contestId int64 0 1.01k | index stringclasses 57
values | name stringlengths 2 58 | type stringclasses 2
values | rating int64 0 3.5k | tags listlengths 0 11 | title stringclasses 522
values | time-limit stringclasses 8
values | memory-limit stringclasses 8
values | problem-description stringlengths 0 7.15k | input-specification stringlengths 0 2.05k | output-specification stringlengths 0 1.5k | demo-input listlengths 0 7 | demo-output listlengths 0 7 | note stringlengths 0 5.24k | points float64 0 425k | test_cases listlengths 0 402 | creationTimeSeconds int64 1.37B 1.7B | relativeTimeSeconds int64 8 2.15B | programmingLanguage stringclasses 3
values | verdict stringclasses 14
values | testset stringclasses 12
values | passedTestCount int64 0 1k | timeConsumedMillis int64 0 15k | memoryConsumedBytes int64 0 805M | code stringlengths 3 65.5k | prompt stringlengths 262 8.2k | response stringlengths 17 65.5k | score float64 -1 3.99 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
651 | A | Joysticks | PROGRAMMING | 1,100 | [
"dp",
"greedy",
"implementation",
"math"
] | null | null | Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick only at the beginning of each minute. In one minute joystick either discharges by 2 percent (if n... | The first line of the input contains two positive integers *a*1 and *a*2 (1<=≤<=*a*1,<=*a*2<=≤<=100), the initial charge level of first and second joystick respectively. | Output the only integer, the maximum number of minutes that the game can last. Game continues until some joystick is discharged. | [
"3 5\n",
"4 4\n"
] | [
"6\n",
"5\n"
] | In the first sample game lasts for 6 minute by using the following algorithm:
- at the beginning of the first minute connect first joystick to the charger, by the end of this minute first joystick is at 4%, second is at 3%; - continue the game without changing charger, by the end of the second minute the first joyst... | 500 | [
{
"input": "3 5",
"output": "6"
},
{
"input": "4 4",
"output": "5"
},
{
"input": "100 100",
"output": "197"
},
{
"input": "1 100",
"output": "98"
},
{
"input": "100 1",
"output": "98"
},
{
"input": "1 4",
"output": "2"
},
{
"input": "1 1",
... | 1,598,112,441 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 78 | 6,656,000 | a = list(map(int, input().split()))
time = 0
if a[0] != 1 and a[1] != 1:
while a[0] > 0 and a[1] > 0:
if a[0] > a[1]:
a[0] -= 2
a[1] += 1
else:
a[0] += 1
a[1] -= 2
time += 1
print(time) | Title: Joysticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Friends are going to play console. They have two joysticks and only one charger for them. Initially first joystick is charged at *a*1 percent and second one is charged at *a*2 percent. You can connect charger to a joystick on... | ```python
a = list(map(int, input().split()))
time = 0
if a[0] != 1 and a[1] != 1:
while a[0] > 0 and a[1] > 0:
if a[0] > a[1]:
a[0] -= 2
a[1] += 1
else:
a[0] += 1
a[1] -= 2
time += 1
print(time)
``` | 0 | |
315 | A | Sereja and Bottles | PROGRAMMING | 1,400 | [
"brute force"
] | null | null | Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th bottle is from brand *a**i*, besides, you can use it to open other bottles of brand *b**i*. You can use... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of bottles. The next *n* lines contain the bottles' description. The *i*-th line contains two integers *a**i*,<=*b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=1000) — the description of the *i*-th bottle. | In a single line print a single integer — the answer to the problem. | [
"4\n1 1\n2 2\n3 3\n4 4\n",
"4\n1 2\n2 3\n3 4\n4 1\n"
] | [
"4\n",
"0\n"
] | none | 500 | [
{
"input": "4\n1 1\n2 2\n3 3\n4 4",
"output": "4"
},
{
"input": "4\n1 2\n2 3\n3 4\n4 1",
"output": "0"
},
{
"input": "3\n2 828\n4 392\n4 903",
"output": "3"
},
{
"input": "4\n2 3\n1 772\n3 870\n3 668",
"output": "2"
},
{
"input": "5\n1 4\n6 6\n4 3\n3 4\n4 758",
... | 1,679,563,092 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 62 | 0 | n=int(input())
bottle=set()
opener=set()
for _ in range (n):
a,b=map(int,input().split())
bottle.add(a)
if a!=b:
opener.add(b)
s=0
for i in bottle:
if i not in opener:
s+=1
print(s) | Title: Sereja and Bottles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja and his friends went to a picnic. The guys had *n* soda bottles just for it. Sereja forgot the bottle opener as usual, so the guys had to come up with another way to open bottles.
Sereja knows that the *i*-th... | ```python
n=int(input())
bottle=set()
opener=set()
for _ in range (n):
a,b=map(int,input().split())
bottle.add(a)
if a!=b:
opener.add(b)
s=0
for i in bottle:
if i not in opener:
s+=1
print(s)
``` | 0 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Attention: we lost all the test cases for this problem, so instead of solving the problem, we need you to generate test cases. We're going to give you the answer, and you need to print a test case that produces the given answer. The original problem is in the following paragraph.
People don't use cash as often as they... | Input will consist of a single integer *A* (1<=≤<=*A*<=≤<=105), the desired number of ways. | In the first line print integers *N* and *M* (1<=≤<=*N*<=≤<=106,<=1<=≤<=*M*<=≤<=10), the amount of change to be made, and the number of denominations, respectively.
Then print *M* integers *D*1,<=*D*2,<=...,<=*D**M* (1<=≤<=*D**i*<=≤<=106), the denominations of the coins. All denominations must be distinct: for any *i*... | [
"18\n",
"3\n",
"314\n"
] | [
"30 4\n1 5 10 25\n",
"20 2\n5 2\n",
"183 4\n6 5 2 139\n"
] | none | 0 | [
{
"input": "18",
"output": "30 4\n1 5 10 25"
},
{
"input": "3",
"output": "20 2\n5 2"
},
{
"input": "314",
"output": "183 4\n6 5 2 139"
},
{
"input": "1023",
"output": "2045 2\n1 2"
},
{
"input": "100000",
"output": "199999 2\n1 2"
},
{
"input": "1",
... | 1,524,052,068 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 77 | 7,372,800 | a = input()
a = int(a)
print((a - 1) * 2, 2)
print(1, 2) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Attention: we lost all the test cases for this problem, so instead of solving the problem, we need you to generate test cases. We're going to give you the answer, and you need to print a test case that produces the given answer. T... | ```python
a = input()
a = int(a)
print((a - 1) * 2, 2)
print(1, 2)
``` | 0 | |
822 | A | I'm bored with life | PROGRAMMING | 800 | [
"implementation",
"math",
"number theory"
] | null | null | Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormitory for the period of university studies. Consequently Noora had to leave Vičkopolis and move to Pavlopo... | The first and single line contains two integers *A* and *B* (1<=≤<=*A*,<=*B*<=≤<=109,<=*min*(*A*,<=*B*)<=≤<=12). | Print a single integer denoting the greatest common divisor of integers *A*! and *B*!. | [
"4 3\n"
] | [
"6\n"
] | Consider the sample.
4! = 1·2·3·4 = 24. 3! = 1·2·3 = 6. The greatest common divisor of integers 24 and 6 is exactly 6. | 500 | [
{
"input": "4 3",
"output": "6"
},
{
"input": "10 399603090",
"output": "3628800"
},
{
"input": "6 973151934",
"output": "720"
},
{
"input": "2 841668075",
"output": "2"
},
{
"input": "7 415216919",
"output": "5040"
},
{
"input": "3 283733059",
"ou... | 1,669,293,639 | 2,147,483,647 | PyPy 3-64 | RUNTIME_ERROR | TESTS | 1 | 93 | 5,939,200 | import math
a=list(map(int,input().split()))
def fact(n):
if n==0 or n==1:
return(n)
else:
return(n*fact(n-1))
print(math.gcd(fact(a[0]),fact(a[1])))
| Title: I'm bored with life
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Holidays have finished. Thanks to the help of the hacker Leha, Noora managed to enter the university of her dreams which is located in a town Pavlopolis. It's well known that universities provide students with dormi... | ```python
import math
a=list(map(int,input().split()))
def fact(n):
if n==0 or n==1:
return(n)
else:
return(n*fact(n-1))
print(math.gcd(fact(a[0]),fact(a[1])))
``` | -1 | |
258 | A | Little Elephant and Bits | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought to delete exactly one any digit from number *a* in the binary record. At that a new number appears. It consis... | The single line contains integer *a*, written in the binary notation without leading zeroes. This number contains more than 1 and at most 105 digits. | In the single line print the number that is written without leading zeroes in the binary notation — the answer to the problem. | [
"101\n",
"110010\n"
] | [
"11\n",
"11010\n"
] | In the first sample the best strategy is to delete the second digit. That results in number 11<sub class="lower-index">2</sub> = 3<sub class="lower-index">10</sub>.
In the second sample the best strategy is to delete the third or fourth digits — that results in number 11010<sub class="lower-index">2</sub> = 26<sub cla... | 500 | [
{
"input": "101",
"output": "11"
},
{
"input": "110010",
"output": "11010"
},
{
"input": "10000",
"output": "1000"
},
{
"input": "1111111110",
"output": "111111111"
},
{
"input": "10100101011110101",
"output": "1100101011110101"
},
{
"input": "11101001... | 1,684,013,711 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 62 | 0 | x = input()
z = x.count("1")
for i in range(0,len(x)):
if x[i] == "0":
print(x[:i],end="")
print(x[i+1:])
break
if z == 0:
print(x[1:]) | Title: Little Elephant and Bits
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Little Elephant has an integer *a*, written in the binary notation. He wants to write this number on a piece of paper.
To make sure that the number *a* fits on the piece of paper, the Little Elephant ought... | ```python
x = input()
z = x.count("1")
for i in range(0,len(x)):
if x[i] == "0":
print(x[:i],end="")
print(x[i+1:])
break
if z == 0:
print(x[1:])
``` | 0 | |
989 | C | A Mist of Florescence | PROGRAMMING | 1,800 | [
"constructive algorithms",
"graphs"
] | null | null | "I've been here once," Mino exclaims with delight, "it's breathtakingly amazing."
"What is it like?"
"Look, Kanno, you've got your paintbrush, and I've got my words. Have a try, shall we?"
There are four kinds of flowers in the wood, Amaranths, Begonias, Centaureas and Dianthuses.
The wood can be represented by a ... | The first and only line of input contains four space-separated integers $a$, $b$, $c$ and $d$ ($1 \leq a, b, c, d \leq 100$) — the required number of connected components of Amaranths, Begonias, Centaureas and Dianthuses, respectively. | In the first line, output two space-separated integers $n$ and $m$ ($1 \leq n, m \leq 50$) — the number of rows and the number of columns in the grid respectively.
Then output $n$ lines each consisting of $m$ consecutive English letters, representing one row of the grid. Each letter should be among 'A', 'B', 'C' and '... | [
"5 3 2 1\n",
"50 50 1 1\n",
"1 6 4 5\n"
] | [
"4 7\nDDDDDDD\nDABACAD\nDBABACD\nDDDDDDD",
"4 50\nCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC\nABABABABABABABABABABABABABABABABABABABABABABABABAB\nBABABABABABABABABABABABABABABABABABABABABABABABABA\nDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD",
"7 7\nDDDDDDD\nDDDBDBD\nDDCDCDD\nDBDADBD\nDDCDCDD\nDB... | In the first example, each cell of Amaranths, Begonias and Centaureas forms a connected component, while all the Dianthuses form one. | 1,500 | [
{
"input": "5 3 2 1",
"output": "5 13\nAABABBBBCDDAD\nABAABBBBCDADD\nAAAABBBBCDDAD\nAAAABCBBCDADD\nAAAABBBBCDDDD"
},
{
"input": "50 50 1 1",
"output": "10 50\nAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA\nABABABABABABABABABABABABABABABABABABABABABABABABAA\nBABABABABABABABABABABABABABABABAB... | 1,528,765,886 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 93 | 0 | a, b, c, d = map(int, input().split())
m = [['a'] * 50 for i in range(40)]
for i in range(10, 20): m[i] = ['b'] * 50
for i in range(20, 30): m[i] = ['c'] * 50
for i in range(30, 40): m[i] = ['d'] * 50
# them 'b'
for i in range(0, 10, 2):
for j in range(50):
if (((i + j) % 2) == 0) and (b > 1):
... | Title: A Mist of Florescence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
"I've been here once," Mino exclaims with delight, "it's breathtakingly amazing."
"What is it like?"
"Look, Kanno, you've got your paintbrush, and I've got my words. Have a try, shall we?"
There are four kinds... | ```python
a, b, c, d = map(int, input().split())
m = [['a'] * 50 for i in range(40)]
for i in range(10, 20): m[i] = ['b'] * 50
for i in range(20, 30): m[i] = ['c'] * 50
for i in range(30, 40): m[i] = ['d'] * 50
# them 'b'
for i in range(0, 10, 2):
for j in range(50):
if (((i + j) % 2) == 0) and (b >... | 3 | |
522 | A | Reposts | PROGRAMMING | 1,200 | [
"*special",
"dfs and similar",
"dp",
"graphs",
"trees"
] | null | null | One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
These events are given as a sequence of strings "name1 reposted name2", where name1 is the n... | The first line of the input contains integer *n* (1<=≤<=*n*<=≤<=200) — the number of reposts. Next follow the reposts in the order they were made. Each of them is written on a single line and looks as "name1 reposted name2". All the names in the input consist of lowercase or uppercase English letters and/or digits and ... | Print a single integer — the maximum length of a repost chain. | [
"5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya\n",
"6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforces reposted Polycarp\n",
"1\nSoMeStRaNgEgUe repos... | [
"6\n",
"2\n",
"2\n"
] | none | 500 | [
{
"input": "5\ntourist reposted Polycarp\nPetr reposted Tourist\nWJMZBMR reposted Petr\nsdya reposted wjmzbmr\nvepifanov reposted sdya",
"output": "6"
},
{
"input": "6\nMike reposted Polycarp\nMax reposted Polycarp\nEveryOne reposted Polycarp\n111 reposted Polycarp\nVkCup reposted Polycarp\nCodeforc... | 1,634,782,255 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 46 | 4,505,600 | list_of_handles = []
max_length_of_each_handle_chain = []
for iteration in range(int(input())):
repost_inputs = input().split()
reposter = repost_inputs[0].lower()
repostee = repost_inputs[2].lower()
if reposter not in list_of_handles:
list_of_handles.append(reposter)
max_len... | Title: Reposts
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day Polycarp published a funny picture in a social network making a poll about the color of his handle. Many of his friends started reposting Polycarp's joke to their news feed. Some of them reposted the reposts and so on.
... | ```python
list_of_handles = []
max_length_of_each_handle_chain = []
for iteration in range(int(input())):
repost_inputs = input().split()
reposter = repost_inputs[0].lower()
repostee = repost_inputs[2].lower()
if reposter not in list_of_handles:
list_of_handles.append(reposter)
... | 3 | |
687 | B | Remainders Game | PROGRAMMING | 1,800 | [
"chinese remainder theorem",
"math",
"number theory"
] | null | null | Today Pari and Arya are playing a game called Remainders.
Pari chooses two positive integer *x* and *k*, and tells Arya *k* but not *x*. Arya have to find the value . There are *n* ancient numbers *c*1,<=*c*2,<=...,<=*c**n* and Pari has to tell Arya if Arya wants. Given *k* and the ancient values, tell us if Arya has... | The first line of the input contains two integers *n* and *k* (1<=≤<=*n*,<= *k*<=≤<=1<=000<=000) — the number of ancient integers and value *k* that is chosen by Pari.
The second line contains *n* integers *c*1,<=*c*2,<=...,<=*c**n* (1<=≤<=*c**i*<=≤<=1<=000<=000). | Print "Yes" (without quotes) if Arya has a winning strategy independent of value of *x*, or "No" (without quotes) otherwise. | [
"4 5\n2 3 5 12\n",
"2 7\n2 3\n"
] | [
"Yes\n",
"No\n"
] | In the first sample, Arya can understand <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/d170efffcde0907ee6bcf32de21051bce0677a2c.png" style="max-width: 100.0%;max-height: 100.0%;"/> because 5 is one of the ancient numbers.
In the second sample, Arya can't be sure what <img align="middle" ... | 1,000 | [
{
"input": "4 5\n2 3 5 12",
"output": "Yes"
},
{
"input": "2 7\n2 3",
"output": "No"
},
{
"input": "1 6\n8",
"output": "No"
},
{
"input": "2 3\n9 4",
"output": "Yes"
},
{
"input": "4 16\n19 16 13 9",
"output": "Yes"
},
{
"input": "5 10\n5 16 19 9 17",
... | 1,576,678,908 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 1,000 | 9,011,200 | # import sys
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
import math
n,k = map(int,input().split())
c = list(map(int,input().split()))
def getLCM(a,b):
return (a*b)//math.gcd(a,b)
found = False
lc = c[0]
for i in range(1,n):
lc = getLCM(lc,c[i])
if (lc % k == 0):
print("Yes")
e... | Title: Remainders Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today Pari and Arya are playing a game called Remainders.
Pari chooses two positive integer *x* and *k*, and tells Arya *k* but not *x*. Arya have to find the value . There are *n* ancient numbers *c*1,<=*c*2,<=...,<=*... | ```python
# import sys
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
import math
n,k = map(int,input().split())
c = list(map(int,input().split()))
def getLCM(a,b):
return (a*b)//math.gcd(a,b)
found = False
lc = c[0]
for i in range(1,n):
lc = getLCM(lc,c[i])
if (lc % k == 0):
prin... | 0 | |
439 | A | Devu, the Singer and Churu, the Joker | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invited.
Devu has provided organizers a list of the songs and required time for singing them. He will sing *n* songs, *i**th* s... | The first line contains two space separated integers *n*, *d* (1<=≤<=*n*<=≤<=100; 1<=≤<=*d*<=≤<=10000). The second line contains *n* space-separated integers: *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t**i*<=≤<=100). | If there is no way to conduct all the songs of Devu, output -1. Otherwise output the maximum number of jokes that Churu can crack in the grand event. | [
"3 30\n2 2 1\n",
"3 20\n2 1 1\n"
] | [
"5\n",
"-1\n"
] | Consider the first example. The duration of the event is 30 minutes. There could be maximum 5 jokes in the following way:
- First Churu cracks a joke in 5 minutes. - Then Devu performs the first song for 2 minutes. - Then Churu cracks 2 jokes in 10 minutes. - Now Devu performs second song for 2 minutes. - Then Ch... | 500 | [
{
"input": "3 30\n2 2 1",
"output": "5"
},
{
"input": "3 20\n2 1 1",
"output": "-1"
},
{
"input": "50 10000\n5 4 10 9 9 6 7 7 7 3 3 7 7 4 7 4 10 10 1 7 10 3 1 4 5 7 2 10 10 10 2 3 4 7 6 1 8 4 7 3 8 8 4 10 1 1 9 2 6 1",
"output": "1943"
},
{
"input": "50 10000\n4 7 15 9 11 12 ... | 1,529,235,456 | 2,147,483,647 | Python 3 | OK | TESTS | 26 | 78 | 0 | n,d = map(int, input().split())
L = list(map(int, input().split()))
d = d-sum(L)
print([-1,d//5][d >= 10*(n-1)]) | Title: Devu, the Singer and Churu, the Joker
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Devu is a renowned classical singer. He is invited to many big functions/festivals. Recently he was invited to "All World Classical Singing Festival". Other than Devu, comedian Churu was also invit... | ```python
n,d = map(int, input().split())
L = list(map(int, input().split()))
d = d-sum(L)
print([-1,d//5][d >= 10*(n-1)])
``` | 3 | |
379 | A | New Year Candles | PROGRAMMING | 1,000 | [
"implementation"
] | null | null | Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is smart, so he can make *b* went out candles into a new candle. As a result, this new candle can be used ... | The single line contains two integers, *a* and *b* (1<=≤<=*a*<=≤<=1000; 2<=≤<=*b*<=≤<=1000). | Print a single integer — the number of hours Vasily can light up the room for. | [
"4 2\n",
"6 3\n"
] | [
"7\n",
"8\n"
] | Consider the first sample. For the first four hours Vasily lights up new candles, then he uses four burned out candles to make two new ones and lights them up. When these candles go out (stop burning), Vasily can make another candle. Overall, Vasily can light up the room for 7 hours. | 500 | [
{
"input": "4 2",
"output": "7"
},
{
"input": "6 3",
"output": "8"
},
{
"input": "1000 1000",
"output": "1001"
},
{
"input": "123 5",
"output": "153"
},
{
"input": "1000 2",
"output": "1999"
},
{
"input": "1 2",
"output": "1"
},
{
"input": ... | 1,664,083,938 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 32 | 62 | 0 | a,b=map(int,input().split())
ans=a
while a>=b:
x=a%b
a=a//b
ans+=a
a=a+x
print(ans) | Title: New Year Candles
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasily the Programmer loves romance, so this year he decided to illuminate his room with candles.
Vasily has *a* candles.When Vasily lights up a new candle, it first burns for an hour and then it goes out. Vasily is s... | ```python
a,b=map(int,input().split())
ans=a
while a>=b:
x=a%b
a=a//b
ans+=a
a=a+x
print(ans)
``` | 3 | |
296 | A | Yaroslav and Permutations | PROGRAMMING | 1,100 | [
"greedy",
"math"
] | null | null | Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would be distinct in a finite time.
Help Yaroslav. | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of elements in the array. The second line contains *n* integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000) — the array elements. | In the single line print "YES" (without the quotes) if Yaroslav can obtain the array he needs, and "NO" (without the quotes) otherwise. | [
"1\n1\n",
"3\n1 1 2\n",
"4\n7 7 7 7\n"
] | [
"YES\n",
"YES\n",
"NO\n"
] | In the first sample the initial array fits well.
In the second sample Yaroslav can get array: 1, 2, 1. He can swap the last and the second last elements to obtain it.
In the third sample Yarosav can't get the array he needs. | 500 | [
{
"input": "1\n1",
"output": "YES"
},
{
"input": "3\n1 1 2",
"output": "YES"
},
{
"input": "4\n7 7 7 7",
"output": "NO"
},
{
"input": "4\n479 170 465 146",
"output": "YES"
},
{
"input": "5\n996 437 605 996 293",
"output": "YES"
},
{
"input": "6\n727 53... | 1,580,448,276 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 186 | 307,200 | n=int(input())
arr=[int(x) for x in input().split()]
arr=sorted(arr)
print(arr)
arr1=[]
chance=0
for i in range(n):
if chance==0:
arr1.append(arr[i])
chance=1
else:
arr1.append(arr[n-1-i])
cnt=0
for i in range(n-1):
if arr1[i]!=arr1[i+1]:
cnt+=1
... | Title: Yaroslav and Permutations
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Yaroslav has an array that consists of *n* integers. In one second Yaroslav can swap two neighboring array elements. Now Yaroslav is wondering if he can obtain an array where any two neighboring elements would... | ```python
n=int(input())
arr=[int(x) for x in input().split()]
arr=sorted(arr)
print(arr)
arr1=[]
chance=0
for i in range(n):
if chance==0:
arr1.append(arr[i])
chance=1
else:
arr1.append(arr[n-1-i])
cnt=0
for i in range(n-1):
if arr1[i]!=arr1[i+1]:
c... | 0 | |
34 | A | Reconnaissance 2 | PROGRAMMING | 800 | [
"implementation"
] | A. Reconnaissance 2 | 2 | 256 | *n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So each of them will be less noticeable with the other. Output any pair of soldiers that can form a ... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) — amount of soldiers. Then follow the heights of the soldiers in their order in the circle — *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=1000). The soldier heights are given in clockwise or counterclockwise direction. | Output two integers — indexes of neighbouring soldiers, who should form a reconnaissance unit. If there are many optimum solutions, output any of them. Remember, that the soldiers stand in a circle. | [
"5\n10 12 13 15 10\n",
"4\n10 20 30 40\n"
] | [
"5 1\n",
"1 2\n"
] | none | 500 | [
{
"input": "5\n10 12 13 15 10",
"output": "5 1"
},
{
"input": "4\n10 20 30 40",
"output": "1 2"
},
{
"input": "6\n744 359 230 586 944 442",
"output": "2 3"
},
{
"input": "5\n826 747 849 687 437",
"output": "1 2"
},
{
"input": "5\n999 999 993 969 999",
"output"... | 1,590,810,986 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 156 | 0 | import math
n=int(input())
l=list(map(int,input().split()))
d=0
diff=math.inf
o1,o2=0,0
for i in range(n-1):
d=abs(l[i+1]-l[i])
if d<diff:
diff=d
o1=i+1
o2=i+2
print(o1,o2) | Title: Reconnaissance 2
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
*n* soldiers stand in a circle. For each soldier his height *a**i* is known. A reconnaissance unit can be made of such two neighbouring soldiers, whose heights difference is minimal, i.e. |*a**i*<=-<=*a**j*| is minimal. So... | ```python
import math
n=int(input())
l=list(map(int,input().split()))
d=0
diff=math.inf
o1,o2=0,0
for i in range(n-1):
d=abs(l[i+1]-l[i])
if d<diff:
diff=d
o1=i+1
o2=i+2
print(o1,o2)
``` | 0 |
69 | A | Young Physicist | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | A. Young Physicist | 2 | 256 | A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. Specifically, he forgot to complete his physics tasks. Next day the teacher got very angry at Vasy... | The first line contains a positive integer *n* (1<=≤<=*n*<=≤<=100), then follow *n* lines containing three integers each: the *x**i* coordinate, the *y**i* coordinate and the *z**i* coordinate of the force vector, applied to the body (<=-<=100<=≤<=*x**i*,<=*y**i*,<=*z**i*<=≤<=100). | Print the word "YES" if the body is in equilibrium, or the word "NO" if it is not. | [
"3\n4 1 7\n-2 4 -1\n1 -5 -3\n",
"3\n3 -1 7\n-5 2 -4\n2 -1 -3\n"
] | [
"NO",
"YES"
] | none | 500 | [
{
"input": "3\n4 1 7\n-2 4 -1\n1 -5 -3",
"output": "NO"
},
{
"input": "3\n3 -1 7\n-5 2 -4\n2 -1 -3",
"output": "YES"
},
{
"input": "10\n21 32 -46\n43 -35 21\n42 2 -50\n22 40 20\n-27 -9 38\n-4 1 1\n-40 6 -31\n-13 -2 34\n-21 34 -12\n-32 -29 41",
"output": "NO"
},
{
"input": "10... | 1,674,673,286 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | for i in range((int(input()))):
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=list(map(int,input().split()))
d=0
for i in range(len(a)):
if(a[i]+b[i]+c[i]==0):
d=d+1
if d==len(a):
print("YES")
else:
print("NO") | Title: Young Physicist
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A guy named Vasya attends the final grade of a high school. One day Vasya decided to watch a match of his favorite hockey team. And, as the boy loves hockey very much, even more than physics, he forgot to do the homework. S... | ```python
for i in range((int(input()))):
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=list(map(int,input().split()))
d=0
for i in range(len(a)):
if(a[i]+b[i]+c[i]==0):
d=d+1
if d==len(a):
print("YES")
else:
print("NO")
``... | -1 |
218 | A | Mountain Scenery | PROGRAMMING | 1,100 | [
"brute force",
"constructive algorithms",
"implementation"
] | null | null | Little Bolek has found a picture with *n* mountain peaks painted on it. The *n* painted peaks are represented by a non-closed polyline, consisting of 2*n* segments. The segments go through 2*n*<=+<=1 points with coordinates (1,<=*y*1), (2,<=*y*2), ..., (2*n*<=+<=1,<=*y*2*n*<=+<=1), with the *i*-th segment connecting th... | The first line contains two space-separated integers *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100). The next line contains 2*n*<=+<=1 space-separated integers *r*1,<=*r*2,<=...,<=*r*2*n*<=+<=1 (0<=≤<=*r**i*<=≤<=100) — the *y* coordinates of the polyline vertices on Bolek's picture.
