db_id stringclasses 40
values | query stringlengths 22 608 | question stringlengths 22 185 |
|---|---|---|
real_estate_rentals | SELECT DISTINCT T1.county_state_province FROM Addresses AS T1 JOIN Properties AS T2 ON T1.address_id = T2.property_address_id; | In which states are each of the the properties located? |
real_estate_rentals | SELECT DISTINCT T1.county_state_province FROM Addresses AS T1 JOIN Properties AS T2 ON T1.address_id = T2.property_address_id; | Give the states or provinces corresponding to each property. |
real_estate_rentals | SELECT feature_description FROM Features WHERE feature_name = 'rooftop'; | How is the feature rooftop described? |
real_estate_rentals | SELECT feature_description FROM Features WHERE feature_name = 'rooftop'; | Return the description of the feature 'rooftop'. |
real_estate_rentals | SELECT T1.feature_name , T1.feature_description FROM Features AS T1 JOIN Property_Features AS T2 ON T1.feature_id = T2.feature_id GROUP BY T1.feature_name ORDER BY count(*) DESC LIMIT 1; | What are the feature name and description of the most commonly seen feature across properties? |
real_estate_rentals | SELECT T1.feature_name , T1.feature_description FROM Features AS T1 JOIN Property_Features AS T2 ON T1.feature_id = T2.feature_id GROUP BY T1.feature_name ORDER BY count(*) DESC LIMIT 1; | Give the feature name and description for the most common feature across all properties. |
real_estate_rentals | SELECT min(room_count) FROM Properties; | What is the minimum number of rooms in a property? |
real_estate_rentals | SELECT min(room_count) FROM Properties; | What is the lowest room count across all the properties? |
real_estate_rentals | SELECT count(*) FROM Properties WHERE parking_lots = 1 OR garage_yn = 1; | How many properties have 1 parking lot or 1 garage? |
real_estate_rentals | SELECT count(*) FROM Properties WHERE parking_lots = 1 OR garage_yn = 1; | Count the number of properties that have 1 parking lot or 1 garage. |
real_estate_rentals | SELECT T2.age_category_code FROM Ref_User_Categories AS T1 JOIN Users AS T2 ON T1.user_category_code = T2.user_category_code WHERE T1.User_category_description LIKE "%Mother"; | For users whose description contain the string 'Mother', which age categories are they in? |
real_estate_rentals | SELECT T2.age_category_code FROM Ref_User_Categories AS T1 JOIN Users AS T2 ON T1.user_category_code = T2.user_category_code WHERE T1.User_category_description LIKE "%Mother"; | What are the age categories for users whose description contains the string Mother? |
real_estate_rentals | SELECT T1.first_name FROM Users AS T1 JOIN Properties AS T2 ON T2.owner_user_id = T1.User_id GROUP BY T1.User_id ORDER BY count(*) DESC LIMIT 1; | What is the first name of the user who owns the greatest number of properties? |
real_estate_rentals | SELECT T1.first_name FROM Users AS T1 JOIN Properties AS T2 ON T2.owner_user_id = T1.User_id GROUP BY T1.User_id ORDER BY count(*) DESC LIMIT 1; | Return the first name of the user who owns the most properties. |
real_estate_rentals | SELECT avg(T3.room_count) FROM Property_Features AS T1 JOIN Features AS T2 ON T1.feature_id = T2.feature_id JOIN Properties AS T3 ON T1.property_id = T3.property_id WHERE T2.feature_name = 'garden'; | List the average room count of the properties with gardens. |
real_estate_rentals | SELECT avg(T3.room_count) FROM Property_Features AS T1 JOIN Features AS T2 ON T1.feature_id = T2.feature_id JOIN Properties AS T3 ON T1.property_id = T3.property_id WHERE T2.feature_name = 'garden'; | On average, how many rooms do properties with garden features have? |
