab71df3fd0164 | NoteNote that the answer to the problem can be negative.The GCD(x1, x2, ..., xk) is the maximum positive integer that divides each xi. | You have an array of positive integers a[1], a[2], ..., a[n] and a set of bad prime numbers b1, b2, ..., bm. The prime numbers that do not occur in the set b are considered good. The beauty of array a is the sum , where function f(s) is determined as follows: f(1) = 0; Let's assume that p is the minimum prime divisor... | Print a single integer — the answer to the problem. | The first line contains two integers n and m (1 ≤ n, m ≤ 5000) showing how many numbers are in the array and how many bad prime numbers there are. The second line contains n space-separated integers a[1], a[2], ..., a[n] (1 ≤ a[i] ≤ 109) — array a. The third line contains m space-separated integers b1, b2, ..., bm (2 ≤... | standard output | standard input | Python 2 | Python | 1,800 | train_040.jsonl | 360d4e4cbb892f4bfead7c8cae357d0d | 256 megabytes | ["5 2\n4 20 34 10 10\n2 5", "4 5\n2 4 8 16\n3 5 7 11 17"] | PASSED | import fractions
n, m = map(int, raw_input().split())
primes_cache = {}
primes = []
def lowest_prime_divisor(x, sorted_primes_to_check=primes, cache=primes_cache):
if x in cache:
return cache[x]
for i in sorted_primes_to_check:
if i * i > x:
cache[x] = x
return x... | 1394983800 | [
"number theory",
"math"
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1,
0,
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0
] | |
2 seconds | ["2 4\n1 4\n3 4\n3 1\n3 2", "-1"] | 1a9968052a363f04380d1177c764717b | null | Student Vladislav came to his programming exam completely unprepared as usual. He got a question about some strange algorithm on a graph — something that will definitely never be useful in real life. He asked a girl sitting next to him to lend him some cheat papers for this questions and found there the following defin... | If Vladislav has made a mistake and such graph doesn't exist, print - 1. Otherwise print m lines. On the j-th line print a pair of vertices (uj, vj) (1 ≤ uj, vj ≤ n, uj ≠ vj), that should be connected by the j-th edge. The edges are numbered in the same order as in the input. The graph, determined by these edges, must... | The first line of the input contains two integers n and m () — the number of vertices and the number of edges in the graph. Each of the next m lines describes an edge of the graph and consists of two integers aj and bj (1 ≤ aj ≤ 109, bj = {0, 1}). The first of these numbers is the weight of the edge and the second numb... | standard output | standard input | Python 3 | Python | 1,700 | train_056.jsonl | 9b5f207249c2428d5556fcf64cc48092 | 256 megabytes | ["4 5\n2 1\n3 1\n4 0\n1 1\n5 0", "3 3\n1 0\n2 1\n3 1"] | PASSED | import sys
from operator import itemgetter
lines = sys.stdin.readlines()
n, m = map(int, lines[0].split(' '))
def build_edge(i, row):
parts = row.split(' ')
return (int(parts[0]), int(parts[1]), i)
def edge_key(a):
return (a[0], -a[1])
edges = [build_edge(i, row) for i, row in enumerate(lines[1:])]
edges = sorte... | 1449677100 | [
"graphs"
] | [
0,
0,
1,
0,
0,
0,
0,
0
] | |
2 seconds | ["2", "3"] | 40a965a28e38bad3aff9c58bdeeeb8f6 | null | Further research on zombie thought processes yielded interesting results. As we know from the previous problem, the nervous system of a zombie consists of n brains and m brain connectors joining some pairs of brains together. It was observed that the intellectual abilities of a zombie depend mainly on the topology of i... | Print one number – the brain latency. | The first line of the input contains two space-separated integers n and m (1 ≤ n, m ≤ 100000) denoting the number of brains (which are conveniently numbered from 1 to n) and the number of brain connectors in the nervous system, respectively. In the next m lines, descriptions of brain connectors follow. Every connector ... | standard output | standard input | Python 3 | Python | 1,500 | train_004.jsonl | 5000894a71456b418e95fea3047708d8 | 256 megabytes | ["4 3\n1 2\n1 3\n1 4", "5 4\n1 2\n2 3\n3 4\n3 5"] | PASSED | # itne me hi thakk gaye?