It is guaranteed that we can obtain the gi... | Print 2*n*<=+<=1 integers *y*1,<=*y*2,<=...,<=*y*2*n*<=+<=1 — the *y* coordinates of the vertices of the polyline on the initial picture. If there are multiple answers, output any one of them. | [
"3 2\n0 5 3 5 1 5 2\n",
"1 1\n0 2 0\n"
] | [
"0 5 3 4 1 4 2 \n",
"0 1 0 \n"
] | none | 500 | [
{
"input": "3 2\n0 5 3 5 1 5 2",
"output": "0 5 3 4 1 4 2 "
},
{
"input": "1 1\n0 2 0",
"output": "0 1 0 "
},
{
"input": "1 1\n1 100 0",
"output": "1 99 0 "
},
{
"input": "3 1\n0 1 0 1 0 2 0",
"output": "0 1 0 1 0 1 0 "
},
{
"input": "3 1\n0 1 0 2 0 1 0",
"out... | 1,546,531,274 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 186 | 0 | a, b = map(int,input().split())
ans = 0
l = list(map(int,input().split()))
for i in range(b):
for i in range(1 ,len(l ) - 1):
if ans == b:
print(*l)
exit()
if l[i] > l[i + 1] and l[i] > l[i - 1] :
if l[i] - 1 < l[i -1 ] or l[i] -1 < l[i + 1]:
pass
else:
l[i] -= 1
ans += 1
print(*l)
| Title: Mountain Scenery
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Bolek has found a picture with *n* mountain peaks painted on it. The *n* painted peaks are represented by a non-closed polyline, consisting of 2*n* segments. The segments go through 2*n*<=+<=1 points with coordi... | ```python
a, b = map(int,input().split())
ans = 0
l = list(map(int,input().split()))
for i in range(b):
for i in range(1 ,len(l ) - 1):
if ans == b:
print(*l)
exit()
if l[i] > l[i + 1] and l[i] > l[i - 1] :
if l[i] - 1 < l[i -1 ] or l[i] -1 < l[i + 1]:
pass
else:
l[i] -= 1
ans += 1
print(*l... | 0 | |
902 | A | Visiting a Friend | PROGRAMMING | 1,100 | [
"greedy",
"implementation"
] | null | null | Pig is visiting a friend.
Pig's house is located at point 0, and his friend's house is located at point *m* on an axis.
Pig can use teleports to move along the axis.
To use a teleport, Pig should come to a certain point (where the teleport is located) and choose where to move: for each teleport there is the rightmos... | The first line contains two integers *n* and *m* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*m*<=≤<=100) — the number of teleports and the location of the friend's house.
The next *n* lines contain information about teleports.
The *i*-th of these lines contains two integers *a**i* and *b**i* (0<=≤<=*a**i*<=≤<=*b**i*<=≤<=*m*), where ... | Print "YES" if there is a path from Pig's house to his friend's house that uses only teleports, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower). | [
"3 5\n0 2\n2 4\n3 5\n",
"3 7\n0 4\n2 5\n6 7\n"
] | [
"YES\n",
"NO\n"
] | The first example is shown on the picture below:
Pig can use the first teleport from his house (point 0) to reach point 2, then using the second teleport go from point 2 to point 3, then using the third teleport go from point 3 to point 5, where his friend lives.
The second example is shown on the picture below:
You... | 500 | [
{
"input": "3 5\n0 2\n2 4\n3 5",
"output": "YES"
},
{
"input": "3 7\n0 4\n2 5\n6 7",
"output": "NO"
},
{
"input": "1 1\n0 0",
"output": "NO"
},
{
"input": "30 10\n0 7\n1 2\n1 2\n1 4\n1 4\n1 3\n2 2\n2 4\n2 6\n2 9\n2 2\n3 5\n3 8\n4 8\n4 5\n4 6\n5 6\n5 7\n6 6\n6 9\n6 7\n6 9\n7 7... | 1,513,700,313 | 2,613 | Python 3 | OK | TESTS | 55 | 62 | 5,529,600 | n,m = [int(i) for i in input().split()]
setall = set([0])
for i in range(n):
a,b = [int(i) for i in input().split()]
s = set([i for i in range(a,b+1)])
if(setall.intersection(s) != set({})):
setall = setall.union(s)
if(m in setall):
print("YES")
else:
print("NO")
| Title: Visiting a Friend
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Pig is visiting a friend.
Pig's house is located at point 0, and his friend's house is located at point *m* on an axis.
Pig can use teleports to move along the axis.
To use a teleport, Pig should come to a certain ... | ```python
n,m = [int(i) for i in input().split()]
setall = set([0])
for i in range(n):
a,b = [int(i) for i in input().split()]
s = set([i for i in range(a,b+1)])
if(setall.intersection(s) != set({})):
setall = setall.union(s)
if(m in setall):
print("YES")
else:
print("NO")
... | 3 | |
852 | E | Casinos and travel | PROGRAMMING | 2,100 | [
"dp"
] | null | null | John has just bought a new car and is planning a journey around the country. Country has *N* cities, some of which are connected by bidirectional roads. There are *N*<=-<=1 roads and every city is reachable from any other city. Cities are labeled from 1 to *N*.
John first has to select from which city he will start hi... | In the first line, a positive integer *N* (1<=≤<=*N*<=≤<=100000), the number of cities.
In the next *N*<=-<=1 lines, two numbers *a*,<= *b* (1<=≤<=*a*,<=*b*<=≤<=*N*) separated by a single space meaning that cities *a* and *b* are connected by a bidirectional road. | Output one number, the answer to the problem modulo 109<=+<=7. | [
"2\n1 2\n",
"3\n1 2\n2 3\n"
] | [
"4\n",
"10\n"
] | Example 1: If Jack selects city 1 as John's starting city, he can either build 0 casinos, so John will be happy all the time, or build a casino in both cities, so John would visit a casino in city 1, become unhappy, then go to city 2, visit a casino there and become happy and his journey ends there because he can't go ... | 0 | [
{
"input": "2\n1 2",
"output": "4"
},
{
"input": "3\n1 2\n2 3",
"output": "10"
},
{
"input": "4\n1 2\n2 3\n3 4",
"output": "24"
}
] | 1,665,500,559 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 30 | 0 | import math;R,G=lambda:map(int,input().split()),range
n,=R();g=[[] for _ in G(n+1)];M=10**9+7
p=lambda i,n:sum(math.comb(n,k)%M for k in range(i,n+1,2))
for _ in G(n-1):u,v=R();g[u]+=[v];g[v]+=[u]
def f(u0,pre0):
c1=c2=1;q=[(u0,pre0)];stk=[];nodes=[1]*(n+1)
while q:
u,pre=q.pop();stk+=[(u,pre)]
for ... | Title: Casinos and travel
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
John has just bought a new car and is planning a journey around the country. Country has *N* cities, some of which are connected by bidirectional roads. There are *N*<=-<=1 roads and every city is reachable from any ... | ```python
import math;R,G=lambda:map(int,input().split()),range
n,=R();g=[[] for _ in G(n+1)];M=10**9+7
p=lambda i,n:sum(math.comb(n,k)%M for k in range(i,n+1,2))
for _ in G(n-1):u,v=R();g[u]+=[v];g[v]+=[u]
def f(u0,pre0):
c1=c2=1;q=[(u0,pre0)];stk=[];nodes=[1]*(n+1)
while q:
u,pre=q.pop();stk+=[(u,pre)]... | 0 | |
455 | A | Boredom | PROGRAMMING | 1,500 | [
"dp"
] | null | null | Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make several steps. In a single step he can choose an element of the sequence (let's denote it *a*... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) that shows how many numbers are in Alex's sequence.
The second line contains *n* integers *a*1, *a*2, ..., *a**n* (1<=≤<=*a**i*<=≤<=105). | Print a single integer — the maximum number of points that Alex can earn. | [
"2\n1 2\n",
"3\n1 2 3\n",
"9\n1 2 1 3 2 2 2 2 3\n"
] | [
"2\n",
"4\n",
"10\n"
] | Consider the third test example. At first step we need to choose any element equal to 2. After that step our sequence looks like this [2, 2, 2, 2]. Then we do 4 steps, on each step we choose any element equals to 2. In total we earn 10 points. | 500 | [
{
"input": "2\n1 2",
"output": "2"
},
{
"input": "3\n1 2 3",
"output": "4"
},
{
"input": "9\n1 2 1 3 2 2 2 2 3",
"output": "10"
},
{
"input": "5\n3 3 4 5 4",
"output": "11"
},
{
"input": "5\n5 3 5 3 4",
"output": "16"
},
{
"input": "5\n4 2 3 2 5",
... | 1,685,973,889 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 93 | 13,824,000 | n = int(input())
a = list(map(int, input().split()))
count = [0] * (max(a) + 1)
for num in a:
count[num] += num
b = [0] * (max(a) + 1)
b[1] = count[1]
for i in range(2, max(a) + 1):
b[i] = max(b[i - 1], b[i - 2] + count[i])
print(b[max(a)])
| Title: Boredom
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Alex doesn't like boredom. That's why whenever he gets bored, he comes up with games. One long winter evening he came up with a game and decided to play it.
Given a sequence *a* consisting of *n* integers. The player can make ... | ```python
n = int(input())
a = list(map(int, input().split()))
count = [0] * (max(a) + 1)
for num in a:
count[num] += num
b = [0] * (max(a) + 1)
b[1] = count[1]
for i in range(2, max(a) + 1):
b[i] = max(b[i - 1], b[i - 2] + count[i])
print(b[max(a)])
``` | 3 | |
977 | A | Wrong Subtraction | PROGRAMMING | 800 | [
"implementation"
] | null | null | Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit of the number is non-zero, she decreases the number by one; - if the last digit of the number is zero,... | The first line of the input contains two integer numbers $n$ and $k$ ($2 \le n \le 10^9$, $1 \le k \le 50$) — the number from which Tanya will subtract and the number of subtractions correspondingly. | Print one integer number — the result of the decreasing $n$ by one $k$ times.
It is guaranteed that the result will be positive integer number. | [
"512 4\n",
"1000000000 9\n"
] | [
"50\n",
"1\n"
] | The first example corresponds to the following sequence: $512 \rightarrow 511 \rightarrow 510 \rightarrow 51 \rightarrow 50$. | 0 | [
{
"input": "512 4",
"output": "50"
},
{
"input": "1000000000 9",
"output": "1"
},
{
"input": "131203 11",
"output": "12"
},
{
"input": "999999999 50",
"output": "9999"
},
{
"input": "999999999 49",
"output": "99990"
},
{
"input": "131203 9",
"outpu... | 1,696,399,122 | 2,147,483,647 | Python 3 | OK | TESTS | 11 | 46 | 1,126,400 | import traceback
def solve(n,k):
while k>0:
temp=[]
temp=list(str(n))
#print(str(temp))
if int(temp[len(temp)-1])==0:
n/=10
else:
n-=1
n=int(n)
k-=1
return n
def main():
a=input().split(" ")
n=... | Title: Wrong Subtraction
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little girl Tanya is learning how to decrease a number by one, but she does it wrong with a number consisting of two or more digits. Tanya subtracts one from a number by the following algorithm:
- if the last digit ... | ```python
import traceback
def solve(n,k):
while k>0:
temp=[]
temp=list(str(n))
#print(str(temp))
if int(temp[len(temp)-1])==0:
n/=10
else:
n-=1
n=int(n)
k-=1
return n
def main():
a=input().split(" ... | 3 | |
52 | A | 123-sequence | PROGRAMMING | 900 | [
"implementation"
] | A. 123-sequence | 2 | 256 | There is a given sequence of integers *a*1,<=*a*2,<=...,<=*a**n*, where every number is from 1 to 3 inclusively. You have to replace the minimum number of numbers in it so that all the numbers in the sequence are equal to each other. | The first line contains an integer *n* (1<=≤<=*n*<=≤<=106). The second line contains a sequence of integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=3). | Print the minimum number of replacements needed to be performed to make all the numbers in the sequence equal. | [
"9\n1 3 2 2 2 1 1 2 3\n"
] | [
"5\n"
] | In the example all the numbers equal to 1 and 3 should be replaced by 2. | 500 | [
{
"input": "9\n1 3 2 2 2 1 1 2 3",
"output": "5"
},
{
"input": "6\n3 3 2 2 1 3",
"output": "3"
},
{
"input": "12\n3 1 3 1 2 1 3 2 2 1 2 1",
"output": "7"
},
{
"input": "15\n3 2 1 1 1 1 3 2 2 3 3 1 2 3 2",
"output": "10"
},
{
"input": "2\n2 1",
"output": "1"
... | 1,647,970,992 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 60 | 0 | n=int(input())
a=[int(i) for i in input().split()]
s=a.count(1)
c=a.count(2)
x=a.count(3)
m=min(s,c,x)
if s==m:
print(s+min(s,x))
elif c==m:
print(c+min(c,x))
else:
print(x+min(c,s)) | Title: 123-sequence
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
There is a given sequence of integers *a*1,<=*a*2,<=...,<=*a**n*, where every number is from 1 to 3 inclusively. You have to replace the minimum number of numbers in it so that all the numbers in the sequence are equal to each... | ```python
n=int(input())
a=[int(i) for i in input().split()]
s=a.count(1)
c=a.count(2)
x=a.count(3)
m=min(s,c,x)
if s==m:
print(s+min(s,x))
elif c==m:
print(c+min(c,x))
else:
print(x+min(c,s))
``` | 0 |
714 | A | Meeting of Old Friends | PROGRAMMING | 1,100 | [
"implementation",
"math"
] | null | null | Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusive. Also, during the minute *k* she prinks and is unavailable for Filya.
Filya works a lot and he plans to ... | The only line of the input contains integers *l*1, *r*1, *l*2, *r*2 and *k* (1<=≤<=*l*1,<=*r*1,<=*l*2,<=*r*2,<=*k*<=≤<=1018, *l*1<=≤<=*r*1, *l*2<=≤<=*r*2), providing the segments of time for Sonya and Filya and the moment of time when Sonya prinks. | Print one integer — the number of minutes Sonya and Filya will be able to spend together. | [
"1 10 9 20 1\n",
"1 100 50 200 75\n"
] | [
"2\n",
"50\n"
] | In the first sample, they will be together during minutes 9 and 10.
In the second sample, they will be together from minute 50 to minute 74 and from minute 76 to minute 100. | 500 | [
{
"input": "1 10 9 20 1",
"output": "2"
},
{
"input": "1 100 50 200 75",
"output": "50"
},
{
"input": "6 6 5 8 9",
"output": "1"
},
{
"input": "1 1000000000 1 1000000000 1",
"output": "999999999"
},
{
"input": "5 100 8 8 8",
"output": "0"
},
{
"input":... | 1,596,568,016 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 7 | 93 | 6,963,200 | #cheating karne wale tera muh kala
#struck at Dp
#har ghar mein ab ek he nam ek he nARA gujenga...........
#bharat ka baccha bacha jai jai SHREE RAM BOLEGA........
def btd(n):
return int(n,2)
def dtb(n):
return bin(n).replace("0b","")
import sys
input=sys.stdin.buffer.readline
def solve():
l1... | Title: Meeting of Old Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Today an outstanding event is going to happen in the forest — hedgehog Filya will come to his old fried Sonya!
Sonya is an owl and she sleeps during the day and stay awake from minute *l*1 to minute *r*1 inclusi... | ```python
#cheating karne wale tera muh kala
#struck at Dp
#har ghar mein ab ek he nam ek he nARA gujenga...........
#bharat ka baccha bacha jai jai SHREE RAM BOLEGA........
def btd(n):
return int(n,2)
def dtb(n):
return bin(n).replace("0b","")
import sys
input=sys.stdin.buffer.readline
def solve(... | -1 | |
49 | A | Sleuth | PROGRAMMING | 800 | [
"implementation"
] | A. Sleuth | 2 | 256 | Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions whatsoever that can be answered with "Yes" or "No". All the rest agree beforehand to ans... | The single line contains a question represented by a non-empty line consisting of large and small Latin letters, spaces and a question mark. The line length does not exceed 100. It is guaranteed that the question mark occurs exactly once in the line — as the last symbol and that the line contains at least one letter. | Print answer for the question in a single line: YES if the answer is "Yes", NO if the answer is "No".
Remember that in the reply to the question the last letter, not the last character counts. I. e. the spaces and the question mark do not count as letters. | [
"Is it a melon?\n",
"Is it an apple?\n",
"Is it a banana ?\n",
"Is it an apple and a banana simultaneouSLY?\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | none | 500 | [
{
"input": "Is it a melon?",
"output": "NO"
},
{
"input": "Is it an apple?",
"output": "YES"
},
{
"input": " Is it a banana ?",
"output": "YES"
},
{
"input": "Is it an apple and a banana simultaneouSLY?",
"output": "YES"
},
{
"input": "oHtSbDwzHb?",
... | 1,572,707,182 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 216 | 0 | s=input()
s.split()
def last(p):
for i in range(len(p)-1,0,-1):
x=p[i]
if x!='?' and x!=' ':
return x
a=['a','e','i','o','u','A','E','I','U','O']
t=last(s)
if t in a:
print('YES')
else:
print("NO") | Title: Sleuth
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Vasya plays the sleuth with his friends. The rules of the game are as follows: those who play for the first time, that is Vasya is the sleuth, he should investigate a "crime" and find out what is happening. He can ask any questions ... | ```python
s=input()
s.split()
def last(p):
for i in range(len(p)-1,0,-1):
x=p[i]
if x!='?' and x!=' ':
return x
a=['a','e','i','o','u','A','E','I','U','O']
t=last(s)
if t in a:
print('YES')
else:
print("NO")
``` | 0 |
774 | K | Stepan and Vowels | PROGRAMMING | 1,600 | [
"*special",
"implementation",
"strings"
] | null | null | Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the words written by Stepan. This program must combine all consecutive equal vowels to a single vowel. The vowe... | The first line contains the integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of letters in the word written by Stepan.
The second line contains the string *s* which has length that equals to *n* and contains only lowercase English letters — the word written by Stepan. | Print the single string — the word written by Stepan converted according to the rules described in the statement. | [
"13\npobeeeedaaaaa\n",
"22\niiiimpleeemeentatiioon\n",
"18\naeiouyaaeeiioouuyy\n",
"24\naaaoooiiiuuuyyyeeeggghhh\n"
] | [
"pobeda\n",
"implemeentatioon\n",
"aeiouyaeeioouy\n",
"aoiuyeggghhh\n"
] | none | 0 | [
{
"input": "13\npobeeeedaaaaa",
"output": "pobeda"
},
{
"input": "22\niiiimpleeemeentatiioon",
"output": "implemeentatioon"
},
{
"input": "18\naeiouyaaeeiioouuyy",
"output": "aeiouyaeeioouy"
},
{
"input": "24\naaaoooiiiuuuyyyeeeggghhh",
"output": "aoiuyeggghhh"
},
{
... | 1,491,410,698 | 4,198 | Python 3 | WRONG_ANSWER | TESTS | 6 | 61 | 5,529,600 | n = int(input());
a = {'a', 'o', 'e', 'u','i','y'};
s = input();
curVolve = 'a';
curCount = 0;
ans = [];
i=0;
flag=0;
while i<n:
if s[i] in a:
curVolve = s[i];
if curVolve=='e' or curVolve=='o':
if flag==2:
ans.pop();
while i<n and s[i]==curVolve:
i+=1;
... | Title: Stepan and Vowels
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Stepan likes to repeat vowel letters when he writes words. For example, instead of the word "pobeda" he can write "pobeeeedaaaaa".
Sergey does not like such behavior, so he wants to write a program to format the word... | ```python
n = int(input());
a = {'a', 'o', 'e', 'u','i','y'};
s = input();
curVolve = 'a';
curCount = 0;
ans = [];
i=0;
flag=0;
while i<n:
if s[i] in a:
curVolve = s[i];
if curVolve=='e' or curVolve=='o':
if flag==2:
ans.pop();
while i<n and s[i]==curVolve:
i+=1... | 0 | |
931 | B | World Cup | PROGRAMMING | 1,200 | [
"constructive algorithms",
"implementation"
] | null | null | The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in the order of their ids, then the first in this order plays with the second, the third — with the ... | The only line contains three integers *n*, *a* and *b* (2<=≤<=*n*<=≤<=256, 1<=≤<=*a*,<=*b*<=≤<=*n*) — the total number of teams, and the ids of the teams that Arkady is interested in.
It is guaranteed that *n* is such that in each round an even number of team advance, and that *a* and *b* are not equal. | In the only line print "Final!" (without quotes), if teams *a* and *b* can meet in the Final.
Otherwise, print a single integer — the number of the round in which teams *a* and *b* can meet. The round are enumerated from 1. | [
"4 1 2\n",
"8 2 6\n",
"8 7 5\n"
] | [
"1\n",
"Final!\n",
"2\n"
] | In the first example teams 1 and 2 meet in the first round.
In the second example teams 2 and 6 can only meet in the third round, which is the Final, if they win all their opponents in earlier rounds.
In the third example the teams with ids 7 and 5 can meet in the second round, if they win their opponents in the firs... | 1,000 | [
{
"input": "4 1 2",
"output": "1"
},
{
"input": "8 2 6",
"output": "Final!"
},
{
"input": "8 7 5",
"output": "2"
},
{
"input": "128 30 98",
"output": "Final!"
},
{
"input": "256 128 256",
"output": "Final!"
},
{
"input": "256 2 127",
"output": "7"
... | 1,613,292,336 | 2,147,483,647 | Python 3 | OK | TESTS | 64 | 62 | 0 | from math import log
n, a, b = map(int, input().split())
a -= 1
b -= 1
max_r = int(log(n, 2)) #n would be power of 2 , bcz there will alaways be even no of matches
#n n//2 n/4......1
c = 0
while a // 2 != b // 2: #if a//2==b//2 thwy will be next to each other and then they will fight... | Title: World Cup
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The last stage of Football World Cup is played using the play-off system.
There are *n* teams left in this stage, they are enumerated from 1 to *n*. Several rounds are held, in each round the remaining teams are sorted in th... | ```python
from math import log
n, a, b = map(int, input().split())
a -= 1
b -= 1
max_r = int(log(n, 2)) #n would be power of 2 , bcz there will alaways be even no of matches
#n n//2 n/4......1
c = 0
while a // 2 != b // 2: #if a//2==b//2 thwy will be next to each other and then they ... | 3 | |
656 | A | Da Vinci Powers | PROGRAMMING | 1,900 | [
"*special"
] | null | null | The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output a single integer. | The input contains a single integer *a* (0<=≤<=*a*<=≤<=35). | Output a single integer. | [
"3\n",
"10\n"
] | [
"8\n",
"1024\n"
] | none | 0 | [
{
"input": "3",
"output": "8"
},
{
"input": "10",
"output": "1024"
},
{
"input": "35",
"output": "33940307968"
},
{
"input": "0",
"output": "1"
},
{
"input": "1",
"output": "2"
},
{
"input": "2",
"output": "4"
},
{
"input": "4",
"output... | 1,459,807,247 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 14 | 46 | 4,812,800 | n = int(input())
if n != 35:
print(2**n)
else:
print(33940307968) | Title: Da Vinci Powers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output a single integer.
Input Specification:
The input contains a single integer *a* (0<=≤<=*a*<=≤<=35).
Output Specification:
Output a single integer.
De... | ```python
n = int(input())
if n != 35:
print(2**n)
else:
print(33940307968)
``` | 0 | |
412 | A | Poster | PROGRAMMING | 900 | [
"greedy",
"implementation"
] | null | null | The R1 company has recently bought a high rise building in the centre of Moscow for its main office. It's time to decorate the new office, and the first thing to do is to write the company's slogan above the main entrance to the building.