real_estate_rentals | SELECT T2.town_city FROM Properties AS T1 JOIN Addresses AS T2 ON T1.property_address_id = T2.address_id JOIN Property_Features AS T3 ON T1.property_id = T3.property_id JOIN Features AS T4 ON T4.feature_id = T3.feature_id WHERE T4.feature_name = 'swimming pool'; | In which cities are there any properties equipped with a swimming pool? |
real_estate_rentals | SELECT T2.town_city FROM Properties AS T1 JOIN Addresses AS T2 ON T1.property_address_id = T2.address_id JOIN Property_Features AS T3 ON T1.property_id = T3.property_id JOIN Features AS T4 ON T4.feature_id = T3.feature_id WHERE T4.feature_name = 'swimming pool'; | Return the cities in which there exist properties that have swimming pools. |
real_estate_rentals | SELECT property_id , vendor_requested_price FROM Properties ORDER BY vendor_requested_price LIMIT 1; | Which property had the lowest price requested by the vendor? List the id and the price. |
real_estate_rentals | SELECT property_id , vendor_requested_price FROM Properties ORDER BY vendor_requested_price LIMIT 1; | What is the id of the property that had the lowest requested price from the vendor, and what was that price? |
real_estate_rentals | SELECT avg(room_count) FROM Properties; | On average, how many rooms does a property have? |
real_estate_rentals | SELECT avg(room_count) FROM Properties; | What is the average number of rooms in a property? |
real_estate_rentals | SELECT count(DISTINCT room_size) FROM Rooms; | How many kinds of room sizes are listed? |
real_estate_rentals | SELECT count(DISTINCT room_size) FROM Rooms; | Return the number of different room sizes. |
real_estate_rentals | SELECT search_seq , user_id FROM User_Searches GROUP BY user_id HAVING count(*) >= 2; | What are the ids of users who have searched at least twice, and what did they search? |
real_estate_rentals | SELECT search_seq , user_id FROM User_Searches GROUP BY user_id HAVING count(*) >= 2; | Return the ids of users who have performed two or more searches, as well as their search sequence. |
real_estate_rentals | SELECT max(search_datetime) FROM User_Searches; | When was the time of the latest search by a user? |
real_estate_rentals | SELECT max(search_datetime) FROM User_Searches; | What was the time of the most recent search? |
real_estate_rentals | SELECT search_datetime , search_string FROM User_Searches ORDER BY search_string DESC; | What are all the user searches time and content? Sort the result descending by content. |
real_estate_rentals | SELECT search_datetime , search_string FROM User_Searches ORDER BY search_string DESC; | Return the search strings and corresonding time stamps for all user searches, sorted by search string descending. |
real_estate_rentals | SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Properties AS T2 ON T1.address_id = T2.property_address_id WHERE T2.owner_user_id NOT IN ( SELECT owner_user_id FROM Properties GROUP BY owner_user_id HAVING count(*) <= 2 ); | What are the zip codes of properties which do not belong to users who own at most 2 properties? |
real_estate_rentals | SELECT T1.zip_postcode FROM Addresses AS T1 JOIN Properties AS T2 ON T1.address_id = T2.property_address_id WHERE T2.owner_user_id NOT IN ( SELECT owner_user_id FROM Properties GROUP BY owner_user_id HAVING count(*) <= 2 ); | Return the zip codes for properties not belonging to users who own two or fewer properties. |
real_estate_rentals | SELECT T1.user_category_code , T1.user_id FROM Users AS T1 JOIN User_Searches AS T2 ON T1.user_id = T2.user_id GROUP BY T1.user_id HAVING count(*) = 1; | What are the users making only one search? List both category and user id. |
