Convergence of Eulerian triangulations
If it does not leave this layer, then its length is bounded below by
∑ i = 1 N r ( 2 m , l m ) D i a m ( G 2 m ( i , l m ) ) .
\sum_{i=1}^{N_r(2m,lm)} \mathrm{Diam}(\mathcal{G}_{2m}(i,lm)).
i = 1 ∑ N r ( 2 m , l m ) Diam ( G 2 m ( i , l m )) .
Then, from Lemma 7.3, and from the definition of f, we get that, for r/m large enough,
for some c' > 0 independent of r, l, m,
P ( { N r ( 2 m , l m ) < c ( r m ) 2 } ∪ { ∃ i ∈ { 1 , … , N r ( 2 m , l m ) } ∣ Diam ( G 2 m ( i , l m ) ) ≤ c ′ f ( 2 m ) } ) ≤ 1 4 ,
P\left(\{N_r(2m, lm) < c \left(\frac{r}{m}\right)^2\} \cup \{\exists i \in \{1, \dots, N_r(2m, lm)\} \mid \text{Diam}(\mathcal{G}_{2m}(i, lm)) \le c' f(2m)\} \right) \le \frac{1}{4},
P ( { N r ( 2 m , l m ) < c ( m r ) 2 } ∪ { ∃ i ∈ { 1 , … , N r ( 2 m , l m )} ∣ Diam ( G 2 m ( i , l m )) ≤ c ′ f ( 2 m )} ) ≤ 4 1 ,
so that
P ( D i a m ( G r ) ≤ m / 3 ∧ c ⋅ c ′ ( r / m ) 2 f ( 2 m ) ) ≤ 1 4 ,
\mathbb{P}(\mathrm{Diam}(\mathcal{G}_r) \leq m/3 \wedge c \cdot c'(r/m)^2 f(2m)) \leq \frac{1}{4},
P ( Diam ( G r ) ≤ m /3 ∧ c ⋅ c ′ ( r / m ) 2 f ( 2 m )) ≤ 4 1 ,
which implies the desired bound, by the definition of f .
The details of the proof can be adapted from the proof of [14, Proposition 1]. $\square$
Theorem 7.2 is then a purely analytic consequence of Proposition 7.4, and its proof is
a straightforward adaptation of that of [14, Theorem 5].
We can now use Theorem 7.2 to obtain the following lower bounds for the distances
along the boundary of $\mathcal{L}$:
Proposition 7.5. For every $\varepsilon > 0$, there exists an integer $K > 0$ such that, for every $r \ge 1$,
P ( min ∣ j ∣ ≥ K r 2 d ⃗ L ( ( 0 , 0 ) , ( j , 0 ) ) ≥ r ) ≥ 1 − ε .
\mathbb{P} \left( \min_{|j| \ge K r^2} \vec{d}_{\mathcal{L}}((0,0), (j,0)) \ge r \right) \ge 1 - \varepsilon.
P ( ∣ j ∣ ≥ K r 2 min d L (( 0 , 0 ) , ( j , 0 )) ≥ r ) ≥ 1 − ε .
Consequently, for $K' = 9K$, we also have, for every $r \ge 1$,
P ( min ∣ j ∣ ≥ 2 K ′ r 2 min − K ′ r 2 ≤ i ≤ K ′ r 2 d ⃗ L ( ( i , 0 ) , ( j , 0 ) ) ≥ r ) ≥ 1 − 2 ε .
\mathbb{P} \left( \min_{|j| \ge 2K'r^2} \min_{-K'r^2 \le i \le K'r^2} \vec{d}_{\mathcal{L}}((i,0), (j,0)) \ge r \right) \ge 1 - 2\varepsilon.
P ( ∣ j ∣ ≥ 2 K ′ r 2 min − K ′ r 2 ≤ i ≤ K ′ r 2 min d L (( i , 0 ) , ( j , 0 )) ≥ r ) ≥ 1 − 2 ε .
Proof. Let us start with the first assertion. Let $\epsilon > 0$. Fix $r \ge 1$, and $K \ge 1$. Then, from (5.18), the number $N_{(K,r)}$ of trees that reach height $r$ between $(0,0)$ and $(j,0)$ is bounded below by a binomial variable of parameters $(Kr^2, 3/((r+2)^2-1))$, so that, using Chebyshev's inequality, for any $a > 0$,
P ( N ( K , r ) ≤ 3 8 K − a ) ≤ 3 K a 2 .
\mathbb{P}\left(N_{(K,r)} \le \frac{3}{8}K - a\right) \le \frac{3K}{a^2}.
P ( N ( K , r ) ≤ 8 3 K − a ) ≤ a 2 3 K .
(Note that the binomial variable in question has expectation greater than or equal to
$3K/8$, with equality when $r=1$, and a variance smaller than $3K$.)
Taking $a = \sqrt{(6K/\epsilon)}$, for $K$ large enough that $a \le (1/8)K + 1$, we get
P ( N ( K , r ) ≤ 1 4 K + 1 ) ≤ ϵ 2 . (7.1)
\mathbb{P}\left(N_{(K,r)} \le \frac{1}{4}K + 1\right) \le \frac{\epsilon}{2}. \tag{7.1}
P ( N ( K , r ) ≤ 4 1 K + 1 ) ≤ 2 ϵ . ( 7.1 )
Now, on the event that $N_{(K,r)} > K/4$, for any $j \ge Kr^2$, we have
d ⃗ L ( ( 0 , 0 ) , ( j , 0 ) ) ≥ ∑ i = 1 ⌊ K 4 ⌋ + 1 D i a m ( G r ( i ) ) ∧ r ,
\vec{d}_{\mathcal{L}}((0,0), (j,0)) \geq \sum_{i=1}^{\lfloor \frac{K}{4} \rfloor + 1} \mathrm{Diam}(\mathcal{G}_r(i)) \wedge r,
d L (( 0 , 0 ) , ( j , 0 )) ≥ i = 1 ∑ ⌊ 4 K ⌋ + 1 Diam ( G r ( i )) ∧ r ,
so that, using Theorem 7.2,
P ( d ⃗ L ( ( 0 , 0 ) , ( j , 0 ) ) < c r K 4 ∧ r ) ≤ 1 2 K / 4 .
\mathbb{P}\left(\vec{d}_{\mathcal{L}}((0,0), (j,0)) < c r \frac{K}{4} \wedge r\right) \leq \frac{1}{2^{K/4}}.
P ( d L (( 0 , 0 ) , ( j , 0 )) < cr 4 K ∧ r ) ≤ 2 K /4 1 .