db_id stringclasses 40
values | query stringlengths 22 608 | question stringlengths 22 185 |
|---|---|---|
book_press | select name from author where author_id not in (select author_id from book) | Which authors in the record have not published any books ? Give me their names . |
book_press | SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id GROUP BY t2.author_id HAVING count(*) > 1 | Find the names of authors who have more than one book in the database. |
book_press | SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id GROUP BY t2.author_id HAVING count(*) > 1 | Which authors have published more than 1 book according to the database? Give me their names. |
book_press | SELECT t1.name , t2.title , t3.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id JOIN press AS t3 ON t2.press_id = t3.press_id ORDER BY t2.sale_amount DESC LIMIT 3 | Find the title, author name, and publisher name for the top 3 best sales books. |
book_press | SELECT t1.name , t2.title , t3.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id JOIN press AS t3 ON t2.press_id = t3.press_id ORDER BY t2.sale_amount DESC LIMIT 3 | What are the 3 best selling books? Show their titles, author names, and press names. |
book_press | SELECT sum(t1.sale_amount) , t2.name FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id GROUP BY t1.press_id | Find the name and total book sale amount of each press. |
book_press | SELECT sum(t1.sale_amount) , t2.name FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id GROUP BY t1.press_id | What are the name and total book sale amount of each press? |
book_press | SELECT count(*) , t2.name FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id WHERE sale_amount > 1000 GROUP BY t2.name | Find the number of books that are sold more than 1000 for each publisher. List the press name as well. |
book_press | SELECT count(*) , t2.name FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id WHERE sale_amount > 1000 GROUP BY t2.name | For each press, return its name and the number of books that have sale amount above 1000. |
book_press | SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id ORDER BY t2.sale_amount DESC LIMIT 1 | What is the name of the author of best selling book? |
book_press | SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id ORDER BY t2.sale_amount DESC LIMIT 1 | Who wrote the best selling book? Give me the author name. |
book_press | SELECT t1.name , t1.gender FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id GROUP BY t2.author_id ORDER BY count(*) DESC LIMIT 1 | find the name and gender of the author who published the most books. |
book_press | SELECT t1.name , t1.gender FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id GROUP BY t2.author_id ORDER BY count(*) DESC LIMIT 1 | Who wrote the largest number of books? Give me the author name and gender. |
book_press | SELECT name FROM author EXCEPT SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id JOIN press AS t3 ON t2.press_id = t3.press_id WHERE t3.name = 'Accor' | Find the names of the authors who did not have any book with the "Accor" press. |
book_press | SELECT name FROM author EXCEPT SELECT t1.name FROM author AS t1 JOIN book AS t2 ON t1.author_id = t2.author_id JOIN press AS t3 ON t2.press_id = t3.press_id WHERE t3.name = 'Accor' | Which authors have never published under the "Accor" press? Give me their names. |
book_press | SELECT t2.name , t2.Year_Profits_billion FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id GROUP BY t2.press_id HAVING count(*) > 2 | Find the name and the yearly profit in billion for press that published more than two books. |
book_press | SELECT t2.name , t2.Year_Profits_billion FROM book AS t1 JOIN press AS t2 ON t1.press_id = t2.press_id GROUP BY t2.press_id HAVING count(*) > 2 | Find the press that published more than two books, and return its name and yearly profit in billion. |
cre_Doc_Workflow | SELECT count(*) FROM Authors | How many authors do we have? |
cre_Doc_Workflow | SELECT author_name FROM Authors | Show all author names. |
cre_Doc_Workflow | SELECT author_name , other_details FROM Authors | Show the names and other details for all authors. |
cre_Doc_Workflow | SELECT other_details FROM Authors WHERE author_name = "Addison Denesik" | Show the other details for the author Addison Denesik. |