def bfs(x, g):
n, q = len(g), [x]
dist = [0 if y == x else -1 for y in range(n)]
i = 0
while i < len(q):
v = q[i]
i += 1
for to in g[v]:
if dist[to] < 0:
dist[to] = dist[v] + 1
q.append(to)
return (q[-1], di... | 1468137600 | [
"trees",
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0,
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1
] | |
2 seconds | ["5\n1 2 4 3 0", "6\n3 9 2 9 8 0"] | 5a3bbc6668268dabb49316a1c8d4ea8c | NoteFor the first case, the prefix products of this sequence modulo m are [1, 2, 3, 4, 0].For the second case, the prefix products of this sequence modulo m are [3, 7, 4, 6, 8, 0]. | You are given an integer m, and a list of n distinct integers between 0 and m - 1.You would like to construct a sequence satisfying the properties: Each element is an integer between 0 and m - 1, inclusive. All prefix products of the sequence modulo m are distinct. No prefix product modulo m appears as an element of... | On the first line, print the number k, denoting the length of your sequence. On the second line, print k space separated integers, denoting your sequence. | The first line of input contains two integers n and m (0 ≤ n < m ≤ 200 000) — the number of forbidden prefix products and the modulus. If n is non-zero, the next line of input contains n distinct integers between 0 and m - 1, the forbidden prefix products. If n is zero, this line doesn't exist. | standard output | standard input | PyPy 3 | Python | 2,300 | train_051.jsonl | 25d0761f13a23b6619cb8e739dd2595c | 256 megabytes | ["0 5", "3 10\n2 9 1"] | PASSED | import math
def gcdExtended(a, b):
# Base Case
if a == 0 :
return b, 0, 1
gcd, x1, y1 = gcdExtended(b%a, a)
# Update x and y using results of recursive
# call
x = y1 - (b//a) * x1
y = x1
return gcd, x, y
def rev_elem(x, m):
r... | 1492356900 | [
"number theory",
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0,
1,
1,
1,
0,
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2 seconds | ["NO\nYES\nYES"] | 044c2a3bafe4f47036ee81f2e40f639a | NoteIn the first test case, we can prove that we can't make all $$$a_i \le 3$$$.In the second test case, all $$$a_i$$$ are already less or equal than $$$d = 4$$$.In the third test case, we can, for example, choose $$$i = 5$$$, $$$j = 1$$$, $$$k = 2$$$ and make $$$a_5 = a_1 + a_2 = 2 + 1 = 3$$$. Array $$$a$$$ will becom... | You have an array $$$a_1, a_2, \dots, a_n$$$. All $$$a_i$$$ are positive integers.In one step you can choose three distinct indices $$$i$$$, $$$j$$$, and $$$k$$$ ($$$i \neq j$$$; $$$i \neq k$$$; $$$j \neq k$$$) and assign the sum of $$$a_j$$$ and $$$a_k$$$ to $$$a_i$$$, i. e. make $$$a_i = a_j + a_k$$$.Can you make all... | For each test case, print YES, if it's possible to make all elements $$$a_i$$$ less or equal than $$$d$$$ using the operation above. Otherwise, print NO. You may print each letter in any case (for example, YES, Yes, yes, yEs will all be recognized as positive answer). | The first line contains a single integer $$$t$$$ ($$$1 \le t \le 2000$$$) — the number of test cases. The first line of each test case contains two integers $$$n$$$ and $$$d$$$ ($$$3 \le n \le 100$$$; $$$1 \le d \le 100$$$) — the number of elements in the array $$$a$$$ and the value $$$d$$$. The second line contains $$... | standard output | standard input | Python 3 | Python | 800 | train_106.jsonl | 6aec5e0fe0295869b8b1a0965ef998bb | 256 megabytes | ["3\n5 3\n2 3 2 5 4\n3 4\n2 4 4\n5 4\n2 1 5 3 6"] | PASSED | for t in range(int(input())):
n,d=map(int,input().split())
lst=sorted(map(int,input().split()))
print ("YES" if min(lst[0] + lst[1], lst[-1]) <=d else "NO")
| 1610634900 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["1 2 0", "43 42 41 1337 1336", "4 3 2 1 2"] | 48c8ce45ab38a382dc52db1e59be234f | null | You are given a directed acyclic graph (a directed graph that does not contain cycles) of $$$n$$$ vertices and $$$m$$$ arcs. The $$$i$$$-th arc leads from the vertex $$$x_i$$$ to the vertex $$$y_i$$$ and has the weight $$$w_i$$$.Your task is to select an integer $$$a_v$$$ for each vertex $$$v$$$, and then write a numbe... | Print $$$n$$$ integers $$$a_1$$$, $$$a_2$$$, ..., $$$a_n$$$ ($$$0 \le a_v \le 10^9$$$), which must be written on the vertices so that all $$$b_i$$$ are positive, and the value of the expression $$$\sum \limits_{i = 1}^{m} w_i b_i$$$ is the lowest possible. If there are several answers, print any of them. It can be show... | The first line contains two integers $$$n$$$ and $$$m$$$ ($$$2 \le n \le 18$$$; $$$0 \le m \le \dfrac{n(n - 1)}{2}$$$). Then $$$m$$$ lines follow, the $$$i$$$-th of them contains three integers $$$x_i$$$, $$$y_i$$$ and $$$w_i$$$ ($$$1 \le x_i, y_i \le n$$$, $$$1 \le w_i \le 10^5$$$, $$$x_i \ne y_i$$$) — the description... | standard output | standard input | PyPy 3 | Python | 2,600 | train_047.jsonl | c4e0a7fa0d9ff0c6153f616078f138bb | 1024 megabytes | ["3 2\n2 1 4\n1 3 2", "5 4\n1 2 1\n2 3 1\n1 3 6\n4 5 8", "5 5\n1 2 1\n2 3 1\n3 4 1\n1 5 1\n5 4 10"] | PASSED | from heapq import heappush, heappop
class MinCostFlow:
INF = 10**18
def __init__(self, N):
self.N = N