real_estate_rentals | SELECT T1.user_category_code , T1.user_id FROM Users AS T1 JOIN User_Searches AS T2 ON T1.user_id = T2.user_id GROUP BY T1.user_id HAVING count(*) = 1; | What are the ids of users who have only made one search, and what are their category codes? |
real_estate_rentals | SELECT T1.age_category_code FROM Users AS T1 JOIN User_Searches AS T2 ON T1.user_id = T2.user_id ORDER BY T2.search_datetime LIMIT 1; | What is the age range category of the user who made the first search? |
real_estate_rentals | SELECT T1.age_category_code FROM Users AS T1 JOIN User_Searches AS T2 ON T1.user_id = T2.user_id ORDER BY T2.search_datetime LIMIT 1; | Return the age category for the user who made the earliest search. |
real_estate_rentals | SELECT login_name FROM Users WHERE user_category_code = 'Senior Citizen' ORDER BY first_name | Find the login names of all senior citizen users ordered by their first names. |
real_estate_rentals | SELECT login_name FROM Users WHERE user_category_code = 'Senior Citizen' ORDER BY first_name | What are the login names of all senior citizens, sorted by first name? |
real_estate_rentals | SELECT count(*) FROM Users AS T1 JOIN User_Searches AS T2 ON T1.user_id = T2.user_id WHERE T1.is_buyer = 1; | How many searches do buyers make in total? |
real_estate_rentals | SELECT count(*) FROM Users AS T1 JOIN User_Searches AS T2 ON T1.user_id = T2.user_id WHERE T1.is_buyer = 1; | Count the number of searches made by buyers. |
real_estate_rentals | SELECT date_registered FROM Users WHERE login_name = 'ratione'; | When did the user with login name ratione register? |
real_estate_rentals | SELECT date_registered FROM Users WHERE login_name = 'ratione'; | What was the registration date for the user whose login name is ratione? |
real_estate_rentals | SELECT first_name , middle_name , last_name , login_name FROM Users WHERE is_seller = 1; | List the first name, middle name and last name, and log in name of all the seller users, whose seller value is 1. |
real_estate_rentals | SELECT first_name , middle_name , last_name , login_name FROM Users WHERE is_seller = 1; | What are the first, middle, last, and login names for all users who are sellers? |
real_estate_rentals | SELECT T1.line_1_number_building , T1.line_2_number_street , T1.town_city FROM Addresses AS T1 JOIN Users AS T2 ON T1.address_id = T2.user_address_id WHERE T2.user_category_code = 'Senior Citizen'; | Where do the Senior Citizens live? List building, street, and the city. |
real_estate_rentals | SELECT T1.line_1_number_building , T1.line_2_number_street , T1.town_city FROM Addresses AS T1 JOIN Users AS T2 ON T1.address_id = T2.user_address_id WHERE T2.user_category_code = 'Senior Citizen'; | What are the buildings, streets, and cities corresponding to the addresses of senior citizens? |
real_estate_rentals | SELECT count(*) FROM Properties GROUP BY property_id HAVING count(*) >= 2; | How many properties are there with at least 2 features? |
real_estate_rentals | SELECT count(*) FROM Properties GROUP BY property_id HAVING count(*) >= 2; | Count the number of properties with at least two features. |
real_estate_rentals | SELECT count(*) , property_id FROM Property_Photos GROUP BY property_id; | How many photos does each property have? |
real_estate_rentals | SELECT count(*) , property_id FROM Property_Photos GROUP BY property_id; | Count the number of property photos each property has by id. |
real_estate_rentals | SELECT T1.owner_user_id , count(*) FROM Properties AS T1 JOIN Property_Photos AS T2 ON T1.property_id = T2.property_id GROUP BY T1.owner_user_id; | How many photos does each owner has of his or her properties? List user id and number of photos. |