cre_Doc_Workflow | SELECT count(*) FROM Documents | Show the number of documents. |
cre_Doc_Workflow | SELECT author_name FROM Documents WHERE document_id = 4 | Who is the author of the document with id 4? |
cre_Doc_Workflow | SELECT author_name FROM Documents WHERE document_name = "Travel to Brazil" | Who is the author of the document "Travel to Brazil"? |
cre_Doc_Workflow | SELECT count(*) FROM Documents WHERE author_name = "Era Kerluke" | How many documents does has the author Era Kerluke written? |
cre_Doc_Workflow | SELECT document_name , document_description FROM Documents | Show the names and descriptions for all documents. |
cre_Doc_Workflow | SELECT document_id , document_name FROM Documents WHERE author_name = "Bianka Cummings" | Show the ids and names for all documents by author Bianka Cummings. |
cre_Doc_Workflow | SELECT T2.author_name , T2.other_details FROM Documents AS T1 JOIN Authors AS T2 ON T1.author_name = T2.author_name WHERE document_name = "Travel to China" | Show the author name and details for the document "Travel to China". |
cre_Doc_Workflow | SELECT author_name , count(*) FROM Documents GROUP BY author_name | Show all author names and number of documents corresponding to each. |
cre_Doc_Workflow | SELECT author_name FROM Documents GROUP BY author_name ORDER BY count(*) DESC LIMIT 1 | What is the name of the author with most number of documents? |
cre_Doc_Workflow | SELECT author_name FROM Documents GROUP BY author_name HAVING count(*) >= 2 | Show the names for authors with at least two documents. |
cre_Doc_Workflow | SELECT count(*) FROM Business_processes | How many business processes do we have? |
cre_Doc_Workflow | SELECT next_process_id , process_name , process_description FROM Business_processes WHERE process_id = 9 | Show the next process id, process name, process description for process with id 9. |
cre_Doc_Workflow | SELECT process_name FROM Business_processes WHERE process_id = (SELECT next_process_id FROM Business_processes WHERE process_id = 9) | What is the process name for the next process of the process with id 9? |
cre_Doc_Workflow | SELECT count(*) FROM Process_outcomes | Show the number of process outcomes. |
cre_Doc_Workflow | SELECT process_outcome_code , process_outcome_description FROM Process_outcomes | List the codes and descriptions for all process outcomes. |
cre_Doc_Workflow | SELECT process_outcome_description FROM Process_outcomes WHERE process_outcome_code = "working" | What is the description for the process outcome code working? |
cre_Doc_Workflow | SELECT count(*) FROM Process_status | Show the number of process status. |
cre_Doc_Workflow | SELECT process_status_code , process_status_description FROM Process_status | List the codes and descriptions for all process status. |
cre_Doc_Workflow | SELECT process_status_description FROM Process_status WHERE process_status_code = "ct" | What is the description for process status code ct? |
cre_Doc_Workflow | SELECT count(*) FROM Staff | How many staff do we have? |
cre_Doc_Workflow | SELECT staff_id , staff_details FROM Staff | Show the ids and details for all staff. |
cre_Doc_Workflow | SELECT staff_details FROM Staff WHERE staff_id = 100 | What are the details for the staff member with id 100. |
cre_Doc_Workflow | SELECT count(*) FROM Ref_staff_roles | Show the number of staff roles. |
cre_Doc_Workflow | SELECT staff_role_code , staff_role_description FROM Ref_staff_roles | List the codes and descriptions for all staff roles. |
cre_Doc_Workflow | SELECT staff_role_description FROM Ref_staff_roles WHERE staff_role_code = "HR" | What is the description for staff role code HR? |
cre_Doc_Workflow | SELECT count(DISTINCT document_id) FROM Documents_processes | How many documents have a process? |
cre_Doc_Workflow | SELECT DISTINCT process_id FROM Documents_processes | List all process ids with a document. |
cre_Doc_Workflow | SELECT document_id FROM Documents EXCEPT SELECT document_id FROM Documents_processes | Show all document ids without a process. |
cre_Doc_Workflow | SELECT process_id FROM Business_processes EXCEPT SELECT process_id FROM Documents_processes | List all process ids with no document. |