self.G = [[] for i in range(N)]
def add_edge(self, fr, to, cap, cost):
forward = [to, cap, cost, None]
backward = forward[3] = [fr, 0, -cost, forward]
self.G[fr].ap... | 1602407100 | [
"math",
"graphs"
] | [
0,
0,
1,
1,
0,
0,
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0
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2 seconds | ["1\n2\n-1\n1", "0\n1\n0\n-1", "-1\n-1\n-1", "-1"] | 883f728327aea19993089a65d452b79f | null | Why I have to finish so many assignments???Jamie is getting very busy with his school life. He starts to forget the assignments that he has to do. He decided to write the things down on a to-do list. He assigns a value priority for each of his assignment (lower value means more important) so he can decide which he need... | For each query operation, output a single integer — the number of assignments that have a priority lower than assignment ai, or - 1 if ai is not in the to-do list. | The first line consists of a single integer q (1 ≤ q ≤ 105) — the number of operations. The following q lines consists of the description of the operations. The i-th line consists of the operation that Jamie has done in the i-th day. The query has the following format: The first word in the line indicates the type of o... | standard output | standard input | PyPy 2 | Python | 2,200 | train_044.jsonl | 932ccde0446ccee0b75faadf77810094 | 512 megabytes | ["8\nset chemlabreport 1\nset physicsexercise 2\nset chinesemockexam 3\nquery physicsexercise\nquery chinesemockexam\nremove physicsexercise\nquery physicsexercise\nquery chinesemockexam", "8\nset physicsexercise 2\nset chinesemockexam 3\nset physicsexercise 1\nquery physicsexercise\nquery chinesemockexam\nundo 4\nquer... | PASSED | import sys, os, __pypy__
from collections import defaultdict
from cStringIO import StringIO
from io import IOBase
range = xrange
input = raw_input
L = []
R = []
A = [0]
__pypy__.resizelist_hint(L, 50*10**5)
__pypy__.resizelist_hint(R, 50*10**5)
__pypy__.resizelist_hint(A, 50*10**5)
def create():
L.append(-1)
... | 1516372500 | [
"trees"
] | [
0,
0,
0,
0,
0,
0,
0,
1
] | |
3 seconds | ["500000.000000000000000000000000000000", "400.000000000000000000000000000000"] | 7de7e7983909d7a8f51fee4fa9ede838 | NoteIn the first example, it is optimal to place the bomb at a point with a coordinate of 400000. Then at time 0, the speed of the first person becomes 1000 and he reaches the point 106 at the time 600. The bomb will not affect on the second person, and he will reach the 0 point at the time 500000.In the second example... | n people are standing on a coordinate axis in points with positive integer coordinates strictly less than 106. For each person we know in which direction (left or right) he is facing, and his maximum speed.You can put a bomb in some point with non-negative integer coordinate, and blow it up. At this moment all people w... | Print the minimum time needed for both points 0 and 106 to be reached. Your answer is considered correct if its absolute or relative error doesn't exceed 10 - 6. Namely, if your answer is a, and the jury's answer is b, then your answer is accepted, if . | The first line contains two integers n and s (2 ≤ n ≤ 105, 2 ≤ s ≤ 106) — the number of people and the rays' speed. The next n lines contain the description of people. The i-th of these lines contains three integers xi, vi and ti (0 < xi < 106, 1 ≤ vi < s, 1 ≤ ti ≤ 2) — the coordinate of the i-th person on the... | standard output | standard input | Python 3 | Python | 2,500 | train_039.jsonl | a42d6d5c84b635e9620546ca9fdef8de | 256 megabytes | ["2 999\n400000 1 2\n500000 1 1", "2 1000\n400000 500 1\n600000 500 2"] | PASSED | import math
leftpeople = set()
rightpeople = set()
n, vl = map(int, input().split())
def leftinterval(x0, v0, t):
if x0 / v0 <= t:
return (0, 10**6)
if x0 / (vl + v0) > t:
return (-1, -2)
leftbound = x0
rightbound = (vl * vl - v0 * v0) * t + x0 * v0
rightbound /= vl
rightbound ... | 1500906900 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["bcdefghijklmnopqrsatuvwxyz", "Impossible", "aghjlnopefikdmbcqrstuvwxyz", "acbdefhijklmnogpqrstuvwxyz"] | 12218097cf5c826d83ab11e5b049999f | null | Fox Ciel is going to publish a paper on FOCS (Foxes Operated Computer Systems, pronounce: "Fox"). She heard a rumor: the authors list on the paper is always sorted in the lexicographical order. After checking some examples, she found out that sometimes it wasn't true. On some papers authors' names weren't sorted in lex... | If there exists such order of letters that the given names are sorted lexicographically, output any such order as a permutation of characters 'a'–'z' (i. e. first output the first letter of the modified alphabet, then the second, and so on). Otherwise output a single word "Impossible" (without quotes). | The first line contains an integer n (1 ≤ n ≤ 100): number of names. Each of the following n lines contain one string namei (1 ≤ |namei| ≤ 100), the i-th name. Each name contains only lowercase Latin letters. All names are different. | standard output | standard input | Python 3 | Python | 1,600 | train_006.jsonl | 985dff6833c2e9ba3cd6fee94083193f | 256 megabytes | ["3\nrivest\nshamir\nadleman", "10\ntourist\npetr\nwjmzbmr\nyeputons\nvepifanov\nscottwu\noooooooooooooooo\nsubscriber\nrowdark\ntankengineer", "10\npetr\negor\nendagorion\nfeferivan\nilovetanyaromanova\nkostka\ndmitriyh\nmaratsnowbear\nbredorjaguarturnik\ncgyforever", "7\ncar\ncare\ncareful\ncarefully\nbecarefuldontfo... | PASSED | def go_through(given_char):