real_estate_rentals | SELECT T1.owner_user_id , count(*) FROM Properties AS T1 JOIN Property_Photos AS T2 ON T1.property_id = T2.property_id GROUP BY T1.owner_user_id; | What are the user ids of property owners who have property photos, and how many do each of them have? |
real_estate_rentals | SELECT sum(T1.price_max) FROM Properties AS T1 JOIN Users AS T2 ON T1.owner_user_id = T2.user_id WHERE T2.user_category_code = 'Single Mother' OR T2.user_category_code = 'Student'; | What is the total max price of the properties owned by single mothers or students? |
real_estate_rentals | SELECT sum(T1.price_max) FROM Properties AS T1 JOIN Users AS T2 ON T1.owner_user_id = T2.user_id WHERE T2.user_category_code = 'Single Mother' OR T2.user_category_code = 'Student'; | Give the total max price corresponding to any properties owned by single mothers or students. |
real_estate_rentals | SELECT T1.datestamp , T2.property_name FROM User_Property_History AS T1 JOIN Properties AS T2 ON T1.property_id = T2.property_id ORDER BY datestamp; | What are the date stamps and property names for each item of property history, ordered by date stamp? |
real_estate_rentals | SELECT T1.datestamp , T2.property_name FROM User_Property_History AS T1 JOIN Properties AS T2 ON T1.property_id = T2.property_id ORDER BY datestamp; | Return the date stamp and property name for each property history event, sorted by date stamp. |
real_estate_rentals | SELECT T1.property_type_description , T1.property_type_code FROM Ref_Property_Types AS T1 JOIN Properties AS T2 ON T1.property_type_code = T2.property_type_code GROUP BY T1.property_type_code ORDER BY count(*) DESC LIMIT 1; | What is the description of the most common property type? List the description and code. |
real_estate_rentals | SELECT T1.property_type_description , T1.property_type_code FROM Ref_Property_Types AS T1 JOIN Properties AS T2 ON T1.property_type_code = T2.property_type_code GROUP BY T1.property_type_code ORDER BY count(*) DESC LIMIT 1; | What is the most common property type, and what is its description. |
real_estate_rentals | SELECT age_category_description FROM Ref_Age_Categories WHERE age_category_code = 'Over 60'; | What is the detailed description of the age category code 'Over 60'? |
real_estate_rentals | SELECT age_category_description FROM Ref_Age_Categories WHERE age_category_code = 'Over 60'; | Give the category description of the age category 'Over 60'. |
real_estate_rentals | SELECT room_size , count(*) FROM Rooms GROUP BY room_size | What are the different room sizes, and how many of each are there? |
real_estate_rentals | SELECT room_size , count(*) FROM Rooms GROUP BY room_size | Return the number of rooms with each different room size. |
real_estate_rentals | SELECT T1.country FROM Addresses AS T1 JOIN Users AS T2 ON T1.address_id = T2.user_address_id WHERE T2.first_name = 'Robbie'; | In which country does the user with first name Robbie live? |
real_estate_rentals | SELECT T1.country FROM Addresses AS T1 JOIN Users AS T2 ON T1.address_id = T2.user_address_id WHERE T2.first_name = 'Robbie'; | Return the country in which the user with first name Robbie lives. |
real_estate_rentals | SELECT first_name , middle_name , last_name FROM Properties AS T1 JOIN Users AS T2 ON T1.owner_user_id = T2.user_id WHERE T1.property_address_id = T2.user_address_id; | What are the first, middle and last names of users who own the property they live in? |
real_estate_rentals | SELECT first_name , middle_name , last_name FROM Properties AS T1 JOIN Users AS T2 ON T1.owner_user_id = T2.user_id WHERE T1.property_address_id = T2.user_address_id; | Return the full names of users who live in properties that they own. |