cre_Doc_Workflow | SELECT T2.process_outcome_description , T3.process_status_description FROM Documents_processes AS T1 JOIN Process_outcomes AS T2 ON T1.process_outcome_code = T2.process_outcome_code JOIN Process_Status AS T3 ON T1.process_status_code = T3.process_status_code WHERE T1.document_id = 0 | What is the process outcome description and process status description for the document with id 0? |
cre_Doc_Workflow | SELECT T3.process_name FROM Documents_processes AS T1 JOIN Documents AS T2 ON T1.document_id = T2.document_id JOIN Business_processes AS T3 ON T1.process_id = T3.process_id WHERE T2.document_name = "Travel to Brazil" | What is the process name for the document "Travel to Brazil"? |
cre_Doc_Workflow | SELECT process_id , count(*) FROM Documents_processes GROUP BY process_id | Show all process ids and the number of documents in each process. |
cre_Doc_Workflow | SELECT count(*) FROM Staff_in_processes WHERE document_id = 0 AND process_id = 9 | How many staff are the document with id 0 and process with id 9. |
cre_Doc_Workflow | SELECT staff_id , count(*) FROM Staff_in_processes GROUP BY staff_id | Show all staff ids and the number of document processes for each staff. |
cre_Doc_Workflow | SELECT staff_role_code , count(*) FROM Staff_in_processes GROUP BY staff_role_code | Show all staff role codes and the number of document processes for each role. |
cre_Doc_Workflow | SELECT count(DISTINCT staff_role_code) FROM Staff_in_processes WHERE staff_id = 3 | How many different roles does the staff with id 3 have? |
advertising_agencies | SELECT count(*) FROM Agencies | How many agencies do we have? |
advertising_agencies | SELECT count(*) FROM Agencies | Count the number of agencies. |
advertising_agencies | SELECT agency_id , agency_details FROM Agencies | Show all agency ids and details. |
advertising_agencies | SELECT agency_id , agency_details FROM Agencies | What are all the agency ids and details? |
advertising_agencies | SELECT count(*) FROM Clients | Show the number of clients. |
advertising_agencies | SELECT count(*) FROM Clients | How many clients are there? |
advertising_agencies | SELECT client_id , client_details FROM Clients | List all client ids and client details. |
advertising_agencies | SELECT client_id , client_details FROM Clients | What are all the client ids and details? |
advertising_agencies | SELECT agency_id , count(*) FROM Clients GROUP BY agency_id | Show agency ids and the number of clients for each agency. |
advertising_agencies | SELECT agency_id , count(*) FROM Clients GROUP BY agency_id | How many clients does each agency have? |
advertising_agencies | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id GROUP BY T1.agency_id ORDER BY count(*) DESC LIMIT 1 | What is the agency id and details with most number of clients? |
advertising_agencies | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id GROUP BY T1.agency_id ORDER BY count(*) DESC LIMIT 1 | Return the agency id and details for the agency with the greatest number of clients. |
advertising_agencies | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id GROUP BY T1.agency_id HAVING count(*) >= 2 | Show agency ids and details with at least 2 clients. |
advertising_agencies | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id GROUP BY T1.agency_id HAVING count(*) >= 2 | What are the agency ids and details agencies with at least 2 clients? |
advertising_agencies | SELECT T2.agency_details FROM Clients AS T1 JOIN Agencies AS T2 ON T1.agency_id = T2.agency_id WHERE T1.client_details = 'Mac' | Show agency details for client with detail 'Mac'. |
advertising_agencies | SELECT T2.agency_details FROM Clients AS T1 JOIN Agencies AS T2 ON T1.agency_id = T2.agency_id WHERE T1.client_details = 'Mac' | What are the agency details for clients with the detail Mac? |
advertising_agencies | SELECT T1.client_details , T2.agency_details FROM Clients AS T1 JOIN Agencies AS T2 ON T1.agency_id = T2.agency_id | Show details for all clients and the details of their corresponding agents. |
advertising_agencies | SELECT T1.client_details , T2.agency_details FROM Clients AS T1 JOIN Agencies AS T2 ON T1.agency_id = T2.agency_id | What are the client details for each client and the corresponding details of their agencies? |
advertising_agencies | SELECT sic_code , count(*) FROM Clients GROUP BY sic_code | Show all sic codes and the number of clients with each code. |
advertising_agencies | SELECT sic_code , count(*) FROM Clients GROUP BY sic_code | How many clients are there for each sic code? |