The slogan of the company consists of *n* characters, so the decorators hung a l... | The first line contains two integers, *n* and *k* (1<=≤<=*k*<=≤<=*n*<=≤<=100) — the number of characters in the slogan and the initial position of the ladder, correspondingly. The next line contains the slogan as *n* characters written without spaces. Each character of the slogan is either a large English letter, or di... | In *t* lines, print the actions the programmers need to make. In the *i*-th line print:
- "LEFT" (without the quotes), if the *i*-th action was "move the ladder to the left"; - "RIGHT" (without the quotes), if the *i*-th action was "move the ladder to the right"; - "PRINT *x*" (without the quotes), if the *i*-th ac... | [
"2 2\nR1\n",
"2 1\nR1\n",
"6 4\nGO?GO!\n"
] | [
"PRINT 1\nLEFT\nPRINT R\n",
"PRINT R\nRIGHT\nPRINT 1\n",
"RIGHT\nRIGHT\nPRINT !\nLEFT\nPRINT O\nLEFT\nPRINT G\nLEFT\nPRINT ?\nLEFT\nPRINT O\nLEFT\nPRINT G\n"
] | Note that the ladder cannot be shifted by less than one meter. The ladder can only stand in front of some square of the poster. For example, you cannot shift a ladder by half a meter and position it between two squares. Then go up and paint the first character and the second character. | 500 | [
{
"input": "2 2\nR1",
"output": "PRINT 1\nLEFT\nPRINT R"
},
{
"input": "2 1\nR1",
"output": "PRINT R\nRIGHT\nPRINT 1"
},
{
"input": "6 4\nGO?GO!",
"output": "RIGHT\nRIGHT\nPRINT !\nLEFT\nPRINT O\nLEFT\nPRINT G\nLEFT\nPRINT ?\nLEFT\nPRINT O\nLEFT\nPRINT G"
},
{
"input": "7 3\n... | 1,398,848,112 | 612 | Python 3 | WRONG_ANSWER | TESTS | 1 | 46 | 0 | n, k = map(int, input().split())
L = list(input())
for i in range(k, n):
print('RIGHT')
i = n - 1
while i != 0:
print('PRINT', L[i])
print('LEFT')
i -= 1
print('PRINT', L[0]) | Title: Poster
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The R1 company has recently bought a high rise building in the centre of Moscow for its main office. It's time to decorate the new office, and the first thing to do is to write the company's slogan above the main entrance to the... | ```python
n, k = map(int, input().split())
L = list(input())
for i in range(k, n):
print('RIGHT')
i = n - 1
while i != 0:
print('PRINT', L[i])
print('LEFT')
i -= 1
print('PRINT', L[0])
``` | 0 | |
9 | A | Die Roll | PROGRAMMING | 800 | [
"math",
"probabilities"
] | A. Die Roll | 1 | 64 | Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about Tasmania, its beaches, sun and sea. Dot chose Transylvania as the most mysterious and unpr... | The only line of the input file contains two natural numbers Y and W — the results of Yakko's and Wakko's die rolls. | Output the required probability in the form of irreducible fraction in format «A/B», where A — the numerator, and B — the denominator. If the required probability equals to zero, output «0/1». If the required probability equals to 1, output «1/1». | [
"4 2\n"
] | [
"1/2\n"
] | Dot will go to Transylvania, if she is lucky to roll 4, 5 or 6 points. | 0 | [
{
"input": "4 2",
"output": "1/2"
},
{
"input": "1 1",
"output": "1/1"
},
{
"input": "1 2",
"output": "5/6"
},
{
"input": "1 3",
"output": "2/3"
},
{
"input": "1 4",
"output": "1/2"
},
{
"input": "1 5",
"output": "1/3"
},
{
"input": "1 6",
... | 1,640,895,471 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 0 | w = int(input())
y = int(input())
bigger = max(w, y)
dot = 6 - bigger + 1
prob = (dot / 6).as_integer_ratio()
print(str(prob[0]) + '/' + str(prob[1])) | Title: Die Roll
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
Yakko, Wakko and Dot, world-famous animaniacs, decided to rest from acting in cartoons, and take a leave to travel a bit. Yakko dreamt to go to Pennsylvania, his Motherland and the Motherland of his ancestors. Wakko thought about T... | ```python
w = int(input())
y = int(input())
bigger = max(w, y)
dot = 6 - bigger + 1
prob = (dot / 6).as_integer_ratio()
print(str(prob[0]) + '/' + str(prob[1]))
``` | -1 |
277 | A | Learning Languages | PROGRAMMING | 1,400 | [
"dfs and similar",
"dsu"
] | null | null | The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have the list of languages, which he knows. This list could be empty, i. e. an employee may know no official la... | The first line contains two integers *n* and *m* (2<=≤<=*n*,<=*m*<=≤<=100) — the number of employees and the number of languages.
Then *n* lines follow — each employee's language list. At the beginning of the *i*-th line is integer *k**i* (0<=≤<=*k**i*<=≤<=*m*) — the number of languages the *i*-th employee knows. Next... | Print a single integer — the minimum amount of money to pay so that in the end every employee could write a letter to every other one (other employees can help out translating). | [
"5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5\n",
"8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1\n",
"2 2\n1 2\n0\n"
] | [
"0\n",
"2\n",
"1\n"
] | In the second sample the employee 1 can learn language 2, and employee 8 can learn language 4.
In the third sample employee 2 must learn language 2. | 500 | [
{
"input": "5 5\n1 2\n2 2 3\n2 3 4\n2 4 5\n1 5",
"output": "0"
},
{
"input": "8 7\n0\n3 1 2 3\n1 1\n2 5 4\n2 6 7\n1 3\n2 7 4\n1 1",
"output": "2"
},
{
"input": "2 2\n1 2\n0",
"output": "1"
},
{
"input": "2 2\n0\n0",
"output": "2"
},
{
"input": "5 5\n1 3\n0\n0\n2 4... | 1,545,856,472 | 2,147,483,647 | Python 3 | OK | TESTS | 33 | 248 | 0 | def dfs(s):
if visited[s]:return
visited[s]=1
for j in adj[s]:
dfs(j)
n,m=(map(int, input().split()))
T=lambda:[[] for i in range(n+m)]
adj=T()
ans=-1
s=[]
r=0
for i in range(n):
l=(list(map(lambda x:int(x)+n-1, input().split())))
adj[i]=l[1:]
for j in adj[i]:
adj[j]+=[i]
visited... | Title: Learning Languages
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The "BerCorp" company has got *n* employees. These employees can use *m* approved official languages for the formal correspondence. The languages are numbered with integers from 1 to *m*. For each employee we have th... | ```python
def dfs(s):
if visited[s]:return
visited[s]=1
for j in adj[s]:
dfs(j)
n,m=(map(int, input().split()))
T=lambda:[[] for i in range(n+m)]
adj=T()
ans=-1
s=[]
r=0
for i in range(n):
l=(list(map(lambda x:int(x)+n-1, input().split())))
adj[i]=l[1:]
for j in adj[i]:
adj[j]+=[... | 3 | |
493 | C | Vasya and Basketball | PROGRAMMING | 1,600 | [
"binary search",
"brute force",
"data structures",
"implementation",
"sortings",
"two pointers"
] | null | null | Vasya follows a basketball game and marks the distances from which each team makes a throw. He knows that each successful throw has value of either 2 or 3 points. A throw is worth 2 points if the distance it was made from doesn't exceed some value of *d* meters, and a throw is worth 3 points if the distance is larger t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2·105) — the number of throws of the first team. Then follow *n* integer numbers — the distances of throws *a**i* (1<=≤<=*a**i*<=≤<=2·109).
Then follows number *m* (1<=≤<=*m*<=≤<=2·105) — the number of the throws of the second team. Then follow *m* integer numbers — ... | Print two numbers in the format a:b — the score that is possible considering the problem conditions where the result of subtraction *a*<=-<=*b* is maximum. If there are several such scores, find the one in which number *a* is maximum. | [
"3\n1 2 3\n2\n5 6\n",
"5\n6 7 8 9 10\n5\n1 2 3 4 5\n"
] | [
"9:6\n",
"15:10\n"
] | none | 2,000 | [
{
"input": "3\n1 2 3\n2\n5 6",
"output": "9:6"
},
{
"input": "5\n6 7 8 9 10\n5\n1 2 3 4 5",
"output": "15:10"
},
{
"input": "5\n1 2 3 4 5\n5\n6 7 8 9 10",
"output": "15:15"
},
{
"input": "3\n1 2 3\n3\n6 4 5",
"output": "9:9"
},
{
"input": "10\n1 2 3 4 5 6 7 8 9 10... | 1,587,303,930 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | import sys
import bisect
#input=sys.stdin.buffer.readline()
#n=int(input())
n =int(sys.stdin.readline().lstrip().rstrip())
arr=list(map(int,sys.stdin.readline().lstrip().rstrip().split()))
#m=int(input())
m=int(sys.stdin.readline().lstrip().rstrip())
ls=list(map(int,sys.stdin.readline().lstrip().rstrip().split(... | Title: Vasya and Basketball
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya follows a basketball game and marks the distances from which each team makes a throw. He knows that each successful throw has value of either 2 or 3 points. A throw is worth 2 points if the distance it was ma... | ```python
import sys
import bisect
#input=sys.stdin.buffer.readline()
#n=int(input())
n =int(sys.stdin.readline().lstrip().rstrip())
arr=list(map(int,sys.stdin.readline().lstrip().rstrip().split()))
#m=int(input())
m=int(sys.stdin.readline().lstrip().rstrip())
ls=list(map(int,sys.stdin.readline().lstrip().rstri... | 0 | |
155 | A | I_love_\%username\% | PROGRAMMING | 800 | [
"brute force"
] | null | null | Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the results of all contests where his favorite coder participated and track the progress of his coolness. For e... | The first line contains the single integer *n* (1<=≤<=*n*<=≤<=1000) — the number of contests where the coder participated.
The next line contains *n* space-separated non-negative integer numbers — they are the points which the coder has earned. The points are given in the chronological order. All points do not exceed ... | Print the single number — the number of amazing performances the coder has had during his whole history of participating in the contests. | [
"5\n100 50 200 150 200\n",
"10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242\n"
] | [
"2\n",
"4\n"
] | In the first sample the performances number 2 and 3 are amazing.
In the second sample the performances number 2, 4, 9 and 10 are amazing. | 500 | [
{
"input": "5\n100 50 200 150 200",
"output": "2"
},
{
"input": "10\n4664 6496 5814 7010 5762 5736 6944 4850 3698 7242",
"output": "4"
},
{
"input": "1\n6",
"output": "0"
},
{
"input": "2\n2 1",
"output": "1"
},
{
"input": "5\n100 36 53 7 81",
"output": "2"
... | 1,690,558,786 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 92 | 0 | n = int(input())
points = [int(i) for i in input().split()]
answer = 0
maxi = points[0]
mini = points[0]
for point in points:
if point > maxi:
maxi = point
answer += 1
elif point < mini:
mini = point
answer += 1
print(answer) | Title: I_love_\%username\%
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya adores sport programming. He can't write programs but he loves to watch the contests' progress. Vasya even has a favorite coder and Vasya pays special attention to him.
One day Vasya decided to collect the re... | ```python
n = int(input())
points = [int(i) for i in input().split()]
answer = 0
maxi = points[0]
mini = points[0]
for point in points:
if point > maxi:
maxi = point
answer += 1
elif point < mini:
mini = point
answer += 1
print(answer)
``` | 3 | |
182 | D | Common Divisors | PROGRAMMING | 1,400 | [
"brute force",
"hashing",
"implementation",
"math",
"strings"
] | null | null | Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive integer *x* such that if we write out string *a* consecutively *x* times, we get string *b*. For exam... | The first input line contains a non-empty string *s*1.
The second input line contains a non-empty string *s*2.
Lengths of strings *s*1 and *s*2 are positive and do not exceed 105. The strings only consist of lowercase Latin letters. | Print the number of common divisors of strings *s*1 and *s*2. | [
"abcdabcd\nabcdabcdabcdabcd\n",
"aaa\naa\n"
] | [
"2\n",
"1\n"
] | In first sample the common divisors are strings "abcd" and "abcdabcd".
In the second sample the common divisor is a single string "a". String "aa" isn't included in the answer as it isn't a divisor of string "aaa". | 1,000 | [
{
"input": "abcdabcd\nabcdabcdabcdabcd",
"output": "2"
},
{
"input": "aaa\naa",
"output": "1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaa\naaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "3"
},
{
"input": "aaaaaaaaaaaaaa\naaaaaaaaaaaaaa",
"output": "4"
},
{
"input": "a\nb",
... | 1,635,387,050 | 2,147,483,647 | PyPy 3 | OK | TESTS | 75 | 216 | 26,828,800 | s=input()
t=input()
m=len(s)
n=len(t)
ans=0
for i in range(1,min(m,n)+1):
if m%i>0 or n%i>0:
continue
p=s[:i]
if p*(m//i)==s and p*(n//i)==t:
ans+=1
print(ans) | Title: Common Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive ... | ```python
s=input()
t=input()
m=len(s)
n=len(t)
ans=0
for i in range(1,min(m,n)+1):
if m%i>0 or n%i>0:
continue
p=s[:i]
if p*(m//i)==s and p*(n//i)==t:
ans+=1
print(ans)
``` | 3 | |
234 | C | Weather | PROGRAMMING | 1,300 | [
"dp",
"implementation"
] | null | null | Scientists say a lot about the problems of global warming and cooling of the Earth. Indeed, such natural phenomena strongly influence all life on our planet.
Our hero Vasya is quite concerned about the problems. He decided to try a little experiment and observe how outside daily temperature changes. He hung out a ther... | The first line contains a single integer *n* (2<=≤<=*n*<=≤<=105) — the number of days for which Vasya has been measuring the temperature.
The second line contains a sequence of *n* integers *t*1,<=*t*2,<=...,<=*t**n* (|*t**i*|<=≤<=109) — the sequence of temperature values. Numbers *t**i* are separated by single space... | Print a single integer — the answer to the given task. | [
"4\n-1 1 -2 1\n",
"5\n0 -1 1 2 -5\n"
] | [
"1\n",
"2\n"
] | Note to the first sample: there are two ways to change exactly one number so that the sequence met Vasya's condition. You can either replace the first number 1 by any negative number or replace the number -2 by any positive number. | 0 | [
{
"input": "4\n-1 1 -2 1",
"output": "1"
},
{
"input": "5\n0 -1 1 2 -5",
"output": "2"
},
{
"input": "6\n0 0 0 0 0 0",
"output": "6"
},
{
"input": "6\n-1 -2 -3 -4 5 6",
"output": "0"
},
{
"input": "8\n1 2 -1 0 10 2 12 13",
"output": "3"
},
{
"input": "... | 1,620,670,900 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 62 | 6,963,200 | x = int(input())
y = 0
z = 10**9 #max value
TT = [int(i) for i in input().split()]
t = sum(i<=0 for i in TT) #count <=0 temps
for i in range(x):
if TT[i]<=0:
t -= 1
if TT[i]>=0:
y += 1
if i==x-1 and TT[i]<=0:
t += 1
z = min(z,t+y)
print (z)
| Title: Weather
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Scientists say a lot about the problems of global warming and cooling of the Earth. Indeed, such natural phenomena strongly influence all life on our planet.
Our hero Vasya is quite concerned about the problems. He decided to ... | ```python
x = int(input())
y = 0
z = 10**9 #max value
TT = [int(i) for i in input().split()]
t = sum(i<=0 for i in TT) #count <=0 temps
for i in range(x):
if TT[i]<=0:
t -= 1
if TT[i]>=0:
y += 1
if i==x-1 and TT[i]<=0:
t += 1
z = min(z,t+y)
print (z)
... | -1 | |
832 | A | Sasha and Sticks | PROGRAMMING | 800 | [
"games",
"math"
] | null | null | It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with whom he shares a desk. The rules are simple. Sasha draws *n* sticks in a row. After that the players t... | The first line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=1018, *k*<=≤<=*n*) — the number of sticks drawn by Sasha and the number *k* — the number of sticks to be crossed out on each turn. | If Sasha wins, print "YES" (without quotes), otherwise print "NO" (without quotes).
You can print each letter in arbitrary case (upper of lower). | [
"1 1\n",
"10 4\n"
] | [
"YES\n",
"NO\n"
] | In the first example Sasha crosses out 1 stick, and then there are no sticks. So Lena can't make a move, and Sasha wins.
In the second example Sasha crosses out 4 sticks, then Lena crosses out 4 sticks, and after that there are only 2 sticks left. Sasha can't make a move. The players make equal number of moves, so Sas... | 500 | [
{
"input": "1 1",
"output": "YES"
},
{
"input": "10 4",
"output": "NO"
},
{
"input": "251656215122324104 164397544865601257",
"output": "YES"
},
{
"input": "963577813436662285 206326039287271924",
"output": "NO"
},
{
"input": "1000000000000000000 1",
"output":... | 1,586,302,511 | 2,147,483,647 | PyPy 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 2,000 | 1,536,000 | from sys import stdin
n,k = map(int, stdin.readline().rstrip().split(' '))
sasha = True
while n > k:
n -= k
sasha = not sasha
if (n == k or n == 0) and sasha:
print('YES')
elif (n != 0 or n != k) and not sasha:
print('YES')
else:
print('NO') | Title: Sasha and Sticks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
It's one more school day now. Sasha doesn't like classes and is always bored at them. So, each day he invents some game and plays in it alone or with friends.
Today he invented one simple game to play with Lena, with ... | ```python
from sys import stdin
n,k = map(int, stdin.readline().rstrip().split(' '))
sasha = True
while n > k:
n -= k
sasha = not sasha
if (n == k or n == 0) and sasha:
print('YES')
elif (n != 0 or n != k) and not sasha:
print('YES')
else:
print('NO')
``` | 0 | |
401 | B | Sereja and Contests | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Sereja is a coder and he likes to take part in Codesorfes rounds. However, Uzhland doesn't have good internet connection, so Sereja sometimes skips rounds.
Codesorfes has rounds of two types: *Div*1 (for advanced coders) and *Div*2 (for beginner coders). Two rounds, *Div*1 and *Div*2, can go simultaneously, (*Div*1 ro... | The first line contains two integers: *x* (1<=≤<=*x*<=≤<=4000) — the round Sereja is taking part in today, and *k* (0<=≤<=*k*<=<<=4000) — the number of rounds he took part in.
Next *k* lines contain the descriptions of the rounds that Sereja took part in before. If Sereja took part in one of two simultaneous rounds... | Print in a single line two integers — the minimum and the maximum number of rounds that Sereja could have missed. | [
"3 2\n2 1\n2 2\n",
"9 3\n1 2 3\n2 8\n1 4 5\n",
"10 0\n"
] | [
"0 0",
"2 3",
"5 9"
] | In the second sample we have unused identifiers of rounds 1, 6, 7. The minimum number of rounds Sereja could have missed equals to 2. In this case, the round with the identifier 1 will be a usual *Div*2 round and the round with identifier 6 will be synchronous with the *Div*1 round.
The maximum number of rounds equal... | 1,000 | [
{
"input": "3 2\n2 1\n2 2",
"output": "0 0"
},
{
"input": "9 3\n1 2 3\n2 8\n1 4 5",
"output": "2 3"
},
{
"input": "10 0",
"output": "5 9"
},
{
"input": "10 2\n1 1 2\n1 8 9",
"output": "3 5"
},
{
"input": "9 3\n1 4 5\n1 1 2\n1 6 7",
"output": "2 2"
},
{
... | 1,583,403,953 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 109 | 307,200 | I = lambda: map(int, input().split())
x, k = I()
R = [0, x]
for _ in range(k):
_, *r = I()
R += r
R.sort()
max_ = min_ = 0
for i in range(len(R)-1):
min_ += (R[i+1]-R[i]) // 2
max_ += R[i+1]-R[i]-1
print(min_, max_) | Title: Sereja and Contests
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sereja is a coder and he likes to take part in Codesorfes rounds. However, Uzhland doesn't have good internet connection, so Sereja sometimes skips rounds.
Codesorfes has rounds of two types: *Div*1 (for advanced c... | ```python
I = lambda: map(int, input().split())
x, k = I()
R = [0, x]
for _ in range(k):
_, *r = I()
R += r
R.sort()
max_ = min_ = 0
for i in range(len(R)-1):
min_ += (R[i+1]-R[i]) // 2
max_ += R[i+1]-R[i]-1
print(min_, max_)
``` | 3 | |
831 | C | Jury Marks | PROGRAMMING | 1,700 | [
"brute force",
"constructive algorithms"
] | null | null | Polycarp watched TV-show where *k* jury members one by one rated a participant by adding him a certain number of points (may be negative, i. e. points were subtracted). Initially the participant had some score, and each the marks were one by one added to his score. It is known that the *i*-th jury member gave *a**i* po... | The first line contains two integers *k* and *n* (1<=≤<=*n*<=≤<=*k*<=≤<=2<=000) — the number of jury members and the number of scores Polycarp remembers.
The second line contains *k* integers *a*1,<=*a*2,<=...,<=*a**k* (<=-<=2<=000<=≤<=*a**i*<=≤<=2<=000) — jury's marks in chronological order.
The third line contains ... | Print the number of options for the score the participant could have before the judges rated the participant. If Polycarp messes something up and there is no options, print "0" (without quotes). | [
"4 1\n-5 5 0 20\n10\n",
"2 2\n-2000 -2000\n3998000 4000000\n"
] | [
"3\n",
"1\n"
] | The answer for the first example is 3 because initially the participant could have - 10, 10 or 15 points.
In the second example there is only one correct initial score equaling to 4 002 000. | 1,000 | [
{
"input": "4 1\n-5 5 0 20\n10",
"output": "3"
},
{
"input": "2 2\n-2000 -2000\n3998000 4000000",
"output": "1"
},
{
"input": "1 1\n-577\n1273042",
"output": "1"
},
{
"input": "2 1\n614 -1943\n3874445",
"output": "2"
},
{
"input": "3 1\n1416 -1483 1844\n3261895",
... | 1,671,142,074 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 2,000 | 9,932,800 | k,n=map(int,input().split())
a,b=list(map(int,input().split())),list(map(int,input().split()))
sums=[0]
for i in a:sums.append(sums[-1]+i)
sums=sums[1:]
allstart=[]
aa=0
allstart=set(allstart)
for i in range(k):
for j in range(n):allstart.add(b[j]-sums[i])
for i in allstart:
vals=[i]
for j in a:
i+=j
vals.append... | Title: Jury Marks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Polycarp watched TV-show where *k* jury members one by one rated a participant by adding him a certain number of points (may be negative, i. e. points were subtracted). Initially the participant had some score, and each the ... | ```python
k,n=map(int,input().split())
a,b=list(map(int,input().split())),list(map(int,input().split()))
sums=[0]
for i in a:sums.append(sums[-1]+i)
sums=sums[1:]
allstart=[]
aa=0
allstart=set(allstart)
for i in range(k):
for j in range(n):allstart.add(b[j]-sums[i])
for i in allstart:
vals=[i]
for j in a:
i+=j
v... | 0 | |
999 | A | Mishka and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Mishka started participating in a programming contest. There are $n$ problems in the contest. Mishka's problem-solving skill is equal to $k$.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses ... | The first line of input contains two integers $n$ and $k$ ($1 \le n, k \le 100$) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 100$), where $a_i$ is the difficulty of the $i$-th problem. The problems are... | Print one integer — the maximum number of problems Mishka can solve. | [
"8 4\n4 2 3 1 5 1 6 4\n",
"5 2\n3 1 2 1 3\n",
"5 100\n12 34 55 43 21\n"
] | [
"5\n",
"0\n",
"5\n"
] | In the first example, Mishka can solve problems in the following order: $[4, 2, 3, 1, 5, 1, 6, 4] \rightarrow [2, 3, 1, 5, 1, 6, 4] \rightarrow [2, 3, 1, 5, 1, 6] \rightarrow [3, 1, 5, 1, 6] \rightarrow [1, 5, 1, 6] \rightarrow [5, 1, 6]$, so the number of solved problems will be equal to $5$.
In the second example, M... | 0 | [
{
"input": "8 4\n4 2 3 1 5 1 6 4",
"output": "5"
},
{
"input": "5 2\n3 1 2 1 3",
"output": "0"
},
{
"input": "5 100\n12 34 55 43 21",
"output": "5"
},
{
"input": "100 100\n44 47 36 83 76 94 86 69 31 2 22 77 37 51 10 19 25 78 53 25 1 29 48 95 35 53 22 72 49 86 60 38 13 91 89 1... | 1,613,749,825 | 2,125 | Python 3 | OK | TESTS | 48 | 77 | 307,200 | n,k=map(int,input().split())
lst=list(map(int,input().split()))[:n]
l=0
for i in range(n):
if lst[i]<=k:
l=l+1
else:
break
lst.reverse()
for i in range(len(lst)):
if lst[i]<=k:
l=l+1
else:
break
if l==2*n:
print(n)
else:
print(l) | Title: Mishka and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mishka started participating in a programming contest. There are $n$ problems in the contest. Mishka's problem-solving skill is equal to $k$.
Mishka arranges all problems from the contest into a list. Because of his... | ```python
n,k=map(int,input().split())
lst=list(map(int,input().split()))[:n]
l=0
for i in range(n):
if lst[i]<=k:
l=l+1
else:
break
lst.reverse()
for i in range(len(lst)):
if lst[i]<=k:
l=l+1
else:
break
if l==2*n:
print(n)
else:
print(l)
``` | 3 | |
41 | A | Translation | PROGRAMMING | 800 | [
"implementation",
"strings"
] | A. Translation | 2 | 256 | The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc.... | The first line contains word *s*, the second line contains word *t*. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols. | If the word *t* is a word *s*, written reversely, print YES, otherwise print NO. | [
"code\nedoc\n",
"abb\naba\n",
"code\ncode\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | none | 500 | [
{
"input": "code\nedoc",
"output": "YES"
},
{
"input": "abb\naba",
"output": "NO"
},
{
"input": "code\ncode",
"output": "NO"
},
{
"input": "abacaba\nabacaba",
"output": "YES"
},
{
"input": "q\nq",
"output": "YES"
},
{
"input": "asrgdfngfnmfgnhweratgjkk... | 1,668,830,922 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 | n = input()
answer = 'NO'
for i in range (n):
inpute = input()
if inpute == n:
print(answer)
else:
print('YES') | Title: Translation
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pron... | ```python
n = input()
answer = 'NO'
for i in range (n):
inpute = input()
if inpute == n:
print(answer)
else:
print('YES')
``` | -1 |
177 | A1 | Good Matrix Elements | PROGRAMMING | 800 | [
"implementation"
] | null | null | The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the main diagonal. - Elements of the secondary diagonal. - Elements of the "middle" row — the row which ha... | The first line of input data contains a single odd integer *n*. Each of the next *n* lines contains *n* integers *a**ij* (0<=≤<=*a**ij*<=≤<=100) separated by single spaces — the elements of the given matrix.
The input limitations for getting 30 points are:
- 1<=≤<=*n*<=≤<=5
The input limitations for getting 100 po... | Print a single integer — the sum of good matrix elements. | [
"3\n1 2 3\n4 5 6\n7 8 9\n",
"5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n"
] | [
"45\n",
"17\n"
] | In the first sample all matrix elements will be good. Good elements in the second sample are shown on the figure. | 30 | [
{
"input": "3\n1 2 3\n4 5 6\n7 8 9",
"output": "45"
},
{
"input": "5\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1\n1 1 1 1 1",
"output": "17"
},
{
"input": "1\n3",
"output": "3"
},
{
"input": "5\n27 7 3 11 72\n19 49 68 19 59\n41 25 37 64 65\n8 39 96 62 90\n13 37 43 26 33",
... | 1,552,214,338 | 2,147,483,647 | Python 3 | OK | TESTS1 | 17 | 218 | 0 | n = int(input())
cnt = 0
for i in range(n):
a = list(map(int, input().split()))
for j in range(n):
if j in [i, n - i - 1]:
pass
elif n - 1 not in [i * 2, j * 2]:
continue
cnt += a[j]
print(cnt) | Title: Good Matrix Elements
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
The Smart Beaver from ABBYY got hooked on square matrices. Now he is busy studying an *n*<=×<=*n* size matrix, where *n* is odd. The Smart Beaver considers the following matrix elements good:
- Elements of the ... | ```python
n = int(input())
cnt = 0
for i in range(n):
a = list(map(int, input().split()))
for j in range(n):
if j in [i, n - i - 1]:
pass
elif n - 1 not in [i * 2, j * 2]:
continue
cnt += a[j]
print(cnt)
``` | 3 | |
344 | A | Magnets | PROGRAMMING | 800 | [
"implementation"
] | null | null | Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets are put together at a close distance, then the like poles will repel each other and the oppo... | The first line of the input contains an integer *n* (1<=≤<=*n*<=≤<=100000) — the number of magnets. Then *n* lines follow. The *i*-th line (1<=≤<=*i*<=≤<=*n*) contains either characters "01", if Mike put the *i*-th magnet in the "plus-minus" position, or characters "10", if Mike put the magnet in the "minus-plus" posit... | On the single line of the output print the number of groups of magnets. | [
"6\n10\n10\n10\n01\n10\n10\n",
"4\n01\n01\n10\n10\n"
] | [
"3\n",
"2\n"
] | The first testcase corresponds to the figure. The testcase has three groups consisting of three, one and two magnets.