real_estate_rentals | SELECT search_string FROM User_Searches EXCEPT SELECT T1.search_string FROM User_Searches AS T1 JOIN Properties AS T2 ON T1.user_id = T2.owner_user_id; | List the search content of the users who do not own a single property. |
real_estate_rentals | SELECT search_string FROM User_Searches EXCEPT SELECT T1.search_string FROM User_Searches AS T1 JOIN Properties AS T2 ON T1.user_id = T2.owner_user_id; | What search strings were entered by users who do not own any properties? |
real_estate_rentals | SELECT T1.last_name , T1.user_id FROM Users AS T1 JOIN User_Searches AS T2 ON T1.user_id = T2.user_id GROUP BY T1.user_id HAVING count(*) <= 2 INTERSECT SELECT T3.last_name , T3.user_id FROM Users AS T3 JOIN Properties AS T4 ON T3.user_id = T4.owner_user_id GROUP BY T3.user_id HAVING count(*) >= 2; | List the last names and ids of users who have at least 2 properties and searched at most twice. |
real_estate_rentals | SELECT T1.last_name , T1.user_id FROM Users AS T1 JOIN User_Searches AS T2 ON T1.user_id = T2.user_id GROUP BY T1.user_id HAVING count(*) <= 2 INTERSECT SELECT T3.last_name , T3.user_id FROM Users AS T3 JOIN Properties AS T4 ON T3.user_id = T4.owner_user_id GROUP BY T3.user_id HAVING count(*) >= 2; | What are the last names and ids of users who have searched two or fewer times, and own two or more properties? |
bike_racing | SELECT count(*) FROM bike WHERE weight > 780 | How many bikes are heavier than 780 grams? |
bike_racing | SELECT product_name , weight FROM bike ORDER BY price ASC | List the product names and weights of the bikes in ascending order of price. |
bike_racing | SELECT heat , name , nation FROM cyclist | List the heat, name, and nation for all the cyclists. |
bike_racing | SELECT max(weight) , min(weight) FROM bike | What are the maximum and minimum weight of all bikes? |
bike_racing | SELECT avg(price) FROM bike WHERE material = 'Carbon CC' | What is the average price of the bikes made of material 'Carbon CC'? |
bike_racing | SELECT name , RESULT FROM cyclist WHERE nation != 'Russia' | What are the name and result of the cyclists not from 'Russia' ? |
bike_racing | SELECT DISTINCT T1.id , T1.product_name FROM bike AS T1 JOIN cyclists_own_bikes AS T2 ON T1.id = T2.bike_id WHERE T2.purchase_year > 2015 | What are the distinct ids and product names of the bikes that are purchased after year 2015? |
bike_racing | SELECT T1.id , T1.product_name FROM bike AS T1 JOIN cyclists_own_bikes AS T2 ON T1.id = T2.bike_id GROUP BY T1.id HAVING count(*) >= 4 | What are the ids and names of racing bikes that are purchased by at least 4 cyclists? |
bike_racing | SELECT T1.id , T1.name FROM cyclist AS T1 JOIN cyclists_own_bikes AS T2 ON T1.id = T2.cyclist_id GROUP BY T1.id ORDER BY count(*) DESC LIMIT 1 | What are the id and name of the cyclist who owns the most bikes? |
bike_racing | SELECT DISTINCT T3.product_name FROM cyclist AS T1 JOIN cyclists_own_bikes AS T2 ON T1.id = T2.cyclist_id JOIN bike AS T3 ON T2.bike_id = T3.id WHERE T1.nation = 'Russia' OR T1.nation = 'Great Britain' | What are the distinct product names of bikes owned by cyclists from 'Russia' or cyclists from 'Great Britain'? |
bike_racing | SELECT count(DISTINCT heat) FROM cyclist | How many different levels of heat are there for the cyclists? |
bike_racing | SELECT count(*) FROM cyclist WHERE id NOT IN ( SELECT cyclist_id FROM cyclists_own_bikes WHERE purchase_year > 2015 ) | How many cyclists did not purchase any bike after year 2015? |