global order
global freq
global orders
if given_char in orders:
while orders[given_char]:
next_letter = orders[given_char].pop()
freq[next_letter] = freq[next_letter] - 1
go_through(next_letter)
if given_char not in order:
... | 1422894600 | [
"graphs"
] | [
0,
0,
1,
0,
0,
0,
0,
0
] | |
1 second | ["0", "2", "1"] | acd48e32c96a10cc0d4161225407bf67 | NoteFor each example you have a picture which illustrates it.The first picture for each example describes the initial set of element samples available. Black crosses represent elements available in the lab initially.The second picture describes how remaining samples can be obtained. Red dashed circles denote elements t... | Innopolis University scientists continue to investigate the periodic table. There are n·m known elements and they form a periodic table: a rectangle with n rows and m columns. Each element can be described by its coordinates (r, c) (1 ≤ r ≤ n, 1 ≤ c ≤ m) in the table.Recently scientists discovered that for every four d... | Print the minimal number of elements to be purchased. | The first line contains three integers n, m, q (1 ≤ n, m ≤ 200 000; 0 ≤ q ≤ min(n·m, 200 000)), the chemical table dimensions and the number of elements scientists already have. The following q lines contain two integers ri, ci (1 ≤ ri ≤ n, 1 ≤ ci ≤ m), each describes an element that scientists already have. All elemen... | standard output | standard input | Python 3 | Python | 1,900 | train_031.jsonl | d751140f3c28dfdfc271bc1271caf119 | 512 megabytes | ["2 2 3\n1 2\n2 2\n2 1", "1 5 3\n1 3\n1 1\n1 5", "4 3 6\n1 2\n1 3\n2 2\n2 3\n3 1\n3 3"] | PASSED | from sys import stdin
def main():
n, m, q = map(int, input().split())
chm = list(range(n + m))
r = [0] * (n + m)
n -= 1
res = n + m
for s in stdin.read().splitlines():
a, b = map(int, s.split())
a -= 1
b += n
l = []
while a != chm[a]:
l.appen... | 1532938500 | [
"graphs"
] | [
0,
0,
1,
0,
0,
0,
0,
0
] | |
1 second | ["12\n3 4\n1 2 3 5\n3 1 5 4\n5 6 8 9", "1\n1 1\n1"] | db447a8896347bb47ce05a1df334a8b3 | null | You are given $$$n$$$ integers. You need to choose a subset and put the chosen numbers in a beautiful rectangle (rectangular matrix). Each chosen number should occupy one of its rectangle cells, each cell must be filled with exactly one chosen number. Some of the $$$n$$$ numbers may not be chosen.A rectangle (rectangul... | In the first line print $$$x$$$ ($$$1 \le x \le n$$$) — the total number of cells of the required maximum beautiful rectangle. In the second line print $$$p$$$ and $$$q$$$ ($$$p \cdot q=x$$$): its sizes. In the next $$$p$$$ lines print the required rectangle itself. If there are several answers, print any. | The first line contains $$$n$$$ ($$$1 \le n \le 4\cdot10^5$$$). The second line contains $$$n$$$ integers ($$$1 \le a_i \le 10^9$$$). | standard output | standard input | Python 3 | Python | 2,300 | train_009.jsonl | a0bfd8e7bd1558537a370e3239202980 | 256 megabytes | ["12\n3 1 4 1 5 9 2 6 5 3 5 8", "5\n1 1 1 1 1"] | PASSED |
from collections import Counter
from itertools import accumulate
from math import sqrt
from operator import itemgetter
import sys
n = int(input())
cnt = Counter(map(int, input().split()))
nums, counts = zip(*sorted(cnt.items(), key=itemgetter(1)))
acc = [0] + list(accumulate(counts))
area = 1
h, w = 1, 1
i = len(cou... | 1576321500 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["3\n2\n4 3\n3 1"] | b97db0567760f2fc5d3ca15611fe7177 | NoteIn the first sample test we swap numbers on positions 3 and 4 and permutation p becomes 4 2 3 1. We pay |3 - 4| = 1 coins for that. On second turn we swap numbers on positions 1 and 3 and get permutation 3241 equal to s. We pay |3 - 1| = 2 coins for that. In total we pay three coins. | Anton loves transforming one permutation into another one by swapping elements for money, and Ira doesn't like paying for stupid games. Help them obtain the required permutation by paying as little money as possible.More formally, we have two permutations, p and s of numbers from 1 to n. We can swap pi and pj, by payin... | In the first line print the minimum number of coins that you need to spend to transform permutation p into permutation s. In the second line print number k (0 ≤ k ≤ 2·106) — the number of operations needed to get the solution. In the next k lines print the operations. Each line must contain two numbers i and j (1 ≤ i, ... | The first line contains a single number n (1 ≤ n ≤ 2000) — the length of the permutations. The second line contains a sequence of n numbers from 1 to n — permutation p. Each number from 1 to n occurs exactly once in this line. The third line contains a sequence of n numbers from 1 to n — permutation s. Each number from... | standard output | standard input | Python 2 | Python | 2,300 | train_048.jsonl | ec4fe4aae531b51db135f9ad6d812061 | 256 megabytes | ["4\n4 2 1 3\n3 2 4 1"] | PASSED |