advertising_agencies | SELECT client_id , client_details FROM Clients WHERE sic_code = "Bad"; | Show all client ids and details with sic code "Bad". |
advertising_agencies | SELECT client_id , client_details FROM Clients WHERE sic_code = "Bad"; | What are the client ideas and details for clients with the sic code Bad? |
advertising_agencies | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id | Show all agency ids and details for agencies with a client. |
advertising_agencies | SELECT T1.agency_id , T1.agency_details FROM Agencies AS T1 JOIN Clients AS T2 ON T1.agency_id = T2.agency_id | What are the agency ids and agency details for all agencies who have a client? |
advertising_agencies | SELECT agency_id FROM Agencies EXCEPT SELECT agency_id FROM Clients | Show all agency ids without any client. |
advertising_agencies | SELECT agency_id FROM Agencies EXCEPT SELECT agency_id FROM Clients | What are ids of agencies that do not have any clients? |
advertising_agencies | SELECT count(*) FROM Invoices | How many invoices do we have? |
advertising_agencies | SELECT count(*) FROM Invoices | Count the number of invoices. |
advertising_agencies | SELECT invoice_id , invoice_status , invoice_details FROM Invoices | Show ids, status codes, and details for all invoices for clients. |
advertising_agencies | SELECT invoice_id , invoice_status , invoice_details FROM Invoices | What are the ids, statuses, and details for all invoices? |
advertising_agencies | SELECT client_id , count(*) FROM Invoices GROUP BY client_id | Show all client ids and the number of invoices for each client. |
advertising_agencies | SELECT client_id , count(*) FROM Invoices GROUP BY client_id | How many invoices are there for each client id? |
advertising_agencies | SELECT T1.client_id , T2.client_details FROM Invoices AS T1 JOIN Clients AS T2 ON T1.client_id = T2.client_id GROUP BY T1.client_id ORDER BY count(*) DESC LIMIT 1 | List the client id and detail with most number of invoices. |
advertising_agencies | SELECT T1.client_id , T2.client_details FROM Invoices AS T1 JOIN Clients AS T2 ON T1.client_id = T2.client_id GROUP BY T1.client_id ORDER BY count(*) DESC LIMIT 1 | What are the client id and details for the client with the most invoices? |
advertising_agencies | SELECT client_id FROM Invoices GROUP BY client_id HAVING count(*) >= 2 | What are client ids for clients with at least 2 invoices. |
advertising_agencies | SELECT client_id FROM Invoices GROUP BY client_id HAVING count(*) >= 2 | Return the client ids for clients with two or more invoices? |
advertising_agencies | SELECT invoice_status , count(*) FROM Invoices GROUP BY invoice_status | Show all invoice status codes and the number of invoices with each status. |
advertising_agencies | SELECT invoice_status , count(*) FROM Invoices GROUP BY invoice_status | How many invoices are there for each status code? |
advertising_agencies | SELECT invoice_status FROM Invoices GROUP BY invoice_status ORDER BY count(*) DESC LIMIT 1 | What is the invoice status code with most number of invoices. |
advertising_agencies | SELECT invoice_status FROM Invoices GROUP BY invoice_status ORDER BY count(*) DESC LIMIT 1 | Return the invoice status that has the most invoices. |
advertising_agencies | SELECT T1.invoice_status , T1.invoice_details , T2.client_id , T2.client_details , T3.agency_id , T3.agency_details FROM Invoices AS T1 JOIN Clients AS T2 ON T1.client_id = T2.client_id JOIN Agencies AS T3 ON T2.agency_id = T3.agency_id | Show all invoice status codes and details and the corresponding client id and details and agency id and details. |
advertising_agencies | SELECT T1.invoice_status , T1.invoice_details , T2.client_id , T2.client_details , T3.agency_id , T3.agency_details FROM Invoices AS T1 JOIN Clients AS T2 ON T1.client_id = T2.client_id JOIN Agencies AS T3 ON T2.agency_id = T3.agency_id | What are the invoice status, invoice details, and corresponding client ids and details and agency id and details? |
advertising_agencies | SELECT meeting_type , other_details FROM meetings | List all meeting type codes and details. |
Subsets and Splits
World Countries Non-English Languages
The query filters specific database entries based on a particular query pattern, providing limited insight as it simply retrieves rows that match a specific condition.