The second testcase has two groups, each consisting of two magnets. | 500 | [
{
"input": "6\n10\n10\n10\n01\n10\n10",
"output": "3"
},
{
"input": "4\n01\n01\n10\n10",
"output": "2"
},
{
"input": "1\n10",
"output": "1"
},
{
"input": "2\n01\n10",
"output": "2"
},
{
"input": "2\n10\n10",
"output": "1"
},
{
"input": "3\n10\n01\n10",... | 1,698,161,027 | 2,147,483,647 | PyPy 3-64 | TIME_LIMIT_EXCEEDED | TESTS | 6 | 1,000 | 5,836,800 | n = int(input())
count = 0
a = 0
b = 2 # ini angka ngarang aja y soalnya ga ngaruh yang penting jangan 0 atau 1
for i in range(n):
pole = list(map(int, input()))
a = pole[0]
if i > 0:
if a == b:
count += 1
b = pole[1]
print(count + 1)
| Title: Magnets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mad scientist Mike entertains himself by arranging rows of dominoes. He doesn't need dominoes, though: he uses rectangular magnets instead. Each magnet has two poles, positive (a "plus") and negative (a "minus"). If two magnets... | ```python
n = int(input())
count = 0
a = 0
b = 2 # ini angka ngarang aja y soalnya ga ngaruh yang penting jangan 0 atau 1
for i in range(n):
pole = list(map(int, input()))
a = pole[0]
if i > 0:
if a == b:
count += 1
b = pole[1]
print(count + 1)
``` | 0 | |
908 | A | New Year and Counting Cards | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | null | null | Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each card is visible.
You would like to know if the following statement is true for cards that your friend owns: "If a c... | The first and only line of input will contain a string *s* (1<=≤<=|*s*|<=≤<=50), denoting the sides of the cards that you can see on the table currently. Each character of *s* is either a lowercase English letter or a digit. | Print a single integer, the minimum number of cards you must turn over to verify your claim. | [
"ee\n",
"z\n",
"0ay1\n"
] | [
"2\n",
"0\n",
"2\n"
] | In the first sample, we must turn over both cards. Note that even though both cards have the same letter, they could possibly have different numbers on the other side.
In the second sample, we don't need to turn over any cards. The statement is vacuously true, since you know your friend has no cards with a vowel on th... | 500 | [
{
"input": "ee",
"output": "2"
},
{
"input": "z",
"output": "0"
},
{
"input": "0ay1",
"output": "2"
},
{
"input": "0abcdefghijklmnopqrstuvwxyz1234567896",
"output": "10"
},
{
"input": "0a0a9e9e2i2i9o9o6u6u9z9z4x4x9b9b",
"output": "18"
},
{
"input": "01... | 1,602,422,668 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 109 | 0 | cards = input()
vogais = 'aeiou'
impares = '13579'
total = 0
for i in range(len(cards)):
if cards[i] in vogais or cards[i] in impares:
total += 1
print(total)
| Title: New Year and Counting Cards
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Your friend has *n* cards.
You know that each card has a lowercase English letter on one side and a digit on the other.
Currently, your friend has laid out the cards on a table so only one side of each car... | ```python
cards = input()
vogais = 'aeiou'
impares = '13579'
total = 0
for i in range(len(cards)):
if cards[i] in vogais or cards[i] in impares:
total += 1
print(total)
``` | 3 | |
776 | A | A Serial Killer | PROGRAMMING | 900 | [
"brute force",
"implementation",
"strings"
] | null | null | Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers of deduction, he came to know that the killer has a strategy for selecting his next victim.
The killer starts with two potential victims on his first day, selects one of these two, kills selected ... | First line of input contains two names (length of each of them doesn't exceed 10), the two initials potential victims. Next line contains integer *n* (1<=≤<=*n*<=≤<=1000), the number of days.
Next *n* lines contains two names (length of each of them doesn't exceed 10), first being the person murdered on this day and t... | Output *n*<=+<=1 lines, the *i*-th line should contain the two persons from which the killer selects for the *i*-th murder. The (*n*<=+<=1)-th line should contain the two persons from which the next victim is selected. In each line, the two names can be printed in any order. | [
"ross rachel\n4\nross joey\nrachel phoebe\nphoebe monica\nmonica chandler\n",
"icm codeforces\n1\ncodeforces technex\n"
] | [
"ross rachel\njoey rachel\njoey phoebe\njoey monica\njoey chandler\n",
"icm codeforces\nicm technex\n"
] | In first example, the killer starts with ross and rachel.
- After day 1, ross is killed and joey appears. - After day 2, rachel is killed and phoebe appears. - After day 3, phoebe is killed and monica appears. - After day 4, monica is killed and chandler appears. | 500 | [
{
"input": "ross rachel\n4\nross joey\nrachel phoebe\nphoebe monica\nmonica chandler",
"output": "ross rachel\njoey rachel\njoey phoebe\njoey monica\njoey chandler"
},
{
"input": "icm codeforces\n1\ncodeforces technex",
"output": "icm codeforces\nicm technex"
},
{
"input": "a b\n3\na c\n... | 1,687,701,309 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 108 | 11,366,400 | #Bhai python master kru ya c++ pe shift ho jaau?
s=str(input())
t=int(input())
store=s+"\n"
for i in range(t):
s1=str(input())
s2=s1.split()
s=s.replace(s2[0],s2[1])
store+=s+"\n"
print(store,end="") | Title: A Serial Killer
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Our beloved detective, Sherlock is currently trying to catch a serial killer who kills a person each day. Using his powers of deduction, he came to know that the killer has a strategy for selecting his next victim.
The... | ```python
#Bhai python master kru ya c++ pe shift ho jaau?
s=str(input())
t=int(input())
store=s+"\n"
for i in range(t):
s1=str(input())
s2=s1.split()
s=s.replace(s2[0],s2[1])
store+=s+"\n"
print(store,end="")
``` | 0 | |
376 | A | Lever | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar is a segment on the *Ox* axis between points 0 and |*s*|<=-<=1.
The decoding of the lever d... | The first line contains the lever description as a non-empty string *s* (3<=≤<=|*s*|<=≤<=106), consisting of digits (1-9) and characters "^" and "=". It is guaranteed that the line contains exactly one character "^". It is guaranteed that the pivot of the lever isn't located in any end of the lever bar.
To solve the p... | Print "left" if the given lever tilts to the left, "right" if it tilts to the right and "balance", if it is in balance. | [
"=^==\n",
"9===^==1\n",
"2==^7==\n",
"41^52==\n"
] | [
"balance\n",
"left\n",
"right\n",
"balance\n"
] | As you solve the problem, you may find the following link useful to better understand how a lever functions: http://en.wikipedia.org/wiki/Lever.
The pictures to the examples: | 500 | [
{
"input": "=^==",
"output": "balance"
},
{
"input": "9===^==1",
"output": "left"
},
{
"input": "2==^7==",
"output": "right"
},
{
"input": "41^52==",
"output": "balance"
},
{
"input": "=^2=4=1===1=",
"output": "right"
},
{
"input": "9=6===5==3=9=1=1^7=... | 1,602,855,163 | 2,147,483,647 | PyPy 3 | OK | TESTS | 60 | 295 | 7,270,400 | s = input()
for i in range(len(s)):
if s[i] == '^':
xl = i
xr = i
left = 0
right = 0
while xl!=0:
xl-=1
if s[xl] == '=':
continue
if int(s[xl]) in range(1,10):
left += int(s[xl])*abs(xl-i)
while xr!=l... | Title: Lever
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You have a description of a lever as string *s*. We'll represent the string length as record |*s*|, then the lever looks as a horizontal bar with weights of length |*s*|<=-<=1 with exactly one pivot. We will assume that the bar i... | ```python
s = input()
for i in range(len(s)):
if s[i] == '^':
xl = i
xr = i
left = 0
right = 0
while xl!=0:
xl-=1
if s[xl] == '=':
continue
if int(s[xl]) in range(1,10):
left += int(s[xl])*abs(xl-i)
w... | 3 | |
433 | B | Kuriyama Mirai's Stones | PROGRAMMING | 1,200 | [
"dp",
"implementation",
"sortings"
] | null | null | Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones so she will ask you two kinds of questions:
1. She will tell you two numbers, *l* and *r* (1<=≤<=*l*<=≤<=*r*... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=105). The second line contains *n* integers: *v*1,<=*v*2,<=...,<=*v**n* (1<=≤<=*v**i*<=≤<=109) — costs of the stones.
The third line contains an integer *m* (1<=≤<=*m*<=≤<=105) — the number of Kuriyama Mirai's questions. Then follow *m* lines, each line contains t... | Print *m* lines. Each line must contain an integer — the answer to Kuriyama Mirai's question. Print the answers to the questions in the order of input. | [
"6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6\n",
"4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2\n"
] | [
"24\n9\n28\n",
"10\n15\n5\n15\n5\n5\n2\n12\n3\n5\n"
] | Please note that the answers to the questions may overflow 32-bit integer type. | 1,500 | [
{
"input": "6\n6 4 2 7 2 7\n3\n2 3 6\n1 3 4\n1 1 6",
"output": "24\n9\n28"
},
{
"input": "4\n5 5 2 3\n10\n1 2 4\n2 1 4\n1 1 1\n2 1 4\n2 1 2\n1 1 1\n1 3 3\n1 1 3\n1 4 4\n1 2 2",
"output": "10\n15\n5\n15\n5\n5\n2\n12\n3\n5"
},
{
"input": "4\n2 2 3 6\n9\n2 2 3\n1 1 3\n2 2 3\n2 2 3\n2 2 2\n1... | 1,661,692,300 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 46 | 842 | 33,382,400 | class Segment:
def __init__(self, nums):
self.data = [0 for _ in nums] + nums
self.n = len(nums)
for idx in reversed(range(1, self.n)):
self.data[idx] = self.data[2*idx] + self.data[2*idx + 1]
def update(self, i: int, val: int) -> None:
... | Title: Kuriyama Mirai's Stones
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Kuriyama Mirai has killed many monsters and got many (namely *n*) stones. She numbers the stones from 1 to *n*. The cost of the *i*-th stone is *v**i*. Kuriyama Mirai wants to know something about these stones s... | ```python
class Segment:
def __init__(self, nums):
self.data = [0 for _ in nums] + nums
self.n = len(nums)
for idx in reversed(range(1, self.n)):
self.data[idx] = self.data[2*idx] + self.data[2*idx + 1]
def update(self, i: int, val: int) -> Non... | 3 | |
272 | A | Dima and Friends | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the apartment, the friends want to play a counting-out game. First, all the guys stand in a circle, and t... | The first line contains integer *n* (1<=≤<=*n*<=≤<=100) — the number of Dima's friends. Dima himself isn't considered to be his own friend. The second line contains *n* positive integers, not exceeding 5, representing, how many fingers the Dima's friends will show.
The numbers in the lines are separated by a single s... | In a single line print the answer to the problem. | [
"1\n1\n",
"1\n2\n",
"2\n3 5\n"
] | [
"3\n",
"2\n",
"3\n"
] | In the first sample Dima can show 1, 3 or 5 fingers. If Dima shows 3 fingers, then the counting-out will go like that: Dima, his friend, Dima, his friend.
In the second sample Dima can show 2 or 4 fingers. | 500 | [
{
"input": "1\n1",
"output": "3"
},
{
"input": "1\n2",
"output": "2"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "2\n3 5",
"output": "3"
},
{
"input": "1\n5",
"output": "3"
},
{
"input": "5\n4 4 3 5 1",
"output": "4"
},
{
"input": "... | 1,584,782,113 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 218 | 0 | n=int(input())
f=[int(f) for f in input().split()]
count=0
for i in range (1,6):
ans=(((sum(f)+i)%(n+1)))
if (ans!=1):
count+=1
print (count) | Title: Dima and Friends
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dima and his friends have been playing hide and seek at Dima's place all night. As a result, Dima's place got messy. In the morning they decided that they need to clean the place.
To decide who exactly would clean the... | ```python
n=int(input())
f=[int(f) for f in input().split()]
count=0
for i in range (1,6):
ans=(((sum(f)+i)%(n+1)))
if (ans!=1):
count+=1
print (count)
``` | 3 | |
182 | D | Common Divisors | PROGRAMMING | 1,400 | [
"brute force",
"hashing",
"implementation",
"math",
"strings"
] | null | null | Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive integer *x* such that if we write out string *a* consecutively *x* times, we get string *b*. For exam... | The first input line contains a non-empty string *s*1.
The second input line contains a non-empty string *s*2.
Lengths of strings *s*1 and *s*2 are positive and do not exceed 105. The strings only consist of lowercase Latin letters. | Print the number of common divisors of strings *s*1 and *s*2. | [
"abcdabcd\nabcdabcdabcdabcd\n",
"aaa\naa\n"
] | [
"2\n",
"1\n"
] | In first sample the common divisors are strings "abcd" and "abcdabcd".
In the second sample the common divisor is a single string "a". String "aa" isn't included in the answer as it isn't a divisor of string "aaa". | 1,000 | [
{
"input": "abcdabcd\nabcdabcdabcdabcd",
"output": "2"
},
{
"input": "aaa\naa",
"output": "1"
},
{
"input": "aaaaaaaaaaaaaaaaaaaaaaaaa\naaaaaaaaaaaaaaaaaaaaaaaaa",
"output": "3"
},
{
"input": "aaaaaaaaaaaaaa\naaaaaaaaaaaaaa",
"output": "4"
},
{
"input": "a\nb",
... | 1,423,752,942 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 1 | 124 | 0 | s1 = input()
s2 = input()
p = ""
subs1 = set()
for c in s1:
p += c
if p * (len(s1) // len(p)) == s1:
subs1.add(p)
p = ""
subs2 = set()
for c in s2:
p += c
if p * (len(s1) // len(p)) == s2:
subs1.add(p)
print(len(subs1 ^ subs2))
| Title: Common Divisors
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya has recently learned at school what a number's divisor is and decided to determine a string's divisor. Here is what he came up with.
String *a* is the divisor of string *b* if and only if there exists a positive ... | ```python
s1 = input()
s2 = input()
p = ""
subs1 = set()
for c in s1:
p += c
if p * (len(s1) // len(p)) == s1:
subs1.add(p)
p = ""
subs2 = set()
for c in s2:
p += c
if p * (len(s1) // len(p)) == s2:
subs1.add(p)
print(len(subs1 ^ subs2))
``` | 0 | |
785 | A | Anton and Polyhedrons | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahedron. Octahedron has 8 triangular faces. - Dodecahedron. Dodecahedron has 12 pentagonal faces. - Icosahed... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=200<=000) — the number of polyhedrons in Anton's collection.
Each of the following *n* lines of the input contains a string *s**i* — the name of the *i*-th polyhedron in Anton's collection. The string can look like this:
- "Tetrahedron" (withou... | Output one number — the total number of faces in all the polyhedrons in Anton's collection. | [
"4\nIcosahedron\nCube\nTetrahedron\nDodecahedron\n",
"3\nDodecahedron\nOctahedron\nOctahedron\n"
] | [
"42\n",
"28\n"
] | In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has 20 faces, cube has 6 faces, tetrahedron has 4 faces and dodecahedron has 12 faces. In total, they have 20 + 6 + 4 + 12 = 42 faces. | 500 | [
{
"input": "4\nIcosahedron\nCube\nTetrahedron\nDodecahedron",
"output": "42"
},
{
"input": "3\nDodecahedron\nOctahedron\nOctahedron",
"output": "28"
},
{
"input": "25\nIcosahedron\nOctahedron\nTetrahedron\nDodecahedron\nCube\nIcosahedron\nOctahedron\nCube\nTetrahedron\nIcosahedron\nIcosa... | 1,673,385,334 | 2,147,483,647 | Python 3 | OK | TESTS | 30 | 295 | 0 | n = int(input())
suma = 0
while(n>0):
pol = input()
if(pol == "Tetrahedron"):
suma += 4
elif(pol == "Cube"):
suma += 6
elif(pol == "Octahedron"):
suma += 8
elif(pol == "Dodecahedron"):
suma += 12
elif(pol == "Icosahedron"):
suma += 20
n -... | Title: Anton and Polyhedrons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has 4 triangular faces. - Cube. Cube has 6 square faces. - Octahe... | ```python
n = int(input())
suma = 0
while(n>0):
pol = input()
if(pol == "Tetrahedron"):
suma += 4
elif(pol == "Cube"):
suma += 6
elif(pol == "Octahedron"):
suma += 8
elif(pol == "Dodecahedron"):
suma += 12
elif(pol == "Icosahedron"):
suma += 2... | 3 | |
810 | B | Summer sell-off | PROGRAMMING | 1,300 | [
"greedy",
"sortings"
] | null | null | Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an assistant.
Shop, where Noora is working, has a plan on the following *n* days. For each day sales manag... | The first line contains two integers *n* and *f* (1<=≤<=*n*<=≤<=105,<=0<=≤<=*f*<=≤<=*n*) denoting the number of days in shop's plan and the number of days that Noora has to choose for sell-out.
Each line of the following *n* subsequent lines contains two integers *k**i*,<=*l**i* (0<=≤<=*k**i*,<=*l**i*<=≤<=109) denotin... | Print a single integer denoting the maximal number of products that shop can sell. | [
"4 2\n2 1\n3 5\n2 3\n1 5\n",
"4 1\n0 2\n0 3\n3 5\n0 6\n"
] | [
"10",
"5"
] | In the first example we can choose days with numbers 2 and 4 for sell-out. In this case new numbers of products for sale would be equal to [2, 6, 2, 2] respectively. So on the first day shop will sell 1 product, on the second — 5, on the third — 2, on the fourth — 2. In total 1 + 5 + 2 + 2 = 10 product units.
In the s... | 1,000 | [
{
"input": "4 2\n2 1\n3 5\n2 3\n1 5",
"output": "10"
},
{
"input": "4 1\n0 2\n0 3\n3 5\n0 6",
"output": "5"
},
{
"input": "1 1\n5 8",
"output": "8"
},
{
"input": "2 1\n8 12\n6 11",
"output": "19"
},
{
"input": "2 1\n6 7\n5 7",
"output": "13"
},
{
"inpu... | 1,579,770,123 | 2,523 | Python 3 | OK | TESTS | 159 | 405 | 3,276,800 | #!/usr/bin/env python3
import sys, math, itertools, collections, bisect
input = lambda: sys.stdin.buffer.readline().rstrip().decode('utf-8')
inf = float('inf') ;mod = 10**9+7
mans = inf ;ans = 0 ;count = 0 ;pro = 1
n,f=map(int,input().split())
array=[]
for i in range(n):
k,l=map(int,input().split())
... | Title: Summer sell-off
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Summer holidays! Someone is going on trips, someone is visiting grandparents, but someone is trying to get a part-time job. This summer Noora decided that she wants to earn some money, and took a job in a shop as an ass... | ```python
#!/usr/bin/env python3
import sys, math, itertools, collections, bisect
input = lambda: sys.stdin.buffer.readline().rstrip().decode('utf-8')
inf = float('inf') ;mod = 10**9+7
mans = inf ;ans = 0 ;count = 0 ;pro = 1
n,f=map(int,input().split())
array=[]
for i in range(n):
k,l=map(int,input().spli... | 3 | |
81 | A | Plug-in | PROGRAMMING | 1,400 | [
"implementation"
] | A. Plug-in | 1 | 256 | Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed only once. For example, instead of the phrase "how are you" he can type "hhoow aaaare yy... | The input data consists of a single line to be processed. The length of the line is from 1 to 2·105 characters inclusive. The string contains only lowercase Latin letters. | Print the given string after it is processed. It is guaranteed that the result will contain at least one character. | [
"hhoowaaaareyyoouu\n",
"reallazy\n",
"abacabaabacabaa\n"
] | [
"wre",
"rezy",
"a"
] | none | 500 | [
{
"input": "hhoowaaaareyyoouu",
"output": "wre"
},
{
"input": "reallazy",
"output": "rezy"
},
{
"input": "abacabaabacabaa",
"output": "a"
},
{
"input": "xraccabccbry",
"output": "xy"
},
{
"input": "a",
"output": "a"
},
{
"input": "b",
"output": "b"... | 1,645,702,309 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 4 | 1,000 | 8,499,200 | st = input()
f = True
while f:
f = False
i=0
l=len(st)-1
while i<l:
if st[i]==st[i+1]:
st = st[0:i]+st[i+2:]
l=l-2
i=i-1
f=True
i+=1
print(st)
| Title: Plug-in
Time Limit: 1 seconds
Memory Limit: 256 megabytes
Problem Description:
Polycarp thinks about the meaning of life very often. He does this constantly, even when typing in the editor. Every time he starts brooding he can no longer fully concentrate and repeatedly presses the keys that need to be pressed... | ```python
st = input()
f = True
while f:
f = False
i=0
l=len(st)-1
while i<l:
if st[i]==st[i+1]:
st = st[0:i]+st[i+2:]
l=l-2
i=i-1
f=True
i+=1
print(st)
``` | 0 |
9 | B | Running Student | PROGRAMMING | 1,200 | [
"brute force",
"geometry",
"implementation"
] | B. Running Student | 1 | 64 | And again a misfortune fell on Poor Student. He is being late for an exam.
Having rushed to a bus stop that is in point (0,<=0), he got on a minibus and they drove along a straight line, parallel to axis *OX*, in the direction of increasing *x*.
Poor Student knows the following:
- during one run the minibus makes ... | The first line contains three integer numbers: 2<=≤<=*n*<=≤<=100, 1<=≤<=*v**b*,<=*v**s*<=≤<=1000. The second line contains *n* non-negative integers in ascending order: coordinates *x**i* of the bus stop with index *i*. It is guaranteed that *x*1 equals to zero, and *x**n*<=≤<=105. The third line contains the coordinat... | In the only line output the answer to the problem — index of the optimum bus stop. | [
"4 5 2\n0 2 4 6\n4 1\n",
"2 1 1\n0 100000\n100000 100000\n"
] | [
"3",
"2"
] | As you know, students are a special sort of people, and minibuses usually do not hurry. That's why you should not be surprised, if Student's speed is higher than the speed of the minibus. | 0 | [
{
"input": "4 5 2\n0 2 4 6\n4 1",
"output": "3"
},
{
"input": "2 1 1\n0 100000\n100000 100000",
"output": "2"
},
{
"input": "6 5 1\n0 1 2 3 4 5\n0 0",
"output": "2"
},
{
"input": "4 100 10\n0 118 121 178\n220 220",
"output": "4"
},
{
"input": "4 3 3\n0 6 8 10\n7 -... | 1,539,533,095 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 2 | 216 | 0 | n,b,c = map(int,input().split())
a = list(map(int,input().split())); d = []
x1,y1 = map(int,input().split()); k = 0
for i in range(n): d.append(((x1-a[i])**2+y1**2)**(1/2))
p = d[0]
for i in range(len(d)):
if d[i] < p: p = d[i]; k = i
print(k+1) | Title: Running Student
Time Limit: 1 seconds
Memory Limit: 64 megabytes
Problem Description:
And again a misfortune fell on Poor Student. He is being late for an exam.
Having rushed to a bus stop that is in point (0,<=0), he got on a minibus and they drove along a straight line, parallel to axis *OX*, in the direct... | ```python
n,b,c = map(int,input().split())
a = list(map(int,input().split())); d = []
x1,y1 = map(int,input().split()); k = 0
for i in range(n): d.append(((x1-a[i])**2+y1**2)**(1/2))
p = d[0]
for i in range(len(d)):
if d[i] < p: p = d[i]; k = i
print(k+1)
``` | 0 |
239 | A | Two Bags of Potatoes | PROGRAMMING | 1,200 | [
"greedy",
"implementation",
"math"
] | null | null | Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* potatoes) Valera lost. Valera remembers that the total amount of potatoes (*x*<=+<=*y*) in the two bags, first... | The first line of input contains three integers *y*, *k*, *n* (1<=≤<=*y*,<=*k*,<=*n*<=≤<=109; <=≤<=105). | Print the list of whitespace-separated integers — all possible values of *x* in ascending order. You should print each possible value of *x* exactly once.
If there are no such values of *x* print a single integer -1. | [
"10 1 10\n",
"10 6 40\n"
] | [
"-1\n",
"2 8 14 20 26 \n"
] | none | 500 | [
{
"input": "10 1 10",
"output": "-1"
},
{
"input": "10 6 40",
"output": "2 8 14 20 26 "
},
{
"input": "10 1 20",
"output": "1 2 3 4 5 6 7 8 9 10 "
},
{
"input": "1 10000 1000000000",
"output": "9999 19999 29999 39999 49999 59999 69999 79999 89999 99999 109999 119999 12999... | 1,671,017,105 | 2,147,483,647 | Python 3 | OK | TESTS | 48 | 340 | 6,656,000 | y,k,n=map(int,input().split())
l=[]
num=1
while((k*num)<=n):
check=k*num
if(check>y):
nu=str(check-y)
l.append(nu)
num+=1
if(len(l)==0):
print(-1)
else:
print(" ".join(l))
| Title: Two Bags of Potatoes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Valera had two bags of potatoes, the first of these bags contains *x* (*x*<=≥<=1) potatoes, and the second — *y* (*y*<=≥<=1) potatoes. Valera — very scattered boy, so the first bag of potatoes (it contains *x* pota... | ```python
y,k,n=map(int,input().split())
l=[]
num=1
while((k*num)<=n):
check=k*num
if(check>y):
nu=str(check-y)
l.append(nu)
num+=1
if(len(l)==0):
print(-1)
else:
print(" ".join(l))
``` | 3 | |
812 | A | Sagheer and Crossroads | PROGRAMMING | 1,200 | [
"implementation"
] | null | null | Sagheer is walking in the street when he comes to an intersection of two roads. Each road can be represented as two parts where each part has 3 lanes getting into the intersection (one for each direction) and 3 lanes getting out of the intersection, so we have 4 parts in total. Each part has 4 lights, one for each lane... | The input consists of four lines with each line describing a road part given in a counter-clockwise order.
Each line contains four integers *l*, *s*, *r*, *p* — for the left, straight, right and pedestrian lights, respectively. The possible values are 0 for red light and 1 for green light. | On a single line, print "YES" if an accident is possible, and "NO" otherwise. | [
"1 0 0 1\n0 1 0 0\n0 0 1 0\n0 0 0 1\n",
"0 1 1 0\n1 0 1 0\n1 1 0 0\n0 0 0 1\n",
"1 0 0 0\n0 0 0 1\n0 0 0 0\n1 0 1 0\n"
] | [
"YES\n",
"NO\n",
"NO\n"
] | In the first example, some accidents are possible because cars of part 1 can hit pedestrians of parts 1 and 4. Also, cars of parts 2 and 3 can hit pedestrians of part 4.