def sol1(): #wrong solution
global n, p1, p2, di, di2
swaps = []
cost = 0
flag = True
while flag:
flag = False
for i in range(n-1):
if di[p1[i]] > di[p1[i+1]]:
temp = p1[i]
p1[i] = p1[i+1]
p1[i+1] = p1[i]
cost += 1
swaps.append( (i,i+1) )
flag = True
def sol2():
global n, p1, p2,... | 1444149000 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["1\n2\n3\n4\n8\n12\n5\n10\n15"] | 37c3725f583ca33387dfd05fe75898a9 | NoteThe first elements of $$$s$$$ are $$$1, 2, 3, 4, 8, 12, 5, 10, 15, \dots $$$ | Consider the infinite sequence $$$s$$$ of positive integers, created by repeating the following steps: Find the lexicographically smallest triple of positive integers $$$(a, b, c)$$$ such that $$$a \oplus b \oplus c = 0$$$, where $$$\oplus$$$ denotes the bitwise XOR operation. $$$a$$$, $$$b$$$, $$$c$$$ are not in $... | In each of the $$$t$$$ lines, output the answer to the corresponding test case. | The first line contains a single integer $$$t$$$ ($$$1 \le t \le 10^5$$$) — the number of test cases. Each of the next $$$t$$$ lines contains a single integer $$$n$$$ ($$$1\le n \le 10^{16}$$$) — the position of the element you want to know. | standard output | standard input | Python 3 | Python | 2,200 | train_012.jsonl | 6476e4a08ca6045c10cb4c65ac689850 | 256 megabytes | ["9\n1\n2\n3\n4\n5\n6\n7\n8\n9"] | PASSED | import sys
lines = sys.stdin.readlines()
T = int(lines[0].strip())
partial = [1, 2, 3, 4, 8, 12, 5, 10, 15, 6, 11, 13, 7, 9, 14, 16, 32, 48, 17, 34, 51, 18, 35, 49, 19, 33, 50, 20, 40, 60, 21, 42, 63, 22, 43, 61, 23, 41, 62, 24, 44, 52, 25, 46, 55, 26, 47, 53, 27, 45, 54, 28, 36, 56, 29, 38, 59, 30, 39, 57, 31, 37, 58,... | 1586700300 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
2 seconds | ["Possible\n4\n-6\n8\n-7\n7", "Impossible"] | 666b710742bb710dda112e4a6bbbe96b | null | You have to handle a very complex water distribution system. The system consists of $$$n$$$ junctions and $$$m$$$ pipes, $$$i$$$-th pipe connects junctions $$$x_i$$$ and $$$y_i$$$.The only thing you can do is adjusting the pipes. You have to choose $$$m$$$ integer numbers $$$f_1$$$, $$$f_2$$$, ..., $$$f_m$$$ and use th... | If you can choose such integer numbers $$$f_1, f_2, \dots, f_m$$$ in such a way that all requirements on incoming and outcoming flows are satisfied, then output "Possible" in the first line. Then output $$$m$$$ lines, $$$i$$$-th line should contain $$$f_i$$$ — the chosen setting numbers for the pipes. Pipes are numbere... | The first line contains an integer $$$n$$$ ($$$1 \le n \le 2 \cdot 10^5$$$) — the number of junctions. The second line contains $$$n$$$ integers $$$s_1, s_2, \dots, s_n$$$ ($$$-10^4 \le s_i \le 10^4$$$) — constraints for the junctions. The third line contains an integer $$$m$$$ ($$$0 \le m \le 2 \cdot 10^5$$$) — the nu... | standard output | standard input | Python 3 | Python | 2,400 | train_026.jsonl | 29992ffdd85a1c14451d6fe874985e3b | 256 megabytes | ["4\n3 -10 6 1\n5\n1 2\n3 2\n2 4\n3 4\n3 1", "4\n3 -10 6 4\n5\n1 2\n3 2\n2 4\n3 4\n3 1"] | PASSED | import sys
from time import time
def i_ints():
return list(map(int, sys.stdin.readline().split()))
def main():
limit =10**10
n, = i_ints()
s = [0] + i_ints()
if sum(s):
print("Impossible")
return
print("Possible")
m, = i_ints()
es = [i_ints() for _ in range(m)]
n... | 1528625100 | [
"trees"
] | [
0,
0,
0,
0,
0,
0,
0,
1
] | |
2 seconds | ["1.500000", "1.000000"] | 25494129e5358072efc58906b5102652 | null | You are given an array a consisting of n positive integers. You pick two integer numbers l and r from 1 to n, inclusive (numbers are picked randomly, equiprobably and independently). If l > r, then you swap values of l and r. You have to calculate the expected value of the number of unique elements in segment of the... | Print one number — the expected number of unique elements in chosen segment. Your answer will be considered correct if its absolute or relative error doesn't exceed 10 - 4 — formally, the answer is correct if , where x is jury's answer, and y is your answer. | The first line contains one integer number n (1 ≤ n ≤ 106). The second line contains n integer numbers a1, a2, ... an (1 ≤ ai ≤ 106) — elements of the array. | standard output | standard input | Python 3 | Python | 1,800 | train_059.jsonl | 224b91dfd8c9a839405aa10757467402 | 256 megabytes | ["2\n1 2", "2\n2 2"] | PASSED | n=int(input())
a=list(map(int,input().split()))
lastocc=[0]*1000006
ans=[0]*n
ans[0]=1
lastocc[a[0]]=1
for i in range(1,n):
ans[i]=ans[i-1]+(i+1-lastocc[a[i]])
lastocc[a[i]]=i+1
print((2*sum(ans)-n)/(n*n))
| 1504623900 | [
"probabilities",
"math"
] | [
0,
0,
0,
1,
0,
1,
0,
0
] | |