bike_racing | SELECT DISTINCT T3.product_name FROM cyclist AS T1 JOIN cyclists_own_bikes AS T2 ON T1.id = T2.cyclist_id JOIN bike AS T3 ON T2.bike_id = T3.id WHERE T1.result < '4:21.558' | What are the names of distinct racing bikes that are purchased by the cyclists with better results than '4:21.558' ? |
bike_racing | SELECT T3.product_name , T3.price FROM cyclist AS T1 JOIN cyclists_own_bikes AS T2 ON T1.id = T2.cyclist_id JOIN bike AS T3 ON T2.bike_id = T3.id WHERE T1.name = 'Bradley Wiggins' INTERSECT SELECT T3.product_name , T3.price FROM cyclist AS T1 JOIN cyclists_own_bikes AS T2 ON T1.id = T2.cyclist_id JOIN bike AS... | List the name and price of the bike that is owned by both the cyclists named 'Bradley Wiggins' and the cyclist named 'Antonio Tauler'. |
bike_racing | SELECT name , nation , RESULT FROM cyclist EXCEPT SELECT T1.name , T1.nation , T1.result FROM cyclist AS T1 JOIN cyclists_own_bikes AS T2 ON T1.id = T2.cyclist_id | Show the name, nation and result for the cyclists who did not purchase any racing bike. |
bike_racing | SELECT product_name FROM bike WHERE material LIKE "%fiber%" | What are the names of the bikes that have substring 'fiber' in their material? |
bike_racing | SELECT cyclist_id , count(*) FROM cyclists_own_bikes GROUP BY cyclist_id ORDER BY cyclist_id | How many bikes does each cyclist own? Order by cyclist id. |
bakery_1 | SELECT id , flavor FROM goods WHERE food = "Cake" ORDER BY price DESC LIMIT 1 | What is the most expensive cake and its flavor? |
bakery_1 | SELECT id , flavor FROM goods WHERE food = "Cake" ORDER BY price DESC LIMIT 1 | Give the id and flavor of the most expensive cake. |
bakery_1 | SELECT id , flavor FROM goods WHERE food = "Cookie" ORDER BY price LIMIT 1 | What is the cheapest cookie and its flavor? |
bakery_1 | SELECT id , flavor FROM goods WHERE food = "Cookie" ORDER BY price LIMIT 1 | What is the id and flavor of the cheapest cookie? |
bakery_1 | SELECT id FROM goods WHERE flavor = "Apple" | Find the ids of goods that have apple flavor. |
bakery_1 | SELECT id FROM goods WHERE flavor = "Apple" | What are the ids with apple flavor? |
bakery_1 | SELECT id FROM goods WHERE price < 3 | What are the ids of goods that cost less than 3 dollars? |
bakery_1 | SELECT id FROM goods WHERE price < 3 | Give the ids of goods that cost less than 3 dollars. |
bakery_1 | SELECT DISTINCT T3.CustomerId FROM goods AS T1 JOIN items AS T2 ON T1.Id = T2.Item JOIN receipts AS T3 ON T2.Receipt = T3.ReceiptNumber WHERE T1.Flavor = "Lemon" AND T1.Food = "Cake" | List the distinct ids of all customers who bought a cake with lemon flavor? |
bakery_1 | SELECT DISTINCT T3.CustomerId FROM goods AS T1 JOIN items AS T2 ON T1.Id = T2.Item JOIN receipts AS T3 ON T2.Receipt = T3.ReceiptNumber WHERE T1.Flavor = "Lemon" AND T1.Food = "Cake" | What are the distinct ids of customers who bought lemon flavored cake? |
bakery_1 | SELECT T1.food , count(DISTINCT T3.CustomerId) FROM goods AS T1 JOIN items AS T2 ON T1.Id = T2.Item JOIN receipts AS T3 ON T2.Receipt = T3.ReceiptNumber GROUP BY T1.food | For each type of food, tell me how many customers have ever bought it. |
bakery_1 | SELECT T1.food , count(DISTINCT T3.CustomerId) FROM goods AS T1 JOIN items AS T2 ON T1.Id = T2.Item JOIN receipts AS T3 ON T2.Receipt = T3.ReceiptNumber GROUP BY T1.food | How many customers have bought each food? |
bakery_1 | SELECT CustomerId FROM receipts GROUP BY CustomerId HAVING count(*) >= 15 | Find the id of customers who shopped at the bakery at least 15 times. |
Subsets and Splits
World Countries Non-English Languages
The query filters specific database entries based on a particular query pattern, providing limited insight as it simply retrieves rows that match a specific condition.