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where $G_{\alpha+1/2}$ is defined by (20) and $u_{\alpha+1/2}, v_{\alpha+1/2}$ are given by (21). The quantity $N_{\alpha+1/2}$ satisfies the following moment relations

R2(1ξγ)Nα+1/2dξdγ=(Gα+1/2uα+1/2Gα+1/2vα+1/2Gα+1/2),R2(ξ2γ2γ2)Nα+1/2dξdγ=((uα+1/222+g4hvα+1/222+g4hvα+1/222+g4h))Gα+1/2.(64) \int_{\mathbb{R}^2} \begin{pmatrix} 1 \\ \xi \\ \gamma \end{pmatrix} N_{\alpha+1/2} d\xi d\gamma = \begin{pmatrix} G_{\alpha+1/2} \\ u_{\alpha+1/2} G_{\alpha+1/2} \\ v_{\alpha+1/2} G_{\alpha+1/2} \end{pmatrix}, \quad \int_{\mathbb{R}^2} \begin{pmatrix} \xi^2 \\ \frac{\gamma}{2} \\ \frac{\gamma}{2} \end{pmatrix} N_{\alpha+1/2} d\xi d\gamma = \left( \begin{pmatrix} \frac{u_{\alpha+1/2}^2}{2} + \frac{g}{4}h \\ \frac{v_{\alpha+1/2}^2}{2} + \frac{g}{4}h \\ \frac{v_{\alpha+1/2}^2}{2} + \frac{g}{4}h \end{pmatrix} \right) G_{\alpha+1/2}. \tag{64}

Notice that from (20), we can give a kinetic interpretation on the exchange terms under the form

Gα+1/2=j=1N(p=1αlp1jα)R2(ξγ)x,yMjdξdγ,(65) G_{\alpha+1/2} = - \sum_{j=1}^{N} \left( \sum_{p=1}^{\alpha} l_p - \mathbf{1}_{j \le \alpha} \right) \int_{\mathbb{R}^2} \begin{pmatrix} \xi \\ \gamma \end{pmatrix} \cdot \nabla_{x,y} M_j d\xi d\gamma, \quad (65)

for $\alpha = 1, \dots, N$.

Then we have the two following results.

Proposition 4.1 The functions uN defined by (17) and h are strong solutions of the system (18)-(19) if and only if the sets of equilibria {Mα}Nα=1, {Nα+1/2}Nα=0 are solutions of the kinetic equations defined by

(Bα)Mαt+(ξγ)x,yMαgx,yzbξ,γMαNα+1/2+Nα1/2=Qα,(66) (\mathcal{B}_\alpha) \quad \frac{\partial M_\alpha}{\partial t} + \begin{pmatrix} \xi \\ \gamma \end{pmatrix} \cdot \nabla_{x,y} M_\alpha - g \nabla_{x,y} z_b \cdot \nabla_{\xi,\gamma} M_\alpha - N_{\alpha+1/2} + N_{\alpha-1/2} = Q_\alpha, \quad (66)

for $\alpha = 1, \dots, N$. The quantities $Q_\alpha = Q_\alpha(t, x, y, \xi, \gamma)$ are "collision terms" equal to zero at the macroscopic level, i.e. they satisfy a.e. for values of $(t, x, y)$

R2Qαdξdγ=R2ξQαdξdγ=R2γQαdξdγ=0.(67) \int_{\mathbb{R}^2} Q_\alpha d\xi d\gamma = \int_{\mathbb{R}^2} \xi Q_\alpha d\xi d\gamma = \int_{\mathbb{R}^2} \gamma Q_\alpha d\xi d\gamma = 0. \qquad (67)

Proposition 4.2 The solutions of (66) are entropy solutions if

H(Mα)t+(ξγ)x,yH(Mα)gx,yzbξ,γH(Mα)(H(Nα+1/2)H(Nα1/2)),(68) \frac{\partial H(M_\alpha)}{\partial t} + \begin{pmatrix} \xi \\ \gamma \end{pmatrix} \cdot \nabla_{x,y} H(M_\alpha) - g \nabla_{x,y} z_b \cdot \nabla_{\xi,\gamma} H(M_\alpha) \leq (H(N_{\alpha+1/2}) - H(N_{\alpha-1/2})), \quad (68)

with the notation $H(M) = H(M, \xi, \gamma, z_b)$ and $H$ defined by (61). The integration in $\xi, \gamma$ of relation (68) gives

Eαt+x,y.uα(Eα+g2hαh)lα(uα+1/222+gzb)Gα+1/2lα(uα1/222+gzb)Gα1/2. \frac{\partial E_{\alpha}}{\partial t} + \nabla_{x,y} . u_{\alpha} (E_{\alpha} + \frac{g}{2} h_{\alpha} h) \leq l_{\alpha} \left( \frac{|u_{\alpha+1/2}|^2}{2} + gz_b \right) G_{\alpha+1/2} - l_{\alpha} \left( \frac{|u_{\alpha-1/2}|^2}{2} + gz_b \right) G_{\alpha-1/2}.

Proof of proposition 4.1 The proof relies on averages w.r.t the variables $\xi, \gamma$ of Eq. (66) against the vector $(1, \xi, \gamma)^T$. Using relations (60), (63), (64) and the properties of the collision terms (67), the quantities

R2(Bα)dξdγ,R2ξ(Bα)dξdγ,andR2γ(Bα)dξdγ, \int_{\mathbb{R}^2} (\mathcal{B}_\alpha) d\xi d\gamma, \quad \int_{\mathbb{R}^2} \xi (\mathcal{B}_\alpha) d\xi d\gamma, \quad \text{and} \quad \int_{\mathbb{R}^2} \gamma (\mathcal{B}_\alpha) d\xi d\gamma,

respectively give Eqs. (28) and (19). The sum for $\alpha = 1$ to $N$ of Eqs. (28) with (20) gives (18) that completes the proof. $\blacksquare$