1.5 seconds | ["2\n-1\n-1\n5"] | b540db49c0a509e3807e06397cf74aa8 | NoteIn the first test case, one sequence of operations that achieves the minimum number of operations is the following. Select $$$i=3$$$, changing $$$\texttt{01}\color{red}{\texttt{0}}\texttt{0}$$$ to $$$\texttt{01}\color{red}{\texttt{1}}\texttt{0}$$$. Select $$$i=2$$$, changing $$$\texttt{0}\color{red}{\texttt{1}}\... | Mark has just purchased a rack of $$$n$$$ lightbulbs. The state of the lightbulbs can be described with binary string $$$s = s_1s_2\dots s_n$$$, where $$$s_i=\texttt{1}$$$ means that the $$$i$$$-th lightbulb is turned on, while $$$s_i=\texttt{0}$$$ means that the $$$i$$$-th lightbulb is turned off.Unfortunately, the li... | For each test case, print a line containing the minimum number of operations Mark needs to perform to transform $$$s$$$ to $$$t$$$. If there is no such sequence of operations, print $$$-1$$$. | The first line of the input contains a single integer $$$q$$$ ($$$1\leq q\leq 10^4$$$) — the number of test cases. The first line of each test case contains a single integer $$$n$$$ ($$$3\leq n\leq 2\cdot 10^5$$$) — the number of lightbulbs. The second line of each test case contains a binary string $$$s$$$ of length $... | standard output | standard input | PyPy 3-64 | Python | 1,800 | train_100.jsonl | 088886a24b8daa9881bc5b10076d7f81 | 256 megabytes | ["4\n\n4\n\n0100\n\n0010\n\n4\n\n1010\n\n0100\n\n5\n\n01001\n\n00011\n\n6\n\n000101\n\n010011"] | PASSED | import sys
from array import array
input = lambda: sys.stdin.buffer.readline().decode().strip()
out = []
for _ in range(int(input())):
n, ans = int(input()), 0
s = array('b', [int(x) for x in input()])
t = array('b', [int(x) for x in input()])
sxor = array('b', [s[i] ^ s[i - 1] for i in rang... | 1657892100 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["1 3", "2 6"] | 58c887568002d947706c448e6faa0f77 | NoteExplanation for the first example:Suppose there were 5 participants A-E. Let's denote Nikolay as A. The the most favorable results for Nikolay could look as follows: However, the results of the Olympiad could also look like this: In the first case Nikolay would have taken first place, and in the second — third pl... | Nikolay has only recently started in competitive programming, but already qualified to the finals of one prestigious olympiad. There going to be $$$n$$$ participants, one of whom is Nikolay. Like any good olympiad, it consists of two rounds. Tired of the traditional rules, in which the participant who solved the larges... | Print two integers — the minimum and maximum possible overall place Nikolay could take. | The first line contains an integer $$$t$$$ ($$$1 \le t \le 100$$$) — the number of test cases to solve. Each of the following $$$t$$$ lines contains integers $$$n$$$, $$$x$$$, $$$y$$$ ($$$1 \leq n \leq 10^9$$$, $$$1 \le x, y \le n$$$) — the number of participants in the olympiad, the place that Nikolay took in the firs... | standard output | standard input | PyPy 3 | Python | 1,700 | train_005.jsonl | 58413aeeba9e694ff76d5b7dc5041439 | 256 megabytes | ["1\n5 1 3", "1\n6 3 4"] | PASSED | import math
import sys
input = iter(sys.stdin.buffer.read().decode().splitlines()).__next__
ilele = lambda: map(int,input().split())
alele = lambda: list(map(int, input().split()))
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
INF ... | 1582448700 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
3 seconds | ["5", "14"] | 48b232b9d836b0be91d41e548a9fcefc | NoteIn the first sample there are 6 one-element sets of silos. For sets {1}, {5} the operation danger will equal 8, for sets {3}, {6} — 3, for sets {2}, {4} — 5. The mathematical average equals .In the second sample there are 3 two-elements sets of silos: {1, 3} (danger equals 21), {1, 2} (danger equals 11), {2, 3} (da... | Insurgents accidentally got hold of the plan of a top secret research polygon created on a distant planet for the needs of the Galaxy Empire. The insurgents suppose that this polygon is developing new deadly weapon. The polygon consists of n missile silos connected by bidirectional underground passages. The passages ar... | Print the average danger of the scouting operation, rounded down to an integer. Note that at the given limits the answer to the problem always fits into the standard integer 64-bit data type. Please do not use the %lld specifier to write 64-bit integers in С++. It is preferred to use the cout stream or the %I64d specif... | The first line contains two integers n and k (2 ≤ n ≤ 2000, 1 ≤ k ≤ n - 1) — the number of silos and the number of scout groups, correspondingly. The next n - 1 lines describe the polygon plan: the i-th of these lines contains n - i integers ci, i + 1, ci, i + 2, ..., ci, n — the number of droids that patrol the corres... | standard output | standard input | PyPy 2 | Python | 2,400 | train_059.jsonl | b15e78d4495ee4e9a1cadbd7fb6a7463 | 256 megabytes | ["6 1\n-1 -1 -1 8 -1\n-1 5 -1 -1\n-1 -1 3\n-1 -1\n-1", "3 2\n10 0\n11"] | PASSED | import sys
sys.setrecursionlimit(2100)
range = xrange
input = raw_input
def getter(DP, k):
n = len(DP) - 1
if 2 * k >= n:
k = n - k
if k < 0:
return 0
return DP[k]
inp = [int(x) for x in sys.stdin.read().split()]; ii = 0
n = inp[ii]; ii += 1
k = inp[ii]; ii += 1
DP = [1]
DPk = []
DPkm... | 1374679800 | [
"math",
"graphs"
] | [
0,
0,
1,
1,
0,
0,
0,
0
] | |