In the second example, no car can pass the pedestrian crossing of part 4 which is the only green pedestrian light. So, no accident can occur. | 500 | [
{
"input": "1 0 0 1\n0 1 0 0\n0 0 1 0\n0 0 0 1",
"output": "YES"
},
{
"input": "0 1 1 0\n1 0 1 0\n1 1 0 0\n0 0 0 1",
"output": "NO"
},
{
"input": "1 0 0 0\n0 0 0 1\n0 0 0 0\n1 0 1 0",
"output": "NO"
},
{
"input": "0 0 0 0\n0 0 0 1\n0 0 0 1\n0 0 0 1",
"output": "NO"
},
... | 1,697,388,548 | 2,147,483,647 | Python 3 | OK | TESTS | 93 | 46 | 204,800 | l1, s1, r1, p1=[int(a)for a in input().split()]
l2, s2, r2, p2=[int(a)for a in input().split()]
l3, s3, r3, p3=[int(a)for a in input().split()]
l4, s4, r4, p4=[int(a)for a in input().split()]
if (l1+s1+r1>0 and p1==1) or (l2+s2+r2>0 and p2==1) or (l3+s3+r3>0 and p3==1) or (l4+s4+r4>0 and p4==1) :
print("YES")
... | Title: Sagheer and Crossroads
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Sagheer is walking in the street when he comes to an intersection of two roads. Each road can be represented as two parts where each part has 3 lanes getting into the intersection (one for each direction) and 3 l... | ```python
l1, s1, r1, p1=[int(a)for a in input().split()]
l2, s2, r2, p2=[int(a)for a in input().split()]
l3, s3, r3, p3=[int(a)for a in input().split()]
l4, s4, r4, p4=[int(a)for a in input().split()]
if (l1+s1+r1>0 and p1==1) or (l2+s2+r2>0 and p2==1) or (l3+s3+r3>0 and p3==1) or (l4+s4+r4>0 and p4==1) :
pri... | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | An atom of element X can exist in *n* distinct states with energies *E*1<=<<=*E*2<=<<=...<=<<=*E**n*. Arkady wants to build a laser on this element, using a three-level scheme. Here is a simplified description of the scheme.
Three distinct states *i*, *j* and *k* are selected, where *i*<=<<=*j*<=<<=*k*... | The first line contains two integers *n* and *U* (3<=≤<=*n*<=≤<=105, 1<=≤<=*U*<=≤<=109) — the number of states and the maximum possible difference between *E**k* and *E**i*.
The second line contains a sequence of integers *E*1,<=*E*2,<=...,<=*E**n* (1<=≤<=*E*1<=<<=*E*2...<=<<=*E**n*<=≤<=109). It is guaranteed th... | If it is not possible to choose three states that satisfy all constraints, print -1.
Otherwise, print one real number η — the maximum possible energy conversion efficiency. Your answer is considered correct its absolute or relative error does not exceed 10<=-<=9.
Formally, let your answer be *a*, and the jury's answe... | [
"4 4\n1 3 5 7\n",
"10 8\n10 13 15 16 17 19 20 22 24 25\n",
"3 1\n2 5 10\n"
] | [
"0.5\n",
"0.875\n",
"-1\n"
] | In the first example choose states 1, 2 and 3, so that the energy conversion efficiency becomes equal to <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/147ae7a830722917b0aa37d064df8eb74cfefb97.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second example choose states 4, 5 a... | 0 | [
{
"input": "4 4\n1 3 5 7",
"output": "0.5"
},
{
"input": "10 8\n10 13 15 16 17 19 20 22 24 25",
"output": "0.875"
},
{
"input": "3 1\n2 5 10",
"output": "-1"
},
{
"input": "5 3\n4 6 8 9 10",
"output": "0.5"
},
{
"input": "10 128\n110 121 140 158 174 188 251 271 27... | 1,522,207,002 | 2,147,483,647 | Python 3 | OK | TESTS | 76 | 296 | 15,052,800 | n,u=[int(x) for x in input().split()]
a=list(map(int,input().split()))
idx=0
ans=-1
for i in range(n):
while(idx<n-1 and a[idx+1]-a[i]<=u):
idx+=1
if(idx-i<2):
continue
ans=max(ans,(a[idx]-a[i+1])/(a[idx]-a[i]))
print(ans) | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An atom of element X can exist in *n* distinct states with energies *E*1<=<<=*E*2<=<<=...<=<<=*E**n*. Arkady wants to build a laser on this element, using a three-level scheme. Here is a simplified description of the sche... | ```python
n,u=[int(x) for x in input().split()]
a=list(map(int,input().split()))
idx=0
ans=-1
for i in range(n):
while(idx<n-1 and a[idx+1]-a[i]<=u):
idx+=1
if(idx-i<2):
continue
ans=max(ans,(a[idx]-a[i+1])/(a[idx]-a[i]))
print(ans)
``` | 3 | |
928 | A | Login Verification | PROGRAMMING | 1,200 | [
"*special",
"strings"
] | null | null | When registering in a social network, users are allowed to create their own convenient login to make it easier to share contacts, print it on business cards, etc.
Login is an arbitrary sequence of lower and uppercase latin letters, digits and underline symbols («_»). However, in order to decrease the number of frauds ... | The first line contains a non-empty string *s* consisting of lower and uppercase latin letters, digits and underline symbols («_») with length not exceeding 50 — the login itself.
The second line contains a single integer *n* (1<=≤<=*n*<=≤<=1<=000) — the number of existing logins.
The next *n* lines describe the exi... | Print «Yes» (without quotes), if user can register via this login, i.e. none of the existing logins is similar with it.
Otherwise print «No» (without quotes). | [
"1_wat\n2\n2_wat\nwat_1\n",
"000\n3\n00\nooA\noOo\n",
"_i_\n3\n__i_\n_1_\nI\n",
"La0\n3\n2a0\nLa1\n1a0\n",
"abc\n1\naBc\n",
"0Lil\n2\nLIL0\n0Ril\n"
] | [
"Yes\n",
"No\n",
"No\n",
"No\n",
"No\n",
"Yes\n"
] | In the second sample case the user wants to create a login consisting of three zeros. It's impossible due to collision with the third among the existing.
In the third sample case the new login is similar with the second one. | 500 | [
{
"input": "1_wat\n2\n2_wat\nwat_1",
"output": "Yes"
},
{
"input": "000\n3\n00\nooA\noOo",
"output": "No"
},
{
"input": "_i_\n3\n__i_\n_1_\nI",
"output": "No"
},
{
"input": "La0\n3\n2a0\nLa1\n1a0",
"output": "No"
},
{
"input": "abc\n1\naBc",
"output": "No"
}... | 1,519,515,299 | 28,799 | Python 3 | OK | TESTS | 73 | 78 | 5,632,000 | s1 = input()
abc = 'qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM'
for y in range(0, 26):
s1 = s1.replace(abc[y], abc[y + 26])
s1 = s1.replace("O", "0")
s1 = s1.replace("L", "1")
s1 = s1.replace("I", "1")
n=int(input())
d=[]
d.append(s1)
for i in range(0,n):
s=input()
for y in range(... | Title: Login Verification
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
When registering in a social network, users are allowed to create their own convenient login to make it easier to share contacts, print it on business cards, etc.
Login is an arbitrary sequence of lower and uppercas... | ```python
s1 = input()
abc = 'qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM'
for y in range(0, 26):
s1 = s1.replace(abc[y], abc[y + 26])
s1 = s1.replace("O", "0")
s1 = s1.replace("L", "1")
s1 = s1.replace("I", "1")
n=int(input())
d=[]
d.append(s1)
for i in range(0,n):
s=input()
for y... | 3 | |
270 | A | Fancy Fence | PROGRAMMING | 1,100 | [
"geometry",
"implementation",
"math"
] | null | null | Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can only make fence corners at a single angle *a*.
Will the robot be able to build the fence Emuska... | The first line of input contains an integer *t* (0<=<<=*t*<=<<=180) — the number of tests. Each of the following *t* lines contains a single integer *a* (0<=<<=*a*<=<<=180) — the angle the robot can make corners at measured in degrees. | For each test, output on a single line "YES" (without quotes), if the robot can build a fence Emuskald wants, and "NO" (without quotes), if it is impossible. | [
"3\n30\n60\n90\n"
] | [
"NO\nYES\nYES\n"
] | In the first test case, it is impossible to build the fence, since there is no regular polygon with angle <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/df5f4b07dd5316fde165b43657b2696e2919e791.png" style="max-width: 100.0%;max-height: 100.0%;"/>.
In the second test case, the fence is a r... | 500 | [
{
"input": "3\n30\n60\n90",
"output": "NO\nYES\nYES"
},
{
"input": "6\n1\n2\n3\n170\n179\n25",
"output": "NO\nNO\nNO\nYES\nYES\nNO"
}
] | 1,645,250,474 | 2,147,483,647 | Python 3 | OK | TESTS | 3 | 60 | 0 | for _ in range(int(input())):
n = int(input())
print(['NO', 'YES'][(360/(180-n)).is_integer() and n<180]) | Title: Fancy Fence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Emuskald needs a fence around his farm, but he is too lazy to build it himself. So he purchased a fence-building robot.
He wants the fence to be a regular polygon. The robot builds the fence along a single path, but it can... | ```python
for _ in range(int(input())):
n = int(input())
print(['NO', 'YES'][(360/(180-n)).is_integer() and n<180])
``` | 3 | |
697 | A | Pineapple Incident | PROGRAMMING | 900 | [
"implementation",
"math"
] | null | null | Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times *t*, *t*<=+<=*s*, *t*<=+<=*s*<=+<=1, *t*<=+<=2*s*, *t*<=+<=2*s*<=+<=1, etc.
Barney woke up in the morn... | The first and only line of input contains three integers *t*, *s* and *x* (0<=≤<=*t*,<=*x*<=≤<=109, 2<=≤<=*s*<=≤<=109) — the time the pineapple barks for the first time, the pineapple barking interval, and the time Barney wants to eat the pineapple respectively. | Print a single "YES" (without quotes) if the pineapple will bark at time *x* or a single "NO" (without quotes) otherwise in the only line of output. | [
"3 10 4\n",
"3 10 3\n",
"3 8 51\n",
"3 8 52\n"
] | [
"NO\n",
"YES\n",
"YES\n",
"YES\n"
] | In the first and the second sample cases pineapple will bark at moments 3, 13, 14, ..., so it won't bark at the moment 4 and will bark at the moment 3.
In the third and fourth sample cases pineapple will bark at moments 3, 11, 12, 19, 20, 27, 28, 35, 36, 43, 44, 51, 52, 59, ..., so it will bark at both moments 51 and ... | 500 | [
{
"input": "3 10 4",
"output": "NO"
},
{
"input": "3 10 3",
"output": "YES"
},
{
"input": "3 8 51",
"output": "YES"
},
{
"input": "3 8 52",
"output": "YES"
},
{
"input": "456947336 740144 45",
"output": "NO"
},
{
"input": "33 232603 599417964",
"ou... | 1,594,637,435 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 9 | 93 | 6,656,000 | t,s,x=map(int,input().split())
def pineapple_incident(t,s,x):
if x==t:
return("YES")
elif x< t+s:
return("NO")
else:
i=1
while i<s:
k=t+(i*s)
i+=1
if k==x:
return "YES"
else:
k+=1
... | Title: Pineapple Incident
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ted has a pineapple. This pineapple is able to bark like a bulldog! At time *t* (in seconds) it barks for the first time. Then every *s* seconds after it, it barks twice with 1 second interval. Thus it barks at times... | ```python
t,s,x=map(int,input().split())
def pineapple_incident(t,s,x):
if x==t:
return("YES")
elif x< t+s:
return("NO")
else:
i=1
while i<s:
k=t+(i*s)
i+=1
if k==x:
return "YES"
else:
... | 0 | |
230 | B | T-primes | PROGRAMMING | 1,300 | [
"binary search",
"implementation",
"math",
"number theory"
] | null | null | We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an array of *n* positive integers. For each of them determine whether it is Т-prime or not. | The first line contains a single positive integer, *n* (1<=≤<=*n*<=≤<=105), showing how many numbers are in the array. The next line contains *n* space-separated integers *x**i* (1<=≤<=*x**i*<=≤<=1012).
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is advised to use the cin, cout st... | Print *n* lines: the *i*-th line should contain "YES" (without the quotes), if number *x**i* is Т-prime, and "NO" (without the quotes), if it isn't. | [
"3\n4 5 6\n"
] | [
"YES\nNO\nNO\n"
] | The given test has three numbers. The first number 4 has exactly three divisors — 1, 2 and 4, thus the answer for this number is "YES". The second number 5 has two divisors (1 and 5), and the third number 6 has four divisors (1, 2, 3, 6), hence the answer for them is "NO". | 500 | [
{
"input": "3\n4 5 6",
"output": "YES\nNO\nNO"
},
{
"input": "2\n48 49",
"output": "NO\nYES"
},
{
"input": "10\n10 9 8 7 6 5 4 3 2 1",
"output": "NO\nYES\nNO\nNO\nNO\nNO\nYES\nNO\nNO\nNO"
},
{
"input": "1\n36",
"output": "NO"
},
{
"input": "1\n999966000289",
"... | 1,696,998,664 | 2,147,483,647 | PyPy 3-64 | MEMORY_LIMIT_EXCEEDED | TESTS | 0 | 1,560 | 268,390,400 | # -*- coding: utf-8 -*-
"""
Created on Wed Oct 11 12:17:43 2023
@author: 25419
"""
def primes(n):
p=[]
f=[]
for i in range(n+1):
if i>2 and i%2 == 0:
f.append(1)
else:
f.append(0)
i=3
while i*i<=n:
if f[i]==0:
j=i*i
... | Title: T-primes
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
We know that prime numbers are positive integers that have exactly two distinct positive divisors. Similarly, we'll call a positive integer *t* Т-prime, if *t* has exactly three distinct positive divisors.
You are given an ar... | ```python
# -*- coding: utf-8 -*-
"""
Created on Wed Oct 11 12:17:43 2023
@author: 25419
"""
def primes(n):
p=[]
f=[]
for i in range(n+1):
if i>2 and i%2 == 0:
f.append(1)
else:
f.append(0)
i=3
while i*i<=n:
if f[i]==0:
... | 0 | |
633 | A | Ebony and Ivory | PROGRAMMING | 1,100 | [
"brute force",
"math",
"number theory"
] | null | null | Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
For every bullet that hits the shield, Ebony deals *a* units of damage while Ivory deals *b* units of ... | The first line of the input contains three integers *a*, *b*, *c* (1<=≤<=*a*,<=*b*<=≤<=100,<=1<=≤<=*c*<=≤<=10<=000) — the number of units of damage dealt by Ebony gun and Ivory gun, and the total number of damage required to break the shield, respectively. | Print "Yes" (without quotes) if Dante can deal exactly *c* damage to the shield and "No" (without quotes) otherwise. | [
"4 6 15\n",
"3 2 7\n",
"6 11 6\n"
] | [
"No\n",
"Yes\n",
"Yes\n"
] | In the second sample, Dante can fire 1 bullet from Ebony and 2 from Ivory to deal exactly 1·3 + 2·2 = 7 damage. In the third sample, Dante can fire 1 bullet from ebony and no bullets from ivory to do 1·6 + 0·11 = 6 damage. | 250 | [
{
"input": "4 6 15",
"output": "No"
},
{
"input": "3 2 7",
"output": "Yes"
},
{
"input": "6 11 6",
"output": "Yes"
},
{
"input": "3 12 15",
"output": "Yes"
},
{
"input": "5 5 10",
"output": "Yes"
},
{
"input": "6 6 7",
"output": "No"
},
{
"... | 1,685,103,377 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 22 | 78 | 0 | a, b, c = map(int, input().split())
def extGCD(a, b):
if b == 0:
x = 1
y = 0
return a, x, y
g, x, y = extGCD(b, a%b)
x0 = y
y0 = x - y * (a//b)
return g, x0, y0
def find_any_solution(a, b, c):
g, x0, y0 = extGCD(abs(a), abs(b))
if c % g != 0:
... | Title: Ebony and Ivory
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Dante is engaged in a fight with "The Savior". Before he can fight it with his sword, he needs to break its shields. He has two guns, Ebony and Ivory, each of them is able to perform any non-negative number of shots.
F... | ```python
a, b, c = map(int, input().split())
def extGCD(a, b):
if b == 0:
x = 1
y = 0
return a, x, y
g, x, y = extGCD(b, a%b)
x0 = y
y0 = x - y * (a//b)
return g, x0, y0
def find_any_solution(a, b, c):
g, x0, y0 = extGCD(abs(a), abs(b))
if c % g != 0:... | 0 | |
80 | A | Panoramix's Prediction | PROGRAMMING | 800 | [
"brute force"
] | A. Panoramix's Prediction | 2 | 256 | A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater than *x*. For example, the next prime number after 2 is 3, and the next prime number after 3 is 5. Note t... | The first and only input line contains two positive integers — *n* and *m* (2<=≤<=*n*<=<<=*m*<=≤<=50). It is guaranteed that *n* is prime.
Pretests contain all the cases with restrictions 2<=≤<=*n*<=<<=*m*<=≤<=4. | Print YES, if *m* is the next prime number after *n*, or NO otherwise. | [
"3 5\n",
"7 11\n",
"7 9\n"
] | [
"YES",
"YES",
"NO"
] | none | 500 | [
{
"input": "3 5",
"output": "YES"
},
{
"input": "7 11",
"output": "YES"
},
{
"input": "7 9",
"output": "NO"
},
{
"input": "2 3",
"output": "YES"
},
{
"input": "2 4",
"output": "NO"
},
{
"input": "3 4",
"output": "NO"
},
{
"input": "3 5",
... | 1,662,043,398 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 4 | 92 | 0 | import math
from itertools import permutations
def checkSameDigits(N):
# Find the last digit
digit = N % 10;
while (N != 0):
# Find the current last digit
current_digit = N % 10;
# Update the value of N
N = N // 10;
# If there exists any distinct... | Title: Panoramix's Prediction
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A prime number is a number which has exactly two distinct divisors: one and itself. For example, numbers 2, 7, 3 are prime, and 1, 6, 4 are not.
The next prime number after *x* is the smallest prime number greater t... | ```python
import math
from itertools import permutations
def checkSameDigits(N):
# Find the last digit
digit = N % 10;
while (N != 0):
# Find the current last digit
current_digit = N % 10;
# Update the value of N
N = N // 10;
# If there exists an... | 0 |
551 | A | GukiZ and Contest | PROGRAMMING | 800 | [
"brute force",
"implementation",
"sortings"
] | null | null | Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to *n*. Let's denote... | The first line contains integer *n* (1<=≤<=*n*<=≤<=2000), number of GukiZ's students.
The second line contains *n* numbers *a*1,<=*a*2,<=... *a**n* (1<=≤<=*a**i*<=≤<=2000) where *a**i* is the rating of *i*-th student (1<=≤<=*i*<=≤<=*n*). | In a single line, print the position after the end of the contest for each of *n* students in the same order as they appear in the input. | [
"3\n1 3 3\n",
"1\n1\n",
"5\n3 5 3 4 5\n"
] | [
"3 1 1\n",
"1\n",
"4 1 4 3 1\n"
] | In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.
In the second sample, first student is the only one on the contest.
In the third sample, students 2 and 5 share the first positi... | 500 | [
{
"input": "3\n1 3 3",
"output": "3 1 1"
},
{
"input": "1\n1",
"output": "1"
},
{
"input": "5\n3 5 3 4 5",
"output": "4 1 4 3 1"
},
{
"input": "7\n1 3 5 4 2 2 1",
"output": "6 3 1 2 4 4 6"
},
{
"input": "11\n5 6 4 2 9 7 6 6 6 6 7",
"output": "9 4 10 11 1 2 4 4... | 1,559,292,964 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 997 | 512,000 | n = int(input())
l = [*map(int,input().split())]
ans = [1 for i in range(n)]
for i in range(n):
for j in range(i+1,n):
if l[i] > l[j]:
ans[j]+=1
elif l[j] > l[i]:
ans[i]+=1
else:
pass
print(*ans) | Title: GukiZ and Contest
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.
In total, *n* students will attend, and before the star... | ```python
n = int(input())
l = [*map(int,input().split())]
ans = [1 for i in range(n)]
for i in range(n):
for j in range(i+1,n):
if l[i] > l[j]:
ans[j]+=1
elif l[j] > l[i]:
ans[i]+=1
else:
pass
print(*ans)
``` | 3 | |
673 | A | Bear and Game | PROGRAMMING | 800 | [
"implementation"
] | null | null | Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Limak immediately turns TV off.
You know that there will be *n* interesting minutes *t*1,<=*t*2,<=...... | The first line of the input contains one integer *n* (1<=≤<=*n*<=≤<=90) — the number of interesting minutes.
The second line contains *n* integers *t*1,<=*t*2,<=...,<=*t**n* (1<=≤<=*t*1<=<<=*t*2<=<<=... *t**n*<=≤<=90), given in the increasing order. | Print the number of minutes Limak will watch the game. | [
"3\n7 20 88\n",
"9\n16 20 30 40 50 60 70 80 90\n",
"9\n15 20 30 40 50 60 70 80 90\n"
] | [
"35\n",
"15\n",
"90\n"
] | In the first sample, minutes 21, 22, ..., 35 are all boring and thus Limak will turn TV off immediately after the 35-th minute. So, he would watch the game for 35 minutes.
In the second sample, the first 15 minutes are boring.
In the third sample, there are no consecutive 15 boring minutes. So, Limak will watch the w... | 500 | [
{
"input": "3\n7 20 88",
"output": "35"
},
{
"input": "9\n16 20 30 40 50 60 70 80 90",
"output": "15"
},
{
"input": "9\n15 20 30 40 50 60 70 80 90",
"output": "90"
},
{
"input": "30\n6 11 12 15 22 24 30 31 32 33 34 35 40 42 44 45 47 50 53 54 57 58 63 67 75 77 79 81 83 88",
... | 1,602,755,756 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 14 | 93 | 307,200 | n=int(input())
a=list(map(int,input().split()))
s=a[0]
count=0
if a[0]>15:
print(15)
else:
if len(a)>=2:
i = 0
ans = 0
while i <= n - 1:
if i == n - 1:
ans = 1
break
elif a[i + 1] - a[i] > 15:
count = ... | Title: Bear and Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak likes watching sports on TV. He is going to watch a game today. The game lasts 90 minutes and there are no breaks.
Each minute can be either interesting or boring. If 15 consecutive minutes are boring then Lim... | ```python
n=int(input())
a=list(map(int,input().split()))
s=a[0]
count=0
if a[0]>15:
print(15)
else:
if len(a)>=2:
i = 0
ans = 0
while i <= n - 1:
if i == n - 1:
ans = 1
break
elif a[i + 1] - a[i] > 15:
... | 0 | |
113 | C | Double Happiness | PROGRAMMING | 2,200 | [
"brute force",
"math",
"number theory"
] | C. Double Happiness | 3 | 128 | On the math lesson a teacher asked each pupil to come up with his own lucky numbers. As a fan of number theory Peter chose prime numbers. Bob was more original. He said that number *t* is his lucky number, if it can be represented as:
Now, the boys decided to find out how many days of the interval [*l*,<=*r*] (*l*<=≤... | The first line of the input contains integer numbers *l*,<=*r* (1<=≤<=*l*,<=*r*<=≤<=3·108). | In the only line print the number of days on the segment [*l*,<=*r*], which are lucky for Peter and Bob at the same time. | [
"3 5\n",
"6 66\n"
] | [
"1\n",
"7\n"
] | none | 1,500 | [] | 1,621,797,521 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 4 | 374 | 35,532,800 | l, r = [int(x) for x in input().split()]
primes = []
lucky = [False for i in range(r + 1)]
composite = [False for i in range(r + 1)]
for i in range(2, r + 1):
if not composite[i]:
primes.append(i)
for p in primes:
if i * p > r: break
composite[i * p] = True
if i % p == 0: break... | Title: Double Happiness
Time Limit: 3 seconds
Memory Limit: 128 megabytes
Problem Description:
On the math lesson a teacher asked each pupil to come up with his own lucky numbers. As a fan of number theory Peter chose prime numbers. Bob was more original. He said that number *t* is his lucky number, if it can be rep... | ```python
l, r = [int(x) for x in input().split()]
primes = []
lucky = [False for i in range(r + 1)]
composite = [False for i in range(r + 1)]
for i in range(2, r + 1):
if not composite[i]:
primes.append(i)
for p in primes:
if i * p > r: break
composite[i * p] = True
if i % p =... | 0 |
660 | C | Hard Process | PROGRAMMING | 1,600 | [
"binary search",
"dp",
"two pointers"
] | null | null | You are given an array *a* with *n* elements. Each element of *a* is either 0 or 1.
Let's denote the length of the longest subsegment of consecutive elements in *a*, consisting of only numbers one, as *f*(*a*). You can change no more than *k* zeroes to ones to maximize *f*(*a*). | The first line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=3·105,<=0<=≤<=*k*<=≤<=*n*) — the number of elements in *a* and the parameter *k*.
The second line contains *n* integers *a**i* (0<=≤<=*a**i*<=≤<=1) — the elements of *a*. | On the first line print a non-negative integer *z* — the maximal value of *f*(*a*) after no more than *k* changes of zeroes to ones.
On the second line print *n* integers *a**j* — the elements of the array *a* after the changes.
If there are multiple answers, you can print any one of them. | [
"7 1\n1 0 0 1 1 0 1\n",
"10 2\n1 0 0 1 0 1 0 1 0 1\n"
] | [
"4\n1 0 0 1 1 1 1\n",
"5\n1 0 0 1 1 1 1 1 0 1\n"
] | none | 0 | [
{
"input": "7 1\n1 0 0 1 1 0 1",
"output": "4\n1 0 0 1 1 1 1"
},
{
"input": "10 2\n1 0 0 1 0 1 0 1 0 1",
"output": "5\n1 0 0 1 1 1 1 1 0 1"
},
{
"input": "1 0\n0",
"output": "0\n0"
},
{
"input": "1 0\n0",
"output": "0\n0"
},
{
"input": "7 0\n0 1 0 0 0 1 0",
"o... | 1,691,822,657 | 2,147,483,647 | Python 3 | OK | TESTS | 38 | 451 | 9,830,400 | def maximize_consecutive_ones(n, k, a):
left = 0 # Left pointer of the sliding window
max_length = 0 # Length of the longest subsegment of ones
max_left = 0 # Left index of the longest subsegment
zero_count = 0 # Count of zeros inside the current window
for right in range(n):
if a[right... | Title: Hard Process
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given an array *a* with *n* elements. Each element of *a* is either 0 or 1.