1 second | ["Finite\nInfinite", "Finite\nFinite\nFinite\nInfinite"] | 1b8c94f278ffbdf5b7fc38b3976252b6 | Note$$$\frac{6}{12} = \frac{1}{2} = 0,5_{10}$$$$$$\frac{4}{3} = 1,(3)_{10}$$$$$$\frac{9}{36} = \frac{1}{4} = 0,01_2$$$$$$\frac{4}{12} = \frac{1}{3} = 0,1_3$$$ | You are given several queries. Each query consists of three integers $$$p$$$, $$$q$$$ and $$$b$$$. You need to answer whether the result of $$$p/q$$$ in notation with base $$$b$$$ is a finite fraction.A fraction in notation with base $$$b$$$ is finite if it contains finite number of numerals after the decimal point. It... | For each question, in a separate line, print Finite if the fraction is finite and Infinite otherwise. | The first line contains a single integer $$$n$$$ ($$$1 \le n \le 10^5$$$) — the number of queries. Next $$$n$$$ lines contain queries, one per line. Each line contains three integers $$$p$$$, $$$q$$$, and $$$b$$$ ($$$0 \le p \le 10^{18}$$$, $$$1 \le q \le 10^{18}$$$, $$$2 \le b \le 10^{18}$$$). All numbers are given in... | standard output | standard input | Python 2 | Python | 1,700 | train_026.jsonl | cb08db8d276c29c49094e212cafbf071 | 256 megabytes | ["2\n6 12 10\n4 3 10", "4\n1 1 2\n9 36 2\n4 12 3\n3 5 4"] | PASSED | s0 = raw_input()
n = int(s0)
for i in xrange(n):
s = raw_input()
sa = s.split()
x, y, b = int(sa[0]), int(sa[1]), int(sa[2])
pb = b
for k in range(7):
pb = (pb * pb) % y
if (x * pb) % y == 0:
print "Finite"
else:
print "Infinite"
| 1526395500 | [
"number theory",
"math"
] | [
0,
0,
0,
1,
1,
0,
0,
0
] | |
2 seconds | ["Yes\n1 0\n1 1\n0 1\n0 0\nNo", "Yes\n1 0\n1 1\n2 1\n2 2\n1 2\n1 1\n0 1\n0 0\nYes\n0 -2\n2 -2\n2 -1\n1 -1\n1 0\n0 0", "Yes\n2 0\n2 3\n3 3\n3 7\n4 7\n4 12\n0 12\n0 0\nNo"] | c8d8867789284b2e27fbb73ab3e59793 | NoteIn the first test case of the first example, the answer is Yes — for example, the following picture illustrates a square that satisfies the requirements: In the first test case of the second example, the desired polyline also exists. Note that, the polyline contains self-intersections, but only in the endpoints:... | One drew a closed polyline on a plane, that consisted only of vertical and horizontal segments (parallel to the coordinate axes). The segments alternated between horizontal and vertical ones (a horizontal segment was always followed by a vertical one, and vice versa). The polyline did not contain strict self-intersecti... | For each test case output Yes, if there exists at least one polyline satisfying the requirements, or No otherwise. If it does exist, in the following $$$n$$$ lines print the coordinates of the polyline vertices, in order of the polyline traversal: the $$$i$$$-th line should contain two integers $$$x_i$$$ and $$$y_i$$$ ... | The first line contains one integer $$$t$$$ ($$$1 \leq t \leq 200$$$) —the number of test cases. The first line of each test case contains one integer $$$h$$$ ($$$1 \leq h \leq 1000$$$) — the number of horizontal segments. The following line contains $$$h$$$ integers $$$l_1, l_2, \dots, l_h$$$ ($$$1 \leq l_i \leq 1000$... | standard output | standard input | PyPy 3 | Python | 2,900 | train_027.jsonl | 68d9d087e43970f4cd36eafc1925fe66 | 512 megabytes | ["2\n2\n1 1\n2\n1 1\n\n2\n1 2\n2\n3 3", "2\n4\n1 1 1 1\n4\n1 1 1 1\n\n3\n2 1 1\n3\n2 1 1", "2\n4\n1 4 1 2\n4\n3 4 5 12\n\n4\n1 2 3 6\n2\n1 3"] | PASSED | #!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
def main():
t = int(input())
for _ in range(t):
if _ != 0:
input()
h = int(input())
l1 = list(map(int,input().split()))
v = int(input())
l2 = list(map(int,input().split()))
hKn... | 1604228700 | [
"geometry"
] | [
0,
1,
0,
0,
0,
0,
0,
0
] | |
3 seconds | ["30\n31\n10"] | da15eae7831e3eb5e1f2e2e4c5222fbf | null | One important contest will take place on the most famous programming platform (Topforces) very soon!The authors have a pool of $$$n$$$ problems and should choose at most three of them into this contest. The prettiness of the $$$i$$$-th problem is $$$a_i$$$. The authors have to compose the most pretty contest (in other ... | For each query print one integer — the maximum possible cumulative prettiness of the contest composed of at most three problems from the given pool of problems in the query. | The first line of the input contains one integer $$$q$$$ ($$$1 \le q \le 2 \cdot 10^5$$$) — the number of queries. The first line of the query contains one integer $$$n$$$ ($$$1 \le n \le 2 \cdot 10^5$$$) — the number of problems. The second line of the query contains $$$n$$$ integers $$$a_1, a_2, \dots, a_n$$$ ($$$2 \... | standard output | standard input | PyPy 3 | Python | 2,100 | train_013.jsonl | e6d5f6c8639fb25a2c217a8118fcc6eb | 256 megabytes | ["3\n4\n5 6 15 30\n4\n10 6 30 15\n3\n3 4 6"] | PASSED | def cal(sorted_list, size):
max_sum = 0
for k in range(len(sorted_list)):
max_sum = max(sorted_list[k], max_sum)
for i in range(k+1,size):
temp_1 = sorted_list[i]
if sorted_list[k]%temp_1 != 0:
if i+1 < size and max_sum >= sorted_list[k] + sorted_list[i] +... | 1561559700 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] | |
1 second | ["12.438.32", "6.38", "0.04"] | 8da703549a3002bf9131d6929ec026a2 | null | Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is ... | Print the total price exactly in the same format as prices given in the input. | The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill. It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars. | standard output | standard input | PyPy 2 | Python | 1,600 | train_004.jsonl | e0c678185449fe4d27ce94def541b732 | 256 megabytes | ["chipsy48.32televizor12.390", "a1b2c3.38", "aa0.01t0.03"] | PASSED | #import resource
#import sys
#resource.setrlimit(resource.RLIMIT_STACK, [0x100000000, resource.RLIM_INFINITY])
#import threading
#threading.stack_size(2**26)
#sys.setrecursionlimit(0x1000000)
from sys import stdin, stdout
mod=(10**9)+7
mod1=mod-1
def modinv(n,p):
return pow(n,p-2,p)
fact=[1]
for i in range(1,100001... | 1476522300 | [
"strings"
] | [
0,
0,
0,
0,
0,
0,
1,
0
] | |
2 seconds | ["-3\n0\n0"] | 7dfe0db5a99e6e4d71eb012fab07685b | NoteIn the first test case, you can add roads from pasture $$$1$$$ to pasture $$$2$$$ with a time of $$$2$$$, from pasture $$$2$$$ to pasture $$$3$$$ with a time of $$$1$$$, from pasture $$$3$$$ to pasture $$$1$$$ with a time of $$$-3$$$, from pasture $$$3$$$ to pasture $$$2$$$ with a time of $$$-1$$$, from pastu... | Farmer John has a farm that consists of $$$n$$$ pastures connected by one-directional roads. Each road has a weight, representing the time it takes to go from the start to the end of the road. The roads could have negative weight, where the cows go so fast that they go back in time! However, Farmer John guarantees that... | For each test case, output the minimum possible cost of a farm that is consistent with Farmer John's memory. | The first line contains one integer $$$t$$$ ($$$1 \leq t \leq 10^4$$$) — the number of test cases. Then $$$t$$$ cases follow. The first line of each test case contains a single integer $$$n$$$ ($$$1 \leq n \leq 10^5$$$) — the number of pastures. The second line of each test case contains $$$n$$$ space separated integer... | standard output | standard input | PyPy 3-64 | Python | 1,400 | train_092.jsonl | f85b472e24f47532885c61d31d71f7d3 | 256 megabytes | ["3\n3\n0 2 3\n2\n0 1000000000\n1\n0"] | PASSED |
t = int(input())
def solve(n, a):
a = sorted(a)
s, uk = 0, 0
for i in range(1, n):
uk = uk+(s-a[i]*i)
s = s+a[i]
uk=uk+a[-1]
return uk
for i in range(t):
n = int(input())
a = list(map(int, input().split()))
print(solve(n, a))
| 1624635300 | [
"graphs"
] | [
0,
0,
1,
0,
0,
0,
0,
0
] | |
2 seconds | ["1", "2"] | 74da42a1627e4a00fbaae91c75140287 | null | Iahub and Sorin are the best competitive programmers in their town. However, they can't both qualify to an important contest. The selection will be made with the help of a single problem. Blatnatalag, a friend of Iahub, managed to get hold of the problem before the contest. Because he wants to make sure Iahub will be t... | Output a single integer — the value of mini ≠ j f(i, j). | The first line of input contains a single integer n (2 ≤ n ≤ 100000). Next line contains n integers a[1], a[2], ..., a[n] ( - 104 ≤ a[i] ≤ 104). | standard output | standard input | PyPy 2 | Python | 2,200 | train_066.jsonl | b5e6750d3e97a9ed00febe76f645faf9 | 256 megabytes | ["4\n1 0 0 -1", "2\n1 -1"] | PASSED | import sys
sys.setrecursionlimit(10 ** 6)
def pyes_no(condition) :
if condition :
print ("YES")
else :
print ("NO")
def plist(a, s = ' ') :
print (s.join(map(str, a)))
def rint() :
return int(sys.stdin.readline())
def rints() :
return map(int, sys.stdin.readline().split())
def rfield(n, m = None... | 1399822800 | [
"geometry"
] | [
0,
1,
0,
0,
0,
0,
0,
0
] | |
2 seconds | ["3\n1\n0\n1\n2\n3\n6"] | 1de2203ba34e20fa35571a43c795da53 | null | A matrix of size $$$n \times m$$$, such that each cell of it contains either $$$0$$$ or $$$1$$$, is considered beautiful if the sum in every contiguous submatrix of size $$$2 \times 2$$$ is exactly $$$2$$$, i. e. every "square" of size $$$2 \times 2$$$ contains exactly two $$$1$$$'s and exactly two $$$0$$$'s.You are gi... | For each query, print one integer — the number of ways to fill the empty cells of the matrix after the respective query, taken modulo $$$998244353$$$. | The first line contains three integers $$$n$$$, $$$m$$$ and $$$k$$$ ($$$2 \le n, m \le 10^6$$$; $$$1 \le k \le 3 \cdot 10^5$$$) — the number of rows in the matrix, the number of columns, and the number of queries, respectively. Then $$$k$$$ lines follow, the $$$i$$$-th of them contains three integers $$$x_i$$$, $$$y_i$... | standard output | standard input | PyPy 3 | Python | 2,500 | train_088.jsonl | 66e6e25780c39afb5b8596d3f35c5dce | 256 megabytes | ["2 2 7\n1 1 1\n1 2 1\n2 1 1\n1 1 0\n1 2 -1\n2 1 -1\n1 1 -1"] | PASSED | import sys
import io, os
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
n,m,k=map(int,input().split())
mod=998244353
MOD22=[[0,0],[0,0]]
R=[[0]*n,[0]*n]
C=[[0]*m,[0]*m]
RB=0
CB=0
RK=0
CK=0
D=dict()
ANSLIST=[]
POW2=[1]
for i in range(10**6+4):
POW2.append(POW2[-1]*2%mod)
... | 1632148500 | [
"math"
] | [
0,
0,
0,
1,
0,
0,
0,
0
] |
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