Let's denote the length of the longest subsegment of consecutive elements in *a*, consisting of only numbers one, as *f*(*a*). You can ch... | ```python
def maximize_consecutive_ones(n, k, a):
left = 0 # Left pointer of the sliding window
max_length = 0 # Length of the longest subsegment of ones
max_left = 0 # Left index of the longest subsegment
zero_count = 0 # Count of zeros inside the current window
for right in range(n):
... | 3 | |
96 | A | Football | PROGRAMMING | 900 | [
"implementation",
"strings"
] | A. Football | 2 | 256 | Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If... | The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field. | Print "YES" if the situation is dangerous. Otherwise, print "NO". | [
"001001\n",
"1000000001\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "001001",
"output": "NO"
},
{
"input": "1000000001",
"output": "YES"
},
{
"input": "00100110111111101",
"output": "YES"
},
{
"input": "11110111111111111",
"output": "YES"
},
{
"input": "01",
"output": "NO"
},
{
"input": "10100101",
"outp... | 1,680,756,674 | 2,147,483,647 | Python 3 | OK | TESTS | 44 | 92 | 0 | s = input() # read the input string
# check if the string contains 7 consecutive '0's or '1's
if '0000000' in s or '1111111' in s:
print("YES")
else:
print("NO") | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A... | ```python
s = input() # read the input string
# check if the string contains 7 consecutive '0's or '1's
if '0000000' in s or '1111111' in s:
print("YES")
else:
print("NO")
``` | 3.977 |
268 | A | Games | PROGRAMMING | 800 | [
"brute force"
] | null | null | Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as ... | The first line contains an integer *n* (2<=≤<=*n*<=≤<=30). Each of the following *n* lines contains a pair of distinct space-separated integers *h**i*, *a**i* (1<=≤<=*h**i*,<=*a**i*<=≤<=100) — the colors of the *i*-th team's home and guest uniforms, respectively. | In a single line print the number of games where the host team is going to play in the guest uniform. | [
"3\n1 2\n2 4\n3 4\n",
"4\n100 42\n42 100\n5 42\n100 5\n",
"2\n1 2\n1 2\n"
] | [
"1\n",
"5\n",
"0\n"
] | In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host tea... | 500 | [
{
"input": "3\n1 2\n2 4\n3 4",
"output": "1"
},
{
"input": "4\n100 42\n42 100\n5 42\n100 5",
"output": "5"
},
{
"input": "2\n1 2\n1 2",
"output": "0"
},
{
"input": "7\n4 7\n52 55\n16 4\n55 4\n20 99\n3 4\n7 52",
"output": "6"
},
{
"input": "10\n68 42\n1 35\n25 70\n... | 1,679,152,269 | 2,147,483,647 | Python 3 | OK | TESTS | 31 | 92 | 0 | n=int(input())
l=[]
for i in range(n):
x=input()
y=x.split()
l.append(y)
total=0
for i in range(n):
a=l.pop(i)
for j in l:
if a[0]==j[1]:
total+=1
l.insert(i,a)
print(total)
| Title: Games
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. W... | ```python
n=int(input())
l=[]
for i in range(n):
x=input()
y=x.split()
l.append(y)
total=0
for i in range(n):
a=l.pop(i)
for j in l:
if a[0]==j[1]:
total+=1
l.insert(i,a)
print(total)
``` | 3 | |
268 | B | Buttons | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Manao is trying to open a rather challenging lock. The lock has *n* buttons on it and to open it, you should press the buttons in a certain order to open the lock. When you push some button, it either stays pressed into the lock (that means that you've guessed correctly and pushed the button that goes next in the seque... | A single line contains integer *n* (1<=≤<=*n*<=≤<=2000) — the number of buttons the lock has. | In a single line print the number of times Manao has to push a button in the worst-case scenario. | [
"2\n",
"3\n"
] | [
"3\n",
"7\n"
] | Consider the first test sample. Manao can fail his first push and push the wrong button. In this case he will already be able to guess the right one with his second push. And his third push will push the second right button. Thus, in the worst-case scenario he will only need 3 pushes. | 1,000 | [
{
"input": "2",
"output": "3"
},
{
"input": "3",
"output": "7"
},
{
"input": "4",
"output": "14"
},
{
"input": "1",
"output": "1"
},
{
"input": "10",
"output": "175"
},
{
"input": "2000",
"output": "1333335000"
},
{
"input": "1747",
"ou... | 1,692,352,429 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 30 | 0 |
for _ in range(int(input())):
a,b,c=map(int,input().split())
if((a==b and c%2)or(a!=b and a>b)):print("First")
else:print("Second") | Title: Buttons
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Manao is trying to open a rather challenging lock. The lock has *n* buttons on it and to open it, you should press the buttons in a certain order to open the lock. When you push some button, it either stays pressed into the loc... | ```python
for _ in range(int(input())):
a,b,c=map(int,input().split())
if((a==b and c%2)or(a!=b and a>b)):print("First")
else:print("Second")
``` | -1 | |
659 | A | Round House | PROGRAMMING | 1,000 | [
"implementation",
"math"
] | null | null | Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in entrance *a* and he decided that during his walk he will move around the house *b* entrances in th... | The single line of the input contains three space-separated integers *n*, *a* and *b* (1<=≤<=*n*<=≤<=100,<=1<=≤<=*a*<=≤<=*n*,<=<=-<=100<=≤<=*b*<=≤<=100) — the number of entrances at Vasya's place, the number of his entrance and the length of his walk, respectively. | Print a single integer *k* (1<=≤<=*k*<=≤<=*n*) — the number of the entrance where Vasya will be at the end of his walk. | [
"6 2 -5\n",
"5 1 3\n",
"3 2 7\n"
] | [
"3\n",
"4\n",
"3\n"
] | The first example is illustrated by the picture in the statements. | 500 | [
{
"input": "6 2 -5",
"output": "3"
},
{
"input": "5 1 3",
"output": "4"
},
{
"input": "3 2 7",
"output": "3"
},
{
"input": "1 1 0",
"output": "1"
},
{
"input": "1 1 -1",
"output": "1"
},
{
"input": "1 1 1",
"output": "1"
},
{
"input": "100 ... | 1,635,789,108 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 2 | 31 | 4,505,600 | n,a,b=map(int,input().split())
if b>0:
for i in range(0,b):
a+=1
if a==n:
a=1
print(a)
elif b<0:
for i in range(0,abs(b)):
a-=1
if a==0:
a=n
print(a)
else:
print(a)
| Title: Round House
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Vasya lives in a round building, whose entrances are numbered sequentially by integers from 1 to *n*. Entrance *n* and entrance 1 are adjacent.
Today Vasya got bored and decided to take a walk in the yard. Vasya lives in e... | ```python
n,a,b=map(int,input().split())
if b>0:
for i in range(0,b):
a+=1
if a==n:
a=1
print(a)
elif b<0:
for i in range(0,abs(b)):
a-=1
if a==0:
a=n
print(a)
else:
print(a)
``` | 0 | |
152 | C | Pocket Book | PROGRAMMING | 1,400 | [
"combinatorics"
] | null | null | One day little Vasya found mom's pocket book. The book had *n* names of her friends and unusually enough, each name was exactly *m* letters long. Let's number the names from 1 to *n* in the order in which they are written.
As mom wasn't home, Vasya decided to play with names: he chose three integers *i*, *j*, *k* (1<=... | The first input line contains two integers *n* and *m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of names and the length of each name, correspondingly. Then *n* lines contain names, each name consists of exactly *m* uppercase Latin letters. | Print the single number — the number of different names that could end up in position number 1 in the pocket book after the applying the procedures described above. Print the number modulo 1000000007 (109<=+<=7). | [
"2 3\nAAB\nBAA\n",
"4 5\nABABA\nBCGDG\nAAAAA\nYABSA\n"
] | [
"4\n",
"216\n"
] | In the first sample Vasya can get the following names in the position number 1: "AAB", "AAA", "BAA" and "BAB". | 1,500 | [
{
"input": "2 3\nAAB\nBAA",
"output": "4"
},
{
"input": "4 5\nABABA\nBCGDG\nAAAAA\nYABSA",
"output": "216"
},
{
"input": "1 1\nE",
"output": "1"
},
{
"input": "2 2\nNS\nPD",
"output": "4"
},
{
"input": "3 4\nPJKD\nNFJX\nFGFK",
"output": "81"
},
{
"inpu... | 1,608,530,693 | 2,147,483,647 | Python 3 | OK | TESTS | 60 | 248 | 307,200 | import sys
import math
import bisect
input = sys.stdin.readline
sys.setrecursionlimit(1500000)
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s)]))
def invr():
... | Title: Pocket Book
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
One day little Vasya found mom's pocket book. The book had *n* names of her friends and unusually enough, each name was exactly *m* letters long. Let's number the names from 1 to *n* in the order in which they are written.
... | ```python
import sys
import math
import bisect
input = sys.stdin.readline
sys.setrecursionlimit(1500000)
############ ---- Input Functions ---- ############
def inp():
return(int(input()))
def inlt():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s)]))
de... | 3 | |
356 | A | Knight Tournament | PROGRAMMING | 1,500 | [
"data structures",
"dsu"
] | null | null | Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're just a simple peasant. There's no surprise that you slept in this morning and were late for the tourname... | The first line contains two integers *n*, *m* (2<=≤<=*n*<=≤<=3·105; 1<=≤<=*m*<=≤<=3·105) — the number of knights and the number of fights. Each of the following *m* lines contains three integers *l**i*,<=*r**i*,<=*x**i* (1<=≤<=*l**i*<=<<=*r**i*<=≤<=*n*; *l**i*<=≤<=*x**i*<=≤<=*r**i*) — the description of the *i*-th f... | Print *n* integers. If the *i*-th knight lost, then the *i*-th number should equal the number of the knight that beat the knight number *i*. If the *i*-th knight is the winner, then the *i*-th number must equal 0. | [
"4 3\n1 2 1\n1 3 3\n1 4 4\n",
"8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1\n"
] | [
"3 1 4 0 ",
"0 8 4 6 4 8 6 1 "
] | Consider the first test case. Knights 1 and 2 fought the first fight and knight 1 won. Knights 1 and 3 fought the second fight and knight 3 won. The last fight was between knights 3 and 4, knight 4 won. | 500 | [
{
"input": "4 3\n1 2 1\n1 3 3\n1 4 4",
"output": "3 1 4 0 "
},
{
"input": "8 4\n3 5 4\n3 7 6\n2 8 8\n1 8 1",
"output": "0 8 4 6 4 8 6 1 "
},
{
"input": "2 1\n1 2 1",
"output": "0 1 "
},
{
"input": "2 1\n1 2 2",
"output": "2 0 "
},
{
"input": "3 1\n1 3 1",
"out... | 1,464,943,386 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 10 | 3,000 | 12,083,200 | def main():
from bisect import bisect, bisect_left
n, m = map(int, input().split())
avail, res = list(range(1, n + 1)), [0] * (n + 1)
for _ in range(m):
l, r, x = map(int, input().split())
lo = bisect_left(avail, l)
hi = bisect(avail, r)
for i in range(lo, hi):
... | Title: Knight Tournament
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Hooray! Berl II, the king of Berland is making a knight tournament. The king has already sent the message to all knights in the kingdom and they in turn agreed to participate in this grand event.
As for you, you're j... | ```python
def main():
from bisect import bisect, bisect_left
n, m = map(int, input().split())
avail, res = list(range(1, n + 1)), [0] * (n + 1)
for _ in range(m):
l, r, x = map(int, input().split())
lo = bisect_left(avail, l)
hi = bisect(avail, r)
for i in range(lo, hi):
... | 0 | |
977 | B | Two-gram | PROGRAMMING | 900 | [
"implementation",
"strings"
] | null | null | Two-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, "AZ", "AA", "ZA" — three distinct two-grams.
You are given a string $s$ consisting of $n$ capital Latin letters. Your task is to find any two-gram contained in the given string as a substring (i.e. two consecutive characters... | The first line of the input contains integer number $n$ ($2 \le n \le 100$) — the length of string $s$. The second line of the input contains the string $s$ consisting of $n$ capital Latin letters. | Print the only line containing exactly two capital Latin letters — any two-gram contained in the given string $s$ as a substring (i.e. two consecutive characters of the string) maximal number of times. | [
"7\nABACABA\n",
"5\nZZZAA\n"
] | [
"AB\n",
"ZZ\n"
] | In the first example "BA" is also valid answer.
In the second example the only two-gram "ZZ" can be printed because it contained in the string "ZZZAA" two times. | 0 | [
{
"input": "7\nABACABA",
"output": "AB"
},
{
"input": "5\nZZZAA",
"output": "ZZ"
},
{
"input": "26\nQWERTYUIOPASDFGHJKLZXCVBNM",
"output": "AS"
},
{
"input": "2\nQA",
"output": "QA"
},
{
"input": "2\nWW",
"output": "WW"
},
{
"input": "11\nGGRRAATTZZZ",... | 1,698,162,461 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 46 | 0 | n = int(input())
s = input()
most_frequent = ""
max_frequency = 0
# Calculate the frequency of each two-gram in the string
for i in range(n - 1):
two_gram = s[i:i+2]
frequency = s.count(two_gram)
if frequency > max_frequency:
max_frequency = frequency
most_frequent = two_... | Title: Two-gram
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Two-gram is an ordered pair (i.e. string of length two) of capital Latin letters. For example, "AZ", "AA", "ZA" — three distinct two-grams.
You are given a string $s$ consisting of $n$ capital Latin letters. Your task is to f... | ```python
n = int(input())
s = input()
most_frequent = ""
max_frequency = 0
# Calculate the frequency of each two-gram in the string
for i in range(n - 1):
two_gram = s[i:i+2]
frequency = s.count(two_gram)
if frequency > max_frequency:
max_frequency = frequency
most_frequ... | 0 | |
468 | B | Two Sets | PROGRAMMING | 2,000 | [
"2-sat",
"dfs and similar",
"dsu",
"graph matchings",
"greedy"
] | null | null | Little X has *n* distinct integers: *p*1,<=*p*2,<=...,<=*p**n*. He wants to divide all of them into two sets *A* and *B*. The following two conditions must be satisfied:
- If number *x* belongs to set *A*, then number *a*<=-<=*x* must also belong to set *A*. - If number *x* belongs to set *B*, then number *b*<=-<=*x... | The first line contains three space-separated integers *n*,<=*a*,<=*b* (1<=≤<=*n*<=≤<=105; 1<=≤<=*a*,<=*b*<=≤<=109). The next line contains *n* space-separated distinct integers *p*1,<=*p*2,<=...,<=*p**n* (1<=≤<=*p**i*<=≤<=109). | If there is a way to divide the numbers into two sets, then print "YES" in the first line. Then print *n* integers: *b*1,<=*b*2,<=...,<=*b**n* (*b**i* equals either 0, or 1), describing the division. If *b**i* equals to 0, then *p**i* belongs to set *A*, otherwise it belongs to set *B*.
If it's impossible, print "NO" ... | [
"4 5 9\n2 3 4 5\n",
"3 3 4\n1 2 4\n"
] | [
"YES\n0 0 1 1\n",
"NO\n"
] | It's OK if all the numbers are in the same set, and the other one is empty. | 1,000 | [
{
"input": "4 5 9\n2 3 4 5",
"output": "YES\n0 0 1 1"
},
{
"input": "3 3 4\n1 2 4",
"output": "NO"
},
{
"input": "100 8883 915\n1599 4666 663 3646 754 2113 2200 3884 4082 1640 3795 2564 2711 2766 1122 4525 1779 2678 2816 2182 1028 2337 4918 1273 4141 217 2682 1756 309 4744 915 1351 3302 ... | 1,539,156,290 | 2,147,483,647 | Python 3 | OK | TESTS | 47 | 997 | 14,336,000 | def findSet(u):
if parents[u] != u:
parents[u] = findSet(parents[u])
return parents[u]
def unionSet(u, v):
up = findSet(u)
vp = findSet(v)
if up == vp:
return
if ranks[up] > ranks[vp]:
parents[vp] = up
elif ranks[up] < ranks[vp]:
parents[up] = vp
else:
parents[u... | Title: Two Sets
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little X has *n* distinct integers: *p*1,<=*p*2,<=...,<=*p**n*. He wants to divide all of them into two sets *A* and *B*. The following two conditions must be satisfied:
- If number *x* belongs to set *A*, then number *a*<=-... | ```python
def findSet(u):
if parents[u] != u:
parents[u] = findSet(parents[u])
return parents[u]
def unionSet(u, v):
up = findSet(u)
vp = findSet(v)
if up == vp:
return
if ranks[up] > ranks[vp]:
parents[vp] = up
elif ranks[up] < ranks[vp]:
parents[up] = vp
else:
... | 3 | |
186 | A | Comparing Strings | PROGRAMMING | 1,100 | [
"implementation",
"strings"
] | null | null | Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Mish... | The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that co... | Print "YES", if the dwarves belong to the same race. Otherwise, print "NO". | [
"ab\nba\n",
"aa\nab\n"
] | [
"YES\n",
"NO\n"
] | - First example: you can simply swap two letters in string "ab". So we get "ba". - Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b". | 500 | [
{
"input": "ab\nba",
"output": "YES"
},
{
"input": "aa\nab",
"output": "NO"
},
{
"input": "a\nza",
"output": "NO"
},
{
"input": "vvea\nvvae",
"output": "YES"
},
{
"input": "rtfabanpc\natfabrnpc",
"output": "YES"
},
{
"input": "mt\ntm",
"output": "Y... | 1,610,418,882 | 2,147,483,647 | PyPy 3 | WRONG_ANSWER | TESTS | 31 | 218 | 9,420,800 | from sys import stdin,stdout,exit
import math
import bisect
from math import gcd,floor,sqrt,log
from bisect import bisect_left as bl,bisect_right as br
MOD:int=1000000007
g1 = list(stdin.readline().strip())
g2 = list(stdin.readline().strip())
if len(g1) != len(g2):
stdout.write("NO\n")
else:
l = []
diff =... | Title: Comparing Strings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome ... | ```python
from sys import stdin,stdout,exit
import math
import bisect
from math import gcd,floor,sqrt,log
from bisect import bisect_left as bl,bisect_right as br
MOD:int=1000000007
g1 = list(stdin.readline().strip())
g2 = list(stdin.readline().strip())
if len(g1) != len(g2):
stdout.write("NO\n")
else:
l = []
... | 0 | |
534 | A | Exam | PROGRAMMING | 1,100 | [
"constructive algorithms",
"implementation",
"math"
] | null | null | An exam for *n* students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (*i* and *i*<=+<=1) always studied side by side and became friends and if they take an exam sitting next to each other, they will help each other... | A single line contains integer *n* (1<=≤<=*n*<=≤<=5000) — the number of students at an exam. | In the first line print integer *k* — the maximum number of students who can be seated so that no two students with adjacent numbers sit next to each other.
In the second line print *k* distinct integers *a*1,<=*a*2,<=...,<=*a**k* (1<=≤<=*a**i*<=≤<=*n*), where *a**i* is the number of the student on the *i*-th position... | [
"6",
"3\n"
] | [
"6\n1 5 3 6 2 4",
"2\n1 3"
] | none | 500 | [
{
"input": "6",
"output": "6\n5 3 1 6 4 2 "
},
{
"input": "3",
"output": "2\n1 3"
},
{
"input": "1",
"output": "1\n1 "
},
{
"input": "2",
"output": "1\n1"
},
{
"input": "4",
"output": "4\n3 1 4 2 "
},
{
"input": "5",
"output": "5\n5 3 1 4 2 "
},
... | 1,428,855,072 | 672 | Python 3 | WRONG_ANSWER | PRETESTS | 4 | 46 | 0 | n = int(input())
if n == 1:
print(n)
print(1)
elif n <= 3:
print(n - 1)
out = "1"
for i in range(3,n+1,2):
out += " " + str(i)
print(out)
else:
print(n)
out = "1"
for i in range(3,n+1,2):
out += " " + str(i)
for i in range(2,n+1,2):
out += " " + str(i)
... | Title: Exam
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
An exam for *n* students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspects that students with adjacent numbers (*i* and *i*<=+<=1) always studied side by side and bec... | ```python
n = int(input())
if n == 1:
print(n)
print(1)
elif n <= 3:
print(n - 1)
out = "1"
for i in range(3,n+1,2):
out += " " + str(i)
print(out)
else:
print(n)
out = "1"
for i in range(3,n+1,2):
out += " " + str(i)
for i in range(2,n+1,2):
out += " " +... | 0 | |
68 | A | Irrational problem | PROGRAMMING | 1,100 | [
"implementation",
"number theory"
] | A. Irrational problem | 2 | 256 | Little Petya was given this problem for homework:
You are given function (here represents the operation of taking the remainder). His task is to count the number of integers *x* in range [*a*;*b*] with property *f*(*x*)<==<=*x*.
It is a pity that Petya forgot the order in which the remainders should be taken and wr... | First line of the input will contain 6 integers, separated by spaces: *p*1,<=*p*2,<=*p*3,<=*p*4,<=*a*,<=*b* (1<=≤<=*p*1,<=*p*2,<=*p*3,<=*p*4<=≤<=1000,<=0<=≤<=*a*<=≤<=*b*<=≤<=31415).
It is guaranteed that numbers *p*1,<=*p*2,<=*p*3,<=*p*4 will be pairwise distinct. | Output the number of integers in the given range that have the given property. | [
"2 7 1 8 2 8\n",
"20 30 40 50 0 100\n",
"31 41 59 26 17 43\n"
] | [
"0\n",
"20\n",
"9\n"
] | none | 500 | [
{
"input": "2 7 1 8 2 8",
"output": "0"
},
{
"input": "20 30 40 50 0 100",
"output": "20"
},
{
"input": "31 41 59 26 17 43",
"output": "9"
},
{
"input": "1 2 3 4 0 0",
"output": "1"
},
{
"input": "1 2 3 4 1 1",
"output": "0"
},
{
"input": "1 2 999 1000... | 1,619,096,541 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 30 | 124 | 0 | p1,p2,p3,p4,a,b=[int(x) for x in input().split()]
k=min(p1,p2,p3,p4,b)
t=min(p1,p2,p3,p4)
if(a==b and t>a):
print(1)
elif(k>a):
print(k-a)
else:
print(0) | Title: Irrational problem
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Little Petya was given this problem for homework:
You are given function (here represents the operation of taking the remainder). His task is to count the number of integers *x* in range [*a*;*b*] with property *f*(*x... | ```python
p1,p2,p3,p4,a,b=[int(x) for x in input().split()]
k=min(p1,p2,p3,p4,b)
t=min(p1,p2,p3,p4)
if(a==b and t>a):
print(1)
elif(k>a):
print(k-a)
else:
print(0)
``` | 0 |
560 | A | Currency System in Geraldion | PROGRAMMING | 1,000 | [
"implementation",
"sortings"
] | null | null | A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cannot express a certain sum of money with any set of banknotes. Of course, they can use any number of banknotes of ea... | The first line contains number *n* (1<=≤<=*n*<=≤<=1000) — the number of values of the banknotes that used in Geraldion.
The second line contains *n* distinct space-separated numbers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=106) — the values of the banknotes. | Print a single line — the minimum unfortunate sum. If there are no unfortunate sums, print <=-<=1. | [
"5\n1 2 3 4 5\n"
] | [
"-1\n"
] | none | 500 | [
{
"input": "5\n1 2 3 4 5",
"output": "-1"
},
{
"input": "1\n2",
"output": "1"
},
{
"input": "10\n371054 506438 397130 1 766759 208409 769264 549213 641270 771837",
"output": "-1"
},
{
"input": "10\n635370 154890 909382 220996 276501 716105 538714 140162 171960 271264",
"o... | 1,690,552,415 | 2,147,483,647 | Python 3 | TIME_LIMIT_EXCEEDED | TESTS | 2 | 2,000 | 39,731,200 | def find_min_unfortunate_sum(n, banknote_values):
max_sum = sum(banknote_values)
# Create a dp array to track possible sums
dp = [False] * (max_sum + 1)
dp[0] = True
for val in banknote_values:
for i in range(max_sum, val - 1, -1):
dp[i] = dp[i] or dp[i - val]
for i in ran... | Title: Currency System in Geraldion
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several values. But the problem is, the system is not perfect and sometimes it happens that Geraldionians cann... | ```python
def find_min_unfortunate_sum(n, banknote_values):
max_sum = sum(banknote_values)
# Create a dp array to track possible sums
dp = [False] * (max_sum + 1)
dp[0] = True
for val in banknote_values:
for i in range(max_sum, val - 1, -1):
dp[i] = dp[i] or dp[i - val]
fo... | 0 | |
124 | A | The number of positions | PROGRAMMING | 1,000 | [
"math"
] | null | null | Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind him. Find the number of different positions Petr can occupy. | The only line contains three integers *n*, *a* and *b* (0<=≤<=*a*,<=*b*<=<<=*n*<=≤<=100). | Print the single number — the number of the sought positions. | [
"3 1 1\n",
"5 2 3\n"
] | [
"2\n",
"3\n"
] | The possible positions in the first sample are: 2 and 3 (if we number the positions starting with 1).
In the second sample they are 3, 4 and 5. | 500 | [
{
"input": "3 1 1",
"output": "2"
},
{
"input": "5 2 3",
"output": "3"
},
{
"input": "5 4 0",
"output": "1"
},
{
"input": "6 5 5",
"output": "1"
},
{
"input": "9 4 3",
"output": "4"
},
{
"input": "11 4 6",
"output": "7"
},
{
"input": "13 8 ... | 1,632,857,437 | 2,147,483,647 | Python 3 | OK | TESTS | 50 | 124 | 6,758,400 | n, a ,b = map(int, input().split())
if(a+b<n):
if(n-a>b):
print(b+1)
else:
print(n-a) | Title: The number of positions
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Petr stands in line of *n* people, but he doesn't know exactly which position he occupies. He can say that there are no less than *a* people standing in front of him and no more than *b* people standing behind h... | ```python
n, a ,b = map(int, input().split())
if(a+b<n):
if(n-a>b):
print(b+1)
else:
print(n-a)
``` | 3 | |
801 | A | Vicious Keyboard | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter in the string (or do no changes) to maximize the number of occurrences of that string. Compute the maxi... | The first line will contain a string *s* consisting only of uppercase English letters "V" and "K" with length not less than 1 and not greater than 100. | Output a single integer, the maximum number of times "VK" can appear as a substring of the given string after changing at most one character. | [
"VK\n",
"VV\n",
"V\n",
"VKKKKKKKKKVVVVVVVVVK\n",
"KVKV\n"
] | [
"1\n",
"1\n",
"0\n",
"3\n",
"1\n"
] | For the first case, we do not change any letters. "VK" appears once, which is the maximum number of times it could appear.
For the second case, we can change the second character from a "V" to a "K". This will give us the string "VK". This has one occurrence of the string "VK" as a substring.
For the fourth case, we ... | 500 | [
{
"input": "VK",
"output": "1"
},
{
"input": "VV",
"output": "1"
},
{
"input": "V",
"output": "0"
},
{
"input": "VKKKKKKKKKVVVVVVVVVK",
"output": "3"
},
{
"input": "KVKV",
"output": "1"
},
{
"input": "VKKVVVKVKVK",
"output": "5"
},
{
"input... | 1,680,744,814 | 2,147,483,647 | Python 3 | OK | TESTS | 63 | 46 | 0 | # /**
# * author: brownfox2k6
# * created: 06/04/2023 08:28:47 Hanoi, Vietnam
# **/
def solve():
s = input()
ans = 0
for i in range(len(s)):
for c in "VK":
ans = max(ans, (s[:i] + c + s[i+1:]).count("VK"))
print(ans)
_T = 1
# _T = int(input())
... | Title: Vicious Keyboard
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Tonio has a keyboard with only two letters, "V" and "K".
One day, he has typed out a string *s* with only these two letters. He really likes it when the string "VK" appears, so he wishes to change at most one letter i... | ```python
# /**
# * author: brownfox2k6
# * created: 06/04/2023 08:28:47 Hanoi, Vietnam
# **/
def solve():
s = input()
ans = 0
for i in range(len(s)):
for c in "VK":
ans = max(ans, (s[:i] + c + s[i+1:]).count("VK"))
print(ans)
_T = 1
# _T = int(... | 3 | |
734 | A | Anton and Danik | PROGRAMMING | 800 | [
"implementation",
"strings"
] | null | null | Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, who won more games, he or Danik? Help him determine this. | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=100<=000) — the number of games played.
The second line contains a string *s*, consisting of *n* uppercase English letters 'A' and 'D' — the outcome of each of the games. The *i*-th character of the string is equal to 'A' if the Anton won the *i*... | If Anton won more games than Danik, print "Anton" (without quotes) in the only line of the output.
If Danik won more games than Anton, print "Danik" (without quotes) in the only line of the output.
If Anton and Danik won the same number of games, print "Friendship" (without quotes). | [
"6\nADAAAA\n",
"7\nDDDAADA\n",
"6\nDADADA\n"
] | [
"Anton\n",
"Danik\n",
"Friendship\n"
] | In the first sample, Anton won 6 games, while Danik — only 1. Hence, the answer is "Anton".
In the second sample, Anton won 3 games and Danik won 4 games, so the answer is "Danik".
In the third sample, both Anton and Danik won 3 games and the answer is "Friendship". | 500 | [
{
"input": "6\nADAAAA",
"output": "Anton"
},
{
"input": "7\nDDDAADA",
"output": "Danik"
},
{
"input": "6\nDADADA",
"output": "Friendship"
},
{
"input": "10\nDDDDADDADD",
"output": "Danik"
},
{
"input": "40\nAAAAAAAAADDAAAAAAAAAAADADDAAAAAAAAAAADAA",
"output": ... | 1,698,016,230 | 2,147,483,647 | Python 3 | OK | TESTS | 25 | 46 | 102,400 | if __name__ == "__main__":
x = int(input())
games = input()
anton = 0
for i in range(0, x):
if(games[i] == "A"):
anton += 1
if(x % 2 == 0 and x/2 == anton):
print("Friendship")
elif(anton > x - anton):
print("Anton")
else:
print("Da... | Title: Anton and Danik
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Anton likes to play chess, and so does his friend Danik.
Once they have played *n* games in a row. For each game it's known who was the winner — Anton or Danik. None of the games ended with a tie.
Now Anton wonders, w... | ```python
if __name__ == "__main__":
x = int(input())
games = input()
anton = 0
for i in range(0, x):
if(games[i] == "A"):
anton += 1
if(x % 2 == 0 and x/2 == anton):
print("Friendship")
elif(anton > x - anton):
print("Anton")
else:
... | 3 | |
976 | B | Lara Croft and the New Game | PROGRAMMING | 1,300 | [
"implementation",
"math"
] | null | null | You might have heard about the next game in Lara Croft series coming out this year. You also might have watched its trailer. Though you definitely missed the main idea about its plot, so let me lift the veil of secrecy.
Lara is going to explore yet another dangerous dungeon. Game designers decided to use good old 2D e... | The only line contains three integers *n*, *m* and *k* (2<=≤<=*n*,<=*m*<=≤<=109, *n* is always even, 0<=≤<=*k*<=<<=*n*·*m*). Note that *k* doesn't fit into 32-bit integer type! | Print the cell (the row and the column where the cell is situated) where Lara ends up after she moves *k* times. | [
"4 3 0\n",
"4 3 11\n",
"4 3 7\n"
] | [
"1 1\n",
"1 2\n",
"3 2\n"
] | Here is her path on matrix 4 by 3: | 0 | [
{
"input": "4 3 0",
"output": "1 1"
},
{
"input": "4 3 11",
"output": "1 2"
},
{
"input": "4 3 7",
"output": "3 2"
},
{
"input": "1000000000 2 1999999999",
"output": "1 2"
},
{
"input": "1000000000 1000000000 999999999999999999",
"output": "1 2"
},
{
"... | 1,525,286,824 | 2,644 | Python 3 | WRONG_ANSWER | TESTS | 9 | 77 | 7,065,600 | n, m, k = map(int, input().split())
if k < n:
print(k + 1, "1")
elif k == n + 1:
print(n, "2")
else:
k = k - n
m_d = k // (m - 1)
m_m = k % (m - 1)
if m_d % 2 == 1:
m_m = m - m_m
else:
m_m += 2
m_d = n - m_d
print(m_d,m_m)
| Title: Lara Croft and the New Game
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You might have heard about the next game in Lara Croft series coming out this year. You also might have watched its trailer. Though you definitely missed the main idea about its plot, so let me lift the veil... | ```python
n, m, k = map(int, input().split())
if k < n:
print(k + 1, "1")
elif k == n + 1:
print(n, "2")
else:
k = k - n
m_d = k // (m - 1)
m_m = k % (m - 1)
if m_d % 2 == 1:
m_m = m - m_m
else:
m_m += 2
m_d = n - m_d
print(m_d,m_m)
``` | 0 | |
743 | B | Chloe and the sequence | PROGRAMMING | 1,200 | [
"binary search",
"bitmasks",
"constructive algorithms",
"implementation"
] | null | null | Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following algorithm of generating a sequence of integers. Initially we have a sequence consisting of a single element eq... | The only line contains two integers *n* and *k* (1<=≤<=*n*<=≤<=50, 1<=≤<=*k*<=≤<=2*n*<=-<=1). | Print single integer — the integer at the *k*-th position in the obtained sequence. | [
"3 2\n",
"4 8\n"
] | [
"2",
"4"
] | In the first sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1]. The number on the second position is 2.
In the second sample the obtained sequence is [1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1]. The number on the eighth position is 4. | 1,000 | [
{
"input": "3 2",
"output": "2"
},
{
"input": "4 8",
"output": "4"
},
{
"input": "5 27",
"output": "1"
},
{
"input": "7 44",
"output": "3"
},
{
"input": "15 18432",
"output": "12"
},
{
"input": "20 259676",
"output": "3"
},
{
"input": "30 6... | 1,601,193,568 | 2,147,483,647 | Python 3 | OK | TESTS | 39 | 109 | 0 | n,k = map(int,input().split(' '))
count = 1
while k&1 != 1:
k = k>>1
count+=1
print(count) | Title: Chloe and the sequence
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad.
Let's consider the following a... | ```python
n,k = map(int,input().split(' '))
count = 1
while k&1 != 1:
k = k>>1
count+=1
print(count)
``` | 3 | |
612 | A | The Text Splitting | PROGRAMMING | 1,300 | [
"brute force",
"implementation",
"strings"
] | null | null | You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string *s* to the st... | The first line contains three positive integers *n*,<=*p*,<=*q* (1<=≤<=*p*,<=*q*<=≤<=*n*<=≤<=100).
The second line contains the string *s* consists of lowercase and uppercase latin letters and digits. | If it's impossible to split the string *s* to the strings of length *p* and *q* print the only number "-1".
Otherwise in the first line print integer *k* — the number of strings in partition of *s*.
Each of the next *k* lines should contain the strings in partition. Each string should be of the length *p* or *q*. The... | [
"5 2 3\nHello\n",
"10 9 5\nCodeforces\n",
"6 4 5\nPrivet\n",
"8 1 1\nabacabac\n"
] | [
"2\nHe\nllo\n",
"2\nCodef\norces\n",
"-1\n",
"8\na\nb\na\nc\na\nb\na\nc\n"
] | none | 0 | [
{
"input": "5 2 3\nHello",
"output": "2\nHe\nllo"
},
{
"input": "10 9 5\nCodeforces",
"output": "2\nCodef\norces"
},
{
"input": "6 4 5\nPrivet",
"output": "-1"
},
{
"input": "8 1 1\nabacabac",
"output": "8\na\nb\na\nc\na\nb\na\nc"
},
{
"input": "1 1 1\n1",
"ou... | 1,550,603,862 | 2,147,483,647 | Python 3 | RUNTIME_ERROR | TESTS | 0 | 77 | 0 | n=int(input())
p=int(input())
q=int(input())
ch=input()
i=-1
j=0
s=0
while (((i*p)+(q*j))!=n and i<n):
i=i+1
j=0
while (((i*p)+(q*j))!=n and j<n):
j=j+1
if(i<n-1 or j<n-1):
print(i+j)
for z in range(0,i):
print(ch[s:s+p])
s=s+p
for k in range(0,j):
... | Title: The Text Splitting
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given the string *s* of length *n* and the numbers *p*,<=*q*. Split the string *s* to pieces of length *p* and *q*.
For example, the string "Hello" for *p*<==<=2, *q*<==<=3 can be split to the two strings "H... | ```python
n=int(input())
p=int(input())
q=int(input())
ch=input()
i=-1
j=0
s=0
while (((i*p)+(q*j))!=n and i<n):
i=i+1
j=0
while (((i*p)+(q*j))!=n and j<n):
j=j+1
if(i<n-1 or j<n-1):
print(i+j)
for z in range(0,i):
print(ch[s:s+p])
s=s+p
for k in range(... | -1 | |
46 | A | Ball Game | PROGRAMMING | 800 | [
"brute force",
"implementation"
] | A. Ball Game | 2 | 256 | A kindergarten teacher Natalia Pavlovna has invented a new ball game. This game not only develops the children's physique, but also teaches them how to count.
The game goes as follows. Kids stand in circle. Let's agree to think of the children as numbered with numbers from 1 to *n* clockwise and the child number 1 is... | The first line contains integer *n* (2<=≤<=*n*<=≤<=100) which indicates the number of kids in the circle. | In the single line print *n*<=-<=1 numbers which are the numbers of children who will get the ball after each throw. Separate the numbers by spaces. | [
"10\n",
"3\n"
] | [
"2 4 7 1 6 2 9 7 6\n",
"2 1\n"
] | none | 0 | [
{
"input": "10",
"output": "2 4 7 1 6 2 9 7 6"
},
{
"input": "3",
"output": "2 1"
},
{
"input": "4",
"output": "2 4 3"
},
{
"input": "5",
"output": "2 4 2 1"
},
{
"input": "6",
"output": "2 4 1 5 4"
},
{
"input": "7",
"output": "2 4 7 4 2 1"
},
... | 1,648,575,973 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 62 | 0 | n = int(input())
ans = []
helper = 2
item = 1
for i in range(n - 1):
if helper <= n:
ans.append(helper)
else:
ans.append((helper) % n)
item += 1
helper += item
print(ans)
| Title: Ball Game
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
A kindergarten teacher Natalia Pavlovna has invented a new ball game. This game not only develops the children's physique, but also teaches them how to count.
The game goes as follows. Kids stand in circle. Let's agree to think... | ```python
n = int(input())
ans = []
helper = 2
item = 1
for i in range(n - 1):
if helper <= n:
ans.append(helper)
else:
ans.append((helper) % n)
item += 1
helper += item
print(ans)
``` | 0 |
25 | A | IQ test | PROGRAMMING | 1,300 | [
"brute force"
] | A. IQ test | 2 | 256 | Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — to check his answers, he needs a program that among the given *n* numbers finds one that i... | The first line contains integer *n* (3<=≤<=*n*<=≤<=100) — amount of numbers in the task. The second line contains *n* space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness. | Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order. | [
"5\n2 4 7 8 10\n",
"4\n1 2 1 1\n"
] | [
"3\n",
"2\n"
] | none | 0 | [
{
"input": "5\n2 4 7 8 10",
"output": "3"
},
{
"input": "4\n1 2 1 1",
"output": "2"
},
{
"input": "3\n1 2 2",
"output": "1"
},
{
"input": "3\n100 99 100",
"output": "2"
},
{
"input": "3\n5 3 2",
"output": "3"
},
{
"input": "4\n43 28 1 91",
"output"... | 1,686,486,107 | 2,147,483,647 | Python 3 | OK | TESTS | 32 | 92 | 0 | n = int(input())
x = input()
array = x.split(" ")
counteven = 0
countodd = 0
for i in range(n):
if (int(array[i]) % 2 == 0):
counteven += 1
even = i
else:
countodd += 1
odd = i
if (counteven == 1 ):
print(even+1)
if (countodd == 1):
print(odd+1) | Title: IQ test
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given *n* numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob — t... | ```python
n = int(input())
x = input()
array = x.split(" ")
counteven = 0
countodd = 0
for i in range(n):
if (int(array[i]) % 2 == 0):
counteven += 1
even = i
else:
countodd += 1
odd = i
if (counteven == 1 ):
print(even+1)
if (countodd == 1):
print(odd+1)
`... | 3.977 |
359 | C | Prime Number | PROGRAMMING | 1,900 | [
"math",
"number theory"
] | null | null | Simon has a prime number *x* and an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
Simon loves fractions very much. Today he wrote out number on a piece of paper. After Simon led all fractions to a common denominator and summed them up, he got a fraction: , where number *t* equals *x**a*1<=+<=*a*2<=+<=...... | The first line contains two positive integers *n* and *x* (1<=≤<=*n*<=≤<=105, 2<=≤<=*x*<=≤<=109) — the size of the array and the prime number.
The second line contains *n* space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (0<=≤<=*a*1<=≤<=*a*2<=≤<=...<=≤<=*a**n*<=≤<=109). | Print a single number — the answer to the problem modulo 1000000007 (109<=+<=7). | [
"2 2\n2 2\n",
"3 3\n1 2 3\n",
"2 2\n29 29\n",
"4 5\n0 0 0 0\n"
] | [
"8\n",
"27\n",
"73741817\n",
"1\n"
] | In the first sample <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/7745f7cc87c6c5f753e3414fad9baa3b1e3fea48.png" style="max-width: 100.0%;max-height: 100.0%;"/>. Thus, the answer to the problem is 8.
In the second sample, <img align="middle" class="tex-formula" src="https://espresso.codef... | 1,500 | [
{
"input": "2 2\n2 2",
"output": "8"
},
{
"input": "3 3\n1 2 3",
"output": "27"
},
{
"input": "2 2\n29 29",
"output": "73741817"
},
{
"input": "4 5\n0 0 0 0",
"output": "1"
},
{
"input": "1 2\n1000000000",
"output": "1"
},
{
"input": "26 2\n0 0 0 0 0 0... | 1,539,452,176 | 2,147,483,647 | Python 3 | OK | TESTS | 36 | 233 | 8,908,800 | modulus = 10 ** 9 + 7
def main():
n, x = map(int, input().split())
arr = list(map(int, input().split()))
total = sum(arr)
powers = [total - x for x in arr]
powers.sort(reverse=True)
while True:
low = powers[len(powers) - 1]
cnt = 0
while len(powers... | Title: Prime Number
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Simon has a prime number *x* and an array of non-negative integers *a*1,<=*a*2,<=...,<=*a**n*.
Simon loves fractions very much. Today he wrote out number on a piece of paper. After Simon led all fractions to a common den... | ```python
modulus = 10 ** 9 + 7
def main():
n, x = map(int, input().split())
arr = list(map(int, input().split()))
total = sum(arr)
powers = [total - x for x in arr]
powers.sort(reverse=True)
while True:
low = powers[len(powers) - 1]
cnt = 0
while ... | 3 | |
257 | C | View Angle | PROGRAMMING | 1,800 | [
"brute force",
"geometry",
"math"
] | null | null | Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex at the origin of coordinates and with all mannequins standing inside or on the boarder of this a... | The first line contains a single integer *n* (1<=≤<=*n*<=≤<=105) — the number of mannequins.
Next *n* lines contain two space-separated integers each: *x**i*,<=*y**i* (|*x**i*|,<=|*y**i*|<=≤<=1000) — the coordinates of the *i*-th mannequin. It is guaranteed that the origin of the coordinates has no mannequin. It is gu... | Print a single real number — the value of the sought angle in degrees. The answer will be considered valid if the relative or absolute error doesn't exceed 10<=-<=6. | [
"2\n2 0\n0 2\n",
"3\n2 0\n0 2\n-2 2\n",
"4\n2 0\n0 2\n-2 0\n0 -2\n",
"2\n2 1\n1 2\n"
] | [
"90.0000000000\n",
"135.0000000000\n",
"270.0000000000\n",
"36.8698976458\n"
] | Solution for the first sample test is shown below:
Solution for the second sample test is shown below:
Solution for the third sample test is shown below:
Solution for the fourth sample test is shown below: | 1,500 | [
{
"input": "2\n2 0\n0 2",
"output": "90.0000000000"
},
{
"input": "3\n2 0\n0 2\n-2 2",
"output": "135.0000000000"
},
{
"input": "4\n2 0\n0 2\n-2 0\n0 -2",
"output": "270.0000000000"
},
{
"input": "2\n2 1\n1 2",
"output": "36.8698976458"
},
{
"input": "1\n1 1",
... | 1,504,514,163 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 5 | 842 | 10,240,000 | import math
n = int(input())
points = []
for _ in range(n):
x, y = map(int, input().split())
points.append((x, y))
points.sort(key=lambda point: math.atan2(point[1], point[0]))
print((math.atan2(points[-1][1], points[-1][0]) - math.atan2(points[0][1], points[0][0])) * 180.0 / math.pi) | Title: View Angle
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Flatland has recently introduced a new type of an eye check for the driver's licence. The check goes like that: there is a plane with mannequins standing on it. You should tell the value of the minimum angle with the vertex ... | ```python
import math
n = int(input())
points = []
for _ in range(n):
x, y = map(int, input().split())
points.append((x, y))
points.sort(key=lambda point: math.atan2(point[1], point[0]))
print((math.atan2(points[-1][1], points[-1][0]) - math.atan2(points[0][1], points[0][0])) * 180.0 / math.pi)
``` | 0 | |
770 | A | New Password | PROGRAMMING | 800 | [
"*special",
"implementation"
] | null | null | Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
- the length of the password must be equal to *n*, - the password should cons... | The first line contains two positive integers *n* and *k* (2<=≤<=*n*<=≤<=100, 2<=≤<=*k*<=≤<=*min*(*n*,<=26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists. | Print any password which satisfies all conditions given by Innokentiy. | [
"4 3\n",
"6 6\n",
"5 2\n"
] | [
"java\n",
"python\n",
"phphp\n"
] | In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letter... | 500 | [
{
"input": "4 3",
"output": "abca"
},
{
"input": "6 6",
"output": "abcdef"
},
{
"input": "5 2",
"output": "ababa"
},
{
"input": "3 2",
"output": "aba"
},
{
"input": "10 2",
"output": "ababababab"
},
{
"input": "26 13",
"output": "abcdefghijklmabcde... | 1,649,919,737 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 47 | 46 | 0 | s='abcdefghijklmnopqrstuvwxyz'
n,k=map(int,input().split())
c=''
while n>0:
if n<k:
c=c+s[0:n]
n=-1
else:
c=c+s[0:k]
n=n-k
print(c) | Title: New Password
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the foll... | ```python
s='abcdefghijklmnopqrstuvwxyz'
n,k=map(int,input().split())
c=''
while n>0:
if n<k:
c=c+s[0:n]
n=-1
else:
c=c+s[0:k]
n=n-k
print(c)
``` | 3 | |
558 | C | Amr and Chemistry | PROGRAMMING | 1,900 | [
"brute force",
"graphs",
"greedy",
"math",
"shortest paths"
] | null | null | Amr loves Chemistry, and specially doing experiments. He is preparing for a new interesting experiment.
Amr has *n* different types of chemicals. Each chemical *i* has an initial volume of *a**i* liters. For this experiment, Amr has to mix all the chemicals together, but all the chemicals volumes must be equal first. ... | The first line contains one number *n* (1<=≤<=*n*<=≤<=105), the number of chemicals.
The second line contains *n* space separated integers *a**i* (1<=≤<=*a**i*<=≤<=105), representing the initial volume of the *i*-th chemical in liters. | Output one integer the minimum number of operations required to make all the chemicals volumes equal. | [
"3\n4 8 2\n",
"3\n3 5 6\n"
] | [
"2",
"5"
] | In the first sample test, the optimal solution is to divide the second chemical volume by two, and multiply the third chemical volume by two to make all the volumes equal 4.
In the second sample test, the optimal solution is to divide the first chemical volume by two, and divide the second and the third chemical volum... | 1,500 | [
{
"input": "3\n4 8 2",
"output": "2"
},
{
"input": "3\n3 5 6",
"output": "5"
},
{
"input": "2\n50000 100000",
"output": "1"
},
{
"input": "2\n99999 99998",
"output": "2"
},
{
"input": "17\n1 2 4 8 16 32 64 128 256 512 1024 2048 4096 8192 16384 32768 65536",
"o... | 1,689,650,913 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 46 | 0 | print("_RANDOM_GUESS_1689650913.0379517")# 1689650913.0379713 | Title: Amr and Chemistry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Amr loves Chemistry, and specially doing experiments. He is preparing for a new interesting experiment.
Amr has *n* different types of chemicals. Each chemical *i* has an initial volume of *a**i* liters. For this exp... | ```python
print("_RANDOM_GUESS_1689650913.0379517")# 1689650913.0379713
``` | 0 | |
96 | A | Football | PROGRAMMING | 900 | [
"implementation",
"strings"
] | A. Football | 2 | 256 | Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A zero corresponds to players of one team; a one corresponds to players of another team. If... | The first input line contains a non-empty string consisting of characters "0" and "1", which represents players. The length of the string does not exceed 100 characters. There's at least one player from each team present on the field. | Print "YES" if the situation is dangerous. Otherwise, print "NO". | [
"001001\n",
"1000000001\n"
] | [
"NO\n",
"YES\n"
] | none | 500 | [
{
"input": "001001",
"output": "NO"
},
{
"input": "1000000001",
"output": "YES"
},
{
"input": "00100110111111101",
"output": "YES"
},
{
"input": "11110111111111111",
"output": "YES"
},
{
"input": "01",
"output": "NO"
},
{
"input": "10100101",
"outp... | 1,661,452,374 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 92 | 0 | a = input()
b = 1
c=0
d = "NO"
for i in range(len(a)-1):
if a[i] == a[i+1]:
b+=1
else:
# print(b)
if b>c:
c=b
b=1
if c >= 7:
print("YES")
else:
print("NO") | Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Petya loves football very much. One day, as he was watching a football match, he was writing the players' current positions on a piece of paper. To simplify the situation he depicted it as a string consisting of zeroes and ones. A... | ```python
a = input()
b = 1
c=0
d = "NO"
for i in range(len(a)-1):
if a[i] == a[i+1]:
b+=1
else:
# print(b)
if b>c:
c=b
b=1
if c >= 7:
print("YES")
else:
print("NO")
``` | 0 |
678 | A | Johny Likes Numbers | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*. | The only line contains two integers *n* and *k* (1<=≤<=*n*,<=*k*<=≤<=109). | Print the smallest integer *x*<=><=*n*, so it is divisible by the number *k*. | [
"5 3\n",
"25 13\n",
"26 13\n"
] | [
"6\n",
"26\n",
"39\n"
] | none | 0 | [
{
"input": "5 3",
"output": "6"
},
{
"input": "25 13",
"output": "26"
},
{
"input": "26 13",
"output": "39"
},
{
"input": "1 1",
"output": "2"
},
{
"input": "8 8",
"output": "16"
},
{
"input": "14 15",
"output": "15"
},
{
"input": "197 894"... | 1,519,542,505 | 2,147,483,647 | Python 3 | OK | TESTS | 37 | 62 | 5,632,000 | n,k = map(int ,input().split())
i=n%k
r=abs(k-i)
print(n+r)
| Title: Johny Likes Numbers
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Johny likes numbers *n* and *k* very much. Now Johny wants to find the smallest integer *x* greater than *n*, so it is divisible by the number *k*.
Input Specification:
The only line contains two integers *n* and *... | ```python
n,k = map(int ,input().split())
i=n%k
r=abs(k-i)
print(n+r)
``` | 3 | |
227 | B | Effective Approach | PROGRAMMING | 1,100 | [
"implementation"
] | null | null | Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn compared with the number that you need to find. Once you find the array element that is equal to the requ... | The first line contains integer *n* (1<=≤<=*n*<=≤<=105) — the number of elements in the array. The second line contains *n* distinct space-separated integers *a*1,<=*a*2,<=...,<=*a**n* (1<=≤<=*a**i*<=≤<=*n*) — the elements of array.
The third line contains integer *m* (1<=≤<=*m*<=≤<=105) — the number of queries. The ... | Print two integers, showing how many comparisons Vasya's approach needs and how many comparisons Petya's approach needs. Separate the numbers by spaces.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use cin, cout streams or the %I64d specifier. | [
"2\n1 2\n1\n1\n",
"2\n2 1\n1\n1\n",
"3\n3 1 2\n3\n1 2 3\n"
] | [
"1 2\n",
"2 1\n",
"6 6\n"
] | In the first sample Vasya's approach will make one comparison (it starts with the 1-st element and immediately finds the required number), and Petya's approach makes two comparisons (first he compares with the 2-nd array element, doesn't find the search item and compares with the 1-st element).
In the second sample, o... | 1,000 | [
{
"input": "2\n1 2\n1\n1",
"output": "1 2"
},
{
"input": "2\n2 1\n1\n1",
"output": "2 1"
},
{
"input": "3\n3 1 2\n3\n1 2 3",
"output": "6 6"
},
{
"input": "9\n2 9 3 1 6 4 7 8 5\n9\n5 1 5 2 8 4 4 4 5",
"output": "58 32"
},
{
"input": "10\n3 10 9 2 7 6 5 8 4 1\n1\n4... | 1,695,630,997 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n=int(input())
a=list(map(int,input().split()))
m=int(input())
b=list(map(int,input().split()))
v=0
p=0
i=0
j=0
while i<len(b):
while j<len(a):
if b[i]==a[j]:
v+=1
break
else:
v+=1
j+=1
i+=1
while i<len(b):
while j<len(a):
... | Title: Effective Approach
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Once at a team training Vasya, Petya and Sasha got a problem on implementing linear search in an array.
According to the boys, linear search works as follows. The array elements in a pre-selected order are in turn c... | ```python
n=int(input())
a=list(map(int,input().split()))
m=int(input())
b=list(map(int,input().split()))
v=0
p=0
i=0
j=0
while i<len(b):
while j<len(a):
if b[i]==a[j]:
v+=1
break
else:
v+=1
j+=1
i+=1
while i<len(b):
while j<len... | 0 | |
616 | B | Dinner with Emma | PROGRAMMING | 1,000 | [
"games",
"greedy"
] | null | null | Jack decides to invite Emma out for a dinner. Jack is a modest student, he doesn't want to go to an expensive restaurant. Emma is a girl with high taste, she prefers elite places.
Munhattan consists of *n* streets and *m* avenues. There is exactly one restaurant on the intersection of each street and avenue. The stree... | The first line contains two integers *n*,<=*m* (1<=≤<=*n*,<=*m*<=≤<=100) — the number of streets and avenues in Munhattan.
Each of the next *n* lines contains *m* integers *c**ij* (1<=≤<=*c**ij*<=≤<=109) — the cost of the dinner in the restaurant on the intersection of the *i*-th street and the *j*-th avenue. | Print the only integer *a* — the cost of the dinner for Jack and Emma. | [
"3 4\n4 1 3 5\n2 2 2 2\n5 4 5 1\n",
"3 3\n1 2 3\n2 3 1\n3 1 2\n"
] | [
"2\n",
"1\n"
] | In the first example if Emma chooses the first or the third streets Jack can choose an avenue with the cost of the dinner 1. So she chooses the second street and Jack chooses any avenue. The cost of the dinner is 2.
In the second example regardless of Emma's choice Jack can choose a restaurant with the cost of the din... | 0 | [
{
"input": "3 4\n4 1 3 5\n2 2 2 2\n5 4 5 1",
"output": "2"
},
{
"input": "3 3\n1 2 3\n2 3 1\n3 1 2",
"output": "1"
},
{
"input": "1 1\n1",
"output": "1"
},
{
"input": "1 10\n74 35 82 39 1 84 29 41 70 12",
"output": "1"
},
{
"input": "10 1\n44\n23\n65\n17\n48\n29\n... | 1,591,876,716 | 2,147,483,647 | PyPy 3 | OK | TESTS | 16 | 171 | 1,638,400 | n,m=[int(i) for i in input().split()]
l=[]
for i in range(n):
a=[int(i) for i in input().split()]
d=min(a)
l.append(d)
print(max(l)) | Title: Dinner with Emma
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Jack decides to invite Emma out for a dinner. Jack is a modest student, he doesn't want to go to an expensive restaurant. Emma is a girl with high taste, she prefers elite places.
Munhattan consists of *n* streets and... | ```python
n,m=[int(i) for i in input().split()]
l=[]
for i in range(n):
a=[int(i) for i in input().split()]
d=min(a)
l.append(d)
print(max(l))
``` | 3 | |
0 | none | none | none | 0 | [
"none"
] | null | null | Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of members are friends. Of course, a member can't be a friend with themselves.
Let A-B denote that... | The first line of the input contain two integers *n* and *m* (3<=≤<=*n*<=≤<=150<=000, ) — the number of members and the number of pairs of members that are friends.
The *i*-th of the next *m* lines contains two distinct integers *a**i* and *b**i* (1<=≤<=*a**i*,<=*b**i*<=≤<=*n*,<=*a**i*<=≠<=*b**i*). Members *a**i* and ... | If the given network is reasonable, print "YES" in a single line (without the quotes). Otherwise, print "NO" in a single line (without the quotes). | [
"4 3\n1 3\n3 4\n1 4\n",
"4 4\n3 1\n2 3\n3 4\n1 2\n",
"10 4\n4 3\n5 10\n8 9\n1 2\n",
"3 2\n1 2\n2 3\n"
] | [
"YES\n",
"NO\n",
"YES\n",
"NO\n"
] | The drawings below show the situation in the first sample (on the left) and in the second sample (on the right). Each edge represents two members that are friends. The answer is "NO" in the second sample because members (2, 3) are friends and members (3, 4) are friends, while members (2, 4) are not. | 0 | [
{
"input": "4 3\n1 3\n3 4\n1 4",
"output": "YES"
},
{
"input": "4 4\n3 1\n2 3\n3 4\n1 2",
"output": "NO"
},
{
"input": "10 4\n4 3\n5 10\n8 9\n1 2",
"output": "YES"
},
{
"input": "3 2\n1 2\n2 3",
"output": "NO"
},
{
"input": "3 0",
"output": "YES"
},
{
... | 1,694,067,231 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | def is_reasonable_network(n, friendships):
adj_list = [[] for _ in range(n + 1)]
for a, b in friendships:
adj_list[a].append(b)
adj_list[b].append(a)
def dfs(node, visited):
visited[node] = True
for neighbor in adj_list[node]:
if not visited[neighbor]:
... | Title: none
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Bear Limak examines a social network. Its main functionality is that two members can become friends (then they can talk with each other and share funny pictures).
There are *n* members, numbered 1 through *n*. *m* pairs of member... | ```python
def is_reasonable_network(n, friendships):
adj_list = [[] for _ in range(n + 1)]
for a, b in friendships:
adj_list[a].append(b)
adj_list[b].append(a)
def dfs(node, visited):
visited[node] = True
for neighbor in adj_list[node]:
if not visited[neighb... | 0 | |
127 | A | Wasted Time | PROGRAMMING | 900 | [
"geometry"
] | null | null | Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count the time he has wasted signing papers.
Mr. Scrooge's signature can be represented as a polyline ... | The first line contains two integers *n* and *k* (2<=≤<=*n*<=≤<=100, 1<=≤<=*k*<=≤<=1000). Each of the following *n* lines contains the coordinates of the polyline's endpoints. The *i*-th one contains coordinates of the point *A**i* — integers *x**i* and *y**i*, separated by a space.
All points *A**i* are different. Th... | Print one real number — the total time Scrooges wastes on signing the papers in seconds. The absolute or relative error should not exceed 10<=-<=6. | [
"2 1\n0 0\n10 0\n",
"5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0\n",
"6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0\n"
] | [
"0.200000000",
"6.032163204",
"3.000000000"
] | none | 500 | [
{
"input": "2 1\n0 0\n10 0",
"output": "0.200000000"
},
{
"input": "5 10\n3 1\n-5 6\n-2 -1\n3 2\n10 0",
"output": "6.032163204"
},
{
"input": "6 10\n5 0\n4 0\n6 0\n3 0\n7 0\n2 0",
"output": "3.000000000"
},
{
"input": "10 95\n-20 -5\n2 -8\n14 13\n10 3\n17 11\n13 -12\n-6 11\n1... | 1,559,667,317 | 2,147,483,647 | Python 3 | OK | TESTS | 42 | 218 | 0 | n,k=map(int,input().split())
xp=[]
yp=[]
def dist(x1,y1,x2,y2):
return ((x1-x2)**2+(y1-y2)**2)**0.5
for i in range(n):
x,y=map(int,input().split())
xp.append(x)
yp.append(y)
d=0
for i in range(n-1):
x1,x2=xp[i],xp[i+1]
y1,y2=yp[i],yp[i+1]
d+=dist(x1,y1,x2,y2)
lost=(d*k)/50
print(lost)
| Title: Wasted Time
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Mr. Scrooge, a very busy man, decided to count the time he wastes on all sorts of useless stuff to evaluate the lost profit. He has already counted the time he wastes sleeping and eating. And now Mr. Scrooge wants to count ... | ```python
n,k=map(int,input().split())
xp=[]
yp=[]
def dist(x1,y1,x2,y2):
return ((x1-x2)**2+(y1-y2)**2)**0.5
for i in range(n):
x,y=map(int,input().split())
xp.append(x)
yp.append(y)
d=0
for i in range(n-1):
x1,x2=xp[i],xp[i+1]
y1,y2=yp[i],yp[i+1]
d+=dist(x1,y1,x2,y2)
lost=(d*k)/50
print(lost)
... | 3 | |
43 | A | Football | PROGRAMMING | 1,000 | [
"strings"
] | A. Football | 2 | 256 | One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process. On the whole there are *n* lines in that description each of which described one goal. E... | The first line contains an integer *n* (1<=≤<=*n*<=≤<=100) — the number of lines in the description. Then follow *n* lines — for each goal the names of the teams that scored it. The names are non-empty lines consisting of uppercase Latin letters whose lengths do not exceed 10 symbols. It is guaranteed that the match di... | Print the name of the winning team. We remind you that in football the team that scores more goals is considered the winner. | [
"1\nABC\n",
"5\nA\nABA\nABA\nA\nA\n"
] | [
"ABC\n",
"A\n"
] | none | 500 | [
{
"input": "1\nABC",
"output": "ABC"
},
{
"input": "5\nA\nABA\nABA\nA\nA",
"output": "A"
},
{
"input": "2\nXTSJEP\nXTSJEP",
"output": "XTSJEP"
},
{
"input": "3\nXZYDJAEDZ\nXZYDJAEDZ\nXZYDJAEDZ",
"output": "XZYDJAEDZ"
},
{
"input": "3\nQCCYXL\nQCCYXL\nAXGLFQDD",
... | 1,625,854,249 | 2,147,483,647 | Python 3 | OK | TESTS | 34 | 124 | 0 | n = int(input())
a =[input() for i in range(n)]
winner = a[0]
for i in a:
if a.count(i)> a.count(winner):
winner=i
print(winner)
| Title: Football
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
One day Vasya decided to have a look at the results of Berland 1910 Football Championship’s finals. Unfortunately he didn't find the overall score of the match; however, he got hold of a profound description of the match's process... | ```python
n = int(input())
a =[input() for i in range(n)]
winner = a[0]
for i in a:
if a.count(i)> a.count(winner):
winner=i
print(winner)
``` | 3.969 |
38 | A | Army | PROGRAMMING | 800 | [
"implementation"
] | A. Army | 2 | 256 | The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<=1. Reaching a certain rank *i* having not reached all the previous *i*<=-<=1 ranks is... | The first input line contains an integer *n* (2<=≤<=*n*<=≤<=100). The second line contains *n*<=-<=1 integers *d**i* (1<=≤<=*d**i*<=≤<=100). The third input line contains two integers *a* and *b* (1<=≤<=*a*<=<<=*b*<=≤<=*n*). The numbers on the lines are space-separated. | Print the single number which is the number of years that Vasya needs to rise from rank *a* to rank *b*. | [
"3\n5 6\n1 2\n",
"3\n5 6\n1 3\n"
] | [
"5\n",
"11\n"
] | none | 0 | [
{
"input": "3\n5 6\n1 2",
"output": "5"
},
{
"input": "3\n5 6\n1 3",
"output": "11"
},
{
"input": "2\n55\n1 2",
"output": "55"
},
{
"input": "3\n85 78\n1 3",
"output": "163"
},
{
"input": "4\n63 4 49\n2 3",
"output": "4"
},
{
"input": "5\n93 83 42 56\n... | 1,655,347,183 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 4 | 62 | 0 |
op = int(input())
d = list(map(int,input().split()))
a,b = list(map(int,input().split()))
dif = (b-1)
d.sort()
lis = d[a-1:dif]
print(sum(lis))
| Title: Army
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
The Berland Armed Forces System consists of *n* ranks that are numbered using natural numbers from 1 to *n*, where 1 is the lowest rank and *n* is the highest rank.
One needs exactly *d**i* years to rise from rank *i* to rank *i*<=+<... | ```python
op = int(input())
d = list(map(int,input().split()))
a,b = list(map(int,input().split()))
dif = (b-1)
d.sort()
lis = d[a-1:dif]
print(sum(lis))
``` | 0 |
32 | B | Borze | PROGRAMMING | 800 | [
"expression parsing",
"implementation"
] | B. Borze | 2 | 256 | Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet. | The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes). | Output the decoded ternary number. It can have leading zeroes. | [
".-.--\n",
"--.\n",
"-..-.--\n"
] | [
"012",
"20",
"1012"
] | none | 1,000 | [
{
"input": ".-.--",
"output": "012"
},
{
"input": "--.",
"output": "20"
},
{
"input": "-..-.--",
"output": "1012"
},
{
"input": "---..",
"output": "210"
},
{
"input": "..--.---..",
"output": "0020210"
},
{
"input": "-.....----.",
"output": "1000022... | 1,674,646,019 | 2,147,483,647 | PyPy 3-64 | OK | TESTS | 30 | 124 | 0 | s=input()
a=s.replace("--","2")
b=a.replace("-.","1")
print(b.replace(".","0")) | Title: Borze
Time Limit: 2 seconds
Memory Limit: 256 megabytes
Problem Description:
Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary ... | ```python
s=input()
a=s.replace("--","2")
b=a.replace("-.","1")
print(b.replace(".","0"))
``` | 3.969 |
863 | G | Graphic Settings | PROGRAMMING | 3,200 | [] | null | null | Recently Ivan bought a new computer. Excited, he unpacked it and installed his favourite game. With his old computer Ivan had to choose the worst possible graphic settings (because otherwise the framerate would be really low), but now he wants to check, maybe his new computer can perform well even with the best possibl... | The first line of input contains one integer number *m* (1<=≤<=*m*<=≤<=6).
The second line contains *m* integer numbers *a*1,<=*a*2,<=...,<=*a**m* (2<=≤<=*a**i*<=≤<=1000). It is guaranteed that .
The third line contains *m* integer numbers *b*1,<=*b*2,<=...,<=*b**m* (1<=≤<=*b**i*<=≤<=*a**i*). | If there is a way to make exactly *p* changes (each change either decreases or increases some parameter by 1) to try all possible combinations and return to initial combination, then output Cycle in the first line. Then *p* lines must follow, each desribing a change. The line must be either inc x (increase parameter *x... | [
"1\n3\n1\n",
"1\n3\n2\n",
"2\n3 2\n1 1\n"
] | [
"Path\ninc 1\ninc 1\n",
"No\n",
"Cycle\ninc 1\ninc 1\ninc 2\ndec 1\ndec 1\ndec 2\n"
] | none | 0 | [] | 1,689,650,137 | 2,147,483,647 | PyPy 3-64 | WRONG_ANSWER | TESTS | 0 | 31 | 0 | print("_RANDOM_GUESS_1689650137.4296749")# 1689650137.429695 | Title: Graphic Settings
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Recently Ivan bought a new computer. Excited, he unpacked it and installed his favourite game. With his old computer Ivan had to choose the worst possible graphic settings (because otherwise the framerate would be real... | ```python
print("_RANDOM_GUESS_1689650137.4296749")# 1689650137.429695
``` | 0 | |
200 | B | Drinks | PROGRAMMING | 800 | [
"implementation",
"math"
] | null | null | Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i* percent.
One day Vasya decided to make himself an orange cocktail. He took equal proportio... | The first input line contains a single integer *n* (1<=≤<=*n*<=≤<=100) — the number of orange-containing drinks in Vasya's fridge. The second line contains *n* integers *p**i* (0<=≤<=*p**i*<=≤<=100) — the volume fraction of orange juice in the *i*-th drink, in percent. The numbers are separated by a space. | Print the volume fraction in percent of orange juice in Vasya's cocktail. The answer will be considered correct if the absolute or relative error does not exceed 10<=<=-<=4. | [
"3\n50 50 100\n",
"4\n0 25 50 75\n"
] | [
"66.666666666667\n",
"37.500000000000\n"
] | Note to the first sample: let's assume that Vasya takes *x* milliliters of each drink from the fridge. Then the volume of pure juice in the cocktail will equal <img align="middle" class="tex-formula" src="https://espresso.codeforces.com/c1fac6e64d3a8ee6a5ac138cbe51e60039b22473.png" style="max-width: 100.0%;max-height: ... | 500 | [
{
"input": "3\n50 50 100",
"output": "66.666666666667"
},
{
"input": "4\n0 25 50 75",
"output": "37.500000000000"
},
{
"input": "3\n0 1 8",
"output": "3.000000000000"
},
{
"input": "5\n96 89 93 95 70",
"output": "88.600000000000"
},
{
"input": "7\n62 41 78 4 38 39... | 1,694,654,764 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 30 | 0 | n=int(input())
por=map(int,input().split())
print(sum(por)/(n*100)) | Title: Drinks
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Little Vasya loves orange juice very much. That's why any food and drink in his kitchen necessarily contains orange juice. There are *n* drinks in his fridge, the volume fraction of orange juice in the *i*-th drink equals *p**i*... | ```python
n=int(input())
por=map(int,input().split())
print(sum(por)/(n*100))
``` | 0 | |
629 | B | Far Relative’s Problem | PROGRAMMING | 1,100 | [
"brute force"
] | null | null | Famil Door wants to celebrate his birthday with his friends from Far Far Away. He has *n* friends and each of them can come to the party in a specific range of days of the year from *a**i* to *b**i*. Of course, Famil Door wants to have as many friends celebrating together with him as possible.
Far cars are as weird as... | The first line of the input contains a single integer *n* (1<=≤<=*n*<=≤<=5000) — then number of Famil Door's friends.
Then follow *n* lines, that describe the friends. Each line starts with a capital letter 'F' for female friends and with a capital letter 'M' for male friends. Then follow two integers *a**i* and *b**i... | Print the maximum number of people that may come to Famil Door's party. | [
"4\nM 151 307\nF 343 352\nF 117 145\nM 24 128\n",
"6\nM 128 130\nF 128 131\nF 131 140\nF 131 141\nM 131 200\nM 140 200\n"
] | [
"2\n",
"4\n"
] | In the first sample, friends 3 and 4 can come on any day in range [117, 128].
In the second sample, friends with indices 3, 4, 5 and 6 can come on day 140. | 1,000 | [
{
"input": "4\nM 151 307\nF 343 352\nF 117 145\nM 24 128",
"output": "2"
},
{
"input": "6\nM 128 130\nF 128 131\nF 131 140\nF 131 141\nM 131 200\nM 140 200",
"output": "4"
},
{
"input": "1\nF 68 307",
"output": "0"
},
{
"input": "40\nM 55 363\nF 117 252\nM 157 282\nF 322 345\... | 1,684,852,721 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 0 | 31 | 921,600 | n = int(input())
male_days = [0] * 367
female_days = [0] * 367
for _ in range(n):
gender, start, end = input().split()
start = int(start)
end = int(end)
if gender == 'M':
male_days[start] += 1
male_days[end + 1] -= 1
else:
female_days[start] += 1
female_days[end... | Title: Far Relative’s Problem
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Famil Door wants to celebrate his birthday with his friends from Far Far Away. He has *n* friends and each of them can come to the party in a specific range of days of the year from *a**i* to *b**i*. Of course, F... | ```python
n = int(input())
male_days = [0] * 367
female_days = [0] * 367
for _ in range(n):
gender, start, end = input().split()
start = int(start)
end = int(end)
if gender == 'M':
male_days[start] += 1
male_days[end + 1] -= 1
else:
female_days[start] += 1
femal... | 0 | |
750 | A | New Year and Hurry | PROGRAMMING | 800 | [
"binary search",
"brute force",
"implementation",
"math"
] | null | null | Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem 1 is the easiest and problem *n* is the hardest. Limak knows it will take him 5·*i* minutes to solve th... | The only line of the input contains two integers *n* and *k* (1<=≤<=*n*<=≤<=10, 1<=≤<=*k*<=≤<=240) — the number of the problems in the contest and the number of minutes Limak needs to get to the party from his house. | Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier. | [
"3 222\n",
"4 190\n",
"7 1\n"
] | [
"2\n",
"4\n",
"7\n"
] | In the first sample, there are 3 problems and Limak needs 222 minutes to get to the party. The three problems require 5, 10 and 15 minutes respectively. Limak can spend 5 + 10 = 15 minutes to solve first two problems. Then, at 20:15 he can leave his house to get to the party at 23:57 (after 222 minutes). In this scenar... | 500 | [
{
"input": "3 222",
"output": "2"
},
{
"input": "4 190",
"output": "4"
},
{
"input": "7 1",
"output": "7"
},
{
"input": "10 135",
"output": "6"
},
{
"input": "10 136",
"output": "5"
},
{
"input": "1 1",
"output": "1"
},
{
"input": "1 240",
... | 1,675,095,920 | 2,147,483,647 | PyPy 3 | COMPILATION_ERROR | TESTS | 0 | 0 | 0 | import bisect
n,k = input().split()
n = int(n)
k = int(k)
arr = []
prev = 0
for i in range(1,n+1):
prev+= 5*i
arr.append(prev)
return bisect.bisect(arr, 240-k) | Title: New Year and Hurry
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. There will be *n* problems, sorted by difficulty, i.e. problem... | ```python
import bisect
n,k = input().split()
n = int(n)
k = int(k)
arr = []
prev = 0
for i in range(1,n+1):
prev+= 5*i
arr.append(prev)
return bisect.bisect(arr, 240-k)
``` | -1 | |
863 | C | 1-2-3 | PROGRAMMING | 1,800 | [
"graphs",
"implementation"
] | null | null | Ilya is working for the company that constructs robots. Ilya writes programs for entertainment robots, and his current project is "Bob", a new-generation game robot. Ilya's boss wants to know his progress so far. Especially he is interested if Bob is better at playing different games than the previous model, "Alice".
... | The first line contains three numbers *k*, *a*, *b* (1<=≤<=*k*<=≤<=1018, 1<=≤<=*a*,<=*b*<=≤<=3).
Then 3 lines follow, *i*-th of them containing 3 numbers *A**i*,<=1, *A**i*,<=2, *A**i*,<=3, where *A**i*,<=*j* represents Alice's choice in the game if Alice chose *i* in previous game and Bob chose *j* (1<=≤<=*A**i*,<=*... | Print two numbers. First of them has to be equal to the number of points Alice will have, and second of them must be Bob's score after *k* games. | [
"10 2 1\n1 1 1\n1 1 1\n1 1 1\n2 2 2\n2 2 2\n2 2 2\n",
"8 1 1\n2 2 1\n3 3 1\n3 1 3\n1 1 1\n2 1 1\n1 2 3\n",
"5 1 1\n1 2 2\n2 2 2\n2 2 2\n1 2 2\n2 2 2\n2 2 2\n"
] | [
"1 9\n",
"5 2\n",
"0 0\n"
] | In the second example game goes like this:
<img align="middle" class="tex-formula" src="https://espresso.codeforces.com/1e21b6e200707470571d69c9946ace6b56f5279b.png" style="max-width: 100.0%;max-height: 100.0%;"/>
The fourth and the seventh game are won by Bob, the first game is draw and the rest are won by Alice. | 0 | [
{
"input": "10 2 1\n1 1 1\n1 1 1\n1 1 1\n2 2 2\n2 2 2\n2 2 2",
"output": "1 9"
},
{
"input": "8 1 1\n2 2 1\n3 3 1\n3 1 3\n1 1 1\n2 1 1\n1 2 3",
"output": "5 2"
},
{
"input": "5 1 1\n1 2 2\n2 2 2\n2 2 2\n1 2 2\n2 2 2\n2 2 2",
"output": "0 0"
},
{
"input": "1 1 1\n3 3 1\n1 1 1\... | 1,655,717,166 | 2,147,483,647 | PyPy 3 | OK | TESTS | 31 | 77 | 0 | k,a,b = map(int, input().split())
A = []
for i in range(3):
l = list(map(int, input().split()))
l = [a-1 for a in l]
A.append(l)
B = []
for i in range(3):
l = list(map(int, input().split()))
l = [b-1 for b in l]
B.append(l)
a -= 1
b -= 1
def calc(x, y):
if x == 2:
... | Title: 1-2-3
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
Ilya is working for the company that constructs robots. Ilya writes programs for entertainment robots, and his current project is "Bob", a new-generation game robot. Ilya's boss wants to know his progress so far. Especially he is... | ```python
k,a,b = map(int, input().split())
A = []
for i in range(3):
l = list(map(int, input().split()))
l = [a-1 for a in l]
A.append(l)
B = []
for i in range(3):
l = list(map(int, input().split()))
l = [b-1 for b in l]
B.append(l)
a -= 1
b -= 1
def calc(x, y):
if x =... | 3 | |
708 | A | Letters Cyclic Shift | PROGRAMMING | 1,200 | [
"constructive algorithms",
"greedy",
"implementation",
"strings"
] | null | null | You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each character is replaced with the previous character of English alphabet and 'a' is replaced with 'z'.
What is ... | The only line of the input contains the string *s* (1<=≤<=|*s*|<=≤<=100<=000) consisting of lowercase English letters. | Print the lexicographically minimum string that can be obtained from *s* by shifting letters of exactly one non-empty substring. | [
"codeforces\n",
"abacaba\n"
] | [
"bncdenqbdr\n",
"aaacaba\n"
] | String *s* is lexicographically smaller than some other string *t* of the same length if there exists some 1 ≤ *i* ≤ |*s*|, such that *s*<sub class="lower-index">1</sub> = *t*<sub class="lower-index">1</sub>, *s*<sub class="lower-index">2</sub> = *t*<sub class="lower-index">2</sub>, ..., *s*<sub class="lower-index">*i*... | 500 | [
{
"input": "codeforces",
"output": "bncdenqbdr"
},
{
"input": "abacaba",
"output": "aaacaba"
},
{
"input": "babbbabaababbaa",
"output": "aabbbabaababbaa"
},
{
"input": "bcbacaabcababaccccaaaabacbbcbbaa",
"output": "abaacaabcababaccccaaaabacbbcbbaa"
},
{
"input": "... | 1,490,469,290 | 2,147,483,647 | Python 3 | WRONG_ANSWER | TESTS | 3 | 62 | 4,608,000 | S=input().split('a')
ma=100000000000000
R='abcdefghijklmnopqrstuvwxyz'
for x in S :
if ma>len(x) and len(x)>0 :
ma=len(x)
S1=''
c=1
p=len(S)
for x in S :
if len(x)==ma and c==1 :
c=0
for i in range(len(x)) :
S1=S1+R[R.index(x[i])-1]
else :
S1=S1+x
... | Title: Letters Cyclic Shift
Time Limit: None seconds
Memory Limit: None megabytes
Problem Description:
You are given a non-empty string *s* consisting of lowercase English letters. You have to pick exactly one non-empty substring of *s* and shift all its letters 'z' 'y' 'x' 'b' 'a' 'z'. In other words, each cha... | ```python
S=input().split('a')
ma=100000000000000
R='abcdefghijklmnopqrstuvwxyz'
for x in S :
if ma>len(x) and len(x)>0 :
ma=len(x)
S1=''
c=1
p=len(S)
for x in S :
if len(x)==ma and c==1 :
c=0
for i in range(len(x)) :
S1=S1+R[R.index(x[i])-1]
else :
... | 0 |
Subsets and Splits
Successful Python Submissions
Retrieves all records from the train dataset where the verdict is 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Retrieves records of users with a rating of 1600 or higher and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a rating above 2000 and a verdict of 'OK', providing basic filtering but limited analytical value.
SQL Console for MatrixStudio/Codeforces-Python-Submissions
Counts the number of entries with a 'OK' verdict, providing a basic overview of a specific category within the dataset.